5.2015高考预测试卷

2015年高考预测金卷（安徽卷）语文试题本试卷分为第I卷（阅读题）和第II卷（表达题）两部分，第I卷第1页至6页，第II 卷第7页至8页.全卷满分150分，考试时间150分钟。

考生注意事项：1．答题前，务必在试题卷、答题卡规定的地方填写自己的姓名、座位号，并认真核对答题卡上所粘贴的条形码中的姓名、座位号与本人姓名、座位号是否一致。

务必在答题卡背面规定的地方填写姓名和座位号后两位。

2．答选择题（第I卷1 ~ 6题，第II卷15 ~ 17题）时，每小题选出答案后，用2B铅笔把答题卡上．．．．所对应题目的答案标号涂黑。

如需改动，用橡皮擦干净后，再选涂其他答案标号。

3．答非选择题（第I卷7 ~ 14题，第II卷18 ~ 21题）必须使用0.5毫米的黑色墨水签字笔在答题卡上书写，要求字体工整、笔迹清晰。

作图题可先用铅笔在答题卡．．．的规定的位置绘出，确认后再用0.5毫米的黑色墨水签字笔描清楚。

必须在题号所指示的答题区域作答，超出答题区域书写的答案无效，在试题卷、草稿纸上答题无效．．．．．．．．．．．．．．．．．．．．．．．．．．．。

4．考试结束后，务必将试题卷和答题卡一并上交。

第I卷（阅读题，共66分）一、（9分）阅读下面的文字，完成1 ~ 3题。

一、（9分）阅读下面的文字，完成1～3题。

任何民族的饮食乃至由饮食折射出的文化特质都体现了这个民族独一无二的文化风范。

中华文化的核心理念体现在“和”字上，“和”有“中和”“融合”之意。

中华饮食的发展鲜明地体现了“和”文化的思想精髓。

中华饮食起源于农耕文明，大量食物来自土地。

随着民族文化的交融，汉族逐渐接受了游牧民族的“肉食”饮食方式，扩大了食物范围，丰富了饮食结构。

汉唐以后，中亚及东南亚等地的食物品种大量引进，增补了中华饮食品种。

近世以来，西方饮食理念与方式得到认同，具有现代特征的中华饮食形态逐渐形成，翻开中国食谱，到底哪种是地道的中国食物或外来食物，人们恐怕已经模糊。

2015年高考预测卷理科综合能力测试本试卷分第Ⅰ卷（选择题）和第Ⅱ卷（非选择题）两部分。

考生注意事项：1. 答题前，务必在试题卷、答题卡规定的地方填写自己的姓名、座位号，并认真核对答题卡上所粘帖的条形码中姓名、座位号与本人姓名、座位号是否一致。

务必在答题卡背面规定的地方填写姓名和座位号后两位。

2. 答第Ⅰ卷时，每小题选出答案后，用2B铅笔把答题卡上．．．．对应题目的答案标号涂黑，如需改动，用橡皮擦干净后，再选涂其他答案标号。

3. 答第Ⅱ卷时，必须用0.5毫米黑色墨水签字笔在答题卡上．．．．书写，要求字体工整、笔迹清晰。

作图题时可先用铅笔在答题卡．．．规定的位置绘出，确认后用0.5毫米的黑色墨水签字笔描清楚。

必须在题号所指示的答题区域作答，超出答题区域书写的答案无效．．．．．．．．．．．．．．．．，在试题卷．．．．、草稿纸上答题无效．．．．．。

4. 考试结束，务必将试题卷和答题卡一并上交。

第Ⅰ卷（选择题共120分）本卷共20小题，每小题6分.共120分。

在每题给出的四个选项中，只有一项是最符合题目要求的。

1、一切生命活动都离不开蛋白质，下图表示部分细胞结构和多种蛋白质，有关叙述错误的是（）A．若A蛋白与细胞间的相互粘连有关，则在动物细胞工程中常用胰蛋白酶处理组织碎块，使细胞分散开B．若B蛋白与物质跨膜运输有关，且转运过程不消耗ATP，则转运方式为协助扩散C．若C蛋白只能与特定分子结合，结合后引起细胞内一系列变化，则C蛋白是细胞膜完成信息交流的分子基础D．若E蛋白具有催化功能，则其只能与一种物质结合，功能特征表现为专一性的特点2、图甲表示全光照和不同程度遮光对某植物叶片中叶绿素含量的影响，图乙表示初夏某天在遮光50%条件下，温度、光照强度、该植物净光合速率和气孔导度（气孔张开的程度）的日变化趋势。

下列说法错误．．的是（）A．图甲中叶绿素含量的测定，可先用无水乙醇提取叶片中的色素B．据图甲推测，该植物可通过增加叶绿素含量以增强对弱光的适应能力C．图乙中8:00到12:00净光合速率降低的原因一定是光合作用速率减弱D．图乙中18:00时光合作用固定CO2速率和呼吸作用释放CO2速率相等3、人21号染色体上的短串联重复序列（STR，一段核苷酸序列）作为遗传标记，可对21三体综合症作出快速的基因诊断（遗传标记可理解为等位基因）。

保密★启用前试卷类型：A 2015年普通高等学校招生全国统一考试语文预测卷（山东卷）注意事项：1．本试题分为选择题和非选择题两部分，共8页。

时间150分钟，满分150分。

2．务必将自己的班级、姓名、座号、考号填涂在答题卡的相应位置。

第Ⅰ卷（共36分）一、（每小题3分，共15分）1.下列词语中加点字读音全都正确的一项是A.跟帖．（tiě）弱冠．（ɡｕàn）闷．葫芦（mēn）若即．若离（jí）B.更．名（gēng）骠．勇（biāo）根状茎．（jīng）方枘圆凿．（záo）C.蓦．然（mò）混．浊（hùn）电饭煲．（bāo）间．不容发（jiàn）D.着．魔（zháo）矜．持（jīn）夹．生饭（jiā）经．史子集（jīnɡ）2．下列各句中，标点符号使用正确的一项是A．随着香港非法“占领中环”活动的结束，香港特首梁振英提醒广大市民，要深刻反思一下香港究竟应该追求怎样的民主的问题?B．市安监局近期检查了部分酿酒企业，其中存在的共性问题包括：厂区设计不合理，消防设施不齐全，应对措施不完善等，这些都是引发重大事故的隐患。

C．中国比较文学学会在四川大学举行颁奖典礼，向乐黛云、陈悖、谢天振等九位在比较文学领域作出卓越贡献的专家颁发了“中国比较文学终身成就奖”。

D．李光耀强行将英语作为新加坡中小学的第一教学语言，并反对将华人方言列入学校教程(如粤语、闽南语等)，以免因国人说多种方言而造成社会分裂。

3．依次填入下列横线处的词语，最恰当的一项是①日本著名健身教练秋元惠久认为，身体肥胖往往与不良习惯有关，注意加强锻炼和控制饮食就会使_____得到重塑，整体气质得到提升。

②因突降大雪，为防止路面积雪结冰，影响市民安全出行，环卫部门启动应急预案，在第一时间向市区各主干道_____了颗粒状融雪剂。

③上世纪三十年代，粉画艺术开始传入中国，并一度兴盛，____多年，受各种条件限制，粉画艺术日趋衰落。

2015届新课标高考预测试题语文说明：本试卷分为第I卷（选择题）和第II卷（非选择题）两部分。

其中第卷II第11、12题为二选一，其他题为必考题。

考生作答时，将答案写在答题卡上，在本试卷上答题无效，考试结束后，将本试卷和答题卡一并交回。

本试卷满分150分，考试时间150分钟。

注意事项：1、答题前，考生务必将自己的姓名、准考证号填写在答题卡上，认真核对条形码上的姓名、准考证号，并将条形码粘贴在答题卡的指定位臵。

2、选择题答案使用2B 铅笔填涂，如需改动，用橡皮擦干净后，再选涂其他答案标号；非选择题答案使用0.5毫米的黑色中性笔或碳素笔书写，字体工整、笔迹清楚。

3、请按题号在各题的答题区域（黑色线框）内作答，超出答题区域书写的答案无效。

4、保持卡面清洁，不折叠，不破损。

做选考题时，考生按照题目要求作答，并用2B铅笔在答题卡上把所选题目对应题号涂黑。

第Ⅰ卷（阅读题）甲必考题一、现代文阅读（9分，每小题3分）阅读下面的文字，完成1～3题。

墨家何以成为历史上的失踪者陈玉明先秦诸子百家中，影响最大的自然要数儒、墨、道、法四家。

但自秦汉大一统帝国形成之后，它们的命运开始分化：儒家成了中华文化的正统和主流；法家虽在舆论上不大受好评，但实际上主宰了两千年来专制朝廷的庙堂政治；与法家相反，道家则占据了民间社会的广阔天地，成为幽人隐士的精神家园。

只有墨家，在刹那辉煌之后，无论是作为一种学说，还是作为一种组织，都烟消云散，湮没在历史的长河中。

作为一个长期而普遍的历史事实，墨家的消亡大概也并非偶然的命运安排。

只是，原因是什么？墨家与儒、道、法三家有一点差别，那就是它不仅有一套学说，还有自己的组织。

这方面它与晚起的作为宗教的道教和东汉以后传入中国的佛教相类似，胡适先生甚至直接把墨家视为一种宗教，所以我们不妨拿墨家与释道二教来作比较。

就外因看，百家既罢、儒术独尊的历史环境可能是墨家消亡的重要原因，但同样不能居庙堂之高的道教（个别时期除外）却没有像墨家一样消亡，反而在民间发扬光大，并深深影响了中华民族的底层民俗文化。

