广西玉林师院附中、玉林十一中、玉林市田家炳中学2019-2020学年高一上学期期中考试化学试题
- 格式:doc
- 大小:452.00 KB
- 文档页数:13
玉林市田家炳中学、玉林师院附中、玉林市育才中学、玉林市第十一中学、玉林市福绵高中2020年秋季期教学质量评价高一生物试卷玉林市田家炳中学高一生物基组命题、审题一、选择题1.答案:C2.答案:D3.答案:C4.答案:B5.答案:A6. 答案:C7.答案:D8、答案:C9.答案:D10.答案:D11. 答案:D12. 答案:A13.答案:B15. 答案:B16、答案:C17、答案:C18、答案:D19、答案C20、答案:C21、答案:D22、答案:B23、答案:B24.答案:D25、.答案:D二、填空题26.(11分,除标注外每空1分)(1)蛋白质(填多肽不给分)其结构通式是(2分)。
(2)5 脱水缩合 4 氨基和羧基(3)(蛋白质的)空间结构不同(2分)(4)ma–18×(m–n)(2分)27、(10分,每空2分)(1)差异性(2)C C、H、O、N 化合物(或有机物)(3)不是,人体内运输氧气的血红蛋白合成需要铁28、(9分,除标注外每空1分)(1)C、H、O 核糖、磷酸、含氮碱基(填其中具体的每一种含氮碱基也可以)(2分)(2)氨基酸(2分)保温缓冲和减压(3)淀粉(4)F(填脂肪也给分)29、(10分,除注明外,每空1分)(1)①⑥⑧(填不全不给分)无由核膜包被的细胞核(2)细胞膜脂质(磷脂)和蛋白质(填不全不给分)(3)差速离心同位素标记(或荧光标记法)(4)控制物质进出细胞(填“选择透过性”不给分)(2分)(5)④内质网⑦高尔基体30、(10分,每空2分)(1) 原生质层与细胞壁的分离 (2) ②④⑤(有错或填不全不给分)(3)外界溶液浓度高于细胞液浓度原生质层的伸缩性大于细胞壁的伸缩性(4) 细胞液的浓度大于外界溶液的浓度。
广西玉林师院附中、玉林十一中等五校2024-2025学年高一历史上学期期中试题本试卷分第I卷(选择题)和第II卷(非选择题)两部分,满分100分。
考试时间75分钟。
考生留意:1.答题前,考生务必将学号、班级、姓名填写在答题卡上。
考生仔细核对答题卡上的学号、姓名等信息。
2.第I卷每小题选出答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑。
第II卷请用黑色签字笔在答题卡,上各题的答题区域内作答,在试题卷上作答无效.........。
第I卷(选择题,共48分)一、选择题(本题共24小题,每小题2分,共48分。
在每小题给出的四个选项中,只有一项符合题目要求。
)1.中华民族素来特别重视族谱的纂修,目的是尊崇人伦,维系宗族。
这种传统源于商周时期的A.禅让制B.郡县制C.分封制D.宗法制2.公元前704年,第17代楚君熊通再一次向周天子恳求提高封号,遭拒后大怒说:“王不加位,我自尊耳。
”于是,他独立为楚武王,开诸侯僭号称王之先河。
这表明当时A.禅让制渐成风尚B.世袭制起先确立C.分封制遭到破坏D.宗法制消逝殆尽3.钱穆先生在《中国历史探讨法》中说:“至秦汉以来的郡县政治,到今日民国时代还存在,中国之永为一统一国,此项政治制度实贡献过其甚大之绩效。
”“甚大之绩效”是指郡县制A.导致官僚政治取代了贵族政治B.形成中心垂直管理地方的模式C.促进统一多民族国家巩固发展D.标记中心集权制度的最终形成4.“刺史六条”是汉代为规范刺史的监察职权设定的。
在针对郡国守相的五条规定中,把“不奉诏书遵承典制,倍公向私,旁诏守利”列于首位。
这反映了A.汉代重视加强中心集权B.刺史成为地方行政长官C.汉代官民关系严峻恶化D.汉代君主专制空前强化5.秦汉时期设立了朝议制度,凡遇军国大事,皇帝往往“下其议”于群臣,议定结果通常由宰相领衔上奏,最终必需经皇帝裁决方能施行。
这一制度A.反映了皇权与相权的冲突B.有利于皇帝决策集思广益C.表明军国大事最终由朝臣议定D.起到了限制和监督皇权的作用6.有学者评论说:“(它)克服了社会流淌的堵塞,让民间精英往体制内去流淌,给中国带来一种良性的社会治理。
某某某某师院附中、某某十一中等五校2020-2021学年高一物理上学期期中试题(含解析)一、选择题(每题4分,12小题,共48分・期中第L8題为单选,第9-12题为多选)1.卜列说法正确的是A.物体彼抽彖为质点后,物体自身的大小和体积就可以忽略不计了B.研究地球公转时不町以把地球看做质点C.研究自行车车轮的转动问题町以把车轮看作质点D.硏究艺术体操运动员的动作可以把运动员看作质点【答案】A【解析】【详解】A.质点是理想化的物理模型,没有大小和形状,只有质量的点,故A正确;B.研究地球公转时,地球的人小町以忽略不计,町以把地球看做质点,选项B错误.C.研究自行车车轮的转动问题不可以把车轮看作质点,否则就没有转动了,选项C错误:D.研究艺术体操运动员的动作时,运动员的大小不能忽略,不可以把运动员看作质点,选项D错误。
2.关于位移和路程,下列说法不正确的是A.质点的位移是矢量,路程是标最B.质点通过的路程不等,但位移町能相同C.质点通过的路程不为零,但位移可能是零D.质点做直线运动时,那么它通过的路程和位移人小一定相等【答案】D【解析】【详解】质点的位移是矢量,路程是标量,故A正确:质点通过的路程不等,首末位豐町能相同,则位移可能相同,故B正确:质点通过的路程不为零,首末位置可能觅合,则位移可能为零,故C正确;路程是标量,位移是矢量,两者不能等同,且物体做直线运动,位移的人小与路程不一定相等,故D错误.3.汽车和高铁是现在我们出行的甫要交通工具,假设甲、乙两地直线距离是50 km,从甲地到乙地乘汽车需要1 h,乘高佚需要0.25 h,则A.汽车的瞬时速度人小一定是50 km/hB. 汽车从甲地到乙地路程一定是50 kmC. 高铁的平均速度人小人于200 km/hD. 高铁的平均速度人小等丁• 200 km/h【答案】D 【解析】【详解】B.由题总知位移A = 50kin,考虑到公路与铁路都会有一定的弯曲,所以路程5 > 50kin ,选项B 错误.A •根据平均速度的定义式紂汽车的平均速度为:考虑到汽车的加速与减速未知,汽车行驶的瞬时速度不一定是50 km/h :选项A 错误: CD.高铁的平均速度人小为:-X 50 kill “小八v = —= ---------- = 200 kin/ h t 0.2511选项C 错误,D 正确.4.做匀加速直线运动的物体的加速度为2m/s =,对任意Is 來说,卜列说法中不正确的是()■A. 某Is 末的速度比该Is 初的速度总是人2m/sB. 菜Is 末的速度比该Is 初的速度总是人2倍C. 某Is 初的速度与前Is 末的速度相等D. 某Is 末的速度比前Is 初的速度人4m/s【答案】B 【解析】【详解】AB.做匀加速直线运动的物体的加速度为2m/sX 某Is 末比该Is 初多Is,根据得,某Is 末的速度比该Is 初的速度总是人2m/s,但不一定人2倍,故A 止确,B错误;C.某1S 初与前Is 末指的是同一时刻.△/ = (),根据v - v 0 = a • Ar=50k m/ li50 kin lh知某Is初的速度与前Is末的速度相等,故C正确;D.某Is末比前Is初多2s,根据Av = « A/,知某Is末的速度比前Is初的速度大4m/s,故D正确。
玉林市田家炳中学、玉林师院附中、玉林市育才中学、玉林市十一中学、玉林市福绵高中2020年秋季期期中教学质量评价高一化学试卷考试范围:必修1第一章、第二章;考试时间:70分钟满分:100分注意:本试卷包含I、II两卷。
第I卷为选择题,所有答案必须用2B铅笔涂在答题卡中相应的位置,如II卷为非选择题,所有答案必须填在答题卡的相应位置。
答案写在试卷上均无效,不予记分。
