习题参考答案new1

C语言法式设计习题参考谜底之迟辟智美创作习题 1一、判断题1．在计算机中，小数点和正负号都有专用部件来保管和暗示.2．二进制是由0和1两个数字组成的进制方式.3．二进制数的逻辑运算是按位进行的，位与位之间没有进位和借位的关系.4．在整数的二进制暗示方法中，0的原码、反码都有两种形式.5．有符号数有三种暗示法：原码、反码和补码.6．经常使用字符的ASCII码值从小到年夜的排列规律是：空格、阿拉伯数字、年夜写英文字母、小写英文字母.解：1．F2．T 3．T 4．T 5．T 6．T二、单选题1．在计算机中，最适合进行数值加减运算的数值编码是 .A. 原码B. 反码C. 补码D. 移码2．已知英文小写字母m的ASCII码为十进制数109，则英文小写字母y的ASCII码为十进制数 .A. 112B. 120C. 121D. 1223．关于ASCII码，在计算机中的暗示方法准确地描述是 .A. 使用8位二进制数，最右边一位为1B. 使用8位二进制数，最左边一位为1C. 使用8位二进制数，最右边一位为0D. 使用8位二进制数，最左边一位为04．设在机器字长4位，X＝0111B，Y＝1011B，则下列逻辑运算中，正确的是___________.A. X∧Y＝1000B. X∨Y＝1111C. X⊕Y＝0011D. ¯Y＝10005．下列叙述中正确的是（）.A．高级语言就是机器语言B．汇编语言法式、高级语言法式都是计算机法式，但只有机器语言法式才是计算机可以直接识别并执行的法式C．C语言因为具有汇编语言的一些特性，所以是汇编语言的一种D．C源法式经过编译、连接，若正确，执行后就能获得正确的运行结果6．用C语言编写的源法式经过编译后，若没有发生编译毛病，则系统将（）.A．生成可执行文件B．生成目标文件C．输出运行结果D．自动保管源文件7．下列叙述中不正确的是（）.A．main函数在C法式中必需有且只有一个B. C法式的执行从main函数开始，所以main函数必需放在法式最前面C. 函数可以带参数，也可以不带参数.D. 每个函数执行时，按函数体中语句的先后次第，依次执行每条语句解：1．C 2．C 3．D 4．B 5．B 6．B 7．B三、填空题1．（87.625）10=（）2=（）8=（）162．（1001010111001.10111）2=（）8=（）16=（）103．输入三个数，计算并输出三个数的和与三个数的乘积.法式如下：#include <stdio.h>void main(){inta,b,c,s,z;printf("Please input a b c:\n");s=a+b+c;printf("%d\n",s);}*4. 输入三角形三条边的边长，计算并输出三角形的面积.根据三条边的边长，计算三角形面积的公式如下：法式如下：#include <stdio.h>#include <math.h>void main(){double x,y,z,s,dime;scanf("%lf%lf%lf",&x,&y,&z);dime=sqrt(s*(s-x)*(s-y)*(s-z));}解：1．1010111.101 127.5 57.A2．11271.56 12B9.B8 4793.718753．scanf("%f%f%f",&a,&b,&c); z=a*b*c; printf("%f",z);4．s=(x+y+2)/2; printf("%f",dim);四、编程题1．仿照例1.1，编法式在屏幕上显示：*****************************MerryChristmas!HappyNewYear!*****************************解：#include <stdio.h>void main(){ printf("*****************************\n");printf(" Merry Christmas!\n");printf(" Happy New Year!\n");printf("*****************************\n");}2．仿照例1.2编程，输入一个整数，计算这个数的平方.解：#include<stdio.h>void main(){ int a,z;printf("请输入一个整数:\n");scanf("%d",&a);z=a*a;printf("%d*%d=%d\n",a,a,z);}*3．仿照例1.3编程，输入两个数后，输出其中较小值.解：#include<stdio.h>float min(float x, float y){ float m;if (x<y) m=x;else m=y;return m;}void main(){ float a,b,c,mindata;printf("请输入二个数:\n");scanf("%f %f",&a,&b);mindata=min(a,b);printf("较小数：%f\n",mindata);}*4．仿照例1.2编程，输入a、b后，输出一元一次方程ax+b=0的解.解：#include<stdio.h>void main(){ float a,b,x;printf("请输入a、b:\n");scanf("%f %f",&a,&b);x=-a/b;printf("x=%f\n",x);}*5．仿照例1.2编程，输入圆柱体的半径和高，计算并输出圆柱体的体积.解：#include <stdio.h>void main(){ float r,h,s,v;printf("Please input r and h:\n");scanf("%f %f",&r,&h);v=3.14*r*r*h;printf("V=%f\n",v);}习题2一、判断题1．任何变量都必需要界说其类型.2．C语言的double类型数据在其数值范围内可以暗示任何实数.3．C语言的任何类型数据在计算机内都是以二进制形式存储的.4．isdigit(‘5’)的结果为0.5．printf函数中格式符“%c”对应的参数只能是字符类型.6．按格式符“%d”输出float类型变量时，截断小数位取整后输出.7．在C语言法式中，ABC与abc是两个相同的变量.8．scanf函数中的格式符“%d”不能用于输入实型数据.9．格式符“%f”不能用于输入double类型数据.10．当格式符中指定宽度时，输出的信息完全取决于所指定的宽度.