江苏省太湖高级中学

2004 年荣膺为四星级高中：（第一批）1.一中全称：无锡市第一中学2.辅仁高中全称：无锡市辅仁高级中学3.省锡中全称：江苏省锡山高级中学4.天一中学全称：江苏省天一中学5.梅村高中全称：江苏省梅村高级中学6.太湖中学全称：江苏省太湖高级中学7.羊尖中学全称：江苏省羊尖高级中学8.怀仁高中全称：江苏省怀仁高级中学9.玉祁高中全称：江苏省玉祁高级中学2006 年荣膺为四星级高中：10.市北高中全称：无锡市市北高级中学11.洛社高中全称：无锡市洛社高级中学12.三中全称：江苏省无锡市第三高级中学1 / 6无锡 13 所初中排名1、大桥中学优势：1、大桥中学学风较好，孩子们互相竞争，有优异的学风。

2、大桥中学教课质量向来比较排名靠前。

3、大桥中学有直升名额，借读生成绩比较好，也可直升。

4、大桥中学借读生，能够经过自主招生和计划外考中其余四星级高中劣势：1、大桥中学尖子生云集，竞争强烈，孩子学习压力大。

2、大桥实验学校学生数目相对较小，中考名额分派较小，借读更不享有分派名额。

3、大桥实验学校订常学费每学期6000 元左右，花费偏高，借读生还要在学籍所在学校缴纳必定花费，花销比较大。

2、辅仁中学优势：1、辅仁初中是无锡一流初中。

近来几年的成绩不错，2011 年中考成绩超出外国语。

2、辅仁初中年级排名前五十，一般都能获取辅仁高中的签约。

一部分能直接进入辅仁高中的双语班 A 班。

据统计，辅仁初中 65%的学生能进入辅仁高中。

3、无锡市民办辅仁中学是一所管理满严格的学校,教课水平很好。

劣势：1、辅仁中学与辅仁高中之间没有直接关系，辅仁高中是公办的，辅仁初中是民办的。

2、辅仁中学是平行分班。

3、公办快班和辅仁差距不大，择校要考虑距离远近的问题。

4、交通不是很方便。

5、花费较高。

3.天一中学优势：1、学籍学籍是选择公办中学的一个重要要素。

天一实验学校本区内学校集中转移学籍相对简单，跨区则需要自己解决学籍问题。

2、分派名额名额多天一实验班级前十能获取分派名额，天一实验学校对比于省锡中实验学校，分派名额许多。

2023——2024学年度第一学期期中考试高二物理试卷一、单项选择题：共11题，每题4分，共44分每题只有一个选项最符合题意。

1．当导线中分别通以图示方向的电流，小磁针静止时N 极垂直纸面向外的是2．如图所示，某区域内有垂直纸面向里的匀强磁场，磁感应强度大小为B .一正方形刚性线圈，边长为L ，匝数为n ，线圈平面与磁场方向垂直，线圈一半在磁场内．某时刻，线圈中通过大小为I 的电流，则此线圈所受安培力的大小为A.2BILB.12nBILC ．nBIL D.2nBIL3．如图所示，电子射线管放在U 形磁铁的N 极和S 极之间，射线管的P 和Q 两极分别接在直流高压电源的正极和负极，此时荧光屏上显示的电子束运动径迹将 A ．向上偏转 B ．向下偏转 C ．不发生偏转D ．先向上偏转后向下偏转4．高空坠物极易对行人造成伤害。

若一个50 g 的鸡蛋从一居民楼的25层坠下，与地面的碰撞时间约为2 ms ，则该鸡蛋对地面产生的冲击力约为A.10 N 2 N 3 N 4 N 5．在如图所示的电路中，小量程电流表G 的内阻R g ＝100Ω，满偏电流I g ＝1mA ，R 1＝900Ω，R 2＝100999Ω.下列说法正确的是A ．当S 1和S 2均断开时，改装成的表是电流表B ．当S 1和S 2均断开时，改装成的是量程为10V 的电压表C ．当S 1和S 2均闭合时，改装成的表是电压表D ．当S 1和S 2均闭合时，改装成的是量程为1A 的电流表6．如图所示，甲木块的质量为m 1，以速度v 沿光滑水平地面向右运动，正前方有一静止的、质量为m 2的乙木块，乙木块上连有一轻质弹簧。

