莆田一中08~09学年度第一学期期中考试试卷[岳麓版][试题19]
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2008-2009学年度福建省莆田一中第一学期高三第二学段考试英语试卷本试卷分为第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分。
共150分,考试时间120分钟。
第Ⅰ卷一、听力(共20小题;每小题1.5分,满分30分)第一节1.What is the man?A.A waiter. B.A clerk. C.An airhostess.2.How many hours does the woman work every week?A.40. B.47. C.50.3.What is the probably relationship between the speakers?A.Sister and brother. B.Mother and son. C.Teacher and pupil.4.What would the woman like to drink?A.Coffee. B.Milk. C.Tea.5.What does the woman plan t do tomorrow?A.Sleeping late. B.Do some washing upC.Cooking breakfast herself.第二节听第6段材料,回答第6至7题。
6.Who is “Mr. Rice Guy”?A.A famous cook. B.An actor C.A dancer.7.What can we learn about “Mr. Rice Guy”?A.He is good at cooking B.He likes watching dinnertime show.C.He is learning to cool from his wife.听第7段材料,回答第8至10题。
8.Where is the man going?A.To Paris. B.To London. C.To Berlin.9.How did the man go to Europe in World War ⅡA.By plane. B.By warship. C.By truck.10.How soon will the speakers arrive?A.In 2 hours. B.In 4 hours. C.In 6 hours.听第8段材料,回答第11至13题。
莆田一中2008~2009学年上学期第一学段考试试卷高二 数学必修3选修1-1命题人:文科备课组一、 选择题:本大题共12小题,每小题5分,共60分. 1. “21<-x ”是“3<x ”的 ( )A .充分不必要条件 B.必要不充分条件C .充分必要条件 D.既不充分也不必要条件2.如果方程222x ky +=表示焦点在y 轴上的椭圆,那么实数k 的取值范围是 A .(0,)+∞ B .(0,2) C .(1,)+∞ D .(0,1)3. 现有五个球分别记为A ,B ,C ,D ,E ,随机放进三个盒子,每个盒子只能放一个球,则D 或E 不在盒中的概率是( ) A.103 B. 53 C. 107 D. 1094.有以下四个命题,其中真命题的个数有( ) ①“若1xy =,则,x y 互为倒数”的逆命题; ②“相似三角形的周长相等”的否命题;③“若1b ≤-,则方程2220x bx b b -++=有实根”的逆否命题; ④“若B B A = ,则A B ⊇”的逆否命题.A .①②B .②③C .①③D .③④5. 两个事件对立是两个事件互斥的( ) A.充分非必要条件 B.必要非充分条件 C.充要条件 D.既不充分又不必要条件6.用二分法求方程的近似根,精确度为 ,则当型循环结构的终止条件是( ) A. >-21x x B. ==21x x C.21x x << D. <-21x x7.把38化成二进制数为( )A .100110 B.101010 C.110100 D.1100108.计算机执行右边的程序段后,输出的结果是( ) A .1,3 B .4,1 C .0,0 D .6,09. 有一部四卷文集,按任意顺序排放在书架的同一层上,则各卷自左到右或由右到左卷号恰为1,2,3,4顺序的概率等于( )A.81 B.121 C.161 D. 24110.椭圆221259x y +=上的点M 到焦点F 1的距离是2,N 是MF 1的中点,则|ON |为( )A .4 B.2 C.8 D.2311. 设椭圆的两个焦点分别为F 1、F 2,过F 2作椭圆长轴的垂线交椭圆于点P ,若△FPF 2为等腰直角三角形,则椭圆的离心率是( )A.C.2- 1 12. P 是椭圆22195x y +=上的动点,过P 作椭圆长轴的垂线,垂足为M ,则PM 的中点的轨迹方程是( )A .224195x y += B. 224195x y += C .221920x y += D .221365x y +=二、填空题:本大题共6小题,每小题5分,共30分.13.命题“若ab =0,则a ,b 中至少有一个为零”的逆否命题是 。
莆田一中2023-2024学年度上学期高三期中考试卷数学试题1.答题前,考生务必将自己的姓名、考生号等填写在答题卡和试卷指定位置上.2.回答选择题时,选出每小题答案后,用铅笔把答题卡上对应题目的答案标号涂黑.如需改动,用橡皮擦干净后,再选涂其它答案标号.3.考试结束后,将答题卡交回.一、单项选择题:8小题,每小题5分,共40分.在每小题给出的四个选项中,只有一项符合题意.1.设集合{}{24,A x x x B x y =≤==,则A B ⋂=Rð()A.[)0,3 B.(]0,3 C.[]3,4 D.(]3,42.实数,x y 满足21,0x y x +=->,则yx x-的最小值为()A.1B.2C.3D.43.设α是第二象限角,P (x ,1)为其终边上一点,且1cos 3x α=,则tan α=()A.22-B.24-C.22 D.244.正多面体被古希腊圣哲认为是构成宇宙的基本元素,加上它们的多种变体,一直是科学、艺术、哲学灵感的源泉之一.如图,该几何体是一个棱长为2的正八面体,则此正八面体的体积与表面积之比为()A.18B.69C.612D.635.已知定义域为R 的函数()f x ,其导函数为()f x ',且满足()()0f x f x '-<,()01f =,则()A.()e 11f -< B.()1ef > C.1e 2f ⎛⎫<⎪⎝⎭D.()11e 2f f ⎛⎫>⎪⎝⎭6.已知()sin cos f x a x x =+的图象关于π3x =对称,则函数()sin cos g x x a x =+的图象的一条对称轴是x =()A.π6 B.π3C.2π3D.5π67.函数()(),01,21,20x x x f x f x x ⎧-≤≤⎪=⎨+-≤<⎪⎩的图象大致为()A.B.C. D.8.在三棱锥-P ABC 中,6,2PA PB PC AC AB =====,且AC AB ⊥,则三棱锥-P ABC 外接球的表面积为()A.8πB.9πC.16πD.24π二、多项选择题:本题共4小题,每小题5分,共20分.在每小题给出的选项中有多项符合题目要求.全部选对的得5分,部分选对的得2分,有选错的得0分.9.下列化简结果正确的是()A.1cos22sin52sin22cos522︒︒-︒︒= B.tan24tan3631tan24tan36︒︒︒-︒+=C.cos15sin152︒-︒=D.1sin15sin30sin754︒=︒︒10.下列命题正确的是()A.“1x >”是“2232xx +>”的充分不必要条件B.2log 211log 27lg25lg472+++=C.函数()[]2sin ,0,πf x x x x =-∈,则()πππ62f f f ⎛⎫⎛⎫<<⎪ ⎪⎝⎭⎝⎭D.函数()21,1,2log ,1,xx f x x x ⎧⎛⎫≤⎪ ⎪=⎨⎝⎭⎪>⎩若()2f x ≤,则实数x 的取值范围是[]1,4-11.已知0ω>,函数()πcos 3f x x ω⎛⎫=+⎪⎝⎭,下列选项正确的有()A.若()f x 的最小正周期2T =,则πω=B.当2ω=时,函数()f x 的图象向右平移π3个单位长度后得到()cos 2g x x =的图象C.若()f x 在区间2π,π3⎛⎫⎪⎝⎭上单调递增,则ω的取值范围是51,3⎡⎤⎢⎥⎣⎦D.若()f x 在区间()0,π上只有一个零点,则ω的取值范围是17,66⎛⎤⎥⎝⎦12.已知函数()2ln ,01,0x x x f x x x >⎧=⎨-≤⎩,则()A.若函数()()g x f x k =-有两个零点,则01k ≤≤B.当0x >时,()32f x x <恒成立C.若方程()()ff x a =有5个解,则实数a 的取值范围是1,0e⎛⎫- ⎪⎝⎭D.若过点(),(0)P a a a >与曲线()f x 相切的直线有两条,则实数a 的取值范围是()e,+∞三、填空题:本题共4小题,每小题5分,共20分.13.已知函数()322f x ax bx x =-+是定义在[]21,3a a +-上的奇函数,则a b +=______.14.已知π0,2α⎛⎫∈ ⎪⎝⎭,10cosα10=,则1sin2cos2αα-=______.15.已知函数()()sin f x A x ωϕ=+(其中π0,0,2A ωϕ>><)的部分图像如右图所示,则()f x 在ππ,23⎡⎤--⎢⎥⎣⎦上的值域为______.16.已知实数,a b 满足32e e e ,ln e ab a b==,其中e 是自然对数的底数,则ab 的值为______.四、解答题:本题共6小题,共70分.解答应写出文字说明、证明过程或演算步骤.17.已知函数()()26cos 3sin230f x x x ωωω=+->的最小正周期为8.(1)求函数()f x 的单调减区间;(2)若()0835f x =,且0102,33x ⎛⎫∈- ⎪⎝⎭,求()01f x +的值.18.已知函数()()32R f x x bx c x =++∈的图象过点()1,2P -,且在点P 处的切线恰好与直线330x y -+=垂直.(1)求函数()f x 的解析式;(2)若函数()y f x =的图象与抛物线213412y x x m =-+-恰有三个不同交点,求m 的取值范围.19.如图,在三棱锥-P ABC 中,,PA PC AB AC ⊥⊥,平面PAC ⊥平面ABC ,24AC PA ==.(1)证明:PB PC ⊥;(2)若三棱锥-P ABC 的体积为833,求平面ABC 与平面PBC 所成角的余弦值.20.已知函数()sin xf x x=.(1)当π0,2x ⎛⎤∈ ⎥⎝⎦时,求函数()f x 的最小值;(2)若()33e xx g x x x a =-+-,且对1π0,2x ⎛⎤∀∈ ⎥⎝⎦,都[]20,2x ∃∈,使得()()12f x g x ≤成立,求实数a的取值范围.21.中国象棋是中国棋文化,也是中华民族的文化瑰宝,它源远流长,趣味浓厚,基本规则简明易懂.在中国有着深厚的群众基础,是普及最广的棋类项目.某地区举行中国象棋比赛,先进行小组赛,每三人一组,采用单循环赛(任意两人之间只赛一场),每场比赛胜者积3分,负者积0分,平局各1分.根据积分排名晋级淘汰赛,若出现积分相同的情况,则再进行加赛.已知甲、乙、丙三人分在同一个小组,根据以往比赛数据统计,甲、乙对局时,甲胜概率为25,平局概率为15;甲、丙对局时,甲胜概率为13,平局概率为13;乙、丙对局时,乙胜概率为12,平局概率为16.各场比赛相互独立,若只考虑单循环赛的三场比赛,求:(1)甲积分的期望;(2)甲、乙积分相同的概率22.已知函数()()ln f x x x k k =--(1)讨论函数()f x 在[]1,e 上的单调性;(2)若函数()()xf x kxg x +=在[]1,e 上单调递减,求实数k 的取值范围.莆田一中2023-2024学年度上学期高三期中考试卷数学试题1.答题前,考生务必将自己的姓名、考生号等填写在答题卡和试卷指定位置上.2.回答选择题时,选出每小题答案后,用铅笔把答题卡上对应题目的答案标号涂黑.如需改动,用橡皮擦干净后,再选涂其它答案标号.3.