C语言程序设计教程 课后答案4(周争鸣版)

C语言程序设计(谭浩强)第四版-课后答案解析(总70页)--本页仅作为文档封面，使用时请直接删除即可----内页可以根据需求调整合适字体及大小--第一章程序设计和C语言【第15页】1-5#include <>int main ( ){ printf ("**************************\n\n");printf(" Very Good!\n\n");printf ("**************************\n");return 0;}1-6#include <>int main(){int a,b,c,max;printf("please input a,b,c:\n");scanf("%d,%d,%d",&a,&b,&c);max=a;if (max<b)max=b;if (max<c)max=c;printf("The largest number is %d\n",max);return 0;}第2章算法——程序的灵魂【第36页】暂无答案第3章最简单的C程序设计——顺序程序设计【第82页】3-1#include <>#include <>int main(){float p,r,n;r=;n=10;p=pow(1+r,n);printf("p=%f\n",p);return 0;}3-2-1#include <>#include <>int main(){float r5,r3,r2,r1,r0,p,p1,p2,p3,p4,p5; p=1000;r5=;r3=;r2=;r1=;r0=;p1=p*((1+r5)*5); #include <> #include <>int main(){float d=300000,p=6000,r=,m;m=log10(p/(p-d*r))/log10(1+r);printf("m=%\n",m);return 0;}3-4#include <>int main(){int c1,c2;c1=197;c2=198;printf("c1=%c,c2=%c\n",c1,c2);printf("c1=%d，c2=%d\n",c1,c2);return 0;}3-5#include <>int main(){int a,b;float x,y;char c1,c2;scanf("a=%d b=%d",&a,&b);scanf("%f %e",&x,&y);scanf("%c%c",&c1,&c2);printf("a=%d,b=%d,x=%f,y=%f,c1=%c,c2=%c\n",a,b,x,y,c1,c2); return 0;}3-6#include <>int main(){char c1='C',c2='h',c3='i',c4='n',c5='a';c1=c1+4;c2=c2+4;c3=c3+4;c4=c4+4;c5=c5+4;printf("passwor is %c%c%c%c%c\n",c1,c2,c3,c4,c5);return 0;}3-7#include <>int main (){float h,r,l,s,sq,vq,vz;float pi=;printf("请输入圆半径r，圆柱高h∶");scanf("%f,%f",&r,&h); #include <>int main(){ int x,y;printf("输入x:");scanf("%d",&x);if(x<1) /* x<1 */{ y=x;printf("x=%3d, y=x=%d\n" ,x,y);}else if(x<10) /* 1=<x<10 */{ y=2*x-1;printf("x=%d, y=2*x-1=%d\n",x,y);}else /* x>=10 */{ y=3*x-11;printf("x=%d, y=3*x-11=%d\n",x,y);}return 0;}4-7-1#include <>int main(){int x,y;printf("enter x:");scanf("%d",&x);y=-1;if(x!=0)if(x>0)y=1;elsey=0;printf("x=%d,y=%d\n",x,y); return 0;}4-7-2#include <>int main(){int x,y;printf("please enter x:");scanf("%d",&x);y=0;if(x>=0)if(x>0) y=1;else y=-1;printf("x=%d,y=%d\n",x,y); return 0;}4-8#include <>int main(){ float score;char grade;printf("请输入学生成绩:"); scanf("%f",&score);while (score>100||score<0){printf("\n 输入有误,请重输");scanf("%f",&score);}switch((int)(score/10)){case 10:case 9: grade='A';break;case 8: grade='B';break;case 7: grade='C';break;case 6: grade='D';break;case 5:case 4:case 3:case 2:case 1:case 0: grade='E';}printf("成绩是 %,相应的等级是%c\n ",score,grade);return 0;}4-9#include <>#include <>int main(){int num,indiv,ten,hundred,thousand,ten_thousand,place; .=%d\n",sn); return 0;}5-6#include <>int main(){double s=0,t=1;int n;for (n=1;n<=20;n++){t=t*n;s=s+t;}printf("1!+2!+...+20!=%\n",s);return 0;}5-7#include <>int main(){int n1=100,n2=50,n3=10;double k,s1=0,s2=0,s3=0;for (k=1;k<=n1;k++) /*计算1到100的和*/{s1=s1+k;}for (k=1;k<=n2;k++) /*计算1到50各数的平方和*/ {s2=s2+k*k;}for (k=1;k<=n3;k++) /*计算1到10的各倒数和*/ {s3=s3+1/k;}printf("sum=%\n",s1+s2+s3);return 0;}5-8#include <>int main(){int i,j,k,n;printf("parcissus numbers are ");for (n=100;n<1000;n++){i=n/100;j=n/10-i*10;k=n%10;if (n==i*i*i + j*j*j + k*k*k)printf("%d ",n);}printf("\n");return 0;}5-9-1#define M 1000 /*定义寻找范围*/#include <>int main(){int k1,k2,k3,k4,k5,k6,k7,k8,k9,k10;int i,a,n,s;for (a=2;a<=M;a++) /* a是2-1000之间的整数，检查它是否完数 */{n=0; /* n用来累计a的因子的个数 */s=a; /* s用来存放尚未求出的因子之和，开始时等于a */for (i=1;i<a;i++) /* 检查i是否a的因子 */if (a%i==0) /* 如果i是a的因子 */{n++; /* n加1，表示新找到一个因子 */s=s-i; /* s减去已找到的因子，s的新值是尚未求出的因子之和 */ switch(n) /* 将找到的因子赋给k1...k9，或k10 */{case 1:k1=i; break; /* 找出的笫1个因子赋给k1 */case 2:k2=i; break; /* 找出的笫2个因子赋给k2 */case 3:k3=i; break; /* 找出的笫3个因子赋给k3 */case 4:k4=i; break; /* 找出的笫4个因子赋给k4 */case 5:k5=i; break; /* 找出的笫5个因子赋给k5 */case 6:k6=i; break; /* 找出的笫6个因子赋给k6 */case 7:k7=i; break; /* 找出的笫7个因子赋给k7 */case 8:k8=i; break; /* 找出的笫8个因子赋给k8 */case 9:k9=i; break; /*找出的笫9个因子赋给k9 */case 10:k10=i; break; /* 找出的笫10个因子赋给k10 */}}if (s==0){printf("%d ,Its factors are ",a);if (n>1) printf("%d,%d",k1,k2); /* n>1表示a至少有2个因子 */if (n>2) printf(",%d",k3); /* n>2表示至少有3个因子，故应再输出一个因子 */if (n>3) printf(",%d",k4); /* n>3表示至少有4个因子，故应再输出一个因子 */if (n>4) printf(",%d",k5); /* 以下类似 */if (n>5) printf(",%d",k6);if (n>6) printf(",%d",k7);if (n>7) printf(",%d",k8);if (n>8) printf(",%d",k9);if (n>9) printf(",%d",k10);printf("\n");}}return 0;}5-9-2#include <>int main(){int m,s,i;for (m=2;m<1000;m++){s=0;for (i=1;i<m;i++)if ((m%i)==0) s=s+i;if(s==m){printf("%d,its factors are ",m); for (i=1;i<m;i++)if (m%i==0) printf("%d ",i); printf("\n");}}return 0;}5-10#include <>int main(){int i,n=20;double a=2,b=1,s=0,t;for (i=1;i<=n;i++){s=s+a/b;t=a,a=a+b,b=t;}printf("sum=%\n",s);return 0;}5-11#include <>int main(){double sn=100,hn=sn/2;int n;for (n=2;n<=10;n++){sn=sn+2*hn; /*第n次落地时共经过的米数*/hn=hn/2; /*第n次反跳高度*/}printf("第10次落地时共经过%f米\n",sn);printf("第10次反弹%f米\n",hn);return 0;}5-12#include <>int main(){int day,x1,x2;day=9;x2=1;while(day>0){x1=(x2+1)*2; /*第1天的桃子数是第2天桃子数加1后的2倍.*/ x2=x1;day--;}printf("total=%d\n",x1);return 0;}5-13#include <>#include <>int main(){float a,x0,x1;printf("enter a positive number:");scanf("%f",&a);x0=a/2;x1=(x0+a/x0)/2;dox1=(x0+a/x0)/2;}while(fabs(x0-x1)>=1e-5);printf("The square root of % is %\n",a,x1); return 0;}5-14#include <>#include <>int main(){double x1,x0,f,f1;x1=;do{x0=x1;f=((2*x0-4)*x0+3)*x0-6;f1=(6*x0-8)*x0+3;x1=x0-f/f1;}while(fabs(x1-x0)>=1e-5);printf("The root of equation is %\n",x1); return 0;}5-15#include <>#include <>int main(){float x0,x1,x2,fx0,fx1,fx2;do{printf("enter x1 & x2:");scanf("%f,%f",&x1,&x2);fx1=x1*((2*x1-4)*x1+3)-6;fx2=x2*((2*x2-4)*x2+3)-6;}while(fx1*fx2>0);do{x0=(x1+x2)/2;fx0=x0*((2*x0-4)*x0+3)-6;if ((fx0*fx1)<0){x2=x0;fx2=fx0;}else{x1=x0;}}while(fabs (fx0)>=1e-5);printf("x=%\n",x0);return 0;}5-16#include <>int main(){int i,j,k;for (i=0;i<=3;i++){for (j=0;j<=2-i;j++)printf(" ");for (k=0;k<=2*i;k++)printf("*");printf("\n");}for (i=0;i<=2;i++){for (j=0;j<=i;j++)printf(" ");for (k=0;k<=4-2*i;k++)printf("*");printf("\n");}return 0;}5-17#include <>int main(){char i,j,k; /*是a的对手;j是b的对手;k是c的对手*/ for (i='x';i<='z';i++)for (j='x';j<='z';j++)if (i!=j)for (k='x';k<='z';k++)if (i!=k && j!=k)if (i!='x' && k!='x' && k!='z')printf("A--%c\nB--%c\nC--%c\n",i,j,k);return 0;}第6章利用数组处理批量数据【第168页】6-1#include <>#include <>int main(){int i,j,n,a[101];for (i=1;i<=100;i++)a[i]=i;a[1]=0;for (i=2;i<sqrt(100);i++)for (j=i+1;j<=100;j++){if(a[i]!=0 && a[j]!=0)if (a[j]%a[i]==0)a[j]=0;}printf("\n");for (i=2,n=0;i<=100;i++){ if(a[i]!=0){printf("%5d",a[i]);n++;}if(n==10){printf("\n");n=0;}}printf("\n");return 0;}6-2#include <>int main(){int i,j,min,temp,a[11];printf("enter data:\n");for (i=1;i<=10;i++){printf("a[%d]=",i);scanf("%d",&a[i]);}printf("\n");printf("The orginal numbers:\n");for (i=1;i<=10;i++)printf("%5d",a[i]);printf("\n");for (i=1;i<=9;i++){min=i;for (j=i+1;j<=10;j++)if (a[min]>a[j]) min=j;temp=a[i];a[i]=a[min];a[min]=temp;}printf("\nThe sorted numbers:\n");for (i=1;i<=10;i++)printf("%5d",a[i]);printf("\n");return 0;}6-3#include <>int main(){int a[3][3],sum=0;int i,j;printf("enter data:\n");for (i=0;i<3;i++)for (j=0;j<3;j++)scanf("%3d",&a[i][j]);for (i=0;i<3;i++)sum=sum+a[i][i];printf("sum=%6d\n",sum);return 0;}6-4#include <>int main(){ int a[11]={1,4,6,9,13,16,19,28,40,100}; int temp1,temp2,number,end,i,j;printf("array a:\n");for (i=0;i<10;i++)printf("%5d",a[i]);printf("\n");printf("insert data:");scanf("%d",&number);end=a[9];if (number>end)a[10]=number;else{for (i=0;i<10;i++){if (a[i]>number){temp1=a[i];a[i]=number;for (j=i+1;j<11;j++){temp2=a[j];a[j]=temp1;temp1=temp2;}break;}}}printf("Now array a:\n");for (i=0;i<11;i++)printf("%5d",a[i]);printf("\n");return 0;}6-5#include <>#define N 5int main(){ int a[N],i,temp;printf("enter array a:\n");for (i=0;i<N;i++)scanf("%d",&a[i]);printf("array a:\n");for (i=0;i<N;i++)printf("%4d",a[i]);for (i=0;i<N/2;i++) n",number);;printf("continu or not(Y/N)"); scanf(" %c",&c);if (c=='N'||c=='n')flag=0;}return 0;}6-10#include <>int main(){int i,j,upp,low,dig,spa,oth;char text[3][80];upp=low=dig=spa=oth=0;for (i=0;i<3;i++){ printf("please input line %d:\n",i+1); gets(text[i]);for (j=0;j<80 && text[i][j]!='\0';j++){if (text[i][j]>='A'&& text[i][j]<='Z')upp++;else if (text[i][j]>='a' && text[i][j]<='z') low++;else if (text[i][j]>='0' && text[i][j]<='9') dig++;else if (text[i][j]==' ')spa++;elseoth++;}}printf("\nupper case: %d\n",upp);printf("lower case: %d\n",low);printf("digit : %d\n",dig);printf("space : %d\n",spa);printf("other : %d\n",oth);return 0;}6-11#include <>int main(){ char a[5]={'*','*','*','*','*'};int i,j,k;char space=' ';for (i=0;i<5;i++){ printf("\n");printf(" ");for (j=1;j<=i;j++)printf("%c",space);for (k=0;k<5;k++)printf("%c",a[k]);}printf("\n");return 0;}6-12a-c#include <>int main(){ int j,n;char ch[80],tran[80];printf("input cipher code:");gets(ch);printf("\ncipher code :%s",ch);j=0;while (ch[j]!='\0'){ if ((ch[j]>='A') && (ch[j]<='Z'))tran[j]=155-ch[j];else if ((ch[j]>='a') && (ch[j]<='z')) tran[j]=219-ch[j];elsetran[j]=ch[j];j++;}n=j;printf("\noriginal text:");for (j=0;j<n;j++)putchar(tran[j]);printf("\n");return 0;}6-12b#include <>int main(){int j,n;char ch[80];printf("input cipher code:\n");gets(ch);printf("\ncipher code:%s\n",ch); j=0;while (ch[j]!='\0'){ if ((ch[j]>='A') && (ch[j]<='Z'))ch[j]=155-ch[j];else if ((ch[j]>='a') && (ch[j]<='z')) ch[j]=219-ch[j];elsech[j]=ch[j];j++;}n=j;printf("original text:");for (j=0;j<n;j++)putchar(ch[j]);printf("\n");return 0;}6-13#include <>int main(){ char s1[80],s2[40];int i=0,j=0;printf("input string1:");scanf("%s",s1);printf("input string2:");scanf("%s",s2);while (s1[i]!='\0')i++;while(s2[j]!='\0')s1[i++]=s2[j++];s1[i]='\0';printf("\nThe new string is:%s\n",s1); return 0;}6-14#include <>int main(){ int i,resu;char s1[100],s2[100];printf("input string1:");gets(s1);printf("\ninput string2:");gets(s2);i=0;while ((s1[i]==s2[i]) && (s1[i]!