甘肃省武威第五中学武威期中、武威十六中2017-2018学年高二下学期期末联考英语试题 Word版含解析

2017-2018学年第二学期武威五中高二年级生物试卷第Ⅰ卷一、选择题（共60分，每小题2分）1．育种专家在稻田中发现了一株十分罕见的“一秆双穗”植株，经鉴定该变异性状是由基因突变引起的。

下列叙述正确的是( )A．这种现象是由显性基因突变成隐性基因引起的B．该变异株自交可产生这种变异性状的纯合个体C．观察细胞有丝分裂中期染色体形态可判断基因突变发生的位置D．将该株水稻的花粉离体培养后即可获得稳定遗传的高产品系2.玉米花药培养的单倍体幼苗，经秋水仙素处理后形成二倍体植株。

如图是该过程中某时段细胞核DNA含量变化示意图。

下列叙述错误的是( )A．a～b过程中细胞内不会发生基因重组B．c～d过程中细胞内发生了染色体数加倍C．e点后细胞内各染色体组的基因组成相同D．f～g过程中同源染色体分离，染色体数减半3.下图表示生物新物种形成的基本环节，对图示分析正确的是（）A.图中A表示基因突变和基因重组，为进化提供原材料B.种群基因频率的定向改变是形成新物种的前提C.图中B表示地理隔离，是新物种形成的必要条件D.图中C表示生殖隔离，指两种生物不能杂交产生后代4. 下列关于基因工程的叙述，正确的是( )A.基因工程经常以抗菌素抗性基因为目的基因B.细菌质粒是基因工程常用的运载体C.通常用一种限制性内切酶处理含目的基因的DNA，用另一种处理运载体DNAD.为育成抗除草剂的作物新品种，导入抗除草剂基因时只能以受精卵为受体5．下列关于杂交育种与诱变育种的叙述正确的是( )A．诱变育种是通过改变原有基因结构而导致新品种出现的方法B ．基因重组是杂交育种的原理，基因重组发生在受精作用过程中C ．诱变育种一定能较快选育出新的优良品种D ．通过杂交育种方式培育新品种，从F 1就可以进行选择6．人们试图利用基因工程的方法，用乙种生物生产甲种生物的一种蛋白质。

生产流程是：甲生物的蛋白质→mRNA――→①目的基因――→②与质粒DNA 重组――→③导入乙细胞――→④获得甲生物的蛋白质，下列说法正确的是( )A ．①过程需要的酶是逆转录酶，原料是A 、U 、G 、CB ．②要用限制酶切断质粒DNA ，再用DNA 连接酶将目的基因与质粒连接在一起C ．如果受体细胞是细菌，可以选用枯草杆菌、炭疽杆菌等D ．④过程中用的原料不含有A 、U 、G 、C7．马体细胞中有64个染色体，驴体细胞中有62个染色体。

武威第五中学第二学期高二物理期末试卷武威第五中学第二学期高二物理期末试卷答案命题人：韩明一、选择题（本题共15小题，每小题4分，共60分．1-9单选，10-15多选，全部选对的得4分，选不全的得2分，有选错或不答的得0分）二、本题共4小题，共40能得分，有数值计算的题，答案中必须明确写出数值和单位．16．（12分）（1）核聚变的反应方程为ν224014211++→e He H ，每次核聚变中的质量亏损4.39×10-29Kg（2）太阳辐射能量的总功率为3.84×1026W； （3）太阳的寿命为1×1010年．解析：（1）ν224014211++→e He H 2mc ∆=∆EKg 29281961039.4)103(106.1107.24m ---⨯=⨯⨯⨯⨯=∆（2）P1=W10×1.362.03.0130=--PP=P14πr2=1.36×118×4×3.14×(1.5×1011)2=3.84×1026W (3)每秒消耗的质子质量为1960106.1107.241026W×3.84--⨯⨯⨯=∆=E P m ×4×1.67×10-27=6.5×1011kg （或6.4×1011kg）太阳寿命t=1130010×6.5 10%×10×2=m M =3×1017s=1×1010年17．（8分）解：S=AB ×BC=10cm ×4cm=40cm ²=0.018m ² E=BS ω=1.5T×0.018m ²×120rad/s=0.72V 18．（8分）解：输出电流I=P /U =20000W/400V=50A, …………（2分）输电线上损失的电功率P' =I²R =（50A ）²×0.5Ω=1250W , …………（2分） 用电户得到的电功率P=P —P'=20000W —1250W=18750W…………（4分） 19．解：（12分）依题意： （1）线圈中的感应电动势 （2）电路中产生的电流（3）线圈两端的电压一、选择题（本题共15小题，每小题4分，共60分．1-9单选，10-15多选，全部选对的得4分，选不全的得2分，有选错或不答的得0分） 1. 分子大小的数量级约为（ ） A.10－8cm B.10－10cmC.10－8mmD.10－8m 2. 下列可算出阿伏加德罗常数的一组数据是（ ）A ．水的密度和水的摩尔质量B ．水的摩尔质量和水分子的体积C ．水分子的体积和水分子的质量D ．水分子的质量和水的摩尔质量3．有两个完全相同的电阻，一个通以10A 的直流电流,热功率为P ，另一个通以正弦式交变…………（5分）20V =V 0.020.01×0.4×100=Δt ΔBS n =Δt ΔΦn =E A＝2A 9.5＋0.520＝r +R E =I …………（5分）…………（5分）19V=9.5×2=IR =U电流，热功率为2P ，那么 （ ） A ．交流的有效值为10AB ．交流的最大值为10AC ．交流的有效值为20AD ．交流的最大值为20A4．U23892衰变成Th23490，之后Th23490衰变成Pa23491，Pa 处于高能级，它向低能级跃迁时辐射一个粒子．在这个过程中，前两次衰变放出的粒子和最后辐射的粒子依次是A ．粒子、粒子、光子B ．粒子、光子、粒子C ．粒子、光子、中子D ．光子、电子、粒子5．“朝核危机”引起全球瞩目，其焦点就是朝鲜核电站采用轻水堆还是重水堆．重水堆核电站在发电的同时还可以生产出可供研制核武器的钚239（Pu23994），这种钚239可由铀239（U23992）经过n 次衰变而产生，则n 为A ．2B ．239C ．145D ．926．如图所示，物块A 、B 静止在光滑水平面上，且BA m m ，现用大小相等的两个力F 和F/分别作用在A 和B 上，使A 、B 沿一条直线相向运动，然后又先后撤去这两个力，使这两个力对物体做的功相同，接着两物体碰撞并合为一体后，它们A ．可能停止运动B ．一定向右运动C ．可能向左运动D ．仍运动，但运动方向不能确定7．当两个中子和两个质子结合成一个粒子时，放出28．30MeV 的能量，当三个粒子结合成一个碳核时，放出7．26MeV 的能量，则当6个中子和6个质子结合成一个碳核时，释放的能量为A ．21．18MeVB ．35．56MeVC ．92．16MeVD ．77．64MeV8．月球上特有的能源材料He 32，总共大约有100万吨，这是由于太阳风里带有大量中子打入月表面的X 粒子中，形成He32，月球表面稀薄气体里，每立方厘米中有数个He32分子，收集这些He 32可以在月球上建立He 32发电站，其中X 粒子应该为A ．He 52 B ．He424 C ．He323D ．H 1129．如图3为理想变压器原线圈所接电源电压波形，原副线圈匝数之比n1∶n2 = 10∶1，串联在原线圈电路中电流表的示数为1A ，下则说法正确的是（ ）A ．变压器输出两端所接电压表的示数为222VB ．变压器输出功率为2202WC ．变压器输出的交流电的频率为50HZD ．该交流电每秒方向改变50次10．对于扼流圈的以下说法，正确的是（ ） A ．低频扼流圈用来“通低频、阻高频” B ．扼流圈是利用电感阻碍交变电流的作用制成的 C ．高频扼流圈用来“通直流、阻交流”D ．高频扼流圈对低频交变电流阻碍作用小，对高频交变电流阻碍作用大11．理想变压器的原线圈接正弦式电流，副线圈接负载电阻Ｒ，若输入电压不变，要增大变压器的输出功率，可行的措施有（ ）Ａ．只增大负载电阻Ｒ的阻值 Ｂ．只减小负载电阻Ｒ的阻值 Ｃ．只增大原线圈的匝数 Ｄ．只增大副线圈的匝数12. 在用油膜法估测分子的大小的实验中，若已知油的摩尔质量为M ，密度为p ，油滴质量为m ，油滴在液面上扩散后的最大面积为S ，阿伏加德罗常数为N A ，以上各量均采用国际单 位，那么（ ） A ．油滴分子直径S M d ⋅=ρ B ．油滴分子直径Smd ⋅=ρ C ．油滴所含分子数A N m M n ⋅=D ．油滴所含分子数A N Mmn ⋅= 13. 已知阿伏伽德罗常数为N ，铝的摩尔质量为M ，铝的密度为P ，则下列说法正确的是（ ） A ．1kg 铝所含原子数为PN B ．1个铝原予的质量为M ／N C ．1m 铝所含原子数为N ／(PM) D ．1个铝原子所占的体积为M ／(PN)22202220-14. 关于温度，以下说法正确的是 （ ） Ａ.温度是表示物体冷热程度的物理量 B.温度是物体内大量分子平均动能的标志 C.温度是物体内大量分子平均速率的标志 Ｄ.一切达到热平衡的系统都具有相同的温度15．一只小球沿光滑水平面运动，垂直撞到竖直墙上．小球撞墙前后的动量变化量为p ∆，动能变化量为E ∆，下列关于p ∆和E ∆说法中正确的是A ．若p ∆最大，则E ∆也最大； B ．若p ∆最大，则E ∆一定最小； C ．若p ∆最小，则E ∆也最小； D ．若p ∆最小，则E ∆一定最大二、本题共4小题，共40能得分，有数值计算的题，答案中必须明确写出数值和单位． 16．（12分）太太阳内部进行着多种核聚变反应过程，反应过程可简化为：四个质子聚变为一个氦核，同时放出24.7MeV 的能量．这个核反应释放出的能量就是太阳不断向外辐射能量的来源．（1）请写出这个核聚变的反应方程，并计算每次核聚变中的质量亏损．（2）已知地球的半径R=6400km ，地球到太阳的距离r=1.5×1011m，太阳能照射到地球上时，有约30%在穿过大气层的过程中被云层或较大的粒子等反射，有约20%被大气层吸收．现测得在地球表面 垂直太阳光方向每平方米面积上接收到太阳能的平均功率为P0=6.8×102W，求太阳辐射能量的总功率；（3）若太阳辐射的能量完全来源于上述第（1）问中的核反应，假设原始太阳的质量为2.0×1180kg ，并且只有其10%的质量可供核反应中“亏损”来提供能量，质子的质量mH=1.67×10-27kg ，1年=3×118秒，试估算太阳的寿命．（保留1位有效数字）17．（8分）如图当线圈以P 为10cm ，BC 为4cm ，角速度ω=120rad/s 。

