湖南省常德市石门县第一中学2015-2016学年高二下学期第一次月考(单元检测)生物(文)试题含答案
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长沙市第一中学 2024—2025 学年度高二第一学期第一次阶段性检测语文时量:150分钟满分:150分一、现代文阅读(35分)(一)现代文阅读I(本题共5小题,19分)阅读下面的文字,完成下面小题。
材料一:马克思主义者认为人类社会的生产活动,是一步又一步地由低级向高级发展,因此,人们的认识,不论对于自然界方面,还是对于社会方面,也都是一步又一步地由低级向高级发展,即由浅入深,由片面到更多的方面。
在很长的历史时期内,大家对于社会的历史只能限于片面的了解,这一方面是由于剥削阶级经常歪曲社会的历史,另一方面,则是由于生产规模的狭小,限制了人们的眼界。
人们能够对于社会历史的发展作全面的历史的了解,把对于社会的认识变成科学,这只是到了伴随巨大生产力——工业而出现近代无产阶级的时候,这就是马克思主义的科学。
马克思主义者认为,只有人们的社会实践,才是人们对于外界认识的真理性的标准。
实际的情形是这样的,只有在社会实践过程中(物质生产过程中,阶级斗争过程中,科学实验过程中),人们达到了思想中所预想的结果时,人们的认识才被证实了。
人们要想得到工作的胜利即得到预想的结果,一定要使自己的思想合于客观外界的规律性,如果不合,就会在实践中失败。
人们经过失败之后,也就从失败取得教训,改正自己的思想使之适合于外界的规律性,人们就能变失败为胜利,所谓“失败者成功之母”,“吃一堑长一智”,就是这个道理。
辨证唯物论的认识论把实践提到第一的地位,认为人的认识一点也不能离开实践,排斥一切否认实践重要性、使认识离开实践的错误理论。
列宁这样说过:“实践高于(理论的)认识,因为它不但有普遍性的品格,而且还有直接现实性的品格。
”马克思主义的哲学辩证唯物论有两个最显著的特点:一个是它的阶级性,公然申明辩证唯物论是为无产阶级服务的;再一个是它的实践性,强调理论对于实践的依赖关系,理论的基础是实践,又转过来为实践服务。
判定认识或理论校之是否真理,不是依主观上觉得如何而定,而是依客观上社会实践的结果如何而定。
湖南师大附中2016届高二第一次月考试题数学(文科)命题:高二文科数学备课组审题:高二文科数学备课组一、选择题:本大题共10个小题,每小题5分,共50分,在每小题给出的四个选项中,只有一项是符合题目要求的. 1.设集合A ={1,2,3,5,7},B ={x ∈N |2<x ≤6},全集U A B =U ,则()U A B =I ð(A ) A.{1,2,7}B.{1,7}C.{2,3,7}D.{2,7}2.设a ,b ,c 为实数,则使a >b 成立的一个充分不必要条件是(D ) A.ac >bc B.a bc c> C.a +c >b +c D.ac 2>bc 2 3..函数f (x )=1ln x +1+29x -(B )A.[-3,0)∪(0,3]B.(-1,0)∪(0,3]C.[-3,3]D.(-1,3]4.师大附中高二年级开展“我的未来不是梦”演讲比赛,七位评委为某参赛选手给出的分数(满分:100分)如右茎叶图所示,去掉一个最高分和一个最低分后,则余下5个分数的方差是(A )A.1.6B.8 1.6 D.225.已知tan(π-α)=2,则2sin 2cos αα+=(D ) A.1B.35C.15- D.35- 【解析】由已知,tan α=-2,则原式22222sin cos cos 2tan 13sin cos tan 15ααααααα++===-++,选D.7 98 4 4 6 4 79 3茎叶6.在区间(0,1)上任取两个数x ,y ,则事件“43x y +<”发生的概率是(D ) A.92 B.95 C.94D.97 【解析】图中阴影部分的面积除以正方形的面积为所求的概率所以122712339P =-⋅⋅=,选D.7.已知函数f (x )=(t 2-t +1)35t x+是幂函数,其图象关于y 轴对称,则实数t 的值为(C )A.-1B.0C.1D.0或18.设等差数列{a n }的前n 项和为S n ,已知112a =,且123a a a +=,则S 40=(C ) A.290B.390C.410D.430 9.将函数sin(2)3y x π=+图象上各点的横坐标伸长到原来的2倍(纵坐标不变),再将图象向右平移3π个单位,则所得图象的函数解析式是(D )A.f (x )=cos4xB.f (x )=cos xC.f (x )=sin4xD.f (x )=sin x10.已知向量a ,b 满足:|a |=1,b =1),则|a -b |的最大值是(B )A.4B.3C.2D.1二、填空题:本大题共5个小题,每小题5分,共25分.把各题答案的最简形式写在题中的横线上. 11.从某500件产品中随机抽取50件进行质检,利用随机数表法抽取样本时,先将这500件产品按001,002,…,500进行编号.如果从随机数表第8行第8列的数8开始,从左往右读数,则依次抽取的第4个个体的编号是_ 286 .(下面摘录了随机数表第7行至第9行各数) 8442175331572455068877047447672176335025 8392120676 6301637859169556671998105071751286735807443952387933211234297864560782524207443815510013429966027954【解析】第一个读数是859,舍去;第二个读数是169,取出;….依次抽取的前4个个体的编号分别是169,105,071,286.12.一个底面是正三角形的三棱柱的正视图如图所示,则这个三棱柱.13.若△ABC 的面积为BC =3,C =60°,则AB 14.已知x >0,y >0,且211x y+=,则x +2y 的最小值是 8 . 【解析】由已知,211x y +=,则2142(2)()448x y x y x y x y y x +=++=++≥+=. 当且仅当x =4,y =2时取等号,所以x +2y 的最小值是8.15.函数221,0()(1),0axax x f x a e x ⎧+≥⎪=⎨-<⎪⎩在(,)-∞+∞上单调,则实数a 的取值范围是(,-∞U三、解答题:本大题共6个小题,共75分,解答应写出文字说明,证明过程或演算步骤. 16.(本题满分12分)已知集合A ={x |x 2-4ax +3a 2<0},集合B ={x |x 2+6x +8≥0},其中a <0为常数.(Ⅰ)设条件p :x ∈A ;条件q :x ∈B ,若﹁p 是﹁q 的必要不充分条件,求a 的取值范围; (Ⅱ)设命题r :∃a <0,使A B =∅I ,试判断命题r 的真假. 【解】(Ⅰ)由x 2-4ax +3a 2<0,得(3)()0x a x a --<.因为a <0,则3a <x <a ,所以A =(3a ,a ).(2分)由x 2+6x +8≥0,得(x +4)(x +2)≥0,即x ≤-4或x ≥-2. 所以B =(-∞,-4]∪[-2,+∞).(4分)因为﹁p 是﹁q 的必要不充分条件,则q p ⌝⇒⌝,即p q ⇒,所以A 是B 的真子集.(6分) 所以a ≤-4或-2≤3a <0,故a 的取值范围是2(,4][,0)3-∞--U .(8分) (Ⅱ)假设A B =∅I ,则342a a ≥-⎧⎨≤-⎩,即432a a ⎧≥-⎪⎨⎪≤-⎩,无解.(10分)所以对任意a <0,A B ≠∅I ,即﹁r 为真命题,故命题r 为假命题.(12分) 17.(本题满分12分)已知函数f (x)=2cos x (3sin x +cos x )-1. (Ⅰ)求函数f (x )在区间[0,π2]上的最大值和最小值;(Ⅱ)若f (x 0)=65,x 0∈[π4,π2],求cos2x 0的值.【解】(Ⅰ)因为f (x )=23sin x cos x +2cos2x -1=3sin2x +cos2x =2sin(2x +π6).(3分)当[0,]2x π∈时,72[,]666x πππ+∈,1sin(2)[,1]62x π+∈-.(5分) 所以f (x )在区间[0,π2]上的最大值为2,最小值为-1.(6分)(Ⅱ)因为f (x 0)=2sin(2x 0+π6)=65,则sin(2x 0+π6)=35.(7分)因为x 0∈[π4,π2],则2x 0+π6∈[2π3,7π6].从而cos(2x 0+π6)=45=-(2分)故cos2x 0=cos[(2x 0+π6)-π6]=cos(2x 0+π6)cos π6+sin(2x 0+π6)sin π6=3-4310.(12分)18.(本题满分12分)为了解学生家长对师大附中实施现代教育教改实验的建设性意见,学校决定用分层抽样的方法,从高中三个年级的家长委员会中共抽取6人进行座谈.已知高一、高二、高三年级的家长委员会分别有54人、18人、36人.(Ⅰ)求从三个年级的家长委员会中应分别抽取的家长人数;故所求的概率为1205P =-=.(12分)19.(本题满分12分)如图,在长方体ABCD -A 1B 1C 1D 1中,BC =CC 1,点E 在棱AB 上. (Ⅰ)证明:B 1C ⊥C 1E ;(Ⅱ)若四棱锥E -B 1BCC 1的体积为43,求异面直线AA 1与C 1E 所成的角. 【解】(Ⅰ)连结BC 1,因为BC =CC 1,则四边形BCC 1B 1为正方形,所以B 1C ⊥BC 1.①(2分)因为AB ⊥平面BCC 1B 1,则AB ⊥B 1C.②(4分) 结合①②知,B 1C ⊥平面BC 1E ,所以B 1C ⊥C 1E.(6分) (Ⅱ)因为CC 1∥AA 1,则∠CC 1E 为所求的角.(7分) 因为BC =CC 1,则1111233E B BCC V BC CC BE BE -=⋅⋅⋅=. 由已知,2433BE =,则BE =2.(9分) 在Rt △CBE 中,CE ==(10分)在Rt △C 1CE 中,11tan CECC E CC ∠==CC 1E =60°. 故异面直线AA 1与C 1E 所成的角为60°.(12分) 20.(本题满分13分)已知圆C :x 2+y 2-2x +4y -4=0.问在圆C 上是否存在两点A 、B 关于直线y =kx -1对称,且以AB 为直径的圆经过原点?若存在,写出直线AB 的方程;若不存在,说明理由. 【解】 圆C 的方程可化为(x -1)2+(y +2)2=9,圆心为C (1,-2).假设在圆C 上存在两点A 、B 满足条件,则圆心C (1,-2)在直线y =kx -1上,即k =-1.(3分) 于是可知,1=AB k .A BC D A 1B 1C 1D 1E设b x y AB +=:,代入圆C 的方程,整理得044)1(2222=-++++b b x b x , 则Δ>0,即0962=-+b b .解得233233+-<<--b .(7分) 设点A 、B 的坐标分别为A (x 1,y 1),B (x 2,y 2),则x 1+x 2=-b -1,x 1x 2=12b 2+2b -2.由题意知OA ⊥OB ,则有x 1x 2+y 1y 2=0,(10分) 也就是x 1x 2+(x 1+b )(x 2+b )=0. ∴2x 1x 2+b (x 1+x 2)+b 2=0.∴b 2+4b -4-b 2-b +b 2=0,化简得b 2+3b -4=0. 解得b =-4或b =1,均满足Δ>0,[12分]即直线AB 的方程为x -y -4=0,或x -y +1=0.(13分) 21.(本题满分13分) 已知数列{a n }满足:21212n n a a a n+++=-L (n ∈N*). (Ⅰ)求数列{a n }的通项公式;(Ⅱ)设22n nn nb a -=,数列{b n }的前n 项和为.n S 若对一切n ∈N*,都有S n <M 成立(M 为正整数),求M 的最小值. 【解】(Ⅰ)因为21212n n a a a n +++=-L ,则11212121n n a aa n --+++=--L (n ≥2).(2分) 两式相减,得12n na n-=,即12(2).n n a n n -=⋅≥(3分) 由已知,a 1=2-1=1满足上式.(4分)故数列{a n }的通项公式是12.n n a n -=⋅(5分)(Ⅱ)由题设,11(21)2122n n n n n n b n ----==⋅.(6分)则21135211222n n n S --=++++L ,21113232122222n n nn n S ---=++++L .(8分) 两式相减,得22111211212311332222222n n n n n n n n n S ----+=++++-=--=-L .(10分) 所以1236.2n n n S -+=-(11分)显然,6n S <,又5136516S =->,所以M ≥6,故M 的最小值为6.(13分)。
