湖北省部分重点中学2020届高三第一次联考

湖北省部分重点中学2020届高三第一次联考高三物理答案一、选择题：本大题共12小题，每小题4分.在每小题给出的四个选项中，第1~8题只有一项符合题目要求，第9~12题有多项符合题目要求.全部选对的得4分，选对但不全的得2分，有选错的得0分。

13 AC0.183m/s 0.603m/s 2, 偏大 14 10.296—10.299BD =+三、计算题（48分）15（9分）解：（1）环在A 处被挡住立即停止，小球以速度绕A 点做圆周运动，据牛顿第二定律和圆周运动的向心力公式有：2v F mg m L-= 2分绳对小球的拉力大小2F mg = 2分（2）在环被挡住后，细绳突然断裂，此后小球做平抛运动。

假设小球直接落在地面上，则，竖直方向：212h L gt == 水平方向：x vt =联立解得:小球的水平位移x L =>所以小球与右墙碰撞后再落在地上（不说明不扣分）设小球平抛运动到右墙的时间为2t ，则：2L t v ==分 小球在2t 内下降的高度222122Lh gt ==2分 球的第一次碰撞点离墙角B 点的距离122L s L L =-= 1分16 （12分） （1）滑块在木板上运动的过程中，滑块与木板的位移之差等于木板的长度，设滑块刚滑上木板时的速度大小为1v ，滑块滑到木板右端时的速度大小为2v ， 则有：12222v v vt t l +-= 3分 由题图乙可知：24/v m s =，t=2s解得：s m v /101=2分(其他解法正确同样给分)（2）滑块在木板上做匀减速运动，由运动学公式可知：at v v -=12， 1分其中mg ma μ=1分 解得：0.3μ=1分滑块在 全程运动时，由动能定理得：2212f mgR w mv +=2分 解得：52f w J =- 2分即克服阻力做功52J其它方法正确同样给分17（12分） (1)对A 、B 由整体法得：2mg －q A－q=0 2分解得：q A =6q2分(2 )当B 球下落速度达到最大时，由平衡条件得mg=qE=qx 0，解得：x 0=4L 2分 运动过程中，电场力大小线性变化，从x=2L 处到x=4L 处 由动能定理可得：2212244242mmv L LqL mgq L qL mg qmgL =+- 2分解得： gL v m =1分设下降的高度为h ，由动能定理可得2)2(424=++-h h L qLmgq L qL mg qmgh 2分解得：1分其它方法正确同样给分18（15分）（1）设A 球与B 球第一次碰撞前的速度为v 0，碰撞后的速度分别为v A1、v B1。

湖北省部分重点中学2020 届高三第一次联考高三物理试卷命题学校:武汉市第一中学命题教师:王竹青审题教师: 彭芳试卷满分考试时间:2019 年11 月8 号上午10:30-12:00 :110 分一、选择题:本题共12小题,每小题4,第1-8 题只有一项符合题目要分,共48 分。

在每小题给出的四个选项中4 分,求第9-12 题有多项符合题目要求。

全部选对的得,选对但不全的得2 分,有选错的得0 分。

结合有关“场”的知识判断以, ,1.静电场和重力场在某些特点上具有一定的相似性,并进行合理的类比和猜想(下说法中正确的是)A.法国物理学家库仑利用扭秤实验发现了点电荷间的相互作用规律,并测定了元电荷的电荷量并引出电场线来描述电场,B.电场的概念是法拉第建立的,C.如果把地球抽象为一个孤立质点用于形象描述它所产生的重力场的所谓“重力场线”的分布类似于真空中一个孤立的正电荷所产生的静电场的电场线分布D.重力场与静电场相类比,重力场的“场强”等于重力加速度,其“场强”大小的决定式为g=G/ma 车和2.在平直公路上行驶的b 车,其位移时间(x-t)图象分别为图中直线a 和曲线b,已知b 车的加速度恒定且2 (刚好相切,则当等于-2m/s , t=3s,直线a 和曲线 b )8v=A.a 车做匀速直线运动且其速度为m/s3 B.t=3s 时a 车和b 车相遇但此时速度不等C.t=1s 时b 车的速度为10m/s=9m 车的距离xD.t=0 时a 车和b 0B 点到达°,一质点做平抛运动先后经过3.如图所示,A、B 两点到达 A 点时速度方向与竖直方向的夹角为,60) (B 的时间之比是质点运动到45°, A 点与质点运动到时速度方向与水平方向的夹角为132 C.B.A.无法求出,D.条件不够3334.如图所示,质量都为m 的A、B 两物体叠放在竖直弹簧上并保持静止,用大小等于mg 的恒力F向上拉B,B 向( ,上运动运动距离A 与B h 时分离。

