富县高级中学2011-2012学年度第二学期阶段性检测
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学 校班 级试 场姓 名考 号……………………………答……………………………………………………题…………………………………………线………………………富县高级中学2011—2012学年度第一学期阶段性检测高二语文试题(卷)考生注意:本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分,满分120分。
考试时间120分钟。
请将第一卷的答案填写在题后相应的答题栏内。
第Ⅰ卷(选择题 共 27分))一、 阅读下面的文字,完成1--3题(9分,每小题3分)砚铭考砚,是人们熟悉的磨墨工具,在我国已经有悠久的历史。
黄帝时代是我国从原始氏族阶段向国家形成过渡的时期,当时,已经出现私有财产,人们把自己心爱的墨海——大砚,刻上自己的名字表示拥有。
砚铭,是刻在砚底、砚头、砚盖、砚身四侧或其他空余部分的一种可长可短,亦诗亦文,不拘一格的自由文体。
古人大多把格言、诗句、警句作为砚铭,奉为自己的行为准则,并时时劝勉自己要躬身力行。
就是今人,也时闻有如此雅兴。
因此,它也是我国独有的文化现象和优秀的传统文化形式之一。
它不仅能增加砚台的艺术欣赏价值,而且还是文物评定的标准和鉴定真伪的依据,故颇受人们的喜爱和重视。
后来,随着社会的进步,砚铭也由最初简单表示所属关系的姓名,逐渐发展成为一种记事咏物、说理寄情、言志叙怀的文学形式。
《大戴礼记》所载的西周太公金匮砚铭是我国现存最 早的砚铭,是以文学形式写成的,其铭曰:“石墨相著而黑,邪心谗言,得无白。
”不过作为一种文学创作体裁的砚铭,还是到了汉魏时期才形成。
作为文学形式的早期砚铭,大多数是就砚说砚,是文人用以品评和赞美砚的。
到了宋代,人们喜欢用它抒发自己的思想感情,从此以后,言志寄情、赋诗颂词便成了砚铭创作的主流之一,并留下了许多脍炙人口的名篇佳作。
如文天祥写的砚铭:“砚虽非铁难磨穿,心虽非石如其坚,守之弗失道自全。
”就属此类。
砚铭作为艺术品的出现,比作为文学作品要晚得多,它兴于宋元,盛于明清。
某某市2011—2012学年度第二学期第一次阶段性检测高二数学(理)试卷第I 卷(选择题,共50分)一、选择题(本大题共有10个小题,每小题5分,共50分;在每小题给出的四个选项中,只有一项是符合题目要求的) 1.已知f(x)=x 2-2x+1则)2(f '=( )A.0B.4 C 7 D2 2.用反证法证明命题:“三角形的内角中至少有一个不大于60度”时,假设正确的是()A .假设三内角都不大于60度 B.假设三内角都大于60度C .假设三内角至多有一个大于60度 D.假设三内角至多有两个大于60度 3.32()32f x ax x =++,若'(1)4f -=,则a 的值等于( )A .319 B .316 C .313 D .310 4. 若曲线4y x =的一条切线l 与直线480x y +-=垂直,则l 的方程为( )A .430x y --=B .450x y +-=C .430x y -+=D .430x y ++= 5.已知数列{a n }满足a 1 =0,nn a a -=+211则a 2012=()。
A.20112012 B 20122011 C 20112 D 201320126.设函数[]0)()(,,12)(3<∈+--=n f m f n m x x x x f 且则方程[]n m x f ,0)(在=上( )。
A.至少有三个实数根 B. 至少有两个实数根 C. 有且只有一个实数根 D 无实数根7.函数[]3,0523在区间+--=x x x y 上的最大值和最小值分别是()。
A.22,27106 B.20, 4 C.20, 5 D.5, 271068. 某个与自然数有关的命题:如果当n=k(*N k ∈)时,命题成立,则可以退出n=k+1时,该命题也成立。
现已知n=6时命题不成立().A.当n=5时命题不成立B. 当n=7时命题不成立C. 当n=5时命题成立D. 当n=8时命题成立9已知函数(]0)(,3,0)()()(≠∈=x g x x g x f x h ,,对任意(])()()()(,3,0x g x f x g x f x '>'∈恒成立,则()。
富县高级中学2013-2014学年第二学期期中考试高二语文试题一、现代文阅读(9分,每小题3分)阅读下面的文字,完成第1—3题。
1答案:C解析:原文说,“即便发生冲突,也未尝不可以化解”“成功地化解冲突,便进入了‘和’的状态”。
2、答案:B解析:三教不可或缺,是说接受其文化的渐染而并非一定要信奉。
3、答案:D解析:A项中,原文无“人只有一种精神诉求是一种不健全的心态”这一说法;C项“缺一则‘互补’之说即无从谈起”错,只儒、道二教即有互补;B项中,“中国固有的学问”是比“儒道两家”大得多的概念,二者不可混淆,且“只是”一词太绝对,原文为“主要是讲人生哲学”。
二、文言文阅读(19分)阅读下面的文言文,完成第4—7题。
4、答案:A解析:A项,去:离开。
5、答案:C解析:A项中“孔子适齐,为高昭子家臣”说明的是孔子的经历,并未说明“好学有才”;B项中“于是反鲁,鲁复善待”说明的是鲁国对孔子的态度,并未说明“好学有才”。
D项中“由大司寇行摄相事,有喜色”说明的是孔子对职位变动的态度,并未说明“执政才能”。
6、答案:D解析:D项中“却没有受到善待”的说法与原文不符,原文说“于是反鲁,鲁复善待”,说明孔子得到了善待。
7.将下列句子翻译成现代汉语。
(10分)答案: (1)不久离开鲁国,在齐国受到排挤,被宋人、卫人所驱逐,在陈国、蔡国之间受困,于是返回鲁国。
鲁君又善待孔子。
(2)他与齐国的乐官谈论音乐,听到了舜时的《韶》乐,就学习了起来,有三个月的时间竟尝不出肉的味道,齐国人都称赞他。
三.名句默写8. 按要求写出下列名篇名句中的空缺部分。
(15分)1).不愤不启,不悱不发2).谨庠序之教,申之以孝悌之义3).己所不欲,勿施于人己欲立而立人,己欲达而达人。
4).躬自厚而薄责于人,则远怨矣。
5).有杀身以成仁6).学而不思则罔,思而不学则殆7). 生于忧患,死于安乐四.现代文阅读(20分)9.(1)坚决地干预现实生活。
○…………装…………○…………订…………○…………线…………○…… 姓名 考号 考场号富县高级中学2011-2012学年度第二学期阶段水平测试高一英语试题(卷)注意:本试卷第Ⅰ、Ⅱ卷均答在答题卡上,满分120分,时间120分钟。
第Ⅰ卷(选择题 共80分)一、单项选择(共计20小题;每题1分;共20分) 1.The picture______ on the wall was drawn by Picasso. A. is attached to B. attaching to C. attached to D. attaching on2. Mother received a letter from her son, telling that he had ____the money and food.A. run out ofB. ran out ofC. run outD. ran out 3. At this time tomorrow, ______on the road.A. he's going to practise drivingB. he'll be practising drivingC. he'll practise drivingD. he is to practise driving4.The scientific research on how to fight against the A(H1N1) flu virus is ______A. in dangerB. in controlC. in orderD. in progress5.Our headmaster worked so hard day and night that_____ he made himself ill.A. definitelyB. quicklyC. eventuallyD. probably 6. Come to my house whenever______A you are convenient B. you will be convenient C it is convenient to you D. it will be convenient to you7. The school provided clothes and food ______ the children from Yunnan.A. forB. toC. withD. / 8.The book written by Yu Dan is _____worth _____. A good; reading B. well; reading C. well; being read