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甘肃省武威第五中学2017—2018学年高二数学下学期第二次月考试题文一、选择题（共 12 小题，每小题 5 分，共 60 分）1.是虚数单位，等于（ )A。

B。

C。

D.2。

根据程序框图，若输出的值是,则输入的实数的值为（ )A.B。

C。

或D。

或3.若(为虚数单位），则复数的虚数部分为（）A。

B。

C.D。

4。

一名中学生在家庭范围内推广“节水工程”–做饭、淘米、洗菜的水留下来擦地或浇花，洗涮的水留下来冲卫生间（如图）,该图示称为（）A。

流程图 B.程序框图C.组织结构图D。

知识结构图5。

在复平面内，复数对应的点位于（）A.第一象限B.第二象限C.第三象限D。

第四象限6。

某成品的组装工序流程图如图所示，箭头上的数字表示组装过程中所需要的时间（小时）,不同车间可同时工作,同一车间不能同时做两种或两种以上的工作，则组装该产品所需要的最短时间是( ）A.小时B.小时C 。

小时 D.小时7。

复数（为虚数单位)，为的共轭复数，则下列结论正确的是（）A 。

的实部为B 。

的虚部为C 。

D.8.已知复数满足,则A. B.C 。

D 。

9。

已知复数和复数，则为( ）A.B 。

C. D.10.设复数满足，则等于（ )A.B 。

C. D.11。

2017-2018学年甘肃省武威第五中学、武威三中、武威七中、武威十六中高二下学期期末联考英语试卷考试总分：150分考试时间： 120 分钟注意事项：1．答题前填写好自己的姓名、班级、考号等信息;2．请将答案正确填写在答题卡上;一、阅读理解（共 20 小题，每小题 2分，共40分）AAre you interested in higher education in the United States？The foll owing advice might help you．●Coll ege，University or InstituteColl ege and universities offer und ergraduate d egrees in arts and sciences．And both can help prepare young peopl e to earn a living．But many coll eges d on’t offer graduate studie s．Universities are generally bigger,offer more programs and d o more research．An insti tute of technol ogy can offer a wid e choice of programs and activities．Seventyfive percen t of freshmen go there with a strong interest and involvement in the arts．●The Application ProcessInternational admissions officers advise stud ents to apply to at l east three schools．You may be abl e to apply online and pay the application charge with a credit card,or by mail ．You should study the websites of schools to find information about how and when to ap ply,how much it will cost and whether any financial aid is availabl e．●Get a Stud ent CardIf you requesting a visa for the first time，you will have to go to an American embassy or consulate（领馆）．You will need to bring a government form sent to you by your American school that shows you have been accepted．A consular official will also take your picture and your fi ngerprints．You will also need banking and tax records that show you have enough money to pay for your education．●Financial AidAmerican schools provid e aid，like scholarships，fell owships,to almost half of foreign graduate stud ents，but only ten percent of und ergraduates．But grants，which，unlike a loan，d oes not have to be paid．1．It can be inferred from the passage that American coll eges and universities________．A．have their own origins in institutes of technol ogyB．have both similarities and differencesC．can offer a wid e choice of programs and activitiesD．provid e about seventy-five percent stud ents with art courses2．In what ord er should the steps for applying to an American school be compl eted by a f oreign stud ent？________a．Apply onlineb．Find out how much it will cost and whether any financial aid is availabl e online c．Pay the application charge with a credit card，or by maild．Choose at l east three schoolse．Find information about how and when to apply onlineA．a-c-e-d-b B．e-d-c-a-b C．d-a-c-e-b D．b-c-e-d-a3．To apply for a vise for the first time，you’ll have to d o the following things EXCEPT________．A．paying an American embassy or consulate some moneyB．taking your picture and your fingerprintsC．showing a government form given by the American school admitting you D．providing evid ence that you have enough money to pay for your education4．The purpose of the passage is________．A．to make some moneyB．to provid e foreign stud ents with a guid eC．to improve education qualityD．to attract foreign visitors to America．BTim Richter and his wife，Linda，had taught for over 30 years near Buffalo，New York-he in computers,she in special education．―Teaching means everything to us，‖Tim would sa y．In April 1998,he learned he would need a heart operation．It was the kind of news that lea ds to some serious thinking about life’s purpose．Not long after the surgery，Tim saw a brochure describing Imagination Library,a program started by Dolly Parton’s found ation（基金会）that mailed a book every month to children from birth to age five in the singer’s home town of Sevier，Tennessee．―I thought，maybe Linda and I could do something like this when we retire，‖Tim recalls．He placed the brochure on his desk，―as a reminder．‖Five years later，now retired and with that brochure still on the desk，Tim clicked on imaginationlibrary．com．The program had been opened up to partners who could take advantage of book and postage discounts．The quality of the books was of great concern to the Richters．Rather than sign up online，they went to Dollywood for a look-see．―We didn’t want to give the children rubbish，‖says Linda．The books-reviewed each year by teachers，literacy specialists，and Dollywood board members-included classics such as Ezra Jack Keats’s The Snowy Day and newer books like Anna Dewd ney’s Llama Llama series．Satisfied，the couple set up the Richter Family Foundation and got to work．Since 2004，they have shipped more than 12，200 books to preschoolers in their area．Megan Williams，a mother of four，is more than appreciative：―This program introduces us to books I’ve never heard of．‖The Richters spend about﹩400 a month sending books to 200 children．―Some people sit there and wait to die，‖says T im．―Others get as busy as they can in the time they have left．‖5．What led Tim to think seriously about the meaning of life？________A．His health problem．B．His love for teaching．C．The influence of his wife．D．The news from the Web．6．What did Tim want to do after learning about Imagination Library？________A．Give out brochures．B．Do something similar．C．Write books for children．D．Retire from being a teacher．7．Why did the Richters go to Dollywood？________A．To avoid signing up online．B．To meet Dollywood board members．C．To make sure the books were the newest．D．To see if the books were of good quality．8．What can we learn from Tim’s words in the last paragraph？________A．He needs more money to help the children．B．He wonders why some people are so busy．C．He tries to save those waiting to die．D．He considers his efforts worthwhile．CCan dogs and cats live in perfect harmony in the same home？People who are thinking about adopting a dog as a friend for their cats are worried that they w ill fight．A recent research has found a new recipe of success．According to the study，if the cat is adopted before the dog，and if they are introduced when still young （less than 6 months for cats，a year for dogs），it is highly probable that the two pets will get along ．Two-thirds of the homes interviewed reported a positive relationship between their cat and dog． However，it wasn’t all sweetness and��light．There was a reported coldness between the cat and dog i n 25% of the homes，while aggression and fighting were observed in 10% of the homes．One reason for this is pro bably that some of their body signals were just opposite．For example，when a cat turns its head away it signals aggression，while a dog doing the same signals submission．In homes with cats and dogs living peacefully，researchers observed a surprising behaviour．They are learning how to talk each other’s lang uage．It is a surprise that cats can learn how to talk’dog’，and dogs can learn how to talk’Cat’．What’s interesting is that both cats and dogs have appeared to develop their intelligence．T hey can learn to read each other’s body signals，suggesting that the two may have more in common than we previously suspected．Once fami liar with each other’s presence and body language，cats and dogs can play together，greet each other nose to nose，and enjoy sleeping together in the sofa．They can easily share the same water bowl and in so me cases groom（梳理）each other．The significance of this research on cats and dogs may go beyond pets–to people who don’t get along，including neighbors，colleagues at work，and even world superpowers．If cats and dogs can learn to get along，surely people have a good chance．9．The underlined word swimmingly in paragraph 1 is closest in meaning to________．A．earlyB．sweetlyC．quicklyD．smoothly10．Some cats and dogs may fight when________．A．they are cold to each otherB．they look away from each otherC．they misunderstand each other’s signalsD．they are introduced at an early age11．What is found surprising about cats and dogs？________A．They eat and sleep togetherB．They observe each others behaviorsC．They learn to speak each other’s languageD．They know something from each other’s voice12．What can we human beings learn from cats and dogs？________A．We should learn to live in harmonyB．We should knows more about animalsC．We should live in peace with animalsD．We should learn more body languages．DCherish the Moments with Our ParentsThere was something in an elderly woman’s behavior that caught my eye．Unsure of her step s，the woman moved slowly，along with a younger woman who I guessed was her daughter．The daughter was rolling her eyes and checking her watch every few seconds．The older woman left the younger one and began to tick through the DVDs on the nearest shel f．Without hesitation，I walked over and asked if I could help her find something．The woman smiled at me and sh owed me a title on a piece of paper．Rather than rush off to locate the DVD for the woman，I asked her to walk with me so I could show her where she could find it．Looking back，I think I wanted to enjoy her company for a moment．Her movements reminded me of my o wn mother，who had passed away the previous Christmas．As we walked，the woman seemed glad of the unrushed company and casual conversation．We found the mo vie and she told me it was the one she’d enjoyed when she was her son’s age and that she hop ed he would enjoy it as much as she had．Maybe，she said he could enjoy it with his own young children．I accompanied her to the queue at the cashier．As the cashier put the DVD into a plastic bag ，I went over to the younger woman，who was still tapping her foot at the front of the store．―Is that your mom？‖I asked．I had expected her to tell me it was none of my business．But she rolled her eyes and said，―Yeah．‖There was annoyance in her reply．Still watching the mother，I said，―Mind some advice？‖―Go ahead，‖said the daughter．I smiled to show her I wasn’t criticizing―Cherish her，‖I said，―When she’s gone，it’s the little moments that’ll come back to you．Moments like this．I know．‖It was true．I missed my mom still and remembered with sadness the moments when I’d used my impatience to make her life miserable．The elderly woman moved slowly back to her daughter．Together they made their way towar d the store’s exit．They stood there for a moment，side by side，watching the rush of the holiday current．