考试结束后,将答题卡交回.一、单项选择题:8小题,每小题5分,共40分.在每小题给出的四个选项中,只有一项符合题意.1.设集合{}{24,A x x x B x y =≤==,则A B ⋂=Rð()A.[)0,3 B.(]0,3 C.[]3,4 D.(]3,4【答案】A 【解析】【分析】先解不等式求出A ,再求出B 和R B ð,最后求出R A B ⋂ð即可.【详解】2404x x x ≤⇒≤≤,所以{}04A x x =≤≤,303x x -≥⇒≥,所以{}3B x x =≥,所以{}R 3B x x =<ð,所以{}R 03A B x x ⋂=≤<ð,故选:A2.实数,x y 满足21,0x y x +=->,则yx x-的最小值为()A.1B.2C.3D.4【答案】D 【解析】【分析】用已知条件消元后用基本不等式即可.【详解】因为21x y +=-,所以12y x =--所以1212224y x x x x x x x+-=+=++≥+=,当且仅当1x =取等号故选:D .3.设α是第二象限角,P (x ,1)为其终边上一点,且1cos 3x α=,则tan α=()A.22-B.24-C.22 D.24【答案】B 【解析】【分析】利用三角函数的定义先解得x ,再求正切值即可.【详解】由三角函数定义可知:1cos 3x x α==⇒=±,又α是第二象限角,故x =-,所以tan 4y x α==-.故选:B4.正多面体被古希腊圣哲认为是构成宇宙的基本元素,加上它们的多种变体,一直是科学、艺术、哲学灵感的源泉之一.如图,该几何体是一个棱长为2的正八面体,则此正八面体的体积与表面积之比为()A.618B.69C.612D.63【答案】B 【解析】【分析】正八面体的上、下结构是两个相同的正四棱锥,由勾股定理求得斜高,再由棱锥的体积公式即可求解.【详解】如上图,由边长为2,可得正八面体上半部分的斜高为2213EG =-=312EO =-=其体积为22282222333AB BC EO V ⋅⋅⨯⨯=⨯=⨯=,其表面积为328888322EG BC S ⋅=⨯=⨯=∴此正八面体的体积与表面积之比为69.故选:B.5.已知定义域为R 的函数()f x ,其导函数为()f x ',且满足()()0f x f x '-<,()01f =,则()A.()e 11f -<B.()1ef >C.12f ⎛⎫<⎪⎝⎭D.()112f ⎛⎫>⎪⎝⎭【答案】C 【解析】【分析】构造()()x f x g x =e,利用导数及已知判断其单调性,根据单调性及相对应函数值判断各项的大小.【详解】令()()x f x g x =e,则()()()()()()2e e e e x x x x f x f x f x f x g x ⋅--==''',因为()()0f x f x '-<在R 上恒成立,所以()0g x '<在R 上恒成立,故()g x 在R 上单调递减,()()10g g ->,即()()()110e 11eef f f --=->=,故A 不正确;()()10g g <,即()()010eef f <,即()()1e 0e f f <=,故B 不正确;()102g g ⎛⎫< ⎪⎝⎭,即()1021021e ef f ⎛⎫⎪⎝⎭<=,即12f ⎛⎫< ⎪⎝⎭,故C 正确;()112g g ⎛⎫> ⎪⎝⎭,即()12112e e f f ⎛⎫ ⎪⎝⎭>,即()112f ⎛⎫< ⎪⎝⎭,故D 不正确;故选:C6.已知()sin cos f x a x x =+的图象关于π3x =对称,则函数()sin cos g x x a x =+的图象的一条对称轴是x =()A.π6 B.π3C.2π3D.5π6【答案】A 【解析】【分析】化简后结合三角函数的对称轴即可求解.【详解】()()1sin cos ,tan f x a x x x aϕϕ=+=+=,又图象关于3x π=对称,,32k k ππϕπ+=+∈Z ,可以求得6k πϕπ=+,故()11sin 2sin cos 2sin tan 223a g x x x x x x πϕ⎫⎛⎛⎫===+=+=+⎪ ⎪⎪⎝⎝⎭⎭,对称轴为,326x k x k πππππ+=+=+,0k =时即A 项.故选:A .7.函数()()1,21,20x x f x f x x ⎧-≤≤⎪=⎨+-≤<⎪⎩的图象大致为()A. B.C. D.【答案】D 【解析】【分析】先利用导函数研究01x <≤上的单调性,得到()f x x =-在10,4x ⎛⎫∈ ⎪⎝⎭上单调递减,在1,14x ⎛⎤∈ ⎥⎝⎦上单调递增,且1144f ⎛⎫=- ⎪⎝⎭,进而研究10-<≤x 上的单调性,得到在314x -<≤-上单调递减,在304x -<≤上单调递增,且3142f ⎛⎫-=- ⎪⎝⎭,从而选出正确答案.【详解】当01x <≤时,()1f x '=-=当10,4x ⎛⎫∈ ⎪⎝⎭时,()0f x '<,当1,14x ⎛⎤∈ ⎥⎝⎦时,()0f x ¢>,故()f x x =10,4x ⎛⎫∈ ⎪⎝⎭上单调递减,在1,14x ⎛⎤∈ ⎥⎝⎦上单调递增,所以()f x x =-14x =处取得极小值,11114424f ⎛⎫=-=- ⎪⎝⎭,当10-<≤x 时,011x <+≤,故()(21f x x =+-,()2f x '==,当314x -<≤-时,()0f x '=<,当304x -<≤时,()0f x '=>,()(21f x x =+-在314x -<≤-上单调递减,在304x -<≤上单调递增,且33121442f ⎛⎛⎫-=-+=- ⎪ ⎝⎭⎝,显然1124-<-,综上:只有D 选项满足要求.故选:D8.在三棱锥-P ABC 中,2PA PB PC AC AB =====,且AC AB ⊥,则三棱锥-P ABC 外接球的表面积为()A.8πB.9πC.16πD.24π【答案】B 【解析】【分析】根据题意,由条件确定球心的位置,即可得到球的半径,再由球的表面积公式,即可得到结果.【详解】由题意可得,点P 在底面上的射影M 是CB 的中点,是三角形ABC 的外心,令球心为O ,因为2AC AB ==,且AC AB ⊥,所以MB MC MA ===,又因为PA PB PC ===2PM ==,在直角三角形OBM 中,222OB OM BM =+,即()2222R R =+-,解得32R =,则三棱锥外接球的表面积为294π4π9π4R =⨯=.故选:B 二、多项选择题:本题共4小题,每小题5分,共20分.在每小题给出的选项中有多项符合题目要求.全部选对的得5分,部分选对的得2分,有选错的得0分.9.下列化简结果正确的是()A.1cos22sin52sin22cos522︒︒-︒︒=B.tan24tan361tan24tan36︒︒︒-︒+=C.cos15sin15︒-︒=D.1sin15sin30sin754︒=︒︒【答案】AB【解析】【分析】根据题意,由三角函数的和差角公式,代入计算,对选项逐一判断,即可得到结果.【详解】()1cos22sin52sin22cos52sin 5222sin302︒︒-︒︒=︒-︒=︒=,所以A 正确;()tan24tan36tan 2436tan601tan24tan36︒+︒=︒+︒=︒=-︒︒B正确;)()2cos15sin15cos45cos15sin45sin1545152︒-︒=︒︒-︒︒=︒+︒=,所以C 错误;()11sin15sin30sin75sin15sin30sin 9015sin15cos15sin30sin30sin3028︒︒︒=︒︒︒-︒=︒︒︒=︒︒=,所以D 错误.故选:AB .10.下列命题正确的是()A.“1x >”是“2232x x +>”的充分不必要条件B.2log 211log lg25lg472+++=C.函数()[]2sin ,0,πf x x x x =-∈,则()πππ62f f f ⎛⎫⎛⎫<<⎪ ⎪⎝⎭⎝⎭D.函数()21,1,2log ,1,xx f x x x ⎧⎛⎫≤⎪ ⎪=⎨⎝⎭⎪>⎩若()2f x ≤,则实数x 的取值范围是[]1,4-【答案】ABD【解析】【分析】对于选项A ,令20x t =>,转化为2320t t -+>求解判断;对于选项B ,利用对数的运算求解判断;对于选项C ,利用导数法判断()2sin f x x x =-的单调性求解判断;对于选项D ,分1x ≤,1x >,分别利用指数函数和对数函数不等式求解判断.【详解】对于选项A ,令20x t =>,则由2232x x +>得2320t t -+>,解得2t >或1t <,1x ∴>或0x <,故“1x >”是“2232x x +>”的充分不必要条件.故A 正确;对于选项B ,原式()323311log 3lg 25422222=+⨯+=++=,故B 正确;对于选项C ,函数()2sin f x x x =-,可得()2cos 1f x x ='-,其中[]0,πx ∈,当π0,3x ⎡⎫∈⎪⎢⎣⎭时,()0f x ¢>;当π,π3x ⎛⎤∈ ⎥⎝⎦时,()0f x '<,所以()f x 在π0,3⎡⎫⎪⎢⎣⎭上单调递增,在π,π3⎛⎤ ⎥⎝⎦上单调递减,因为ππππππππ2sin 2,2sin 122226666f f ⎛⎫⎛⎫=-=-=-=-⎪ ⎪⎝⎭⎝⎭,可得πππππ211026263f f ⎛⎫⎛⎫-=--+=-< ⎪ ⎪⎝⎭⎝⎭,所以ππ26f f ⎛⎫⎛⎫< ⎪ ⎪⎝⎭⎝⎭,又()f x 在π,π3⎛⎤ ⎥⎝⎦上单调递减,所以()ππ2f f ⎛⎫< ⎪⎝⎭,所以()πππ26f f f ⎛⎫⎛⎫<< ⎪ ⎪⎝⎭⎝⎭,所以C 是错误.对于选项D ,当1x ≤时,令122x ⎛⎫ ⎪⎭≤⎝,得1x ≥-,故11x -≤≤;当1x >时,令2log 2x ≤,得4x ≤,故14x <≤.综上,14x -≤≤.故D 是正确;故选:ABD11.已知0ω>,函数()πcos 3f x x ω⎛⎫=+ ⎪⎝⎭,下列选项正确的有()A.若()f x 的最小正周期2T =,则πω=B.当2ω=时,函数()f x 的图象向右平移π3个单位长度后得到()cos 2g x x =的图象C.若()f x 在区间2π,π3⎛⎫ ⎪⎝⎭上单调递增,则ω的取值范围是51,3⎡⎤⎢⎥⎣⎦D.若()f x 在区间()0,π上只有一个零点,则ω的取值范围是17,66⎛⎤ ⎥⎝⎦【答案】ACD【分析】由余弦函数周期的公式,可判定A 正确;利用三角函数的图象变换,可判定B 错误;根据()f x 在区间2π,π3⎛⎫ ⎪⎝⎭上单调递增,列出不等式组,求得ω的范围,得到当0k =时,不等式有解,可判定C 正确;由()f x 在区间()0,π上只有一个零点,列出不等式组,求得ω的范围,可判定D 正确.【详解】解:由余弦函数图象与性质,可得2π2T ω==,得πω=,所以A 正确;当2ω=时,可得()πcos 23f x x ⎛⎫=+⎪⎝⎭,将函数()f x 的图象向右平移π3个单位长度后得()ππππcos 2cos 23333f x x x g x ⎡⎤⎛⎫⎛⎫⎛⎫-=-+=-≠ ⎪ ⎪ ⎪⎢⎝⎭⎝⎭⎝⎭⎣⎦,所以B 错误;若()f x 在区间2π,π3⎛⎫ ⎪⎝⎭上单调递增,则2ππ2π33,Z ππ2π2π3k k k ωπω⎧+≥+⎪⎪∈⎨⎪+≤+⎪⎩,解得5132,Z 3k k k ω+≤≤+∈,又因为0ω>,所以只有当0k =时,此不等式有解,即513ω≤≤,所以C 正确;若()f x 在区间()0,π上只有一个零点,则ππ32π3π32πωπω⎧+>⎪⎪⎨⎪+≤⎪⎩,解得1766ω<≤,所以D 正确.故选:ACD .12.已知函数()2ln ,01,0x x x f x x x >⎧=⎨-≤⎩,则()A.若函数()()g x f x k =-有两个零点,则01k ≤≤B.当0x >时,()32f x x <恒成立C.若方程()()f f x a =有5个解,则实数a 的取值范围是1,0e ⎛⎫- ⎪⎝⎭D.若过点(),(0)P a a a >与曲线()f x 相切的直线有两条,则实数a 的取值范围是()e,+∞【解析】【分析】对于A ,画出函数图象,根据图象即可判断;对于B ,化简为ln x <t =,不等式变形为2ln t t <,构造函数()2ln ,0h t t t t =->,利用导数考查单调性,求得最大值即可判断;对于C ,令()(),f x t f t a ==,分离讨论a 的范围,考查()f t a =的解的情况,进一步分析即可;对于D ,根据图象观察即可.【详解】因为当当0x >时,()ln ,()ln 1f x x x f x x '==+,令()ln 10f x x '=+>得1x e >,令()ln 10f x x '=+<,得10x e<<,所以()f x 在1(,)e +∞上单调递增,在1(0,)e上单调递减,则min 11()(f x f e e==-,且0x ≤时,2()1f x x =-,故可画出函数()f x 的大致图象如图所示:由图知函数()()g x f x k =-有两个零点时,则01k ≤≤或1ek =-,故A 错误;对于B ,因为0x >,不等式为32ln x x x <,即ln x <t =不等式化为2ln t t <.令()()22ln ,t h t t t h t t=='--,令()0h t '=,得2t =,当()0,2t ∈时,()0h t '>,则()h t 在()0,2上单调递增,当()2,t ∈+∞时,()0h t '<,则()h t 在()2,+∞上单调递减,故最大值为()22ln220h =-<,则2ln t t <恒成立,故B 正确;对于C ,令()(),f x t f t a ==,当1a >或1e<-a 时,方程()f t a =只有一解记为0t ,此时()0f x t =不可能有5解。
