时间序列分析R语言程序文件

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#例2.1 绘制1964——1999年中国年纱产量序列时序图(数据见附录1.2)Data1.2=read.csv("C:\\Users\\Administrator\\De sktop\\附录1.2.csv",header=T)#如果有标题,用T;没有标题用Fplot(Data1.2,type='o')#例2.1续tdat1.2=Data1.2[,2]a1.2=acf(tdat1.2)#例2.2绘制1962年1月至1975年12月平均每头奶牛产奶量序列时序图(数据见附录1.3)Data1.3=read.csv("C:\\Users\\Administrator\\De sktop\\附录1.3.csv",header=F)tdat1.3=as.vector(t(as.matrix(Data1.3)))[1:168 ]#矩阵转置转向量plot(tdat1.3,type='l')#例2.2续acf(tdat1.3) #把字去掉pacf(tdat1.3)#例2.3绘制1949——1998年市每年最高气温序列时序图Data1.4=read.csv("C:\\Users\\Administrator\\De sktop\\附录1.4.csv",header=T)plot(Data1.4,type='o')##不会定义坐标轴#例2.3续tdat1.4=Data1.4[,2]a1.4=acf(tdat1.4)#例2.3续Box.test(tdat1.4,type="Ljung-Box",lag=6) Box.test(tdat1.4,type="Ljung-Box",lag=12)#例2.4随机产生1000个服从标准正态分布的白噪声序列观察值,并绘制时序图Data2.4=rnorm(1000,0,1)Data2.4plot(Data2.4,type='l')#例2.4续a2.4=acf(Data2.4)#例2.4续Box.test(Data2.4,type="Ljung-Box",lag=6) Box.test(Data2.4,type="Ljung-Box",lag=12)#例2.5对1950——1998年市城乡居民定期储蓄所占比例序列的平稳性与纯随机性进行检验Data1.5=read.csv("C:\\Users\\Administrator\\De sktop\\附录1.5.csv",header=T)plot(Data1.5,type='o',xlim=c(1950,2010),ylim=c (60,100))tdat1.5=Data1.5[,2]a1.5=acf(tdat1.5)#白噪声检验Box.test(tdat1.5,type="Ljung-Box",lag=6) Box.test(tdat1.5,type="Ljung-Box",lag=12)#例2.5续选择合适的ARMA模型拟合序列acf(tdat1.5)pacf(tdat1.5)#根据自相关系数图和偏自相关系数图可以判断为AR (1)模型#例2.5续 P81 口径的求法在文档上#P83arima(tdat1.5,order=c(1,0,0),method="ML")#极大似然估计ar1=arima(tdat1.5,order=c(1,0,0),method="ML") summary(ar1)ev=ar1$residualsacf(ev)pacf(ev)#参数的显著性检验t1=0.6914/0.0989p1=pt(t1,df=48,lower.tail=F)*2#ar1的显著性检验t2=81.5509/ 1.7453p2=pt(t2,df=48,lower.tail=F)*2#残差白噪声检验Box.test(ev,type="Ljung-Box",lag=6,fitdf=1) Box.test(ev,type="Ljung-Box",lag=12,fitdf=1) #例2.5续P94预测及置信区间predict(arima(tdat1.5,order=c(1,0,0)),n.ahead= 5)tdat1.5.fore=predict(arima(tdat1.5,order=c(1,0 ,0)),n.ahead=5)U=tdat1.5.fore$pred+1.96*tdat1.5.fore$seL=tdat1.5.fore$pred-1.96*tdat1.5.fore$seplot(c(tdat1.5,tdat1.5.fore$pred),type="l",col =1:2)lines(U,col="blue",lty="dashed")lines(L,col="blue",lty="dashed")#例3.1.1 例3.5 例3.5续#方法一plot.ts(arima.sim(n=100,list(ar=0.8))) #方法二x0=runif(1)x=rep(0,1500)x[1]=0.8*x0+rnorm(1)for(i in 2:length(x)){x[i]=0.8*x[i-1]+rnorm(1)}plot(x[1:100],type="l")acf(x)pacf(x)##拟合图没有画出来#例3.1.2x0=runif(1)x=rep(0,1500)x[1]=-1.1*x0+rnorm(1)for(i in 2:length(x)){x[i]=-1.1*x[i-1]+rnorm(1)}plot(x[1:100],type="l")acf(x)pacf(x)#例3.1.3方法一plot.ts(arima.sim(n=100,list(ar=c(1,-0.5)))) #方法二x0=runif(1)x1=runif(1)x=rep(0,1500)x[1]=x1x[2]=x1-0.5*x0+rnorm(1)for(i