湖南省常德市汉寿县第一中学2024-2025学年高二上学期10月月考数学试题一、单选题1.已知集合{}21A x x =∈-<<Z ,{}2230B x x x =∈--<Z ,则A B 的子集个数是()A .4B .8C .16D .322.78337857sin cos cos cos ︒︒-︒︒的值()A .12B .12-C .2D .3.已知单位向量12,e e 是平面内的一组基底,且12π,3e e = ,若向量123a e e =+ 与12b e e λ=+垂直,则λ的值为()A .75-B .75C .1D .1-4.如果不共线向量,a b 满足2a b = ,那么向量2a b + 与2a b - 的夹角为()A .6πB .3πC .2πD .23π5.复数z 的共轭复数z 满足()1i 1i z +=-,则复数z 在复平面内对应的点位于()A .第一象限B .第二象限C .x 轴D .y 轴6.已知圆锥PO (P 为圆锥的顶点,O 为圆锥底面的圆心)的轴截面是等边三角形,,,A B C 为底面圆周上的三点,且AB 为底面圆的直径,D 为PC 的中点.若三棱锥D ABC -的外接球的表面积为4π,则圆锥PO 的外接球的表面积为()A .16π3B .32π3C .16πD .64π37.已知,{1,2,3,4,5,6}x y ∈,且7x y +=,则2xy ≥的概率为A .13B .23C .12D .568.分别标有数字1,2,3,4的4张卡片,从这4张卡片中随机抽取2张卡片,则取出的2张卡片上的数字之和为奇数的取法数为()A .2B .3C .4D .6二、多选题9.已知事件A 与B ,且()()0.4,0.1P A P B ==,则下列结论正确的是()A .如果A 与B 互斥,那么()0.5P A B = B .如果A 与B 相互独立,则()0.04P AB =C .如果A 与B 相互独立,那么()0.96P AB =D .如果A 与B 相互独立,那么()0.54P AB =10.如图,已知在棱长为2的正方体1111ABCD A B C D -中,点E ,F ,H 分别是AB ,1DD ,1BC 的中点,点G 是11A D 上的动点,下列结论正确的是()A .11//C D 平面ABHB .1AC ⊥平面1BDA C .直线EF 与1BC 所成的角为30°D .三棱锥1G DBC -的体积最大值为8311.下列关于空间向量的命题中,是真命题的是()A .若三个非零向量能构成空间的一个基底,则它们一定不共面B .若0a b ⋅>,则a ,b 的夹角是锐角C .不相等的两个空间向量的模可能相等D .若a,b 是两个不共线的向量,且(,c a b λμλμ=+∈R 且0)λμ⋅≠,则{},,a b c 构成空间的一个基底三、填空题12.一艘船以每小时10海里的速度向东航行,船在A 处发现灯塔M 在北偏西15︒方向,灯塔N 在北偏东45︒方向,行驶4小时后,船到达B 处,测得灯塔N 在B 处的正北方向,灯塔M 在B 处的北偏西60︒方向,则M 、N 两处灯塔间的距离为海里.13.如图,ABC 中,π3B ∠=,D 为边AB 上的一点,CD =AD =,4BC =,则AC =.14.为估计某草场内兔子的数量,使用以下方法:先随机从草场中捕捉兔子100只,在每只兔子的尾巴上作上记号后放回草场.再随机从草场中捕捉60只,若尾巴上有记号的兔子共有10只,估计此草场内约有兔子只.四、解答题15.已知())222cos sin 2cos 14f x x x x π⎛⎫=--++ ⎪⎝⎭的定义域为[02π,].(1)求()f x 的最小值.(2)ABC V 中,45A︒=,b =a 的长为6,求角B 大小及ABC V 的面积.16.已知向量a b,,满足||1||1a b == ,,|||ka b a kb +=- ,0k >,(1)用k 表示a b,,并求a 与b 的夹角θ的最大值;【注:若0,0a b >>,则a b +≥,当且仅当a b =时取等号】(2)如果//a b,求实数k 的值.17.某学校为增强学生自主学习意识,现向全校学生进行中午学习时长的调查,得到一个样本,按时长分成[)20,25,[)25,30,[)30,35,[)35,40,[]40,45,得到的频率分布直方图如图所示,已知时长在[)20,25内的人数为5.(1)若用分层抽样的方法从时长在[)35,40,[]40,45内的学生中抽取6名参加座谈,再从这6名学生中随机抽取2名发言,求这2名发言学生中至少有1名时长在[)35,40内的概率;(2)在(1)的条件下,记抽取的2名发言者分别为甲、乙,学校给甲、乙各随机派发价值50元,80元,100元的图书一本,求甲获得的图书价值不比乙获得图书价值高的概率.18.已知甲、乙两个盒子都装有4个外形完全相同的小球.甲盒中是3个黑色小球(记为123,,A A A )和1个红色小球(记为B ),乙盒中是2个黑色小球(记为12,a a )和2个红色小球(记为12,b b ).(1)若从甲、乙两个盒子中各取1个小球,共有多少种不同的结果?请列出所有的结果;(2)若从甲、乙两个盒子中各取1个小球,求取出的2个小球中至少有一个是黑色的概率.19.如图,四棱锥P ABCD -中,底面ABCD 是直角梯形,//AB CD ,AB AD ⊥,224AB CD AD ===,侧面PAB 是等腰直角三角形,PA PB =,平面PAB ⊥平面ABCD ,点E ,F 分别是棱AB ,PB 的中点.(1)证明:平面//CEF 平面PAD .(2)求三棱锥C DEF -的体积.。
常德市第一中学2025届高三第一次月水平检测数学时量:120分钟满分:150分一、单选题。
(本题共8小题,每题5分,共40分,在每小题给出的四个选项中,只有一个是符合题目要求的。
)1.已知集合{}{}21,24A x x B x x =-≤=-<≤,则A B = ()A .{}4x x ≤B .{}34x x ≤≤C .{}23x x -<≤D .{}24x x -<≤2.命题“x ∃∈R ,ln e 0x x x ++>”的否定是()A .x ∃∈R ,ln e 0x x x ++≤B .x ∀∈R ,ln e 0x x x ++≤C .x ∀∉R ,ln e 0x x x ++≤D .x ∃∉R ,ln e 0x x x ++<3.设5log 2a =,25log 3b =,0.20.6c =,则()A .c b a>>B .c a b>>C .b a c>>D .a c b>>4.近年,“人工智能”相关软件以其极高的智能化水平引起国内关注,深度学习是人工智能的一种具有代表性的实现方法,它是以神经网络为出发点的.在神经网络优化中,指数衰减的学习率模型为181425G L ⎛⎫=⨯ ⎪⎝⎭,其中L 表示每一轮优化时使用的学习率,G 表示训练迭代轮数,则学习率衰减到0.2及以下所需的训练迭代轮数至少为(参考数据:lg20.301≈)()A .16B .72C .74D .905.“1m £”是“函数()()22log 1f x x mx =--在()1,+∞单调递增”的()A .充分不必要条件B .必要不充分条件C .充要条件D .既不充分也不必要条件6.对于三次函数()()³²0f x ax bx cx d a =+++≠给出定义:设()f x '是函数()y f x =的导数,()f x ''是()f x '的导数,若方程()0f x ''=有实数解0x ,则称点00(,())x f x 为函数()y f x =的“拐点”.某同学经过探究发现:任何一个三次函数都有“拐点”;任何一个三次函数都有对称中心,且“拐点”就是对称中心.给定函数32115()33212f x x x x =-+-,请你根据上面探究结果,计算12320202021202120212021f f f f ⎛⎫⎛⎫⎛⎫⎛⎫+++⋅⋅⋅+= ⎪ ⎪ ⎪ ⎪⎝⎭⎝⎭⎝⎭⎝⎭()A .1010B .2020C .2023D .20247.()1212,[1,e]x x x x ∀∈≠,均有122121ln ln x x x x a x x -<-成立,则a 的取值范围为()A .(],0-∞B .[)1,+∞C .[]0,1D .[)0,+∞8.已知函数()()22e ,e xf x x x ag x x =-+=-,若(][]12,0,1,e x x ∞∀∈-∃∈,使()()12g x f x ≤成立,则实数a 的取值范围是()A .[)2e 1,-+∞B .12e 1,e ∞⎡⎫+-+⎪⎢⎣⎭C .)2e ,⎡+∞⎣D .21e ,e ⎡⎫++∞⎪⎢⎣⎭二、多选题(本题有3小题,每小题6分,共18分,在每小题给出的选项中,有多项符合题目要求,全部选对得6分,部分选对得部分分,选错得0分)9.下列选项中正确的有()A .若a b >,则22ac bc >B .若集合{}{}20|1,2,A B x ax =-=+=,且B A ⊆,则实数a 的取值所组成的集合是{}1,2-.C .若不等式20ax bx c ++>的解集为{}3|1x x <<,则不等式20cx bx a ++<的解集为1{3x x <或1}x >D .已知函数()1y f x =+的定义域是[]2,3-,则()1y f x =-的定义域是[]0,5.10.已知0,0a b >>,且1a b +=,则()A .ab 的最小值是14B .222a b +最小值为23CD .12aa b+的最小值是111.已知函数()1e ,01ln ,04x x x f x x x +⎧-≤⎪=⎨->⎪⎩,下列选项中正确的是()A .()f x 在(),1-∞-上单调递增,在()1,0-上单调递减B .()f x 有极大值C .()f x 无最小值D .若函数()()()()2[]24h x f x af x a =-+∈R 恰有6个零点,则实数a 的取值范围是5,2⎛⎫+∞ ⎪⎝⎭三、填空题(本题共3小题,每小题5分,共15分)12.已知命题“[]1,5x ∃∈,使得1e 0xa x--<”是假命题,则实数a 的取值范围是.13.已知函数()f x ,()g x 分别是定义在R 上的奇函数,偶函数,且()()e xf xg x +=,则()()22f xg x -=⎡⎤⎡⎤⎣⎦⎣⎦.14.设函数()2e e xf x ax x =--,若在()0,∞+上满足()0f x <的正整数至多有两个,则实数a 的取值范围是.四、解答题(本题共5小题,共77分,解答应写出文字说明,证明过程和演算步骤)15.(13分)在ABC 中,内角,,A B C 所对的边分别为,,a b c ,已知向量,m n 满足(2,6m a =-,)2sin ,n B b =,且m n ⊥.(1)求角A ;(2)若ABC 是锐角三角形,且3a =,求ABC 周长的取值范围.16.(15分)已知正方体1111ABCD A B C D -的棱长为3,11113PD A D =,11123QC C D =,M 为线段BD 上的动点,M '是点M 关于AD 所在直线的对称点.(1)求证:1MB PQ ⊥;(2)求三棱锥1Q PMB -的体积;(3)当2BM DM =时,求二面角M PQ M '--的余弦值的绝对值.17.(15分)数列{}n a 满足321212222n n a a a a n -+++⋯+=.(1)求{}n a 的通项公式;(2)若n nnb a =,求{}n b 的前n 项和n T .18.(17分)已知椭圆2222:1(0)x y C a b a b+=>>的右焦点与点3,12P ⎛⎫ ⎪⎝⎭连线的斜率为2,且点()1,e 在椭圆C 上(其中e 为C 的离心率).(1)求椭圆C 的标准方程.(2)已知点(2,0)D ,过点P 的直线l 与C 交于A ,B 两点,直线DA ,DB 分别交C 于M ,N 两点,试问直线MN 的斜率是否为定值?若是,求出该定值;若不是,请说明理由.19.(17分)已知()2ln x ax x bf x x++=(1)当3,1a b =-=-时,求曲线()y f x =在点()()1,1f 处的切线方程;(2)已知()f x 有两个极值点12,x x ,且满足()()120f x f x +=,求b 的值;(3)在(2)的条件下,若()1f x x ≥-+在[)1,+∞上恒成立,求a 的取值范围.参考答案:1.C 2.B3.B4.C5.B 6.B 7.B 8.B9.CD10.BC 11.ABD 12.(],e 1∞--13.1-14.3e 3e ,9⎛⎤--∞ ⎥⎝⎦11.【详解】对于A ,当0x ≤时,1()e x f x x +=-,则111()(e e )e (1)x x x f x x x +++'=-+=-+,当1x <-时,()0f x '>,当10x -<<时,()0f x '<,所以()f x 在(),1∞--上单调递增,在()1,0-上单调递减,所以A 正确,对于B ,由选项A 可知()f x 在(),1∞--上单调递增,在()1,0-上单调递减,所以()f x 在=1x -处取得极大值,所以B 正确,对于C ,当0x >时,14141ln ,e 14()ln 41ln ,0e 4x x f x x x x ⎧-≥⎪⎪=-=⎨⎪-<<⎪⎩,当14e x ≥时,1ln 04x -≥,当140e x <<时,1ln 04x ->,所以当0x >时,()0f x ≥,因为()f x 在(),1∞--上单调递增,在()1,0-上单调递减,且当0x ≤时,()0f x ≥恒成立,综上,()f x 的值域为[0,)+∞,所以()f x 有最小值0,所以C 错误,对于D ,因为()f x 在(),1∞--上单调递增,在()1,0-上单调递减,()11f -=,(0)0f =,14141ln ,e 14()ln 41ln ,0e 4x x f x x x x ⎧-≥⎪⎪=-=⎨⎪-<<⎪⎩所以()f x 的大致图象如图所示由()0h x =,得()()2[]240f x af x -+=,令()f x t =,则2240t at -+=,由()f x 的图象可知,要使()h x 有6个零点,则方程2240t at -+=有两个不相等的实数根12,t t ,不妨令12t t <,若120,01t t =<<,则由图可知()h x 有6个零点,但202040a -⨯+≠,所以不符合题意,所以1201,1t t <<>,因为2020440a -⨯+=>,所以21240a -+<,解得52a >,即实数a 的取值范围是5,2∞⎛⎫+ ⎪⎝⎭,所以D 正确,故选:ABD 14.3e 3e ,9⎛⎤--∞ ⎝⎦【详解】由在()0,∞+上满足()2e e 0xf x ax x =--<的正整数至多有两个,即在()0,∞+上满足2e e x x a x ->的正整数至多有两个,设()2e e x xg x x -=,0x >,则()()3e 2e xx x g x x -+'=,设()()e 2e x h x x x =-+,0x >,则()()e 1e x h x x '=-+,0x >,设()()e 1e x m x x =-+,0x >,则()e 0xm x x '=>恒成立,则()m x 在()0,∞+上单调递增,即()()0e 10m x m >=->,即()0h x '>,所以()h x 在()0,∞+上单调递增,又()10h =,所以当()0,1x ∈时,()0h x <,即()0g x '<,()g x 单调递减;当()1,x ∈+∞时,()0h x >,即()0g x '>,()g x 单调递增;所以当1x =时,()g x 取最小值,又在()0,∞+上满足()2e e x x a g x x ->=的正整数至多有两个,则()3e 3e39a g -≤=,即3e 3e ,9a ⎛⎤-∈-∞ ⎥⎝⎦,故答案为:3e 3e ,9⎛⎤--∞ ⎥⎝⎦.15.(1)π3A =或2π3.(2)(333,9]+【详解】(1)解:∵m n ⊥,∴22sin 60a B b =,即22sin 6a B b =.由正弦定理得2sin sin 3A B B .