D. good; being read9. _____me before you come, or we might be out.A . Calling B. Call C. Called D. To call10. My brother's pale face suggested that he ____ill, and my parents suggested that he ____ a medical examination. A. be; should take B. was; take C. should be; took D. was; takes11.The prices of meat______ greatly with seasons.A. variesB. variousC. varyD. variety 12. Most people prefer a _____show to a recorded one. A. living B. alive C. lively D. live13.I'll see you at the theatre___ you call me to say you're not coming. A. when B. if C. unless D. though14. I have decided to realize my dream of being a professional athlete_____ difficulty I will meet.A. whateverB. howeverC. wheneverD. wherever 15. The box is too heavy . Would you do me a ____?A. helpB. favourC. handD. gesture 16.If you work hard from now on, ______,you will succeed. A. finally B. eventually C. at last D. in the end 17.------Excuse me, when _____ the plane______ off?-------I'm afraid it will be delayed because of the heavy frog. A.has; taken B. does; take C. Is; taken D. did; take 18. There is no simple solution_____ this problem.A.ofB. forC. toD. about19.After being without _____for a month, the soldier was arrested asa deserter(逃兵)A.permitB. allowanceC. leaveD. agreement20.In fact, although we often don't like to admit it, some of the most important innovations have happened ______.A. at timesB. suddenlyC. all at onceD. by accident二、完形填空(共计20 小题;每题1.5分;共30分)One day, Nancy came home from school crying. Taking her in the arms, Mummy tried to 21_______her. After a while, she stopped crying and asked, “Mummy, am I 22_______?”“No, you are not,” said Mummy, “but let us discuss this after you 23_______,OK?”Several minutes later, Nancy began to have supper with Mummy.“Who 24______that you are bad?” asked Mummy.“Phillips, my friend. He asked me for help with his maths but I 25_______ because I wanted to read the new book Daddy gave me. He got 26______and said i was a bad girl,” said Nancy.“Y ou are 27______,”said Mummy.“Phillips has often helped you with your English. Y ou should have helped him. Why don't you phone him and say 28______ to him? ”“But he called me bad and 29________with me. I do n't want to go, ”Nancy said.“Though you have done 30______bad, it does not make you a bad person. Y ou are 31_____ a good person.”Nancy showed a 32______look on her face. “How can that be, Mummy ?”she asked.“Our 33______ is always good. So never believe that you are bad, ”Mummy replied with a smile.34_______flooded on Nancy's face. “Am I 35______good, Mummy?” she asked“Y es, you are good, and always will be so. But that does not mean that you should not 36_______ the wrong that you do. Y ou will have to c all and 37______ to Phillips. Do you understand me?”“Y es, Mummy,”said Nancy slowly. “Thanks you for telling me this. I feel much better now,”said Nancy 38______.“I am going to 39____Phillips right away, and I am never going to 40_____that I am always go od. ”21.A. calm B. protect C. trick D. praise22.A. shy B. foolish C. bad D. strong23.A. get up B. grow up C. wash up D. turn up24.A. said B. saw C. heard D . doubted25.A. cried B. refused C. admitted D. allowed26.A. excited B. comfortable C. Nervous D. angry27.A. wrong B. brave C. wise D. careful28.A. goodbye B. sorry C. thank-you D. hello29.A. competed B. lived C. worked D. argued30.A.everything B. anything C. something D. nothing31.A. always B. sometimes C. ever D. never32.A. worried B. puzzled C. confident D. satisfied33.A. chance B. choice C. condition D. nature34.A. Fear B. Patience C. Shock D. Joy35.A. really B. hardly C. already D. gradually36.A. account for B. pay for C. look forward to D. rely on37.A. devote B. apologize C. introduce D. turn38.A. coldly B.. sadly C. grateful D. pitifully39.A. consult B. change C. teach D. call40.A. agree B. explain C. forget