太和中学高二寒假生(五)
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安徽省阜阳市太和县太和中学2024-2025学年高二上学期开学英语试题一、阅读理解A Visit to Joshua Tree National Park, CaliforniaJoshua Tree National Park is nearly 800,000 acres large and surrounds parts of the Mojave and Colorado Deserts in South-central California. Although deserted at first sight, the park is full of wildlife and provides a variety of entertainment activities from hiking to climbing. Within a 3-hour drive, Joshua Tree National Park takes at least a full day to visit.Things to do·Hiking opportunities within the park include several choices, from 12 self-guided nature trails (小径) to all-day back-country hikes.·Joshua Tree National Park has nine camping grounds, and back-country camping is also allowed.·Rock-climbing is a popular activity in the park, which has 10 mountains greater than5,000 feet in height.When to visitJoshua Tree National Park is open 365 days a year, although the best time to visit is October through April, when the temperature is comfortable. The high season is when the wild flowers bloom, and summer months are the least crowded.What to bringIn addition to your camera and telescope, be sure to carry lots of water. Park and trail maps can be picked up at any of the three visitor centres.Fees·Parking fees: A single-day parking permit is for $5. You can buy a 7-day vehicle permit for$15, with each additional day for $ 3.·Camping fees: They vary by camping ground.1.Which activity might visitors experience in the park?A.Beach volleyball.B.Desert hiking.C.Visiting museums.D.Fishing.2.When is the recommended time to visit Joshua Tree National Park?A.February.B.May.C.June.D.September. 3.The parking fees are at least if you go to the park by car for 8 days.A.$5B.$15C.$18D.$ 20Finnish Lapland, in the far north of Europe, is home to some 180,000 people and around 200,000 reindeer (驯鹿). The animals live wild but each one has an owner, identified by a mark on its ear. Anne Ollila, 50, one of 4,000 such owners, works in the Finnish part of this region with her husband and two adult sons and their families. They farm the animals mainly for meat, but reindeer tourism has also become an important source of income.Ollila lives 80 kilometres inside the Arctic Circle, an hour from Lapland’s capital city, Rovaniemi, and seven kilometres from her nearest neighbour. Summer days — when the reindeer raisers earmark newborn reindeer — are long and in June the sun never sets. At that time Ollila sleeps during the day and walks up to 20 kilometres a night through the forest, making the most of the cooler temperatures to do her work but having to endure large groups of insects along the way.In deepest winter, there is little daylight. Many grasslands are frozen and the reindeer move into the forest for protection against wolves and golden eagles — the birds can kill an adult reindeer.Ollila and her family offer tourists reindeer experiences through their company Reindeer Journey. Visitors can get close to the animals in the wild or at their farm, watching them being trained to pull sledges (雪橇) or take a sleigh ride.