2015年高考数学分析与预测不少专家把2014年称作中国教育改革元年，从教育部到各省区市，相继出台减轻学生课业负担、规范教学过程、治理择校、改革考试评价制度等一系列的改革措施。

这意味着教育改革已经进入了“深水区”。

在这种情况下，2015年的高考显得非同寻常。

专家指出，综合运用所学知识解决生活中的实际问题，也就是检验学生的思辨力，将是今后高考的考查方向。

知识是用来解决实际问题的“繁复的计算”、“海量的公式和原理”、“考过就忘”似乎是很多学生对数学的记忆。

不过，今年高考数学全国卷中的一道题，让人眼前一亮。

“甲、乙、丙三位同学被问到是否去过A，B，C三个城市时，甲说：我去过的城市比乙多，但没去过B城市；乙说：我没去过C城市；丙说：我们三人去过同一城市。

由此可判断乙去过的城市为____”“没有公式、没有原理、没有运算，只考查推理能力。

”考试中心数学命题专家说。

这种通过所学知识、获得解决问题的方法并能解决生活实际中可能遇到的问题，体现了高考改革的方向。

这位专家同时指出，计算并不是不重要，而是要把计算同逻辑推理结合起来，即使要计算也首先要通过逻辑推理之后再计算。

今后全国卷会慢慢普及，各省高考方向都在变化，但无论教育制度体制怎么改，数学最基本的知识是一成不变的，该考什么还考什么，只是侧重点会有一点的倾斜，所以大家记住无论其他学科怎么变，数学是基本不变的。

未来的数学考试：主要考查学生的自学能力、接受新知识的能力、应用意识实践能力、创新精神和潜质、同时这样的试题更加具备科学性、公平性和规范性是一个良好的趋势。

在这里我建议2015届的考生要关注平时的练习中出现的基础问题，出错了不能归纳为一时的马虎粗心，要查找深层次的原因，提升数学素养，查漏补缺，才能在2015年高考取得理想成绩。

下面给出2015年两套预测卷，理科文科各一套，难度依然很明显,理科要大很多。

2015年高考预测卷理科 数学一、选择题：本大题共10小题，每小题5分，共50分，在每小题给出的四个选项中，有且只有一项符合题目要求． 1．若复数2()1aiz a R i-=∈+是纯虚数，i 是虚数单位，则a 的值是 ( ) A ．2 B ．1 C ．1- D ．2- 2. 已知随机变量2(2,)N ξσ，且(1)0.4P ξ<=，则(3)P ξ≤等于 ( )A ．0.3B ．0.4C ．0.5D ．0.6 3．某几何体的三视图如右图所示，则该几何体的体积为（ ）A ．1B ．13 C ．12 D ．324．设实数,x y 满足约束条件20,30,2,x y x y x y m -≤⎧⎪+-≥⎨⎪+≤⎩且z x y =-的最小值为3-，则实数m 的值为（ ）A ．1-B ．52-C ．6D ．7 5．已知i 为执行如图所示的程序框图输出的结果，则二项式61i x x ⎛⎫⋅- ⎪⎝⎭的展开式中含2x -项的系数是（ ）A ．192B ．32C ．42-D ．192- 6．正方体1111ABCD A B C D -中，O 为侧面11BCC B 的中心，则AO 与平面ABCD 所成的角的正弦值为（ ）A ．32 B ．12 C ．36 D ． 667．已知函数3()log ()(0a f x x a a=+>且1)a ≠恒过点(2,1)，则2()232f x x x =--+的解的个数为（ ）A ．1B ．2C ．3D ．48．在ABC ∆中，()3AB AC CB -⊥，则角A 的最大值为（ ）A ．6πB ．4πC ．3πD ．2π 9．已知双曲线22221(0,0)x y a b a b -=>>的两个焦点为12,F F ，其中一条渐近线方程为()2by x b N +=∈，P 为双曲线上一点，且满足5OP <(其中O 为坐标原点)，若1PF 、12F F 、2PF 成等比数列，则双曲线C 的方程为（ ）A ．2214x y -=B ．221x y -= C ．22149x y -= D ．221416x y -= 10．给出下列命题：① “0x R ∃∈，使得20010x x -+<”的否定是“x R ∀∈，使得210x x -+≥”； ② 0a b ⋅>是向量,a b 的夹角为锐角的充要条件；③ 设ABC ∆的内角A B C 、、的对边分别为a b c 、、，且满足3cos cos 5a Bb Ac -=， 则tan 4tan AB=； ④ 记集合{1,2,3},{1,2,3,4}M N ==，定义映射:f M N →，则从中任取一个映射满足“由点(1,(1)),(2,(2)),(3,(3))A f B f C f 构成ABC ∆且AB BC =”的概率为316． 以上命题正确的个数为（ ）A ．1B ．2C ．3D ．4二、填空题：本大题共6小题，考生作答5小题，每小题5分，共25分．把答案填在答题卡中对应题号的横线上．（一）选做题（请考生在第11，12，13三题中任选两题作答，如果全做，则按前两题记分） 11．在极坐标系中，已知直线l 的极坐标方程为sin()214πρθ+=+，圆C 的圆心为2,4π⎛⎫ ⎪⎝⎭，半径为2，则直线l 被圆C 所截得的弦长为__________．12．已知222236,2x y z a x y z a ++=++=-，则实数a 的取值范围是________． 13．如图，在ABC ∆中，90,60C A ∠=∠=，过C 作ABC ∆的外接圆的切线CD ，BD CD ⊥于D ，BD 与外接圆交于点E ，已知5DE =，则ABC ∆的外接圆的半径为________. （二）必做题（14～16题）14．已知向量1(2sin ,),(2,cos )3a b αα==且//a b ，则2cos ()4πα+= _______．15．已知函数()sin()(0)3f x x πωω=+>在区间5,66ππ⎡⎤-⎢⎥⎣⎦的端点上恰取相邻一个最大值点和一个最小值点，则 （1）ω的值为______； （2）在,,136x x y ππ=-==和x 轴围成的矩形区域里掷一小球，小球恰好落在函数()f x =sin()([,])336x x πππω+∈-与x 轴围成的区域内的概率为__________．16．科拉茨是德国数学家，他在1937年提出一个著名的猜想：任给一个正整数n ，如果n 是偶数，就将它减半（即2n）；如果n 是奇数，则将它乘3加1（即31n +），不断重复这样的运算，经过有限步后，一定可以得到1．如初始正整数为6，按照上述变换规则，我们可以得到一个数列：6，3，10，5，16，8，4，2，1．（1）如果2n =，则按照上述规则施行变换后的第8项为_________；（2）如果对正整数n （首项）按照上述规则施行变换后的第8项为1（注：1可以多次出现），则n 的所有不同值的个数为________．三、解答题（本大题共6小题，共75分，请将解答过程写在答题卡的相应位置，要有必要的文字说明和演算步骤） 17．（本小题满分12分）在ABC ∆中，三内角A ，B ，C 所对的边分别是a ，b ，c ，且c a C b -=2cos 2． （Ⅰ）求角B 的大小；（Ⅱ）若C A sin sin 的取值范围．点评：作为第一道大题，三角函数的考察一般都是送分，出难也可以，不过肯定会被骂的，第一道想出新有些难度，就算换考点这第一道题难度最好还是不要太高。

姓名准考证号绝密★启用前2015年高考预测卷（联考）语文注意事项：1.本试卷分第Ⅰ卷（阅读题）和第Ⅱ卷（表达题）两部分，共150分。

2.答第Ⅰ卷前，考生务必将自己的姓名、准考证号、考试科目涂写在机读卡上。

3.回答1～6题、13～15题时，选出每小题答案后，用2B铅笔把机读卡上对应题目的答案标号涂黑。

如需改动，用橡皮擦干净后，再选涂其他答案标号。

写在本试卷和答题卡上无效。

4.本卷共18小题，除1～6题、13～15题外，均需把答案写在答题卡相应位置上，写在本试卷上无效。

5.考试结束后，将本试卷、机读卡和答题卡一并交回。

第Ⅰ卷甲必考题一、现代文阅读（9分，每小题3分）阅读下面文字，完成1~3题。

西洋画素描与中国画的白描及水墨法，摆脱了彩色的纷华灿烂、轻装简从，直接把握物的轮廓、物的动态、物的灵魂。

画家的眼、手、心与造物面对面肉搏。

物象在此启示它的真形，画家在此流露他的手法与个性。

抽象线纹，不存于物，不存于心，却能以它的匀整、流动、回环、曲折，表达万物的体积、形态和生命；更能凭借它的节奏、速度、刚柔、明暗，有如弦上的音、舞中的态，写出心情的灵境而探入物体的诗魂。

所以中国画自始至终以线为主。

张彦远的《历代名画记》上说：‚无线者非画也。

‛这句话何其爽直和肯定！西洋画的素描则自米开朗琪罗、达芬奇、拉斐尔、伦勃朗以来，不但是作为油画的基础工作，画家与物象第一次会晤交接的产儿，且以其表示画家‚心灵艺术的探险史‛的光荣与胜利，使我们直接窥见艺人心物交融的灵感刹那，惊天动地的非常际会。

