ch24
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调光台型号DISCO240,16CH*24DM*512说明书一;电脑灯的程序场编辑1.按(BLACK)键使该LED指示灯熄灭2.按(DEIT\RUN)键使该LED指示灯亮,进入编程状态3.按数字键(P1—P12)中任意一次,选择要编程的程序场编号,显示在LED的CHASE括号中。
4.再按数字键(P1—P12)选择出受控的电脑灯,使之对应的LED灯亮,则表示该项灯未选中,不受第5步的影响。
电脑灯效果(如果以设置了X\Y运行方向扫描通道转移,则其中有两个直滑电位器不求作用,你可操纵右下角摇杆电位器获取数据)。
5.推动CH1—CH8调节电脑灯个通道数值,或按SA\SB键,推动CH9—CH16调光对应的6.重复4.5步调节其他电脑灯,使之所需电脑等场景达到预订效果。
7.推动SPEED CROSS电位器,调节好场景停留时间及场景过渡时间。
8.按(+ 三角行)记忆次步场景效果,并进入下一步编辑。
若按(三角形—)键可查看一步场景。
重复4567步修改,再按(+ 三角形)储存。
9.重复4~8步编辑其他场景(程序步)10.按(EDIT\RUN)键,使该对应指示灯熄灭,记忆并退出编程状态,进入运行状态。
11.重复2~10步编辑其它程序场。
二:特殊场景表现在运行程序状态下,即(RUN\EDIT)键对应指示灯熄灭,按(RUN\SCENE)J键,再按P1~P12中任意键可调出已编程中第一号程序中的前12个场景,所以我们建议第一号程序的前12个场景在编程时最好有特殊定义,可作一些特技表演效果。
三:如何设置取消摇杆电位器设置摇杆电位器设置,按RUN\EDIT键,使该指示灯亮紧接着按SET X\Y键,根据液晶屏显示从P1~P8或按SA\SB键从PCH9~PCH16中选取两个对应电脑灯XY运行方向的扫描通道,转移到摇杆电位器去控制绿色指示灯随即点亮,如果输入错误按DELETE消除输入数据,绿色指示灯熄灭再按SET X\Y键记忆退出。
Chapter 24Risk Management in Financial Institutions24.1Multiple Choice24.1.1)Banks face the problem of _________ in loan markets because bad credit risks are the ones mostlikely to seek bank loans.A)adverse selectionB)moral hazardC)moral suasionD)intentional fraudAnswer:AQuestion Status:Previous Edition24.1.2)If borrowers with the most risky investment projects are more likely to seek bank loans thanborrowers with the safest investment projects, banks face the problem ofA)adverse credit risk.B)adverse selection.C)moral hazard.D)conflict of interest.Answer:BQuestion Status:Previous Edition24.1.3)Because borrowers, once they have a loan, are more likely to invest in high-risk investmentprojects, banks face theA)adverse selection problem.B)lemon problem.C)adverse credit risk problem.D)moral hazard problem.Answer:DQuestion Status:Previous Edition24.1.4)Banksʹ attempts to solve adverse selection and moral hazard problems help explain loanmanagement principles such asA)screening and monitoring of loan applicants.B)collateral and compensating balances.C)credit rationing.D)all of the above.E)only A and B of the above.Answer:DQuestion Status:Previous Edition24.1.5)In one sense, _________ appears surprising since it means that the bank is not _________ itsportfolio of loans and thus is exposing itself to more risk.A)specialization in lending; diversifyingB)specialization in lending; rationingC)credit rationing; diversifyingD)screening; rationingAnswer:AQuestion Status:Previous EditionChapter 24 Risk Management in Financial Institutions 351 24.1.6)From the standpoint of _________, specialization in lending is surprising but makes perfectsense when one considers the _________ problem.A)moral hazard; diversificationB)diversification; moral hazardC)adverse selection; diversificationD)diversification; adverse selectionAnswer:DQuestion Status:Previous Edition24.1.7)Provisions in loan contracts that proscribe borrowers from engaging in specified risky activitiesare calledA)proscription bonds.B)collateral clauses.C)restrictive covenants.D)liens.Answer:CQuestion Status:Previous Edition24.1.8)Banks attempt to screen good from bad credit risks to reduce the incidence of loan defaults. Todo this, banksA)specialize in lending to certain industries or regions.B)write restrictive covenants into loan contracts.C)expend resources to acquire accurate credit histories of their potential loan customers.D)do all of the above.Answer:DQuestion Status:Previous Edition24.1.9)A bankʹs commitment (for a specified future period of time) to provide a firm with loans up toa given amount at an interest rate that is tied to a market interest rate is calledA)credit rationing.B)a line of credit.C)continuous dealings.D)none of the above.Answer:BQuestion Status:Previous Edition24.1.10)Lines of credit and long-term relationships between banks and their customersA)reduce the costs of information collection.B)make it easier for banks to screen good from bad risks.C)enable banks to deal with moral hazard contingencies that are neither anticipated norspecified in restrictive covenants.D)do all of the above.E)do only A and B of the above.Answer:DQuestion Status:Previous Edition352 Mishkin/Eakins · Financial Markets and Institutions, Sixth Edition24.1.11)Compensating balancesA)are a particular form of collateral commonly required on commercial loans.B)are a required minimum amount of funds that a borrower (i.e., a firm receiving a loan)must keep in a checking account at the bank.C)allow banks to monitor firmsʹ check payment practices which can yield information abouttheir borrowersʹ financial conditions.D)all of the above.Answer:DQuestion Status:Previous Edition24.1.12)A bank that wants to monitor the check payment practices of its commercial borrowers, so thatmoral hazard can be prevented, will require borrowers toA)place a bank officer on their board of directors.B)place a corporate officer on the bankʹs board of directors.C)keep compensating balances in a checking account at the bank.D)do all of the above.E)do only A and B of the above.Answer:CQuestion Status:Previous Edition24.1.13)Of the following methods that banks might use to reduce moral hazard problems, the one notlegally permitted in the United States is the requirement thatA)firms keep compensating balances at the banks from which they obtain their loans.B)firms place on their board of directors an officer from the bank.C)loan contracts include restrictive covenants.D)individuals provide detailed credit histories to bank loan officers.Answer:BQuestion Status:Previous Edition24.1.14)When a lender refuses to make a loan, although borrowers are willing to pay the stated interestrate or even a higher rate, it is said to engage inA)constrained lending.B)strategic refusal.C)credit rationing.D)collusive behavior.Answer:CQuestion Status:Previous Edition24.1.15)When a lender refuses to make a loan, even though borrowers are willing to pay the statedinterest rate or even a higher rate, it is said to engage inA)specialized lending.B)strategic