辽宁省大连经济技术开发区得胜高级中学2020-2021学年高二下学期期中试题生物 无答案

2024年辽宁省大连经济技术开发区得胜高级中学高三数学第一学期期末学业水平测试模拟试题注意事项：1．答卷前，考生务必将自己的姓名、准考证号填写在答题卡上。

2．回答选择题时，选出每小题答案后，用铅笔把答题卡上对应题目的答案标号涂黑，如需改动，用橡皮擦干净后，再选涂其它答案标号。

回答非选择题时，将答案写在答题卡上，写在本试卷上无效。

3．考试结束后，将本试卷和答题卡一并交回。

一、选择题：本题共12小题，每小题5分，共60分。

在每小题给出的四个选项中，只有一项是符合题目要求的。

1．若，则（ ）A ．B ．C ．D ．2．ABC ∆ 的内角,,A B C 的对边分别为,,a b c ，已知22cos a c b A +=，则角B 的大小为（ ） A ．23π B ．3π C ．6π D ．56π 3．某几何体的三视图如图所示，则此几何体的体积为（ ）A ．23B ．1C ．43D ．834．在ABC ∆中,,A B C ∠∠∠所对的边分别是,,a b c ，若3,4,120a b C ︒==∠=，则c =（ ） A ．37B ．13C 13D 375．一个由两个圆柱组合而成的密闭容器内装有部分液体，小圆柱底面半径为1r ，大圆柱底面半径为2r ，如图1放置容器时，液面以上空余部分的高为1h ，如图2放置容器时，液面以上空余部分的高为2h ，则12h h =（ ）A ．21r rB ．212r r ⎛⎫ ⎪⎝⎭C ．321r r ⎛⎫ ⎪⎝⎭D ．21r r 6．《九章算术》是我国古代内容极为丰富的数学名著，书中有如下问题：“今有刍甍，下广三丈，袤四丈，上袤二丈，无广，高二丈，问：积几何”其意思为：“今有底面为矩形的屋脊状的楔体，下底面宽3丈，长4丈，上棱长2丈，高2丈，问：它的体积是多少?”已知l 丈为10尺，该楔体的三视图如图所示，其中网格纸上小正方形边长为1，则该楔体的体积为（ ）A ．10000立方尺B ．11000立方尺C ．12000立方尺D ．13000立方尺7．已知双曲线()222:10y C x b b-=>的一条渐近线方程为2y x =，1F ，2F 分别是双曲线C 的左、右焦点，点P在双曲线C 上，且13PF =，则2PF =( ) A ．9B ．5C ．2或9D ．1或58．已知函数()sin()f x x ωθ=+，其中0>ω，0,2πθ⎛⎫∈ ⎪⎝⎭，其图象关于直线6x π=对称，对满足()()122f x f x -=的1x ，2x ，有12min2x x π-=，将函数()f x 的图象向左平移6π个单位长度得到函数()g x 的图象，则函数()g x 的单调递减区间是（） A ．()2,6k k k Z ππππ⎡⎤-+∈⎢⎥⎣⎦B ．(),2k k k Z πππ⎡⎤+∈⎢⎥⎣⎦C ．()5,36k k k Z ππππ⎡⎤++∈⎢⎥⎣⎦D ．()7,1212k k k Z ππππ⎡⎤++∈⎢⎥⎣⎦9．如图，用一边长为2的正方形硬纸，按各边中点垂直折起四个小三角形，做成一个蛋巢，将体积为43π的鸡蛋（视为球体）放入其中，蛋巢形状保持不变，则鸡蛋中心（球心）与蛋巢底面的距离为（ ）A ．22B 3C ．212D 31+ 10．已知函数()cos 2321f x x x =++，则下列判断错误的是（ ） A ．()f x 的最小正周期为π B ．()f x 的值域为[1,3]-C ．()f x 的图象关于直线6x π=对称D ．()f x 的图象关于点,04π⎛⎫-⎪⎝⎭对称 11．记单调递增的等比数列{}n a 的前n 项和为n S ，若2410a a +=，23464a a a =，则（ ）A ．112n n n S S ++-=B ．2nn a =C ．21nn S =-D ．121n n S -=-12．已知()21,+=-∈a i bi a b R ，其中i 是虚数单位，则z a bi =-对应的点的坐标为（ ） A ．()12,-B ．()21,-C ．()1,2D ．()2,1二、填空题：本题共4小题，每小题5分，共20分。