∵sin 0B ≠,∴3sin 2A =,∵(0,π)A ∈,∴π3A =或2π3.(2)∵3a =,且三角形ABC 为锐角三角形,∴π3A =.∴由正弦定理得23sin sin sin 32a b cA B C====.∴23sin b B =,23sin c C =.∴)2π23sin sin 3sin sin 3b c B C B B⎤⎛⎫+=+=+- ⎪⎥⎝⎭⎦,31333sin cos sin 3sin 2222B B B B B ⎫⎫=++=+⎪⎪⎪⎪⎭⎭)331π33sin cos 32sin cos 6sin 2226B B B B B ⎛⎫⎛⎫=+=⨯+=+ ⎪ ⎪ ⎪⎝⎭⎝⎭.又∵ABC 为锐角三角形,∴π02B <<,∴2π0π32B <-<,得ππ62B <<,ππ2π363B <+<.∴3πsin()126B <+≤,336sin 66B π⎛⎫<+≤ ⎪⎝⎭,∴336b c <+≤,又∵3a =,∴3339a b c +<++≤.∴ABC 的周长的取值范围为(333,9]+.16.(1)证明见解析(2)52(3)1719【详解】(1)证明:连接1111,AC B D .由11123QC C D =,得11113QD C D =,又11113PD A D =,则有11//PQ AC ,正方体1111ABCD A B C D -中,1BB ⊥平面1111D C B A ,11AC ⊂平面1111D C B A ,得111BB A C ⊥,又正方形1111D C B A 中,1111B D AC ⊥,1111BB B D B ⋂=,111,BB B D ⊂平面11BB D D ,所以11AC ⊥平面11BB D D ,由1MB ⊂平面11BB D D ,得111AC MB ⊥.又11//PQ A C ,所以1PQ MB ⊥.(2)111D P D Q ==,22112PQ D P D Q =+=,111111,A B C B A P C Q ==,1111Rt Rt A B P C B Q ≅ ,222222*********B P B Q A P A B ==+=+=,有1113B P B Q ==1221111521322222PQB PQ S PQ PB ⎛⎫=-=-= ⎪⎝⎭,∴11115332Q PMB M PQB PQB V V S --==⨯⨯= .(3)如图所示,以D 为坐标原点,DA 所在直线为x 轴,DC 所在直线为y 轴,1DD 所在直线为z 轴建立空间直角坐标系.则(0,0,0)D ,(3,0,0)A ,(1,0,3)P ,(0,1,3)Q ,当2BM DM =时,有(1,1,0)M ,则(1,1,0)M -',(1,1,0)PQ =- ,(1,2,3)QM -'=- .(0,1,3)PM =-设()111,,m x y z = 为平面QPM '的一个法向量,∴111110230PQ m x y QM m x y z ⎧⋅=-+=⎪⎨⋅='--=⎪⎩ ,令13x =,得113,1y z ==-,可得()3,3,1m =- .设()222,,n x y z = 为平面QPM 的一个法向量,∴2222030PQ n x y PM n y z ⎧⋅=-+=⎪⎨⋅=-=⎪⎩,令23x =,得223,1y z ==,可得(3,3,1)n = .设M PQ M '--所成的角为θ∴17cos 19991991m n m n θ⋅==⋅++⨯++ .17.(1)2nn a =(2)222n nn T +=-【详解】(1)数列{}n a 满足321212222n n a a a a n -++++= ,当2n ≥时,()31212221222n n a a a a n --+++⋯+=-,两式相减可得,122nn a -=,所以2n n a =,当1n =时,1122a ==也满足上式,所以2n n a =;(2)由(1)得2n n n b =,所以231232222nn nT =++++ ,则234111*********n n n n n T +-=+++++ ,两式相减的,2311111(1)11111222112222222212n n n n n n n n n T +++-+=++++-=-=-- ,所以222n nn T +=-.18.(1)2212x y +=(2)是定值,定值为2-(1)由题意可得22222221023211c c a a b a b c-⎧=⎪-⎪⎪⎪+=⎨⎪=+⎪⎪⎪⎩,解得222211a b c ⎧=⎪=⎨⎪=⎩故椭圆C 的标准方程为2212xy +=;(2)由题意可知直线l 的斜率不为0,设直线l 的方程为()312x m y =-+,()11,A x y ,()22,B x y ,()33,M x y ,()44,N x y ,则直线DA 的方程为1122x x y y -=+.联立11222212x x y y x y -⎧=+⎪⎪⎨⎪+=⎪⎩,整理得()()22111132220x y x y y y -+-+=则2113132y y y x =-,即13132y y x =-.代入1122x x y y -=+,得()13112312322232x x x x -=+=---.同理可得()2442231,322232y y x x x ==---.因为()()()()21211213214312123232323211232232MNy y y x y x y y x x k x x x x x x -------===-----()()()21112112123332322222,y my m y my m m y y m y y m y y ⎡⎤⎡⎤⎛⎫⎛⎫--+---+ ⎪ ⎪⎢⎥⎢⎥-⎝⎭⎝⎭⎣⎦⎣⎦===---所以直线MN 的斜率为定值,且定值为2-.19.(1)1y x =-+(2)1b =-(3)[)3,2--【详解】(1)当3,1a b =-=-时,()()13ln ,10f x x x f x =--=,所以()2311f x x x '=-+,所以()11f '=-.所以曲线()y f x =在点()()1,1f 处的切线方程为1y x =-+.(2)因为()()ln ,0,b f x x a x x x =++∈+∞,所以()2221a b x ax bf x x x x +-=+-=',因为()f x 有两个极值点12,x x ,所以()f x '有两个大于0的变号零点,所以方程20x ax b +-=有两个不等正根,所以21212Δ4000a b x x b x x a ⎧=+>⎪=->⎨⎪+=->⎩,解得2400a bb a ⎧>-⎪<⎨⎪<⎩,又因为()()120f x f x +=,即有112212ln ln 0b b x a x x a x x x +++++=,整理得()()12121212ln 0x x x x a x x bx x ++++=,代入1212,x x b x x a =-+=-,可得()()ln 0aa ab b b--+-+=-,解得1b =-,又因为240a ba ⎧>-⎨<⎩,所以可得2a <-,经检验,符合题意.(3)由(2)可知1b =-且2a <-,从而()1ln f x x a x x=+-,因为()1f x x ≥-+在[)1,+∞上恒成立,令()()[)112ln 1,1,g x f x x x a x x x=+-=+--∈+∞,则有()0g x ≥在[)1,+∞上恒成立,易得()12ln1110g a =+--=,因为()2221212a x ax g x x x x ++=++=',所以()13g a '=+,令()[)()221,1,,13h x x ax x h a =++∈+∞=+,对称轴4a x =-,①当32a -≤<-时,()3130,44a h a x =+≥=-≤,所以()h x 在[)1,+∞单调递增,从而()()130h x h a ≥=+≥恒成立,所以()()20h x g x x ='≥在[)1,+∞也恒成立,所以()g x 在[)1,+∞单调递增,从而()()10g x g ≥=恒成立.②当3a <-时,()130h a =+<,所以2210x ax ++=有两个不等实根34,x x (不妨设34x x <),所以341x x <<,且当()41,x x ∈时,()0h x <,从而()()20h x g x x='<,所以()g x 在[]41,x 上单调递减,所以()()410g x g <=,与“()0g x ≥在[)1,+∞上恒成立”矛盾,综上,a 的取值范围是[)3,2--。
2015湖南省常德市一中高三月考英语试题及答案以下2015湖南省常德市一中高三月考英语试题及答案由高考频道为您精心提供,希望对您有所帮助。
常德市第一中学2015届高三上学期第五次月考英语试题PARTⅠ LISTENING COMPREHENSION (30)SECTION A (1.5×15=22.5)Direction: In this section you’ll hear 6 conversations between two speakers. For each conversation, there are several questions and each question is followed by 3 choices. Listen to the conversations carefully and then answer the questions by marking the corresponding letter (A, B or C) on the question booklet.You will hear each conversation TWICE.Conversation One1. What score did the young man get?A. An 85.B. An 82.C.An 80.2. Who got sick last night?A. The young man’s mother.B. The young man’s sister.C. The young man’s brother.Conversation Two3.Where was the woman waiting?A.In a library.B. In a restaurant.C. In a bar.4. What day is it today?A. Saturday.B. Friday.C. Sunday.Conversation Three5. What does the woman plan to do after three o’clock?A. Go shopping.B. See a movie.C. Order a pizza.6. Who is Sharon?A. The woman’s sister.B. The man’s mother.C. The woman’s daughter.Conversation Four7. Who is Guy?A.The man.B. A horse.C. The woman’s brother.8. Which part of the girl’s body is hurt?A. Her leg.B. Her head.C. Her neck.9.What’s the relationship between the speakers?A. Father and daughter.B. Teacher and student.C. Doctor rand patient.Conversation Five10. What does the man think about the sweater?A. It’s ugly.B. It’s classic.C. It’s beautiful.11. Who picked the color?A. The public.B. Clothing manufacturers(制造商).C. Fashion designers.12. What’s the woman trying to do?A. Explain the reason for the color.B. Persuade the man to buy the sweater.C. Make the man interested in fashion.Conversation Six13. When did the doctors think the uncle would die?A. Within a few years.B. Within several months.C. Within a few days.14. What did the woman do with her uncle?A. They played video games.B. She took him to his appointment.C. She brought him to the park.15. According to the woman, what has helped Uncle Jim getbetter?A.The medicine.B. Being out of the hospital.C. Laughter.SECTION B (1.5×5=7.5)Directions: In this section, you will hear a mini-talk. Listen carefully and then fill in the numbered blanks with the information you’ve got. Fill in each blank with NO MORE THAN THREE WORDS. You will hear the short passage TWICE.The School TripDestination FranceTime At the end of 16._________________Activities Eat delicious 17.______________ for breakfastWatch 18.__________________ along the Mediterranean coast Walk around Paris and visit the Eiffel TowerPlay a human 19.