2015年金牛区二诊断试卷
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四川省成都市2015级高中毕业班第二次诊断性检测英语本试卷分选择题和非选择题两部分。
第I卷(选择题1至8页,第II卷(非选择题)9至10页,共10页;满分150分,考试时间120分钟。
注意事项:1.答题前,务必将自己的姓名、考籍号填写在答题卡规定的位置上。
2.答选择题时,必须使用2B铅笔将答题卡上对应题目的答案标号涂黑,如需改动,用橡皮擦擦干净后,再选涂其它答案标号。
3.答非选择题时,必须使用0. 5毫米黑色签字笔,将答案书写在答题卡规定的位置上。
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第I卷(100分)第一部分听力(共两节,满分30分)做题时,先将答案标在试卷上。
录音内容结束后,你将有两分钟的时间将试卷上的答案转涂到答题卡上。
第一节(共5小题;每小题1.5分,满分7. 5分)听下面5段对话。
每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。
听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. What will the man do at the weekend?A. Go hiking.B. Camp in the mountains.C. Host his friends.2. Where does this conversation most probably take place?A. At home.B. In a hotel.C. In a restaurant.3. What did the man probably do?A. He offered Gary advice.B . He had a fight with Gary. C. He made peace with Gary.4. Who is making the call?A. Stanley.B. Mr. Miller.C. Betty.5. What is the woman going to do?A. Stay with the man.B. Go to see a doctor.C. Visit John in hospital.第二节(共15小题;每小题1.5分,满分22. 5分)听下面5段对话或独白。
2015年四川省成都市金牛区中考数学二诊试卷一、选择题(每小题3分,共30分)1.(3分)﹣6的绝对值是()A.6B.﹣6C.±6D.2.(3分)用4个小立方块搭成如图所示的几何体,该几何体的左视图是()A.B.C.D.3.(3分)在下列交通标志中,既是轴对称图形,又是中心对称图形的是()A.B.C.D.4.(3分)“PM2.5”是指大气中危害健康的直径小于或等于2.5微米的颗粒物,也称为可入肺颗粒物,它们含有大量的有毒、有害物质,对人体健康和大气环境质量有很大危害,2.5微米即0.0000025米.将0.0000025用科学记数法表示为()A.2.5×10﹣7B.2.5×10﹣6C.25×10﹣7D.0.25×10﹣5 5.(3分)下列计算正确的是()A.x2+x3=x5B.x2•x3=x6C.(x2)3=x5D.x5÷x3=x2 6.(3分)函数y=中的自变量x的取值范围是()A.x≥0B.x≠2C.x>0D.x≥0且x≠2 7.(3分)一元二次方程x2﹣4x+5=0的根的情况是()A.没有实数根B.只有一个实数根C.有两个相等的实数根D.有两个不相等的实数根8.(3分)如图,已知D、E在△ABC的边上,DE∥BC,∠B=60°,∠AED=40°,则∠A的度数为()A.100°B.90°C.80°D.70°9.(3分)如图,AB是⊙O的直径,若∠BAC=35°,则∠ADC=()A.35°B.55°C.70°D.110°10.(3分)如图,在4×4的正方形网格中,每个小正方形的边长为1,若将△AOC绕点O顺时针旋转90°得到△BOD,则的长为()A.πB.6πC.3πD.1.5π二.填空题(每小题4分,共16分)11.(4分)分解因式:x3﹣4x2﹣12x=.12.(4分)若等腰三角形两边长分别为3和5,则它的周长是.13.(4分)在某公益活动中,小明对本班同学的捐款情况进行了统计,绘制成如图不完整的统计图.其中捐100元的人数占全班总人数的25%,则本次捐款的中位数是元.14.(4分)如图,锐角三角形ABC中,直线PL为BC的垂直平分线,射线BM 为∠ABC的平分线,PL与BM相交于P点.若∠PBC=30°,∠ACP=20°,则∠A 的度数为°.三、解答题(本大题共6个小题,共54分)15.(12分)(1)计算:()﹣2+(π﹣2014)0+sin60°+|﹣2|(2)求不等式组的整数解.16.(8分)先化简,再求值:(﹣)÷,其中a=﹣1.17.(8分)如图,据热气球的探测器显示,从热气球A看一栋高楼顶部B的仰角为30°,看这栋高楼底部C的俯角为60°,热气球A与高楼的水平距离为120m,求这栋高楼BC的高度.18.(8分)如图,已知A(﹣4,),B(﹣1,a)是一次函数y=x+b与反比例函数y=(m≠0,x<0)图象的两个交点,AC⊥x轴于C,BD⊥y轴于D.(1)求m、a的值及一次函数表达式;(2)P是线段AB上的一点,连接PC,PD,若△PCA和△PDB面积相等,求点P 坐标.19.(8分)为了解中考体育科目训练情况,某县从全县九年级学生中随机抽取了部分学生进行了一次中考体育科目测试(把测试结果分为四个等级:A级:优秀;B级:良好;C级:及格;D级:不及格),并将测试结果绘成了如下两幅不完整的统计图.请根据统计图中的信息解答下列问题:(1)本次抽样测试的学生人数是;(2)图1中∠α的度数是,并把图2条形统计图补充完整;(3)该县九年级有学生3500名,如果全部参加这次中考体育科目测试,请估计不及格的人数为.(4)测试老师想从4位同学(分别记为E、F、G、H,其中E为小明)中随机选择两位同学了解平时训练情况,请用列表或画树形图的方法求出选中小明的概率.20.(10分)已知如图半圆O的半径OA=4,P是OA延长线上一点,过线段OP 的中点B作垂线交⊙O于点C,射线PC交⊙O于点D,联结OD.(1)若=,求∠COD的度数;(2)若=,求弦CD的长;(3)若点C在上时,设PA=x,CD=y,求y与x的函数关系式及自变量x的取值范围.一.B卷(50分)填空题(每小题4分,共20分)21.(4分)设一元二次方程x2﹣8x+3=0的两实数根分为x1和x2,则x12﹣11x1﹣3x2+5=.22.(4分)如图,是由四个直角边分别为3和4的全等的直角三角形拼成的“赵爽弦图”,小亮随机的往大正方形区域内投针一次,则针扎在阴影部分的概率是.23.(4分)为确保信息安全,信息需加密传输,发送方由明文→密文(加密);接收方由密文→明文(解密).已知加密规则为:明文a,b,c,d对应的密文为a+b,b+c,c+d,d+2a.例如:明文1,2,3,4对应的密文为3,5,7,6.当接收方收到密文8,11,15,15时,则解密得到的明文应为.24.(4分)如图,在矩形ABCD中,AB的长度为a,BC的长度为b,其中b<a <b.将此矩形纸片按下列顺序折叠,则C′D′的长度为(用含a、b的代数式表示).25.(4分)如图,在平面直角坐标系中,直线y=﹣x+1分别交x轴、y轴于A,B两点,点P(a,b)是反比例函数y=在第一象限内的任意一点,过点P 分别作PM⊥x轴于点M,PN⊥y 轴于点N,PM,PN分别交直线AB于E,F,有下列结论:①AF=BE;②图中的等腰直角三角形有4个;③S△OEF=(a+b﹣1);④∠EOF=45°.其中结论正确的序号是.二、解答题(共3个小题,共30分)26.(8分)由于国家重点扶持节能环保产业,某种节能产品的销售市场逐渐回暖,某经销商销售这种产品,年初与生产厂家签订了一份进货合同,约定一年内进价为0.1万元/台.若一年内该产品的售价y(万元/台)与月份x(1≤x≤12且为整数)满足关系式:y=,一年后,发现这一年来实际每月的销售量p(台)与月份x之间存在如图所示的变化趋势.(1)求实际每月的销售量p(台)与月份x之间的函数表达式;(2)全年中哪个月份的实际销售利润w最高,最高为多少万元?27.(10分)已知:如图,菱形ABCD中,对角线AC,BD相交于点O,且AC=12cm,BD=16cm.点P从点B出发,沿BA方向匀速运动,速度为1cm/s;同时,直线EF从点D出发,沿DB方向匀速运动,速度为1cm/s,EF⊥BD,且与AD,BD,CD分别交于点E,Q,F;当直线EF停止运动时,点P也停止运动.连接PF,设运动时间为t(s)(0<t<8).解答下列问题:(1)当t为何值时,四边形APFD是平行四边形?(2)设四边形APFE的面积为y(cm2),求y与t之间的函数关系式;(3)是否存在某一时刻t,使S四边形APFE :S菱形ABCD=17:40?若存在,求出t的值,并求出此时P,E两点间的距离;若不存在,请说明理由.28.(12分)如图1,在平面直角坐标系中,已知点A的坐标是(4,0),并且OA=OC=4OB,动点P在过A,B,C三点的抛物线上.(1)求抛物线的解析式;(2)是否存在点P,使得△ACP是以AC为直角边的直角三角形?若存在,求出所有符合条件的点P的坐标;若不存在,说明理由;(3)过动点P作PE垂直于y轴于点E,交直线AC于点D,过点D作x轴的垂线.垂足为F,连接EF,以线段EF的中点G为圆心,以EF为直径作⊙G,当⊙G最小时,求出点P的坐标.2015年四川省成都市金牛区中考数学二诊试卷参考答案与试题解析一、选择题(每小题3分,共30分)1.(3分)﹣6的绝对值是()A.6B.﹣6C.±6D.【分析】根据绝对值的概念可得﹣6的绝对值是数轴表示﹣6的点与原点的距离.【解答】解:﹣6的绝对值是6,故选:A.【点评】此题主要考查了绝对值,关键是掌握绝对值的概念:数轴上某个数与原点的距离叫做这个数的绝对值.2.(3分)用4个小立方块搭成如图所示的几何体,该几何体的左视图是()A.B.C.D.【分析】找到从几何体左面看得到的平面图形即可.【解答】解:从几何体左面看得到一列正方形的个数为2,故选:A.【点评】考查三视图的相关知识;掌握左视图是从几何体左面看得到的平面图形是解决本题的关键.3.(3分)在下列交通标志中,既是轴对称图形,又是中心对称图形的是()A.B.C.D.【分析】根据轴对称图形与中心对称图形的概念求解.【解答】解:A、是轴对称图形,不是中心对称图形.故错误;B、不是轴对称图形,也不是中心对称图形.故错误;C、是轴对称图形,也是中心对称图形.故正确;D、不是轴对称图形,也不是中心对称图形.故错误.故选:C.【点评】本题考查了中心对称图形与轴对称图形的概念:轴对称图形的关键是寻找对称轴,图形两部分沿对称轴折叠后可重合;中心对称图形是要寻找对称中心,旋转180度后与原图重合.4.(3分)“PM2.5”是指大气中危害健康的直径小于或等于2.5微米的颗粒物,也称为可入肺颗粒物,它们含有大量的有毒、有害物质,对人体健康和大气环境质量有很大危害,2.5微米即0.0000025米.将0.0000025用科学记数法表示为()A.2.5×10﹣7B.2.5×10﹣6C.25×10﹣7D.0.25×10﹣5【分析】绝对值小于1的正数也可以利用科学记数法表示,一般形式为a×10﹣n,与较大数的科学记数法不同的是其所使用的是负指数幂,指数由原数左边起第一个不为零的数字前面的0的个数所决定.【解答】解:0.0000025=2.5×10﹣6.故选:B.【点评】本题考查用科学记数法表示较小的数,一般形式为a×10﹣n,其中1≤|a|<10,n为由原数左边起第一个不为零的数字前面的0的个数所决定.5.(3分)下列计算正确的是()A.x2+x3=x5B.x2•x3=x6C.(x2)3=x5D.x5÷x3=x2【分析】根据合并同类项的法则:把同类项的系数相加,所得结果作为系数,字母和字母的指数不变;同底数幂的乘法法则:同底数幂相乘,底数不变,指数相加;幂的乘方法则:底数不变,指数相乘;同底数幂的除法法则:底数不变,指数相减,分别进行计算,即可选出答案.【解答】解:A、x2与x3不是同类项,不能合并,故此选项错误;B、x2•x3=x2+3=x5,故此选项错误;C、(x2)3=x6,故此选项错误;D、x5÷x3=x2,故此选项正确;故选:D.【点评】此题主要考查了同底数幂的除法,合并同类项,同底数幂的乘法,幂的乘方,很容易混淆,一定要记准法则才能做题.6.(3分)函数y=中的自变量x的取值范围是()A.x≥0B.x≠2C.x>0D.x≥0且x≠2【分析】根据二次根式的性质和分式的意义,被开方数大于或等于0,分母不等于0,可以求出x的范围.【解答】解:由题意,得x≥0且x﹣2≠0.解得x≥0且x≠2,故选:D.【点评】本题考查了函数自变量的取值范围,函数自变量的范围一般从三个方面考虑:当函数表达式是整式时,自变量可取全体实数;当函数表达式是分式时,考虑分式的分母不能为0;当函数表达式是二次根式时,被开方数非负.7.(3分)一元二次方程x2﹣4x+5=0的根的情况是()A.没有实数根B.只有一个实数根C.有两个相等的实数根D.有两个不相等的实数根【分析】首先求出一元二次方程x2﹣4x+5=0根的判别式,然后结合选项进行判断即可.【解答】解:∵一元二次方程x2﹣4x+5=0,∴△=(﹣4)2﹣4×5=16﹣20=﹣4<0,即△<0,∴一元二次方程x2﹣4x+5=0无实数根,故选:A.【点评】本题主要考查了根的判别式的知识,解答本题要掌握一元二次方程根的情况与判别式△的关系:(1)△>0⇔方程有两个不相等的实数根;(2)△=0⇔方程有两个相等的实数根;(3)△<0⇔方程没有实数根,此题难度不大.8.(3分)如图,已知D、E在△ABC的边上,DE∥BC,∠B=60°,∠AED=40°,则∠A的度数为()A.100°B.90°C.80°D.70°【分析】先根据平行线的性质求出∠C的度数,再根据三角形内角和定理求出∠A的度数即可.【解答】解:∵DE∥BC,∠AED=40°,∴∠C=∠AED=40°,∵∠B=60°,∴∠A=180°﹣∠C﹣∠B=180°﹣40°﹣60°=80°.故选:C.【点评】本题考查的是平行线的性质及三角形内角和定理,先根据平行线的性质求出∠C的度数是解答此题的关键.9.(3分)如图,AB是⊙O的直径,若∠BAC=35°,则∠ADC=()A.35°B.55°C.70°D.110°【分析】先根据圆周角定理求出∠ACB=90°,再由三角形内角和定理得出∠ABC 的度数,根据圆周角定理即可得出结论.【解答】解:∵AB是⊙O的直径,∴∠ACB=90°,∵∠BAC=35°,∴∠ABC=180°﹣90°﹣35°=55°,∴∠ADC=∠ABC=55°.故选:B.【点评】本题考查的是圆周角定理,在解答此类问题时往往用到三角形的内角和是180°这一隐含条件.10.(3分)如图,在4×4的正方形网格中,每个小正方形的边长为1,若将△AOC绕点O顺时针旋转90°得到△BOD,则的长为()A.πB.6πC.3πD.1.5π【分析】根据弧长公式列式计算即可得解.【解答】解:的长==1.5π.故选:D.【点评】本题考查了旋转的性质,弧长的计算,熟记弧长公式是解题的关键.二.填空题(每小题4分,共16分)11.(4分)分解因式:x3﹣4x2﹣12x=x(x+2)(x﹣6).【分析】首先提取公因式x,然后利用十字相乘法求解即可求得答案,注意分解要彻底.【解答】解:x3﹣4x2﹣12x=x(x2﹣4x﹣12)=x(x+2)(x﹣6).故答案为:x(x+2)(x﹣6).