2020-2021学年莆田一中高三数学期中考试卷命题人: 审核人:高三备课组(满分:150分,时间:120分钟)一、选择题(8小题,每小题5分,共40分.在每小题给出的四个选项中,只有一项符合题意)1.设集合A={y| y=4-x2},B={x| y=4-x2},则( ) A.A=B B. A⋂B=∅ C. A⊆B D. B⊆A2.复数z满足i⋅z=1-2i, z̅是z的共轭复数则z⋅z̅=( )A. 3B. 5C. 3D. 53.已知向量a=(1,1),b=(-1,3),c=(2,1)且(a-λb)⊥c,则λ=( )A.3B.2C.-2D.-34.已知f(x)=e-x+k e x(k为常数),那么函数f(x)的图象不可能是( )A B C D5. 在平面直角坐标系xOy中,角α与角β均以Ox为始边,它们的终边关于y轴对称.若sinα=2 3,则cos(α-β)=( )A.19 B.459 C.-19 D.-4596. 把物体放在冷空气中冷却,如果物体原来的温度为θ1︒C,空气温度为θ0︒C,那么t 分钟后物体的温度θ(单位︒C)可由公式:θ=θ0+(θ1-θ0)e -kt 求得,其中k 是一个随着物体与空气的接触状况而定的正常数.现有100︒C 的物体,放在20︒C 的空气中冷却,4分钟后物体的温度是60︒C ,则再经过m 分钟后物体的温度变为40︒C(假设空气温度保持不变),则m = ( ) A.2 B.4 C.6 D.87.已知P 是椭圆C :x 2a 2+y 2b 2=1(a >b >0)上的点,F 1,F 2分别是C 的左,右焦点,O 是坐标原点, 若|OP →+OF 2→|=2|OF 1→|且∠F 1PF 2=60︒,则椭圆的离心率为 ( )A. 12B.32C. 3-12D. 338.集合论中著名的“康托三分集”是数学理性思维的产物,具有典型的分形特征,其具体操作过程如下:将闭区间[0,1]均分为三段,去掉中间的区间段(13,23),记为第一次操作;再将剩余的两个区间[0,13],[23,1]分别均分为三段,并各自去掉中间的区间段,记为第二次操作;⋅⋅⋅;如此这样,每次在上一次操作的基础上将剩下的各个区间分别均分为三段,同样各自去掉中间的区间段,操作的过程不断进行下去,以至无穷,剩下的区间集合即是“康托三分集”。
莆田一中2008—2009学年度上学期第一学段高三语文科试卷命题人:高三备课组审核人:黄喜彬友情提示:考试时间150分钟,满分150分。
沉着冷静,认真答题,祝你成功!一、阅读下面的文言文,完成1—3题。
(9分)李希烈陷汝州。
(卢)杞乃建遣真卿:“四方所信.,若往谕之,可不劳师而定。
”诏可,公卿皆失色。
至河南,河南尹郑叔则以.希烈反状明,劝不行,答曰:“君命可避乎?”既见希烈,宣诏旨,希烈养子千余拔刃争进,诸将皆慢骂,将食之,真卿色不变。
希烈以身捍,麾其众退,乃就.馆,逼使上书雪己,真卿不从。
乃诈遣真卿兄子岘与从吏数辈继请,德宗不报。
真卿每与诸子书,但戒严奉家庙,恤诸孤,讫无它语。
希烈遣李元平说之,真卿叱曰:“尔受国委任,不能致命,顾吾无兵.戮汝,尚说我邪?”希烈大会其.党,召真卿,使倡优斥侮朝廷,真卿怒曰:“公,人臣,奈何如是!”拂衣去。
时朱滔、王武俊等使者皆在坐,谓希烈曰:“闻太师名德久矣,公欲建大号而太师至,求宰相孰先太师者?”真卿叱曰:“吾年且八十,官太师,吾守吾节,死而后已,岂受若.等胁邪!”诸贼失色。
希烈乃拘真卿,守以甲士,掘方丈坎于廷,传将坑之。
真卿见希烈曰:“死生分矣,何多为?”会其党周曾、康秀林等谋袭希烈,奉真卿为帅,事泄,曾死,乃拘送真卿蔡州。
真卿度必死,乃作遗表、墓志、祭文,指寝室西壁下曰:“此吾殡所也。
”希烈僭.称帝,使问仪式,对曰:“老夫耄矣,曾掌国礼,所记诸侯朝觐耳!”兴元后,王师复振,贼虑变,遣将辛景臻、安华至其所,积薪于廷曰:“不能屈节,当焚死。
”真卿起赴火,景臻等遽止之。
希烈弟希倩坐朱此诛,希烈因.发怒,使阉奴等害真卿,曰:“有诏。
”真卿再拜.奴曰:“宜赐卿死。
”曰:“老臣无状,罪当死,然使人何日长安来?”奴曰:“从大粱来。
”骂曰:“乃逆贼耳,何诏云!”遂缢杀之,年七十六。
(节选自((新唐书·颜真卿传》)注:①建大号:即称帝。
1、对下列句子中加点词语的解释,不正确的一项是(3分) ()A、四方所信.信:信任B、麾其众退,乃就.馆就:进入C、顾吾无兵.戮汝兵:士兵D、希烈僭.称帝僭:越过,超过2、下列各组句子中,加点的词的意义和用法都相同的一组是(3分) ()A、郑叔则以.希烈反状明夫夷以.近,则游者众B、希烈因.发怒因.人之力而敝之,不仁C、希烈大会其.党而余亦悔其.随之而不得极夫游之乐也D、岂受若.等胁邪不者,若.属皆且为所虏3、下列对原文有关内容的分析和概括,不正确的一项是(3分) ()A、颜真卿明知去李希烈处传达圣旨,生还希望渺茫,但他认为君命不能违,所以没有以年老为借口,而是义无反顾,勇于赴死。
2008-2009学年度福建省莆田一中第一学期高三第一学段考试生物试卷第Ⅰ卷(共43分)一、选择题(本题包括42小题,前41题为单项选择,每小题1分;42题2分,为多项选择。
)1.果蝇的体色由常染色体上一对等位基因控制,基因型BB.Bb为灰身,bb为黑身。
若人为地组成一个群体,其中80%为BB的个体,20%为bb的个体,群体随机交配,其子代中Bb的比例是A.25%B.32%C.50%D.64%2.下列为某一遗传病的家系图,已知I一1为携带者。
可以准确判断的是A.该病为常染色体隐性遗传B.II-4是携带者C.II一6是携带者的概率为1/2 D.Ⅲ一8是正常纯合子的概率为1/2 3.格里菲思(F.Griffith)用肺炎双球菌在小鼠身上进行了著名的转化实验,此实验结果A.证明了DNA是遗传物质B.证明了RNA是遗传物质C.证明了蛋白质是遗传物质D.没有具体证明哪一种物质是遗传物质4、DNA复制和转录的场所有①细胞核②线粒体③叶绿体④核糖体⑤拟核A.①②③⑤B.①③④⑤C.①②③④D.①②④⑤5、下面是几个同学对有关蛋白质和核酸之间关系的总结,你认为其中错误的是A.在同一生物体内,不同的体细胞核中DNA分子是相同的,但蛋白质和RNA是不同的B.基因中遗传信息通过mRNA传递到蛋白质,遗传信息通过蛋白质中的氨基酸的排列顺序得到表达C.在蛋白质合成旺盛的细胞中,DNA分子多,转录成的mRNA分子也多,从而翻译成的蛋白质就多,如胰岛腺细胞与口腔上皮细胞相比较就是如此D.在真核细胞中,DNA的复制和RNA的转录主要在细胞核中完成而蛋白质的合成均在细胞质中完成6.下列为某一段多肽链和控制它合成的DNA双链的一段。
“-甲硫氨酸-脯氨酸-苏氨酸-甘氨酸-缬氨酸”密码表:甲硫氨酸AUG 脯氨酸CCA.CCC.CCU苏氨酸ACU、ACC.ACA 甘氨酸GGU、GGA.GGG缬氨酸GUU、GUC.GUA根据上述材料,下列描述中,错误的是()A.这段DNA中的①链起了转录模板的作用B.决定这段多肽链的遗传密码子依次是AUG、CCC.ACC.GGG、GUAC.这条多肽链中有4个“一CO—NH一”的结构D.若这段DNA的②链右侧第二个碱基T为G替代,这段多肽中将会出现两个脯氨酸7、已知病毒的核酸有双链DNA.单链DNA.双链RNA和单链RNA四种类型。
莆田一中2008—2009学年上学期第一学段考试试题高一英语必修Ⅰ命题人胥均审核人郑惠华(本试卷考试时间120分钟,满分100分,附加题20分)一、听力理解:(共两节,20分)第一节1.What are the two speakers going to buy?A.Bread.B.Cheese. C.Eggs.2.How does the woman find the fish?A.Just so-so. B. Bad C.Quite good. 3.What does the woman mean?A.Mark should go on with the game.B.Mark should draw pictures on the computer.C.Mark should review his lessons.4.Where does the conversation take place?A.In the bookstore. B.In the library. C.In the classroom. 5.Why doesn’t she like chocolate cake?A.She doesn’t like chocolate.B.She has trouble with her tooth.C.She has no tooth.第二节:请听第6段材料,回答第6-7题。
6.In which department can this conversation most probably take place?A.Shoe Department. B.ClothingDepartment. C.Jewelry Department. 7.What could be the reason if the woman does not buy the overcoat?A.The color. B.The size. C.The price.请听第7段材料,回答第8—10题8.What can the woman be?A.A waitress at a hotelB.The secretary of Mr. BlackC.The assistant of Professor Green.9.How could the man get in touch with Mr. Green?A.Ask the woman to find the Blackwood Hotel.B.Dial 809.C.Dial 114 to find the telephone number of the Blackwood Hotel.10.Why did the man ask the woman to change the dollar?A.To pay for the information.B.To make a phone call.C.To go to the hotel by bus.请听第8段材料,回答第11—14题11.What is the man doing?A.Selling his house.B.Looking for a house.C.Looking for work.12.How long has the woman lived in the house?A.19 years. B.8 years. C.20 years. 13.Why does the woman want to sell the house?A.She wants to move abroad.B.She wants to move to the countryside.C.She hopes to get a lot of money.14.How much does the house cost?A.