“Reindeer are very smart animals,” Ollila says. “They have different personalities, and some are very funny.” One of her favourites is Rocky, named after the movie boxing legend. “He’s very curious and always in trouble,” she says. “He once got himself stuck in tree branches and had to be lifted out, and he has been known to walk off with his owners’ drying underwear.”Ollila gave up her job as a sociology researcher at the University of Lapland in 2010 to devote herself to raising reindeer. “I love the environment, the animals and the freedom,” she says. “Also, I have a sense of belonging to something bigger than me, to a way of life through the generations.”4.What does the underlined word “endure” in paragraph 2 mean?A.Go away with.B.Catch up with.C.Look forward to.D.Put up with.5.Why do the reindeer move into the forest in winter according to the text?A.To get earmarked.B.To find their owners.C.To protect themselves.D.To avoid cold temperatures.6.What does Ollila think of Rocky?A.He is foolish.B.He is a troublemaker.C.He is interested in planting trees.D.He is a famous filmmaker.7.What can we infer about Ollila from the last paragraph?A.She has a deep affection for nature.B.She has long been tired of raising reindeer.C.She has been a sociology researcher since 2010.D.She had no chance to receive a college education.Over the years, movies and books have used tornadoes to sweep their characters off to magical lands, to destroy entire cities, or to defeat a superhero’s dangerous super villain (恶棍). All of these tornadoes have one thing in common: They are incredibly powerful. They can have wind speeds over 300 miles per hour (mph), grow over a mile wide, and travel over 50 miles. They are incredibly dangerous and should be avoided at all costs.Scientists can’t go inside tornadoes, which means that they are extremely hard to research. As a result, we know surprisingly little about them. In order to tell how powerful a tornado is, scientists look at how much destruction it causes. Scientists then rank the tornado on the Enhanced Fujita Scale (级别) (EF-Scale), which ranges from EF0 to EF5. For example, a tornado that only damages trees but doesn’t significantly damage buildings would be rated EFO with wind speeds between 65 and 85 mph. A tornado that blows away buildings and tears up sidewalks, on the other hand, would be rated EF5 with wind speeds over 200 mph.The most powerful tornado in United States history occurred near Oklahoma City in1999. It had wind speeds over 310 mph, the highest wind speed ever recorded on Earth. A tornado with wind speeds that high can not only pick up and throw automobiles, but also knock over trains andtear up roadways.Luckily for anyone living in an area that experiences the occasional tornadoes, they usually only last one to ten minutes. More powerful tornadoes can last over an hour in the right conditions, but they are very rare.If you find yourself experiencing a tornado, find a safe place inside, like an interior hall, basement or closet. Stay away from windows and heavy objects that could fall on you, and lie on your stomach with your hands protecting the back of your head. Having a tornado emergency plan is extremely important as tornadoes can appear very quickly. Make sure to listen to the radio or television to stay updated on serious weather patterns in your area.8.Which of the following is probably the wind speed of an EF4 tornado?A.65 mph.B.85 mph.C.200 mph.D.310 mph.9.What can we learn from the example given in paragraph 3?A.Tornadoes can do great harm.B.American cars need developing.C.Oklahoma City had no trains in 1999.D.The strongest tornado occurred in the UK. 10.What is the last paragraph mainly about?A.What a tornado is.B.How a tornado forms.C.Tips to survive a tornado.D.How to recognize a tornado.11.Where is the text most probably taken from?A.A guidebook to the USA.B.An introduction to a historical book.C.A review of famous movies.D.An article on natural disasters.When Adele released (发行) her 2011 single Someone Like You, this bittersweet song is popular with millions worldwide. More than a decade later, it remains one of her most popular songs. Her artistry, as well as that of many others who have mastered the art of making listeners feel moved with slow and emotional beats, has a way of managing the emotional pain of heartbreak and loss.Listening to favorite songs could also reduce people’s feelings of pain, according to a new study published in the journal Frontiers in Pain Research. And the most effective pain relievers were found to be sad songs detailing bittersweet and emotional experiences.