【期末提升】辽宁省锦州市黑山县黑山中学2019-2020学年高一6月质量检测地理试题

辽宁省锦州市黑山县黑山中学2022高一语文6月质量检测试题考试时间：150分钟满分150分注意事项：1．答题前，先将自己的姓名、准考证号填写在试题卷和答题卡上。

2．选择题的作答：每小题选出答案后，用2B铅笔把答题卡上对应题目的答案标号涂黑。

写在试题卷、草稿纸和答题卡上的非答题区域均无效。

3．非选择题的作答：用签字笔直接答在答题卡上对应的答题区域。

写在试题卷、草稿纸和答题卡上的非答题区域均无效。

一、现代文阅读（36分）（一）论述类文本阅读（共3小题，9分）阅读下面的文字，完成1～3题。

关汉卿与莎士比亚悲剧特点对比关汉卿和莎士比亚在设置人物来推动剧情发展上，都突出了主要人物的重要性和次要人物的辅佐性。

在他们的悲剧中，都只有一个突出的中心人物。

关汉卿的《窦娥冤》中，中心人物自然是含冤赴死的窦娥，莎士比亚的《哈姆莱特》《麦克白》《李尔王》《奥赛罗》中，中心人物则显而易见地分别是哈姆莱特、麦克白、李尔王、奥赛罗。

当然，莎士比亚的另外两部悲剧《罗密欧与朱丽叶》和《安东尼与克莉奥佩特拉》，中心人物是处于矛盾漩涡中心的罗密欧与朱丽叶、安东尼与克莉奥佩特拉两对情侣，但他们都是可以当作一体看待的。

两位戏剧家的核心人物设置手法，区别于后来出现的“花开两朵，各表一枝”的双主角，甚至多主角的戏剧人物设置，体现了较为保守的戏剧人物设置手法，符合单一戏剧线索的要求。

关汉卿的戏剧人物全部是善恶分明、正邪明晰的典型人物。

正面人物就是一身正气、意志坚定、抗争到底的典型；反面人物则是狡猾奸诈、恶毒卑鄙、瞒上欺下的典型。

这种人物的脸谱化，和中国戏曲的角色脸谱处理是分不开的。

同时，也体现了由于时代的限制，文人思维的固定性一时无法改变。

相比之下，莎士比亚的人物则显得比较丰满和富于多面性。

他所描绘的每一个英雄都有其自身不可消弭的缺陷：哈姆莱特的优柔寡断、奥赛罗的嫉妒冲动、麦克白的好胜野心等。

这些都是人类性格共同的缺憾，这样的处理，使得英雄的形象既不被刻意夸大，又显得明朗鲜活、真实可信。

辽宁省锦州市黑山县黑山中学2019-2020学年高一6月质量检测试题考试时间：90分钟命题人：可能用到的原子量：Zn 65；一、选择题(本题包括20小题，每小题3分，共60分)1、下列我国科研成果所涉及材料中，主要成分为同主族元素形成的无机非金属材料的是()A.4.03米大口径碳化硅反射镜B.2022年冬奥会聚氨酯速滑服C.能屏蔽电磁波的碳包覆银纳米线D.“玉兔二号”钛合金筛网轮22增加的是()A．节约用水用电B．利用风力发电C．增加值被面积D．燃烧煤炭供热3、下列表述正确的是()A．硅晶体具有半导体性能，可用于光导纤维B．常温下铁能被浓硝酸钝化，可用铁制容器贮运浓硝酸C．浓硫酸具有吸水性，故能使蔗糖炭化D．SO2能使酸性KMnO4溶液褪色，体现了SO2的漂白性4、下列有关化学反应中能量变化的理解，正确的是()A．凡是伴随能量变化的过程都是化学变化B．在化学反应过程中总是伴随着能量的变化C．在确定的化学反应中反应物的总能量一定等于生成物的总能量D．在确定的化学反应中反应物的总能量总是高于生成物的总能量5．下列物质中，属于纯净物的是()①陶瓷②水泥③玻璃④漂白粉⑤胆矾⑥氨水⑦液氨A．①③⑤B．②④⑥C．⑤⑦D．⑥⑦6、对可逆反应4NH3(g)＋5O2(g) 4NO(g)＋6H2O(g)，下列叙述正确的是() A．达到化学平衡时，4v正(O2)＝5v逆(NO)B．若单位时间内生成x mol NO的同时，消耗x mol NH3，则反应达到平衡状态C．达到化学平衡时，若增加容器体积，则正反应速率减少，逆反应速率增大D．化学反应速率关系是：2v正(NH3)＝3v正(H2O)7、对于反应Zn(s)＋H2SO4(aq)===ZnSO4(aq)＋H2(g)，下列叙述不正确的是()A．其反应物或生成物都能用来表示该反应的速率B．反应过程中能量关系可用右图表示C．若将该反应设计成原电池，锌为负极D．若设计为原电池，当有32.5 g锌溶解，正极放出标准状况下11.2 L气体8．对下列事实的解释错误的是()A．在蔗糖中加入浓硫酸后出现发黑现象，说明浓硫酸具有脱水性B．浓硝酸在光照条件下颜色变黄，说明浓硝酸不稳定C．常温下浓硫酸、浓硝酸可以用铝罐储存，说明浓硫酸、浓硝酸与铝不反应D．反应CuSO4＋H2S===CuS↓＋H2SO4说明硫化铜既不溶于水，也不溶于稀硫酸9、一定温度下，在2 L的密闭容器中，X、Y、Z三种气体的物质的量随时间变化的曲线如下图所示：下列描述正确的是()A．反应的化学方程式为：X(g)＋Y(g) Z(g)B．反应开始到10 s，用Z表示的反应速率为0.158 mol·L－1·s－1C．反应开始到10 s，X的物质的量浓度减少了0.79 mol·L－1D．反应开始到10 s，Y的转化率为79.0%10、你认为减少酸雨产生可采用的措施是()①少用煤作燃料②把工厂烟囱加高③燃料脱硫④在已酸化的土壤中加石灰⑤开发新能源A．①②③B．②③④⑤C．①③⑤D．①③④⑤11．燃料电池是目前电池研究的热点之一。

