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淮安市淮阴区东城开明中学2019--2020年(上)单元提优Unit 2

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单元测试Unit2 Let’s play sports（总分:120分）一、单项选择（每小题1分，满分15分）（）1. I like playing__________ basketball, but my brother likes playing_________ piano.A.the；theB.a；theC./; theD.the；/（）2. The girl___________ glasses likes drawing pictures____________ her free time.A.in；onB. with；inC.in；atD.with; about（）3. Jim and Kate___________ in Beijing now. They both_________ from America.A.is; comeB.are; comeC.is; comesD.are; comes（）4. I often play football__________my friends___________ school.A. and; afterB.with; toC.with; afterD.and; at（）5. The man has____________ friends in this city，so he often stays at home.A. a fewB.fewC. a littleD.little（）6.---Jane，__________ the picture. ---Oh，it_____________ so beautiful.A. look; looksB. looks at; looksC.look; looks atD.look at; looks （）7. Kitty enjoys playing volleyball. It____________ her happy.A.makeB. makesC.takeD.takes（）8. I am from Nanjing.___________ I live in Huai’an now.A.AndB.ButC.AfterD.So（）9. Frank is a___________football player. He usually plays football very___________.A.good; goodB.well; wellC. good; wellD.well; good（）10. He doesn’t like__________ but he enjoys__________.A.sing; danceB. to sing; to danceC. singing; to danceD. to sing; dancing （）11. My best friend hopes__________a great scientist like Qian Xuesen.A. him to beB. beC.isD. to be（）12.Mary，____________ late for school again！A.isn’tB. doesn’tC.doesn’t beD. don’t be（）13. ---How do you go to school？---I go to school____________.A. by bikesB. by a bikeC. by bikeD. on bike（）14. ___________do you go shopping every week？---Twice.A. How oftenB. How many timesC. How longD. How much （）15.---You are beautiful in the new dress. ---___________.A. No, I am notB. I’m fineC. Thank youD. You’re right二、完形填空（每小题1分，满分15分）Many students have hobbies, like reading, painting, growing vegetables in 16 gardens, or looking 17 lovely animals. Some hobbies are relaxing（放松的）and 18 are useful.19 can help you grow as a person and learn new skills. David Smith is a student. His hobby is 20 . In the middle school, he 21 a（n）22 and it came out （出版）in 2003. Many teenagers love his book and he becomes a 23 young writer.David is successful（成功的）but he thinks of writing 24 only one of his many hobbies and interests. “ I lke playing badminton too，” says David. He isn’t sure if（是否）he is going to write more books 25 .David is very lucky 26 his hobby makes him 27 and successful. But he is also 28 in many other things, and he often plays badminton for his school team.It’s sometimes difficult to remember that we shouldn't 29 all our time on our hobbies. There are many other interesting things to do in life, and we should try to do 30 new or different.（）16.A.Their B. Our C. Your D. They（）17.A.at B.for C. after D.up（）18. A.the other B.another C.others D.other（）19. A. Friends B Hobbies C.Books D.Life（）20. A. reading B.painting C. writng D. fishing（）21.A.wrote B.writes C.read D. reads（）22.A.article B.book C.story D. magazine（）23.A.friendly B.excellent C.famous D. useful（）24. A. as B.with C.for D.to（）25. A in the past B. just now C. Now D. in the future（）26.A.so B. because C.but D. or（）27. A happiness B.unhappy C. happily D. happy（）28. A good B.excited C.interested D.sad（）29. A take B. spend C.pay D.cost（）30.A.something B. Anything C. nothing D.everything三、阅读理解(A、B两篇每小题2分,C篇每小题1分,满分25分)A. A football match.B.A football player.C.A basketball player.D.A football team. （）32. Where was he born?A. In Spain.B. In Argent.C. In Brazil.D.In Barcelona.（）33. When was Messi born?A.In1978.B.In1983.C.In1987.D. We don't know.（）34. He plays football for____________.A.a Chinese teamB. an Argentina clubC. Barcelona FCD. Spain（）35 People think Messi is a best player because__________.A. he is a tall player in a teamB. he is youngC. he scores many goalsD. he is short but he runs fastB In our school, many students like sports. Every morning, we run around our large school campus(校园).We have PE lessons twice a week, but we do sports after school every day. We like playing ball games. One sport is basketball. The boys like playing it best, and many ofthe girls enjoy playing it, too. Another sport is football. In every class there are lots of football fans.We often play volleyball when the weather is fine. Besides (除......之外) ball games, Some students like running, climbing, playing badminton and swimming. We have school teams of basketball, football and volleyball. Our school teams often have matches with teams from other schools. When there is a match, many students go towatch and cheer for them. We have a sports meeting twice a year. One is in autumn, andthe other is in winter. We like sports and sports help us to keep healthy.（）36. We have PE lessons _________. A. every day B. twice a weekC. once a weekD. after school（）37. Which do the boy students like best?A. Football.B. V olleyball.C. Basketball.D.Running.（）38. On a sunny day, the students may___________.A.w atch a football matchB. play volleyballC. go swimmingD. have a sports meeting（）39. What does the underlined word "cheer"mean in Chinese?A.喝彩B.锻炼C.关心D.支持（）40. Which of the following is TRUE?A.In our school, everyone loves sports.B. The boys like basketball, butthe girls don't like it.B.We have a sports meeting once a year. D. We have school teams ofbasketball, football and volleyball.CWhen class is over, most students in our class go out of the classroom. We have a twenty minutes' rest between classes. Look! Most of us are playing during the rest time. Some students are in the playground. They are having a basketball match. Oh! A boy is running with a ball and another is trying to stop him. They are so cool. And there are some girls watching the match. Some students are still in the classroom. They are talking. A few of them are reading and doing homework. Look! A girl islooking at the birds in a tree in front of the classroom.She must be thinking of somethinginteresting because she is smiling. What are the teachers doing? Some of them are doing their work in the office, andsome are talking with students. Everyone is busy with his or her work. They are busy and happy.（）41. Some students are having a match________.A.in the classroomB. in front of the classroomC. in the playgroundD. near the door of the classroom（）42. A girl is looking at the birds. She is_________.A.happyB. not happyC. interested in the matchD. watching the match（）43. There are_________students in the classroom.A.noB. someC. littleD. many（）44. The teachers are___________. A. doing their work or talking with studentsB. having a basketball matchC. reading newspapers .D. playing with the students（）45. This article is mainly about____________.A.a classB. a basketball matchC.studentsD.the rest time四、词汇运用（每小题1分，满分15分）47. The students in our school go home___________________ a week.48. There are usually 22 _____________________in a football match.49.My_____________________ are listening to music and playing football.50. Nancy is good at playing volleyball. She often plays it__________________.51. I hope_________________ football in the next World Cup.52. Everyone in our class_____________________ hard before the exams（考试）.53. I’m busy at the moment，but I’ll________________ this afternoon.（B）根据句意，用括号中所给单词的正确形式填空54. It’s time for us_______________ （go）home.55. She enjoys________________________ （listen）to music.56.________________ （walk）is one of his hobbies，so he is strong.57. Please write down these__________________ （hero）names on the paper.58.I am____________________ （real）sorry to hear that your mother is ill.59. These books aren’t_____________________ （we）. They are those children’s.60. My dream is__________________ （travel）around the world in the future.五、完成句子（每小题2分，满分10分）61.每天游泳能使我们健康强壮。