解：(1)T (2)F (3)T (4)F (5)F (6)F (7)F (8)T (9)T (10)F二、指出下列各项中哪些是C语言中的常量，并指出其类型10,150 007 –0x3d π 1e0 e1 o7o8‘x’ ‘x o’ 1.52e0.5 sin(3) 0xf16 ‘\a’‘\009’1.414E+22.54‘\\’ ‘a’+2 0x100h 0128 10L解：合法的C常量有：整型常量： 007 –0x3d0xf16 10L实型常量： 1e0 1.414E+2字符型常量：‘x’‘\a’‘\\’三、指出下列各项中哪些是C语言中的用户标识符x_1 X_2 High printf β 3DS i/je2 －e2 count Int number $23 next_sizeof IF sum_12_123# NO1: double for解：C的用户标识符有：x_1 X_2 High e2 count Int number next_ IF sum_12四、单项选择题1．C语言中，char型数据在内存中的存储形式是（）.A．原码 B．反码C．补码D．ASCII码2．若有界说语句“char c='\72'；”则变量c（）.A．包括1个字符B．包括2个字符C．包括3个字符D．界说分歧法3．C语言中的基本数据类型包括（）.A．整型、实型、逻辑型B．整型、实型、字符型C．整型、逻辑型、字符型D．整型、实型、逻辑型、字符型4．设c1、c2为字符型变量，执行语句“c1=getchar()；c2=getchar()；”时，从键盘输入A↙，c1和c2的值分别为（）.A．都是‘A’B．c1是‘A’，c2未输入C．c1未输入，c2是‘A’D．c1是‘A’，c2是‘\n’5．a、b是整型变量，执行语句“scanf("a=%d，b=%d"，&a，&b)；”，使a和b的值分别为1和2，正确的输入是（）.A．1 2B．1，2C．a=1，b=2D．a=1 b=26．设c为字符型变量值为‘A’，a为整型变量值为97，执行语句“putchar(c)；putchar(a)；”后，输出结果为（）.A．AaB．A97C．A9D．aA7．已知字母A的ASCII码值为65，以下语句段的输出结果是（）.char c1='A',c2='Y'; printf("%d,%d\n",c1,c2);A．输出格式非法，输犯毛病信息B．65，90C．A，YD．65，898．若要使用输入语句“scanf("%4d%4d%10f"，&i，&j，&x)；”，为i输入－10，为j输入12，为x输入345.67，则正确的输入形式是（）.A．–1012345.67↙B．–1012345.67↙C．–10001200345.67↙D．–10,12,345.67↙9．能正确地界说符号常量的是（）.A．#define n=10B．#define n 10C．#define n 10； D．#DEFINE N 1010．在C语言中，int、char、short三种类型数据在内存中所占的字节数（）.A．由用户自己界说 B．均为2个字节 C．是任意的 D．由机器字长决定解：(1) D (2) A (3) B (4) D (5) C(6) A (7) D (8) B (9) B (10) D五、填空题1．char ch='$'；float x=153.4523；语句“printf("%c%–8.2f\\n",ch,x)；”的输出结果是 .解：$153.45 \n2．int i=123；float x=– 1234.56789；语句“printf("i=%5d x=%7.3f\n",i,x)；”的输出结果是 .解：i= 123 x=-1234.5683．char c='a'；int a=65；语句“putchar(c+1);putchar(a)；”的输出结果是 .解：bA4．int a=98；语句“printf(“%d,%c,%o,%x”,a,a+1,a+2,a+3);”的输出结果是 .解：98,c,144,655．int k; float f;语句“scanf(“%3d%*4d%6f”,&k,&f);”执行时输入 12345678765.43↙则 k= ，f= .解：k=123 f=8765.46．使用pow()函数时，法式的开头必需写一条预处置命令： .解：#include <math.h>5．填空题.(1)int i=123,j=45;函数printf("%d,%d\n",i,j);的输出结果是.解：123,45(2)int i=123; float x=-45.678;语句printf("i=%5d x=%7.4f\n",i,x); 的输出结果是.解：i= 123 x=-45.6780(3)float alfa=60,pi=3习 题 3一、根据下列数学式，写出C 的算术表达式.解：-(a 2+b 2)×y 4的C 表达式：-(a*a+b*b)*pow(y,4)π++-x 12tan 102的C 表达式：(sqrt(2)+10*10)/(pow(tan(x),-1)+3.141593) 5.3|)sin(|x 的C 表达式：sqrt(pow (fabs (sin(x)),3.5))56e x -的C 表达式：pow(x,6)-exp(5)cd d c b a d c ab +-+++221的C 表达式：(1.0/2*a*b+c+d)/(a+2*b-(c+d)/c/d)二、依照要求，写出下列C 的表达式.1．写出int 类型变量x 为“奇数”的表达式.解：x%2==12．Int 类型变量x 、y 、z ，写出描述“x 或y 中有且仅有一个小于z ”的表达式.解：x<z&&y>=z||x>=z&&y<z3．将double 类型变量y 保管四位小数的表达式.解：(int)(y*10000+0.5)/10000.04．为变量s 赋值：取变量x 的符号，取变量y 的绝对值.解：s=(x>=0?1:-1)*(y>=0?y:-y)5．条件“-5≤x ≤3”所对应的C 逻辑表达式.解：-5<=x&&x<=36．a 、b 是字符变量，已知a 的值为年夜写字母、b 的值为小写字母，写出判断a 、b 是否为同一字母(不区分年夜小写)的逻辑表达式 解：a+32==b 或 b-a==32?1:07．int 类型变量a 、b 均为两位正整数，写出判断a 的个位数即是b 的十位数、且b的个位数即是a的十位数的逻辑表达式.