2016-高一下学期期末考试试题
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2016—2017学年高一年级第二学期期末考试考生注意:(1)本试题满分120分,考试时间100分钟(2)将各题答案按序号答在答题卡上,试卷考生自己保存第I卷第一部分:阅读理解(共20小题,每小题2分,满分40分)第一节(共15小题,每小题2分,满分30分)阅读下列短文,从每题所给的四个选项(A、B、C和D)中,选出最佳选项。
AThere are a lot of products out there that make your life ea sier. Some, however, are a little sillier than others — so much that they seem like joke products. Here are a few products tha t sound crazy, but actually rule.Sleep PhonesIt’s hard to imagine something sillier than a music-playing headband you wear while you sleep, but they exist —and are quite popular. Sleep Phones won’t give you the highe st quality sound in the world, but if you prefer to fall asleep to music, they’re far more comfortable than normal headphones. While they’re a bit expensive, they might be perfec t for you. There’s also a wireless version (版本) if you prefer. Onion GogglesIf cutting onion brings on the waterworks no matter what you t ry, it’s time for desperate measures. We tested a bunch of me thods for avoiding onion tears, and found the best solutions c ame down to cutting the onion under a vent (通风孔), or wearing these stylish and awesome goggles.Lock LacesThere’re some great ways to tie your shoes better, but if you l ong for the laceless shoes of your childhood days, Lock Lace s are a pretty good choice. They’re basically elastic (有弹性的) laces that remove the need to tie your shoes. Sure, peopl e will make fun of you, but you can make fun of them after the y trip over their own untied laces. Or you can make your own slip-on shoes with elastic tubing.2D-GlassesHate 3D-movies, but have to go to one? The difference between 2D-glasses and 3D-glasses lies in their lenses (镜片). Each lens of 2D-glasses blocks the same picture, so each eye gets the same picture, while each lens of 3D-glasses blocks a different picture, so each eye gets a different picture which the brain interprets as 3D. Now you have a pair of glasses that can save you from the headache caused by w earing 3D-glasses which are popular in our movie theaters. You can buy them or make a pair for yourself.1.What do we know about Sleep Phones?A. There are two versions.B. They’re comfortable but unhealthy.C. They give you the best quality sound.D. They’re cheaper than other headphones.2.The underlined part “b rings on the waterworks” in the text probably means _____.A. makes your eyes waterB. makes your fingers hurtC. destroys your water pipesD. adds to your washing work3.What is the advantage of Lock Laces?A. They are strong and lasting.B. They help you walk comfortably.C. They are stylish and eco-friendly.D. They save you from tying your shoes.4.Compared with 3D-glasses, 2D-glasses _____.A. are cheaper and thinnerB. won’t give you a headacheC. let you see a different pictureD. are more popular in movie theaters.BThe arts, especially music, should be part of every school's lessons at every grade level. Students would be much smart er if they had some musical experience. They could improve t heir classroom skills,such as paying attention and following di rections and so on. People develop all these skills when they l earn music. Making music also lets children use their imaginat ion. It provides students with a chance to try out their own ide as.Music not only makes children better students, but also gives them something positive to do. In a music program, children c an be part of a band instead of joining a gang (团伙). Parents can enjoy listening to their children's music instea d of seeing them glued to a computer or TV