“It doesn’t take the place of medicine when you have a headache, but music can help reduceyour pain,” said Patrick Stroman, a professor at Queen’s University in Kingston, Ontario. He didn’t join in the study. “Unlike other medications,” he noted, “there is no side effect or risk in listening to music (just keep the volume at a reasonable level).”The small study invited 63 young adults to bring one of their favorite songs. The researchers also had the young adults pick one of seven songs that the team considered relaxing and were unfamiliar to the study participants. All the while, the researchers stuck a hot object — similar to the pain of a boiling hot teacup on the participants’ skin — to their left inner forearms. When rating their experiences, people were more likely to report feeling less pain when listening to their favorite songs compared with hearing the unfamiliar relaxing songs.With millions of songs available, one person’s favorite song is likely not the same as another. After interviewing the participants about the song they brought and their rating of pain, the researchers found people who listened to bittersweet and moving songs felt less pain than when they listened to songs with calming or cheerful themes (主题).“It’s a very cool result,” said lead study author Darius Valevicius, a doctoral student of neurosciences at the University of Montreal. “I think it’s why I myself and probably many people choose to listen to bittersweet or even spiritual music.”12.Why does the author mention Adele in the first paragraph?A.To reach a conclusion.B.To lead in the topic.C.To offer a suggestion.D.To provide the background.13.What is Stroman’s attitude to the effect of listening to music?A.Doubtful.B.Positive.C.Unclear.D.Unconcerned. 14.What did the participants do in the new study?A.They reported their feelings of pain.B.They interviewed many musicians.C.They made various kinds of teacups.D.They picked out the music they don't like. 15.Which is the most suitable title for the text?A.When Is the Best Time to Listen to Music?B.How Do You Create Popular Songs Quickly?C.The Best Way to Reduce Pain Might Be to Write MusicD.Certain Types of Music Could Help You Feel Less PainIt’s easy to let things slide in midlife. But our 40s to 60s is actually the best time to increase activity levels. Indeed, a study found that people aged 40 — 61, who increased their fitness routine with activities such as walking and cycling, to a few hours a week, were 16. To 43 per cent less likely to die from cancer and heart disease. Therefore, exercise is necessary for this group of people. 16 .·Walk fasterThe best way to get fit is also the easiest: head out for a quick walk. 17 . “You’ll have more energy and be much less likely to need the doctor,” says Professor Tom Yates.·Play racquet (球拍) sports18 . People playing tennis or badminton for at least two and a half hours a week had a16 per cent lower risk of dying from any cause. 19 , including swimming, cycling and walking. The researchers say this is because racquets sports work all your body’s muscles at once and require good hand-eye coordination (协调) while running around the court strengthens your heart and lungs.