解：a%10==b/10&&a/10==b%108．写出判断某个人是否是成年人(年龄年夜于21)，且不是老年人(年龄年夜于65)的逻辑表达式.解：y>21&&y<=659．写出取变量a、b、c中最年夜值的条件表达式.解：(a>b?a:b)>c?(a>b?a:b):c10．若字符变量ch为小写字母，则将其转换为对应的年夜写字母.解：ch=ch>='a'&&ch<='z'?ch-32:ch三、单项选择题1．设int x=3，y=4，z=5；，下列表达式中值为0的是（）.A．'x'&&'y'B.x<=yC．x||y+z&&y–zD.!((x<y)&&!z||1)2．已知x=10，ch='A'，y=0；，则表达式“x>=y&&ch<'B'&&!y”的值是（）.A．0B.1C．“假”D．“真”3．判断char型变量c为数字字符的正确表达式为（）.A．'0'<=c<='9'B．'0'<=c&&c<='9' C．c>='0'||c<='9'D．c>=0&&c<=94．下列运算符中，优先级最低的是（）.A．？：B．&&C．= =D．*=5．若有条件表达式“x?a++:b--”，则以下表达式中（）等价于表达式x.A．x==0B．x!=0C．x==1D．x!=16．有界说int k=4，a=3，b=2，c=1；，表达式“k<a?k:c<b?c:a”的值是（）.A．4B．3C．2D．17．执行下列法式段后，变量a，b，c的值分别是（）.int x=10，y=9，a，b，c；a=(--x= =y++)?--x：++y；b=x++；c=y；A．a=9，b=9，c=9B．a=8，b=8，c=10C．a=9，b=10，c=9D．a=1，b=11，c=108．有界说int a=9；，语句“a+=a–=a+a；”执行后，变量的值是（）.A．18B．9C．–18D．–99．设x和y均为int型变量，则语句“x+=y；y=x–y；x–=y；”的功能是（）.A．把x和y按从小到年夜排列B．把x和y按从年夜到小排列C．无确定结果D．交换x和y中的值10．有界说double x=1，y；，表达式“y=x+3/2”的值是（）.A．1B．2C．2.0D．2.511．设有界说int x;double y；，则下列表达式中结果为整型的是（）.A.(int)y+xB．(int)x+yC．int(y+x)D．(double)x+y12．设有整型变量x，下列说法中，毛病的是（）.A．“5.0”不是表达式B．“x”是表达式C．“！x”是表达式D．“sqrt(x)”是表达式解：(1)D (2)B (3)B (4)D (5)B (6)D(7)B (8)C (9)D (10)C (11)A (12)A四、填空题.1．设float x=2.5,y=4.7; int a=7;，表达式x+a%3*(int)(x+y)%2/4 值为 .解：2.52．设int x=2，y=3；，执行语句“x*=x+y”后x的值为 .解：103．设int x=17，y=5；，执行语句“x%=x–y”后x的值为.解：54．设 int a=6,b=4,c=2;，表达式 !(a-b)+c-1&&b-c/2 的值为 .解：15．设 int a=2,b=4,x,y;，表达式!(x=a)||(y=b)&&!(2-3.5) 的值为 .解：06．判断变量a、b是否绝对值相等而符号相反的逻辑表达式为 .解：a==-b7．判断变量a、b中必有且只有一个为0的逻辑表达式为 .解：a*b==0&&a+b!=08．设int m=2,n=2,a=1,b=2,c=3;执行语句d=(m=a==b)&&(n=b>c);后，m和n的值分别为 .解：m为0，n为29．设int a=2；，表达式“a%2!=0”的值为.解：010．设char c='y'；，表达式“c>='a'&&c<='z'|| c>='A'&&c<='Z'”的值为.解：111．写出与代数式 (x+2)e x+2对应的C表达式 .解：(x+2)*exp(x+2)12．设int a=2;执行语句a=3*5,a*4;后a的值为 .解：15五、写出下列法式的输出结果.1．#include <stdio.h>void main(){unsigned k,n;scanf("%u",&n); //输入数据为：69k=n%10*10+n/10;printf("n=%d k=%d\n",n,k);}解：n=69 k=962．#include <stdio.h>void main(){int x=2,y=3;x*=y+4;printf("%d,%d\n",x,y);x/=y=5;printf("%d,%d\n",x,y);x-=y%2;printf("%d,%d\n",x,y);}解：14,32,51,53．#include <stdio.h>void main(){int a, b;a=8;b=7;a=(a-- ==b++)? a%3 : a/3;printf("a=%d b=%d\n",a,b);}解：a=2 b=8六、法式填空题.1．以下法式输入三个整数值给a,b,c，法式把b中的值给a，把c 中的值给b，把a中的值给c，交换后输出a、b、c的值.例如输入1 2 3，输出a=2 b=3 c=1.#include <stdio.h>void main(){ int a,b,c,①;p rintf(“Enter a,b,c:”);scanf(“%d%d%d”,②);③; a=b; b=c; ④;printf(“a=%d b=%d c=%d\n”,a,b,c);}解：① t ② &a,&b,&c ③ t=a ④ c=t2．以下法式不借助任何变量把a、b中的值进行交换.#include <stdio.h>void main(){ int a,b;printf(“Input a,b:”);scanf(“%d%d”,①);a+=②; b=a-③; a-= ④;printf(“a=%d b=%d\n”,a,b);}解：① &a,&b ② b ③ b ④ b七、编程题.1．输入3个字符后，按各字符ASCII码从小到年夜的顺序输出这些字符.解：#include <stdio.h>void main(){ char c1,c2,c3,t,min,mid,max;c1=getchar(); c2=getchar(); c3=getchar();min=(t=c1<c2?c1:c2)<c3?t:c3;max=(t=c1>c2?c1:c2)>c3?t:c3;mid=c1+c2+c3-min-max;putchar(min);putchar(mid);putchar(max);}2．