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江苏省淮阴中学初中部开明分校2018-2019学年九上 Unit 2单元测试 (含答案和部分解析)

江苏省淮阴中学初中部开明分校2018-2019学年九上 Unit 2单元测试 (含答案和部分解析)

单元测试（九上Unit 2）班级____________ 姓名_____________ 学号___________ 得分___________I. 单项选择。

（每题1分，共15分）( ) 1. I have _______ indigo notebook and I’d like to draw ______ rainbow in it.A. a; aB. an; anC. a; anD. an; a( ) 2. ---Could you tell me how many key rings _____ on the shelf? ---Sorry, I don’t know.A. are thereB. there areC. is thereD. there is( ) 3.The girl _______ pink is a top student, but she is usually green _______envy.A. in; ofB. with; inC. in; withD. on; at( ) 4. My sister believes _______ yellow can bring her good luck.A. thatB. whatC. ifD. whether ( ) 5. If you hope for _______, maybe yellow will help you.A. sadnessB. successC. calmD. strength ( ) 6. Your son is old enough to ______ himself. He isn’t a baby any more.A. wearB. dressC. put onD. have on ( ) 7. Please tell us whether you know _______ else about colour therapy.A. somethingB. anythingC. nothingD. everything ( ) 8. Mary’s poor English makes her mother _______.A. worries a lotB. very worriedC. worrying muchD. to worry a lot ( ) 9. ---Do you think Andy can be a good policeman?---Yes. He has the ability to stay _______ when something dangerous happens.A. calmB. excitedC. afraidD. nervous ( ) 10. We found _______ a little nervous to speak in front of people.A. itB. it’sC. thatD. that’s( )11.The girl herself can’t decide if she ______ her project if her teacher ______ supporting her next term.A. continues; stopsB. will continue; will stopC. will continue; stopsD. continues; will stop( ) 12. I’ve got some new books on colour therapy. You can borrow _______ if you like.A. eachB. itC. everyD. one( ) 13.I wonder __________ the walls of your room __________ orange.A. whether; paintB. that; was paintedC. that; are paintingD. if; were painted( ) 14. The girls asked if they ______ some food and drink with them.A. tookB. takeC. takesD. will take ( ) 15. ---I’m not sure _______. ---You can ask her friend Jessica.A. when Emily left Huai’anB. if will Emily leave Huai’anC. that Emily will leave Huai’anD. when did Emily leave Huai’anⅡ. 完形填空(共15小题；每小题1分，满分15 分)In a small village, there was a big mountain rock shaped like a human face. It was said that it was the face of the greatest person, and everyone in the village wanted to know who the greatest person was.Ernest, a farmer, spent many years working in the 16 . He was always loving and devoted.17 he was also very smart. Years later, Ernest grew old, and 18 hair started appearing on his head. He once lived a simple and common life, and nobody knew him. But after many years, this 19 . Over the years, his 20 had become deeper so many people from many places came to 21 wisdom. People were always so 22 by him. Ernest often gave speeches to the local people 23 the Great Stone Face. He was now giving a speech. It was such a powerful speech because it told about his 24 . He lived a life of greatest deeds(行为).Now, in the 25 of the evening, the final rays (光线) of the sun shone on the Great Stone Face. It looked like it had white hair, too.At that moment, a man 26 something. He looked at Ernest again. Then, he looked 27 to the Great Stone Face. 28 , he cried out, “Everyone! Look at the Great Stone! Look at Ernest! They are 29 in looks.”Everyone there was surprised that Ernest was the greatest person. But Ernest 30 his head and left without saying anything, still in the hope of finding the real greatest person.( ) 16. A. school B. hospital C. shop D. field( ) 17. A. And B. But C. Or D. If( ) 18. A. indigo B. purple C. white D. black( ) 19. A. remained B. changed C. lasted D. continued( ) 20. A. age B. looks C. wisdom D. love( ) 21. A. work for B. look for C. care for D. hunt for( ) 22. A. discovered B. impressed C. hurt D. worried( ) 23. A. in B. out C. before D. behind( ) 24. A. dream B. life C. achievements D. courage( ) 25. A. light B. darkness C. wind D. clouds( ) 26. A. heard B. smelt C. noticed D. felt( ) 27. A. inside B. outside C. up D. down( ) 28. A. Peacefully B. Slowly C. Suddenly D. Usually( ) 29. A. ancient B. similar C. different D. special( ) 30. A. put B. lifted C. nodded D. shookⅢ. 阅读理解(每小题1分，共5 分)According to scientists’ research, the month in which babies are born could influence them in some ways.Babies born in spring get sick easily. Children born under Aquarius (Jan. 21st-Feb.19th ) may be less clever than those born in other seasons. They may also have shorter lives than those born in autumn. Scientists believe many of the differences can be explained by the mother’s exposure(暴露) to sunlight in pregnancy(怀孕). Sunlight helps lead to the production of vitamin Din the body. The lack(缺乏) of vitamin D in the first months of life may have a bad effect on health.Vitamin D is called the “sunshine vitamin”. It has a good effect on health. A study showed that people born from April to June had slightly shorter lives than those born in October, November or December. Similar Studies in the US showed that people born in autumn lived about 160 days longer than those born in spring.Professor Russell Foster said the conclusions were surprising and interesting. He added, “These are small effects but they are very, very clear. I am not giving voice to star signs and they are just for fun. But it is true that we are affected by our season of birth.”( )31. A child’s season of birth can affect all the following things EXCEPT ___________ according to the first two paragraphs.A. his healthB. his heightC. his length of lifeD. his quality of being clever ( )32. What does the underlined word “effect” mean ___________.A. progressB. methodC. matchD. influence( )33. What can we know about vitamin D according to the passage?A. It comes from sunlight.B. It helps people live longer.C. Sunlight prevents its production.D. It does harm to people’s health.( )34.Which of the following is TRUE according to the passage?A. Women should get enough sunlight in pregnancy.B. Children born under Aquarius are cleverer than those born in autumn.C. People born in May will live longer than those born in October.D. Professor Russell Foster is interested in star signs and believes in them.( )35. What does the passage mainly tell us?A. People can know the length of life by star signs.B. Women should choose to give birth to children in spring.C. A child’s season of birth has an effect on him or her.D. Vitamin D is not very important to people’s health.V. 用所给词的适当形式填空。

