【全国市级联考Word】辽宁省辽阳市2017-2018学年高二下学期期末考试数学(文)试题
- 格式:doc
- 大小:4.57 MB
- 文档页数:13
辽宁省辽阳市2017-2018学年高二英语下学期期末考试试题(考试时间:100分钟试卷满分:120分)第一部分阅读理解(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)阅读下列短文,从每题所给的A、B、C和D四个选项中,选出最佳选项。
AWelcome to Amazon. Here are some top films to recommend this week.MagellanScores 5.5101 min 2017When NASA picks up three outer space signals coming from within our own solar system, the space agency speeds a mission to investigate the sources. As Earth’s lone messenger, they send Commander Roger Nelson, the test pilot for an experimental spacecraft called the Magellan, assisted by an on board A. I. named Ferdinand.Rent Movie HD $3.99Buy Movie HD $9.99The Lost City of ZScores 6.6141 min 2016The Lost City of Z tells the unbelievable true story of British explorer Percy Fawcett, who journeys into the Amazon at the beginning of the 20th century and discovers evidence of a formerly unkown and advanced civilization that may have once ruled the region.Rent Movie HD $6.99Buy Movie HD $19.99The PostScores 7.2115 min 2017Steven Spielberg, Tom Hanks and Meryl Streep team for the first time in this exciting true story about how the Washington Post uncovered a huge cover-up of government secrets that lastedthree decades. It made Richard Milhous Nixon, the president of the United States of the time, lose his power in the end.Rent Movie HD $5.99.Buy Movie HD $19.99RoomScores 8.2117 min 2015Both highly suspenseful and deeply emotional, Room is a unique and unexpectedly gentle exploration of the endless love between a mother and her child. After 5-year-old Jack and his Ma escape from the closed surroundings that Jack has known in his entire life, the boy makes a thrilling discovery: the outside world.Rent Movie HD $3.99Buy Movie HD $12.991. Which film lasts the shortest time?A. Magellan.B. The Lost City of Z.C. The Post.D. Room.2. Which films are based on true stories?A. Magellan and The Post.B. The Post and The Lost City of Z.C. The Lost City of Z and Room.D. Room and Magellan.3. The Post would probably attract audiences who love ________.A. adventuring outdoorsB. exploring outer spaceC. discussing politicsD. studying human natureBWhat a lesson for me! It was August and it was hot. I had to wear a tie to do a survey door by door in this neighbourhood, but I was always refused. I finally caught on and began with “Before you close the door, I am not selling anything and I just need to ask a few questions about yourself and the community”.The young woman inside the doorway stopped for a moment, confused by my rude introduction and finally said, “Sure. Come on in. Don’t mind the mess. It’s hard to keep up with my kids.”“I just need to ask a few questions about yourself and your family. Although this may sound。
高二数学期末试题(文科)第Ⅰ卷(共60分)一、选择题:本大题共12个小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的.1.设命题,则为()A. B.C. D.【答案】D【解析】分析:根据全称命题的否定解答.详解:由全称命题的否定得为:,故答案为:D.点睛:(1)本题主要考查全称命题的否定,意在考查学生对这些知识的掌握水平.(2) 全称命题:,全称命题的否定():.2.已知集合,则中元素的个数为()A. B. C. D.【答案】B【解析】分析:先化简集合B,再求中元素的个数.详解:由题得B={-2,-1,0},所以={0},故中元素的个数为1,故答案为:B.点睛:(1)本题主要考查集合的化简和集合的交集运算,意在考查学生对这些知识的掌握水平.(2)解答集合的题目时,首先要看集合“|”前集合元素的一般形式,如,表示的是函数的值域. 集合表示的是函数的定义域.3.复数在复平面内对应的点位于()A. 第一象限B. 第二象限C. 第三象限D. 第四象限【答案】A【解析】分析:先化简复数z,再看复数z在复平面内对应的点所在的象限.详解:由题得,所以复数z在复平面内对应的点为(2,4),故答案为:A.点睛:(1)本题主要考查复数的运算和复数的几何意义,意在考查学生对这些知识的掌握水平.(2) 复数对应的点是(a,b),点(a,b)所在的象限就是复数对应的点所在的象限.复数和点(a,b)是一一对应的关系.4.下列四个函数中,在上为减函数的是()A. B.C. D.【答案】A【解析】分析:直接画出每一个选项对应的函数的图像,即得解.详解:对于选项A,函数的图像的对称轴为开口向上,所以函数在上为减函数.所以选项A是正确的.对于选项B,在在上为增函数,所以选项B是错误的. 对于选项C,在在上为增函数,所以选项C是错误的.对于选项D,,当x=0时,没有意义,所以选项D是错误的.故答案为:A.点睛:本题主要考查函数的图像和性质,意在考查学生对这些知识的掌握水平和数形结合的思想方法.5.已知函数,若,则()A. B. C. D.【答案】D【解析】分析:首先根据题意,将自变量的值代入函数解析式,利用对数式和指数式的运算性质,求得关于的等量关系式,从而求得结果.详解:根据题意得,即,解得,故选D.点睛:该题考查的是有关已知函数值,求自变量的问题,在解题的过程中,需要将相关量代入解析式,得到参数所满足的条件,求解即可得结果.6.函数在区间上的最小值为()A. B. C. D.【答案】D【解析】分析:先求导得到函数的单调性,即得函数的最小值.详解:由题得,因为x∈,所以所以函数f(x)在上单调递减,所以,故答案为:D.点睛:(1)本题主要考查求导和利用导数求函数的最值,意在考查学生对这些知识的掌握水平.(2)一般地,函数在某个区间可导,<0 在这个区间是减函数.7.“”是“”成立的()A. 充分不必要条件B. 必要不充分条件C. 充要条件D. 既不充分也不必要条件【答案】B【解析】由,解得,所以“”是“”成立的必要不充分条件.故选B.8.现有下面三个命题:常数数列既是等差数列也是等比数列;:,;:椭圆的离心率为.下列命题中为假命题的是()A. B. C. D.【答案】C【解析】分析:首先将题中所给的几个命题的真假作出判断,根据0常数列是等差数列但不是等比数列,得到是真命题,根据二次式和对数式的性质,可得是真命题,求出椭圆的离心率,可得是假命题,之后根据复合命题真值表得到结果.详解:,常数均为0的数列是等差数列,不是等比数列,故其为假命题;,当时,,所以,,故其为真命题;,椭圆表示焦点在轴上的椭圆,且,所以,所以其离心率,故其为假命题,所以为真命题,为真命题,为假命题,为真命题,故选C.点睛:该题考查的是有关命题的真假判断,所涉及到的知识点有简单命题的真假判断和复合命题的真假判断,而要判断复合命题的真假,对于三个简单命题的真值必须要作出正确判断,这就要求平时对基础知识要牢固掌握.9.“已知函数,求证:与中至少有一个不少于.”用反证法证明这个命题时,下列假设正确的是()A. 假设且B. 假设且C. 假设与中至多有一个不小于D. 假设与中至少有一个不大于【答案】B【解析】分析:因为与中至少有一个不少于的否定是且,所以选B.详解:因为与中至少有一个不少于的否定是且,故答案为:B.点睛:(1)本题主要考查反证法,意在考查学生对这些知识的掌握水平.(2)两个数中至少有一个大于等于a的否定是两个数都小于a.10.设,则()A. B. C. D.【答案】B【解析】分析:先判断b是负数,再分析出a<1,c>1,即得解.详解:由题得,,.故答案为:B.点睛:(1)本题主要考查实数大小的比较和对数函数的图像和性质,意在考查学生对这些知识的掌握水平.(2)比较实数的大小,一般先把所有的数分成正数和负数两个集合,再把正数和1比较,负数和“-1”比较.11.函数的大致图象为()A. B. C. D.【答案】A【解析】∵,∴函数为奇函数,排除B,D.又,故排除C,故选:A点睛:识图常用的方法(1)定性分析法:通过对问题进行定性的分析,从而得出图象的上升(或下降)的趋势,利用这一特征分析解决问题;(2)定量计算法:通过定量的计算来分析解决问题;(3)函数模型法:由所提供的图象特征,联想相关函数模型,利用这一函数模型来分析解决问题.12.已知函数有个零点,则的取值范围是()A. B.C. D.【答案】D【解析】分析:先构造函数,再利用导数求函数g(x)的单调区间和最值,再通过数形结合分析得到a的取值范围.详解:设,所以,所以函数g(x)的单调增区间为,单调减区间为,所以.当时,当即时,的图像和y=a-1有两个零点.故答案为:D.点睛:(1)本题主要考查利用导数求函数的最值,考查利用导数研究函数的零点问题,意在考查学生对这些知识的掌握水平和分析推理能力数形结合的思想方法.(2)零点问题的处理常用的方法有方程法、图像法和方程+图像法,本题利用的是方程+图像法.第Ⅱ卷(共90分)二、填空题(每题5分,满分20分,将答案填在答题纸上)13.若函数,则__________.【答案】2【解析】分析:先求导,再令x=1即得解.详解:由题得故答案为:2.点睛:本题主要考查函数的求导,意在考查学生对该知识的掌握水平.14.已知函数,则__________.【答案】【解析】分析:先计算,再计算的值.详解:由题得=所以故答案为:.点睛:(1)本题主要考查分段函数求值和对数指数的化简求值,意在考查学生对这些知识的掌握水平和基本运算能力.(2)分段函数求值,一般从里往外.15.设复数满足,则的虚部为__________.【答案】-7【解析】分析:先求出复数z,再求z的虚部.详解:由题得,所以z的虚部为-7,故答案为:-7.点睛:(1)本题主要考查复数的运算和复数的虚部概念,意在考查学生对这些知识的掌握水平和基本的运算能力.(2) 复数的实部是a,虚部为b,不是bi.16.甲、乙、丙三位同学被问到是否去过三个城市时,甲说:我没去过城市;乙说:我去过的城市比甲多,但没去过城市;丙说:我们三人去过同一城市,由此可判断甲去过的城市为__________.【答案】A【解析】分析:一般利用假设分析法,找到甲去过的城市.详解:假设甲去过的城市为A,则乙去过的城市为A,C,丙去过A城市.假设甲去过的城市为B时,则乙说的不正确,所以甲去过城市不能为B.故答案为:A.点睛:(1)本题主要考查推理证明,意在考查学生对该知识的掌握水平和推理能力.(2)类似本题的题目,一般都是利用假设分析推理法找到答案.三、解答题(本大题共6小题,共70分.解答应写出文字说明、证明过程或演算步骤.)17.已知复数.(1)若是纯虚数,求;(2)若,求.【答案】(1);(2)或1-2i.【解析】分析:(1)根据纯虚数的定义得到,解不等式组即得a的值.(2)由题得,解之得a的值,再求.详解:(1)若是纯虚数,则,所以(2)因为,所以,所以或.当时,,当时,.点睛:(1)本题主要考查复数的概念、复数的模和共轭复数,意在考查学生对这些知识的掌握水平和基本的运算能力.(2) 复数为纯虚数不要把下面的b≠0漏掉了.18.已知函数在区间上是减函数;关于的不等式无解.如果“”为假,“”为真,求的取值范围.【答案】【解析】分析:先化简命题p,q得到m的取值范围,再分析“”为假,“”为真时,命题p,q的真假情况,得到m 的不等式组,解之得m的取值范围.详解:若为真,则对称轴,即若为真,则,即,解得因为“”为假,“”为真,所以一真一假.若真假,则,得或若真假,则,得综上,所以或,即的取值范围是.点睛:(1)本题主要考查复合命题真假的判定,意在考查学生对这些知识的掌握水平和分析推理能力.(2)复合命题真假判定的口诀:真“非”假,假“非”真,一真“或”为真,两真“且”才真.19.(1)在平面上,若两个正方形的边长的比为,则它们的面积比为.类似地,在空间中,对应的结论是什么?(2)已知数列满足,求,并由此归纳得出的通项公式(无需证明).【答案】(1)见解析;(2)见解析.【解析】分析:(1)利用类比推理得到若两正方体的棱长的比为,则它们的体积之比为.(2)先根据递推式得到的值,再归纳出.详解:(1)对应的结论为:若两正方体的棱长的比为,则它们的体积之比为.(2)由,得,由此可归纳得到.