Then the daughter glanced over and slowly placed her arm with apparently unaccustomed affection around her mother’s shoulders and gently gui ded her home．13．The daughter checked her watch frequently because she________．A．had to wait for a friendB．wanted to buy a new watchC．was impatient to shop with her momD．was uninterested in watching the DVD14．From Paragraphs 3and 4we know that________．A．the elderly woman hadn’t seen the movie beforeB．the elderly woman found her son’s favorite movieC．the author and the eldly woman hurried to find the DVDD．the author and the elderly woman enjoyed each other’s company15．We can learn from the passage that________．A．the author had treated her mom very wellB．the elderly woman looked like the author’s momC．the author scolded the daughter for her behaviorD．the daughter changed her attitude toward her mom．任务型阅读根据短文内容，从短文后选项中选出能填入空白处的最佳选项．选项中有两项为多余选项，并在答题卡上将该项涂黑．Common-sense Safety Tips for Travelling AbroadWhen a holiday is just around the corner，you may be planning a trip abroad．But to enjoy a worry-free adventure abroad，you also should pay attention to the following common-sense safety tips for travelling abroad．（16）________Another reason to take only carry-on carriage—besides avoiding baggage fees—is that the less you have to carry around，the more quickly you can move，if necessary．You should always have a free hand．Besides，you won’t be exhausted from dragging all those bags around．（17）________Lock it up．Leave your hotel with only what you need and lock up the rest．Take a lock for your luggage just in case your hotel doesn’t offer a safe．（18）________ If you don’t need all your cash and cards，don’t take them all with you when you go out for a day of sightseeing or shopping．Also，leave your passport in the hotel．Make photocopies of all your important documents and leav e the hotel with a copy of your passport plus a one photo I．D．Why？（19）________ If all of your identification is in it，imagine the trouble you have to go through to replace it all．Think and Plan．Always keep in mind that，when you travel abroad，you are in a place you don’t know well and you can always be a target．Trust your senses．（20）________ After your arrival，ask the hotel staff and locals about the areas you are thinking of visiting，especially at night．And you should walk in well-lit areas at night and know how to contact the local police with your cell phone or a payphone in a foreign country，if necessary．A．Travel light．B．Pay by credit card．C．Imagine having your bag stolen off a restaurant table．D．You should also make it a habit to take your watch with you．E．Plus，dragging lots of luggage is a dead giveaway that you aren’t a local resident．F．You should call ahead to be sure，especially if your luggage is made of cloth material．G．You are smart and mature，so if something or some situation doesn’t feel safe，it probably isn’t．二、完形填空（共 20小题，共40 分）One day.a poor boy who was trying to pay his way through school by selling goods from doo r to door found that he only had one dime left．He was hungry so he decided to （21）________ for a meal at the next house．However，he lost his nerve （22）________ a lovely young woman opened the door．Instead of a meal he asked for a drink of water．She thought he looked （23）________ so she brought him a large glass of milk．He drank it （24）________，and then asked，―How much do I owe you？‖―You don’t owe me anything，‖she（25）________．―Mother has taught me never to accept pay for a（26）________．‖He said，―Then I thank you from the bottom of my heart．‖As Howard Kelly left that house，he not only felt stronger（27）________，but it also increased his faith in God and human race．He was about to give up and quit before this point．Years later the young woman became critically ill．The local doctors were baffled．They f inally sent her to the big city，where specialists can be called （28）________ to study her rare disease．Dr．Howard Kelly，now （29）________，was called in for the consultation．When he heard the name of the town she came from，a strange light （30）________ his eyes．Immediately，he （31）________ and went down through the hospital hall into her room．（32）________in his doctor’s gown he went in to see her．He （33）________her at once．He went back to the consultation room and （34）________ to do his best to save her life．From that day on，he gave（35）________ attention to her case．After a long（36）________，the battle was won．Dr．Kelly （37）________the business office to pass the final bill to him for approval．He looked at it and then wrote something on the side．The bill was sent to her room．She was afraid to open it beca use she was（38）________ that it would take the rest of her life to pay it off．Finally she looked，and the note on the side of the bill caught her（39）________．She read these words…―Paid in full with a glass of milk．‖（Signed） Dr．Howard KellyTears of joy flooded her eyes as she（40）________ silently．―Thank you，God．Your love has spread through human hearts and hands．‖21．A．call B．make C．beg D．prepare 22．A．while B．when C．though D．unless 23．A．thirsty B．lazy C．tired D．hungry 24．A．slowly B．unexpectedly C．steadily D．hurriedly25．A．announced B．shook C．replied D．doubted 26．A．reward B．kindness C．hand D．value 27． A．physically B．mentally C．normally D．properly 28．A．up B．for C．on D．in 29．A．rich B．famous C．observant D．vivid 30．A．filled B．consulted C．fixed D．concentrated 31．A．rose B．raised C．got D．left 32．A．Worn B．Having C．putting D．Dressed 33．A．recognized B．knew C．spared D．regained 34．A．desired B．declared C．determined D．declined 35．A．special B．ordinary C．normal D．no 36．A．decision B．preparation C．struggle D．debate 37．A．ordered B．requested C．confused D．compressed 38．A．negative B．uncertain C．positive D．obvious 39．A．presentation B．preference C．attention D．arrangement 40．A．prayed B．pretended C．pressed D．praised三、语法填空题（共 10小题，共20 分）阅读下面短文，在空白处填入1个适当的单词或括号内单词的正确形式，答案写在答题卡上．A mouse，because of an（41）________ （luck） chance，made close friends with an evil frog．One day，（42）________frog played a trick on the mouse by（43）________ （tie） a foot of the mouse to his own．At first，both of them joined together and the frog（44）________ （lead） his friend toward the pool in which he lived，and didn’t stop（45）________ he reached the side of the water．Then the frog suddenly jumped into the water and the mouse was pulled in with（46）________ （he）．The frog enjoyed the water and swam in it around，happily crying（47）________if he had done a great deed．The unhappy mouse died soon in the water，and his dead body floated around on the surface，（48）________（fasten） to the foot of the frog．A hawk saw the dead mouse，suddenly flew down towards it，caught it and flew away．The frog，still tied to the leg of the mouse，was also carried off as a（49）________（prison），and it （50）________（eat） by the hawk．Harm hatch，harm catch．四、短文改错题（共10 小题，共 20 分）假定英语课上老师要求同桌之间交换修改作文，请你修改你同桌写的以下短文．短文中共有10处错误，每句中最多有两处．错误涉及一个单词的增加、删除或修改．增加：在缺词处加一个漏字符号（∧），并在此符号下面写出该加的词．删除：把多余的词用斜线（\）划掉．修改：在错的词下划一横线，并在该词下面写出修改后的词．注意：1．每处错误及其修改均仅限一词；2．只允许修改10处，多者（从第11处起）不计分．One day，a young man，whom couldn’t get back home，came into my office to ask for help．He said his mother was disabled．His phone had stolen with his wallet and he hadn’t contacted her for the past two days．However，his job was assessing housing applications，not provide money for travel．I asked him to wait outside unless I finished my work．After work I drove him all the way home．We arrive at his mother’s house at 10：30p．m..She was in a wheelchair and she answered a door．I saw tears in her eye as she than ked for me．I just hoped that if my son experienced nothing similar，someone would be nicely enough to bring him home to me．五、书面表达（共1 小题，共30 分）共享单车（sharing bikes）的出现，为大家带来了方便．同时，也反映出一些问题．例如，随意停放，影响行人通行；故意破坏车辆，造成维护成本增加，并影响他人正常使用，等等．请针对此现象，写一封倡议书，号召大家文明用车．要点提示：1、共享单车的好处；2、使用过程中出规的问题；3、如何做到文明用车．写作要求：1、文章要涵盖上述要点，并适当增加细节．2、字数：不少于100字．高二英语参考答案一、阅读理解1-4.[ ―B‖, ―C‖, ―A‖, ―B‖ ]5-8.[ ―A‖, ―B‖, ―D‖, ―D‖ ]9-12.[ ―D‖, ―C‖, ―C‖, ―A‖ ]13-15.[ ―C‖, ―D‖, ―D‖ ]16-20.[ ―A‖, ―E‖, ―F‖, ―C‖, ―G‖ ]二、完形填空21-40.[ ―C‖, ―B‖, ―D‖, ―A‖, ―C‖, ―B‖, ―A‖, ―D‖, ―B‖, ―A‖, ―A‖, ―D‖, ―A‖, ―C‖, ―A‖,―C‖, ―B‖, ―C‖, ―C‖, ―A‖ ]三、语法填空41-50.[ ―unlucky‖,―the‖,―tying‖, ―led‖, ―until‖, ―him‖, ―as‖, ―fastened‖, ―prisoner‖,―was eaten‖ ]四、语法填空One day，a young man，couldn’t get back home，came into my office to ask for help．He said his mother was disabled．His phone had∧stolen with his wallet and he hadn’t contacted her for the past two days．However， job was assessing housing applications，not money for travel．I asked him to wait outside I finished my work．After work I drove h im all the way home．We at his mother’s house at 10：30p．m..She was in a wheelchair and she answered a door．I saw tears in heras she thanked f or me．I just hoped that if my son experienced similar，someone would be enough to bring him home to me．详解：51．whom改为who 考查定语从句．分析句子结构可知这是一个定语从句，先行词a young man在从句中作主语，用有关系代词who．52．加been 考查动词语态．His phone与steal之间是动宾关系，用过去完成时的被动语态．53．his改为my 考查代词．根据上下文语境，此处应是―我的工作‖，用代词my．54．provide改为providing 考查动名词．assessing housing applications和providing money for travel是并列表语，都是动名词作表语．55．unless改为until 考查连词．根据句意：我让他在外面等到我完成工作．用连词until．56．arrive改为arrived 考查动词时态．全文讲述的是过去的事情，要用一般过去时态．57．eye改为eyes 考查名词复数．人的眼睛有两只，要用复数形式．58．去掉for 考查词语用法．thank是及物动词，后接宾语时不需要介词．59．nothing改为something 考查不定代词．根据句意：如果我的儿子经历相似的事情．用不定代词something．60．nicely改为nice 考查形容词．be动词后用形容词作表语．五、书面表达My Views on Sharing bikes Presently，in big cities like Shanghai and Guangzhou，sharing bikes have become increasingly popular．A large number of sharing bikes can be fou nd and rented at a low price．（高分句型一）Moreover,you can park the bike almost anywhere you like．Urban transportation hasthus been made much more convenient and even revolutionized．However,along with its rapi d development，sharing bikes also bring some problems，including random parking，vandalism and possession of sharing bikes，etc．（高分句型二）To solve these problems,there are some measures for the authorities to take．Firstly,the gover nment could implement more strict laws and rules to regulate the operation and management of sharing bikes．Secondly,the public should raise their awareness of using sharing bikes reas onably．Lastly,urban transportation system should be upgraded and improved to accommodat e automobiles，bikes and pedestrians．To conclude,a sensible attitude should be held toward sharing bikes．With effective and efficient measures taken，and efforts made by those involved，it can be expected that sharing bikes will play a contributive and constructive role in urban pu blic transportation．（高分句型三）。