输入两点坐标（x1，y1）、（x2，y2），计算并输出两点间的距离.解：#include <stdio.h>#include <math.h>void main(){double x1,y1,x2,y2,d;printf(“请输入两点坐标 (x1,y1),(x2,y2)\n”);scanf(“(%lf,%lf),(%lf,%lf)”,&x1,&y1,&x2,&y2);d=sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));printf(“两点间距离=%f\n”,d);}3．编写法式，计算球体积并输出它的值.要求输入半径值，计算结果保管三位小数.解：#include <stdio.h>#include <math.h>#define PI 3.1415926void main(){ double r,gv;printf(“请输入半径值：\n”);scanf(“%lf”,&r);gv=4.0/3*PI*pow(r,3);printf(“半径为%f的球的体积为：%.3f\n”,r,gv);}4．输入三角形的底和高，求三角形面积.解：#include <stdio.h>#define PI 3.14159void main(){double a,h,s;printf(“请输入三角形的底，高\n”);scanf(“%lf,%lf”,&a,&h);s=a*h/2;printf(“三角形面积=%f\n”,s);}5．编写法式，输入一个实数后输出该数的绝对值.解：#include <stdio.h>void main(){double x,y;printf(“请输入一个实数\n”);scanf(“%lf”,&x);y=x>=0?x:-x;printf(“|%g|=%g\n”,x,y);}6．输入梯形的上底、下底和高，求梯形面积.解：#include <stdio.h>void main(){double a,b,h,s;printf(“请输入梯形的上底，下底，高\n”);scanf(“%lf,%lf,%lf”,&a,&b,&h);s=(a+b)*h/2;printf(“梯形面积=%f\n”,s);}7. 输入矩形的边长，求矩形面积.解：#include <stdio.h>void main(){double a,b,s;printf(“请输入矩形的长，宽\n”);scanf(“%lf,%lf”,&a,&b);s=a*b;printf(“矩形面积=%f\n”,s);}8. 已知等差数列的第一项为a，公差为d，求前n项之和，a、d、n由键盘输入.解：#include <stdio.h>void main(){int a,d,n,sum;printf(“请输入等差数列的首项公差项数\n”);scanf(“%d%d%d”,&a,&d,&n);sum=a*n+n*(n-1)*d/2;printf(“ sum=%d\n”,sum);}9. 编写法式，将d天h小时m分钟换算成份钟，输入d、h、m，输出换算结果.解：#include <stdio.h>void main(){int d,h,m,t;printf(“请输入天小时分钟\n”);scanf(“%d%d%d”,&d,&h,&m);t=d*24*60+h*60+m;printf(“%d天%d小时%d分钟=%d分钟\n”,d,h,m,t);}10. 编写法式，求出给定半径r的圆以及内接正n边形的面积，输出计算结果.r和n的值由键盘输入.解：#include <stdio.h>#include <math.h>#define PI 3.14159void main(){double r,s1,s2;int n;printf(“Input r n\n”);scanf(“%lf%d”,&r,&n);s1=PI*r*r;s2=n/2.0*r*r*sin(2*PI/n);printf(“圆面积=%f,正内接%d边形面积=%f\n”,s1,s2);}习题4一、单项选择题1．下列语句将小写字母转换为年夜写字母，其中正确的是（）.A．if(ch>='a'&ch<='z')ch=ch-32；B．if(ch>='a'&&ch<='z')ch=ch-32；C．ch=(ch>='a'&&ch<='z')?ch-32:''；D．ch=(ch>'a'&&ch<'z')?ch-32:ch；2．下列各语句中，能够将变量u、s中最年夜值赋给变量t的是（）.A．if(u>s)t=u；t=s；B．t=s；if(u>s)t=u；C．if(u>s)t=s；else t=uD．t=u；if(u>s)t=s；3．假设变量x、k都已界说，下列语句片段中，无语法毛病的是（）.A.switch(x){case x>=90: putchar('A');case x<60: putchar('E');}B.switch(x) {case 1+2: k='A';defualt: k='E';case 2*4: k='B';}C.switch(x){case 2+x: k=x-2;case 3*x: k=x+3;default: k=0;}D.switch(x){case 3.5: k=0.5*x;case 7.8: k=8*x;default: k=0;}*4．与语句while(!s )中的条件等价的是（）.A．s==0B．s!=0C．s==1D．s=05．下列语句中，哪一个可以输出26个年夜写英文字母（）.A．for(a='A'；a<='Z'；printf("%c"，++a));B．for(a='A'；a<'Z'；a++)printf("%c"，a)；C．for(a='A'；a<='Z'；printf("%c"，a++))；D．for(a='A'；a<'Z'；printf("%c"，++a))；6．判断下面的while循环体的执行次数（）.i=0;k=10;while( i=8 ) i=k––;A．8次B．10次C．2次D．无数次解：(1) B (2) B (3) B (4) A (5) C (6) D二、写出下列法式的输出结果1．#include <stdio.h>void main(){char x;。