· 20We tend to forget about our balance until we lose it but research shows that practising balance skills improves our fitness, strengthens brain health and leads to a longer life. In a 12-year study of 1,702 people, the ability to stand for 10 seconds was associated with longevity and health. Or simply practise standing on one leg. If you can manage 10 seconds, your balance is good. A.Balance on one legB.Keep a balanced dietC.Here are the tips for midlife fitnessD.We ought to move more and sit lessE.Tennis or badminton offers more health benefits than other sportsF.Fast-paced walkers live longer and are less likely to get heart diseaseG.If you want to stay sharp and lively into old age, take up tennis or badminton二、完形填空Granny Basketball is more competitive than you’d think! Just ask the women over 50 who21 in the 18th annual Granny National Basketball Championships last weekend. Hosted in Decorah, Iowa, the event 22 teams from across the country. Players might 23 different walks of life, but they all have one thing 24 : They’re members of the Granny Basketball League (联盟).Founded by Barb McPherson Trammell, this organization offers 25 women an unbelievable opportunity to stay 26 , make friends and relieve stress. Grannies play by a (n) 27 set of rules to make up for any 28 mobility. According to their website, it’s “a game for 29 of a certain age.” Regulations include a strict “no running” policy, instead 30 players to speed walk. Jumping is not 31 , either.32 , there are 42 Granny Basketball teams in the United States. National Championships have been held for the 33 every year since 2008. Grannies have also been 34 to compete against teams outside their league for charity, including men’s and women’s teams of all ages. Of course, the changed 35 apply to their competitors as well.“I think we’re redefining (重新定义) what old is,” said one player.21.A.talked B.lied C.believed D.played 22.A.improved B.saved C.attracted D.tracked 23.A.come from B.give up C.adapt to D.search for 24.A.in hurry B.in print C.in need D.in common 25.A.young B.senior C.gifted D.disabled 26.A.fit B.calm C.awake D.quiet 27.A.impossible B.unnecessary C.different D.difficult 28.A.shared B.limited C.social D.great 29.A.women B.men C.girls D.boys 30.A.teaching B.helping C.persuading D.encouraging 31.A.recognized B.allowed C.praised D.compared 32.A.Immediately B.Unlikely C.Currently D.Unfortunately 33.A.job B.future C.record D.sport 34.A.reminded B.refused C.known D.warned 35.A.orders B.rules C.values D.messages三、语法填空阅读下面短文,在空白处填入1个适当的单词或括号内单词的正确形式。
安徽省阜阳市太和中学2019-2020i学年高二下学期5月月考理科化学试题一、单选题(★★★) 1. 下列分子或离子中,不存在sp 3杂化类型的是:A.H2O2B.NH3C.C2H6D.SO2(★★) 2. 下列原子的价电子排布中,对应元素第一电离能最大的是()A.3s23p1B.3s23p2C.3s23p3D.3s23p4(★★★) 3. 某元素原子的质量数为84,原子核内的中子数为48,它的N能层上的电子数为A.32B.18C.8D.6(★★★) 4. 某元素的外围电子构型是3d 64s 2,下列对该元素的说法中错误的是A.位于周期表中第四周期Ⅷ族B.只有2个价电子C.+3价离子比+2价离子的氧化性强D.其单质常温下难溶于浓硝酸(★★) 5. 若将15P原子的电子排布式写成1s 22s 22p 63s 23p x23p y1,它违背了A.能量最低原则B.泡利不相容原理C.洪特规则D.能量守恒原理(★★★) 6. 下列说法中不正确的是A.σ键比π键的电子云重叠程度大,形成的共价键强B.s-sσ键与s-pσ键的电子云形状对称性相同C.丙烯(CH3—CH=CH2)分子有8个σ键,1个π键,其中碳原子分别是sp2、sp3杂化D.N2分子中有一个σ键,2个π键;NH4+中4个N-H键的键能不相同(★★★) 7. 已知磷酸分子中的三个氢原子都可以跟重水分子(D 2O)中的D原子发生氢交换,又知次磷酸(H 3PO 2)也可跟D 2O进行氢交换,但次磷酸钠(NaH 2PO 2)却不再能跟D 2O发生氢交换,由此可推断出H 3PO 2的分子结构是A.B.C.D.(★★) 8. 下列有关化学用语错误的是A.H2O电子式为:B.某元素原子(R)的轨道排布式:C.Ca2+离子基态电子排布式为:1s22s22p63s23p6D.钾(K)原子的原子结构示意图为:(★★★) 9. 下列说法中正确的是A.所有元素中钠的第一电离能最小B.铝的第一电离能比镁的第一电离能大C.在所有元素中,氟的第一电离能和电负性值都是最大D.氮、氧、氟的原子半径小,电负性值大,与氢形成的共价键极性强,容易形成氢键(★★★) 10. 