='\0'))i++;if (s1[i]=='\0' && s2[i]=='\0')resu=0;elseresu=s1[i]-s2[i];printf("\nresult:%d.\n",resu);return 0;}6-15#include <>#include <>int main(){ char s1[80],s2[80];int i;printf("input s2:");scanf("%s",s2);for (i=0;i<=strlen(s2);i++)s1[i]=s2[i];printf("s1:%s\n",s1);return 0;}第7章用函数实现模块化程序设计【第218页】7-1-1#include <>int main(){int hcf(int,int);int lcd(int,int,int);int u,v,h,l;scanf("%d,%d",&u,&v);h=hcf(u,v);printf("",h);l=lcd(u,v,h);printf("",l);return 0;}int hcf(int u,int v){int t,r;if (v>u){t=u;u=v;v=t;}while ((r=u%v)!=0){u=v;v=r;}return(v);}int lcd(int u,int v,int h) {return(u*v/h);}7-1-2#include <>int Hcf,Lcd;int main(){void hcf(int,int);void lcd(int,int);int u,v;scanf("%d,%d",&u,&v); hcf(u,v);lcd(u,v);printf("",Hcf);printf("",Lcd);return 0;}void hcf(int u,int v) {int t,r;if (v>u){t=u;u=v;v=t;}while ((r=u%v)!=0){u=v;v=r;}Hcf=v;}void lcd(int u,int v){Lcd=u*v/Hcf;}7-2#include <>#include <>float x1,x2,disc,p,q;int main(){void greater_than_zero(float,float);void equal_to_zero(float,float);void smaller_than_zero(float,float);float a,b,c;printf("input a,b,c:");scanf("%f,%f,%f",&a,&b,&c);printf("equation: %*x*x+%*x+%=0\n",a,b,c); disc=b*b-4*a*c;printf("root:\n");if (disc>0){greater_than_zero(a,b);printf("x1=%f\t\tx2=%f\n",x1,x2);}else if (disc==0){equal_to_zero(a,b);printf("x1=%f\t\tx2=%f\n",x1,x2);}else{smaller_than_zero(a,b);printf("x1=%f+%fi\tx2=%f-%fi\n",p,q,p,q); }return 0;}void greater_than_zero(float a,float b){x1=(-b+sqrt(disc))/(2*a);x2=(-b-sqrt(disc))/(2*a);}void equal_to_zero(float a,float b){x1=x2=(-b)/(2*a);}void smaller_than_zero(float a,float b) {p=-b/(2*a);q=sqrt(-disc)/(2*a);}7-3#include <>int main(){int prime(int);int n;printf("input an integer:");scanf("%d",&n);if (prime(n))printf("%d is a prime.\n",n);elseprintf("%d is not a prime.\n",n);return 0;}int prime(int n){int flag=1,i;for (i=2;i<n/2 && flag==1;i++)if (n%i==0)flag=0;return(flag);}7-4#include <>#define N 3int array[N][N];int main(){ void convert(int array[][3]);int i,j;printf("input array:\n");for (i=0;i<N;i++)for (j=0;j<N;j++)scanf("%d",&array[i][j]);printf("\noriginal array :\n");for (i=0;i<N;i++){for (j=0;j<N;j++)printf("%5d",array[i][j]);printf("\n");}convert(array);printf("convert array:\n");for (i=0;i<N;i++){for (j=0;j<N;j++)printf("%5d",array[i][j]);printf("\n");}return 0;}void convert(int array[][3]){int i,j,t;for (i=0;i<N;i++)for (j=i+1;j<N;j++){t=array[i][j];array[i][j]=array[j][i];array[j][i]=t;}}#include <>#include <>int main(){void inverse(char str[]);char str[100];printf("input string:");scanf("%s",str);inverse(str);printf("inverse string:%s\n",str);return 0;}void inverse(char str[]){char t;int i,j;for (i=0,j=strlen(str);i<(strlen(str)/2);i++,j--) {t=str[i];str[i]=str[j-1];str[j-1]=t;}}7-6#include <>int main(){void concatenate(char string1[],char string2[],char string[]); char s1[100],s2[100],s[100];printf("input string1:");scanf("%s",s1);printf("input string2:");scanf("%s",s2);concatenate(s1,s2,s);printf("\nThe new string is %s\n",s);return 0;}void concatenate(char string1[],char string2[],char string[]) {int i,j;for (i=0;string1[i]!='\0';i++)string[i]=string1[i];for(j=0;string2[j]!='\0';j++)string[i+j]=string2[j];string[i+j]='\0';}7-7#include <>int main(){void cpy(char [],char []);char str[80],c[80];printf("input string:");gets(str);cpy(str,c);printf("The vowel letters are:%s\n",c);return 0;}void cpy(char s[],char c[])for (i=0,j=0;s[i]!='\0';i++)if (s[i]=='a'||s[i]=='A'||s[i]=='e'||s[i]=='E'||s[i]=='i'|| s[i]=='I'||s[i]=='o'||s[i]=='O'||s[i]=='u'||s[i]=='U'){c[j]=s[i];j++;}c[j]='\0';}7-8#include <>#include <>int main(){char str[80];void insert(char []);printf("input four digits:");scanf("%s",str);insert(str);return 0;}void insert(char str[]){int i;for (i=strlen(str);i>0;i--){str[2*i]=str[i];str[2*i-1]=' ';}printf("output:\n%s\n",str);}7-9#include <>int letter,digit,space,others;int main(){void count(char []);char text[80];printf("input string:\n");gets(text);printf("string:");puts(text);letter=0;digit=0;others=0;count(text);printf("\nletter:%d\ndigit:%d\nspace:%d\nothers:%d\n",letter,digit,space,others); return 0;}void count(char str[]){int i;for (i=0;str[i]!='\0';i++)if ((str[i]>='a'&& str[i]<='z')||(str[i]>='A' && str[i]<='Z'))letter++;else if (str[i]>='0' && str [i]<='9')digit++;else if (str[i]==32)space++;elseothers++;}7-10#include <>#include <>int main(){int alphabetic(char);int longest(char []);int i;char line[100];printf("input one line:\n");gets(line);printf("The longest word is :");for (i=longest(line);alphabetic(line[i]);i++)printf("%c",line[i]);printf("\n");return 0;}int alphabetic(char c){if ((c>='a' && c<='z')||(c>='A'&&c<='z'))return(1);elsereturn(0);}int longest(char string[]){int len=0,i,length=0,flag=1,place=0,point; for (i=0;i<=strlen(string);i++)if (alphabetic(string[i]))if (flag){point=i;flag=0;}elselen++;else{flag=1;if (len>=length){length=len;place=point;len=0;}}return(place);}7-11#include <>#include <>#define N 10char str[N];int main(){void sort(char []);int i,flag;for (flag=1;flag==1;){printf("input string:\n");scanf("%s",&str);if (strlen(str)>N)printf("string too long,input again!"); elseflag=0;}sort(str);printf("string sorted:\n");for (i=0;i<N;i++)printf("%c",str[i]);printf("\n");return 0;}void sort(char str[]){int i,j;char t;for(j=1;j<N;j++)for (i=0;(i<N-j)&&(str[i]!='\0');i++)if(str[i]>str[i+1]){t=str[i];str[i]=str[i+1];str[i+1]=t;}}7-12#include <>#include <>int main(){float solut(float a,float b,float c,float d); float a,b,c,d;printf("input a,b,c,d:");scanf("%f,%f,%f,%f",&a,&b,&c,&d);printf("x=%\n",solut(a,b,c,d));return 0;}float solut(float a,float b,float c,float d) {float x=1,x0,f,f1;do{x0=x;f=((a*x0+b)*x0+c)*x0+d;f1=(3*a*x0+2*b)*x0+c;x=x0-f/f1;}while(fabs(x-x0)>=1e-3);return(x);}7-13#include <>#define N 10#define M 5float score[N][M];float a_stu[N],a_cour[M];int r,c;int main(){ int i,j;float h;float s_var(void);float highest();void input_stu(void);void aver_stu(void);void aver_cour(void);input_stu();aver_stu();aver_cour();printf("\n NO. cour1 cour2 cour3 cour4 cour5 aver\n"); for(i=0;i<N;i++){printf("\n NO %2d ",i+1);for(j=0;j<M;j++)printf("%",score[i][j]);printf("%\n",a_stu[i]);}printf("\naverage:");for (j=0;j<M;j++)printf("%",a_cour[j]);printf("\n");h=highest();printf("highest:% NO. %2d course %2d\n",h,r,c);printf("variance %\n",s_var());return 0;}void input_stu(void){int i,j;for (i=0;i<N;i++){printf("\ninput score of student%2d:\n",i+1);for (j=0;j<M;j++)scanf("%f",&score[i][j]);}}void aver_stu(void){int i,j;float s;for (i=0;i<N;i++){for (j=0,s=0;j<M;j++)s+=score[i][j];a_stu[i]=s/;}}void aver_cour(void){int i,j;float s;for (j=0;j<M;j++){s=0;for (i=0;i<N;i++)s+=score[i][j];a_cour[j]=s/(float)N;}}float highest(){float high;int i,j;high=score[0][0];for (i=0;i<N;i++)for (j=0;j<M;j++)if (score[i][j]>high){high=score[i][j];r=i+1;c=j+1;}return(high);}float s_var(void){int i;float sumx,sumxn;sumx=;sumxn=;for (i=0;i<N;i++){sumx+=a_stu[i]*a_stu[i];sumxn+=a_stu[i];}return(sumx/N-(sumxn/N)*(sumxn/N)); }7-14#include <>#define N 10#define M 5float score[N][M];float a_stu[N],a_cour[M];int r,c;int main(){ int i,j;float h;float s_var(void);float highest();void input_stu(void);void aver_stu(void);void aver_cour(void);input_stu();aver_stu();aver_cour();printf("\n NO. cour1 cour2 cour3 cour4 cour5 aver\n"); for(i=0;i<N;i++){printf("\n NO %2d ",i+1);for(j=0;j<M;j++)printf("%",score[i][j]);printf("%\n",a_stu[i]);}printf("\naverage:");for (j=0;j<M;j++)printf("%",a_cour[j]);printf("\n");h=highest();printf("highest:% NO. %2d course %2d\n",h,r,c);printf("variance %\n",s_var());return 0;}void input_stu(void){int i,j;for (i=0;i<N;i++){printf("\ninput score of student%2d:\n",i+1);for (j=0;j<M;j++)scanf("%f",&score[i][j]); }}void aver_stu(void){int i,j;float s;for (i=0;i<N;i++){for (j=0,s=0;j<M;j++)s+=score[i][j];a_stu[i]=s/;}}void aver_cour(void){int i,j;float s;for (j=0;j<M;j++){s=0;for (i=0;i<N;i++)s+=score[i][j];a_cour[j]=s/(float)N;}}float highest(){float high;int i,j;high=score[0][0];for (i=0;i<N;i++)for (j=0;j<M;j++)if (score[i][j]>high){high=score[i][j];r=i+1;c=j+1;}return(high);}float s_var(void){int i;float sumx,sumxn;sumx=;sumxn=;for (i=0;i<N;i++){sumx+=a_stu[i]*a_stu[i];sumxn+=a_stu[i];}return(sumx/N-(sumxn/N)*(sumxn/N)); }7-15#include <>#include <>#define N 10int main(){void input(int [],char name[][8]);void sort(int [],char name[][8]);void search(int ,int [],char name[][8]);int num[N],number,flag=1,c;char name[N][8];input(num,name);sort(num,name);while (flag==1){printf("\ninput number to look for:");scanf("%d",&number);search(number,num,name);printf("continue ot not(Y/N)");getchar();c=getchar();if (c=='N'||c=='n')flag=0;}return 0;}void input(int num[],char name[N][8]){int i;for (i=0;i<N;i++){printf("input NO.: ");scanf("%d",&num[i]);printf("input name: ");getchar();gets(name[i]);}}void sort(int num[],char name[N][8]){ int i,j,min,templ;char temp2[8];for (i=0;i<N-1;i++){min=i;for (j=i;j<N;j++)if (num[min]>num[j]) min=j;templ=num[i];strcpy(temp2,name[i]);num[i]=num[min];strcpy (name[i],name[min]);num[min]=templ;strcpy(name[min],temp2);}printf("\n result:\n");for (i=0;i<N;i++)printf("\n %5d%10s",num[i],name[i]);}void search(int n,int num[],char name[N][8]){int top,bott,mid,loca,sign;top=0;bott=N-1;loca=0;sign=1;if ((n<num[0])||(n>num[N-1]))loca=-1;while((sign==1) && (top<=bott)){mid=(bott+top)/2;if (n==num[mid]){loca=mid;printf("NO. %d , his name is %s.\n",n,name[loca]);sign=-1;}else if (n<num[mid])bott=mid-1;elsetop=mid+1;}if (sign==1 || loca==-1)printf("%d not been found.\n",n);}。