$6,850. B.$6,815. C.$7,850请听第9段材料,回答第15—17题15.What’s the probable relationship between the two speakers?A.Friends. B.Strangers.C.Husband and wife16.How did the woman find her stay there?A.Boring B.Wonderful C.Adventurous 17.What does the man advise the woman to do when she gets home?A.Send him an email. B.Write a letter to him.C.Give him a call.请听第10段材料,回答第18—20题.18.How old was Rose when she left school?A.16. B.17. C.18 19.What did Rose learn in the college?A.Computer. B.English. C.Typing. 20.How much will the office pay Rose in three months if she gets the job?A.$30. B.$27. C.$20.二.单项填空:(15分)21. Jenny ______ have kept her word, I wonder why she changed her mind.A. mustB. shouldC. needD. would22. Could you tell me ______ last year?A. which school you were atB. which school you wereC. which school were you atD. where school were you23. Some people ______ playing football while others enjoy ______ football matches.A. be fond of; watchB. are fond; watchingC. are fond of; watchedD. are fond of; watching24. Tom promises he’ll come to the party ______ he isn’t invited.A. as ifB. evenC. even thoughD. because25. I had just gone to bed after a very hard day ______ the phone rang.A. suddenlyB. whenC. whileD. as26. All these changes will lead to ______ strong and powerful China, ______ countrythat can surprise and enrich our planet.A. a; aB. the; aC. the; theD. a; the27. Over 200 people ______ in the building when the fire ____outA. worked; brokeB. had worked; brokeC. worked; was breakingD. were working; broke28. Why not _____ her _______ as she likes?A. let; doesB. let; doC. to let; to doD. letting; do29. _____ the age of ten, he ___ to play the piano.A. At; had learnedB. At; learnsC. By; had learnedD. At; has learned30. ---- When ____ you ____ for Shanghai?---- Next Monday.A. are; leavingB. do; leaveC. did; leaveD. are; left31. There are ____ women doctors in this hospital. ____them is 52.A. a number of; The number ofB. the number of; A number ofC. number of; Number ofD. a number of; The number32. It____ that more than 200 people _____ in the fire.A. is reported; are killedB. was reported; had been killedC. is reported; were killedD. is reported; killed33. The yellow house ______ windows face south is the place ____I spent mychildhood.A. whose; thatB. whose; whereC. which; whereD. where; which34. Patient: I have a serious stomachache.Doctor: _________. You’ll be fine soon.A. Take it easyB. It doesn’t matter.C. That’s OKD. Don’t worry35. The doctor asked me what _______ with you .A. was the matterB. the matter wasC. is the matterD. the matter is36. This is the place _____ I visited three years ago.A. whereB. thatC. in whichD. there37. He called the police for help, _______ that the problem was more than he coulddeal with.A. having been realizedB. to realizeC. realizingD. realized38. If you don’t go there, _________.A. so will IB. neither will IC. I won’t, tooD. nor do I39. --- You haven’t done it well, I’m afraid.--- But I did it the way _______ you told me.A. 不填B. howC. whatD. which40. Noise is unpleasant, ________ when you’re trying to get some sleep.A. generallyB. usuallyC. speciallyD. especially41. Oh, I’m not feeling well in the stomach. I ____ so much fried chicken just now.A. shouldn’t eatB. mustn’t have eatenC. shouldn’t have eatenD. mustn’t eat42. You should be playing ________ working indoors; you need some exercise.A. andB. orC. instead ofD. in order to43. During the working hours all the doctors and nurses had to ________ masks andclose-fitting white caps because SARS was going around.A. wearB. put onC. dressD. be dressed in44. You made the same mistake for ________ second time, dropping ________ “n” inthe word government.A. a; theB. a; anC. the; anD. a; a45. All through his life Abraham Lincoln fought _____ an end of slavery(奴隶制度).A. againstB. forC. withD. up46. ________ is known to all, China will be an ________ and powerful country in 20or 30 years’ time.A. That; advancingB. It; advancedC. As; advancingD. As; advanced47. The poor man, ________ lost his money just now, is called John.A. thatB. whichC. whoD. whom48. She decided to write about Chaplin, one of ______ films she had seen years before.A. whoseB. whomC. whichD. that49. The boy pointed to the direction ________ he would run.A. in whichB. to whichC. thatD. which50. This is the reason ________ at the meeting for his carelessness in his work.A. he explainedB. what he explainedC. how he explainedD. why he explained三.