河南省新乡市新誉佳高级中学2015-2016学年高二上学期第一次月考英语试题

河南省新乡市新乡县新誉佳高中 2015～2016 学年度高二上学期第一次月考物理试卷（理科）一、选择题（单项选择，每题4分，共56 分）1．下列说法正确的是（） A．牛顿第一定律是通过实验得出的 B．万有引力常量是由牛顿直接给定的 C．元电荷e的数值最早是由密立根测得 D．用实验可以揭示电场线是客观存在的2．如图把两张用软纸摩擦过的塑料片相互靠近，它们会张开，这是由于它们之间存在（）A．弹力B．摩擦力C．静电力D．磁场力3．下列说法正确的是（） A．元电荷就是质子 B．带电体所带电荷量一定是元电荷的整数倍 C．点电荷一定是带电量很少的带电体D．处于静电平衡的导体的内部可能有净电荷4．关于库仑定律，下列说法正确的是（）A．库仑定律适用于点电荷，点电荷其实就是体积最小的带电体B．根据F=，当两个带电体间的距离趋近于零时，库仑力将趋向无穷大C．带电量分别为Q和3Q 的点电荷A、B 相互作用时，B 受到的静电力是A受到的静电力的3倍D．库仑定律的适用条件是：真空和静止点电荷5．关于电场强度E的说法正确的是（）A．根据E=可知，电场中某点的电场强度与电场力F成正比，与电量q成反比 B．电场中某点的场强的大小与试探电荷的大小、有无均无关 C．电场中某点的场强方向就是放在该点的电荷所受电场力方向 D．以上说法均不正确6．A 、B 两个带同种电荷的绝缘金属小球，半径为 r ，球心相距 3r ，A 带电荷量 Q 1，B 带电荷量 Q 2，则 A 、B 间相互作用力（）A ．无法确定B ．等于C ．大于D ．小于 7．两个完全相同的小金属球，它们带异种电荷，电荷量的大小之比为 5：1（两小球皆可视为点电 荷），它们在相距一定距离时相互作用力为 F 1，如果让它们接触后再放回各自原来的位置上，此时 相互作用力变为 F 2，则 F 1：F 2 为（ ）A ．5：2B ．5：4C ．5：6D ．5：98．某电场的分布如图所示，带箭头的实线为电场线，虚线为等势面．A 、B 、C 三点的电场强度分 别为 E A 、E B 、E C ，电势分别为 φA 、φB 、φC ，关于这三点的电场强度和电势的关系，以下判断正确 的是（ ）A ．E A ＜EB ，φB =φC B ．E A ＞E B ，φA ＜φB C ．E A ＞E B ，φA ＞φBD ．E A =E C ，φB =φC9．关于电场、电场强度、电场线，下列说法中不正确的是（ ）A ．电场是电荷周围客观存在的物质B ．电场线是为了形象描述电场而假想的曲线C ．电场线不可能相交D ．电场中某点电场强度的大小与放入该点的试探电荷的电荷量有关10．真空中两个同性的点电荷 q 1、q 2，它们相距较近，保持静止．释放 q 2 且 q 2 只在 q 1 的库仑力作 用下运动，则 q 2 在运动过程中受到的库仑力（ ）A ．不断减小B ．不断增加C ．始终保持不变D ．先增大后减小11．如图所示为电场中的一条电场线，A 、B 为其上的两点，E A 、E B 分别为这两点的电场强度， φA 、φB 分别为这两点的电势．下列说法正确的是（ ）A ．E A 与 EB 一定不等，φA 与 φB 一定不等B ．E A 与 E B 可能相等，φA 与 φB 可能相等C ．E A 与 E B 一定不等，φA 与 φB 可能相等D ．E A 与 E B 可能相等，φA 与 φB 一定不等二、多选题﹣18 12．关于点电荷和元电荷的说法中，正确的是（ ） A ．只有很小的球形带电体才叫做点电荷 B ．带电体间的距离比它们本身的大小大得多，以至带电体的形状和大小对它们之间的作用力影响 可以忽略不计时，带电体就可以视为点电荷 C ．元电荷就是电子 D ．任何带电体的电量都是元电荷的整数倍13．关于电现象，下列说法中正确的是（ ） A ．感应起电是利用静电感应，使电荷从物体的一部分转移到物体的另一部分的过程 B ．带电现象的本质是电子的转移，中性物体得到多余电子就一定带负电，失去电子就一定带正电 C ．摩擦起电是普遍存在的现象，相互摩擦的两个物体总是同时带等量同种电荷 D ．当一种电荷出现时，必然有等量异种电荷出现，当一种电荷消失时，必然有等量异种电荷同时 消失14．如图所示为点电荷 a 、b 所形成的电场线分布，以下说法正确的是（ ）A ．a 、b 为异种电荷B ．a 、b 为同种电荷C ．A 点场强大于 B 点场强D ．A 点电势高于 B 点电势15．如图甲所示，在 x 轴上有一个点电荷 Q （图中未画出），O 、A 、B 为轴上三点，放在 A 、B 两 点的试探电荷受到的电场力跟试探电荷所带电荷量的关系如图乙所示，则（ ）A ．A 点的电场强度大小为 2×103 N/CB ．B 点的电场强度大小为 2×103 N/CC ．点电荷 Q 在 A 、B 之间D ．点电荷 Q 在A 、O 之间三、计算题（要求写出必要的解题步骤及文字说明）16．一点电荷 Q =2.0×10﹣8C ，在距此点电荷 30cm 处，该电荷产生的电场的强度是多大？17．如图所示，在匀强电场中，有 a 、b 、c 三点，ab=5cm ，bc=12cm ，其中 a b 沿电场方向，bc 和电 场方向成 60°角，一电子（电荷量为 e =1.6×10﹣19C ）从 a 移到 b 电场力做功为 W =3.2×10 J 求：ab （1）匀强电场的场强大小及方向．电子从 b 移到 c ，电场力对它做功．（3）设φa=0，则电子在c点的电势能为多少？（4）a、c 两点的电势差等于多少？18．如图所示，一个质量m，带电量为﹣q，半径极小的小球，用丝线悬挂在某匀强电场中（电场线与水平面平行），当小球静止时，测得悬线与竖直线夹角为30°，求该匀强电场的场强大小及方向．河南省新乡市新乡县新誉佳高中2015～2016 学年度高二上学期第一次月考物理试卷（理科）参考答案与试题解析一、选择题（单项选择，每题4分，共56 分）1．下列说法正确的是（） A．牛顿第一定律是通过实验得出的 B．万有引力常量是由牛顿直接给定的 C．元电荷e的数值最早是由密立根测得 D．用实验可以揭示电场线是客观存在的【考点】物理学史．【专题】常规题型．【分析】根据物理学史和常识解答，记住著名物理学家的主要贡献即可．【解答】解：A、牛顿第一定律是在实验的基础上进一步的推理概括出来的科学理论，而不是直接通过实验得出的，也不是直接经过推论得出的，故A错误． B、万有引力常量是由卡文迪许测得的，故B错误；C、元电荷e的数值最早是由密立根测得，故C正确；D、电场线是虚拟的，实际不存在的，故D错误；故选：C．【点评】本题考查物理学史，是常识性问题，对于物理学上重大发现、发明、著名理论要加强记忆，这也是考试内容之一．2．如图把两张用软纸摩擦过的塑料片相互靠近，它们会张开，这是由于它们之间存在（）A．弹力B．摩擦力C．静电力D．磁场力【考点】物体的弹性和弹力．【专题】弹力的存在及方向的判定专题．【分析】用软纸摩擦过的塑料片会带电，两张用软纸摩擦过的塑料片带同种电，相互排斥，会张开．【解答】解：由于摩擦起电，用两张用软纸摩擦过的塑料片带同种电荷，相互靠近时，相互排斥，塑料片会张开，是由于静电力作用．故选C【点评】本题考查对摩擦起电和电荷间作用力的理解能力．同种电荷相互排斥，异种电荷相互吸引．3．下列说法正确的是（）A．元电荷就是质子 B．带电体所带电荷量一定是元电荷的整数倍 C．点电荷一定是带电量很少的带电体 D．处于静电平衡的导体的内部可能有净电荷【考点】静电现象的解释．【分析】带电体看作点电荷的条件，当一个带电体的形状及大小对它们间相互作用力的影响可忽略时，这个带电体可看作点电荷，是由研究问题的性质决定，与自身大小形状无具体关系．元电荷是最小的电荷单位；其数值等于电子或质子的带电量．【解答】解：A、元电荷是指质子或电子的带电量，不是质子、电子，更不是原子，故A错误； B、带电体所带电荷量一定是元电荷的整数倍，故B正确； C、带电体看作点电荷的条件，当一个带电体的形状及大小对它们间相互作用力的影响可忽略时，这个带电体可看作点电荷，是由研究问题的性质决定，与自身大小形状无具体关系．