C语言程序设计教程课后习题答案第一章C语言程序设计概述－习题答案1算法的描述有哪些基本方法？答1、自然语言2、专用工具2C语言程序的基本结构是怎样的？举一个例子说明。

答1、C语言程序由函数构成；2、“/*”与“*/”之间的内容构成C语言程序的注释部分；3、用预处理命令#include、#define可以包含有关文件或预定义信息；4、大小写字母在C语言中是有区别的；5、除main()函数和标准库函数外，用户也可以自己编写函数，应用程序一般由多个函数组成，这些函数指定实际所需要做的工作。

3C语言有什么特点？答1、具有结构语言的特点，程序之间很容易实现段的共享；2、主要结构成分为函数，函数可以在程序中被定义完成独立的任务，独立地编译代码，以实现程序的模块化；3、运算符丰富，包含的范围很广；4、数据类型丰富；5、允许直接访问物理地址，即可直接对硬件进行损伤，实现汇编语言的大部分功能；6、限制不太严格，程序设计自由度大，这样使C语言能够减少对程序员的束缚；7、生成的目标代码质量，程序执行效率高，同时C语言编写的程序的可移植性好。

4★指出合法与不合法的标识符命名。

答AB12--√ leed_3-- a*b2--× 8stu--× D.K.Jon--× EF3_3--√ PAS--√ if--×XYZ43K2--√ AVE#XY--× _762--√ #_DT5--× C.D--×5说明下列Turbo C热键的功能。

答F2:源文件存盘 F10:调用主菜单 F4:程序运行到光标所在行（用于调试程序）Ctrl+F9:编译并链接成可执行文件 Alt+F5:将窗口切换到 DOS 下，查看程序运行结果。

6说明下列Turbo C方式下输入并运行下列程序，记录下运行结果。

①main(){printf("********************\n");printf(" welcome you \n");printf(" very good \n);printf("********************\n");}②main(){ int a,b,c,t;printf("please input three numbers;");scanf("%d,%d,%d",&a,&b,&c); /*教材S是错误的*/t=max(max(a,b),c);printf("max number is:%d\n",t);}int max(int x, int y){ int z;if(x>y)z=x;else z=y;return(z);}答运行结果：********************welcome youvery good********************运行结果：please input three numbers;3,1,4 /*左侧下划线内容为键盘输入*/max number is:47一个C程序是由若干个函数构成的，其中有且只能有一个＿＿＿函数。

C程序设计第四版习题完整版答案排版整洁集团标准化办公室：[VV986T-J682P28-JP266L8-68PNN]第1章程序设计和C语言1什么是计算机程序1什么是计算机语言1语言的发展及其特点3最简单的C语言程序5最简单的C语言程序举例6语言程序的结构10运行C程序的步骤与方法12程序设计的任务141-5 #include <>int main ( ){ printf ("**************************\n\n"); printf(" Very Good!\n\n");printf ("**************************\n"); return 0;}1-6#include <>int main(){int a,b,c,max;printf("please input a,b,c:\n");scanf("%d,%d,%d",&a,&b,&c);max=a;if (max<b)max=b;if (max<c)max=c;printf("The largest number is %d\n",max); return 0;}第2章算法——程序的灵魂16什么是算法16简单的算法举例17算法的特性21怎样表示一个算法22S流程图表示算法28结构化程序设计方法34习题36第章最简单的C程序设计——顺序程序设计37 顺序程序设计举例37数据的表现形式及其运算39语句57数据的输入输出65 习题823-1 #include <>#include <>int main(){float p,r,n;r=;n=10;p=pow(1+r,n);printf("p=%f\n",p);return 0;}3-2-1#include <>#include <>int main(){float r5,r3,r2,r1,r0,p,p1,p2,p3,p4,p5; p=1000;r5=;r3=;r2=;r1=;r0=;p1=p*((1+r5)*5); #include <> #include <>int main(){float d=300000,p=6000,r=,m;m=log10(p/(p-d*r))/log10(1+r);printf("m=%\n",m);return 0;}3-4#include <>int main(){int c1,c2;c1=197;c2=198;printf("c1=%c,c2=%c\n",c1,c2); printf("c1=%d，c2=%d\n",c1,c2); return 0;}3-5#include <>int main(){int a,b;float x,y;char c1,c2;scanf("a=%d b=%d",&a,&b);scanf("%f %e",&x,&y);scanf("%c%c",&c1,&c2);printf("a=%d,b=%d,x=%f,y=%f,c1=%c,c2=%c\n",a,b,x,y,c1,c2); return 0;}3-6#include <>int main(){char c1='C',c2='h',c3='i',c4='n',c5='a';c1=c1+4;c2=c2+4;c3=c3+4;c4=c4+4;c5=c5+4;printf("passwor is %c%c%c%c%c\n",c1,c2,c3,c4,c5);return 0;}3-7#include <>int main (){float h,r,l,s,sq,vq,vz;float pi=;printf("请输入圆半径r，圆柱高h∶");scanf("%f,%f",&r,&h); #include <> int main(){ int x,y;printf("输入x:");scanf("%d",&x);if(x<1) /* x<1 */{ y=x;printf("x=%3d, y=x=%d\n" ,x,y);}else if(x<10) /* 1=<x<10 */{ y=2*x-1;printf("x=%d, y=2*x-1=%d\n",x,y); }else /* x>=10 */{ y=3*x-11;printf("x=%d, y=3*x-11=%d\n",x,y); }return 0;}4-7-1#include <>int main(){int x,y;printf("enter x:");scanf("%d",&x);y=-1;if(x>0)y=1;elsey=0;printf("x=%d,y=%d\n",x,y); return 0;}4-7-2#include <>int main(){int x,y;printf("please enter x:"); scanf("%d",&x);y=0;if(x>0) y=1;else y=-1;printf("x=%d,y=%d\n",x,y); return 0;}4-8#include <>int main(){ float score;char grade;printf("请输入学生成绩:"); scanf("%f",&score);while (score>100||score<0) {printf("\n 输入有误,请重输"); scanf("%f",&score);switch((int)(score/10)){case 10:case 9: grade='A';break;case 8: grade='B';break;case 7: grade='C';break;case 6: grade='D';break;case 5:case 4:case 3:case 2:case 1:case 0: grade='E';}printf("成绩是 %,相应的等级是%c\n ",score,grade); return 0;4-9#include <>#include <>int main(){int num,indiv,ten,hundred,thousand,ten_thousand,place; .=%d\n",sn); return 0;}5-6#include <>int main(){double s=0,t=1;int n;for (n=1;n<=20;n++){t=t*n;s=s+t;}printf("1!+2!+...+20!=%\n",s);return 0;}5-7#include <>int main(){int n1=100,n2=50,n3=10;double k,s1=0,s2=0,s3=0;for (k=1;k<=n1;k++) /*计算1到100的和*/{s1=s1+k;}for (k=1;k<=n2;k++) /*计算1到50各数的平方和*/ {s2=s2+k*k;}for (k=1;k<=n3;k++) /*计算1到10的各倒数和*/ {s3=s3+1/k;}printf("sum=%\n",s1+s2+s3);return 0;}5-8#include <>int main(){int i,j,k,n;printf("parcissus numbers are ");for (n=100;n<1000;n++){i=n/100;j=n/10-i*10;k=n%10;if (n==i*i*i + j*j*j + k*k*k)printf("%d ",n);}printf("\n");return 0;}5-9-1#define M 1000 /*定义寻找范围*/#include <>int main(){int k1,k2,k3,k4,k5,k6,k7,k8,k9,k10;int i,a,n,s;for (a=2;a<=M;a++) /* a是2-1000之间的整数，检查它是否完数 */ {n=0; /* n用来累计a的因子的个数 */s=a; /* s用来存放尚未求出的因子之和，开始时等于a */for (i=1;i<a;i++) /* 检查i是否a的因子 */if (a%i==0) /* 如果i是a的因子 */{n++; /* n加1，表示新找到一个因子 */s=s-i; /* s减去已找到的因子，s的新值是尚未求出的因子之和 */ switch(n) /* 将找到的因子赋给k1...k9，或k10 */{case 1:k1=i; break; /* 找出的笫1个因子赋给k1 */case 2:k2=i; break; /* 找出的笫2个因子赋给k2 */case 3:k3=i; break; /* 找出的笫3个因子赋给k3 */case 4:k4=i; break; /* 找出的笫4个因子赋给k4 */case 5:k5=i; break; /* 找出的笫5个因子赋给k5 */case 6:k6=i; break; /* 找出的笫6个因子赋给k6 */case 7:k7=i; break; /* 找出的笫7个因子赋给k7 */case 8:k8=i; break; /* 找出的笫8个因子赋给k8 */case 9:k9=i; break; /*找出的笫9个因子赋给k9 */case 10:k10=i; break; /* 找出的笫10个因子赋给k10 */}}if (s==0){printf("%d ,Its factors are ",a);if (n>1) printf("%d,%d",k1,k2); /* n>1表示a至少有2个因子 */if (n>2) printf(",%d",k3); /* n>2表示至少有3个因子，故应再输出一个因子 */if (n>3) printf(",%d",k4); /* n>3表示至少有4个因子，故应再输出一个因子 */if (n>4) printf(",%d",k5); /* 以下类似 */if (n>5) printf(",%d",k6);if (n>6) printf(",%d",k7);if (n>7) printf(",%d",k8);if (n>8) printf(",%d",k9);if (n>9) printf(",%d",k10);printf("\n");}}return 0;}5-9-2#include <>int main(){int m,s,i;for (m=2;m<1000;m++){s=0;for (i=1;i<m;i++)if ((m%i)==0) s=s+i;if(s==m){printf("%d,its factors are ",m); for (i=1;i<m;i++)if (m%i==0) printf("%d ",i); printf("\n");}}return 0;}5-10#include <>int main()int i,n=20;double a=2,b=1,s=0,t; for (i=1;i<=n;i++){s=s+a/b;t=a,a=a+b,b=t;}printf("sum=%\n",s); return 0;}5-11#include <>int main()double sn=100,hn=sn/2;int n;for (n=2;n<=10;n++){sn=sn+2*hn; /*第n次落地时共经过的米数*/ hn=hn/2; /*第n次反跳高度*/}printf("第10次落地时共经过%f米\n",sn); printf("第10次反弹%f米\n",hn);return 0;}5-12#include <>int main(){day=9;x2=1;while(day>0){x1=(x2+1)*2; /*第1天的桃子数是第2天桃子数加1后的2倍.*/ x2=x1;day--;}printf("total=%d\n",x1);return 0;}5-13#include <>#include <>int main(){printf("enter a positive number:");scanf("%f",&a);x0=a/2;x1=(x0+a/x0)/2;do{x0=x1;x1=(x0+a/x0)/2;}while(fabs(x0-x1)>=1e-5);printf("The square root of % is %\n",a,x1); return 0;}5-14#include <>#include <>int main(){double x1,x0,f,f1;x1=;do{x0=x1;f=((2*x0-4)*x0+3)*x0-6;f1=(6*x0-8)*x0+3;x1=x0-f/f1;}while(fabs(x1-x0)>=1e-5);printf("The root of equation is %\n",x1); return 0;}5-15#include <>#include <>int main(){float x0,x1,x2,fx0,fx1,fx2;{printf("enter x1 & x2:"); scanf("%f,%f",&x1,&x2);fx1=x1*((2*x1-4)*x1+3)-6; fx2=x2*((2*x2-4)*x2+3)-6; }while(fx1*fx2>0);do{x0=(x1+x2)/2;fx0=x0*((2*x0-4)*x0+3)-6; if ((fx0*fx1)<0){x2=x0;fx2=fx0;}else{x1=x0;fx1=fx0;}while(fabs (fx0)>=1e-5); printf("x=%\n",x0);return 0;}5-16#include <>int main(){int i,j,k;for (i=0;i<=3;i++){for (j=0;j<=2-i;j++) printf(" ");for (k=0;k<=2*i;k++) printf("*");printf("\n");for (i=0;i<=2;i++){for (j=0;j<=i;j++)printf(" ");for (k=0;k<=4-2*i;k++)printf("*");printf("\n");}return 0;}5-17#include <>int main(){char i,j,k; /*是a的对手;j是b的对手;k是c的对手*/ for (i='x';i<='z';i++)for (j='x';j<='z';j++)if (i!=j)for (k='x';k<='z';k++)if (i!=k && j!=k)if (i!='x' && k!='x' && k!='z')printf("A--%c\nB--%c\nC--%c\n",i,j,k); return 0;}。