screen. In a scho ol band, students get to be part of a team. They can get along well with old friends and make new friends through music.Music builds self-confidence, too. It gives children a sense of achievement and success. Making music is something for them to be proud of, and it lets kids practice performing in front of an audience. Mu sic gives children an opportunity for self-expression, and that helps develop their self-confidence. Once again, music is important because it can make children better students, give them something positive to do, and build their character. That is why music should be offered in every s ingle grade in every school.5.According to the passage, music could make students sm arter by _______________.A. improving their classroom skills and paying attentionB. improving their classroom skills and imaginationC. improving their attention, direction and imaginationD. learning music, making music and trying out their own idea s6.What does the underlined phrase "glued to" in the second paragraph mean?A. unwilling to turn onB. always lookingC. unwilling to leaveD. always playing7.The third paragraph mainly tells us that music could _____ __________.A. give children self-expression and self-confidenceB. bring to children achievement and successC. give children something to be proud ofD. develop children's self-confidence8.What's the best title of this passage?A. Music is a must as a course at schoolB. Music builds children's self-confidenceC. Music makes students much smarterD. Learning music and making music.CThe spread of Western eating habits around the world is ba d for human health and for the environment. Those findings c ome from a new report in the journal Nature.David Tilman is a professor at the of . In the study, he examin ed information from 100 nations to show what people ate and how diet affected health. Mr. Tilman noted a movement begin ning in the 1960s. He found that as nations industrialized(工业化), population increased and earnings rose. More people began to adopt what has been called the Western diet. The Wes tern diet is high in sugar, fat, oil and meat. By eating these foo ds, people began to get fatter and sicker.“The food, let us say, in the 15 richest nations of the world, rig ht now contains about 400 or 500 extra calories(热量) a day that are eaten beyond what people need, and that le ads people to gain weight.”David Tillman says overweight people are at greater risk for di seases like diabetes, heart disease and some cancers. Diabet es is shooting to very high rates in the United States and acro ss Europe. Heart disease is a major cause of death in the We stern nations. Unfortunately when people become industrializ ed, if they adopt this Western diet, they are going to have thes e same health problems.A diet bad for human beings, it seems, is also bad for the envi ronment. As the world’s population grows, experts say more f orests and areas will become farmland for crops or grassland s for raising cattle. These areas will be needed to meet the inc reasing demand for food.Mr. Tilman calls the link between diet, the environment and hu man health, “a dilemma”, a situation where it is very difficult to decide what to do. He says one possible solution is leaving th e Western diet behind.9.Why did people get fatter in the 1960s?A. They ate foods high in calories.B. They adopted a western lifestyle.C. They set aside little time for exercise.D. They had a better life and became lazier.10.According to the text, overweight people may suffer the foll owing diseases EXCEPT_____.A. diabetesB. skin diseaseC. cancersD. he art disease11.What can we infer from Paragraph 5?A. There will be fewer and fewer forests.B. People won’t care about the environment.C. The world’s population will grow faster than ever.D. Raising cattle will be the most moneymaking business. 