2015-2016学年度得胜高中高二理科数学期中考试卷考试时间：150分钟；命题人：高一备课组第I 卷（选择题）1．命题：“对任意的x R ∈，210x x ++>”的否定是（ ）A ．不存在x R ∈，210x x ++>B ．存在0x R ∈，20010x x ++> C ．存在0x R ∈，20010x x ++≤ D ．对任意的x R ∈，012≤++x x2．已知,a b R ∈，则a b >是11()()22a b <的（ ）条件A ．充分不必要B ．必要不充分C ．充要D ．既不充分也不必要3．设平面α的一个法向量为()11,2,2=-n ，平面β的一个法向量为()22,4,=--n k ，若α∥β，则k=（ ）A ．2B ．﹣4C ．﹣2D ．4 4．函数33y x x =-的单调递减区间是（ ）A ．(),0-∞B ．()0,+∞C ．()1,1-D ．()(),11,-∞-+∞5．21,F F 是椭圆192522=+y x 的两焦点，过1F 的直线交椭圆于A 、B 两点，若8|=AB |， 则=+||22B F A F ||（ ）A ．2 B.12 C.18 D.96 6．若曲线xy e =在1x =处的切线与直线210x my ++=垂直，则m = A ．2e - B ．2e C ．2e- D ．2e7．抛物线214y x =的准线方程是（ ） A ．1x = B ．1y = C ．1x =- D ．1y =-8．已知曲线221:13x C y +=和222:1C x y -=的焦点分别为12,F F ，点M 是1C 和2C 的一个交点，则12MF F ∆的形状是（ ）A ．锐角三角形B ．直角三角形C ．钝角三角形D ．不能确定 9．下列双曲线中，渐近线方程为2y x =±的是( )A ．2214y x -= B ．2214x y -=C ．2212y x -= D ．2212x y -=10．若椭圆+=1（a ＞b ＞0）的离心率为，则双曲线﹣=1的渐近线方程为（ ）A ．y=±xB ．y=±xC ．y=±xD ．y=±x11．过双曲线)0,0(1:2222>>=-b a by a x C 的一个焦点F 作双曲线C 的一条渐近线的垂线，若垂足恰好在线段OF 的垂直平分线上，则双曲线C 的离心率是（ ） A ．332 B ．3 C ．2 D ．2 12．设()f x 、()g x 分别是定义在R 上的奇函数和偶函数，当0x <时，''()()()()0f x g x f x g x +>且(3)0g =，则不等式()()0f x g x <的解集是（ ）A ．(3,0)(3,)-+∞B ．(3,0)(0,3)-C ．(,3)(3,)-∞-+∞D ．(,3)(0,3)-∞-第II 卷（非选择题） 13．dx= ．14．已知直线y ＝a 交抛物线y ＝x 2于A ，B 两点．若该抛物线上存在点C ，使得∠ACB 为直角，则a 的取值范围为________．15．双曲线221kx y -=的一条渐近线与直线230x y -+=垂直，则双曲线的离心率是___________． 16．曲线x 在点处切线的倾斜角为 ．三、解答题17．已知c ＞0，且c≠1，设p ：函数xc y =在R 上单调递减；q ：函数12)(2+-=cx x x f 在1,2⎛⎫+∞ ⎪⎝⎭上为增函数，若“p∧q”为假，“p∨q”为真，求实数c 的取值范围．18．如图，在三棱柱111ABC A B C -中，四边形11AA C C 是边长为4的正方形，平面ABC ⊥平面11AA C C ，3AB =，5BC =.（Ⅰ）求证：1AA ⊥平面ABC ；（Ⅱ）若点D 是线段BC 的中点，请问在线段1AB 是否存在点E ，使得DE 面11AA C C ？若存在，请说明点E 的位置，若不存在，请说明理由； （Ⅲ）求二面角111C A B C --的大小.19．(12分) 已知函数23)(bx ax x f +=,在1x =时有极大值3; （Ⅰ）求,a b 的值；（Ⅱ）求函数)(x f 在[]2,1-上的最值.20．点P 在圆22:8O x y +=上运动，PD x ⊥轴，D 为垂足，点M 在线段PD 上， 满足PM MD =． (Ⅰ) 求点M 的轨迹方程；(Ⅱ) 过点11,2Q ⎛⎫ ⎪⎝⎭作直线l 与点M 的轨迹相交于A 、B 两点，使点Q 为弦AB 的中点，求直线l 的方程．21．已知椭圆的离心率，过点A （0，﹣b ）和B （a ，0）的直线与原点的距离为．（1）求椭圆的方程；（2）已知定点E （﹣1，0），若直线y=kx+2（k≠0）与椭圆交于C 、D 两点，问：是否存在k 的值，使以CD 为直径的圆过E 点？请说明理由．22．已知函数2()ln f x a x bx =-，,a b R ∈．（1）若()f x 在1x =处与直线12y =-相切，求a ，b 的值； （2）在（1）的条件下，求()f x 在1[,]e e上的最大值；（3）若不等式()f x x ≥对所有的(,0]b ∈-∞，2(,]x e e ∈都成立，求a 的取值范围．参考答案 1．C 【解析】试题分析：全称命题的否定是特称命题，所以其否定是存在0x R ∈，20010x x ++≤，故选C.考点：全称命题的否定 2．C 【解析】试题分析：由题意得，根据指数函数1()2x y =为单调递减函数，则当a b >时，11()()22a b <成立的；当11()()22a b <时，a b >是成立，所以a b >是11()()22a b <的充要条件，故选C ． 考点：充要条件的判定及指数函数的性质． 3．D 【解析】试题分析：平面α的一个法向量为()11,2,2n =-，平面β的一个法向量为()22,4,n k =--，αβ，由题意可得24122k--==-，4k ∴=，故选D. 考点: 1、平面的法向量的性质；2、两平面平行的性质.4．C 【解析】试题分析：易知定义域为R ，可得导函数为))(('113332-+=-=x x x y ．由0<'y 得，11<<-x ，所以函数的单调递减区间为()1,1-．故选C ． 考点：利用导数求函数的单调区间． 5．B 【解析】试题分析：由题意得：22112211||||||||4,||||4(||||)445812F A F B F A F B a F A F B a F A F B a AB +++=+=-+=-=⨯-=选B.考点：椭圆定义 【名师点睛】1. 应用椭圆定义的情境往往为“焦点三角形PF 1F 2” ，而涉及椭圆焦点三角形有关的计算或证明，常利用正(余)弦定理、椭圆定义，向量运算，并注意|PF 1|＋|PF 2|与|PF 1|·|PF 2|整体代换．2．利用椭圆定义求解，要注意两点：(1)距离之和为定值，(2)2a>|F 1F 2|，(3)焦点所在坐标轴的位置． 6．B 【解析】试题分析：xy e '=，1x y e ='=，所以曲线xy e =在1x =处的切线斜率为k e =，直线210x my ++=与切线垂直，则210x my ++=的斜率应为1e -，所以21(0)m m e-=-≠，所以2m e =．考点：1．导数的几何意义；2．两直线垂直． 7．D 【解析】试题分析：由题意得，抛物线的标准方程为24x y =，所以2p =且开口向上，所以准线方程为1y =-，故选D.考点：抛物线的几何性质. 8．B 【解析】试题分析：由题曲线221:13x C y +=的焦点分别为()()122,02,0F F -、，且点M 是1C 和2C 的一个交点，联立2222131x y x y ⎧+=⎪⎨⎪-=⎩，得2231,22x y ==，故不妨设62,22M ⎛⎫ ⎪ ⎪⎝⎭，则2216||222312MF ⎛⎫⎛⎫=+=+ ⎪ ⎪ ⎪ ⎪⎝⎭⎝⎭+，21222236||2||22,212MF F F ⎛⎫⎛⎫=+=- ⎪ ⎪ ⎪ ⎪⎝⎭⎝-=⎭则△MF 1F 2的中|F 1F 2|最长，2221212|||||MF F MF F =+.故△MF 1F 2是直角三角形．选B ． 考点：三角形的形状的判断【名师点睛】本题考查三角形的形状的判断，属中档题.解题时要认真审题，注意勾股定理的合理运用．由已知条件分别求出()()122,02,0F F -、，由于两条曲线相交由四个交点，而且具有对称性，故不妨设62,22M ⎛⎫⎪ ⎪⎝⎭，分别求出△MF 1F 2的三条边，用勾股定理判断△MF 1F 2的形状. 9．A 【解析】试题分析：A 中1,2a b ==，渐近线为2y x =±，B 中2,1a b ==，渐近线为12y x =±，C 中1,2a b == 渐近线为2y x =±，D 中2,1a b ==，渐近线为22y x =±考点：双曲线方程及性质 10．A【解析】试题分析：通过椭圆的离心率，得到ab 的关系式，然后求解双曲线的渐近线方程． 解：椭圆+=1（a ＞b ＞0）的离心率为，可得，可得，解得，∴双曲线﹣=1的渐近线方程为：y=±x ．故选：A ．考点：双曲线的简单性质；椭圆的简单性质． 11．D 【解析】试题分析：因为双曲线)0,0(1:2222>>=-b a b y a x C 的一条渐近线为b y x a =，且过其焦点(,0)Fc 的直线l 与b y x a =垂直，所以直线l 的方程为：()a y x cb =-，所以由()a y xc b b y x a ⎧=-⎪⎪⎨⎪=⎪⎩可得垂足的横坐标为222222a c a c a x a b c c ===+．因为垂足恰好在线段OF 的垂直平分线2cx =上，所以22a c c =，即222c a =，所以双曲线C 的离心率为2e =，故应选D ．考点：1、双曲线的简单性质；2、直线与双曲线的综合问题．【思路点睛】本题主要考查双曲线的简单几何性质和直线与双曲线的综合问题，属中档题．其解题的一般思路为：首先求出双曲线的一条渐近线与过焦点的与之垂直的直线的交点，然后由该交点在线段OF 的垂直平分线上，即可得出关于,,a b c 之间的等式关系，最后由双曲线的离心率的计算公式即可得出所求的结果． 12．D 【解析】试题分析：因''()()()()0f x g x f x g x +>，即'[()()]0f x g x >，故()()f x g x 在(,0)-∞上递增，又∵()f x ，()g x 分别是定义R 上的奇函数和偶函数，∴()()f x g x 为奇函数，关于原点对称，所以()()f x g x 在(0,)+∞上也是增函数．∵(3)(3)0f g =，∴(3)(3)0f g --=，所以()()0f x g x <的解集为：3x <-或03x <<，故选D ．考点： 函数奇偶性的性质；导数的运算；不等式． 13． 【解析】试题分析：根据微积分基本定理计算即可．解：dx==故答案为：． 考点：定积分． 14．[)1,+∞ 【解析】试题分析：可知()(),,,A a a Ba a -，设C ()2,m m ，()()22,,,AC m a m a BC m a m a =+-=--．∵该抛物线上存在点C ，使得∠ACB 为直角，()()()220AC BC m a m a m a ∴⋅=+-+-=，化为()2220m a m a -+-=．2101m a m a a ≠∴=-≥∴≥，∴a 的取值范围为[)1,+∞．考点：直线与圆锥曲线的关系 15．52【解析】试题分析：双曲线2210tx y --=的渐近线为y k x =±，一条渐近线与直线230x y -+=垂直，所以渐近线的斜率为12-，所以12b a ＝，所以22214c a a -＝，所以52e =． 考点：1、双曲线的性质；2、两条直线垂直的充要条件． 16．【解析】试题分析：首先对曲线的方程求导，代入曲线上的所给的点的横标，做出曲线对应的切线的斜率，进而得到曲线的倾斜角． 解：∵曲线∴y′=x， ∴曲线在点处切线的斜率是1， ∴切线的倾斜角是故答案为：考点：利用导数研究曲线上某点切线方程；直线的倾斜角． 17．112c <<【解析】试题分析：由指数函数二次函数的单调性可分别求得命题p,q 中c 的取值范围；借助于复合命题的判定方法分情况讨论得到c 需满足的条件，进而得到其范围 试题解析：依题意：p 真q 假或p 假q 真p 真01c ⇔<<（3分） q 真102c ⇔<≤011112c p q c c <<⎧⎧⎪∴⇔⎨⎨<<>⎩⎪⎩真假或 112c ∴<<1102c p q c >⎧⎧⎪∴⇔⎨⎨<≤⎩⎪⎩假真 ϕ∴综上可知：112c << 考点：1．函数单调性；2．复合命题18．（Ⅰ）见解析；（Ⅱ）当点E 是线段1AB 的中点时，有DE 面11AA C C ；（Ⅲ）45︒．【解析】试题分析：（Ⅰ）由正方形的性质得1AC AA ⊥，然后由面面垂直的性质定理可证得结果；（Ⅱ）当点E 是线段1AB 的中点时，利用中位线定理可得1DEA C ，进而得出DE 面11AA C C ；（Ⅲ）利用二面角的定义先确定11C A C ∠是二面角111C A B C --的平面角，易求得11tan C A C ∠，从而求得二面角的平面角为的度数．试题解析：（Ⅰ）因为四边形11AA C C 为正方形，所以1AC AA ⊥． 因为平面ABC ⊥平面11AA C C ，且平面ABC 平面11AAC C AC =，所以1AA ⊥平面ABC ．（Ⅱ）当点E 是线段1AB 的中点时，有DE 面11AA C C ，连结1A B 交1AB 于点E ，连结DE ，因为点E 是1A B 中点，点D 是线段BC 的中点，所以1DE A C ．又因为DE ⊄面11AA C C ，1A C ⊂面11AA C C ，所以DE 面11AA C C .（Ⅲ）因为1AA ⊥平面ABC ，所以1AA AB ⊥.又因为AC AB ⊥，所以AB ⊥面11AA C C ，所以11A B ⊥面11AA C C ，所以11A B ⊥11A C ，11A B ⊥1A C ， 所以11C A C ∠是二面角111C A B C --的平面角， 易得11111tan 1C CC A C C A ∠==，所以二面角111C A B C --的平面角为45°. 考点：1、线面垂直的判定；2、线面平行的判定；2、二面角．【方法点睛】立体几何中的探索性问题主要是对平行、垂直关系的探究，对条件和结论不完备的开放性问题的探究．解决这类问题时一般根据探索性问题的设问，假设其存在并探索出结论，然后在假设下进行推理，若得到合乎情理的结论就肯定假设，若得到矛盾就否定假设． 19．（Ⅰ）6,9a b =-=;（Ⅱ）最大值()115f -=, 最小值()212f =- 【解析】试题分析：（Ⅰ）由题意可知()13f =且()'10f =,从而可求得,a b 的值. （Ⅱ）求导,讨论导数的正负得函数的增减区间,比较其极值与端点处函数值,其中最大的为最大值,最小的为最小值. 试题解析：解: （Ⅰ）()2'32f x ax bx =+,由题意可知()()1336,9320'10f a b a b a b f =⎧+=⎧⎪⇒⇒=-=⎨⎨+==⎩⎪⎩. 6分 （Ⅱ）由（Ⅰ）知()3269f x x x =-+,()()2'1818181f x x x x x ∴=-+=--, 令()'0f x =得0x =或1x =()'0f x >时, 01x <<;()'0f x <时10x -<<或12x <<.所以函数()f x 在()1,0-和()1,2上单调递减,在()0,1上单调递增.因为()()16915,1693f f -=+==-+=,()()00,212f f ==-,最大值()115f -=, 最小值()212f =- 12分考点：用导数求函数的极值和最值.20．(Ⅰ) 22182y x +=;(Ⅱ) 220x y +-=. 【解析】试题分析：(Ⅰ)根据PM MD =可知M 是线段PD 的中点.设(,)M x y ,根据中点坐标公式可得点P 坐标,将其代入圆O 方程,整理即可求得点M 的轨迹方程. (Ⅱ) 设11(,)A x y 、22(,)B x y ,将其代入点M 的轨迹方程.两式相减,结合中点坐标公式可得直线l 的斜率.由点斜式可得直线l 的方程.试题解析：解：(Ⅰ) 点M 在线段PD 上，满足PM MD =∴点M 是线段PD 的中点设(,)M x y ，则(,2)P x y点P 在圆22:8O x y +=上运动则 ()2228x y += 即 22182y x += ∴点M 的轨迹方程为22182y x +=． (Ⅱ) 方法一：当直线l x ⊥轴时，由椭圆的对称性可得弦AB 的中点在x 轴上，不可能是点Q ，这种情况不满足题意．设直线l 的方程为1(1)2y k x -=-，由 221()248y kx k x y ⎧=+-⎪⎨⎪+=⎩可得 22211(14)8()4()8022k x k k x k ++-+--= 由韦达定理可得 12218()214k k x x k -+=-+ 由AB 的中点为11,2Q ⎛⎫ ⎪⎝⎭，可得218()2214k k k --=+ 解得12k =- 即直线l 的方程为11(1)22y x -=-- ∴直线l 的方程为220x y +-=方法二：当直线l x ⊥轴时，由椭圆的对称性可得弦AB 的中点在x 轴上，不可能是点Q ，这种情况不满足题意设11(,)A x y 、22(,)B x yA 、B 两点在椭圆上，满足 221122221(1)821(2)82x y x y ⎧+=⎪⎪⎨⎪+=⎪⎩ 由(1)(2)-可得 22221212082x x y y --+= 则 1212121214y y y y x x x x -+⋅=--+ 由AB 的中点为11,2Q ⎛⎫⎪⎝⎭，可得12122,1x x y y +=+=，代入上式121212AB y y k x x -==-- 即直线l 的方程为11(1)22y x -=-- ∴直线l 的方程为220x y +-=考点：1代入法求轨迹方程;2中点弦问题. 21．（1）．（2）经验证k=使得①成立综上可知，存在k=使得以CD 为直径的圆过点E ． 【解析】试题分析：（1）直线AB方程为bx﹣ay﹣ab=0，依题意可得：，由此能求出椭圆的方程．（2）假设存在这样的值．，得（1+3k2）x2+12kx+9=0，再由根的判别式和根与系数的关系进行求解．解：（1）直线AB方程为bx﹣ay﹣ab=0，依题意可得：，解得：a2=3，b=1，∴椭圆的方程为．（2）假设存在这样的值．，得（1+3k2）x2+12kx+9=0，∴△=（12k）2﹣36（1+3k2）＞0…①，设C（x1，y1），D（x2，y2），则而y1•y2=（kx1+2）（kx2+2）=k2x1x2+2k（x1+x2）+4，要使以CD为直径的圆过点E（﹣1，0），当且仅当CE⊥DE时，则y1y2+（x1+1）（x2+1）=0，∴（k2+1）x1x2+（2k+1）（x1+x2）+5=0…③将②代入③整理得k=，经验证k=使得①成立综上可知，存在k=使得以CD为直径的圆过点E．考点：圆与圆锥曲线的综合；椭圆的标准方程．22．（1）11,2a b==；（2）最大值为1(1)2f=-；（3）2[,)2e+∞．【解析】试题分析：（1）已知“()f x 在1x =处与直线12y =-相切”说明'(1)0f =，1(1)2f =-，联立可解得,a b ；（2）要求最大值，首先通过导数研究函数()f x 在1[,]e e上的单调性与极值，发现在此区间上只要一个极大值点，它一定是最大值点；（3）本小题不等式恒成立问题，有两个参数,a b ，因此要把问题进行转化，不等式()f x x ≥对所有的(,0]b ∈-∞，2(,]x e e ∈都成立，即2ln a x bx x -≥对所有的(,0]b ∈-∞，2(,]x e e ∈都成立，即2ln a x x bx -≥对所有的(,0]b ∈-∞，2(,]x e e ∈都成立，即ln 0a x x -≥对2(,]x e e ∈恒成立，即ln x a x≥对2(,]x e e ∈恒成立， 即a 大于等于ln x x 在区间2(,]e e 上的最大值，下面只要求得于()ln x h x x=在区间2(,]e e 上的最大值即可． 试题解析：（1）'()2a f x bx x =-． 由函数()f x 在1x =处与直线12y =-相切，得'(1)01(1)2f f ⎧=⎪⎨=-⎪⎩，即2012a b b -=⎧⎪⎨-=-⎪⎩． 解得：112a b =⎧⎪⎨=⎪⎩． （2）由（1）得：21()ln 2f x x x =-，定义域为(0,)+∞． 此时，2'11()x f x x x x -=-=，令'()0f x >，解得01x <<，令'()0f x <，得1x >． 所以()f x 在1(,1)e上单调递增，在(1,)e 上单调递减，所以()f x 在1[,]e e 上的最大值为1(1)2f =-． （3）若不等式()f x x ≥对所有的(,0]b ∈-∞，2(,]x e e ∈都成立，即2ln a x bx x -≥对所有的(,0]b ∈-∞，2(,]x e e ∈都成立， 即2ln a x x bx -≥对所有的(,0]b ∈-∞，2(,]x e e ∈都成立， 即ln 0a x x -≥对2(,]x e e ∈恒成立， 即ln x a x≥对2(,]x e e ∈恒成立， 即a 大于等于ln x x 在区间2(,]e e 上的最大值．令()ln x h x x=，则'2ln 1()(ln )x h x x -=，当2(,]x e e ∈时，'()0h x >，()h x 单调递增， 所以()ln x h x x=，2(,]x e e ∈的最大值为22()2e h e =，即22e a ≥． 所以a 的取值范围为2[,)2e +∞． 考点：用导数研究函数在某点处的切线，用导数研究函数的最值，不等式恒成立问题．【名师点睛】1．求曲线y ＝f （x ）在点P （x 0，f （x 0））处的切线方程：（1）求出函数y ＝f （x ）在点x ＝x 0处的导数，即曲线y ＝f （x ）在点P （x 0，f （x 0））处切线的斜率．（2）切线方程为：y ＝y 0＋f ′（x 0）（x －x 0）．2．不等式恒成立问题可转化为函数最值，转化为用导数求函数的最值，具体的转化方法是用分离参数法．。