c语言程序设计教程答案第一章C语言概述一、简答题1．（1）语言简洁、紧凑，使用方便、灵活；（2）运算符丰富；（3）具有丰富的数据类型；（4）具有结构化的控制语句；（5）语法限制不太严格，程序设计自由度大；（6）C语言允许直接访问物理地址，能进行位（bit）操作，能实现汇编语言的大部分功能，可以直接访问硬件；（7）生成目标代码质量高，程序执行效率高；（8）用C语言写的程序可移植性好，基本上不作修改就能用于各种型号的计算机和各种操作系统。

2．顺序结构，分支结构，循环结构3．所谓算法就是为解决一个问题而采取的方法和步骤。

算法的特性：有穷性、确定性、输入、输出、可行性。

表示算法的方式：（1）用自然语言表示；（2）用流程图表示；（3）用N—S流程图表示；（4）用伪代码表示；（5）用计算机语言表示。

二、算法1．瓶子A里盛有醋瓶子B里盛有酱油有一个空瓶C将A中的醋倒入C将B中的酱油倒入A将C中的醋倒入B 2．输入一个数放在a中max = a以下步骤重复9次：输入一个数放在a中如果a>max，max=a打印max的值3．如果a<btemp=aa=bb=temp如果 c>atemp = aa=cc=temp否则如果c>btemp=bb=cc=temp打印a,b,c的值4．i=1sum=0以下程序循环100遍：sum=sum+ii=i+1打印sum的值5．如果（n除以3的余数为0 并且n除以5的余数为0）n能够同时被3和5整除否则n不能够同时被3和5整除6．i=101以下语句循环50遍：j=2flag=1当j<（i除以2的整数部分）时循环以下语句：如果i除以j的余数为零flag=0退出该循环如果flag==1打印i的值i=i+27．如果m<ntemp=mm=nn=tempi=n做以下循环，直到m,n能够被i整除：如果m能够被i整除并且n能够被i整除i即是m和n的最大公约数跳出循环否则i=i-1打印i的值8．data=b*b—4*a*c如果data＞0否则如果data=0x1=x2=—b/2否则无实数解三、编程题1．main（）{printf(“##############################\n”）；printf(“How do you do？\n”）；printf(“##############################\n”)；}2．main（）{int a,b,c;scanf(“%d%d%d”,&a,&b,&c);printf(“sum=%d”,a+b+c);}第二章数据类型与表达式一、单项选择题1. B2. C3. A4. A5. D6. B7.A8.C9.D二、写出下列程序的运行结果1.aabb cc abcAN2.ab97983. 9,11,9,104.a=2,b=3,c=25.s1=2.500000s2=3三、编程题main(){char c1='c',c2='h',c3='i',c4='n',c5='a';c1=c1+4;c2=c2+4;c3=c3+4;c4=c4+4;c5=c5+4;printf("%c%c%c%c%c\n",c1,c2,c3,c4,c5);}第三章顺序程序设计选择题1）B 2）D 3）D 4）A 5）A 6）B 7）B 8）A 9）D 10）C 11）D 12）A 填空题1）b 2）261 3）25 21 37 4）abc 5）5.0,4,c=3 6）3编程题#define PI 3.1415926main( ){float h, r, l, sv, sz ;printf(“请输入圆的半径r，圆柱高h：\n”) ;scanf(“%f,%f”,&r, &h) ;l=2* PI *r ;s= PI *r*r ;sv=3.0/4.0* PI *r*r*r ;sz= PI *r*r*h ;printf(“圆周长为：l=%6.2f, 圆面积为：s=%6.2f\n”, l, s) ;printf(“求体积为：sv=%6.2f, 圆柱体积为：sz=%6.2f\n”, sv, sz) ; }2、main( ){float c, f ;printf(“请输入一个华氏温度：\n”) ;scanf(“%f”, &f) ;c=5.0/9.0*(f-32) ;printf(“摄氏温度为：%6.2f\n”, c) ;}第四章循环程序设计一、选择题1.D2.D3.D4.C5.D6.A7.B8.B9.A 10.D.11.B 12.A 13.B 14.C 15.C16.A 17.A 18.B 19.D 20.D 21.A二、填空题１．585858２．0３．18４．8921５．２０，０６．６７．１，３，２8．Year%400==0year%100!=0count++三、编程题1.main(){long a;scanf(“%ld”,&a);if (a>=10000&&a<=99999)printf(“这是个五位数”)；else if (a>=1000&&a<=9999) printf(“这是个四位数”)；else if (a>=100&&a<=999) printf(“这是个三位数”)；else if (a>=10&&a<=99) printf(“这是个二位数”)；else if (a>=0&&a<=9)printf(“这是个一位数”)；elseprintf(“输入错误”)；}3.main(){int a;int g,s,b;//个位、十位、百位printf("水仙花数有:\n");for(a=100;i<=999;a++){g=a%10;s=a/10%10;b=a/100;if (a==g*g*g+s*s*s+b*b*b) printf("%d ",a);}printf("\n");}4、main(){int i,n;printf("input n:");scanf("%d",&n);printf("\n%d=",n);for(i=2;i<=n;i++){while(i!=n)if(n%i==0){printf("%d*",i);n/=i;} else break;}printf("%d\n",n);}5、#include “stdio.h”main(){char c;int w,x,y,z;w=x=y=z=0;while((c=getchar())!=’\n’){if((c>’a’&&c<’z’)||(c>’A’&&c<’Z’)) w++;else if (c==’ ’)x++;else if (c>’0’&&c<’9’)y++;else z++；}printf(“英文字母个数：%d\n”,w); printf(“空格个数：%d\n”,x); printf(“数字个数：%d\n”,y); printf(“其他字母个数：%d\n”,z); }6、main(){float h=100,t=100;int j;for(j=1;j<10;j++){t=t/2;h=h+t*2;}printf(“共经过：%f 米\n”,h);printf(“第十次反弹%f 米\n”,t/2);}第五章数组一、单项选择题1. B2. A3. C4. C5. D6. B7.C8.B9.C 10. B二、写出下列程序的运行结果1．S=3682．*************************3．S1=18S2=104．!margorP5．数字0的出现次数是：3数字1的出现次数是：2数字2的出现次数是：2数字3的出现次数是：2数字4的出现次数是：0数字5的出现次数是：1数字6的出现次数是：1数字7的出现次数是：1数字8的出现次数是：1数字9的出现次数是：1 三、编程题1．#include "stdio.h"main(){int a[11];int i,j,t;printf("input 10 number:\n"); for (i=1;i<11;i++)scanf("%d",&a[i]);printf("\n");for (i=1;i<=9;i++)for (j=1;j<=10-i;j++)if (a[j]<a[j+1]){t=a[j];a[j]=a[j+1];a[j+1]=t;}printf("the sorted number is:\n"); for (i=1;i<11;i++)printf("%4d",a[i]);}2．#include "stdio.h"main(){int a[11],i,b;printf("imput 10 sorted number:\n"); for (i=0;i<10;i++)scanf("%d",&a[i]);printf("input an integer:\n");scanf("%d",&b);for (i=9;i>=0&&a[i]>b;i--)a[i+1]=a[i];a[i+1]=b;printf("sorted numbers:\n");for (i=0;i<11;i++)printf("%5d",a[i]);}3．#include "stdio.h"main(){int a[5],i,j,t;printf("input 5 integer:\n");for (i=0;i<5;i++) /*输入5个整数*/scanf("%d",&a[i]);for (i=0,j=4;i<j;i++,j--) /*逆序存放*/{t=a[i];a[i]=a[j];a[j]=t;}for (i=0;i<5;i++) /*逆序存放后重新输出*/printf("%5d",a[i]);}4．#include "stdio.h"main(){int i,j,a[10][10]={{1},{1,1}};for (i=2;i<10;i++) /*给二维数组每个元素赋值*/{a[i][0]=1;for (j=1;j<=i;j++)a[i][j]=a[i-1][j-1]+a[i-1][j];}for (i=0;i<10;i++) /*输出二维数组*/{for (j=0;j<=i;j++)printf("%-5d",a[i][j]);printf("\n");}}5．#include "stdio.h"main(){int a[3][4],i,j,max,row,col;printf("input 3*4 matrix:\n");for (i=0;i<3;i++) /*输入3*4矩阵*/for (j=0;j<4;j++)scanf("%d",&a[i][j]);max=a[0][0]; row=0; col=0;for (i=0;i<3;i++) /*寻找矩阵中的最大值及其行列号*/for (j=0;j<4;j++)if (max<a[i][j]){max=a[i][j]; row=i, col=j;}printf("\n数组中最大的数是%d,其行号是%d,列号是%d\n",max,row,col);}6．#define N 3#define M 4#include "stdio.h"main(){int a[N][M],i,j,k,max,row,col;printf("input %d*%d matrix: \n",N,M);for (i=0;i<N;i++) /*输入二维矩阵*/for (j=0;j<M;j++)scanf("%d",&a[i][j]);for (i=0;i<N;i++) /*求鞍点*/{max=a[i][0]; row=i; col=0;for(j=1;j<M;j++) /*求矩阵中每一行的最大值及其所行列号*/if (max<a[i][j]){max=a[i][j]; col=j;}for (k=0;k<N;k++) /*判断每一行的最大值在其所在列是否最大*/if (a[k][col]<max)break;if (k==N) /*得到鞍点*/{printf("the point is %d,row=%d,col=%d\n",max,row,col);break;}}if (i==N) /*没有鞍点*/printf("no point\n");}7．#include "stdio.h"main(){int num=0,word=0;/*word=0表示未出现单词,如出现单词就置word为1.num用来统计单词个数*/char c;printf("please input a string :\n");while ((c=getchar())!='\n')if (c==' ')word=0;else if (word==0){word=1; num++;}printf("There are %d words in the line\n",num);}8．#include "stdio.h"main(){int i,j,uppn,lown,dign,span,othn;/*uppn,lown,dign,span,othn分别存放英文大写字母、小写字母、数字、空格和其他字符的个数*/char text[3][80];uppn=lown=dign=span=othn=0;for(i=0;i<3;i++){gets(text[i]);for(j=0;j<80&&text[i][j]!='\0';j++) {if(text[i][j]>='A'&&text[i][j]<='Z') uppn++;else if(text[i][j]>='a'&&text[i][j]<='z') lown++;else if(text[i][j]>='0'&&text[i][j]<='9') dign++;else if(text[i][j]==' ')span++;elseothn++;}}for(i=0;i<3;i++)printf("%s\n",text[i]);printf("uppn=%d\n",uppn);printf("lown=%d\n",lown);printf("dign=%d\n",dign);printf("span=%d\n",span);printf("othn=%d\n",othn);}9．#include "stdio.h"main(){int i,j;char str1[20],str2[20];printf("input two strings:\n");gets(str1);gets(str2);j=strlen(str1); /*求字符串1的长度*/for (i=0;str2[i]!='\0';i++,j++) /*字符串合并*/str1[j]=str2[i];str1[j]='\0'; /*加上字符串结束标志*/puts(str1);}10．#include "stdio.h"main(){int i,n;char str1[20],str2[20];printf("input two strings:(no more than 20 characters)\n");gets(str1); gets(str2);n=strlen(str1)<strlen(str2)?strlen(str1):strlen(str2); /*n中存放较短字符串的长度*/for (i=0;i<n&&str1[i]==str2[i];i++);printf("%d\n",str1[i]-str2[i]);}第六章函数与编译预处理一、单项选择题1. C2. B3. B4. B5. A6. B7.A8.C9.D 10. A二、写出下列程序的运行结果1．92．4,B8,B3．-4.0000004．a=6,b=55．48三、编程题1．main(){ int prime(int n);int n;printf("input n(n>0):\n");scanf("%d",&n);if (prime(n))printf("%d is a sushu\n",n);else printf("%d is not a sushu\n",n);}int prime(int n){int flag=1,i;for (i=2;i<=n/2&&flag==1;i++) if (n%i==0) flag=0;return(flag);}2.#define N 3convert(int array[3][3]){ int i,j,t;for (i=0;i<N-1;i++)for (j=i+1;j<N;j++){t=array[i][j];array[i][j]=array[j][i];array[j][i]=t;}}main(){int i,j;int a[N][N];printf("input a:\n");for (i=0;i<N;i++)for (j=0;j<N;j++)scanf("%d",&a[i][j]);printf("Array a:\n");for (i=0;i<N;i++){for (j=0;j<N;j++)printf("%5d",a[i][j]);printf("\n");}convert(a);printf("a de zhuanzhi is:\n"); for (i=0;i<N;i++){for (j=0;j<N;j++)printf("%5d",a[i][j]);printf("\n");}}3. #include <stdio.h>#include <string.h>main(){char str[100];printf("input a string:\n") ;gets(str);inverse(str);printf("the reversed string is:%s\n",str); }inverse(char str[]){char t;int i,j;for (i=0,j=strlen(str)-1;i<j;i++,j--){t=str[i];str[i]=str[j];str[j]=t;}}4. #include <stdio.h>concat(char str1[],char str2[]){ int i=0,j;while (str1[i]!='\0')i++;for (j=0;str2[j]!='\0';i++,j++)str1[i]=str2[j];}main(){char str1[100],str2[100];gets(str1);gets(str2);concat(str1,str2);puts(str1);}5. main(){char str[80];printf("input a string (4 ge shu zi zi fu):\n"); scanf("%s",str);insert(str);printf("result is:\n%s\n",str);}insert(char str[]){int i;for (i=strlen(str);i>0;i--){str[2*i]=str[i];}}6. #include "stdio.h"int i,ndight,nwhite,nletter,nother;count(char str[]){ndight=nwhite=nletter=nother=0;for (i=0;str[i]!='\0';i++)if (str[i]>='0'&&str[i]<='9')ndight++;else if ((str[i]>='A'&&str[i]<='Z')||(str[i]>='a'&&str[i]<='z')) nletter++;else if (str[i]==' ')nwhite++;else nother++;}main(){char text[80];printf("input a string:\n");gets(text);count(text);printf("ndight=%d,nletter=%d,nwhite=%d,nother=%d\n",ndight,nletter,n white,nother);}7. #define N 10#include <stdio.h>sort(char str[]){int i,j;char t;for (i=1;i<N;i++)for (j=0;j<N-i;j++)if (str[j]>str[j+1]){t=str[j];str[j]=str[j+1] ;str[j+1]=t;}}main(){char str[N];int i ;printf("Input 10 ge zi fu:\n");gets(str);sort(str);printf("The sorted result:\n") ;for(i=0;i<N;i++)printf("%c",str[i]);}8.