湖南省浏阳一中、攸县一中、醴陵一中2014-2015学年高二上学期12月联考试题 英语

2016年上学期浏阳一中高二年级期中测试卷英语时量：120分钟分值：150分命题人：刘庆元审题人：刘恋第I卷第一部分听力（共两节，满分30分）第一节听下面5段对话。

每段对话后有一个小题，从题中所给的Ａ、Ｂ、Ｃ三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

（）1.What’s the woman going to do this evening?A. Go to a movie.B. Go to a concert.C. Study in the library. （）2.How will the man go to the office?A. By train.B. By taxi.C. By bus.（）3.What’s the probable relationship between the two speakers?A. Classmates.B. Workmates.C. Friends.（）4.What’s the woman doing?A. Ordering some food.B. Selling some food.C. Cooking some food. （）5.Where does the conversation probably take place?A. In a store.B. In an office.C. In a bank.第二节听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的Ａ、Ｂ、Ｃ三个选项中选出最佳选项，并标在试卷的相应位置。

听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。

每段对话或独白读两遍。

听下面一段对话,回答第6至7两个小题。

（）6.Where does the man work?A. In a factoryB. In a hotelC. In a school.（）7.What does the man do?A. A manager.B. A cleaner.C. An electrician.听下面一段对话，回答第8至9两个小题。

2016届高二浏阳一中、攸县一中、醴陵一中十二月联考物理试卷时量：90分钟总分：100分命题人：聂正国审题人：陈军一、单项选择题：本题共8小题，每小题4分，共32分，每小题只有一个.选项符合题意。

1、关于科学家在电磁学中的贡献，下列说法错误的是（）A. 密立根测出了元电荷e的数值B. 法拉第提出了电场线和磁感线的概念C. 奥斯特发现了电流周围存在磁场，并且总结出了右手螺旋定则D. 安培提出了分子电流假说2、关于通电直导线在匀强磁场中所受的安培力，下列说法正确的是（）A. 安培力的方向可以不垂直于直导线B. 安培力的方向总是垂直于磁场的方向C. 将通电直导线从中点折成直角，安培力的大小一定变为原的-倍D. 安培力是洛伦兹力的宏观表现，所以安培力永不做功3、如图所示，处于真空中的匀强电场与水平方向成15°角，AB直线与强场E互相垂直。

在A 点，以大小为v°的初速度水平抛出一质量为m带电荷量为+q的小球，经时间t，小球下落一段距离过C点（图中未画出）时其速度大小仍为V o,在小球由A点运动到C点的过程中，B. 电场力做的负功C. 小球机械能增加D. C点可能位于AB直线的左方4、如图所示的实验装置中，平行板电容器两极板的正对面积为S,两极板的间距为d,电容器所带电荷量为Q电容为C,静电计指针的偏转角为0,平行板中间悬挂了一个带电小球,悬线与竖直方向的夹角为0，下列说法正确的是（）A. 若增大d,则$减小，0减小B. 若增大Q则$减小，0不变C. 将A板向上提一些时，$增大，0增大D. 在两板间插入云母片时，则 $减小，0不变5、如图所示，正方形区域ABCD内存在方向垂直纸面向里的匀强磁场，三个完全相同的带电粒子a、b、c分别以大小不同的初速度v a、v b、v c从A点沿图示方向射入该磁场区域，经磁场偏转后粒子a、b、c分别从BC边中点、CD边中点、AD边中点射出。

若t a、t b、t c分别表示粒子a、b、c 在磁场中的运动时间。

浏阳一中醴陵一中南方中学2017年下学期高二年级联考英语试题总分：150分时量:120分钟考试时间：2017年12月12日命题人：审题人:第Ⅰ卷第一部分听力（共两节,满分30分)第一节(共5小题：每小题1.5分，满分7。

5分）听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C 三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题.每段对话仅读一遍。