可能用到的相对原子质量:H 1 C 12 N 14 O 16 Al 27 S 32 Cl 35.5 Cu 64 Na 23第I卷(选择题共54分)一、选择题(本大题共18小题,每小题3分,共54分,每小题只有一个选项符合题意。
)1.下列状态的物质,既属于电解质又能导电的是A.氯化镁晶体B.氯化钠溶液C.液态氯化氢D.熔融氢氧化钾2.“纳米材料”是指粒子直径在几纳米到几十纳米之间的材料,如将“纳米材料”分散到液体分散剂中,所得混合物具有的性质是A.不均一、不稳定B.具有丁达尔效应C.所得液体一定能导电D.所得物质一定为悬浊液或乳浊液3.运输氢氧化钠的车辆上应贴的图标是4.容量瓶上的标记有下列各项中的①温度②浓度③容量④压强⑤刻度线⑥所配溶液的酸碱性A.①③⑤B.③⑤⑥C.①②④D.②④⑥5.下列化学方程式中,能用离子方程式Ca2++CO32-=CaCO3↓来表示的是A.2Ca(HCO3)2+2NaOH=CaCO3↓+Na2CO3+2H2OB.Ca(OH)2+K2CO3=CaCO3↓+2KOHC.2KHCO3+Ca(OH)2=CaCO3↓+K2CO3+2H2OD.Ca(OH)2+CO2=CaCO3↓+H2O6.下列离子方程式书写不正确的是A.铁跟稀硫酸反应:Fe+2H+=Fe2++H2↑B.铜片插入硝酸银溶液中:Cu+Ag+=Cu2++AgC.铁与氯化铜溶液反应:Fe+Cu2+=Fe2++CuD.碳酸钙跟稀盐酸反应:CaCO3+2H+=Ca2++H2O+CO2↑7.某无色透明的酸性溶液中能大量共存的一组离子是A.MnO4-、K+、SO42-、Na+B.Na+、HCO3-、K+、SO42-C.NH4+、NO3-、Fe2+、Cl-D.Al3+、Mg2+、SO42-、NO3-8.50 mL 0.1 mol/L硫酸铁溶液与100 mL 0.3 mol/L硫酸钠溶液相比,它们的SO42-离子的浓度比是A.1:1B.1:3C.1:2D.3:19.下列电离方程式中,书写正确的是A.Na2SO4=2Na++SO42-B.H2SO4=H2++SO42-C.NH4NO3=NH4++NO3-D.Fe2(SO4)3=2Fe2++3SO42-10.下列反应不属于氧化还原反应的是A.3NO2+H2O=2HNO3+NOB.FeCl3+3NaOH=3NaCl+Fe(OH)3↓C.2KMnO4∆==K2MnO4+MnO2+O2↑ D.Cl2+2NaOH=NaClO+NaCl+H2O11.用N A表示阿伏加德罗常数的值,下列判断正确的是A.常温常压下,16 g CH4分子所含质子数为10N AB.1 mol Cl2所含分子数为2N AC.标准状况下,22.4 L乙醇所含分子数为N AD.0.01 mol·L-1的NaCl溶液中含有0.01N A个Cl-12.在标准状况下,W L N2含有n个氮分子,则阿伏加德罗常数可表示为A.Wn mol-1B.22.4 n/w mol-1C.28 nw/22.4 mol-1D.22.4 n/w13.下列实验操作正确的是A.制取蒸馏水时,为了防止瓶内产生暴沸现象,应先向烧瓶内加入几片碎瓷片B.稀释浓硫酸时,常把水加入到盛浓硫酸的烧杯中C.做CO 还原Fe 2O 3实验时,为防止CO 污染环境,实验完毕,常先停止通CO ,再停止加热D.在用水吸收HCl 气体时可把导管直接插入液面下14.用下列方法均可制得氧气①2KClO 32MnO ∆===2KCl +3O 2↑ ②2HgO ∆==2Hg +O 2↑③2KMnO 4∆==K 2MnO 4+MnO 2+O 2↑若要制得相同质量的氧气,反应中电子转移数目之比为A.3:1:1B.3:1:4C.1:1:1D.2:1:115.某学生做如下实验:第一步,在淀粉-KI 溶液中,滴入少量NaClO 溶液,并加入少量稀硫酸,溶液立即变蓝;第二步,在上述蓝色溶液中,滴加足量的Na 2SO 3溶液,蓝色逐渐消失。
玉林市田家炳中学、玉林师院附中、玉林市育才中学、玉林市第十一中学、玉林市福绵高中2020 年秋季期教学质量评价高一生物试卷玉林市田家炳中学高一生物基组命题、审题一、选择题(本题一共25 小题,每小题只有一个正确答案,每小题2 分,共50 分)1.下列实例中,能说明生命活动离不开细胞的是()①新冠肺炎患者咳嗽时,会有大量新冠病毒随飞沫散布于空气中②手触碰到盛有沸水的电水壶会迅速缩回③体操运动员完成单杠动作离不开肌肉细胞的收缩和舒张④人的胚胎发育过程中,细胞不断地进行分裂增殖A.①②③B.①②④C.②③④D.①②③④2.下列有关显微镜操作的表述,其中正确的是()A.用高倍镜观察比用低倍镜观察,看到的细胞数目越多、细胞越小和视野越亮B.若转换高倍物镜观察,需先升高镜筒,以免镜头碰坏装片C.标本染色较深,观察时应选用凸面反光镜和大光圈D.视野中存在异物时,可通过移动装片,更换目镜和转换物镜来确定位置3.下列组合中能体现生命系统的结构层次由复杂到简单的正确顺序是()①洋葱根尖分生区细胞②细胞内蛋白质,无机盐等化合物③一棵小草④某森林中的所有生物⑤一个池塘内所有的鱼⑥人的呼吸系统⑦大熊猫的肝脏A.④⑦③⑥①②B.④③⑥⑦①②C.④③⑥⑦①D.⑤③⑥⑦①4.以下关于实验的描述中,正确的是()A.甘蔗茎的薄壁组织、甜菜的块根等都含有较多的糖且近于白色,因此可以用于进行还原糖的实验B.蛋白质变性后,仍能与双缩脲试剂发生作用,产生紫色反应C.脂肪可被苏丹Ⅲ染成红色,被苏丹Ⅳ染成橘黄色D.用于鉴定可溶性还原糖的斐林试剂甲液和乙液,可直接用于蛋白质的鉴定5.下列描述中,说法正确的是()A.细胞学说揭示了细胞统一性和生物体结构的统一性B.发菜、颤藻、念珠藻都属于蓝藻,蓝藻的叶绿体含有藻蓝素和叶绿素C.组成生物体蛋白质的氨基酸约有20种,有8种非必需氨基酸,12种必需氨基酸D.组成生物体的大量元素中,C是最基本的元素,在细胞中含量是最多的6、细菌、水稻、噬菌体、酵母菌都具有的是()A.纤维素B.淀粉C.脱氧核糖D.糖原7、从某生物中提取到磷脂,该生物不可能是()A.小鼠B.大肠杆菌C.玉米D.新冠病毒8、下列选项中,属于动植物细胞共有的糖类是()A.淀粉、脱氧核糖、乳糖B.葡萄糖、淀粉和果糖C.葡萄糖、核糖、脱氧核糖D.麦芽糖、果糖、乳糖9、夏季炎热,在室外作业的人们应多饮用()A.牛奶B.纯净水C.奶茶 D.盐汽水10、下列哪一项不属于细胞膜的功能()A.作为系统的边界,维持细胞内部环境的相对稳定B.将蛋白质分泌到细胞外C.进行细胞间的信息交流D.提高细胞内各种化学反应的速率11、番茄细胞中的核苷酸种类一共有多少种类?()A.4种B.5 种C.20 种D.8种12、当缺乏某种化学元素时,植物往往表现出缺绿的症状,这种化学元素是()。
广西壮族自治区玉林市玉州区玉林市第十一中学2024-2025学年高一上学期10月月考英语试题一、阅读理解School NewsWelcome back to school! Have you signed up for an after-school activity yet? Here are some of the activities you can try.SPORTS TEAMSDo you like sports? How about joining the football team? It has try-outs next Tuesday at 3:00. Many of our best players have moved up to college. So now the team needs new players. For more information, meet our sports advisors, Ms. Matte or Mr.Stergis.GOOD AT ART?This year, your classmates in the school art club