点睛:(1)本题主要考查类比推理和不完全归纳法,意在考查学生对这些知识的掌握水平.(2)在平面中类比时,长度的比与面积的比一般类比为空间长度的比与体积的比.20.市某机构为了调查该市市民对我国申办2034年足球世界杯的态度,随机选取了位市民进行调查,调查结果统计如下:(1)根据已知数据把表格数据填写完整;(2)利用(1)完成的表格数据回答下列问题:(i)能否有的把握认为支持申办足球世界杯与性别有关;(ii)已知在被调查的支持申办足球世界杯的男性市民中有位退休老人,其中位是教师,现从这位退体老人中随机抽取人,求至多有位老师的概率.参考公式:,其中.参考数据:【答案】(1)见解析;(2)(i)有的把握认为支持申办足球世界杯与性别有关.(ii).【解析】分析:(1)根据已知数据的关系把表格数据填写完整.(2) (i)利用公式求出,再根据参考数据表判定能否有的把握认为支持申办足球世界杯与性别有关. (ii)利用古典概型求至多有位老师的概率.详解:(1)(2)(i)由已知数据可求得所以有的把握认为支持申办足球世界杯与性别有关.(ii)从人中任意取人的情况有种,其中至多有位教师的情况有种,故所求的概率.点睛:(1)本题主要考查独立性检验和古典概型,意在考查学生对这些知识的掌握能力和解决实际问题的能力.(2) 古典概型的解题步骤:①求出试验的总的基本事件数;②求出事件A所包含的基本事件数;③代公式=.21.已知函数.(1)当,求函数的单调区间;(2)若函数在上是减函数,求的最小值;【答案】(1)的单调递减区间是,单调递增区间是;(2).【解析】分析:(1)先求导,再利用导数求函数的单调区间.(2)先转化为在上恒成立,再转化为,再求≤0,即得a的最小值.详解:函数的定义域为,(1)函数,当且时,;当时,,所以函数的单调递减区间是,单调递增区间是(2)因在上为减函数,故在上恒成立.所以当时,,又,故当,即时,.所以,于是,故的最小值为.点睛:(1)本题主要考查导数求函数的单调区间,考查导数解决恒成立问题,考查利用导数求函数的最值,意在考查学生对这些知识的掌握水平和分析转化推理能力.(2)解答本题的关键有两点,其一是转化为,其二是利用二次函数求得.请考生在22、23两题中任选一题作答,如果多做,则按所做的第一题记分.22.选修4-4:坐标系与参数方程设直线的参数方程为(为参数),以坐标原点为极点,轴的正半轴为极轴建立极坐标系,曲线的极坐标方程为.(1)把曲线的极坐标方程化为直角坐标方程;(2)设直线与曲线交于两点,点,求的值.【答案】(1);(2).【解析】分析:(1)直接利用极坐标公式把曲线的极坐标方程化为直角坐标方程.(2)利用直线参数方程t的几何意义解答,求的值.详解:(1)由曲线的极坐标方程为,即,可得直角坐标方程.(2)把直线的参数方程(为参数)代入曲线的直角坐标方程可得∴.∴.点睛:(1)本题主要考查极坐标和直角坐标的互化,考查直线参数方程t的几何意义,意在考查学生对这些知识的掌握水平和转化能力.(2)过定点、倾斜角为的直线的参数方程(为参数).当动点在定点上方时,. 当动点在定点下方时,.23.已知函数.(1)求不等式的解集;(2)若对恒成立,求的取值范围.【答案】(1);(2)【解析】试题分析:(1)根据“零点分段法”分为,,三种情形,分别解出不等式,再取并集即可;(2)法一:对恒成立等价于对恒成立,利用绝对值三角不等式,求得取得最小值,即可求得的取值范围;法二:设,则,根据绝对值三角不等式求得得最小值,从而求得的取值范围.试题解析:(1)因为,所以当时,由得;当时,由得;当时,由得.综上,的解集为.(2)法一:由得,因为,当且仅当取等号,所以当时,取得最小值.所以当时,取得最小值,故,即的取值范围为.法二:设,则,当时,取得最小值,所以当时,取得最小值,故时,即的取值范围为.点睛:含绝对值不等式的解法法一:利用绝对值不等式的几何意义求解,体现了数形结合的思想;法二:利用“零点分段法”求解,体现了分类讨论的思想;法三:通过构造函数,利用函数的图象求解,体现了函数与方程的思想.。
辽宁省辽阳市2017-2018学年高二英语下学期期末考试试题(考试时间:100分钟试卷满分:120分)第一部分阅读理解(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)阅读下列短文,从每题所给的A、B、C和D四个选项中,选出最佳选项。
AWelcome to Amazon. Here are some top films to recommend this week.MagellanScores 5.5101 min 2017When NASA picks up three outer space signals coming from within our own solar system, the space agency speeds a mission to investigate the sources. As Earth’s lone messenger, they send Commander Roger Nelson, the test pilot for an experimental spacecraft called the Magellan, assisted by an on board A. I. named Ferdinand.Rent Movie HD $3.99Buy Movie HD $9.99The Lost City of ZScores 6.6141 min 2016The Lost City of Z tells the unbelievable true story of British explorer Percy Fawcett, who journeys into the Amazon at the beginning of the 20th century and discovers evidence of a formerly unkown and advanced civilization that may have once ruled the region.Rent Movie HD $6.99Buy Movie HD $19.99The PostScores 7.2115 min 2017Steven Spielberg, Tom Hanks and Meryl Streep team for the first time in this exciting true story about how the Washington Post uncovered a huge cover-up of government secrets that lastedthree decades. It made Richard Milhous Nixon, the president of the United States of the time, lose his power in the end.Rent Movie HD $5.99.Buy Movie HD $19.99RoomScores 8.2117 min 2015Both highly suspenseful and deeply emotional, Room is a unique and unexpectedly gentle exploration of the endless love between a mother and her child. After 5-year-old Jack and his Ma escape from the closed surroundings that Jack has known in his entire life, the boy makes a thrilling discovery: the outside world.Rent Movie HD $3.99Buy Movie HD $12.991. Which film lasts the shortest time?A. Magellan.B. The Lost City of Z.C. The Post.D. Room.2. Which films are based on true stories?A. Magellan and The Post.B. The Post and The Lost City of Z.C. The Lost City of Z and Room.D. Room and Magellan.3. The Post would probably attract audiences who love ________.A. adventuring outdoorsB. exploring outer spaceC. discussing politicsD. studying human natureBWhat a lesson for me! It was August and it was hot. I had to wear a tie to do a survey door by door in this neighbourhood, but I was always refused. I finally caught on and began with “Before you close the door, I am not selling anything and I just need to ask a few questions about yourself and the community”.The young woman inside the doorway stopped for a moment, confused by my rude introduction and finally said, “Sure. Come on in. Don’t mind the mess. It’s hard to keep up with my kids.”“I just need to ask a few questions about yourself and your family. Although this may soundpersonal, I won’t need to use your names. This information will be used.” She interrupted me. “Would you like a glass of cold water? You look like you’ve had a rough day.”“Why yes!” I said gratefully. Just as she returned with the water, a man came walking in the front door. It was her husband. “Joe, this man is here to do a survey.”I stood and politely introduced myself.“Joe works for the town,” she said. “What do you do?” I asked. She jumped right in not letting him answer. “Joe collects garbage. You know I’m so proud of him.”There was a silence. I didn’t know what to say. I shook my head searching for the right words. “That’s unbelievable! Most people would not be satisfied with a job like that. It certainly is a difficult one. But your attitude about it is amazing.” I said.She walked over to the shelf. As she returned she held a small framed(装裱)paper, walking toward Joe. “I have always been proud of him and always will be. You see I don’t think the job makes the man, but the man makes the job!” she said as she handed me the paper.It said: If a man is called to be a cleaner, he should clean streets so well that all the hosts of heaven and earth will pause to say, “Here lived a great cleaner who did his job well.”4. Why did the author change his introduction?A. To relieve his stress.B. To look for some water.C. To do his survey smoothly.D. To know about the bad situation.5. What can we learn about the young woman?A. She finds a good job in the city.B. She has a great talent for argument.C. She doesn’t live a life as she dreams.D. She has a positive attitude towards Joe’s job.6. What can we infer from Paragraph 6?A. The Young woman will be with Joe forever.B. The Young woman is proud of her job.C. Any job can be done better by heart.D. Any job can change a person.7. What is the best title for the text?A. A Beneficial Experience of SurveyB. The Pleasure from JobsC. AA Great Street CleanerD. The Power of LaborCScience is always advancing over time. A self-driving car from the Google may be coming to a street near you. However, you won’t be able to buy it now. “We’re working to build the world’s most experienced driver,” Kraft, director of the project, said. “Everything that we learn in one of our cars gets passed to all of our cars. But you may need to get over the