大连市2020～2021学年度第二学期期末考试高二语文注意事项:1．答卷前，考生务必将自己的姓名、考号填写在答题卡上，并认真阅读答题卡上的注意事项。

2．回答选择题时，选出每小题答案后，用铅笔把答题卡上对应题目的答案标号涂黑。

如需改动，用橡皮擦干净后，再选涂其他答案标号。

回答非选择题时，将答案写在答题卡上。

写在本试卷上无效。

3．考试结束后，将本试卷和答题卡一并交回。

一、现代文阅读（35分）（一）现代文阅读I（本题共5小题，19分）阅读下面的文字，完成1～5题。

材料一：对说唱文艺进行跨学科研究，因研究者的立足点不同，其研究的路径、方法等自然会有差异。

例如，唐五代的变文讲唱、宋代的说经、明清时期的宝卷，都是受宗教特别是佛教影响而产生的说唱艺术，如果不借鉴宗教学的知识与方法，不了解宗教艺术，不联系宗教在民间的传布，是无法对之进行深入研究的。

在这一方面，李小荣《变文讲唱与华梵宗教艺术》将变文讲唱和华梵宗教艺术结合起来，就对变文的生成与衍变、变文与华梵音乐戏曲之关系、变文中的三教思想等做了较准确、具体的阐释。

又如，民间说唱与民俗文化关系至为密切，诸如岁时节令、人生礼仪、教化娱乐等在很多说唱文艺作品中都有不同程度的反映。

清代鼓词《封神榜》在说唱哪吒的故事中就穿插、敷衍了京城庙会盛况，鼓词《西游记》在说唱凤仙郡求雨时则穿插、敷衍了京城德胜门外黑寺、黄寺等喇嘛庙“打鬼”驱邪的风习；扬州评话《武松》讲武大郎过年，则渲染了扬州人的过年习俗；广州木鱼书《七夕赞花》也描绘了广府人的乞巧民俗……这样便赋予了说唱内容以浓厚的地方色彩和生活气息，保存了丰富的民间文化记忆。

对此，有必要从社会学、人类学、民俗学等角度阐释其文化内涵与认识价值。

除了基于民间说唱文艺本体开展跨学科研究外，也可以立足于某一学科，从说唱文艺中获取丰富的研究资料，拓新该学科的研究领域，丰富其研究内容，创新其学术观点。

早在20世纪上半叶，刘半农就提出，“研究俗曲，可以从四方面进行：一、文学方面，第 1 页（语文试卷共 10 页）二、风俗方面，三、语言方面，四、音乐方面。

2021年春季学期高二年级期中考试化学试题本试题卷共4页。

全卷满分100分，考试用时75分钟。

可能用到的相对原子质量：H 1 C 12 N14 O 16 F 19 S 32 Cl 35.5 Cu 64 Pb 207 一、选择题：本题共15小题，每小题3分，共45分。

在每小题给出的四个选项中，只有一项是符合题目要求的。

）1．化学在环境、生产和生活中有着广泛的应用。

下列说法中正确的是A．普通锌锰干电池不含环境污染物，可以随意丢弃B．石油化工中的裂化、裂解过程都是通过化学反应来获得气态烯烃C．绿色化学的核心是利用化学原理从源头上减少和消除工业生产对环境的污染D．某些植物具有富集溴的能力，从海产品中提取溴是工业上获取溴的重要途径2．下列各组有机物属于同分异构体的是A．．和B．CH3CH2OH、HOCH2CH2OHC．D．3．正丁烷的二氯取代产物为A(C4H8Cl2)，A分子中又有一个H原子被Cl原子取代，生成的C4H7Cl3有四种同分异构体，则A的结构有A．1种B．2种C．3种D．4种4．关于化学反应速率和限度，下列说法正确的是：A．密闭容器中进行的如下反应：2X(g)+Y(g)Z(g)+W(s) ΔH＞0，升高温度，正反应速率增大，逆反应速率减小B．对于反应：H2S(g) H2(g)＋S(s)ΔH＞0 ，加压或降温都能使化学平衡向逆反应方向移动C．一定条件下，2L 密闭容器中存在反应：CO(g)+H2O(g)CO2(g)+H2(g) △H＜0。