江苏省淮阴中学开明分校2019-2020年八上Unit 2 Grammar同步测试(word版含答案

江苏省淮阴中学开明分校2019-2020年八上Unit 2 Grammar同步测试(word版含答案

Unit 2 Grammar (IV)班级______________ 姓名______________ 学号______________一、根据句意用所给的汉语或单词的适当形式填空。

1. Andy is _________________ (care). He writes ____________________ (care) than any other student in my class. So he is the top student in his class.2. Among the three ladies, Lily bought ____________________ (few) things.3. This CD costs ____________________ (little) in our shop. It’s the cheapest one.4. In the reading class, the more careful you are, the ____________ (easy) you can find answers in the passage.5. ---Who jumps ____________________ (far), Mike, George or Daniel? ---Mike does.6. ---How do you like the film? ---I have never seen a ____________ (nice) one than it.7. My brother came ____________________ (two) in the exam yesterday.8. Of the three workers, she does____________________ (much) work.9. The weather in Beijing is much ______________ (hot) than that in Harbin.10. Daniel studies English ____________ (hard), but Simon studies even ____________ (hard).11. Shirley wants to go to Hong Kong for ____________________ (far) study.12. Who do you think did _______________ (badly) in this competition, Jim or Jane?二、单项选择。

2019-2020学年江苏省淮安市开明中学九年级(上)月考数学试卷(9月份)(解析版)

2019-2020学年江苏省淮安市开明中学九年级(上)月考数学试卷(9月份)(解析版)