故C错误； D、处于静电平衡的导体的内部净电荷为零，故D错误；故选：B．【点评】对于元电荷要注意明确这不是质子也不是电子，它只是在数值上等于它们的电量．点电荷与质点一样都是理想化的模型，实际上不存在，但是有着非常重要的应用．要牢记．4．关于库仑定律，下列说法正确的是（）A．库仑定律适用于点电荷，点电荷其实就是体积最小的带电体B．根据F=，当两个带电体间的距离趋近于零时，库仑力将趋向无穷大C．带电量分别为Q和3Q 的点电荷A、B 相互作用时，B 受到的静电力是A受到的静电力的3倍D．库仑定律的适用条件是：真空和静止点电荷【考点】库仑定律．【专题】计算题．【分析】清楚库仑定律的适用条件，了解点电荷这一个理想化的模型．两个带电体间的距离趋近于零时，带电体已经不能看成点电荷呢．运用牛顿第三定律解决B受到的静电力和A受到的静电力关系．【解答】解：A、库仑定律的适用条件是：真空和静止点电荷．如果在研究的问题中，带电体的形状、大小以及电荷分布可以忽略不计，即可将它看作是一个几何点，则这样的带电体就是点电荷．一个实际的带电体能否看作点电荷，不仅和带电体本身有关，还取决于问题的性质和精度的要求．与质点等概念一样，点电荷是实际带电体的抽象和近似．所以体积大的带电体可能看作点电荷，体积小的带电体可能不能看作点电荷，故A错误．B、两个带电体间的距离趋近于零时，带电体已经不能看成点电荷呢，F=已经不能适用，故B 错误．C、根据牛顿第三定律得：B 受到的静电力和A受到的静电力大小相等．故C错误．D、库仑定律的适用条件是：真空和静止点电荷．故D正确．故选D．【点评】清楚书本中一些定理和定律的适用条件，知道在处理复杂物理问题时建立具有普遍意义的基本规律一些不可或缺的理想模型，使得问题处理更简便．5．关于电场强度 E 的说法正确的是（ ）A ．根据 E =可知，电场中某点的电场强度与电场力 F 成正比，与电量 q 成反比B ．电场中某点的场强的大小与试探电荷的大小、有无均无关 C ．电场中某点的场强方向就是放在该点的电荷所受电场力方向 D ．以上说法均不正确【考点】电场强度．【专题】电场力与电势的性质专题．【分析】电场强度是描述电场本身的性质的物理量，与试探电荷无关．场强方向是放在该点的正电 荷所受电场力方向．【解答】解：A 、B 电场强度是描述电场本身的性质的物理量，与试探电荷无关，不能说电场强度与 电场力 F 成正比，与电量 q 成反比．故 A 错误，B 正确．C 、物理学上规定，场强方向与放在该点的正电荷所受电场力方向相同，与放在该点的负电荷 所受电场力方向相反．故 C 错误．D 、由上可知 D 错误． 故选 B【点评】电场强度的定义式 E =具有比值定义法的共性，定义出场强只与电场本身有关，与放入电 场的试探电荷所受的电场力、电荷量大小无关．6．A 、B 两个带同种电荷的绝缘金属小球，半径为 r ，球心相距 3r ，A 带电荷量 Q 1，B 带电荷量 Q 2，则 A 、B 间相互作用力（）A ．无法确定B ．等于C ．大于D ．小于【考点】库仑定律． 【专题】电场力与电势的性质专题． 【分析】本题题中由于带电球的大小与它们之间的距离相比，不能忽略，因此不能看作点电荷，不 能直接利用库仑定律计算库仑力的大小，只能根据库仑定律定性的比较库仑力的大小．【解答】解：当两球心相距为 3R 时，两球不能看成点电荷，因带同种电荷，导致电量间距大于 3R ，根据库仑定律 F =k ，可知，它们相互作用的库仑力大小 F ＜，故 D 正确，ABC错误． 故选：D【点评】本题应明确当两球心相距为 3R 时，两球不能看成点电荷，不能直接运用库仑定律解答，注 意库仑定律的成立条件，理解点电荷的含义．7．两个完全相同的小金属球，它们带异种电荷，电荷量的大小之比为5：1（两小球皆可视为点电荷），它们在相距一定距离时相互作用力为F1，如果让它们接触后再放回各自原来的位置上，此时相互作用力变为F2，则F1：F2 为（）A．5：2 B．5：4 C．5：6 D．5：9【考点】库仑定律．【专题】电场力与电势的性质专题．【分析】两个球的电性不同，则接触带电的原则是先中和后平分，根据F =得出接触后再放回原处的库仑力大小．【解答】解：它们在相距一定距离时相互作用力为F1=；两电荷异性，接触后再分开，两球电量的绝对值为2q，此时两球的库仑力F2==F1，则F1：F2 为5：4，故B正确，ACD 错误；故选B．【点评】解决本题的关键掌握接触带电的原则，先中和后平分，以及掌握库仑定律的公式F =．8．某电场的分布如图所示，带箭头的实线为电场线，虚线为等势面．A、B、C 三点的电场强度分别为E A、E B、E C，电势分别为φA、φB、φC，关于这三点的电场强度和电势的关系，以下判断正确的是（）A．E A＜E B，φB=φC B．E A＞E B，φA＜φB C．E A＞E B，φA＞φB D．E A=E C，φB=φC【考点】电势差与电场强度的关系；电场强度．【专题】电场力与电势的性质专题．【分析】电场线的疏密表示电场强度的强弱，电场线某点的切线方向表示电场强度的方向．沿着电场线方向电势是降低的．【解答】解：由图示可知，A 处的电场线密，B 处的电场线稀疏，因此A点的电场强度大，B 点的场强小，即E A＞E B，E A＞E C；沿着电场线的方向，电势逐渐降低，在同一等势面上，电势相等，由图示可知，φA＞φB，φB=φC，故C正确，ABD 错误；故选：C．【点评】电场线虽然不存在，但可形象来描述电场的分布．当正电荷沿着电场线方向移动时，电场力做正功，则电势能减少，所以电势在减少．当负电荷沿着电场线方向移动时，电场力做负功，则电势能增加，而电势仍减小．A．电场是电荷周围客观存在的物质 B．电场线是为了形象描述电场而假想的曲线 C．电场线不可能相交D．电场中某点电场强度的大小与放入该点的试探电荷的电荷量有关【考点】电场线；电场强度．【专题】电场力与电势的性质专题．【分析】首先知道电场线是从正电荷或者无穷远出发出，到负电荷或无穷远处为止，沿电场线的方向，电势降低，电场线密的地方电场的强度大，电场线疏的地方电场的强度小；电场线不闭合不相交；电场强度取决于电场本身．【解答】解：AB、电场线是为了形象地描述电场而引入的假象曲线，实际不存在；而电场是实际存在的物质，故A B 正确；C、电场线不相交，否则相交的点的场强方向有两个，故C正确；D、电场中某点的场强取决于电场本身，与放入该点的试探电荷的电荷量无关，故D错误．本题选错误的，故选：D．【点评】本题考查了电场、电场线和场强的特点，知道疏密表示场强大小，切线表示场强方向，沿电场线方向电势逐渐降低，基础题．10．真空中两个同性的点电荷q1、q2，它们相距较近，保持静止．释放q2 且q2 只在q1 的库仑力作用下运动，则q2 在运动过程中受到的库仑力（）A．不断减小B．不断增加C．始终保持不变D．先增大后减小【考点】库仑定律．【专题】电场力与电势的性质专题．【分析】本题比较简单，由题可知小球受斥力，距离越来越远，因此直接利用库仑定律公式即可求解．【解答】解：带电相同的小球受斥力作用，因此距离越来越远，由于电量保持不变，根据可知距离增大，电场力将逐渐减小，故B CD 错误，A 正确．故选A．【点评】对于库仑定律公式，要明确其使用条件和各个物理量的含义．11．如图所示为电场中的一条电场线，A、B 为其上的两点，E A、E B 分别为这两点的电场强度，φA、φB 分别为这两点的电势．下列说法正确的是（）A．E A 与E B 一定不等，φA 与φB 一定不等B．E A 与E B 可能相等，φA 与φB 可能相等C．E A 与E B 一定不等，φA 与φB 可能相等D．E A 与E B 可能相等，φA 与φB 一定不等【考点】电场线．【分析】电场线的疏密表示电场强度的强弱，电场线某点的切线方向表示电场强度的方向．沿着电场线方向电势是降低的．