达平衡后再充入一定量的CO(g)，平衡正向移动，平衡常数K变大D．增大反应物的浓度，平衡向右移动，生成物的百分含量不一定增大5．常温下，下列各组离子在指定溶液中一定能大量共存的是A．无色透明溶液中：NH+4、SO2-4、Na+、MnO-4B．()()12c H110c OH+--=⨯的溶液中：NO-3、Na+、AlO-2、K+C．c(H+)=的溶液中：Fe3+，Mg2+、HCO-3、SO2-4D．c(H+)水电离・c(OH-)水电离=10-26的水溶液中：Na+、NO-3、Ag+、K+6．现有4种元素的基态原子的电子排布式如下：①1s22s22p3；②1s22s22p5；③1s22s22p63s23p3；④1s22s22p63s23p4，则下列比较中正确的是A．第一电离能：②＞①＞④＞③B．原子半径：③＞④＞②＞①C．电负性：②＞①＞④＞③D．最高正化合价：②＞③=①＞④7. 36．（2021·简阳市阳安中学高二月考）下列说法中正确的是A．4P和4CH都是正四面体型分子，且键角相等B．乙烯分子中，碳原子的2sp杂化轨道形成σ键，未杂化的2p轨道形成π键C．Fe成为阳离子时首先失去3d轨道电子D．3PH分子中孤电子对与成键电子对的排斥作用比成键电子对之间的排斥作用弱8.在密闭容器发生下列反应aA(g)⇌cC(g)＋dD(g)，反应达到平衡后，将气体体积压缩到原来的一半，当再次达到平衡时，D的浓度为原平衡的1.8倍，下列叙述正确的是A．a＜c＋d B．平衡向正反应方向移动C．D的体积分数变大D．A的转化率变大9.根据下列实验操作所得的现象及结论不正确的是A ．AB ．BC ．CD ．D 10．主族元素W 、X 、Y 、Z 的原子序数依次增加，且均不大于20。

辽宁省沈阳市2020~2021年高二下学期期中考试练习试卷七一、单选题1．下列物质与其用途相符合的是 （ ）①HClO -----作消毒剂 ①NaHCO 3----医疗上治疗胃酸过多 ①AgI ----人工降雨 ①Na 2O 2----呼吸面具的供氧剂 ①淀粉----检验I 2的存在 ①MgO ----作耐高温材料 A ．①①①①B ．①①①①C ．①①①①①D ．全部2．下列有关说法正确的是（ ）A ．某放热反应能自发进行，因此该反应是熵增反应B ．Fe(OH)3胶体无色、透明，不能透过滤纸C ．单质硅是将太阳阳转变为电能的常用材料D ．SiO 2既能和NaOH 溶液反应又能和氢氟酸反应，所以是两性氧化物 3．下列根据实验操作和现象所得出的结论正确的是A ．AB ．BC ．CD ．D4．下列关于烷烃的表述正确的是( )A ．乙烷的结构式为33CH CHB ．512C H 分子的某种结构为()32323CH CH CH CH CHC ．()3225223CH CH CH C H CH CH CH 与()3222523CH CH CH CH C H CH CH 互为同分异构体D ．410C H 的一氯代物有4种5．连接四种不同原子或原子团的碳原子称为手性碳原子，药物阿司匹林（B ）可由水杨酸（A ）制得。

下列说法正确的是A ．阿司匹林能与溴水反应而使之褪色B ．可用氯化铁溶液鉴别水杨酸和阿司匹林C ．由A 反应生成B ，另一种反应物为乙醇D ．阿司匹林中带星号（*）的碳原子是手性碳原子 6．关于有机物的下列叙述中，正确的是( )A ．它的系统名称是2，4－二甲基－4－戊烯B ．它不能使酸性高锰酸钾溶液褪色C ．它与甲基环己烷互为同分异构体D ．该有机物的一氯取代产物共有4种7．4-甲基-2-乙基-1-戊烯与2H 加成所得产物的名称为（）A ．4-甲基-2-乙基戊烷B ．2，5-二甲基戊烷 C ．2-乙基-4-甲基戊烷 D ．2，4-二甲基己烷8．主链上有4个碳的某烷烃有两种同分异构体，则与该烷烃等碳且主链上四个碳的烯烃的同分异构体有几种（ ） A ．3B ．4C ．5D ．69．下列分子式只能表示一种物质的是 A ．CH 2Cl 2B ．C 4H 10C ．C 5H 12D ．C 6H 1210．下列说法不正确的是（ ）A ．“光化学烟雾”“硝酸型酸雨”的形成都与氮氧化物有关B ．酒精、次氯酸钠消毒液均可以将病毒氧化而达到消毒的目的C ．一束平行光线射入蛋白质溶液里，从侧面可以看到一条光亮的通路D ．氢氧化铁胶体中逐滴滴入稀硫酸，先看到红褐色沉淀生成而后沉淀溶解 11．设N A 为阿伏加德罗常数的值，下列说法正确的是A ．27g 铝加入lmol/L 的NaOH 溶液，转移电子数是3N AB ．28gN 2与CO 混合物中原子总数是4N AC ．一定条件下，将1g 乙炔（C 2H 2）溶于12g 苯，所得混合物中含有的碳原子数为N AD ．标准状况下，2.24 L C 10H 22分子中共价键总数为31 N A12．下列说法正确的是A ．玻尔原子结构模型不但成功解释了氢原子光谱，而且还解释了其他原子光谱B ．基态氧原子轨道表示式违背了泡利不相容原理C ．在基态多电子原子中，p 轨道电子能量一定高于s 轨道电子能量D ．不同的能层所含的s 能级的原子轨道数是不同的 13．下列说法错误．．的是 A ．生石灰可用作食品干燥剂，铁粉可用于食品的防氧化 B ．“低碳生活”中的“碳”是指有毒气体CO ，减少CO 的排放 C ．碳酸钠可用于去除餐具的油污D ．加工后具有吸水性的植物纤维可用作食品干燥剂14．有机物X 完全燃烧的产物只有二氧化碳和水，元素组成分析发现，该物质中碳元素的质量分数为64.86%，氢元素的质量分数为13.51%，它的核磁共振氢谱有5组明显的吸收峰，且只含有一个甲基。

2015-2016学年度得胜高中高二（上）文科数学期中考试卷考试时间：150分钟；命题人：高一备课组第I 卷（选择题）1．与命题“若m ∈M ，则n ∉M”等价的命题（ ） A ．若m ∉M ，则n ∉M B ．若n ∉M ，则m ∈M C ．若m ∉M ，则n ∈M D ．若n ∈M ，则m ∉M2．钱大姐常说“便宜没好货”，她这句话的意思是：“不便宜”是“好货”的（ ） A ．充分条件 B ．必要条件C ．充分不必要条件D ．必要不充分条件 3．复数)2(i i z +=在复平面内对应的点位于（ ）A ．第一象限B ．第二象限C ．第三象限D ．第四象限 4．下列命题中错误的个数是（ ）①命题“若2320x x -+=则x=1”的否命题是“若2320x x -+=则x≠1”.②命题P:0x R ∃∈,使0sin 1x >，则0:P x R ⌝∀∈,使0sin 1x ≤. ③若p 且q 为假命题，则p 、q 均为假命题. ④"2()"2k k Z πφπ=+∈是函数sin(2)y x φ=+为偶函数的充要条件.A.1B.2C.3D.45．“0m >”是“方程2214x y m+=表示椭圆”的（ ） A ．充分不必要条件 B ．必要不充分条件C ．充要条件D ．既不充分也不必要条件 6．设复数1z ，2z 在复平面内的对应点关于虚轴对称，12z i =+，则12z z =（ ）A.5B.5-C.4i -+D.4i --7．直线4kx －4y －k ＝0与抛物线y 2＝x 交于A 、B 两点，若|AB|＝4，则弦AB 的中点到直线x ＋12＝0的距离等于( ) A ．74 B ．2 C ．94D ．4 8．用反证法证明命题“若0a b c ++≥，0abc ≤，则,,a b c 三个实数中最多有一个小于零”的反设内容为（ ）A ．,,a b c 三个实数中最多有一个不大于零B ．,,a b c 三个实数中最多有两个小于零C ．,,a b c 三个实数中至少有两个小于零D ．,,a b c 三个实数中至少有一个不大于零9．已知椭圆C 的上、下顶点分别为1B 、2B ，左、右焦点分别为1F 、2F ，若四边形1122B F B F 是正方形，则此椭圆的离心率e 等于A ．13 B ．12C ．2D 10．下列说法：①将一组数据中的每个数据都加上或减去同一个常数后，方差恒不变； ②设有一个回归方程，变量x 增加一个单位时，y 平均增加5个单位；③线性回归方程必过；④在一个2×2列联表中，由计算得K 2=13.079，则有99%的把握确认这两个变量间有关系； 其中错误的个数是（ ） A.0 B.1 C.2 D.311．已知过双曲线2222:1(0,0)x y C a b a b-=>>的中心的直线交双曲线于点,A B ，在双曲线C 上任取与点,A B不重合的点P ，记直线,,PA PB AB 的斜率分别为12,,k k k ，若12k k k >恒成立，则离心率e 的取值范围为()A ．1e <<．1e <≤．e >．e ≥12．设函数()f x '是奇函数()f x （x R ∈）的导函数，且(1)0f -=，当0x >时，()()0xf x f x '-<，则使()0f x >成立的x 的取值范围是（ ） A ．()(),10,1-∞- B ．()()1,01,-+∞ C ．()(),11,0-∞-- D ．()()0,11,+∞第II 卷（非选择题）13．复数z =（i 是虚数单位），则2z z += ． 14．直线12y x b =+是曲线y=ln x （x>0）的一条切线，则实数b= 15．椭圆1422=+y m x 的一个焦点为（0,1）则m ＝________. 16．设曲线x y e =在点（0,1）处的切线与曲线1(0)y x x=>上点P 处的切线垂直，则P 的坐标为 ． 三、解答题（题型注释）17．已知:(2)(6)0,:25p x x q x +-≤-<，命题“p q ∨”为真，“p q Λ”为真，求实数x 的取值范围． 18．为考察某种药物预防禽流感的效果，进行动物家禽试验，调查了100个样本，统计结果为：服用药的共有60个样本，服用药但患病的仍有20个样本，没有服用药且未患病的有20个样本. （1）根据所给样本数据完成下面2×2列联表； （2）请问能有多大把握认为药物有效？19．（1）已知抛物线的顶点在原点，准线方程为41-=x ，求抛物线的标准方程； （2）已知双曲线的焦点在x 轴上，且过点（ 2-，-3），（315，2），求双曲线的标准方程。