plan to paint a mural(壁画)on the wall by the office. So they need new members to help create it! Are you interested in drawing, painting or taking photographs? This club is for you. The first meeting of the school year is next Wednesday at 3:15 in Room 221. Please see Ms. Greenway for more information.NEW THIS YEARThere are some new activities you can have a try. Try the new after-school science club! It has plans to enter the national Senior Robotics competition this year. So if you want to try building a robot, this club is for you. See Mr. Larson in Room 105 for more details. The club meets every Thursday at 3:30.Do you like acting? Are you good at singing? The school play this year is a musical—The Sound of Music. Come and try out next Monday at 3:10 in Room 125.For a list of all the after-school activities this year, click here. Or pick up a membership form from the advisor’s office, Room 107.1.When are the try-outs for the football team?A.Next Monday at 3:10.B.Next Wednesday at 3:15.C.Next Tuesday at 3:00.D.Next Thursday at 3:30.2.What does the art club plan to do this year?A.To paint a mural.B.To put on a musical.C.To offer photography courses.D.To enter a national competition.3.Where can you get more information about the science club?A.In Room 221.B.In Room 125.C.In Room 107.D.In Room 105.At 12, my father decided to take me a trip to France. I had never been out of the country before, so I was very excited. My aunt, my father and I went around with my father showing us all the unbelievable attractions in Paris. None of us spoke much French but we loved the city.We had taken the subway all over the city and were congratulating ourselves on our understanding of what is honestly a good subway design that is pretty easy to follow. We decided to visit Versailles by train. We chatted happily along the way until my father realized we were far into the French countryside and no one around spoke English.We reached the end of the line and felt frightened when everyone finally left the train. An old man and his grandchild noticed us and came up to help. He spoke no English, so in broken French we tried to explain. When he finally understood, this great man settled his grandson and showed us to the correct train and then got on it with us.Later we knew the truth that there was a train transfer(换乘) and he didn’t want us to miss it. This kind man rode a train an hour and a half out of his way to make sure that three Americans got where they wanted to be. He refused to let us pay for his ticket. He did it all with a gentle smile and shook our hands gently at the stop. Then with his quiet way, he got on the train to return the way he had come.What impressed me most was the man and his kindness during the amazing trip. Some Americans think the French are rude for some reason, but I always try to make them change their minds with this story.4.What happened to the author and his family on the train?A.They failed to get off the train at the right time.B.They couldn’t understand the signs of the train.C.They had a quarrel about where to go first.D.They found it hard to live in the countryside.5.How did the man help the author and his family?A.By paying for their train tickets.B.By leading them to where they wanted to be.C.By inviting them to travel together.D.By showing them