1。

What will the man do first?A。

Fix a bike。

B. Have a Coke。

C. Clean the windows。

2。

How is the woman learning Chinese?A。

On the radio. B。

On television。

C. On the Internet. 3。

What has made the man so upset？A。

The ugly walls. B. His kids. C。

The business。

4。

When will the man leave for Tianjin？A。

At 5:00。

B。

At 5:30。

C。

At 6：00。

5。

What are the speakers mainly talking about？A. A storm.B. A tree。

C. A house。

第二节（共15小题;每小题1.5分,满分22。

5分)听下面5段对话或独白。

每段对话或独白后有几个小题，从每题所给的A，B，C三个选项中选出最佳选项，并标在试卷的相应位置。

听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。

每段对话或独白读两遍.请听第6段材料，回答第6至7题.6。

How many people did the woman travel with?A.Two。

湖南省长沙市浏阳一中、攸县一中、醴陵一中三校联考2014-2015学年高一上学期12月月考数学试卷一、选择题（每小题5分，共50分）1．（5分）下列函数中，不满足f（2x）=2f（x）的是（）A．f（x）=x+1 B．f（x）=x﹣|x| C．f（x）=|x| D．f（x）=﹣x2．（5分）设集合A={x||x﹣2|≤2，x∈R}，B={y|y=﹣x2，﹣1≤x≤2}，则∁R（A∩B）等于（）A．R B．{x|x∈R，x≠0} C．{0} D．∅3．（5分）a=log0.70.8，b=log1.10.9，c=1.10.9的大小关系是（）A．c＞a＞b B．a＞b＞c C．b＞c＞a D．c＞b＞a4．（5分）已知m，n是两条不同的直线，α，β是两个不同的平面（）A．若m∥n且m⊂α，n⊂β，则α与β不会垂直B．若m，n是异面直线，且m⊥α，n⊥β，则α与β不会平行C．若m，n是相交直线且不垂直，m⊂α，n⊂β，则α与β不会垂直D．若m，n是异面直线，且m∥α，n∥β，则α与β不会平行5．（5分）一个棱锥的三视图如图，则该棱锥的表面积为（）A．48+12B．48+24C．72+12D．72+246．（5分）设函数表示不超过x的最大整数，则函数y=的值域是（）A．{0，1} B．{0，﹣1} C．{﹣1，1} D．{1，1}7．（5分）若函数f（x）=在（0，+∞）上是增函数，则a的范围是（）A．（1，2]B．D．（1，+∞）8．（5分）用一个平面去截正方体，则截面不可能是（）A．正三角形B．正方形C．正五边形D．正六边形9．（5分）已知异面直线a与b所成的角为50°，P为空间一点，则过点P与a、b所成的角都是300的直线有且仅有（）A．1条B．2条C．3条D．4条10．（5分）已知f（x）为偶函数，当x≥0时，f（x）=﹣（x﹣1）2+1，满足f=的实数a的个数为（）A．2B．4C．6D．8二、填空题：（本大题共5小题，每小题5分，共25分）11．（5分）计算lg52+lg8+lg5•lg20+（lg2）2=．12．（5分）定义在R上的函数f（x）=，若关于的方程f2（x）+bf （x）+c=0有5个不同的实根x1，x2，x3，x4，x5，则f（x1+x2+x3+x4+x5）=．13．（5分）已知函数的定义域是R，则实数m的取值范围是．14．（5分）如图，正方体ABCD﹣A1B1C1D1的棱长为1，E，F分别为棱DD1和AB上的点，则下列说法正确的是．（填上所有正确命题的序号）①A1C⊥平面B1CF；②在平面A1B1C1D1内总存在与平面B1EF平行的直线；③△B1EF在侧面BCC1B1上的正投影是面积为定值的三角形；④当E，F为中点时，平面B1EF截该正方体所得的截面图形是五边形；⑤当E，F为中点时，平面B1EF与棱AD交于点P，则AP=．15．（5分）已知f（x）为R上的偶函数，对任意x∈R都有f（x+6）=f（x）+f（3），当x1，x2∈，且x1≠x2时，有＞0成立，给出四个命题：①f（3）=1；②直线x=﹣6是函数y=f（x）的图象的一条对称轴；③函数y=f（x）在上为增函数；④函数y=f（x）在上有四个零点．其中所有正确命题的序号为．（请将正确的序号都填上）三、解答题：（本大题共6小题，共75分）16．（12分）设函数f（x）=lg（2x﹣3）的定义域为集合M，函数的定义域为集合N．求：（1）集合M，N；（2）集合M∪N，C R N．17．（12分）设集合A={x|x2+4x=0}，B={x|x2+2（a+1）x+a2﹣1=0}，若A∩B={0}，求a的值．18．（12分）四棱锥P﹣ABCD中，底面ABCD是边长为8的菱形，∠BAD=，若PA=PD=5，平面PAD⊥平面ABCD．（1）求四棱锥P﹣ABCD的体积；（2）求证：AD⊥PB．19．（13分）如图，在三棱柱ABC﹣A1B1C1中，四边形AA1C1C是边长为4的正方形，平面ABC⊥平面AA1C1C，AB=3，BC=5．（Ⅰ）求证：AA1⊥平面ABC；（Ⅱ）若点D是线段BC的中点，请问在线段AB1是否存在点E，使得DE∥面AA1C1C？若存在，请说明点E的位置，若不存在，请说明理由；（Ⅲ）（本小问只理科学生做）求二面角C﹣A1B1﹣C1的大小．20．（13分）对于定义域为D的函数y=f（x），若同时满足下列条件：①f（x）在D内单调递增或单调递减；②存在区间⊆D，使f（x）在上的值域为；那么把y=f（x）（x∈D）叫闭函数．（1）求闭函数y=﹣x3符合条件②的区间；（2）判断函数是否为闭函数？并说明理由；（3）若是闭函数，求实数k的取值范围．21．（13分）已知函数f（x）=9x﹣3x+1+c（其中c是常数）．（1）若当x∈时，恒有f（x）＜0成立，求实数c的取值范围；（2）若存在x0∈，使f（x0）＜0成立，求实数c的取值范围；（3）若方程f（x）=c•3x在上有唯一实数解，求实数c的取值范围．湖南省长沙市浏阳一中、攸县一中、醴陵一中三校联考2014-2015学年高一上学期12月月考数学试卷参考答案与试题解析一、选择题（每小题5分，共50分）1．（5分）下列函数中，不满足f（2x）=2f（x）的是（）A．f（x）=x+1 B．f（x）=x﹣|x| C．f（x）=|x| D．f（x）=﹣x考点：抽象函数及其应用．专题：函数的性质及应用．分析：代入选项直接判断正误即可．解答：解：对于A，f（x）=x+1，f（2x）=2x+1≠2f（x）=2x+2，A不正确；对于B，f（x）=x﹣|x|，f（2x）=2x﹣|2x|=2f（x）=2x+2|x|，B正确；对于C，f（x）=|x|，f（2x）=2|x|=2f（x）=2|x|，C正确；对于D，f（x）=﹣x，f（2x）=﹣2x=2f（x）=﹣2x，D正确；故选：A．点评：本题考查抽象函数的应用，函数的值的求法，基本知识的考查．2．（5分）设集合A={x||x﹣2|≤2，x∈R}，B={y|y=﹣x2，﹣1≤x≤2}，则∁R（A∩B）等于（）A．R B．{x|x∈R，x≠0} C．{0} D．∅考点：交、并、补集的混合运算．分析：集合A为绝对值不等式的解集，由绝对值的意义解出，集合B为二次函数的值域，求出后进行集合的运算．解答：解：A=，B=，所以A∩B={0}，∁R（A∩B）{x|x∈R，x≠0}，故选B．点评：本题考查对集合的认识以及集合的基本运算，属基本题．3．（5分）a=log0.70.8，b=log1.10.9，c=1.10.9的大小关系是（）A．c＞a＞b B．a＞b＞c C．b＞c＞a D．c＞b＞a考点：指数函数的图像与性质．专题：计算题．分析：由指数函数，对数函数的单调性，确定0＜a=log0.70.8＜1，b=log1.10.9＜0，c=1.10.9＞1．解答：解：0＜a=log0.70.8＜1，b=log1.10.9＜0，c=1.10.9＞1．故选A．点评：本题考查了指数函数与对数函数的单调性的应用，属于基础题．4．（5分）已知m，n是两条不同的直线，α，β是两个不同的平面（）A．若m∥n且m⊂α，n⊂β，则α与β不会垂直B．若m，n是异面直线，且m⊥α，n⊥β，则α与β不会平行C．若m，n是相交直线且不垂直，m⊂α，n⊂β，则α与β不会垂直D．若m，n是异面直线，且m∥α，n∥β，则α与β不会平行考点：空间中直线与平面之间的位置关系．专题：空间位置关系与距离．分析：分别利用线面平行的性质和定义，利用面面平行和垂直的判定定理进行判断．解答：解：A．若m∥n且m⊂α，n⊂β，则α与β可能平行，可能相交，当相交时，α与β可能垂直，所以A错误．B．若α∥β，则由m⊥α，n⊥β，得到m∥n，与m，n是异面直线矛盾，所以α与β不会平行，所以B正确．C．