线上教学检测试卷高一数学试卷一、选择题（共12小题，每题5分，共60分） 1.179︒是（） A. 第一象限角 B. 第二象限角C. 第三象限角D. 第四象限角 【答案】B 【解析】 【分析】利用象限角的定义直接求解，即可得到答案．【详解】由题意，1791801︒︒︒=-，所以179︒表示第二象限角，故选B ．【点睛】本题主要考查了角所在象限的判断，考查象限角的定义等基础知识，考查了推理能力与计算能力，是基础题．2.已知 sin 0θ>且cos 0θ<，则角的终边所在的象限是（ ） A. 第一象限 B. 第二象限C. 第三象限D. 第四象限【答案】B 【解析】 【分析】利用三角函数的定义，可确定0y >且0x <，进而可知θ所在的象限，得到结果. 【详解】依据题设及三角函数的定义可知角θ终边上的点的横坐标小于零，纵坐标大于零， 所以终边在第二象限， 故选B.【点睛】该题考查的是有关根据三角函数值的符号断定角所属的象限，涉及到的知识点有三角函数的定义，三角函数值在各个象限内的符号，属于简单题目.3.已知向量()5,a m =，()2,2b =-，若()a b b -⊥，则实数m = ( ) A. -1 B. 1C. 2D. -2【答案】B 【解析】根据向量坐标的线性运算得到a b -，再根据向量垂直的坐标表示，得到关于m 的方程，解出m 的值，得到答案.【详解】因为向量()5,a m =，()2,2b =- 所以()3,2a b m +=+，因为()a b b -⊥， 所以()0a b b -⋅=所以()6220m -+= 解得1m =. 故选：B.【点睛】本题考查向量线性运算的坐标表示，根据向量垂直关系求参数的值，属于简单题.4.若角α的终边与单位圆交于点13,22P ⎛ ⎝⎭，则sin α=（ ）A.12B.323 D. 不存在【答案】B 【解析】 【分析】由三角函数的定义可得：sin y α=，得解.【详解】解：在单位圆中，3sin y α==， 故选B.【点睛】本题考查了三角函数的定义，属基础题. 5.下列函数中，最小正周期为π的是（ ） A. sin y x =B. cos y x =C. 1sin2y x = D.cos 2y x =【解析】 【分析】由函数的最小正周期为2T ωπ=，逐个选项运算即可得解.【详解】解:对于选项A, sin y x =的最小正周期为2π, 对于选项B, cos y x =的最小正周期为2π, 对于选项C, 1sin2y x =的最小正周期为4π, 对于选项D, cos 2y x =的最小正周期为π, 故选D.【点睛】本题考查了三角函数的最小正周期，属基础题.6.已知弧度数为2的圆心角所对的弦长也是2，则这个圆心角所对的弧长是（ ） A. 2 B.2sin1C. 2sin1D. sin 2【答案】B 【解析】 【分析】先由已知条件求出扇形的半径为1sin1，再结合弧长公式求解即可. 【详解】解：设扇形的半径为R ，由弧度数为2的圆心角所对的弦长也是2，可得1sin1R =， 由弧长公式可得：这个圆心角所对的弧长是22sin1R =，故选：B.【点睛】本题考查了扇形的弧长公式，重点考查了运算能力，属基础题. 7.已知1sin cos 3αα+=，则sin2α=（ ） A. 89-B.C.D.89【答案】A 【解析】试题分析：1sin cos 3αα+=的两边分别平分得1812sin cos sin 299ααα+=∴=- 考点：同角间三角函数关系 8.1tan 751tan 75-︒=+︒（ ）A. 333 D. 3【答案】D 【解析】 【分析】先用“1”的代换转化1tan 75tan 45tan 751tan 751tan 45tan 75-︒-︒=+︒+⋅︒，再利用两角差的正切公式的逆用求解. 【详解】()1tan 75tan 45tan 753tan 301tan 751tan 45tan 753-︒-︒==-=-+︒+⋅︒ 故选：D【点睛】本题主要考查了两角差的正切公式的逆用及“1”的代换，还考查了运算求解的能力，属于基础题. 9.函数2cos 21y x =+ 的定义域是（ ）A. {|22,}2x k x k k Z πππ≤≤+∈B. {|,}2x k x k k Z πππ≤≤+∈C. {|,}3x k x k k Z πππ≤≤+∈D. {|,}33x k x k k Z ππππ-≤≤+∈【答案】D 【解析】要使原函数有意义，则2210cos x +≥ ，即122cos x ≥-， 所以2222233k x k k Z ππππ-≤≤+∈，． 解得：33k x k k Z ππππ-≤≤+∈，．所以，原函数的定义域为{|}33x k x k k Z ππππ-≤≤+∈，．故选D ．【点睛】本题考查了函数的定义域及其求法，考查了三角不等式的解法，解答此题的关键是掌握余弦函数线，在单位园中利用三角函数线分析该题会更加直观 10.已知a 是实数，则函数()1sin f x a ax =+的图象不可能是（ ）A. B. C.D.【答案】D 【解析】 【详解】由题知，．若，，选项C 满足；若，，，其中，，函数周期，选项A 满足；若，，，其中，，函数周期，选项B 满足；若,则，且周期为．而选项D 不满足以上四种情况，故图象不可能是D ．故本题正确答案D ．11.已知tan α、tan β是方程23340x x ++=的两根，且22ππα-<<，22ππβ-<<，则αβ+的值为（ ）A.3πB. 23π-C.3π或23π- D. 3π-或23π 【答案】B 【解析】 【分析】由根与系数的关系得tan tan 33αβ+=-tan tan 4αβ⋅=，再求出tan()αβ+的值即得解.【详解】由根与系数的关系得tan tan 33αβ+=-tan tan 4αβ⋅=， ∴tan 0,tan 0αβ<<，∴tan tan 33tan()31tan tan αβαβαβ+-+===-，又,2222ππππαβ-<<-<<，且tan 0α<，tan 0β<，∴0παβ-<+<，∴23αβπ+=-． 故选：B【点睛】本题主要考查和角的正切公式，意在考查学生对该知识的理解掌握水平. 12.若将函数()tan 04y x πωω⎛⎫=+> ⎪⎝⎭的图像向右平移6π个单位长度后，与函数tan 6y x πω⎛⎫=+ ⎪⎝⎭的图像重合，则ω的最小值为A.16B.14C.13D.12【答案】D 【解析】 函数tan()(0)4y x πωω=+>的图像向右平移6π个单位得tan[()]tan()6464y x x ππωππωω=-+=-+，所以,646k k Z ωππππ-+=+∈16,2k k Z ω=-+∈，所以ω得最小值为12．二、填空题（共4小题，每题5分，共20分）13.已知5,3a b ==，且12a b ⋅=-，则向量a 在向量b 上的投影等于______ 【答案】-4 【解析】 【分析】利用向量a 在向量b 上的投影公式即可得到答案．【详解】由于5,3a b ==，且12a b ⋅=-，∴ 利用向量a 在向量b 上的投影12cos ,43a b a b a a b a a b b⋅⋅-==⋅===-⋅， 故向量a 在向量b 上的投影等于-4【点睛】本题考查向量投影的计算，熟练掌握投影公式是关键，属于基础题． 14.1cos 123πθ⎛⎫-=⎪⎝⎭，则5sin 12πθ⎛⎫+= ⎪⎝⎭ ________ 【答案】13【解析】 【分析】因为51212ππθθ-++=2π ，所以结合三角函数的诱导公式求值；【详解】因为51212ππθθ-++=2π，由诱导公式得： 5sin 12πθ⎛⎫+= ⎪⎝⎭sin --212ππθ⎡⎤⎢⎥⎣⎦（） =1cos 123πθ⎛⎫-= ⎪⎝⎭ 故答案为13【点睛】本题考查三角函数的化简求值，考查三角函数中的恒等变换应用，关键是“拆角配角”思想的应用，是中档题． 15.()sin1013tan 70+=_____【答案】1 【解析】 【分析】3tan 60，切化弦后，利用两角和差余弦公式可将原式化为sin10cos10cos 60cos 70，利用二倍角公式可变为1sin 202cos 60cos 70⋅，由sin 20cos70=可化简求得结果. 【详解】()()cos 60cos 7060sin 70sin1013tan70sin101tan 60tan70sin1s 0co i s 60o 7n c s 0+=++⋅=()cos 7060sin10cos101sin 201sin101cos60cos70cos60cos702cos60cos702cos60-=⋅==⋅==本题正确结果：1【点睛】本题考查利用三角恒等变换公式进行化简求值的问题，涉及到两角和差余弦公式、二倍角公式的应用. 16.已知函数()sin 03y x πωω⎛⎫=+> ⎪⎝⎭的最小正周期为π，若将该函数的图像向左平移()0m m >个单位后，所得图像关于原点对称，则m 的最小值为________.【答案】3π 【解析】 【分析】先利用周期公式求出ω，再利用平移法则得到新的函数表达式，依据函数为奇函数，求出m 的表达式，即可求出m 的最小值． 【详解】由2T ππω==得2ω=，所以sin 23y x π⎛⎫=+ ⎪⎝⎭，向左平移()0m m >个单位后，得到sin[2()]sin(22)33y x m x m ππ=++=++，因为其图像关于原点对称，所以函数为奇函数，有2,3m k k Z ππ+=∈，则62k m ππ=-+，故m 的最小值为3π．【点睛】本题主要考查三角函数性质以及图像变换，以及sin()y A x ωϕ=+ 型的函数奇偶性判断条件．一般地sin()y A x ωϕ=+为奇函数，则k ϕπ=；为偶函数，则2k πϕπ=+；cos()y A x ωϕ=+为奇函数，则2k πϕπ=+；为偶函数，则k ϕπ=．三、解答题（共6道解答题，满分70分） 17.