__________ game against a 20._______________Paris high schoolPART Ⅱ LANGUAGE KNOWLEDGE (45 marks)SECTION A (15 marks)21.When _____ with prices of goods, the quality of the goods has to be taken into consideration.A. comparedB. comparingC. to compareD. being compared22.We were delayed at the airport. Otherwise, we_______ here by lunch time.A. must beB. must have beenC. would beD. would have been23. ____once a year by fire officials, whether a school is large or small, is a regulation that must be carried out in this country.A. InspectedB. Being inspectedC. InspectingD. Havingbeen inspected24._____he misunderstood my position on the problem was obvious from his comments.A. WhichB. WhereC. ThatD. What25.______we cannot close the gulf between us, we can try to bridge it so that we may be able to walk across it.A. UnlessB. AsC. WhileD. Ifst night, Bob made a call to me, ______sorry for his absence from my wedding ceremony.A say B. saying C. said D. to have said27._______for the villagers that he gave away all his money and belongings.A.So the traveler was gratefulB. So grateful the traveler wasC.So grateful was the travelerD.Grateful was the traveler so28.It was MaYun’s persistence and innovation(创新) ______contributes to the success in his career.A. whichB. whatC. whoD. that29.The company invested 80 percent of the money in training the staff, the rest of which ____saved for other purposes.A. isB. areC. wasD. were30.Mary _______as a secretary in this company for twenty years and now she stays at home taking care of her own garden.A. has servedB. had servedC. is servingD. served31.He is really nervous. He ______back and forth all the night waiting for the results.A. has been walkingB. had walkedC. walkedD. is walking32.The fans _____the names of the band members when they appeared at the airport.A. had screamed outB. were screaming outC. would scream outD. have screamed out33.In some places, red indicates sadness, as in South Africa, _______ it is the color people wear when they mourn.A. whichB. whereC. whenD. what34.There is no doubt that _____ a goal, one needs not only knowledge but also good personalities.A. realizedB. realizingC. to realizeD. being realized35.---Please don’t make any noise.---_________. I’ll be as quiet as a mouse.A. Yes, I won’tB. No, I won’tC. No, I willD. Yes, I will.SECTION B (18 marks)Directions: Fill in each blank with the word or phrase that best fits the context.Robert Moody, 52, is an experienced police officer. Much of his work involves dealing with drugs and gang problems in the schools of his community. Knowing that many kids often __36___trouble, he decided to do something about it. So in 1991 he began to invite small groups of kids to go fishing with him on his day off.Those fun trips had a__37___impact(影响). A chance encounter in 2000 proved that. One day, while working security at a school basketball game, Moody noticed two young guys __38___. He sensed trouble between them. _39___, one of them headed toward Moody and gave him a hug. “I remember you. You took me __40___ when I was in fifth grade. That was one of the __41__days of my life.”Deeply touched by the boy’s words, Moody decided to create a foundation that _42__ teenagers to the basis of fishing incamping programs. “As a policeman, I saw where there was violence, drugs were always behind it. They have a damage __43__ on the kids,” says Moody.By turning kids on to fishing, he intended to present an alternative way of life, “When you are sitting there waiting for a __44___” he says, “you can’t help but talk to each other, and such conversation can be very deep.”“Talking about drugs helped prepare me for the peer(同龄人) pressures in high school ,”says Michelle, 17, who __45__ the first program. “And I was able to help my little brother __46___drugs”Moody faces retirement in three years, when he hopes to run the foundation full-time. “I’m living a happy life and I have a responsibility to my__47___to give back,” Moody says. “If I teach a kid to fish today, he can teach his brother to fish tomorrow.”36.A. ran into B. got over C. left behind D. looked into37.A. immediate B. damaging C. limited D. lasting38.A. quarreling B. complaining C. talking D. cheering39.A. Slowly B. Suddenly C. Finally D. Secretly 40.A. fishing B. sailing C. boating D. swimming41.A. quietest B. longest C. best D. busiest 42.A. connects B. introduces C. reduces D. commits43.A. impression B. burden C. decision D. effect 44.A. solution B. change C. bite D. surprise45.A. participated in B. worked out C. approved of D. made up46.A. misuse B. avoid C. tolerate D. test47.A. team B. school C. family D. communitySECTION C (12 marks)Directions: Complete the following passage by using one word that best fits the context.We need more men in our hospital, not as doctors, 48 _ as nurses. There are several reasons for wanting male nurses here. Men make excellent careers and are equally as good as women _49 taking care of others. In fact, many men take good care of their children, wives, parents, sisters, brothers and even 50 nieces and nephews.Another reason that men make great nurses is _51 in general, men are physically stronger than women. Also, male nurses can be a great help in keeping patients still 52 they receive painful treatment, such as when bandages covering wounds are changed. Another advantage to having male nurses is that they see things from a different angle from women, 53 allows the hospital to work better 54 if we only approach problems one way. Having a mix of male and female nurses also helps create _55_ fun atmosphere, which helps patients recover faster.PART Ⅲ READING COMPREHENSION (30 marks)Directions: Read the following three passages. Each passage is followed by several questions or unfinished statements. For each of them are four choices marked A, B, C and D. Choose the one that fits best according to the information given in the passage.AWith all the wars, fighting and sadness in the world today, it's not only necessary, but also essential to have a good sense of humor just to help us get through each and every day of our lives. Putting a smile on someone's face when you know they are feeling down in the