其历史的价值与心理的趣味有时超过完成的油画。

然而中西线画之关照物象与表现物象的方式、技法，有着历史上传统的差别：西画线条是显露着凹凸，体贴轮廓以把握坚固的实体感觉；中国画则以飘洒流畅的线纹，笔畅墨饱，自由组织，暗示物象的骨骼、气势与动向。

顾恺之是中国线画的祖师，唐代吴道子是中国线画的创造天才与集大成者，他的画法有所谓‚吴带当风‛，可以想见其线纹的动荡、自由、超象而取势。

2015届高三预测金卷（新课标I卷）理综1、随着生活水平的提高和生活方式的改变，高血脂人群相对增多。

脂类在血液中以脂蛋白的形式进行运送，并可与细胞膜上存在的特异性受体相结合，进入细胞内进行代谢(如图所示)。

对该图分析不合理的是（）A．图中物质X很可能是具有识别功能的受体蛋白B．物质X在溶酶体酶的作用下被水解为氨基酸C．该过程的完成与生物膜的结构特点密切相关D．该过程需要消耗ATP直接提供的能量2、关于生物学实验的基本原理，叙述正确的是（）A．用健那绿染色时，在光学显微镜下可看到线粒体内膜某些部位向内腔折叠形成的嵴B．用双缩脲试剂鉴定蛋白质是因为其与蛋白质作用产生特定的紫色反应C．成熟植物细胞在高渗溶液中发生质壁分离是因为细胞壁有选择透过性D．向锥形瓶的酵母菌培养液通入空气是为了抑制无氧呼吸的需要3、研究发现，诱导人体表皮细胞使之具有胚胎干细胞活动特征，且这些细胞可以转变为心脏和神经细胞。

下列与此有关的说法不正确的是（）A. 诱导后的细胞具有分裂和分化能力B. 人体表皮细胞具有全能性C. 该研究说明细胞分化是可以逆转的D. 该研究可以为治疗心血管绝症提供帮助4、拟南芥细胞中某个基因编码蛋白质的区段插入了一个碱基对，下列分析正确的是（）A.根尖成熟区细胞一般均可发生此过程B.该细胞的子代细胞中遗传信息不会发生改变C.若该变异发生在基因中部，可能导致翻译过程提前终止D.若在插入位点再缺失3个碱基对，对其编码的蛋白质结构影响最小5、为控制野兔种群数量，澳洲引入一种主要由蚊子传播的兔病毒。

引入初期强毒性病毒比例最高，兔被强毒性病毒感染后很快死亡，致兔种群数量大幅下降。

兔被中毒性病毒感染后可存活一段时间。

几年后中毒性病毒比例最高，兔种群数量维持在低水平。

由此无法推断出( )A ．病毒感染对兔种群的抗性具有选择作用B ．毒性过强不利于维持病毒与兔的寄生关系C ．中毒性病毒比例升高是因为兔抗病毒能力下降所致D ．蚊子在兔和病毒之间的协同（共同）进化过程中发挥了作用6、当细胞癌变后，它会表达某种特殊的蛋白质于细胞表面而成为肿瘤表面抗原，但此时不能引发免疫反应。

2015年普通高等学校招生全国统一考试数学理科预测试题（全国课标卷一）（满分150分，考试时间120分）第Ⅰ卷（选择题 60分）一、选择题(5×12＝60分，在每小题给出的四个选项中，只有一项是符合题目要求的，请将正确选项用2B铅笔涂黑答题纸上对应题目的答案标号)1.若全集U=R，集合A={x|x2+x﹣2≤0}，B={y|y=log2（x+3），x∈A}，则集合A∩（∁U B）=（）A． {x|﹣2≤x＜0} B． {x|0≤x≤1} C． {x|﹣3＜x≤﹣2} D． {x|x≤﹣3}1.A【考点】：交、并、补集的混合运算．【专题】：集合．【分析】：求出A中x的范围确定出A，根据全集U=R及B，求出B的补集，找出A与B 补集的交集即可．解：A={x|x2+x﹣2≤0}={x|﹣2≤x≤1}，∵B={y|y=log2（x+3），x∈A}，由于函数y=log2（x+3）为增函数，∴B={y|0≤y≤2}，∵全集U=R∴∁U B={y|y＜0或y≥2}，∴A∩∁U B={x|﹣2≤x＜0}．故选：A．【点评】：本题考查了交、并、补集的混合运算，熟练掌握运算法则是解本题的关键．2.设是虚数单位，若复数为纯虚数，则实数的值为．．．．答案及解析：2.依题意．由复数为纯虚数可知，且，求得．故选．3.已知向量是单位向量，，若•=0，且|﹣|+|﹣2|=，则|+2|的取值范围是（）A． [1，3] B． [] C． [，] D． [，3]答案及解析：3.D【考点】：平面向量数量积的运算．【专题】： 平面向量及应用． 解：因为•=0，且|﹣|+|﹣2|=，设单位向量=（1，0），=（0，1），=（x ，y ）， 则=（x ﹣1，y ），=（x ，y ﹣2）， 则，即（x ，y ）到A （1，0）和B （0，2）的距离和为，即表示点（1，0）和（0，2）之间的线段， |+2|=表示（﹣2，0）到线段AB 上点的距离，最小值是点（﹣2，0）到直线2x+y ﹣2=0的距离所以|+2|min =，最大值为（﹣2，0）到（1，0）的距离是3，所以|+2|的取值范围是[，3]；故选：D ． 4．设f(x)是定义在R 上的奇函数，其f(x)=f(x-2),若f(x)在区间[]2,3单调递减，则（ ）(A) f(x)在区间[]3,2--单调递增 (B) f(x)在区间[]2,1--单调递增(C) f(x)在区间[]3,4单调递减 (D) f(x)在区间[]1,2单调递减【知识点】奇偶性与单调性的综合【答案解析】D 解析：由f （x ）=f （x ﹣2），则函数的周期是2，若f （x ）在区间[2，3]单调递减，则f （x ）在区间[0，1]上单调递减，∵f （x ）是定义在R 上的奇函数，∴f （x ）在区间[﹣1，0]上单调递减，且f （x ）在区间[1，2]上单调递减，故选：D【思路点拨】根据函数奇偶性和单调性之间的关系即可得到结论．5．将甲、乙、丙等六人分配到高中三个年级，每个年级2人，要求甲必须在高一年级，乙和丙均不能在高三年级，则不同的安排种数为 ( )A ．18B ．15C ．12D ．9【知识点】排列组合的应用J2【答案解析】D 解析：可以先排高三年级有233C =种排法，再排高一年级有13C =3种排法，剩余的排在高二，所以一共有3×3=9种排法.【思路点拨】在计算有限制条件的排列问题时，可以从特殊位置出发，先排特殊位置再排一般位置.6.已知某几何体的三视图（单位：cm ）如图所示，则该几何体的体积是( ) A. B.100 C.92 D.84答案及解析：6.【知识点】由三视图求面积、体积．G2B 解析：如图所示，原几何体为：一个长宽高分别为6，3，6的长方体砍去一个三棱锥，底面为直角边分别为3，4直角三角形，高为4．因此该几何体的体积=3×6×6﹣=108﹣8=100．故选B．【思路点拨】如图所示，原几何体为：一个长宽高分别为6，3，6的长方体砍去一个三棱锥，底面为直角边分别为3，4直角三角形，高为4．利用长方体与三棱锥的体积计算公式即可得出．7.执行右图程序框图，如果输入的，均为2，则输出的S= （）A. 4B. 5C. 6D. 7答案及解析：7.【知识点】程序框图．D 解：若x=t=2，则第一次循环，1≤2成立，则M= ×2＝2，S=2+3=5，k=2，第二次循环，2≤2成立，则M= ×2＝2，S=2+5=7，k=3，此时3≤2不成立，输出S=7，故选：D．【思路点拨】根据条件，依次运行程序，即可得到结论．8.已知都是定义在上的函数，，，且，且，．若数列的前项和大于，则的最小值为（）A．6 B．7 = C．8 D．9答案及解析：8.【知识点】导数的应用A∵，∴，∵，∴，即，∴，∵，∴，∴，∴，∴，∴数列为等比数列，∴，∴，即，所以的最小值为6。

2015年普通高等学校招生全国统一考试语文预测卷（湖南卷）注意事项：1、答题前，考生务必将自己的姓名、准考证号写在答题卡上，并认真核对条形码上的姓名、准考证号和科目。

2、考生作答时，选择题和非选择题均需作在答题卡上，在本试卷上答题无效。

考生在答题卡上按答题卡中注意事项的要求答题。

3、考试结束后，将本试卷和答题卡一并交回。

4、本试卷共8页。

如缺页，考生须声明，否则后果自负。

5、本试题卷共7道大题，22道小题，时量150分钟，满分150分。

一、语言文字运用（12分，每小题3分）阅读下面的文字，完成1～3题。

当电视( )屏上刮了太久的轻浅风之后，（甲）看到《平凡的世界》这样的电视作品，许多人都觉得不大习惯。

有时，我们麻木又没心没肺地跟随遥控器穿梭在不同的频道间，满眼皆是( )皮笑脸、( )情造作的电视剧，它们轻飘飘地掠过我们的眼球、大脑，最终什么也留不下。

当下的国产电视剧，够多、够长，也够华丽，但偏偏不够重。

讲爱情的，没有_______；讲亲情的，没有_______；讲历史的，没有_______；讲战争的，也没有_______。

作品失重带来的是趣味失重、（乙）失重，甚至是观念失重。

于是，尺度大的、无厘头的电视剧竟然最受欢迎。

在这一形势下，《平凡的世界》多次出现在微博热搜榜上，是一个有趣且令人( )奋的现象。

1．下列汉字，依次填入语段中括号内，字音和字形全都正确的一项是（）A．荧yín 嘻矫jiǎo 震B．萤yíng 嬉娇jiāo 振C．萤yín 嘻娇jiāo 震 D．荧yíng 嬉矫jiǎo 振2．语段中（甲）（乙）两处应该填写的词语正确的一项是（）A．（甲）偶然（乙）品味B．（甲）偶然（乙）品位C．（甲）偶尔（乙）品味D．（甲）偶尔（乙）品位3．依次填入语段横线处的语句，衔接最恰当的一项是（）①温暖的重量②血肉的重量③古朴的重量④动人的重量A．①④③②B．①②④③C．④①③②D．④①②③4．下列句子中谦敬辞使用恰当的一项是（）A．令嫒这次能在儿童画展上获奖，多亏您悉心指导，我们全家万分感谢。