idea of traditional car ownership along the way.”Google’s software has already driven 5 million miles in U.S. cities, including an “early rider” test in Phoenix last April. Since then Google has grown confident enough to remove the “auxiliary wheel”: a human “safety driver”. Powering the vehicle’s self-driving functions is a series of cameras, radars and sensors on the car’s roof, which detect everything nearby from other vehicles and passers-by to cyclists.Kraft stressed that Google’s cars aren’t connected—they don’t need a 5G wireless link to go anywhere. “The car has everything it needs to drive on the car itself.” He said, “There are no signals coming from outer space or something telling it to turn right.” The resulting ride may not be too exciting but safe. Kraft added. “We can see three football fields down the road, we would come to a stop before we ran into these crowds.”Google’s system has a major advantage over the semi-autonomous(半自主的)systems of Tesla and Cadillac, both of which need continued human attention. Kraft said Google plans to have service in every major city by 2028 with thousands of cars driving themselves.8. What does the underlined words “auxiliary wheels” in Paragraph 2 refer to?A. A car that is very old.B. A driver who has been trained well.C. A part of a car used to sound the alarm.D. A condition where a driver doesn’t know his role.9. Why is Google’s car thought to be safe in the text?A. Because it can get away from danger easily.B. Because it is equipped with 5G wireless link.C. Because it can stop before the crowds occasionally.D. Because it can keep a safe distance from everything nearby.10. What can we learn from the text?A. Google’s software has not been tested.B. Google’s cars have not been put into the market.C. Driving the Google’s car may not be too exciting.D. Google’s cars still need driver’s attention all the way.11. What does the author think of the Google’s car?A. It’s affordable.B. It’s still a theory.C. It has a bright future.D. It’s the most advanced by now.DAre you using a dating App to make friends? How do you know that Ben from London is really 25-year-old? Is his photo taken recently? Is his name even Ben? Dating apps can be tricky to operate, particularly when you’re trying to know whether someone is trustworthy, but one thing you can’t cheat is your gene, which is why a new dating app is using DNA as a basis for its match.A dating app named Pheramor requires all users to hand in a cheek sample, from which a team of in-house scientists using a specially-created tool can queue the specific genes connected with attraction and then identify which users might be suitable. The process works by separating the 11 genes that link to our pheromones(信息素), the chemical signals that are believed to control; one’s attraction. Combining this data with the personal information allows the app to make very specific matches.“Pheramor uses both your biology and your social technology: we collect your genetic data through a cheek sample and collect your like, dislikes, and interest from your social media introductions like Facebook, Twitter, etc,” the app’s website explains. “All of them will be used in our specific software, which is designed to learn what you prefer.”The co-founder Brittany Barreto, who has a PHD in genetics added that Pheramor’s technology digs deeper than traditional dating apps, making it almost impossible for people to cheat theirway to a date.The Houston-based app is already up and running but hopes to be officially put into market in February with 3,000 members.12. What do we know about the new dating app according to Paragraph 1?A. It can be operated easily by users.B. It can know others’ trustworthiness.C. It can select information on the website.D. It can use DNA to make matches for users.13. What is Paragraph 2 mainly about?A. What Pheramor is.B. How Pheramor works.C. How scientists deal with the data.D. How the genes are connected with attraction.14. What will be used in Pheramor to learn the users’ preference?A. Attraction and pheromones.B. Pheromones and genetic data.C. Social technology and attraction.D. Genetic data and social media introductions.15. What is the author’s purpose in writing the text?A. To introduce a safe dating app.B. To explore the future of the app.C. To avoid unreasonable requirements.D. To teach people how to design apps.第二节(共5小题;每小题2分,满分10分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。
辽宁省辽阳市2017-2018学年高二下学期期末考试地理试题第Ⅰ卷本卷共25小题。
每小题2分,共50分。
在每个小题给出的四个选项中,只有一项是符合题目要求的。
河南登封观星台(34°N,113°E)上有两间小屋,小屋之间有一横梁,台下有一长堤。
每天正午,横梁的影子会投射在长堤上。
读下图,完成下列各题。
1. 每天横梁的影子投射在长堤上时,北京时间是A. 12:28B. 11:32C. 12:32D. 12:002. 下列日期中,横梁在长堤上的影子距观星台最近的日期是A. 春分日B. 夏至日C. 秋分日D. 冬至日3. 长堤位于观星台的A. 东侧B. 南侧C. 西侧D. 北侧【答案】1. A 2. B 3. D【解析】1. 每天横梁的影子投射在长堤上时,地方时是12点,该地经度是113°E,北京时间是120°E经线的地方时,经度每差1°,时间相差4分钟,北京时间是12:28,A对。
B、C、D错。
2. 横梁在长堤上的影子距观星台最近,说明正午太阳高度角最大,根据纬度,该地位于北温带,夏至日正午太阳高度角最大,B对。
A、C、D错。
3. 北温带,正午物体影子朝向正北方,正午横梁影子落在长堤上,说明长堤位于观星台的北侧,D对。
A、B、C错。
北京时间2017年9月6日17:10太阳连续发生两次剧烈的耀斑爆发,其中第二次耀斑爆发是近十多年来最强烈的一次,其强度达到惊人的X9.3级。
据此完成下列各题。
4. 耀斑发生在太阳圈层中的A. 光球层B. 太阳内部C. 日冕层D. 色球层5. 耀斑强烈爆发对地球产生的直接影响是A. 全球变暖,海平面上升B. 北极地区可能在夜晚看到极光C. 有利于无线电短波通信D. 导致珠穆朗玛峰雪线下降【答案】4. D 5. B【解析】4. 太阳大气由外而内分别是日冕、色球层、光球层。
太阳活动的表现形式有黑子、耀斑、日珥和太阳风。
黑子出现在光球层,耀斑和日珥出现在色球层,太阳风出现在日冕。
辽宁省辽阳市2017-2018学年高二英语下学期期末考试试题(考试时间:100分钟试卷满分:120分)第一部分阅读理解(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)阅读下列短文,从每题所给的A、B、C和D四个选项中,选出最佳选项。
AWelcome to Amazon. Here are some top films to recommend this week.MagellanScores 5.5101 min 2017When NASA picks up three outer space signals coming from within our own solar system, the space agency speeds a mission to investigate the sources. As Earth’s lone messenger, they send Commander Roger Nelson, the test pilot for an experimental spacecraft called the Magellan, assisted by an on board A. I. named Ferdinand.Rent Movie HD $3.99Buy Movie HD $9.99The Lost City of ZScores 6.6141 min 2016The Lost City of Z tells the unbelievable true story of British explorer Percy Fawcett, who journeys into the Amazon at the beginning of the 20th century and discovers evidence of a formerly unkown and advanced civilization that may have once ruled the region.Rent Movie HD $6.99Buy Movie HD $19.99The PostScores 7.2115 min 2017Steven Spielberg, Tom Hanks and Meryl Streep team for the first time in this exciting true story about how the Washington Post uncovered a huge cover-up of government secrets that lastedthree decades. It made Richard Milhous Nixon, the president of the United States of the time, lose his power in the end.Rent Movie HD $5.99.Buy Movie HD $19.99RoomScores 8.2117 min 2015Both highly suspenseful and deeply emotional, Room is a unique