湖北省重点中学2020届高三上学期第一次联考化学试卷参考答案1～5 ACDAC 6～10 ABDDD 11～14 CBCA15.（每空1分，共11分）（1）第四周期第Ⅷ族 15 （2） H Na Na+＜O2-＜S2-（3）HClO4 H3BO3+OH-=B(OH)4-（4）（5） 0.1NA（6）F-N=N-F 16.（除注明分数之外每空1分，共7分）（1）Cu和P （2）Ca(H2PO4)2CaHPO4（3）2 Ca3(PO4)2+ 6 SiO2+ 10C 6CaSiO3+ 10CO↑+ P4（2分）（4）PH3正盐（5）3n＋1 17.（除注明分数之外每空1分，共7分）（1） Cu2S+O2（适量）2Cu+SO2（2分） O2和Cu2S（2）① +6②强氧化性③ABC18. （除注明分数之外每空2分，共16分）（1）去油污（1分）铁（1分）（2）bcae（3）取最后的洗涤液，向其中滴加盐酸酸化的氯化钡溶液，不产生白色沉淀，则已洗涤干净（4）温度太低反应速率慢，温度高过氧化氢会分解 (两个要点各1分)2FeC2O4·2H2O+H2O2+H2C2O4+3C2O42-=2[Fe(C2O4)3]3-+6H2O（5）除去晶体表面的水分，快速干燥（6）（7）铁氰化钾溶液19.（除注明分数之外每空2分，共17分）（1）4VOSO4+O2⇌2V2O5+4SO3（2）①② 2︰3（3）10Al(s)+3V2O5（s）= 5Al2O3(s)+6V(s) △H=-2421.5kJ/mol（4）① V2+ +VO2++2H+=V3++VO2++H2O②参与正极反应，通过隔膜向正极定向移动形成闭合回路(两个要点各1分)减少1mol③ VO2+ +H2O - e－＝VO2+ +2H+降低（1分）。