2017-2018学年第二学期期末考试高一英语试卷（考试时间：90分钟试卷满分：120分）第一部分阅读理解（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C和D四个选项中，选出最佳选项。

AThe Harvard Student-led Walking TourWe welcome our neighbors to stop by the Harvard University Events & Information Centre, located in the Holyoke Centre Arcade at 1350 Massachusetts Avenue in the heart of Harvard Square in Cambridge.Let a student take you and your family, school, or organization on an engaging, hour-long free historical tour of the Harvard campus. The tours leave from the Events & Information Centre. Not only will you discover the location of fascinating exhibition and programmers on campus, you will also see Harvard’s rich sampling of American history and architecture from the colonial period to the present.Schedule of ToursTours leave the Events & Information Centre at 10 a.m. and 2 p.m. Monday through Friday, and at 2 p.m. on Saturday through the academic year (February 4 through May 2; September 23 through December 16).Summer tours (June 24 through August 15)are offered at 10 a.m.,11:15 a.m., 2 p.m., and 3:15 p.m. Monday through Saturday. Reservations for special tours of 20 or more people may be made by calling the Events & Information Centre at (617)495-1573 or emailing icenter@ .NOTE：Prospective(未来的) students may take tours originating at the Harvard Admission Office, located at Byerly Hall on 8 Garden Street in Cambridge. From April through August, the Admissions staff conducts an information session at l0 a.m., followed by an 11 a.m. tour. Monday through Friday. For more information on tours for prospective students, please callat(617)495-1551.Harvard University Events & Information Centre.1. The above ad is mainly intended for ____________.A. foreign visitorsB. high school studentsC. teachersD. Harvard University’s students2. How many summer tours are offered every week?A. 4.B. 6.C. 20.D. 24.3. A student who wants more information on tours may ____________.A. call (617)495-1573B. call (617)495-1551C. email icenter@ D. go to the Events & Information Centre【答案】1. B 2. D 3. B【解析】【分析】这是一篇广告类阅读。

甘肃省武威第五中学2017-2018学年高二数学下学期第二次月考试题理一、选择题（共 12 小题，每小题 5 分，共 60 分）1.一植物园参观路径如图所示，若要全部参观并且路线不重复，则不同的参观路线种数共有（）A. B. C. D.2.设，则的值为（）A. B.C. D.3.有件产品，其中有件次品，从中不放回地抽件产品，抽到的次品数的数学期望值是（）A. B. C. D.4.三张卡片的正反面上分别写有数字与，与，与，把这三张卡片拼在一起表示一个三位数，则三位数的个数为（）A. B. C. D.5.设复数满足，则等于（）A. B. C. D.6.设二项式的展开式中常数项为，则A. B. C. D.7.直角坐标平面上，平行直线,…,与平行直线,…,组成的图形中，矩形共有（）A.个B.个C.个D.个8.设是虚数单位，则复数在复平面上对应的点位于（）A.第一象限B.第二象限C.第三象限D.第四象限9.有个不同的红球和个不同的黑球排成一列，其中红球甲和黑球乙相邻的排法有（）A. B. C. D.10.设随机变量的的分布列为，则A. B. C. D.11.若，则等于（）A. B. C. D.12.某个同学进行投篮比赛，已知每个同学投篮命中率为，每个同学投篮次，且投篮之间和同学之间都没有影响．现规定：投中两个得分，投中一个得分，一个未中得分，记为个同学的得分总和，则的数学期望为（）A. B. C. D.二、填空题（共 4 小题，每小题 5 分，共 20 分）13.已知，则________．14.设复数满足（为虚数单位），则________．15.在市数学竞赛中，、、三间学校分别有名、名、名同学获一等，将这六名同学排成一排合影，要求同学校的同学相邻，那么不同的排法共有________种．16.已知，，成等差数列，则的值为________．三、解答题（共 6 小题，共 70 分）17.(10分) 从名男生和名女生中选出人参加学校辩论赛．如果人中男生和女生各选人，有多少种选法？如果男生中的甲和女生中的乙至少有人在内，有多少种选法？18.(12分) 甲、乙、丙、丁、戊五名学生被随机分到、、、四个不同的工厂实习．求甲乙两人不在同一工厂实习的安排方法有多少种；若每个工厂至少有一名学生实习，求甲乙两人不在同一工厂实习的安排方法有多少种．19.(12分) 已知复数，且为纯虚数．求复数；若，求复数的模．20.(12分) 口袋中装有除颜色，编号不同外，其余完全相同的个红球，个黑球．现从中同时取出个球．求恰有一个黑球的概率；记取出红球的个数为随机变量，求的分布列和数学期望．21.(12分) 甲、乙、丙三人参加了一家公司的招聘面试，面试合格者可正式签约，甲表示只要面试合格就签约．乙、丙则约定：两人面试都合格就一同签约，否则两人都不签约．设每人面试合格的概率都是，且面试是否合格互不影响．求：至少有人面试合格的概率；签约人数的分布列和数学期望．22.(12分) 已知．求展开式中的倒数第项；求展开式中含项的系数；设的展开式中前三项的二项式系数之和为，的展开式中各项系数之和为，若，求实数的值．高二数学（理）答案DBCBA BDBDA AA13.[ "或" ] 14.[ "" ] 15.[ "" ]16.[ "" ]17.解：∵从名男生和名女生中选出人参加学校辩论赛，∴人中男生和女生各选人，共有种方法利用间接法，男生中的甲和女生中的乙不在内的情况，共有∴可得男生中的甲和女生中的乙至少有人在内，有种方法…18.解：先安排甲乙有种方法，再安排其余三人有种方法，由分步计数原理，可得甲乙两人不在同一工厂实习的安排方法有种；总的方法数为，甲乙两人在同一工厂实习的安排方法为种，所以甲乙两人不在同一工厂实习的安排方法为种．19.解：∵是纯虚数∴，且∴，∴∴20.解：记“恰有一个黑球”为事件，则．的可能取值为，，，则，，；则的分布列为∴的数学期望．21.解：用，，分别表示事件甲、乙、丙面试合格．由题意知，，相互独立，且．至少有人面试合格的概率是．的可能取值为，，，，．．．所以，的分布列是的期望．22.解：∵二项展开式中共有项，∴倒数第项即为第项…，∴…．令，则，…∴展开式中含的项为：，展开式中含的项的系数为．由题意可知：……，即，∴．…。