D. confirm○…………装…………○…………订…………○…………线…………○…… 姓名 考号 考场号三、阅读理解(共15题,每题2分,满分30分)Passage AIf you ask some people, “How did you learn English so well?” you may get a surprising answer: “In my sleep!”These are people who have taken part in one of the recent experiments to test the learn while you sleep method , which is now being tried in several countries, and with several subjects. English is among them.Scientists say that this sleep study method greatly speeds language learning. They say that the ordinary person can learn two or three times as much during sleep as in the same period during the day —and this does not affect his rest in any way. However, sleep teaching will only put into your head what you have studied already while you are awake.In one experiment, ten lessons were broadcast over the radio for two weeks. Each lesson lasted twelve hours — from 8 p.m. to 8 a.m. The first three hours of English grammar and vocabulary were given with the students awake. At 11 p.m. a lullaby (催眠曲) was broadcast to send the student to sleep and for the next three hours the radio in a soft and low voice broadcast the lesson again into his sleeping ears. At 2 a.m. a sharp noise was sent over the radio to wake the sleeping student up for a few minutes to go over the lesson. The soft music sent him back to rest again while the radio went on. At 5 o'clock his sleep ended and he had to go through the lesson again for three hours before breakfast. 41.By the learn while you sleep method, one____ . A. starts to learn a new lesson in sleep B. learns how to sleep betterC. is made to remember his lesson in sleepD. can listen to the radio broadcast while lying in bed 42.In the experiment, lessons were given____ . A. in the night timeB. after lullabies were broadcastC. while the student was awakeD. all through the twelve hours43.Before each lesson finishes, the student has to____ . A. get up and take breakfast B. be woken up by a loud voiceC. listen to the lesson again in sleepD. review the lesson by himself44.The sleep study method is being tried in many countries to teach____ . A. the English language B. grammar and vocabulary C. a number of subjects D. foreign languages Passage BFrom Monday until Friday most people are busy working or studying, but in the evenings and on weekends they are free to relax and enjoy themselves. Some watch TV or go to the movies; others take part in sports. It depends on individual interests. There are many different ways to spend our spare time. Almost everyone has some kinds of hobbies. It may be anything fromcollecting stamps to making model airplanes. Some hobbies are very expensive, but others don't cost anything at all. Some collections are worth a lot of money; others are valuable only to their owners.I know a man who has a coin collection worth several thousand dollars. A short time ago he bought a rare fifty cent piece worth S |250! He was very happy about his buying and thought the price was reasonable . On the other hand, my youngest brother collects matchboxes. He has almost 600 of them but I doubt if they are worth any money. However, to my brother they are very valuable. Nothing makes him happier than to find a new matchbox for his collection.That's what a hobby means, I guess. It is something we like to do in our spare time simply for the fun of it. The value in dollars is not important, but the pleasure it gives us is.:45.The underlined word “individual” in the first paragraph most probably means____ .A. differentB. strangeC. secretD. one's own46. In the writer's opinion, ____.A. all hobbies are very expensiveB. some hobbies don't cost anythingC. hobbies are worthlessD. hobbies are valuable to everybody47.Something that one enjoys doing in one's spare time is a____ .A. jobB. pleasureC. hobbyD. habit48.Which of the following statements is NOT true?A. The