2019-2020学年江苏省淮安市开明中学九年级第一学期月考数学试卷（9月份）一、选择题（共8小题，共24分.）1．已知α为锐角，且sinα＝，则α的度数为（）A．15°B．30°C．45°D．60°2．如图，在△ABC中，点D、E分别在AB、AC上，DE∥BC．若AD＝4，DB＝2，则的值为（）A．B．C．D．23．如图，有一斜坡AB，坡顶B离地面的高度BC为30m，斜坡的倾斜角是∠BAC，若tan ∠BAC＝，则此斜坡的水平距离AC为（）A．75m B．50m C．30m D．12m4．将抛物线y＝2x2向上平移3个单位长度后，得到的新抛物线解析式为（）A．y＝2（x﹣3）2B．y＝2（x+3）2C．y＝2x2﹣3D．y＝2x2+35．如图，人字梯AB，AC的长都为2米，当α＝50°时，人字梯顶端离地面的高度AD是（）米．A．2sin50°B．2cos50°C．D．6．已知x＝1是方程x2+bx﹣2＝0的一个根，则方程的另一个根是（）A．1B．2C．﹣2D．﹣17．如图，在6×4的正方形网格中，△ABC的顶点均为格点，则∠ACB的正弦值为（）A．B．C．D．28．如图1，在矩形ABCD中，点E在CD上，∠AEB＝90°，点P从点A出发，沿A→E →B的路径匀速运动到点B停止，作PQ⊥CD于点Q，设点P运动的路程为x，PQ长为y，若y与x之间的函数关系图象如图2所示，当x＝6时，PQ的值是（）A．2B．3C．D．二、填空题：（本大题共8小题，共24分，请将答案填写在答题卡上）9．如果＝，那么的值为．10．已知A（﹣4，y1），B（1，y2）为二次函数y＝（x+2）2图象上的两点，则y1y2（填“＞，＜或＝”）．11．在Rt△ABC中，∠C＝90°，cos A＝，AC＝4，则AB＝．12．如图，利用标杆BE测量建筑物的高度，已知标杆BE高1.5m，AB＝2m，BC＝18m．则建筑物CD的高m．13．请写出一个二次函数，使它满足条件：当x＝0时，y有最大值为3：．14．如图，一张三角形纸片ABC，∠C＝90°，AC＝8cm，BC＝6cm．现将纸片折叠：使点A与点B重合，那么折痕长等于cm．15．如图，某校教学楼AC与实验楼BD的水平间距CD＝15米，在实验楼顶部B点测得教学楼顶部A点的仰角是30°，底部C点的俯角是45°，则教学楼AC的高度是米（结果保留根号）．16．如图，在平面直角坐标系中，点A1的坐标为（1，0），以OA1为直角边作Rt△OA1A2，并使∠A1OA2＝60°，再以OA2为直角边作Rt△OA2A3，并使∠A2OA3＝60°，再以OA3为直角边作Rt△OA3A4，并使∠A3OA4＝60°…按此规律进行下去，则点A2019的坐标为．三、解答题：（本大题共11小题，共102分）17．（1）计算：（﹣1）2019﹣+tan60°+（π﹣3.14）0；（2）解方程：x2﹣2x﹣3＝0．18．先化简，再求值：（﹣）÷，其中x＝﹣1．19．如图，△ABC中，∠C＝90°，点D在AC上，已知∠BDC＝45°，BD＝10，AB＝20．求∠A的度数．20．如图，正方形网格中，每个小正方形的边长是1．已知△ABC的三个顶点坐标分别是A （2，﹣1），B（1，﹣2），C（3，﹣3）．（1）△ABC的面积为；（2）画出将△ABC向左平移4个单位长度后得到的△A1B1C1；（3）以点A为位似中心，在网格内画出△AB2C2，使△AB2C2与△ABC位似，且位似比为3：1．21．如图，两栋居民楼之间的距离CD＝30m，楼AC和BD均为10层，每层楼高为3m．上午某时刻，太阳光线GB与水平面的夹角为30°．若小明家住在楼AC的4楼，此时他家是否会被遮挡住？请说明理由（参考数据：≈1.732，≈1.414）．22．如图，已知抛物线y＝mx2和直线y＝﹣2x+b都经过点A（﹣2，6），点O为坐标原点，直线y＝﹣2x+b与x轴交于点B．（1）求m、b的值；（2）连接AO，点C是抛物线上一点（异于点A），且S△AOB＝S△COB，求点C的坐标．23．某景区商店销售一种纪念品，这种商品的成本价10元/件，已知销售价不低于成本价，且物价部门规定这种商品的销售价不高于16元/件，市场调查发现，该商品每天的销售量y（件）与销售价x（元/件）之间的函数关系如图所示．（1）求y与x之间的函数关系式，并写出自变量x的取值范围；（2）每件销售价为多少元时，每天的销售利润为125元？24．如图，在△ABC中，AB＝8，BC＝4，CA＝6，CD∥AB，BD是∠ABC的平分线，BD 交AC于点E．（1）求CD的长；（2）求AE的长．25．如图是某区域的平面示意图，码头A在观测站B的正东方向，码头A的北偏西60°方向上有一小岛C，小岛C在观测站B的北偏西15°方向上，码头A到小岛C的距离AC 为10海里．（1）填空：∠BAC＝°，∠C＝°；（2）求观测站B到码头A的距离（结果保留根号）．26．若一个四边形的一条对角线把四边形分成两个等腰三角形，我们把这条对角线叫做这个四边形的和谐线，这个四边形叫做和谐四边形．（1）如图1，在8×5的网格图上（每个小正方形的边长为1）有一个△ABC，点A、B、C均在格点上，请在网格图中找出2个格点D，使得以A、B、C、D为顶点的四边形是和谐四边形，并画出相应的四边形．（2）如图2，在四边形ABCD中，AB∥CD，∠DAB＝40°，∠B＝80°，AC平分∠DAB．试说明：AC是四边形ABCD的和谐线；（3）已知，在四边形ABCD中，AB＝AD＝BC＝2，∠BAD＝90°，AC是四边形ABCD 的和谐线，直接写出CD的长．27．如图1，矩形OABC顶点B的坐标为（6，2），定点D的坐标为（9，0），动点P从点O出发，以每秒2个单位长度的速度沿x轴的正方向匀速运动，动点Q从点D出发，以每秒1个单位长度的速度沿x轴的负方向匀速运动，P、Q两点同时运动，相遇时停止，在运动过程中，以PQ为斜边在x轴上方作等腰直角三角形PQR．设运动时间为t秒．（1）当t＝时，△PQR的边QR经过点B，当t＝时，点R落在边BC上；（2）设△PQR和矩形OABC重叠部分的面积为S，求S与t的函数关系式；（3）如图2，过定点E（4，0）作EF⊥BC，垂足为F，当△PQR的顶点R落在矩形OABC 的内部时，过点R作x轴、y轴的平行线，分别交EF、BC于点M、N，若∠MAN＝45°，直接写出t的值．参考答案一、选择题：（本大题共8小题，共24分.请将答案填涂在答题卡上）1．已知α为锐角，且sinα＝，则α的度数为（）A．15°B．30°C．45°D．60°【分析】根据特殊角的三角函数值即可解答．解：因为sinα＝，所以α＝45°，故选：C．2．