refusal.C)diversified lending.D)coercive behavior.E)none of the above.Answer:EQuestion Status:Previous EditionChapter 24 Risk Management in Financial Institutions 35324.1.16)Credit rationing occurs when a bankA)refuses to make a loan of any amount to a borrower, even when she is willing to pay ahigher interest rate.B)restricts the amount of a loan to less than the borrower would like.C)does either A or B of the above.D)does neither A nor B of the above.Answer:CQuestion Status:Previous Edition24.1.17)Because larger loans create greater incentives for borrowers to engage in undesirable activitiesthat make it less likely they will repay the loans, banksA)ration credit, granting borrowers smaller loans than they have requested.B)ration credit, charging higher interest rates to borrowers who want large loans than tothose who want small loans.C)ration credit, charging higher fees as a percentage of the loan to borrowers who wantlarge loans than to those who want small loans.D)do none of the above.Answer:AQuestion Status:Previous Edition24.1.18)When banks offer borrowers smaller loans than they have requested, banks are said toA)shave credit.B)discount the loan.C)raze credit.D)ration credit.Answer:DQuestion Status:Previous Edition24.1.19)Which of the following are not generally rate-sensitive assets?A)Securities with a maturity of less than one yearB)Variable-rate mortgagesC)Fixed-rate mortgagesD)All of the above are rate-sensitive assetsE)None of the above is a rate-sensitive assetAnswer:CQuestion Status:Previous Edition24.1.20)Liabilities that are partially, but not fully, rate-sensitive includeA)checkable deposits.B)federal funds.C)non-negotiable CDs.D)fixed-rate mortgages.E)money market deposit accounts.Answer:AQuestion Status:Previous Edition354 Mishkin/Eakins · Financial Markets and Institutions, Sixth Edition24.1.21)If a bank has more rate-sensitive liabilities than rate-sensitive assets, then a(n) _________ ininterest rates will _________ bank profits.A)increase; increaseB)increase; reduceC)decline; reduceD)decline; not affectAnswer:BQuestion Status:Previous Edition24.1.22)If a bank has more rate-sensitive assets than rate-sensitive liabilities, then a(n) _________ ininterest rates will _________ bank profits.A)increase; increaseB)increase; reduceC)decline; increaseD)decline; not affectAnswer:AQuestion Status:Previous Edition24.1.23)If a bank has _________ rate-sensitive assets than rate-sensitive liabilities, then a(n) _________in interest rates will increase bank profits.A)more; declineB)more; increaseC)less; increaseD)both A and CAnswer:BQuestion Status:Previous Edition24.1.24)The difference between rate-sensitive liabilities and rate-sensitive assets is known as theA)duration.B)interest-sensitivity index.C)interest-rate risk index.D)gap.Answer:DQuestion Status:Previous EditionFirst National BankAssets LiabilitiesRate-sensitiveFixed-rate$20 million$50 million $80 million$40 million Table 24.124.1.25)Referring to Table 24.1, First National Bank has a gap of _________.A)-30B)+30C)60D)0Answer:AQuestion Status:Previous EditionChapter 24 Risk Management in Financial Institutions 355 24.1.26)Referring to Table 24.1, if interest rates rise by 5 percentage points, then bank profits (measuredusing gap analysis) willA)decline by $0.5 million.B)decline by $1.5 million.C)decline by $2.5 million.D)increase by $1.5 million.Answer:BQuestion Status:Previous Edition24.1.27)Refer to Table 24.1. Assuming that the average duration of its assets is five years, while theaverage duration of its liabilities is three years, a rise in interest rates from 5% to 10% will causethe net worth of First National to _________ by _________ of the total original asset value.A)increase; 11%B)decline; 11%C)increase; 10%D)decline; 5%Answer:BQuestion Status:Previous EditionFirst National BankAssets LiabilitiesRate-sensitiveFixed-rate$40 million$50 million $60 million$40 million Table 24.224.1.28)Referring to Table 24.2, First National Bank has a gap of _________.A)-10B)10C)20D)0Answer:AQuestion Status:Previous Edition24.1.29)Referring to Table 24.2, if interest rates rise by 5 percentage points, then bank profits (measuredusing gap analysis) willA)decline by $0.5 million.B)decline by $1.5 million.C)decline by $2.5 million.D)increase by $2.0 million.Answer:AQuestion Status:Previous Edition356 Mishkin/Eakins · Financial Markets and Institutions, Sixth Edition24.1.30)Refer to Table 24.2. Assuming that the average duration of the bankʹs assets is four years, whilethe average duration of its liabilities is three years, a rise in interest rates from 5 percent to 10percent will cause the net worth of First National to _________ by _________ of the totaloriginal asset value.A)decline; 5%B)decline; 1.3%C)decline; 6.2%D)increase; 5%Answer:CQuestion Status:Previous Edition24.1.31)If First State Bank has a gap equal to a positive $20 million, then a 5 percentage point drop ininterest rates will cause profits toA)increase by $10 million.B)increase by $1.0 million.C)decline by $10 million.D)decline by $1.0 million.Answer:DQuestion Status:Previous Edition24.1.32)If First National Bank has a gap equal to a negative $30 million, then a 5 percentage pointincrease in interest rates will cause profits toA)increase by $15 million.B)increase by $1.5 million.C)decline by $15 million.D)decline by $1.5 million.Answer:DQuestion Status:Previous Edition24.1.33)Measuring the sensitivity of bank profits to changes in interest rates by multiplying the gaptimes the change in the interest rate is calledA)basic duration analysis.B)basic gap analysis.C)interest-exposure analysis.D)gap-exposure analysis.Answer:BQuestion Status:Previous Edition24.1.34)Measuring the sensitivity of bank profits to changes in interest rates by multiplying the gap forseveral maturity subintervals by the change in the interest rate is calledA)basic gap analysis.B)the segmented maturity approach to gap analysis.C)the