（1）已知4cos 5α=-，且α为第三象限角，求sin α，tan α的值 （2）已知tan 3α=，求4sin 2cos 5cos 3sin αααα-+ 的值.【答案】（1）35，34；（2）57【解析】 【分析】（1）根据题意，利用同角三角函数的平方关系和商的关系，即可求出结果； （2）已知tan 3α=，利用齐次式化简得出4sin 2cos 4tan 25cos 3sin 53tan αααααα--=++，即可求出结果.【详解】解：（1）4cos 5α=- 且α 为第三象限23sin 3sin 1cos ,tan 5cos 4ααααα∴=--=-==，（2）由于tan 3α=， 而4sin 2cos 4tan 255cos 3sin 53tan 7αααααα--==++.【点睛】本题考查三角函数化简求值，运用了同角三角函数的平方关系和商的关系，以及利用齐次式进行化简，属于基础题.18.设向量a ，b 满足1==a b ，且327a b -=. （1）求a 与b 的夹角； （2）求23a b +的大小. 【答案】（1）3π（219【解析】 【分析】（1）根据向量数量积的运算和向量模的公式，即可计算出1cos 2θ=，得到a 与b 的夹角； （2）根据向量的模的平方等于向量的平方，可得22323a b a b +=+，化简即可得到答案 【详解】解：（1）设a 与b 的夹角为θ.由已知得()2232(7)7a b-==，即2291247a a b b -⋅+=，因此9412cos 7θ+-=，于是1cos 2θ=，故3πθ=，即a 与b的夹角为3π.（2）22323a b a b +=+221412941292a ab b=+⋅+=+⨯+19=.【点睛】本题考查向量数量积的运算性质、向量模的公式和向量的夹角公式，考查学生的运算能力，属于中档题． 19.已知02πβα<<<，3cos 5α=，4cos()5αβ-=. （1）求tan2α； （2）求cos β. 【答案】（1）24tan 27α=-；（2）24cos 25β=. 【解析】 【分析】（1）利用同角三角函数的基本关系求出tan α的值，然后利用二倍角的正切公式可求出tan2α的值；（2）先利用同角三角函数的平方关系求出()sin αβ-的值，然后利用两角差的余弦公式可计算出cos β的值. 【详解】（1）02πα<<，24sin 1cos 5αα∴=-=，sin 4tan cos 3ααα∴==， 因此，22422tan 243tan 21tan 7413ααα⨯===--⎛⎫- ⎪⎝⎭； （2）02βαπ<<<，则02πβ<<，02πα<<且αβ>，02αβπ∴<-<，()()23sin 1cos 5αβαβ∴-=--=，因此，()()()3443cos cos cos cos sin sin 5555βααβααβααβ=--=-+-=⋅+⋅⎡⎤⎣⎦2425=.【点睛】本题考查利用二倍角的正切公式和两角差的余弦公式求值，同时也涉及了同角三角函数基本关系的应用，解题时要确定角的取值范围，考查计算能力，属于中等题. 20.函数()2sin()(0,)22f x x ππωϕωϕ=+>-<<的部分图象如图所示.（1）求()f x 的解析式.（2）若不等式()3f x m -<，对任意[,]123x ππ∈恒成立，求实数m 的取值范围. 【答案】（1）f (x)＝2sin(2x －3π)． （2）33，2）． 【解析】 【分析】 （1）利用531234T ππ⎛⎫--= ⎪⎝⎭，再用522,Z 122k k ππϕπ⨯+=+∈（），求出ϕ即可；（2）,123x ππ⎡⎤∈⎢⎥⎣⎦，得13sin 232x π⎡⎛⎫-∈-⎢ ⎪⎝⎭⎣⎦，转化成()3()3()3m f x f x m m f x <+⎧-<⇔⎨>-⎩，最后求出m取值范围.【详解】（1）因为5231234πππω⎛⎫--=⋅ ⎪⎝⎭，所以2ω=， 又因为522,Z 122k k ππϕπ⨯+=+∈（），且22ππϕ-<<，所以3πϕ=-，故()2sin 23f x x π⎛⎫=-⎪⎝⎭． （2）由（1）知()2sin 23f x x π⎛⎫=- ⎪⎝⎭，当,123x ππ⎡⎤∈⎢⎥⎣⎦时，2,363x πππ⎡⎤-∈-⎢⎥⎣⎦，13sin 2,322x π⎡⎛⎫∴-∈-⎢ ⎪⎝⎭⎣⎦，即1()3f x -，又对任意,123x ππ⎡⎤∈⎢⎥⎣⎦，()3()3()3m f x f x m m f x <+⎧-<⇔⎨>-⎩恒成立， ()()min max 33m f x m f x ⎧⎪∴⎨⎪⎩＜＋＞－332m <<，故m 的取值范围是(33,2)．【点睛】本题属于三角函数的综合题，考查了三角函数的周期性和已知定义域，求三角函数的值域等问题，难点在于对绝对值要进行分段处理和化简.21.已知函数()22sin 324f x x x π⎛⎫=+- ⎪⎝⎭，,42x ππ⎡⎤∈⎢⎥⎣⎦. （1）求()f x 的最大值和最小值； （2）若关于x 的方程()2f x m -=在,42x ππ⎡⎤∈⎢⎥⎣⎦上有两个不同的实根，求实数m 的取值范围.【答案】（1）最大值为3，最小值为2；（2）)31,1⎡-⎣. 【解析】 【分析】（1）利用二倍角的余弦公式、诱导公式以及辅助角公式化简函数()y f x =的解析式为()2sin 213f x x π⎛⎫=-+ ⎪⎝⎭，由,42x ππ⎡⎤∈⎢⎥⎣⎦计算出23x π-的取值范围，结合正弦函数的基本性质可求出函数()y f x =在区间,42ππ⎡⎤⎢⎥⎣⎦上的最大值和最小值；（2）由()2f x m -=，可得出12sin 23m x π⎛⎫+=-⎪⎝⎭，令22,363t x πππ⎡⎤=-∈⎢⎥⎣⎦，将问题转化为直线1y m =+与函数2sin y t =在区间2,63ππ⎡⎤⎢⎥⎣⎦上的图象有两个交点，利用数形结合思想能求出实数m 的取值范围.【详解】（1）()22sin 3cos 21cos 23cos 244f x x x x xππ⎡⎤⎛⎫⎛⎫=+-=-+- ⎪ ⎪⎢⎥⎝⎭⎝⎭⎣⎦1cos 23cos 2sin 23cos 212sin 2123x x x x x ππ⎛⎫⎛⎫=-+-=-+=-+ ⎪ ⎪⎝⎭⎝⎭，,42x ππ⎡⎤∈⎢⎥⎣⎦，22,363x πππ⎡⎤∴-∈⎢⎥⎣⎦，1sin 2123x π⎛⎫∴≤-≤ ⎪⎝⎭， 因此，函数()y f x =在区间,42ππ⎡⎤⎢⎥⎣⎦上的最大值为()max 2113f x =⨯+=，最小值为()min 12122f x =⨯+=；（2）由()2f x m -=，即2sin 2123x m π⎛⎫-+-= ⎪⎝⎭，得12sin 23m x π⎛⎫+=- ⎪⎝⎭. 令22,363t x πππ⎡⎤=-∈⎢⎥⎣⎦，则直线1y m =+与函数2sin y t =在区间2,63ππ⎡⎤⎢⎥⎣⎦上的图象有两个交点，如下图所示：由图象可知，312m ≤+<时，311m ≤<时，直线1y m =+与函数2sin y t =在区间2,63ππ⎡⎤⎢⎥⎣⎦上的图象有两个交点. 因此，实数m 的取值范围是)31,1⎡⎣.【点睛】本题考查正弦型三角函数在区间上最值的计算，同时也考查了利用正弦型函数的零点个数求参数，一般利用参变量分离法转化为参数直线与函数图象的交点个数，考查运算求解能力与数形结合思想的应用，属于中等题.22.已知O 为坐标原点，()cos ,1OA x =，()2cos 3sin2OB x x =，R x ∈，若()f x OA OB =⋅.⑴ 求函数()f x 的最小正周期和单调递增区间；⑵ 将函数()y f x =的图象上各点的横坐标伸长为原来的2倍(纵坐标不变)，再将得到的图象向左平移4π个单位，得到函数()y g x =的图象，求函数()y g x =在5,1212ππ⎡⎤-⎢⎥⎣⎦上的最小值．【答案】（1）,,36k k k Z ππππ⎡⎤-+∈⎢⎥⎣⎦；（2）2 【解析】 【分析】（1）由题意得到()2216f x sin x π⎛⎫=++ ⎪⎝⎭，进而可得函数的周期和单调增区间；（2）根据图象变换得到()52112g x sin x π⎛⎫=++ ⎪⎝⎭，根据x 的范围得到512x π+的取值范围，然后可得()g x 的最小值．【详解】(1)由题意()cos ,1OA x =，()2cos 3sin2OB x x =， 所以()22cos 3sin2cos23sin212sin 216f x x x x x x π⎛⎫=+=+=++ ⎪⎝⎭， 所以函数()f x 的最小正周期为2ππ2T ==， 由222,262k x k k Z πππππ-≤+≤+∈，得,36k x k k Z ππππ-≤≤+∈，所以()f x 的单调递增区间为,,36k k k Z ππππ⎡⎤-+∈⎢⎥⎣⎦.(2)由(1)得()2sin 216f x x π⎛⎫=++ ⎪⎝⎭， 将函数()y f x =的图象上各点的横坐标伸长为原来的2倍(纵坐标不变)，得到的图象对应的函数为2sin 16y x π⎛⎫=++ ⎪⎝⎭；再将得到的图象向左平移4π个单位，得到的图象对应的函数为 52sin 12sin 14612y x x πππ⎛⎫⎛⎫=+++=++ ⎪ ⎪⎝⎭⎝⎭，∴()52sin 112g x x π⎛⎫=++ ⎪⎝⎭， ∵5,1212x ππ⎡⎤∈-⎢⎥⎣⎦， ∴55,1236x πππ⎡⎤+∈⎢⎥⎣⎦， ∴当55126x ππ+=，即512x π=时，()g x 有最小值，且()min 552sin 12126g x g ππ⎛⎫==+= ⎪⎝⎭， ∴函数()y g x =在5,1212ππ⎡⎤-⎢⎥⎣⎦上的最小值为2． 【点睛】（1）解决三角函数的有关问题时，一般将所给的函数化为()φy Asin x ω=+的形式，然后将φx ω+作为一个整体，并结合正弦函数的相关性质进行求解．（2）求函数()φy Asin x ω=+在给定区间上的最值或范围时，先由所给的范围得到φx ω+的范围，然后结合函数的图象求解．。