2015年江苏省高考数学预测试卷（5）一、填空题：本大题共14小题，每小题5分，计70分.不需写出解答过程,请把答案写在答题纸的指定位置上.1．已知集合A={x|x2－2x≤3}，{|21,}B x x n n Z==+∈，则集合A B=2．函数xy5.0log=的定义域为___________3.若复数2z i i=+（i是虚数单位），则||z=4．sin43°sin13°–cos43°cos167°的值为5．如图，程序执行后输出的结果为_________6.将一颗质地均匀的正方体骰子先后抛掷两次，记第一次出现的点数为x，第二次出现的点数为y，则事件“3≤+yx”的概率为 ____7. 某学校对1000名学生的英语水平测试成绩进行统计，得到样本频率分布直方图如右图所示，现规定不低于70分为合格，则合格人数是8．曲线siny x=在点（3π）处的切线方程为；9．已知一圆锥的侧面展开图为半圆，且面积为S，则圆锥的底面面积是__________．10．设函数()f x的定义域为R，且对任意两不等实数x、y，都有)()()(yfxfyxf=+及0)()(>--yxyfxf，请写出一个满足条件的函数。

11．已知圆222:ryxC=+，直线2:rbyaxl=+，若点),(baP在圆外，则直线l与圆C的位置关系是12．在ABC ∆所在的平面有一点P ，满足=++,则PBC ∆与ABC ∆的面积之比是 13．已知x x x f co ss i n )(1+=，记),()('12x f x f =),()('23x f x f =，)2,(),()(*'1≥∈=-n N n x f x f n n ，则=+++)2()2()2(200921πππf f f14．若数列{}{},n n a b 的通项公式分别是2008(1)n n a a +=-⋅，2009(1)2,n n n n b a b n+-=+<且对任意n N *∈恒成立，则常数a 的取值范围是二、解答题：本大题共6小题，计90分.解答应写出必要的文字说明,证明过程或演算步骤,请把答案写在答题纸的指定区域内.15．（本题满分14分）在ABC ∆中，三边a 、b 、c 对角分别为A 、B 、C ，且0c o s c o s c o s 3=--B c C b B a（1）求角B 的余弦值；（2）若2BA BC ⋅=，且22=b ，求a 和c 的值.16．（本题满分14分）如图，四棱锥S ABCD -中，AD ⊥侧面SCD ，DC SD =，点O 是平行四边形ABCD 对角线的交点，G F E ,,分别是SC SB SA ,,的中点. （1）试判断四点F G D A ,,,是否共面？并加以证明； （2）求证：OE // 平面SCD ； （3）求证：OE ⊥平面ADF .17．（本题满分14分）设椭圆2222:1(0)x y C a b a b+=>>的上顶点为A ，椭圆C 上两点,P Q 在x 轴上的射影分别为左焦点1F 和右焦点2F ，直线PQ 的斜率为32，过点A 且与1AF 垂直的直线与x 轴交于点B ，1AF B ∆的外接圆为圆M ． (1)求椭圆的离心率； (2)直线213404x y a ++=与圆M 相交于,E F 两点，且212ME MF a ⋅=-，求椭圆方程；18．（本题满分16分）某著名景区新近开发一种旅游纪念品，每件产品的成本为30元，并且每卖出一件产品需向地方税务部门上交a 元（a 为常数，2≤a ≤5 ）的税收。

