( ) ( ) EAC T,T0 = eAC (T )-eAC T0 ( ) ( ) EBC T,T0 = eBC (T )-eBC T0
两式相减得:
E T,T -E T,T
AC
0
BC
0
e T -e T -e T e T
AC
AC 0
BC
BC
0
e T -e T -e T -e T
AC
BC
eA(T,T0) A
eAB(T-)
T
T0
eAB(T0)
B eB(T,T0)
图1 闭合回路总的热电势
EAB T ,T0 eAB T -eAB T0 eB T ,T0 -eA T ,T0
kT ln N AT - kT0 ln N AT0
e N BT
e
N BT 0
T T0
B- A
dT
AC
0
BC
0
——(1)
若一个热电偶由A、B、C三种导体组成, 且回路中三个接点的温度都相同,则回路 总电动势必为零,即:
eAC (T ) + eCB (T ) + eBA (T ) = 0
( ) ( ) ( ) eAC T0 + eCB T0 + eBA T0 = 0
( ) ( ) ( ) 或 eAC (T )-eBC (T ) = eAB (T )
( ) ( ) ( ) eAB T0 + eBC T0 + eCA T0 = 0
即 eBC T0 eCA T0 eAB T0
则
EABC T,T0 eAB T -eAB T0 EAB T,T0
如果按右图接入第三 T0
C