maturity bucket approach to gap analysis.D)the segmented maturity approach to interest-exposure analysis.E)none of the above.Answer:CQuestion Status:Previous EditionChapter 24 Risk Management in Financial Institutions 35724.1.35)Duration gap analysisA)is a refinement of basic gap analysis that accounts for interest-rate changes over amultiyear period.B)is a refinement of basic gap analysis that accounts for how long a gap will last.C)is a complement to basic gap analysis that accounts for the effect of interest rate changeson market value.D)is a complement to basic gap analysis that accounts for the influence of partiallyrate-sensitive assets.Answer:CQuestion Status:Previous Edition24.1.36)Duration analysis involves comparing the average duration of the bankʹs _________ to theaverage duration of its _________A)securities portfolio; non-deposit liabilities.B)loan portfolio; non-deposit liabilities.C)loan portfolio; rate-sensitive liabilities.D)rate-sensitive assets; rate-sensitive liabilities.E)assets; liabilities.Answer:EQuestion Status:Previous Edition24.1.37)To use the concept of duration to analyze the effect of changes in interest rates on the marketvalue of an asset, a bank manager would multiplyA)the negative of the duration of the asset by the change in the interest rate, Δi.B)the negative of the duration of the asset by Δi/(1 +i).C)the duration of the asset by the change in the interest rate, Δi.D)the duration of the asset by Δi/(1 +i).Answer:BQuestion Status:Previous Edition24.1.38)If a bank has a duration gap of 2 years, then a rise in interest rates from 6 percent to 9 percentwill lead toA)a rise in the market value of its net worth of 5.66 percent.B)a rise in net interest income of 5.66 percent.C)a fall in the market value of its net worth of 5.66 percent.D)a fall in net interest income of 5.66 percent.E)an unknown change.Answer:CQuestion Status:Previous Edition24.1.39)If a bank has a duration gap of 2 years, then a fall in interest rates from 6 percent to 3 percentwill lead toA)a rise in the market value of its net worth of 5.66 percent.B)a fall in the market value of its net worth of 5.66 percent.C)a rise in net interest income of 5.66 percent.D)a fall in net interest income of 5.66 percent.E)an unknown change.Answer:AQuestion Status:Previous Edition358 Mishkin/Eakins · Financial Markets and Institutions, Sixth Edition24.1.40)If a decline in interest rates causes the market value of a bankʹs net worth to rise, then the bankmust have aA)negative duration gap.B)positive duration gap.C)negative gap.D)positive gap.Answer:BQuestion Status:Previous Edition24.1.41)If a rise in interest rates causes the market value of a bankʹs net worth to rise, then the bankmust have aA)negative duration gap.B)positive duration gap.C)negative gap.D)positive gap.Answer:AQuestion Status:Previous Edition24.1.42)One problem with duration gap analysis is that itA)is calculated assuming that the yield curve is flat.B)is calculated assuming that the yield curve does not change.C)does not measure the sensitivity of net worth to interest rate changes.D)does not measure the sensitivity of income to interest rate changes.E)applies only to financial institutions.Answer:AQuestion Status:Previous Edition24.1.43)One problem with basic gap analysis is that itA)is calculated assuming interest rates on all maturities are equal.B)is calculated assuming interest rates on all maturities change by equal amounts.C)measures the sensitivity of net worth to interest rate changes.D)does not measure the sensitivity of income to interest rate changes.E)applies only to financial institutions.Answer:BQuestion Status:Previous Edition24.1.44)A bank manager concerned about interest income who expects interest rates to rise and whoknows the bank currently has a positive gap should _________ rate-sensitive assets and_________ rate-sensitive liabilities.A)increase; increaseB)decrease; increaseC)decrease; decreaseD)increase; decreaseAnswer:DQuestion Status:Previous EditionChapter 24 Risk Management in Financial Institutions 35924.1.45)A bank manager concerned about interest income who expects interest rates to fall and whoknows the bank currently has a positive gap should _________ rate-sensitive assets and_________ rate-sensitive liabilities.A)increase; increaseB)decrease; increaseC)decrease; decreaseD)increase; decreaseAnswer:BQuestion Status:Previous Edition24.2True/False24.2.1)If a bank has more rate-sensitive liabilities than assets, then an increase in interest rates willreduce bank profits.Answer:TRUEQuestion Status:Previous Edition24.2.2)The difference between rate-sensitive liabilities and rate-sensitive assets is known as theduration gap.Answer:FALSEQuestion Status:Previous Edition24.2.3)If a bank has a negative gap, then a decrease in interest rates will increase income.Answer:TRUEQuestion Status:Previous Edition24.2.4)Banks face the problem of adverse selection in loan markets because bad credit risks are theones most likely to seek bank loans.Answer:TRUEQuestion Status:Previous Edition24.2.5)Due-on-sale clauses in loan contracts reduce moral hazard.Answer:FALSEQuestion Status:Previous Edition24.2.6)A correspondent account is sometimes required of a borrower as a condition for a loan.Answer:FALSEQuestion Status:Previous Edition24.2.7)Credit rationing reduces adverse selection problems.Answer:TRUEQuestion Status:Previous Edition24.2.8)Credit rationing occurs when lenders charge higher interest rates on the loans they make toriskier borrowers.Answer:FALSEQuestion Status:Previous Edition360 Mishkin/Eakins · Financial Markets and Institutions, Sixth Edition24.2.9)Developing and maintaining long-term customer relationships help to reduce banksʹ costs ofscreening and monitoring borrowers.Answer:TRUEQuestion Status:Previous Edition24.2.10)Measuring the sensitivity of bank profits to changes in interest rates by multiplying the gap forseveral maturity