【解答】解：电场线的疏密表示电场强度的强弱，该处仅仅一条电场线，所以不能判断出A B 两点电场强度的大小关系；沿着电场线方向电势是降低，所以φA＞φB．只有选项D符合题意，故A BC 错误，D 正确．故选：D【点评】电场线虽然不存在，但可形象来描述电场的分布，利用电场线的疏密判断场强，利用沿电场线电势逐渐减小判断电势．二、多选题12．关于点电荷和元电荷的说法中，正确的是（） A．只有很小的球形带电体才叫做点电荷B．带电体间的距离比它们本身的大小大得多，以至带电体的形状和大小对它们之间的作用力影响可以忽略不计时，带电体就可以视为点电荷C．元电荷就是电子D．任何带电体的电量都是元电荷的整数倍【考点】元电荷、点电荷．【分析】点电荷是一种理想化的物理模型；元电荷又称“基本电量”，在各种带电微粒中，电子电荷量的大小是最小的，人们把最小电荷叫做元电荷，常用符号e表示，任何带电体所带电荷都是e的整数倍【解答】解：A、带电体间的距离比它们本身的大小大得多，以至带电体的形状和大小对它们之间的作用力影响可以忽略不计时，带电体就可以视为点电荷，故A错误B正确； C、元电荷是物体带电量的最小值，不是某种电荷，故C错误； D、目前认为自然界中任何带电体所带的电荷量都是元电荷的整数倍，故D正确；故选：BD【点评】点电荷是电荷，有电荷量与电性，而元电荷不是电荷，有电荷量但没有电性13．关于电现象，下列说法中正确的是（） A．感应起电是利用静电感应，使电荷从物体的一部分转移到物体的另一部分的过程 B．带电现象的本质是电子的转移，中性物体得到多余电子就一定带负电，失去电子就一定带正电 C．摩擦起电是普遍存在的现象，相互摩擦的两个物体总是同时带等量同种电荷 D．当一种电荷出现时，必然有等量异种电荷出现，当一种电荷消失时，必然有等量异种电荷同时消失【考点】元电荷、点电荷．【专题】常规题型．【分析】摩擦起电的实质是电子从一个物体转移到另一个物体，并没有创造电荷．感应起电的实质是电荷可以从物体的一部分转移到另一个部分．【解答】解：A、感应起电是利用静电感应，使电荷从物体的一部分转移到物体的另一部分的过程，故A正确； B、带电现象的本质是电子的转移，中性物体得到多余电子就一定带负电，失去电子就一定带正电，故B正确； C、摩擦起电是普遍存在的现象，相互摩擦的两个物体总是同时带等量异种电荷，故C错误； D、当一种电荷出现时，必然有等量异种电荷出现，当一种电荷消失时，必然有等量异种电荷同时消失，故D正确；故选：ABD．【点评】摩擦起电和感应起电的实质都电子发生了转移，只是感应起电是电子从物体的一部分转移 到另一个部分．摩擦起电是电子从一个物体转移到另一个物体．14．如图所示为点电荷 a 、b 所形成的电场线分布，以下说法正确的是（ ）A ．a 、b 为异种电荷B ．a 、b 为同种电荷C ．A 点场强大于 B 点场强D ．A 点电势高于 B 点电势【考点】电场线；电场强度．【专题】电场力与电势的性质专题．【分析】电场线是从正电荷或者无穷远出发出，到无穷远处或负电荷，电场线密的地方电场的强度 大，电场线疏的地方电场的强度小．沿着电场线的方向电势降低．【解答】解：AB 、根据电场线的特点，从正电荷出发到负电荷终止可以判断是异种点荷的电场 线．故A 正确，B 错误．C 、电场线密的地方电场的强度大，电场线疏的地方电场的强度小．所以 A 点场强小于 B 点场强， 故C 错误．D 、沿着电场线的方向电势降低，所以 A 点电势高于 B 点电势，故 D 正确． 故选：AD ．【点评】加强基础知识的学习，掌握住电场线的特点，即可解决本题．15．如图甲所示，在 x 轴上有一个点电荷 Q （图中未画出），O 、A 、B 为轴上三点，放在 A 、B 两 点的试探电荷受到的电场力跟试探电荷所带电荷量的关系如图乙所示，则（ ）A ．A 点的电场强度大小为 2×103 N/CB ．B 点的电场强度大小为 2×103 N/CC ．点电荷 Q 在 A 、B 之间D ．点电荷 Q 在A 、O 之间【考点】电场强度． 【分析】由图读出两个检验电荷所受的电场力方向，分析 Q 的位置．根据电场强度的定义式 E =可 知，F ﹣q 图线的斜率等于场强的大小，分析场强的大小．【解答】解：A 、由图线斜率表示场强，可知 A 点场强大小为：E==N/C=2×103N/C ．故A 正确．× ﹣18B 、由图线斜率表示场强，可知 B 点场强大小为：E= =N/C=5×102N/C ．故 B 错误． C 、D 、由图（乙），正检验电荷放在 A 点和负检验电荷放在 B 点所受电场力方向均沿 x 轴正方向， 说明点电荷 Q 为负电荷且放在 A B 之间．故 C 正确，D 错误．故选：AC【点评】本题要掌握电场力与场强方向、大小的关系，从数学的角度理解图线 F ﹣q 斜率的物理意 义，是常用的思路．三、计算题（要求写出必要的解题步骤及文字说明）16．一点电荷 Q =2.0×10﹣8C ，在距此点电荷 30cm 处，该电荷产生的电场的强度是多大？【考点】点电荷的场强．【分析】知道点电荷的电荷量，知道离点电荷的距离，由点电荷的场强公式可以直接求得结果． 【解答】解：由点电荷的场强公式 E =k 可知，E=k =9.0×109 =2000N/C ，所以电荷产生的电场的强度是 2000N/C ． 【点评】本题是点电荷的场强公式的直接应用，掌握住公式就很简单了．17．如图所示，在匀强电场中，有 a 、b 、c 三点，ab=5cm ，bc=12cm ，其中 a b 沿电场方向，bc 和电 场方向成 60°角，一电子（电荷量为 e =1.6×10﹣19C ）从 a 移到 b 电场力做功为 W =3.2×10 J 求：ab （1）匀强电场的场强大小及方向．电子从 b 移到 c ，电场力对它做功．（3）设 φa =0，则电子在 c 点的电势能为多少？（4）a 、c 两点的电势差等于多少？【考点】电势能；电势差．【专题】电场力与电势的性质专题．【（1）电子从 a 移到 b 电场力做正功，可知电场力方向向右，由此判断电场强度方向．由 W=qEd 求解 E 的大小．电子从 b 移到 c ，电场力对它做功 W =qEbccos60°．（3）根据电场力做功，求出 a 与 c 电势能的差，再由 φa =0，求出电子在 c 点的电势能．（4）由 U =求解 a 、c 两点的电势差．【解答】解：（1）电子从 a 移到 b 电场力做正功，可知电场力方向向右，则电场强度方向水平向左．由 W ab =qEab ，得 E = =400V/m﹣18电子从b移到c，电场力做功W bc=qEbc•cos60°=3.84×10J﹣18（3）电子从a移到c，电场力做功W ac=W ab+W bc=7.04×10 J电子电势能减小7.04×10﹣18J．﹣18设φa=0，则电子在c点的电势能为﹣7.04×10 J．（4）a、c 两点的电势差U ac= =﹣44V．答：（1）匀强电场的场强大小为400V/m，方向水平向左．电子从b移到c，电场力对它做功3.84×10﹣18J．﹣18（3）设φa=0，则电子在c点的电势能为﹣7.04×10 J．（4）a、c 两点的电势差等于﹣44V．【点评】本题考查对电场中基本物理量的分析和计算能力．注意在涉及电势能的公式物理量一般代入符号运算，涉及电场力的公式一般不代入符号运算．18．如图所示，一个质量m，带电量为﹣q，半径极小的小球，用丝线悬挂在某匀强电场中（电场线与水平面平行），当小球静止时，测得悬线与竖直线夹角为30°，求该匀强电场的场强大小及方向．【考点】电场强度；物体的弹性和弹力；共点力平衡的条件及其应用．【专题】电场力与电势的性质专题．【分析】以小球为研究对象，分析小球的受力情况，作出力图，根据平衡条件和电场力公式F=qE求解场强大小和方向．【解答】解：小球在电场中受重力、电场力、拉力三个力，合力为零，则知电场力的方向水平向左，而小球带负电，电场强度的方向与负电荷所受电场力方向相反，所以匀强电场场强方向水平向右．F=mgtan30°E===，答：该匀强电场的场强大小为．。