and unexpectedly gentle exploration of the endless love between a mother and her child. After 5-year-old Jack and his Ma escape from the closed surroundings that Jack has known in his entire life, the boy makes a thrilling discovery: the outside world.Rent Movie HD $3.99Buy Movie HD $12.991. Which film lasts the shortest time?A. Magellan.B. The Lost City of Z.C. The Post.D. Room.2. Which films are based on true stories?A. Magellan and The Post.B. The Post and The Lost City of Z.C. The Lost City of Z and Room.D. Room and Magellan.3. The Post would probably attract audiences who love ________.A. adventuring outdoorsB. exploring outer spaceC. discussing politicsD. studying human natureBWhat a lesson for me! It was August and it was hot. I had to wear a tie to do a survey door by door in this neighbourhood, but I was always refused. I finally caught on and began with “Before you close the door, I am not selling anything and I just need to ask a few questions about yourself and the community”.The young woman inside the doorway stopped for a moment, confused by my rude introduction and finally said, “Sure. Come on in. Don’t mind the mess. It’s hard to keep up with my kids.”“I just need to ask a few questions about yourself and your family. Although this may soundpersonal, I won’t need to use your names. This information will be used.” She interrupted me. “Would you like a glass of cold water? You look like you’ve had a rough day.”“Why yes!” I said gratefully. Just as she returned with the water, a man came walking in the front door. It was her husband. “Joe, this man is here to do a survey.”I stood and politely introduced myself.“Joe works for the town,” she said. “What do you do?” I asked. She jumped right in not letting him answer. “Joe collects garbage. You know I’m so proud of him.”There was a silence. I didn’t know what to say. I shook my head searching for the right words. “That’s unbelievable! Most people would not be satisfied with a job like that. It certainly is a difficult one. But your attitude about it is amazing.” I said.She walked over to the shelf. As she returned she held a small framed(装裱)paper, walking toward Joe. “I have always been proud of him and always will be. You see I don’t think the job makes the man, but the man makes the job!” she said as she handed me the paper.It said: If a man is called to be a cleaner, he should clean streets so well that all the hosts of heaven and earth will pause to say, “Here lived a great cleaner who did his job well.”4. Why did the author change his introduction?A. To relieve his stress.B. To look for some water.C. To do his survey smoothly.D. To know about the bad situation.5. What can we learn about the young woman?A. She finds a good job in the city.B. She has a great talent for argument.C. She doesn’t live a life as she dreams.D. She has a positive attitude towards Joe’s job.6. What can we infer from Paragraph 6?A. The Young woman will be with Joe forever.B. The Young woman is proud of her job.C. Any job can be done better by heart.D. Any job can change a person.7. What is the best title for the text?A. A Beneficial Experience of SurveyB. The Pleasure from JobsC. AA Great Street CleanerD. The Power of LaborCScience is always advancing over time. A self-driving car from the Google may be coming to a street near you. However, you won’t be able to buy it now. “We’re working to build the world’s most experienced driver,” Kraft, director of the project, said. “Everything that we learn in one of our cars gets passed to all of our cars. But you may need to get over the idea of traditional car ownership along the way.”Google’s software has already driven 5 million miles in U.S. cities, including an “early rider” test in Phoenix last April. Since then Google has grown confident enough to remove the “auxiliary wheel”: a human “safety driver”. Powering the vehicle’s self-driving functions is a series of cameras, radars and sensors on the car’s roof, which detect everything nearby from other vehicles and passers-by to cyclists.Kraft stressed that Google’s cars aren’t connected—they don’t need a 5G wireless link to go anywhere. “The car has everything it needs to drive on the car itself.” He said, “There are no signals coming from outer space or something telling it to turn right.” The resulting ride may not be too exciting but safe. Kraft added. “We can see three football fields down the road, we would come to a stop before we ran into these crowds.”Google’s system has a major advantage over the semi-autonomous(半自主的)systems of Tesla and Cadillac, both of which need continued human attention. Kraft said Google plans to have service in every major city by 2028 with thousands of cars driving themselves.8. What does the underlined words “auxiliary wheels” in Paragraph 2 refer to?A. A car that is very old.B. A driver who has been trained well.C. A part of a car used to sound the alarm.D. A condition where a driver doesn’t know his role.9. Why is Google’s car thought to be safe in the text?A. Because it can get away from danger easily.B. Because it is equipped with 5G wireless link.C. Because it can stop before the crowds occasionally.D. Because it can keep a safe distance from everything nearby.10. What can we learn from the text?A. Google’s software has not been tested.B. Google’s cars have not been put into the market.C. Driving the Google’s car may not be too exciting.D. Google’s cars still need driver’s attention all the way.11. What does the author think of the Google’s car?A. It’s affordable.B. It’s still a theory.C. It has a bright future.D. It’s the most advanced by now.DAre you using a dating App to make friends? How do you know that Ben from London is really 25-year-old? Is his photo taken recently? Is his name even Ben? Dating apps can be tricky to operate, particularly when you’re trying to know whether someone is trustworthy, but one thing you can’t cheat is your gene, which is why a new dating app is using DNA as a basis for its match.A dating app named Pheramor requires all users to hand in a cheek sample, from which a team of in-house scientists using a specially-created tool can queue the specific genes connected with attraction and then identify which users might be suitable. The process works by separating the 11 genes that link to our pheromones(信息素), the chemical signals that are believed to control; one’s attraction. Combining this data with the personal information allows the app to make very specific matches.