如图，在△ABC中，点D、E分别在AB、AC上，DE∥BC．若AD＝4，DB＝2，则的值为（）A．B．C．D．2【分析】首先根据DE∥BC，得出△ADE∽△ABC，即可得出＝，进而得出的值．解：∵DE∥BC，∴△ADE∽△ABC，∴＝，∵AD＝4，DB＝2，∴＝＝＝．则的值为．故选：B．3．如图，有一斜坡AB，坡顶B离地面的高度BC为30m，斜坡的倾斜角是∠BAC，若tan∠BAC＝，则此斜坡的水平距离AC为（）A．75m B．50m C．30m D．12m【分析】根据题目中的条件和图形，利用锐角三角函数即可求得AC的长，本题得以解决．解：∵∠BCA＝90°，tan∠BAC＝，BC＝30m，∴tan∠BAC＝，解得，AC＝75，故选：A．4．将抛物线y＝2x2向上平移3个单位长度后，得到的新抛物线解析式为（）A．y＝2（x﹣3）2B．y＝2（x+3）2C．y＝2x2﹣3D．y＝2x2+3【分析】直接根据“上加下减”的原则进行解答．解：将抛物线y＝2x2向上平移3个单位长度后，得到的新抛物线解析式为y＝2x2+3．故选：D．5．如图，人字梯AB，AC的长都为2米，当α＝50°时，人字梯顶端离地面的高度AD是（）米．A．2sin50°B．2cos50°C．D．【分析】根据锐角三角函数的定义即可求出答案．解：∵sinα＝，∴AD＝AC•sinα＝2sinα＝2sin50°（米），故选：A．6．已知x＝1是方程x2+bx﹣2＝0的一个根，则方程的另一个根是（）A．1B．2C．﹣2D．﹣1【分析】根据根与系数的关系得出x1x2＝＝﹣2，即可得出另一根的值．解：∵x＝1是方程x2+bx﹣2＝0的一个根，∴x1x2＝＝﹣2，∴1×x2＝﹣2，则方程的另一个根是：﹣2，故选：C．7．如图，在6×4的正方形网格中，△ABC的顶点均为格点，则∠ACB的正弦值为（）A．B．C．D．2【分析】连接格点B、D，利用勾股定理先计算BC的长，在Rt△BCD中，再求出∠ACB 的正弦值．解：如图所示，连接格点B、D．∵BD＝2，CD＝1，∴BC＝＝．∴sin∠ACB＝＝＝．故选：A．8．如图1，在矩形ABCD中，点E在CD上，∠AEB＝90°，点P从点A出发，沿A→E →B的路径匀速运动到点B停止，作PQ⊥CD于点Q，设点P运动的路程为x，PQ长为y，若y与x之间的函数关系图象如图2所示，当x＝6时，PQ的值是（）A．2B．3C．D．【分析】由图象可知：AE＝3，BE＝4，∠DAE＝∠CEB＝α，设：AD＝BC＝a，在Rt△ADE中，cosα＝，在Rt△BCE中，sinα＝，由勾股定理可得a＝，当x ＝6时，即EN＝3，则y＝MN＝EN sinα＝．解：由图象可知：AE＝3，BE＝4，∠DAE＝∠CEB＝α，设：AD＝BC＝a，在Rt△ADE中，cosα＝，∴AD＝，在Rt△BCE中，sinα＝，∵∠D＝∠C＝90°，∴△ADE∽△ECB，∴＝，∴DE＝，又∵AD2+DE2＝AE2，∴，解得：a＝，当x＝6时，即：EN＝3，则y＝MN＝EN sinα＝．故选：C．二、填空题：（本大题共8小题，共24分，请将答案填写在答题卡上）9．如果＝，那么的值为．【分析】根据合比性质即可求解．解：∵＝，∴＝＝．故答案为：．10．已知A（﹣4，y1），B（1，y2）为二次函数y＝（x+2）2图象上的两点，则y1＜y2（填“＞，＜或＝”）．【分析】求出二次函数的图象的对称轴，再根据图象上的点的横坐标距离对称轴的远近来判断纵坐标的大小．解：∵二次函数y＝（x+2）2，∴该抛物线开口向上，且对称轴为x＝﹣2．∵A（﹣4，y1），B（1，y2）在二次函数y＝（x+2）2的图象上，点（﹣4，y1）横坐标离对称轴的距离小于点（1，y2）横坐标离对称轴的距离，∴y1＜y2．故答案为：＜．11．在Rt△ABC中，∠C＝90°，cos A＝，AC＝4，则AB＝10．【分析】根据余弦的定义列式计算即可．解：在Rt△ABC中，∠C＝90°，cos A＝，∵cos A＝，AC＝4，∴＝，解得：AB＝10，故答案为：10．12．如图，利用标杆BE测量建筑物的高度，已知标杆BE高1.5m，AB＝2m，BC＝18m．则建筑物CD的高15m．【分析】直接利用已知得出△ABE∽△ACD，再利用相似三角形的性质得出答案．解：由题意可得：BE∥DC，则△ABE∽△ACD，∴，∵标杆BE高1.5m，AB＝2m，BC＝18m，∴，解得：CD＝15．故答案为：15．13．请写出一个二次函数，使它满足条件：当x＝0时，y有最大值为3：y＝﹣x2+3．【分析】根据题意，可知该函数的对称轴是直线x＝0，再根据当x＝0时，y有最大值为3，即可写出一个符合要求的函数解析式．解：∵当x＝0时，二次函数取得最大值，∴该函数的对称轴为x＝0，又∵当x＝0时，y有最大值为3，∴该函数的解析式可以为y＝﹣x2+3，故答案为：y＝﹣x2+3．14．如图，一张三角形纸片ABC，∠C＝90°，AC＝8cm，BC＝6cm．现将纸片折叠：使点A与点B重合，那么折痕长等于cm．【分析】根据折叠得：GH是线段AB的垂直平分线，得出AG的长，再利用两角对应相等证△ACB∽△AGH，利用比例式可求GH的长，即折痕的长．解：如图，折痕为GH，由勾股定理得：AB＝＝10cm，由折叠得：AG＝BG＝AB＝×10＝5cm，GH⊥AB，∴∠AGH＝90°，∵∠A＝∠A，∠AGH＝∠C＝90°，∴△ACB∽△AGH，∴＝，∴＝，∴GH＝cm．故答案为：．15．如图，某校教学楼AC与实验楼BD的水平间距CD＝15米，在实验楼顶部B点测得教学楼顶部A点的仰角是30°，底部C点的俯角是45°，则教学楼AC的高度是（15+15）米（结果保留根号）．【分析】首先分析图形：根据题意构造直角三角形．本题涉及到两个直角三角形△BEC、△ABE，进而可解即可求出答案．解：过点B作BE⊥AB于点E，在Rt△BEC中，∠CBE＝45°，BE＝15；可得CE＝BE×tan45°＝15米．在Rt△ABE中，∠ABE＝30°，BE＝15，可得AE＝BE×tan30°＝15米．故教学楼AC的高度是AC＝15米．答：教学楼AC的高度是（15）米．16．如图，在平面直角坐标系中，点A1的坐标为（1，0），以OA1为直角边作Rt△OA1A2，并使∠A1OA2＝60°，再以OA2为直角边作Rt△OA2A3，并使∠A2OA3＝60°，再以OA3为直角边作Rt△OA3A4，并使∠A3OA4＝60°…按此规律进行下去，则点A2019的坐标为（﹣22017，22017）．【分析】通过解直角三角形，依次求A1，A2，A3，A4，…各点的坐标，再从其中找出规律，便可得结论．