2015-2016学年上学期第一次月考高二英语试题【新课标】120分钟满分150分第一部分听力(共两节，满分30分）第一节（共5小题，每小题1.5分，满分7.5分）听下面5段对话，每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. How much did the foundation actually give to the university?A. $20000B. $30000C. $40000.2. What is the woman's suggestion to the man?A. He should ask the instructor about it.B. He should read the instruction book.C. He should have the table installed.3. What does the man really want to do?A. Edit an advertisement.B. Work as an editor.C. Find a job.4. Why did Katie look unhappy?A. Because she just lost her job.B. Because she failed to find a job.C. Because she was sick and felt terrible.5. What does the woman imply?A. She can't help the man carry the computer.B. She is feeling too dizzy to go downstairs.C. She thinks the man can carry the computer himself.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白，每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

2015-2016学年河南省新乡市新誉佳高级中学高二（上）期中数学试卷（理科）一、选择题（每题5分，共12题）1．在△ABC中，AB=5，BC=6，AC=8，则△ABC的形状是( )A．锐角三角形B．直角三角形C．钝角三角形D．非钝角三角形2．如果a＜b，那么下列不等式一定成立的是( )A．c﹣a＜c﹣b B．﹣2a＞﹣2b C．a+c＞b+c D．a+d＞b+c3．在△ABC中，若sinA：sinB：sinC=3：4：5，则cosA的值为( )A．B．C．0 D．14．数列1，﹣3，5，﹣7，9，…的一个通项公式为( )A．a n=2n﹣1 B．a n=（﹣1）n（1﹣2n）C．a n=（﹣1）n（2n﹣1）D．a n=（﹣1）n（2n+1）5．已知{a n}是等差数列，且a2+a3+a10+a11=48，则a6+a7=( )A．12 B．16 C．20 D．246．在△ABC中，a=8，B=60°，C=75°，则b=( )A．B．C．D．7．有一长为1km的斜坡，它的倾斜角为20°，现要将倾斜角改为10°，则坡底要加长( ) A．0.5km B．1km C．1.5km D．km8．已知等差数列{a n}的前n项和为S n，若a3+a17=10，则S19的值是( )A．55 B．95 C．100 D．不确定9．设S n是等差数列的前n项和，若=，则=( )A．B．C．D．10．如果实数x、y满足条件，则2x+y的最大值为( )A．1 B．C．2 D．311．正数x、y满足x+2y=1，则xy的最大值为( )A．B．C．1 D．12．不等式y≤3x+b所表示的区域恰好使点（3，4）不在此区域内，而点（4，4）在此区域内，则b的取值范围是( )A．﹣8≤b≤﹣5 B．b≤﹣8或b＞﹣5 C．﹣8≤b＜﹣5 D．b≤﹣8或b≥﹣5二、填空题（每题5分，共4题）13．不等式（x﹣1）（2﹣x）≥0的解集是__________．14．已知不等式x2+px﹣6＜0的解集为{x|﹣3＜x＜2}，则p=__________．15．若m，n＞0，且m+2n=1，则的最小值为__________．16．等比数列{a n}的各项均为正数，且a1a5=4，则log2a1+log2a2+log2a3+log2a4+log2a5=__________．三、解答题（共6题，共70分）17．锐角三角形ABC中，边a，b是方程x2﹣2x+2=0的两根，角A，B满足2sin（A+B）﹣=0，求：（1）角C的度数；（2）边c的长度及△ABC的面积．18．某货轮在A处看灯塔B在货轮北偏东75°，距离为n mile；在A处看灯塔C在货轮的北偏西30°，距离为n mile．货轮由A处向正北航行到D处时，再看灯塔B在北偏东120°，求：（Ⅰ）A处与D处之间的距离；（Ⅱ）灯塔C与D处之间的距离．19．解不等式a2x2﹣ax﹣2＜0（a∈R）20．数列{a n}是等差数列，S n为数列{a n}的前n项和，且a2=0，a4=4．（I）求数列{a n}的通项公式a n；（n）设b n=，求数列{b n}的前n项和T n（n∈N+）．21．（1）当x＞3时，求函数y=的最小值．（2）若x2﹣2ax+2≥0在R上恒成立，求实数a的取值范围．22．设{a n}是等差数列，{b n}是各项都为正数的等比数列，且a1=b1=1，a3+b5=21，a5+b3=13 （Ⅰ）求{a n}、{b n}的通项公式；（Ⅱ）求数列的前n项和S n．2015-2016学年河南省新乡市新誉佳高级中学高二（上）期中数学试卷（理科）一、选择题（每题5分，共12题）1．在△ABC中，AB=5，BC=6，AC=8，则△ABC的形状是( )A．锐角三角形B．直角三角形C．钝角三角形D．非钝角三角形【考点】三角形的形状判断．【专题】计算题．【分析】由三角形的三边判断出b为最大边，根据大边对大角可得B为最大角，利用余弦定理表示出cosB，将已知的三边长代入求出cosB的值，由cosB的值小于0及B为三角形的内角，可得B为钝角，即三角形为钝角三角形．【解答】解：∵AB=c=5，BC=a=6，AC=b=8，∴B为最大角，∴由余弦定理得：cosB===﹣＜0，又B为三角形的内角，∴B为钝角，则△ABC的形状是钝角三角形．故选C【点评】此题考查了三角形形状的判断，涉及的知识有：余弦定理，三角形的边角关系，以及余弦函数的图象与性质，熟练掌握余弦定理是解本题的关键．2．如果a＜b，那么下列不等式一定成立的是( )A．c﹣a＜c﹣b B．﹣2a＞﹣2b C．a+c＞b+c D．a+d＞b+c【考点】不等式比较大小．【专题】应用题；整体思想；分析法；不等式的解法及应用．【分析】本选择题利用取特殊值法解决，即取符合条件的特殊的a，b的值，可一一验证A，C，D不成立，而由不等式的基本性质知B成立，从而解决问题．【解答】解：对于A，取a=﹣1，b=1，c=0即知不成立，故错；对于B，由于不等式的两边同乘以同一个负数不等号方向改变，由不等式基本性质即知成立，故对；对于C，取a=﹣1，b=1，即知不成立，故错；对于C，取a=﹣1，b=1，d=﹣2，c=0，即知不成立，故错，故选B．【点评】本小题主要考查不等关系与不等式、不等关系与不等式的应用、不等式的基本性质等基础知识，属于基础题．3．在△ABC中，若sinA：sinB：sinC=3：4：5，则cosA的值为( )A．B．C．0 D．1【考点】余弦定理．【专题】三角函数的求值．【分析】已知等式利用正弦定理化简求出三边之比，设出三边长，利用余弦定理表示出cosA，将三边长代入即可求出cosA的值．【解答】解：已知等式利用正弦定理化简得：a：b：c=3：4：5，设a=3k，b=4k，c=5k，由余弦定理得：cosA===．故选：B．【点评】此题考查了正弦、余弦定理，熟练掌握定理是解本题的关键．4．数列1，﹣3，5，﹣7，9，…的一个通项公式为( )A．a n=2n﹣1 B．a n=（﹣1）n（1﹣2n）C．a n=（﹣1）n（2n﹣1）D．a n=（﹣1）n（2n+1）【考点】数列的概念及简单表示法．【专题】计算题．【分析】首先注意到数列的奇数项为正，偶数项为负，其次数列各项绝对值构成一个以1为首项，以2为公差的等差数列，从而易求出其通项公式．【解答】解：∵数列{a n}各项值为1，﹣3，5，﹣7，9，…∴各项绝对值构成一个以1为首项，以2为公差的等差数列，∴|a n|=2n﹣1又∵数列的奇数项为正，偶数项为负，∴a n=（﹣1）n+1（2n﹣1）=（﹣1）n（1﹣2n）．故选B．【点评】本题给出数列的前几项，猜想数列的通项，挖掘其规律是关键．解题时应注意数列的奇数项为正，偶数项为负，否则会错．5．已知{a n}是等差数列，且a2+a3+a10+a11=48，则a6+a7=( )A．12 B．16 C．20 D．24【考点】等差数列的通项公式．【专题】等差数列与等比数列．【分析】利用等差数列的性质可得：a2+a11=a3+a10=a6+a7．代入已知即可得出．【解答】解：∵{a n}是等差数列，∴a2+a11=a3+a10=a6+a7．又a2+a3+a10+a11=48，∴2（a6+a7）=48，解得a6+a7=24．故选D．【点评】本题考查了等差数列的性质，属于基础题．6．在△ABC中，a=8，B=60°，C=75°，则b=( )A．B．C．D．【考点】正弦定理．【专题】计算题．【分析】由B和C的度数，利用三角形的内角和定理求出A的度数，然后由a，sinA，sinB 的值，利用正弦定理即可求出b的值．【解答】解：由内角和定理得：A=180°﹣60°﹣75°=45°，根据正弦定理得：=，又a=8，sinA=，sinB=，则b===4．故选C【点评】此题考查学生灵活运用正弦定理及特殊角的三角函数值化简求值，是一道基础题．学生做题时注意内角和定理这个隐含条件．7．有一长为1km的斜坡，它的倾斜角为20°，现要将倾斜角改为10°，则坡底要加长( ) A．0.5km B．1km C．1.5km D．km【考点】解三角形的实际应用．【专题】解三角形．【分析】根据题意作图，设出相应参数，根据∠BAC=∠ABD﹣∠C，求得∠BAC=∠C判断出三角形ABC为等腰三角形，进而求得BC．【解答】解：如图设坡顶为A，A到地面的垂足为D，坡底为B，改造后的坡底为C，根据题意要求得BC的长度，∵∠ABD=20°，∠C=10°，∴∠BAC=20°﹣10°=10°．∴AB=BC，∴BC=1，即坡底要加长1km．故选B．【点评】本题主要考查了解三角形的实际应用．考查了学生分析问题和解决问题的能力．8．已知等差数列{a n}的前n项和为S n，若a3+a17=10，则S19的值是( )A．