“Pheramor uses both your biology and your social technology: we collect your genetic data through a cheek sample and collect your like, dislikes, and interest from your social media introductions like Facebook, Twitter, etc,” the app’s website explains. “All of them will be used in our specific software, which is designed to learn what you prefer.”The co-founder Brittany Barreto, who has a PHD in genetics added that Pheramor’s technology digs deeper than traditional dating apps, making it almost impossible for people to cheat theirway to a date.The Houston-based app is already up and running but hopes to be officially put into market in February with 3,000 members.12. What do we know about the new dating app according to Paragraph 1?A. It can be operated easily by users.B. It can know others’ trustworthiness.C. It can select information on the website.D. It can use DNA to make matches for users.13. What is Paragraph 2 mainly about?A. What Pheramor is.B. How Pheramor works.C. How scientists deal with the data.D. How the genes are connected with attraction.14. What will be used in Pheramor to learn the users’ preference?A. Attraction and pheromones.B. Pheromones and genetic data.C. Social technology and attraction.D. Genetic data and social media introductions.15. What is the author’s purpose in writing the text?A. To introduce a safe dating app.B. To explore the future of the app.C. To avoid unreasonable requirements.D. To teach people how to design apps.第二节(共5小题;每小题2分,满分10分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。
高二数学期末试题(文科)第Ⅰ卷(共60分)一、选择题:本大题共12个小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的.1.设命题,则为()A. B.C. D.【答案】D【解析】分析:根据全称命题的否定解答.详解:由全称命题的否定得为:,故答案为:D.点睛:(1)本题主要考查全称命题的否定,意在考查学生对这些知识的掌握水平.(2) 全称命题:,全称命题的否定():.2.已知集合,则中元素的个数为()A. B. C. D.【答案】B【解析】分析:先化简集合B,再求中元素的个数.详解:由题得B={-2,-1,0},所以={0},故中元素的个数为1,故答案为:B.点睛:(1)本题主要考查集合的化简和集合的交集运算,意在考查学生对这些知识的掌握水平.(2)解答集合的题目时,首先要看集合“|”前集合元素的一般形式,如,表示的是函数的值域. 集合表示的是函数的定义域.3.复数在复平面内对应的点位于()A. 第一象限B. 第二象限C. 第三象限D. 第四象限【答案】A【解析】分析:先化简复数z,再看复数z在复平面内对应的点所在的象限.详解:由题得,所以复数z在复平面内对应的点为(2,4),故答案为:A.点睛:(1)本题主要考查复数的运算和复数的几何意义,意在考查学生对这些知识的掌握水平.(2) 复数对应的点是(a,b),点(a,b)所在的象限就是复数对应的点所在的象限.复数和点(a,b)是一一对应的关系.4.下列四个函数中,在上为减函数的是()A. B.C. D.【答案】A【解析】分析:直接画出每一个选项对应的函数的图像,即得解.详解:对于选项A,函数的图像的对称轴为开口向上,所以函数在上为减函数.所以选项A是正确的.对于选项B,在在上为增函数,所以选项B是错误的. 对于选项C,在在上为增函数,所以选项C是错误的.对于选项D,,当x=0时,没有意义,所以选项D是错误的.故答案为:A.点睛:本题主要考查函数的图像和性质,意在考查学生对这些知识的掌握水平和数形结合的思想方法.5.已知函数,若,则()A. B. C. D.【答案】D【解析】分析:首先根据题意,将自变量的值代入函数解析式,利用对数式和指数式的运算性质,求得关于的等量关系式,从而求得结果.详解:根据题意得,即,解得,故选D.点睛:该题考查的是有关已知函数值,求自变量的问题,在解题的过程中,需要将相关量代入解析式,得到参数所满足的条件,求解即可得结果.6.函数在区间上的最小值为()A. B. C. D.【答案】D【解析】分析:先求导得到函数的单调性,即得函数的最小值.详解:由题得,因为x∈,所以所以函数f(x)在上单调递减,所以,故答案为:D.点睛:(1)本题主要考查求导和利用导数求函数的最值,意在考查学生对这些知识的掌握水平.(2)一般地,函数在某个区间可导,<0 在这个区间是减函数.7.“”是“”成立的()A. 充分不必要条件B. 必要不充分条件C. 充要条件D. 既不充分也不必要条件【答案】B【解析】由,解得,所以“”是“”成立的必要不充分条件.故选B.8.现有下面三个命题:常数数列既是等差数列也是等比数列;:,;:椭圆的离心率为.下列命题中为假命题的是()A. B. C. D.【答案】C【解析】分析:首先将题中所给的几个命题的真假作出判断,根据0常数列是等差数列但不是等比数列,得到是真命题,根据二次式和对数式的性质,可得是真命题,求出椭圆的离心率,可得是假命题,之后根据复合命题真值表得到结果.详解:,常数均为0的数列是等差数列,不是等比数列,故其为假命题;,当时,,所以,,故其为真命题;,椭圆表示焦点在轴上的椭圆,且,所以,所以其离心率,故其为假命题,所以为真命题,为真命题,为假命题,为真命题,故选C.点睛:该题考查的是有关命题的真假判断,所涉及到的知识点有简单命题的真假判断和复合命题的真假判断,而要判断复合命题的真假,对于三个简单命题的真值必须要作出正确判断,这就要求平时对基础知识要牢固掌握.9.“已知函数,求证:与中至少有一个不少于.”用反证法证明这个命题时,下列假设正确的是()A. 假设且B. 假设且C. 假设与中至多有一个不小于D. 假设与中至少有一个不大于【答案】B【解析】分析:因为与中至少有一个不少于的否定是且,所以选B.详解:因为与中至少有一个不少于的否定是且,故答案为:B.点睛:(1)本题主要考查反证法,意在考查学生对这些知识的掌握水平.(2)两个数中至少有一个大于等于a的否定是两个数都小于a.10.设,则()A. B. C. D.【答案】B【解析】分析:先判断b是负数,再分析出a<1,c>1,即得解.详解:由题得,,.故答案为:B.点睛:(1)本题主要考查实数大小的比较和对数函数的图像和性质,意在考查学生对这些知识的掌握水平.(2)比较实数的大小,一般先把所有的数分成正数和负数两个集合,再把正数和1比较,负数和“-1”比较. 11.函数的大致图象为()A. B. C. D.【答案】A【解析】∵,∴函数为奇函数,排除B,D.又,故排除C,故选:A点睛:识图常用的方法(1)定性分析法:通过对问题进行定性的分析,从而得出图象的上升(或下降)的趋势,利用这一特征分析解决问题;(2)定量计算法:通过定量的计算来分析解决问题;(3)函数模型法:由所提供的图象特征,联想相关函数模型,利用这一函数模型来分析解决问题.12.已知函数有个零点,则的取值范围是()A. B.C. D.【答案】D【解析】分析:先构造函数,再利用导数求函数g(x)的单调区间和最值,再通过数形结合分析得到a的取值范围.详解:设,所以,所以函数g(x)的单调增区间为,单调减区间为,所以.当时,当即时,的图像和y=a-1有两个零点.故答案为:D.点睛:(1)本题主要考查利用导数求函数的最值,考查利用导数研究函数的零点问题,意在考查学生对这些知识的掌握水平和分析推理能力数形结合的思想方法.(2)零点问题的处理常用的方法有方程法、图像法和方程+图像法,本题利用的是方程+图像法.第Ⅱ卷(共90分)二、填空题(每题5分,满分20分,将答案填在答题纸上)13.若函数,则__________.【答案】2【解析】分析:先求导,再令x=1即得解.详解:由题得故答案为:2.点睛:本题主要考查函数的求导,意在考查学生对该知识的掌握水平.14.已知函数,则__________.【答案】【解析】分析:先计算,再计算的值.详解:由题得=所以故答案为:.点睛:(1)本题主要考查分段函数求值和对数指数的化简求值,意在考查学生对这些知识的掌握水平和基本运算能力.(2)分段函数求值,一般从里往外.15.设复数满足,则的虚部为__________.【答案】-7【解析】分析:先求出复数z,再求z的虚部.详解:由题得,所以z的虚部为-7,故答案为:-7.点睛:(1)本题主要考查复数的运算和复数的虚部概念,意在考查学生对这些知识的掌握水平和基本的运算能力.(2) 复数的实部是a,虚部为b,不是bi.16.甲、乙、丙三位同学被问到是否去过三个城市时,甲说:我没去过城市;乙说:我去过的城市比甲多,但没去过城市;丙说:我们三人去过同一城市,由此可判断甲去过的城市为__________.【答案】A【解析】分析:一般利用假设分析法,找到甲去过的城市.详解:假设甲去过的城市为A,则乙去过的城市为A,C,丙去过A城市.假设甲去过的城市为B时,则乙说的不正确,所以甲去过城市不能为B.故答案为:A.点睛:(1)本题主要考查推理证明,意在考查学生对该知识的掌握水平和推理能力.(2)类似本题的题目,一般都是利用假设分析推理法找到答案.三、解答题(本大题共6小题,共70分.解答应写出文字说明、证明过程或演算步骤.)17.已知复数.(1)若是纯虚数,求;(2)若,求.【答案】(1);(2)或1-2i.【解析】分析:(1)根据纯虚数的定义得到,解不等式组即得a的值.(2)由题得,解之得a的值,再求.详解:(1)若是纯虚数,则,所以(2)因为,所以,所以或.当时,,当时,.点睛:(1)本题主要考查复数的概念、复数的模和共轭复数,意在考查学生对这些知识的掌握水平和基本的运算能力.(2) 复数为纯虚数不要把下面的b≠0漏掉了.18.已知函数在区间上是减函数;关于的不等式无解.如果“”为假,“”为真,求的取值范围.【答案】【解析】分析:先化简命题p,q得到m的取值范围,再分析“”为假,“”为真时,命题p,q的真假情况,得到m的不等式组,解之得m的取值范围.详解:若为真,则对称轴,即若为真,则,即,解得因为“”为假,“”为真,所以一真一假.若真假,则,得或若真假,则,得综上,所以或,即的取值范围是.点睛:(1)本题主要考查复合命题真假的判定,意在考查学生对这些知识的掌握水平和分析推理能力.(2)复合命题真假判定的口诀:真“非”假,假“非”真,一真“或”为真,两真“且”才真.19.(1)在平面上,若两个正方形的边长的比为,则它们的面积比为.类似地,在空间中,对应的结论是什么?(2)已知数列满足,求,并由此归纳得出的通项公式(无需证明). 【答案】(1)见解析;(2)见解析.【解析】分析:(1)利用类比推理得到若两正方体的棱长的比为,则它们的体积之比为.(2)先根据递推式得到的值,再归纳出.详解:(1)对应的结论为:若两正方体的棱长的比为,则它们的体积之比为.(2)由,得,由此可归纳得到.点睛:(1)本题主要考查类比推理和不完全归纳法,意在考查学生对这些知识的掌握水平.(2)在平面中类比时,长度的比与面积的比一般类比为空间长度的比与体积的比.20.市某机构为了调查该市市民对我国申办2034年足球世界杯的态度,随机选取了位市民进行调查,调查结果统计如下:(1)根据已知数据把表格数据填写完整;(2)利用(1)完成的表格数据回答下列问题:(i)能否有的把握认为支持申办足球世界杯与性别有关;(ii)已知在被调查的支持申办足球世界杯的男性市民中有位退休老人,其中位是教师,现从这位退体老人中随机抽取人,求至多有位老师的概率.参考公式:,其中.参考数据:【答案】(1)见解析;(2)(i)有的把握认为支持申办足球世界杯与性别有关.(ii).【解析】分析:(1)根据已知数据的关系把表格数据填写完整.(2) (i)利用公式求出,再根据参考数据表判定能否有的把握认为支持申办足球世界杯与性别有关. (ii)利用古典概型求至多有位老师的概率.详解:(1)(2)(i)由已知数据可求得所以有的把握认为支持申办足球世界杯与性别有关.(ii)从人中任意取人的情况有种,其中至多有位教师的情况有种,故所求的概率.点睛:(1)本题主要考查独立性检验和古典概型,意在考查学生对这些知识的掌握能力和解决实际问题的能力.(2) 古典概型的解题步骤:①求出试验的总的基本事件数;②求出事件A所包含的基本事件数;③代公式=.21.已知函数.(1)当,求函数的单调区间;(2)若函数在上是减函数,求的最小值;【答案】(1)的单调递减区间是,单调递增区间是;(2).【解析】分析:(1)先求导,再利用导数求函数的单调区间.(2)先转化为在上恒成立,再转化为,再求≤0,即得a的最小值.详解:函数的定义域为,(1)函数,当且时,;当时,,所以函数的单调递减区间是,单调递增区间是(2)因在上为减函数,故在上恒成立.所以当时,,又,故当,即时,.所以,于是,故的最小值为.点睛:(1)本题主要考查导数求函数的单调区间,考查导数解决恒成立问题,考查利用导数求函数的最值,意在考查学生对这些知识的掌握水平和分析转化推理能力.(2)解答本题的关键有两点,其一是转化为,其二是利用二次函数求得.请考生在22、23两题中任选一题作答,如果多做,则按所做的第一题记分.22.选修4-4:坐标系与参数方程设直线的参数方程为(为参数),以坐标原点为极点,轴的正半轴为极轴建立极坐标系,曲线的极坐标方程为.(1)把曲线的极坐标方程化为直角坐标方程;(2)设直线与曲线交于两点,点,求的值.【答案】(1);(2).【解析】分析:(1)直接利用极坐标公式把曲线的极坐标方程化为直角坐标方程.(2)利用直线参数方程t的几何意义解答,求的值.详解:(1)由曲线的极坐标方程为,即,可得直角坐标方程.(2)把直线的参数方程(为参数)代入曲线的直角坐标方程可得∴.∴.点睛:(1)本题主要考查极坐标和直角坐标的互化,考查直线参数方程t的几何意义,意在考查学生对这些知识的掌握水平和转化能力.(2)过定点、倾斜角为的直线的参数方程(为参数).当动点在定点上方时,. 当动点在定点下方时,.23.已知函数.(1)求不等式的解集;(2)若对恒成立,求的取值范围.【答案】(1);(2)【解析】试题分析:(1)根据“零点分段法”分为,,三种情形,分别解出不等式,再取并集即可;(2)法一:对恒成立等价于对恒成立,利用绝对值三角不等式,求得取得最小值,即可求得的取值范围;法二:设,则,根据绝对值三角不等式求得得最小值,从而求得的取值范围.试题解析:(1)因为,所以当时,由得;当时,由得;当时,由得.综上,的解集为.(2)法一:由得,因为,当且仅当取等号,所以当时,取得最小值.所以当时,取得最小值,故,即的取值范围为.法二:设,则,当时,取得最小值,所以当时,取得最小值,故时,即的取值范围为.点睛:含绝对值不等式的解法法一:利用绝对值不等式的几何意义求解,体现了数形结合的思想;法二:利用“零点分段法”求解,体现了分类讨论的思想;法三:通过构造函数,利用函数的图象求解,体现了函数与方程的思想.。