writer's brother has a large collection of matchboxes, which makes him very happy.B. We collect a subject in our spare time simply for the fun of it.C. The pleasure that a hobby can give is important.D. To have a hobby means to spend a lot of money.Passage CMillions of years ago there were many types of dinosaurs on earth. Most dinosaurs were plant eaters. The Apatosaurus, for example, had a long thin neck so that it could eat leaves from trees. Other dinosaurs were meat eaters. The Tyrannosaurus Rex killed smaller dinosaurs for food.Dinosaurs were real animals that once lived on the earth, but they died out about 65 million years ago. The disappearance of the dinosaurs is in some way a great mystery. Some scientists think that the climate changed suddenly. Fossils (化石) of trees tell us that the temperature dropped a lot and that the level of the sea dropped as well. This means that it got suddenly much colder. Perhaps the dinosaurs were too slow to change with the climate.A new idea is that a meteor (流星) crashed into the earth. Scientists discovered a place in Mexico where they think the meteor crashed. They think that there was a lot of dust from the meteor. The dust landed on the plants. Also the dust blocked (阻挡) the sun's light for as long as five years. Many animals, including dinosaurs, were plant eaters, and perhaps the dust killed them. This means there was nothing left for meat eating dinosaurs to eat, and so they died out. But, as many animals from that time didn’t die, we are not 100% su re what really happened.49.What is the subject discussed in the text?A. Dinosaurs, the real animals living millions of years ago.B. The two types of dinosaurs.C. The probable reasons for dinosaurs disappearance.D. A meteor crashed into the earth.50.What are the two possible explanations to the dinosaurs disappearance?A. Temperature dropping and sea level dropping.B. Climate changing and meteor's crashing.C. The dropping of temperature and sea level.D. Climate changing and the dust blocking the sun.○…………装…………○…………订…………○…………线…………○…… 姓名 考号 考场号51.What is the direct cause of the disappearance of meat eating dinosaurs? A. A meteor's crashing. B. The dust blocking the sun. C. The plant eating dinosaurs death. D. It is still unknown. Passage DIn choosing a friend, one should be very careful. A good friend ca n help you study. You can have fun together and make each other happ y. Sometimes you will meet fair weather friends. They will be with you as long as you have money or luck, but when you are down, they will r un away. How do I know when I have found a good friend? I look for certain qualities of character, especially understanding, honesty and reliabil ity.Above all else, I look for understanding in a friend. A good friend tries to understand how another person is feeling. He is not quick to judge. Instead, he tries to learn from others. He puts himself in the other person's place, and he tries to think of ways to be helpful. He is also a good listener.At the same time, however, a good friend is honest. He does not look for faults in others. He notices their good points. In short, a friend will try to understand me and accept me.Another quality of a friend is reliability. I can always depend on a good friend. If he tells me he will meet me somewhere at a certain time, I can be sure that he will be there. If I need a favor, he will do his best to help me. If I am in trouble, he will not run away from me.There is a fourth quality that makes a friend special. A special friend is someone with whom we can have fun. We should enjoy our lives, and wewould enjoy our friendship. That is why I especially like friends who are fun to be with. A good friend likes the same things I like. We share experience and learn from each other. A good friend has a good sense of humor, too. He likes to laugh with me. That is how we share in the joy of being friends. And I know that he is looking for the same quality in me.When I meet someone who is reliable, honest, and understanding, I know I've found a friend!52.Which of the following qualities the writer thinks is the most important in choosing a friend?A. Understanding.B. honesty.C. Reliability.D. a sense of humor. 