55 B．95 C．100 D．不确定【考点】等差数列的前n项和；等差数列的通项公式．【专题】等差数列与等比数列．【分析】由等差数列的性质，结合a3+a17=10求出a10，代入前19项的和得答案．【解答】解：在等差数列{a n}中，由a3+a17=10，得2a10=10，∴a10=5．∴．故选：B．【点评】本题考查了等差数列的性质，考查了等差数列的前n项和，是基础的计算题．9．设S n是等差数列的前n项和，若=，则=( )A．B．C．D．【考点】数列的求和．【专题】方程思想；消元法；等差数列与等比数列．【分析】设等差数列的首项为a1，公差为d，运用等差数列的求和公式，由条件可得a1=﹣2d，代入求和公式，即可得到所求值．【解答】解：设等差数列的首项为a1，公差为d，由题意可得S6=3S3，即有6a1+×6×5d=3a1+×3×2d，可得a1=﹣2d，则===．故选C．【点评】本题考查等差数列的求和公式的运用，注意运用代入消元法，考查运算能力，属于基础题．10．如果实数x、y满足条件，则2x+y的最大值为( )A．1 B．C．2 D．3【考点】简单线性规划．【专题】不等式的解法及应用．【分析】由约束条件作出可行域，数形结合得到最优解，联立方程组求出最优解的坐标，代入目标函数得答案．【解答】解：由约束条件作出可行域如图，联立，解得B（1，1），令z=2x+y，得y=﹣2x+z，由图可知，当直线y=﹣2x+z过B时直线在y轴上的截距最大，z最大为2×1+1=3．故选：D．【点评】本题考查了简单的线性规划，考查了数形结合的解题思想方法，是中档题．11．正数x、y满足x+2y=1，则xy的最大值为( )A．B．C．1 D．【考点】基本不等式在最值问题中的应用．【专题】不等式的解法及应用．【分析】总经理于基本不等式求解表达式的最值即可．【解答】解：xy=x•2y≤=，当且仅当x=，时取等号．故选：A．【点评】本题考查基本不等式的应用，考查计算能力．12．不等式y≤3x+b所表示的区域恰好使点（3，4）不在此区域内，而点（4，4）在此区域内，则b的取值范围是( )A．﹣8≤b≤﹣5 B．b≤﹣8或b＞﹣5 C．﹣8≤b＜﹣5 D．b≤﹣8或b≥﹣5【考点】二元一次不等式（组）与平面区域．【专题】计算题．【分析】根据点与区域的位置关系和不等式之间的联系建立不等式组，解之可求出所求．【解答】解：∵点（3，4）不在不等式y≤3x+b所表示的区域，而点（4，4）在不等式y≤3x+b 所表示的区域∴即﹣8≤b＜﹣5故选C【点评】本题主要考查了二元一次不等式（组）与平面区域，以及点与区域的位置关系和不等式之间的联系，属于基础题．二、填空题（每题5分，共4题）13．不等式（x﹣1）（2﹣x）≥0的解集是{x|1≤x≤2}．【考点】一元二次不等式的解法．【专题】不等式的解法及应用．【分析】将不等式（x﹣1）（2﹣x）≥0的两边同乘﹣1后将二次项系数化为正，进而根据大于看两边，小于看中间，求出不等式的解集．【解答】解：∵（x﹣1）（2﹣x）≥0，∴（x﹣1）（x﹣2）≤0∴1≤x≤2故答案为：{x|1≤x≤2}【点评】本题考查的知识点是一元二次不等式，其中熟练掌握一元二次不等式的解法步骤是解答的关键．14．已知不等式x2+px﹣6＜0的解集为{x|﹣3＜x＜2}，则p=1．【考点】一元二次不等式的解法．【专题】计算题．【分析】先利用一元二次不等式的解集与相应的一元二次方程的根的关系得到一元二次方程的两个根，利用韦达定理得到不等式，求出p的值．【解答】解：因为不等式x2+px﹣6＜0的解集为{x|﹣3＜x＜2}，所以﹣3，2是方程x2+px﹣6=0的两个根所以﹣3+2=﹣p所以p=1故答案为1【点评】一元二次不等式的解集的端点是相应方程的两个根；一元二次方程的根与系数的关系．15．若m，n＞0，且m+2n=1，则的最小值为．【考点】基本不等式．【专题】不等式的解法及应用．【分析】利用“乘1法”与基本不等式的性质即可得出．【解答】解：∵m，n＞0，且m+2n=1，∴=（m+2n）=3+=3+2，当且仅当m=n=﹣1时取等号．∴的最小值为3+2．故答案为：3+2．【点评】本题考查了“乘1法”与基本不等式的性质，属于基础题．16．等比数列{a n}的各项均为正数，且a1a5=4，则log2a1+log2a2+log2a3+log2a4+log2a5=5．【考点】等比数列的性质；对数的运算性质；等比数列的前n项和．【专题】等差数列与等比数列．【分析】可先由等比数列的性质求出a3=2，再根据性质化简log2a1+log2a2+log2a3+log2a4+log2a5=5log2a3，代入即可求出答案．【解答】解：log2a1+log2a2+log2a3+log2a4+log2a5=log2a1a2a3a4a5=log2a35=5log2a3．又等比数列{a n}中，a1a5=4，即a3=2．故5log2a3=5log22=5．故选为：5．【点评】本题考查等比数列的性质，灵活运用性质变形求值是关键，本题是数列的基本题，较易．三、解答题（共6题，共70分）17．锐角三角形ABC中，边a，b是方程x2﹣2x+2=0的两根，角A，B满足2sin（A+B）﹣=0，求：（1）角C的度数；（2）边c的长度及△ABC的面积．【考点】余弦定理；正弦定理．【专题】解三角形．【分析】（1）由已知可得sin（A+B）=，由△AB C是锐角三角形，从而求得A+B=120°，即可求∠C的值．（2）由已知可得a+b=2，ab=2，根据余弦定理可求c的值，由三角形面积公式即可求解．【解答】解：（1）由2sin（A+B）﹣=0，得sin（A+B）=，∵△ABC是锐角三角形，∴A+B=120°，∴∠C=60°，（2）∵a，b是方程x2﹣2x+2=0的两根，∴a+b=2，ab=2，∴c2=a2+b2﹣2abcosC，=（a+b）2﹣3ab=12﹣6=6，∴c=，∴S△ABC=absinC==．【点评】本题主要考察了正弦定理、余弦定理、三角形的面积公式在解三角形中的应用，属于基本知识的考查．18．某货轮在A处看灯塔B在货轮北偏东75°，距离为n mile；在A处看灯塔C在货轮的北偏西30°，距离为n mile．货轮由A处向正北航行到D处时，再看灯塔B在北偏东120°，求：（Ⅰ）A处与D处之间的距离；（Ⅱ）灯塔C与D处之间的距离．【考点】解三角形的实际应用．【专题】应用题．【分析】（Ⅰ）利用已知条件，利用正弦定理求得AD的长．（Ⅱ）在△ADC中由余弦定理可求得CD，答案可得．【解答】解：（Ⅰ）在△ABD中，由已知得∠ADB=60°，B=45°由正弦定理得（Ⅱ）在△ADC中，由余弦定理得CD2=AD2+AC2﹣2AD•ACcos30°，解得CD=．所以A处与D处之间的距离为24nmile，灯塔C与D处之间的距离为nmile．【点评】本题主要考查了解三角形的实际应用．解题的关键是根据题意建立适当的三角函数模型，利用正弦定理，余弦定理等常用公式来求解．19．解不等式a2x2﹣ax﹣2＜0（a∈R）【考点】一元二次不等式的解法．【专题】计算题；分类讨论；综合法；不等式的解法及应用．【分析】由a为实数，可用a等于0和不等于0两种情况考虑：若a为0时，把a=0代入原不等式，显然不等式恒成立，当a不为0时，得到a2大于0，利用十字相乘法把方程的左边分解因式，再分类解决即可．【解答】解：根据题意分两种情况考虑：（i）当a=0时，原不等式化为﹣2＜0，显然成立，因此不等式的解集为R；（ii）当a≠0时，a2＞0，不等式a2x2﹣ax﹣2＜0变形为（ax+1）（ax﹣2）＜0，即为（x+）（x﹣）＜0，则当a＞0时，解得：﹣＜x＜，∴原不等式的解集为（﹣，），当a＜0时，解得：＜x＜﹣，∴原不等式的解集为（，﹣），综上可知，当a=0时，原不等式的解集为R，当a＞0时，原不等式的解集为（﹣，），当a＜0时，原不等式的解集为（，﹣）．【点评】此题考查了一元二次不等式的解法，由于实数a的取值不确定，故本题利用分类讨论的思想，要求学生考虑问题要全面，不要遗漏．20．数列{a n}是等差数列，S n为数列{a n}的前n项和，且a2=0，a4=4．（I）求数列{a n}的通项公式a n；（n）设b n=，求数列{b n}的前n项和T n（n∈N+）．【考点】数列的求和；等差数列的通项公式．【专题】等差数列与等比数列．【分析】（Ⅰ）设等差数列的公差为d，运用通项公式，求得公差d，即可得到所求通项公式；（Ⅱ）运用等差数列的求和公式化简b n=﹣，再由裂项相消求和，即可得到所求．【解答】解：（Ⅰ）设等差数列的公差为d，由a2=0，a4=4．即有a4﹣a2=2d=4，解得d=2，可得a n=a2+（n﹣2）d=2n﹣4；（Ⅱ）b n====﹣，则前n项和T n=b1+b2+…+b n=1﹣+﹣+…+﹣=1﹣=．【点评】本题考查等差数列的通项公式和求和公式的运用，考查数列的求和方法：裂项相消求和，考查运算能力，属于中档题．21．（1）当x＞3时，求函数y=的最小值．（2）若x2﹣2ax+2≥0在R上恒成立，求实数a的取值范围．【考点】函数的最值及其几何意义；函数恒成立问题．【专题】转化思想；换元法；函数的性质及应用；不等式的解法及应用．【分析】（1）令t=x﹣3（t＞0），用t表示函数y，再由基本不等式计算即可得到最小值；（2）运用二次函数的判别式小于等于0，解不等式即可得到所求a的范围．【解答】解：（1）令t=x﹣3（t＞0），即x=t+3，即有y==2（t++6）≥2（2+6）=24，当且仅当t=3，即x=6时，取得最小值24；（2）x2﹣2ax+2≥0在R上恒成立，即为△=4a2﹣8≤0，解得﹣≤a≤．则实数a的取值范围为．【点评】本题考查函数的最值的求法：注意运用换元法和基本不等式，考查函数恒成立问题的解法，注意运用二次函数判别式小于等于0，考查运算能力，属于中档题．22．设{a n}是等差数列，{b n}是各项都为正数的等比数列，且a1=b1=1，a3+b5=21，a5+b3=13 （Ⅰ）求{a n}、{b n}的通项公式；（Ⅱ）求数列的前n项和S n．【考点】等差数列的通项公式；等比数列的通项公式；数列的求和．【专题】等差数列与等比数列．【分析】（Ⅰ）设{a n}的公差为d，{b n}的公比为q，根据等比数列和等差数列的通项公式，联立方程求得d和q，进而可得{a n}、{b n}的通项公式．（Ⅱ）数列的通项公式由等差和等比数列构成，进而可用错位相减法求得前n项和S n．【解答】解：（Ⅰ）设{a n}的公差为d，{b n}的公比为q，则依题意有q＞0且解得d=2，q=2．所以a n=1+（n﹣1）d=2n﹣1，b n=q n﹣1=2n﹣1．（Ⅱ），，①S n=，②①﹣②得S n=1+2（++…+）﹣，则===．【点评】本题主要考查等差数列的通项公式和用错位相减法求和．。