dump, makes me feel good and warms my heart.How would you feel if you could not joke around with your wife, husband, child, co-worker, neighbor, close friends, or even just someone that you are standing in line with at your corner store? I am always saying things that make others smile or laugh, even if I don't know the person I'm joking around with. My Grandma always found humor in everything she did, even if it was the hardest job anyone could imagine. This not only relieves stress in any situation, but also is common courtesy(礼貌)to speak to others that are around you.I know of a few people that don’t have a funny bone in their bodies, as they say. Everyone around them could be rolling on the floor after hearing a great joke and they would sit there without the slightest smile on their face. They don't get the joke that makes others laugh. I am busting a gut while they just sit there, looking at me as if I were from outer space. How can people not get a really funny joke?Laughing is essential to keep your stress levels under control. Without humor we would find ourselves with a lot of psychological problems, or on a lot of medications(药物治疗) to keep us from going crazy. There is too much sadness in this present world. It drives people crazy. We all need to find a way to ignore the sadness and bring a little light into our lives. So, I believe our best medicine is to get together and tell some jokesand have some fun laughing together.56. According to the author, humor is useful in the aspect that _________.A. it makes people more confidentB. it can pick up people’s spiritsC. it can help get rid of the cruelty in the worldD. it can help people get on well with others57.From the second paragraph, we can know that __________.A. the writer is funny and politeB. family members should play tricks on each otherC. the writer’s grandma is humorousD. we should relieve stress in any situation58.The phrase “busting a gut" in the th ird paragraph can be replaced by _______.A. explaining carefullyB. speaking loudC. keeping silentD. laughing hard59.In writing the passage, the author mainly intends to _______.A. encourage people to be humorous in daily lifeB. talk about his own understanding of humorC. introduce a practical way to get through daily lifeD. convince people of the power of being optimistic about life60.What is the author’s attitude towards the present world?A. CriticalB. PositiveC. SatisfiedD. IndifferentBCountless people long to make a difference this holiday season, yet they don’t realize that opportunities to make adifference are everywhere .Here are some ideas to get you started.Organize a blanket driveIt is cold outside, but imagine how thousands of homeless people may feel without a home of their own, or even a blanket to keep them from the cold. Organize a blank drive for your local homeless, and ask around for donations!Practice random acts of kindnessI’ll never forget the time when I went to pay for my Dr. Pepper, but the server resisted, saying my bill was paid by an anonymous(匿名的) guest. It’s this random act of kindness that restores my faith in humanity. Bless someone by paying for their drink at Starbucks, or praising them! If you live somewhere where it snows, shovel your neighbour’s snow out of their driveway for them! Whether it is as simple as praise or as complex as paying the bill, you’ll never know how far your impact will reach.Say thank youJust a simple thank-you can mak e somebody’s day, especially if they feel like their work is never noticed. Cultivate (培养) a smile on their face by being sincere and grateful for all that they do.Use your talents to help the communityThe best way to show your appreciation for people is by using the talents and skills you have to bless others. For me, I love to coordinate(协调) events and write , and so my way of reaching out to the community is through writing articles and creating awareness about problems we face today. If you can bake, make some delicious cookies for people to enjoy! If you can knit, put your talents to use by making clothes for children in foster care. Any talent can be used to help the community inmeaningful ways.Wish you a happy, healthy and helpful holiday season.61.If you join a blank drive, you can _________A. keep yourself from the coldB. bring a blanket to go on a tripC. buy a home for homeless peopleD. collect donations for the homeless people62.How did the author restore his faith in humanity?A. he helps othersB. he often blessed othersC. He got help from othersD. He got praised by others63.The underlined phrase” to make somebody’s day” is to ________A. make someone feel grateful all dayB. do something unnoticed by peopleC. make someone feel good all dayD. help someone to solve problems64.What is the author’s talent?A. SewingB. WritingC. BakingD. Knitting65.Which of the following can be the best title for the passage?A. Help Others in NeedB. Make the Best of TalentC. Enjoy Your Holiday SeasonD. Make a Difference in Your Holiday SeasonCOn the island of New Zealand, there is a (蚂蚱)grasshopper-like species of insect that is found nowhere else on earth. New Zealanders have given it the nickname weta, which is a native Maori word meaning “god of bad looks”. It’s easy to see why anyone would call this insect a bad-looking bug. Most people feel disgusted at the sight of these bulky(笨重的),slow-movingcreatures.Wetas are natural creatures; they come out of their caves and holes only after dark. A giant weta can grow to over three inches long and weigh as much as 1.5 ounces. Giant wetas can hop up to two feet at a time. Some of them live in trees, and others live in caves. They are very long-lived for insects, and some adult wetas can live as long as two years. Just like their cousins grasshoppers and crickets, wetas are able to “sing” by rubbing their leg parts together, or against their lower bodies.Most people probably don’t feel sympathy for these endangered creatures, but they do need protecting. The slow and clumsy wetas have been around on the island since the times of the dinosaurs, and have evolved and survived in an environment where they had no enemies until rats came to the island with European