湖北省重点中学2020届高三上学期第一次联考英语试卷湖北省部分重点中学2020届高三第一次联考高三英语参考答案听力：1-5. ACACA 6-10. BACAB 11-15. BABBC 16-20. ACBBB阅读：21-23 CCD 24-27 DCAC 28-31 CBAD 32-35 DADB36-40 DEFBG完形：41-45 CBADA 46-50 BDCBA 51-55 CADBC 56-60 DACBD填词：61. most difficult 62. has become 63. curiosity 64. but 65. Moving66. easily 67. which 68. from 69. memories 70. a改错：Dear Mr. Lee,I’m very exciting to write to you to express my thanks.excitedI am Li Hua, one of the poor children who was crying for knowledge, but couldn’t afford thewereschool fees because my father was ill or my family was deeply in debt. Thank you for give meand givinggenerous support so that I could have the chance ∧go back to school. Has it not been for the support,to HadI wouldn’t have realized my dream. Your help has made much difference to me. I was going to spreadamthe love to help people in the need.In brief, my appreciation for your kindness can never be expressed in word. Please accept mywordssincerely gratitude.sincereYours.Li Hua书面表达：Possible version:Dear Peter,Glad to hear from you. Since you asked me about the National Day celebrations this year, I am honored to tell you some details.It was in order to show our love for the motherland that my school held a singing competition the day before the National Day. Every class was required to choose a song about loving our motherland to compete against each other and we practiced a lot before the final competition. Without doubt all the students tried their best to sing well. Owing to our efforts, my class won the first prize in the end, which we thought was the most significant gift for our country.On October 1st, there was a grand Chinese military parade on the Tiananmen Square to celebrate the 70th birthday of our country. Most people in China watched the live broadcast of it on TV or on the Internet, which was supposed to be one of the most popular events during the 7-day holiday.In a word, never have I experienced a more unforgettable holiday before. How I wish you had come to China and watched the parade with me at that time!Best wishes!YoursLi Hua听力原稿Text 1M: Are you going to the first floor too, Madam?W: I am going to the parking lot. Could you please help me push the P2 button?Text 2M: This laptop costs two thousand dollars, but I only have twelve hundred.W: Don't worry, I can lend you the rest.Text 3W: How was the party last night?M: It was too crowded and the food was gone before I got there.W: What time did you get home?M: It was pretty boring so I left at ten and got home before eleven.Text 4M: How was the weather for your hiking trip last Saturday?W: It rained a little in the morning, but got sunny in the afternoon.M: Did you have a lot of fun?W: Sure.Text 5W: The new clothes shop has a variety of styles, but everyone does their shopping on Saturday so there aren't enough changing rooms.M: And I heard the prices are really high.Text 6W: I’ve got two tickets for a volleyball match this evening. Why don't you come with me?M: Uh. No, thanks. I'm interested in basketball and football. And you know, there is an important football game on TV tonight.W: Oh, you don’t know what you're missing?M: Don't I? Why?W: It's very fast, with lots of action, and very exciting.M: Really? Who's playing?W: Two of the best women's teams in the world, one from Finland and the other from Belgium. By the way, Brazilian team is my favorite.M: Mmm, it sounds exciting.W: Yes, it is!Text 7W: So, this is the kitchen...I keep the dishes in the cupboards above the electric cooker. In the bottom ones, I keep all the cleaning supplies. We have a microwave above the stove.M: All right. I don't cook much, anyway. Is there a specific time you use the kitchen?W: I don't really have any specific rules. Feel free to use it whenever you need it.M: OK, got it. And what about bills and house supplies?W: We split the gas, water, and electricity bills. As far as supplies, we usually take turns from month to month. This month, it's my turn to buy. Next month, it's yours.Text 8M: Have you tried that new restaurant downtown? It looks fancy.W: No, I haven’t been there yet. What type of food do they serve?M: I think it's Italian.W: I don' t like Italian food very much. I prefer Japanese or Indian food. But I guess I could give it a try.M: I can make a reservation for some night this week.W: Okay. Monday and Wednesday are better because I'm off work early on those days.M: I'll see if they can take us either of those days. What about Friday or Saturday?W: Saturday could work, but I thought we had Sara's party to go to this weekend. We haven't seen her in a long time - not since her wedding! Isn’t her party on Saturday?M: Yeah, you're right. Then Monday is probably the best because I have an early work meeting and will be home by the afternoon.W: Yeah. Monday is the best for me too, actually, I like to go to the gym on Tuesdays after work, anyway.Text 9M: We have Molly Taylor in the studio today. Molly is arranging a holiday course to teach children a variety of activities. Molly, this is the second year for the course, isn't it?W: Yes. It was for six weeks last year. This year it will be for seven, since some schools finish term a week early. And in fact, the two private schools in the town have an eight-week summer holiday.M: What was last year’s course like?W: There were a few problems. We didn't have enough staff to look after all the children who wanted to attend. And then there was such a lot of rain that we couldn't go outside.M: So what activities can the children look forward to this year?W: The course is currently available for children aged eight to thirteen. There will be art and music classes, as there were last year. We considered putting in some adventure sports, such as rock climbing, but decided not to in the end because they would have made the course more expensive. Instead, we’re introducing some fun projects, such as putting on a talent show.M: Wonderful! I hope it's a success!Text 10Doctors at the famous Cambridge University think that hip-hop music can help depressed and mentally ill people. They say with "hip-hop treatment”, many of the words to the hip-hop songs can reach out to people with emotional problems. A team of doctors wrote a report about this in a special medical magazine. The doctors said a lot of hip-hop music speaks of getting over hardships and big difficulties in life. The report on hip-hop and mental health says hip-hop artists use their talents to des cribe their world and be free. There’s often a message of hope in the lyrics. The doctors chose five hip-hop songs for the treatment. One of them is “the Message” by Grandmaster Flash. Another is called “Juicy” by the Notorious BIG. This tells people they can be successful even if others say they can't. BIG explains how teachers said he would be nothing, but then he became a superstar.。