the return way.6.What impressed the writer most about the old man?A.His honesty B.His kindness C.His gentleness D.His happiness 7.What’s the purpose of the author’s writing the passage?A.To explain an unexpected problem.B.To list the unbelievable attractions in Paris.C.To show the importance of learning a foreign language.D.To share an unforgettable foreign experience.My high school life has been filled with many ups and downs, whether it was social or academic. Even though it was not my first choice, I never regretted attending Dragon Up High School. “Since you have chosen it, then it is the best for you,’’ said my parents.Up until the junior year I did not perform well as a student, even though I had been told that my junior year would be the toughest in all the years of high school. With this “little” piece of information, I walked into my junior year, frightened of my grades. As weeks went by, I started to believe that the junior year was not as hard as everyone had said, but I was wrong. My grades were rapidly declining and by the end of the first term I did a terrible job. I could not believe it. I tried my best to get my grades up myself without any help from anyone, but my pride just made my grades worse. I was heartbroken. I realized that I could not survive my junior year on my own.Fortunately, my English teacher Rey helped me a lot and gave me much courage and advice.I slowly started to gain my confidence back in all of my classes and even myself. By the time the third and fourth quarter came around, I had been on the honor roll twice, and I was receiving awards from speeches and debates, tennis and school.Dragon Up has taught me to always keep my head up and never give up on myself no matter what life throws at me. I am proud to be a real dragon.8.From the first paragraph, we can learn that ______.A.the writer always thought Dragon Up High School was the best.B.the writer’s parents persuaded her into attending Dragon Up High School.C.the writer has met many challenges since she attended high school.D.life has become easier since the writer came to Dragon Up High School.9.How did the writer feel when she walked into her junior year?A.Confident B.Worried C.Curious D.Uninterested. 10.Why was the writer’s study worse and worse?A.She didn’t work hard enough.B.She didn’t ask others for help because of pride.C.She missed her old friends.D.No one would like to help her.11.What important lesson has the writer learned at Dragon Up High School?A.Students should face challenges bravely.B.Students should be careful in choosing school.C.Students should be proud of their school.D.Students should better learn about life.One of the crucial issues for mankind to solve before landing humans on Mars is that they must find usable water on the barren, reddish planet for the explorers to consume.A recent finding by Chinese scientists based on data obtained by China’s Martian rover (探测器) Zhurong may have brought that goal closer to reality.According to data obtained by the rover, they have identified hydrated (含水的) materials at Zhurong’s landing site in the southern part of an impact basin called Utopia Planitia. “These hydrated minerals are associated with bright-toned rocks and are interpreted to be duricrust (铝铁硅钙壳) developed locally. The duricrusts suggest that formation