完形填空:(20分)It was Tom’s first visit to England, and he was looking forward to his first journey, on London’s Underground Railway. And against his friends’_51___, he was determined to travel __52__.He entered the station shortly after five o’clock in the afternoon. This is a __53___time to travel in London, _54__crowds of people go home from work at this hour. He _55___ to join a long line of people waiting for tickets. When at last his _56__ came, he had some difficulty in making himself understood by the ticket seller. __57___, he got the right ticket in the end and, by asking people the way, he also found the right _58___. It was __59___ tight with people. He did not _60___ to get on the first train, but he was able to move nearer to the edge of the platform so as to be in a better _61____ to get on the next one. When this train came in, Tom was _62_____ forward onto the train by the _63____ of people from behind. The doors closed and the train moved off. He was unable to see the _64___ of the stations where the train _65____, but he knew that the station he wanted was the sixth _66____ along the line. When the train reached the sixth station, Tom got off, feeling _67___ that his journey had been so easy. But he suddenly realized that he had come to a station he had never _68____. He explained his __69___ to a man who was standing on the platform. With a _70____ on his face, he told Tom that he had caught a train going in the opposite direction.51. A. thought B. advice C. favor D. view52. A. alone B. away C. along D. abroad53. A. certain B. possible C. bad D. proper54. A. for B. and C. so D. but55. A. hoped B. had C. planned D.happened56. A. chance B. time C. luck D. turn57. A. Thus B. But C. Therefore D. However58. A. train B. platform C. conductor D. station59. A. packed B. caught C. covered D. seized60. A. manage B. try C. succeed D. expect61. A. situation B. state C. position D.condition62. A. fighting B. swept C. struggling D. drawn63. A. help B. strike C. support D. push64. A. notices B. marks C. names D. scenes65. A. left B. stopped C. started D. moved66. A. pause B. arrival C. stop D. part67. A. glad B. puzzled C. exciting D. tired68. A. heard of B. talked about C. thought of D. arrivedat69. A. result B. mistake C. difficulty D. question70. A. surprise B. pity C. sadness D. smile四阅读理解:(30分)ATelevision in the United States is free. To pay for programs, there are many advertisements.Often these advertisements are short plays with actors. The following television advertisement is like many others that Americans see daily.We see a man and his wife at the breakfast table. They have been married for a long time. They are not speaking to each other. They haven’t spoken to each other at the breakfast table for years. The husband is reading his newspaper. We can’t see his face. The wife looks very bored as she pours a cup of coffee for him. Today, she is using a new kind of coffee for the first time. The husband picks up his cup. He isn’t very interested. He tastes his coffee. Suddenly he puts down his newspaper.Something is different, Can it be the coffee? He takes another taste. It’s wonderful.He smiles.He looks at his wife and says in amazement, “Doris, when did you cut your hair?” Doris is pleased. She answers,“Two months ago.” Doris asks, “Herbie, when did your hair begin to turn gray?” He replies,“A long time ago.” Doris says, “Oh, very handsome.” Now they aren’t bored anymore. Breakfast is different.Has a new kind of coffee changed their lives? 71.In the TV story, Doris looks bored because______.A.she doesn’t like the breakfast that morningB.she has been married to Herbie for a long timeC.Herbie doesn’t care much for herD.Herbie isn’t interested in the breakfast she cooks72.The TV story wants to tell the viewers______.A.to have an immediate try at the new coffeeB.to have a good laugh at the good coupleC.that a nice breakfast must go with nice coffeeD.that advertisement can certainly increase goods production73.This text is mainly about______.A.who pays for TV programs in the United StatesB.what a TV advertisement is usually like in the USAC.why long-married couples dislike speaking to each otherD.what made Herbie and Doris not bored any moreB( TV programmes in Beijing Sunday, May 26,2002 CCTV )74.If you are interested in football games, which of the following programs will you choose first?A.China Sports Report.B.Special Sports.C.Today’s Focus.D.China Music TV.75.If you are going to Guangzhou by pla ne from Chongqing Airport, you’d better pay attention to the programme ________.A.Weather Report B.World-famous CitiesC.Economy 30 Minutes D.The Story of EarthCAfter The First World War, a small group of soldiers left the army and returned to their hometown in France. Most of them lived well, but one of them was poor. His name was Clinton.Once a year they had supper in Barton’s house. Barton was very rich.One evening Barton showed his friends a large gold coin at the supper table. The coin was passed around and praised by everyone. At the same time they were talking and talking. They soon forgot about the coin.After supper, Barton asked for his coin, but nobody could tell where it was. It was lost.One man said that everyone must be searched. One by one they turned out their pockets. Only Clinton refused.“I didn’t steal the coin, and I will not be searched,” he said.After that, people turned their heads away from Clinton when they met him. Hegrew poorer. Soon his wife died. A few years later, Barton had his house repaired.The lost coin was found under the floor. Barton felt sorry and went to Clinton to apologize.“But,” he asked, “You knew the coin was not in your pocket.“Why did you refuse to be searched?”