53.If you have fair weather friends, ______ .A. they will give you all that they have when you need helpB. you will be refused when you get into troubleC. you will become richD. you can be sure that you get real friends 54.Good friends need to ______.A. always point out each other's mistakesB. be helped with moneyC. understand each other's feelingsD. have money or luck 55.This passage mainly discuss ______ .A. the qualities of a friendB. where to choose friendsC. how to get along with friendsD. the importance of having a friend第Ⅱ卷(非选择题共40分)四、单词拼写(共计10 小题;每题1分;共10分)56.The society is always developing and we can't make exact____________(预测) of the future.57.Y ou should ______(当然) stay in the bed if the doctor tells you to.58.She is always ___________(乐观的) when she meets with difficulties.59.Will it be _______________(方便的)to come in the afternoon?60.She was __________(遭受) from a headache.61.Several official were_________(卷入)in the matter.62.She ______(变化) her dress as fashion changes.63.The orchestra will give two more ________(表演) this week.64.Students shouldn't leave school without the teacher's______(许可)65.Being deaf and dumb makes_________(交流) very difficult.五、写作(30分)近几年,由于汽车产业的迅速发展,私家车的购买量猛增。
富县高级中学2012—2013学年度高二模块检测试题思想政治(生活与哲学)文科本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分。
第Ⅰ卷1至6页,第Ⅱ卷7至8页,共100分。
考试时间 90 分钟。
第Ⅰ卷(选择题共 60 分)注意事项:1.答第Ⅰ卷前,考生务必将自己的姓名、考号用铅笔涂写在答题卡上。
2.每小题选出答案后,用铅笔把答案卡上对应题目的答案标号涂黑,如需改动,用橡皮擦干净后,再选涂其他答案,不能答在试卷上。
第Ⅰ卷(选择题共60分)一、单项选择题(在下列各题的4个选项中,只有1项最符合题目要求。
每小题2分,共60分)党的“十七大”报告中指出:要繁荣发展哲学社会科学,推进学科体系、学术观点、科研方法创新,鼓励哲学社会科学界为党和人民事业发挥思想库作用,推动我国哲学社会科学优秀成果和优秀人才走向世界。
据此回答1-2题。
1、下列选项中对哲学理解正确的是()①哲学是关于世界观的学说②哲学是哲学家研究的学科③哲学是世界观和方法论的统一④哲学是系统化和理论化的世界观A、①②③B、②③④C、①③④D、①②④2、党的十七大之所以提出要繁荣发展哲学社会科学,是因为哲学()A、是具体知识的概括和总结B、能够直接推动经济社会发展C、是唯物论与辩证法的有机统一D、能够提供世界观和方法论指导3.右图漫画中公鸡的观点与下列选项中哪种说法的哲学思想一致()A、存在就是被感知B、谋事在人、成事在天C、人不能两次踏入同一条河流D、天不变、道亦不变4、“不登高山,不知天之高也;不临深渊,不知地之厚也”与下列名句所蕴涵的哲理相一致的是()①近水知鱼性,近山识鸟音②千里之行,始于足下③没有调查就没有发言权④不出户,知天下;不窥牗,见天道⑤百闻不如一见,百见不如一干-1-A、①③④B、②③④C、①③⑤D、②③5、《石钟山记》中写道:“士大夫终不肯以小舟停泊于绝壁之下,故莫能知;而渔工水师虽知而不能言。
”其中蕴涵的哲理是 ( )①实践是认识发展的动力②实践是认识的来源③实践是检验认识的真理性的唯一标准④感性认识有待于上升为理性认识A、①③B、②④C、②③D、①④6、“露从今夜白,月是故乡明”是杜甫《月夜忆舍弟》中的名句。
2011-2012学年陕西省咸阳市某校高三二轮测试数学试卷2(理科)一、选择题:本大题共10小题,每小题5分,共50分.在每小题给出的四个选项中,只有一项是符合题目要求的.1. 若集合A={y|y=lgx},B={x|y=√1−x},则A∩B为()A [0, 1]B (0, 1]C [0, ∞)D (−∞, 1]2. 复数1−i1+i等于()A −1B −iC 1D i3. 已知a,b∈R,下列四个条件中,使a>b成立的必要而不充分的条件是( )A a>b−1B a>b+1C |a|>|b|D 2a>2b4. 已知锐角α的终边上一点P(sin40∘, 1+cos40∘),则锐角α=()A 80∘B 70∘C 20∘D 10∘5. 一个正方体的展开图如图所示,A,B,C,D为原正方体的顶点,则在原来的正方体中()A AB // CDB AB与CD相交C AB⊥CD D AB与CD所成的角为60∘6. 如图,在A、B间有四个焊接点,若焊接点脱落,而可能导致电路不通,如今发现A、B之间线路不通,则焊接点脱落的不同情况有()A 10B 12C 13D 157. 已知双曲线x2a2−y2b2=1(a>0, b>0)的两条渐近线均和圆C:x2+y2−6x+5=0相切,且双曲线的右焦点为圆C的圆心,则该双曲线的方程为()A x25−y24=1 B x24−y25=1 C x23−y26=1 D x26−y23=18. 已知实数x,y满足{x≥1x+y≤4ax+by+c≤0,且目标函数z=2x+y的最大值为6,最小值为1,其中b≠0,则cb的值为()A 4B 3C 2D 19. 若关于x的方程|x|x+2=kx2有四个不同的实数解,则实数k的取值范围为()A (0, 1)B (12, 1) C (12, +∞) D (1, +∞)10. 已知点A(−1, 1),若曲线G上存在两点B,C,使△ABC为正三角形,则称G为T型曲线.给定下列三条曲线:①y =−x +3(0≤x ≤3) ②y =√2−x 2(−√2≤x ≤0) ③y =−1x (x >0),则T 型曲线的个数是( ) A 0 B 1 C 2 D 3二、填空题:本大题共5小题,每小题5分,共25分.11. 一空间几何体的三视图如图所示,则该几何体的体积为( )A 43 B 2 C4 D 612.如图,如果执行它的程序框图,输入正整数n =8、m =4,那么输出的p 等于________.13. 已知数列{a n },{b n }满足a 1=12,a n +b n =1,b n+1=bn 1−a n2(n ∈N ∗),则b 2012=________.14. 已知函数f(x)=−x 3+3f′(2)x ,令n =f′(2),则二项式(x +√x)n展开式中常数项是第________ 项.15. (考生注意:从下列三题中任选一题,多选的只按照第一题计分)①对任意x ∈R ,|2−x|+|3+x|≥a 2−4a 恒成立,则a 满足________. ②在极坐标系中,点P(2, −π6)到直线l:ρsin(θ−π6)=1的距离是________;③如图,点P 在圆O 直径AB 的延长线上,且PB =OB =2,PC 切圆O 于点C ,CD ⊥AB 于点D ,则CD =________.