12.What is the purpose of the author in writing this passage ?A. To tell people effective ways to keep healthy.B. To call on people to give up the Western diet.C. To show the problems industrialized nations are facing.D. To draw people’s attention to environmental protection.DWhile astronauts in space get to do many exciting things, t hey miss out on ordinary things that we will take for granted—being able to walk on firm ground, hanging out with family and digging into a slice of hot steaming pizza. Though not much c an be done about the first two things, there may soon be a sol ution to the third one, thanks to this cool 3-D pizza printer. About a year ago, NASA offered $125,000 to Anjan Contracto r, a 3-D technology expert, to build a device that would allow astron auts to make pizza on demand. The mechanical engineer pro mised that his invention would produce pies in large quantities that looked, tasted and even smelledlike pizza made in common ovens.Late last year, the engineer presented a video of his first proto type(原型) that begins by creating a single slice of dough that is cook ed and printed at the same time. Then comes the tomato sau ce--a mix of tomato powder, oil and water and finally, a protein sli ce that resembles cheese. While the video doesn't show theb aking process, the inventor says that once the pizza is printed, it can be ready to be consumed in 7 seconds.While the pie in the video looks delicious enough to attract an y pizza lover, Anjan Contractor is far from ready for astronaut s. That's because he still has to find a solution to make the fo od container in the printer last for 30 years. Though that may sound unrealistic ,actually it is not.Anjan Contractor believes that the only way that is possible is that the water is removed from all the ingredients and then the y are reduced to the powder form. This, as you can imagine, will not be so easy. But, while the printer may not be ready for space, it certainly looks ready enough for people on earth. H opefully, NASA and Contractor will consider selling it to those not fortunate enough to go to Mars !13.NASA offered $125,000 to Anjan Contractor mainly to __ __.A. create some new type of 3-D printerB. attract more companies to work for NASAC. help astronauts in space enjoy fresh pizza one dayD. produce pizza in large quantities to earn great profits 14.The biggest challenge that Anjan Contractor is faced with now is probably that ____A. he has no money left to go on with his researchB. the pizza doesn't seem appetizing(令人开胃的) to pizza loversC. he has no way to make pizza that can last for thirty yearsD. he cannot make the food container last for decades 15.What's the best title of the passage?A. NASA is trying its best to help astronautsB. Astronauts may soon be able to enjoy steaming hot pizzaC. NASA is working on making pizza for common peopleD. A 3-D pizza printer has been used to make pizza第二节:七选五(共5小题,每小题2分,满分10分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。
2014年重庆一中高2016级高一下期期末考试数 学 试 题 卷 2014.7第Ⅰ卷(选择题,共50分)【试卷综评】本次试卷(1) 注重基础知识、基本技能的考查,符合高考命题的意图和宗旨。
让不同的考生掌握不同层次的数学,让几乎所有的考生都能感受到成功的喜悦。
注重基础知识的考查,这样让所有同学对数学学习有了更强的信心。