【点评】此题考查了提公因式法、十字相乘法分解因式的知识.此题比较简单,注意因式分解的步骤:先提公因式,再利用其它方法分解,注意分解要彻底.12.(4分)若等腰三角形两边长分别为3和5,则它的周长是11或13.【分析】题目给出等腰三角形有两条边长为3和5,而没有明确腰、底分别是多少,所以要进行讨论,还要应用三角形的三边关系验证能否组成三角形.【解答】解:有两种情况:①腰长为3,底边长为5,三边为:3,3,5可构成三角形,周长=3+3+5=11;②腰长为5,底边长为3,三边为:5,5,3可构成三角形,周长=5+5+3=13.故答案为:11或13.【点评】本题考查了等腰三角形的性质和三角形的三边关系;已知没有明确腰和底边的题目一定要想到两种情况,分类进行讨论,还应验证各种情况是否能构成三角形进行解答,这点非常重要,也是解题的关键.13.(4分)在某公益活动中,小明对本班同学的捐款情况进行了统计,绘制成如图不完整的统计图.其中捐100元的人数占全班总人数的25%,则本次捐款的中位数是20元.【分析】根据捐款100元的人数占全班总人数的25%求得总人数,然后确定捐款20元的人数,然后确定中位数即可.【解答】解:∵捐100元的15人占全班总人数的25%,∴全班总人数为15÷25%=60人,∴捐款20元的有60﹣20﹣15﹣10=15人,∴中位数是第30和第31人的平均数,均为20元∴中位数为20元.故答案为20.【点评】本题考查了中位数的求法,解题的关键是首先求得总人数和捐款20元的人数.14.(4分)如图,锐角三角形ABC中,直线PL为BC的垂直平分线,射线BM 为∠ABC的平分线,PL与BM相交于P点.若∠PBC=30°,∠ACP=20°,则∠A 的度数为70°.【分析】根据角平分线得出∠ABC=60°,再根据线段垂直平分线得出∠PCB=30°,利用三角形的内角和解答即可.【解答】解:∵射线BM为∠ABC的平分线,∠PBC=30°,∴∠ABC=60°,∵直线PL为BC的垂直平分线,∴∠PCB=30°,∴∠A的度数=180°﹣60°﹣30°﹣20°=70°,故答案为:70.【点评】此题考查线段垂直平分线性质,关键是根据角平分线得出∠ABC=60°,再根据线段垂直平分线得出∠PCB=30°进行分析.三、解答题(本大题共6个小题,共54分)15.(12分)(1)计算:()﹣2+(π﹣2014)0+sin60°+|﹣2|(2)求不等式组的整数解.【分析】(1)原式第一项利用负整数指数幂法则计算,第二项利用零指数幂法则计算,第三项利用特殊角的三角函数值计算,最后一项利用绝对值的代数意义化简,计算即可得到结果;(2)分别求出不等式组中两不等式的解集,找出解集的公共部分确定出不等式组的解集,即可确定出整数解.【解答】解:(1)原式=9+1++2﹣=12﹣;(2),由①得:x≥1;由②得:x<4,∴不等式组的解集为1≤x<4,则原不等式组的整数解为1,2,3.【点评】此题考查了实数的运算,熟练掌握运算法则是解本题的关键.16.(8分)先化简,再求值:(﹣)÷,其中a=﹣1.【分析】先根据分式混合运算的法则把原式进行化简,再把a的值代入进行计算即可.【解答】解:原式=÷=•(a+1)=,当a=﹣1时,原式==﹣7﹣4.【点评】本题考查的是分式的化简求值,熟知分式混合运算的法则是解答此题的关键.17.(8分)如图,据热气球的探测器显示,从热气球A看一栋高楼顶部B的仰角为30°,看这栋高楼底部C的俯角为60°,热气球A与高楼的水平距离为120m,求这栋高楼BC的高度.【分析】过A作AD⊥BC,垂足为D,在直角△ABD与直角△ACD中,根据三角函数的定义求得BD和CD,再根据BC=BD+CD即可求解.【解答】解:过A作AD⊥BC,垂足为D.在Rt△ABD中,∵∠BAD=30°,AD=120m,∴BD=AD•tan30°=120×=40m,在Rt△ACD中,∵∠CAD=60°,AD=120m,∴CD=AD•tan60°=120×=120m,∴BC=BD+CD=40+120=160m.【点评】本题主要考查了解直角三角形的应用﹣仰角俯角问题,难度适中.对于一般三角形的计算,常用的方法是利用作高线转化为直角三角形的计算.18.(8分)如图,已知A(﹣4,),B(﹣1,a)是一次函数y=x+b与反比例函数y=(m≠0,x<0)图象的两个交点,AC⊥x轴于C,BD⊥y轴于D.(1)求m、a的值及一次函数表达式;(2)P是线段AB上的一点,连接PC,PD,若△PCA和△PDB面积相等,求点P 坐标.【分析】(1)根据反比例函数图象上点的坐标特征可计算出m=﹣4×=﹣2,再把B(﹣1,a)代入y=﹣可求得a=2,然后把A点坐标代入y=x+b求出b,从而得到一次函数解析式;(2)连接PC、PD,如图,设P(x,x+),根据三角形面积公式得到××(x+4)=×|﹣1|×(2﹣x﹣),解得x=,然后计算自变量为时的一次函数值即可得到P点坐标.【解答】解:(1)∵反比例y=的图象过点(﹣4,),∴m=﹣4×=﹣2,把B(﹣1,a)代入y=﹣得﹣a=﹣2,解得a=2,∵y=x+b的图象过点A(﹣4,)∴×(﹣4)+b=,解得b=,∴一次函数的表达式是y=x+;(2)连接PC、PD,如图,设P(x,x+),∵△PCA和△PDB面积相等,∴××(x+4)=×|﹣1|×(2﹣x﹣),解得x=,当x=时,y=x+=,∴P点坐标是(﹣,).【点评】本题考查了反比例函数与一次函数的交点问题:求反比例函数与一次函数的交点坐标,把两个函数关系式联立成方程组求解,若方程组有解则两者有交点,方程组无解,则两者无交点.注意用点的坐标表示线段的长.19.(8分)为了解中考体育科目训练情况,某县从全县九年级学生中随机抽取了部分学生进行了一次中考体育科目测试(把测试结果分为四个等级:A级:优秀;B级:良好;C级:及格;D级:不及格),并将测试结果绘成了如下两幅不完整的统计图.请根据统计图中的信息解答下列问题:(1)本次抽样测试的学生人数是40;(2)图1中∠α的度数是54°,并把图2条形统计图补充完整;(3)该县九年级有学生3500名,如果全部参加这次中考体育科目测试,请估计不及格的人数为700.(4)测试老师想从4位同学(分别记为E、F、G、H,其中E为小明)中随机选择两位同学了解平时训练情况,请用列表或画树形图的方法求出选中小明的概率.【分析】(1)用B级的人数除以所占的百分比求出总人数;(2)用360°乘以A级所占的百分比求出∠α的度数,再用总人数减去A、B、D 级的人数,求出C级的人数,从而补全统计图;(3)用九年级所有得学生数乘以不及格的人数所占的百分比,求出不及格的人数;(4)根据题意画出树状图,再根据概率公式进行计算即可.【解答】解:(1)本次抽样测试的学生人数是:=40(人),故答案为:40;(2)根据题意得:360°×=54°,答:图1中∠α的度数是54°;C级的人数是:40﹣6﹣12﹣8=14(人),如图:故答案为:54°;(3)根据题意得:3500×=700(人),答:不及格的人数为700人.故答案为:700;(4)根据题意画树形图如下:共有12种情况,选中小明的有6种,则P(选中小明)==.【点评】此题考查了条形统计图和扇形统计图的综合应用,用到的知识点是用样本估计总体、频数、频率、总数之间的关系等,读懂统计图,从不同的统计图中得到必要的信息是解决问题的关键.20.(10分)已知如图半圆O的半径OA=4,P是OA延长线上一点,过线段OP 的中点B作垂线交⊙O于点C,射线PC交⊙O于点D,联结OD.(1)若=,求∠COD的度数;(2)若=,求弦CD的长;(3)若点C在上时,设PA=x,CD=y,求y与x的函数关系式及自变量x的取值范围.【分析】(1)首先利用垂直平分线的性质易得CP=CO,利用等边对等角得∠P=∠COP,由同弧所对的圆心角相等易得∠DOC=∠COP,利用外角的性质和三角形的内角和定理,等量代换得出结论;(2)首先利用(1)中的结论,运用相似三角形的判定定理得△DOC∽△DPO,再利用相似三角形的性质得=,代入数值得出CD;(3)首先由四点共圆可得∠PQD+∠ACD=180°,由邻补角定义易得∠PCA=∠PQD,易得△PCA∽△PQD,利用相似三角形的性质易得,代入可得关系式.【解答】解:(1)连接OC,如图1,∵BC⊥PO,PB=OB,∴CP=CO,∴∠P=∠COP,∵,∴∠DOC=∠COP,在△COD中,2∠DCO+∠DOC=180°,∵∠DCO=∠P+∠COP=2∠COP=2∠DOC,∴5∠DOC=180°,∴∠DOC=36°;(2)∵,∴∠DOC=∠COP,∵BC垂直平分OP,∴PC=OC=4,∴∠P=∠POC=∠DOC,∴△DOC∽△DPO,∴=,设CD=y,则16=(y+4)y,解得:y=2﹣2,即CD的长为2﹣2;(3)延长PO交圆于Q点,连结AC,如图2,∵∠PQD+∠ACD=180°,∴∠PCA=∠PQD,∵∠P=∠P,∴△PCA∽△PQD,∴,∴4(4+y)=x(x+8),∴y=(4﹣4<x<4).【点评】此题主要考查了圆周角定理,垂直平分线的性质,相似三角形的判定及性质等,作出适当的辅助线,综合运用各定理是解答此题的关键.一.B卷(50分)填空题(每小题4分,共20分)21.(4分)设一元二次方程x2﹣8x+3=0的两实数根分为x1和x2,则x12﹣11x1﹣3x2+5=﹣22.【分析】根据一元二次方程的解的定义及根与系数的关系可得,x12﹣8x1+3=0,即x12﹣8x1=﹣3,x1+x2=8,再将x12﹣11x1﹣3x2+5变形为x12﹣8x1﹣3(x1+x2)+5,代入计算即可求解.【解答】解:∵一元二次方程x2﹣8x+3=0的两实数根分为x1和x2,∴x12﹣8x1+3=0,即x12﹣8x1=﹣3,x1+x2=8,∴x12﹣11x1﹣3x2+5=x12﹣8x1﹣3(x1+x2)+5=﹣3﹣3×8+5=﹣22.故答案为﹣22.【点评】此题主要考查了根与系数的关系,将根与系数的关系与代数式变形相结合解题是一种经常使用的解题方法.同时考查了一元二次方程的解的定义.22.(4分)如图,是由四个直角边分别为3和4的全等的直角三角形拼成的“赵爽弦图”,小亮随机的往大正方形区域内投针一次,则针扎在阴影部分的概率是.【分析】根据几何概率的求法:针扎在阴影部分的概率就是阴影区域的面积与总面面积的比值.【解答】解:根据勾股定理可知正方形的边长为5,面积为25,阴影部分的面积=正方形的面积﹣4个三角形的面积=25﹣4××3×4=25﹣24=1,故针扎在阴影部分的概率.【点评】本题考查几何概率的求法:首先根据题意将代数关系用面积表示出来,一般用阴影区域表示所求事件(A);然后计算阴影区域的面积在总面积中占的比例,这个比例即事件(A)发生的概率.关键是得到大正方形的边长.23.(4分)为确保信息安全,信息需加密传输,发送方由明文→密文(加密);接收方由密文→明文(解密).已知加密规则为:明文a,b,c,d对应的密文为a+b,b+c,c+d,d+2a.例如:明文1,2,3,4对应的密文为3,5,7,6.当接收方收到密文8,11,15,15时,则解密得到的明文应为3,5,6,9.【分析】设密文8,11,15,15分别对应的明文为a,b,c,d,根据密文与明文的数量关系建立方程组求出其解即可.【解答】解:设密文8,11,15,15分别对应的明文为a,b,c,d,由题意,得,解得:.故答案为:3,5,6,9.【点评】本题考查了列四元一次方程组解实际问题的运用,四元一次方程组的解法的运用,解答时根据明文与密文的数量关系建立方程组是关键.24.(4分)如图,在矩形ABCD中,AB的长度为a,BC的长度为b,其中b<a <b.将此矩形纸片按下列顺序折叠,则C′D′的长度为3a﹣2b(用含a、b 的代数式表示).【分析】由轴对称可以得出A′B=AB=a,就有A′C=b﹣a,从而就有A′C′=b﹣a,就可以得出C′D′=a﹣2(b﹣a),化简就可以得出结论.【解答】解:由轴对称可以得出A′B=AB=a,∵BC=b,∴A′C=b﹣a.由轴对称可以得出A′C′=b﹣a,∴C′D′=a﹣2(b﹣a),∴C′D′=3a﹣2b.故答案为:3a﹣2b.【点评】本题考查了轴对称的运用,代数式的运用,折叠问题在实际问题中的运用,解答本题时利用折叠问题抓住在折叠变化中不变的线段是解答本题的关键.25.(4分)如图,在平面直角坐标系中,直线y=﹣x+1分别交x轴、y轴于A,B两点,点P(a,b)是反比例函数y=在第一象限内的任意一点,过点P 分别作PM⊥x轴于点M,PN⊥y 轴于点N,PM,PN分别交直线AB于E,F,=(a+b﹣有下列结论:①AF=BE;②图中的等腰直角三角形有4个;③S△OEF 1);④∠EOF=45°.其中结论正确的序号是②③④.【分析】由P的坐标及四边形PNOM为矩形,表示出OM=a,即为E的横坐标,PM=b,即为F的纵坐标,又E和F都为直线y=﹣x+1上的点,将E的横坐标代入直线y=﹣x+1中求出E的纵坐标,将F的纵坐标代入直线y=﹣x+1中求出F的横坐标,进而确定出EM和NF,表示出PE及PF,然后三角形OEF的面积=矩形PNOM的面积﹣直角三角形NOF的面积﹣直角三角形OEM的面积﹣直角三角形PEF的面积,求出各自的面积代入,整理后即可求出三角形OEF的面积,可对选项③进行判断;由B和E的坐标,利用两点间的距离公式表示出BE的长,同理由A和F的坐标,表示出AF的长,可判断BE与AF是否相等;图中的等腰直角三角形有4个,分别为三角形AOB,三角形BNF,三角形PEF及三角形AEM,由直线y=﹣x+1,分别令x=0及y=0,求出对应的y与x的值,确定出A和B的坐标,进而得到OA=OB,由OA与OB垂直,可得出三角形AOB为等腰直角三角形,即∠OBA=∠OAB=45°,又∠BNF与∠EMA都为直角,可得出三角形BFN与三角形AEM都为直角三角形,同理三角形PEF 也为等腰直角三角形,即可确定出图中等腰三角形有4个,选项②正确;由P 为反比例函数图象上的点,将P的坐标代入反比例函数解析式中求出2ab=1,将表示出AF及BE代入AF•BE中,计算后将2ab=1代入,可得出AF•BE=1,又OA=OB=1,得到OA•OB=1,即AF•BE=OA•OB,变形后得到一个比例式,再根据夹角都为45°,根据两边对应成比例且夹角相等的两三角形相似可得出三角形BOE与三角形AOF相似,根据相似三角形的对应角相等可得出∠BOE=∠AFO,而∠BOE=∠BOF+∠FOE,∠OFE为三角形BFO的外角,利用外角性质得到∠OFE=∠BOF+∠OBF,根据等式的性质及等量代换可得出∠FOE=∠OBF=45°,选项④,综上,得到所有正确的选项.【解答】解:∵P(a,b),∴OM=a,PM=b,∴点E的横坐标为a,F的纵坐标为b,又E和F都在直线y=﹣x+1上,∴点E(a,1﹣a),点F(1﹣b,b),即OM=a,EM=1﹣a,ON=b,NF=1﹣b,∴PE=PM﹣EM=b﹣(1﹣a)=a+b﹣1,PF=PN﹣NF=a﹣(1﹣b)=a+b﹣1,=S矩形MONP﹣S△EMO﹣S△FNO﹣S△EPF,∴S△EOF=ab﹣a(1﹣a)﹣b(1﹣b)﹣(a+b﹣1)2=(a+b﹣1),选项③正确;∵BE==a,AF==b,∴BE与AF不一定相等,选项①错误;∵直线y=﹣x+1分别交x轴、y轴于A,B两点,∴令x=0,求出y=1,即B(0,1);令y=0,求出x=1,即A(1,0),∵OA=OB=1,且∠AOB=90°,即△AOB为等腰直角三角形,又∠BNF=90°,∠NBF=45°,∴△BNF为等腰直角三角形,同理△PEF和△AEM都为等腰直角三角形,则图中等腰三角形有4个,选项②正确;∵△AOB为等腰直角三角形,∴∠FAO=∠EBO=45°,∵点P(a,b)是曲线y=上一点,∴2ab=1,即AF•B E=a•b=2ab=1,又∵OA•OB=1,∴=,∴△AOF∽△BEO,∴∠AFO=∠BOE,又∠BOE=∠BOF+∠FOE,且∠AFO=∠OBF+∠BOF,∴∠FOE=∠OBE,又∠OBE=45°,则∠FOE=45°,选项④正确,综上,正确选项的序号有:②③④.故答案为:②③④.【点评】此题属于反比例函数的综合题,涉及的知识有:相似三角形的判定与性质,等腰三角形的判定与性质,点的坐标与平面图形,以及两点间的距离公式,是一道中考常考的题型.二、解答题(共3个小题,共30分)26.(8分)由于国家重点扶持节能环保产业,某种节能产品的销售市场逐渐回暖,某经销商销售这种产品,年初与生产厂家签订了一份进货合同,约定一年内进价为0.1万元/台.若一年内该产品的售价y(万元/台)与月份x(1≤x≤12且为整数)满足关系式:y=,一年后,发现这一年来实际每月的销售量p(台)与月份x之间存在如图所示的变化趋势.(1)求实际每月的销售量p(台)与月份x之间的函数表达式;(2)全年中哪个月份的实际销售利润w最高,最高为多少万元?【分析】(1)要根据自变量的不同取值范围,运用待定系数法分段计算出p与x 的函数关系式;(2)可根据实际销售利润=单件的利润×销售的数量,然后根据题目中给出的售价与月次的函数式以及(1)中销售量与月次的关系式,得出实际销售利润与月次的函数关系式,根据自变量的不同的取值范围分别进行讨论,然后找出最高售价.。