subintervals by the change in the interest rate is called duration analysis.Answer:FALSEQuestion Status:Previous Edition24.2.11)If interest rates rise by 5 percentage points, then bank profits (measured using gap analysis)will increase regardless of the income gap.Answer:FALSEQuestion Status:Previous Edition24.3Essay24.3.1)What is the difference between credit risk and interest-rate risk?Question Status:Previous Edition24.3.2)How is credit risk related to the concepts of adverse selection and moral hazard?Question Status:Previous Edition24.3.3)What steps do banks take to reduce their exposure to credit risk?Question Status:Previous Edition24.3.4)How do the concepts of adverse selection and moral hazard explain the credit riskmanagement principles that banks adopt?Question Status:Previous Edition24.3.5)What is gap analysis and why is it important to a bank?Question Status:Previous Edition24.3.6)What is duration gap analysis and why is it important to a bank?Question Status:Previous Edition24.3.7)Explain how banks benefit from long-term customer relationships.Question Status:Previous Edition24.3.8)Explain how banks benefit from specialization in lending.Question Status:Previous Edition24.3.9)What special assumptions do income and duration gap analyses make about interest ratechanges and the yield curve?Question Status:Previous Edition。
第24章动态模型(Dynamic Models)动态电动机起动、暂态稳定性和发电机起动分析中都要用到电动机动态模型。
发电机动态模型和一些控制单元(如励磁器和调速器等)只在暂态稳定分析中用到。
另外,电动机起动分析和暂态稳定分析也要求有负荷转矩特性。
ETAP为各种分析提供了各种感应电机和同步电机模型以及全面的励磁器和调速器库。
在动态电机加速分析中,只有加速的电动机需要动态模型,也就是说,发电机,励磁器和调速器都不需要动态模型。
在暂态稳定分析中,所有的发电机,励磁器和调速器都是动态模型的。
有动态模型的电动机和在分析案例中被设为动态模型的电动机都会被动态模拟。
在发电机起动和依赖于频率的暂态稳定分析中,所有的发电机、励磁器和调速器都必须是依赖于频率的模型。
本章描述了不同类型的电机模型,电机控制单元模型和负荷模型并解释了他们在电动机起动和暂态稳定性分析中的应用。
也介绍了在选择模型和设定模型参数时所用到的工具。
感应电机模型部分介绍了五种不同的感应电机模型和这些模型的依赖于频率形式,分别是电路模型 (Single1、Single2、DBL1、DBL2) 和特性曲线模型。
在同步电机模型部分,介绍了五种不同的同步电机模型和这些模型的依赖于频率形式。
这些模型分别是等值电路模型,隐极电机的暂态模型,隐极电机的次暂态模型,凸极电机的暂态模型和凸极电机的次暂态模型。
电动机起动分析和暂态稳定性分析也把等效电网系统模拟成一个等值电机。
在等效电网部分介绍了等效电网系统的模型。
在励磁器和自动电压调节器模型部分定义不同类型的励磁器和自动电压调节器模型,包括标准IEEE模型和商用特有模型。
在调速器-涡轮部分列举了以IEEE标准和商用产品手册为准的调速器-涡轮模型。
最后,在机械负荷部分介绍了不同类型的负荷模型。
24.1 感应电机模型(Induction Machine Models)ETAP提供了五种在感应电机设计中较常用的感应电机模型。
CHAPTER 24 PERFORMANCE MEASUREMENT AND RESPONSIBILITY ACCOUNTING*See additional information on next page that pertains to these quick studies, exercises and problems. SP refers to the Serial ProblemES refers to Excel SimulationsAdditional Information on Related Assignment MaterialConnectA vailable on the instructor’s course-specific website) repeats all numerical Quick Studies, all Exercises and Problems Set A. Connect also provides algorithmic versions for Quick Study, Exercises and Problems. It allows instructors to monitor, promote, and assess student learning. It can be used in practice, homework, or exam mode.Connect InsightThe first and only analytics tool of its kind, Connect Insight is a series of visual data displays that are each framed by an intuitive question and provide at-a-glance information regarding how an instructor’s class is performing. Connect Insight is available through Connect titles.The Serial Problem (SP) for Success Systems continues in this chapter.General LedgerAssignable within Connect, General Ledger (GL) problems offer students the ability to see how transactions post from the general journal all the way through the financial statements. Critical thinking and analysis components are added to each GL problem to ensure understanding of the entire process. GL problems are auto-graded and provide instant feedback to the student.Excel SimulationsAssignable within Connect, Excel Simulations allow students to practice their Excel skills—such as basic formulas and formatting—within the context of accounting. These questions feature animated, narrated Help and Show Me tutorials (when enabled). Excel Simulations are auto-graded and provide instant feedback to the student. Synopsis of Chapter RevisionsNEW opener—Ministry of Supply and entrepreneurial assignment.Reorganized chapter.Revised discussion of performance evaluation and decentralization.Revised discussion of Kraft Heinz responsibility centers.Revised exhibit on responsibility accounting.Revised discussion of responsibility accounting reports.Added NTKs on responsibility accounting, cost allocations, and balanced scorecard.Revised discussion of indirect expense allocations.New exhibit and discussion of general model of expense allocation.New exhibit on common allocation bases for indirect expenses.Revised discussion of preparing departmental income.New exhibit and formula for computing departmental income.Added short section on transfer pricing to the chapter.New Sustainability section with discussion of General Mills, Target and performance reporting, and Ministry of Supply example.Chapter OutlineNotes I.Responsibility AccountingA. Performance Evaluationrge companies are easier to manage if divided into smallerunits called divisions, segments, or departments.2.In decentralized organizations, decisions are made by unitmanagers rather than top management.3.In responsibility accounting, unit managers are evaluated onlyon what they are responsible for.4.The methods of performance evaluation vary for cost centers,profit centers and investment centers.a.Cost center−incurs cost or expenses without directlygenerating revenues (e.g. manufacturing department andservice department).b.Profit center−incurs costs and generates revenues (e.g.product centers).c.Investment center−incurs costs, generates revenues and isresponsible for effectively using center assets.5.Basis for evaluating performance:a.Cost center managers are evaluated on their success incontrolling costs compared to budgeted costs. Profit center:ability to generate more revenue than expenses.b.Profit center managers are evaluated on their success ingenerating income.c.Investment center managers are evaluated on their use ofinvestment-center