得胜高中2015-2016学年度第二学期期中高二英语试卷时间：120分钟满分：150分第一部分听力（共20小题，满分30分略）第二部分阅读理解（共两节，满分40分）第一节 (共15小题，每小题2分，满分30分)阅读下列短文，从每题所给的四个选项中选出最佳选项并在答题卡上将该项涂黑。

AMany years ago my student asked me the question, "Mrs. Kindred, why do you teach?" Without taking time to reflect, I answered, "Because someday I might say something that might make a difference in someone's life." Even though I was honest, that wasn't a very good answer and my student didn't let it slide."Let me get this straight," he said, "You went to college for four years so you could come here every day because you have the hope that someday you might say something that will influence someone?" He shook his head as if I were crazy and walked away looking confused. I'm one of those people who look back and wish they had said something smart or witty, or swift.Even though that particular student might no longer wonder why I teach, there are days when I wonder. On those days, I remind myself of the real reasons I teach:It's in my blood. My mother was my most influential teacher, and she was a 6th grade reading teacher until her death in 1990. She instilled(逐渐灌输) in me a love of reading and the knowledge that education opens doors.Teaching is a way to make a difference. If you throw a stone in a pond the ripples go on and on until they reach the shore. You can't have ripples without a "stone." Good teachers throw stones that make a positive difference, and that's what I strive to do.I genuinely love teenagers.I want to share with others what I know and what I have learned through the years. Life is full of ups and downs, and if I can help students avoid some potholes on the road of life, I want to do so. If they'll allow me to celebrate their victories with them, I want to do too. Teaching isn't for everyone, but I know I made the right career choice.21. Why did the student continue to ask the question about the writer’s being a teacher?A. Because he thought her answer was unbelievable.B. Because the writer was insincere.C. Because the student was naughty.D. Because the answer was difficult to understand.22. What do you think of the writer?A. Stupid.B. Honest.C. Conservative.D. Polite.23. According to the text, which of the following is NOT true?A. The writer’s mother has the greatest influence on her.B. The writer’s answer made the student confused.C. In the writer’s opinion, some people in the world are unfit to teach.D. The writer annoyed the student who asked the question.24. Wh at’s the main idea of the text?A. A student’s silly question.B. A good teacher who likes students.C. The reason why I teach.D. A confused student.BMargaret, married with two small children, has been working for the last seven years as a night cleaner, cleaning offices in a big building.She got trained as a nurse, but had to give it up when her elder child became seriously ill. “I would have liked to go back to it , but the shifts(工作班次)are all wrong for me, as I have to be home to get the children up and off to school.”So she works as a cleaner instead, from 9 p.m. till 6 a.m. five nights a week for just ￡ 90, before tax and insurance. “It’s better than it was last year, but I still think that people who work ‘unsocial hours’ should get a bit extra.”The hours she’s chosen to work mean that she sees plenty of the children, but very little of her husband. However, she doesn’t think that puts any pressure on their relationship.Her work isn’t physically very hard, but it’s not exactly pleasant, either. “I do get angry with people who leave their offices like a place for raising pigs. If they realized people like me have to do it, perhaps they’d be a bit more careful.”The fact that she’s working all night doesn’t worry Margaret at all. Unlike some dark buildings at night, the building where she works is fully lit, and the women work in groups of three. “Since I’ve got to be here, I try to enjoy myself－and I usually do, together with the other girls. We all have a good l augh, so the time never drags.”Another challenge Margaret has to face is the reaction of other people when she tells them what she does for a living. “They think you’re a cleaner because you don’t know how to read and write,” said Margaret. “I used to think wha t my parents would say if they knew what I’d been doing, but I don’t think that way any more. I don’t dislike the work though I can’t say I’m mad about it.”25．Margaret quit her job as a nurse because ______．A．she wanted to earn more money to support her familyB．she had suffered a lot of mental pressureC．she needed the rig ht time to look after her childrenD．she felt tired of taking care of patients26．Margaret gets angry with people who work in the office because ______．A．they never clean their offices B．they look down upon cleanersC．they never do their work carefully D. they always make a mess in their offices 27．When at work, Margaret feels ______．A．light-he arted because of her fellow workers B．happy because the building is fully lit C．tired because of the heavy workload D．bored because time passes slowly28．The underlined part in the last paragraph implies that Margaret’s parents would _____．A．help care for her children B．feel disappointed with herC．show sympathy for her D．regret what they had saidCJoin the discussion…LakeLander 2 hours agoToday, a man talked very loud on his phone on a train between Malvern and Reading, making many passengers upset. I wonder how he would react if I were to read my newspaper out loud on the train.I have never had the courage to do it, though.Pak50 57 minutes agoWhy not give it a try? Perhaps you should take lessons on a musical instrument. The late musician Dennis Brian is said to have asked a fellow train passenger to turn off his radio. When his request was refused, he took out his French horn(号) and started to practice.Angie O’Edema 42 minutes agoI don’t see how musical instruments can help improve manners in public. Don’t do to others what you wouldn’t like to be done to yourself. Once, a passenger next to me talked out loud on his mobile phone. I left my seat quietly, giving him some privacy to finish his conversation. He realized this and apologised to me. When his phone rang again later, he left his seat to answer it. You see, a bit of respect and cooperation can do the job better.Taodas 29 minutes agoI did read my newspaper out loud on a train, and it turned out well. The guy took it in good part, and we chatted happily all the way to Edinbergh.Sophie 76 13minutes agoI have not tried reading my newspaper out loud on a train, but ,several years ago, I read some chapters from Harry Porter to my bored and noisy children. Several passengers seemed to appreciate what I did.29. The passenger made an apology to Angie O’Edema because ________.A. he offered his seat to someone elseB. he spoke very loudly on his phoneC. he refused to talk with AngieD. he ignored Angie’s request30. Who once read a newspaper out loud on a train?A. Pak50B. Angie O’EdemaC. TaodasD. Sophie7631. What is the discussion mainly about?A. How to react to bad behavior.B. How to kill time on a train.C. How to chat with strangers.D. How to make a phone call.32.Where is the passage most probably taken from _______.A. A webpageB. A newspaperC. A novelD. A reportDIt’s wonderful to go to another country, complete a volunteer project and feel that you really have a positive influence. But how can you become an international volunteer?* Plan practically. Contact(联系) the organization a few months before leaving and find out if there are materials which are rare and hard to get for the project. What you often consider plentiful here, such as nails or hammers, is in great need in other parts of the world.* Do the project together, not on your own. You are a guest in the community(社区). The most successful result is not that you build something and walk away, but that you and community buildsomething as a team. Share skills and build together.* Be flexible. Not everything is going to happen as planned. Often the other country doesn’t have the right tools, manpower, transportation or funds to get all the needed work done. In a word, they lack infrastructure(基础设施).* Contact the peopl e in the community. Often you will have “downtime” outside the range of the project. Rather than move back to the group with whom you traveled, be sure to spend time with the people of the community. Listen to the things about their lives. If you can’t spe ak the language, smiles work wonders. And you will be surprised —you will find a way to community. Volunteering is a special and life-long experience for everyone involved(参与的). Be prepared that the person who may be changed most is you. It’s a joyful, often careful experience which will encourage you to view yourself, your neighbors and your world quite differently.33. To become a good volunteer in another country, you need to _________.A. stick to your original planB. speak the language fluentlyC. get well prepared in advanceD. bring along nails or hammers34. Which might be the most successful result when you do the project?A. Donating books to the community library.B. Spending some time chatting with the people.C. Building a school for the children before leaving.D. Making practical tools with the community members.35. What is the text ma inly about?A. Places in great need of volunteers.B. Ways to cooperate with local people.C. Reasons for the popularity of volunteering.D. Tips on becoming an international volunteer.第二节 (共5小题，每小题2分, 满分10分)根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。

2022-2022年度高二下学期英语期中试题第一局部阅读理解〔共20小题，每题2分，总分值40分〕阅读以下短文,从每题所给的四个选项(A、B、C和D)中选出最正确选项AAt a meeting, a well-known speaker lifted up a bill of 20 dollars before starting his speech.Facing 200 people, he asked, “Who wants this 20-dollar bill?〞 A great many hands were put up. Then he continued to say, “I intended to give it to any one of you, but allow me to do a thing before giving it to you.〞 Suddenly he crumpled it into a round mass. Then he asked, “Who wants it?〞 Still some hands were lifted up.He as ked again, “Well, how could it be if I do it like this?〞 he threw the bill onto the ground, stepped on it and twisted it. As he picked it up, the bill had become not only dirty but wrinkled.“Who still wants it?〞 Still a few people put up their hands.“My dear friends, you have had a meaningful class. No matter how I treated this bill, you still want it, because it is worth 20 dollars. On your life road, you may be knocked down or even broken into pieces by your determination or unfavorable situations. We may feel ourselves worth nothing, but, my darling, remember that whatever happens in the future, you should never lose your value in the God’s heart. You’re particular ---- never forget it.〞1. How many times did the speaker ask the people whether they wanted the bill?A. OnceB. TwiceC. Four timesD. Three times2. The underlined word “wrinkled〞 in the third paragraph probably means _____.A. having small lines or folds in itB. brokenC. flatD. having holes on it3. The speaker did this test in order to _____________.A. tell the audience that God values money mostB. tell the audience that one should never lose one’s own valueC. test if some of the audience were extremely interested in moneyD. play a trick on the audience4. What would the speaker probably talk about next?A. How money can make people crazy.B. How to avoid being knocked down in one’s life.C. How to give a meaningful class.D. How to keep one’s value of life.BMore and more students are going abroad for their further study. Do you want to know some famous colleges and universities? Started in 1636, Harvard University is the oldest of all the many colleges and universities in the United States. Yale, Princeton, Columbia and Dartmouth were opened soon after Harvard.In the early years, these schools were much alike .Only young men went to college. All the students studied the same subjects, and everyone learned Latin, Greek and Hebrew. Little was known about science then, and one kind of school could teach everything that was known about the world. When the students graduated, most of them became ministers or teachers.In 1782, Harvard started a medical school for young men who wanted to become doctors. Later, lawye rs could receive their training in Harvard’s law school. In 1825, besides Latin and Greek, Harvard began teaching modern languages, such as French and German. Soon it began teaching American history.As knowledge increased, Harvard and other colleges began to teach many new subjects. Students were allowed to choose the subjects that interested them.Today, there are many different kinds of colleges and universities. Most of them are made up of smaller schools that deal with special fields of learning. There’s so much to learn that one kind of school can’t offer it all.。