“Because I was a thief,” Clinton answered. “My pockets were full of food at that time. I had taken some food from the table to carry to my wife and hungry children.”76. The story took place _______.A. in 1920B. after 1945C. in 1950D. after the First World War77. The coin was passed and praised because ________A. Clinton was richB. the supper was goodC. it was a large gold coinD. they were happy78. Everyone was searched because _________.A. they were thievesB. the gold coin was lostC. Clinton stole the gold coinD. they stole the gold coin79. Clinton refused to be searched because _________.A. he was afraid to be found that there was some food in his pocketsB. he didn’t steal the coinC. he was poor enoughD. the gold coin was in his pocket80. “After that, people turned their heads away from Clinton when they met him.”From the sentence we know that _____.A. people thought of him as a beggarB. people were afraid of himC. people look down upon himD. Clinton refused to see his friendsDThe story of the Kennedy brothers is rather like one of those songs which children sing happily and which end up with the shout, “And then there none.”The eldest brother was killed in the war, John was shot in Dallas in 1963, Robert was murdered in 1968, and Edward’s chances of becoming president may have died when his car had an accident, killing the passenger.The four boys were brought up by their father to do and fight for nothing but the best, whether on the games field or in political life. He managed to give them so much ambition(雄心) and energy that only since the youngest brother found his political death, have people begun to ask themselves, “Why did we look on the Kennedys as the family chosen to lead the USA to a better future?”In fact, John and Robert had both shown their ability and courage in international politics and their work for civil rights, and Edward had a good record as senator(上议员); but so had many other people. Only history will show how much of the Kennedy story was built on fact and how much on the famous family name.81. The best title for the article is ________.A. Political MurderB. The Best Family of USAC. A Famous Family NameD. The Kennedy Brother82. From the article we know that old Kennedy taught his sons _______.A. to aim high and try to achieve great successB. to fight for everythingC. to try their best to be good citizensD. not to waste so much of their energy in fighting83. According to the article, Edward Kennedy _______.A. was the oldest of the four brothersB. liked to sing children’s songC. died in a hospital soon after the car accidentD. was active in political life84. Which of the following is wrong?A. Two of the brothers were murdered in the 1960s.B. Edward was elected president of the US.C. The father raised the boys by teaching them what to struggle for.D. People used to think highly of the Kennedy brothers.85. The writer thought that _______.A. the Kennedy family was the best choice of the American peopleB. the brothers had the greatest chance of becoming president of the USAC. besides the Kennedy brothers, many other people had great ability in politics.D. the Kennedy story was built not on fact but on the family name.EBelieve it or not, optical illusion(视觉错觉) cut high way accidents.Japan is a case in point. It has reduced traffic accidents on some roads by nearly 75%, using a simple optical illusion. Bent stripes, called chevrons (人字形) painted on the roads make drivers think that they are driving faster than they really are, and thus drivers slow down.Now the American Automobile Association Foundation for Traffic Safety in Washington D.C is planning to repeat Japan’s success. Starting next year, the foundation will paint chevrons and other patterns of stripes on selected roads around the country to test how well the patterns reduce highway accidents.Over speeding plays a major role in as much as one fifth of all fatal traffic accidents, according to the foundation. To help reduce those accidents, the foundation will conduct its tests in areas where speed-related dangers are the greatest---curves, exit slopes, traffic circles, and bridges.Some studies suggest that straight, horizontal(平行的) bars painted across roads can initially cut the average speed of drivers in half. However, traffic often returns to full speed within months as drivers become used to seeing the painted bars.Chevrons, scientists say, not only give drivers the impression that they are driving faster than really are, but also make a lane(车道) appear to be narrower. The result is a longer lasting reduction(减少) in highway speed and the number of traffic accidents.86. The passage mainly discusses ____.A. a new way of highway speed controlB. a new method of training driversC. a new pattern for painting highwaysD. a new type of optical illusion87. On roads painted with chevrons, drivers are likely to feel that ____.A.they should avoid speed-related dangersB.they are driving in the wrong laneC.they should slow down their speedD.they are reaching the speed limit88. Compared to horizontal bars, the advantage of chevrons is that ____.A.it can keep drivers awakeB.it will have a longer effect on driversC. it can cut road accidents in halfD. it will look more attractive89. The American Automobile Association Foundation for Traffic Safety plans to ___.A.try out the Japanese method in certain areasB.change the road signs across the countryC.replace straight, horizontal bars with chevronsD.repeat the Japanese road patterns90. What does the writer say about straight, horizontal bars painted across roads?A.They are falling out of use in the United States.B.They are likely to be taken no notice of by drivers in a short time.C.They are suitable only on broad roads.D.They cannot have a successful effect in traffic circles第Ⅱ卷五、书面表达:(15分)李明是你的好朋友,已经同学三年。