with substantial liquid water originates by either groundwater rising or subsurface ice melting,” reads a paper published in the newest issue of the scientific journal Science Advances.Liu Yang, lead author of the paper, said their findings indicate that liquid water activities might have been more active than previously thought during the Amazonian Period, which began about 3 billion years ago and remains ongoing. “There is likely to be a large amount of usable water in hydrated minerals around the landing site of Zhurong as well as the vast areas in Mars' northern lowlands,” he added.Zhurong is the core component (核心部分) of Tianwen-1, the country’s first inter-planetarymission, and is also the sixth rover on the Red Planet, following five from the United States. It is tasked with surveying Mars ’landforms, geological structures, soil characteristics, potential locations of water and ice, and atmospheric and environmental characteristics, as well as magnetic, gravitational and other physical fields.As of Thursday, Zhurong has worked on Mars for nearly a year — far outliving its three-month life expectancy (预期寿命) and obtained a great deal of data, mission controllers said, adding it still has sufficient energy and is in good condition12.What does the underlined words “that goal” in paragraph 2 refer to?A.Collecting materials on Mars.B.Landing humans on Mars.C.Obtaining consumable water on Mars.D.Testing Rover Zhurong on Mars. 13.What can we learn from duricrust?A.Mineral amount.B.Water source.C.Planet developments.D.Soil characteristics.14.Which statement may Liu Yang agree with?A.Abundant water is stored on Mars.B.Landing site is the only water location.C.Water activities began 3 billion years ago.D.The findings indicate decrease of water formation.15.What can we learn about Zhurong?A.It is the first rover on Mars.B.It can continue to serve on Mars.C.It searches for minerals on Mars.D.It is expected to outlive 3 months.College can be a challenging time for newcomers. For most students, it’s the first time they’ll be living alone and away from their parents. While students may face problems in university, there are solutions to these problems.16 From the moment you get into school, you will need to choose your own classes, plan your schedule and eventually find out where your classes are at the school. Although there are tutors to help you with this, much of it needs to be done on your own.Balance academics (学业) and a social life. You will first need to put your classes, studies, projects and homework in order of importance. But you will need to find a way to balanceacademics with your social life, too. 17 This is because you go to school with your friends at the same time each day. But in college, your schedule may differ from your friends’ schedules.Deal with financial problems. 18 For many students, this is the first time they’re really on their own financially. Therefore, you have to be careful about how much money you’re spending each time. If having financial concerns, you can talk to a trusted adult in your family.Find time to eat healthily and exercise. 