若m，n是相交直线且不垂直时，交点若在α和β的交线上时，满足m⊂α，n⊂β，此时α与β相交即可，所以α与β有可能会垂直，所以C错误．D．若α∥β时，若m，n是异面直线，存在直线m，n满足m∥α，n∥β，所以α与β可以平行，所以D错误．故选B．点评：本题主要考查空间直线和平面位置关系的判断，考查学生的空间想象能力和推理能力．5．（5分）一个棱锥的三视图如图，则该棱锥的表面积为（）A．48+12B．48+24C．72+12D．72+24考点：由三视图求面积、体积．专题：空间位置关系与距离．分析：由三棱锥的三视图知：该三棱锥的底面是腰长为6的等腰直角三角形，三棱锥的高为3，由此画出其直观图，求出各侧面的斜高，从而求出各侧面的面积，再求全面积．解答：解：由三棱锥的三视图得：该三棱锥的底面是腰长为8的等腰直角三角形，∴其底面面积S△BCD=×8×8=32；由正视图知：三棱锥的高AO=3，过O作OE⊥BC，连接AE，∵AO⊥平面BCD，∴OE为AE在平面BCD内的射影，由三垂线定理得AE⊥BC，在Rt△AOE中，AE==5，△ABC与△ABD全等，其面积S△ABC=S△ABD=×8×5=20，S△ACD=×8×3=12，∴棱锥的表面积S=32+20+20+12=72+12．故选：C．点评：本题考查由三棱锥的三视图求三棱锥的表面积，解题时要认真审题，仔细解答，注意空间想象能力的培养．6．（5分）设函数表示不超过x的最大整数，则函数y=的值域是（）A．{0，1} B．{0，﹣1} C．{﹣1，1} D．{1，1}考点：函数的值域．专题：计算题．分析：先把函数的解析式变形，根据指数函数的值域和反比例函数的单调性求出函数的值域，利用表示不超过x的最大整数可得本题的答案．解答：解：f（x）==﹣，∵2x＞0，∴1+2x＞1，0＜＜1，∴﹣＜y＜，∵表示不超过x的最大整数，∴y=的值域为{0，﹣1}，故选B．点评：本题考查函数值域的求法，本题利用指数函数的值域与复合函数的单调性规律求解，解答要细心．7．（5分）若函数f（x）=在（0，+∞）上是增函数，则a的范围是（）A．（1，2]B．D．（1，+∞）考点：函数单调性的性质．专题：计算题；函数的性质及应用；不等式的解法及应用．分析：分别考虑各段的单调性，可得﹣0，a＞1，1a﹣2≤a1﹣a，解出它们，求交集即可．解答：解：由于f（x）=x2+ax﹣2在（0，1]递增，则有﹣0，解得，a≥0，再由x＞1为增，则a＞1，再由增函数的定义，可知：1a﹣2≤a1﹣a，解得，a≤2．则有1＜a≤2．故选A．点评：本题考查分段函数的单调性和运用，考查运算能力，属于中档题和易错题．8．（5分）用一个平面去截正方体，则截面不可能是（）A．正三角形B．正方形C．正五边形D．正六边形考点：平面的基本性质及推论．专题：空间位置关系与距离．分析：画出用一个平面去截正方体得到的几何体的图形，即可判断选项．解答：解：画出截面图形如图显然A正三角形，B正方形：D正六边形可以画出五边形但不是正五边形；故选：C．点评：本题是基础题，考查学生作图能力，判断能力，以及逻辑思维能力，明确几何图形的特征，是解好本题的关键．9．（5分）已知异面直线a与b所成的角为50°，P为空间一点，则过点P与a、b所成的角都是300的直线有且仅有（）A．1条B．2条C．3条D．4条考点：异面直线及其所成的角．专题：压轴题；探究型；转化思想；运动思想．分析：根据异面直线a与b所成的角为50°，P为空间一点，过P分别作直线a，b的平行线，得到∠APB=50°，过P点作直线c，d分别是角∠APB的平分线和面APB的垂线，这时c与a，b所成角为25°，d与a，b所成角为90°，然后直线从c转到直线d的过程中一定经过30°的角，可求出直线的条数．解答：解：把异面直线a，b平移到相交，使交点为P，此时∠APB=50°，过P点作直线c平分∠APB，这时c与a，b所成角为25°，过P点作直线d垂直a和b，这时d与a，b所成角为90°，直线从c向两边转到d时与a，b所成角单调递增，必有经过30°，因为两边，所以有2条．故选B．点评：此题是个基础题．考查异面直线所成的角，以及解决异面直线所成的角的方法（平移法）的应用，体现了转化的思想和运动变化的思想方法．10．（5分）已知f（x）为偶函数，当x≥0时，f（x）=﹣（x﹣1）2+1，满足f=的实数a的个数为（）A．2B．4C．6D．8考点：函数奇偶性的性质．专题：计算题．分析：令f（a）=x，则f=转化为f（x）=．先解f（x）=在x≥0时的解，再利用偶函数的性质，求出f（x）=在x＜0时的解，最后解方程f（a）=x即可．解答：解：令f（a）=x，则f=变形为f（x）=；当x≥0时，f（x）=﹣（x﹣1）2+1=，解得x1=1+，x2=1﹣；∵f（x）为偶函数，∴当x＜0时，f（x）=的解为x3=﹣1﹣，x4=﹣1+；综上所述，f（a）=1+，1﹣，﹣1﹣，﹣1+；当a≥0时，f（a）=﹣（a﹣1）2+1=1+，方程无解；f（a）=﹣（a﹣1）2+1=1﹣，方程有2解；f（a）=﹣（a﹣1）2+1=﹣1﹣，方程有1解；f（a）=﹣（a﹣1）2+1=﹣1+，方程有1解；故当a≥0时，方程f（a）=x有4解，由偶函数的性质，易得当a＜0时，方程f（a）=x也有4解，综上所述，满足f=的实数a的个数为8，故选D．点评：本题综合考查了函数的奇偶性和方程的解的个数问题，同时运用了函数与方程思想、转化思想和分类讨论等数学思想方法，对学生综合运用知识解决问题的能力要求较高，是高考的热点问题．二、填空题：（本大题共5小题，每小题5分，共25分）11．（5分）计算lg52+lg8+lg5•lg20+（lg2）2=3．考点：对数的运算性质．专题：计算题．分析：利用对数的运算性质lgm n=nlgm；lgmn=lgm+lgn；计算可得答案．解答：解：原式=2lg5+×3lg2+lg5×（1+lg2）+（lg2）2=2（lg5+lg2）+lg5+lg2×lg5+（lg2）2=2+1﹣lg2+lg2×（1﹣lg2）+（lg2）2=3．故答案是3．点评：本题考查了对数的运算性质，计算要细心．12．（5分）定义在R上的函数f（x）=，若关于的方程f2（x）+bf （x）+c=0有5个不同的实根x1，x2，x3，x4，x5，则f（x1+x2+x3+x4+x5）=lg16．考点：根的存在性及根的个数判断；函数的值．专题：函数的性质及应用．分析：当x=4时，解得x1=4，c=﹣b﹣1；当x＞4时，解得lg（x﹣4）=1，x2=14或lg（x ﹣4）=b，x3=4+10b；当x＜4时，解得lg（4﹣x）=1，x4=﹣6或lg（2﹣x）=b，x5=4﹣10b．从而f（x1+x2+x3+x4+x5）=f（4+14+4+10b﹣6+4﹣10b）=f=lg|20﹣4|=lg16．解答：解：当x=4时，f（x）=1，则由f2（x）+bf（x）+c=0得1+b+c=0．∴x1=4，c=﹣b﹣1．当x＞4时，f（x）=lg（x﹣4），由f2（x）+bf（x）+c=0，得2+blg（x﹣4）﹣b﹣1=0，解得lg（x﹣4）=1，x2=14或lg（x﹣4）=b，x3=4+10b．当x＜4时，f（x）=lg（4﹣x），由f2（x）+bf（x）+c=0，得2+blg（4﹣x）﹣b﹣1=0），解得lg（4﹣x）=1，x4=﹣6或lg（2﹣x）=b，x5=4﹣10b．∴f（x1+x2+x3+x4+x5）=f（4+14+4+10b﹣6+4﹣10b）=f=lg|20﹣4|=lg16．故答案是：lg16．点评：本题考查函数值的求法，是中档题，解题时要认真审题，注意对数性质和分类讨论思想的合理运用．13．（5分）已知函数的定义域是R，则实数m的取值范围是考点：空间中直线与直线之间的位置关系；棱柱的结构特征．专题：空间位置关系与距离．分析：由正方体的结构特征，对所给的几个命题用线面，面面之间的位置关系直接判断正误即可得到答案．解答：解：对于①，A1C⊥平面B1EF，不一定成立，因为A1C⊥平面AC1D，而两个平面面B1EF与面AC1D不一定平行．故①错误；对于②，在平面A1B1C1D1内总存在与平面B1EF平行的直线，此两平面相交，一个面内平行于两个平面的交线一定平行于另一个平面，故②正确；对于③，△B1EF在侧面BCC1B1上的正投影是面积为定值的三角形，此是一个正确的结论，因为其投影三角形的一边是棱BB1，而E点在面上的投影到此棱BB1的距离是定值，故③正确；对于④当E，F为中点时，平面B1EF截该正方体所得的截面图形是五边形B1QEPF，故④正确；对于⑤由面面平行的性质定理可得EQ∥B1F，故D1Q=，B1Q∥PF，故AP=，故⑤正确．故正确的命题有：②③④⑤．故答案为：②③④⑤．点评：本题考点是棱柱的结构特征，考查对正方体的几何特征的了解，以及线面垂直，线面平行等位置关系的判定，涉及到的知识点较多，综合性强．15．（5分）已知f（x）为R上的偶函数，对任意x∈R都有f（x+6）=f（x）+f（3），当x1，x2∈，且x1≠x2时，有＞0成立，给出四个命题：①f（3）=1；②直线x=﹣6是函数y=f（x）的图象的一条对称轴；③函数y=f（x）在上为增函数；④函数y=f（x）在上有四个零点．其中所有正确命题的序号为②④．