成都市2015级高中毕业班第二次诊断性检测数学(文科)注意事项:1.答卷前,考生务必将自己的姓名和准考证号填写在答题卡上。
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第Ⅰ卷(选择题,共60分)一、选择题:本大题共12小题,每小题5分,共60分。
在每小题给出的四个选项中,只有一项是符合题目要求的。
1、设集合{}11<-=x x P ,{}21<<-=x x Q ,则=Q P I ( )。
A.⎪⎭⎫ ⎝⎛21,1 B.()2,1- C.()2,1 D.()2,02、已知向量()1,2=a ,()4,3=b ,=c ()2,k ,若()c b a //3-,则实数k 的值( )。
A.-8B.-6C.-1D.13、若复数z 满足()3211i z i -=+,则=z ( )。
A.210 B.23 C.22 D.214、设等差数列{}n a 的前n 项和n S ,若4S =20,105=a ,则=16a ( )。
A.-32 B.12 C.16 D.325、已知m 、n 是空间中两条不同的直线,α、β是空间中两个相互垂直的平面,则下列命题正确的是( )。
A.若α⊂m ,则β⊥mB.若βα⊂⊂n m ,,则n m ⊥C.若βα⊥⊄m m ,,则α//mD.若n m m ⊥=,βαI ,则α⊥n6、在平面直角坐标系中,经过点()2,22-P 且离心率为3的双曲线方程为( )。
A.12422=-y xB.114722=-y xC.16322=-y xD.171422=-y x 7、已知()()ϕω+=x A x f sin ⎪⎭⎫⎝⎛<>>2,0,0πϕωA ,的部分图像如图所示,现将()x f 图像上所有的点向右平移4π个单位长度得到()x g 的图像,则函数()x g 的解析式为( )。
绝密★启用前2015届四川省成都市高中毕业班第二次诊断性检测语文试卷(带解析)试卷副标题考试范围:xxx ;考试时间:107分钟;命题人:xxx学校:___________姓名:___________班级:___________考号:___________注意事项.1.答题前填写好自己的姓名、班级、考号等信息 2.请将答案正确填写在答题卡上第I 卷(选择题)一、选择题(题型注释)1、下列各句中,语意明确、没有语病的一项是A 今年的《网购商品监测报告》显示,在92件抽样商品中,38件商品存在着假冒伪劣、无质量认证和非授权正规渠道销售,被认定为“非正品”。
B .上周六,我市文化馆启动了市民文化艺术培训学校今年春季班的现场报名工作,14个班次的500余个学员名额在半天内被市民一抢而空。
C .出租车是城市流动的名片,这要求出租车司机要具备相关的从业资格、过硬的驾驶技术、良好的职业道德和热情的服务态度才能够胜任。
D .参加完为期一周的中学生排球联赛,他发现自己的功课已经落下了一大截,为了赶上大家的学习进度,他在假期里强迫自己做了一周的作业。
2、下列各句中,划线词语使用恰当的一项是A 恰逢农历羊年,某影城对动画片《羊年喜羊羊》分外照顾,在购票大厅布置了电影中的场景,让小朋友拍照留念。
试卷第2页,共11页B .在竞争激烈的手机市场上,这款自诩“为自拍而生”的手机,凭着优异的自拍功能,获得了众多年轻消费者的青睐。
C 一味地迎合市场使文学变得浮躁,现今的图书市场充斥着内容浅薄的通俗读物,缺乏力透纸背的经典之作。
D .为让公司尽快走出困境,实现盈利,年逾花甲的他临危授命,再次出任公司总经理,开始了大刀阔斧的改革。
3、下列词语中,没有错别字的一项是 A .毗临缄默怦然心动出其不意 B .巅峰坐落心心相映食不果腹 C .贸然凄惋大快朵颐出类拔萃 D .装潢腊梅杀身成仁锄强扶弱4、下列词语中加点的字,读音全部正确的一项是 A .辟邪(bì)烘焙(bèi )柏油路(bái )晕头转向(zhuàn ) B .铜臭(chóu )绮丽(qí)紧箍咒(gú)顺蔓摸瓜(wán ) C .光纤(xiàn )悲恸(tóng )着眼点(zháo )吃里扒外(pá) D .咋舌(zè)圭臬(niè)酵母菌(jiào )磕磕绊绊(pán )第II卷(非选择题)二、作文(题型注释)5、阅读下面的一首诗,根据你的感悟或认识,写一篇文章。
2015年四川省成都市高考英语二诊试卷第一部分英语知识运用(共两节,满分10分)第一节:语法和词汇知识(共10小题;每小题1分,满分10分)从A、B、C、D四个选项中,选出可以填入空白处的最佳选项,并在答题卡上将该选项涂黑.1. ----Congratulations on your 18th birthday,Mark!Many happy returns!----____()A My pleasureB Good heavensC Thanks a lotD The same to you.2. There are times ____ you have to act from the heart.()A whenB thatC whereD which.3. ---It's a pity that I can speak neither German nor French.---I can't,____()A tooB eitherC alsoD as well4. _____to make his fortune in South America,Mark Twain set off from his home for New Orleans in his teens.()A Being determinedB To determineC DeterminedD Determine.5. ____working hard does not necessarily guarantee one's success,it is almost impossible to succeed without it.()A IfB WhenC AsD While.6. ---Have you worked out the schedule for our graduation trip?---Yes.I___ on it for 3 hours.()A have been workingB was workingC workedD had worked.7. With so many plans____,I'm sure to have a tight but rewarding summer holiday.()A carrying outB to carry outC carried outD to be carried out.8. Film reviewers are surprised to find that Han Han's first film,The Continent,____be such a huge success()A canB mustC mayD should9. You can tell about a person by ____ he says about others in their absence.()A whatB whichC thatD whether10. One Hundred Years of Solitude,a world-famous novel about a seven-generation Colombian family,___ into 37 languages since 1967()A translatedB was translatedC has translatedD has been translated第二节完形填空(共20个小题;每小题1.5分,满分30分)阅读下面短文,从短文后各题所给的四个选项(A、B、C和D)中,选出可以填入空白处的最佳选项,并在答题卡上将该项涂黑.11. Luke didn't know what to do.He wanted to yell at Kyle, his(1)________, because Kyle continued to(2)________ with his mom, Jane.She didn't demand very much from him---"Study hard, get the best(3)________ you can, "she told him.She tried to get it into his head that she didn't have the (4)________ for his college education.Not a cent could be expected!(5)________ studying harder, Kyle spent hour after hour playing video games on his computer.He always waited until the last minute to study for school(6)________, and stayed up all night cramming(强记硬背) for them.When Jane tried to(7)________ him that he needed good grades to get a(8)________, he would turn a deaf ear to her or even get angry.He said it was her(9)________to take care for him financially(10)________ he graduated from college."Where did he get that(11)________? "Luke asked."You've(12)________him for 10years all by yourself.You don't(13)________ him a thing.He should be glad you haven't kicked him out of the apartment already .When I was in the eleventh grade, my father made it (14)________ to me that when I graduated from high school, I was expected to leave home.(15)________ Kyle thinks you have to pay his way through college!"Jane would(16)________ Luke to talk to Kyle."He says you're not his father, so why should he have to listen to you? ""Well, his father's dead.He should appreciate that I'm(17)________ to try to help him."Luke said."Kyle will be able to learn to accept your help and advice(18)________.But before that, Luke, we need to try hard to get him to accept you in his heart, clos e to the (19)________ of his own father.""I agree and we sure have every confidence in him."said Luke."Yes.And in(20)________, too!"Jane reminded him.(1)A cousinB stepbrotherC nephewD stepson(2)A discussB meetC argueD deal(3)A teachersB gradesC friendsD prizes(4)A needB moneyC hopeD time(5)A Instead ofB In addition toC In spite of D(6)A rulesB testsC regulationsD admissions(7)A informB warnC promiseD remind(8)A scholarshipB degreeC rewardD job(9)A honorB rightC pleasureD responsibility(10)A sinceB whenC untilD after(11)A principleB decisionC sayingD idea(12)A helpedB raisedC educatedD sponsored(13)A oweB askC lendD offer(14)A easyB possibleC clearD strange(15)A SoB YetC Still D(16)A forceB allowC inviteD forbid(17)A aroundB outC awayD off(18)A in turnB at firstC in timeD at once(19)A heartB placeC dutyD life(20)A himselfB ourselvesC myselfD yourselves第二部分阅读理解(共两节,满分40分)第一节阅读下列短文,从每题所给的四个选项(A,B,C和D)中,选出最佳选项,并在答题卡上将该选项涂黑.