甲木块与弹簧接触后 A.甲、乙两木块所组成系统的动量守恒 B.甲、乙两木块所组成系统的机械能守垣 D.乙木块的动量守恒7．质量为m A 的A 球，以某一速度沿光滑水平面向静止的B 球运动，并与B 球发生弹性正碰．假设B 球的质量m B 可选取为不同的值，则 A ．当m B =m A 时，碰后B 球的速度最大 B ．当m B =m A 时，碰后B 球的动能最大 C ．当m B =m A 时，碰后B 球的动量最大D ．在保持m B >m A 的条件下，m B 越小，碰后A 球的速度越大8．如图所示，两根光滑金属导轨平行放置，导轨所在平面与水平面间的夹角为θ，一根长为L ，质量为m 的直导体棒垂直导轨放在如图所示的电路中，欲使导体棒静止，可加一垂直于导轨平面的匀强磁场，当磁感应强度B 的方向由垂直斜面向上沿逆时针转至水平向左的过程中，下列关于B 的大小变化的说法中，正确的是 A ．先减小后增大 B ．先增大后减小C ．逐渐减小D ．逐渐增大9．有一只小船停靠在湖边码头，小船又窄又长(重一吨左右)。

江苏省无锡市江苏省太湖高级中学2022年高一上学期期中考试化学试题1.下列我国古代发明中，不涉及化学反应的是A．A B．B C．C D．D2.对下列物质进行的分类正确的是A．冰水混合物属于混合物B．属于纯净物C．凡能电离出H +的化合物均属于酸D．盐类物质中一定含有金属阳离子3.下列说法不正确的是A．氢气的摩尔质量是 2g/mol B．摩尔是物质的量的单位C． 1molOH —的质量是 17g D． 1mol 气体所占的体积约为 22.4L4.根据气象台报道，近年每到春季，沿海一些城市多次出现大雾天气，致使高速公路关闭，航班停飞，雾属于下列分散系中的A．溶液B．悬浊液C．乳浊液D．胶体5.如果8g甲烷(CH4)含有的分子数为a个，则11g二氧化碳的分子数为A．0.5a个B．a个C．2a个D．4a个6.“侯氏制碱法”是我国化工专家侯德榜为世界制碱工业作出的突出贡献。

“侯氏制碱法”是将二氧化碳通入含有氨气的饱和NaCl溶液中，结晶，过滤，加热分解NaHCO3制得Na2CO3。

实验室模拟制取Na2CO3，下列使用的装置能达到实验目的的是A．用图1所示装置制取CO 2气体B．用图2所示装置除去CO 2气体中的HCl杂质C．用图3所示装置从溶液中分离出NaHCO 3固体D．用图4所示装置加热分解制取Na 2 CO 37.“侯氏制碱法”是我国化工专家侯德榜为世界制碱工业作出的突出贡献。