绝密★启用前2015-2016学年度新誉佳学校9月月考卷考试时间：100分钟；注意事项：1．答题前填写好自己的姓名、班级、考号等信息2．请将答案正确填写在答题卡上第I卷（选择题）请点击修改第I卷的文字说明一、阅读理解（（共20小题；每小题2分，满分40分）ADoing homework not only can help children master the knowledge they have learned, but also can train their abilities of finishing the work alone, planning the time and doing the duties. But some children don’t like to complete the work. Why? There are some reasons.Some children feel it i s very difficult to do their homework, because they can’t understand their teacher clearly, and can’t follow their teacher’s teaching process. Maybe there is something wrong with their intelligence.But some children’s intelligence is normal. They are even cleverer, but they don’t listen to the teacher carefully. It is hard for them to sit well and pay attention to anything. It needs to carry on the attention centralized（集中注意力）training to help the children.Some children love their teacher and then they like the subject. Their interest depends on the teacher who teaches them. So every teacher should be helpful and kind. It can make children love you and the subject you teach. So they can do their homework happily.1. Doing homework can help children ___________.A. master the knowledgeB. train their abilitiesC. lean new lessonsD. Both A and B2．Some children find the homework difficult. Which reason is NOT right?A. They can’t understand their teacher clearly.B. They can’t follow their teacher’s teaching process.C. The intelligence of all the students isn’t normal.D. They don’t listen to the teacher carefully.3．What’s the Chinese meaning of the underlined word “intelligence”?A. 作业B. 智商C. 思想D. 方式4．According to the last paragraph, the writer thinks ________ is very important.A. a teacherB. a subjectC. attentionD. homework5．What is the best title of the passage?A. Some children don’t like their teacher.B. Children’s homework is very difficultC. Why don’t some children like to do homework?D. Why can’t some children study the subjects well?BAmericans won’t live without cars! Each year there is an increasing number of cars on roads and streets, as millions of new cars are produced．One of every six Americans work at putting together the parts of cars, driving trucks, buin by cars．The lding roads or filling cars with gas．Most Americans find it hard to think what life would be without a car．However, so me have realized the serious problem of air pollutiopolluted air is poisonous and dangerous to health．One way to get rid of the polluted air is to design a new car that does not pollute．That’s what several large car factories are trying to do．But to build the new car is easier said than done．Progress in this field has been slow．Another way is to take place of the car engine by something else．Engineers are now working on some new cars．Many makers believe that it will take years to develop a practical model that pleases man．To prevent the world fro m being polluted by cars, we’ll have to make some changes in the way many of us live．Americans, for example, have to cut down the number of their cars they are encouraged to travel and go to work by bike．Riding a bike is thought to help keep the air clean．But this change does not come easily．A large number of workers may find themselves with no jobs if a car factory closes down．And the problem of air pollution would become less important than that of unemployment．6．Large car factories are trying to build a clean car, ．A．which is clean itselfB．which is used to clean streetsC．which does not pollute the airD．which is easier to make7．If the number of cars is cut down, the most serious problem in American workers is ．A．to have no work to doB．to keep the air cleanC．to get a better lifeD．to go to work by bike8．What is the conclusion of the writer?A．Bicycling is the only way out．B．The number of ears must be cut down.C．Cars bring us nothing but serious problems.D．Cars bring us not only a better life but serious problemsCThomas Alva Edison was awarded more patents on inventions than any other American. When he died in 1931, Americans wondered how they could best show their respect for him. One suggestion was that the nation observe a minute or two of total blackout. All electric power would be shut off in homes, streets, and factories. Perhaps this suggested plan made Americans realize fully what Edison and his inventions mean to them. Electric power was too important to the country. Shutting it off for even a short time would have led to complete confusion. A blackout was impossible.On the day of Edison's funeral, many people silently dimmed their lights. In this way they honored the man who had done more than anyone else to put the great force of electricity at his countrymen's fingertips.9．This selection says that Thomas Edison ________.A．was the only important American inventorB．received the first American patentC．received more patents than any other AmericanD．was the first American inventor10．People decided to honor Edison when ________.A．he made the first electric lightB．electric power was 100 yearsC．the country realized electricity's importanceD．he died in 193111．The suggested plan was to ________.A．turn off the lights in factories and schoolsB．observe a few minutes of total silenceC．dim all electric lightsD．shut off all electricity for a short timeD．Lillian Hanson, a college student, expects to graduate in about two years. What makes Mrs. Hanson different from her classmates is her age-----73 years. She has been studying at college, a few courses at a time, for 27 years.When Lillian Hanson graduated from high school, she went to the bank to borrow money for further education. The banker gave her no encouragement. He didn’t think that a country girl should borrow money to go to college. He thought she should be at home doing work in the house or around the farm. So Lillian Hanson went home and raised a family of nine children instead of going to college. Mrs. Hanson never forgot her dream of getting a higher education. When her children were grown, she tried again.She finds that it is the hardest part of going back to school at her age to sit in class for long periods of time. Because she is not as quick as she used to be, Mrs. Hanson often gets up and walks around classes to keep from getting stiff(不灵活). At the beginning of a course in using the computer, the other students all stood up to give her a warm welcome when she introduced herself and explained why she was there and what her aims were.12. Mrs. Hanson couldn’t go to college immediately after she graduated from high school because ____________.A. she hadn’t got enough moneyB. she was a country girlC. the banker ordered her not to borrow any moneyD. the banker thought she should raise a family of nine children13. The computer students welcomed Mrs. Hanson warmly because ______.A. she had got an excellent result in the examB. she was good at telling funny storiesC. they wanted to get her help in their studiesD. they were deeply moved by her spirit14. Mrs. Hanson is the sort of person who ________.A. cares for study very muchB. likes to borrow money from the bankC. never misses a chance to talkD. tries to save any money for her family15. In which order did Mrs. Hanson do the following things?a. she began her studies at college.b. She finished high school.c. She got married and gave birth of nine children.d. She had her 73 rd birthday.e. She went to the bank to borrow money.A. a c b e dB. b e c a dC. b c e d aD. e d a c b二、信息匹配（七选五）Kids with Special NeedsKids with special needs refer to any kid who might need extra help because of medical, emotional, or learning problems. For example, disabled kids need wheelchairs. They not only need the equipment that helps them get around, but they might need to have ramps(斜坡) or elevators available.16.．Kids with an illness would have special needs, too. 17．Kids with sight problems might need Braille books to read. Kids with hearing problems might need hearing aids.18．It might be harder to do normal things—like learning to read or just getting aroundschool. The good news is that parents, doctors, nurses, teachers, and others can help. The goal is to help kids be as independent as possible.Other kids also can be a big help. How? By being a friend. Kids who use a wheelchair or have lots of health problems want friends just as you do. But meeting people and making friends can be difficult. 19．Be sure to tell a teacher if you see someone being bullied(欺侮) or teased.20．You might carry the person’s books or do something simple, such as asking him or her to join you and your frie nds at lunch. It’s also important not to be “overly helpful” when no help is needed. Why? Because just like you, kids with special needs like to be as independent as they can be.Being friendly to kids with special needs is one of the best ways to be helpful. As you get to know, they may help you understand what it’s like to be in their shoes. And you’ll be helping fill a very special need, one that everybody has—the need for good friends.A.Some kids might laugh at or make fun of them.B.They also might need to get a special bus to school.C.Life can be challenging for a kid with special needs.D.It’s good manners to try to offer help to kids with special needs.E.Also try to be helpful if you know someone with special needs.F.Kids with special needs usually live a harder life than normal kids.F.They might need medicine or other help as they go about their daily activities.三、完形填空（共20小题；每小题1.5分，满分30分）We are warned by our teachers not to waste time because time 21 will never return. I think it quite 22. What does time look 23? Nobody knows, and we can’t see it or touch it and no 24 of money can buy it. Time is abstract(抽象的), so we have to 25about it.Time passes very quickly. Some students say they don’t have 26time to review their lessons. It is 27 they don’t know how to make use of their time. They waste it in going to theatres or playing, and 28 other useless things. Why do we study everyday? Why do we work? Why do most people 29 take buses instead of walking? The answer is very 30 .We wish to save time because time is31.Today we are living in the 21st century. We 32 time as life. When a person dies, his life ends.Since life is short, we must 33 our time and energy to our study so that we 34 be able to work and live well in the future. Laziness is the 35 of time, for it not only brings us 36, but also does other 37 to us. If it is necessary for us to do our work today, 38 us do it today and not 39 it until tomorrow. Remember that time is much more 40.21．A. lost B. passed C. missed D. used22．A. Important B. true C. interesting D. usual23．A. for B. like C. after D. over24．A. amount B. quality C. quantity D. price25．A. think B. imagine C. examine D. check26．A. spare B. free C. enough D. much27．A. that B. why C. because D. certain28．A. doing B. Making C. taking D. getting29．A. needn’t B. have to C. had better D. would rather30．A. easy B. simple C. stupid D. interesting31．A. worthless B. priceless C. ready D. little32．A. look upon B. agree C. think D. believe33．A. spend B. give C. set D. devote34．A. must B. should C. may D. would35．A. helper B. thief C. friend D. teacher36．A. wealth B. health C. failure D. illness37．A. danger B. harm C. trouble D. difficulty38．A. help B. make C. have D. let39．A. keep B. remain C. manage D. leave40．A. Valuable B. expensive C. worth D. rich第II卷（非选择题）四、语法填空（共10小题，每小题1.5分，共15分）John Snow was a famous doctor in London.In his time cholera was the deadly disease.SoJohn Snow made up his mind to help ordinary people41. (expose) to cholera.At that time, neither its cause42. its cure was understood.He knew it would never be controlled until its cause was found.He thought people got attacked by this disease43. (absorb )into their bodies.He tried to prove this.So when another outbreak hit London in 1854, he gathered information and made a map, marking where all the dead people had lived.It was 44. (value) And finally he concluded that the water was45.(blame).Then John Snow looked into the source of water.He found all the deaths were46. (link) to the polluted water.So he was able to announce with certainty that47.(pollute)water carried the disease.To prevent this 48happening again, John Snow suggested that the source of all the water supplies 49. (examine)and new methods of 50. (deal) with polluted water be found.Finally “King Cholera” was defeated. .五、短文改错（共10小题；每小题1分，满分10分）33．下面短文中有10处语言错误。