莆田一中2008~2009学年期中考试卷高三 数学(理科)命题 高三备课组第I 卷(选择题共60分)一、选择题:本大题共12小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的.请把答案填在答题卡上. 1.已知命题p :x ∀∈R ,sin x x >,则 ( )A .p ⌝:x ∃∈R ,sin x x <B .p ⌝:x ∀∈R ,sin x x ≤C .p ⌝:x ∃∈R ,sin x x ≤D .p ⌝:x ∀∈R ,sin x x <2. 在等差数列{}n a 中,若4a +6a +8a +10a +12a =120,则210a -12a 的值为( )A. 20B. 22C. 24D. 283、已知{}n a 是等比数列,41252==a a ,,则13221++++n n a a a a a a =( )A.16(n --41)B.16(n --21)C.332(n --41) D.332(n --21) 4、根据表格中的数据,可以判定方程20x e x --=的一个零点所在的区间为))(1,(N k k k ∈+,则k 的值为( )A .-1 B.0 C.1 D. 2 5.函数)2(log log 2x x y x +=的值域是( )A .]1,(--∞B .),3[+∞C .]3,1[-D .),3[]1,(+∞⋃--∞6. 已知函数()y f x =是偶函数,当0x >时,有4()f x x x=+,且当[3,1]x ∈--时,()f x 的值域是[,]n m ,则m n -的值是( )A .13B .23C .1D .437.已知(21)4,(1)()log ,(1)xa a x a x f x x -+<⎧=⎨≥⎩是),(+∞-∞上的减函数,那么a 的取值 范围是( )A .)1,0(B .1(0,)2C .11[,)62D .1[,1)68、已知πα<<0,21cos sin =+αα ,则α2cos 的值为 ( ).A.47 B. 47- C.47± D. 43-.9.已知函数11()(sin cos )sin cos 22f x x x x x =+--,则()f x 的值域是( )A.[]1,1-B. 2⎡⎤-⎢⎥⎣⎦C. 1,2⎡-⎢⎣⎦D. 1,2⎡--⎢⎣⎦10. 已知等差数列{}n a 的前n 项和为n S ,若100101OB a OA a OC =+, 且 A B C ,,三点共线(该直线不过点O ),则200S 等于 ( ) A .100B .101C .200D .20111.若xxx f a b ln )(,3=>>,则下列各结论中正确的是( )A.)()2()(ab f b a f a f <+<B.)()()2(ab f b f ba f <<+ C.)()2()(a fb a f ab f <+< D.)()2()(ab f ba fb f <+< 12.设|13|)(-=x x f ,a bc <<且)()()(b f a f c f >>, 则下列关系中一定成立的是( ) A .b c 33> B .ab 33>C .233>+a cD .233<+a c第Ⅱ卷(非选择题 共90分)二、填空题:本大题共4小题,每小题4分,共16分的横线上 13.若α是锐角,且()1sin 63πα-=,则cos α的值是 .14、由抛物线2y x =和直线2x =所围成图形的面积为___________.15.已知点P (x ,y)满足条件3),(02,,0+=⎪⎩⎪⎨⎧≤++≤≥x z k k y x x y x 若为常数y 的最大值为8,则k = .16.若关于x 的不等式234x x a -+-≥的解集为实数集R ,则实数a 的取值范围是 .三、解答题:本大题共6小题,共74分.解答应写出文字说明,证明过程或演算步骤. 17、(本小题满分12分)设向量(sin ,cos )a x x =,(cos ,cos )b x x =,x ∈R ,函数()()f x a a b =∙+. (Ⅰ)求函数f(x)的最小正周期和最小值; (Ⅱ)求函数()f x 在[]0π,上的单调增区间.18、(本小题满分12分)设P :关于x 的不等式210cx cx ++>的解集为实数集R , Q :不等式|2|1x x c +-<在实数集R 上有解,如果P Q ∨为真,P Q ∧为假,求c 的取值范围. 19、(本小题满分12分)在△ABC 中,已知05,60,AB B ==AC 边上的中线BD=72,求sinA 的值.20.(本小题满分12分)等差数列{}n a 的前n 项和为1319n S a S ==+, (Ⅰ)求数列{}n a 的通项n a 与前n 项和n S ;(Ⅱ)设)(2*N n a b n n ∈-=,}{n b 中的部分项n k k k b b b ⋅⋅⋅,,21恰好组成等比数列,且63,141==k k ,求数列}{n k 的通项公式;(III )设)(*N n nSc n n ∈=,求证:数列}{n c 中任意相邻的三项都不可能成为等比数列. 21、(本小题满分12分)已知函数()2472x f x x-=-,[]01x ∈,(Ⅰ)求()f x 的单调区间和值域;(Ⅱ)设1a ≥,函数()[]223201g x x a x a x =--∈,,,若对于任意[]101x ∈,, 总存在[]001x ∈,,使得()()01g x f x =成立,求a 的取值范围22.(本小题满分14分) 已知函数)1ln()(+-=x e x f x 。
2008-2009学年度福建省莆田一中第一学期高三第一学段考试数学试卷(理)第I 卷(选择题共60分)一、选择题:本大题共12小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的.请把答案填在答题卡上. 1.已知命题p :x ∀∈R ,sin x x >,则A .p ⌝:x ∃∈R ,sin x x <B .p ⌝:x ∀∈R ,sin x x ≤C .p ⌝:x ∃∈R ,sin x x ≤D .p ⌝:x ∀∈R ,sin x x <2.在等差数列{}n a 中,若4a +6a +8a +10a +12a =120,则210a -12a 的值为A .20B .22C .24D .283、已知{}n a 是等比数列,41252==a a ,,则13221++++n n a a a a a a = A .16(n--41) B .16(n--21)C .332(n--41)D .332(n--21) 4、根据表格中的数据,可以判定方程20x e x --=的一个零点所在的区间为))(1,(N k k k ∈+,则k 的值为A .-1B .0C .1D .25.函数)2(log log 2x x y x +=的值域是A .]1,(--∞B .),3[+∞C .]3,1[-D .),3[]1,(+∞⋃--∞6.已知函数()y f x =是偶函数,当0x >时,有4()f x x x=+,且当[3,1]x ∈--时,()f x 的值域是[,]n m ,则m n -的值是A .13B .23C .1D .437.已知(21)4,(1)()log ,(1)xa a x a x f x x -+<⎧=⎨≥⎩是),(+∞-∞上的减函数,那么a 的取值范围是A .)1,0(B .1(0,)2C .11[,)62D .1[,1)68.已知πα<<0,21cos sin =+αα ,则α2cos 的值为 A .47 B .47- C .47± D .43-9.已知函数11()(sin cos )sin cos 22f x x x x x =+--,则()f x 的值域是 A .[]1,1-B .2⎡⎤-⎢⎥⎣⎦ C .1,2⎡-⎢⎣⎦D .1,2⎡--⎢⎣⎦10. 已知等差数列{}n a 的前n 项和为n S ,若100101O B a O A a O C =+,且 A B C ,,三点共线(该直线不过点O ),则200S 等于A .100B .101C .200D .20111.若x xx f a b ln )(,3=>>,则下列各结论中正确的是( ) A .)()2()(ab f b a f a f <+< B .)()()2(ab f b f ba f <<+C .)()2()(a f b a f ab f <+<D .)()2()(ab f ba fb f <+<12.设|13|)(-=x x f ,a b c <<且)()()(b f a f c f >>,则下列关系中一定成立的是( )A .bc 33>B .a b33>C .233>+acD .233<+ac第Ⅱ卷(非选择题 共90分)二、填空题:本大题共4小题,每小题4分,共16分将答案填在各题中的横线上13.若α是锐角,且()1sin 63πα-=,则cos α的值是 . 14、由抛物线2y x =和直线2x =所围成图形的面积为___________.15.已知点P (x , y)满足条件3),(02,,0+=⎪⎩⎪⎨⎧≤++≤≥x z k k y x x y x 若为常数y 的最大值为8,则k = .16.若关于x 的不等式234x x a -+-≥的解集为实数集R ,则实数a 的取值范围是 .三、解答题:本大题共6小题,共74分.解答应写出文字说明,证明过程或演算步骤. 17、(本小题满分12分)设向量(sin ,cos )a x x =,(cos ,cos )b x x =,x ∈R ,函数()()f x a a b =∙+. (Ⅰ)求函数f(x)的最小正周期和最小值; (Ⅱ)求函数()f x 在[]0π,上的单调增区间. 18、(本小题满分12分)设P :关于x 的不等式210cx cx ++>的解集为实数集R , Q :不等式|2|1x x c +-<在实数集R 上有解, 如果P Q ∨为真,P Q ∧为假,求c 的取值范围.19、(本小题满分12分)在△ABC 中,已知05,60,AB B ==AC 边上的中线BD=72,求sinA 的值. 20.(本小题满分12分)等差数列{}n a 的前n 项和为1319n S a S ==+, (Ⅰ)求数列{}n a 的通项n a 与前n 项和n S ;(Ⅱ)设)(2*N n a b n n ∈-=,}{n b 中的部分项n k k k b b b ⋅⋅⋅,,21恰好组成等比数列,且63,141==k k ,求数列}{n k 的通项公式;(III )设)(*N n nS c nn ∈=,求证:数列}{n c 中任意相邻的三项都不可能成为等比数列. 21、(本小题满分12分)已知函数()2472x f x x-=-,[]01x ∈,(Ⅰ)求()f x 的单调区间和值域;(Ⅱ)设1a ≥,函数()[]223201g x x a x a x =--∈,,,若对于任意[]101x ∈,,总存在[]001x ∈,,使得()()01g x f x =成立,求a 的取值范围. 22.(本小题满分14分)已知函数)1ln()(+-=x e x f x。
莆田一中2007~2008学年上学期期中考试卷高三化学命题人:俞志敏(总分:100分考试时间:120分钟)相对原子质量: H:1 0:16 S:32 Si:28 Fe:56 Na:23 N:14第Ⅰ卷(共50分)一、选择题:(每小题2分,共50分。
每小题只有一个选项符合题意)1、原子的核电荷数小于18的某元素X,原子的电子层数为n,最外层电子数为2n+1,原子中的质子数是2n2-1(n为正整数)。