三、解答题:本大题共6小题,共75分,解答应写出文字说明、证明过程或演算步骤. 16. 在钝角三角形ABC 中,a 、b 、c 分别是角A 、B 、C 的对边,m →=(2b −c,cosC),n →=(a,cosA),且m → // n →. (1)求角A 的大小;(2)求函数y =2sin 2B +cos(π3−2B)的值域.17. 已知数列{a n }是递增数列,且满足a 3⋅a 5=16,a 2+a 6=10. (1)若{a n }是等差数列,求数列{a n }的通项公式; (2)对于(1)中{a n },令b n =(a n +7)⋅2n 3,求数列{b n }的前n 项和T n .18. 如图,在四棱锥P −ABCD 中,底面ABCD 为直角梯形,AD // BC ,∠ADC =90∘,平面PAD ⊥底面ABCD ,Q 为AD 的中点,M 是棱PC 上的点,PA =PD =2,BC =12AD =1,CD =√3.(1)求证:平面PQB ⊥平面PAD ;(2)若二面角M −BQ −C 为30∘,设PM =tMC ,试确定t 的值.19. 某饮料公司招聘了一名员工,现对其进行一项测试,以便确定工资级别.公司准备了两种不同的饮料共8杯,其颜色完全相同,并且其中4杯为A 饮料,另外4杯为B 饮料,公司要求此员工一一品尝后,从8杯饮料中选出4杯A 饮料.若4杯都选对,则月工资定位3500元;若4杯选对3杯,则月工资定为2800元,否则月工资定为2100元,今X 表示此人选对A 饮料的杯数,假设此人对A 和B 两种饮料没有鉴别能力. (1)求X 的分布列;(2)求此员工月工资的期望.20. 已知点D(0, −2),过点D 作抛物线C 1:x 2=2py(p >0)的切线l ,切点A 在第二象限,如图.(1)求切点A 的纵坐标;(2)若离心率为√32的椭圆x 2a 2+y 2b 2=1(a >b >0)恰好经过切点A ,设切线l 交椭圆的另一点为B ,记切线l ,OA ,OB 的斜率分别为k ,k 1,k 2,若k 1+2k 2=4k ,求椭圆方程.21. 已知函数f(x)=(ax 2+bx +c)e −x (a ≠0)的图象过点(0, −2),且在该点的切线方程为4x −y −2=0.(1)若f(x)在[2, +∞)上为单调增函数,求实数a 的取值范围;(2)若函数F(x)=f(x)−m 恰好有一个零点,求实数m 的取值范围.2011-2012学年陕西省咸阳市某校高三二轮测试数学试卷2(理科)答案1. D2. B3. A4. B5. D6. C7. A8. A9. D 10. B 11. B 12. 1680 13.2012201314. 515. [−1, 5],√3+1,√316. 解:(1)由m → // n →得,(2b −c)cosA −acosC =0,由正弦定理得 2sinBcosA −sinCcosA −sinAcosC =0∴ 2sinBcosA −sin(A +C)=0,即2sinBcosA −sinB =0,可得2sinBcosA =sinB ∵ B ∈(0, π),sinB 为正数∴ 2cosA =1,得cosA =12,结合A ∈(0, π),得A =π3…(2)y =2sin 2B +cos(π3−2B)=1−cos2B +12cos2B +√32sin2B =1−12cos2B +√32sin2B =sin(2B −π6)+1…①当角B 为钝角时,可得B ∈(π2, 2π3),2B −π6∈(5π6, 7π6) ∴ sin(2B −π6)∈(−12, 12),得y ∈(12, 32)… ②当角B 为锐角时,角C 为钝角,即C =2π3−B ∈(π2, π),所以B ∈(0, π6)∴ 2B −π6∈(−π6, π6),sin(2B −π6)∈(−12, 12),得y ∈(12, 32)…综上所以,函数y =2sin2B +cos(π3−2B)的值域为(12, 32)…17. 解:(1)根据题意:a 2+a 6=10=a 3+a 5, 又a 3⋅a 5=16,且a 3<a 5, 解得a 5=8,a 3=2, 所以d =3,∴ a n =3n −7.(2)b n =(a n +7)⋅2n3=n ⋅2n ,T n =1×21+2×22+3×23+...+(n −1)⋅2n−1+n ⋅2n ,①2T n =1×22+2×23+...+(n −2)⋅2n−1+(n −1)⋅2n +n ⋅2n+1,② ①-②得−T n =21+22+23+⋯+2n−1+2n −n ⋅2n+1 =2(1−2n )1−2−n ⋅2n+1,所以T n =n ⋅2n+1−2n+1+2=(n −1)⋅2n+1+2. 18. 证法一:∵ AD // BC ,BC =12AD ,Q 为AD 的中点,∴ 四边形BCDQ 为平行四边形,∴ CD // BQ . ∵ ∠ADC =90∘∴ ∠AQB =90∘,即QB ⊥AD .又∵ 平面PAD ⊥平面ABCD ,且平面PAD ∩平面ABCD =AD , ∴ BQ ⊥平面PAD .∵ BQ ⊂平面PQB ,∴ 平面PQB ⊥平面PAD . 证法二:AD // BC ,BC =12AD ,Q 为AD 的中点,∴ 四边形BCDQ 为平行四边形,∴ CD // BQ . ∵ ∠ADC =90∘∴ ∠AQB =90∘. ∵ PA =PD ,∴ PQ ⊥AD .∵ PQ ∩BQ =Q ,∴ AD ⊥平面PBQ .∵ AD ⊂平面PAD ,∴ 平面PQB ⊥平面PAD . ∵ PA =PD ,Q 为AD 的中点,∴ PQ ⊥AD .∵ 平面PAD ⊥平面ABCD ,且平面PAD ∩平面ABCD =AD , ∴ PQ ⊥平面ABCD .如图,以Q 为原点建立空间直角坐标系. 则平面BQC 的法向量为n →=(0,0,1);Q(0, 0, 0),P(0,0,√3),B(0,√3,0),C(−1,√3,0).设M(x, y, z),则PM →=(x,y,z −√3),MC →=(−1−x,√3−y,−z), ∵ PM →=tMC →,∴ {x =t(−1−x)y =t(√3−y)z −√3=t(−z) ,∴ {x =−t1+t y =√3t1+t z =√31+t ⋯在平面MBQ 中,QB →=(0,√3,0),QM →=(−t1+t ,√3t 1+t ,√31+t),∴ 平面MBQ 法向量为m →=(√3,0,t). ∵ 二面角M −BQ −C 为30∘, ∴ cos30=n →⋅m→|n →||m →|=t √3+0+t2=√32, ∴ t =3.19. 解:(1)X 的所有可能取值为0,1,2,3,4,P(X =0)=1C 84=170P(X =1)=C 41C 43C 84=1670P(X =2)=C 42C 42C 84=3670P(X =3)=C 41C 43C 84=1670P(X =4)=1C 84=170(2)此员工月工资Y 的所有可能取值有3500、2800、2100,P(Y =3500)=P(X =4)=1C 84=170P(Y =2800)=P(X =3)=C 41C 43C 84=1670P(Y =2100)=P(X =0)+P(X =1)+P(X =2)=5370EY =3500×170+2800×1670+2100×5370=2280 20. 解:(1)设切点A(x 0, y 0),且y 0=x 022p ,由切线l 的斜率为k =x 0p,得l 的方程为y =x 0px −x 022p ,又点D(0, −2)在l 上,∴ x 022p =2,即点A 的纵坐标y 0=2.(2)由(1) 得A(−2√p ,2),切线斜率k =√p,设B(x 1, y 1),切线方程为y =kx −2, 由e =√32,得a 2=4b 2,所以椭圆方程为x 24b 2+y 2b 2=1,且过A(−2√p ,2),∴ b 2=p +4.由{y =kx −2x 2+4y 2=4b 2⇒(1+4k 2)x 2−16kx +16−4b 2=0, ∴ {x 0+x 1=16k1+4k 2,x 0x 1=16−4b 21+4k 2,k 1+2k 2=y 0x 0+2y 1x 1=x 1y 0+2x 0y 1x 0x 1=x 1(kx 0−2)+2x 0(kx 1−2)x 0x 1=3k −2x 1+4x 0x 0x 1=3k −2(x 1+x 0)+2x 0x 0x 1=3k −32k1+4k 2−4√p 16−4b 21+4k 2=3k −32k −4√p(1+4k 2)16−4b 2=4k 将k =√p,b 2=p +4代入得:p =32,所以b 2=36,a 2=144, 椭圆方程为x 2144+y 236=1.21. 