(共20个小题;每小题8分,满分40分)12. FRANCEThe France company that spread a Europe-wide cheating of food supply by passing off(冒充)750tons of horse-meat as beef was allowed on Monday to restart production of minced meat, sausages and rea dy-to-eat meals.But the company will no longer be allowed to stock frozen meat, Agriculture Mini ster Stephane Foll said.UNITED KINGDOMA new virus that broke out in the Middle East last year and killed five people is well adapte d to infecting humans but could practically be treated with drugs that improve the immune (免疫)system."The virus is from the same family as the common cold and as SARS."a scientist fr om Oxford on Tuesday.SOUTH AFRICAOlympian runner Oscar Pistorius broke into the door of a small bathroom where his girl fri end was bathing after a shouting match on Valentine's Day, hitting her three times, a South Af rican prosecutor(检察官) said on Tuesday as he charged the sports star with planned murder.EGYPTFormer Egyptian prime minister and presidential(总统的) candidate Ahmed Shafiq was referred to the Cairo Criminal Court on Tuesday over corr uption and money laundering charges, the official News Agency reported.Shafiq has left Eg ypt has left Egypt for the United Arab after losing the presidential race.(1)According to the passage,the French company________.A spread a virus across Europe.B sold 750tons beef as horse-meat. C restarted production of frozen meat. D was again allowed to produce sau sages.(2)The planned murder took place in________A Egypt.B America.C South Africa.D The United Kingdom.(3)We can learn from this passage that________.A the French company once cheated its customers.B patients with the new virus can n ot be cured by now.C Pistorius killed his girlfriend all by chance on Tuesday.D t he former prime minister of Egypt has left the United Arab.(4)This passage is taken from the section of________in a newspaper.A Nation.B World.C Sports.D Science.13. The Children's Book-show Competition is a chance for young readers to be writers. Reading it seems, is coming back in fashion, if a survey by the famous National Literacy Tru st (the NLT) is true.It shows that the percentage of children who admit enjoying reading has grown for the first time in the past 8years.So it's a good time to launch a competition that includes a shed-load of new books for schools as prizes.The Children's Book-show Competition, backed by The Independent, is taking to the roads again from the start of next term, with a nation-wide tour of 15big cities, featuring a line-up of a dozen children's writers and illustrators(插图画家)aiming to persuade pupils to follow their footsteps.The competition, launched by the children's writer and illustrator Jessica Souhami, has two categories: the under-nine's and nine to 13-year-olds.Children are asked to choose their favorite fairy or folk tale and set it in an extraordinary pl ace.Then they are to retell it with the aid of drawings and writings-whether it is set at sea, on a distant planet, in the future or in the past.The closing date for t he competition is 30November."Tell your tale in pictures and in words, "say the organizers of the competition."It can be i n a picture book or comic-book format."The winner of each competition will receive a signed copy of a book by each of the 12autho rs involved in this year's tour, plus£150worth of books for their school.The runners-up will receive a signed copy of Souhami's new book.(1)What can we know about the Book-show Competition?________A It will be held by the famous NLT.B It will be held in different cities.C It has ne ver been organized before.D Children of all ages will join in it.(2)The underlined word"backed"in Paragraph 3means________.A started.B promoted.C supported.D reported.(3)What will be offered as a prize to schools________?A Pictures and comic books.B Books worth£150in all.C Books signed by 12auth ors.D Jessica Souhami?s new books.(4)The author's purpose of writing this passage is to________.A encourage young readers to become writers.B persuade all children to join in the co mpetition.C promote children's books b famous writers.D introduce a book-show to children.14. Just finishing loading his car, my husband Jerry went back to the kitchen."I guess filling my thermos(保温瓶) is all I have left to do, and then I'm off."Down the drain went the hot water that had be en warming his thermos.With a nostalgic(怀旧的) look on his face, he softly said: "Anytime I fill my thermos I think of your mom."The to ne in his voice was so tender as he spoke of my mother, who is sadly no longer with us."Oh honey, I know she's watching and listening right now with a big smile on her face, "I re sponded, tears in my eyes.One morning years ago when we were leaving, mother watched as Jerry was to fill his thermos.Mom then casually said, "Jerry, if you filled your thermos with hot water and let it sit a while, your coffee would stay hot for longer then."With her simple suggestion, his face sho wed that he was shocked by his own lack of common sense, well, of course it would!He poured out the small amount of coffee already in the thermos and refilled it with boilin g hot water.Then he poured the water and refilled it with hot coffee.Mom smiled as Jerry did so.Words of wisdom from a loving mother-in-law made an impact that will never be forgotten.She never dreamed her words would be a t reasured and everlasting memory in the heart of her son-in-law.The lasting memories don{'}t necessarilycome from major moments in life.Memories are often made during those small, ordinary times Life is about small moments we share with fri ends and loved ones.(1)Which word best describes the author's feeling in Paragraph 3________?A Confused.B Concerned.C Touched.D Interested.(2)The advice the mother gave Jerry was to________.A fill the thermos with a little coffee first.B warm the thermos up before filling it with coffee.C fill thermos with coffee before with warm water.D think of her whenev er filling the thermos with coffee.(3)The underlined part"don't necessarily"is similar in meaning to________.A possibly but uncertainly.B without any doubt.C certainly and absolutely.D out of the question.