（请将正确的序号都填上）考点：抽象函数及其应用．专题：阅读型；函数的性质及应用．分析：①令x=﹣3，由偶函数的定义，可得f（3）=0，即可判断；②由于函数y=f（x）是以6为周期的偶函数，可得f（﹣6+x）=f（﹣6﹣x），即可判断；③由条件可得y=f（x）在区间上为增函数，再由偶函数和周期性，即可判断；④先判断方程f（x）=0在上有2个实根（﹣3和3），又函数y=f（x）是以6为周期的函数，即可判断．解答：解：对于①：∵y=f（x）为R上的偶函数，且对任意x∈R，均有f（x+6）=f（x）+f（3），∴令x=﹣3得：f（6﹣3）=f（﹣3）+f（3）=2f（3），∴f（3）=0，故①错；对于②：∵函数y=f（x）是以6为周期的偶函数，∴f（﹣6+x）=f（x），f（﹣6﹣x）=f（x），∴f（﹣6+x）=f（﹣6﹣x），∴y=f（x）图象关于x=﹣6对称，即②正确；对于③：∵当x1，x2∈且x1≠x2时，有＞0成立，∴y=f（x）在区间上为增函数，又函数y=f（x）是偶函数，∴y=f（x）在区间上为减函数，又函数y=f（x）是以6为周期的函数，∴y=f（x）在区间上为减函数，故③错误．对于④：∵y=f（x）在区间上为减函数，在区间上为增函数，且f（3）=f（﹣3）=0，∴方程f（x）=0在上有2个实根（﹣3和3），又函数y=f（x）是以6为周期的函数，∴方程f（x）=0在区间上有一个实根（为9），∴方程f（x）=0在上有4个实根．故④正确．故答案为：②④点评：本题考查抽象函数及其应用，命题真假的判断，着重考查函数的奇偶性、对称性、周期性、单调性，考查函数的零点，属于中档题．三、解答题：（本大题共6小题，共75分）16．（12分）设函数f（x）=lg（2x﹣3）的定义域为集合M，函数的定义域为集合N．求：（1）集合M，N；（2）集合M∪N，C R N．考点：补集及其运算；并集及其运算．专题：计算题．分析：（1）对数的真数大于0求出集合M；开偶次方的被开方数非负且分母不等于0，求出集合N；（2）直接利用集合的运算求出集合M∪N，C R N．解答：解：（1）由题意2x﹣3＞0 所以M={x|x＞}；因为所以N={x|x＜1或x≥3}（2）由（1）可知∁R N={x|1≤x＜3}．点评：本题考查对数函数的定义域，交集、并集、补集及其运算；是基础题．17．（12分）设集合A={x|x2+4x=0}，B={x|x2+2（a+1）x+a2﹣1=0}，若A∩B={0}，求a的值．考点：交集及其运算．专题：集合．分析：根据A与B的交集得到元素0属于A属于B，将x=0代入集合B中的方程，即可求出a的值．解答：解：∵A∩B={0}，∴0∈A，0∈B，将x=0代入B中的方程得：a2﹣1=0，解得：a=1或a=﹣1，当a=1时，A={0，﹣4}，B={0，﹣4}，不合题意，舍去；当a=﹣1时，A={0，﹣4}，B={0}，符合题意，则a的值为﹣1．点评：此题考查了交集及其运算，熟练掌握交集的定义是解本题的关键．18．（12分）四棱锥P﹣ABCD中，底面ABCD是边长为8的菱形，∠BAD=，若PA=PD=5，平面PAD⊥平面ABCD．（1）求四棱锥P﹣ABCD的体积；（2）求证：AD⊥PB．考点：棱柱、棱锥、棱台的体积．专题：空间位置关系与距离．分析：（1）过P作PM⊥AD于M．利用面PAD⊥面ABCD可得PM⊥面ABCD，菱形ABCD的面积S=，再利用V P﹣ABCD=即可得出．（2）连接BM．利用BD=BA=8，AM=DM，．可得AD⊥BM，又AD⊥PM，可得AD⊥平面PMB，即可得出．解答：（1）解：过P作PM⊥AD于M．∵面PAD⊥面ABCD，面PAD∩面ABCD=AD，PM⊂面PAD．∴PM⊥面ABCD，又PA=PD=5，AD=8．∴M为AD的中点且PM==3．∵，AD=8，∴菱形ABCD的面积S==．∴V P﹣ABCD===．（2）证明：连接BM．∵BD=BA=8，AM=DM，．∴AD⊥BM，又AD⊥PM，且BM∩PM=M．∴AD⊥平面PMB．∴AD⊥PB．点评：本题考查了线面面面垂直的判定与性质定理、棱锥的体积计算公式、菱形的性质，考查了推理能力与计算能力，属于中档题．19．（13分）如图，在三棱柱ABC﹣A1B1C1中，四边形AA1C1C是边长为4的正方形，平面ABC⊥平面AA1C1C，AB=3，BC=5．（Ⅰ）求证：AA1⊥平面ABC；（Ⅱ）若点D是线段BC的中点，请问在线段AB1是否存在点E，使得DE∥面AA1C1C？若存在，请说明点E的位置，若不存在，请说明理由；（Ⅲ）（本小问只理科学生做）求二面角C﹣A1B1﹣C1的大小．考点：用空间向量求平面间的夹角；直线与平面平行的判定；直线与平面垂直的判定．专题：空间位置关系与距离；空间角．分析：（Ⅰ）因为四边形AA1C1C为正方形，所以AA1⊥AC．因为平面ABC⊥平面AA1C1C，利用面面垂直的性质；（Ⅱ）当点E是线段AB1的中点时，有DE∥平面AA1C1C．证明时连结A1B交AB1于点E，连结DE，利用线面平行的判定定理．（Ⅲ）推理∠C1A1C是二面角C﹣A1B1﹣C1的平面角．解答：（本小题满分12分）解：（Ⅰ）因为四边形AA1C1C为正方形，所以AA1⊥AC．因为平面ABC⊥平面AA1C1C，且平面ABC∩平面AA1C1C=AC，所以AA1⊥平面ABC．…（4分）（文6分）（Ⅱ）当点E是线段AB1的中点时，有DE∥平面AA1C1C．证明：连结A1B交AB1于点E，连结DE．因为点E是A1B中点，点D是线段BC的中点，所以DE∥A1C．又因为DE⊄平面AA1C1C，A1C⊂平面AA1C1C，所以DE∥平面AA1C1C．…（8分）（文12分）（Ⅲ）因为AA1⊥平面ABC，所以AA1⊥AB．又因为AC⊥AB，所以AB⊥平面AA1C1C，所以A1B1⊥平面AA1C1C，所以A1B1⊥A1C1，A1B1⊥A1C，所以∠C1A1C是二面角C﹣A1B1﹣C1的平面角．易得tan∠C1A1C==1，所以二面角C﹣A1B1﹣C1的平面角为45°．…（12分）点评：本题考查面面垂直，考查面面角，解题的关键是掌握面面垂直的判定，考查二面角的定义，解题时要认真审题，注意空间中平行与垂直的合理运用．20．（13分）对于定义域为D的函数y=f（x），若同时满足下列条件：①f（x）在D内单调递增或单调递减；②存在区间⊆D，使f（x）在上的值域为；那么把y=f（x）（x∈D）叫闭函数．（1）求闭函数y=﹣x3符合条件②的区间；（2）判断函数是否为闭函数？并说明理由；（3）若是闭函数，求实数k的取值范围．考点：函数与方程的综合运用．专题：计算题；压轴题；新定义．分析：（1）根据单调性依据闭区间的定义等价转化为方程，直接求解．（2）判断其在（0，+∞）是否有单调性，再据闭函数的定义判断；（3）根据闭函数的定义一定存在区间，由定义直接转化求解即可．解答：解：（1）由题意，y=﹣x3在上递减，则解得（4分）所以，所求的区间为；（5分）（2）取x1=1，x2=10，则，即f（x）不是（0，+∞）上的减函数．取，，即f（x）不是（0，+∞）上的增函数所以，函数在定义域内不单调递增或单调递减，从而该函数不是闭函数；（9分）（3）若是闭函数，则存在区间，在区间上，函数f（x）的值域为，即，∴a，b为方程的两个实数根，即方程x2﹣（2k+1）x+k2﹣2=0（x≥﹣2，x≥k）有两个不等的实根（11分）当k≤﹣2时，有，解得，（13分）当k＞﹣2时，有，无解，（15分）综上所述，．点评：考查函数的单调性及新定义型函数的理解，以及问题的等价转化能力．21．（13分）已知函数f（x）=9x﹣3x+1+c（其中c是常数）．（1）若当x∈时，恒有f（x）＜0成立，求实数c的取值范围；（2）若存在x0∈，使f（x0）＜0成立，求实数c的取值范围；（3）若方程f（x）=c•3x在上有唯一实数解，求实数c的取值范围．考点：指数函数综合题．专题：计算题；函数的性质及应用．分析：（1）换元法化为当t∈时，g（t）=t2﹣3•t+c＜0恒成立，再化恒成立问题为最值问题；（2）若存在x0∈，使f（x0）＜0，则存在t∈，使g（t）=t2﹣3•t+c＜0．从而化为最值问题；（3）若方程f（x）=c•3x在上有唯一实数解，则方程t2﹣（3+c）t+c=0在上有唯一实数解．从而由单调性及零点判定定理判断．解答：解：（1）f（x）=9x﹣3x+1+c=（3x）2﹣3•3x+c，令3x=t，当x∈时，t∈．问题转化为当t∈时，g（t）=t2﹣3•t+c＜0恒成立．于是，只需g（t）在上的最大值g（3）＜0，即9﹣9+c＜0，解得c＜0．∴实数c的取值范围是（﹣∞，0）；（2）若存在x0∈，使f（x0）＜0，则存在t∈，使g（t）=t2﹣3•t+c＜0．于是，只需g（t）在上的最小值g（）=（）2﹣3•+c＜0，解得c＜；∴实数c的取值范围是（﹣∞，）；（3）若方程f（x）=c•3x在上有唯一实数解，则方程t2﹣（3+c）t+c=0在上有唯一实数解．因△=（3+c）2﹣4c＞0，故t2﹣（3+c）t+c=0在上不可能有两个相等的实数解．令h（t）=t2﹣（3+c）t+c．因h（1）=﹣2＜0，故只需h（3）=﹣2c≥0，解得c≤0．∴实数c的取值范围是（﹣∞，0]．点评：本题考查了恒成立问题及存在性问题，属于中档题．。