immigrants. Since rats love to hunt and eat wetas, the rat population on the island has grown into a real problem for many of the native species that are unaccustomed to its presence, and poses a serious threat to the native weta population.66.According to the passage, which of the following statements is TRUE?A.The weta is a newly discovered insect species.B.The Maoris nicknamed themselves “Wetas”.C.The Europeans brought wetas to New Zealand.D.Wetas are unpleasant to the eye.67.The strange thing about wetas is that they can produce pleasant sounds by ________.A. rubbing their body partsB. moving slowly on the groundC. hopping up to two feel at a timeD. coming out only at night68.Which of the following descriptions of wetas is accurate?A. They are quick in movement.B. They are decreasing in number.C. They are very active in the daytime.D. They have a short lifespan for insects.69.The underlined word “its” in the last paragraph is the closest in meaning to “_________”.A. The dinosau r’sB. The weta’sC. The island’sD. The rat’s70.From which of the following is the passage LEAST likely to be taken?A. A science magazine.B. A travel guide.C. A business journal.D. biology textbook.PART Ⅳ WRITIN G (45 marks)SECTION A (10 marks)Directions: Read the following passage. Complete the numbered blanks by using the information from the passage.Write NO MORE THAN THREE WORDS for each answer.The history of Mother’s Day is pretty interesting. An early form of the idea may have originated in the 17th century England as “Mothering Sunday”, on which the servants, who generally lived with their employers, were encouraged to return home and honor their mothers. A special cake, called the mothering cake, was often brought along to provide a festive touch.Mother’s Day, first suggested in 1872, is linked to the anti-war efforts of Julia Ward Howe. She hoped a day set aside to honour mothers would be a way to promote peace. In 1907 a woman by the name of Anna Ja rvis took Howe’s idea a step further and began a campaign for a nationally recognized Mother’s Day.After considerable effort, Anna Jarvis finally saw her dreamrealized. On May 9, 1914, President Woodrow Wilson made the official proclamation(宣布) that Moth er’s Day would be an annual holiday on the second Sunday in May. And so it is to this day.For those of us whose lives have been shaped and nurtured by loving moms, the day is a wonderful opportunity to say thank you. Unfortunately not everyone’s experienc e of family life evokes (唤起)gratitude. In the complicated maze of human existence, not all mother/child relationships are positive. Evoking the image of Mom for some can be an invitation down a painful memory lane.There is also the reality that not all mothering figures are actually mothers. Hundreds of thousands of children have been raised by foster moms (养母)who never had children of their own, but who gave maternal (母亲般的)love to children that needed them. Aunts and older sisters have filled this role as well.All I am saying is that it is complicated. We might wish that every family had an ideal balance of motherly and fatherly love, but that is simply not the case. There are many different ways that mothering happens. We may as well celebrate the ups and downs of our common life. For those whose childhood evokes praise and thanksgiving, let us give thanks. But for those whose childhood was marked by fear and loss, then let us offer healing.In our world, there’s no reason why all experiences of family li fe, good and bad, can’t be included.Title: 71.._____________SECTION B (10 marks)Directions: Read the following passage. Answer thequestions according to the information given in the passage.The Adventures of Huckleberry Finn by Mark Twain is one of the most famous American novels. Published in 1884, it was one of the first novels in the USA written in common, everyday language. For example, using non-standard English, Twain wrote, ‘I haven’t got any money,’ to mean ‘I do not have any money’. In th is way, Twain made his characters very true to life.The story is told by Huckleberry Finn, called Huck for short, who runs away to escape his abusive father. At first, Huck goes to a small island in the middle of the Mississippi River. There, he finds Jim, a black slave who has run away to escape slavery. The two of them stay on the island for a few weeks and become friends, but they must leave because Huck learns that people are looking for Jim. They decide to travel on a raft on the Mississippi River to reach the Ohio River, which will take them north to a state that does not allow slavery.During their journey, Huck and Jim visit many places along the river and meet many different people. Unfortunately, most of the people they meet are not good. For instance, Huck and Jim meet a family, the Grangerfords, who have been fighting with another family, the Shepherdsons, for so many years that nobody remembers how the fight began. While Huck stays with the Grangerfords, the fighting starts again, and several members of both families are killed. Later, Huck and Jim meet the King and the Duke, two men who take control of their raft and make money by tricking people. During the confusion following one of these tricks, Huck and Jim escape with their raft.Although the people Huck and Jim meet are bad, they are also funny. Mark Twain used humor to show readers the problems of American society in the 1800s. More importantly,despite all of the bad things that happen to Huck and Jim, the novel has a happy ending for both of them. Jim gets his freedom because his owner has died and set him free in her will, and Huck learns that his father has died, so he is also safe.The Adventures of Huckleberry Finn is an adventurous and humorous story, and it teaches modern readers a lot about American society in the 1800s.81. How was The Adventures of Huckleberry Finn different from earlier novels?(No more than 8 words) (2 marks)________________________________________________________________ ____________82.What kind of people do Huck and Jim meet?(No more than 13 words) (3 marks)________________________________________________________________ ____________83.What happens to Huck and Jim in the end?(No more than 8 words) (2 marks)________________________________________________________________ _____________84.What's the main idea of the passage?(No more than 5 words) (3 marks)________________________________________________________________ ______________SECTION C (25 marks)Directions: Write an English composition according to the instructions given below in Chinese.伴随我们成长,长辈们在不经意间老去。