2016-2017学年甘肃省武威高二（下）期中数学试卷一、选择题（共12小题，每小题5分）1．已知集合A={x|x2﹣x﹣2＜0}，B={x|log4x＜0.5}，则（）A．A∩B=∅B．A∩B=B C．∁U A∪B=R D．A∪B=B2．命题“∀x∈R，使得n≥x2”的否定形式是（）A．∀x∈R，使得n＜x2B．∃x∈R，使得n≥x2C．∃x∈R，使得n＜x2D．∀x∈R，使得n≤x23．设f（x）=xlnx，若f′（x0）=2，则x0等于（）A．e2B．e C． D．ln24．下列函数中x=0是极值点的函数是（）A．f（x）=﹣x3B．f（x）=﹣cosx C．f（x）=sinx﹣x D．f（x）=5．以双曲线=1的右顶点为焦点的抛物线的标准方程为（）A．y2=16x B．y2=﹣16x C．y2=8x D．y2=﹣8x6．“|x﹣1|＜2成立”是“x（x﹣3）＜0成立”的（）A．充分不必要条件B．必要不充分条件C．充要条件 D．既不不充分也不必要条件7．已知抛物线y=ax2（a＞0）的焦点到准线距离为1，则a=（）A．4 B．2 C．D．8．函数函数f（x）=（x﹣3）e x的单调递增区间是（）A．（﹣∞，2）B．（0，3）C．（1，4）D．（2，+∞）9．已知f（x）=x2+2xf′（1）﹣6，则f′（1）等于（）A．4 B．﹣2 C．0 D．210．函数f（x）的定义域为开区间（a，b），导函数f′（x）在（a，b）内的图象如图所示，则函数f（x）在开区间（a，b）内有极大值点（）A．1个B．2个C．3个D．4个11．若双曲线﹣=1的一条渐近线经过点（3，﹣4），则此双曲线的离心率为（）A．B．C．D．12．若函数y=x3+x2+mx+1是R上的单调函数，则实数m的取值范围是（）A．（，+∞）B．（﹣∞，] C．[，+∞）D．（﹣∞，）二、填空题（共4小题，每小题5分）13．已知向量=（1，），=（，1），则与夹角的大小为．14．如果双曲线﹣=1上一点P到它的右焦点的距离是8，那么点P到它的左焦点的距离是．15．曲线f（x）=x3+x﹣2（x＞0）的一条切线平行于直线y=4x，则切点P0的坐标为．16．设函数f（x）=x3﹣3x+1，x∈的最大值为M，最小值为m，则M+m= ．三、解答题（共5小题，每小题10分）17．求下列函数的导数．（1）；（2）y=（2x2﹣1）（3x+1）18．如图，在四棱锥P﹣ABCD中，PD⊥底面ABCD，底面ABCD为正方形，PD=DC=2，G，F分别是AD，PB的中点．（Ⅰ）求证：CD⊥PA；（Ⅱ）证明：GF⊥平面PBC．19．已知曲线C：f（x）=x3﹣x+3（1）利用导数的定义求f（x）的导函数f'（x）；（2）求曲线C上横坐标为1的点处的切线方程．20．已知椭圆的两焦点为F1（﹣，0），F2（，0），离心率e=．（1）求此椭圆的方程；（2）设直线l：y=x+m，若l与此椭圆相交于P，Q两点，且|PQ|等于椭圆的短轴长，求m的值．21．设函数f（x）=x3+3ax2﹣9x+5，若f（x）在x=1处有极值（1）求实数a的值（2）求函数f（x）的极值（3）若对任意的x∈，都有f（x）＜c2，求实数c的取值范围．2016-2017学年甘肃省武威十八中高二（下）期中数学试卷参考答案与试题解析一、选择题（共12小题，每小题5分）1．已知集合A={x|x2﹣x﹣2＜0}，B={x|log4x＜0.5}，则（）A．A∩B=∅B．A∩B=B C．∁U A∪B=R D．A∪B=B【考点】1E：交集及其运算．【分析】利用不等式的性质分别求出集合A与B，由此利用交集和并集的定义能求出结果．【解答】解：∵集合A={x|x2﹣x﹣2＜0}={x|﹣1＜x＜2}，B={x|log4x＜0.5}={x|0＜x＜2}，∴A∩B=B，∁U A∪B={x|x≤﹣1或x＞0}，A∪B=A．故选：B．2．命题“∀x∈R，使得n≥x2”的否定形式是（）A．∀x∈R，使得n＜x2B．∃x∈R，使得n≥x2C．∃x∈R，使得n＜x2D．∀x∈R，使得n≤x2【考点】2J：命题的否定．【分析】利用全称命题对方的是特称命题，写出结果即可．【解答】解：因为全称命题对方的是特称命题，所以，命题“∀x∈R，使得n≥x2”的否定形式是：∃x∈R，使得n＜x2．故选：C3．设f（x）=xlnx，若f′（x0）=2，则x0等于（）A．e2B．e C． D．ln2【考点】63：导数的运算．【分析】求函数的导数，解导数方程即可．【解答】解：∵f（x）=xlnx，∴f′（x）=lnx+1，由f′（x0）=2，得lnx0+1=2，即lnx0=1，则x0=e，故选：B4．下列函数中x=0是极值点的函数是（）A．f（x）=﹣x3B．f（x）=﹣cosx C．f（x）=sinx﹣x D．f（x）=【考点】6C：函数在某点取得极值的条件．【分析】结合极值的定义，分别判断各个函数是否满足（﹣∞，0）与（0，+∞）有单调性的改变，若满足则正确，否则结论不正确．【解答】解：A、y′=﹣3x2≤0恒成立，所以函数在R上递减，无极值点B、y′=sinx，当﹣π＜x＜0时函数单调递增；当0＜x＜π时函数单调递减且y′|x=0=0，故B符合C、y′=cosx﹣1≤0恒成立，所以函数在R上递减，无极值点D、y=在（﹣∞，0）与（0，+∞）上递减，无极值点故选B5．以双曲线=1的右顶点为焦点的抛物线的标准方程为（）A．y2=16x B．y2=﹣16x C．y2=8x D．y2=﹣8x【考点】K8：抛物线的简单性质．【分析】根据双曲线方程，算出它的右焦点为F（4，0），也是抛物线的焦点．由此设出抛物线方程为y2=2px，（p＞0），结合抛物线焦点坐标的公式，可得p=8，从而得出该抛物线的标准方程．【解答】解析由双曲线方程﹣=1，可知其焦点在x轴上，由a2=16，得a=4，∴该双曲线右顶点的坐标是（4，0），∴抛物线的焦点为F（4，0）．设抛物线的标准方程为y2=2px（p＞0），则由=4，得p=8，故所求抛物线的标准方程为y2=16x．故选A．6．“|x﹣1|＜2成立”是“x（x﹣3）＜0成立”的（）A．充分不必要条件B．必要不充分条件C．充要条件 D．既不不充分也不必要条件【考点】2L：必要条件、充分条件与充要条件的判断．【分析】利用绝对值不等式的解法、一元二次不等式的解法分别解出，即可判断出关系．【解答】解：由|x﹣1|＜2解得：﹣2+1＜x＜2+1，即﹣1＜x＜3．由x（x﹣3）＜0，解得0＜x＜3．“|x﹣1|＜2成立”是“x（x﹣3）＜0成立”必要不充分条件．故选：B．7．已知抛物线y=ax2（a＞0）的焦点到准线距离为1，则a=（）A．4 B．2 C．D．【考点】K8：抛物线的简单性质．【分析】抛物线y=ax2（a＞0）化为，可得．再利用抛物线y=ax2（a＞0）的焦点到准线的距离为1，即可得出结论．【解答】解：抛物线方程化为，∴，∴焦点到准线距离为，∴，故选D．8．函数函数f（x）=（x﹣3）e x的单调递增区间是（）A．（﹣∞，2）B．（0，3）C．（1，4）D．（2，+∞）【考点】6B：利用导数研究函数的单调性．【分析】首先对f（x）=（x﹣3）e x求导，可得f′（x）=（x﹣2）e x，令f′（x）＞0，解可得答案．【解答】解：f′（x）=（x﹣3）′e x+（x﹣3）（e x）′=（x﹣2）e x，令f′（x）＞0，解得x ＞2．故选：D．9．已知f（x）=x2+2xf′（1）﹣6，则f′（1）等于（）A．4 B．﹣2 C．0 D．2【考点】63：导数的运算．【分析】对函数f（x）的解析式求导，得到其导函数，把x=1代入导函数中，列出关于f'（1）的方程，进而得到f'（1）的值【解答】解：求导得：f′（x）=2x+2f′（1），令x=1，得到f′（1）=2+2f′（1），解得：f′（1）=﹣2，故选：B．10．函数f（x）的定义域为开区间（a，b），导函数f′（x）在（a，b）内的图象如图所示，则函数f（x）在开区间（a，b）内有极大值点（）A．1个B．2个C．3个D．4个【考点】6C：函数在某点取得极值的条件．【分析】根据题目给出的导函数的图象，得到导函数在给定定义域内不同区间上的符号，由此判断出原函数在各个区间上的单调性，从而判断出函数取得极大值的情况．