(2) 注重能力考查 初等数学的基础知识是学生进入高等学校继续学习的基础,也是参加社会实践的必备知识.考查学生基础知识的掌握程度,是高考的重要目标之一.要善于知识之间的联系,善于综合应用,支离破碎的知识是不能形成能力的.考查时,既要注重综合性,又兼顾到全面,更注意突出重点.一、选择题:(本大题共10个小题,每小题5分,共50分)在每小题给出的四个选项中,只有一项是符合题目要求的;各题答案必须答在答题卡上相应的位置.1. 已知等差数列{}n a 中,282a a += ,5118a a +=,则其公差是( )A . 6B .3C .2D .1【知识点】等差数列的性质;等差数列的通项公式.【答案解析】D 解析 :解:∵等差数列{a n }中5118a a +=,282a a +=∴511286,a a a a +-+=即66,1d d ==,故选:D.【思路点拨】将两式5118a a +=,282a a +=作差,根据等差数列的性质建立公差的等式,解之即可.2. 已知直线01)1(:1=+++y a ax l ,02:2=++ay x l ,则“2-=a ”是“21l l ⊥”的( )A .充分不必要条件B .必要不充分条件C .充分必要条件D .既不充分也不必要条件【知识点】两直线垂直的充要条件.【答案解析】A 解析 :解:因为21l l ⊥,则()110a a a ⨯++=,解得2-=a 或0a =,所以“2-=a ”是“21l l ⊥”的充分不必要条件.故选:A.【思路点拨】利用两直线垂直的充要条件解方程可得2-=a 或0a =,然后判断即可.3.学校为了解学生在课外读物方面的支出情况,抽取了n 个同学进行调查,结果显示这些同学的支出都在[10,50)(单位:元),其中支出在[)30,50(单位:元)的同学有67人,其频率分布直方图如右图所示,则n 的值为( )A .100B .120C .130D .3904.(原创)口袋中有形状和大小完全相同的四个球,球的编号分别为1,2,3,4,若从袋中随机抽取两个球,则取出的两个球的编号之和大于5的概率为( )5.如图. 程序输出的结果s=132 , 则判断框中应填( )A. i ≥10B. i ≥C. i ≤11D. i ≥12 【知识点】程序框图.【答案解析】B 解析 :解:由题意,S 表示从12开始的逐渐减小的若干个整数的乘积,由于12×11=132,故此循环体需要执行两次所以每次执行后i 的值依次为11,10,由于i 的值为10时,就应该退出循环,再考察四个选项,B 符合题意 故选B【思路点拨】由框图可以得出,循环体中的运算是每执行一次s 就变成了s 乘以i ,i 的值变为i-2,故S 的值是从12开始的逐渐减小的若干个整数的乘积,由此规律解题计算出循环体执行几次,再求出退出循环的条件,对比四个选项得出正确答案.6.圆()221x a y -+=与直线y x =相切于第三象限,则a 的值是( ).A .2B .2-C ..2【知识点】圆的标准方程;点到直线的距离公式.【答案解析】C 解析 :解:由圆()221x a y -+=,得到圆心(a ,0),半径r=1, 根据题意得:圆心到直线y x =1,=解得:a =∵圆与直线相切于第三象限,∴a <0.即a =故选C .【思路点拨】由圆方程找出圆心坐标与半径,根据题意得到圆心到切线的距离等于圆的半径,利用点到直线的距离公式列出关于a 的方程,求出方程的解即可得到a 的值.7.已知点(,)P x y 在不等式组⎪⎩⎪⎨⎧≥-+≤-≤-0220102y x y x 表示的平面区域上运动,则z x y =-的取值范围是( )A.[]2,1--B. []1,2-C. []2,1-D.[]1,2【知识点】简单的线性规划.【答案解析】B 解析 :解:画可行域如图,画直线y x =,平移直线y x =过点A (0,1)时z 有最大值1;平移直线y x =过点B (2,0)时z 有最小值-2;则z y x =-的取值范围是[-2,1]故选B.【思路点拨】根据步骤:①画可行域②z 为目标函数纵截距③画直线0=y-x ,平移可得直线过A 或B 时z 有最值即可解决.【典型总结】本题主要考查了简单的线性规划,以及利用几何意义求最值.8.设{}n a 是公比为q 的等比数列,令1n n b a =+,*n N ∈,若数列{}n b 的连续四项在集合}{53,23,19,37,82--中,则q 等于( )A .4-B .3-C .3-或2-D .3-或4-9.已知在平面直角坐标系xoy 中,圆C 的方程为2223x y y +=-+,直线l 过点(1,0)且与直线10x y -+=垂直.若直线l 与圆C 交于A B 、两点,则OAB ∆的面积为( )A .1B .2 D .【知识点】点到直线的距离公式;直线的方程;圆的方程;直线与圆的位置关系.【答案解析】A 解析 :解:∵圆C 的方程为x 2+y 2=-2y+3,∴化成标准方程,可得x 2+(y+1)2=4, 由此可得圆的圆心为C (0,-1)、半径为2.∵直线x-y+1=0的斜率为1且与直线l 垂直,直线l 经过点(1,0), ∴直线l 的斜率为k=-1,可得直线l 的方程为y=-(x-1),即x+y-1=0.因此,圆心C 到直线l 的距离d ==AB =又∵坐标原点O 到AB 的距离为d'2,=出圆心C 到l 的距离d =公式即可算出△OAB 的面积.10. (原创) 设集合},,)2(2|),{(222R y x m y x m y x A ∈≤+-≤=, },,122|),{(R y x m y x m y x B ∈+≤+≤=, 若A B φ=,则实数m 的取值范围是( )A 21m ≤≤ B. 02m <<+C. 21m m <->D. 122m m <>+或【知识点】直线与圆的位置关系.【答案解析】D 解析 :解:因为A B φ=,则ÆA=或蛊A ,(1)当ÆA=时,必有22m m <,解得10m <<,满足题意.①0A {20}B {x y |0x y 1}m ===? 时,(,),(,),此时A B φ=,满足题意;②当m 0<时,有||m m --<且<;则有m m 2--->,>, 又由m 0<,则22m 1+>,可得A B φ=,满足题意;③当m ³1m |m ,解可得:221122m m m m ><->+<-,又由m ³2m >第Ⅱ卷(非选择题,共100分)二、填空题:(本大题共5个小题,每小题5分,共25分)各题答案必须填写在答题卡相应的位置上.11. 在△ABC 中,角,,A B C 所对的边分别为,,a b c ,已知2a =,3c =,60B =︒.则b 60B =︒,∴由余弦定理得:222b a c 2accos B 49=+-=+-【思路点拨】利用余弦定理列出关系式,将a ,c 及cosB 代入计算即可求出b 的值.12.在区间[5,5]-内随机地取出一个数a ,使得221{|20}x x ax a ∈+->的概率为 . 【知识点】几何概型.【答案解析】0.3解析 :解:由题意221{|20}x x ax a ∈+->,故有22a a 0>+-,解得1a 2<<-,由几何概率模型的知识知,总的测度,区间[5,5]-的长度为10,随机地取出一个数a ,使得221{|20}x x ax a ∈+->这个事件的测度为3故区间[5,5]-内随机地取出一个数a ,使得221{|20}x x ax a ∈+->的概率为0.3 故答案为0.3【思路点拨】由221{|20}x x ax a ∈+->代入得出关于参数a 的不等式,解之求得a 的范围,再由几何的概率模型的知识求出其概率.【典型总结】本题考查几何概率模型,求解本题的关键是正确理解221{|20}x x ax a ∈+->的意义,即得到参数a 所满足的不等式,从中解出事件所对应的概率.13.若直线)0,(022>=-+b a by ax 始终平分圆082422=---+y x y x 的周长,则ba 121+的最小值为【答案22x 2y 113()(),-+-=∴圆的圆心是(2,1),∵直线平分圆的周长,所以直线恒过圆心(2,1),把(2,1)代入直线)0,(022>=-+b a by ax ,得1a b +=()111322b a a b b a b a b⎛⎫+=++=++ ⎪⎝⎭∵a >0,b >0,()1113222b a a b b a b a b ⎛⎫=++=++≥ ⎪⎝⎭故答案为:. 【思路点拨】先求出圆的圆心坐标,由于直线平分圆的周长,所以直线恒过圆心,从而有a b +=+)112a b a b ⎛⎫++ ⎪⎝⎭,利用基本不等式可求. 