这题较复杂#include <stdio.h>#include <string.h>#define N 10void input_e(int num[],char name[N][8]){int i;for (i=0;i<N;i++){ printf("input gong hao:");scanf("%d",&num[i]);printf("input name:");getchar();gets(name[i]);}for (i=0;i<N;i++)printf("%5d%10s\n",num[i],name[i]);}void sort(int num[],char name[N][8]) /*选择法排序*/ {int i,j,min,temp1;char temp2[8];for (i=0;i<N-1;i++){min=i;for (j=i+1;j<N;j++)if (num[j]<num[min]) min=j;temp1=num[i];strcpy(temp2,name[i]);num[i]=num[min];strcpy(name[i],name[min]);num[min]=temp1;strcpy(name[min],temp2);}printf("the sorted result:\n");for (i=0;i<N;i++)printf("%5d%10s\n",num[i],name[i]);}void search(int n,int num[],char name[N][8]) /*折半查找法*/ {int top,bott,mid,find;find=0;top=0;bott=N-1;if ((n<num[0])||(n>num[N-1]))find=-1;while ((find==0)&&(top<=bott)){mid=(bott+top)/2;if (n==num[mid]){find=1; printf("%d name is:%s\n",n,name[mid]);}else if (n<num[mid])bott=mid-1;else top=mid+1;}if ((find==-1)||(find==0))printf("%d is not found.\n",n);}main(){int num[N],number,c,flag;char name[N][8];input_e(num,name);sort(num,name);for (flag=1;flag;){printf("please input chazhao de gonghao:"); /*输入查找的工号*/ scanf("%d",&number);search(number,num,name);printf("continue Y/N?"); /*是否继续查找*/getchar();c=getchar();if (c=='N'||c=='n')flag=0;}}9. #include "stdio.h"#define MAX 10main(){char str[MAX];char c;int i;i=0;printf("input number(16 jinzhi): "); /*输入一个十六进制的数*/ while((c=getchar())!='\n'&&i<MAX){ str[i]=c;i++;}str[i]='\0';printf("result is :%d\n",htod(str));}int htod(char s[]){int i,n;n=0;for(i=0;s[i]!='\0';i++){if (s[i]>='0'&&s[i]<='9')n=n*16+s[i]-'0';if (s[i]>='a'&&s[i]<='f')n=n*16+s[i]-'a'+10;if (s[i]>='A'&&s[i]<='F')n=n*16+s[i]-'A'+10;}return(n);}10. #define SWAP(a,b) t=a;a=b;b=t main(){int a,b,t;printf("input a,b:") ;scanf("%d,%d",&a,&b);SWAP(a,b);printf("result:a=%d,b=%d\n",a,b);}11. #define SURPLUS(a,b) ((a)%(b)) main(){int a,b;printf("input a,b:");scanf("%d,%d",&a,&b);printf("result is: %d\n",SURPLUS(a,b)); }12. main(){int a,b,c;printf("input a,b,c:");scanf("%d,%d,%d",&a,&b,&c);printf("max=%d\n",max(a,b,c));}int max(int x,int y,int z){int t;t=(x>y ? x : y);return(t>z?t:z);}#define MAX(x,y) ((x)>(y)?(x):(y))main(){int a,b,c;printf("input a,b,c:");scanf("%d,%d,%d",&a,&b,&c);printf("max=%d\n",MAX(MAX(a,b),c));}13. #include "stdio.h"#define CHANGE 1#define MAX 80main(){char str[MAX];int i;printf("input a string:\n");gets(str);#if (CHANGE){ for (i=0;str[i]!='\0';i++)if (str[i]>='a'&&str[i]<'z'||str[i]>='A'&&str[i]<'Z') str[i]=str[i]+1;else if (str[i]=='z'||str[i]=='Z')str[i]=str[i]-25;}#endifprintf("%s\n",str);}第七章指针一、选择题1）A 2）D 3）D 4）C 5）B 6）B 7）B 8）C 9）B 10）C 11）A 12）A 13）A 14）C 15）B 16）A 17）C 18）B 19）D 20）B二、阅读下面程序，写出程序运行结果1）abcdeedcba 2）1113151719 3）（TurboC中是11,97,11 ）（VisualC是9，9 7，11）4）3 6 5）6385三、编程题1、main( ){ int a[10],i,temp,*p=a;printf("Please input array a:\n");for(i=0;i<10;i++)scanf("%d",&a[i]);printf("array a:\n");for(i=0;i<10;i++)printf("%4d",a[i]);for(i=0;i<5;i++){ temp=p[i];p[i]=p[10-i-1];p[10-i-1]=temp;}printf("\n Now array a:\n");for(i=0;i<10;i++)printf("%4d",a[i]);}2、main( ){ int a[3][3],*p,i,j;printf("please input matrix:\n"); for(i=0;i<3;i++)for(j=0;j<3;j++)scanf("%d",&a[i][j]);p=&a[0][0];move(p);printf("\n Now matrix:\n");for(i=0;i<3;i++){ for(j=0;j<3;j++) printf("%4d",a[i][j]); printf("\n");}}move(int *q){ int i,j,t;for(i=0;i<3;i++)for(j=i;j<3;j++){ t=*(q+3*i+j);*(q+3*i+j)=*(q+3*j+i); *(q+3*j+i)=t;}}3、#include <stdlib.h> #include <alloc.h>#include <string.h>#include <stdio.h> main( ){int binary();void insert();char *temp,*ptr1[6]={"BASIC","DATA","PASCAL","SQL","USE"}; int i;ptr1[5]=malloc(20);printf("\n");printf("original string:\n");for(i=0;i<5;i++)printf("%s\n",ptr1[i]);printf("input search string:\n");temp=malloc(20);gets(temp);i=binary(ptr1,temp,5);printf("i=%d\n",i);insert(ptr1,temp,5,i);printf("output strings:\n");for(i=0;i<6;i++)printf("%s\n",ptr1[i]);}int binary(char *ptr[],char *str,int n){int hig,low,mid;low=0;hig=n-1;if(strcmp(str,ptr[0])<0) return(0);if(strcmp(str,ptr[hig])>0) return(n); while(low<=hig){mid=(low+hig)/2;if(strcmp(str,ptr[mid])<0)hig=mid-1;else if(strcmp(str,ptr[mid])>0)low=mid+1;else return(mid);}return(low);}void insert(char *ptr[],char *str,int n,int i) {int j;for(j=n;j>i;j--)strcpy(ptr[j],ptr[j-1]);strcpy(ptr[i],str);}4、main( ){ int i;char *p[6],str[6][20];for(i=0;i<6;i++)p[i]=str[i];printf("Input 6 strings:\n"); for(i=0;i<6;i++)scanf("%s",p[i]);sort(p);printf("Now the strings:\n"); for(i=0;i<6;i++)printf("%s\n",p[i]);}sort(char *q[ ]){ int i,j;char *t;for(i=0;i<5;i++)for(j=0;j<5-i;j++)if(strcmp(*(q+j),*(q+j+1))>0) { t=*(q+j);*(q+j)=*(q+j+1);*(q+j+1)=t;}}5、main( ){ int m;char str1[20],str2[20],*p1,*p2; printf("please input two strings:\n"); scanf("%s",str1);scanf("%s",str2);p1=str1;p2=str2;m=stringcmp(p1,p2);printf("result is %d:\n",m);}stringcmp(char *p1,char *p2){ int i=0;while(*(p1+i)==*(p2+i))if(*(p1+(i++))=='\0') return(0); return((*p1+i)-*(p2+i));}6、main( ){ char str1[30],str2[30],str3[100]; int i=0,j=0,k=0;printf("please input two strings:\n"); scanf("%s",str1);scanf("%s",str2);while(str1[i]!='\0' && str2[j]!='\0'){ str3[k++]=str1[i++];str3[k++]=str2[j++];}while(str1[i]!='\0')str3[k++]=str1[i++];while(str2[j]!='\0')str3[k++]=str2[j++];str3[k]='\0';printf("\n%s\n",str3);}第八章结构体一、选择题1、C2、B3、C4、D5、B6、A7、D8、C9、C 10、B二、填空题1、342、03、514、10，x5、364041三、编程题1、struct complex{float x; /*实部*/float y; /*虚部*/}main(){struct complex c1={5,3},c2={2,6}; float t1,t2;t1=c1.x*c2.x - c1.y*c2.y;t2=c1.x*2.y + c1.y*c2.x;printf(“The two complexs product is:”); printf(“%.2f%+.2f i\n”,t1,t2);}2. struct student{char name[10]; /*姓名*/int number; /*学号*/float x; /*成绩*/float y; /*成绩*/}main( ){struct student s[45];int i;void max();void average();void sort();for (i=0;i<45;i++)scanf(“%s%d%f%d”,s[i].name,&s[i].number,&s[i].x,&s[i].y); /*输入学生的姓名、学号、两门课程成绩*/max(s,45);average(s,45);sort(s,45);}void max(struct student *a,int n){float temp;char na[10];int i ,num;temp=a[0].x+a[0].y;for (i=1;i<n;i++)if(temp<a[i].x+a[i].y) /*求总分最高的学生姓名、学号*/ {temp=a[i].x+a[i].y;strcmp(na,a[i].name);num=a[i].number;}printf(“%s,%d”,na,num);}void average(struct student *b,int n){float aver1,aver2,s1,s2;int i ;s1=s2=0;for(i=0;i<45;i++) /*求每门课程的总成绩*/ {s1+=b[i].x;s2+=b[i].y;}aver1=s1/45;aver2=s2/45;for(i=0;i<45;i++)if(b[i].x<aver1&&b[i].y<aver2)/*输出两门课程都低于平均成绩的学生*/ printf(“%s,%d\n”,b[i].name,b[i].number);}void sort(struct student *c,int n){float t;int i,j ;struct student temp;for (i=0;i<n-1;i++) /*改进的选择法排序可参考课本P89页*/ {k=i ;for(j=i+1;j<n;j++)if(c[k].x<c[j].x)k=j;if(k!=i){temp=c[i];c[i]=c[k];c[k]=temp;}for(i=0;i<n;i++)printf(“%s,%.2f\n”,c[i].n,c[i].x);}3. typedef struct Ljian{int pname;int wnum;struct Ljian *next;}Part;/*用户自定义零件结构体类型*/# include “stdio.h”main( ){int n=1;Part *head,*p1,*p2;head=NULL;p1=( Part * ) malloc (sizeof(struct Ljian));/*创建第一个结点*/scanf(“%d%d”,&p1->pname,&p1->wnum);p1->next=NULL;while(n<=10) /*将结点加入链表*/ {if(n==1)head=p1; /*是第一个结点，作表头*/ elsep2->next=p1; /*不是第一个结点，作表尾*/ p2=p1;p1=( Part *) malloc(sizeof(struct Ljian));/*开辟下一个结点*/scanf(“%d%d”,&p1->pname,&p1->wnum);p1->next=NULL;n++;}}4.#include<stdlib.h>#include<stdio.h>#include<conio.h>#define LEN sizeof(struct student)typedef struct student{ long num; /*学号*/float score; /*成绩*/struct student *next;} STU; /*用户自定义学生结构体类型*/STU *Create ( ) /*创建链表* /{int n=0;STU *p1,*p2,*head;head=NULL;p1=(STU *)malloc(LEN); /*创建第一个结点*/ scanf("%ld,%f",&p1->num,&p1->score);p1->next=NULL;while(p1->num!=0) /*将结点加入链表*/{++n;if(n==1) /*是第一个结点，作表头*/head=p1;else /*不是第一个结点，作表尾*/p2->next=p1;p2=p1;p1=(STU *)malloc(LEN); /*开辟下一个结点*/scanf("%ld,%f",&p1->num,&p1->score);p1->next=NULL;}free(p1); /*释放最后一个结点所占的内存*/ return (head); /*返回链表的头指针*/}void print(STU *head) /*输出链表* /{STU *p;p=head;do{printf("%ld\t%5.1f\n",p->num,p->score);p=p->next;}while(p!=NULL);}STU *merge(STU *p1,STU *p2) /*合并链表* /{STU *p,*head , *s1,*s2;s1=p1;s2=p2;while(s1->next!=NULL)s1=s1->next;/*将指针s1指向链表1的最后一个节点*/while(s2->next!=NULL)s2=s2->next;/*将指针s2指向链表2的最后一个节点*/if(s1->num<p2->num){s1->next=p2;head=p1;}/*因为两个链表都是按学号升序排列，如果链表1的最后一个节点中的学号小于链表2的第一个节点中的学号，则直接将链表2插入到链表1的后面*/else if(s2->num<p1->num){。