2025届湖南省常德市石门县第一中学高三一诊考试数学试卷注意事项:1.答卷前,考生务必将自己的姓名、准考证号填写在答题卡上。
2.回答选择题时,选出每小题答案后,用铅笔把答题卡上对应题目的答案标号涂黑,如需改动,用橡皮擦干净后,再选涂其它答案标号。
回答非选择题时,将答案写在答题卡上,写在本试卷上无效。
3.考试结束后,将本试卷和答题卡一并交回。
一、选择题:本题共12小题,每小题5分,共60分。
在每小题给出的四个选项中,只有一项是符合题目要求的。
1.在ABC ∆中,a ,b ,c 分别为角A ,B ,C 的对边,若ABC ∆的面为S ,且()22a b c =+-,则sin 4C π⎛⎫+= ⎪⎝⎭( )A .1B .2C D 2.已知定义在R 上的奇函数()f x 满足()()11f x f x +=-,且当[]0,1x ∈时,()2xf x m =-,则()2019f =( ) A .1B .-1C .2D .-23.设x ∈R ,则“|1|2x -< “是“2x x <”的( ) A .充分而不必要条件 B .必要而不充分条件 C .充要条件D .既不充分也不必条件4.若5(1)(1)ax x ++的展开式中23,x x 的系数之和为10-,则实数a 的值为( ) A .3-B .2-C .1-D .15.函数()2f x ax =-与()xg x e =的图象上存在关于直线y x =对称的点,则a 的取值范围是( ) A .,4e ⎛⎤-∞ ⎥⎝⎦B .,2e ⎛⎤-∞ ⎥⎝⎦C .(],e -∞ D .(2,e ⎤-∞⎦6.如图是国家统计局于2020年1月9日发布的2018年12月到2019年12月全国居民消费价格的涨跌幅情况折线图.(注:同比是指本期与同期作对比;环比是指本期与上期作对比.如:2019年2月与2018年2月相比较称同比,2019年2月与2019年1月相比较称环比)根据该折线图,下列结论错误的是( )A .2019年12月份,全国居民消费价格环比持平B .2018年12月至2019年12月全国居民消费价格环比均上涨C .2018年12月至2019年12月全国居民消费价格同比均上涨D .2018年11月的全国居民消费价格高于2017年12月的全国居民消费价格7.三棱锥S ABC -的各个顶点都在求O 的表面上,且ABC ∆是等边三角形,SA ⊥底面ABC ,4SA =,6AB =,若点D 在线段SA 上,且2AD SD =,则过点D 的平面截球O 所得截面的最小面积为( ) A .3πB .4πC .8πD .13π8.设集合{}2A x x a =-<<,{}0,2,4B =,若集合A B 中有且仅有2个元素,则实数a 的取值范围为A .()0,2B .(]2,4C .[)4,+∞D .(),0-∞9.在正方体1111ABCD A B C D -中,点E ,F ,G 分别为棱11A D ,1D D ,11A B 的中点,给出下列命题:①1AC EG ⊥;②//GC ED ;③1B F ⊥平面1BGC ;④EF 和1BB 成角为4π.正确命题的个数是( ) A .0B .1C .2D .310.曲线(2)xy ax e =+在点(0,2)处的切线方程为2y x b =-+,则ab =( ) A .4-B .8-C .4D .811.某校团委对“学生性别与中学生追星是否有关”作了一次调查,利用22⨯列联表,由计算得27.218K ≈,参照下表:20()P K k ≥0.01 0.05 0.025 0.010 0.005 0.0010k2.7063.841 5.024 6.635 7.879 10.828得到正确结论是( )A .有99%以上的把握认为“学生性别与中学生追星无关”B .有99%以上的把握认为“学生性别与中学生追星有关”C .在犯错误的概率不超过0.5%的前提下,认为“学生性别与中学生追星无关”D .在犯错误的概率不超过0.5%的前提下,认为“学生性别与中学生追星有关” 12.已知在ABC ∆中,角,,A B C 的对边分别为,,a b c ,若函数()3222111()324f x x bx a c ac x =+++-存在极值,则角B 的取值范围是( ) A .0,3π⎛⎫⎪⎝⎭B .,63ππ⎛⎫⎪⎝⎭ C .,3π⎛⎫π⎪⎝⎭D .,6π⎛⎫π⎪⎝⎭二、填空题:本题共4小题,每小题5分,共20分。
2015-2016学年度第一学期武山一中高一第一次月考卷英语试卷命题人:王映平第I卷(选择题)一、阅读理解(30分)第一节:阅读下面短文,掌握其大意,然后从各题所给的四个选项(A、B、C和D)中,选出最佳选项。
(共15小题;每小题2分,共30分)AEddie liked music very much when he was at school, but when he went to the university he decided to study medicine instead of music. When he passed his examinations and became a doctor, he had to work in a hospital for some time. There he discovered that a lot of patients were happier and caused less trouble if pleasant music was played to them When Eddie got an office and began to work for himself, he decided to keep his patients happy by having a tape recorder in his waiting-room play beautiful music for them.But soon after the tape recorder had been put in, Eddie‟s nurse heard a wo man, who was sitting in the crowded waiting-room one morning, complained, “Here we‟re all waiting to see the doctor, and he‟s just playing the violin in his office instead of doing his work.”1.Eddie became a student of medicine at university__________.A.because he had lost interest in musicB.because he thought medicine was more important than musicC.to find out new use of music in hospitalD.for reasons unknown from this passage2.Why did Eddie put a tape recorder in his office?A.He wanted to help patients waiting to see him pass the time easily.B.He discovered that music was of help to his patientsC.He enjoyed listening to music while he workedD.He wanted to attract more patients to his office3.From the passage we can see that__________.A.the woman thought Eddie was an unusual doctorB.the woman didn‟t understand musicC.the woman did not understand what Eddie meantD.the woman hated to be kept waitingBTwo men were sitting together in a plane. They were on a long journey. One of the men was a businessman. The other was a farmer. They sat without talking for a while, then the farmer said, “Let‟s do something to pass the time.”“What do you want to do?” the businessman asked. “We can ask each other riddles.” The farmer said, “You start.” “Let‟s make the rules first,” the businessman said. “That‟s not fair. You are a businessman with much knowledge. You know more things than I do. I am just a farmer.”“That‟s true.” The businessman said. “What do you want we should do?” “If you don‟t know the answer to a riddle, you pay me $100. And if I don‟t know the answer, I‟ll pay you $50.” The farmer said. The businessman thought about this, then he said, “OK. That‟s fair. Who will go first?”“I will,” The farmer said. “Here is my riddle. What has three legs when it walks, but only two legs when it flies?” The business man repeated the riddle, “What has three legs when it walks, but only two legs when it flies? Mm, that‟s a good one. I‟m afraid I don‟t know the answer.” He gave the farmer $100, then said, “Tell me the answer. What has three legs when it walks, but only two legs when it flies?” “I don‟t know.” The farmer said and gave him $50.4.The story happened ____________.A.on a farm B.in a shopC.before a long plane journey D.between two passengers5.What does the word “riddle” mean in this story?A.A difficult question to find the answer to.B.Something to help to make rules.C.Something to win money.D.a kind of game in doing business.6.Why did the businessman agree to give more money if he lost?A.He made much more money than the farmer.B.He thought he knew more than the farmer.C.He was interested in making riddles.D.He was better at playing riddle games.7.The farmer _________.A.enjoyed himself on his long journey.B.didn‟t want to pay even one dollarC.spent all his money on the plane ticket.D.won fifty dollars by playing the riddle gameCDoing homework not only can help children master the knowledge they have learned, but also can train their abilities of finishing the work alone, planning the time and doing the duties. But some children don‟t like to complete the work. Why? There are some reasons.Some children feel it is very difficult to do their