14. (原创)给出下列四个命题:①某班级一共有52名学生,现将该班学生随机编号,用系统抽样的方法抽取一个容量为4的样本,已知7号、33号、46号同学在样本中,那么样本中另一位同学的编号为23; ②一组有六个数的数据是1,2,3,3,4,5的平均数、众数、中位数都相同; ③根据具有线性相关关系的两个变量的统计数据所得的回归直线方程为y a bx =+中,2,1,3,b x y ===则1a =;其中正确的命题有 (请填上所有正确命题的序号)对于③,回归直线方程为y=ax+2的直线过点(),x y ,把(1,3)代入回归直线方程y=ax+2得a=1.③是真命题;故答案为:②③,【思路点拨】①利用系统抽样的特点可求得该次系统抽样的编号,从而可判断其正误;②利用平均数、众数、中位数的概念,可求得数据1、2、3、4、5的平均数、众数、中位数,从而可知其正误; ③利用回归直线过点(),x y ,即可求得a 的值,从而可知其正误.15. (原创) 数列{}n a 满足*1142(1),()32n n n n a a a n N a n ++==∈+-,则n a 的最小值是【知识点】构造新数列;等差数列的性质.【答案解析】8-解析 :解:因为12(1)2n n n n a a a n++=+,整理得:112(1)2n n n n a a n a na ++=+-, 两边同时除以1n n a a +可得:12(1)21n n n n a a ++-=,则数列2n n a ⎧⎫⎨⎬⎩⎭是公差为1的等差数列,所以()12211n n n a a =+-⨯,即252n n a n =-,当3n ≥时,0n a >,当2n =时,8n a =-,故n a 的最小值是8-.故答案为:8-. 【思路点拨】先把原式变形构造新数列2n n a ⎧⎫⎨⎬⎩⎭进而判断即可. 三、解答题 :(本大题6个小题,共75分)各题解答必须答在答题卡上相应题目指定的方框内(必须写出必要的文字说明、演算步骤或推理过程).16.(本小题满分13分)在等比数列{}n a 中,11a =,且14a ,22a ,3a 成等差数列.(1)求n a ; (2)令2log n n b a =,求数列{}n b 的前n 项和n S .【知识点】等差、等比数列的通项与性质;等差数列的前n 项和公式;对数的运算法则.【答案解析】(1)12n n a -=(2)(1)2n n n S -= 解析 :解:(1)设{}n a 的公比为q ,由14a ,22a ,3a 成等差数列,得13244a a a +=. 又11a =,则244q q +=,解得2q =. ∴12n n a -=(*N n ∈ ).(2)12log 21n n b n -==-,∴11n n b b +-=,{}n b 是首项为0,公差为1的等差数列,它的前n 项和(1)2n n n S -=. 【思路点拨】(1)设{a n }的公比为q ,根据等比数列的通项公式与等差中项的定义,建立关于q 的等式解出q=2,即可求出{a n }的通项公式.(2)根据(I )中求出的{a n }的通项公式,利用对数的运算法则算出b n =n-1,从而证出{b n }是首项为0、公差为1的等差数列,再利用等差数列的前n 项和公式加以计算,可得数列{b n }的前n 项和S n 的表达式. 17. (本小题满分13分)在ABC ∆中,角,,A B C 对的边分别为,,a b c ,且2,60c C ==︒.(1)求sin sin a b A B++的值; (2)若a b ab +=,求ABC ∆的面积ABC S ∆.解析2=sinA sinB sin A sinB sinC sin60a b a b c ===++︒sin A sinB a b +∴+【思路点拨】(1)根据正弦定理以及合比定理即可;(2)由余弦定理求出ab=4,然后根据三角形的面积公式求出答案.18. (本小题满分13分)某车间将10名技工平均分成甲、乙两组加工某种零件,在单位时 间内每个技工加工的合格零件数,按十位数字为茎,个位数字为叶得到的茎叶图如图所示.已知甲、乙 两组数据的平均数都为10. (1)求m ,n 的值; (2)分别求出甲、乙两组数据的方差2S 甲和2S 乙, 并由此分析两组技工的加工水平;(3)质检部门从该车间甲、乙两组技工中各随机抽取一名技工,对其加工的零件进行检测,若两人加工的合格零件数之和大于17,则称该车间“质量合格”,求该车间“质量合格” 的概率.(注:方差2222121[()()()n s x x x x x x n =-+-++-,x 为数据x 1,x 2,…,x n 的平均数)【知识点】古典概型及其概率计算公式;极差、方差与标准差. 【答案解析】(1)m=3,n=8 (2) 乙组更稳定些(3)45 解析 :解:(1)m=3,n=8(2)2 5.2S 甲=, 2S 乙=2,所以两组技工水平基本相当,乙组更稳定些。
2016---2017学年度下学期高一年级期末考试2017-7本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分。
考试时间120分钟,满分150分。
考试结束,将试题卷和答题卡一并交回。
注意事项:1.答第Ⅰ卷时,考生务必将自己的姓名、准考证号填写在答题卡上。
2.选出每小题答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑,如需改动,用橡皮擦干净后,再选涂其他答案标号框。
不能答在试卷上,否则无效。
第Ⅰ卷第一部分听力(共两节,满分30分)第一节(共5小题;每小题1.5分,满分7.5分)听下面5段对话。
每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项, 并标在试卷的相应位置。
听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
第一部分:听力测试(共两节,满分30分,每小题1.5分)第一节(共5小题;每小题1.5分,满分7.5分)听下面 5 段对话, 每段对话后有一个小题, 从题中所给的A、B、C三个选项中选出最佳选项, 并标在试卷的相应位置。
听完每段对话后, 你都有 10 秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. What is the woman going to do tomorrow?A. Go swimming.B. Go fishing.C. Go to the hospital.2. How does the man find his job?A. Its pay is good.B. It is boringC. It is interesting and fun.3. What are the speakers talking about?A. A story.B. A book.C. A movie.4. Where does the conversation probably take place?A. At the airport.B. At the bus stop.C. At the train station.5. Where is the man going ?A. The classroom.B. The library.C. The cinema.第二节(共15小题;每小题1.5分,满分22.5分)听下面5段对话。
秘密★启用前2015-2016学年(春)高一期末测试卷数学试题数学试题共4页,满分150分。
考试时间120分钟。
注意事项:1.答题前,务必将自己的姓名、准考证号填写在答题卡规定的位置上。
2.答选择题时,必须使用2B 铅笔将答题卡上对应题目的答案标号涂黑,如需改动,用橡皮擦擦干净后,再选涂其他答案标号。
3.答非选择题时,必须使用0.5毫米黑色签字笔,将答案书写在答题卡规定的位置上。
4.所有题目必须在答题卡上作答,在试题卷上答题无效。