绝密★启用前2015-2016学年度新誉佳高级中学第一次月考高一年级英语试卷考试时间：100分钟第I卷第一部分听力（共两节，满分30分）第二部分阅读理解（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的四个选项（A、B、C和D）中，选出最佳选项ATwo men were sitting together in a plane. They were on a long journey. One of the men was a businessman. The other was a farmer. They sat without talking for a while, then the farmer said, “Let’s do something to pass the time.”“What do you want to do?” the businessman asked. “We can ask each other riddles.” The farmer said, “You start.” “Let’s make the rules first,” the businessman said. “That’s not fair. You are a businessman with much knowledge. You know more things than I do. I am just a farmer.”“That’s true.” The businessman said. “What do you want we should do?” “If you don’t know the answer to a riddle, you pay me $100. And if I don’t know the answer, I’ll pay you $50.” The farmer said. The businessman thought about this, then he said, “OK. That’s fair. Who will go first?”“I will,” The farmer said. “Here is my riddle. What has three legs when it walks, but only two legs when it flies?” The business man repeated the riddle, “What has three legs when it walks, but only two legs when it flies? Mm, that’s a good one. I’m afraid I don’t know the answer.” He gave the farmer $100, then said, “Tell me the answer. What has three legs when it walks, but only two legs when it flies?” “I don’t know.” The farmer said and gave him $50.1．The story happened ____________.A. on a farmB. in a shopC. before a long plane journeyD. between two passengers2．What does the word “riddle” mean in this story?A. A difficult question to find the answer to.B. Something to help to make rules.C. Something to win money.D. a kind of game in doing business.3．Why did the businessman agree to give more money if he lost?A. He made much more money than the farmer.B. He thought he knew more than the farmer.C. He was interested in making riddles.D. He was better at playing riddle games.4．The farmer _________.A. enjoyed himself on his long journey.B. didn’t want to pay even one dollarC. spent all his money on the plane ticket.D. won fifty dollars by playing the riddle game5．Which of the following is NOT true?A. The two men made rules for their riddle.B. The farmer was much cleverer than the businessman.C. The two men made their riddle game more interesting by paying it for money.D. The businessman knew the answer to his riddle.BEvery person has their own way of saying things, their own special expressions. Many everyday American expressions are based on colours.Red is a hot colour. Americans often use it to express heat. They may say they are red hot about something unfair. When they are red hot they are very angry about something. The small hot tasting peppers found in many Mexican foods are called red hots for their colour and their fiery taste. Fast loud music is popular with many people. They may say the music is popular with many people. They may say the music is red hot, especially the kind called Dixieland jazz.Pink is a lighter kind of red. People sometimes say they're in the pink when they're in good health. The expression was first used in America at the beginning of the 20th century. It probablycame from many babies who were born with a nice pink color showing good health.Blue is a cool colour. The traditional blues music in the United States is the opposite of red hot music. Blues is slow, sad and soulful. Duke Ellington and his orchestra recorded a famous song—Mood Indigo—about the deep blue colour, indigo. In the words of the song: “You aren’t blue till you’ve had that Mood Indigo.” Someone who is blue is very sad.The colour green is natural for trees and grass. But it is an unnatural colour for humans. A person who has a sick feeling in his stomach may say he feels a little green. A passenger on a boat who is feeling very sick from high waves may look very green.Sometimes a person may be upset b ecause he does not have something as nice as his friend’s, like a fast new car. That person may say he is green with envy. Some people are green with envy because a friend has more dollars of greenbacks. Dollars are called greenbacks because that is the colour of the back side of the paper money.The colour black is often used in expressions. People describe a day in which everything goes wrong as a black day. The date of a major tragedy is remembered as a black day. A blacklist is illegal now. But at one time, some businesses refused to employ people who were on a blacklist for belonging to unpopular organizations.6．If you had your wallet stolen while doing some shopping, you may call it _____.A. a white dayB. a black dayC. a red dayD. a green day7．Suppose Mr. Brown says he is very happy because his three children are all in the pink, this means all his children are .A. lucky and wealthyB. gentle and modestC. fit and healthyD. creative and energetic8．When she got home and found nothing had been done by her husband, Jane was really .A. red hotB. greenC. blueD. black9．In the following paragraph, the writer might tell the reader something about .A. unpopular organizations in the worldB. people’s response towards a black dayC. the influence of the traditional bluesD. more words about a colour, such as brownCEveryone needs friends. We all like to feel close to someone. It is nice to have a friend to talk, laugh, and do things with. Surely, there are times when we need to be alone. We don’t always want people around. But we will feel lonely if we never have a friend.No two people are just the same. Sometimes friends don’t get along well. That doesn’t mean that they no longer like each other. Most of the time they will make up and go on being friends. Sometimes friends move away. Then we feel very sad. We miss them very much. But we call them and write to them. It could be that we would even see them again. And we can make new friends. It is surprising to find out how much we like new people when we get to know them.Families sometimes name their children after a close friend. Many places are named after men or women who have been friendly to people in a town. Some libraries are named this way. So are some schools. We think of these people when we go to these places.There’s more good news for people who have friends. They live longer than people who don’t. Why? It could be that they are happier. Being happy helps you stay well. If someone cares about you, you will feel good.10．The first paragraph tells us .A. what the feeling of having no friends isB. we always need friends around usC. making friends is a need in people’s lifeD. we need to be alone in our life11．Which of the following places people name after their friendly people is NOT mentioned (提到) in the passage?A. A town.B. A room.C. A school.D. A library.12．Why do people who have friends live longer?A. They know more about friendship.B. They feel happier and healthier.C. They take less care of themselves.D. They care more about their friends.DHere are a few tips we’ve put together to help you learn English well.●Speak, speak, speakPractise speaking as often as you can—even speaking to yourself is good practice.Try recording yourself whenever you can. Compare your pronunciation with some famous persons’, see how you can do better and have another go. If you do this several times, you will find that each time is better than the last.●Why not learn with someone else?It helps if you can learn with someone else. If you can persuade a friend or a family member to study with you, it will make you keep working.●Don’t get stuck by a word you don’t know.Practise improvising（即兴的）ways of getting your meaning across when speaking spontaneously（本能地）, even if you don’t know the exact words or phrases. Think of things you might want to say whenever you have spare time. Use facial expressions, hand movements, anything to get your meaning across.●Language learning is also about intuition（直觉）.Guesswork is an important way to learn a new language. When listening to recorded material, you aren’t expected to understand everything at once. If you play the same piece several times, you will most probably understand something new each time.●Build up your vocabulary.A wide vocabulary is the key to successful language learning but don’t try to learn too much at once. It’s best to study often, for short periods of time. Take at most six or seven items of vocabulary and learn them. Put them into sentences to remember them in your mind, then come back to them later.And above all, have fun!13．Why should one have himself recorded when practicing speaking?A. To improve his speaking.B. To record his own progress.C. To encourage others to start.D. To become a famous person.14．It is implied(暗示) in the passage that _______ is helpful when you are learning English. A. a good dictionary B. a good school C. excellent pronunciation D. body language 15．According to the passage, one should ______ when you are learning English.A. always work with other peopleB. be able to guess everything newC. often review what he has learntD. take little notice of grammar第二节（共5小题；每小题2分，满分10分）根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。