2020届高三模拟考试英语参考答案听力：1-5CBABA6-10CBBAB11-15CBCCA16-20CACBA阅读理解：21-24CDAC25-28BACA29-31ABA32-35BDAD7选5：36-40DBAGC完形填空：41-50CCACD46-50BCADC51-55BADDB56-60ABDBA语法填空：61.the62.illnesses63.is lost64.which65.at66.started67.yearly68.smoking69.shorter70.but改错：1.walked---walkingrmations---information3.eventual---eventually4.wait---wait for5.the lady---a lady6.says---said7.been去掉8.he---she9.thank---thankful10.so---butDear John,I am happy to hear that you want to take a course on Chinese traditional culture.I am writing to recommend one on Beijing Opera.This course,“Introduction to Beijing Opera”,which will run in Beijing next month for two weeks, contains two sections.A lecture on the history of Beijing Opera will introduce its time-honored development,including the detailed process of how it has spread.What takes the course to a new height is a theater trip.I heartily recommend this course to you based on the following reasons.To begin with,I know you love drama,so you will be able to easily understand Beijing Opera.Besides,it is an interactive course,in which you will have a chance to communicate with opera performers face to face.I hope my introduction is helpful.Please let me know if you have further questions.Yours,Li Hua。

辽宁省锦州市黑山县黑山中学2019—2020学年高一历史6月质量检测试题考试范围（1—7单元)；考试时间：90分钟；分值：100分学校：___________姓名：___________班级：___________考号:___________注意事项：1．答题前填写好自己的姓名、班级、考号等信息2．请将答案正确填写在自己的答题纸上第I卷（选择题，共30个小题，每小题2分，共60分）1。

下列哪一项不能视为文明诞生的基本标志（）A。

阶级的产生B。

考古遗存 C.甲骨卜辞D.青铜铭文2。

“希腊民主不同于现代社会的民主。

它依赖于小规模的城邦和公民的广泛参与。

；"广泛参与"的群体是指( )A。

城邦所有人B。

成年男性公民 C.除外邦人之外的所有人D。

除奴隶之外的说所有人3。

关于古代文明各自扩张所产生的影响,正确的表述是（）A.使不同文明区相互连接起来 B.加速了封建帝国的解体C.和平交流成为文明扩张的唯一方式D。

创建城邦国家成为时代主题4。

中古西欧城市是10—11世纪重新复苏和产生.西欧城市产生的经济前提和物质基础是( ）A.生产力的发展，资本主义萌芽的出现B。

手工业从庄园中分离C.从过去历史现成地继承下来D。

获得自由的农奴武装暴动5.西欧封建制度的特征主要包括（）①封建等级制②庄园制③等级君主制④基督教的精神垄断A.①②③④B。

①②④ C.①③④D.②③④6。

佛教，基督教和伊斯兰教并称为世界三大宗教，它们在产生和发展过程中各自都形成了严格的宗教教规。

以下对宗教活动的描述符合教规的是（）A。

基督教教徒在教堂里诵读《古兰经》 B.伊斯兰教教徒在寺庙里拜佛C。

佛寺中供奉着释迦摩尼的塑像D。

伊斯兰教的清真寺里供奉着耶稣像7。

关于中古时期亚洲一些国家与中国有关的史实，表述正确的是（)A.中国的造纸术经由印度人传入欧洲B。

世纪日本模仿隋唐建立中央集权制度C.高丽王朝模仿汉朝推行土地国有D.16世纪末中朝军民联合抗日维护朝鲜独立8.玛雅文明以印第安玛雅人而得名.约形成于公元前1500年，玛雅人创造了辉煌的玛雅文明。

辽宁省锦州市黑山中学2019-2020学年高一6月质量检测英语试题考试时间：100分钟试卷满分：150分第一部分:阅读(共两节，满分50分)第一节(共15小题;每小题2.5分，满分37.5 分)阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项。