19 It talks about how freshmen usually gain 15 pounds during their first year of college. This is often due to the lack of healthy eating options at the school, the lack of exercise and finally, drinking. In order to keep a healthy lifestyle, be sure about what you’re eating. In short, you should avoid eating unhealthy food. 20A.Have classes on time.B.Plan your class schedule.C.Money is a big challenge for students.D.More students tend to eat unhealthy food.E.Visiting the gym every week is also important.F.In high school, it’s often easier to balance these two.G.“Freshman 15” is a popular expression commonly used in college.二、完形填空It was my 14th birthday and I would have the biggest party ever. The number of the 21 had quickly grown from seven to seventeen. Nearly every girl in my class was 22 . When each guest excitedly 23 the invitation, it was especially happy.The 24 was full of shouts and laughter. We had just finished a game of Twister when the door bell rang. I was so 25 and I could feel my face turning red, because when I 26 the door, there at the front door stood Sarah Westly — the quiet girl who sat next to me in music class-and she was holding a 27 . I thought about the guest list. How did I 28 to invite Sarah?I remembered that I only added a name to the 29 when someone showed an interest in me. But Sarah had 30 done that. I accepted the box, a gift from Sarah, and asked her to join the party. “I can’t 31 ,” she said. “My dad’s waiting in the car.” At thatmoment I felt bad about forgetting to invite Sarah and really wanted her to rest for some time in my room. “Thanks, but I have to go,” she said, turning 32 towards the door. “See you Monday.”I didn’t open the box until the party was 33 . Inside the small box was a ceramic (陶瓷) tabby cat. It was the best gift I had received 34 I didn’t like cats. I later 35 that the gift looked exactly like Sarah’s cat, Seymour. I didn’t know it then, but now I realize that Sarah was my best friend.21.A.boys B.guests C.books D.desks 22.A.invited B.invented C.showed D.suggested 23.A.made B.found C.accepted D.passed 24.A.classroom B.library C.restaurant D.living room 25.A.surprised B.angry C.proud D.sad 26.A.touched B.opened C.caught D.saw27.A.cat B.toy C.pen D.box 28.A.forget B.stop C.hope D.choose 29.A.gift B.list C.diary D.box30.A.still B.even C.never D.only 31.A.stand B.sing C.wait D.stay 32.A.quickly B.carefully C.finally D.early 33.A.ready B.successful C.over D.interesting 34.A.and B.so C.because D.though 35.A.took out B.found out C.thought out D.put out三、语法填空阅读下面材料,在空白处填入适当的内容(不多于3个单词)或括号内单词的正确形式。
2019年秋季期高一期末质量监测物理考生注意:1.本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分,共100分。
考试时间90分钟。
2.请将各题答案填写在答题卡上。
3.本试卷主要考试内容:人教版必修1。
第Ⅰ卷(选择题共48分)一、选择题:每小题4分,共48分。
在每小题给出的四个选项中,第1〜8小题只有一个选项正确,第9〜12小题有多个选项正确,全部选对的得4分,选对但不全的得2分,有选错的得0分。
1.有人曾写下这样一首诗空手把锄头,步行骑水牛。
人从桥上过,桥流水不流。
” “桥流”选的参考系可能是A.人B.河水C.地面D.桥2.关于速度和加速度,下列说法正确的是A.物体具有加速度,速度一定增大B.物体的速度为零,加速度一定为零C.物体的速度变化率越大,加速度就越大D.物体的加速度减小,速度一定减小3.下列关于力的认识正确的是A.物体所受重力的大小与物体运动状态有关B.站在地面上的人受到的弹力是脚形变产生的C.摩擦力的方向可能与物体运动的方向相同D.重心一定在物体上4.图甲中小明用50 N的水平力推木箱,没推动,此时木箱受到的摩擦力为F1;图乙中小明用78 N的水平力恰好能推动木箱,此时木箱受到的摩擦力为F2;图丙中小明用100 N的水平力把木箱推动了,此时木箱受到的摩擦力为F3。
已知木箱对地面的压力为300 N,木箱与地面间的动摩擦因数为0.25,则F1、F2、F3的大小分别为A. 0 N,78 N,100 NB. 0 N,78 N,75 NC. 50 N,78 N,100 ND. 50 N,78 N,75 N5.如图所示,两物体A 和B 由绕过光滑定滑轮的轻绳连接,整个装置处于静止状态,下列说法正确的是A.物体A 可能不受摩擦力B.物体A 可能不受支持力C.物体B 受到的重力小于轻绳对B 的拉力D.给物体A 施加一个竖直向下的外力,整个装置一定继续保持静止6.A 、B 两个物体在同一直线上做匀变速直线运动,且A 、B 从同一位置出发,它们的速度一时间图象如图所示,则A. t=4s 时,A 、B 的速度相同B. A 的加速度比B 的加速度大C. 第4 s 末A 、B 在同一位置D. A 物体的加速度为2.5 m/s 27.如图所示,物体A 、B 叠放在斜面上,处于静止状态。