(4)The message that the story intends to convey is________.A that lasting memories come from small things.B how valuable a mother's advice is t o her children.C what a wise woman the mother is to her son-in-law. D why we should respect our parents and listen to them.15. NEW YORK----Family members gathered on Wednesday evening for the funeral of Eric Garner, who died sh ortly after police put him in a banned chokehold as they arrested him in Staten Island of New York, where the death has cause anger and a promise to reform police training.Garner's wi fe, Esaw Garner, entered the Bethel Baptist Church in Brooklyn, supported by two young boy s, looking upset and exhausted.After her followed six children of the family.Garner's dyin g moments on a Staten Island sidewalk last Thursday were recorded on by bystanders.May or Bill Blasio, who was elected partly because he once promised to mend the worn relations between New York police and the local ethnic minorities, has called the death a tragedy.In the videos, Garner, who was black, can be seen arguing with several police officers arres ting him suspected of selling untaxed cigarettes outside a beauty parlor.Moments later, he was down on the sidewalk with an officer's arm around his neck, pleadi ng(恳求) repeatedly that he couldn't breathe.After he fell down, at least seven minutes passedwithout any apparent attempts at medical help.The Staten Island district lawyer and the police department's internal affairs are investigat ing Garner's death.The city's police have been banned from using the chokehold for more than 20years becau se it can be deadly, particularly when used on someone who is overweight, as Garner was. Two of the police officers involved have been put on desk duty and four emergency respon se workers were suspended without pay.Actually, a complete check of police training was s tarted on Tuesday, focusing on the proper use of force.(1)Which one is TRUE about Garner's death________?A New York police attached great importance to it.B Garner's wife was too weak to att end the funeral.C The police didn't use chokehold in a correct way.D Medical aid was provided immediately to help him.(2)The police officers arrested Garner because they thought________.A he argued with them repeatedly.B he caused black people's anger.C he was se lling untaxed cigarettes.D he belonged to ethnic minorities.(3)The last paragraph mainly tells us________.A the officers and workers involved were fired.B a complete check of police training w as to happen.C what has been done so far in response to Garner's death.D New Y ork police should be responsible for Garner's death.(4)What's the main idea of the passage?________A Recorded videos never tell Lies.B Not all policemen are good ones.C Police tra ining must be reformed.D Black people can hardly avoid tragedies.16.Researchers may have discovered a perfect material of dieting—low fat cake and cheese. British researchers say they have created a protein (蛋白质) that fat perfectly.The proteins will enable food producers to remove much of the fat used in their products but without reducing product quality.Funded by team from University of Edinburgh, the researchers have produced the modified (调整了的) proteins that easily break down and therefore work nearly the same as the fats do during food production."We've paved the way for the development of modified proteins that can be used to produce a wider range of appealing low-fat foods, "said Dr. Steve Euston, who led the research."The result could be important for health benefits, as well as a reduction in the burden on the National Health Service (NHS) caused by many weight-related health problems."Protein-for-fat substitution (替代品) is not a completely new idea, but to date it has been limited to products such as yogurts.In cheeses and cakes it has proved less successful in ensuring the original taste and texture fundamental to consumer satisfaction, mainly because proteins could not mimic thebehavior of fats closely enough.By studying the proteins' chemical structure, the team has developed a detailed understanding of how proteins behave when they are heated or go through other food producing processes.The proteins could encourage development of a wider choice of low-fat foods, helping consumers to eat more healthily and reducing weight-related health problems.The team has achieved particularly promising results in using proteins to replace eggs, which is commonly used in bakery items.Such substitution not only cuts fat content; because eggs can be subject to sharp changesin price, it could also cut the cost products and so encourage consumers to eat more healthily.(1)What can we learn from the passage?________A The NHS will benefit from this new finding.B The research team is funded by food p roducers.C Protein for fat substitution is a completely new idea.D Products of m odified proteins have been put on sale.(2)The underlined word "mimic" means________.A reducesB makesC removesD imitates(3)These new proteins work nearly the same as the fats do because________.A they will cut fat content easily .B they will break down easily.C their products are cheaper and healthier .D they ensure the original taste and texture.(4)Which of the following is best title?________A A Special ProteinB How Proteins WorkC Cut down the Food CostD A special Research Team第二节对话理解根据对话内容,从对话后的选项中选出能填入空白处的最佳选项,并将答案写到答题卡相应的位置上.选项中有两项多余选项.(共5个小题;每小题10分,满分10分)17. Interviewer:Please sit down.Let's see…you're Mr.Smith?Mr.Smith:Yes.John Smith.Interviewer:(1)________Mr.Smith:A little bit.Actually,I've helped out at my father's office,and in a recording studio before.Interviewer:That's good.(2)________Mr.Smith:Yes,I can work any day of the week.Oh,no except Thursday.I work at a nursing home that day.Interviewer:(3)________Mr.Smith:Next Monday.Interviewer:Ok.We've got two stores for your choice:a busy one downtown,and one near the airport with few customers.Mr.Smith:(4)________Interviewer:Good.Everyone else hates it.There are few customers,so you'll most likely be doing jobs such as carrying big boxes and cleaning.Mr.Smith:No problem.Interviewer:(5)________.See you next Monday.A.I prefer the latter.B.Oh,you are lucky.C.Great!That's settled.D.Then when can you start?E.Can you work every day?F.Do you have any job experience?G.How often would you like to work?第三部分写作(共三节,满分10分)第一节阅读表达(共5个小题;每小题10分,满分10分)阅读下面短文并回答问题,然后将答案写到答题卡相应的位置上(请注意每题词数要求)18. One of my wonderful memories is about a Christmas gift.Unlike other gifts,it didn't come in stockings.On September 11th,1958,Mom gave birth to Richard.After she brought him home from hospital,she put him in my lap,saying,"I PROMISED YOU A GIFT,AND HERE IT IS."What an honor!I turned four a month earlier and none of my friends had such a baby doll of their own.I played with it day and night.I sang to it.I told it stories.I told it over and over how much I lived it!One morning,however,I found its bed empty.My doll was gone!I cried for it.Mom wept and told me that the poor little thing had been sent to hospital.It had a fever.For several days,I heard Mom and Dad whispering such words as"hopeless","pitiful",and"dying".Christmas was coming."Don't expect any presents this year."Dad said,pointing at the stockings that I hung in the living room."If your baby brother lives,that'll be Christmas enough."As he spoke,his eyes were filled with tears.I'd never seen him cry before.The phone rang early on Christmas morning.Dad jumped out of bed to answer it.From m y bedroom I heard him say,"What?He's all right?"He hung up and shouted upstairs."The hospital said we can bring Richard home!""Thank God!"I heard Mom cry.From the upstairs window,I watched my parents rush out to the car.I had never seen them that happy.And I was also full of joy.What a wonderful day!My baby doll would be home.I went upstairs.My stock ings still hung there flat.But I knew they were not empty; they were filled with love.56.How old was the writer when Richard was born________?