下列描述中正确的是A.CS2为V形的极性分子B.ClO3-的空间构型为平面三角形C.SF6中S原子和氟原子均满足最外层8电子稳定结构D.SiF4和SO32-的中心原子均为sp3杂化,SiF4分子呈空间正四面体,SO32-呈三角锥形(★★) 11. 已知元素的原子外围电子排布式为,则元素的原子序数为( )A.9B.10C.17D.18(★★★) 12. 下列说法正确的是A.向盛有硫酸铜溶液的试管里加入过量氨水,将得到深蓝色的[Cu(NH3)4]SO4·H2O沉淀B.CH4分子中的sp3杂化轨道是由4个H原子的1s轨道和C原子的2p轨道混合起来而形成的C.杂化轨道只用于形成σ键或用于容纳未参与成键的孤电子对D.凡AB3型的共价化合物,其中心原子A均采用sp3杂化轨道成键,其立体构形都是正四面体(★★★) 13. 下列分子中的中心原子杂化轨道的类型相同的是()A.SO3与SO2B.BF3与NH3C.BeCl2与SCl2D.H2O与SO2(★★) 14. 某主族元素的原子,M层上有一个半充满的能级,这种原子的质子数是()A.只能是7B.只能是15C.是11或15D.是11或13(★★★) 15. 短周期元素X的原子最外电子层中具有最多的未成对电子,元素Y的价电子排布式为 ns n np n+2,则X、Y组成的微粒中,不可能存在的是A.X2Y5B.XY42-C.XY2-D.XY3-(★★) 16. 下列各组分子中,都属于含极性键的非极性分子的是A.CS2、H2S B.BF3、CH4C.C60、C2H4D.NH3、HCl(★★★) 17. 向盛有硫酸铜水溶液的试管里加入氨水,首先形成难溶物,继续添加氨水,难溶物溶解得到深蓝色的透明溶液。
安徽省阜阳市太和中学高二数学文月考试题含解析一、选择题:本大题共10小题,每小题5分,共50分。
在每小题给出的四个选项中,只有是一个符合题目要求的1. 在空间四边形OABC中,OM=2MA,点N为BC中点,则等于A 、B 、C 、D 、参考答案:A略2. 在棱长为2的正四面体ABCD中,E,F分别是BC,AD的中点,则=()A.0 B.﹣2 C.2 D.﹣3参考答案:D【考点】平面向量数量积的运算.【分析】根据题意画出图形,结合图形,利用中线的性质表示出向量与,求出它们的数量积即可.【解答】解:如图所示,棱长为2的正四面体ABCD中,E,F分别是BC,AD的中点,则=(+)?(+)=(?+?+?+?)=(2×2×cos120°+2×2×2×cos90°+2×2×2×cos180°+2×2×cos120°)=﹣3.故选:D.3. 执行如图所示的程序框图,则输出的值为(A)256 (B)512 (C)1024 (D)1048576参考答案:C4. 已知函数的导函数为,且满足,则()A. B. C. D.无法确定参考答案:C略5. 对任意实数,圆C:与直线的位置关系是()A.相交B.相切 C.相离 D.与取值有关参考答案:A6. 下列命题中:①若向量a,b共线,则向量a,b所在的直线平行;②若向量a,b所在的直线为异面直线,则向量a,b一定不共面;③若三个向量a,b,c两两共面,则向量a,b,c共面;④已知空间的三个向量a,b,c,则对于空间的任意一个向量p总存在实数x,y,z使得p =x a+y b+z c.其中正确命题的个数是()A.0 B.1 C.2 D.3参考答案:A略7. 若函数,则A.1B.C.D.4参考答案:B略8. 已知抛物线与直线相交于A、B两点,其中A点的坐标是(1,2)。
安徽省太和中学2019—2020学年高二数学下学期期末考试试题 理考生注意:1.本试卷分选择题和非选择题两部分。
满分150分,考试时间120分钟.2.答题前,考生务必用直径0。
5毫米黑色墨水签字笔将密封线内项目填写清楚.3.考生作答时,请将答案答在答题卡上。
选择题每小题选出答案后,用2B 铅笔把答题卡上对应题目的答案标号涂黑;非选择题请用直径0.5毫米黑色墨水签字笔在答题卡上各题的答题区域内作答,超出答题区域书写的答案无效.............,.在试题卷、草稿纸上作..........答无效...。
4.本卷命题范围:高考范围。
一、选择题:本题共12小题.在每小题给出的四个选项中,只有一项是符合题目要求的。
1.复数()226i1i z +=-的虚部为( )A .iB .i -C .1-D .12.已知集合{}113A x x =-<+<,()12log 1B x y x ⎧⎫⎪⎪==+⎨⎬⎪⎪⎩⎭,则A B ⋂=( )A .()1,-+∞B .()2,1--C .()1,2-D .()2,2-3.已知双曲线()222210,0x y a b a b -=>>的一条渐近线经过点,则该双曲线的离心率为( )A .2 BC .3D 4.某机构对青年观众是否喜欢跨年晚会进行了调查,人数如下表所示:不喜欢喜欢 男性青年观众 30 10 女性青年观众3050现要在所有参与调查的人中用分层抽样的方法抽取n 人做进一步的调研,若在“不喜欢的男性青年观众”的人中抽取了6人,则n =( )A .12B .16C .24D .325.若某程序框图如图所示,则该程序运行后输出的B 等于( ) A .4 B .40 C .13 D .416.已知平面向量a ,b 满足()1236a b a -⋅=,且13a =,12b =,则向量a 与b夹角的余弦值为( )A .1B .12-C .12D .147.某几何体的三视图如图所示,则该几何体的体积为( )A 3B 3C .334D 438.函数()()sin 0,0,22f x A x A ππωϕωϕ⎛⎫=+>>-<< ⎪⎝⎭的部分图象如图所示,则当,122x ππ⎡⎤∈⎢⎥⎣⎦时,()f x 的值域是( )A .1,12⎡⎤-⎢⎥⎣⎦B .3,12⎡⎤-⎢⎥⎣⎦C .13,22⎡⎤-⎢⎥⎣⎦D .33,22⎡⎤-⎢⎥⎣⎦9.函数()2e e 2x xf x x x --=+-的部分图象大致是( )A .B .C .D .10.在ABC△中,角A,B,C的对边分别为a,b,c ,若1b =,()2sin 33cos a B C c A =,点G 是ABC △的重心,13AG =,则ABC △的面积为( )A 3B 333C 323D 3 11.已知四棱锥S ABCD -,SA ⊥平面ABCD ,AB BC ⊥,BCD DAB π∠+∠=,2SA =,BC =二面角S BC A --的大小为3π.若四面体SACD 的四个顶点都在同一球面上,则该球的表面积为( ) A. B .4π C .8π D .16π12.已知函数()e e xx f x -=-,若对任意的()0,x ∈+∞,()f x mx >恒成立,则m 的取值范围为( )A .(],2-∞B .(],1-∞C .(),2-∞D .(),1-∞ 二、填空题:本题共4小题。
安徽省阜阳市太和县实验中学高二生物联考试卷含解析一、选择题(本题共40小题,每小题1.5分。
在每小题给出的四个选项中,只有一项是符合题目要求的。
)1. 某种哺乳动物的直毛(B)对卷毛(b)为显性,黑色(C)对白色(c)为显性(这两对基因分别位于不同对的同源染色体上)。
基因型为BbCc的个体与“个体X”交配,子代的表现型有:直毛黑色、卷毛黑色、直毛白色、卷毛白色,它们之间的比为3∶3∶1∶1。
“个体X”的基因型为()A.BbCc B.Bbcc C.bbCc D .bbCC参考答案:C2. 组成蛋白质分子的约20种氨基酸在结构上不同主要是因为:()A、碱基的数量不同B、羧基的数量不同C、氨基的位置不同D、R基不同参考答案:D3. 如图是作用于人体组织细胞新陈代谢的四大系统模式图,图中1、2、3、4分别是()A.消化系统、循环系统、泌尿系统、呼吸系统B.循环系统、呼吸系统、泌尿系统、消化系统C.呼吸系统、泌尿系统、循环系统、消化系统D.消化系统、循环系统、呼吸系统、泌尿系统参考答案:A【考点】稳态的生理意义.【分析】人体内环境稳态调节的四大系统是呼吸系统、消化系统、循环系统和泌尿系统.【解答】解:呼吸系统可吸入氧气呼出二氧化碳,所以4是呼吸系统;泌尿系统可排出组织细胞产生的代谢废物,所以3是泌尿系统;循环系统与另三大系统相联系,故2是循环系统;消化系统消化吸收的营养物质进入循环系统,所以1是消化系统.故选:A.4. 下图表示某生态系统中甲、乙两种群在一段时间内数量变化情况。