玉林市田家炳中学、玉林师院附中、玉林市育才中学、玉林市第十一中学、玉林市福绵高中2021年秋季期教学质量评价高一生物试卷一、选择题(此题一共25小题,每题只有一个正确答案,每题2分,共50分)1.以下实例中,能说明生命活动离不开细胞的是①新冠肺炎患者咳嗽时,会有大量新冠病毒随飞沫散布于空气中②手触碰到盛有沸水的电水壶会迅速缩回③体操运发动完成单杠动作离不开肌肉细胞的收缩和舒张④人的胚胎发育过程中,细胞不断地进行分裂增殖A.①②③B.①②④C.②③④D.①②③④2.以下有关显微镜操作的表述,其中正确的选项是A.用高倍镜观察比用低倍镜观察,看到的细胞数目越多、细胞越小和视野越亮B.假设转换高倍物镜观察,需先升高镜筒,以免镜头碰坏装片C.标本染色较深,观察时应选用凸面反光镜和大光圈D.视野中存在异物时,可通过移动装片,更换目镜和转换物镜来确定位置3.以下组合中能表达生命系统的结构层次由复杂到简单的正确顺序是①洋葱根尖分生区细胞②细胞内蛋白质,无机盐等化合物③一棵小草④某森林中的所有生物⑤一个池塘内所有的鱼⑥人的呼吸系统⑦大熊猫的肝脏A.④⑦③⑥①②B.④③⑥⑦①②C.④③⑥⑦①D.⑤③⑥⑦①4.以下关于实验的描述中,正确的选项是A.甘蔗茎的薄壁组织、甜菜的块根等都含有较多的糖且近于白色,因此可以用于进行复原糖的实验B.蛋白质变性后,仍能与双缩脲试剂发生作用,产生紫色反响C.脂肪可被苏丹III染成红色,被苏丹IV染成橘黄色D.用于鉴定可溶性复原糖的斐林试剂甲液和乙液,可直接用于蛋白质的鉴定5.以下描述中,说法正确的选项是A.细胞学说揭示了细胞统一性和生物体结构的统一性B.发菜、颤藻、念珠藻都属于监藻,蓝藻的叶绿体含有藻蓝素和叶绿素C.组成生物体蛋白质的氨基酸约有20种,有8种非必需氨基酸,12种必需氨基酸D.组成生物体的大量元素中,C是最根本的元素,在细胞中含量是最多的6、细菌、水稻、噬菌体、酵母菌都具有的是A.纤维素B.淀粉C.脱氧核糖D.糖原7、从某生物中提取到磷脂,该生物不可能是A.小鼠B.大肠杆菌C.玉米D.新冠病毒8、以下选项中,属于动植物细胞共有的糖类是A.淀粉、脱氧核糖、乳糖B.葡萄糖、淀粉和果糖C.葡萄糖、核糖、脱氧核糖D.麦芽糖、果糖、乳糖9、夏季炎热,在室外作业的人们应多饮用A.牛奶B.纯洁水C.奶茶D.盐汽水10、以下哪一项不属于细胞膜的功能A.作为系统的边界,维持细胞内部环境的相对稳定B.将蛋白质分泌到细胞外C.进行细胞间的信息交流D.提高细胞内各种化学反响的速率11、番茄细胞中的核苷酸种类一共有多少种类?A.4种B.5种C.20种D.8种12、当缺乏某种化学元素时,植物往往表现出缺绿的病症,这种化学元素是A.镁B.锰C.硼D.铜13、以下不含有脂质的细胞器是A.核糖体B.细胞膜C.线粒体D.内质网14、如图表示某种大分子物质的根本单位,关于它的表达中错误的选项是A.此物质是核糖核苷酸B.此物质聚合形成的大分子物质是RNA,它只分布在细胞质中C.此物质含有C、H、O、N、P等元素D.在T2噬菌体中找不到这种物质15、热带非洲地区的光棍树,树形奇特,无刺无叶,它茎干中的白色乳汁可以制取“石油〞。
广西壮族自治区玉林市第十一中学2020-2021学年高一生物测试题含解析一、选择题(本题共40小题,每小题1.5分。
在每小题给出的四个选项中,只有一项是符合题目要求的。
)1. 下列生物中属于原核生物的一组是( )①蓝藻②酵母菌③草履虫④小球藻⑤水绵⑥葡萄球菌⑦青霉菌⑧链霉菌A.①⑦⑧B.①⑥⑧C.①③④⑦D.①②⑥⑦⑧参考答案:B2. 下列有关构成细胞的化合物的种类和鉴别方法的叙述中,正确的是A.细胞中的糖分为单糖、二糖和多糖,可以用斐林试剂鉴别B.细胞中的脂质具有多种功能,如储存能量;脂质能被苏丹Ⅲ染成橘黄色C.细胞的遗传物质是DNA或RNA,用甲基绿—吡罗红试剂可以鉴定其存在和分布D.细胞内蛋白质种类众多,但都能与双缩脲试剂发生紫色颜色反应参考答案:D3. 下图是人体生命活动调节过程的示意图,请据图判断下列说法不正确的是()A.如分泌细胞1是性腺细胞,则靶细胞2不可能是神经细胞B.如分泌细胞1是甲状腺细胞,则靶细胞2可能是垂体细胞C.如分泌细胞1是T细胞,则靶细胞2可能是B细胞D.如分泌细胞1是胰岛A细胞,则它既是内分泌细胞又是构成某种非条件反射弧的效应器的组成部分参考答案:A4. 下列四种现象中,可以用右图表示的是A.细胞的物质运输效率随细胞体积的变化B.酶量一定、底物充足时反应速率随温度的变化C.储藏的水果呼吸作用强度随氧含量的变化D.某植物在适宜温度下光合速率与光照强度的关系参考答案:D5. 下列物质中在核糖体内合成的是①性激素②抗体③淀粉④淀粉酶⑤纤维素A.②③B.②④ C.②⑤D.①②参考答案:B6. 下图一为某二倍体动物细胞减数分裂某时期示意图,图二中能表示该动物体细胞正常有丝分裂产生的子细胞的是( )A. AB. BC. CD. D参考答案:A图一为某二倍体动物细胞减数分裂某时期示意图,由于图中没有同源染色体,所以此图应为减数第二次分裂前期,那么该动物体细胞中染色体应该是4条,则体细胞正常有丝分裂产生的子细胞中也应该有4条染色体,A正确。
广西省玉林师院附中、玉林市育才中学、玉林市第十一中学、玉林市田家炳中学2019-2020学年高一上学期期中考试化学试题1. 从20世纪90年代开始,叠氮化钠用作汽车司机安全防护袋的气源,能在发生碰撞的瞬间分解产生大量气体将气囊鼓起。
装运叠氮化钠的包装箱所贴的危险化学品标志应该是( )A B C DA. AB. BC. CD. D【答案】B【解析】【详解】根据题意可知,叠氮化钠属于爆炸品,A.图中所示标志是剧毒品标志,故A错误;B.图中所示标志是爆炸品标志,故B正确;C.图中所示标志是易燃液体标志,故C错误;D.图中所示标志是腐蚀品标志,故D错误;综上所述,本题选B。
2. 《茶疏》中对泡茶过程有如下记载:“治壶、投茶、出浴、淋壶、烫杯、酾茶、品茶…… ”文中未涉及下列操作原理是A 溶解 B. 萃取 C. 蒸馏 D. 过滤【答案】C【解析】【详解】投茶、出浴涉及茶的溶解,淋壶、烫杯、酾茶过程涉及萃取以及过滤等操作,而蒸馏涉及到物质由液态变为气体后再变为液体,泡茶过程没有涉及到此蒸馏。
A. 溶解符合题意;B. 萃取溶解符合题;C. 蒸馏不溶解符合题;D. 过滤溶解符合题;故选C。
3. 下列实验装置能达到实验目的的是①分离乙醇和水②用自来水制取蒸馏水③从食盐水中获取氯化钠④用排空气法收集氯气(Cl2)A. ①②B. ①④C. ③④D. ②③【答案】D【解析】【详解】①乙醇和水互溶,分液漏斗不能分离,应选蒸馏法,故①错误;②图中蒸馏装置可利用自来水制备蒸馏水,故②正确;③食盐溶于水,图中蒸发可分离出NaCl,故③正确;④氯气的密度比空气密度大,应长导管进气收集,故④错误;答案选D。
【点睛】本题考查化学实验方案的评价,把握物质的性质、混合物分离提纯、实验操作、实验技能为解答的关键,侧重分析与实验能力的考查,注意实验的评价性分析,④是解答的易错点。
4. 下列说法正确的是A. 物质不是电解质就是非电解质B. 酸性氧化物不一定都是非金属氧化物,而非金属氧化物一定是酸性氧化物C. 能导电的物质不一定是电解质,电解质也不—定能导电D. 液氨溶于水能导电,所用是电解质【答案】C【解析】【详解】A.电解质和非电解质都是化合物,单质和混合物既不是电解质,又不是非电解质,错误;B.酸性氧化物不一定都是非金属氧化物,如七氧化二锰,非金属氧化物也不一定是酸性氧化物,如一氧化碳属于不成盐氧化物,错误;C.能导电的物质不一定是电解质,如铜。
电解质不一定能导电,如固体氯化钠,正确;D .液氨溶于水能导电,是因为生成的一水合氨发生了电离,而氨气属于非电解质,错误; 答案选C 。