辽宁省辽阳市2017-2018学年高二下学期英语期末考试试卷一、阅读理解(共4题;共30分)1.(6分)阅读理解Welcome to Amazon.Here are some top films to recommend this week.MagellanScores5.5101min2017When NASA picks up three outer space signals coming from within our own solar system,the space agency speeds a mission to investigate the sources.As Earth's lone messenger,they send Commander Roger Nelson,the test pilot for an experimental spacecraft called the Magellan,assisted by an on board d Ferdinand.Rent Movie HD$3.99Buy Movie HD$9.99The Lost City of ZScores6.6141min2016The Lost City of Z tells the unbelievable true story of British explorer Percy Fawcett,who journeys into the Amazon at the beginning of the20th century and discovers evidence of a formerly unkown and advanced civilization that may have once ruled the region.Rent Movie HD$6.99Buy Movie HD$19.99The PostScores7.2115min2017Steven Spielberg,Tom Hanks and Meryl Streep team for the first time in this exciting true story about how the Washington Post uncovered a huge cover-up of government secrets that lasted three decades. It made Richard Milhous Nixon,the president of the United States of the time,lose his power in the end.Rent Movie HD$5.99.Buy Movie HD$19.99RoomScores8.2117min2015Both highly suspenseful and deeply emotional,Room is a unique and unexpectedly gentle exploration of the endless love between a mother and her child.After5-year-old Jack and his Ma escape from the closed surroundings that Jack has known in his entire life,the boy makes a thrilling discovery:the outside world.Rent Movie HD$3.99Buy Movie HD$12.99(1)(2分)Which film lasts the shortest time?A.Magellan.B.The Lost City of Z.C.The Post.D.Room.(2)(2分)Which films are based on true stories?A.Magellan and The Post.B.The Post and The Lost City of Z.C.The Lost City of Z and Room.D.Room and Magellan.(3)(2分)The Post would probably attract audiences who love________.A.adventuring outdoors B.exploring outer spaceC.discussing politics D.studying human nature2.(8分)阅读理解What a lesson for me!It was August and it was hot.I had to wear a tie to do a survey door by door in this neighbourhood,but I was always refused.I finally caught on and began with“Before you close the door, I am not selling anything and I just need to ask a few questions about yourself and the community”.The young woman inside the doorway stopped for a moment,confused by my rude introduction and finally said,“e on in.Don't mind the mess.It's hard to keep up with my kids.”“I just need to ask a few questions about yourself and your family.Although this may sound personal, I won't need to use your names.This information will be used.”She interrupted me.“Would you like a glass of cold water?You look like you've had a rough day.”“Why yes!”I said gratefully.Just as she returned with the water,a man came walking in the front door.It was her husband.“Joe,this man is here to do a survey.”I stood and politely introduced myself.“Joe works for the town,”she said.“What do you do?”I asked.She jumped right in not letting him answer.“Joe collects garbage.You know I'm so proud of him.”There was a silence.I didn't know what to say.I shook my head searching for the right words.“That's unbelievable!Most people would not be satisfied with a job like that.It certainly is a difficult one. But your attitude about it is amazing.”I said.She walked over to the shelf.As she returned she held a small framed(装裱)paper,walking toward Joe.“I have always been proud of him and always will be.You see I don't think the job makes the man,but the man makes the job!”she said as she handed me the paper.It said:If a man is called to be a cleaner,he should clean streets so well that all the hosts of heaven and earth will pause to say,“Here lived a great cleaner who did his job well.”(1)(2分)Why did the author change his introduction?A.To relieve his stress.B.To look for some water.C.To do his survey smoothly.D.To know about the bad situation.(2)(2分)What can we learn about the young woman?A.She finds a good job in the city.B.She has a great talent for argument.C.She doesn't live a life as she dreams.D.She has a positive attitude towards Joe's job.(3)(2分)What can we infer from Paragraph6?A.The Young woman will be with Joe forever.B.The Young woman is proud of her job.C.Any job can be done better by heart.D.Any job can change a person.(4)(2分)What is the best title for the text?A.A Beneficial Experience of Survey B.The Pleasure from JobsC.AA Great Street Cleaner D.The Power of Labor3.(8分)阅读理解Science is always advancing over time.A self-driving car from the Google may be coming to a street near you.However,you won't be able to buy it now.“We're working to build the world's most experienced driver,”Kraft,director of the project,said.“Everything that we learn in one of our cars gets passed to all of our cars.But you may need to get over the idea of traditional car ownership along the way.”Google's software has already driven5million miles in U.S.cities,including an“early rider”test inPhoenix last April.Since then Google has grown confident enough to remove the“auxiliary wheel”:a human “safety driver”.Powering the vehicle's self-driving functions is a series of cameras,radars and sensors on the car's roof,which detect everything nearby from other vehicles and passers-by to cyclists.Kraft stressed that Google's cars aren't connected—they don't need a5G wireless link to go anywhere.“The car has everything it needs to drive on the car itself.”He said,“There are no signals coming from outer space or something telling it to turn right.”The resulting ride may not be too exciting but safe. Kraft added.“We can see three football fields down the road,we would come to a stop before we ran into these crowds.”Google's system has a major advantage over the semi-autonomous(半自主的)systems of Tesla and Cadillac,both of which need continued human attention.Kraft said Google plans to have service in every major city by2028with thousands of cars driving themselves.(1)(2分)What does the underlined words“auxiliary wheels”in Paragraph2refer to?A.A car that is very old.B.A driver who has been trained well.C.A part of a car used to sound the alarm.D.A condition where a driver doesn't know his role.(2)(2分)Why is Google's car thought to be safe in the text?A.Because it can get away from danger easily.B.Because it is equipped with5G wireless link.C.Because it can stop before the crowds occasionally.D.Because it can keep a safe distance from everything nearby.