in 3:length(x)){x[i]=x[i-1]-0.5*x[i-2]+rnorm(1)}plot(x[1:100],type="l")acf(x)pacf(x)#例3.1.4x0=runif(1)x1=runif(1)x=rep(0,1500)x[1]=x1x[2]=x1+0.5*x0+rnorm(1)for(i in 3:length(x)){x[i]=x[i-1]+0.5*x[i-2]+rnorm(1)}plot(x[1:100],type="l")acf(x)pacf(x)又一个式子x0=runif(1) x1=runif(1)x=rep(0,1500)x[1]=x1x[2]=-x1-0.5*x0+rnorm(1)for(i in 3:length(x)){x[i]=-x[i-1]-0.5*x[i-2]+rnorm(1)}plot(x[1:100],type="l")acf(x)pacf(x)#均值和方差smu=mean(x)svar=var(x)#例3.2求平稳AR(1)模型的方差例3.3mu=0mvar=1/(1-0.8^2) #书上51页#总体均值方差cat("population mean and var are",c(mu,mvar),"\n")#样本均值方差cat("sample mean and var are",c(mu,mvar),"\n")#例题3.4svar=(1+0.5)/((1-0.5)*(1-1-0.5)*(1+1-0.5))#例题3.6 MA模型自相关系数图截尾和偏自相关系数图拖尾#3.6.1法一:x=arima.sim(n=1000,list(ma=-2))plot.ts(x,type='l')acf(x)pacf(x)法二x=rep(0:1000)for(i in 1:1000){x[i]=rnorm[i]-2*rnorm[i-1]}plot(x,type='l')acf(x)pacf(x)#3.6.2法一:x=arima.sim(n=1000,list(ma=-0.5))plot.ts(x,type='l')acf(x)pacf(x)法二x=rep(0:1000)for(i in 1:1000){x[i]=rnorm[i]-0.5*rnorm[i-1]}plot(x,type='l')acf(x)pacf(x)##错误于rnorm[i] : 类别为'closure'的对象不可以取子集#3.6.3法一:x=arima.sim(n=1000,list(ma=c(-4/5,16/25))) plot.ts(x,type='l')acf(x)pacf(x)法二:x=rep(0:1000)for(i in 1:1000){x[i]=rnorm[i]-4/5*rnorm[i-1]+16/25*rnorm[i-2] }plot(x,type='l')acf(x)pacf(x)##错误于x[i] = rnorm[i] - 4/5 * rnorm[i - 1] + 16/25 * rnorm[i - 2] :##更换参数长度为零#例3.6续根据书上64页来判断#例 3.7拟合ARMA(1,1)模型,x(t)-0.5x(t-1)=u(t)-0.8*(u-1),并直观观察该模型自相关系数和偏自相关系数的拖尾性。

#法一:x0=runif(1)x=rep(0,1000)x[1]=0.5*x0+rnorm(1)-0.8*rnorm(1)for(i in 2:length(x)){x[i]=0.5*x[i-1]+rnorm(1)-0.8*rnorm(1)}plot(x,type='l')acf(x)pacf(x)##图和书上不一样#法二x=arima.sim(n=1000,list(ar=0.5,ma=-0.8))acf(x)pacf(x)#图和书上一样#例 3.8 选择合适的ARMA模型拟合加油站57天的OVERSHORT序列Data1.6=read.csv("C:\\Users\\Administrator\\De sktop\\附录1.6.csv",header=F)tdat1.6=as.vector(t(as.matrix(Data1.6)))[1:57] plot(tdat1.6,type='o')acf(tdat1.6)pacf(tdat1.6) #把字去掉arima(tdat1.6,order=c(0,0,1),method="CSS")#最小二乘估计ma1=arima(tdat1.6,order=c(0,0,1),method="CSS") summary(ma1)ev=ma1$residualsacf(ev)pacf(ev)##错误于arima(tdat1.6, order = c(0, 0, 1), method = "CSS") :##'x'必需为数值#例3.9选择合适的ARMA模型拟合1880——1985年全球气温改变差值差分序列##没有数据#例3.10 例3.11 例3.12##矩估计#例3.13对等时间间隔的连续70次化学反应的过程数据进行拟合Data1.8=read.csv("C:\\Users\\Administrator\\De sktop\\附录1.8.csv",header=F)tdat1.8=as.vector(t(as.matrix(Data1.8)))[1:70] plot(tdat1.8,type='o')#例3.14AR(2)例3.15AR(3)例3.16AR(3)模型的预测#如果考得话就先。