泄露天机——2015年金太阳高考押题精粹英语本卷共18题，三种题型：阅读理解、英语知识运用和写作。

阅读理解10小题，英语知识运用4小题，写作4小题。

第一部分阅读理解 (10小题)第一节阅读下列短文，从每题所给的四个选项（A、B、C和D）中，选出最佳选项，并在题卡上将该项涂黑。

A1A report from the American Academy of Arts and Sciences' Commission reveals that, due to a job market which disproportionately rewards graduates in STEM (science, technology, engineering, and mathematics) fields, more and more students are seeking degrees in business and hard-science subjects.Some institutions have responded by cutting budgets in the arts and humanities and directing those funds elsewhere. That's the wrong thing to do. The humanities study of languages, literature, history, philosophy, religion, ethics, etc.-and the arts are vital to our future. We should be investing more funds, more time and more expertise, not less, into these endeavors.What detractors（诋毁者）of the "soft" subjects miss is that the arts and humanities provide an essential framework and context for understanding the wider world. Studying the humanities strengthens the ability to communicate and work with others. It allows students to develop broad intellectual and cultural understanding; it nurtures creativity and deepens participation in public discourse and modem democracy.The commission's report points out that "at the very moment when China is seeking to adopt our model of broad education in the humanities, social sciences and natural sciences as a stimulus to invention, the United States is instead narrowing our focus and abandoning our sense of what education has been and should continue to be our sense of what makes America great."These are the telling statistics: First, federal funding for helping American students include international training in their education has been cut 41 percent in four years. Second, the National Assessment of Educational Progress test shows that only less than a quarter of eighth- and 12th-grade US students are proficient in reading, writing and civics.How can we possibly equip the US for its leadership role in an increasingly connected world if we are not adequately teaching students to communicate and helping them understand and encounter diverse perspectives? If we fail to invest in the arts and humanities, our country's future leaders will not have the ability to connect on an emotional level with others. This ability is developed by studying the humanities, and in the global community this skill is not optional - it's essential.In a word, we must enthusiastically support and fund the study of the arts and humanities. For anyone concerned with how this translates into a sound economy and a sound financial future, simply recall what Steve Jobs told graduates of Stanford University in 2005: One of the most influential experiences inhis brief time at Reed College was his exposure to the fine art of calligraphy（书法）．It taught him the important lesson of the relationship between discipline and creativity.1. What can be inferred from the passage?A. Business and hard-science subjects are based upon the arts and humanities.B. At present too much emphasis and investment are put on science in America.C. More students will learn the arts and humanities instead of science in the USA.D. China has spent more money in the humanities and social sciences than the USA.2. The author mentions Steve Jobs in the last paragraph to prove that _____.A. science has a close relationship with the arts and humanitiesB. investment in the arts and humanities promotes economic developmentC. calligraphy plays a determining role in Steve Jobs' accomplishmentD. Reed College supports and funds the study of the arts and humanities3. Which of the following is the most suitable title for this passage?A. Significance of arts and humanitiesB. Key qualities of future leadersC. Decline of arts and humanitiesD. Rise and fall of hard sciencesA2Fuel Cell Technology for CarsFill her up with hydrogen? That's what someCalifornia motorists may be saying soon, as car makers tryto speed up production of zero emission（零排放）cars tomeet state requirements in the near future.Beneath the skin of this ordinary looking HondasFCX Concept Vehicle sits an electro-chemical reactor: ahand built, astronomically expensive power plant knownas a fuel cell. It's expected to be running ordinary family cars on California's roads within three years.So what exactly is a fuel cell, anyway? Why are governments, private businesses and academic institutions cooperating to develop and produce them? A fuel cell, very simply described, is a power generator, making electricity through the combination of hydrogen and oxygen. Fuel cells generate electrical power quietly and efficiently, without pollution, unlike power sources that use fossil fuels, the only by-products from an operating fuel cell are heat and water. To be more technical about it, a hydrogen atom with its one electron, attempts to pass through a fuel cell membrane（膜）to unite with an oxygen atom. The membrane allows only the hydrogen proton（质子）to pass through, forcing its electron to run around the membrane to catch up with the proton on the other side. This creates electricity, water, and heat, but no exhaust emissions.If the fuel cell is powered with pure hydrogen, it has the potential to be up to 80-percent efficient, That is, it turns 80 percent of the energy content of the hydrogen into electrical energy. However, we still need to turn the electrical energy into mechanical work. This is accomplished by the electric motor. A reasonable number for the efficiency of the motor is about 80 percent. So we have 80-percent efficiency in generating electricity, and 80-percent efficiency turning it into mechanical power. That gives an overall efficiency ofabout64 percent. Honda's FCX concept vehicle reportedly has 60-percent energy efficiency, which is twice or even three times more efficient than usual cars.But in spite of all the advantages described above, experts say, "We still have technical challenges getting this extremely complex system to work properly, the way customers expect it to work. There are challenges in using new fuels, and providing the new fuel basic facilities. And before fuel cell vehicles hit the road, there will have to be a network of hydrogen stations that will allow drivers to fill up with the flammable gas, under 36-hundred pounds of pressure."4. What can be inferred from California's "zero emissions policy"?A. New cars with fuel cell technology will surely become much cheaper.B. By carrying out the policy, traffic will not be so busy as it is now.C. The quality of life in California will improve once this policy is in effect.D. With facilities of new kinds, more local employment will be created.5. What does the phrase "power plant" refer to?A. A power device generating electricity.B. A power station providing electricity.C. A power component consuming electricity.D. A power engine using electricity.6. One of the reasons why fuel cell powered vehicles are superior is that . .A. they give out almost no water or heatB. they run faster and more smoothlyC. they give out almost no noiseD. they turn 64% of the energy into electricity7. What does the author want to tell us in the last paragraph?A. Customers will not think it a good idea to develop fuel cell technology.B. It is still not very easy to speed up production of zero emission cars.C. We can't ignore the financial problems to build a network of hydrogen stations.D. We still have much difficulty turning all the chains of the business into reality.A3When DeKalb Walcott III was just 8 years old, his father, a Chicago fire chief, let him tag along on a call. DeKalb says a lot of kids idolized basketball player Michael Jordan when he was growing up in Chicago in the 1990s. Not him."I wanted to be like DeKalb Walcott Jr.," he says of his father.So when his dad asked if he wanted to go on that call with him when he was 8, DeKalb was excited. "I'm jumping up and down, saying, "Mom, can I go? Can I go?' "The experience changed DeKalb’s life, he tells his dad on a visit to Story Corps. "My eyes got big from the moment the alarm went o ff." the younger DeKalb says. “This is the life that I want to live someday.”Now 27, the younger DeKalb is living that life. He became a firefighter at 21 and went to work alongside his dad at the Chicago Fire Department. Before his father retired, the pair even went out on a call together — father supervising（监督）son."You know, it's everything for me to watch you grow," his father says. But he also recalls worrying about one particular fire that his son faced."I received a phone call that night. And they said, 'Well, your son was at this fire.' I said, 'OK, which way is this conversation going to go?' “DeKalb Walcott Jr. recalls."And they said, 'but he's OK. And he put it out all by himself. Everybody here was proud of him.'"And the word went around, 'Who was out there managing that fire? Oh, that's Walcott! That's Walcottup there!' So, you know, moments like that, it's heaven on Earth for a dad."DeKalb Walcott Jr. retired in 2009. The younger DeKalb says he's proud of being a second-generation firefighter. "You know, it makes me look forward to fatherhood as well, because I'm definitely looking forward to passing that torch down to my son."8. The underlined phrase tag along in Paragraph 1 is closest in meaning to ______.A. put out fireB. watch basketballC. follow his fatherD. ask his mother’s permission9. DeKalb Walcott III determined to become a firefighter at the age of _________.A. 8B. 21C. 27D. 3510. What did DeKalb Walcott Jr want to do before he was told that the fire was put out?A. Go on with the conversationB. Put it out all by himselfC. Supervise his sonD. Go to the fire scene11. What can we learn from the last paragraph?A. DeKalb Walcott Jr is proud to be a second-generation firefighter.B. DeKalb Walcott III wants his son to become a firefighter too.C. DeKalb Walcott Jr wants to pass the torch to DeKalb Walcott III.D. DeKalb Walcott III is proud that his son has become an excellent firefighter.A4Engineers should embrace（接受）the arts, Sir John O'Reilly, a fellow of the Institution of Engineering and Technology, argued in a lecture.About 59% of engineering companies in the IET's 2014 survey feared skill shortages could threaten（威胁）business."There is nothing as creative as engineering," Sir John told the reporter. He says science, technology, engineering and mathematics - often known as "Stem" subjects, are vital for a modern knowledge economy. But there is a massive shortfall in the number of recruits（招聘）- with a recent study by the Royal Academy of Engineering saying the UK needs to increase by as much as 50% the number of Stem graduates it produces.Delivering this year's Mountbatten Lecture at the Royal Institution, Sir John argued that engineers should recognise the role of the arts in their work - among other benefits; this could attract more people into the profession. The lecture, Full Steam Ahead for Growth, advocated a wider adoption -- Steam, or science, technology, engineering, arts and maths. Engineers should embrace the arts as being key to creativity and an important component of innovation（创新）, crucial to creating new products and boosting future competitiveness, he argued. "Engineering and technology is an increasingly diverse and creative field," said Sir John.Some university engineering departments already cooperated with art schools to develop understanding, he told the reporter. In particular he mentioned Cranfield University's Centre for Creative CompetitiveDesign and Imperial College's work with the Royal College of Art. The two sets of people could work well together and more emphasis on the creative side of engineering could improve the success of products, he said."Aesthetics(美学) is part of it," he told the reporter, adding that Apple's iPod was not the first digital media player, nor the only one that worked - but it came to dominate the market "because it was nice to have".Sir John said he was not suggesting universities started requiring A-level art from engineering applicants - the key subjects for admission would continue to be maths and the sciences. But an emphasis on creative skills would help "broaden the pool and attract more people in".12. According to the lecture Full Steam Ahead for Growth, _______.A. engineers should cooperate with arts majorsB. Accepting the arts could attract more people into engineeringC. engineers should realize arts play the most important part in their workD. engineering and technology is as diverse and creative as before13. By giving the example of Apple's iPod, Sir John intends to _______.A. stress the importance of artsB. stress the importance of marketingC. stress the importance of communicationD. stress the importance of science and technology14. Which of the following is true according to the passage?A. More university students should study arts instead of engineering.B. Engineering and technology is increasingly different and unrelated fields.C. The IET's skills survey raised concerns about the number of recruits to engineering.D. Students from some university engineering departments have already transferred to art schools15. What is the passage mainly about?A. Lack of creativity makes it difficult for the engineering major to find a satisfactory job.B. The key subjects for engineering majors remain to be maths and the sciences rather than arts.C. University engineering departments should cooperate with art schools to improve the success of products.D. Engineering needs to emphasize its creative side to encourage more young people to choose it as a