(No more than 1 word)57.Why was Richard sent to hospital one da?________(no more than 5 words)58.When did Richard come home________?(no more than 2 words)59.What did the writer think was in the stockings________?(no more than 1 words)60.What indeed was the writer's Christmas gift________?(no more than 6 words)第二节短文改错(共1小题;每小题1.5分,满分15分.将答案写到答题卡相应的位置上)19. 下文中共有10处语言错误.请在有错误的地方增加、删除或修改某个词.增加:在缺词处加一个漏字符号,并在其下面写出该加的词.删除:把多余的词用斜线划掉.修改:在错的词下面划一横线,并在该词下面写出修改后的词.注意:1.每句不超过两个错误.2.每处错误及其修改均仅限一词.3.只允许修改10处,多者(从第11处起)不计分.What does our future depend on?It is determined by many things,such as the opportunities and help,but our determination and hard work can play a much important role.In another words,we are the masters of our future.Taking Abraham Lincoln for example.He born in a poor f amily,but onlyreceived a limited education in his childhood.Yet through his efforts,he not only changed his fate but also the history of American.Even these days,Lincoln is still regarded as one of the most inspiring figure in the world.Therefore,I firm believe that our future in on our own hands.第三节书面表达(满分35分,将答案写到答题卡上相应的位置上)20. 你校拟在课外活动时间开设烹饪课.现在,请你根据以下提示,给校刊的英语专栏写一篇短文.1.同学们对开设烹饪课看法各异;2.你持赞成态度及其理由(两点);3.你对开设烹饪课的建议(一条).注意:1.词数120字左右.2.可适当增加细节,以使行文连贯;3.文中不能出现你和学校的真实名字.2015年四川省成都市高考英语二诊试卷答案1. C2. A3. B4. C5. D6. C7. B8. D9. A10. D11. D CBBABDADCDBACBDACBB 12. D CAB 13. B CBD 14. C BAA 15. A CCC 16. A DBA17. F,E,D,A,C18. Four/4,Because it/he had a fever/Because of a fever,At/On Christmas,Love,The surviving /survival/return of Richard/his/her baby brother.Or:That Richard/his/her baby brother survived/returned.Or:That Richard/his/her baby brother was OK/all right/alright.19. What does our future depend on?It is determined by many things,such as the opportunities and help,but our determination and hard work can play a much去掉the moreimportant role.In another words,we are the masters of our future.Taking Abraham Lincoln for example.He∧born in a poor family,but only received aother Take was andimited education in his childhood.Yet through his efforts,he not only changed his fate but also the history of American.Even these days,Lincoln is stillAmerica regarded as one of the most inspiring figure in the world.Therefore,I firm believe that our future is on our own hands.fingures firmly in1,去掉the;考查冠词的用法,定冠词the 表示特指,这里opportunities是可数名词复数形式,不需要特指,所以去掉the.2.much改为more;考查多音节单词形容词的比较级,多音节形容词或副词的比较级形式是在单词前面加more.3.another改为other;考察形容词,in other words是固定搭配,意为"换句话说".4.Taking改为Take;考查祈使句,祈使句中要用动词原形.5.born前面加was;考查系动词,be born 指出生.6.but改为and;考查连词,and表并列,but转折,根据上下文句意,这里是并列关系,所以用and.7.American改为America;考查名词,作为American指美国人,America指美国,这里the history of America指"美国的历史".8.fingure改为fingures;考查名称复数,one of the+名词复数,表示"中之一"所以用复数fingures.9.firm改为firmly;考查副词,这里用副词firmly修饰动词believe.10.on改为in;考查介词,be in one'sown hand是"在某人手中",例如Life is in your own hand.命运掌握在你自己手中.20. Recently,our school is planning to offer us a cooking course as one of the after-school activities.Towards this,students have different attitudes.同学们对开设烹饪课看法In my opinion,the cooking course can be beneficial and enjoyable.(高分句型一)By attending it,we can learn a very useful living skill to help ourselves not only live independently but also ta ke care of our families.(高分句型二)Besides,taking this course is a way to reduce our study pressure and enrich our after-school life.你的态度及理由To make this course a great success,I'd like to make a suggestion here.(高分句型三)I think it would be ideal if the teachers tell us how to cook safely in order not to get hurt whil e practicing cooking.Actually,the idea of providing the cooking course for students is very creative and I'm really looking f orward to it!你对开设烹饪课的建议。
成都市2015级高中毕业班第二次诊断性检测文科综合参考答案及评分标准第Ⅰ卷(选择题,共140分)1D2.B3.A4.C5.A6.C7.B8.C 9.D10.A11.C12.C13.A14.B15.D16.D17.B 18.B19.D20.B21.B22.D23.C24.B25.D26.A27.C28.D29.A30.C31.B32.D33.B34.C35.C第Ⅱ卷(非选择题,共160分)36.(24分)(1)跨纬度大,热量、水分差异大(2分);东部为高大山脉,气候垂直差异大(2分),所以适宜多种水果生长.(2)北部为干旱的沙漠(2分),东部为高大山脉(2分),西部、南部为海洋(或西临太平洋,南部多冰川)(2分),环境相对封闭(或成为外来病虫害的天然屏障)(2分),不易受外来病虫害影响.(3)劳动力价格和土地租金低(4分)(只答生产成本较低给2分);位于南半球,产品在我国冬季上市,竞争力强(2分);少病虫害影响,农药使用少,品质好(2分).(4)海运运量大,成本低,有价格优势(2分);空运速度快,水果新鲜度高(2分).37.(22分)(1)影响因素:水库建设(2分).依据:①长江流域水土流失面积在增加,应导致入海输沙量增加(2分);②长江流域的降水量和长江的径流量均无明显下降(2分);③三峡等大型水库的修建,泥沙在水库淤积,导致入海输沙量减少(2分).(2)降水量减少导致黄河径流量减少,同时加剧对黄河径流的引用,输沙能力下降(3分);降水量减少,对地表冲刷作用减弱,入河泥沙量减少(2分);径流量减少,对河岸侵蚀作用减弱,泥沙来源减少(2分),所以入海输沙量减少(1分).(3)①海水侵蚀加剧,三角洲增长速度减缓(或海岸线后退);②海水入侵,沿海土地盐碱化加剧;③沿海湿地退化;④河流输送到海洋的营养物质减少,影响海洋生物生存.(任答3点给6分,总分不超过6分)文科综合“二诊”参考答案第1页(共4页)38.(28分)(1)①政府加强宏观调控,运用经济手段鼓励和引导社会加大投资;(3分) ②坚持市场化运作,发挥企业和农牧民的治沙主体作用;(3分)③研发和运用治沙绿化新技术,提高治沙能力和效率;(3分)④坚持社会效益、生态效益和经济效益的统一,开发利用沙漠特有资源发展生态产业,走可持续发展道路.(3分)(说明:学生只要从“政府政策性支持、企业产业化投资、农牧民市场化参与、技术持续性创新、生态持续化改善”五个角度回答,言之成理皆可给分,但总分不得超过本题满分.) (2)增强主人翁意识和责任意识,增强环保观念,自觉践行绿色低碳的生活方式;(3分)坚持权利与义务的统一,坚持个人利益与国家利益的统一,自觉履行保护环境的义务;(3分)通过社情民意反映制度等方式参与民主决策,为绿色发展建言献策;(3分)积极行使监督权,敢于与破坏环境的违法失职行为作斗争.(3分)(3)示例:举办荒漠治理国际论坛,介绍中国成功案例;与中国共建沙漠绿色经济创新中心,研发治沙新技术;邀请中国派出治沙技术人员,对他国沙漠治理提供技术指导或培训人才.(说明:每点2分,学生言之成理皆可给分,但必须围绕“推广中国经验”这一主题提出适合的建议.)39.(24分)(1)①同一事物的矛盾在不同发展阶段有不同的特点,同一矛盾的两个方面也各有其特殊性,要求我们做到具体问题具体分析.(4分)②当前,我国虽然仍处于社会主义初级阶段,但改革开放40年来基本国情发生了重大变化,中国特色社会主义已进入新的发展阶段.党的这一重大政治论断把握了我国发展新的历史方位和阶段性特征.(4分)③现阶段,我国社会生产和社会需求这两个方面都发生了变化:社会生产力水平总体上显著提高,不再是“落后的社会生产”;人民生活水平显著提高,对美好生活的向往更加强烈,只讲“物质文化需要”已经不能真实全面反映人民群众的愿望和要求.党的这一重大政治论断是对我国经济社会发展的客观实际的具体把握.(4分)(2)①立足于中国特色社会主义的伟大实践,勇于探索,创新性地提出了一系列治国理政的新理念新思想新战略.(3分)②对中华文化自身价值充分肯定,继承和弘扬中国优秀传统文化,不断赋予中华文化以鲜明的时代特色.(3分)③积极吸收国外优秀文明成果,坚持以我为主、为我所用,保持自己民族文化的独特性和民族话语的独立性,开辟马克思主义中国化的新境界.(3分)④坚定信念,对中国特色社会主义道路、制度、理论充满信心,对社会主义现代化强国目标充满信心.(3分)文科综合“二诊”参考答案第2页(共4页)40.(25分)(1)妇女法律权利不断扩大,如获得财产权和选举权等;妇女法律地位日趋独立,如可以独立订立契约,独立处理自己的财产等;男女法律地位日趋平等,如21岁以上女子和男子有平等的选举资格等;妇女的人格尊严日益得到法律维护,如行为清白的母亲可以监护14岁以下的孩子等.(每点3分,其中概括2分,说明1分,任答三点9分.若只答出“妇女法律地位总体上不断提高”,并举例说明,只能得3分)(2)特点:要求男女平权的主张受西方影响;妇女法律地位的变化起步较晚;妇女法律地位变化城乡不均;与本国反帝反封建的斗争相关联;受本国封建势力和传统习俗阻碍明显;改善妇女法律地位的司法实践效果有限.(每点2分,任答四点8分)共同原因:政治民主化进程的逐步加深;资本主义经济的发展;思想解放潮流的影响;妇女自身不断的争取与斗争.(每点2分,共8分)41.(12分)[论题1] 商业广告发展与社会变迁(2分) ●(角度1:社会变迁推动商业广告发展)由于生产力发展水平所限,早期广告形式相对原始落后;随着科技的进步和商品经济的发展,印刷广告、广播电视广告、网络广告等新形式相继出现;而社会进步带来的社会观念更新和思想解放,也推动广告内容、人物形象的不断变化,如新女性形象成为民国广告画的主角,工人、农民和解放军战士成为新中国广告形象的主体等.(8分)综上所述,社会不断发展进步推动了商业广告形式和内容的持续发展.