【解答】解：如图，不妨设导函数的零点从小到大分别为x1，x2，x3，x4．由导函数的图象可知：当x∈（a，x1）时，f′（x）＞0，f（x）为增函数，当x∈（x1，x2）时，f′（x）＜0，f（x）为减函数，当x∈（x2，x3）时，f′（x）＞0，f（x）为增函数，当x∈（x3，x4）时，f′（x）＞0，f（x）为增函数，当x∈（x4，b）时，f′（x）＜0，f（x）为减函数，由此可知，函数f（x）在开区间（a，b）内有两个极大值点，是当x=x1，x=x4时函数取得极大值．故选B．11．若双曲线﹣=1的一条渐近线经过点（3，﹣4），则此双曲线的离心率为（）A．B．C．D．【考点】KC：双曲线的简单性质．【分析】利用双曲线的渐近线方程经过的点，得到a、b关系式，然后求出双曲线的离心率即可．【解答】解：双曲线﹣=1的一条渐近线经过点（3，﹣4），可得3b=4a，即9（c2﹣a2）=16a2，解得=．故选：D．12．若函数y=x3+x2+mx+1是R上的单调函数，则实数m的取值范围是（）A．（，+∞）B．（﹣∞，] C．[，+∞）D．（﹣∞，）【考点】6B：利用导数研究函数的单调性．【分析】对函数进行求导，令导函数大于等于0在R上恒成立即可．【解答】解：若函数y=x3+x2+mx+1是R上的单调函数，只需y′=3x2+2x+m≥0恒成立，即△=4﹣12m≤0，∴m≥．故选C．二、填空题（共4小题，每小题5分）13．已知向量=（1，），=（，1），则与夹角的大小为．【考点】9S：数量积表示两个向量的夹角．【分析】根据已知中向量的坐标，代入向量夹角公式，可得答案．【解答】解：∵向量=（1，），=（，1），∴与夹角θ满足：cosθ===，又∵θ∈，∴θ=，故答案为：．14．如果双曲线﹣=1上一点P到它的右焦点的距离是8，那么点P到它的左焦点的距离是4或12 ．【考点】KC：双曲线的简单性质．【分析】根据双曲线的定义，分类讨论，即可求得点P到它的左焦点的距离．【解答】解：由双曲线﹣=1，长轴长2a=4，短轴长2b=4，双曲线的左焦点F1，右焦点F2，当P在双曲线的左支上时，P到它的右焦点的距离丨PF2丨=8，则丨PF2丨﹣丨PF1丨=2a=4，则丨PF1丨=4，当P在双曲线的右支上时，P到它的右焦点的距离丨PF2丨=8，则丨PF1丨﹣丨PF2丨=2a=4，∴丨PF1丨=12，则点P到它的左焦点的距离4或12，故答案为：4或12，15．曲线f（x）=x3+x﹣2（x＞0）的一条切线平行于直线y=4x，则切点P0的坐标为（1，0）．【考点】6H：利用导数研究曲线上某点切线方程．【分析】先求导函数，然后令导函数等于4建立方程，求出方程的解，即可求出切点的横坐标，从而可求出切点坐标．【解答】解：由y=x3+x﹣2，得y′=3x2+1，由已知得3x2+1=4，解之得x=1．x=﹣1（舍去）当x=1时，y=0；∴切点P0的坐标为（1，0）．故答案为：（1，0）．16．设函数f（x）=x3﹣3x+1，x∈的最大值为M，最小值为m，则M+m= 2 ．【考点】6E：利用导数求闭区间上函数的最值．【分析】求出原函数的导函数，得到导函数的零点，进一步得到原函数的极值点，求得极值，再求出端点值，比较可得最大值为M，最小值为m，则M+m可求．【解答】解：由f（x）=x3﹣3x+1，得f′（x）=3x2﹣3=3（x+1）（x﹣1），当x∈（﹣2，﹣1）∪（1，2）时，f′（x）＞0，当x∈（﹣1，1）时，f′（x）＜0．∴函数f（x）的增区间为（﹣2，﹣1），（1，2）；减区间为（﹣1，1）．∴当x=﹣1时，f（x）有极大值3，当x=1时，f（x）有极小值﹣1．又f（﹣2）=﹣1，f（2）=3．∴最大值为M=3，最小值为m=﹣1，则M+m=3﹣1=2．故答案为：2．三、解答题（共5小题，每小题10分）17．求下列函数的导数．（1）；（2）y=（2x2﹣1）（3x+1）【考点】63：导数的运算．【分析】根据导数的运算法则计算即可．【解答】解：（1）===；（2）y=（2x2﹣1）（3x+1）=6x3+2x2﹣3x﹣1，y'=（6x3+2x2﹣3x﹣1）'=（6x3）'+（2x2）'﹣（3x）'﹣（1）'=18x2+4x﹣3．18．如图，在四棱锥P﹣ABCD中，PD⊥底面ABCD，底面ABCD为正方形，PD=DC=2，G，F分别是AD，PB的中点．（Ⅰ）求证：CD⊥PA；（Ⅱ）证明：GF⊥平面PBC．【考点】LW：直线与平面垂直的判定；LO：空间中直线与直线之间的位置关系．【分析】（I）以D为原点建立空间直角坐标系，利用•=0，证得PA⊥CD；（Ⅱ）利用•=0，•=0，去证GF⊥平面PCB．【解答】证明：（I）以D为原点建立空间直角坐标系则A（2，0，0）B（2，2，0）C（0，2，0）P（0，0，2）F（1，1，1）=（2，0，﹣2），=（0，2，0），∴•=0，∴⊥，∴PA⊥CD；（Ⅱ）设G（1，0，0）则=（0，﹣1，﹣1），=（2，0，0），=（0，2，﹣2）∴•=0，•=0，∴FG⊥CB，FG⊥PC，∵CB∩PC=C，∴GF⊥平面PCB．19．已知曲线C：f（x）=x3﹣x+3（1）利用导数的定义求f（x）的导函数f'（x）；（2）求曲线C上横坐标为1的点处的切线方程．【考点】6H：利用导数研究曲线上某点切线方程．【分析】（1）运用导数的定义，求得△y，和f'（x）=，计算即可得到所求；（2）由导数的几何意义，可得切线的斜率和切点，运用点斜式方程，即可得到所求切线的方程．【解答】解：（1）△y=f（x+△x）﹣f（x）=（x+△x）3﹣（x+△x）+3﹣x3+x﹣3=3x2△x+3x△x2+△x3﹣△x，∴=3x2+3x△x+△x2﹣1，则导函数f'（x）==（3x2+3x△x+△x2﹣1）=3x2﹣1；（2）由f（x）得f′（x）=3x2﹣1，设所求切线的斜率为k，则k=f′（1）=3×12﹣1=2，又f（1）=13﹣1+3=3，所以切点坐标为（1，3），由点斜式得切线的方程为y﹣3=2（x﹣1），即2x﹣y+1=0．20．已知椭圆的两焦点为F1（﹣，0），F2（，0），离心率e=．（1）求此椭圆的方程；（2）设直线l：y=x+m，若l与此椭圆相交于P，Q两点，且|PQ|等于椭圆的短轴长，求m的值．【考点】KH：直线与圆锥曲线的综合问题；K3：椭圆的标准方程．【分析】（1）先设椭圆方程为，有c=，求得a，b，最后写出椭圆方程；（2）由，将直线的方程代入抛物线的方程，消去y得到关于x的一元二次方程，再结合根系数的关系利用弦长公式即可求得m值，从而解决问题．【解答】解：（1）设椭圆方程为，则c=，，∴a=2，b=1，所求椭圆方程．（2）由，消去y，得5x2+8mx+4（m2﹣1）=0，则△＞0得m2＜5（*）设P（x1，y1），Q（x2，y2），则x1+x2=﹣，x1x2=，y1﹣y2=x1﹣x2，|PQ|=•=2，解得m=，满足（*）∴m=．21．设函数f（x）=x3+3ax2﹣9x+5，若f（x）在x=1处有极值（1）求实数a的值（2）求函数f（x）的极值（3）若对任意的x∈，都有f（x）＜c2，求实数c的取值范围．【考点】6D：利用导数研究函数的极值；6E：利用导数求闭区间上函数的最值．【分析】（1）求出导数，由题意可得f′（1）=0，解方程可得a=1；（2）求出导数，令导数大于0，可得增区间，令导数小于0，可得减区间，进而得到极值；（3）求出函数在上的最大值，由不等式恒成立思想可得c的二次不等式，解得c即可得到范围．【解答】解：（1）f′（x）=3x2+6ax﹣9，由已知得f′（1）=0，即3+6a﹣9=0，解得a=1．（2）由（1）得：f（x）=x3+3x2﹣9x+5，则f′（x）=3x2+6x﹣9，令f′（x）=0，解得x1=﹣3，x2=1，当x∈（﹣∞，﹣3），f′（x）＞0，当x∈（﹣3，1），f′（x）＜0，当x∈（1，+∞），f′（x）＞0，所以f（x）在x=﹣3处取得极大值，极大值f（﹣3）=32，在x=1处取得极小值，极小值f（1）=0；（3）由（2）可知极大值f（﹣3）=32，极小值f（1）=0，又f（﹣4）=25，f（4）=81，所以函数f（x）在上的最大值为81，对任意的x∈，都有f（x）＜c2，则81＜c2，解得c＞9或c＜﹣9．即有c的范围为（﹣∞，﹣9）∪（9，+∞）．。