第一部分听力（共两节，满分20分）做题时，先将答案标在试卷上。

录音内容结束后，你将有两分钟的时间将试卷上答案转涂到答题卡上。

第一节（共5小题；每小题1分，满分5分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1.How much can the man lend to the woman?A.$1.B. $4.C. $ 5.2.What is wrong with the man in the woman’sopinion?A.H e always feels hungry.B.H e always feels exhausted(筋疲力尽).C.H e always feels nervous.3.What will the man do next?A.W ork on his paper.B.P aint his living room.C.H elp the woman with her paper.4.Where did the man find the advertisement?A. In a newspaper.B. In a magazine.C. On the Internet.5. What does the man mean?A. He doesn’t like to eat breakfast.B. He is too busy to have breakfast.C. He disagrees with the woman.第二节（共15小题；每小题1分，满分15分）听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。

得胜高中2020学年度第二学期期中考试高二物理试卷试卷满分：100分 答题时间：90分钟 第Ⅰ卷一、选择题（本大题共有15小题，每小题4分，合计60分；1～11小题每题只有一项符合正确选项，12～15小题每题至少有两项是正确选项。

）1．线圈在匀强磁场中匀速转动，产生交流电的图象如图所示，由图可知( ) A. 在A 和C 时刻线圈处于中性面位置 B. 在B 和D 时刻穿过线圈的磁通量为零C. 从A 时刻起到D 时刻，线圈转过的角度为π弧度D. 在A 和C 时刻磁通量变化率的绝对值最大 2．以下说法正确的是( ) A. 交变电流的有效值就是它的平均值 B. 任何交变电流的有效值都是它最大值的21倍C. 如果交变电流接在电阻R 上产生的热量为Q ，那么该交变电流的有效值为RQD. 以上说法均不正确3．通过某电流表的电流按如图所示的规律变化，则该电流表的读数为（ ） A. 24 A B. 4A C. 24 A D. 5A4．如图所示，当交流电源的电压（有效值）U=220V ，频率f=50Hz ，3只灯泡L 1、L 2、L 3分别与电容器C 、电感线圈L 、电阻R 相串联连，3只灯泡亮度相同（L 无直流电阻），若将交流电源的频率变为f=100Hz．电压不变，则（）A. L1灯比原来亮 B. L2灯比原来亮C. L3灯比原来暗 D. L3灯比原来亮5．如图所示的理想变压器，两个副线圈匝数分别为 n1和 n2，当把电热器接在 ab，使 cd 空载时，电流表的示数为 I1；当把电热器接在 cd，而使 ab 空载时，电流表的示数为 I2，则 I1∶ I2等于( )A. n1∶n2B. 2221:nnC. n2∶n1D. 2122:nn6．输电线路的总电阻为R，发电站输出功率为P，输电电压为U，则用户得到的功率为( )A. PB. P－()2·RC. P－D. ( )2·R 7．电子秤使用的是（）A. 超声波传感器B. 温度传感器C. 力传感器D. 光传感器8．如图所示，截面为矩形的金属导体，放在磁场中，当导体中通有电流时，导体的上下表面的电势有什么关系( )A. φM ＞φNB. φM ＝φNC. φM ＜φND.条件不足，无法不确定9．质量相等的氢气和氧气，温度相同，不考虑气体分子的势能，则A. 氢气的内能较大B. 氧气的内能较大C. 氧气分子的平均速率大D. 氢气分子的平均动能较大10．一个密闭的钢管内装有空气，在温度为27℃时，压强为1atm，若温度上升到127℃，管内空气的压强为( )A. 43atmB. 34atmC. 12727atmD. 27127atm11．密封在容器中的气体的压强（ ）A. 是由气体受到重力所产生的B. 是由气体分子间的斥力产生的C. 是气体分子频繁地碰撞器壁所产生的D. 当容器自由下落时将气体的压强减小为零12．北京市东城区民用电网改造完成后，某居民小区变压器输出端的交变电压瞬时值表达式t u π100sin 2220=，对此交变电压，下列表述正确的是（ ） A. 有效值是220V B. 频率是50Hz C. 最大值是220V D. 周期是0.01s 13．如图所示，R 1为定值电阻，R 2为负温度系数的热敏电阻(阻值随温度增加而减小)，L 为小灯泡，当温度降低时( ) A. R 1两端的电压减小 B. 电流表的示数增大 C. 小灯泡的亮度变强 D. 小灯泡的亮度变弱 14．关于布朗运动，下列说法中正确的是（ ） A. 布朗运动就是液体分子的热运动 B. 布朗运动间接表明液体的分子运动C. 悬浮的小颗粒越大，撞击它的分子数越多，布朗运动越激烈D. 液体的温度越高，布朗运动越激烈15．如图，一定质量的空气被水银封闭在静置于竖直平面的U 型玻璃管内，右管上端开口且足够长，右管内水银面比左管内水银面高h ，能使h 变大的原因是（ ）A. 大气压强升高B. 环境温度升高C. 沿管壁向右管内加水银D. U 型玻璃管加速上升 第Ⅱ卷二、实验题（本答题共有1个小题，没空2分，合计8分）16．在做“用油膜法测分子的大小”实验时，油酸酒精溶液的浓度为每104mL溶液中有纯油酸6mL，用注射器测得1mL。

辽宁省各地2020-2021年高二下学期英语4月月考试题精选汇编-应用文写作专题辽宁省大连市普兰店区第二中学2020-2021学年高二4月阶段性测试英语试题第一节(满分15分)假定你是李华,你校英语戏剧社正在招募新成员,请根据以下提示,用英文给负责人Mr. Smith写一封电子邮件,申请加入。

内容包括1.申请理由;2.个人优势;3.表达愿望。

注意:1.词数80左右; 2.可以适当增加细节,以使行文连贯;3.开头和结尾已为你写好,不计入总词数。

Dear Mr. Smith,___________________________________________________________________________________________ ___________________________________________________________________________________________ _______________________________________________________________Yours,Li Hua【答案】DearMr.Smith,I’mLiHua,writingtoapplytobeamemberofourschoolEnglishdramasociety.IhaveconfidencethatIamasuitablecan didateforthesociety.Tobeginwith,Iamenthusiasticaboutdramas,especiallyaboutEnglishdramasandstartedplayinginjuniorhighschool.Inaddition,Ihavetakenpartinsevera stbutnotleast,I’mfluentinEnglishandwonfirstpl aceintheEnglishspeechcontestheldinourcitylastyear.Ireallyhopetojoinyou.Iwouldappreciateitifyoucouldreplytomeatyourearliestconvenience.Yours,LiHua辽宁省实验中学东戴河分校两校2020-2021学年高二4月联考英语试题第一节应用文写作（满分15分）假设你是高中生李华，你校为了弘扬中国传统文化和丰富学生课余生活，将于本周五中午12点在学校报告厅(the school lecture hall)举行国画(Traditional Chinese Painting)展览，你的外教老师Linda对中国文化很感兴趣，请写一封邮件邀请她前来观看。

2020-2021学年高二下学期期中测试卷（结构+原理）04化学试题（考试时间：75分钟 试卷满分：100分）考试范围：2019人教版选修3第1、2章+选修4可能用到的相对原子质量：H-1 C-12 N-14 O-16 Na-23 Mg-24 Al-27 P-31 Cl-35.5 Fe-56 Cu-64一、选择题（本大题包括16小题，共44分，1—10每小题2分，共20分,11—16每小题4分，共24分。

在每小题列出的四个选项中，只有一个是正确的）1．我国对铜的认识年代久远，下列关于铜的几种表述正确的是A ．基态Cu 原子的电子排布式：[As]4s 1B ．基态Cu 原子的最高能层符号为NC ．基态Cu 原子的价电子排布图为D ．基态Cu 2+的未成对电子数为22．下列分子既不存在s-p σ键，也不存在p-p π键的是A ．HClB ．HFC ．N 2D ．SCl 23．下列各组物质中，都是极性分子的是A ．BH 3 和 NH 3B ．HCl 和 BeCl 2C ．PCl 3 和 NCl 3D ．SO 2 和 CO 24．多核离子所带电荷可以认为是中心原子得到或失去电子导致，根据VSEPR 模型，下列离子中所有原子都在同一平面的一组是A ．NO 2-和NH 2-B ．H 3O +和ClO 3-C ．NO 3-和CH 3-D ．PO 34-和SO 24-5．B 、C 、N 、O 是短周期主族元素。

下列有关说法正确的是A ．CO 的结构式：C O ≡B ．24N H 中氮原子的轨道杂化类型：2spC ．电负性：N O C >>D ．最高价氧化物的水化物的酸性：3323H BO H CO >6．最新发现C 3O 2是金星大气的成分之一，化学性质与CO 相似。

C 3O 2分子中结构如下：O=C=C=C=O ，下列说法中错误的是A ．元素的电负性和第一电离能O>CB ．CO 分子中σ键和π键的个数比为1：2C ．C 3O 2分子中C 原子的杂化方式为spD ．C 3O 2是一个具有极性共价键和非极性共价键的极性分子7．有几种阴离子的信息如下：阴离子4ClO - 3ClO - M ClO - 中心元素化合价5+ 3+ 1+ 中心原子杂化类型3sp 3sp 下列推断不正确的是A ．3ClO -和23CO -的价电子总数相同B ．M 的化学式为2ClO -C ．3ClO -、ClO -中氯原子的杂化类型都为3spD ．M 的空间结构为V 形8．下列模型分别表示C 2H 2、S 8、SF 6的结构，下列说法错误的是A ．1molC 2H 2分子中有3mol σ键B ．上述三种物质形成的晶体类型相同C ．SF 6属于极性分子D ．S 8中S 原子采用了sp 3杂化9．4LiAlH 是重要的还原剂与储氢材料，在120C ︒下的干燥空气中相对稳定，其合成方法为：44NaAlH LiCl LiAlH NaCl +=+。