解：由题意得，A1的坐标为（1，0），A2的坐标为（1，），A3的坐标为（﹣2，2），A4的坐标为（﹣8，0），A5的坐标为（﹣8，﹣8），A6的坐标为（16，﹣16），A7的坐标为（64，0），…由上可知，A点的方位是每6个循环，与第一点方位相同的点在x正半轴上，其横坐标为2n﹣1，其纵坐标为0，与第二点方位相同的点在第一象限内，其横坐标为2n﹣2，纵坐标为2n﹣2，与第三点方位相同的点在第二象限内，其横坐标为﹣2n﹣2，纵坐标为2n﹣2，与第四点方位相同的点在x负半轴上，其横坐标为﹣2n﹣1，纵坐标为0，与第五点方位相同的点在第三象限内，其横坐标为﹣2n﹣2，纵坐标为﹣2n﹣2，与第六点方位相同的点在第四象限内，其横坐标为2n﹣2，纵坐标为﹣2n﹣2，∵2019÷6＝336…3，∴点A2019的方位与点A3的方位相同，在第二象限内，其横坐标为﹣2n﹣2＝﹣22017，纵坐标为22017，故答案为：（﹣22017，22017）．三、解答题：（本大题共11小题，共102分）17．（1）计算：（﹣1）2019﹣+tan60°+（π﹣3.14）0；（2）解方程：x2﹣2x﹣3＝0．【分析】（1）原式利用算术平方根定义，以及零指数幂法则计算即可求出值；（2）方程利用因式分解法求出解即可．解：（1）原式＝﹣1﹣2++1＝﹣；（2）∵x2﹣2x﹣3＝0，∴（x﹣3）（x+1）＝0，则x﹣3＝0或x+1＝0，解得x1＝3，x2＝﹣1．18．先化简，再求值：（﹣）÷，其中x＝﹣1．【分析】根据分式的混合运算法则把原式化简，把x的值代入计算即可．解：原式＝•＝，当x＝﹣1时，原式＝＝﹣1．19．如图，△ABC中，∠C＝90°，点D在AC上，已知∠BDC＝45°，BD＝10，AB＝20．求∠A的度数．【分析】首先在直角三角形BDC中，利用BD的长和∠BDC＝45°求得线段BC的长，然后在直角三角形ABC中求得∠A的度数即可；解：∵在直角三角形BDC中，∠BDC＝45°，BD＝10，∴BC＝BD•sin∠BDC＝10×＝10∵∠C＝90°，AB＝20∴sin∠A＝＝＝，∴∠A＝30°．20．如图，正方形网格中，每个小正方形的边长是1．已知△ABC的三个顶点坐标分别是A （2，﹣1），B（1，﹣2），C（3，﹣3）．（1）△ABC的面积为 1.5；（2）画出将△ABC向左平移4个单位长度后得到的△A1B1C1；（3）以点A为位似中心，在网格内画出△AB2C2，使△AB2C2与△ABC位似，且位似比为3：1．【分析】（1）割补法求解可得；（2）将点A、B、C分别向左平移4个单位得到对应点，再顺次连接可得；（3）利用位似图形的性质得出对应点位置，进而得出答案．解：（1）△ABC的面积为：2×2﹣﹣﹣＝1.5，故答案为：1.5；（2）如图，△A1B1C1为所作；（3）如图，AB2C2为所作．．21．如图，两栋居民楼之间的距离CD＝30m，楼AC和BD均为10层，每层楼高为3m．上午某时刻，太阳光线GB与水平面的夹角为30°．若小明家住在楼AC的4楼，此时他家是否会被遮挡住？请说明理由（参考数据：≈1.732，≈1.414）．【分析】设太阳光线GB交AC于点F，过F作FH⊥BD于H，解直角三角形求出BH≈17，于是得到FC＝HD＝BD﹣BH≈13，可得此刻楼BD的影子会遮挡到楼AC的第5层．解：他家会被遮挡住，理由：设太阳光线GB交AC于点F，过F作FH⊥BD于H，由题意知，AC＝BD＝3×10＝30m，FH＝CD＝30m，∠BFH＝∠α＝30°，在Rt△BFH中，tan∠BFH＝，∴BH＝30×＝10≈10×1.7＝17（米），∴FC＝HD＝BD﹣BH≈30﹣17＝13（米），∵≈4.3，所以在四层的上面，即第五层，答：他家会被遮挡住．22．如图，已知抛物线y＝mx2和直线y＝﹣2x+b都经过点A（﹣2，6），点O为坐标原点，直线y＝﹣2x+b与x轴交于点B．（1）求m、b的值；（2）连接AO，点C是抛物线上一点（异于点A），且S△AOB＝S△COB，求点C的坐标．【分析】（1）根据抛物线y＝mx2和直线y＝﹣2x+b都经过点A（﹣2，6），将A点坐标代入解析式即可求；（2）根据直线y＝﹣2x+2与x轴交于点B，求出点B的坐标，进而求出S△AOB＝S△COB＝3，进而求出点C的纵坐标，代入抛物线解析式可求．解：（1）∵抛物线y＝mx2和直线y＝﹣2x+b都经过点A（﹣2，6），∴6＝（﹣2）2m，6＝﹣2×（﹣2）+b，∴m＝，b＝2；（2）令y＝0，即﹣2x+2＝0，解得x＝1，点B的坐标为（1，0），∴OB＝1，∴S△COB＝S△AOB＝×1×6＝3，∵S△COB＝×1×y c，∴点C的纵坐标为6，当y＝6时，6＝x2，∴x＝±2，∵C是抛物线上一点（异于点A），∴C点的坐标为（2，6）．23．某景区商店销售一种纪念品，这种商品的成本价10元/件，已知销售价不低于成本价，且物价部门规定这种商品的销售价不高于16元/件，市场调查发现，该商品每天的销售量y（件）与销售价x（元/件）之间的函数关系如图所示．（1）求y与x之间的函数关系式，并写出自变量x的取值范围；（2）每件销售价为多少元时，每天的销售利润为125元？【分析】（1）首先利用待定系数法求出一次函数解析式，进而得出答案；（2）根据已知表示出利润，进而解方程得出答案．解：（1）设y与x之间的函数关系式为：y＝kx+b，把（10，30），（16，24）代入得：，解得：．故y与x之间的函数关系式为：y＝﹣x+40（10≤x≤16）；（2）由题意可得：（﹣x+40）（x﹣10）＝125，解得：x1＝15，x2＝35，根据x的范围，只取x＝15．答：每件销售价为15元时，每天的销售利润为125元．24．如图，在△ABC中，AB＝8，BC＝4，CA＝6，CD∥AB，BD是∠ABC的平分线，BD 交AC于点E．（1）求CD的长；（2）求AE的长．【分析】（1）根据题意BD是∠ABC的平分线，可得∠ABE＝∠CBD，又因为CD∥AB，可得∠ABE＝∠BDC，通过等量代换，可知∠CBD＝∠BDC，以求得CD＝BC＝4；（2）由CD∥AB，可得△ABE∽△CDE，从而求出线段比例关系，求得AE＝2EC，因为CA＝AE+EC＝6，可求AE的长度．解：（1）∵BD是∠ABC的平分线，∴∠ABE＝∠CBD，∵CD∥AB，∴∠ABE＝∠BDC，∴∠CBD＝∠BDC，∴CD＝BC＝4，（2）∵CD∥AB，∴△ABE∽△CDE，∴，∴AE＝2EC，∵CA＝AE+EC＝6，∴AE＝4．25．如图是某区域的平面示意图，码头A在观测站B的正东方向，码头A的北偏西60°方向上有一小岛C，小岛C在观测站B的北偏西15°方向上，码头A到小岛C的距离AC 为10海里．