career.B1Exercise seems to be good for the human brain, with many recent studies suggesting that regular exercise improves memory and thinking skills. But an interesting new study asks whether the apparent cognitive benefits from exercise are real or just a placebo effect — th at is, if we think we will be “smarter” after exercise, do our brains respond accordingly? The answer has significant implications for any of us hoping to use exercise to keep our minds sharp throughout our lives.While many studies suggest that exercise may have cognitive benefits, recently some scientists have begun to question whether the apparently beneficial effects of exercise on thinking might be a placebo effect. So researchers at Florida State University in Tallahassee and the University of Illinois at Urbana-Champaigndecided to focus on expectations, on what people anticipate that exercise will do for thinking. If people’s expectations jibe (吻合) closely with the actual benefits, then at least some of those improvements are probably a result of the placebo effect and not of exercise.For the new study, which was published last month in PLOS One, the researchers recruited 171 people through an online survey system, they asked half of these volunteers to estimate by how much a stretching and toning regimens (拉伸运动) performed three times a week might improve various measures of thinking. The other volunteers were asked the same questions, but about a regular walking program.In actual experiments, stretching and toning program generally have little if an y impact on people’s cognitive skills. Walking, on the other hand, seems to substantially improve thinking ability.But the survey respondents believed the opposite, estimating that the stretching and toning program would be more beneficial for the mind than walking. The estimates of benefits from walking were lower.These data, while they do not involve any actual exercise, are good news for people who do exercise. “The results from our study suggest that the benefits of aerobic exercise are not a placebo effect,” said Cary Stothart, a graduate student in cognitive psychology at Florida State University, who led the study.If expectations had been driving the improvements in cognition seen in studies after exercise, Mr. Stothart said, then people should have expected walking to be more beneficial for thinking than stretching. They didn’t, implying that the changes in the brain and thinking after exercise are physiologically genuine.The findings are strong enough to suggest that exercise really does change the brain and may, in the process, improve thinking, Mr. Stothart said. That conclusion should encourage scientists to look even more closely into how, at a molecular level, exercise remodels the human brain, he said. It also should encourage the rest of us to move, since the benefits are, it seems, not imaginary, even if they are in our head.1. Why did the researchers at the two universities conduct the research?A. To discover the placebo effect in the exercise.B. To prove the previous studies have a big drawback.C. To test whether exercise can really improve cognition.D. To encourage more scientists to get involved in the research.2. What can we know about the research Cary Stothart and his team carried out?A. They employed 171 people to take part in the actual exercise.B. The result of the research removed the recent doubt of some scientists.C. The participants thought walking had a greater impact on thinking ability.D. Their conclusion drives scientists to do research on the placebo effect.3. What might be the best title for the passage?A. Is it necessary for us to take exercise?B. How should people exercise properly?C. What makes us smarter during exercise?D. Does exercise really make us smarter?B2The current Ebola (埃博拉病毒) outbreak in western and central Africa has infected at least 3,069 people, including 1,552 dead, making it the largest outbreak in history. Ebola is a deadly virus —about 60 percent of people infected with it have died.How is Ebola doing its harm?When a person becomes infected with Ebola, the virus damages the body’s immune (免疫的) cells,which defend against infection, said a researcher at Lancaster University. But if a person’s immune system can stand up to this attack, then he is more likely to survive the disease.The patients that survive it best are those who don’t get such a bad disadvantage in immune system. But if the body isn’t able to get rid of this attack, then the immune system becomes less able to regulate (调节) itself. This means the immune system is more likely to run out of control, leading to a drop in blood pressure, multi-organ failure and eventually death.What are the common symptoms of the disease?Fever. Headache. Joint and muscle aches. Weakness. Diarrhea. V omiting. Stomach pain. Lack of appetite. Chills. Rash. Redness in the eyes. Hiccups. Cough. Sore throat. Chest pain. Difficult breathing or swallowing. Bleeding inside and outside of the body.How to prevent the spread of Ebola?Ebola can be spread primarily via direct contact with patients, specifically the blood and fluids of an infected patient.We should avoid contact with infected patients and objects such as clothing, bedding, and needles used by them. Avoid areas where infections have been reported. For now, the disease has only been confirmed in central and West Africa, four cases in America and Europe. Avoid eating wild-caught bush meat. Researchers have suspected that the disease came to humans via animals, probably through the meat of primates(灵长类). If you’re in an area where the disease has been reported, avoid purchasing, eating, or handling wild game to stay on the safe side.Wear protective medical clothing if you’re around infected patients. Extreme caution is necessary. Hospital workers must use masks, gloves, goggles, and gowns, which needed to be worn at all times if you’re around infected patients.How Do People Survive Ebola?Doctors don’t know for certain who will survive Ebola, and there is no specific treatment or cure for the disease. Although in the minority, some people do recover from infection.Our suggestions include:Maintain your electrolytes (电解质) and body liquid. Sports drinks can be used. Monitor your blood pressure and control it if necessary. Dropping blood pressure may be a serious sign of infection. Breathe in an oxygen-rich environment. Quickly address any symptoms of infection. Be honest about when and where you’re feeling pain.4. Ebola causes the death of a human being by ________.A. attacking him with high feverB. regulating his immune systemC. damaging his immune cellsD. harming all his organs directly5. What is NOT mentioned as the symptom of Ebola?A. Fever and chills.B. Swallowing difficulty.C. Loss of blood.D. High blood pressure.6. In order not to be infected by Ebola, we should _________.A. have the clothing of the infected cleanedB. avoid eating wild animals like monkeysC. not travel to Africa, America or EuropeD. stay at home without going anywhere7. It is true that ________.A. a certain number of people survive EbolaB. human has found a special cure for EbolaC. oxygen can save infected people’s livesD. low blood pressure is surely caused by EbolaB3The term “Industry 4.0” refers to the fourth industrial revolution. The first indust rial revolution was the production of goods with machines like steam engines, which was followed by the second industrial revolution that introduced mass production with the help of electric power, followed by the digital revolution —the use of electronics and IT in production.Industry 4.0 is a high-tech project, which promotes the computerization of manufacturing (制造业). The basic principle of Industry 4.0 is that by connecting machines, work pieces and systems, we are creating intelligent networks along the entire value chain that can control each other automatically. The goal is the Smart Factory, which adapts well and uses resources efficiently as well as linking customers and business partners with great intelligence. Technological basis are the Internet systems and advanced factories. Experts believe that Industry 4.0 could be a reality in about 10 to 20 years.So, what effects does this change have on the classic manufacturing? According to an expert, “it is highly likely that the world of production will become more and more networked until everything is connected with everything else.” Networks and processes have so far been limited to one factory. But in the time of Industry 4.0, the boundaries (界限) of individual factories will most likely no longer exist. Instead, they will be lifted in order to inter-connect multiple factories or even geographical regions.How is an Industry 4.0 factory different from a today’s factory? In current industry environment, providing high-end quality service or product with the least cost is the key to success. Factories are trying to increase their profit as much as possible. In the time of Industry 4.0, various data sources are available to provide worthwhile information about different aspects of the factory. Using data for understanding the current condition and checking faults and failures is a natural thing. The sharing of information around the clock and around the globe will enable these connected systems to manage themselves independently, work more efficiently and identify any errors quickly.The good news is that Europe is much better prepared for the Industry 4.0 revolution than one might think. Europe will position itself as a pioneer in the fourth revolution. Industry 4.0 is a project in the high-tech strategy of the German government. Meanwhile, in the U.S., some companies are also working hard on it. But the success of industry depends on whether business and politics can work together. It’s not only politics that needs to help open the door for Industry 4.0. Every company is advised to seize the new digital opportunities.8. What marks the coming of Industry 4.0?A. Steam engines.B. Mass production.C. Use of electronics.D. Intelligent networks.9. Industry 4.0 will probably result in ________ in the world of manufacturing.A. production limited to an individual factoryB. everything connected with everything elseC. networks and processes no longer existingD. classic factories stopping their competition10What’s the meaning of the underlin ed part in Para. 4?A. Sharing information of the world time.B. Global news broadcast at any time.C. Instant worldwide information exchange.D. Spreading news widely on the hour.11. According to the last paragraph, who is the most active in pushing Industry 4.0?A. The European companies.B. The American government.C. The American companies.D. The German government.B4“One City One Book” is a generic name (通称) for a community reading program that attempts to get everyone in a city to read and discuss the same book. Popular book picks have been Harper Lee’s To Kill a Mockingbird，Ernest Gaines’s A Lesson Before Dying，and Ray Bradbury’s Fahrenheit 451.“One City One Book” programs take the idea of a localized book discussion club and expand it to cover a whole city. The first such program was “If All of Seattle Read the Same Book” in 1998，started by Nancy Pearl at Seattle Public Library’s Washington Center for the Book. The book chosen for the program was The Sweet Hereafter by Russell Banks，written in 1991.Other cities copied the idea，and the Library of Congress listed 404 programs occurring in 2007.Each city’s program has its own goals；These typically include building a sense of community and promoting literacy. Nancy Pearl warns against expecting too much from a program：“Keep in mind that this is a library program，it’s not an exercise in civics，and that it’s not intended to have literature cure the racial divide. This is about a work of literature.”Programs typically involve more than having everyone read the same book. Some other activities that have been included are：book discussion sessions，scholarly lectures on the book or related topics，a visit by the author，exhibits，related arts programming (especially showing a movie of the book if there is one)，and integration into school curricula. In Boston the “One City One Story” program used shorter stories and distributed tens of thousands of free copies of the story over the course of a month.American Library Association puts out a detailed step-by-step guide on how to organize a local program，including the critical step of picking the one book. The Center for the Book at the Library of Congress tracks all known programs and the books they have used.12．“One City One Book” p rograms________.A．ask everyone in a city to donate one bookB．can rid a city of racial divide through readingC．choose short stories for people to readD．encourage everyone in a city to read and discuss the same book13．We know from the second p aragraph that “One City One Book” programs________.A．became popular very quicklyB．have been held more than 400 times in SeattleC．were sponsored by the Library of CongressD．reached its peak in 200714．We can infer from the third paragraph that Nancy Pearl________.A．expects much from the programsB．doesn’t expect that the programs would run so wellC．has a practical attitude towards the programsD．believes the programs will push forward community building15．What kind of role does American Library Association play in the programs?A．It picks out the city which runs the programs well.B．It gives free books to the host city.C．It gives a practical guide to the programs.D．It keeps a record of all known programs.第二节根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。