homework, because they can‟t understand their teacher clearly, and can‟t follow their teacher‟s teaching process. Maybe there is something wrong with their intelligence.But some children‟s intelligence is normal. They are even cleverer, but they don‟t listen to the teacher carefully. It is hard for them to sit well and pay attention to anything. It needs to carry on the attention centralized(集中注意力)training to help the children.Some children love their teacher and then they like the subject. Their interest depends on the teacher who teaches them. So every teacher should be helpful and kind. It can make children love you and the subject you teach. So they can do their homeworkhappily.8.Doing homework can help children ___________.A.master the knowledge B.train their abilitiesC.lean new lessons D.Both A and B9.Some children find the homework difficult. Which reason is NOT right? A.They can‟t understand their teacher clearly.B.They can‟t follow their teacher‟s teaching process.C.The intelligence of all the students isn‟t normal.D.They don‟t listen to the teache r carefully.10.What‟s the Chinese meaning of the underlined word “intelligence”?A.作业B.智商C.思想D.方式11.According to the last paragraph, the writer thinks ________ is very important. A.a teacher B.a subjectC.attention D.homeworkDThe first day of school, our professor introduced an old lady Rose to us.“Why are you in college at such an age?” I asked her. She replied, “I always dreamed of having a college education and now I‟m getting one!” We became friends quickly. At the end of the term I invi ted Rose to make a speech to our football team. I‟ll never forget what she taught us. She said, “There are some secrets of staying young and being happy. You have to laugh and find humor every day. You must have a dream. When you lose your dreams, you will die. There is a huge difference between growing old and growing up. Anybody can grow older. That doesn‟t need any talent or ability. To grow up, you must always find the opportunity in change. Have no regrets. The people who are afraid of death are those with regrets.”At the end of the year, Rose finished her college. One week after graduation, Rose died peacefully in her sleep. We would always remember the great woman.根据短文内容,选择正确答案。
湖南师大附中2024—2025学年度高二第一学期第一次大练习物理时量:75分钟 满分:100分一、单项选择题(本题共6小题,每小题4分,共24分。
在每小题给出的四个选项中,只有一项是符合题目要求的)1. 物理公式或物理定律都有成立条件或适用范围,下列叙述中正确的是( ) A. F B IL=是磁感应强度的定义式,适用任何磁场,但电流元IL 一定要垂直磁场方向放置 B. 2Q I Rt =用来计算一段电路电流通过时产生的热量,也可以用来计算电流在这段电路做的功C. 在匀强电场中有关系式U Ed =,任何距离d 相等两点,U 一定相等D. F E q =、Q C U =、U I R=都用到了比值定义法 2. 通量是物理学中的重要概念,在物理中有着重要应用。
在研究磁场时我们定义了磁通量BS Φ=,其中B 为磁感应强度、S 为垂直磁场的面积;磁通量大小可形象表示穿过某一平面的磁感线的净条数;磁通量为标量,但有正负之分。
与之类似,在静电场中,我们定义“垂直穿过某一平面的电场线条数为通过这一平面的电通量”。
如图甲,在磁感应强度大小为B 的匀强磁场中,面积为S 的平面与垂直于B 的平面间的夹角为α,如图乙为电荷量为q 的点电荷的电场,如图丙为匀强电场,场强为E 。
则下列说法正确的是( )A. 甲图中穿过该平面的磁通量sin BS αΦ=B. 乙图中穿过以点电荷所在位置为球心的球面的电通量随着球面半径增大而减少C. 乙图中点电荷从某球面球心位置向右移动少许(仍在所研究的球面内),穿过该球面的电通量不变D. 丙图中通过一半径为R 的球面的电通量为22E R π3. 锂离子电池已被广泛地用于智能手机、智能机器人、电动自行车、电动汽车等领域,锂离子电池主要依靠锂离子(Li +)在电池内部正极和负极之间移动来工作,某款手机充电锂离子电池的标识如图所示。
下列说法正确的是( )的锂离子电池BLP565标准电压:3.8V电池容量:1900mA·h执行标准:GB/T18287-2013A. 该锂离子电池放电时,锂离子从正极运动到负极B. 该锂离子电池把化学能转化为电能的本领比电动势为1.5V 的干电池弱C. 该锂离子电池充满电后可贮存约2.6×104J 电能D. 若该锂离子电池的待机电流为15mA ,则其最长待机时间约为96h4. 苏轼的诗句“定知玉兔十分圆,已作霜风九月寒,寄语重门休上钥,夜潮留向月中看”形象地描述了八月十五日看潮的情景。
湖南省常德市石门县第一中学2015-2016学年高二下学
期第一次月考(单元检测)
生物(文)试题
一、选择题(每题3分,共60分)
1.下列生物群体中属于种群的是
A.一片森林中的全部鸟
B.一个池塘中的所有鲫鱼
C.一块草地的全部动物
D.校园中的所有植物
2.种群最基本的数量特征是
A.种群密度
B.出生率和死亡率
C.迁入率和迁出率
D.年龄组成和性别比例
3.在对某种鼠的调查中,调查范围为1公顷,第一次捕获并标志25只鼠,第二次捕获30只未标志的鼠和10只标志的鼠,则该鼠种群密度大约为
A.125只/公顷
B.100只/公顷
C.75只/公顷
D.50只/公顷
4.近年来,我国沿海城市人口密度急剧增长,造成这一现象的主要原因是
A.年龄组成呈增长型
B.性别比例适当
C.迁入率大于迁出率
D.出生率大于死亡率
5.某一种群生活在资源和空间有限的环境中时,用来描述该种群数量变化的数学模型是
A.t t N N λ0=
B.K/2
C.J 型曲线
D.S 型曲线
6.关于环境容纳量的叙述,正确的是
A.种群数量在任何时候都不可能超出环境容纳量
B.人为地一次性捕杀家鼠后,环境容纳量迅速降低
C.环境容纳量是不会改变的,不受空间和资源的限制
D.建立大熊猫自然保护区的目的是提高环境容纳量
7.在一段倒伏的树干上,生活着蘑菇、苔藓、蚂蚁等,这些生物组成了
A.种群
B.群落
C.生态系统
D.生物圈
8.在培养细菌的培养基上长出了青霉菌,细菌与青霉菌之间的关系是
A.寄生
B.互利共生
C.竞争
D.捕食
9.下列存在互利共生关系的是
A.北极熊与海豹
B.人与蚊子
C.豆科植物与根瘤菌
D.雪兔与猞猁
10.引起森林群落中植物和动物垂直分层现象的主要因素分别是
A.温度、食物
B.温度、光照
C.温度、温度
D.光照、食物
11.下列有关生态系统结构的叙述,正确的是
A.每种动物在生态系统中只能处于一个营养级
B.在生态系统的食物链中,营养级越高的生物体型越大
C.自养生物都是生产者,是生态系统的基石
D.在食物链和食物网中含有生态系统的所有生物成分
12.下图是自然界碳循环的简图,据图分析下列叙述错误的是
A.甲为分解者,乙为消费者,丙为生产者
B..①②③表示
CO通过甲、丙、乙的呼吸作用进入大气中
2
C.④表示大气中
CO进入生物群落的光合作用过程
2
D.碳元素以无机物形式在丙→乙→甲所示的渠道流动
13.环境污染已成为人类社会面临的重大威胁,各种污染数不胜数,下面名词中与环境污染有关的是
①温室效应②赤潮③酸雨④光化学污染⑤臭氧空洞⑥潮汐⑦地热
A.①②③④⑥
B.①②③④⑤
C.②③④⑤⑥⑦
D.①③④⑤⑦
14.群落演替的两种类型是
A.初生演替和再生演替
B.再生演替和次生演替
C.出生演替和后生演替
D.出生演替和次生演替
15.下图为影响种群密度因素的概念图,a、b、c、d依次代表的影响因素是
A.年龄组成、死亡率、迁出率、出生率
B.出生率、年龄组成、迁出率、死亡率
C.死亡率、出生率、迁出率、年龄组成
D.出生率、死亡率、迁出率、年龄组成
16.农业生产上常用人工合成的性引诱剂诱杀害虫的雄性个体,使之不能与雌性个体交尾,致使害虫的种群密度
A.明显下降
B.明显上升
C.保持稳定
D.越来越大
17.群落不断发展变化,按照一定的规律进行着演替。
下列关于演替的叙述正确的是
A.在森林遭受火灾后的地段上重新形成森林属于次生演替
B.在正常情况下,次生演替的最终结果使生物多样性降低
C.人类活动对群落演替的影响与自然演替的方向、速度基本相同
D.地衣→苔藓→灌木→草本→森林五个阶段为出生演替的必经过程
18.下关于生态系统中能量流动的叙述,错误的是
A.几乎所有生态系统需要的能量都来自太阳
B.生态系统中能量流动是反复循环的
C.生态系统中能量流动是逐级递减的
D.生态系统中能量流动是单向的
19.下图是某生态系统中几种生物的食物关系,相关叙述正确的是
A.草属于第一营养级
B.青蛙是初级消费者
C.蛇只属于第三营养级
D.该食物网有2条食物链
20.为了处理好经济发展与人口、资源、环境的关系,我国政府颁布了《退耕还林条例》,实施该条例有利于
A.减少物种数目
B.降低植被调节气候的能力
C.保护生物多样性
D.降低生态系统的稳定性
二、非选择题
1.(12分)回答下列有关生态方面的问题:
(1)图甲中,曲线①②③分别表示某野生动物种群数量达到环境容纳量后,其未来所发生的三种可能变化,曲线说明其种群栖息地被破坏的程度较轻,当曲线③趋近零时,对该动物种群宜采取(填“就地”或“易地”)保护的措施以防止其灭绝。
(2)当种群数量对应于d点时,其年龄组成为。
(3)跳虫、甲螨和线虫是土壤中的主要动物类群,对动植物的分解起重要作用。
请回答:由于跳虫和甲螨活动能力,身体,不适合用样方法或标志重捕法进行调查,在进行这类研究时,常用的方法进行采集、调查。
2.(16分)下列表格内数值表示某人工生态系统一年内主要营养级的能量,下图方框内表示该池塘生态系统的主要食物链,其中a表示一年内该营养级生物总能量,b表示一年内该营养级生物同化的能量,请分析回答:
(1)该池塘生态系统内食物链共有条,其中人处于营养级。
(2)一年内b的利用途径有、、。
(3)如果能量传递效率=[(第n营养级同化的能量)/(第n-1营养级同化的能量)] x 100%,则能量从第一营养级传递到第二营养级的效率是。
(4)要构成一个完整的生态系统,除图中的各种生物、太阳能及土壤等非生物的物质外,还应必不可少的生物类群是。
(5)鲈鱼味道鲜美,如果人类大量捕杀该生态系统中的鲈鱼,则摇蚊种群数量在短期内将会发生的变化是。
3.(12分)图甲是某草原生态系统中碳循环模式图,图中A、B、C、D表示生态系统的成分,
①②③为特定的生理过程,图乙表示该系统中的部分生物间的食物关系,请据图分析回答:
(1)图乙中的生物对应图甲中的(用字母表示)。
在①、③过程中碳以
形式进行循环。
(2)如要调查该生态系统中蒲公英的种群密度,通常采用法。
(3)该生态系统中每种生物在生长发育过程中不断地与其他生物进行着信息交流,其作用在于。
(4)该草原曾发生过火灾,但此后又慢慢恢复,该过程属于,从生态系统的角度分析,这体现了生态系统具有自我调节能力,这种能力的大小主要取决
于。
参考答案
1——5 BABCD 6——10DBCCD 11——15CDBDD 16——20AABAC
非选择题
1.(1)①易地(2)增长型(3)较强微小取样器取样
2.(1) 6 第四、第五、第六(2)呼吸消耗分解者利用下一个营养级(3)18.5% (4)分解者(或细菌、真菌等)(5)减少
3.(1)B、D
CO(2)样方法(3)调节种间关系,维持生态系统2
的稳定
(4)次生演替生物种类多少或物种丰富度高低(营养结构的复杂程度或食物链食物网的复杂程度)。