2020-2021学年高二下学期期中语文试题（一）一、情景默写1．按要求填空。

（1）师者，________。

（韩愈《师说》）（2）《劝学》中阐述学习不够专一的原因的句子是：____________。

（3）《侍坐章》中表明孔子对子路言志的态度的句子_____________。

（4）《屈原列传》中司马迁称赞屈原《离骚》“言浅意深”的句子是：___________。

二、名著阅读2．下列《红楼梦》的诗句中，不是描写梅花的一句是（）。

A．桃李芬芳杏未红，冲寒先喜笑东风。

B．冻脸有痕皆是血，酸心无恨亦成灰。

C．闲庭曲槛无余雪，流水空山有落霞。

D．秋容浅淡映重门，七节攒成雪满盆。

三、选择题3．下面的选项排序正确的一项是（）。

1我们是不是也因之可以说乡下多文盲是因为乡下本来无需文字眼睛？2这样看来，乡村工作的朋友们说乡下人愚3至多是说，乡下人在城市生活所需的知识是不及城市里人多，这是正确的4显然不是指他们智力不及人，而是说他们知识不及人5这一点，依我们上面所说的，还是不太能自圆其说A．15423B．51234C．12453D．24531四、论述类文本阅读阅读下文，完成下面小题。

人生意义何处寻王时中古人云：“人生识字忧患始。

”意思是说，学会识文断字，固然能够给人的交流提供方便，给人的精神带来愉悦，但也可能使人“杞人忧天”、患得患失。

这也是近期“中国民众最关注的十大哲学问题调查”中，“人生的价值与意义”居前列的原因。

相对于不识字的动物不会出现的烦恼与困惑，有了文字之后的人类，不得不面对难以两全的困境：一方面人的自然生命注定人有生必有死，要吃也要喝，会搔痒，会打嗝；另一方面人的文化生命又使得人不安于自然生命的满足，而总想突破固有的限制，赋予生活以价值与意义，甚至不惜与人的自然需要相对立，如不食“嗟来之食”、富贵不淫、贫贱不移、威武不屈。

问题是，当人寻找自身的意义时，用什么作为尺度呢？如果仍然用人自身的尺度，那么，尺度与对象同一，怎么能够衡量呢？用人之外的事物作标准吗？但人自认为是万物之灵长，又岂肯屈从他物？因为这本身就贬低了人存在的意义。

得胜高中2020-2019学年度第一学期期中高二数学学科试卷一、选择题1.命题“∃0x ∈(0，＋∞)，ln 0x ＝0x －1”的否定是( )A ．∀x ∈(0，＋∞)，ln x ≠x －1B ．∀x ∉(0，＋∞)，ln x ＝x －1C ．∃0x ∈(0，＋∞)，ln 0x ≠0x －1D ．∃0x ∉ (0，＋∞)，ln 0x ＝0x －12．命题“若x ，y 都是偶数，则x ＋y 也是偶数”的逆否命题是( )A ．若x ＋y 是偶数，则x 与y 不都是偶数B ．若x ＋y 是偶数，则x 与y 都不是偶数C ．若x ＋y 不是偶数，则x 与y 不都是偶数D ．若x ＋y 不是偶数，则x 与y 都不是偶数 3、若a 、b 、c R ∈且a>b ，则下列不等式成立的是（ ） A ．b a 11<B ．22b a >C ．1122+>+c b c aD ．c b c a > 4．不等式2x 2－x －1>0的解集是( )A.⎝ ⎛⎭⎪⎫－12，1 B ．(1，＋∞) C ．(－∞，1)∪(2，＋∞) D.⎝⎛⎭⎪⎫－∞，－12∪(1，＋∞) 5．若x ，y 满足约束条件⎩⎪⎨⎪⎧ x －1≥0，x －y ≤0，x ＋y －4≤0，则y x 的最大值为________． A.3 B.31 C.1 D.4 6、在等差数列{}n a 中，已知1684=+a a ，则该数列前11项和S 11=（ ）A ．58B ．88C ．143D ．1767.等比数列{}n a 中，已知12324a a +=，3436a a +=，则56a a +=( )A.162B.4C.18D.648 8．设等差数列{a n }的前n 项和为S n ，若=1a －11，=+64a a －6，则当S n 取得最小值时，n 等于( )A ．5B ．6C ．7D ．89. 命题p ：||x ＋2＞2；命题q ：2＜x ＜3，则⌝p 是⌝q 的( )A ．充分不必要条件B ．必要不充分条件C ．充要条件D ．既不充分也不必要条件10.已知不等式ax 2－bx －1≥0的解集是⎣⎢⎡⎦⎥⎤－12，－13，则不等式x 2－bx －a <0的解集是( ) A.⎝ ⎛⎭⎪⎫－∞，13∪⎝ ⎛⎭⎪⎫12，＋∞ B ．(－∞，2)∪(3，＋∞)C.⎝ ⎛⎭⎪⎫13，12 D. (2,3) 11．等比数列{a n }的前n 项和为S n ，且4a 1,2a 2，a 3成等差数列，若a 1＝1，则S 4＝( ) A ．4 B ．10 C ．15 D ．1612．设,x y 满足约束条件1122x y x y x y +≥⎧⎪-≥-⎨⎪-≤⎩，若目标函数(0,0)z ax by a b =+>>的最大值为7,则34a b+的最小值为（ ） A.4 B.743+ C.247 D.7 二、填空题13. （16）数列{}n a 满足na a -=+111n ，2a =2，则1a =_________. 14．若实数,x y 满足不等式组2,24,0,x y x y x y +≥⎧⎪-≤⎨⎪-≥⎩则23z x y =+的最小值是__________．15.已知命题“,R x ∈∀ 021552>+-a x x ”的否定是假命题，则实数a 的取值范围是16.已知a >0，b >0，若不等式2a ＋1b ≥m 2a ＋b恒成立，则m 的最大值等于________．三、解答题17.设数列{}n a 满足：11a =，13n n a a +=，n N +∈．（Ⅰ）求{}n a 的通项公式及前n 项和n S ；（Ⅱ）已知{}n b 是等差数列，n T 为前n 项和，且12b a =，3123b a a a =++，求20T ．18、 解关于x 的不等式()012<++-a x a x .19.已知不等式22214x a x ax ->++对一切实数x 恒成立，求实数a 的取值范围．20. 给定两个命题，命题p ：04≤-a a ，命题q ：关于x 的方程02=+-a x x 有实数根， 若“p ∨q ”为真命题，“p ∧q ”为假命题，求实数a 的取值范围．21.已知数列{a n }的前n 项和S n ＝n 2＋n 2，n ∈N *. (1)求数列{a n }的通项公式；(2)设b n ＝n a 2＋(－1)na n ，求数列{b n }的前2n 项和．22.设n S 为数列{n a }的前项和，已知01≠a ，2n n S S a a •=-11，∈n N * （Ⅰ）求1a ，2a ，并求数列｛n a ｝的通项公式；(Ⅱ)求数列｛n na ｝的前n 项和.。

辽宁省大连经济技术开发区得胜高级中学2017-2018学年高二数学下学期期中试题文（无答案）编辑整理：尊敬的读者朋友们：这里是精品文档编辑中心，本文档内容是由我和我的同事精心编辑整理后发布的，发布之前我们对文中内容进行仔细校对，但是难免会有疏漏的地方，但是任然希望（辽宁省大连经济技术开发区得胜高级中学2017-2018学年高二数学下学期期中试题文（无答案））的内容能够给您的工作和学习带来便利。

同时也真诚的希望收到您的建议和反馈，这将是我们进步的源泉，前进的动力。

本文可编辑可修改，如果觉得对您有帮助请收藏以便随时查阅，最后祝您生活愉快业绩进步，以下为辽宁省大连经济技术开发区得胜高级中学2017-2018学年高二数学下学期期中试题文（无答案）的全部内容。

得胜高中2017-2018学年度第二学期期中高二数学（文）试卷一、选择题（本大题共12小题，每小题5分,共60分） 1.i 是虚数单位，1+i 3等于( ）（A)i (B)—i （C ）1+i (D ）1-i2.某商品销售量y （件)与销售价格x （元/件）负相关，则其回归方程可能是（ ) (A)^10200y x =-+ （B ）^10200y x =+ (C ）^10200y x =-- (D ）^10200y x =- 3。

极坐标方程cos ρθ=和参数方程123x ty t =--⎧⎨=+⎩（t 为参数）所表示的图形分别是（ )(A ）圆、直线 （B)直线、圆 （C ）圆、圆 (D ）直线、直线 4。

设复数z =－错误!＋错误!i ，则∣z ∣=( ） （A)1（B ）-54（C ）—1(D ）535。

通过随机询问110名性别不同的行人,对过马路是愿意走斑马线还是愿意走人行天桥进行抽样调查，得到如下的列联表：由22()()()()()n ad bc K a b c d a c b d -=++++，算得22110(40302020)~7.8.60506050K ⨯⨯-⨯=≈⨯⨯⨯附表：参照附表，得到的正确结论是（ ）（A ）有99％以上的把握认为“选择过马路的方式与性别有关” （B ）有99％以上的把握认为“选择过马路的方式与性别无关”（C ）在犯错误的概率不超过0．1％的前提下,认为“选择过马路的方式与性别有关”(D ）在犯错误的概率不超过0．1％的前提下，认为“选择过马路的方式与性别无关" 6.已知a R ∈，i 是虚数单位，若3,4z a i z z =+⋅=,则a=（ ) （A ）1或－1 （B ）7-7或 （C ）－3 （D)37。

（无答案）编辑整理：尊敬的读者朋友们：这里是精品文档编辑中心，本文档内容是由我和我的同事精心编辑整理后发布的，发布之前我们对文中内容进行仔细校对，但是难免会有疏漏的地方，但是任然希望（辽宁省大连经济技术开发区得胜镇2016-2017学年高二物理下学期期中试题（无答案））的内容能够给您的工作和学习带来便利。