2015年普通高等学校招生全国统一考试预测卷（广东卷）理科综合一、单项选择题：本大题共4小题，每小题4分，共16分。

在每小题给出的四个选项中，只有一个选项符合题目要求，选对的得4分，选错或不答的得0分。

13、如图1所示为甲、乙两个物体运动的v -t 图像，若两个物体在同一地出发，且两物体最终运动的位移相等，甲的初速度是乙的初速度的2倍，则下列说法正确的是（）图1A 、甲、乙都沿负方向运动B 、甲、乙在运动过程中一定会相遇C 、甲、乙在t 0时刻相距最远D 、乙运动的时间一定是甲运动的时间的3倍14、如图2所示，质量为m 的硬质面字典A 对称跨放在硬质面的书本B 上。

将书本B 的一端缓慢抬高至字典刚要滑动，此时书脊与水平面的夹角为θ。

下列说法中正确的是（）图2A 、B 对A 的作用力为零B 、B 的一个侧面对A 的弹力为mgcosθC 、B 对A 的最大静摩擦力的合力为mgsinθD 、A 受到三个力的作用15、如图3所示，通过水平绝缘传送带输送完全相同的铜线圈，线圈等距离排列，且与传送带以相同的速度匀速运动．为了检测出个别未闭合的不合格线圈，让传送带通过一固定匀强磁场区域，磁场方向垂直于传送带运动方向，根据穿过磁场后线圈间的距离，就能够检测出不合格线圈．通过观察图形，判断下列说法正确的是（）图3A 、若线圈闭合，进入磁场时，线圈中感应电流方向从上向下看为逆时针B 、若线圈闭合，传送带以较大速度匀速运动时，磁场对线圈的作用力增大t00C、从图中可以看出，第2个线圈是不合格线圈D、从图中可以看出，第3个线圈是不合格线圈16、如图4所示，将一轻弹簧下端固定在倾角为θ的粗糙斜面底端，弹簧处于自然状态时上端位于A点，质量为，舱的物体从斜面上的B点由静止下滑，与弹簧发生相互作用后，最终停在斜面上，下列说法正确的是（）图4A、物体最终将停在A点B、物体第一次反弹后不可能到达B点C、整个过程中重力势能的减少量大于克服摩擦力做的功D、整个过程中物体的最大动能大于弹簧的最大弹性势能二、双项选择题：本大题共5小题，每小题6分，共30分。