英语习题册参考答案一、选择题1. A) 根据题目中的语境，选择A项，表示“他经常在周末去图书馆”。

2. C) 题目要求选择正确的动词形式，C项“has been”表示过去开始的动作一直持续到现在。

3. B) 根据句意，选择B项，表示“她正在努力完成她的论文”。

4. D) 题目考查固定搭配，D项“look after”意为“照顾”。

5. A) 根据题目中的时态一致性原则，选择A项，表示“他们正在讨论他们的假期计划”。

二、填空题6. 正确答案是“arrived”，因为根据句子的时态，需要使用动词的过去式。

7. 填入“if”，因为句子需要一个条件状语从句的引导词。

8. 填入“more”，因为句子需要一个比较级来表达“更少的噪音”。

9. 填入“Although”，因为句子需要一个让步状语从句的引导词。

10. 填入“to”，因为“pay attention to”是一个固定短语，意为“注意”。

三、阅读理解A篇：11. 答案：C) 根据文章第一段，作者提到了“the importance of learning English”，所以选择C。

12. 答案：A) 文章第二段提到了“the best way to learnEnglish”，因此选择A。

13. 答案：B) 第三段中提到了“the benefits of using English in daily life”，所以B项正确。

B篇：14. 答案：D) 文章最后一段提到了“the future of the company”，所以选择D。

15. 答案：B) 第二段中提到了“the company's new product”，因此B项正确。

16. 答案：C) 第一段中提到了“the company's history”，所以C项正确。

四、完形填空17. 答案：C) “considered”表示“被认为”，符合语境。

18. 答案：A) “influenced”表示“影响”，与前文“a great writer”相呼应。

计算机应用基础第二版习题答案(NEW)计算机应用基础第二版习题答案1. 选择题1. 选择题答案：A2. 选择题答案：C3. 选择题答案：B4. 选择题答案：D5. 选择题答案：A6. 选择题答案：B7. 选择题答案：D8. 选择题答案：C9. 选择题答案：A10. 选择题答案：B2. 填空题1. 答案：二进制2. 答案：硬件3. 答案：操作系统4. 答案：冯·诺伊曼5. 答案：图灵机6. 答案：高级语言7. 答案：编译8. 答案：硬盘9. 答案：光盘10. 答案：USB3. 简答题1. 计算机是利用什么进行数据存储、处理和输出的？计算机是利用二进制进行数据存储、处理和输出的。

2. 请简要解释计算机的硬件组成。

计算机的硬件组成包括中央处理器（CPU）、主存储器、输入设备、输出设备和外部存储器。

中央处理器负责对数据的处理和控制，主存储器用于存储正在运行的程序和数据，输入设备用于输入数据，输出设备用于显示或打印计算机处理结果，外部存储器用于长期存储数据和程序。

3. 请简要解释操作系统的作用。

操作系统是计算机系统的核心软件，它管理计算机系统的硬件资源，为用户和应用程序提供一个友好的界面，并协调各个应用程序的运行。

操作系统负责管理内存、处理器、文件系统等资源，同时也支持多任务、多用户的并发操作，提供了基本的输入输出功能和文件管理功能。

4. 简述冯·诺伊曼体系结构的特点。

冯·诺伊曼体系结构是现代计算机体系结构的基础，其特点包括存储程序思想、按指令执行和以存储器为中心。

存储程序思想指的是将程序和数据存储在同一存储器中，并且程序可以像数据一样进行处理。

按指令执行指的是计算机按照程序指定的顺序执行指令，每条指令完成一个基本操作。

以存储器为中心指的是计算机的各个部件都通过存储器进行数据传输和交互。

5. 请简要解释编译和解释的区别。

编译是将高级语言程序一次性翻译成机器语言程序的过程，生成的机器语言程序可以重复执行，执行速度较快。

高一年级英语课后练习题一、选择题（本大题共10小题，每小题2分，共20分）（）1、In winter, the field in the north is always _____ by snow。