一、选择题:本大题共12小题,毎小题5分,共60分.在毎小)每给出的四个条选项中,只有一项是符合题目要求1、某工厂生产甲、乙、丙三种型号的产品,产品数量之比为2:3:5,现按型号用分层抽样的方方法随机抽出容量为n 的样本,若抽抽到12件甲,产品,则n = A 、50 B 、60 C 、70 D 、802、设,a b 是非零实数,且a b <,则下列不等式一定成立的是:A 、22a b <,B 、22ba ab >C 、11a b < D 、2211ba ab> 3、已知具有线性相关关系的两个变量,x y 的5对观察数据112255(,)(,)(,)x y x y x y ,若其中12345x x x x x <<<<,下列说法正确的是:A 、必存在a b R ∈、,使得(1,25)i i y b a i =+=B 、若,x y 高度正相关,则必存在,0a R b ∈>,使得(1,25)i i y b a i =+=C 、若,x y 正相关,则必有12345y y y y y <<<<D 、若12345y y y y y <<<<,则,x y 正相关4、等差数列{}n a 中,31140a a +=,则678a a a ++的值等于:A 、48B 、60C 、72D 、845、已知向量(2,1)a =,(,2)b x =-,若a b ⊥,则a b -=A 、(1,3)-B 、(3,1)--C 、(3,1)-D 、(1,3)6、执行如图所示的程序框图,若输入a 的值是1,则输出的结果是:A 、1B 、2C 、3D 、57、在区间[]0,10内任取一个a ,则对x R ∀∈,2280x ax -+≥的概率是:A 、15 B 、25 C 、35 D 、45 8、若甲乙丙三个人随机站成一排,则甲乙相邻且甲在乙的右边的概率是:A 、13 B 、12 C 、23 D 、349、若实数,x y 满足不等式组231402,1x y y x +-≤⎧⎪≥⎨⎪≥⎩且log a y x =,则a 的最大值为: A 、1 B 、2 C 、3 D 、410、设ABC ∆的内角C B A 、、所对的边分别为c b a 、、.已知1=a ,2=b ,2cos cos cos b A c A a C =+.则A = A 、34π B 、23π C 、3π D 、4π 11、某市出租车的收费标准如下:①不超过4千米的里程收费12元;②超过4千米的里程超过的部分按每千米2元收费〈对于其中不足1千米的部分,若其小鱼0.5千米,则不收费,否则按1千米收费〉:③当车程超过4千米时,另收燃油附加费1元12、如图所示,D 是BC 上的中点,En 是AC 上的一列动点,且111(1),22n n n n n E A a E B a E D +=--若10a =,则n a 等于: A 、11()2n - B 、111()2n -- C 、1()12n - D 、11()12n --二、填空题(本大题共4小题,每小题5分,共20分) 13、样本数据4,9,6,1,3,8的中位数是14、设ABC ∆的内角C B A 、、所对的边分别为c b a 、、.已知23C π=,2=b ,23ABC S ∆=.,则a = 15、下图是样本容量为200的频率分布直方图。
2015-2016学年度(下)调研检测2016.7高一物理试题卷本试题卷分为第一部分(选择题)和第二部分(非选择题)两部分,共6页。
考生作答时,须将答案答在答题卡上,在本试题卷、草稿纸上答题无效。
满分100分,考试时间90分钟。
第一部分(选择题,共39分)注意事项:1. 答题前,务必将自己的姓名、考号填写在答题卡规定的位置上。
并用2B 铅笔将答题卡考号对应数字标号涂黑。
2. 答选择题时,必须使用2B 铅笔将答题卡上对应题目的答案标号涂黑。
如需改动,用橡皮擦干净后,再选涂其它答案标号。
一、 选择题(本题共6小题,每小题3分,共18分。
每小题给出的四个选项中,只有一个....选项符合题目要求)1.对于做匀速圆周运动的物体,下列说法中正确的是A .线速度、加速度都不变B .线速度、角速度都不变C .角速度、加速度都不变D .角速度、周期都不变 2.人造地球卫星绕地球做匀速圆周运动,离地面越远的卫星A .向心加速度越大B .线速度越大C .周期越大D .角速度越大3.如图所示,长为L =0.5 m 的轻质细杆OA ,其A 端固定有一小球,小球质量为5 kg ,小球以O 点为圆心在竖直平面内做圆周运动,通过最高点时速率为2 m/s ,g 取10m/s 2,则此时细杆OA 受到A .40 N 的拉力B .40 N 的压力C .10 N 的拉力D .10 N 的压力4.如图为一辆老式自行车,它的前轮直径是后轮直径的3倍,当该自行车在平直路面上匀速行驶(不打滑)时,前、后车轮边缘上的点相对于各自转轴做匀速圆周运动的向心加速度大小之比为A .1∶3B .3∶1C .1∶9D .9∶15.如图所示,初速度大小相等的A 、B 、C 三个小球,在同一水平面上,A 球竖直上抛,B 球以倾斜角θ斜向上抛出,C 球沿倾角为θ的光滑斜面上滑,不计空气阻力,它们上升的最大高度分别为h A 、h B 、h C ,则A .h A =hB =hC B .h B <h A <h CC .h A = h C > h BD .h A =h B >h C6.如图所示,B 为竖直面内的圆弧轨道的右端点,B 点与圆心O 的连线与竖直方向的夹角为θ,一小球从B 点右上方的A 点以速度v 0水平抛出,恰好沿B 点的切线方向进入圆弧轨道,已知重力加速度为g ,则A 、B 两点间的竖直高度为A .220tan v g θB .220tan 2v g θC .20tan v g θD .20tan 2v gθ二、 选择题(本题共7小题,每小题3分,共21分。
2016年高一下学期数学期末试卷(含答案)孝感高中2015—2016学年度高一下学期期末考试数学试题命题人:陈文科考试时间:120分钟分值:150分一、选择题(本大题共12个小题,每小题5分,共60分,在每小题所给出的四个选项中,只有一项是符合题目要求的)1.等差数列中,若,则的值为()A.B.C.D.2.设为不重合的两个平面,为不重合的两条直线,则下列判断正确的是()A.若α⊥β,α∩β=n,m⊥n,则m⊥αB.若mα,nβ,m∥n,则α∥βC.若m∥α,n∥β,m⊥n,则α⊥βD.若n⊥α,n⊥β,m⊥β,则m⊥α3.若两直线与平行,则它们之间的距离为()A.B.C.D.4.在如图所示的长方体中,,,分别是的中点,则异面直线与所成角的余弦值是()A.B.C.D.5.已知点,若直线过点与线段相交,则直线的斜率的取值范围是()A.B.C.D.6.在空间直角坐标系中,点,则两点间的距离为()A.B.C.D.7.在中,角所对的边分别为,已知,若三角形有两解,则边的取值范围为()A.B.C.D.8.半径为,圆心角为的扇形卷成一个圆锥,则它的体积为()A.B.C.D.9.过点作圆的两条切线,切点分别为,点为坐标原点,则的外接圆方程是()A.B.C.D.10.一个几何体是由一个三棱柱截去一个四棱锥而成,它的三视图如图所示,则这个几何体的体积是() A.B.C.D.11.已知圆上到直线的距离为的点有且仅有个,则的取值范围是()A.B.C.D.12.已知圆,设,若圆是的内切圆,则面积的最大值为()A.B.C.D.二、填空题(本大题共4小题,每小题5分,共20分,把答案填在答题卡中的横线上)13.经过直线的交点且垂直于直线的直线方程为.14.已知满足条件(),若目标函数的最大值为,则的值为.15.已知点,点在圆上运动,则的最大值为.16.已知正方体的棱长为,下列说法:①对角线被平面和平面三等分;②以正方体的顶点为顶点的四面体的体积都是;③正方体的内切球,与各条棱相切的球,外接球的表面积之比为;④正方体与以为球心,为半径的球的公共部分的体积为;则正确的是.(写出所有正确的序号)三、解答题(本大题共6小题,满分70分,解答应写出文字说明、证明过程或演算步骤)17.(10分)设直线的方程为;(Ⅰ)若直线不经过第二象限,求实数的取值范围;(Ⅱ)若直线与坐标轴围成三角形的面积为,求实数的值. 18.(12分)在中,角的对边分别为.(Ⅰ)求的值;(Ⅱ)若,求的面积.19.(12分)如图1所示,在边长为的等边三角形中,分别是边上的点,,是的中点,与交于点,将沿折叠,得到如图2所示的三棱锥,其中;(Ⅰ)证明:平面;(Ⅱ)证明:平面;(III)当时,求三棱锥的体积.20.(12分)甲、乙两地相距,货车从甲地匀速行驶到乙地,速度不得超过,已知货车每小时的运输成本(单位:元)由可变成本和固定成本组成,可变成本是速度平方的倍,固定成本为元;(Ⅰ)将全程运输成本(元)表示为速度()的函数,并指出这个函数的定义域;(Ⅱ)若,为了使全程运输成本最小,货车应以多大的速度行驶?21.