2.2 #include<stdio.h>main(){float x=2.5,y=2.5,z=2.5;printf("x=%f\n",x);printf("y=%f\n",y);printf("z=%f\n",z);}3.1(1)#include<stdio.h>main(){int a=12,b=3;float x=18.5,y=4.6;printf("%f\n",(float)(a*b)/2);printf("%d\n",(int)x%(int)y);}3.1(2)#include<stdio.h>main(){int x=32,y=81,p,q;p=x++;q=--y;printf("%d %d\n",p,q); printf("%d %d\n",x,y); }3.2#include<stdio.h>main(){int x,b0,b1,b2,s;printf("Inputx:");scanf("%d",&x);b2=x/100;b1=(x-b2*100)/10;//或(x%100)/10;或x/10%10; b0=x%10;s=b0*100+b1*10+b2;printf("s=%d\n",s);}3.3#include<stdio.h>#include<math.h>main(){float rate=0.0225;float n,capital,deposit;printf("Input n,capital:");scanf("%f,%f",&n,&capital);deposit=capital*pow(1+rate,n);printf("deposit=%f\n",deposit);}3.4#include<stdio.h>#include<math.h>main(){float a, b, c;double x, y;printf("Input a, b, c:");scanf("%f %f %f", &a, &b, &c);x=(-b+sqrt(b*b-4*a*c))/(2*a);y=(-b-sqrt(b*b-4*a*c))/(2*a);printf("x=%f,y=%f\n",x,y);}习题44.1(1)#include<stdio.h>main(){char c1='a',c2='b',c3='c';printf("a%cb%cc%c\n",c1,c2,c3);}4.1(2)#include<stdio.h>main(){int a=12,b=15;} 4.1(3)#include<stdio.h>main(){int a,b;printf("%d,%d\n",a,b);}4.2#include<stdio.h>main(){long a,b;float x,y;scanf("%d,%d\n",&a,&b);scanf("%f,%f\n",&x,&y);printf("a=%d,b=%d\n",a,b);printf("x=%f,b=%f\n",x,y); }5.1#include<stdio.h>main(){float a;printf("Input a:");scanf("%f",&a);if(a>=0){a=a;printf("a=%f\n",a);}else{a=-a;printf("a=%f\n",a);}}5.2#include<stdio.h>main(){int a;printf("Input a:");scanf("%d", &a);if(a%2==0){printf("a是偶数");}else{printf("a是奇数");}}5.3#include<stdio.h>#include<math.h>main(){float a,b,c,s,area;printf("Input a, b, c:");scanf("%f %f %f", &a, &b, &c);if(a+b>c&&a+c>b&&b+c>a){s=(a+b+c)/2;area=(float)sqrt(s*(s-a)*(s-b)*(s-c));printf("area=%f\n",area);}else{printf("不是三角形");}}5.4#include<stdio.h>#include<math.h>main(){float a,b,c,x,y;printf("Inputa,b,c:");scanf("%f,%f,%f",&a,&b,&c);if(a==0){printf("该方程不是一元二次方程\n");}if(b*b-4*a*c>0){x=(-b+sqrt(b*b-4*a*c))/(2*a);y=(-b-sqrt(b*b-4*a*c))/(2*a);printf("x=%f,y=%f\n",x,y);}else if(b*b-4*a*c==0){x=-b/(2*a);y=-b/(2*a);printf("x=%f,y=%f\n",x,y);}else{printf("该方程无实根\n");}}5.5#include<stdio.h>main(){int year,flag;printf("Input a year:");scanf("%d",&year);if(year%4==0&&year%400!=0||year%400==0){flag=1;}else{flag=0;}if(flag==1){printf("%d is a leap year!\n",year);}else{printf("%d is not a leap year!\n",year);}}5.6#include<stdio.h>main(){int year,flag;printf("Input a year:");scanf("%d",&year);flag=year%400==0||year%4==0&&year%100!=0?1:0;if(flag==1&&flag!=0){printf("%d is a leap year!\n",year);}else{printf("%d is not a leap year!\n",year);}}5.7#include<stdio.h>main(){char ch;printf("Inputch:");scanf("%c",&ch);if(ch>='a'&&ch<='z'){ch=getchar();ch=ch-32;printf("%c,%d\n",ch,ch);}else if(ch>='A'&&ch<='Z'){ch=getchar();ch=ch+32;printf("%c,%d\n",ch,ch);}else{printf("%c",ch);}}5.8#include<stdio.h>main(){char ch;printf("Inputch:");scanf("%c",&ch);if(ch>=48&&ch<=57){printf("ch是数字字符\n");}else if(ch>=65&&ch<=90){printf("ch是大写字母\n");}else if(ch>=97&&ch<=122){printf("ch是小写字母\n");}else if(ch==32){printf("ch是空格\n");}else{printf("ch是其他字符\n");}}5.9#include<stdio.h>main(){int score,grade;printf("Input score:");scanf("%d",&score);grade=score/10;if(score<0||score>100){printf("Input error\n");}if(score>=90&&score<=100){printf("%d--A\n",score);}else if(score>=80&&score<90){printf("%d--B\n",score);}else if(score>=70&&score<80){printf("%d--C\n",score);}else if(score>=60&&score<70){printf("%d--D\n",score);}else if(score>=0&&score<60){printf("%d--E\n",score);}}5.10#include<stdio.h>main(){int year,month;printf("Input year,month:");scanf("%d,%d",&year,&month);if(month>12||month<=0){printf("error month\n");}else{switch(year,month){case12:case10:case8:case7:case5:case3:case1:printf("31天\n");break;case11:case9:case6:case4:printf("30天\n");break;case2:if(year%4==0&&year!=0||year%400==0){printf("29天\n");}else{printf("28天\n");}break;default:printf("Input error\n");}}}6.1(1)#include<stdio.h>main(){int i,j,k;char space='';for(i=1;i<=4;i++){for(j=1;j<=i;j++){printf("%c",space);}for(k=1;k<=6;k++){printf("*");}printf("\n");}}6.1(2)#include<stdio.h>main(){int k=4,n;for(n=0;n<k;n++){if(n%2==0)continue;k--;}printf("k=%d\n,n=%d\n",k,n);}6.1(3)#include<stdio.h>main(){int k=4,n;for(n=0;n<k;n++){if(n%2==0)break;k--;}printf("k=%d,n=%d\n",k,n);}6.2(1)#include<stdio.h>main(){int i,sum=0;for(i=1;i<=101;i++){sum=sum+i;}printf("sum=%d\n",sum);}6.2(2)#include<stdio.h>main(){long i;long term,sum=0;for(i=1;i<=101;i=i+2){term=i*(i+1)*(i+2);sum=sum+term;}printf("sum=%ld\n",sum);}6.2(4)#include<stdio.h>#include<math.h>main(){int n=1;float term=1.0,sign=1,sum=0;while(term<=-1e-4||term>=1e-4){term=1.0/sign;sum=sum+term;sign=sign+n;n++;}printf("sum=%f\n",sum);}6.2(5)#include<stdio.h>#include<math.h>main(){int n=1,count=1;float x;double sum,term;printf("Input x:");scanf("%f",&x);sum=x;term=x;do{term=-term*x*x/((n+1)*(n+2));sum=sum+term;n=n+2;count++;}while(fabs(term)>=1e-5);printf("sin(x)=%f,count=%d\n",sum,count);}6.3#include<stdio.h>main(){int x=1,find=0;while(!find){if(x%2==1&&x%3==2&&x%5==4&&x%6==5&&x%7==0){printf("x=%d\n",x);find=1;x++;}}}/*int x,find=0;for(x=1;!find;x++){if(x%2==1&&x%3==2&&x%5==4&&x%6==5&&x%7==0){printf("x=%d\n",x);find=1;}}}*/6.4#include<stdio.h>main(){int i,n;long p=1,m=1;printf("Input n:");scanf("%d",&n);for(i=1;i<=n;i++){p=i*i;m=i*i*i;printf("p=%d,m=%d\n",i,p,i,m);}}6.5#include<stdio.h>main(){float c,f;for(c=-40;c<=110;c=c+10){f=9/5*c+32;printf("f=%f\n",f);}}6.6#include<stdio.h>#include<math.h>main(){int n;double c=0.01875,x;do{x=x*pow(1+c,12)-1000;n++;}while(x>0);printf("x=%d\n",x);}6.7#include<stdio.h>main(){int n=0;float a=100.0,c;printf("Inputc:");scanf("%f",&c);do{a=a*(1+c);n++;}while(a<=200);printf("n=%d\n",n);}6.8#include<stdio.h>#include<math.h>main(){int n=1,count=1;double sum=1,term=1;while(fabs(term)>=1e-5){term=pow(-1,count)*(1.0/(n+2));sum=sum+term;n=n+2;count++;}sum=4*sum;printf("sum=%f,count=%d\n",sum,count); }6.9#include<stdio.h>#include<math.h>main(){int n=1,count=1;double sum=1,term=1;while(fabs(term)>=1e-5){term=term*(1.0/n);sum=sum+term;n++;count++;}printf("sum=%f,count=%d\n",sum,count);}6.10#include<stdio.h>#include<math.h>main(){int x;for(x=100;x<=999;x++){if(x==pow(x/100,3)+pow(x/10%10,3)+pow(x%10,3))printf("x=%d\n",x);}}6.11#include<stdio.h>main(){int i=0,n;long sum=0,term=1;printf("Inputn:");scanf("%d",&n);do{i++;term=term*i;sum=sum+term;}while(sum<n);printf("%d\n",i-1);}6.12#include<stdio.h>main(){int i,n,m,count=0,sum=0;printf("Input n:");scanf("%d",&n);for(i=1;i<=n;i++){printf("Inputm:");scanf("%d",&m);if(m>0){sum=sum+m;count++;}else{break;}printf("sum=%d,count=%d\n",sum,count);}}6.13#include<stdio.h>main(){int i,n,m,count=0,sum=0;printf("Inputn:");scanf("%d",&n);for(i=1;i<=n;i++){printf("Inputm:");scanf("%d",&m);if(m>0||m<0){sum=sum+m;count++;}else{break;}printf("sum=%d,count=%d\n",sum,count);}}6.14#include<stdio.h>main(){int x,y,z;for(x=0;x<=17;x++){for(y=0;y<=25;y++){3*x+2*y+z==50;z=30-x-y;if(3*x+2*y+z==50&&x+y+z==30)printf("x=%d,y=%d,z=%d\n",x,y,z);}}}6.15#include<stdio.h>main(){int x,y;for(x=0;x<=98;x++){y=98-x;2*x+4*y==386;if(x+y==98&&2*x+4*y==386){printf("x=%d,y=%d\n",x,y);}}}6.16#include<stdio.h>main(){int x,y,z;for(x=0;x<=20;x++){for(y=0;y<=33;y++){3*y+5*x+z/3.0==100;z=100-x-y;if(5*x+3*y+z/3.0==100&&z+x+y==100){printf("x=%d,y=%d,z=%d\n",x,y,z);}}}}6.17#include<stdio.h>main(){int x,y,z;for(x=1;x<=9;x++){for(y=1;y<=17;y++){10*x+5*y+z==100;z=50-x-y;if(10*x+5*y+z==100&&x+y+z==50&&z>0){printf("x=%d,y=%d,z=%d\n",x,y,z);}}}}7.1#include<stdio.h>int Square(int i){return i*i;}int main(){int i=0;i=Square(i);for(;i<3;i++){static int i=1;i+=Square(i);printf("%d,",i);}printf("%d\n",i);return0;}7.2#include<stdio.h>int hour,minute,second;void update(){second++;if(second==60){second=0;minute++;}if(minute==60){minute=0;hour++;}if(hour==24)hour=0;}void display(){printf("%d,%d,%d\n",hour,minute,second); }void delay(){int t;for(t=0;t<100000000;t++);}int main(){int i;void updaye(),display(),delay();for(i=0;i<1000000;i++){update();display();delay();}return0;}7.3#include<stdio.h>int GetMax(int a,int b);int main(){int x,y,max;printf("Inputx,y:");scanf("%d,%d",&x,&y);max=GetMax(x,y);printf("max=%d\n",max);return0;}int GetMax(int m,int n){if(m>=n)return m;elsereturn n;}7.4#include<stdio.h>int LCM(int n,int m);int main(){int a,b;printf("Inputa,b:");scanf("%d,%d",&a,&b);printf("%d\n",LCM(a,b));return0;}int LCM(int n,int m){int x;int find=0;for(x=1;!find;x++){if(x%n==0&&x%m==0){find=1;}}return x-1;}7.5#include<stdio.h>long Fact(int n);int main(){int m,a;printf("Inputm:");scanf("%d",&m);for(a=1;a<=m;a++){printf("%d!=%ld\n",a,Fact(a));}return0;}long Fact(int n){int i;long result=1;for(i=2;i<=n;i++)result*=i;return result;}7.6#include<stdio.h>long Fact(int n);int main(){int m;long ret;printf("Inputm:");scanf("%d",&m);ret=Fact(m);printf("ret=%d\n",ret);return0;}long Fact(int n){int i;long result=1,sum=0;for(i=2;i<=n;i++){result*=i;sum=sum+result;}return sum;}7.7(1)#include<stdio.h>int Gcd(int a,int b);int main(){int m,n;printf("Inputm,n:");scanf("%d,%d",&m,&n);printf("%d\n",Gcd(m,n));return0;}int Gcd(int a,int b){int t,min,find=0;min=a<b?a:b;t=min;for(t=min;!find;t--){a%t==0;b%t==0;if(a%t==0&&b%t==0)return t;}find=1;}7.7(2)#include<stdio.h> int Gcd(int a,int b);int main(){int m,n;printf("Inputm,n:");scanf("%d,%d",&m,&n);printf("%d\n",Gcd(m,n));return0;}int Gcd(int a,int b){int r,temp;r=a%b;if(r==0)return b;elsedo{temp=b;b=r;a=temp;r=a%b;}while(r!=0);return b;}8.1(1)#include<stdio.h> void Func(int x){x=2;}int main(){int x=10;Func(x);printf("%d",x);return0;}8.1(2)#include<stdio.h> void Func(int b[]){int j;for(j=0;j<4;j++){b[j]=j;}}int main(){static int a[]={5,6,7,8},i;Func(a);for(i=0;i<4;i++){printf("%d",a[i]);}return0;}8.2(1)int PositiveNum(int a[],int n) {int i,count=0;for(i=0;i<n;i++){if(a[i]>0)count++;}return0;}8.2(2)void Fib(long f[],long n){int i;f[0]=0;f[1]=1;for(i=2;i<n;i++){f[i]=f[i-1]+f[i-2];}}8.2(3)#include<stdio.h>int main(){int a[10],n,max,min,maxPos,minPos;for(n=0;n<10;n++){scanf("%d",&a[n]);}max=min=a[0];maxPos=minPos=0;for(n=0;n<10;n++){if(a[n]>max){max=a[n];maxPos=n;}else if(a[n]<min){min=a[n];minPos=n;}}printf("max=%d,pos=%d\n",max,maxPos);printf("min=%d,pos=%d\n",min,minPos);return0;}8.3void DivArray(int*pArray,int n){int i;for(i=0;i<n;i++){pArray[i]/=pAttay[0];}}8.4#include<stdio.h>#define N40int FailNum(int score[],int n);void ReadScore(int score[],int n);int main(){int score[N],n;printf("Input n:");scanf("%d",&n);ReadScore(score,n);FailNum(score,n);printf("FailNum students are%d\n",FailNum(score,n));return0;}int FailNum(int score[],int n){int i,count=0;for(i=0;i<n;i++){if(score[i]<60)count++;}return count;}void ReadScore(int score[],int n){int i;printf("Input score:");for(i=0;i<n;i++){scanf("%d",&score[i]);}}8.5#include<stdio.h>#define N40int HighAver(int score[],int n);int ReadScore(int score[]);int main(){int score[N],n;n=ReadScore(score);printf("HighAver students are%d\n",HighAver(score,n));return0;}int HighAver(int score[],int n){int i,count=0,sum=0,aver;for(i=0;i<n;i++){sum=sum+score[i];aver=sum/n;}for(i=0;i<n;i++){if(score[i]>aver)count++;}return count;}int ReadScore(int score[]){int i=-1;do{i++;printf("Input score:");scanf("%d",&score[i]);}while(score[i]>=0);return i;}8.6#include<stdio.h>#define N40int ReadScore(int score[],long num[]);int FindMax(int score[],long num[],int n);int main(){int score[N],n,max,num,t;long num[N];t=FindMax(score,n);max=score[t];num=num[t];printf("max=%d,num=%d\n",max,num);return0;}int ReadScore(int score[],long num[]){int i=-1;do{i++;printf("Input student's ID and score:");scanf("%ld%d",&num[i],&score[i]);}while(num[i]>0&&score[i]>=0);return i;}int FindMax(int score[],long num[],int n){int max,i;max=score[0];for(i=1;i<n;i++){if(score[i]>max)max=score[i];}return i;}8.7#include<stdio.h>#define N40int Read(int a[]);int ChangeArry(int a[],int n);int main(){int a[N],n;printf("%d\n",ChangeArry(a,n));return0;}int Read(int a[]){int i;for(i=0;i<9;i++){printf("Input a:");scanf("%d",&a[i]);return i;}int ChangeArry(int a[],int n){int max,min,i,maxpos,minpos,term;max=min=score[0];for(i=1;i<n;i++){if(a[i]>max)max=score[i];maxpos=n;else(a[i]<min)min=a[i];minpos=n;temp=maxpos;maxpos=minpos;minpos=temp;}return a[i];}8.10#include<stdio.h>#define N5void main(){int a[N][N];int sum=0;int i,j;printf("请输入一个%d*%d的矩阵\n",N,N);for(i=0;i<N;i++){for(j=0;j<N;j++){scanf("%d",&a[i][j]);}}for(i=0;i<N;i++){for(j=0;j<N;j++){if(i==j||i+j==N-1)sum=sum+a[i][j];}}printf("对角线元素之和为：%d\n",sum);}8.11#include<stdio.h>#define N2#define M3void main(){int a[N][M],b[N][M];int i,j,sum1=0,sum2=0,sum=0;printf("请输入一个%d*%d的矩阵\n",N,M);for(i=0;i<N;i++){for(j=0;j<M;j++){scanf("%d",&a[i][j]);sum1=sum1+a[i][j];}}printf("请输入一个%d*%d的矩阵\n",N,M);for(i=0;i<N;i++){for(j=0;j<M;j++){scanf("%d",&b[i][j]);sum2=sum2+a[i][j];}}sum=sum1+sum2;printf("sum=%d\n",sum);}8.12#include<stdio.h>#define N7void YangHui(int a[N][N],int n);void main(){int i,j,n,b[N][N];printf("Input n:");scanf("%d",&n);YangHui(b,n);for(i=0;i<n;i++){for(j=0;j<=i;j++){printf("%4d",b[i][j]);}printf("\n");}}void YangHui(int a[N][N],int n){int i,j;for(i=0;i<n;i++){a[i][0]=1;a[i][i]=1;}for(i=2;i<n;i++){for(j=1;j<i;j++)a[i][j]=a[i-1][j-1]+a[i-1][j];}}8.13#include<stdio.h>#define N12void main(){int i;int f[N]={1,1};printf("%d:%d\n",0,f[0]);printf("%d:%d\n",1,f[1]);for(i=2;i<N;i++){f[i]=f[i-1]+f[i-2];printf("%d:%d\n",i+1,f[i]);}}8.14#include<stdio.h>#include<stdlib.h>#include<time.h>#define N6000void main(){int a[N],i;int b1=0,b2=0,b3=0,b4=0,b5=0,b6=0;float p1,p2,p3,p4,p5,p6;srand(time(NULL));for(i=0;i<N;i++){a[i]=rand()%6+1;printf("%3d",a[i]);if(a[i]==1)b1++;if(a[i]==2)b2++;if(a[i]==3)b3++;if(a[i]==4)b4++;if(a[i]==5)b5++;if(a[i]==6)b6++;p1=(float)(b1/6000.0);p2=(float)(b2/6000.0);p3=(float)(b3/6000.0);p4=(float)(b4/6000.0);p5=(float)(b5/6000.0);p6=(float)(b6/6000.0);}printf("骰子出现1的概率：%.2f\n",p1);printf("骰子出现2的概率：%.2f\n",p2);printf("骰子出现3的概率：%.2f\n",p3);printf("骰子出现4的概率：%.2f\n",p4);printf("骰子出现5的概率：%.2f\n",p5);printf("骰子出现6的概率：%.2f\n",p6);}9.1(1)void Swap(int*x,int*y){int*pTemp;//*pTemp未进行初始化，*pTemp指向哪里位置*pTemp=*x;*x=*y;*y=*pTemp;}9.1(2)void Swap(int*x,int*y){int*pTemp;pTemp=x;x=y;y=pTemp;}//错误，x,y没有指向类型9.2#include<stdio.h>int main(){int a[]={1,2,3,4,5};int*p=a;printf("%d,%d,%d,%d,%d,%d,%d\n",*p,*(++p),(*p)++,*p,*p--,--(*p),*p);return0;}9.3#include<stdio.h>void Swap(int*x,int*y);int main(){int a[6]={1,2,3,4,5,6},b[6]={11,22,33,44,55,66};int i;printf("Before Array\n");for(i=0;i<6;i++){printf("%d\n",a[i]);}for(i=0;i<6;i++){printf("%d\n",b[i]);}for(i=0;i<6;i++){Swap(&a[i],&b[i]);}printf("After Array\n");for(i=0;i<6;i++){printf("%d\n",a[i]);}for(i=0;i<6;i++){printf("%d\n",b[i]);}return0;}void Swap(int*x,int*y){int temp;temp=*x;*x=*y;*y=temp;}9.4#include<stdio.h>#define N10void FindMaxMin(int a[],int*pMaxa,int*pMaxnum,int*pMina,int*pMinnum);int main(){int a[N];int i,maxa,mina,maxnum,minnum;printf("Input a:");for(i=0;i<10;i++){scanf("%d",&a[i]);}FindMaxMin(a,&maxa,&maxnum,&mina,&minnum);printf("maxa=%d,maxnum=%d,mina=%d,minnum=%d\n",maxa,maxnum,mina,minnum);return0;}void FindMaxMin(int a[],int*pMaxa,int*pMaxnum,int*pMina,int*pMinnum){int i;*pMaxa=a[0];*pMina=a[0];*pMaxnum=0;*pMinnum=0;for(i=0;i<10;i++){if(a[i]>*pMaxa){*pMaxa=a[i];*pMaxnum=i;}else if(a[i]<*pMina){*pMina=a[i];*pMinnum=i;}}}10.1void MYStrcpy(char*dstStr,const char*srcStr){while((*dstStr++=*srcStr++)!='\0'){}}10.2#include<stdio.h>main(){char*a="main(){char*a=%c%s%c;printf(a,34,a,34);}";printf(a,34,a,34);} 10.3(1)unsigned int MyStrlen(char*p)main(){unsigned int len;len=0;for(;*pa!='\0';pa++){len++;}return len;}10.3(2)unsigned int MyStrlen(char s[]){char*p=s;while(*p!='\0'){p++;}return(p-*p);}10.3(3)int MyStrcmp(char*p1,char*p2){for(;*p1==*p2;p1++,p2++){if(*p1=='\0')return-1;}return1;}10.3(4)int MyStrcmp(char s[],char t[]){int i;for(i=0;s[i]==t[i];i++){if(s[i]=='\0')return0;}return i;}10.3(5)#include<stdio.h>#include<string.h>int main(){char password[7]="secret";char userInput[81];printf("Input Password:");scanf("%s",userInput);if(strcmp(userInput,password)==0)printf("Coorrect password!Welcome to the system...\n");else if(strcmp(userInput,password)<0)printf("Invalid password!user input<password...\n");elseprintf("Invalid password!user input>password...\n");return0;}10.4#include<stdio.h>#define N24unsigned int CountLetter(char str[]);int main(){char a[N];printf("Input a letter:\n");gets(a);printf("The length of the letter is:%d\n",CountLetter(a));return0;}unsigned int CountLetter(char str[]){char*p=str;int c=0,flag=0;while(*p!='\0'){if(*p!='')flag=1;else if(flag==1){c++;flag=0;}p++;}return c+1;}12.1#include<stdio.h>typedef struct data{int year;int month;int day;}DATA;typedef struct work{char a[14];char b[10];char c[6];}WORK;typedef struct student{char studentName[10];char studentSex;DATA birthday;WORK profession;}STUDENT;int main(){STUDENT stu={"王刚",'M',{1991,5,19},{"信息工程系","学习人员","学生"}};printf("stu:%2s%3c%6d/%02d/%02d%4s,%4s,%4s\n",stu.studentName,stu.studentSex,st u.birthday.year,stu.birthday.month,stu.birthday.day,stu.profession.a,stu.profession.b,stu.profession.c);return0;}12.4#include<stdio.h>#include<string.h>#define N10typedef struct people{char peopleName[10];}PEOPLE;int main(){int sum1=0,sum2=0,sum3=0,sum4=0;int i;char name[N][N];PEOPLE stu[5]={"zhang","li","wang"};printf("Enter their name:\n");for(i=0;i<10;i++){gets(name[i]);if(strcmp(name[i],stu[0].peopleName)==0)sum1++;else if(strcmp(name[i],stu[1].peopleName)==0) sum2++;else if(strcmp(name[i],stu[2].peopleName)==0) sum3++;elsesum4++;}printf("stu:%4s%2d\n",stu[i].peopleName,sum[j]);printf("stu:%4s%2d\n",stu[1].peopleName,sum2);printf("stu:%4s%2d\n",stu[2].peopleName,sum3);printf("%2d\n",sum4);return0;}。