assets to generate income.II.Controllable versus Uncontrollable CostsA.Controllable Costs -1.Those which a manager has the power to determine or at leastsignificantly affect the amount incurred.B. Uncontrollable costs –1.Are not within the manager’s control.2. A manager’s performance is evaluated using responsibilityreports that describe the department’s activities in terms ofcontrollable costs3.Distinguishing between controllable and uncontrollable costsdepends on the particular manager and the time period underanalysis.4.All costs are controllable at some level of management if the timeperiod is sufficiently long;5.Good judgment is required when identifying controllable costs.Chapter OutlineNotesC.Responsibility Accounting Performance Report1.Reports actual expenses that a manager is responsible for andtheir budgeted amounts.a.Management’s analysis of differences between actual andbudget often results in corrective actions.ed by upper management to evaluate effectiveness oflower-level managers in controlling costs.c.Recognizes that control over costs and expenses belongs toseveral layers of management.2.Responsibility Accounting Reporta.Provide relevant information for each management level.b.At lower levels, managers have limited responsibilities andtherefore fewer controllable costs.c.Responsibility and control broaden for higher-levelmanagers.III.Profit CentersA.The responsibility report focuses on how well each departmentcontrolled costs and generated revenues.B.The departmental income statement is a common way to reportprofit center performance.C.When computing department profits, two key accounting challengesinvolve allocating expenses:1.How to allocate indirect expenses, such as rent and utilities whichbenefit several departments.2.How to allocate service department expenses, such as payroll orpurchasing, that perform services that benefit severaldepartments.D.Direct and Indirect Expenses1.Direct Expenses are readily traced to a department.a.Incurred for sole benefit of that one department; no allocationrequired.b.Often, but not always, controllable costs.2.Indirect Expenses are incurred for joint benefit of more than onedepartment; can’t be readily traced to just one department.a.Allocated across departments benefiting from them.b.Ideally allocated using a cause-effect relation or, if cause-effect relation cannot be identified, allocated on a basisapproximating the benefit received by each department.c.Typically considered uncontrollable costs.Chapter OutlineNotesE.General Model – indirect and service department expenses areallocated across departments benefiting from them. Allocated using acause-effect relation. Sometimes hard to identify.1.Allocated Cost = Total Cost to Allocate x Percentage ofAllocation Base Used.F.Allocating Indirect Expenses – allocation bases vary acrossdepartments and organizations. Managers must use careful judgmentin developing allocation bases. Commonly used allocation bases:1.Wages and salaries –allocated using relative amount of hoursworked in each department.2.Rent and Utilities allocated based on portion of floor spaceoccupied. More valuable location may charge department higherrate.3.Advertising – allocated using a percentage of total sales.4.Depreciation – allocated using hours of depreciable asset used.G.Service Department expenses –provide support to an organization’soperating departments. Common allocation bases:1.Office, personnel, and payroll expenses – allocated based onnumber of employees in each department.2.Purchasing costs – allocated based on dollar amount of purchasesor number of purchase orders processed.3.Maintenance expenses – allocated based on square footage.H.Departmental Income Statements1.Departmental income is computed using the following formula:Departmental income = Dept. sales – Dept. direct expenses –Allocated indirect expenses – Allocated service dept. expenses.2.Four Steps for allocating costs and preparing departmentalincome statements:a.Step one – accumulate revenues and direct and indirectexpenses by department. Involves collecting the necessarydata from general company and departmental accounts.i.Direct and indirect expenses include salaries, depreciationand supplies expenses.b.Step two – allocate indirect expenses across both service andoperating departments.i. Uses a departmental expense allocation spreadsheetshown in Exhibit 24.10.ii.After selecting allocation bases, indirect expenses arerecorded in company accounts and allocated to bothoperating and service departments.Chapter OutlineNotesc.Step three – allocate service department expenses tooperating departments using a departmental expenseallocation spreadsheet. After service department costs areallocated, no expenses remain in the service departments.d.Step four – prepare departmental income statements using thedepartmental expense allocation spreadsheet.i. Actual service department expenses are compared withbudgeted amounts to help assess cost center performance.ii.Amounts in the operating department columns are used toprepare departmental income statements. (Exhibit 24.15)I.Departmental Contribution to Overhead (see Exhibit 24.12)1.Departmental income statements not always best for evaluatingeach profit center’s performance especially when indirectexpenses are a large portion of total expenses.2.Evaluate using departmental contributions to overhead a reportof the amount of sales less direct expenses.3.Behavioral Aspects of Departmental Performance Reports –a.Indirect expenses are typically uncontrollable, so a better wayto evaluate is using departmental contribution to overhead.b.Including indirect expenses in department manager’sperformance evaluation can lead to the manager being morecareful in using service departments.c.Some companies allocate budgeted service department costsso operating departments are not held responsible forexcessive costs from service departments.IV.Investment