A、coverB、coveringC、coveredD、to cover（）2、Wang Shuang, a member of the Chinese women's soccer team who started her youth training in Wuhan, is famous _____ her soccer skills。

A、ofB、forC、asD、to（）3、Gilbert ______ electricity, but Edison invented the light bulb.A、found outB、foundC、coveredD、discovered （）4、Wei Hua didn’t come to the party because she had to take care __ her mother in hospital、A、ofB、forC、aboutD、with（）5、With the support of his family, Xu ____ for the first time at 22 and took four major trips in his lifetime。

A、set ofB、setted ofC、set offD、setted off（）6 I wish my father could give up _____、A、drinkB、drinkingC、to drinkD、drank（）7、All sorts of difficulties and hardships were his valuable ________ in his lifetimeA、experienceB、experiencedC、experiencesD、experiencing （）8、____ his poor management, the factory had to be closed、A、DueB、Due toC、BecauseD、Cause （）9、Marco Polo _____ about his travels along the Silk Road and different places that he passed through.A、wroteB、writesC、writeD、written（）10、There ____ an old temple here in the past.A、isB、areC、wereD、was八、阅读理解（本大题共5小题，每小题2分，共10分）I work in a nursing home and my job is to look after the elderly.This year, a very sweet old lady that I cared for, Alice, had gone through a difficult time. She got dementia and so she had been in the hospital twice. In November I was finally able to get her back to her “home”.Alice had thought her daughter was coming to visit her on Christmas day and that they were going to have the whole family together like the old days. When she finally realized that the happy moment was not going to happen, she was very sad.Knowing that her daughter was coming after Christmas was not enough to make her feel happy, I hated the idea of her being alone on the holiday!On Christmas Eve, I gave her a surprise by asking if she would like to go to a candlelight service at church that night.Instead of taking her to my church, I took her to her old neighborhood church where all her friends were. We got there early and I got her a seat where her friends could see her as they came in. Then soon some of her friends came to the church and they rushed over to greet her and sit with her.The candlelight service was beautiful and Alice got a lot of love from her old and new friends there.The truth of the story is that I am the one who got the best gift: the smile on Alice’s face.（）11、The underlined word “dementia”in Paragraph 2 probably is _____A、an illnessB、a letterC、a houseD、a plan（）12、From the passage we can learn that Alice _____A、didn’t like living in the nursing homeB、was thrown out by her daughterC、returned to her home after leaving the hospitalD、expected to spend Christmas with her daughter（）13、Where did Alice spend her Christmas Eve according to the story?A、In her old house、B、In her old neighborhood church、C、In the nursing home、D、In the hospital、（）14、What was the best gift that the author got on Christmas Eve?A、Alice’s happiness、B、Praise from Alice’s friends、C、Thanks from Alice’s daughter、D、The candlelight service、（）15、What is the best title for this passage?A、A real presentB、The dream of an old lonely ladyC、A special candlelight Christmas EveD、The true love参考答案：CBDAC BCBAD ADBAC。

高一英语阅读理解高一英语阅读理解练习题及参考答案高一英语阅读理解练习题(一)Elizabeth Blackwell was born in England in 1821, and moved to New York City when she was ten years old. One day she decided that she wanted to bee a doctor. That was nearly impossible for a woman in the middleof the nineteenth century. After writing many letters asking for admission(录取) to medical schools, she was finally accepted by a doctor in Philadelphia. She was so determined that she taught school and gave music lessons to get money for the cost of schooling.In 1849, after graduation from medical school. she decided to further her education in Paris. She wanted to be a surgeon(外科医师) , but a serious eye problem forced her to give up the idea.Upon returning to the United States, she found it difficult to start her own practice because she was a woman. By 1857 Elizabeth and her sister, also a doctor, along with another woman doctor, managed to open a new hospital, the first for women and children Besides being the first woman physician and founding her own hospital , she also set up the first medical schoolfor women.1. Why couldn’t Elizabeth Blackwell realize her dream of being a surgeon?A. She couldn’t get admitted to medical schoolB. She decided to further her education in ParisC. A serious eye problem stopped herD. It was difficult for her to start a practice in the United States2. What main obstacle(障碍) almost destroyed Elizabeth’s chances for being for a doctor?A. She was a woman.B. She wrote too many letters.C. She couldn’t graduate from medical school.D. She couldn’t set up her hospital.3. How many years passed between her graduation from medical school and the opening of her hospital?A. Eight yearsB. Ten yearsC. Nineteen yearsD. Thirty-six years4. According to the passage, all of the following are “firsts” in the life of Elizabeth Blacekwell,except that she ______.A. became the first woman physicianB. was the first woman doctorC. and several other women founded the first hospital for women and childrenD. set up the first medical school for women5. Eilzabeth Blackwell spent most of her lift in _______.A. EnglandB. ParisC. the United StatesD. New York City高一英语阅读理解练习题答案1C 2 A 3 A 4 B 5 C高一英语阅读理解练习题(二)An expensive car speeding down the main street of a small town was soon caught up with by a young motorcycle policeman. As he started to make out the ticket, the woman behind the wheel said proudly, “Before you go any further, young man, I think you should know that the mayor of this city is a good friend of mine.”The officer did not say a word, but kept writing. “I am also a friend of chief of police Barens,”continued the woman, getting more angry each moment, Still he kept on writing. “Young man,”she persisted, “I know Judge Lawso n and State Senator (参议员) Patton.” Handing the ticket to the woman, the officer asked pleasantly , “Tell me, do you know Bill Bronson.”“Why, no,”she answered.“Well, that is the man you should have known,”he said, heading back to his motorcycle, “I an Bill Bronson.”1. The policeman stopped the car because_____A. it was an expensive carB. the driver was a proud ladyC. the driver was driving beyond the speed limitD. the driver was going to make trouble for the police2. The woman was getting more angry each moment because _____.A. the policeman didn’t know her friendsB. the policeman didn’t accept her kindnessC. the policeman was going to punish herD. she didn’t know the policeman’s name3. The policeman was _______.A. an honourable fellowB. a stupid fellowC. an impolite manD. a shy man4. The woman was _______.A. kind-heartedB. a person who depended on someone else to finish her workC. trying to frighten the policeman on the strength of her friends’ powerf ul positionsD. introducing her good friends’ names to the young officer5. The policeman _______.A. had no sense of humor (幽默)B. had s sense of humorC. had no sense of dutyD. was senseless。