湖南省浏阳一中、攸县一中、醴陵一中2014-2015学年高二上学期12月联考试题 数学（理）一、选择题（本大题共10小题，每小题5分，共50分，在每小题给出的四个选项中，只有一项是符合题目要求的。

）1．若0a b >>，0c d >>，则一定有( )A ．a b d c > B ． a bd c< C ． b a d c < D ． b a d c > 2．已知向量)5,3,2(-=a 与向量),,4(y x b -=平行,则,x y 的值分别是（ ） A ．–6和10B ．6和10C ．–6和-10D ． 6和-103．设n S 是等差数列{}n a 的前n 项和，已知23a =，611a =，则7S 等于（ ）A ．13B ．35C ．49D ．634．已知命题,:R x p ∈∃使;25sin =x 命题R x q ∈∀:，都有012>++x x 。

给出下列结论：①命题""q p ∧是真命题； ②命题""q p ∨⌝是真命题； ③命题""q p ⌝∨⌝是假命题； ④命题""q p ⌝∧是假命题。

其中正确的是（ ） A ．②③ B ．②④ C ．③④ D ．①②③5．已知命题265:x x p ≥-，命题2|1:|>+x q ，则p 是q 的（ ） A ．充分不必要条件 B ．必要不充分条件 C ．充要条件 D ．既不充分也不必要条件6．要制作一个容积为4 m 3，高为1 m 的无盖长方体容器．已知该容器的底面造价是每平方米20元，侧面造价是每平方米10元，则该容器的最低总造价是（ ） A ．160元B ．80元C ．240元D ．120元7. 抛物线24y x =的焦点到双曲线2213yx -=的渐近线的距离是（ ）A ．12B C ．1 D8．已知实数x ,y 满足约束条件⎪⎩⎪⎨⎧≤-≤≥021y x y x ’则y x z -=2的取值范围是（ ）A ．[0,1]B ．[1,2]C ．[1,3]D ．[0,2]9．已知数列{}n a 中,11,a =前n 项和为n S ，且点*1(,)()n n P a a n N +∈在直线10x y -+=上，则1231111nS S S S ++++= （ ） A.21n n + B. 2(1)n n + C. (1)2n n + D.2(1)n n + 10．若直线4=+ny mx 和⊙O ∶422=+y x 没有交点，则过),(n m 的直线与椭圆14922=+y x 的交点个数（ ） A ．至多一个 B ．2个 C ．1个 D ．0个二、填空题（本大题共5小题，每小题5分，共25分，将正确答案填在相应位置上。

2016届高二浏阳一中、攸县一中、醴陵一中十二月联考 语文试卷 时量：150分钟 总分：150分 命题人：张敏敏 审题人：贺洪爱 语言文字运用（12分，每小题3分。

） 阅读下面的文字，完成1—4题。

莎士比亚的剧作经几百年时光的磨洗，仍以旺盛的生命力，活跃在各国的舞台上， 它们历久弥新，甲了莎翁作品的现实意义和不朽生命力。

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因此，他的历史剧主人会时而现身宫廷，时而出没沙场，情节起伏跌宕；他的悲剧和喜剧都不是单纯的，而是错综的混合体。