高二第一次月考英语试题（时间：120分钟满分：150分）第一卷第一部分：听力（共两节，满分30分）第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话，每段对话后有一个小题，从题后所给的A,B, C三个选项中选出最佳选项，听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1.What does the man mean?A.Mike is often late for school.B. Mike is never late for school.C.Mike is sometimes late for school.2.Who knows the way to the hospital?A .The woman B. The man C. Neither of them3. What are the speakers listening to?A. The televisionB. The recorderC. The radio4. Where does the conversation probably take place?A. In a restaurantB. In a libraryC. At a market5.What does the man mean?A. The woman has enough bread to eat.B. There isn’t enough bread for the woman to eat.C. The woman has eaten enough bread.第二节（共15小题；每小题1.5分，满分22.5分）听下面4段对话或独白。

每段对话或独白后有几个小题，从题中所给的A , B , C三个选项中选出最佳选项，听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各个小题将给出5秒钟的作答时间。

2016届高二年级月考英语试卷及答案第I卷第一部分听力（共两节，满分30分）做题时，先将答案标在试卷上。

录音内容结束后，你将有两分钟的时间将试卷上的答案转答到答题卡上。

第一节（共5小题；每小题1.5分，满分7.5分）听下面 5 段对话。

每段对话后有一个小题，从题中所给的 A、B、C 三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有 10 秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1．Who will help fix the man’s comput er?A．Jim B．His brother C．The woman’s brother2．How does the man feel about his interview?A．Worried B．Confident C．Disappointed3．Whom are the two speakers probably talking about?A．Their student B．Their classmate C．Their daughter4．How often does the woman go bowling each week?A．Twice a week B．Three times a week C．Four times a week\5．What does the woman think of the dress?A．Ugly B．Common C．Excellent第二节听下面 5 段对话。

每段对话后有几个小题，从题中所给的 A、B、C 三个选项中选出最佳选项，并标在试卷的相应位置。

听每段对话前，你将有时间阅读各个小题，每小题 5 秒钟；听完后，各小题将给出 5 秒钟的作答时间。

每段对话读两遍。

听第 6 段材料，回答第 6、7 题。

6．Where does the man read the news?A．In the newspaper B．In the magazine C．On the Internet7．What is the news mainly about?A．A latest plane crash B．The effect of global warmingC．Actions taken to prevent pollution听第 7 段材料，回答第 8、9 题。

2015-2016学年度秋学期第一次月考高二英语试卷Class: Name: Marks: 满分（150）第一部分听力（共两节，满分30分）第一节（共5小题;每小题15分，满分7. 5分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1.What’s John’s address?A.1343 King Street.B. 1344 Queen Street.C. 1434 King Street.2.How much should the skirt have cost?A . $6. B. $ 12. C. $ 24.3.What can we learn about the man?A .He might lie very often.B. His grandmother died just now.C. His grandfather gets ill quite often .4.When is the man’s birthday?A .March 31st . B. April 1st . C. April 2nd.5.How will the woman get to New York?A By carB By trainC By airplane第二节（共15小题;每小题1. 5分，满分22. 5分）听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟;听完后，各小题将给出5秒钟的作答时间。

每段对话或独白读两遍。

听第6段材料，回答第6、7题。

6.What will the woman do on Friday night?A. Visit a friend.B. Work overtimeC. Have dinner with Tim.7.What is the woman’s phone number?A.917-8427.B. 917-8426.C. 916-8426.听第7段材料，回答第8至10题。

英语试题试卷共4页, 全卷满分150, 考试用时120分钟。

★祝考试顺利★第一部分：听力（共两节, 满分 30 分）第一节: 听下面5 段对话。

每段对话后有一个小题, 从题中所给的A、B、C 三个选项中选出最佳选项, 并标在试卷的相应位置。

1. What does Professor Evans do most of the time?A. Conduct experiments.B. Give lectures.C. Attend meetings.2. How does the woman learn Chinese?A. By chatting with others.B. By listening to the radio.C. By taking an online course.3. What is the man going to do?A. Go back to his office.B. Attend a meeting.C. Leave the office.4. How does the woman plan to improve the article?A. By talking to the editor.B. By asking the man to rewrite it.C. By making suggestions on it.5. What season is it now?A. Spring.B. Autumn.C. Winter.第二节：（共15 小题；每小题 1.5, 满分22.5 分）听第6段材料，回答第6、7题。

6. Where does this conversation most likely take place?A. In a concert hall.B. In a parking lot.C. In a restaurant.7. What does the man advise the woman to do?A. Make a quick choice.B. Find their seats first.C. Drive to the hall.听第7段材料，回答第8至10题。

2015-2016学年度新誉佳高级中学期中考试高一年级英语试卷考试时间：100分钟第I卷第一部分听力（共两节，满分30分）第二部分阅读理解（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的四个选项（A、B、C和D）中，选出最佳选项AIt was a dark and cold night. The car driver didn’t have even one passenger all day. When he went by the railway station, he saw a young man coming out with two bags in his hands. So he quickly opened the door of the car and asked, “Where do you want to go, sir?”“To the Star Hotel,” the young man answered. When the car driver heard that, h e didn’t feel happy. The young man would give him only three dollars because the hotel was not far from the railway station. But suddenly, he had an idea. He took the passenger through many streets of the big city.After a long time, the car finally ar rived at the hotel. “You should pay me fifteen dollars,” the car driver said to the young man. “What! Fifteen dollars? Do you think I’m a fool? Only last week I took a car from the railway station to this same hotel and I only gave the driver thirteen dollars. I know how much I have to pay for the trip. I won’t pay you one dollar more than I paid to the other car driver last week.”1．Which of the following is true?____________A.The young man went past the railway station.B.The young man was working in the railway stationC.The young man had just got off a train.D.The you man was waiting for his friend there.2． What do you think of the car driver?__________A.He was a nice and clever man.B. He liked to work very hard.C. He was good at drivingD. He was not an honest person.3．The driver felt very _________ when he saw the young man coming out of the railway station.A.sadB. sorryC. happyD. worried4．From the passage we know that the young man__________.A.knew clearly how far it was from the station to the hotel.B.Had been to the hotel several times.C.Didn’t want to stay in this city.D.Must be a stranger and didn’t know the city very well.BHave you ever been to London? Here is some hotel information for you.Kingsway Hall HotelWe offer quality service (优质服务) in Kingsway Hall Hotel. This location puts guests in easy reach of many places, such as the British Museum and Piccadilly Circus. Our hotel also has modern Western food, and offers a perfect dining environment. The lounge bar is a comfortable place to enjoy a drink while watching the tourists. There are hundreds of dining choices within walking distance. Non-smoking rooms are ready for guests.Hilton Docklands RiversideLocated on the bank of the Thames, our hotel is about two miles east of Tower Bridge and 36 miles from London Heathrow Airport. Our hotel has a beauty salon, a flower shop and a swimming pool. The hotel also offers laundry (洗衣店) services, babysitting, shining shoes, and local area transportation.Windermere HotelLocated in the center of London, our hotel puts guests within easy reach of London’s well-known buildings. Buckingham Palace and the Royal Parks are just a short walk away. Within 1.5 miles you can visit Westminster Abbey and the Houses of Parliament. The theatres, Harrods shopping centre, and the designer shops of5． What does Kingsway Hall Hotel provide for its guests?A. Chinese food.B. A lounge bar.C. Smoking rooms.D. A swimming pool.6．What is special about Hilton Docklands Riverside?A. It offers different kinds of service.B. It offers a reasonable price.C. It has convenient transport.D. It has delicious food.7．This passage is most likely to be found in ______.A. a travel guideB. a story bookC. a technical reportD. a geography magazineCToo many people want others to be their friends, but they don’t give friendship back. That is why some friendships do not last very long. To have a friend, you must learn to be one. You must learn to treat your friend the way you want your friend treat you. Learning to be a good friend means learning three rules. Be honest; be generous; be understanding.Honesty is where a good friendship starts. Friends must be able to trust one another. If you do not tell the truth, people usually find out. If a friend finds out that you haven’t been honest you may lose your friends’ trust. Good friends always count on one another to speak and act honestly.Generosity means sharing and sharing makes a friendship grow. You do not have to give your lunch money on your clothes of course. Instead you have to learn how to sharethings you enjoy, like your hobbies and your interest. Naturally you will want to share your ideas and feelings. These can be very valuable to a frien d. They tell your friend what is important to you. By sharing them you help your friend know yo u better. Sooner or later every one needs understanding and help with a problem. Something may go wrong at school. Talking about the problem can make it easier to solve. Turning to a friend can be a first step in solving the problem. So to be a friend you must listen and understand. You must try to put yourself in your friend’s place so you can understand the problem better.No two friendships are ever exactly alike. But all true friendships have three things in common. If you plan to keep your friends, you must practise honesty, generosity, and understanding.8．Some friendships don’t last very long because ____.DThe arts, especially music, should be part of every school's lessons at every grade level. Students would be much smarter if they had some musical experience. They could improve their classroom skills, like paying attention and following directions. People develop all these skills when they learn music. Making music also lets children use their imagination. It provides students with a chance to try out their own ideas. Music not only makes children better students, but also gives them something positive to do. In a music program, children can be part of a band instead of joining a gang (团伙). Parents can enjoy listening to their children's music instead of seeing them glued to a computer or TV screen. In a school band, students get to be part of a team. They can get along well with old friends and make new friends through music. Music builds self-confidence, too. It gives children a sense of achievement and success. Making music is something for them to be proud of, and it lets kids practice performing in front of an audience. Music gives children an opportunity for self-express ion, and that helps develop their self-confidence.Once again, music is important because it can make children better students, give them something positive to do, and build their character. That is why music should be offered in every single grade in every school.12．According to the passage, music could make students smarter by _______________.A. improving their classroom skills and payin g attentionB. improving their classroom skills and imaginationC. improving their attention, direction and imaginationD. learning music, making music and trying out their own ideas13．What does the underlined phrase "glued to" in the second paragraph mean?A. unwilling to turn onB. always lookingC. unwilling to leaveD. always playing14．The third paragraph mainly tells us that music could _______________.A. give children self-expression and self-confidenceB. bring to children achievement and successC. give children something to be proud ofD. develop children's self-confidence15．What's the best title of this passage？A. Music is a must as a course at schoolB. Music builds children's self-confidenceC. Music makes students much smarterD. Learning music and making music第二节（共5小题；每小题2分，满分10分）根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。