2020届湖北省部分重点中学高三第一次联考试卷理综高中化学第I卷〔选择题，共126分〕一、选择题〔此题包括13小题。

每题只有一个选项符合题意〕。

6.新型无机材料碳化钛〔TiC〕，碳化硼〔B4C3〕，氮化硅〔Si3N4〕等称为非氧化物陶瓷，合成这些物质需在高温条件下进行，在合成工艺中必须注意：A. 通入充足的氧气B. 幸免与氧气接触C. 可在氮气气氛中合成D. 通入氟气7.以下讲法或表示方法中正确的选项是：A. 等质量的硫蒸气和硫磺分不完全燃烧，后者放出的热量多B. 氢气的燃烧热为285.8kJ · mol-1，那么氢气燃烧的热化学方程式为2H2(g) ＋ O2(g) ＝ 2H2O(l)；△H＝－285.8 kJ· mol-1C. Ba(OH)2 · 8H2O(s) ＋ 2NH4Cl(s) ＝ BaCl2(s) ＋ 2NH3(g) ＋ 10H2O(l)；△H＜0D. 中和热为57.3 kJ · mol-1，假设将含0.5mol H2SO4的浓溶液与含1mol NaOH的溶液混合，放出的热量要大于57.3 Kj8.C3N4晶体具有比金刚石还大的硬度，且每个原子的最外层均满足8电子结构。

以下关于C3N4晶体的讲法正确的选项是:A. C3N4晶体可能是分子晶体，晶体中微粒间通过共价键相结合B. C3N4晶体中每个碳原子连接4个氮原子，每个氮原子连接3个碳原子C. C3N4晶体中，C—N键的键长比金刚石中C—C键的键长要长D. C3N4晶体中每个氮原子上还有2对未共用电子9.以下能够使反应：Cu+2H2O=C u(O H)2+H2↑获得成功的是：A. 铜片作原电池的负极，碳棒作原电池的正极，氯化钠作电解质溶液B. 铜——锌合金在潮湿的空气中发生电化学腐蚀C. 用铜片作阴、阳电极，电解氯化钠溶液D. 用铜片作阴、阳电极，电解硫酸铜溶液10.以下各组顺序不正确的选项是：A. 粒子半径：S2-＞Cl -＞ F -＞Na+＞Mg2+B. 热稳固性：SiH4 ＜ PH3＜ NH3＜ H2O ＜ HFC. 熔点： S i O2＞ NaCl ＞干冰＞碘＞臭氧D. 还原性：HF ＜ HCl ＜ HBr ＜ HI ＜ H2S11.以下除去杂质的方法正确的选项是A. 除去FeCl2溶液中的少量FeCl3: 加入足量铁屑，充分反应后过滤B. 除去CO2中的少量HCl: 通入Na2CO3溶液，收集气体C. 除去N2中的少量O2: 通过灼热的CuO粉末，收集气体D. 除去KCl溶液中的少量MgCl2: 加入适量NaOH溶液，过滤12.以下反应的离子方程式正确的选项是：A. 用惰性电极电解MgCl2溶液：2Cl-＋2H2O Cl2↑＋H2↑＋2OH -B. 向次氯酸钙溶液中通人过量CO2：ClO-＋CO2＋H2O ＝ HClO＋HCO3-C. 小苏打溶液与甲酸溶液混合：HCO3-＋H+＝ H2O＋CO2↑D. 硫酸亚铁溶液中加入H2O2溶液：Fe2+＋H2O2＋2H+ ＝ Fe3+＋2H2O13.以下反应中，同时有离子键、极性共价键和非极性共价键的断裂和形成的反应是：A. NH4Cl NH3↑＋ HCl↑B. Na2CO3＋CO2＋H2O＝2NaHCO3C. 2NaOH＋Cl2 ＝NaCl＋NaClO＋H2OD. 2 Na2O2＋2CO2＝2Na2CO3＋O2第II卷〔非选择题，共174分〕三、非选择题。