（1）填空：∠BAC＝30°，∠C＝45°；（2）求观测站B到码头A的距离（结果保留根号）．【分析】（1）由题意得∠BAC＝90°﹣60°＝30°，∠ABC＝90°+15°＝105°，再由三角形内角和定理即可得出∠C的度数；（2）证出△BCP是等腰直角三角形，得出BP＝PC，再由锐角三角函数定义求出PA＝BP，然后求出BP的长，即可解决问题．解：（1）由题意得：∠BAC＝90°﹣60°＝30°，∠ABC＝90°+15°＝105°，∴∠C＝180°﹣∠BAC﹣∠ABC＝45°，故答案为：30，45；（2）过B作BP⊥AC于P，如图所示：则∠BPC＝∠BPA＝90°，∵∠C＝45°，∴△BCP是等腰直角三角形，∴BP＝PC，∵∠BAC＝30°，∴AB＝2PB，tan∠BAC＝＝，∴PA＝BP，∵PA+PC＝AC，∴BP+BP＝10海里，解得：BP＝（5﹣5）海里，∴AB＝2BP＝（10﹣10）海里，即观测站B到码头A的距离为（10﹣10）海里．26．若一个四边形的一条对角线把四边形分成两个等腰三角形，我们把这条对角线叫做这个四边形的和谐线，这个四边形叫做和谐四边形．（1）如图1，在8×5的网格图上（每个小正方形的边长为1）有一个△ABC，点A、B、C均在格点上，请在网格图中找出2个格点D，使得以A、B、C、D为顶点的四边形是和谐四边形，并画出相应的四边形．（2）如图2，在四边形ABCD中，AB∥CD，∠DAB＝40°，∠B＝80°，AC平分∠DAB．试说明：AC是四边形ABCD的和谐线；（3）已知，在四边形ABCD中，AB＝AD＝BC＝2，∠BAD＝90°，AC是四边形ABCD 的和谐线，直接写出CD的长2或2．【分析】（1）根据和谐四边形的定义，作出图形即可．（2）证明DA＝DC，AC＝AB，即可．（3）首先根据题意画出图形，然后由AC是四边形ABCD的和谐线，可以得出△ACD是等腰三角形，从图3，图4两种情况运用等边三角形的性质，正方形的性质和30°的直角三角形性质就可以得出结论．【解答】（1）解：如图，四边形ABDC即为所求．（2）证明：如图2中，∵AC平分∠DAB，∴∠DAC＝∠CAB＝∠DAB＝20°，∵CD∥AB，∴∠DCA＝∠CAB＝20°，∴∠DAC＝∠DCA，∴DA＝DC，∵∠ACB＝180°﹣∠CAB﹣∠B＝180°﹣20°﹣80°＝80°，∴∠ACB＝∠B，∴AC＝AB，∴AC是四边形ABCD的和谐线．（3）如图3，4，∵AC是四边形ABCD的和谐线，∴△ACD是等腰三角形．∵AB＝AD＝BC，如图3，当AD＝AC时，∴AB＝AC＝BC，∠ACD＝∠ADC，∴△ABC是正三角形，∴∠BAC＝∠BCA＝60°．∵∠BAD＝90°，∴∠CAD＝30°，过点C作CE⊥AD于E，∴CE＝AC＝1，∴AE＝，∴DE＝AD﹣AE＝2﹣，∴CD＝＝2如图4，当AD＝CD时，CD＝2，综上所述，满足条件的CD的长为2或2．27．如图1，矩形OABC顶点B的坐标为（6，2），定点D的坐标为（9，0），动点P从点O出发，以每秒2个单位长度的速度沿x轴的正方向匀速运动，动点Q从点D出发，以每秒1个单位长度的速度沿x轴的负方向匀速运动，P、Q两点同时运动，相遇时停止，在运动过程中，以PQ为斜边在x轴上方作等腰直角三角形PQR．设运动时间为t秒．（1）当t＝1时，△PQR的边QR经过点B，当t＝时，点R落在边BC上；（2）设△PQR和矩形OABC重叠部分的面积为S，求S与t的函数关系式；（3）如图2，过定点E（4，0）作EF⊥BC，垂足为F，当△PQR的顶点R落在矩形OABC 的内部时，过点R作x轴、y轴的平行线，分别交EF、BC于点M、N，若∠MAN＝45°，直接写出t的值．【分析】（1）△PQR的边QR经过点B时，△ABQ构成等腰直角三角形，则有AB＝AQ，由此列方程求出t即可，当R落在BC边上时，因为△PQR是等腰直角三角形，故PR＝AB，由此列出方程求解即可；（2）在图形运动过程中分三种情况讨论，按t的取值范围分段写出关系式即可；（3）首先判定四边形ABFE是正方形，其次通过旋转，由三角形全等证明MN＝EN+BN，设EM＝m，BN＝n，在Rt△FMN中，有勾股定理得出m和n的关系式，由此等式列方程求出t的值即可．解：（1）△PQR的边QR经过点B时，△ABQ构成等腰直角三角形，∴AB＝AQ，即2＝9﹣6﹣t，解得t＝1，∴t＝1时，△PQR的边QR经过点B；点R落在边BC上，则R纵坐标的长度和AB相同，∵△PQR为等腰直角三角形，∴PQ＝2AB＝2×2＝4，即9﹣t﹣2t＝4，解得t＝，∴t＝时，点R落在边BC上；故答案为：1，；（2）①当0≤t≤1时，如图1所示，设PR交BC于点G，过点P作PH⊥BC于点H，则CH＝OP＝2t，GH＝PH＝2，∴S＝S矩形OABC﹣S梯形OPGC＝6×2﹣（2t+2t+2）×2＝10﹣4t；②当1＜t≤时，如图2所示，设PR交BC于点C，RQ交BC、AB于点S、T，过点P作PH⊥BC于点H，则CH＝OP＝2t，GH＝HP＝2，QD＝t，则AQ＝AT＝9﹣6﹣t＝3﹣t，∴BT＝BS＝AB﹣AT＝2﹣（3﹣t）＝t﹣1，∴S＝S矩形OABC﹣S梯形OPGC﹣S△BST＝6×2﹣﹣（2t+2t+2）×2﹣（t﹣1）2＝﹣t2﹣3t+；③当＜t≤3时，如图3所示，设RQ与AB交于点T，则AT＝AQ＝9﹣6﹣t＝3﹣t，PQ＝9﹣2t﹣t＝9﹣3t，∴PR＝RQ＝PQ＝（9﹣3t），∴S＝S△PQR﹣S△AQT＝PR2﹣AQ2＝[（9﹣3t）]2﹣（3﹣t）2＝t2﹣t+；综上，S与t的函数关系式为；（3）∵E（4，0），∴AE＝AB＝2，∴四边形ABFE是正方形，如图4，将△AME绕A顺时针旋转90°，得到△ABM'，其中AE和AB重合，∵∠MAN＝45°，∴∠EAM+∠NAB＝45°，∴∠BAM'+∠NAB＝45°，∴∠MAN＝∠M'AN，连接MN，在△MAN和△M'AN中，，∴△MAN≌△M'AN（SAS），∴MN＝M'N＝M'B+BN，∴MN＝EM+BN，设EM＝m，BN＝n，则FM＝2﹣m，FN＝2﹣n，在Rt△FMN中，由勾股定理得：FM2+FN2＝MN2，即（2﹣m）2+（2﹣n）2＝（m+n）2，整理得，mn+（m+n）﹣4＝0，①延长NR交x轴于点S，则m＝EM＝RS＝PQ＝×（9﹣3t），∵QS＝PQ＝×（9﹣3t），AQ＝3﹣t，∴n＝BN＝AS＝QS﹣AQ＝×（9﹣3t）﹣（3﹣t）＝﹣，∴m＝3n，代入①式，化简得：3n2+4n﹣4＝0，解得n＝或n＝﹣2（舍去），∴BN＝﹣＝，解得t＝，故答案为：．。