“侯氏制碱法”是将二氧化碳通入含有氨气的饱和NaCl溶液中，结晶，过滤，加热分解NaHCO3制得Na2CO3。

下列关于NaHCO3和Na2CO3说法正确的是A．用澄清石灰水鉴别NaHCO 3和Na 2 CO 3B．NaHCO 3固体中含有少量Na 2 CO 3杂质，可通过加热的方法除去C．向同浓度NaHCO 3和Na 2 CO 3溶液中滴加几滴酚酞，NaHCO 3的红色较深D．相同温度下，0.1mol•L -1的两种盐溶液分别与同浓度的稀盐酸反应，NaHCO 3较剧烈8.下列反应既属于化合反应又属于氧化还原反应的是A．Fe+2HCl=H 2↑+FeCl 2B．2FeCl 2 +Cl 2 =2FeCl 3C．CaO+H 2 O=Ca(OH) 2D．2Fe(OH) 3 Fe 2 O 3 +3H 2 O9.下列关于物质分类的正确组合是A．A B．B C．C D．D10.用N A表示阿伏加德罗常数的值，下列说法正确的是A．16gO 2中含有的氧分子数为N AB．常温常压下，11.2LH 2中含有的氢分子数为0.5N AC．常温常压下，28g氮气所含的原子数为N AD．标准状况下，44.8LCO 2含有的分子数为2N A11.下列有关物质的性质与用途具有对应关系的是A．小苏打能与碱反应，可用作抗酸药B．钠具有导电性，可用于冶炼部分金属C．次氯酸具有弱酸性，可用作有色物质的漂白剂D．Na 2 O 2能吸收CO 2产生O 2，可用作呼吸面具供氧剂12.用自来水(以Cl2为杀菌消毒剂)配制下列物质的水溶液，不会出现明显的药品变质问题的是A．Na 2 CO 3B．AgNO 3C．CuSO 4D．NaOH13.下列反应的离子方程式书写正确的是( )A．稀硫酸与铁粉反应：2Fe+6H + =2Fe 3+ +3H 2↑B．盐酸溶解石灰石： +2H + =H 2 O+CO 2↑C．盐酸与Mg(OH) 2反应：Mg(OH) 2 +2H + =Mg 2+ +2H 2 OD．氢氧化钡溶液与稀硫酸反应：Ba 2+ + =BaSO 4↓14.下列说法中，正确的是A．氢气在氯气中燃烧，发出苍白色的火焰B．氯气泄露，可用浸有NaOH溶液的毛巾捂住口鼻，逃离现场C．铜丝在氯气中燃烧，生成蓝色的氯化铜固体D．氯元素在自然界中既有游离态又有化合态存在15.某溶液中大量存在Ba2+、H+、Cl-，该溶液中还可能大量存在的离子是A．Ag +B．SO C．ClO -D．Mg 2+16.下列变化需要加入氧化剂才能实现的是（）C．HCl→Cl 2D．CuO→Cu A． KClO 3→O 2B． H 2 SO 4→BaSO 417.常温常压下，用等质量的CH4、CO2、O2、SO2分别吹出四个气球，其中气体为CH4的是A．B．C．D．18.反应SiCl4 +2H2 Si +4HCl可制纯硅。

