商师《土力学与基础工程》第三版(赵明华)课后习题答案武汉理工大学出版社

3
m / Nk0.81 = 5.3
m1 = d
m2 = b
z
apk 2.402=24.41+43+26.91+42.631 =
apk24.41= 001 270.0 270. 0= 1c
2=
4z
apk001 = 0p )4(
apk43= 001 071.0
0 71. 0 =
1c
2=
3z
333.1 =
5.1 b = 2 z
2=
5.1 b = 3 l
apk001 = 0p )3(
a pk 26.91=001
890.0 =
n e = %001 = )n − 1( s dv s dw
w s
w
v v = rs v
n −1 e +1 =e⇒ =n n e
w
%001
v
v =n v
3
e +1 e +1 e +1 = = =g r d + wre rs wr s d + wrw s d wr)w + 1( s d
e +1 v =g =g =r )w + 1( s d m e = rs dw
d
98.1 4.7
30.2 8.8
31.2 0.01
60.2 2.71
)mc/ g(P ) %(w 21.2
s
g7.01=64.72-531.83
g531. 83=45.251 * 52.0 = 2wm ⇒ % 52=%001 * g 64.72= 1wm
m m
2w
= 2m
g45.251= sm ∴ g 081 = 1m
sv sv = =eQ w sv s d vv
68. 0=23.0 *86. 2= w s d =
w
w v
w sv s d = vv
w
w v s w
w
s s
v d=
v
v
∴
w
s s
v d = sm ⇒
w sv = sd m s
v
= sm ⇒
m
w
w
sm = v v
v
=%001 *
w
sm =w m
v = wv ⇒ % 0 0 1 =% 0 0 1 *
2c
2 33.1 76.0 0 )cfea( b/z 6 4 2 0 )m(Z
6 4 2 0 ) m( Z
5- 5 7 6 5 4
(2 =
z
25.62 67.83 78.96 5.721
) apk ( 0p 1c 4 =
z
250.0 670.0 731.0 052.0
1c
7- 4 3 2 1 0
3- 0 apk 5.721 = 5.71 − 541 = − p = 0p
2 1
500.0= 0i s/mm 5−01 5 = k =Q v Q ba s/mm 01 5 = k
2−
2
m1
3
2
h 2 ba b.a 53. 2 71< p I < 01 2 1 1 m02 01.2
i m 02. 32 m05.32
52.0<80. 0= L I <0 80.0 =
pI 6 .2 1 = = LI 4.53 − 4.63 pw − w
571.0 = 571.0 =
3c
1=
b z
4.3
m 0. 2 = z
m
3 3.3
4.3
11
z apk 77 =
n im 0
p
apk 722 =
xam 0
p
dc
− p = 0p
dc
a pk 81=1
81 = dor =
a pk 59=
3 4 W A 4 = = 001 08 + 006 M G + F
m * h / 3 m 3− 01 * 7.2 = 6 01 * 1 * 0063 * 4−01 * 5.7 = tsr = Q
s / mm 4− 01 * 5.7 = 510.0 * 2−01 * 5 = ik = v 510.0 = 02 L =i = 02.32 − 05.32 2h − 1h
v 78.0 v = %001 * w v 78.0 s
%001 = %001 *
e = rs dw
g 75.3 = wm + sm = m g 78.0 = 0.1 * 07.2 * 223.0 =
w s
dw = wm
s
g07.2=0.1 * 07.2 =
3
w
d = sm
mc 78.1 = 78.0 + 1 = e + 1 = v
6.21 = 4.53 − 84 = pw − Lw = p I
7
% 01
639.1= xam d 188.1=
067.1= d
880.0 + 1 =d 30.2
639.1= d 529.1= d 328. 1= d
857.1 =
d
271.0 + 1 w + 1 = = 60.2
s
d
po w
56.2= 61.2 2.21 01.2 2.51
d w s
026.0 = 1 −
66.1 = 1− 1 ∗ 96.2 ?
d
=e
%04 = rs 96.2 = s d
3
mc / g 66.1 =
d
w 96.2= s d , 3mc /g66.1=
%04 7.2
∴
33.0> rD >76.0 Q
595.0 =
164.0 − 349.0 nime − xame = = rD 656.0 − 349.0 e − xame
%3. 49 = %001∗
18.0 e = = rs 86.2 ∗ 582.0 s dw
w
18.0 = 1 −
9.1 = 1− 1 ∗ )582.0 + 1( ∗ 86.2
)w + 1( s d %05
=e
2
% 9.68=%5.73+% 0. 12+%6.81+%4.9 41=N m3
mm570.0
n im
p
apk542=
3 A W 2 ∗2 4 + = + = 001 08 + 006 M G + F
xam
p
3 6 6 6 = =2 2 = lb = w 4 8 1 2 1 nK 08=1 2 2 02=dAgr =G
5.3
m 0. 2 = z m ⋅ Nk 001 = M Nk 006 = F
2c
202.0 =
1c
b 1= z b 1= z 2=
1z
b 1= :liem l b 5. 2 = :jqme l A 021.0 =
b l
4c
B =
2c
a pk 811=002
021.0+571.0
2= b z
2=
:
1c
mcde : 1= 4 b l fgda
hgcm bmhf bmea A ) a(
3
4zc
m / Nk6.9 = 01 − 6.91 = wr − tasr = ' r
3zc
a p k 6 . 0 4 1 = 2 . 4 * 791.8 + 2.601 = 3h ' r + 2.601 = m /Nk791.8=
3
e +1 1 4 . 0 + 1 47.2 )w + 1( s d = ='r = r)1 − s d ( wr )1 − s d( 2.81)1 − 47.2 ( a pk 2. 601=8.3 *91+0.43= 2h 2r +0. 43= 2 zc apk0.43=0.2 * 71 = 1h1r = 1zc
e = vv
v
sv =e v
1 = sv
e +1 n = = rs ) 3( w s )n − 1( S dw r d + wre rs
) 2(
w
e +1 =d d
s
1 2.2
2
3
%6.6= %001 * mc / g 997.1 =
sm 5.121 sm = %001 * s = %001 * w = w )1( m−m 5.121 − 5.921 m
2
72 = 54 − 27 = sv − v = vv
54 =
sd 7.2 = = sv ⇒ 5.121 sm
w sv = sd m s
5
%4.53= Pw
%84= Lw
%4.63= w ) 2(
L
I
P
I
)1( 9.2 41=N 4 3
.%4.53= Pw
%84= Lw
%4. 63= w 51 N <01
081= 1wm + sm
%81=% 001 *
s
m m
1w
= 1w Q % 52 = 2w
%81 = 1w
8
5 m/Nk052
5
7
4
3 0
3
m / Nk5.71 = 23.3 3.3
4
apk8.122 = )0.2 + 2.4 ( wr + 8.951 =
2.3 2.3
13.3 apk8.951= 0. 2* 6.9 + 6.041 = 4h ' r + 6.041 =