下列有关X的说法不正确...的是()A.X的单质肯定具有强氧化性B.X肯定能形成化学式为NaXO3的含氧酸钠盐C.X原子的最外层电子数和核电荷数肯定为奇数D.X可能与氧元素形成X2O4型化合物2、有关晶体的下列说法中正确的是()A.晶体中分子间作用力越大,分子越稳定B.原子晶体中共价键越强,熔点越高C.冰熔化时分子中共价键发生断裂D.氯化钠熔化时离子键未被破坏3、在下列变化过程中,既有离子键被破坏又有共价键被破坏的是()A.将SO2通入水中B.NaOH溶于水C.将HCl通入水中D.NaHSO4溶于水4、下列物质的性质递变规律与化学键无关的是()A.熔点:MgO>CaO>NaCl>KCl B.沸点:CHI3>CHBr3>CHCl3>CHF3 C.硬度:金刚石>碳化硅>晶体硅D.稳定性:H2O>H2S>H2Se>H2Te5、下列哪种物质的中心原子的最外层不是8电子结构()A.CO2B.NF3C.BF3D.OF26、下列有关叙述中正确的是()A.液态氟化氢中存在氢键,所以其分子比氯化氢更稳定B.由碳、氮原子形成的化合物比金刚石坚硬,其主要原因是碳氮键比碳碳键更短C.S8和NO2都是共价化合物,NH4Cl和CaC2都是离子化合物D.若ⅡA族某元素的原子序数为m,则同周期ⅢA族元素的原子序数有可能为m+107、根据中学化学教材中所附元素周期表判断,下列叙述不正确的是()A.第16列元素的最高价氧化物为RO3B.第2列元素中一定没有非金属元素C.第15列元素的最高价氧化物的水化物的化学式均为H3RO4D.第14列元素所形成的化合物种类最多8、将足量的碳与100mL18mol/L的浓H2SO4充分反应,下列对此反应的有关说法中错误..的是()A.反应中浓硫酸起到氧化剂的作用B.反应结束后两种反应物均有剩余C.生成物CO2为氧化产物D.生成的SO2气体在标准状况下为40.32L 9、据报道,德国INTEGRAL公司研究出无辐射冷却技术(用水和冰组成的物质代替传统的氟利昂或氨)而荣获德国环境大奖。
莆田一中2008—2009学年上学期第一学段考试试卷高一历史必修Ⅰ命题人:张丽英审核人:朱成武尹立华鲁恒(满分100分时间100分钟)本卷共有44题。
1-40题为单项选择题,每题1.5分共60分;41-44为综合题,共40分。
请认真阅读材料并依据提示答题。
一、选择题:(每小题1.5分,共60分)1、对商朝的内外服制度理解不正确的是()A.内服是商王直接统治的地区B.外服是附属国管辖的地区C.商王控制着支配内服与外服的实际权力D.商王对附属国的控制力很大,附属国基本没有自主权2、“亲情是缘,相聚是缘”,这是自古以来就深存于每一个中国人心底的情结。
因此1793年,英国使团的随行画师亚历山大谈到在中国的见闻时说:“中国人每家都保留家谱……本家族每年至少一次在一起祭扫祖坟。
”中国人的这种传统与下列哪一制度有关() A.分封制B.宗法制C.礼乐制度D.中央集权制度3、历史典故“烽火戏诸侯”讲述的是:诸侯因义务所在,看见烽火点燃,蜂拥而至勤王。
这一典故所反映的政治制度是()A.宗法制B.分封制 C.郡县制 D.王位世袭制4、在宗法观念盛行的封建社会,姓氏也有贵贱之分。
“赵”姓并不是中国最大的姓氏,但在《百家姓》中却排序第一,由此可推断出该作品最早可能出现在()A.西周B.唐朝 C.北宋D.明朝5、“他是中国最勤劳的帝王之一,不分昼夜地为他的帝国服务,(他)给中国历代王朝奠定了权威性的规范,以后几百个帝王只能在他所想到的圈子里作小小的修正。
”他是指() A.孔子B.秦始皇 C.汉武帝D.明太祖6、嬴政统一全国后,以“三皇”“五帝”各取一字,称皇帝;自称“朕”,命令称“制”或“诏”;印称“玺”。
这些规定的根本意图是()A.维护皇权的至高无上 B.将皇权神化C.确立恶劣严格的等级制度 D.保持皇位永远由他的后裔承袭7、20世纪90年代,陕西章台出土了一些秦代封泥(密封信件文书时加盖了印章的泥块),上面有上郡、代郡、邯郸等郡名和蓝田等县名。
这一发现可以印证秦朝()A、政治上四分五裂的事实B、出现了造纸业的事实C、实行了郡县制度的事实D、用泥制陶的事实8、“欲天下之治安,莫若众建诸侯而少其力”,“力小则易使以义,国小则亡邪心。
”贾谊这一主张后来发展为()A.刺史制度 B.推恩令 C.削藩策 D.分封制9.下列各项中,分割宰相军权的官职是()A.秦朝的御史大夫B.汉朝的刺史C.唐朝的节度使D.宋朝的枢密使10、宋太祖消除地方割据势力的物质基础的措施是()A.收精兵B.削实权C.制钱谷D.杯酒释兵权11、下列关于科举制的评价,不正确的是()A 秦朝建立的科举制度,使门第不高的一般地主可以凭自己的才学参加政权,扩大了地主阶级的统治基础。
B 明清的八股取士制度束缚了知识分子的思想,加强了封建君主统治C 清末,科举制度严重阻碍了科技文化的发展,阻碍了新型人才培养D 科举制为官僚队伍提供了源源不断的高素质人才,成为中华帝国长期保持繁荣的制度保障之一。
12、下列中国古代的官职,按职能分组不同的一组是()A.御史大夫、刺史B.丞相、参知政事C.太尉、通判D.郡守、巡抚13、“有明之无善治,自高皇帝罢相始也,”这句话中废除丞相制的“高皇帝”应该是指() A.汉高祖B.唐高祖C.宋高宗D.明太祖14、明初,朱元璋立了一块“宦官不得干预政事”的铁牌,但事与愿违,明王朝却成为历代宦官干政最厉害的王朝。
宦官干政的根源是()A.明朝皇帝懦弱无能B.明朝推行特务统治C.封建君主专制体制D.明初废除了丞相制度15、春联是日常生活中对书画艺术的使用。
“春联之设,自明太祖始。
”朱元璋始令春联用朱砂纸作底,用黑墨写字,并取名为“万年红”,因“红”与“朱”义同。
朱元璋此举的真正用意在于()A.强调“朱”姓的尊贵显赫 B.祈盼专制政权的长治久安C.营造红红火火的新年气氛 D.改革节日的风俗习惯16、有学者把17世纪20年代东西方两位末代君主(英国查理—世和明朝崇祯皇帝)的暴亡,视为两个民族历史的一个楔子———世界的天平开始失衡,西方的崛起与东方的没落明显加快。
此说法的着眼点在于()A、政权发生更替B、社会形态转变C、国力对比变化D、文化途径迥异17、我们要去西方文明的源头探访,这个源头是()A、古希腊文明B、罗马文明C、埃及文明D、迈锡尼文明18、很快,你就注意到古希腊的政治状况跟古代中国有很大不同。
以下国家和城市中,不是实行君主制的是()A、古代中国B、米诺斯统治时期的克诺索斯C、迈锡尼D、梭伦统治时期的雅典19、在古代希腊的诸多城邦中,城邦间的关系是()A、聚集在斯巴达城邦下B、城邦之间存在隶属关系C、小邦是大邦的属国D、各邦均为独立主权国家20、古希腊城邦政体的多元状态和公民政治给你留下了深刻的印象。
在下列政体中,公民大会拥有国家最高治权的是()A、贵族制B、寡头制C、民主制D、僭主制21、古希腊出了许多有名的演说家,如德漠修斯,艾斯霍尼斯,狄摩西尼斯等,它与古希腊的一项民主制度有关,它是()A、表决制B、辩论制C、选举制D、任期制22、按照土地收入和财产多寡划分公民等级并授予相应官职,是梭伦改革的重要措施,其主要意义在于()①沉重打击了依靠血统关系谋取特权的贵族②促进了奴隶制国家的发展③确立了雅典民主政治制度④满足了所有雅典公民参政的要求A、①②③B、②③④C、①②D、③④23、在雅典民主制下,可能发生的事情是()A.一名中国男子为躲避国内政治迫害来到雅典,取得了各种民主权利B.公民德里希因为邻里纠纷而向公民大会申述C.雅典的民主制激发了所有人建设国家的积极性D.公民沃尔默迪和妻子玛丽亚一起去参加公民大会24、在雅典民主政治发展的过程中,为保护公民利益,制约官员,曾经实行“陶片放逐法”。
在公民大会上,凡公民认为某人的行为有损公民利益,就把他的名字写在陶片上。
如写名的人数超过6000,就意味着多数通过,那个人就会被流放国外10年,但不得动其财产。
该材料反映了雅典民主政治的哪些基本原则()①执政为民②少数服从多数的民主集中制③私有财产不可侵犯④三权分立A、②③④B、①②④C、①③④D、①②③25、雅典民主“人民主权与轮番而治”的充分体现是()①公民大会②五百人议事会③民众法庭④元老院A、①②③B、①②③④C、①②D、②③④26、假如你是中国秦朝的丞相,当你与同时期的罗马元老院成员相遇时,在治国原则上的最大分歧是()A、“秦法”与《十二铜表法》B、“郡县制”与“元首制”C、“皇权至上”与“政事共商”D、“三公九卿”与“公民大会”27、罗马的兴衰成败虽已成为过去,但罗马人创造的文明成果却千古犹存。
罗马的基本法是()A、《十二铜表法》B、《查士丁尼法典》C、《查士丁尼民法大全》D、“陶片放逐法”28、《十二铜表法》第八表第十二条规定:“如果在夜里行窃的人被人当场杀死,则这种杀人的行为被认为是合法的。
”以上规定的实质是()A.保护罗马平民的权益 B.极力维护私有财产权C.维护罗马帝国的统治 D.重视良好道德的培养29、确立英国近代资产阶级君主立宪制的标志是()A、处死了国王查理一世。
B、宣布英国为共和国。
C、1688年“光荣革命”。
D、《权利法案》的通过。
30、18世纪英国的内阁制与同时期中国的内阁制相比最大的不同是()A、组织形式 B内阁与君主的关系 C社会性质D民主化的程度31、1787年宪法颁布标志着美国建立了联邦制国家。
下列有关联邦制的说法,正确的是()①作为邦联组成部分的邦国,变成了“州”②中央政府与州政府实行分权③国家主权属于联邦④联邦法律是全国的最高法律A、①②B、②③C、②③④D、①②③④32、翻开美国历史,共有九位总统曾在众议院被提案弹劾。
他们是泰勒·强森、克里夫兰·胡佛、杜鲁门、尼克松、里根、老布什和克林顿,民主党和共和党领袖都未能幸免。
这充分体现了()A.法律至上B.分权制衡的原则C.两党政治D.联邦制33、每到美国选举季节,你就会看到铺天盖地的驴和象的“光辉形象”,美国两党激烈争夺的战场是()A、国会B、最高法院C、政治选举D、联邦政府34、美国国会通过宪法第14条修正案规定:“任何一州,都不得制定或实施限制合众国公民的特权或豁免权的任何法律。
”这肯定了()A.联邦法律的多样性 B.维护国家的统一的重要性C.联邦法律的公正性 D.联邦法律的至上性和国家的统一35、马克思说:“在美国历史上和人类历史上,林肯必将与华盛顿齐名。
”马克思如此高度评价林肯,是因为林肯政府()A.巩固了北方工业资产阶级的统治B.满足了人们要求得到土地的愿望C.维护了联邦国家的统一D.取消了对黑人的种族歧视36、某份晚清画报刊登一则人物图像,称他是再造普鲁士、统一德意志的“大豪杰”,此人是()A.俾斯麦B.威廉一世C.兴登堡D.威廉二世37、有人告诉你,“如果想了解德国,就必须抓住这样一个事实:德国,特别是普鲁士,是一个倒立着的金字塔。
牢牢埋在地里的塔尖是普鲁士士兵头盔上的尖铁,一切都是由它托着。
”这说明在德意志帝国中占重要地位的是()A、军队B、国会C、民主势力D、民族势力38.“德意志民族曾经号称‘思想家和诗人的民族’,也涌现出了一流的科学家和艺术家。
……但是,这个伟大的民族又曾在一个狂人的操纵下进行过最骇人听闻的大屠杀。
”后者产生的历史根源是()A.德意志民族性格的双重性B.资本主义经济发展不充分C.军国主义和专制主义传统的影响D.没有形成一部宪法39.根据法兰西第三共和国宪法,法国总统的产生方式()A、由选民普遍直接选举产生B、由选民间接选出C、由参众两院组成的议会依据绝对多数票选出D、由众议院选举产生40、法国走向共和的显著特征是()A、共和派与封建势力、君主立宪派斗争异常激烈,过程曲折B、颁布了《人权宣言》,为欧美国家民主政治发展提供范本C、资产阶级比较软弱,未能彻底完成革命的任务D、无产阶级积极参与,推动了民主政治的发展二、综合题:(共4大题40分),请把你的回答认真写在答案卷的相应题号上。
41、阅读以下材料:材料一:一位英国的宪法权威人士曾说:“上下两院如果作出决定,就是把女王本人的死刑判决书送到她面前,她也不得不签字。
”材料二:英国前首相布莱尔在2007年6月27日辞职,执政党工党新任领袖布朗应英国女王伊丽莎白二世的邀请前往白金汉宫,接受女王授权组建新一届内阁,并从女王手中接受印玺,正式就任英国首相。
随后,布朗在首相府发表讲话说:“我将竭尽全力倾听英国公众的呼声,改革住房、教育、卫生服务体系,努力为英国人民服务,充分发挥公众的潜力,使英国成为21世纪的全球成功典范。
”请回答:(1)材料一那位宪法权威人士的话表明英王在国家政治生活中处于什么地位?(2分)(2)根据英国法律,布莱尔辞职,其内阁成员是否随其一起辞职?为什么?(3分)(3)布朗作出住房改革决策,如果女王伊丽莎白反对,布朗会不会放弃?为什么?(3分)(4)如果议会中大多数议员反对首相的决策,布朗将面临怎样的处境?(4分)42、在中国历史上,专制主义中央集权制度似乎是一个永恒的政治主题。