CenterA.Financial Performance Evaluation Measures include:1.Return on investment, return on assets, computed as investmentcenter income / by investment center average invested assets.2.Residual income – Expressed in dollars. Encourages divisionmanagers to accept all opportunities that return more than targetincome. Computed as investment center income – targetinvestment center income.3.Profit margin and investment turnover – split return oninvestment into two measures – profit margin and investmentturnover.a.Profit margin measures income earned per dollar of salescomputed as investment center income divided by investmentcenter sales. Usually use income before tax. Expressed as apercent.b.Investment turnover measures how efficiently an investmentcenter generates sales from its invested assets. Calculated asinvestment center sales divided by investment center averageassets. Expressed as the number of times assets wereconverted into sales.Chapter OutlineNotes4.Nonfinancial Performance Evaluation Measures –using solelyfinancial measures has limitations. Companies can considernonfinancial measures to help in evaluating division manager’sperformance.5.Balanced Scorecard: system of performance measures,including nonfinancial measures used to assess company anddivision manager performance. Requires managers to think oftheir company from four perspectives.a.Customer: what do they think of us?b.Internal process: which of our operations are critical?c.Innovation and learning: how can we improve?d.Financial: what do our owners think of us?V.Decision Analysis Cycle Time and Cycle EfficiencyA.As lean manufacturing practices help companies move toward justin time manufacturing it is important for companies to reduce thetime it takes to manufacture its products and improve efficiency.1.Cycle time measures the time element which describes the timeit takes to produce a product or service.Cycle time = Process + Inspection + Move + WaitTime Time Time Timea.Process time is considered value-added time – it is the onlyactivity in cycle time that adds value to the product from thecustomer’s perspective. The other three activities areconsidered non-value-added time: they add no value to thecustomer.2.Cycle Efficiency measures production efficiency. It is the ratioof value added time to total cycle time.Cycle Efficiency = Value added timecycle timea.If the cycle efficiency is low, the company should evaluatethe production process to see if it can identify ways toreduce the non-value added activities.VI.Appendix 24A – Cost Allocations uses the general model of costallocation to show how the cost allocations in Exhibits 24.10 and 24.11for A-1 Hardware. Rent expense, utilities expense, advertising expenseand insurance expense are allocated first. Then, the two servicedepartment’s expenses are allocated to the three operating departments.Chapter OutlineNotes VII.Appendix 24B – Transfer PricingThe price used to record transfers between divisions in the samecompany is called a transfer price. Can be used in cost, profit andinvestment centers.A.If there is no excess capacity, the internal supplier will not accept atransfer price less than the market price. This is called market basedtransfer pricing.B.If there is excess capacity, the internal supplier should accept a pricebetween the costs to manufacturer the part and the market price.This is called cost based transfer pricing.C.Other issues to consider in determining transfer prices include:1.Market price may not exist2.Cost controls3.Division managers’ negotiation4.Nonfinancial factors to consider include: quality control,reduced lead times and impact on employee morale.III.Appendix 24C – Joint CostsA.Joint Costs−the costs incurred to produce or purchase two or moreproducts at the same time; similar to indirect expense in that it’sshared across more than one cost object.1.Ignored when deciding to sell product as is or process further.2.Allocated to different products produced from it when total costof each product must be estimated (e.g., preparation of GAAPfinancial statements).3.Allocation basesa.Physical basis−allocates joint costs using physicalcharacteristics such as ratio of pounds, cubic feet or gallonsof each joint product to the total pounds, cubic feet orgallons of all joint products flowing from the cost; does notreflect the extra value flowing into some products or theinferior value flowing into others. Not the preferred method.b.Value basis−allocates joint cost in proportion to the salesvalue of the output produced by the process at the “split-offpoint”.Chapter 24 Alternate Demo ProblemJack and Susan Roberts own a farm that produces potatoes. Based on a review of the income statement shown below, Jack remarked that they should have fed the No. 3 potatoes to the pigs; then they would have avoided the loss from the sale of the those potatoes.JACK AND SUSAN ROBERTSIncome from the Production and Sale of PotatoesFor Year Ended December 31, 20xxResults by GradeSales by grades:No. 1, 300,000 lbs. $0.045 per lb.No. 2, 500,000 lbs. $0.04 per lb.No. 3, 200,000 lbs. $0.03 per lb.CombinedCosts:Land preparation, seed,planting,cultivating @ $0.01422 per lb.Harvesting, sorting, grading@ $0.01185 per lb.Marketing @ $0.00415 per lb.Total costsNet income (or loss)Jack and Susan divided their costs among the grades on a per pound basis, because their records do not show cost per grade. However, their records did show that $4,020 of the $4,150 of marketing costs represented the cost of placing the No. 1 and No. 2 potatoes in bags and hauling them to the warehouse of the produce buyer. Bagging and hauling costs were the same for both grades. The remaining $130 represented the cost of loading the No.3 potatoes into the trucks of the potato starch factory that bought these potatoes in bulk and picked them up at the farm.Required:Prepare an income statement that will better show the results of producing and marketing the each of the grades of potatoes.Chapter 24 Alternate Demo Problem: SolutionJACK AND SUSAN ROBERTSIncome from the Production and Sale of PotatoesFor Year Ended December 31, 20xxRevenue from sales:Costs:Land preparation, seed,planting, cultivatingHarvesting, sorting, gradingMarketingTotal costsNet incomeCOST ALLOCATIONSLand preparation, seed, planting, andcultivating:No. 1: $13,500 / $39,500 x $14,220 = No. 2: $20,000 / $39,500 x $14,220 = No. 3: $ 6,000 / $39,500 x $14,220 = $ 4,8607,2002,160 $14,220Harvesting, sorting, and grading:No. 1: $13,500 / $39,500 x $11,850 = No. 2: $20,000 / $39,500 x $11,850 = No. 3: $ 6,000 / $39,500 x $11,850 = $ 4,0506,0001,800 $11,850Marketing:No. 1: $13,500 / $33,500 x $4,020 = No. 2: $20,000 / $33,500 x $4,020 = $1,620 2,400Subtotal bagging and hauling costs 4,020 No. 3: Loading costs 130$4,150。