2017–2018学年第二学期武威五中高二年级数学（理）试卷一、选择题（共 12 小题，每小题 5 分，共 60 分）1.函数在点处的切线方程为（）A. B.C. D.2.复数，互为共轭复数，若，则A. B. C. D.3.如果随机变量，且，，则等于（）A. B. C. D.4.随机变量服从正态分布，若落在区间和上取值的概率分别为、，则（）A. B. C. D.不确定5.已知函数的导函数为，且满足关系式，则的值等于（）A. B.C. D.6.极坐标方程化为直角坐标方程是（）A. B.C. D.7.甲，乙，丙，丁，戊人站成一排，要求甲，乙均不与丙相邻，不同的排法种数有（）A.种B.种C.种D.种8.下列积分值等于的是（）A. B.C. D.9.曲线（为参数）的对称中心（）A.在直线上B.在直线上C.在直线上D.在直线上10.随机变量，那么的值为（）A. B. C. D.11.设是定义在正整数集上的函数，且满足：“当成立时，总可推出成立”．那么，下列命题总成立的是（）A.若成立，则成立B.若成立，则成立C.若成立，则当时，均有成立D.若成立，则当时，均有成立12.设函数在上可导，其导函数为，且函数的图象如图所示，则下列结论中一定成立的是（）A.函数有极大值和极小值B.函数有极大值和极小值C.函数有极大值和极小值D.函数有极大值和极小值二、填空题（共 4 小题，每小题 5 分，共 20 分）13.已知函数存在极大值和极小值，则实数的取值范围是___ _____．14.在的二项展开式中，常数项等于_______．15.下列图形中，若黑色三角形的个数依次构成一个数列的前项，则这个数列的一个通项公式为_______16.下列说法中正确的是________（把所有正确说法的序号都填上）．①“若，则”的逆命题为真；②线性回归方程对应的直线一定经过其样本数据点，，…，中的一个点；③命题“，”的否定是“，”；④命题“函数在处有极值，则”的否命题是真命题．三、解答题（共 6 小题，共 70 分）17.(10分) 在平面直角坐标系中，以原点为极点，轴正半轴为极轴建立极坐标系，并在两坐标系中取相同的长度单位．已知曲线的极坐标方程为，直线的参数方程为（为参数，为直线的倾斜角）．。