2025届江苏省无锡市太湖高级中学化学高三第一学期期中考试模拟试题考生须知：1．全卷分选择题和非选择题两部分，全部在答题纸上作答。

选择题必须用2B 铅笔填涂；非选择题的答案必须用黑色字迹的钢笔或答字笔写在“答题纸”相应位置上。

2．请用黑色字迹的钢笔或答字笔在“答题纸”上先填写姓名和准考证号。

3．保持卡面清洁，不要折叠，不要弄破、弄皱，在草稿纸、试题卷上答题无效。

一、选择题（每题只有一个选项符合题意） 1、下列对古文献记载内容理解错误．．的是 A ．《天工开物》记载：“凡埏泥造瓦，掘地二尺余，择取无沙黏土而为之”。

“瓦”，传统无机非金属材料，主要成分为硅酸盐。

B ．《本草纲目》“烧酒”条目下写道：“自元时始创其法，用浓酒和糟入甑，蒸令气上……其清如水，味极浓烈，盖酒露也”。

这里所用的“法”是指蒸馏。

C ．《抱朴子·金丹篇》中记载：“丹砂烧之成水银，积变又还成丹砂”。

该过程未发生氧化还原反应。

D ．《本草经集注》中关于鉴别硝石(KNO 3)和朴硝(Na 2SO 4)的记载：“以火烧之，紫青烟起，乃真硝石也”，该方法应用了焰色反应。

2、工业酸性废水中的Cr 2O 72﹣可转化为Cr 3+除去，实验室用电解法模拟该过程，结果如表所示（实验开始时溶液体积为50mL ，Cr 2O 72﹣的起始浓度、电压、电解时间均相同）．下列说法中，不正确的是A ．对比实验①②可知，降低pH 可以提高Cr 2O 72﹣的去除率B ．实验②中，Cr 2O 72﹣在阴极放电的电极反应式是Cr 2O 72﹣+6e ﹣+14H +═2Cr 3++7H 2OC ．实验③中，Cr 2O 72﹣去除率提高的原因是Cr 2O 72﹣+6 Fe 2++14H +═2Cr 3++6Fe 3++7H 2OD ．实验③中，理论上电路中每通过6 mol 电子，则有1 mol Cr 2O 72﹣被还原 3、下列固体混合物与过量的稀H 2SO 4反应，能产生气泡并有沉淀生成的是（ ） A ．3NaHCO 和()3Al OH B ．2BaCl 和NaCl C ．23Na SO 和3BaCOD ．3HClO 和24K SO4、下列各项叙述中，正确的是（ ） A ．Na 的简化电子排布式： [Na]3s 1B．价电子排布为4s24p3的元素位于第四周期第V A族，是p区元素C．2P和3P轨道形状均为哑铃形，能量也相等D．氮原子的最外层电子轨道表示式：5、A、B、C是三种金属，根据下列①、② 两个实验：① 将A与B浸在稀硫酸中用导线相连，A表面有气泡逸出，B 逐渐溶解；② 电解物质的量浓度相同的A、C混合盐溶液时，阴极上先析出C（使用惰性电极）。