湖北省部分重点中学2020届高三第一次联考高三数学试卷（理科）一、选择题：（本大题共12小题，每小题5分共60分；在每小题给出的四个选项中，只有一个选项是符合题目要求的）1.集合{}260A x x x =--<，集合{}2|log 1B x x =<，则A B = （）A.()2,3-B.(),3-∞C.()2,2-D.()0,22.已知a 是实数，1a ii +-是纯虚数，则a 等于（） A.2- B.1- C.2 D.13.若2sin cos 12x x π⎛⎫-+= ⎪⎝⎭，则cos 2x =（）A.89- B.79- C.79 D.-14.已知{}n a 为等比数列，若3528a a ==，，则78a a +=（）A.-32B.96C.-32或96D.-96或325.点P 是ABC △所在平面上一点，若2355AP AB AC =+，则ABP △与ACP △的面积之比是（）A.35 B.52 C.32 D.236.下列说法正确的个数是（）①命题“若4a b + ，则a ，b 中至少有一个不小于2”的逆命题是真命题②命题“设a b R ∈，，若5a b +≠，则3a ≠或2b ≠”是一个真命题③“20000x R x x ∃∈-<，的否定是“20x R x x ∀∈->，”④已知x ，y 都是实数，“||||1x y + ”是“221x y + ”的充分不必要条件A.1B.2C.3D.47.下列函数中，既是偶函数，又在(),0-∞内单调递增的为（）A .2||y x x =- B.||2x y = C.22x x y -=- D.212log ||y x x =-8.已知定义在R 上的奇函数21()2x x f x a-=+，则不等式()2(2)40f x f x -+-<的解集为（）A.（-1，6） B.（-6，1） C.（-2，3） D.（-3，2）9.AOB 中，OA a OB b == ，，满足||2a b a b ⋅=-= ，则AOB ∆的面积的最大值为（） A.3 B.2 C.23 D.2210.已知函数log (1),(11)()(2)1,(13)a x x f x f x a x +-<<⎧=⎨-+-<<⎩（0a >且1a ≠），若12x x ≠，且()()12f x f x =，则12x x +的值（）A .恒小于2 B.恒大于2 C.恒等于2 D.以上都不对11.已知函数22()2sin cos sin (0)24x f x x x ωπωωω⎛⎫=⋅--> ⎪⎝⎭在区间25,36ππ⎡⎤-⎢⎥⎣⎦上是增函数，且在区间[0]π，上恰好取得一次最大值1，则ω的取值范围是（）A.30,5⎛⎤ ⎥⎝⎦ B.13,25⎡⎤⎢⎥⎣⎦ C.13,24⎡⎤⎢⎥⎣⎦ D.15,22⎡⎫⎪⎢⎣⎭12.已知对任意实数x 都有()2()(0)1x f x e f x f '=+=-，，若不等式()(1)f x a x <-，（其中1a <）的解集中恰有两个整数，则a 的取值范围是（）A.3,12e ⎡⎫⎪⎢⎣⎭ B.3,12e ⎡⎫-⎪⎢⎣⎭ C.253,32e e ⎡⎫⎪⎢⎣⎭ D.25,13e ⎡⎫⎪⎢⎣⎭二、填空题（本大题共4个小题，共20分）13.已知实数x ，y 满足约束条件30,20,2,x y x y x -+⎧⎪+⎨⎪⎩则3z x y =+的最小值为___________.14.非零向量a 和b 满足2a b = ，()a ab ⊥+ ，则a 与b 的夹角为___________.15.已知函数()2sin 23f x x π⎛⎫=+⎪⎝⎭在区间173a π⎛⎫ ⎪⎝⎭，上是单调函数，则实数a 的最大值为__________.16.已知函数21()ln()22x x f x g x e -=+=，，若(0)m R n ∀∈∃∈+∞，，使得()()g m f n =成立则n m -的最小值是__________.三、解答题（本大题共6小题共70分解答应写出证明过程或算步）17.已知数列{}n a 满足11a =，135n n a a n ++=+，1,2,3n =（1）证明：113n n a a +--=，2,3n = ；（2）求和：12233445212122n n n n a a a a a a a a a a a a +--+-+-+ 18.如图，在ABC △中，M 是边BC 的中点，57cos 14BAM ∠=，27cos 7AMC ∠=-.（1）求B Ð的大小；（2）若7AM =，求ABC △的面积.19.已知四棱锥P ABCD -中，侧面PAD ⊥底面ABCD ，PB AD ⊥，PAD △是边长为2的正三角形底面ABCD 是菱形，点M 为PC 的中点（1）求证：PA 平面MDB ；（2）求二面角A PB C --的余弦值.20.已知椭圆2222:1x y C a b +=的离心率为22其右顶点为A ，下顶点为B ，定点()02C ，，ABC △的面积为322过点C 作与y 轴不重合的直线l 交椭圆C 于P Q ，两点，直线BP BQ ，分别与X 轴交于M N ，两点.（1）求椭圆C 的方程；（2）试探究M N ，的横坐标的乘积是否为定值，说明理由.21.某汽车公司最近研发了一款新能源汽车，并在出厂前对100辆汽车进行了单次最大续航里程的测试。