(3)(2分)What can we learn from the text?A.Google's software has not been tested.B.Google's cars have not been put into the market.C.Driving the Google's car may not be too exciting.D.Google's cars still need driver's attention all the way.(4)(2分)What does the author think of the Google's car?A.It's affordable.B.It's still a theory.C.It has a bright future.D.It's the most advanced by now.4.(8分)阅读理解Are you using a dating App to make friends?How do you know that Ben from London is really25-year-old?Is his photo taken recently?Is his name even Ben?Dating apps can be tricky to operate, particularly when you're trying to know whether someone is trustworthy,but one thing you can't cheat is your gene,which is why a new dating app is using DNA as a basis for its match.A dating app named Pheramor requires all users to hand in a cheek sample,from which a team ofin-house scientists using a specially-created tool can queue the specific genes connected with attraction and then identify which users might be suitable.The process works by separating the11genes that link to our pheromones(信息素),the chemical signals that are believed to control one's bining this data with the personal information allows the app to make very specific matches.“Pheramor uses both your biology and your social technology:we collect your genetic data through a cheek sample and collect your like,dislikes,and interest from your social media introductions like Facebook,Twitter,etc,”the app's website explains.“All of them will be used in our specific software,which is designed to learn what you prefer.”The co-founder Brittany Barreto,who has a PHD in genetics added that Pheramor's technology digs deeper than traditional dating apps,making it almost impossible for people to cheat their way to a date.The Houston-based app is already up and running but hopes to be officially put into market in February with3,000members.(1)(2分)What do we know about the new dating app according to Paragraph1?A.It can be operated easily by users.B.It can know others'trustworthiness.C.It can select information on the website.D.It can use DNA to make matches for users.(2)(2分)What is Paragraph2mainly about?A.What Pheramor is.B.How Pheramor works.C.How scientists deal with the data.D.How the genes are connected with attraction.(3)(2分)What will be used in Pheramor to learn the users'preference?A.Attraction and pheromones.B.Pheromones and genetic data.C.Social technology and attraction.D.Genetic data and social media introductions.(4)(2分)What is the author's purpose in writing the text?A.To introduce a safe dating app.B.To explore the future of the app.C.To avoid unreasonable requirements.D.To teach people how to design apps.二、任务型阅读(共1题;共10分)5.(10分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项,故答案选项中有两项为多余选项。
辽宁省辽阳市2017-2018学年高二下学期期末考试物理试题一、选择题1. 小华将一网球从高处竖直向下抛出,网球从地面上反弹竖直上升到高处被接住,从抛出到接住共历时,下列有关网球整个运动过程的说法,正确的是()A. 网球走过的路程为B. 网球的位移大小为C. 题中提到的是时刻D. 研究网球在运动过程中的转动情况时可以把网球看成质点【答案】A【解析】A. 网球通过的路程为运动轨迹的长度,故大小为1+1.5m=2.5m,故A正确;B.位移大小是从初位置到末位置的有向线段的长度,为0.5m,故B错误;C. 题中提到的0.6s是时间间隔,故C错误;D. 研究网球在运动过程中的转动情况时,形状不能忽略,故不可以把网球看成质点,故D错误;故选:A。
2. 关于光,下列说法正确的是()A. 光在水中的传播速度大于在空气中的传播速度B. 树荫下的太阳光班大多成圆形是因为光的衍射C. 透过竖直放置的肥皂膜看竖直的日光灯,能看到彩色干涉条纹D. 当光在水面上发生反射时,反射光是偏振光【答案】D..................B.树荫下的太阳光班大多成圆形是太阳通过小孔在地上成的像,是因为光的直线传播,故B错误;C.透过竖直放置的肥皂膜看水平放置的日光灯,能看到彩色干涉条纹,这是薄膜干涉,故C错误;D.光在水面上发生反射时,反射光是偏振光,故D正确。
故选:D3. 关于光电效应,下列说法正确的是()A. 光电子的最大初动能与入射光的频率成正比B. 光的频率一定时,入射光越强,饱和电流越大C. 光的频率一定时,入射光越强,遏止电压越大D. 光子能量与光的速度成正比【答案】B【解析】根据光电效应方程,得知光电子的最大初动能与入射光的频率、金属的逸出功都有关,与入射光的强度无关,。
但是最大初动能不与入射光的频率成正比。
所以A错误。
又根据知遏止电压与光的频率有光,与光的强度无关。
所以C错。
而如果光的频率一定,入射光越强,则饱和光电流越大。
高二数学期末试题(文科)第Ⅰ卷(共60分)一、选择题:本大题共12个小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的.1.设命题,则为()A. B.C. D.【答案】D【解析】分析:根据全称命题的否定解答.详解:由全称命题的否定得为:,故答案为:D.点睛:(1)本题主要考查全称命题的否定,意在考查学生对这些知识的掌握水平.(2) 全称命题:,全称命题的否定():.2.已知集合,则中元素的个数为()A. B. C. D.【答案】B【解析】分析:先化简集合B,再求中元素的个数.详解:由题得B={-2,-1,0},所以={0},故中元素的个数为1,故答案为:B.点睛:(1)本题主要考查集合的化简和集合的交集运算,意在考查学生对这些知识的掌握水平.(2)解答集合的题目时,首先要看集合“|”前集合元素的一般形式,如,表示的是函数的值域. 集合表示的是函数的定义域.3.复数在复平面内对应的点位于()A. 第一象限B. 第二象限C. 第三象限D. 第四象限【答案】A【解析】分析:先化简复数z,再看复数z在复平面内对应的点所在的象限.详解:由题得,所以复数z在复平面内对应的点为(2,4),故答案为:A. 点睛:(1)本题主要考查复数的运算和复数的几何意义,意在考查学生对这些知识的掌握水平.(2) 复数对应的点是(a,b),点(a,b)所在的象限就是复数对应的点所在的象限.复数和点(a,b)是一一对应的关系.4.下列四个函数中,在上为减函数的是()A. B.C. D.【答案】A【解析】分析:直接画出每一个选项对应的函数的图像,即得解.详解:对于选项A,函数的图像的对称轴为开口向上,所以函数在上为减函数.所以选项A是正确的.对于选项B,在在上为增函数,所以选项B是错误的. 对于选项C,在在上为增函数,所以选项C是错误的.对于选项D,,当x=0时,没有意义,所以选项D是错误的.故答案为:A.点睛:本题主要考查函数的图像和性质,意在考查学生对这些知识的掌握水平和数形结合的思想方法.5.已知函数,若,则()A. B. C. D.【答案】D【解析】分析:首先根据题意,将自变量的值代入函数解析式,利用对数式和指数式的运算性质,求得关于的等量关系式,从而求得结果.详解:根据题意得,即,解得,故选D.点睛:该题考查的是有关已知函数值,求自变量的问题,在解题的过程中,需要将相关量代入解析式,得到参数所满足的条件,求解即可得结果.6.函数在区间上的最小值为()A. B. C. D.【答案】D【解析】分析:先求导得到函数的单调性,即得函数的最小值.详解:由题得,因为x∈,所以所以函数f(x)在上单调递减,所以,故答案为:D.点睛:(1)本题主要考查求导和利用导数求函数的最值,意在考查学生对这些知识的掌握水平.(2)一般地,函数在某个区间可导,<0 在这个区间是减函数.7.“”是“”成立的()A. 充分不必要条件B. 必要不充分条件C. 充要条件D. 既不充分也不必要条件【答案】B【解析】由,解得,所以“”是“”成立的必要不充分条件.故选B.8.现有下面三个命题:常数数列既是等差数列也是等比数列;:,;:椭圆的离心率为.下列命题中为假命题的是()A. B. C. D.【答案】C【解析】分析:首先将题中所给的几个命题的真假作出判断,根据0常数列是等差数列但不是等比数列,得到是真命题,根据二次式和对数式的性质,可得是真命题,求出椭圆的离心率,可得是假命题,之后根据复合命题真值表得到结果.详解:,常数均为0的数列是等差数列,不是等比数列,故其为假命题;,当时,,所以,,故其为真命题;,椭圆表示焦点在轴上的椭圆,且,所以,所以其离心率,故其为假命题,所以为真命题,为真命题,为假命题,为真命题,故选C. 点睛:该题考查的是有关命题的真假判断,所涉及到的知识点有简单命题的真假判断和复合命题的真假判断,而要判断复合命题的真假,对于三个简单命题的真值必须要作出正确判断,这就要求平时对基础知识要牢固掌握.9.“已知函数,求证:与中至少有一个不少于.”用反证法证明这个命题时,下列假设正确的是()A. 假设且B. 假设且C. 假设与中至多有一个不小于D. 假设与中至少有一个不大于【答案】B【解析】分析:因为与中至少有一个不少于的否定是且,所以选B.详解:因为与中至少有一个不少于的否定是且,故答案为:B.点睛:(1)本题主要考查反证法,意在考查学生对这些知识的掌握水平.(2)两个数中至少有一个大于等于a 的否定是两个数都小于a.10.设,则()A. B. C. D.【答案】B【解析】分析:先判断b是负数,再分析出a<1,c>1,即得解.详解:由题得,,.故答案为:B.点睛:(1)本题主要考查实数大小的比较和对数函数的图像和性质,意在考查学生对这些知识的掌握水平.(2)比较实数的大小,一般先把所有的数分成正数和负数两个集合,再把正数和1比较,负数和“-1”比较.11.函数的大致图象为( )A. B. C. D.【答案】A 【解析】∵,∴函数为奇函数,排除B ,D.又,故排除C ,故选:A点睛:识图常用的方法(1)定性分析法:通过对问题进行定性的分析,从而得出图象的上升(或下降)的趋势,利用这一特征分析解决问题;(2)定量计算法:通过定量的计算来分析解决问题;(3)函数模型法:由所提供的图象特征,联想相关函数模型,利用这一函数模型来分析解决问题. 12.已知函数有个零点,则的取值范围是( )A. B.C. D.【答案】D 【解析】 分析:先构造函数,再利用导数求函数g(x)的单调区间和最值,再通过数形结合分析得到a 的取值范围.详解:设,所以,所以函数g(x)的单调增区间为,单调减区间为,所以.当时,当即时,的图像和y=a-1有两个零点.故答案为:D.点睛:(1)本题主要考查利用导数求函数的最值,考查利用导数研究函数的零点问题,意在考查学生对这些知识的掌握水平和分析推理能力数形结合的思想方法.(2)零点问题的处理常用的方法有方程法、图像法和方程+图像法,本题利用的是方程+图像法.第Ⅱ卷(共90分)二、填空题(每题5分,满分20分,将答案填在答题纸上)13.若函数,则__________.【答案】2【解析】分析:先求导,再令x=1即得解.详解:由题得故答案为:2.点睛:本题主要考查函数的求导,意在考查学生对该知识的掌握水平.14.已知函数,则__________.【答案】【解析】分析:先计算,再计算的值.详解:由题得=所以故答案为:.点睛:(1)本题主要考查分段函数求值和对数指数的化简求值,意在考查学生对这些知识的掌握水平和基本运算能力.(2)分段函数求值,一般从里往外.15.设复数满足,则的虚部为__________.【答案】-7【解析】分析:先求出复数z,再求z的虚部.详解:由题得,所以z的虚部为-7,故答案为:-7.点睛:(1)本题主要考查复数的运算和复数的虚部概念,意在考查学生对这些知识的掌握水平和基本的运算能力.(2) 复数的实部是a,虚部为b,不是bi.16.甲、乙、丙三位同学被问到是否去过三个城市时,甲说:我没去过城市;乙说:我去过的城市比甲多,但没去过城市;丙说:我们三人去过同一城市,由此可判断甲去过的城市为__________.【答案】A【解析】分析:一般利用假设分析法,找到甲去过的城市.