恩格斯称赞莎士比亚戏剧是情节生动性、丰富性与思想深度、历史内容完美的融合。

他常布置几条线索平行而后交织，于错综复杂中展现广阔多彩的画面，总是 乙增加悬念，使读者、观众的紧张感不断增强。

莎翁的戏剧语言，俏皮、华丽、精萃而丰富，从典雅的书面语言到粗俗的市井俚(lǐ) 语，从民谣体到古诗体，无所不有。

剧本中不少台词，成了成语典故或人们经常引用的格 言。

比如，“?丙是智慧的灵魂，冗( rǒng)长是肤浅的藻饰”，“心里的瑕疵( cī)是真的污诟”。

莎翁创作的三十七部戏剧，塑造了几百个不同的人物形象，每个人物都有一套 符(fù)合各自性格特点的语言，而且随着场面的更叠、际遇的变化，人物语言也有所发展变化。

比如，哈姆莱特的语言，有时温文尔雅，有时明白晓畅，有时妙语连珠，有时又语无伦次，淋漓尽致地表达出一位单枪匹马企图重整乾坤的年轻的理想主义者的迷惘、痛苦和悲怆。

l. 文中加点字的注音和字形都不正确的一项是（ ） A俚(lǐ)语? ? 精萃 ? B冗( rǒng)长藻饰 C瑕疵( cī)? ?污诟? ?D符(fù)合 更叠 2．在文中甲、乙、丙处依次填入词语，恰当的一项是（ ） A印证逐步简洁? ?B印证逐步简捷 C见证逐渐简捷? ?D见证逐渐简洁 3. 文中划线的成语，使用不正确的一项是（ ） A历久弥新B错综复杂C温文尔雅D单枪匹马 4. 填入文中横线处的语句与上下文衔接最恰当的一项是（ ） A莎翁写戏讲求反映“自然”或真实，关注当时有关民族和个人的重大问题，较多地考 虑观众的趣味和需求，不太介意悲喜雅俗之类的划分。

理科数学试卷一、选择题〔本大题共10小题，每一小题5分，共50分，在每一小题给出的四个选项中，只有一项为哪一项符合题目要求的。

〕1．假设0a b >>，0c d >>，如此一定有( )A ．a b d c > B ．a b d c< C ．b a d c < D ．b ad c > 2．向量)5,3,2(-=a 与向量),,4(y x b -=平行,如此,x y 的值分别是〔 〕 A ．–6和10B ．6和10C ．–6和-10D ． 6和-103．设n S 是等差数列{}n a 的前n 项和，23a =，611a =，如此7S 等于〔 〕A ．13B ．35C ．49D ．63 4．命题,:R x p ∈∃使;25sin =x 命题R x q ∈∀:，都有012>++x x 。

给出如下结论：①命题""q p ∧是真命题； ②命题""q p ∨⌝是真命题； ③命题""q p ⌝∨⌝是假命题； ④命题""q p ⌝∧是假命题。

其中正确的答案是〔 〕 A ．②③ B ．②④ C ．③④ D ．①②③5．命题265:x x p ≥-，命题2|1:|>+x q ，如此p 是q 的〔 〕 A ．充分不必要条件 B ．必要不充分条件 C ．充要条件 D ．既不充分也不必要条件6．要制作一个容积为4 m 3，高为1 m 的无盖长方体容器．该容器的底面造价是每平方米20元，侧面造价是每平方米10元，如此该容器的最低总造价是〔〕 A ．160元 B ．80元 C ．240元 D ．120元7. 抛物线24y x =的焦点到双曲线2213yx -=的渐近线的距离是〔 〕 A ．12B．2C ．1D 8．实数x ,y 满足约束条件⎪⎩⎪⎨⎧≤-≤≥021y x y x ’如此y x z -=2的取值范围是〔 〕A ．[0,1]B ．[1,2]C ．[1,3]D ．[0,2]9．数列{}n a 中,11,a =前n 项和为n S ，且点*1(,)()n n P a a n N +∈在直线10x y -+=上，如此1231111nS S S S ++++= 〔 〕 A.21n n + B.2(1)n n + C.(1)2n n + D.2(1)n n +10．假设直线4=+ny mx 和⊙O ∶422=+y x 没有交点，如此过),(n m 的直线与椭圆14922=+y x 的交点个数〔 〕 A ．至多一个 B ．2个 C ．1个 D ．0个二、填空题〔本大题共5小题，每一小题5分，共25分，将正确答案填在相应位置上。