(12分)已知点都在直线上,为直线与轴的交点,数列成等差数列,公差为;(Ⅰ)求数列,的通项公式;(Ⅱ)若=问是否存在,使得成立;若存在,求出的值,若不存在,说明理由;(III)求证:.22.(12分)已知,若由不等式组围成的区域为,设两曲线的交点为,且;(Ⅰ)求实数的取值范围;(Ⅱ)若,求的面积;(III)求的面积的最大值.孝感高中2015—2016学年度高一下学期期末考试数学答案一、选择题1~5BDADC6~10BCACD11~12BA二、填空题13.14.15.16.①③三、解答题17.解:(Ⅰ)由题意知:∴(Ⅱ)由题意知:令令∴∴,或18.(Ⅰ)(Ⅱ)由(Ⅰ)知由正弦定理知:∴∴19.(Ⅰ)在等边三角形ABC中,AD=AE,∴A DDB=AEEC. 在折叠后的三棱锥A­BCF中也成立,∴DE∥BC.∵DE平面BCF,BC⊂平面BCF,∴DE∥平面BCF. (Ⅱ)在等边三角形ABC中,F是BC的中点,∴AF⊥FC,BF=CF=12.∵在三棱锥A­BCF中,BC=22,∴BC2=BF2+CF2,∴CF⊥BF.∵BF∩AF=F,∴CF⊥平面由(1)可知GE∥CF,结合(2)可得GE⊥平面­DFG=13×12×DG×FG×GE=13×12×13×13×32×13=3324.20.(Ⅰ)可变成本为,固定成本为元,所用时间为,即。
2016-2017学年高一下学期期末考试第I卷(三部分,共115分)第一部分听力(共两节,满分30分)第一节(共5小题;每小题1.5分,满分7.5分)听下面5段对话。
每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项。
听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
请听下面5段对话,选出最佳选项。
1. What’s wrong with the man’s watch?A. It goes slowly.B. It goes too fast.C. It doesn’t work so metimes.2. When will the speakers meet?A. At 2:00.B. At 4:00.C. At 6:00.3. What is the relationship between the speakers?A. Neighbors.B. Teacher and student.C. Classmates.4. What will the woman do?A. Give Tom some medicine.B. Take Tom’s temperature.C. Have a look at Tom’s mouth.5. Why did the woman make Mr. Jones angry?A. She asked the answered question again.B. She didn’t finish her work in 20 minutes.C. She asked the same question three times.第二节(共15小题;每小题1.5分,满分22.5分)听下面5段对话或独白。
每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。
听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,各小题将给出5秒钟的作答时间。
答案2016学年下学期高一期末测试一、阅读理解(40分)1-3ACB 4-7A DBD 8-12 BCACA 13-15 C DA 16-20 CDEBG二、完形填空(30分)21-25 CBADB 26-30 CBCDA 31-35 AACBD 36-40BCDAB三、单项选择(10分)41--45 BBDAD 50—55 BCABC四、语法填空(1.5分)51.with 52. be made 53. to create 54. The 55. using 56 .as 57. gradually58. who 59.development 60. were五、单词拼写(10分)61.arrival 62. benefits 63. surrounded 64. wandering 65. argued66. reduces/ decreases 67. therefore 68. approached 69. modelled 70. convincing六、完成句子(10分)71.You may find it astonishing72. was she allowed to begin her project/research73. Rather than take/Instead of taking the plane all the way74. no wonder (the) tourism is increasing wherever there is a Disneyland/it is no wonder where there is a Disneyland, (the) tourism is increasing.75. according to a widely/universally accepted/acknowledged theory七、短文改错(10分)e 改为came 77.student改为students 78.paid 和visit之间加入a 79. or 改为and 80.删除in 和London 之间的the 81. where改为which 82. beautifully改为beautiful 83.But 后面的that 改为it 84. here改为there 85.excited改为exciting 八、书面表达(25分)Dear Editor,As more and more students are getting fond of western fast food which leads to obesity,I’m writing to talk something about this phenomenon.Although people hold different views about it, I don’t think western fast food is good for our health because they are rich in sugar and fat. In my opinion,the Chinese food is healthier. The Chinese food contains a lot of fruits and green vegetables which are high in vitamins and fibers. In addition, the Chinese food is very delicious and has various dishes,which provide us with all kinds of beneficial nutrition. That’s why many Chinese people enjoy it and keep fit as well. I think the Chinese food is the healthiest one in the world.What’s your opinion about it? I am expecting your reply!Best wishes!Yours SincerelyLi Hua。
2016-2017高一下学期期末考试试题work Information Technology Company.2020YEAR18级(高一)第二学期期末考试本试卷分为第I 卷(选择题)和第II 卷(非选择题)两部分,共150分,考试时间120分钟第I 卷(选择题,共60分)一、选择题(本大题共12小题,每小题5分,共60分。