(2分)●(角度2:商业广告发展助推社会变迁)商业广告的持续发展不仅丰富了商品信息,也扩大了广告传播范围,提升了民众对商品的认识,极大推动了商品经济发展;而广告内容、人物形象的变化也有利于民众的思想进步和观念变化,如民国新女性形象主题就有移风易俗的意义,“爱国主义”内涵的广告则有利于民族工业发展和政治运动的开展.(8分)综上所述,广告发展一定程度上有利于经济发展、思想解放和社会变迁.(2分)[论题2]商业广告人物形象的变迁(2分)近代以来,伴随学习西方文化和近代化探索的深入和发展,民族工业发展、政治革命和思想解放共同推动社会转型,圆润、摩登、甜美的女性形象成为广告设计的重要内容;建国初期,新中国成立和社会主义革命建设取得的伟大成就,人民不仅实现了当家作主的理想,也成为了社会建设的中坚力量,广告画中的人物形象也变成了以工人、农民和解放军战士为主.(8分)总之,广告人物形象的变化与时代发展和社会变迁密切相关.(2分)[论题3]商业广告形式的变迁(阐述略)[论题4] 商业广告的文化特色(阐述略) [论题5]商业广告与民众生活(阐述略)(评分标准:论题2分,阐述8分,结论2分.阐述时可选择任一示例角度展开,其他角度言之成理亦可)文科综合“二诊”参考答案第3页(共4页)42.(10分)有独特的热带风光和民俗风情,旅游资源丰富,游览价值高(2分);位于联结亚洲和大洋洲、太平洋和印度洋的“十字路口”,交通便利(2分);距中国、韩国、日本、澳大利亚等国近,市场广阔(2分);旅游服务业发达,地区接待能力强(2分);各国政府都重视旅游业的发展(国家政策的大力支持)(2分).43.(10分)问题:①排放大量酸性气体,形成酸雨污染;②可吸收颗粒物增多,大气污染加重;③大量排放温室气体,加速全球变暖.(任答两点得4分,总分不超过4分)措施:①限制石油焦的进口量与使用量;②加大科技投入,提高石油焦(能源)利用效率;③调整国内产业结构,降低能源消耗;④开发新能源,优化能源消费结构.(任答三点得6分)44.(15分)(1)前代地方治理混乱,弊端日益显现;国家政权初步统一,需要加强中央集权;统治者善于采纳大臣建议,励精图治.(每点2分,共6分)(2)结束了士族豪强垄断地方政权的局面,加强了中央集权;减轻了政府和民众的负担,提高了行政效率;为科举制的推行奠定了基础;影响了后世的行政区划及基层社会的治理.(四点以下每点2分,答出四点9分)45.(15分)(1)中国领导人为维护国家利益据理力争;牵涉到朝鲜问题;苏联表现出大国强权主义色彩.(每点2分,共6分)(2)巩固了中苏同盟但也埋下了矛盾的隐患;加速了朝鲜战争的爆发;阻碍了中国台湾问题的解决与统一大业的实现;固化了朝鲜半岛的冷战局势;强化了西方对中国的敌视.(四点以下每点2分,答出四点9分)46.(15分)(1)身份转换:第一次:从政府官吏到(官办高等学堂的)教育工作者;(2分)第二次:从(官办高等学堂的)教育工作者到民间出版企业投资者和主持人.(2分)贡献:主持编译所推动了商务印书馆的发展,为近代出版事业的发展做出了重要贡献;支持戊戌变法,编译西学著作有利于新思想的传播;出版教科书有助于教育变革.(从出版、教育、思想等角度展开,三点以下每点2分,答出三点5分)(2)戊戌变法及民主革命的兴起和发展,为张元济人生抉择及出版活动提供了有利的政治环境;近代以来民族工业和民族资本主义的持续发展,为张元济的商业出版事业提供了经济基础和保障;西学的传播和向西方学习的深入发展,为张元济编译出版创造了适宜的文化环境;张元济历经戊戌变法、辛亥革命等重大历史变革,其人生抉择几乎都与这些历史事件有关.(每点2分,任答三点6分)文科综合“二诊”参考答案第4页(共4页)。
英语 二诊 参考答案第1㊀页(共2页)成都市2015级高中毕业班第二次诊断性检测英语参考答案及评分标准第一部分㊀听力(满分30分)1~5C B A B C 6~10B C B C A 11~15B A C C B 16~20A A A C B评分标准:1~20小题,每小题1.5分.第二部分㊀阅读理解(满分40分)第一节㊀(满分30分)21~25D C C B C 26~30C A B A D 31~35B B D A D评分标准:21~35小题,每小题2分.第二节㊀(满分10分)36~40G D B F E 评分标准:36~40小题,每小题2分.第三部分㊀语言知识运用(满分45分)第一节㊀完形填空(满分30分)41~45D C A B D 46~50C A B D A 51~55C B D C B 56~60A C D B A 评分标准:41~60小题,每小题1.5分.第二节(满分15分)61.l i v i n g ㊀㊀㊀62.f i x e d ㊀㊀63.b e f o u n d ㊀㊀㊀64.c h o i c e ㊀㊀65.a d v e n t u r o u s 66.i f /w h e n 67.g o 68.i n 69.r e a d i l y 70.a评分标准:61~70小题,每小题1.5分.有任何错误,包括用词错误㊁单词拼写错误(含大小写)或语法形式错误,均不给分.第四部分㊀写作(满分35分)第一节㊀短文改错(满分10分)I h a v e a l w a y s b e e nd o i n g v o l u n t e e rw o r k ,s o b u t /y e t I h a dn e v e r r e a l l y t h o u g h t a b o u t d o i n g w o r ka b r o a d u n t i lIf o u n ds o m ei n f o r m a t i o n s i n f o r m a t i o n o nt h i ss p e c i f i ct r i p .T h e r e w a sa p i c t u r e a t t a c h i n g a t t a c h e d t oa ne Gm a i l ,w h i c hw a s s e n t r e g a r d i n g a t h e t r i p .I t s h o w e d t w o l i t t l e g i r l s t h a t t h e y \n e e d e d v o l u n t e e r s .T h e i m a g em a k e s m a d e m e f a l l i n l o v ew i t h t h e i d e a o f g o i n g s o m e w h e r e c o m p l e t e c o m p l e t e l y d i f f e r e n t f r o m m y h o m e .W h a t a t t r a c t e d m ea b o u t t h e t r i p w a s ɡt h a t i tw a s t oa p l a c e Iw o u l d n e v e r v i s i t b y m y s e l f .Iw a n t e d t o g o n o w h e r e s o m e w h e r e /a n y w h e r e t h a tw o u l dm a k em e s t e p o u t i n t o o f m y c o m f o r t z o n e .评分标准:有任何错误,包括用词错误㊁单词拼写错误(含大小写)或语法形式错误,均不给分.第二节㊀书面表达(满分25分)一㊁各档次语言要点配分参考标准档次要点数要点分语言要点表达情况划档依据第五档521~25语言基本无误,行文连贯,表达清楚第四档416~20语言有少量错误,行文基本连贯,表达基本清楚第三档311~15语言有一些错误,尚能表达第二档26~10语言错误很多,影响表达第一档10~5只能写出与要求内容有关的一些单词二㊁内容要点认定及计分参考标准1㊁恰当的开头(表达正确,计5分);2㊁环境保护的紧迫性(阐述清楚㊁表达正确,计6分);3㊁如何开展环境保护(表意清楚㊁表达正确,计7分);4㊁呼吁大家积极参与(表意清楚㊁表达正确,计4分);5㊁恰当的结尾(表达正确,计3分).三㊁扣分参考依据1㊁其表达未能达成正确句意的,不给分,如:写出了主语或谓语等关键词,但未能达成符合要点要求㊁意义正确的句子;2㊁句子结构完整㊁但关键点出现错误或漏掉部分关键词,扣半个要点分,如:主谓一致错误,或关键词拼写错误(如主语,关键性名词等),或谓语动词时态/语态错误等;3㊁凡使用铅笔答题㊁或答题中使用了涂改液或不干胶条,一律不给分;4㊁凡多次出现非关键性单词拼写错误或其它同类错误,原则上每4处扣1分;5㊁文章内容要点全面,但写出了一些多余内容(连接或过渡词句不在此列),原则上不扣分;6㊁凡书写超出规定的答题区域,全卷不给分;7㊁书写潦草凌乱㊁但基本不影响阅卷的,酌情扣卷面分1~2分.四㊁O n e p o s s i b l e v e r s i o n(略)英语 二诊 参考答案第2㊀页(共2页)。
成都市2015届高中毕业班第二次诊断性检测理科综合·物理部分第Ⅰ卷(选择题,42分)1.下列说法正确的是A电磁波是一种横波B.空间有变化的电场(或磁场)存在,一定能形成电磁波C.微波的频率高于可见光D.当物体以接近光速的速度运动时,物体的质量变化才明显,因此牛顿运动定律不仅适用于低速运动,而且适用于高速运动2.如图所示,一束复色光a由空气中斜射到上下表面平行的厚平板玻璃的上表面,穿过玻璃后分为b、c两束平行单色光从下表面射出。
关于这两束单色光,下列说法正确的是A.此玻璃对b光的折射率等于对c光的折射率B.在真空中b光的传播速度等于c光的传播速度C.在此玻璃中b光的全反射临界角大于c光的全反射临界角D.用同一双缝干涉装置进行实验,屏上b光相邻的干涉条纹间距比c光的宽3.质量m=50 kg的某同学站在观光电梯地板上,用速度传感器记录了电梯在一段时间内运动的速度随时间变化情况(以竖直向上为正方向)。
由图像提供的信息可知A.在0~15 s内,观光电梯上升的高度为25 mB.在5~15 s内,电梯地板对人的支持力做了-2500J的功C.在20~25 s与25~35 s内,观光电梯的平均速度大小均为10m/sD.在25~35 s内,观光电梯在减速上升,该同学的加速度大小2m/s24.图甲为一简谐横波在t=0时刻的波形图像,图乙为该横波中x=3 m处质点A的振动图像,则下列说法正确的是A.波的传播方向沿x轴正方向B.波的传播速度大小为1 cm/sC.在t=2. 0 s时刻,图甲中x=4 m处质点B的振动加速度大小为0D.若该波遇到尺寸大小为1m的障碍物或孔时,该波会发生明显的衍射现象5.如图所示,理想变压器原、副线圈的匝数比为10:1,电压表和电流表均为理想电表。
原线圈所接交流电源的电压随时间变化的关系是220tV2sinuπ100=,副线圈回路中的输电线1ab和cd的总电阻r=2Ω,滑动变阻器的最大阻值R=30Ω,其余输电线电阻忽略不计,则A.理想变压器输出电压的频率是100 HzB.在t=0.O1s,时,电压表V的示数为OVC.在滑动变阻器滑动触头向下滑动的过程中,电流表A 1的示数不变、电流表A Z 的示数变大D.当滑动变阻器接人电路的阻值为R=20Ω时,理想变压器的输人功率为22 W6.嫦娥三号”于2013年12月2日在中国西昌卫星发射中心由长征三号乙运载火箭送人太空,12月14日成功软着陆于月球雨海西北部,12月15日完成着陆器和巡视器分离,并陆续开展了“观天、看地、测月”,的科学探测和其它预定任务。
3题2015年成都市金牛区九年级诊断数学试题注意事项:1. 全套试卷分为A 卷和B 卷,A 卷满分100分,B 卷满分50分;考试时间120分钟。
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A 卷(共100分)一、选择题(每小题3分,共30分) 1.-6的绝对值是( )A.6B.-6C.16D.±6 2.用4个小立方块搭成如图所示的几何体,该几何体的左视图是( )3.下列交通标志中,既是轴对称图形,又是中心对称图形的是( )ABCD4.“PM 2.5”是指大气中危害健康的直径小于或等于2.5微米的颗粒物,也称为可入肺颗粒物,它们含有大量的有毒、有害物质,对人体健康和大气环境质量有很大危害,2.5微米即0.0000025米.将0.0000025用科学记数法表示为( ) A .2.5×10-7B.2.5×10-6C.25×10-7D.0.25×10-55.下列计算正确的是( )A. 532x x x =+ B. 632x x x =⋅ C. 532)(x x = D. 235x x x =÷6.函数y=2-x x中的自变量x 的取值范围是( ) A . x ≥0 B . x ≠2C . x >0D .x ≥且x ≠27.一元二次方程x 2-4x +5=0的根的情况是( ) A. 没有实数根B. 只有一个实数根C.有两个相等的实数根D.有两个不相等的实数根8.如图,已知D 、E 在△ABC 的边上,DE ∥BC ,∠B = 60°,∠AED = 40°,则∠A 的度数为( )A .100°B .90°C .80°D .70°9.如图,AB 是⊙O 的直径,若∠BAC=35°,则∠ADC=( )A .35°B .55°C .70°D .110°10.如图,在4×4的正方形网格中,每个小正方形的边长为1,若将△AOC 绕点O顺时针旋转90°得到△BOD ,则的长为( ) A.π B.1.5π C.3π D. 6π二.填空题(每小题4分,共16分) 11.分解因式:=--x x x 1242312.等腰三角形的两边长是3和5,它的周长是 .13.在某公益活动中,小明对本班同学的捐款情况进行了统计,绘制成如下不完整的统计图.其中捐100元的人数占全班总人数的25%,则本次捐款的中位数是 元.14.如图,锐角三角形ABC 中,直线PL 为BC 的垂直平分线,射线BM 为∠ABC 的平分线,PL 与BM 相交于P 点.若∠PBC =30°,∠ACP =20°,则∠A 的度数为______________°.三、解答题(本大题共6个小题,共54分) 15.(本小题满分12分,每题6分)人数捐款金额100元50元20元10元20151059题10题13题14题A BCD E8题(1) 计算:(13)-2+(π-2014)0+sin60°+|3-2| (2)求不等式组()x 3x 2412x x 13⎧--≤⎪⎨+>-⎪⎩的整数解16.(本小题8分)先化简,再求值:11)1112(+÷+--a a a ,其中31a =-17.(本小题8分)如图,热气球的探测器显示,从热气球底部A 处看一栋楼顶部的仰角为30°,看这栋楼底部的俯角为60°,热气球A 处与该楼的水平距离为120m ,求这栋楼的高.(结果精确到1m ,参考数据:3≈1.732.)18.(本小题8分)如,5,已知A (-4,12),B (-1,a )是一次函数y =12x +b 与反比例函数y =mx (m ≠0,m <0)图象的两个交点,AC ⊥x 轴于C ,BD ⊥y 轴于D . (1)求m 、a 的值及一次函数表达式;(2)P 是线段AB 上的一点,连接PC ,PD ,若△PCA 和△PDB 面积相等, 求点P 坐标.17题18题19.(本小题8分)为了解中考体育科目训练情况,某县从全县九年级学生中随机抽取了部分学生进行了一次中考体育科目测试(把测试结果分为四个等级:A 级:优秀;B 级:良好;C 级:及格;D 级:不及格),并将测试结果绘成了如右两幅不完整的统计图.请根据统计图中的信息解答下列问题: (1)本次抽样测试的学生人数是______________; (2)图1中∠α的度数是______________, 并把图2条形统计图补充完整;(3)该县九年级有学生3500名,如果全部参 加这次中考体育科目测试,请估计不及格的 人数为________.