A.向左B.向右C.向上D.向下（第17题图）18.如下图，A 为一放在竖直轻弹簧上的小球, 在竖直向下恒力 F 的作用下，在弹簧弹性限度内，弹簧由原长压缩到B 点，现突然撒去力 F ,小球将向上弹起直至速度为零，那么小球在上升过程中〔不计空气阻力〕A. 小球，弹簧和地球组成的系统包括弹性势能在内的机械能守恒B. 小球速度减为零时，还未脱离弹簧（第18题图）2020届湖北省部分重点中学高三第一次联考试卷理综高中物理第I 卷〔选择题，共126分〕二、选择题〔此题包括 8小题，每题给出的四个选项中，有的只有一个选项正确，有的有多 个选项正确，全部选对的得 6分，选对但不全的得 3分，有选错的得0分〕。

14.采纳绝热〔即系统不与外界交换热量〕的方式使一定质量的理想气体由初态 A 变化至终态B,关于不同的绝热方式以下讲法正确的选项是:A. 对气体所做的总功不同C.对气体不需做功，因为没有热的传递 15. 以下讲法正确的选项是：A. 光波是一种概率波，也是一种电磁波B.单色光从光密介质进入光疏介质时，光子的能量改变C. 爱因斯坦为讲明光电效应的实验规律提出了光子讲D. 爱因斯坦的质能方程为核能的开发和利用提供了理论依据16. 质量相等的两颗人造地球卫星 A 和B,分不在不同轨道上绕地球做匀速圆周运动，两卫 星的轨道半径分不为 r A 和r B ,且">® 那么A 和B 两卫星比较，以下讲法正确的选项是:A.卫星A 受到地球引力较小B.卫星A 的动能较大+C.卫星B 的运动周期较大D.卫星A 的机械能较大17. 如下图，当波沿着一条一端固定的绳子传播到B 点的波形图，由图可判定出 A 点开始振动的方向是：B.对气体所做的总功相同 D.以上三种讲法都不对FBC. 小球机械能逐步增大D. 小球动能先增大后减小19. 在水平面内有一固定的 U 型裸金属框架，框架上放置一根重金 属杆ab ,金属杆与框架接触电阻不计，整个装置放在竖直方向的 匀强磁场中，如下图：A. 只有当磁场方向向上且增强， ab 杆才可能向左移动B.只有当磁场方向向下且减弱， ab 杆才可能向右移动C.不管磁场方向如何，只要磁场减弱， ab 杆才有向右移动的可能D. 当磁场变化时，ab 杆中一定有电流产生，但它不一定移动 20. 一质量m 2kg 的能够看作质点的物体，受到一个变力作 用，从静止做变加速度直线运动， 其加速度a 随时刻t 的变化规 律如下图，那么该物体在 4.0s 末的动量值为：A. 30kg • m/sB. 40kgC. 80kg • m/sD. 20kg21. A 、B 两小球在光滑水平面上沿同一直线向同一方向运动， A球的动量为5kg - m/s , B 球的动量为7kg - m/s ,当A 球追上B 球时发生对心碰撞，那么碰 撞后A 、 B 两球动量的可能值为：A. P A 6kg m/s, P B 6kg m/sB. P A 3kg 1m/s, P B9kg m/sC.P A2kg m/s, P B14kg m/sD. P A 5kg1m/s, P B 17kg m/ s第II 卷〔非选择题，共174分〕-m/s -m/sa〔第19题图〕三、非选择题。