Conversation 11.What is the relationship between the speakers?A. Mother and son.B. Wife and husband.C. Customer and salesman.2. Who is in the garden?A. The woman.B. The man.C. The man’sfather.Conversation 23.Why does the boy want to have a look at the girl’s notebook?A. He didn’t have the math class.B. He didn’t go to school.C. He missed some notes.4.What are the speakers going to do next?A. Go to see Jimmy.B. Do homework.C. Buy some fruits.Conversation 35.What did the man do last weekend?A. He went back to his university.B. He visited the woman.C. He went on with his work.6. What do we know about the woman?A. She doesn’t like her university.B. She is very busy.C. Shealways meets her teachers.Conversation 47.What does the man plan to do at first?A. Find the sales receipt.B. Return the shoes.C. Change theshoes.8. When did the man buy the shoes ?A. One week ago.B. One month ago.C. Yesterday.9. Why does the man want to change the shoes?A. They are a bit tight.B. They are too big.C. They arebroken.Conversation 510. What kind of food does the man want?A. Beef.B. Porridge.C. Noodles.11.What’s wrong with the man?A. He is hungry.B. He has a headache.C. His stomach doesn’t feel well.12. Where does the coversation mostly probably take place?A. In a restaurant.B. In a bar.C. On a train. Conversation 613. What did the man do first after he saw the fire?A. He went to the kitchen.B. He ran into the house on fire.C. He calle the firemen.14. Why was the man trapped in the fire?A. The fire became too big.B. He got lost.C. He was injured.15. How long did the man spend in hospital?A. Three days.B. Four weeks.C. Six months. Section B (7.5 marks)Directions: In this section, you will hear a short passage. Listen carefully and then fill in the numbered blanks with the information you have heard. Fill in each blank with NO MORE THAN THREE WORDS.You will hear the short passage TWICE.Part II Language Knowledge (45 marks)Section A (15 marks)Directions: Beneath each of the following sentences there are four choices marked A, B, C and D. Choose the one answer that best completes the sentence. 21. —They are living with their parents at present because their own house ________.A.is being builtB. has been bulitC. is builtD. has built22. It is ten years since we _______ each other last time.A. seeB. have seenC. sawD. had seen23. She pretended _____ me when I passed by.A. not to seeB. not seeingC. to not seeD. having not seen24. ______ is no doubt that the Rockets will defeat the Washington Wizards in the next game.A. ItB. AsC. ThatD. There25. I’m afraid Mr. Harding ______ see you now. He is very busy.A.can’tB.must n’tC.shouldn’tD. needn’t26.My suggestion is that he________ an operation at once.A. hasB. must haveC. should haveD. had27. ______I really don’t like art, I find his work impressive.A. IfB. WhileC. BecauseD. As28. ---- Will you go to Tina’s birthday party?---- No. ______ invited, I can’t go. I’ll be very busy then.A. Even ifB. As ifC. UnlessD. In case29. He wrote a lot of novels, none of ______ was published, though.A. themB. whatC. whereD. which30. Jane returned from work, only______ that his house had been broken into.A. foundB. to findC. findingD. to have found31. ____________ by many tall trees, the lake looks more beautiful.A. SurroundingB. SurroundedC. Being surroundedD. To surround32. It is difficult to imagine his ______the decision without any consideration.A. acceptB. acceptingC. to acceptD. accepted33.With a lot of difficulties ___ ,they went to the seashore and had a good rest.A. s ettledB.settlingC.to settleD.being settled34. To master a foreign language, ______.A. a lot of practice is neededB. it needs a lot of practiceC. practice is in need ofD. one needs a lot of practice35. ____ the floor, I found his pen lying on the ground.A. While sweepingB. While sweptC. If sweepingD. If sweptSection B (18 marks)Directions: For each blank in the following passage there are four words or phrases marked A, B, C and D. Fill in each blank with the word or phrase that best fits the context.Once upon a time, there was a bird in a cage who sang for her merchant(商人) owner. He was very happy with her 36 . Before he left for a business trip one day, he asked if she had a wish: “I will go through the forest where you were born. What 37 should I take for the birds there?” The bird said, “Tell them I am full of sorrow in a cage singing my captive (被监禁的）song and I’m cut off from all of life’s sweet things. I hope it won’t be long before I can fly 38 _ through the trees with them again.”When the merchant reached the forest, he stopped and said, “Dear birds!39 to you all from my pretty bird locked in her cage. She asks for a40 from you. She wants to join you, but I would 41 her beautifulsong and cannot let her go.”Suddenly one bird screamed and 42 to the ground.Nothing else could be more shocking. The merchant thought it was dead. He continued on to the city and 43 his goods. On returning home, the merchant said, “I do not know what happened. I told them your message. Then, one of them fell down dead.”Suddenly the bird 44 a terrible scream and fell on her head to the bottom of the cage. The merchant was terrified and wept in 45 . He opened the cage door and took her into his hands carefully. The bird suddenly flew up, then out of the window and 46 on the nearest tree. She turned to him and said gratefully,”I really appreciate your delivering my message. That bird instructed me how to 47 my freedom. All I had to do was to pretend to be dead.”36. A.cry B. poem C. speech D. song37. A. report B. conversation C. message D. invitation38. A. carefully B. proudly C. luckily D. freely39. A.Thanks B. Reward s C. Greetings D. Congratulations40. A. reply B. story C. joke D. letter41. A. avoid B. miss C. ignore D. quit42. A. flew B. ran C. fell D. jumped43. A. afforded B. served C. offered D. traded44. A. let out B. worked out C. thought out D. found out45. A. surprise B. interest C. hopelessness D. curiosity46. A. hid B．started C．hit D. landed47. A. fight B. treat C. win D. strikeSection CDirections: Complete the following passage by filling in each blank with one word that best fits the context.Considered 48._______ a virtue, honesty is admired in every country and every culture.49._______, there are still some dishonest people living in this world. Some businessmen are not always honest in their dealings. Some students 50._______ caught cheating in a test. Some newspapers carry some untrue news just in order to attract 51._______ readers.Actually, being dishonest is generally regarded as a bad behavior, which is looked down upon by the society. But being 52._______honest person, we can benefit a lot. 53. _______, we can have s peaceful life, for we will not feel ashamed of telling lies. Second, we can be trusted by other people,54._______ will do good to our lives.I do believe honesty is a virtue which is the very key 55._______ the door of success.Part III Reading Comprehension (30 marks)Directions: Read the following three passages. Each passage is followed by several questions or unfinished statements. For each of them there are four choices marked A, B,C and D. Choose the one that fits best according to the information given in the passage.ADonald was not very good at maths. He could not understand the teacher’s explanations. Eve n when the teacher explained something a second time, Donald still could not understand it. “Never mind,” Donald told himself. “I’m quite good at other subjects. I’ll cheat in the maths exam, then I won’t be in trouble.”“I wi ll sit next to the boy who’s best at maths,” he thought, “and copy down his answers.” The day of the exam came, and Donald sat next to Brian Smith, who always was at the top of the class in maths. Don ald carefully copied Brian’s answers onto his own exam paper. At the end of the exam, the teacher collected the papers and graded them. Then she said, “Well, boys and girls. I’ve decided to give a prize to the student who got the highest grade. However, i t’s difficult for me to decide who to give the prize to, because two students, Doanld and Brian, got the same grade.”“Let them share it,” one of the other students said.“I have thought about that,” the teacher said, “but I have decided to give the prize to Brian.” Donald was angry when he heard this. He stood up and said. “That is not fair. I got the same grade as Brian.” “That is ture,” the teacher said. “However, Brian’s answer to Question 18 was ‘I don’t know,’ while your s was ‘Neither do I.’”56. Donald decided to cheat in the maths exam because_________.A. he was always at the top of the class in mathsB. he understood the questionsC. he was not very good at mathsD. the maths teacher did not explain the questions carefully57. Donald got a high grade in maths because __________A. maths was his best subjectB. the questions were easyC. he copied from another boyD. the teacher explained the questions carefully58. Donald got the same grade as Brian because _________.A. both boys were good at mathsB. Donald cheatedC. Brian copied Donald’s answersD. the question were very easy59. The teacher knew it was Donald who cheated because _______.A. his answers were the same as Brian’sB. he wrote “I don’t know” as a n answerC. he got the same wrong answers as BrianD. he wrote the words “Neither do I”60. Why was he angry when Donald heard that the teacher would give a prize to Brian?A. Because he got the same grade as Brian.B. Because Brian copied him.C. Because the teacher didn’t know Donald’s answers.D. Because he cheated in the maths exam.BI was in a strange city I didn’t know at all, and what’s more, I could not speak a word of the language. On my second day I got on the first bus that passed, rode on it for several stops，then got off and walked on. The first two hours passed pleasantly enough, then I decided to turn back to my hotel for lunch. After walking about for some time，I decided I had better ask the way. The trouble was that the only word I knew of the language was the name of the street in which I lived，and even that I pronounced badly. I stopped to ask a newspaper-seller. He handed me a paper. I shook my head and repeated the name of the street and he put the paper into my hands. I had to give him some money and went on my way. The next personI asked was a policeman. He listened to me carefully, nodded and gently took me by the arm. There was a strange look in his eyes as he pointed left and right and left again. I nodded politely and began walking in the direction he pointed.About an hour passed and I noticed that the houses were getting fewer and fewer and green fields were appearing on either side of me. I had come all the way into the countryside. The only thing left for me to do was find the nearest railway station.61.The writer preferred to walk back to his hotel because_______.A. he had no money to buy a ticketB. he wanted to lose himself in the cityC. he tried to know the city in this wayD.it was late and there were no buses passing by62. The newspaper-seller______.A. didn’t know where the hotel wasB. didn’t understand what the writer saidC. could understand what the writer saidD. didn’t want to take the money from the writer63. From the story we know that the policeman______.A. was kind but didn’t understand the writerB. told the writer where to take a trainC. knew what the writer really meantD.was cold-hearted and didn’t help the writer64. What can we learn from the last paragraph?A. The writer got close to the hotel where he stayed.B. The writer got to the hotel with the policeman’s help.C. The writer found he was much farther away from the hotel.D.The writer found the hotel in the direction the policeman pointed.65.In your opinion, what was the writer’s r eal trouble?A. He didn’t know the city at all.B. He couldn’t speak the language.C. He went too far in the wrong bus.D.He followed the policeman’s direction.CWhat is your favorite color? Do you like yellow, orange, red? If you do, you must be an optimist, a leader, an active person who enjoys life, people and excitement. Do you prefer grays and blues? Then you are probably quiet, shy and you would rather follow than lead. If you love green, you are strong-minded and determined. You wish to succeed and want other people to see you are successful. At least this is what psychologists tell us, and they should know, because they have been seriously studying the meaning of color preference, and the effect that colors have on human beings. They tell us that we don't choose our favorite color as we grow up. If you happen to love brown, you did so as soon as you opened your eyes, or at least as soon as you could see clearly.A yellow room makes us feel more cheerful and more comfortable than a dark green one, and a red dress rings warmth and cheer to the saddest winter day. On the other hand, black is depressing. Light and bright colors make people not only happier but more active. It is a fact that factory workers work better, harder, and have fewer accidents when their machines are painted orange rather than black or dark gray. Remember, then, that if you feel low, you can always brighten your day or your life with a new shirt or a few colorful things. Remember also that you will know your friends and your enemies better when you find out what colors they like and dislike. And don't forget that anyone can guess a lot about your character when you choosea piece of handkerchief.66. According to this passage, _________.A. one can choose his color preferenceB. one is born with his color preferenceC. one's color preference is changeableD. one has to choose his favorite color as soon as he can see clearly67. We would pay attention to colors because _______.A. colors do have effect on our moodsB. colors may have effect on our work and studyC. light and bright colors make people happyD. you can know your friends better by the colors they like or dislike68. If someone choose a red handkerchief, he will probably do the following things EXCEPT _______.A. Becoming a leader.B. Joining the Student Union.C. Always complain and blame others.D. Getting along well with others.69. "I am feeling black" means ______.A. I am feeling wellB. I am very happyC. I am excitedD. I am depressed70. The main idea of this passage is ________.A. one's color preference shows one's characterB. you can brighten your life with wonderful colorsC. psychologists have been studying the meaning of color preferenceD. one's color preference has something to do with his character and colors have effects on human beingsPart IV Writing (45 marks)Section A (10 marks)Directions: Read the following passage. Fill in the numbered blanks by using the information from the passage.Write NO MORE THAN THREE WORDS for each answer.Coffee has become a popular drink in our culture. Most people have a coffee maker at home for guests who come to visit. It naturally contains caffeine (咖啡因), which people in today’s society have somewhat come to rely on (依靠) to provide them with energy.In the workplace many people start their day with a cup of coffee, and then continue to drink it until it’s time to go home. Many meetings also begin with a cup of coffee --- which is why so many workplaces now have a steady flow of office coffee.Coffee is unsurprisingly one of the most traded agricultural products in the world, supporting the economy in many countries. Coffee is made from the roasted(烤，烘，焙) seeds of coffee cherries, which grow on trees in over 70 countries. The seeds are roasted to different degrees depending on the flavors wanted, and then are brewed (泡，煮) to create the coffee drink. Coffee usually sold is already roasted, so that all you have to do is add hot water.Coffee is classified according to its appearance --- light, medium light, medium, medium dark, dark, or very dark.People argue a lot about whether the effect of drinking coffee is positive or negative. Some people think that drinking too much coffee is bad for our health. But you can buy decaffeinated (脱去咖啡因的) coffee, which has a lot less caffeine. Most people, however, would not care about the negative effects of drinking coffee.Section B (10 marks)Directions: Read the following passage . A nswer the questions according to the information given in the passage.Most people think that making a film is exciting. In fact, sometimes it is and sometimes it isn’t. Earlier this year, I worked in a new film. It was about a bomb threat on a big British ship. Two hundred people were needed to act as the passenger s in the film. I was one of them.Before we left, we were wanted to bring some warm clothes. These were necessary because the ship was going to spend the whole 16 days sailing in bad weather.Then the day came and we sailed out of Dover. The boat had on board the film crew, the direct or, the actors and actres ses includ ing Brinksley Meers, who acted the leading role, and us-200 amateur(业余的) extras.People came for different purposes. Some wanted to meet Brinksley Meers in person. Others were curious to see how a film was made. A housewife with her three children came for free holiday and a bit of adventure. During the voyage, a lot of people were very seasick. And although the work was very interesting, it was also very hard. We often worked all day on one scene, performing it again and again under the hot lights. In the evening s, there were drinks in the bar, but most people were so tired that they went to bed early. The next day often began at 6:30 in the morning, sometimes with breakfast being filmed.When the ship finally returned to port, most people had enjoyed the trip, but were also so tired that they at least needed a week’s holiday. 81. Which role did he ( the author ) act in the film? (No more than 5 words)82. Why the film crew were asked to bring some warm clothes? (No more than 15 words)83. Why did the author say “they at least needed a week’s holiday”? (No more than 4 words).84. What’s the author’s purpose of writing this article? (No more than 15 words)Section C (25 marks)Directions: Write an English composition according to the instructions given below in Chinese.假设你是校学生会成员李华，为了更好地发现和解决同学们中存在的学习压力问题，学生会以How to Deal With Study Pressure为主题于上周采访了200名高二的学生。