2019-2020学年江苏省太湖高级中学高三英语月考试卷及答案第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项AJuanito Estrella has been a housekeeping manager on the US-based large passenger ship Carnival Spirit for 18 months and feels he has found the suitable position in his career(职业). He has always wanted to travel. “I guess I am a really restless spirit.I like traveling, so when the chance came, I jumped at it,” he says.The chance came in the form of a newspaper advertisement for work on cruise ships（游船）. At the time Estrella was the housekeeping manager at a Melbourne hotel. He applied and, after two interviews, a medical check and police clearance, the job was his.Estrella is responsible(负责的)for the cleanliness of the ship, making sure that 160 crew work properly. “I enjoy it because there is no other work-you wake up each day in a different place anda different culture. It’s exciting when you go to the next country and you don’t understand the language,” he says.Estrella likes being busy and getting to know people from all over the world. The 1,000 crew come from 94 countries, and Estrella has learnt Spanish and a little Croatian.But there is adownside. “You cannot get really drunk...because you have safety responsibilities to yourself and others,” he says. “You don’t really think about home.You start to think about home only when you get closer to your vacation and wonder what you’ll be doing.”Life on the ship is anything but cruising. Estrella and his fellows work at least 10 hours a day, seven days a week. He warns the job is not for everybody. “You have to love being busy and be prepared to work every day-and to give up drinking too much alcohol.” In his spare time, if the ship sails into a port, Estrella explores it, otherwise he works out in the crew’s gym, goes on the internet or calls home.1.Which of the following is true?A.He has been a housekeeping manager for 18 months.B.He doesn’t drink wine now.C.He cannot speak a foreign language.D.He used to be a housekeeping manager.2.The underlined word“downside”in paragraph 5 probably means ________ .A.disappointmentB.disadvantageC.failureD.loss3.In the last paragraph, the writer thinks that life on the ship is ________.A.not a tiring journey at allB.just an interesting voyageC.far from a voyage for pleasureD.more than a pleasant travel by seaBMy school appeared on the news last week because we had made an important change in our local area. Our class had planted a large garden in what was once only a vacant lot. It was a lot of work but it was all worth it. I got blisters(水泡) from digging, and we all got insect bites, too.I learned a lot about gardening and collaboration(合作), and then I learned about the media. Our teacher telephoned the TV station and informed them of what we had accomplished. She spoke with the producer. The producer checked with the directors, but they said there were plenty of stories similar to ours. They wanted to know what was special about our particular garden, since many schools plant them.The teacher explained that, after going on the Internet to learn about the prairie(大草原), we had made a prairie garden. We had gone to a prairie and gotten seeds from the plants, and then we planted them. We did not water the garden, but we did weed it. We decided to let nature water it with rain, since that was how prairies grew in the past. We sent a picture of the garden to the news station. In the picture, the grass was so high that it stood taller than the fourth grade students.As a result, the producer sent a reporter to our school. He interviewed the headmaster and asked him many questions about the garden. After that, they interviewed us, and we explained to them what we had learned through this project.That night, we watched the news, and there we were. The news reporter told our story. It was only two minutes long, but it was us. We were famous. All that work, all those blisters, it was worth it. We knewthatwhen we saw the garden every day, but now we knew that the whole city thought so, too.4. What seemed to be the TV directors’ initial reaction to the garden?A. They were excited.B. They were surprised.C. They were worried.D. They were uninterested.5. What is special about the garden?A. Weeds were allowed to spread naturally.B. The grass grew faster than common grass.C. The seeds came from the plants of a prairie.D. Underground water was used for the plants.6. What does the underlined word “that” refer to in the last paragraph?A. We got blisters on our hands.B. Our hard work was worthwhile.C. The garden would be famous.D. The project would be finished.7. How did the author feel about the project?A. Annoyed.B. Curious.C. Proud.D. Regretful.CGuangzhououtbreak linked to strains inIndiaThe gene sequencing of the COVID-19 outbreak inGuangzhou.Guangdongprovince, indicates it is very similar in structure to the mutatedstrains detected inIndia, a senior health official from the city said on Sunday.“And it has the characteristic of quick spread.” Chen Bin, deputy director of the city's health commission, said at a news conference inGuangzhouon Sunday.She urged relevant departments and medical staff to act quickly to block the chain of infection and control the spread of the coronavirus in the southern metropolis.Zhang Zhoubin, deputy director of theGuangzhoucenter for disease control and prevention, said the strain of coronavirus spreads easily.