2015年普通高等学校招生全国统一考试数学理科预测试题（北京卷）（满分150分，考试时间120分）第Ⅰ卷（选择题 40分）一、选择题(本大题共8小题，每小题5分，共40分，在每小题给出的四个选项中，只有一项是符合题目要求的)1、设集合A ＝{(x ，y )|x ＋y ＝1}，B ＝{(x ，y )|x －2y ＝3}，则满足M ⊆(A ∩B )的集合M 的个数是( )A ．0B ．1C ．2D ．32、下列函数中，既是偶函数又在(－∞，0)上单调递增的是( )A ．y ＝x 2B ．y ＝2|x |C ．y ＝log 21|x |D ．y ＝sin x3、曲线25()12x tt y t =-+⎧⎨=-⎩为参数与坐标轴的交点是（ ）A ．21(0,)(,0)52、B ．11(0,)(,0)52、C ．(0,4)(8,0)-、D ．5(0,)(8,0)9、 4、程序框图如下图所示，当0.96A =时，输出的k 的值为（ ）A ．20B ．22C ．24D ．255、设集合M ＝{x |0<x ≤3}，N ＝{x |0<x ≤2}，那么“a ∈M ”是“a ∈N ”的( ) A ．充分不必要条件 B ．必要不充分条件 C ．充要条件D ．既不充分也不必要条件6、设实数x ，y 满足不等式组⎩⎪⎨⎪⎧x ＋y ≤2y －x ≤2，y ≥1，则x 2＋y 2的取值范围是( )A ．[1,2]B ．[1,4]C ．[2，2]D ．[2,4]否1(1)S S k k =++S A≥开始1,0k S ==k输出结束1k k =+是7、一个几何体的三视图如图所示，其中俯视图是菱形，则该几何体的侧面积为( )A.3＋ 6B.3＋ 5C.2＋ 6D.2＋ 58、定义区间(a ，b )，[a ，b )，(a ，b ]，[a ，b ]的长度均为d ＝b －a ，多个区间并集的长度为各区间长度之和，例如，(1,2)∪[3,5)的长度d ＝(2－1)＋(5－3)＝3.用[x ]表示不超过x 的最大整数，记{x }＝x －[x ]，其中x ∈R .设f (x )＝[x ]·{x }，g (x )＝x －1，当0≤x ≤k 时，不等式f (x )＜g (x )的解集区间的长度为5，则k ＝( )A ．6B ．7C ．8D ．9 第Ⅱ卷二、填空题：（本大题共6小题，每小题5分，共30分．把答案填在答题纸上.） 9、已知11xyi i=-+，其中,x y 是实数，i 是虚数单位，则x yi +的共轭复数为10、已知点M (5，－6)和向量a ＝(1，－2)，若MN ＝－3a ，则点N 的坐标为________________．11、直线x －2y ＋2＝0过椭圆x 2a 2＋y 2b2＝1的左焦点F 1和一个顶点B ，则椭圆的方程为________________．12、在等差数列{a n }中，a 1＝7，公差为d ，前 n 项和为S n ，当且仅当n ＝8 时S n 取得最大值，则d 的取值范围为________．13、从6名志愿者中选出4人分别从事翻译、导游、导购、保洁四项不同的工作，若其中甲、乙两名志愿者不能从事翻译工作，则选派方案共有________________．14、已知函数f (x )＝3sin ⎝⎛⎭⎪⎫ωx －π6(ω＞0)和g (x )＝3cos(2x ＋φ)的图象完全相同，若x ∈⎣⎢⎡⎦⎥⎤0，π2，则f (x )的值域是________．三、解答题（本大题共6小题，共80分，解答应写出文字说明，证明过程或演算步骤．）15.（本小题满分13分）已知向量)4cos ,4(cos ),1,4sin 3(2x x n x m ==．记n m x f ⋅=)((I)求)(x f 的周期；(Ⅱ)在∆ABC 中，角A 、B 、C 的对边分别是a 、b 、c ，且满足(2a —c)cos B=b cos C ， 若132f (A )+=，试判断∆ABC 的形状． 16、（本小题满分13分）某学校的三个学生社团的人数分布如下表(每名学生只能参加一个社团)：围棋社 舞蹈社 拳击社 男生 5 10 28女生1530m学校要对这三个社团的活动效果进行抽样调查，按分层抽样的方法从三个社团成员中抽取18人，结果拳击社被抽出了6人．(1)求拳击社团被抽出的6人中有5人是男生的概率； (2)设拳击社团有X 名女生被抽出，求X 的分布列．17、（本小题满分13分）如图，在四棱锥P ­ABCD 中，底面ABCD 是边长为2的正方形，侧面PAD ⊥底面ABCD ，且PA ＝PD ＝22AD ，E ，F 分别为PC ，BC 的中点．(1)求证：EF ∥平面PAD ； (2)求证：平面PAB ⊥平面PDC ；(3)在线段AB 上是否存在点G ，使得二面角C ­PD ­G 的余弦值为13？说明理由．18、（本小题满分13分）已知函数f (x )＝ln x ，g (x )＝12ax ＋b .(1)若f (x )与g (x )在x ＝1处相切，求g (x )的表达式； (2)若φ(x )＝m x －1x ＋1－f (x )在[1，＋∞)上是减函数，求实数m 的取值范围．19、（本小题满分14分）(2015·衡水中学二调)已知椭圆C 的对称中心为原点O ，焦点在x 轴上，左、右焦点分别为F 1和F 2，且|F 1F 2|＝2，点⎝ ⎛⎭⎪⎫1，32在该椭圆上． (1)求椭圆C 的方程；(2)过F 1的直线l 与椭圆C 相交于A ，B 两点，若△AF 2B 的面积为1227，求以F 2为圆心且与直线l 相切的圆的方程．20、（本小题满分13分）设函数F (x )在区间D 上的导函数为F 1(x )，F 1(x )在区间D 上的导函数为F 2(x )，如果当x ∈D 时，F 2(x )≥0，则称F (x )在区间D 上是下凸函数．已知e 是自然对数的底数，f (x )＝e x－ax 3＋3x －6.(1)若f (x )在[0，＋∞)上是下凸函数，求a 的取值范围；(2)设M (x )＝f (x )＋f (－x )＋12，n 是正整数，求证：M (1)M (2)…M (n )＞en ＋1＋2n.理科答案选择题1.解析：选C 由题中集合可知，集合A 表示直线x ＋y ＝1上的点，集合B 表示直线x－2y ＝3上的点，联立⎩⎪⎨⎪⎧x ＋y ＝1，x －y ＝3可得A ∩B ＝{(2，－1)}，M 为A ∩B 的子集，可知M 可能为{(2，－1)}，∅，所以满足M ⊆(A ∩B )的集合M 的个数是2，故选C.2.解析：选C 函数y ＝x 2在(－∞，0)上是减函数；函数y ＝2|x |在(－∞，0)上是减函数；函数y ＝log 21|x |＝－log 2|x |是偶函数，且在(－∞，0)上是增函数；函数y ＝sin x 不是偶函数．综上所述，选C.3.解析：选B 当0x =时，25t =，而12y t =-，即15y =，得与y 轴的交点为1(0,)5； 当0y =时，12t =，而25x t =-+，即12x =，得与x 轴的交点为1(,0)2选B4.【答案解析】 C 解析 ：解：由程序框图可知当k=n 时：()11111223341S n n =++++⨯⨯⨯⨯+ =1111111(1)223341n n ⎛⎫⎛⎫⎛⎫-+-+-++- ⎪ ⎪ ⎪+⎝⎭⎝⎭⎝⎭=1111nn n -=++0.96≥，解得24n ≥，所以选C 5.解析：选B M ＝{x |0<x ≤3}，N ＝{x |0<x ≤2}，所以NM ，故a ∈M 是a ∈N 的必要不充分条件．6.解析：选B 如图所示，不等式组表示的平面区域是△ABC 的内部(含边界)，x 2＋y 2表示的是此区域内的点(x ，y )到原点距离的平方．从图中可知最短距离为原点到直线BC 的距离，其值为1；最远的距离为AO ，其值为2，故x 2＋y 2的取值范围是[1,4]．7.解析：选C 由三视图还原为空间几何体，如图所示，则有OA ＝OB ＝1，AB ＝ 2.又PB ⊥平面ABCD ， ∴PB ⊥BD ，PB ⊥AB ，∴PD ＝22＋1＝5，PA ＝2＋12＝3，从而有PA 2＋DA 2＝PD 2，∴PA ⊥DA ，∴该几何体的侧面积S ＝2×12×2×1＋2×12×2×3＝2＋ 6.8.选B f (x )＝[x ]·{x }＝[x ]·(x －[x ])＝[x ]x －[x ]2，由f (x )＜g (x )，得[x ]x －[x ]2＜x －1，即()[x ]－1x ＜[x ]2－1.当x ∈(0,1)时，[x ]＝0，不等式的解为x ＞1，不符合题意；当x ∈[1,2)时，[x ]＝1，不等式可化为0＜0，无解，不符合题意；当x ∈[2，＋∞)时，[x ]＞1，不等式([x ]－1)x ＜[x ]2－1等价于x ＜[x ]＋1，此时不等式恒成立，所以不等式的解集为[2，k ]，因为不等式f (x )＜g (x )的解集区间的长度为5，所以k －2＝5，即k ＝7，故选B. 填空题 9. 2i -1()1,2,1,12x x xi yi x y i =-=-∴==+故2i -．10.解析：(2,0) MN ＝－3a ＝－3(1，－2)＝(－3,6)，设N (x ，y )，则MN ＝(x －5，y ＋6)＝(－3,6)，所以⎩⎪⎨⎪⎧x －5＝－3，y ＋6＝6，即⎩⎪⎨⎪⎧x ＝2，y ＝0，(2,0)11.解析：直线x －2y ＋2＝0与x 轴的交点为(－2,0)，即为椭圆的左焦点，故c ＝2. 直线x －2y ＋2＝0与y 轴的交点为(0,1)，即为椭圆的顶点，故b ＝1. 故a 2＝b 2＋c 2＝5，椭圆方程为x 25＋y 2＝1.答案：x 25＋y 2＝112.解析：由题意，当且仅当n ＝8时S n 有最大值，可得⎩⎪⎨⎪⎧d <0，a 8>0，a 9<0，即⎩⎪⎨⎪⎧d <0，7＋7d >0，7＋8d <0，解得－1<d <－78.答案：⎝⎛⎭⎪⎫－1，－78 13.解析：选B 根据题意，由排列可得，从6名志愿者中选出4人分别从事四项不同工作，有A 46＝360种不同的情况，其中包含甲从事翻译工作，有A 35＝60种，乙从事翻译工作，有A 35＝60种，若其中甲、乙两名志愿者都不能从事翻译工作，则选派方案共有360－60－60＝240种．14.解析：f (x )＝3sin ⎝ ⎛⎭⎪⎫ωx －π6＝3cos ⎣⎢⎡⎦⎥⎤π2－⎝⎛⎭⎪⎫ωx －π6＝3cos ⎝ ⎛⎭⎪⎫ωx －2π3，易知ω＝2，则f (x )＝3sin ⎝⎛⎭⎪⎫2x －π6， ∵x ∈⎣⎢⎡⎦⎥⎤0，π2，∴－π6≤2x －π6≤5π6， ∴－32≤f (x )≤3.答案：⎣⎢⎡⎦⎥⎤－32，3 15.解2311()3sin cos cos sin cos 44422222x x x x x f x =+=++1sin 262x π⎛⎫=++⎪⎝⎭（I ）π4=T（Ⅱ 根据正弦定理知：()2cos cos (2sin sin )cos sin cos a c B b C A C B B C -=⇒-=12sin cos sin()sin cos 23A B B C A B B π⇒=+=⇒=⇒= ∵13()2f A += ∴ 113sin 2622263A A πππ+⎛⎫++=⇒+= ⎪⎝⎭或23π3A π⇒=或 π 而203A π<<，所以3A π=，因此∆ABC 为等边三角形.……………13分16.解：(1)由于按分层抽样的方法从三个社团成员中抽取18人，拳击社被抽出了6人， ∴628＋m ＝1820＋40＋28＋m， ∴m ＝2.设A 为“拳击社团被抽出的6人中有5人是男生”， 则P (A )＝C 528C 12C 630＝48145.(2)由题意可知：X ＝0,1,2，P (X ＝0)＝C 628C 630＝92145，P (X ＝1)＝C 528C 12C 630＝48145，P (X ＝2)＝C 428C 22C 630＝5145＝129，X 的分布列为X12P92145 48145 12917.解：(1)证明：如图，连接AC ，交BD 于点F ，底面ABCD 为正方形，F 为AC 中点，E 为PC 中点．所以在△CPA 中，EF ∥PA . 又PA ⊂平面PAD ，EF ⊄平面PAD ， 所以EF ∥平面PAD .(2)证明：因为平面PAD ⊥平面ABCD ，平面PAD ∩平面ABCD ＝AD . 底面ABCD 为正方形，CD ⊥AD ，CD ⊂平面ABCD ，所以CD ⊥平面PAD . 又PA ⊂平面PAD ，所以CD ⊥PA . 又PA ＝PD ＝22AD ，所以△PAD 是等腰直角三角形，且∠APD ＝π2，即PA ⊥PD . 又CD ∩PD ＝D ，且CD ，PD ⊂平面PDC ，所以PA ⊥平面PDC . 又PA ⊂平面PAB ，所以平面PAB ⊥平面PDC .(3)如图，取AD 的中点O ，连接OP ，OF ，因为PA ＝PD ，所以PO ⊥AD .又侧面PAD ⊥底面ABCD ，平面PAD ∩平面ABCD ＝AD ，所以PO ⊥平面ABCD ，而O ，F 分别为AD ，BD 的中点，所以OF ∥AB ， 又底面ABCD 是正方形，故OF ⊥AD ，以O 为原点，建立空间直角坐标系O ­xyz 如图所示，则有A (1，0,0)，C (－1,2,0)，F (0,1,0)，D (－1,0,0)，P (0,0,1)，若在AB 上存在点G ，使得二面角C ­PD ­G 的余弦值为13，连接PG ，DG ，设G (1，a,0)(0≤a ≤2)，则DP ＝(1,0,1)，GD ＝(－2，－a,0)，由(2)知平面PDC 的一个法向量为PA ＝(1,0，－1)，设平面PGD 的法向量为n ＝(x ，y ，z )．则⎩⎨⎧n ·DP ＝0，n ·GD ＝0，即⎩⎪⎨⎪⎧x ＋z ＝0，－2x －ay ＝0，解得⎩⎪⎨⎪⎧z ＝a2y ，x ＝－a2y .令y ＝－2，得n ＝(a ，－2，－a )，所以|cos 〈n ，PA 〉|＝|n ·PA ||n ||PA |＝2a 2×4＋2a 2＝13， 解得a ＝12⎝⎛⎭⎪⎫舍去－12.所以，在线段AB 上存在点G ⎝ ⎛⎭⎪⎫1，12，0⎝ ⎛⎭⎪⎫此时AG ＝14AB ，使得二面角C ­PD ­G 的余弦值为13.18.解：(1)由已知得f ′(x )＝1x ，∴f ′(1)＝1＝12a ，a ＝2.又∵g (1)＝0＝12a ＋b ，∴b ＝－1，∴g (x )＝x －1.(2)∵φ(x )＝m x －1x ＋1－f (x )＝m x －1x ＋1－ln x 在[1，＋∞)上是减函数．∴φ′(x )＝－x22m －2x －1xx ＋12≤0在[1，＋∞)上恒成立．即x 2－(2m －2)x ＋1≥0在[1，＋∞)上恒成立， 则2m －2≤x ＋1x，x ∈[1，＋∞)，∵x ＋1x∈[2，＋∞)，∴2m －2≤2，m ≤2.故数m 的取值范围是(－∞，2]． 19.解：(1)由题意知c ＝1,2a ＝⎝ ⎛⎭⎪⎫322＋ ⎝ ⎛⎭⎪⎫322＋22＝4， a ＝2，故椭圆C 的方程为x 24＋y 23＝1.(2)①当直线l ⊥x 轴时，可取A ⎝ ⎛⎭⎪⎫－1，－32，B ⎝ ⎛⎭⎪⎫－1，32，△AF 2B 的面积为3，不符合题意．②当直线l 与x 轴不垂直时，设直线l 的方程为y ＝k (x ＋1)，代入椭圆方程得(3＋4k 2)x 2＋8k 2x ＋4k 2－12＝0，显然Δ>0成立，设A (x 1，y 1)，B (x 2，y 2)， 则x 1＋x 2＝－8k 23＋4k 2，x 1x 2＝4k 2－123＋4k 2，可得|AB |＝1＋k 2·x 1＋x 22－4x 1x 2＝12k 2＋13＋4k2， 又圆F 2的半径r ＝2|k |1＋k2，∴△AF 2B 的面积为12|AB |·r ＝12|k |k 2＋13＋4k 2＝1227， 代简得：17k 4＋k 2－18＝0，得k ＝±1， ∴r ＝2，圆的方程为(x －1)2＋y 2＝2.20.解：(1)f ′(x )＝e x－3ax 2＋3，设F 1(x )＝f ′(x )，则F 1′(x )＝e x－6ax . ∵f (x )在[0，＋∞)上是下凸函数，∴当x ∈[0，＋∞)时，F 1′(x )＝e x－6ax ≥0.当x ＝0时，1≥0成立，即F 1′(x )＝e x－6ax ≥0成立，此时a ∈R . 当x ∈(0，＋∞)时，由F 1′(x )＝e x－6ax ≥0得，a ≤ex6x.设H (x )＝e x x ，则H ′(x )＝x e x －e x x2＝exx －1x 2. ∴当x ∈(1，＋∞)时，H ′(x )＞0，H (x )单调递增； 当x ∈(0,1)时，H ′(x )＜0，H (x )单调递减， ∴当x ＝1时，H (x )取得最小值H (1)＝e ， ∴a ≤e 6，∴a 的取值范围为⎝ ⎛⎭⎪⎫－∞，e 6. (2)证明：∵f (x )＝e x －ax 3＋3x －6， ∴M (x )＝f (x )＋f (－x )＋12＝e x＋e －x＞0.∵M (x 1)M (x 2)＝e x 1＋x 2＋e x 1－x 2＋e x 2－x 1＋e －x 1－x 2＞e x 1＋x 2＋e x 1－x 2＋e x 2－x 1， 又e x 1－x 2＋e x 2－x 1≥2e x 1－x 2e x 2－x 1＝2，∴M (x 1)M (x 2)＞e x 1＋x 2＋2， ∴M (1)M (n )＞en ＋1＋2，M (2)M (n －1)＞en ＋1＋2，M (3)M (n －2)＞e n ＋1＋2，…，M (n )M (1)＞e n ＋1＋2，∴[M (1)M (n )][M (2)M (n －1)]· …·[M (n )M (1)]＞(e n ＋1＋2)n，∴M (1)M (2)· …·M (n )＞en ＋1＋2n.。