江苏省淮阴中学开明分校2019-2020学年八上Unit 2 Reading完形阅读同步测试(word版含答案)

江苏省淮阴中学开明分校2019-2020学年八上Unit 2 Reading完形阅读同步测试(word版含答案)

Unit 2 Reading (II)班级______________ 姓名______________ 学号______________一、完形填空。

I recently started a new job in a small office. In the office four of us 1 a water filter (滤水壶). One of my workmates complained the water 2 bad. It went on for a few days, and I could drink the water 3 any trouble. I started to doubt (怀疑) my taste buds, but the water really tasted 4 .Finally, she 5 the problem was actually her cup. She simply 6 to clean it. Then she cleaned her cup, and drank the water with no problem.I can’t help but think about the 7 we live in. Too often we quickly 8 about other people, other things, anything else but not 9 . “You’re silly.”“You’re slow.”“You are the problem.” The world 10 perfect, I know, but I think we should take a step back sometimes and ask ourselves some questions. Can I be 11 ? Is my heart really pure (纯洁的)? Can I help this situation with kindness?I want to tell you this: please 12 your cup. Because when you do this, the water will taste much better. I promise you this.( ) 1. A. bought B. shared C. cleaned D. drank( ) 2. A. looked B. tasted C. smelled D. sounded( ) 3. A. in B. with C. without D. out of( ) 4. A. bad B. fine C. terrible D. strange( ) 5. A. gave up B. put off C. found out D. looked for( ) 6. A. decided B. tried C. planned D. forgot( ) 7. A. world B. country C. city D. house( ) 8. A. care B. complain C. think D. help( ) 9. A. yourself B. ourselves C. themselves D. myself( ) 10. A. is B. isn’t C. must be D. was( ) 11. A. better B. worse C. fatter D. smaller( ) 12. A. face B. clean C. break D. taste二、阅读理解。