“The virus can be spread through a meal or through a short period of indirect contact,” he said.The city reported five confirmed eases and 21 asymptomatic carriers as of 2 pm Sunday after the first con finned case was detected in the city's Liwan district on May 21, Chen said.To prevent the virus from spreading, the city government tightened its disease control and prevention measures over the weekend. Six communities and housing estates previously designated as low-risk areas were raised to medium-risk ones, Chen said.In addition to asking local residents to get vaccinated, the city has organized nucleic acid testing in Haizhu and Yuexiu districts starting from Sunday. Residents in specific areas of Tianhe, Baiyun and Panyu districts have also been required to take nucleic acid tests to expand the screening of suspected patients and asymptomatic carriers.Liwan previously required all its residents to take nucleic acid tests.As of Saturday, more than 2-25 million residents of the city have had samples collected for nucleic acid tests, Chen said. More than 10,000 medical workers from the entire city have been sent to Liwan to help vaccinate locals against COVID-19 and collect samples for nucleic acid testing.Deng Wenjun, director of circulation section with Guangzhou Supply and Marketing Cooperative, said there are sufficient supplies of food and daily necessities in the medium-risk areas.8. What is the characteristic of the COVID-19 which broke out inGuangzhou?A. It disappears quickly.B. It spreads fast.C. It has a lot to do with temperature.D. It has the same nature as the seasonal flu.9. Which district have residents who have not been required to take nucleic acid tests?A. Tianhe.B. Haizhu.C. Panyu.D. Zengcheng.10. Which of the following statements is TRUE?A. The virus can hardly be spread through a short period of indirect contact.B. There are 21 symptomatic carriers in the Liwan district as of 2 pm Sunday.C. All the people living in Liwan district arc previously asked to take nucleic acid tests.D. Supplies of food and daily necessities in the medium-risk areas arc still not enough.11. Where can you probably find this article?A. On a news website.B. In a fashion magazine.C. In a history book.D. In a travel journal.DCuckoos don’t bother building their own nests—they just lay eggs that perfectly imitate those of other birds and take over their nests. But other birds are wishing up, evolving some seriously impressive tricks to spot the cuckoo eggs.Cuckoos are often know asparasites, meaning that they hide their eggs in the nest of other species. To avoid detection, the cuckoos have evolved so that eggs seem reproduction of those of their preferred targets. If the host bird doesn’t notice the strange egg in its nest, the little cuckoo will actually take the entire nest for itself after it comes out, taking the other eggs on its back and dropping them out of the nest.To avoid this unpleasant fate for their young, the other birds have evolved a few smart ways to spot the fakes, which we’re only now beginning to fully understand. One of the most amazing finds is that birds have an extra colour-sensitive cell in their eyes, which makes them far more sensitive to ultraviolet wavelengths and allows them to see a far greater range of colours than humans can. This allows cautious birds to detect a fake egg which might be exactly the same to our eyes.Fascinatingly, we’re actually able to observe different bird species at very different points in their evolutionary war with the cuckoos. For instance, some cuckoos lay their eggs in the nests of the redstarts. Theblue eggs these cuckoos lay are practically alike to those of the redstarts, and yet they are still sometimes rejected. Compare that with cuckoos who target dunnocks. While those birds lay perfectly blue eggs, their cuckoo invaders just lay white eggs with brown irregular shaped spots. And yet dunnocks barely ever seem to notice the obvious trick.Biologists suspect these more easily fooled species like the dunnocks are on the same evolutionary path as the redstarts, but they have a long way to go until they evolve the same levels of suspicion. What’s remarkable is that the dunnocks fakes are so bad and the redstart ones so good, and yet cuckoos are still more successful with the former than the latter.It speaks to just how thoroughly a species’ behavior can be changed by the pressures of natural selection, or it might just be a bit of strategic cooperation on the part of the dunnocks. Biologists have suggested that these birds are willing to tolerate a parasite every so often because they don’t want to risk accidentally getting rid of one of their own eggs.12. This passage can be most likely found in a ________.A. science surveyB. nature magazineC. zoo advertisementD. travel journal13. What does the underlined word “parasite” in paragraph 2 most probably refer to?A. Animals that work together to raise young.B Small harmful animals such as worms or mice.C. Animals that can adapt to changing environments.D. Animals which live on or inside other host animals.14. Which of the following is TRUE about the dunnock according to the passage?A. It is colour-blind and therefore cannot identify foreign eggs in the nest.B. It can easily remove cuckoo eggs from the nest because fakes are so bad.C. It is a host bird that is more likely to raise a cuckoo chick than the redstart.D. It is unable to evolve and hence accepts cuckoo eggs that appear in the nest.15. Which of the following can be inferred from the passage?A. Dunnocks may eventually learn to recognise foreign eggs.B. Redstarts seem to be less suspicious compared to dunnocks.C. Cuckoo birds are good at taking responsibility for their own young.D. It is very easy for cuckoos to imitate the colouring of the dunnock’s egg.第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。