绝密★启用前2017-2018学年甘肃省武威高二下学期期末考试数学（理）试题一、选择题（每小题5分）1. 函数的定义域为开区间，导函数在内的图象如图所示，则函数在开区间内有极小值点（）A 1个B 2个C 3个D 4个2. 定义在R上的可导函数f(x)，已知y＝e f ′(x) 的图象如下图所示，则y＝f(x)的增区间是A．(－∞，1) B．(－∞，2) C．(0,1) D．(1,2)3. 已知函数无极值，则实数的取值范围是 ( )A．B．C．D．4. 若对可导函数，恒有，则（）A．恒大于0 B．恒小于0C．恒等于0 D．和0的大小关系不确定5. 下列各式中，正确的是( )A. =f′(b)-f′(a)B. =f′(a)-f′(b)C. =f(b)-f(a)D. =f(a)-f(b)6. 在数列中，，，则等于（）B．C．D．A．7. 设P 是△ABC 所在平面内的一点，，则（）A．B．C．D．8. 设是虚数单位，若复数是纯虚数，则的值为（）A．-3 B．-1 C．1 D．39. 复数（为虚数单位）在复平面上对应的点位于A．第一象限B．第二象限C．第三象限D．第四象限10. 5名运动员争夺3项比赛冠军（每项比赛无并列冠军），获得冠军的可能种数为：A．B．C．D．11. 从0，2中选一个数字．从1，3，5中选两个数字，组成无重复数字的三位数．其中奇数的个数为( ) A．24 B．18 C．12 D．612. 五个工程队承建某项工程的5个不同的子项目，每个工程队承建1项，其中甲工程队不能承建1号子项目，则不同的承建方案共有A．种B．种C．种D．种二、填空题（每小题5分）13. 随机变量ξ的分布列如图，其中a，b，成等差数列，则 .14. 某人射击次，命中~ 环的概率如下图所示：环环环环则“射击次，命中不足环”的概率为．15. 袋中有大小相同的三个球，编号分别为1,2,2，从袋中每次取出一个球，若取到球的编号为奇数，则取球停止，用X表示所有被取到的球的编号之和，则X的方差为________．16. 以下关于线性回归的判断，正确的是________．①散点图中所有点都在一条直线附近，这条直线为回归直线②散点图中的绝大多数点都在回归直线的附近，个别特殊点不影响线性回归性③已知直线方程为＝0.50x－0.81，则x＝25时，为11.69④回归直线方程的意义是它反映了样本整体的变化趋势三、解答题（每小题14）17. 火车上有十名乘客，沿途有五个车站，乘客下车的可能方式有多少种？18. 甲、乙两个盒子里各放有标号为1，2，3，4的四个大小形状完全相同的小球，从甲盒中任取一小球，记下号码后放入乙盒，再从乙盒中任取一小球，记下号码.（Ⅰ）求的概率；（Ⅱ）设随机变量，求随机变量的分布列及数学期望.19. 已知f ( x )＝log a x ( a >0且a ≠1)，如果对于任意的x ∈都有| f ( x )|≤1 成立，试求a 的取值范围20. 如图所示，S为△ABC平面外一点，SA⊥平面ABC，平面SAB⊥平面SBC.求证：AB⊥BC.21. （本小题满分8分）设等差数列的前项和为, 已知.（Ⅰ）求首项和公差的值; （Ⅱ）若，求的值.2017-2018学年甘肃省武威高二下学期期末考试数学（理）试题答案及答案)一、选择题1、【答案】A【解析】根据题意，由于导数的正负代表了原函数的单调增减性质，因此可知，当导数函数图像穿过x轴时，此时说明该点的导数左右两侧异号，说明是极值点，因此可以看到满足题意的极值点有3个，而极小值点，是指的是从下面穿过x轴到上面的点，因此可知只有一个，故选A.2、【答案】B【解析】试题分析：若f ‘(x)≥0，则e f ′(x) ≥ e 0 =1，由图知当x<2时，e f ′(x) ≥ 1，所以y＝f(x)的增区间是(－∞，2) 。

武威五中2016-2017学年第二学期高二年级下学期期末英语试卷第一卷一、阅读理解（共20小题；每小题2分,共40分）第一节（共15小题；每小题2分,满分30分）阅读下列短文，从每题所给的四个选项（A、B、C和D）中，选出最佳选项。

A Films provide more than just entertainment．For many people，watching English films is a way to develop language skills．While watching a film，you are immersed（沉浸在)in the language and can pick up new expressions that you might not find in a textbook．Some difficulties can arise when watching English films-for example,unfamiliar colloquial language or strong regional accents．With this in mind，here are my tips to help you make progress in English learning while enjoying the films．Choose a film genre类型) that you enjoy.If you like action films，watch an action film-for example Indiana Jones．If you prefer comedies,watch a comedy-anything with Hugh Grant in always provides a laugh！It's simple enough，but if you choose something you enjoy watching in your native language，you’re more likely to enjoy it in English．Choose something that you are familiar with。