测试老师想从4位同学(分别 记为E 、F 、G 、H ,其中E 为小明)中随机选择两 位同学了解平时训练情况,请用列表或画树形图的 方法求出选中小明的概率.20.(本小题10分) 已知如图半圆O 的半径4OA =,P 是OA 延长线上一点,过线段OP 的中点B 作垂线交O 于点C ,射线PC 交O 于点D ,联结OD . (1)若=AC CD ,求∠COD 度数 (2)若=AC CD ,求弦CD 的长.(3)若点C 在AD 上时,设=PA x ,CD y =,求y 与x 的函数关系式及自变量x 的取值范围;19题图1图220题B 卷(50分)一、填空题(每小题4分,共20分)21.设一元二次方程x 2-8x+3=0的两实数根分为x 1和x 2,则x 12-11x 1-3x 2+5= .22.如图,是由四个直角边分别为3和4的全等的直角三角形拼成的“赵爽弦图”,小亮随机的往大正方形区域内投针一次,则针扎在阴影部分的概率是 .23.为确保信息安全,信息需加密传输,发送方由明文→密文(加密);接收方由密文→明文(解密).已知加密规则为:明文a ,b ,c ,d 对应的密文为a +b ,b +c ,c +d ,d +2a .例如:明文1,2,3,4对应的密文为3,5,7,6.当接收方收到密文8,11,15,15时,则解密得到的明文应为__24.如图,在矩形ABCD 中,AB 的长度为a ,BC 的长度为b ,其中b <a <b .将此矩形纸片按下列顺序折叠,则C ′D ′的长度为 (用含a 、b 的代数式表示).25.如图,在平面直角坐标系中,直线y=﹣x+1分别交x 轴、y 轴于A ,B 两点,点P (a ,b )是反比例函数y=在第一象限内的任意一点,过点P 分别作PM ⊥x 轴于点M ,PN ⊥y 轴于点N ,PM ,PN 分别交直线AB 于E ,F ,有下列结论:①AF=BE ;②图中的等腰直角三角形有4个;③S △OEF =(a+b ﹣1);④∠EOF=45°.其中结论正确的序号是 ▲ .22题 25题24题12月4月4036x (月份)p (台)20二、解答题(共3个小题,共30分) 26.(本小题满分8分)由于国家重点扶持节能环保产业,某种节能产品的销售市场逐渐回暖,某经销商销售这种产品,年初与生产厂家签订了一份进货合同,约定一年内进价为0.1万元/台.若一年内该产品的售价y (万元/台)与月份x (1≤x ≤12且为整数)满足关系式:y =⎩⎨⎧﹣0.05x +0.4(1≤x <4)0.2(4≤x ≤12),一年后,发现这一年来实际每月的销售量p (台)与月份x 之间存在如图12所示的变化趋势.(1)求实际每月的销售量p (台)与月份x 之间的函数表达式; (2)全年中哪个月份的实际销售利润w 最高,最高为多少万元?27.(本小题满分10分)已知:如图13,菱形ABCD 中,对角线AC ,BD 相交于点O ,且AC =12cm ,BD =16cm .点P 从点B 出发,沿BA 方向匀速运动,速度为1cm/s ;同时,直线EF 从点D 出发,沿DB 方向匀速运动,速度为1cm/s ,EF ⊥BD ,且与AD ,BD ,CD 分别交于点E ,Q ,F ;当直线EF 停止运动时,点P 也停止运动.连接PF ,设运动时间为t (s)(0<t <8).解答下列问题:(1)当t 为何值时,四边形APFD 是平行四边形?(2)设四边形APFE 的面积为y (cm 2),求y 与t 之间的函数关系式;(3)是否存在某一时刻t ,使S 四边形APFE :S 菱形ABCD =17:40?若存在,求出t 的值,并求出此时P ,E 两点间的距离;若不存在,请说明理由.27题26题28.(本小题满分12分)如图,在平面直角坐标系中,已知点A的坐标是(4,0),并且OA=OC=4OB,动点P在过A,B,C三点的抛物线上.(1)求抛物线的解析式;(2)是否存在点P,使得△ACP是以AC为直角边的直角三角形?若存在,求出所有符合条件的点P的坐标;若不存在,说明理由;(3)过动点P作PE垂直于y轴于点E,交直线AC于点D,过点D作x轴的垂线.垂足为F,连接EF,以线段EF的中点G为圆心,以EF为直径作⊙G,当⊙G最小时,求出点P的坐标.28题金牛区初2015级九年级诊断数学参考答案A 卷(共100分) 第Ⅰ卷(选择题 共30分)一、选择题(本大题共10个小题,每小题3分,共30分)1.A 2.A 3.C 4.B 5.D 6.D 7.A 8.C 9.B 10.B第Ⅱ卷(非选择题共70分)二、填空题(本大题共4个小题,每小题4分,共16分)11.()()26+-x x x 12.11或13 13.20 14.6.70 三、解答题(本大题共6个小题,共54分) 15. (每小题12分,每题6分) (1)解:原式=9+1+32+2-3 (12)32…… (2)解:()x 3x 24--≤得x 1≥……解12xx 13+>-得x 4<…… ∴原不等式组的解为1x 4≤<……∴原不等式组的整数解为1,2,3. 16.(本题8分) 原式221(1)(1)(1)a a a a a +-+=⨯+-+31a a +=- 当31a =-时,原式3232+=-743=--17.(本题8分)解:设过A 的水平线交楼房于点D .在Rt △ABD 中,∵∠BAD =30°,AD =120m , ∴BD =AD •tan30°=120×33=403(m).在Rt △ACD 中,∵∠CAD =60°,AD =120m ,∴CD =AD •tan60°=120×3=1203(m). ∴BC =403+1203=1603≈277(m). 答:这栋楼高约为277m . 18.(本题8分)解:(1)∵反比例函数y =m x 图象过点(-4,12),∴m =-4×12=-2.将B (-1,a )代入y =-2x ,可求a =2.∵y =12x +b 的图象过点(-4,12)∴ 一次函数的表达式是y =12x +52.(2) 连接PC 、PD ,如图,设P (x ,12x +52).由△PCA 和△PDB 面积相等得, 12×12×(x +4)=12×|-1|×(2-12x -52), 解得,x =52,∴y =12x +52=54,∴P 点坐标是(-52,54).19.解:(1)40.2分(2)54°,条形统计图中C 级为14人 ···························································· 6分 (3)700 ··········································································································· 8分 (4) 根据题意画树形图(列表略)如下:共有12种情况,选中小明的有6种,则P (选中小明)=612=12. 20.(本题10分)解:(1)36度(2)连接OC ,若当AC=CD 时,有∠DOC=∠POCCA OPDBE∵BC 垂直平分OP, ∴PC=OC=4, ∴∠P=∠POC=∠DOC ∴△DOC ∽△DPO , ∴DO DCDP DO= 设CD=y , 则16=(y+4)y ∴解得252y =-…… 即CD 的长为252-(3)延长PO 交圆于Q 点,连结AD , ∵∠PQC+∠ACD=180, ∴易证∠PCA=∠PQD∵∠P=∠P,∴△PCA ∽△PQD ∴PC PAPQ PD=, ∴4(4)(8)y x x +=+ ∴28164x x y +-= (4244x -<<)B 卷(共50分)一、填空题(本大题共5个小题,每小题4分,共20分) 21.-22 22.25123.3,5,6,9;24.3a-2b 25.②③④ 二、解答题(本大题共3个小题,共30分)26.解:(1)p =⎩⎨⎧﹣5x +40(1≤x <4且x 为整数)2x +12(4≤x ≤12且x 为整数), ····················································································· 4分(2)①当1≤x <4时,w =(-0.05x +0.4-0.1) ×(-5x +40)=14(x -6)(x -8)= 14x 2-72x +12 ························································································· 5分 ∵a =14>0,-b 2a=7>4,∴当1≤x <4时,w 随x 的增大而减小, ∴当x =1时取得w 的最大值为:14×12-144×1+12=8.75 (万元). ················································································· 6分 ②当4≤x ≤12时,w =(0.2-0.1) ×(2x +12)=15x +65∵k =15>0,∴当4≤x ≤12时,w 随x 的增大而增大, ∴当x =12时取得w 的最大值为3.6:15×12+65=3.6 (万元). ······························································································· 7分 综上得:全年中1月份的实际销售利润w 最高,为8.75万元. ···································· 8分27.解:(1)∵四边形ABCD 是菱形,∴AB ∥CD ,AC ⊥BD ,OA =OC =12AC =6,OB =OD =12BD =8.在Rt △AOB 中,AB =62+82=10. ··········································································· 1分 ∵EF ⊥BD ,∴∠FQD =∠COD =90°.又∵∠FDQ =∠CDO ,∴△DFQ ∽△DCO .∴DF DC =DQ DO .即DF 10=t 8,∴DF =54t . ············································································ 2分 ∵四边形APFD 是平行四边形,∴AP =DF .即10﹣t =54t , 解这个方程,得t =409. ∴当t =409s 时,四边形APFD 是平行四边形. ··························································· 3分(2)如图,过点C 作CG ⊥AB 于点G ,∵S 菱形ABCD =AB •CG =12AC •BD , 即10•CG =12×12×16, ∴CG =485. ∴S 梯形APFD =12(AP +DF )•CG =12(10﹣t +54t )•485=65t +48. ······································································· 4分 ∵△DFQ ∽△DCO ,∴FQ CO =DQ DO .即FQ 6=t 8,∴QF =34t . 同理,EQ =34t . ∴EF =QF +EQ =32t . ∴S △EFD =12EF •QD =12×32t ×t =34t 2. ················································································ 5分 ∴y =(65t +48)﹣34t 2=﹣34t 2+65t +48. ············································································ 6分 (3)若S 四边形APFE :S 菱形ABCD =17:40,则﹣34t 2+65t +48=1740×96, 即5t 2﹣8t ﹣48=0,解这个方程,得t 1=4,t 2=﹣125(舍去) ········································································· 7分 过点P 作PM ⊥EF 于点M ,PN ⊥BD 于点N ,当t =4时,∵△PBN ∽△ABO ,∴PN AO =PB AB =BN BO ,即PN 6=410=BN 8. ∴PN =125,BN =165. ···································································································· 8分 ∴EM =EQ ﹣MQ =3﹣125=35. PM =BD ﹣BN ﹣DQ =16﹣165﹣4=445. ······································································· 9分 在Rt △PME 中,PE =PM 2+EM 2=(445)2+(35)2=19455(cm). ························································ 10分 28.解:(1) (1)由A (4,0),可知OA =4,∵OA =OC =4OB ,∴OA =OC =4,OB =1,∴C (0,4),B (﹣1,0).设抛物线的解析式是y =ax 2+bx +x ,则,解得:,则抛物线的解析式是:y =﹣x 2+3x +4; ··························································································· 3分(2)存在.第一种情况,当以C 为直角顶点时,过点C 作CP 1⊥AC ,交抛物线于点P 1.过点P 1作y 轴的垂线,垂足是M . ∵∠ACP 1=90°,∴∠MCP 1+∠ACO =90°.∵∠ACO +∠OAC =90°,∴∠MCP 1=∠OAC .∵OA=OC,∴∠MCP1=∠OAC=45°,∴∠MCP1=∠MP1C,∴MC=MP1,设P(m,﹣m2+3m+4),则m=﹣m2+3m+4﹣4,解得:m1=0(舍去),m2=2.∴﹣m2+3m+4=6,即P(2,6). ········································································································ 6分第二种情况,当点A为直角顶点时,过A作AP2,AC交抛物线于点P2,过点P2作y轴的垂线,垂足是N,AP交y轴于点F.∴P2N∥x轴,由∠CAO=45°,∴∠OAP=45°,∴∠FP2N=45°,AO=OF.∴P2N=NF,设P2(n,﹣n2+3n+4),则n=(﹣n2+3n+4)﹣1,解得:n1=﹣2,n2=4(舍去),∴﹣n2+3n+4=﹣6,则P2的坐标是(﹣2,﹣6).综上所述,P的坐标是(2,6)或(﹣2,﹣6);……………………………8分(3)连接OD,由题意可知,四边形OFDE是矩形,则OD=EF.根据垂线段最短,可得当OD⊥AC时,OD最短,即EF最短.由(1)可知,在直角△AOC中,OC=OA=4,则AC==4,根据等腰三角形的性质,D是AC的中点.又∵DF∥OC,∴DF=OC=2,∴点P的纵坐标是2.则﹣x2+3x+1=2,解得:x=,∴当EF最短时,圆最小。