程序设计基础教程(c语言版)课后答案课后答案及解析z习题解答课后答案及解析目录1.2 习题解答 (3)1.2.1 选择题 (3)1.2.2 填空题 (3)1.2.3 编程题 (4)2.2 习题解答 (5)2.2.1 选择题 (5)2.2.2 填空题 (7)2.2.3 编程题 (8)3.2 习题解答 (11)3.2.1 选择题 (11)3.2.2 填空题 (12)3.2.3 编程题 (12)4.2 习题解答 (15)4.2.1 选择题 (15)4.2.2 填空题 (17)4.2.3 编程题 (18)5.2 习题解答 (29)5.2.1 选择题 (29)5.2.2 填空题 (31)5.2.3 编程题 (33)6.2 习题解答 (37)6.2.1 选择题 (37)6.2.2 填空题 (41)6.2.3 编程题 (43)7.2 习题解答 (67)7.2.1 选择题 (67)7.2.2 填空题 (68)7.2.3 编程题..................................................................................................68 2课后答案及解析1.2 习题解答1.2.1 选择题1、B在一个C程序中必须有且只能有一个main函数，而且main 函数可以在任何地方出现.2、CC 语言中合法以的标识符组成为：字母，数字，下划线，且数字不能打头，亦不能为关键字。