下列有关叙述正确的是()A.该生态系统的能量流动由乙流向甲B.M时甲种群的年龄结构呈增长型C.若在M时乙的出生率小于死亡率D.两个种群数量波动一定程度上体现了生态系统的负反馈调节参考答案:D略5. 右图表示环境条件发生变化后某个种群中A和a基因频率的变化情况,下列说法错误的是 ( )A.环境条件发生变化后,使生物产生适应性的变异B.P点时两曲线相交,此时A和a的基因频率均为50%C.Q点表示环境发生了变化,A控制的性状更加适应环境D.基因频率是指在一个种群基因库中,某个基因占全部等位基因的比率参考答案:A6. 镰刀型细胞贫血症是一种人类遗传病,下图为该病病因的图解。
太和中学2014级高二上学期第一次月考化学本试卷分选择题和非选择题两部分,共9页,共100分,考试工夫90分钟。
可能用到的原子量:H:1 C:12 N:14 O:16 Na:23 S:32 Cl:35.5 K:39 Fe:56 Cu:64第Ⅰ卷(选择题共50分)一、选择题(本题包括25个小题,每小题2分,共50分。
每小题只需一个选项符合题意。
)1.为了减少大气净化,许多城市推行汽车运用清洁燃料。
目前运用的清洁燃料次要有两类:一类是紧缩自然气(CNG),另一类是液化石油气(LPG)。
这两类燃料的次要成分是( )A.碳水化合物 B.碳氢化合物 C.氢气D.醇类2.以下物资中,不属于高分子化合物的是( )A.酶 B.自然橡胶 C.淀粉 D.硬脂酸甘油酯3.以下球棍模型表示的各烷烃分子中,一氯代物只需一种的是( )4.以下说法正确的是( )A.乙烯和乙烷都能发生加聚反应 B.蛋白质水解的毕竟产物是多肽C.米酒变酸的过程触及了氧化反应 D.石油裂解和油脂皂化都是由高分子生成小分子的过程5.将等体积的苯、汽油和水在试管中充分混合后静置。
以下图示景象正确的是( )6.关于生活中的无机物,以下说法不正确的是( )A.葡萄糖可以发生氧化反应和水解反应B.工业上利用油脂在碱性条件下的水解反应制取肥皂和甘油C.食用植物油的次要成分是高级不饱和脂肪酸甘油酯,是人体的营养物资D.皮肤接触浓硝酸变黄是蛋白质的颜色反应7.制取最合理的方法是( )A.CH3CH3与Cl2取代 B.CH2===CH2与HCl加成C.CH2===CH2与Cl2加成 D.CH3CH2Cl与Cl2取代8.以下无机物的一氯取代物的同分异构体有3种的是( )①CH3CH2CH2CH2CH3②(CH3)3CCH2CH3③CH(CH2CH3)3④(CH3)2C(CH2CH3)2⑤(CH3)2CH—C(CH3)3 ⑥(CH3)3C—C(CH3)3A.①②③④⑤ B.②⑥ C.①②⑥ D.④⑤⑥9.可以用来鉴别甲烷和乙烯,还可以用来除去甲烷中乙烯的操作方法的是( ) A.将混合气体经过盛有酸性KMnO4溶液的洗气瓶B.将混合气体经过盛有适当溴水的洗气瓶C.将混合气体中通入氢气,在Ni催化加热的条件下反应D.将混合气体经过盛有NaOH溶液的洗气瓶10.在CH3COOH+C2H5OH 酸△CH3COOC2H5+H2O的平衡体系中,加入必然量的C2H185OH,当重新达到平衡时,18O原子还应存在于( )A.乙酸乙酯中 B.乙酸中 C.水中 D.乙酸、乙酸乙酯和水中11.以下说法正确的是( )A.日常生活中无水乙醇常用于杀菌消毒 B.用乙醇作萃取剂可以将碘从碘水中萃取出来C.乙醇、乙烷和苯都可以与钠反应生成氢气 D.乙醇是一种可再生能源12.以下关于油脂的叙说不正确的是 ( )A.利用油脂在碱性条件下的水解反应,可以消费甘油和肥皂B.油脂在小肠内受酶的催化作用而水解,生成的高级脂肪酸和甘油作为人体营养成分为肠壁所吸收,同时提供人体活动所需求的能量C.油脂中的碳链为碳碳单键时,次要是高沸点的动物脂肪D.油脂是人体所需的基本营养物资之一,应尽量多食用油脂类物资13.常温下能溶于水,必然条件下又能与水反应的是( )A.乙酸乙酯 B.麦芽糖 C.葡萄糖 D.纤维素14.以下关于高分子化合物的叙说正确的是( )A.高分子化合物结构复杂,绝对分子质量很大B.对于一块高分子材料来说,n是一个整数,因而它的绝对分子质量是确定的C.高分子化合物是纯净物D.高分子材料可分为自然高分子材料和合成高分子材料15.以下说法中,错误的是 ( )A.不管乙烯与Br2的加成,还是乙烯使酸性KMnO4溶液褪色,都与分子内含有碳碳双键有关B.用溴的四氯化碳溶液或酸性KMnO4溶液都可以鉴别乙烯和乙烷C.相反质量的乙烯和甲烷完全燃烧后产生的水的质量相反D.乙烯的化学性质比乙烷的化学性质活泼16.以下与无机物结构、性质相关的叙说错误的是( )A.乙酸分子中含有羧基,可与NaHCO3溶液反应生成CO2B.蛋白质和油脂都属于高分子化合物,必然条件下都能水解C.甲烷和氯气反应生成一氯甲烷与苯和硝酸反应生成硝基苯的反应类型相反D.苯不能使溴的四氯化碳溶液褪色,阐明苯分子中没有与乙烯分子中类似的碳碳双键17.以下实验理想可以用同一反应原理解释的是( )A.活性炭、氯气都能使品红溶液褪色B.苯、乙醇、纤维素都能与浓硝酸反应C.乙烯、氯乙烯都能使溴水褪色D.淀粉、蛋白质都能发生显色(或颜色)反应18.用石灰水保存鲜蛋是一种化学保鲜法,石灰水能保存鲜蛋的原理是( )①石灰水具有强碱性,杀菌能力强②Ca(OH)2能与鲜蛋呼出的CO2反应,生成CaCO3薄膜,起保护作用③石灰水是电解质溶液,能使蛋白质凝聚④石灰水能浸透蛋内中和酸性物资A.①② B.③④ C.②④ D.①③19.以下有关甲苯的实验理想中,能阐明苯环对侧链性质有影响的是()A.甲苯和硝酸反应生成三硝基甲苯B.甲苯能使酸性高锰酸钾溶液褪色C.甲苯燃烧产生带浓烟的火焰D.1mol甲苯与3mol氢气发生加成反应20.以下说法正确的是( )A.特氟隆(聚四氟乙烯)的单体是氟利昂B.蛋白质是由氨基酸构成的可水解的高分子化合物,其水溶液有丁达尔景象C.聚丙烯的结构简式为:D.石英的化学式为CaSiO321.以下关于无机化合物的说法正确的是( )A.是两种不同的物资B.聚氯乙烯的单体为CH2===CHClC.乙烷和乙烯均能使酸性KMnO4溶液褪色D.1 mol乙酸与充足乙醇在浓硫酸催化下加热,可生成1 mol乙酸乙酯22.只用一种试剂就可以鉴别乙酸溶液、葡萄糖溶液、蔗糖溶液,这类试剂是( ) A.NaOH溶液 B.Cu(OH)2悬浊液 C.石蕊溶液 D.Na2CO3溶液23.从结构揣测无机物CH2===CHCOOCH3最不可能具有的性质是( )A.能发生取代反应 B.能被新制Cu(OH)2悬浊液氧化C.能发生加聚反应 D.能使溴水褪色24.对于碳原子数小于或等于6的烃,以下说法中正确的是( )A.6个碳原子构成的烃分子中,最多有5个C—C单键 B.C2H4的结构简式可表示为CH2CH2C.C3H6分子中必然含有C===C双键 D.C6H6分子中,一切原子均可能在同一平面内25.必然量的甲烷燃烧后得到产物为CO、CO2和水蒸气,此混合气体质量为49.6 g,当其缓缓经过无水CaCl2时,CaCl2增重25.2 g。
四川省遂宁市射洪县太和中学高二数学理联考试卷含解析一、选择题:本大题共10小题,每小题5分,共50分。
在每小题给出的四个选项中,只有是一个符合题目要求的1. 函数的单调递增区间是( )A. B. C. D.参考答案:D略2. 一个人打靶时连续射击两次,事件“至少有一次中靶”的互斥事件是()A.至多有一次中靶 B.两次都中靶C.只有一次中靶 D.两次都不中靶参考答案:D3. 已知点P为抛物线y2=4x上一点,设P到此抛物线的准线的距离为d1,到直线x+2y+10=0的距离为d2,则d1+d2的最小值为()A.B.C.D.参考答案:C略4. 过椭圆的一个焦点F作与椭圆长轴的夹角为arccos的直线,交椭圆于A、B两点。