在每小题给出的四个选项中,只有一项是符合题目要求的)1.sin480°的值是( )A .-12B .-32 C.12 D.322.现有200辆汽车通过某一段公路时的时速的频率分布直方图如图所示,时速在[50,60)的汽车大约有( )A .80辆B .60辆C .40辆D .30辆 3.一条弦的长等于半径,则这条弦所对的圆心角是 ____弧度.( )A .π B.π2 C.π3D.π44.已知3cos 4α=,(,0)2απ∈-,则sin 2α的值为 ( ) (A )38 (B )38- (C )378 (D )378-5.已知平面向量)3,1(-=,)2,4(-=,b a +λ与a 垂直,则λ是( )A .-1B .1C .-2D .26. 具有线性相关关系的变量x ,y ,满足一组数据如右表所示.若y 与x 的回归直线方程为233ˆ-=x y,x 01 2 3 y-1 1 m 8 A. 4 B.2C. 5D. 6 7. 若某程序框图如右图所示,则该程序运行后输出的B 等于( )考 号 姓 名A .63B .31C .127D .158.要得到函数sin 2y x =的图象,只需将函数πsin(2)3y x =-的图象 ( )A .向右平移π6个单位长度B .向右平移π3个单位长度 C .向左平移π6个单位长度 D .向左平移π3个单位长度9.设)cos ,21(),1,(sin x b x a ==,且b a //,则锐角x 为( ) A .3π B .4π C .6π D .12π10.已知函数()()sin 002f x A x x R A πωφωφ⎛⎫=+∈>>< ⎪⎝⎭,,,的图象(部分)如图所示,则()x f 的解析式是 ( )A .()2sin()()6f x x x R ππ=+∈B .()2sin(2)()6f x x x R ππ=+∈C .()2sin()()3f x x x R ππ=+∈ D .()2sin(2)()3f x x x R ππ=+∈11.一只受伤的丹顶鹤在如图所示(直角梯形)的草原上飞过,其中2,2,1AD DC BC ===,它可能随机在草原上任何一处(点),若落在扇形沼泽区域ADE 以外丹顶鹤能生还,则该丹顶鹤生还的概率是( )A .1215π- B.110π- C.16π- D.3110π-12.如图,AOB∆为等腰直角三角形,1=OA,OC为斜边AB的高,P为线段OC的中点,则=⋅OPAP( )A.1- B.41- C.81- D.21-第II卷(非选择题,共90分)二、填空题(本大题共4小题,每小题5分,共20分)13.取一根长度为30cm的绳子,拉直后在任意位置剪断,那么剪得两段的长都不小于10cm的概率为 .14. 已知平面向量a,b满足1==a b,a与b的夹角为60︒,则()⋅+=a a b.15. 若点P(3a-9,a+2)在角α的终边上,且cosα≤0,sin α>0,则实数a的取值范围是__________.16.在∆ABC中,内角,,A B C的对边分别为,,a b c,若2=c a,4=b,1cos4=B.则边c的长度为__________.三、解答题(本大题共70分。
解答应写出文字说明)17. (本题满分10分)已知1a=,4b=,且向量a与b不共线.(1)若a与b的夹角为60︒,求()2a b-·()a b+;(2)若向量ka b+与ka b-互相垂直,求k的值.18、(本题满分12分)如图是校园“十佳歌手”大奖赛上,七位评委为甲、乙两位选手打出的分数的茎叶图.(1)写出评委为乙选手打出分数数据的众数,中位数;AOCBP(2)求去掉一个最高分和一个最低分后,两位选手所剩数据的平均数和方差,根据结论,说明哪位选手发挥稳定。
19. (本题满分12分)口袋中装有除编号外其余完全相同的5个小球,编号依次为1,2,3,4, 5.现从中同时取出两个球,分别记录下其编号为,m n . (Ⅰ)求“5+=m n ”的概率; (Ⅱ)求“5≥mn ”的概率.20、(本题满分12分)已知ABC ∆的内角,,A B C 的对边分别为,,a b c ,3B π∠=.(1)若2a =,b =c 的值;(2)若tan A =tan C 的值.21. (本题满分已知函数2()cos 2cos 1f x x x x =-+.(Ⅰ)当[0,]2x π∈时,求函数()f x 的最大值;(Ⅱ)若8()([0,])56f παα=∈,求cos2α的值.22.(本题满分12分)设函数()f x m n =⋅,其中向量(2cos ,1)m x =,(cos 2)n x x =,x R ∈. (1)求)(x f 的最小正周期与单调递减区间;(2)在△ABC 中,a 、b 、c 分别是角A 、B 、C 的对边,已知2)(=A f ,1=b ,△ABC 的面积为23,求CB c b sin sin ++的值.鞍山市一中教育集团兰开美术高中 17届(高一)第二学期期末考试 数学试题标准答案一、选择题1.D2.B3.C4.D5.A6. A7.A8.C9.B. 10 .A 11.B 12.C 二、填空题13. 13 14. 23 15. (-2,3] 16. 4三、解答题17. 解:(1)(2)()a b a b -⋅+2a a a b b b =⋅+⋅-⋅222cos a a b b θ=+⋅- …… 3分22114cos604=⨯+⨯⨯︒-12=-. …… 5分(2)由题意可得:()ka b +⋅()0ka b -=, 即2220k a b -=, …… 8分 ∴2160k -=, ∴4k =±. …… 10分18解:(1)众数为84,中位数84; …… 2分(2)2288,85, 5.2, 1.6x x S S ====甲乙甲乙,…… 10分所以22S S >甲乙,所以乙的数据波动小. …… 12分19.解(1,2),(1,3), (1,4),(1,5) (2,3),(2,4),(2,5)(3,4),(3,5)(4,5) …… 4分(1)记“5+=m n ”为事件A ,则21()105==P A . …… 8分 (2)记“5≥mn ”为事件B ,则只有 (1,2),(1,3),(1,4)三种情况不满足mn ≥537()11010=-=P B . …… 12分20.解:(1)由余弦定理得,2222cos b c a c a B =+-⋅,因为3B π∠=,2a =,b =21242c c =+-,即2280c c --=解之得4c =,2c =-(舍去).所以4c =. …… 6分(2)因为πA B C ++=,tan A = tan B =所以tan tan()C A B =-+ tan tan1tan tan A BA B +=-- 5==.所以tan C =. …… 12分21..解: 212cos 2()cos 2cos 12212xf x x x x x +=-+=-⨯+2cos 22sin(2)6x x x π=-=-. …… 3分(1)因为[0,]2x π∈,所以5(2)[,]666x πππ-∈-,所以当3x π=时,max ()2f x =. …7分(2)由8()5f α=,知4sin(2)65πα-=,因为[0,]6πα∈,所以(2)[,]662πππα-∈-,因此3cos(2)65πα-=, 所以cos 2cos[(2)]cos(2)cos sin(2)sin 666666ππππππαααα=-+=---3415252=⨯-⨯410=. …… 12分 22. 解:(1)x x n m x f 2sin 3cos 2)(2+=⋅=1)62sin(212cos 2sin 3++=++=πx x x …… 4分∴函数)(x f 的最小正周期ππ==22T …… 5分令Z k k x k ∈+≤+≤+,2236222πππππ,解得Z k k x k ∈+≤≤+,326ππππ ∴函数)(x f 的单调递减区间是Z k k k ∈++,]32,6[ππππ …… 7分(2)由2)(=A f ,得21)62sin(2=++πA ,即21)62sin(=+πA在△ABC 中,∵π<<A 0,∴6562ππ=+A ,得3π=A …… 9分又∵2323121sin 21=⨯⨯⨯==∆c A bc S ABC ,∴2=c∴由余弦定理得:3cos 2222=-+=A bc c b a ,∴3=a由233sin sin sin ===AaC c B b ,得B b sin 2=,C c sin 2=∴2sin sin =++CB cb …… 12分。