2.1×105MPa)。
解:H0=2.5mm,H=1.0mm,h=0.7mm
−
2.5−1.0
0 −ℎ
2.5−0.7
0 = 0 = 2.5 = 60%, 1 =
= 2.5 = 72%
0
0
ҧ = 0.40 + 0.61 = 0.4 × 60% + 0.6 × 72% = 67.2%
= ×(+) = . s-1
= 85 ∙ 0.124 ∙ (10)0.167 ∙ (
=85× 9.350.124
=122.4MPa
∙ 10 × 35.4%
)−2.5410来自00.167∙
1050 −2.54
1000
,计算轧
K = 1.15 = 1.15 × 122.4 = 140.8MPa
3 在φ750/φ1050×1700mm热轧机上,轧制Q235普碳钢,其变形抗力模型采用下
0.124
0.167
∙ (10)
∙(
)−2.54 ,某道次轧制温度
式计算: = 85 ∙
1000
为1050℃,轧件轧制前厚度H=65mm,轧后厚度h=42mm,板宽B=1200mm,轧
制速度v=2m/s。应力状态系数
例题2:在φ850mm轧机上,轧制Q235普碳钢,某道次轧制温度为1100℃,
轧件轧制前厚度H=93mm,轧后厚度h=64.2mm,板宽B=610mm,轧
制速度v=2m/s。试用西姆斯公式计算轧制力,并求此时轧制力矩多大。
(忽略宽展,变形速率 =
)
+
解:
l = ∙ ∆ℎ =
ℎത
0.85
= =