解:(1)由f(0)=−2,可得c =−2…求导函数可得f′(x)=(−ax 2+2ax −bx +b −c)e −x ,∴ f′(0)=(b −c)e 0=b −c ∵ 切线方程为4x −y −2=0,∴ b −c =4,∴ b =2…∴ f(x)=(ax2+2x−2)e−x,f′(x)=(−ax−2)(x−2)e−x,∵ f(x)在[2, +∞)上为单调增函数,∴ (−ax−2)(x−2)e−x≥0在[2, +∞)上恒成立即−ax−2≥0,∴ a≤−2x,∴ a≤−1…(2)函数F(x)=f(x)−m恰好有一个零点,即y=m和y=f(x)恰好有一个交点∵ f′(x)=(−ax−2)(x−2)e−x,①当a>0时,f(x)在区间(−∞, −2a ),(2, +∞)单调递减,在(−2a,2)上单调递增,极大值为f(2)=(4a+2)e−2,极小值为f(−2a)=−2e2a,(当x趋向于+∞时图象在x轴上方,并且无限接近于x轴)所以m=(−2)e 2a或m>(4a+2)e−2,…②当a<0时:(1)当−2a >2,即−1<a<0时,f(x)在区间(−∞, 2),(−2a, +∞)单调递增,在(2, −2a )上单调递减,极大值f(2)=(4a+2)e−2,极小值为f(−2a)=−2e2a,(当x趋向于+∞时图象在x轴下方,并且无限接近于x轴)当(4a+2)e−2≥0,即−12≤a<0时,m=(4a+2)e−2或m<(−2)e2a当(4a+2)e−2<0,即−1<a<−12时,(4a+2)e−2<m<0或m<(−2)e2a…(2)当−2a <2时,即a<−1时,f(x)在区间(−∞, −2a),(2, +∞)单调递增,在(−2a, 2)上单调递减,极小值为f(2)=(4a+2)e−2,极大值为f(−2a)=−2e2a,(当x趋向于+∞时图象在x轴下方,并且无限接近于x轴)∴ m=(−2)e2a或m<(4a+2)e−2,…(3)−2a=2时,即a=−1时,f(x)在R上单调增(当x趋向于+∞时图象在x轴下方,并且无限接近于x轴),此时m<0…。
…………………………答……………………………………………………题…………………………………………线………………………富县高级中学2013--2014学年度第二学期期中考试高二生物试题(卷)(试题共分为两部分:选择题和非选择题 满分:100分;时间:100分钟)第I 卷(选择题 共60分)一. 选择题(共30小题,每题2分,共60分)1.下列哪项不是基因工程中经常使用的来运载目的基因的载体 ( ) A .细菌质粒 B .噬菌体 C .动植物病毒 D .细菌核区DNA 2.蛋白质工程中,直接需要进行操作的对象是( )A .氨基酸结构B .蛋白质的空间结构C .基因结构D .肽链结构3.下列选项中,肯定没有采用植物组织培养技术的一项是( )A.花药离体培养得到单倍体植株 B 细胞工程培育“番茄—马铃薯”杂种植株 C 基因工程培育抗虫棉植株 D.秋水仙素处理萌发的种子或幼苗得到多倍体 4.在基因工程中,切割载体和含有目的基因的DNA 片段,一般需要使用( ) A .同种限制酶 B .两种限制酶 C .同种连接酶D .两种连接酶5.在基因工程的基本操作步骤中,不进行碱基互补配对的是( )A .人工合成目的基因B .目的基因与运载体结合C .将目的基因导入受体细胞D .目的基因的检测表达6.下列哪项正确的表示了牛胚胎发育的顺序 ( )A. 配子→受精→合子→胚→卵裂B. 合子→胚→胎儿→幼体→成体C. 合子→卵裂→囊胚→原肠胚→胎儿D. 精卵细胞形成→受精→合子→胎儿→出生 7.基因工程的操作步骤:①目的基因与运载体结合②将目的基因导入受体细胞 ③检测目的基因的表达是否符合特定性状要求 ④提取目的基因。
正确操作顺序是( )A .③②④①B .④①②③ C. ②④①③ D .③④①②8.下列有关基因工程中限制内切酶的描述,错误的是( ) A .一种限制性内切酶只能识别一种特定的脱氧核苷酸序列 B .限制性内切酶的活性受温度的影响 C .限制性内切酶能识别和切割RNAD .限制性内切酶可从原核生物中提取9.在动物体细胞克隆技术中,不一定涉及( )A .卵母细胞的培养B .细胞核移植C .早期胚胎培养D .导入外源基因 10.试管牛所采用的技术是( )①胚胎移植 ②基因工程 ③细胞工程 ④体外受精 ⑤克隆技术A .①④B .②④C .①③D .①⑤11.将来能发育为胎儿的胎膜和胎盘的结构是( )A. 原肠胚B. 内细胞团C. 桑椹胚D. 滋养层12.在克隆羊培育过程中,将雄羊的体细胞核移入雌羊的卵细胞中。
陕西省富县高二下学期语文期中考试试卷姓名:________ 班级:________ 成绩:________一、选择题 (共3题;共6分)1. (2分) (2017高三上·庄浪月考) 下列各句中,没有语病的一句是()A . 说实话,当时对自己的稿子能否被刊用,没抱太大的希望,因为那时经常在该报发表文章的都是一些大家。
B . 济南惨案纪念钟于4月28日凌晨从广州运抵济南,至此,济南惨案纪念园的布展工作全部完成,5月3日将开门迎客。
C . 在两会的遏制态度、刚性需求几乎消耗殆尽以及投资需求的观望气氛等因素的影响下,高房价如何调整备受关注,楼市正面临着一个新的拐点。
D . 中华全国总工会紧急拨款100万元,用于对在黑龙江省鹤岗新兴煤矿爆炸事故中遇难矿工家属的慰问。
2. (2分)依次在下列横线处填入词语,最恰当的一项是()(1)那时,北大的学生好幸运,学生的借书证,可以借十本线装书。
(2)阿Q这个艺术形象,了鲁迅先生对国民灵魂弱点的认识深度。
(3)与会的很多国家认为,严厉打击国际恐怖活动无可厚非,但草木皆兵,随意扩大战争范围,则轻率。
(4)日本政府抛出的“购岛”闹剧,表现出日本军国主义大有之势,这极大的伤害了中国人民的感情。
A . 居然表现有失东山再起B . 居然体现失之死灰复燃C . 竟然体现失之东山再起D . 竟然表现有失死灰复燃3. (2分) (2016高三上·遵义模拟) 下列各句中划线成语的使用,全部正确的一项是()①“13岁中国布兰妮”“7岁美女模特”等消息满天飞,使“出名要趁早,出道要趁早”的心态蔓延,孩子们不知不觉地沦为急功近利的牺牲品。
②性格决定命运,任何一个人的命运悲剧实际上就是其个人的性格悲剧,王灿性格孤傲,卓尔不群,因而难以与周围人相处。
③幼儿园入园需摇号,看似做到了概率面前人人平等,但却是一种假公平,这种方式作为缓兵之计不妨一用,但绝不能成为长期施行的政策。
④有一双轻跳舞靴太美观了,细长到不可理喻的地步;那双带布口的漆皮靴,叫人看了舍不得离开。
○…………内…………○…………装…………○…………订…………○…………线…………○……班级 姓名 考号 考场号富县高级中学2011-2012学年度第二学期阶段水平测试高二历史试题(卷)注意:本试卷第Ⅰ、Ⅱ卷均答在答题卡上,满分100分,时间100分钟。
第Ⅰ卷(选择题 共60分)一、单项选择题(每题只有一个正确选项,请将正确选项填涂在答题卡指定位置,每小题2分,共60分)1.位于无锡梅村的鸿声钱氏家族,因诞生了“国学大师”钱穆、“力学之父”钱伟长、环保专家钱易、经济学家钱俊瑞、物理学家钱临照和工程力学家钱令希等六位院士而蜚声海内外,鸿声钱氏家族也引以为荣。
家族观念自中国古代就得到了人们的高度重视,其主要原因是 A .宗法制的影响 B .商品经济的影响 C .分封制的影响 D .弘扬儒学的需要2.2011年4月28日国家统计局局长马建堂透露,第六次全国人口普查汇总情况显示,出生人口性别男女比例为118∶100,性别比失调凸现,这说明重男轻女观念仍然存在,从历史角度看,这种观念形成的主要原因是A .宗法制B .科举制C .分封制D .郡县制 3.下图是有关省份的汽车号牌图片,这些省份的简称源自西周分封制的是4.有学者把文字的发明作为文明出现的标志之一。
下列所选取的一组甲骨文主要反映了中国古代的A .宗法制B .分封制C .郡县制D .禅让制5. “讳法,自周以前无之,至周公立制。
人生既冠,以字易明。
及有爵者,死而定谥,则固以弥文矣。
后世遵之,其法愈严。
……汉吕后讳雉,改雉名野鸡。
”由此推断,“周公”立“讳法”的真正目的是A .维护皇权的不可僭越B .维护等级制度的尊严C .维护分封制与宗法制D .维护儒家的伦理纲常6.柏杨在《中国人史纲》中写道:“这是一个划时代的突破和最骇人听闻的政治结构,没有封国封爵,没有公侯伯子男。
当时没有一个人敢于想象皇帝的儿子们竟会跟平民一样,竟没有拥有土地,更没有拥有奴隶群。
宜宾市高中2011级第二次诊断性考试题数 学(理工农医类)本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分,第I 卷1至2页,第Ⅱ卷3至8页.满分150分.考试时间120分钟.第Ⅰ卷注意事项:1. 答第Ⅰ卷前,考生务必将自己的姓名、准考证号、考试科目涂写在答题卡上.2. 每小题选出答案后,用铅笔把答题卡上对应题目的答案标号涂黑,如需改动,用橡皮擦干净后,再选涂其它答案,不能答在试题卷上.3. 考试结束后,监考人员将答题卡收回.参考公式 如果事件B A ,互斥,那么球的表面积公式)()()(B P A P B A P +=+; 24R S π=,如果事件B A ,相互独立,那么其中R 表示球的半径. )()()(B P A P B A P ⋅=⋅;球的体积公式如果事件A 在一次试验中发生的概率是P ,那么334R V π=,n 次独立重复试验中恰好发生k 次的概率 其中R 表示球的半径.kn k kn n P P C k P --=)1()(一、选择题。