2021-2022学年江苏省无锡市太湖高二下学期3月月考数学试题一、单选题1．函数的导数是（ ）()cos 2f x x =A ．B ．C ．D ．2cos 2x 2cos 2x-2sin 2x2sin 2x-D【分析】根据复合函数求导法则即可求解.【详解】令，则.2u x =cos y u =(cos )()(sin )sin .x u x y y u u x u x '''=⋅=⋅=-=-''2222故选：D2．函数f (x )＝ex －ex ，x ∈的单调递增区间是（ ）R A ．(0，＋∞)B ．(－∞，0)C ．(－∞，1)D ．(1，＋∞)D【分析】求得，令，即可求得单调增区间.()f x '()0f x '>【详解】由题意知，f ′(x )＝e x －e ，令f ′(x )>0，解得x >1，故的单调增区间为.()f x ()1,+∞故选：D.本题考查利用导数研究函数的单调区间，属简单题.3．2021年重庆市实行“”新高考模式，学生选科时语文、数学、英语三科必选，312++物理、历史两科中选择1科，政治、地理、化学、生物四科中选择2科，则学生不同的选科方案共有（ ）A ．8种B ．12种C ．15种D ．20种B【分析】先求得物理､历史两科中选择1科的选法，再求得政治､地理､化学､生物四科中选择2科的选法，根据乘法计数原理，即可求得答案.【详解】解：由题意得：物理､历史两科中选择1科，有种选法，122C =政治､地理､化学､生物四科中选择2科，有种选法，246C =所以学生不同的选科方案共有种.2612⨯=故选：B4．已知函数f (x )可导，且满足，则函数y ＝f (x )在x ＝3处的导0(3)l (m2i 3)x f f x x ∆→-+∆=∆数为（ ）A ．－1B ．－2C ．1D ．2B【分析】根据导数的定义即可得到答案.【详解】由题意，，所以()()()()()3333limlim3x x f f x f x f f xx∆→∆→-+∆+∆-=-=-∆'∆.()32f '=-故选：B.5．已知函数的图象在处的切线与函数的图象相切，则实数()2f x x =1x =()e xg x a ==a A BCD．B【分析】先求函数的图象在处的切线，再根据该切线也是函数()2f x x =1x =图象的切线，设出切点即可求解.()e xg x a =【详解】由，得，则，()2f x x =()2f x x'=()12f '=又，所以函数的图象在处的切线为，即.(1)1f =()2f x x =1x =12(1)y x -=-21y x =-设与函数的图象相切于点,21y x =-()e x g x a =00(,)x y 由，可得e ()x g x a '=0000e ()2,e ()21,x x g x a g x x a⎧==⎪⎪⎨⎪==-⎩'⎪解得32031,e 22x a ==故选B.本题考查导数的几何意义与函数图象的切线问题.已知切点时，可以直接利用导数求解；切点未知时，一般设出切点，再利用导数和切点同时在切线和函数图象上列方程(组)求解.6．将5名北京冬奥会志愿者分配到花样滑冰、短道速滑、冰球和冰壶4个项目进行培训，每名志愿者只分配到1个项目，每个项目至少分配1名志愿者，则不同的分配方案共有（ ）A ．60种B ．120种C ．240种D ．480种C【分析】先确定有一个项目中分配2名志愿者，其余各项目中分配1名志愿者，然后利用组合，排列，乘法原理求得.【详解】根据题意，有一个项目中分配2名志愿者，其余各项目中分配1名志愿者，可以先从5名志愿者中任选2人，组成一个小组，有种选法；然后连同其余三人，25C 看成四个元素，四个项目看成四个不同的位置，四个不同的元素在四个不同的位置的排列方法数有4！种，根据乘法原理，完成这件事，共有种不同的分配方254!240C ⨯=案，故选：C.本题考查排列组合的应用问题，属基础题，关键是首先确定人数的分配情况，然后利用先选后排思想求解.7．设直线与函数的图像分别交于点，则当达到最x t =2(),()ln f x x g x x ==,M N MN 小时的值为tA ．1B ．CD 12D【详解】由题，不妨令，则，令2ln MN x x=-(0)x >2()ln h x x x =-1'()2h x x x =-解得时，，当时，，所'()0h x =x x ∈'()0h x <)x ∈+∞'()0h x >以当时，达到最小．即．x =MN t =8．已知函数的定义域为，若在上为增函数，则()f x ()0+∞，()*()k f x y k x =∈N ()0+∞，称为“阶比增函数”．若函数为“阶比增函数"，则实数的()f x k 2()ln f x m x x x =+-1m 取值范围是（ ）A ．B ．C ．D ．1,4⎛⎤-∞- ⎥⎝⎦1,4⎛⎫-∞- ⎪⎝⎭1,4⎡⎫-+∞⎪⎢⎣⎭1,4⎛⎫-+∞ ⎪⎝⎭A【分析】由题知在上为增函数，故令()ln f x mx x x x =+-()0+∞，，进而在上恒成立，()ln ,0mg x x x x x =+->()2221'10m x x m g x x x x --=-+-=≥()0+∞，即在上恒成立，再求函数最值即可．2m x x ≤-()0+∞，()2,0y x x x =-∈+∞，【详解】解：因为函数为“阶比增函数”，2()ln f x m x x x =+-1所以函数在上为增函数，()ln f x mx x x x =+-()0+∞，所以令，()ln ,0mg x x x x x =+->故在上恒成立，()2221'10m x x mg x x x x --=-+-=≥()0+∞，所以在上恒成立，2m x x ≤-()0+∞，由于，()22111,0244y x x x x ⎛⎫=-=--≥-∈+∞ ⎪⎝⎭，所以.