高考完形填空专项练习题及答案详解一、高中英语完形填空1．阅读下面短文，从短文后各题所给的四个选项（A、B、C和D）中，选出可以填入空白处的最佳选项。

I had worried myself sick over Simon's mother coming to see me. I was a new 1 , and I gave an honest account of the students' work. In Simon's case, the grades were awfully low. He couldn't read his own handwriting. 2 he was a bright student. He discussed adult subjects with nearly adult comprehension. His work in no way reflected his 3 .So when Simon's mother entered the room, my palms(手掌心) were sweating. I was completely 4 for her kisses on both my cheeks. "I came to thank you," she said, surprising me beyond speech. 5 me, Simon had become a different person. He talked of how he6 me, he had began to make friends, and for the first time in his twelve years, he had7 spent an afternoon at a friend's house. She wanted to tell me how grateful she was for the8 I had nurtured(培养) in her son. She kissed me again and left.I sat, stunned (惊呆), for about half an hour, 9 what had just happened. How did I make such a life-changing difference to that boy without 10 knowing it? What I finally came to 11 was one day, several months before, when some students were 12 reports in the front of the class, Jeanne spoke 13 , and to encourage her to raise her voice, I had said, "Speak up. Simon's the expert on this. He is the 14 one you have to convince, and he can't hear you in the 15 of the room." That was it. From that day on, Simon had sat up straighter, paid more attention, 16 more, and became happy. And it was all because he 17 to be the last kid in the last row. The boy who most needed 18 was the one who took the last seat that day.It taught me the most 19 lesson over the years of my teaching career, and I'm thankful that it came 20 and positively. A small kindness can indeed make a difference.1. A. cleaner B. reporter C. monitor D. teacher2. A. Or B. And C. But D. So3. A. courage B. abilities C. feelings D. dream4. A. desperate B.responsibleC. unpreparedD. unsuitable5. A. Because of B. In spite of C. Apart from D. As for6. A. loved B. envied C. pleased D. criticized7. A. gradually B. constantly C. recently D. obviously8. A. self-respect B. self-doubt C. self-pity D. self-defence9. A. imagining B. observing C. wondering D. regretting10. A. also B. even C. always D. still11. A. expect B. remember C. believe D. accept12. A. writing B. reviewing C. editing D. giving13. A. quietly B. repeatedly C. quickly D. firmly14. A. lucky B. lonely C. only D. likely15. A. entrance B. middle C. front D. back16. A. slept B. smiled C. shouted D. quarreled17. A. intended B. pretended C. refused D. happened18. A. change B. praise C. thanks D. visits19. A. difficult B. painful C. valuable D. enjoyable20. A. early B. slowly C. frequently D. occasionally【答案】（1）D；（2）C；（3）B；（4）C；（5）A；（6）A；（7）C；（8）A；（9）C；（10）B；（11）B；（12）D；（13）A；（14）C；（15）D；（16）B；（17）D；（18）B；（19）C；（20）A；【解析】【分析】本文是一篇记叙文，讲述了一个新老师，因为偶然的一句表扬，改变了一个成绩很差的孩子的性格和命运．足可见老师的话对学生有多么重要．老师教给学生知识，而最重要的是通过给孩子鼓励和信心而形式积极的人生观。