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2—羟基丙酸正217cho6123丙酯218丙二酸二乙酯cho7124 、chooc—ch—cooch252252—丁酮酸异丁219cho8143酯220乙酸对甲酚酯cho9102221甲酸氯甲,醇,酯chocl232222异戊酸异戊酯cho10202、,ch,chcoo,ch,ch,ch,32232乙二酸乙二,醇,223cho444酯三硝酸甘油酯224chno3539,硝化甘油,硝基化合物225硝基苯chno652、、ch—no652226硝基甲烷chnoch—no、chno323232227硝基乙烷chnoch—no、chno、chchno252252252322 2,4,6—三硝基228chno7536甲苯,tnt,229,—硝基萘chno1072230,—硝基萘chno10721,8—二硝基萘231chno106242321,5—二硝基萘chno10624糖类233葡萄糖cho6126、choh,choh,cho24234果糖chochoh,choh,cochoh6126232235蔗糖chocho122211122211236麦芽糖chocho122211122211237淀粉,cho,,cho,6115n122211n238纤维素,cho,6115n、[cho,oh,]6723n氨基酸甘氨酸239chno252,氨基乙酸,丙氨酸240chno372,—氨基丙酸苯丙氨酸241,—氨基—,—chno8112苯基丙酸谷氨酸242chno594,—氨基戊二酸高分子化合物243聚乙烯,ch,24n244聚丙烯,ch,36n245聚氯乙烯,chcl,23n246聚苯乙烯,ch,88n、有机玻璃,聚甲247,cho,582n基丙烯酸甲酯,、聚丙烯腈248,ch,23n,人造羊毛,聚四氟乙烯249,cf,24n,塑料王,250酚醛塑料,电木,,cho,76n251脲醛塑料,电玉,,chno,42n252环氧树脂,cho,19203n聚对苯二甲酸253乙二醇酯,cho,10103n,涤纶、的确良,聚己内酰胺254,chno,611n,绵纶,聚乙烯醇缩甲255醛,cho,582n,维尼纶,256丁苯橡胶,ch,1214n257顺丁橡胶,ch,46n258氯丁橡胶,chcl,45n259丁腈橡胶,ch,79n260聚硫橡胶,chs,244n261硅橡胶,chsio,26n262丁基橡胶异戊橡胶263,ch,58n,合成天然橡胶,264聚乳酸,cho,332n265聚丙酸甲酯,cho,462n266聚丙酸正丁酯,cho,7122n267聚乙丙丁酯,ch,918n268人造象牙,cho,2n289聚环氧乙烷,cho,24n290聚乙炔,ch,22n291,ch,916n292戊苯橡胶,ch,1316n293,ch,1010n294,ch,1010n295nomex纤维,chno,141022n296,cho,15166n其它297二恶英,chocl,12424n298维生素c,cho,686n299立方烷,ch,88n2,3,4—三羟基苯甲酸—2,3—300,cho,14109n二羟基—5—羧基苯,酚,酯301苯磺酸chso663302对氨基苯磺酸chnso1093303吗啡chno17173304葡萄糖二酸cho6108三硝酸纤维素305,chno,6739n酯丙二酰氯306chocl3222307丙二酰胺chno36223,7—二甲基—308cho10162,6—辛二烯醛三聚甲醛309cho363310氨基树脂chn66621 / 21__来源网络整理,仅作为学习参考。
Ch 24Electric PotentialOne goal of physics is to identify basic forces in ourworld, such as the electric force we discussed in Ch. 21.A related goal is to determine whether a force is conservative—that is, whether we can find a potential energy to be associated with the force.The motivation (動機) for associating a potentialenergy with a force is that we can then apply the principle of the conservation of mechanical energy to closed systems involving the force. This extremely powerful principle allows us to calculate the results of experiments for which force calculations alone would be very difficult.Experimentally, physicists and engineers discoveredthat the electric force is conservative and thus has an associated electric potential energy.When an electrostatic force acts between two or more charged particles within a system of particles, we can assign an electric potential energy U to the system. If the system changes its configuration(組態) from an initial state i to a final state f, the electrostatic force (帶電粒子之間)does work W (≡∫F•d S)on the particles. The resulting change in the potential energy of the system isΔU=U f-U i=-W(24-1) [保守力(重力、彈力、電力)作功(等速之下)造成系統位能變化(減少): W=-ΔU=-(U f-U i)]As with other conservative forces, the work done by the electrostatic force is path independent.Suppose a charged particle within the system moves from point i to point f while an electrostatic force between it and the rest of the system acts on it. Provided the rest of the system does not change, the work W done by the force on the particle is the same for all paths between points i and f.For convenience, we usually take the reference configuration of a system of charged particles to be that in which the particles are all infinitely separated from one another. Also, we usually set the corresponding reference potential energy to be zero(因為所有帶電粒子都相距無窮遠,當然之間電力為零,因此可設此時系統電位能為零).Suppose that several charged particles come together from initially infinite separations(initial state i) to form a system of neighboring particles (final state f).Let the initial potential energy U i=0, and let W∞representthe work done by the electrostatic forces between the particles during the move from initial state (相距∞)to final state (相距有限遠,此時之間電力≠0,可設系統位能≠0). Then from Eq. 24-1, the final potential energy U f≡U of the system isΔU = U f–U i= -W (24-1)U = -W∞(24-2)功的單位ΔU = U f–U i= -W (24-1)Adjacent points that have the same electric potential form an equipotential surface.No net work W is done on a charged particle by an electric field when the particle moves between two points i and f on the same equipotential surface. This follows from Eq. 24-7, which tells us that W must be zero if V f=V i.Because of the path independence of work(and thus of potential energy and potential), W=0 for any path connecting points i and f on a given equipotential surface regardless of whether that path lies entirely on that surface.1) The work done by the electric field on a charged particle as the particle moves from one end to the other of paths I and II is zero because each of these paths begins and ends on the same equipotentialsurface.2) The work done as the charged particle moves from one end to the other of paths III and IV is not zero but has the same value for both these paths because the initial and finalpotentials are identical for the two paths.e.g.DiscussionFrom symmetry, the equipotential surfaces produced by a point charge or a spherically symmetrical charge distribution are a family of concentric spheres.Equipotential surfaces are always perpendicular to electric field lines and thus to E, which is always tangent to these lines. If E were not perpendicular to an equipotential surface, it would have a component lying along that surface. This component would then do work on a charged particle as it moved along the surface.