AWe work with Cambridge County Council’s Participation Team to create opportunities for young people to visit the University and learn more about it. The following events are scheduled for the 2019/2020 academic year.SuperStar workshops12 engaging workshops are planned for young people aged 7 to 11. These half-day visits will be held throughout the year, at times when young people are not at school. If participants complete 8 of the 12 workshops, they will be awarded the nationally recognised SuperStar Crest Award.Please note, workshops will only run if we have a sufficient number of attendees (usually around 3+ participants).Explore University DaysExplore University Days are for young people aged 12-15. Participants visit the University for two days and engage with a range of university-related workshops, and other fun activities.Previous participants have engaged with the following:◆Visited the Sports Centre◆Took part in a Neuroscience workshop◆Enjoyed a two-course meal at a University CollegeDates will be confirmed in early December 2019, and a schedule for event will follow in the New Year.Events for post-16 studentsIf you are studying for your post-16 qualifications and are considering applying for Cambridge or would like to find out more about a specific subject, the following events might be for you:◆University and College Open Days◆Subject Masterclasses◆Cambridge Science Festival1. What can the participants do in SuperStar workshops?A. To stay only half a day.B. To get a gift.C. To enjoy a free meal.D. To visit all the 12 workshops.2. Which event is specially for applicants of Cambridge?A. SuperStar workshops.B. Events for post-16 students.C. Explore University Days.D. The Neuroscience workshop.3. The events in the passage most probably aim to .A. introduce some coursesB. advertise Cambridge UniversityC. en rich students’ spare time lifeD. promote children’s interest in touringBWalk around the city of Ann Arbor, Michigan, and you may see a green animal named Sluggo and a flying pig named Philomena.You might even see street artist David Zinn drawing them using only sidewalk chalk and charcoal (炭笔)．At the age of 12, David began working as an artist.His dad was writing a computer instruction and worried that it would be boring to read.So he asked David to draw pictures of turtles (the name of the computer program) to explain it.The publisher liked his drawings, and soon David had the job of drawing more turtles in action.“I learned a great lesson, which was that, to make money as an artist, I couldn’t always draw what I wanted，” he says.“I had to f igure out how to draw a turtle drinking tea and other things like that.”David worked for 20 years as a commercial (商业的) artist, but he often felt cooped up (禁锢) sitting at a computer for 10 hours a day.Then, on a sunny afternoon about ten years ago, he br ought some chalk and started drawing on the sidewalk.That’s when Sluggo came to life.“One of the reasons I like to put art on the street is to take people by surprise，” he says.“I can have fun drawing, and knowing it will be washed away helps me not think too much.It frees me up.”It takes David about two hours to complete one drawing.He uses a lot of sidewalk characteristics in his street art.It can be difficult to draw on surfaces that are not flat.He has tonotice where shadows will land so they won’t d estroy the 3D drawings he creates.Today, more and more people are accepting and looking for his work.David’s artwork can also be found across the country and even throughout the world.Photos of his drawings have been shown at many universities and museums.4. What did David learn from drawing turtles for his father?A．Work hard.B．Follow your heart.C．Draw what you like. D．Draw in a creative way.5．How does David feel when knowing his drawing will be washed away?A．Relaxed. B．Worried.C．Unhappy. D．Surprised.6．In what way is David’s art special?A．It shows his real life.B．It is drawn on the flat sidewalk.C．It needs a very long time to finish a drawing.D．It is 3D street art created by simple painting tools.7．What do we know about David’s drawings?A．They are becoming popular.B．They are too difficult to understand.C．They are found mainly at museums.D．They are hardly accepted by adults.CHow many sports stars can you name? Whether it’s ten or thirty, I believe that 90% of them would be male (男性). Even in today’s society, which calls for gender equality (男女平等), it seems that female sports stars simply don’t get the same coverage (报道) as male players.The World Cup is the most widely followed sporting event in the world. According to a report, almost 715 million people watched the final match of the 2006 FIFA World Cup, a ninth of the whole population of the planet. But how many people notice the fact that the FIFA Women’s World Cup has just taken place in Canada? The US team was the winner, after beating the Japanese team 5-2 in the final match. England even got a third place! However, the England team in the men’s World Cup seldom runs to the quarter­finals. While the World Cup enjoys prime­time on most BBC channels, the FIFA Women’s World Cup is put aside. The only time the media (媒体) made the news was when an English player scored an own goal!The inequality doesn’t end with football. Just recently, Caroline Wozniacki (a top Danish tennis player) complained that women don’t get the same chance as men to play on the show courts at Wimbledon. In this case, I think it’s the luck of the draw — the further you get in the competition, the more likely you are to play on the show courts. In the opening stages, it is true that often only the best players w ill play their matches on the show courts. Women’s tennis does get lots of coverage, though many complain that it isn’t exciting to watch.Many people think the women’s sport is often paid less attention to, but I think this is slowly starting to change. In the UK, there is a campaign called This Girl Can, which aims to get girls and women back into sports, regardless of their ages, shapes or sporting abilities. Hopefully this campaign will encourage more people to take up and enjoy sports, and help to redu ce the nation’s health problems.8．The hidden message in Paragraph 1 is that ________.A．female players don’t get much attentionB．male players are more likely to enjoy sportsC．there are more male players than female playersD．the media prefer to provide coverage of female sports9．The author thinks Caroline’s case ________.A．is due to the level of players’ abilityB．is another example of gender inequalityC．helps women’s tennis get a lot of coverageD．leads to disappointment at women’s tennis10．What’s the author’s attitude toward the fixture of women’s sport?A．Negative. B．Positive.C．Unconcemed. D．Doubtful.11．Why does the author expect more women to take part in sports?A．To beat male players.B．To have a household name.C．To achieve their dreams.D．To improve their health.DThe sun rises above the Arctic Ocean (北冰洋). Across the frozen sea, a white bear moves slowly.The bear stops and sways (摇晃) his head from side to side. There is nothing to see but endless ice and red sky. Then his powerful nose senses what his eyes cannot: a beluga whale is nearby.The bear follows the smell and spots a large hole in the ice where a small white whale is swimming. He silently walks toward the hole, then stops, standing still. The whale does not see the bear, whose white fur makes him appear invisible (看不见的) against the ice.Finally, the whale swims close to where the bear is waiting. With terrifying speed, the bear comes to life and moves toward the whale. In a moment it is over, and the bear eats his first meal in nearly a week.Polar bears rule the frozen sea, but their ancestors weren’t always built for ice and snow. The first Arctic bears were brown bears, a species that includes grizzly bears. They came to the icy north over a hundred thousand years ago.No one knows for sure why these bears traveled to such a cold place. Scientists think they might have wandered north looking for food. Maybe they became trapped by glaciers and couldn’t leave. Whatever the reason, the bears never should have survived.But they did. They got used to their new environment. Their bodies changed. Their behavior changed, too. Eventually, the bears developed into an entirely new species: the polar bear. You can see some of the characteristics that polar bears developed to survive.Sadly, these characteristics may now threaten the polar bear’s survival. As sea ice melts due to global warming, polar bears are frequently forced to come ashore (在岸上). They are poor hunters on land, which means they often go a long time between meals. The polar bear, king of the Arctic, is now classified as a threatened species.Although the future of the polar bear is unknown, the tale of two bears continues. As temperatures rise, grizzly bears have been spotted moving north into polar bear territory (领地). These long-lost cousins, once forced apart by nature, are coming back together again.12．What can be inferred about the white bear mentioned in the first four paragraphs?A．It is noisy. B．It is smelly.C．It is starving. D．It has good eyesight.13．What do we know about polar bears’ ancestors?A．They were a darker-colored species.B．They were born to live in ice and snow.C．They had no trouble getting used to the icy north.D．They came to the Arctic Ocean about 1,000 years ago.14．Why are polar bears struggling to survive?A．They are losing their hunting ground.B．They are threatened by other animals.C．They are spending little time on land.D．They have difficulty reaching the shore.15．Which of the following can be the best title for the text?A．The climate changeB．The polar bear’s favorite mealC．The dark past of the polar bearD．The mysteries of the Arctic Ocean第二节(共5小题；每小题2.5分，满分12.5分)根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。

辽宁省锦州市黑山县黑山中学2019-2020学年高一生物6月质量检测试题考试时间：90分钟注意事项：1．答题前填写好自己的姓名、班级、考号等信息2．请将答案正确填写在答题卡上第I卷（选择题）一、单选题（本题共40道小题，每小题1.5分，共60分）1.孟德尔发现遗传基本规律所运用的科学方法是（）A．模型建构法B．类比推理法C．假说一演绎法 D．同位素标记法2.假说﹣演绎法是现代科学研究中常用的方法，包括“提出问题、作出假设、演绎推理、检验推理、得出结论”五个基本环节．利用该方法，孟德尔发现了两个遗传定律．下列关于孟德尔的研究过程的分析正确的是（）A．孟德尔所作假设的核心内容是“性状是由位于染色体上的基因控制的”B．孟德尔依据减数分裂的相关原理进行“演绎推理”的过程C．为了验证作出的假设是否正确，孟德尔设计并完成了测交实验D．测交后代性状比为1：1，可以从细胞水平上说明基因分离定律的实质3.下列关于遗传实验和遗传规律的叙述，正确的是（）A．孟德尔定律描述的过程发生在有丝分裂过程中B．F2的3：1性状分离比一定依赖于雌雄配子的随机结合C．孟德尔巧妙设计的测交方法只能用于检测F1的基因型D．按照孟德尔定律，AaBbCc个体自交，子代基因型有8种4.豌豆的高茎（D）对矮茎为显性，种子黄色（Y）对绿色为显性．假如要对某高茎绿粒豌豆进行测交实验，则与之测交个体的基因型是（）A．DDYY B．DdYy C．ddYy D．ddyy5.在孟德尔两对相对性状的豌豆杂交实验中，F2代中能稳定遗传的个体和性状重组型个体所占的比例分别是A．和 B．和 C．和 D．和6.下列是人类探索遗传奥秘的几个经典实验，其中表述合理的是A．沃森和克里克发现了DNA双螺旋结构，提出了DNA半保留复制方式的假说B．格里菲思用肺炎双球菌感染小鼠的实验，证明了DNA是转化因子C．孟德尔通过豌豆杂交实验发现了基因，摩尔根用实验证明了基因在染色体上D．噬菌体侵染大肠杆菌的实验除了证明DNA是遗传物质外，还证明了蛋白质不是遗传物质7.已知基因型为AaBbCc的植物体自花传粉，后代全显性的个体中，杂合子的几率是A. 27/64B. 37/64C. 9/16D. 26/278.以黄色皱粒(YYrr)与绿色圆粒(yyRR)的豌豆作亲本进行杂交，F1植株自花传粉，从F1植株上所结的种子中任取1粒绿色圆粒和1粒绿色皱粒的种子，这两粒种子都是纯合子的概率为( )A. 1/3B. 1/4C. 1/9D. 1/169.下列关于基因的叙述不正确的是（）A．确认两个基因是相同基因的依据是两者具有相同的碱基排列顺序B．真核生物细胞和原核生物中都有基因存在，病毒没有细胞结构也有基因C．基因是有遗传效应的DNA片段,绿色植物的根尖细胞中，基因存在于染色体、线粒体、叶绿体D．豌豆中控制高茎的基因和控制矮茎的基因位于同源染色体上，基因的基本组成单位是核苷酸10.真核生物进行有性生殖时，通过减数分裂和随机受精使后代（）A．增加发生基因突变的概率B．继承双亲全部的遗传性状C．从双亲各获得一半的DNA D．产生不同于双亲的基因组合11.下列关于基因和染色体在减数分裂过程中行为变化的描述，错误的是（）A．同源染色体分离的同时，等位基因也随之分离B．非同源染色体自由组合，使所有非等位基因之间也发生自由组合C．染色单体分开时，复制而来的两个基因也随之分开D．非同源染色体数量越多，非等位基因组合的种类也越多12.正常人的染色体是46条，在以下细胞中，有可能找到2个X染色体的是（）①精原细胞②卵原细胞③初级精母细胞④初级卵母细胞⑤次级精母细胞⑥次级卵母细胞．A．②③⑤⑥ B．②④⑥C．①③⑤D．②④⑤⑥13.图是某种动物细胞生活周期中染色体数目变化图，据图判断下列叙述错误的是（）A. 等位基因分离、非等位基因自由组合发生在A～C段B. CD段、GH段的染色体与核DNA的数目之比为1∶1C. 图中显示两种分裂方式，Ⅰ～M段可表示有丝分裂的一个细胞周期D. “一母生九子，九子各不同”现象与AH、HI所代表的生理过程有关14.已知甲、乙、丙三图表示细胞分裂过程中DNA含量的变化，下列分析中正确的是( )A. 甲、乙、丙三图分别表示无丝分裂、有丝分裂和减数分裂B. 甲、乙、丙三图中DNA含量加倍的原因相同C. 甲、乙、丙三图中DNA含量减半都与着丝点的分裂有关D. 甲、乙、丙三图中DNA含量减半时，细胞都一分为二15.如图为取自同一哺乳动物不同细胞的细胞分裂示意图（假设该生物的体细胞有4条染色体，基因型为MMNn），下列说法错误的是（）①图甲、乙、丙所示的细胞分裂过程中可发生基因重组②图甲、图乙细胞中含有两个染色体组，图丙、图丁中不具有同源染色体③图丁细胞的名称为次级精母细胞或极体④若相应基因如图丁所示，则说明该细胞在此之前发生了同源染色体非姐妹染色单体之间的交叉互换A. ①②B. ①②⑤C. ③④D. ①②③④16.抗维生素D佝偻病为X染色体显性遗传病，短指为常染色体显性遗传病，红绿色盲为X染色体隐性遗传病，白化病为常染色体隐性遗传病。