同时也真诚的希望收到您的建议和反馈，这将是我们进步的源泉，前进的动力。

本文可编辑可修改，如果觉得对您有帮助请收藏以便随时查阅，最后祝您生活愉快业绩进步，以下为辽宁省大连经济技术开发区得胜镇2016-2017学年高二物理下学期期中试题（无答案）的全部内容。

试题（无答案)注意事项：1．请在答题纸上作答，在试卷上作答无效.2．本试卷分第Ⅰ卷（选择题）和第Ⅱ卷（非选择题)两部分，共100分,考试时间90分钟.第Ⅰ卷选择题（共60分）一、选择题(本题共12小题,每小题6分,共60分.在每小题给出的四个选项中全部选对的得6分，选对但不全的得3分，有选错的得0分。

）1。

下列描绘两种温度下黑体辐射强度与波长关系的图中，符合黑体辐射规律的是（）2.在卢瑟福α粒子散射实验中，金箔中的原子核可以看作静止不动，下列各图画出的是其中两个α粒子经历金箔散射过程的径迹,其中正确的是.（填选图下方的字母）3.产生光电效应时，关于逸出光电子的最大初动能E k,下列说法正确的是（）A．对于同种金属,E k与照射光的强度无关B．对于同种金属，E k与照射光的波长成反比C．对于同种金属，E k与光照射的时间成正比D ．对于同种金属，E k 与照射光的频率成线性关系4。

氢弹爆炸的核反应是（ )A ．n He H H 10423121+→+B ．H O He N 1117842147+→+C ．n 3Kr Ba n U 109236141561023592++→+D ．n C He Be 101264294+→+5.一个质子和一个中子聚变结合成一个氘核,同时辐射一个γ光子.已知质子、中子、氘核的质量分别为m 1、m 2、m 3，普朗克常量为h ，真空中的光速为c 。

得胜高中2020 学年度下学期期中高一英语试卷本试卷满分为120 分，考试时间为100 分钟第一部分阅读理解（共两节，满分40 分）第一节（共15 小题；每小题 2 分，满分30 分）阅读下列短文，从每题所给的四个选项（A B、C和D）中，选出最佳选项。

AIn 1978, I was 18 and was working as a nurse in a small town about 270 km away from Sydney, Australia. I was looking forward to having five days off from duty. Unfortunately, the only one train a day back to my homein Sydney had already left. So I thought I 'd hitch a ride （搭便车）.I waited by the side of the highway for three hours but no one stopped for me. Finally, a manwalked over and introduced himself as Gordon. He said that although he couldn 't give me a lift, I should come back to his housefor lunch. He noticed mestanding for hours in the Novemberheat and thought I must be hun gry. I was doubtful as a young girl but he assured （使…放心）meI was safe, and he also offered to help mefind a lift homeafterwards. When we arrived at his house, he made us sandwiches. After lunch, he helpedme find a lift home.Twenty-five years later, in 2020, while I was driving to a nearby town one day, I saw an elderly man standing in the glaring heat, trying to hitch a ride. I thought it was another chance to repay someonefor the favour I 'd been given decades earlier. I pulled over and picked him up. I made him comfortable on the back seat and offered him some water.After a few moments of small talk, the man said to me, changed a bit, even your red hair is still the same.You haven't I couldn ' t remember where I ' d met him. He then told me he was theman who had given melunch and helped mefind a lift all those years ago. It wasGordon.1. The author had to hitch a ride one day in 1978 because .A. her work delayed her trip to SydneyB. she was going home for her holidaysC. the town was far away from SydneyD. she missed the only train back home2. Which of the following did Gordon do according to Paragraph 2?A. He helped the girl find a ride.B. He gave the girl a ride back home.C. He bought sandwiches for the girl.D. He watched the girl for three hours.3. The reason why the author offered a lift to the elderly man was that .A. she realized he was GordonB. she had known him for decadesC. she was going to the nearby townD. she wanted to repay the favour she once got4. What does the author want to tell the readers through the story?A. Giving sometimes produces nice results.B. Those who give rides will be repaid.C. Good manners bring about happiness.D. People should offer free rides to others.BScientists in Argentina have created the world 's first cow with two human genes that will enable it to produce human-like milk.Genetic engineering was used to introduce the "mothers ' milk" genes intothe animal before birth, according to the National Institute of Agribusiness Technology in Buenos Aires.As an adult, the cloned cow "will produce milk that is similar to that of humans", which will prove "a development of great importance for the nutrition of infants（婴儿）", said the institute. "The cloned cow, namedRosita ISA, is the first in the world with two human genes that contain the proteins present in human milk," said the statement.In April, scientists in China published details of research showing that they had created dairy cows which produced milk containing proteins found in humanbreast milk. But the Argentine team said the Chinese only introduced one human gene, while their research involved two, meaning the milk will more closely resemble that of humans.“Our goal was to raise the nutrition value of cows ' milk by addingtwo humangenes, which do good to the immunesystem of infants, ” said Adrian Mutto, from the National University of San Martin which worked with the institute.Cristina Kirchner, President of Argentina, said that the scientific institute madeall Argentines proud. She also said that she had rejected the "honor" of having the cow named after her. "They came to tell me that the name is Cristina, but what woman would like to have a cow named after her? It appeared to me to be more proper to call it Rosita.”5. What is the passage mainly about?A. The importance of genetic engineering.B. Ways to improve mothers ' milk.C. A cloned cow to produce human-like milk.D. Advanced agricultural technology in Argentina.6. Which of the following can best replace “more closely resemble ” in Paragraph 4?A. have more varieties thanB. be more similar toC. have more nutrition thanD. be more different from7. What can be inferred from Cristina Kirchner 's statements?A. She was quite satisfied with the research done by the institute.B. She considered it an honor to name the special cow.C. She felt it improper to be named after the cow.D. She refused to give a name to the cow out of self-respect.CDoes Fame Drive You Crazy? Although being famous might sound like a dream come true, today 's star, feeling like zoo animals, face pressures that few of us can imagine. They are at the center of muchof the world 's attention. Paparazzi （狗仔队） camp outside their homes, cameras ready. Tabloids （小报） publish thrilling stories about their personal lives. Just imagine not being able to do anything without being photographed or interrupted for a signature!According to psychologist Christina Villareal, celebrities —famous people —worry constantly about their public appearance. Eventually, they start to lose track of who they really are, seeing themselves the way their fans imagine them, not as the people they were before everyone knew their names. “Over time, ” Villareal says,“they feel separated and alone. ”The phenomenonof tracking celebrities has been around for ages. In the 4th century B.C., painters followed Alexander the Great into battle, hopingto picture his victories for his admirers. When Charles Dickens visited America in the19th century, his sold-out readings attracted thousands of fans, leading him to complain （抱怨） about his lack of privacy. Tabloids ofthe 1920s and 1930s ran articles about film-stars in much the same way that modern tabloids and websites do.Being a public figure today, however, is a lot more difficult than itused to be. Superstars cannot moveabout without worrying about photographers with modern cameras. Whenthey say something silly or do something ridiculous, there is always the Internet to spread the news in minutes and keep their “story ” alive forever.If fame is so troublesome, why aren 't all celebrities running away from it? The answer is there are still ways to deal with it. Somestars stay calm by surrounding themselves with trusted friends and family or by escaping to remote places away from big cities. They focus not on how famous they are but on what they love to do or whatever madethem famous in the first place.Sometimes a few celebrities can get a little justice. Still, even stars who enjoy full justice often complain about how hard their lives are. They are tired of being famous already.8. It can be learned from the passage that stars today ________ .A. are often misunderstood by the publicB. can no longer have their privacy protectedC. spend too much on their public appearanceD. care little about how they have come into fame9. What is the main idea of Paragraph 3?A. Great heroes of the past were generally admired.B. The problem faced by celebrities has a long history.C. Well-known actors are usually targets of tabloids.D. Works of popular writers often have a lot of readers.10. What makes it much harder to be a celebrity today?A. Availability of modern media.B. Inadequate social recognition.C. Lack of favorable chances.D. Huge population of fans.11. What is the author 's attitude toward modern celebrity?A. Sincere.B. Sceptical.C. Disapproving.D. Sympathetic.DGuide to Stockholm UniversityLibraryOur library offers different types of studying places and provides a good studying environment.Zoneswith over a thousand places for silent reading, and sit and work with your own computer. The reading places consistmostly of tables and chairs. The ground floor is the zone where you can talk. Here you can find sofas and armchairs for group work.ComputersYou can use your own computer to connect to the wi-fi specially prepared for notebook computers ；you can also use library computers, which contain the most commonlyused applications, such as Microsoft Office. They are situated in the area known as the Experimental Field on the ground floor.Group-study placesIf you want to discuss freely without disturbing others, you can book a study room or sit at a table on the ground floor. Somestudy rooms are for 2-3 people and others can hold up to 6-8 people. All rooms are marked on the library maps.There are 40 group-study rooms that must be booked via the website. To book, youThe library is divided into different zones. The upper floor is a quiet zoneplaces where you canneed an active University account and a valid University card. You can use a room three hours per day, nine hours at most per week.Storage of Study MaterialThe library has lockers for students to store course literature. When youhave obta ined at least 40 credits（学分）,you may rent a locker and pay 400 SEK for a year 's rental period.Rules to be FollowedMobile phone conversations are not permitted anywhere in the library. Keep your phone on silent as if you were in a lecture and exit the library if you need to receive calls. Please note that food and fruit are forbidden in the library, but you are allowed to have drinks and sweets with you.12. The library 's upper floor is mainly for students to _______ .A. read in a quiet placeB. have group discussionsC. take comfortable seatsD. get their computers fixed13. Library computers on the ground floor ________ .A. help students with their field experimentsB. contain software essential for schoolworkC. are for those who want to access the wi-fiD. are mostly used for filling out application forms14. What condition should be met to book a group-study room?A. A group must consist of 8 people .B. Three-hour use per day is the minimum.C. One should first register at the university .D. Applicants must mark the room on the map.15. A student can rent a locker in the library if he ________ .A. can afford the rental feeB. attends certain coursesC. has nowhere to put his booksD. has earned the required credits 第二节（共5 小题；每小题2分，满分10分）根据短文内容，从短文后的选项中选出能填入空白处的最佳选项，选项中有两项为多余选项。