【点晴】本题考查了电解质的概念,注意电解质不一定导电,导电的物质不一定是电解质。
注意:①电解质和非电解质均指化合物,单质和混合物既不属于电解质也不属于非电解质;②电解质必须是自身能直接电离出自由移动的离子的化合物,如SO 2、CO 2属于非电解质;③条件:水溶液或融化状态,对于电解质来说,只须满足一个条件即可,而对非电解质则必须同时满足两个条件;④难溶性化合物不一定就是弱电解质,如硫酸钡属于强电解质。
5. 某溶液中含有较大量的Cl -、23CO -、 OH -三种阴离子,如果只取一次该溶液就能够分别将三种阴离子依次检验出来,下列实验操作顺序正确的是①滴加足量的Mg(NO 3)2溶液;②过滤;③滴加适量的AgNO 3溶液;④滴加足量的Ba(NO 3)2溶液A. ①②④②③B. ④②①②③C. ①②③②④D.④②③②① 【答案】B 【解析】【详解】Ag +能与Cl -、23CO -、 OH -三种结合,Mg 2+能与23CO -、 OH -结合,Ba 2+只能与23CO -结合,故先加入Ba(NO 3)2溶液溶液,检验出23CO -离子,过滤除去生成的BaCO 3沉淀;然后加入Mg(NO 3)2溶液,检验出 OH -,过滤除去生成的Mg(OH)2沉淀;最后加入AgNO 3溶液,检验出Cl -,故正确的操作顺序是④②①②③,故合理选项是B 。
6. 磁流体是电子材料的新秀,它既具有固体的磁性,又具有液体的流动性。
制备时将含等物质的量的FeSO 4和Fe 2(SO 4)3的溶液混合,再滴入稍过量的NaOH 溶液,随后加入油酸钠溶液,即可生成黑色的、分散质粒子的直径为5.5∼36nm 的磁流体。
下列说法中正确的是 A. 所得到的分散系属于胶体B. 用一束光照射该分散系时,看不到一条光亮的“通路”C. 该分散系不能透过滤纸D. 该分散系的分散质为Fe(OH)3 【答案】A 【解析】【详解】根据题意,磁流体分散系分散质粒子直径在5.5~36nm,该分散系属于胶体,所以应具备胶体的性质;A、据以上分析可知,所得到的分散系属于胶体,故A正确;B、磁流体分散系属于胶体,具有丁达尔现象,故B错误;C、该分散系属于胶体,胶体可以透过滤纸,故C错误;D、该分散系的分散质是由氢氧化亚铁、氢氧化铁共同组成的,故D错误;综上所述,本题选A。
7. 下列说法正确的是()A. 熔融NaCl能导电,是因为通电时NaCl发生了电离B. NaCl固体不导电,因为NaCl固体中无带电微粒C. NH4NO3电离时产生了NH4+、NO3-,无金属离子,所以NH4NO3不是盐D. NaHSO4在水溶液中电离生成了Na+、H+、SO24-三种离子【答案】D【解析】【详解】A、熔融NaCl能电离出自由移动的Na+和Cl-,电离与电流无关,选项A错误;B、氯化钠固体不导电是因为NaCl固体中带电的离子不能自由移动,选项B错误;C、由金属阳离子或铵根离子和酸根离子构成的纯净物是盐,硝酸铵是由铵根离子和酸根离子构成的纯净物,属于盐,选项C错误;D、硫酸氢钠在水溶液中完全电离出三种离子,即NaHSO4=Na++H++SO42-,选项D正确。
答案选D。
8. 对于某些常见离子的检验及结论一定正确的是A. 加入氯化钠溶液有白色沉淀产生,再加稀硝酸沉淀不消失,一定有Ag+SOB. 加入氯化钡溶液有白色沉淀产生,再加盐酸沉淀不消失,一定有2-4COC. 加入稀盐酸产生无色气体,将气体通入澄清石灰水中,溶液变浑浊,一定有2-3D. 加入碳酸钠溶液产生白色沉淀,再加盐酸白色沉淀消失,一定有Ba2+【答案】A【解析】【详解】A.加入氯化钠溶液有白色沉淀产生,再加稀硝酸沉淀不消失,说明生成了AgCl,则一定有Ag +,故A 正确;B .加入氯化钡溶液有白色沉淀产生,再加盐酸沉淀不消失,可能为24SO -、Ag +,故B 错误;C .加入稀盐酸产生无色气体,将气体通入澄清石灰水中,溶液变浑浊,可能为23CO -、3HCO -、23SO -、3HSO -,故C 错误;D .加入碳酸钠溶液产生白色沉淀,再加盐酸白色沉淀消失,可能为Ba 2+、Mg 2+,故D 错误。
综上所述,答案为.A 。
9. 每年10月23日上午6:02到晚上6:02被誉为“摩尔日"(Mole Day),这个时间的美式写法为6:0210/23,外观与阿伏加德罗常数6.02×1023相似。
用N A 表示阿伏加德罗常数的值,下列说法中正确的是A. 标准状况下,22.4L CCl 4含有N A 个CCl 4分子B. 1mol/L Mg (NO 3)2溶液中含有NO 3﹣的数目为2N AC. 等物质的量浓度的盐酸和硫酸中,H +的物质的量浓度也相等 D. 5.6g 铁与足量盐酸反应转移的电子数为0.2N A 【答案】D 【解析】 【分析】A.标准状况下,四氯化碳不是气体,不能使用标况下的气体摩尔体积计算其物质的量;B.没有告诉硝酸镁溶液的体积,无法计算溶液中硝酸根离子的物质的量;C.盐酸为一元酸,而硫酸为二元酸,浓度相等的两溶液中,氢离子浓度一定不相等;D.铁与盐酸反应生成亚铁离子,0.1mol 铁反应失去0.2mol 电子。
【详解】A.标况下,四氯化碳不是气体,题中条件无法计算四氯化碳的物质的量,故A 错误;B.没有告诉1mol/L Mg (NO 3)2溶液的体积,无法计算溶液中硝酸根离子的数目,故B 错误;C.等物质的量浓度的盐酸和硫酸中,硫酸中H +的物质的量浓度为盐酸的2倍,故C 错误;D. 5.6g 铁的物质的量为0.1mol ,0.1mol 铁与足量盐酸完全反应失去0.2mol 电子,转移的电子数为0.2N A ,所以D 选项是正确的。
所以D 选项是正确的。
10. 下列反应的离子方程式书写正确的是A. 铜和醋酸反应:Cu +2CH 3COOH=2CH 3COO -+Cu 2++H 2↑B. 氧化铁与稀盐酸反应:Fe2O3+6H+=2Fe3++3H2OC. 锌与硝酸银溶液反应:Zn+Ag+=Zn2++AgD. 稀硝酸和石灰乳反应:H++OH-=H2O【答案】B【解析】【详解】A.铜和醋酸不反应,A错误;B.离子方程式正确,B正确;C.没有配平,应该是Zn+2Ag+=Zn2++2Ag,C错误;D.石灰乳应该用化学式表示,D错误。
答案选B。
11. 已知Iˉ、Fe2+、SO2、Clˉ、H2O2均有还原性,它们在酸性溶液中还原性的强弱顺序为Clˉ< Fe2+< H2O2< Iˉ< SO2。
则下列反应不能发生的是SO+4H+ B. Cl2+SO2+2H2O=H2SO4+2HClA. 2Fe3++SO2+2H2O=2Fe2++2-4SO=SO2↑+O2↑+2H2O D. 2Iˉ+2H++H2O2=2H2O+I2C. H2O2+2H++2-4【答案】C【解析】【详解】A.SO2的还原性比Fe2+强,符合强制弱原理,该氧化还原反应能发生,故A错误;B.SO2的还原性比Clˉ强,符合强制弱原理,该氧化还原反应能发生,故B错误;C.H2O2的还原性比SO2弱,违反强制弱原理,该氧化还原反应不能发生,故C正确;D.H2O2的还原性比Iˉ弱,该氧化还原反应不能发生,故D错误。
答案选C。
12. 对某次酸雨成分的分析数据如表,此次酸雨中c(H+)约为A. 1×10﹣3B. 1×10﹣4C. 1×10﹣5D. 1×10﹣6【答案】B【解析】【分析】根据溶液中电荷守恒计算酸雨中氢离子浓度,再根据pH 的计算公式计算溶液的pH 。
【详解】溶液中阴阳离子所带电荷总数相等,设氢离子浓度为c ,则c (NH 4+)+c (Na +)+c (H +)=c (Cl -)+c (NO 3-)+2×c (SO 42-),即2×10-5mol/L+1.9×10-5mol/L+c (H+)=6×10-5mol/L+2.3×10-5mol/L+2×2.8×10-5mol/L ,解得c (H +)=10-4 mol/L ,pH=4, 答案选B 。