详解:假设甲去过的城市为A,则乙去过的城市为A,C,丙去过A城市.假设甲去过的城市为B时,则乙说的不正确,所以甲去过城市不能为B.故答案为:A.点睛:(1)本题主要考查推理证明,意在考查学生对该知识的掌握水平和推理能力.(2)类似本题的题目,一般都是利用假设分析推理法找到答案.三、解答题(本大题共6小题,共70分.解答应写出文字说明、证明过程或演算步骤.)17.已知复数.(1)若是纯虚数,求;(2)若,求.【答案】(1);(2)或1-2i.【解析】分析:(1)根据纯虚数的定义得到,解不等式组即得a的值.(2)由题得,解之得a 的值,再求.详解:(1)若是纯虚数,则,所以(2)因为,所以,所以或.当时,,当时,.点睛:(1)本题主要考查复数的概念、复数的模和共轭复数,意在考查学生对这些知识的掌握水平和基本的运算能力.(2) 复数为纯虚数不要把下面的b≠0漏掉了.18.已知函数在区间上是减函数;关于的不等式无解.如果“”为假,“”为真,求的取值范围.【答案】【解析】分析:先化简命题p,q得到m的取值范围,再分析“”为假,“”为真时,命题p,q的真假情况,得到m的不等式组,解之得m的取值范围.详解:若为真,则对称轴,即若为真,则,即,解得因为“”为假,“”为真,所以一真一假.若真假,则,得或若真假,则,得综上,所以或,即的取值范围是.点睛:(1)本题主要考查复合命题真假的判定,意在考查学生对这些知识的掌握水平和分析推理能力.(2)复合命题真假判定的口诀:真“非”假,假“非”真,一真“或”为真,两真“且”才真.19.(1)在平面上,若两个正方形的边长的比为,则它们的面积比为.类似地,在空间中,对应的结论是什么?(2)已知数列满足,求,并由此归纳得出的通项公式(无需证明). 【答案】(1)见解析;(2)见解析.【解析】分析:(1)利用类比推理得到若两正方体的棱长的比为,则它们的体积之比为.(2)先根据递推式得到的值,再归纳出.详解:(1)对应的结论为:若两正方体的棱长的比为,则它们的体积之比为.(2)由,得,由此可归纳得到.点睛:(1)本题主要考查类比推理和不完全归纳法,意在考查学生对这些知识的掌握水平.(2)在平面中类比时,长度的比与面积的比一般类比为空间长度的比与体积的比.20.市某机构为了调查该市市民对我国申办2034年足球世界杯的态度,随机选取了位市民进行调查,调查结果统计如下:(1)根据已知数据把表格数据填写完整;(2)利用(1)完成的表格数据回答下列问题:(i)能否有的把握认为支持申办足球世界杯与性别有关;(ii)已知在被调查的支持申办足球世界杯的男性市民中有位退休老人,其中位是教师,现从这位退体老人中随机抽取人,求至多有位老师的概率.参考公式:,其中.参考数据:【答案】(1)见解析;(2)(i)有的把握认为支持申办足球世界杯与性别有关.(ii).【解析】分析:(1)根据已知数据的关系把表格数据填写完整.(2) (i)利用公式求出,再根据参考数据表判定能否有的把握认为支持申办足球世界杯与性别有关. (ii)利用古典概型求至多有位老师的概率.详解:(1)(2)(i)由已知数据可求得所以有的把握认为支持申办足球世界杯与性别有关.(ii)从人中任意取人的情况有种,其中至多有位教师的情况有种,故所求的概率.点睛:(1)本题主要考查独立性检验和古典概型,意在考查学生对这些知识的掌握能力和解决实际问题的能力.(2) 古典概型的解题步骤:①求出试验的总的基本事件数;②求出事件A所包含的基本事件数;③代公式=.21.已知函数.(1)当,求函数的单调区间;(2)若函数在上是减函数,求的最小值;【答案】(1)的单调递减区间是,单调递增区间是;(2).【解析】分析:(1)先求导,再利用导数求函数的单调区间.(2)先转化为在上恒成立,再转化为,再求≤0,即得a的最小值.详解:函数的定义域为,(1)函数,当且时,;当时,,所以函数的单调递减区间是,单调递增区间是(2)因在上为减函数,故在上恒成立.所以当时,,又,故当,即时,.所以,于是,故的最小值为.点睛:(1)本题主要考查导数求函数的单调区间,考查导数解决恒成立问题,考查利用导数求函数的最值,意在考查学生对这些知识的掌握水平和分析转化推理能力.(2)解答本题的关键有两点,其一是转化为,其二是利用二次函数求得.请考生在22、23两题中任选一题作答,如果多做,则按所做的第一题记分.22.选修4-4:坐标系与参数方程设直线的参数方程为(为参数),以坐标原点为极点,轴的正半轴为极轴建立极坐标系,曲线的极坐标方程为.(1)把曲线的极坐标方程化为直角坐标方程;(2)设直线与曲线交于两点,点,求的值.【答案】(1);(2).【解析】分析:(1)直接利用极坐标公式把曲线的极坐标方程化为直角坐标方程.(2)利用直线参数方程t的几何意义解答,求的值.详解:(1)由曲线的极坐标方程为,即,可得直角坐标方程.(2)把直线的参数方程(为参数)代入曲线的直角坐标方程可得∴.∴.点睛:(1)本题主要考查极坐标和直角坐标的互化,考查直线参数方程t的几何意义,意在考查学生对这些知识的掌握水平和转化能力.(2)过定点、倾斜角为的直线的参数方程(为参数).当动点在定点上方时,. 当动点在定点下方时,.23.已知函数.(1)求不等式的解集;(2)若对恒成立,求的取值范围.【答案】(1);(2)【解析】试题分析:(1)根据“零点分段法”分为,,三种情形,分别解出不等式,再取并集即可;(2)法一:对恒成立等价于对恒成立,利用绝对值三角不等式,求得取得最小值,即可求得的取值范围;法二:设,则,根据绝对值三角不等式求得得最小值,从而求得的取值范围.试题解析:(1)因为,所以当时,由得;当时,由得;当时,由得.综上,的解集为.(2)法一:由得,因为,当且仅当取等号,所以当时,取得最小值.所以当时,取得最小值,故,即的取值范围为.法二:设,则,当时,取得最小值,所以当时,取得最小值,故时,即的取值范围为.点睛:含绝对值不等式的解法法一:利用绝对值不等式的几何意义求解,体现了数形结合的思想;法二:利用“零点分段法”求解,体现了分类讨论的思想;法三:通过构造函数,利用函数的图象求解,体现了函数与方程的思想.。
高二数学期末试题(文科)第Ⅰ卷(共60分)一、选择题:本大题共12个小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的.1.设命题2:,10p x R x ∀∈+>,则p ⌝为( )A .200,10x R x ∃∈+> B .2,10x R x ∀∈+≤C .200,10x R x ∃∈+<D .200,10x R x ∃∈+≤2.已知集合{}{}11,31A x R x B x Z x =∈-<≤=∈-<<,则A B ⋂中元素的个数为()A .0B .1C .2D .33.复数()()131z i i =-+-在复平面内对应的点位于( )A .第一象限B .第二象限C .第三象限D .第四象限4.下列四个函数中,在(],0-∞上为减函数的是( )A .()22f x x x =-B .()2f x x =-C .()1f x x =+D .()1f x x =5.已知函数()f x =,若()3log f a =,则a =( )A .13B .14C .12 D .26.函数()sin f x x x =-在区间[]0,1上的最小值为( )A .0B .sin1 C.1 D .sin11-7.“1x <”是“ln 0x <”的( )A .充分不必要条件B .必要不充分条件C.充要条件 D .既不充分也不必要条件8.现有下面三个命题1:p 常数数列既是等差数列也是等比数列;()22020:,log 10p x R x ∃∈+≤;3:p 椭圆2213y x +=下列命题中为假命题的是( )A .12p p ∨B .()()12p p ⌝∨⌝C. ()13p p ⌝∧ D .()()23p p ⌝∨⌝9.“已知函数()()2f x x ax a a R =++∈,求证:()1f 与()2f 中至少有一个不少于12.”用反证法证明这个命题时,下列假设正确的是( )A .假设()112f ≥且()122f ≥ B .假设()112f <且()122f < C. 假设()1f 与()2f 中至多有一个不小于12D .假设()1f 与()2f 中至少有一个不大于1210.设3123log 2,log 2,log 3a b c ===,则( ) A .a c b >> B .c a b >> C.c b a >> D .b c a >>11.函数()444x x x f x -=-的大致图象为( ) A . B .C. D .12.已知函数()()31x f x x e a =--+有2个零点,则a 的取值范围是( )A .()1,1e --B .(),0e -C. ()21,1e --- D .()21,1e - 第Ⅱ卷(共90分)二、填空题(每题5分,满分20分,将答案填在答题纸上)13.若函数()3ln f x x x =-,则()'1f = . 14.已知函数()32,0ln ,0x x x f x x x ⎧-≤=⎨>⎩,则1f f e ⎛⎫⎛⎫= ⎪ ⎪⎝⎭⎝⎭ . 16.设复数z 满足()()213z i i +=-,则z 的虚部为 .16.甲、乙、丙三位同学被问到是否去过,,A B C 三个城市时,甲说:我没去过C 城市;乙说:我去过的城市比甲家,但没去过B 城市;丙说:我们三人去过同一城市,由此可判断甲去过的城市为 .三、解答题 (本大题共6小题,共70分.解答应写出文字说明、证明过程或演算步骤.)17.已知复数()1z a ai a R =-+∈.(1)若z 是纯虚数,求a ;(2z .18. 已知:p 函数()()22485f x x m x =+-+在区间(),1-∞上是减函数; :q 关于x 的不等式2430x mx m -+-<无解.如果“p q ∧”为假,“p q ∨”为真,求m 的取值范围. 19.(1)在平面上,若两个正方形的边长的比为1:3,则它们的面积比为1:9.类似地,在空间中,对应的结论是什么?(2)已知数列{}n a 满足11212,4n n n a a a a +-==+,求2345,,,a a a a ,并由此归纳得出{}n a 的通项公式(无需证明).20.A 市某机构为了调查该市市民对我国申办2034年足球世界杯的态度,随机选取了140位市民进行调查,调查结果统计如下:(1)根据已知数据把表格数据填写完整;(2)利用(1)完成的表格数据回答下列问题:(i )能否有99%的把握认为支持申办足球世界杯与性别有关;(ii )已知在被调查的支持申办足球世界杯的男性市民中有5位退休老人,其中2位是教师,现从这5位退体老人中随机抽取3人,求至多有1位老师的概率.参考公式:()21322122321212n n n n n n n n n χ++++-=,其中11122122n n n n n =+++. 参考数据:21.已知函数()ln f x axx =-. (1)当0a =,求函数()f x 的单调区间;(2)若函数()f x 在()2,+∞上是减函数,求a 的最小值;请考生在22、23两题中任选一题作答,如果多做,则按所做的第一题记分.22.选修4-4:坐标系与参数方程设直线l 的参数方程为112x t y ⎧=-⎪⎪⎨⎪=⎪⎩(t 为参数),以坐标原点O 为极点,x 轴的正半轴为极轴建立极坐标系,曲线C 的极坐标方程为2sin 4cos ρθθ=.(1)把曲线C 的极坐标方程化为直角坐标方程;(2)设直线l 与曲线C 交于,M N 两点,点()1,0A ,求22MA NA +的值.23.选修4-5:不等式选讲已知函数()23f x x x =-++.(1)求不等式()15f x ≤的解集;(2)若()2x a f x -+≤对x R ∈恒成立,求a 的取值范围.高二数学期末试题参考答案(文科)一、选择题1-5:DBAAD 6-10:DBCBB 11、12:AD二、填空题13.2 14.3215.7- 16.A 三、解答题17.解:(1)若z 是纯虚数,则100a a -=⎧⎨≠⎩,所以1a =(2= 所以220a a --=,所以2a =或1a =-.当2a =时,12,12z i z i =+=-,当1a =-时,2,2z i z i =--=-+.18.解:若p 为真,则对称轴21x m =-≥,即1m ≤若q 为真,则()216430m m ∆=--≤,即2430m m +-≤,解得314m -≤≤ 因为“p q ∧”为假,“p q ∨”为真,所以,p q 一真一假.若p 真q 假,则1314m m m ≤⎧⎪⎨><-⎪⎩或,得314m <≤或1m <- 若q 真p 假,则1314m m >⎧⎪⎨-≤≤⎪⎩,得m ∈∅ 综上,所以314m <≤或1m <-,即m 的取值范围是()3,1,14⎛⎤-∞- ⎥⎝⎦.19.解:(1)对应的结论为:若两正方体的棱长的比为1:3,则它们的体积之比为1:27.(2)由1121321,14nn n a a a a +-==-=+, 得23453313031132321,01,1,191562234445524a a a a --===-===-==-=-==-=-, 由此可归纳得到31n a n =- 20.解:(1)(2)(i )由已知数据可求得()221404*********.667 6.63560807070χ⨯⨯-⨯=≈>⨯⨯⨯ 所以有99%的把握认为支持申办足球世界杯与性别有关.(ii )从5人中任意取3人的情况有35C 种,其中至多有1位教师的情况有123233C C C +种,故所求的概率12323353710C C C P C =+= 21.解:函数()f x 的定义域为()()0,11,⋃+∞,(1)函数()()2ln 1'ln x f x x -=,当0x e <<且1x ≠时,()'0f x <;当x e >时,()'0f x >,所以函数()f x 的单调递减区间是()()0,1,1,e ,单调递增区间是(),e +∞(2)因在()f x 上()2,+∞为减函数,故()()2ln 1'0ln x f x a x -=-≤在()2,+∞上恒成立.所以当()2,x ∈+∞时,()max '0f x ≤,又()()222ln 111111'ln ln ln 24ln x f x a a a x x x x -⎛⎫⎛⎫=-=-+-=--+- ⎪ ⎪⎝⎭⎝⎭, 故当11ln 2x =,即2x e =时,()max 1'4f x a =-. 所以104a -≤,于是14a ≥, 故a 的最小值为14. 22.解:(1)由曲线C 的极坐标方程为2sin 4cos ρθθ=,即22sin 4cos ρθρθ=, 可得直角坐标方程24y x =. (2)把直线l的参数方程112x t y ⎧=-⎪⎪⎨⎪=⎪⎩(t 为参数)代入曲线C 的直角坐标方程可得238160t t +-= ∴1212816,33t t t t +=-=-. ∴()2222212121264321602939MA NA t t t t t t +=+=+-=+= 23.解:(1)因为()21,35,3221,2x x f x x x x --<-⎧⎪=-≤≤⎨⎪+>⎩,所以当3x <-时,由()15f x ≤,得83x -≤<-;当32x -≤≤时,由()15f x ≤,得32x -≤≤;当2x >时,由()15f x ≤,得27x <≤.综上,()15f x ≤的解集为[]8,7-.(2)设()2g x x a =-+,则()()max 0g x g a ==, 当32x -≤≤时,()f x 取得最小值5.所以当0x =时,()2x f x +取得最小值5,故5a ≤,即a 的取值范围为(],5-∞.。