2018-2019学年湖南省浏阳一中、醴陵一中高二12月联考英语试题总分：150分时量：120分钟考试时间2018年12月命题人：审题人：第一部分听力（共两节，满分30分）第一节（共五小题；每小题1.5分，满分7.5分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. What time does the bus leave?A.10:10.B.9:05C. 10:05.2.Where is the man’s biology textbook?A. Next to the TV.B. On the cupboard.C. Under his bed.3.What does the man think is the best way to get to know a place？A. Seeing travel films about it.B. Reading descriptions of it.C. Going therein person.4. Why does the woman make an early appointment?A. The tests must be done in the morning.B. She doesn’t want to take time off work.C. She mustn’t eat before the tests.5. What do we know about the woman?A. She has a meeting this eveningB. She will call the man at noon.C. She plans to play badminton this afternoon.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白。

2016届高二浏阳一中、攸县一中、醴陵一中十二月联考历史试卷时量：90分钟总分：100分命题人：易钰翔审题人：宋奇辉一、选择题（每小题只有一个正确答案，共25小题，计50分）1、关于中国画，现代画家潘天寿先生说过：“水墨画，能浓淡得体，黑白相用，干湿相成，则百彩骈臻，虽无色，胜于有色矣。

无色在其中，胜于青黄朱紫矣。

”下列哪位思想家的思想与该创作精神相符A．荀子 B．韩非子 C．墨子 D．老子2、“故圣人与天地合其德，日月合其明，四时合其序，鬼神合其吉凶。

君子修之，吉，小人悖之，凶。

……故曰：立天之道，曰阴与阳；立地之道，曰柔与刚；立人之道，曰仁与义。

”与上述认识最接近的观点是A．“天行有常，不为尧存，不为桀亡” B．“天理是宇宙万物的本原”C．“宇宙便是吾心，吾心即是真理” D．“理在气中，道不离器”3、董仲舒认为，“道之大原出于天”，自然、人事都受制于天命，因此反映天命的政治秩序和政治思想都应该是统一的。

在此，董仲舒提出的治国理念是A．竭力济贫以安抚广大民众 B．政治的最高目标是仁政C．维护大一统的中央集权统治 D．实行变法奖励耕战4、明末清初思想家唐甄在《太子》篇内这样说，“凡教太子，观于桑，则知衣服所自出，观于肆，则知器用所自出。

凡教太子，过市，则见贩鬻之劳，在途，则见负担之劳。

该言论反映了唐甄的治国思想是A．关注下层民众的疾苦 B．重视农工，勤俭治国C．民富是国富的前提 D．全面关注社会经济5、材料一：考古工作者曾在新疆、陕西、甘肃、内蒙古等地的汉代遗址和墓葬中发现了西汉纸的残片。

材料二：《后汉书·蔡伦传》记载：“伦乃造意，用树肤、麻头及敝布、鱼网以为纸。

……自是莫不从用焉，故天下咸称‘蔡侯纸’。

”研读上述材料而得出的结论最为合理的是A．造纸术诞生于西汉 B．蔡伦发明了造纸术C．汉代是造纸术发明的重要阶段 D．两汉时代，纸是唯一的文书用品6、2013年，被誉为中国“第五发明”的珠算成为世界非物质文化遗产。