高中英语完形填空经典习题(含答案)一、高中英语完形填空1．阅读下面短文，从短文后各题所给的四个选项（A、B、C和D）中，选出可以填人空白处的最佳选项。

It was a warm, sunny Saturday afternoon some fifteen or sixteen years ago. I took my two kidsto the local playground. As soon as we got there my daughter headed for the swings (秋千)and asked for a 1 . I noticed another little girl 2 to get her own swing going high as I was3 my daughter to go higher and higher.I walked over to the little girl and asked 4 she needed help. She smiled and said YES andI soon had her feet flying towards the 5 while she laughed happily. For the next two hoursI found myself pushing swings and playing games with my daughter and the little girl. By the time we headed home, I was 6 tired, but my spirits were flying 7 than those swings.Three years later I was 8 again after a day's work. Still, I needed to 9 my kids from their school before heading home. I stood in the 10 waiting area waiting for my children. Suddenly, I felt two 11 arms wrapped around my legs. I looked down and there was the little girl I met 3 years before on the 12 smiling up at me. She gave me a big hug before running away to 13 the school bus. As I watched her 14 , I didn't feel tired any more and my spirits were once again 15 with that swing.The love we 16 with others will find its way back to us. It will travel from heart to heart.It may take seconds or it may take 17 . The law of love, 18 , is never broken. We will get back what we give. We will harvest what we 19 . The kindness we give and the joy we create will always come back to 20 us.1. A. jump B. pull C. push D. climb2. A. failed B. decided C. stopped D. managed3. A. encouraging B. helping C. refusing D. advising4. A. why B. how C. when D. whether5. A. clouds B. ground C. swing D. trees6. A. finally B. suddenly C. physically D. mentally7. A. faster B. higher C. more quickly D. more slowly8. A. amazed B. upset C. concerned D. tired9. A. look after B. pick up C. take away D. bring up10. A. parents' B. teachers'C. patients' D. passengers'11. A. strong B. long C. small D. weak12. A. classroom B. school C. kindergarten D. playground13. A. drive B. catch C. reach D. repair14. A. hands B. head C. face D. back15. A. flying B. crying C. running D. falling16. A. own B. care C. share D. find17. A. hours B. days C. months D. years18. A. however B. therefore C. still D. besides19. A. save B. plant C. design D. offer20. A. frighten B. interest C. excite D. shock【答案】（1）C；（2）A；（3）B；（4）D；（5）A；（6）C；（7）B；（8）D；（9）B；（10）A；（11）C；（12）D；（13）B；（14）D；（15）A；（16）C；（17）D；（18）A；（19）B；（20）C；【解析】【分析】本文是一篇记叙文，作者叙述了她帮助一个小女孩荡秋千得到了女孩的感激。

第一章1.1 图给出两台DFA M1和M2的状态图. 回答下述有关问题.a.M1的起始状态是q1b.M1的接受状态集是{q2}c.M2的起始状态是q1d.M2的接受状态集是｛q1，q4｝e.对输入aabb,M1经过的状态序列是q1，q2，q3，q1，q1f.M1接受字符串aabb吗？否g.M2接受字符串ε吗？是1.2 给出练习2.1中画出的机器M1和M2的形式描述.M 1=(Q1,Σ,δ1,q1,F1) 其中1）Q1={q1,q2,q3,};2）Σ={a,b}; 3）δ1为：4）q1是起始状态5）F1={q2}M2=(Q2,Σ,δ2,q2,F2) 其中1）Q2={q1,q2,q3,q4};2）Σ={a,b}; 3）δ2为：3）q2是起始状态4）F 2={q 1,q 4}1.3 DFA M 的形式描述为 ( {q 1，q 2，q 3，q 4，q 5}，{u,d},δ,q 3，{q 3}),其中δ在表2-3中给出。

试画出此机器的状态图。

1.6 画出识别下述语言的DFA 的状态图。

a){w | w 从1开始以0结束}b){w | w 至少有3个1}c) {w | w 含有子串0101}d) {w | w 的长度不小于3，且第三个符号为0}e) {w | w 从0开始且为奇长度，或从1开始且为偶长度}或f) {w | w 不含子串110}g) {w | w 的长度不超过5}1个1}k) {ε,0}0,11l) {w | w 含有偶数个0，或恰好两个1}m) 空集n) 除空串外的所有字符串1.7 给出识别下述语言的NFA a. {w | w 以00结束}，三个状态b. 语言｛w | w 含有子串0101，即对某个x 和y ，w=x0101y ｝，5个状态.c. 语言｛w | w 含有偶数个0或恰好两个1｝，6个状态。

d. 语言｛0｝，2个状态。

e.语言0*1*0*0，3个状态。

f. 语言{ε}，1个状态。

练习一参考答案1将下列句子或段落翻译成英语1)A process is any operation or series of operations that causes a physical or chemical change in asubstance or a mixture of substances .The material that enters a process is referred to as input or feed the process,and that which leaves is called output or product.2)As a chemical engineer,you might be called on to design individual process units (such as reactors,distillation columns,heat exchangers),supervise the operation of a process,or modify a process design to accommodate a change in the feed or in the desired product characteristics.As a rule,to any of these things you must know the amounts,compositions,and conditions of the materials that enter and leave each process unit,and if you are working with an existing units,you must be able to measure enough of these quantities to verify that the process is doing what it was designed to do.3)Founded in 1839from a small production firm for pharmaceutical products,B.Braun has grown steadilyinto a multinational company dealing with medical products,medical technology,pharmaceutical and biotechnology.2将下列句子或段落翻译成汉语1）包括的一系列操作，如混合、蒸发、过滤，无论产物是什么，这些操作都基本同，从而导致了单元操作的概念。