若| AF | ? | BF | = 1 ?3,那么椭圆的离心率等于()(A)(B)(C)(D)参考答案:D 5. 函数在内(-1,0)有极小值,则实数a的取值范围为()A.B.(0,3) C. (-∞,3) D.(0,+∞)参考答案:A由函数的解析式可得y′=?3x2+2a,∵函数y=?x3+2ax+a在(?1,0)内有极小值,∴令y′=?3x2+2a=0,则有一根在(?1,0)内,分类讨论:a>0时,两根为,满足题意时,小根在(?1,0)内,则,即0<a<.a=0时,两根相等,均为0,f(x)在(?1,0)内无极小值.a<0时,无实根,f(x)在(?1,0)内无极小值,综合可得,实数的取值范围为.本题选择A选项.6. 函数单调递增区间是()A. B. C. D.参考答案:C略7. 设F1、F2分别是双曲线x2-=1的左、右焦点.若点P在双曲线上,且·=0,则|+|=()A.2 B. C.4 D.2参考答案:D根据已知△PF1F2是直角三角形,向量+=2,根据直角三角形斜边上的中线等于斜边的一半即可求出.·=0,则|+|=2||=||=2.8. 下列说法正确的个数为( )(1)椭圆x2+my2=1的焦点在x轴上,长轴长是短轴长的2倍,则m的值为4.(2)直线L:ax+y﹣a=0在x轴和y轴上的截距互为相反数,则a的值是﹣1(3)圆x2+y2=9的弦过点P(1,2),当弦长最短时,圆心到弦的距离为2.(4)等轴双曲线的离心率为1.A.2 B.3 C.4 D.1参考答案:A【考点】椭圆的简单性质;双曲线的简单性质.【专题】转化思想;数学模型法;圆锥曲线的定义、性质与方程.【分析】(1)由题意可得:1=,解得m,即可判断出;(2)当a=0时,y=0,不满足题意;当a≠0时,直线方程化为x+=1,则a的值是﹣1,即可判断出正误;(3)当弦长AB最短时,AB⊥OP,圆心到弦的距离d=OP,利用两点之间的距离个数即可得出.(4)等轴双曲线的离心率为.【解答】解:(1)椭圆x2+my2=1即=1的焦点在x轴上,长轴长是短轴长的2倍,1=,解得m=4,正确;(2)直线L:ax+y﹣a=0在x轴和y轴上的截距互为相反数,当a=0时,y=0,不满足题意;当a≠0时,直线方程化为x+=1,则a的值是﹣1,正确;(3)圆x2+y2=9的弦过点P(1,2),当弦长AB最短时,AB⊥OP,圆心到弦的距离d==,因此不正确.(4)等轴双曲线的离心率为,因此不正确.综上可得:正确命题的个数为2.故选:A.【点评】本题考查了圆锥曲线的标准方程及其性质,考查了推理能力与计算能力,属于中档题.9. P为双曲线右支上一点,F1,F2分别为双曲线的左右焦点,且,直线PF2交y轴于点A,则△AF1P的内切圆半径为()A.2 B.3 C.D.参考答案:A【考点】KC:双曲线的简单性质.【分析】本题先根据直角三角形内切圆半径得到边长的关系,结合双曲线定义和图形的对称性,得到本题结论.【解答】解:∵PF1⊥PF2,△APF1的内切圆半径为r,∴|PF1|+|PA|﹣|AF1|=2r,∴|PF2|+2a+|PA|﹣|AF1|=2r,∴|AF2|﹣|AF1|=2r﹣4,∵由图形的对称性知:|AF2|=|AF1|,∴r=2.故选:A.【点评】本题考查了双曲线的定义、图形的对称性,本题难度不大,属于基础题.10. 设二次函数的值域为,则的最小值为A.2 B.4C.8 D.17参考答案:B二、 填空题:本大题共7小题,每小题4分,共28分11. 点是曲线上任意一点, 则点到直线的距离的最小值是 ▲ .参考答案:略 12. 若“或”是假命题,则的取值范围是_________.参考答案:13. 已知满足不等式, 则的最大值是_______________.参考答案:14. 若不存在整数满足不等式,则实数的取值范围是___________.参考答案:略15. 下列命题中:①△ABC 中,A >B?sinA >sinB②数列{a n }的前n 项和S n =n 2﹣2n+1,则数列{a n }是等差数列.③锐角三角形的三边长分别为3,4,a ,则a 的取值范围是<a <5.④若S n =2﹣2a n ,则{a n }是等比数列 真命题的序号是 .参考答案:①③④【考点】命题的真假判断与应用.【专题】方程思想;转化思想;数学模型法;简易逻辑.【分析】①△ABC 中,利用正弦定理与三角形的边角大小关系可得:A >B?a >b?sinA >sinB ,即可判断出正误;②由S n =n 2﹣2n+1,可得a n =,即可判断出正误;③若a 是最大边,则32+42>a 2,解得a ;若4是最大边,则32+a 2>42,解得a ,即可判断出正误. ④由S n =2﹣2a n ,可得a n =,即可判断出正误.【解答】解:①△ABC 中,A >B?a >b?sinA >sinB ,正确;②数列{a n }的前n 项和S n =n 2﹣2n+1,可得a n =,因此数列{a n }不是等差数列.③锐角三角形的三边长分别为3,4,a ,若a 是最大边,则32+42>a 2,解得a <5;若4是最大边,则32+a 2>42,解得,则a 的取值范围是<a <5,正确.④若S n =2﹣2a n ,可得a n =,可知首项与公比都为,因此{a n }是等比数列,正确.真命题的序号是 ①③④.故答案为:①③④【点评】本题考查了正弦定理、数列的前n 项和公式与通项公式、三角形三边大小关系、命题真假的判定方法,考查了推理能力,属于中档题.16. 若一束光线沿着直线x -2y +5=0射到x 轴上一点,经x 轴反射后其反射线所在直线的方程是__________.参考答案:略17. 已知+=,-=,用、表示=。
安徽省阜阳市太和县太和中学2024届物理高一第二学期期末调研试题请考生注意:1.请用2B铅笔将选择题答案涂填在答题纸相应位置上,请用0.5毫米及以上黑色字迹的钢笔或签字笔将主观题的答案写在答题纸相应的答题区内。
写在试题卷、草稿纸上均无效。
2.答题前,认真阅读答题纸上的《注意事项》,按规定答题。
一、选择题(本题共12小题,每小题5分,共60分,在每小题给出的四个选项中,有的小题只有一个选项正确,有的小题有多个选项正确.全部选对的得5分,选不全的得3分,有选错的或不答的得0分)1、(本题9分)某同学在桌面上用一个小钢球和一个弹簧来探究弹簧的弹性势能.弹簧一端固定(如图所示),另一端用钢球压缩弹簧后释放,钢球被弹出后落地.他发现弹簧压缩得越多,钢球被弹出得越远,由此能得出的结论应是()A.弹性势能与形变量有关,形变量越大,弹性势能越大B.弹性势能与形变量有关,形变量越大,弹性势能越小C.弹性势能与劲度系数有关,劲度系数越大,弹性势能越大D.弹性势能与劲度系数有关,劲度系数越大,弹性势能越小2、(本题9分)如图所示,在光滑的水平面上有两个质量相同的球A和球B,A、B之间以及B球与固定点O之间分别用两段轻绳相连并以相同的角速度绕着O点做匀速圆周运动,如果OB=AB,则绳OB与绳BA的张力之比为()A.2∶1B.3∶2C.5∶3D.5∶23、(本题9分)单位制由基本单位和导出单位组成。
功是物理学中的重要物理量之一,在国际单位制中,功的单位用基本单位可表示为()A.J B.N·m C.kg·m2·s-2D.kg·m·s-14、 (本题9分)牛顿在1687年提出万有引力定律后,首次比较准确地测定引力常量的科学家是: A .开普勒B .伽利略C .卡文迪许D .牛顿5、汽车在水平路面上做匀速运动,发动机输出的功率为P ,速度为v ,当汽车上坡时( )A .如果输出的功率不变,则应减小速度B .如果输出的功率不变,则应增大速度C .如果保持速度不变,则应减小输出功率D .如果保持速度不变,则还应保持输出功率不变 6、关于功和能,下列说法正确的是( ) A .合外力对物体做功为零时,机械能一定守恒B .物体所受的力越大,位移越大,则该力对物体做功一定越多C .物体所受的合外力不为零时,动能可能不变D .在一对作用力和反作用力中,若作用力对物体做正功,则反作用力对物体一定做负功7、 (本题9分)光滑的水平面上有一辆小车处于静止状态,在力F 作用下小车开始加速,如图所示,则( )A .力F 对小车做正功B .力F 对小车做负功C .合力对小车做正功D .以上说法都不对8、 (本题9分)一个人用手把一个质量为m =1kg 的物体由静止向上提起1m ,这时物体的速度为2m/s ,则下列说法中正确的是 A .手对物体所做的功为12J B .合外力对物体所做的功为2J C .合外力对物体所做的功为12JD .物体克服重力所做的功为10J9、 (本题9分)1957年10月4日,世界上第一颗人造地球卫星在苏联发射成功.此卫星质量为83.6m kg =,每96min 绕地球飞行一圈.关于此卫星,说法正确的是( ) A .卫星运行时,速度37.910/v m s >⨯. B .卫星运行时,速度37.910/v m s <⨯ C .该卫星轨道比同步卫星轨道更高.D .该卫星周期比同步卫星周期更短.10、(本题9分)如图所示为大型电子地磅电路图,电源电动势为E,内阻为r0。
四川省遂宁市射洪县太和中学高二数学文月考试卷含解析一、选择题:本大题共10小题,每小题5分,共50分。