黑山中学质量检测高一英语考试试卷科目：英语考试时间：100分钟试卷满分:150分命题人：核对人：注意事项:1．答卷前，考生务必将自己的姓名、考生号等填写在答题卡和试卷指定位置上。

2．回答选择题时，选出每小题答案后，用铅笔把答题卡上对应题目的答案标号涂黑。

如需改动，用橡皮擦干净后,再选涂其他答案标号.回答非选择题时，将答案写在答题卡上.写在本试卷上无效。

3．考试结束后，将本试卷和答题卡一并交回。

第一部分：阅读（共两节，满分50分)第一节（共15小题；每小题2。

5分，满分37.5 分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项。

AWe work with Cambridge County Council's Participation Team to create opportunities for young people to visit the University and learn more about it。

The following events are scheduled for the 2019/2020 academic year.SuperStar workshops12 engaging workshops are planned for young people aged 7 to 11. These half-day visits will be held throughout the year, at times when young people are not at school. If participants complete 8 of the 12 workshops, they will be awarded the nationally recognised SuperStar Crest Award.Please note, workshops will only run if we have a sufficient number of attendees （usually around 3+ participants).Explore University DaysExplore University Days are for young people aged 12-15. Participants visit the University for two days and engage with a range of university—related workshops，and other fun activities.Previous participants have engaged with the following：◆ Visited the Sports Centre◆ Took part in a Neuroscience workshop◆ Enjoyed a two-course meal at a University CollegeDates will be confirmed in early December 2019, and a schedule for event will follow in the New Year。

黑山中学6月质量检测语文（高一）试卷考试时间:150分钟满分150分命题人：审核人:班级: 姓名：考号:注意事项:1．答题前,先将自己的姓名、准考证号填写在试题卷和答题卡上。

2．选择题的作答:每小题选出答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑。

写在试题卷、草稿纸和答题卡上的非答题区域均无效.3．非选择题的作答：用签字笔直接答在答题卡上对应的答题区域。

写在试题卷、草稿纸和答题卡上的非答题区域均无效.一、现代文阅读（36分）（一）论述类文本阅读（共3小题，9分）阅读下面的文字，完成1～3题。

关汉卿与莎士比亚悲剧特点对比关汉卿和莎士比亚在设置人物来推动剧情发展上，都突出了主要人物的重要性和次要人物的辅佐性。

在他们的悲剧中，都只有一个突出的中心人物.关汉卿的《窦娥冤》中，中心人物自然是含冤赴死的窦娥,莎士比亚的《哈姆莱特》《麦克白》《李尔王》《奥赛罗》中，中心人物则显而易见地分别是哈姆莱特、麦克白、李尔王、奥赛罗。

当然,莎士比亚的另外两部悲剧《罗密欧与朱丽叶》和《安东尼与克莉奥佩特拉》,中心人物是处于矛盾漩涡中心的罗密欧与朱丽叶、安东尼与克莉奥佩特拉两对情侣，但他们都是可以当作一体看待的.两位戏剧家的核心人物设置手法，区别于后来出现的“花开两朵,各表一枝"的双主角，甚至多主角的戏剧人物设置，体现了较为保守的戏剧人物设置手法,符合单一戏剧线索的要求。

关汉卿的戏剧人物全部是善恶分明、正邪明晰的典型人物。

正面人物就是一身正气、意志坚定、抗争到底的典型;反面人物则是狡猾奸诈、恶毒卑鄙、瞒上欺下的典型。

这种人物的脸谱化，和中国戏曲的角色脸谱处理是分不开的。

同时，也体现了由于时代的限制，文人思维的固定性一时无法改变。

相比之下，莎士比亚的人物则显得比较丰满和富于多面性。

他所描绘的每一个英雄都有其自身不可消弭的缺陷：哈姆莱特的优柔寡断、奥赛罗的嫉妒冲动、麦克白的好胜野心等.这些都是人类性格共同的缺憾，这样的处理,使得英雄的形象既不被刻意夸大，又显得明朗鲜活、真实可信。

辽宁省锦州市黑山县黑山中学2019-2020学年高一数学6月质量检测试题注意事项：1．答题前填写好自己的姓名、班级、考号等信息 2．请将答案正确填写在答题卡上 第I 卷（选择题）请点击修改第I 卷的文字说明评卷人 得分一、选择题（本题共12道小题，每小题5分，共60分）1.复数2i i 在复平面内对应的点位于（ ）A. 第一象限B. 第二象限C. 第三象限D. 第四象限 2. sin225°的值为（ ）A. 2-B.2C. D.3.函数()2cos2f x x =的最小正周期是（ ） A.4π B.2π C. πD. 2π4.已知3cos 25πα⎛⎫-= ⎪⎝⎭，则cos α=（ ）A.35 B. 45-C.45D.45± 5.在△ABC 中，2a =，3b =，则sin :sin A B 的值是（ ）A.23B.32C.25 D.526.在△ABC 中，角A 、B 的对边分别为a 、b ，根据下列条件解三角形，其中有两解的是（ ）A. 50a =，30b =，60A =B. 30a =，65b =，30A =C. 30a =，60b =，30A =D. 30a =，50b =，30A =7.已知1a =，=(0,2)b ，且1a b ⋅=，则向量a 与b 夹角的大小为( )A.6π B.4π C.3π D.2π 8.在△ABC 中，60A ︒∠=，||2AB =，||1CA =，则AB CA ⋅的值为（ ）A. －1B. 12-C.12D. 1 9.已知12,e e 是单位向量，若12|4|13e e -=则1e 与2e 的夹角为（ ）A. 30°B. 60°C. 90°D.120°10.已知函数()sin()f x x ωϕ=+（0>ω，0ϕπ<<）的最小正周期为π，且图象向右平移6π个单位后得到函数()cos g x x ω=的图象，则ϕ=（ ）A. 6π B.3π C.23π D.56π11.已知函数()sin f x a x x =-的图像的一条对称轴为直线56x π=，且12()()4f x f x ⋅=-，则12x x +的最小值为( )A. 3π-B. 0C.3π D.23π 12.在△ABC 中，内角A 、B 、C 所对的边分别为a 、b 、c ，已知23C π=，sin 3sin B A =，若△ABC 的面积为，则c =（ ）A. B.C. D.第II 卷（非选择题）评卷人 得分二、填空题（本题共4道小题，每小题5分，共20分）13.若复数()13z i i +=-，则z =______.14.在△ABC 中，内角A 、B 、C 的对边分别是a 、b 、c ，若223a b bc -=，sin 23sin C B =，则A =____.15.已知a →，b →为单位向量，2c a b →→→=-，且,3a b π→→<>=，则,a c →→〈〉=________．16.如图，在边长为2的菱形ABCD 中60BAD ∠=，E 为CD 中点，则AE BD ⋅= 、评卷人 得分三、解答题（共6道小题,第17题10分,其它各题每题12分）17.已知z 为复数，2z i +和2zi-均为实数，其中i 是虚数单位.(1)求复数z 和z ；(2)若11712z z i m m =+--+在第四象限，求m 的取值范围.18.已知函数f (x )＝2sin x cos x ＋32x 3 (1)求函数f (x )的最小正周期和单调减区间；(2)已知△ABC 的三个内角A ，B ，C 的对边分别为a ，b ，c ，其中a ＝7，若锐角A 满足π26A f ⎛⎫-= ⎪⎝⎭，且sin sin B C +=bc 的值．19.在△ABC 中，a 、b 、c 是角A 、B 、C 所对的边，且()2cos cos 0a b C c A -+=.（1）求C 的大小；（2）若2b =，c =AB 边上的高.20.已知2,1a b ==，a b 与的夹角为45°.（1）求a b 在方向上的投影； （2）求2a b +的值;（3）若向量()2-3a b a b λλ-与（的夹角是锐角，求实数λ的取值范围.21.已知函数()21cos 2cos f x x x x m =--+在R 上的最大值为3.（1）求m 的值及函数f (x )的单调递增区间;（2）若锐角△ABC 中角A 、B 、C 所对的边分别为a 、b 、c ，且()0f A =，求b c的取值范围.22.在△ABC 中，a ，b ，c 分别是角A ，B ，C 的对边，向量BA 与AC 的夹角的余弦值为13。