本大题共12个小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的.1.设全集U={的正整数是小于10x x },A={1,2,3,4,},B={4,5,6,7,8},则(U C A ∪B)= (A ){9} (B) {1,2,3} (C) {5,6,7,8} (D) {1,2,3,4,5,6,7,8}2. 抛物线22x y =的准线方程是 (A )21=x (B )81=y (C )21-=y (D )81-=y 3.i 是虚数单位,计算i i21232321-+=(A) 1 (B) -1 (C) i (D) -i 4.设命题A:“sin θ+cos θ=32”,命题B:“sin2θ=95- ”,则命题A 是命题B 的 (A )充分非必要条件 (B )必要非充分条件(C )充分且必要条件 (D )既非充分也非必要条件(A )2或10 (B )1或0 (C )5或 (D)6. 从4名男生和3名女生中选出4人参加市中学生知识竞赛活动,若这4人中必须既有男生又有女生,不同的选法共有(A )140种 (B )120种 (C )35种 (D )34种 7. 有两个等差数列}{n a 、}{n b ,若3122121++=++++++n n b b b a a a n n ΛΛ,则=33b a( )(A )67 (B )811 (C ) 913 (D )988.已知球的半径为R ,则半球的最大内接正方体的边长为 (A)22R (B )26R (C )36R (D )(12- )R 9. 如图,动点P 在正方体1AC 的对角线1BD 上.过点P 作垂直于平面11BB D D 的直线,与正方体表面相交于M N ,.设BP x =,MN y =,则()y f x =的图象大致是10. 设双曲线22221x y a b-=的渐近线与抛物线21y x =+只有两个公共点,则双曲线的离心率为(A )5 (B)(C)(D) 5411. 设,x y 满足约束条件⎪⎩⎪⎨⎧≥≥≤-+≥+-0,00168044y x y x y x ,若目标函数)08(>>+=a b by ax z 的最大值为5,则b a 21+的最小值为(A )5 (B) 6 (C) 7 (D) 812. 若函数)0()(2≠++=a c bx ax x f 对一切]1,0[∈x ,恒有2)(≤x f ,则a 的最大值为 (A )2 (B) 4 (C) 8 (D) 16ABCD MN P A 1BB 1C 1D 1B 1第Ⅱ卷(非选择题,共90分)注意事项:1.第Ⅱ卷共4页,用蓝、黑的钢笔或圆珠笔直接答在答题卡上.2.答卷前将密封线内的项目填写清楚.二、填空题:本大题共4小题,每小题4分,共16分.请把答案填在答题卡对应的题中横线上.13. 已知622x xp ⎛⎫- ⎪⎝⎭的展开式中的常数项是415,那么常数p 的值是 ▲ .14.πππ--→x xx linx 2sin)(= ▲ .15. .函数d cx bx ax x f +++=23)(的图像如图,)(/x f 为函数)(x f 的导函数,则不等式 0)/<⋅x f x (的解集为 ▲ .16.若函数)(x f 在其定义域内某一区间],[b a 上连续,且对],[b a 中任意实数1x 、2x 都有2)()()2(2121x f x f x x f +≤+,则称函数)(x f 在],[b a 上是下凸函数;有以下几个函数: ①b ax x x f ++=2)(,R x ∈ ②xx x f 1)(+=,)0(∞+∈,x ③x x f sin )(=,)2,0[π∈x ④x x f tan )(=,)2,2(ππ-∈x ⑤x x f 21log )(=,),0(+∞∈x其中是下凸函数的有 ▲ .x请答在答题卡相应的方框内. 17. (本小题满分12分)已知向量a =(cos α,sin α),b =(cos β,sin β),且|a -b|=552. (Ⅰ) 求cos(α-β)的值; (Ⅱ)若02,20<<-<<βππα,且sin β=135-,求sin α.18(本小题满分12分)某校选拔若干名学生组建数学奥林匹克集训队,要求选拔过程分前后两次进行,当第一次选拔合格后方可进入第二次选拔,两次选拔过程相互独立.根据甲、乙、丙三人现有的水平,第一次选拔,甲、乙、丙三人合格的概率依次为5.0,6.0,4.0,第二次选拔,甲、乙、丙三人合格的概率依次为6.0,5.0,5.0。
期末试卷
1 …
…○…………内…………○…………装…………○…………订…………○…………线
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班级 姓名 考号 考场号
富县高级中学2011-2012学年度第二学期阶段性检测
高二(文)数学试卷
注意:本试卷第Ⅰ、Ⅱ卷均答在答题卡上,满分100分,时间100分钟。
第Ⅰ卷(选择题 共40分)
一、选择题(每小题4分,共40分) 1、下列关系式中不正确的是( )
A 0∈∅
B {}0∈∅
C {}0=∅
D {}0∅⊆ 2.在①1⊆{0,1,2};②{1}∈{0,1,2};③{0,1,2}⊆{0,1,2}; ④、φ{0}
上述四个关系中,错误的个数是( )
A 、1个
B 、2个
C 、3个
D 、4个 3.已知全集
}
12|{≤≤-=x x U ,
}
12|{<<-=x x A ,
}
02|{2
=-+=x x x B ,
}12|{<≤-=x x C ,则( )
A 、A C ⊆
B 、 A
C C U ⊆ C 、C B C U =
D 、B
A C U =
4.已知集合}1|{≤=x x M ,}|{t x x P >=,若φ≠P M ,则实数t 应该满足的条件是( )
A 、1>t
B 、1≥t
C 、1<t
D 、1≤t 5.下列不等式在a 、b >0时一定成立的是( )
A.
b
a ab
+2≤
ab
≤
2
b
a +≤
2
2
2b
a + B
ab
≤b
a a
b +2≤
2
b
a +≤
2
2
2b
a +
C ab ≤2
b
a +≤
b a ab
+2≤
2
2
2b
a + D a
b ≤b a ab
+2≤
2
2
2b
a +≤2b
a +
6.已知集合P=
{}
2
|2,y y x
x R =-+∈,Q={
}
|2,y y x x R =-+∈,那么P Q 等于
( )
A 、 (0,2),(1,1)
B 、 {(0,2 ),(1,1)}
C 、 {1,2}
D 、 {
}
|2y y ≤
7.数i z i z -=+=1,321,则21z z z ⋅=在复平面内的对应点位于( )
A .第一象限
B .第二象限
C .第三象限
D .第四象限 8.已知复数
i
m m m m z )23()2(2
2
+-+--=对应的点位于复平面的虚轴上,
则实数 m 为( )
A. 1
B. –1或 2
C. -1
D. 2
9. 2005
32i i i i ++++ 的值等于 ( )
A. 1 B .–1 C. i D. i -
10.设a , b 为实数,且a +b =3,则22a b
+的最小值是( )
A 6
B 42
C 22
D 26
第Ⅱ卷(非选择题 共60分)
二、填空题(每空4分,共16分)
11. 已知集合A={a ,b ,2},B={2,2b ,2a }且,A =B ,则a = 12. 不等式|x+10|-|x-2|≥8的解集是
13. 已知lgx +lgy =2,则
x
1+
y
1的最小值是
14.(考生注意:请在下列三题中任选一题作答,如果多做,则按所做的第一题
2
评阅记分)
A.(不等式选做题)若不等式a ≤|x+1 |+|x-2| 对任意的x R ∈恒成立,则实数a 的取值范围是
B.(几何证明选做题)如图PAB 、PCD 为O 的两条割线,
若5,7,11,2,PA AB CD AC ==== 则BD 等于去
C.(坐标系与参数方程选做题)曲线cos 1sin x y α
α
=⎧⎨
=+⎩(α为参
数)与曲线22cos 0ρρθ-=的交点个数为 三、解答题(本题包括 4小题,共 44 分)
15.(本题10分)已知:0,x <求证:
(x+3)(x-5)>(x+5)(x-3)
16. (本题12分) 解下列绝对值不等式:(1)4210x --< (2)234x x -≤+ (3)21325x x ++-≥
17. (本题12分)用分析法证明:15223
>
-+。
18. (本题10分)已知n N ∈且1n >,用放缩法证明:1111 (2)
3
n n
+
+
++
>
P
C
D
B
A O
∙。