在每小题给出的四个选项中,只有是一个符合题目要求的1. 程序框图的算法思路源于我国古代数学名著《九章算术》中的“更相减损术”,执行该程序框图,若输入的a,b分别为14,18,则输出的a=()A.0 B.2 C.4 D.14参考答案:B【考点】程序框图.【专题】算法和程序框图.【分析】由循环结构的特点,先判断,再执行,分别计算出当前的a,b的值,即可得到结论.【解答】解:由a=14,b=18,a<b,则b变为18﹣14=4,由a>b,则a变为14﹣4=10,由a>b,则a变为10﹣4=6,由a>b,则a变为6﹣4=2,由a<b,则b变为4﹣2=2,由a=b=2,则输出的a=2.故选:B.【点评】本题考查算法和程序框图,主要考查循环结构的理解和运用,以及赋值语句的运用,属于基础题.2. 已知等差数列的前n项和为,若,则的值为( )A.B.C.D.参考答案:C略3. 小明的妈妈为小明煮了5 个粽子,其中两个腊肉馅三个豆沙馅,小明随机取出两个,事件,事件,则()A. B. C. D.参考答案:B【详解】由题意,P(A)==,P(AB)==,∴P(B|A)==,故选B.4. 如果一个三位正整数如“a1a2a3”满足a1<a2>a3,则称这样的三位数为凸数(如120,232,354等),那么所有小于700的凸数的个数为()A.44 B.86 C.112 D.214参考答案:D【考点】排列、组合的实际应用.【专题】计算题;分类讨论;数学模型法;排列组合.【分析】按照中间一个数字的情况分8类,当中间数为2时,百位数字只能选1,个位数字可以选1和0,当中间数为3时,百位数字有两种选择,个位数字有3种选择,以此类推,写出其他情况,利用加法原理得到结果.【解答】解:按照中间一个数字的情况分8类,当中间数为2时,百位数字只能选1,个位数字可以选1和0,有1×2=2种;当中间数为3时,百位数字有两种选择,个位数字有3种选择,有2×3=6种;以此类推当中间数为4时,有3×4=12种;当中间数为5时,有4×5=20种;当中间数为6时,有5×6=30种;当中间数为7时,有6×7=42种;当中间数为8时,首位只有6种选择,末尾有8种选择,故有6×8=48种,当中间数为9时,首位只有6种选择,末尾有9种选择,故有6×9=54种,根据分类计数原理知故共有2+6+12+20+30+42+48+54=214种.故选:D.【点评】数字问题是排列中的一大类问题,条件变换多样,把排列问题包含在数字问题中,解题的关键是看清题目的实质,很多题目要分类讨论,要做到不重不漏.5. 定义在R上的偶函数f(x)满足:对任意的,,有,则().A. B.C. D.参考答案:A由对任意x1,x2 [0,+∞)(x1≠x2),有<0,得f(x)在[0,+∞)上单独递减,所以,选A.点睛:利用函数性质比较两个函数值或两个自变量的大小,首先根据函数的性质构造某个函数,然后根据函数的奇偶性转化为单调区间上函数值,最后根据单调性比较大小,要注意转化在定义域内进行6. 当时,关于函数,下列叙述正确的是:()A、函数有最小值3B、函数有最大值3C、函数有最小值4D、函数有最大值4参考答案:C7. 用反证法证明命题:“若,且,则a,b,c,d中至少有一个负数”的假设为()A. a,b,c,d中至少有一个正数B. a,b,c,d全都为正数C. a,b,c,d全都为非负数D. a,b,c,d中至多有一个负数参考答案:C根据命题的否定可知,所以用反证法证明命题:“,且,则中至少有一个负数”时的假设为“全都大于等于”故选C.8. 以抛物线的焦点为圆心,3为半径的圆与直线相交的弦长为()A. B. C.D. 8参考答案:A略9. 若二项式的展开式的第四项是,而第三项的二项式系数是,则的值为()A. B. C. D.参考答案:B略10. 设是函数的导数,的图像如图所示,则的图像最有可能的是().参考答案: C 略二、 填空题:本大题共7小题,每小题4分,共28分11. 在平面直角坐标系中,直线的参数方程为(参数),圆的参数方程为(参数),则圆的圆心坐标为 ,圆心到直线的距离为参考答案:12. 椭圆上一点到焦点的距离为,是的中点,则等于___________.参考答案:4 略13. 《九章算术》“竹九节”问题:现有一根节的竹子,自上而下各节的容积成等差数列,上面节的容积共升,下面节的容积共升,则第节的容积为 升. 参考答案:14. 已知函数,___________ .参考答案:15. 已知数列为,依它的前10项的规律,则____.参考答案:略 16. 已知直线,给出下列四个命题:(1)直线的倾斜角是;(2)无论如何变化,直线不过原点;(3)无论如何变化,直线总和一个定圆相切;(4)当直线和两坐标轴都相交时,它和坐标轴围成的三角形的面积不小于1;其中正确命题的序号是 .(把你认为正确命题的序号全填上)参考答案:2,3,4略17. 已知幂函数f(x)的图象经过点,P(x 1,y 1),Q(x 2,y 2)(x 1<x 2)是函数图象上的任意不同两点,给出以下结论:①x 1f(x 1)>x 2f(x 2);②x 1f(x 1)<x 2f(x 2);③;④.其中正确结论的序号是__________.参考答案:②③三、 解答题:本大题共5小题,共72分。
太和中学高二寒假生活------哲学篇
(五)
时间40分钟满分100分日期得分
趣味哲学:
三堆火的故事
严寒的冬天里,一群人点燃了一堆火。
大火熊熊燃烧,烤得人浑身暖烘烘的,有个人想:天这么冷,我决不能离开火,不然我就会被冻死。
其他人也都这么想,于是这堆无人添柴的火不久便熄灭了,这群人全部被冻死了。
又有一群人点燃了一堆火,其中有一个人想,如果大家都只烤火不添柴,这火迟早也会熄灭,其他人也都这么想,于是大家都去捡柴,没有人烧火,都被陆续冻死在捡柴的路上,火最终因缺柴而灭。
另有一群人点燃了一堆火,这群人没有全部围着火堆取暖,也没有全部去捡柴,二是制订了轮流取暖、轮流捡柴的制度;一半人取暖,一半人捡柴。
结果火一直燃烧着,人们轮流烘烤,没有一个人被冻死。
思考:这则故事反映了什么哲理?(12分)
1.近20年来,约有7000条新词产生。
诸如外资企业、知识经济、经济特区、电子邮件、多媒体、再就业等。
从哲学上看,这一事实说明()
A.科学理论对实践具有指导作用B.意识是客观存在的反映
C.意识是人脑的机能D.理性认识依赖于感性认识
2.在创建卫生城市活动中,某小区居民全员参与共建文明小区。
居民举止与社区文明的关系体现的哲学原理是()
A.部分依赖整体B.部分影响整体
C.部分与整体相互转化D.部分与整体同等重要、不可分割3.为了维护经济社会发展全局稳定,宏观调控要根据具体情况区别对待,不搞一刀切。
这体现了()
A.事物之间存在互为因果的关系
B.意识反作用于客观事物
C.部分决定整体,整体影响部分
D.不同质的矛盾要用不同质的方法解决
4.由中部塌陷到中部崛起,关键靠中部的主动、东西部的联动、国家的推动。
这表明()
①事物发展是前进性与曲折性的统一②矛盾双方的转化是有条件的
③要坚持内外因相结合的观点④事物的质变有一个量变的过程
A.①②
B.②③
C.③④
D.①④
5.“小岗村的历史是改革开放的历史,小岗村是中国农村改革的缩影”。
从中同学们可以领悟到的哲学道理是()
A.事物发展的前途是光明的B.矛盾的普遍性寓于特殊性之中C.矛盾是事物发展的源泉D.量变达到一定程度必然引起质变6.互联网给我们提供了大量有益的信息,也带来了许多毫无价值的信息,甚至传播一些有悖于社会道德规范的东西。
这启示我们()
A.要坚持一分为二的观点分析解决问题
B.要用不同的方法解决不同的矛盾
C.要重视事物量的积累
D.要解决矛盾就要认识矛盾的特点
7.有这样一则寓言:狐狸昼伏夜出,夜间捕食,它总是希望太阳别出来。
当公鸡鸣叫时,白天就要来临了,狐狸以为是公鸡叫出来的,所以把公鸡咬死了,但太阳还是照样出来了。
这则寓言告诉我们()
A.事物的联系是偶然的、不确定的
B.人们应当尊重规律,按规律办事
C.事物的因果联系具有客观性
D.联系是客观的,但人能根据它建立新的具体的联系
8.十七大报告指出“改革开放作为一场新的伟大的革命,不可能一帆风顺,也不可能一蹴而成。
”这体现的哲理是()
①事物发展的道路是曲折的②事物发展的总趋势是向前的
③外因是事物变化发展的条件④在前进中有曲折,在曲折中前进
A. ①③④
B. ②③④
C. ①②④
D. ①②③
9.我国每年都要从进口大量动画片以满足电视播放要求。
中国动漫产业发展与欧美日等国相比,处于起步阶段,不具备竞争优势,所以国家规定电视台黄金时间要优先播放国产动画片,限制外国动画片播放。
中国的落后,也蕴藏着巨大潜力,目前,我国动漫产业发展的教育培训工作、政策保护、财政支持工作全面启动,未来前景不可限量。
当然,动漫创作不能停留在模仿别人作品的基础上,而应从中国特色出发,重在原创,使原创动漫作品具有鲜活的个性、鲜明民族文化特点。
对我国动漫产业现状、未来的分析是如何体现发展观点的?(40分)。