黑山中学质量检测高一化学试卷可能用到的原子量：Zn-65一、选择题(本题包括20小题，每小题3分，共60分)1.下列我国科研成果所涉及材料中，主要成分为同主族元素形成的无机非金属材料的是（）A.4.03米大口径碳化硅反射镜B.2022年冬奥会聚氨酯速滑服C.能屏蔽电磁波的碳包覆银纳米线D.“玉兔二号”钛合金筛网轮A. AB. BC. CD. D【答案】A【解析】【详解】A．碳化硅(SiC)是由碳元素和硅元素组成的无机非金属材料，且碳元素与硅元素均位于元素周期表第IVA族，故A符合题意；B．聚氨酯为有机高分子化合物，不属于无机非金属材料，故B不符合题意；C．碳包覆银纳米材料属于复合材料，不属于无机非金属材料，且银不是主族元素，故C不符合题意；D．钛合金为含有金属钛元素的合金，其属于金属材料，不属于无机非金属材料，故D不符合题意；答案选A。

【点睛】创新点在于除了要判断是否为无机非金属材料，还给其加了限制条件“同主族”，应注意有机物中一定含碳元素，但含碳元素的却不一定是有机物。

2.大气中CO2含量的增加会加剧“温室效应”。

下列活动会导致大气中CO2含量增加的是（）A. 节约用水用电B. 利用风力发电C. 增加植被面积D. 燃烧煤炭供热【答案】D【解析】【详解】A．我国的电能来源主要来自燃煤发电，节约用水用电可以节约能源燃烧，会降低大气中CO2的含量，故A不符合题意。

B．利用风力发电能可以减少燃煤发电，从而减少CO2的排放，故B不符合题意；C．增加植被面积，绿色植物的光合作用能吸收CO2，降低大气中CO2的含量，故C不符合题意；D．燃烧煤炭供热，煤炭的主要成分是碳，燃烧会产生二氧化碳，导致大气中CO2的含量增加，故A符合题意；答案选D。

3.下列表述正确的是（）A. 硅晶体具有半导体性能，可用于光导纤维B. 常温下铁能被浓硝酸钝化，可用铁质容器贮运浓硝酸C. 浓硫酸具有吸水性，故能使蔗糖炭化D. SO2能使酸性KMnO4溶液褪色，体现了SO2的漂白性【答案】B【解析】【分析】A.光导纤维主要成分为二氧化硅；B.依据浓硝酸强氧化性解答；C.依据浓硫酸脱水性解答；D.依据二氧化硫还原性解答。

2019年辽宁省锦州市黑山县第二中学高一化学上学期期末试卷含解析一、单选题（本大题共15个小题，每小题4分。

在每小题给出的四个选项中，只有一项符合题目要求，共60分。

）1. 对于放热反应Zn＋H2SO4===ZnSO4＋H2↑，下列叙述正确的是()A. 反应过程中的能量关系可用上图表示B. 1 mol Zn的能量大于1 mol H2的能量C. 若将其设计为原电池，则锌作正极D. 若将其设计为原电池，当有32．5 g Zn溶解时，正极放出的气体一定为11．2 L参考答案：A根据能量守恒，则反应物的总能量高于生成物的总能量，该反应为放热反应，锌和硫酸反应为放热反应，A正确；反应物的总能量高于生成物的总能量，反应物和生成物均有两种，无法比较1molZn和1molH2的能量大小，B错误；若将其设计为原电池，锌化合价升高，失电子，则锌作负极，C错误；若将其设计为原电池，当有32.5gZn溶解时，消耗锌的物质的量为，根据反应方程式可知生成，但气体所处状态未知，不能确定气体体积，D错误；正确选项A。

2. 2004年4月19日，温家宝总理批示：严查安徽“杀人奶粉”。

经检测“杀人奶粉”中蛋白质、钙、磷、锌、铁等含量严重不足，营养价值比米汤还差。

这里的钙是指（）A．原子 B．分子 C．元素 D．单质参考答案：C略3. 下列各组物质用水就能鉴别的是A．苯、四氯化碳、酒精 B．四氯化碳、溴乙烷、苯C．酒精、溴乙烷、硝基苯 D．电石、大理石参考答案：AD略4. A、B两种烃，它们含碳质量分数相同，下列关于A和B的叙述正确的是A．A和B一定是同分异构体 B．A和B不可能是同系物C．A和B最简式一定相同 D．A和B的化学性质相似参考答案：C略5. 自来水常用Cl2消毒，某学生用这种自来水去配制下列物质的溶液，不会产生明显的药品变质问题的是( )A．AgNO3B．FeCl2C．Na2SO3D．AlCl3参考答案：D略6. 下列反应的离子方程式正确的是()A．氢氧化钠溶液中通入少量二氧化硫：SO2＋OH－===HSOB．碳酸氢钠溶液与足量氢氧化钡溶液混合：HCO＋Ba2＋＋OH－===BaCO3↓＋H2OC．盐酸滴入氨水中：H＋＋OH－===H2OD．碳酸钙溶解于稀硝酸中：CO＋2H＋===CO2↑＋H2O参考答案：B略7. 下列各组溶液中离子，能在溶液中大量共存的是A．OH－、Ca2+、NO3－、SO32－B．Ca2＋、HCO3－、Cl－、K＋C．NH4+、Ag+、NO3－、I－D．K+、OH－、Cl－、HCO3－参考答案：BA.Ca2+、SO32－发生反应，生成微溶于水的CaSO3，所以不能大量共存，故不选A；B.Ca2＋、HCO3－、Cl－、K＋之间，不发生反应，所以可以大量共存，故选B；C.Ag+、I－发生反应，生成AgI固体，所有不能大量共存，故不选C；D.OH－、HCO3－生成水和碳酸根离子，所有不能大量共存，故不选D；本题答案为B。

黑山县黑山中学2021-2021学年高一英语6月质量检测试题考试时间是是：100分钟试卷满分是：150分考前须知：1．答卷前，所有考生必须将本人的姓名、考生号等填写上在答题卡和试卷规定的正确位置上.2．答复选择题时，选出每一小题答案后，用铅笔把答题卡上对应题目之答案标号涂黑.如需改动，用橡皮擦干净后，再选涂其他答案标号.答复非选择题时，将答案写在答题卡上.写在套本套试卷上无效.3．在在考试完毕之后以后，将本套试卷和答题卡一起交回.第一局部:阅读(一共两节，满分是50分)第一节(一共15小题;每一小题2.5分，满分是37.5 分)阅读以下短文，从每一小题所给的A、B、C、 D四个选项里面选出最正确选项。