¨By Eq. 24-7 work cannot be done if the surface is truly an equipotential surface [V i=V f, W=0]; the only possible conclusion is that E must be everywhere perpendicular to the surface.perpendicularvf v可得(V=0, r=∞)∞單位正電荷q3q q21rO p = qd 其中p為電偶極矩22Many molecules, such as water, have permanent electric dipole moments. In other molecules (called nonpolar molecules) and in every isolated atom, the centers of the positive and negative charges coincide and thus no dipole moment is set up. If we place an atom or a nonpolar molecule in an external E-field, the field distorts the electron orbits and separates the centers of positive and negative charge. Because the electrons are negatively charged, they tend to be shifted in a direction opposite the field. This shift sets up a dipole moment that points in the direction of the field. This dipole moment p is said to be induced by the field, and the atom or molecule is then said to be polarized (極化) by the field. When the field is removed, the induced dipole moment pind and the polarization disappear.23Continuous distribution of charge (電荷連續分佈) → 將電荷 連 續 分 佈 源 切 割 成 無 數 細 小 微 分 電 荷 元 素 (dq) → dV dq=λds=σdA=ρdvPdV =1 4 πε0dq rdv dqr→ Use calculus (微積分) to calculate V已在§24-6假設無窮遠處之電位為024V=? λ dq=λdx假設2526取微分元素環dq27In Sec. 24-5, 已知 electric field 可求出 V In this section, 已知 electric potential 可求出E E=?A positive test charge q0 moves through a displacement ds from one equipotential surface to the adjacent surface.28(1) From Eq. 24-7, we see that the work the electric field does on the test charge during the move is dW=–q0dV. (2) From Eq. 24-16 and Fig. 24-14, we see that the work done by the electric field may also be written as the scalar product dW=(q0E)•ds, or q0E(cosθ)ds.Fig. 24-142930For any value of z, the direction of E must be along that axis because the disk has circular symmetry about that axis →只有E z≠0, E x=E y=0(1) 由q 1建立一電位雙點電荷粒子系統具有之電位能由q 1建立(2)<proof><example>(a) A plot of V(r) both inside and outside a charged spherical shell of radius 1.0 m. (b) A plot of E(r) for the same shell.On nonspherical conductors, a surface charge does not distribute itself uniformly over the surface of the conductor. At sharp points or sharp edges, the surface charge density—and thus the external electric field, which is proportional to it—may reach very high values (導體尖端處電荷分佈非常集中,使得電荷密度相當高,故電場於該尖端附近相當強).The air around such sharp points oredges may become ionized(離子化),producing the corona (冠狀) discharge.Such corona discharges, like hair thatstands on end, are often the precursors(前兆) of lightning strikes. In such circumstances, it is wise to encloseyourself in a cavity inside a conductingshell, where the electric field is guaranteedto be zero. A car is almost ideal.41HomeworksAns:Ans:Ans:Ans:Ans:Ans:Ans:Ans: -6.20 V.Ans: 3.24×10-2V。
第24章多用途时钟信号生成器(MCG)24.1 介绍多用途多用途时钟信号生成器(MCG)模块为MCU提供多种时钟源选项。
这个模块由一个频率环锁(FLL)和一个相位环锁(PLL)组成。
FLL可由一个内部或外部参考时钟控制,而PLL可由一个外部参考时钟控制。
这个模块要么在FLL或PLL输出时钟之间,要么在内部参考时钟或外部参考时钟之间选择一个时钟源以作为MCU系统时钟。
MCG操作与晶体振荡器有关,其中晶体振荡器允许一个外部晶体、陶瓷共振器或外部时钟源产生外部参考时钟。
24.1.1 特性MCG模块的关键特性:◆频率环锁(FLL)。
●数控石晶(DCO)。
●DCO可设置时钟范围有四个。
●低频率外部参考时钟源的编程选项和最大DCO输出频率。
●内外参考时钟可以作为FLL源。
●可以作为其他片上外设的时钟源。
◆相位环锁(PLL)●电压控制振荡器(VCO)●外部参考时钟作为PLL时钟源。
●VCO频分模块。
●相位/频率检测器。
●集成环过滤器。
●可以作为其他片上外设的时钟源。
◆内参考时钟生成器●9个微调位的精确慢时钟●4个微调位的快时钟●可以被用作FLL的时钟源。
在FEI模式下,只有慢内参考时钟(IRC)可以被用作FLL源。
●无论是快时钟还是慢时钟都不能用作MCU的时钟源●可以作为其他片上外设的时钟源。
◆低功耗的石晶时钟发生器位MCG外部参考提供控制信号:●HGO,RANGE,EREFS◆从晶振获得外部时钟●可被用作FLL或PLL的时钟源●可被用作MCU的时钟源◆从RTC获得外部时钟●只能作为FLL的时钟源●只能选择MCU的时钟源◆带有重置请求能力的外部时钟监视器,可以在FBE,PEE,BLPE或者FEE模式下对外部时钟进行监测◆在PLL中使用的有中断请求能力的锁检测器◆外时钟参考的内参考时钟自动裁切功能(ATM)。
◆FLL和PLL的参考分频。
◆为其他片上设备提供时钟源的MCG PLL 时钟(MCGPLLCLK)◆为其他片上设备提供时钟源的MCG FLL时钟(MCGPLLCLK)◆为其他片上设备提供时钟源的MCG Fixed Frequency时钟(MCGPLLCLK)◆为其他片上设备提供时钟源的MCG 内参考时钟(MCGPLLCLK)图24-1 多用途时钟生成器(MCG)框图24.1.2 运行模式MCG共有九中运行模式:FEI,FEE,FBI,FBE,PEE,BLPI,BLPE,和终止模式。
24个声母的正确读法声母,是汉语拼音系统中的一个重要组成部分,它是识别汉字音节的基本元素之一。
汉语拼音共有24个声母,它们分别是b, p, m, f, d, t, n, l, g, k, h, j, q, x, zh, ch, sh, r, z, c, s, y, w。
正确掌握这24个声母的读音,对于学好汉语拼音和提高中文水平具有重要意义。
本文将详细介绍24个声母的正确读法。
1. b:发音时,嘴唇紧闭,气流从口腔中间猛地排出,发出一声短促的爆破音。
如“笔、报、八”。
2. p:发音时,与b类似,但唇部更紧闭,气流更猛烈,发出声音更清脆的爆破音。
如“批、披、盘”。
3. m:发音时,唇部紧闭,声音从鼻腔中发出,是唇鼻音。
如“妈、面、木”。
4. f:发音时,嘴唇稍微张开,舌头轻轻触到下齿,气流从口中排出,发出轻微摩擦声。
如“飞、非、凤”。
5. d:发音时,舌头抵住上牙龈,气流从口中猛烈排出,发出一个短促的爆破音。
如“的、大、地”。
6. t:与d类似,但舌头抵住上牙齿,气流更猛烈,发出声音更清脆的爆破音。
如“特、题、天”。
7. n:发音时,舌尖抵住上齿龈,气流从鼻腔中排出,是舌齿鼻音。
如“难、年、女”。
8. l:发音时,舌尖抵住上齿龈,舌面平铺,气流从舌面两侧排出,发出舌侧音。
如“路、来、绿”。
9. g:发音时,口腔中气流受到喉部的阻碍,压力逐渐增大,然后突然爆破,发出一个短促的声音。
如“狗、高、哥”。
10. k:与g类似,但口腔中的气流更猛烈,发出声音更清脆的爆破音。
如“卡、考、客”。
11. h:发音时,口腔中气流从喉部冲出,与声带摩擦,发出一个轻微的嘶声。
如“好、汉、红”。
12. j:发音时,舌尖先抵住上齿龈,然后突然离开,气流从口中排出,发出一个清脆的爆破音。
如“家、机、鸡”。
13. q:与j类似,但口腔中的气流更猛烈,发出声音更清脆的爆破音。
如“切、七、球”。
14. x:与q类似,但发音时舌头的位置稍微向后移动一点,舌尖抵住上腭,发出一个清脆的爆破音。
24声母字母表声母、韵母和整体认读音节是汉语拼音的三大要素,其中声母指的是以元音和辅音开头的音节,是汉语拼音的重要组成部分。
中国的汉语拼音制度规定了有24个声母字母,它们分别是:b、p、m、f、d、t、n、l、g、k、h、j、q、x、zh、ch、sh、r、z、c、s、y、w、yi 。
一、声母:1、辅音b、p、m、f、d、t、n、l:b:表示清爆音,发音时双唇分开,上下齿略有发出爆音时的尖端,舌位在双齿之间,声带震动。
如:ban(班),bi(比)。
p:表示清爆音,发音时双唇尽量接近,上下齿接近,舌位在上下齿之间,声带震动。
如:pan(叛),pi(皮)。
m:表示清合音,发音时双唇尽量接近,上唇显眉,下唇收起,舌位在双齿之间,唇齿表达音,声带震动。
如:man(满),mi(米)。
f:表示清爆音,发音时双唇稍微接近,上下唇稍微分开,舌位在上下齿之间,唇齿表达浊音,声带震动。
如:fan(番),fu(服)。
d:表示清爆音,发音时双唇尽量接近,上下齿略有发出爆音时的尖端,舌位在双齿之间,唇齿表达浊音,声带震动。
如:dan(但),di(底)。
t:表示清爆音,发音时双唇稍微接近,上下齿分开,舌位在上下齿之间,唇齿表达浊音,声带震动。
如:tan(叹),ti(体)。
n:表示清合音,发音时双唇尽量接近,上唇显眉,下唇收起,舌位在双齿之间,唇齿表达音,声带震动。
如:nan(难),ni(尼)。
l:表示清合音,发音时唇张得略宽,舌位在双齿之间,唇齿表达音,声带震动,发出混合清音。
如:lan(烂),li(里)。
2、辅音g、k、h、j、q、x:g:表示音,发音时双唇略张,上下齿靠的很近,舌位在双齿之间,唇齿表达浊音,舌头稍稍向上拱形,声带震动。
如:gan(赶),gu估)。
k:表示音,发音时双唇略张,上下齿略有间隔,舌位在上下齿之间,唇齿表达浊音,舌头稍稍向上拱形,声带震动。
如:kan(看),ku裤)。
h:表示音,发音时双唇几乎接触,上下齿间隔不大,舌位在上下齿之间,唇齿表达浊音,舌头稍稍向上拱形,声带震动。