A中，-sub 不合法。

B 中4d 不合法。

D 中void 为关键字。

3、4、C转义字符中，第一个\”输出“，第二\\输出\,第三个\b退格，把前一个\去掉了，第四个\ 输出，第五个\t跳格，第六个\”输出”，第七个\n输出换行。

5、C本题将10进制17，分别按8、16进制输出。

8的进制21=2*8+1*1=17(10, 16制11=1*16+1*1=17(10)1.2.2 填空题1、主一个C源程序中至少包括一个主函数，其他函数没有限制。

目录第1章C语言编程 (4)练习1.1 (4)练习1.2 (4)练习1.3 (5)第2章编程初步 (5)习题2.1 (5)习题2.2 (6)习题2.3 (7)习题2.4 (9)第3章条件判断 (10)习题3.1 (10)习题3.2 (12)习题3.3 (16)习题3.4 (18)第4章循环 (20)习题4.1 (20)习题4.2 (21)习题4.3 (22)习题4.4 (22)习题4.5 (24)第5章数组 (26)习题5.1 (26)习题5.2 (28)习题5.4 (30)习题5.5 (32)第6章字符串和文本的应用 (34)习题6.1 (34)习题6.2 (41)习题6.3 (43)习题6.4 (44)第7章指针 (47)习题7.1 (47)习题7.2 (49)习题7.3 (51)习题7.4 (52)第8章程序的结构 (54)习题8.1 (54)习题8.2 (55)习题8.3 (57)习题8.4 (60)第9章函数再探 (65)习题9.1 (65)习题9.2 (66)习题9.3 (69)习题9.4 (71)第10章基本输入输出操作 (72)习题10.2 (73)习题10.3 (75)习题10.4 (76)第11章结构化数据 (78)习题11.1 (78)习题11.2 (82)习题11.3 (86)习题11.4 (91)习题11.5 (95)第12章处理文件 (99)习题12.1 (99)习题12.2 (100)习题12.3 (104)习题12.4 (105)第13章支持功能 (110)习题13.1 (110)习题13.2 (111)习题13.3 (112)《C语言入门经典(第4版)》课后练习参考答案第1章 C语言编程练习1.1 编写一个程序，用两个printf()语句分别输出自己的名字和地址。

练习1.2将上一个练习修改成所有的输出只用一个printf()语句。

练习1.3编写一个程序，输出下列文本，格式如下所示："It's freezing in here," he said coldly.第2章编程初步习题2.1 编写一个程序，提示用户用英寸输入一个距离，然后将该距离值输出为码、英尺和英寸的形式。

第1章程序设计和C语言11.1什么是计算机程序11.2什么是计算机语言11.3C语言的发展及其特点31.4最简单的C语言程序51.4.1最简单的C语言程序举例61.4.2C语言程序的结构101.5运行C程序的步骤与方法121.6程序设计的任务141-5 #include <stdio.h>int main ( ){ printf ("**************************\n\n");printf(" Very Good!\n\n");printf ("**************************\n");return 0;}1-6#include <stdio.h>int main(){int a,b,c,max;printf("please input a,b,c:\n");scanf("%d,%d,%d",&a,&b,&c);max=a;if (max<b)max=b;if (max<c)max=c;printf("The largest number is %d\n",max); return 0;}第2章算法——程序的灵魂162.1什么是算法162.2简单的算法举例172.3算法的特性212.4怎样表示一个算法222.4.1用自然语言表示算法222.4.2用流程图表示算法222.4.3三种基本结构和改进的流程图262.4.4用N S流程图表示算法282.4.5用伪代码表示算法312.4.6用计算机语言表示算法322.5结构化程序设计方法34习题36第章最简单的C程序设计——顺序程序设计37 3.1顺序程序设计举例373.2数据的表现形式及其运算393.2.1常量和变量393.2.2数据类型423.2.3整型数据443.2.4字符型数据473.2.5浮点型数据493.2.6怎样确定常量的类型513.2.7运算符和表达式523.3C语句573.3.1C语句的作用和分类573.3.2最基本的语句——赋值语句593.4数据的输入输出653.4.1输入输出举例653.4.2有关数据输入输出的概念673.4.3用printf函数输出数据683.4.4用scanf函数输入数据753.4.5字符数据的输入输出78习题823-1 #include <stdio.h>#include <math.h>int main(){float p,r,n;r=0.1;n=10;p=pow(1+r,n);printf("p=%f\n",p);return 0;}3-2-1#include <stdio.h>#include <math.h>int main(){float r5,r3,r2,r1,r0,p,p1,p2,p3,p4,p5;p=1000;r5=0.0585;r3=0.054;r2=0.0468;r1=0.0414;r0=0.0072;p1=p*((1+r5)*5); // 一次存5年期p2=p*(1+2*r2)*(1+3*r3); // 先存2年期，到期后将本息再存3年期p3=p*(1+3*r3)*(1+2*r2); // 先存3年期，到期后将本息再存2年期p4=p*pow(1+r1,5); // 存1年期，到期后将本息存再存1年期，连续存5次p5=p*pow(1+r0/4,4*5); // 存活期存款。

C程序设计(第四版)(谭浩强)第一章课后习题答案P006 向屏幕输出文字.#include<>代码均调试成功,若有失误大多不是代码问题.自已找找.int main(){printf("Welcome to \n");return 0; }P008 求两个数的和.#include<>int main(){int a,b,sum;a=5;b=4;sum=a+b;printf("The sum is %d .\n",sum);return 0;}P008 调用函数比较两个数的大小.#include<>int main(){int max(int x,int y); int a,b,c;scanf("%d,%d",&a,&b); c=max(a,b); printf("The max is %d .\n",c);return 0;}int max(int x,int y) {int z; if (x>y)z=x;elsez=y;return(z); }P015 三个数的大小.(数字0表示课后练习题)#include<>int main(){int a,b,c,d; int max(int x , int y , int z);printf("Please input 3 numbers :\n");scanf("%d %d %d",&a,&b,&c);d=max(a,b,c); printf("The max is :%d .\n",d); }int max(int x , int y , int z){int m;if (x>y && x>z) m=x;if (y>x && y>z)m=y;if (z>y && z>x)m=z;return (m); }C程序设计(第四版)(谭浩强)第2章课后习题答案算法——程序的灵魂P017 计算机1-5相乘的积.#include<>int main(){int i,s=1; for(i=1;i<6;i++) {s=s*i; n",s);return 0;}#include<> int main(){int i,s=1; for(i=1;i<12;i++) 可以是i=i+2 {if(i%2!=0) s=s*i;elsecontinue; }printf("The sum is %d .\n",s);return 0;}P019 按要求输出80分以上的学生信息.暂时没法做.P019 判断2000-2500年中的闰年,并输出.年的概念是地球围绕太阳一周的时间（所谓公转周期）称为一年，这个周期是相当稳定的，很长时间也不会变动1秒，但是真正的一年是天（目前）。