.AWe work with Cambridge County Council's Participation Team to create opportunities for young people to visit the University and learn more about it. The following events are scheduled for the 2021/2021 academic year.SuperStar workshops12 engaging workshops are planned for young people aged 7 to 11. These half-day visits will be held throughout the year, at times when young people are not at school.If participants complete 8 of the 12 workshops, they will be awarded the nationally recognised SuperStar Crest Award.Please note, workshops will only run if we have a sufficient number of attendees (usually around 3+ participants).Explore University DaysExplore University Days are for young people aged 12-15. Participants visit the University for two days and engage with a range of university-related workshops, and other fun activities.Previous participants have engaged with the following:◆ Visited the Sports Centre◆ Took part in a Neuroscience workshop◆ Enjoyed a two-course meal at a University CollegeDates will be confirmed in early December 2021, and a schedule for event will follow in the New Year.Events for post-16 studentsIf you are studying for your post-16 qualifications and are considering applying for Cambridge or would like to find out more about a specific subject, the following events might be for you:◆ University and College Open Days◆ Subject M asterclasses◆ Cambridge Science Festival1. What can the participants do in SuperStar workshops?A. To stay only half a day.B. To get a gift.C. To enjoy a free meal.D. To visit all the 12 workshops.2. Which event is specially for applicants of Cambridge?A. SuperStar workshops.B. Events for post-16 students.C. Explore University Days.D. The Neuroscience workshop.3. The events in the passage most probably aim to .A. introduce some coursesB. advertise Cambridge UniversityC. enrich students' spare time lifeD. promote children's interest in touringBWalk around the city of Ann Arbor, Michigan, and you may see a green animal named Sluggo and a flying pig named Philomena.You might even see street artist David Zinn drawing them using only sidewalk chalk and charcoal (炭笔)．At the age of 12, David began working as an artist.His dad was writing a computer instruction and worried that it would be boring to read.So he asked David to draw pictures of turtles (the name of the computer program) to explain it.The publisher liked his drawings, and soon David had the job of drawing more turtles in action.“I learned a great lesson, which was that, to make money as an artist, I couldn't always draw what I wanted，〞he says.“I had to figure out how to draw a turtle drinking tea and other things like that.〞David worked for 20 years as a commercial (商业的) artist, but he often felt cooped up (禁锢) sitting at a computer for 10 hours a day.Then, on a sunny afternoon about ten years ago, he brought some chalk and started drawing on the sidewalk.That'swhen Sluggo came to life.“One of the reasons I like to put art on the street is to take peop le by surprise，〞he says.“I can have fun drawing, and knowing it will be washed away helps me not think too much.It frees me up.〞It takes David about two hours to complete one drawing.He uses a lot of sidewalk characteristics in his street art.It can be difficult to draw on surfaces that are not flat.He has to notice where shadows will land so they won't destroy the 3D drawings he creates.Today, more and more people are accepting and looking for his work.David's artwork can also be found across the country and even throughout the world.Photos of his drawings have been shown at many universities and museums.4.What did David learn from drawing turtles for his father?A．Work hard. B．Follow your heart.C．Draw what you like. D．Draw in a creative way.5．How does David feel when knowing his drawing will be washed away?A．Relaxed. B．Worried.C．Unhappy. D．Surprised.6．In what way is David's art special?A．It shows his real life.B．It is drawn on the flat sidewalk.C．It needs a very long time to finish a drawing.D．It is 3D street art created by simple painting tools.7．What do we know about David's drawings?A．They are becoming popular.B．They are too difficult to understand.C．They are found mainly at museums.D．They are hardly accepted by adults.CHow many sports stars can you name? Whether it's ten or thirty, I believe that 90% of them would be male (男性). Even in today's society, which calls for gender equality (男女平等), it seems that female sports stars simply don't get the same coverage (报道) as male players.The World Cup is the most widely followed sporting event in the world. According to a report, almost 715 million people watched the final match of the 2021 FIFA World Cup, a ninth of the whole population of the planet. But how many people notice the fact that the FIFA Women's World Cup has just taken place in Canada? The US team was the winner, after beating the Japanese team 5­2 in the final match. England even got a third place! However, the England team in the men's World Cup seldom runs to the quart er­finals. While the World Cup enjoys prime­time on most BBC channels, the FIFA Women's World Cup is put aside. The only time the media (媒体) made the news was when an English player scored an own goal!The inequality doesn't end with football. Just recently, Caroline Wozniacki (a top Danish tennis player) complained that women don't get the same chance as men to play on the show courts at Wimbledon. In this case, I think it's the luck of the draw — the further you get in the competition, the more likely you are to play on the show courts. In the opening stages, it is true that often only the best players will play their matches on the show courts. Women's tennis does get lots of coverage, though many complain that it isn't exciting to watch.Many people think the women's sport is often paid less attention to, but I think this is slowly starting to change. In the UK, there is a campaign called This Girl Can, which aims to get girls and women back into sports, regardless of their ages, shapes or sporting abilities. Hopefully this campaign will encourage more peopleto take up and enjoy sports, and help to reduce the nation's health problems.8．The hidden message in Paragraph 1 is that ________.A．female players don't get much attentionB．male players are more likely to enjoy sportsC．there are more male players than female playersD．the media prefer to provide coverage of female sports9．The author thinks Caroline's case ________.A．is due to the level of players' abilityB．is another example of gender inequalityC．helps women's tennis get a lot of coverageD．leads to disappointment at women's tennis10．What's the author's attitude toward the fixture of women's sport?A．Negative. B．Positive.C．Unconcemed. D．Doubtful.11．Why does the author expect more women to take part in sports?A．To beat male players.B．To have a household name.C．To achieve their dreams.D．To improve their health.DThe sun rises above the Arctic Ocean (北冰洋). Across the frozen sea, a white bear moves slowly.The bear stops and sways (摇摆) his head from side to side. There is nothing to see but endless ice and red sky. Then his powerful nose senses what his eyes cannot: a beluga whale is nearby.The bear follows the smell and spots a large hole in the ice where a small whitewhale is swimming. He silently walks toward the hole, then stops, standing still. The whale does not see the bear, whose white fur makes him appear invisible (看不见的) against the ice.Finally, the whale swims close to where the bear is waiting. With terrifying speed, the bear comes to life and moves toward the whale. In a moment it is over, and the bear eats his first meal in nearly a week.Polar bears rule the frozen sea, but their ancestors weren't always built for ice and snow. The first Arctic bears were brown bears, a species that includes grizzly bears. They came to the icy north over a hundred thousand years ago.No one knows for sure why these bears traveled to such a cold place. Scientists think they might have wandered north looking for food. Maybe they became trapped by glaciers and couldn't leave. Whatever the reason, the bears never should have survived.But they did. They got used to their new environment. Their bodies changed. Their behavior changed, too. Eventually, the bears developed into an entirely new species: the polar bear. You can see some of the characteristics that polar bears developed to survive.Sadly, these characteristics may now threaten the polar bear's survival. As sea ice melts due to global warming, polar bears are frequently forced to come ashore (在岸上). They are poor hunters on land, which means they often go a long time between meals. The polar bear, king of the Arctic, is now classified as a threatened species.Although the future of the polar bear is unknown, the tale of two bears continues. As temperatures rise, grizzly bears have been spotted moving north into polar bear territory (领地). These long­lost cousins, once forced apart by nature, are coming back together again.12．What can be inferred about the white bear mentioned in the first fourparagraphs?A．It is noisy. B．It is smelly.C．It is starving. D．It has good eyesight.13．What do we know about polar bears' ancestors?A．They were a darker­colored species.B．They were born to live in ice and snow.C．They had no trouble getting used to the icy north.D．They came to the Arctic Ocean about 1,000 years ago.14．Why are polar bears struggling to survive?A．They are losing their hunting ground.B．They are threatened by other animals.C．They are spending little time on land.D．They have difficulty reaching the shore.15．Which of the following can be the best title for the text?A．The climate changeB．The polar bear's favorite mealC．The dark past of the polar bearD．The mysteries of the Arctic Ocean第二节(一共5小题；每一小题分，满分是分)根据短文内容，从短文后的选项里面选出能填入空白处的最正确选项。