()2min14m x x ≤-=-故实数的取值范围是m 1,4⎛⎤-∞-⎥⎝⎦故选：A 二、多选题9．函数的导函数的图象如图所示，以下命题正确的是（ ）()y f x =()y f x '=A ．函数在处取得最小值B ．是函数的极值点()y f x =4x =-0x =()y f x =C ．在区间上单调递增D ．在处切线的斜率大于零()y f x =(4,1)-()y f x =1x =ACD【分析】根据导函数图象可判定导函数的符号，从而确定函数的单调性，得到极值点，以及根据导数的几何意义可知在某点处的导数即为在该点处的切线斜率．【详解】根据导函数图象可知当时，，在时，(,4)x ∈-∞-()0f x '<(4,)x ∈-+∞，()0f x '≥函数在上单调递减，在上单调递增，且故C 正确；∴()y f x =(,4)-∞-(4,)-+∞易知函数在处取得最小值，故正确；()y f x =4x =-A 在上单调递增，故不是函数的极值点，故B 不正确； (4,)-+∞0x =()y f x =函数在处的导数大于0，切线的斜率大于零，故D 正确.()y f x =1x =∴故选：ACD ．10．函数的一个零点在区间内，则实数a 的可能取值是（ ）2()2x f x ax =--(1,2)A ．0B ．1C ．2D ．3BC【分析】根据初等函数的单调性判断函数的单调性，根据零点存在定()22x f x a x =--理可得，从而可得结果.()()120f f <【详解】因为函数在定义域上单调递增，22x y y x ==-、{}0x x ≠所以函数在上单调递增，()22x f x a x =--{}0x x ≠由函数的一个零点在区间内，()22x f x a x =--()1,2得，()()()()12(22)(41)30f f a a a a ⨯=----=-⨯-<解得,0<<3a 故选：BC11．用0、1、2、3、4这五个数字组成无重复数字的自然数，如果十位上的数字比百位上的数字和个位上的数字都小，则称这个数为“凹数”，如301、423等都是“凹数”，则下列结论中正确的是（ ）A ．组成的三位数的个数为60B ．在组成的三位数中，偶数的个数为30C ．在组成的三位数中，“凹数”的个数为20D ．在组成的三位数中，“凹数”的个数为24BC【分析】对于A ，因为百位数上的数字不能为零，然后利用分步乘法原理即可判断；对于B ，将所以三位数的偶数分为两类，①个位数为，②个位数为或，然后根024据分步乘法原理及分类加法原理即可判断；对于C 、D ，将这些“凹数”分为三类，①十位为，②十位为，③十位为，然后根012据分步乘法原理及分类加法原理即可得判断.【详解】对于A ，因为百位数上的数字不能为零，所以组成的三位数的个数为，故A 不正确；124444348A A =⨯⨯=对于B ，将所以三位数的偶数分为两类，①个位数为，则有种，0244312A =⨯=②个位数为或，则有种，24A A A =⨯⨯=11123323318所以在组成的三位数中，偶数的个数为，故B 正确；121830+=对于C 、D ，将这些“凹数”分为三类，①十位为，则有种，0244312A =⨯=②十位为，则有种，123326A =⨯=③十位为，则有种,222212A =⨯=所以在组成的三位数中，“凹数”的个数为， 故C 正确，D 不正确.126220++=故选：BC.12．已知函数有两个互异的极值点，下列32()(0)f x ax bx cx d a =+++≠()1212,x x x x <说话正确的是（ ）A ．230b ac ->B ．有三个零点的充要条件是12()()0f x f x <C ．时，在区间上单调递减0a >()f x 12(,)x x D ．时，为极大值，为极小值0a <1()f x 2()f x ABC求导，根据有两个互异的极值点逐项验证.2()32f x ax bx c '=++()f x ()1212,x x x x <【详解】因为函数，32()(0)f x ax bx cx d a =+++≠所以，2()32f x ax bx c '=++因为有两个互异的极值点，()f x ()1212,x x x x <所以，故A 正确；()()22212430b ac b ac ∆=-=->所以若有三个零点则，故B 正确；()f x 12()()0f x f x <当时，开口向上，则时，，所以区0a >2()32f x ax bx c '=++12(,)x x x ∈()0f x '<()f x 间上单调递减，故C 正确；12(,)x x 当时，当或时，，当时，，所以为极0a <1x x <2x x >()0f x '<12x x x <<()0f x '>1()f x小值，为极大值，故D 错误；2()f x 故选：ABC本题主要考查导数与函数的极值，导数与函数的零点，还考查了运算求解的能力，属于中档题.三、填空题13．已知，则________．34m m C C =21889m m m C C C --++=120【分析】根据已知条件及组合数公式求得，再利用组合数的性质m 递推关系及组合数公式即可求解11m m m n n nC C C -+=+【详解】由，得，解得.34mmC C=!!!()!!()!m m m m =--33447m =所以.562188988997677910120m m m C C C C C C C C C --++=++==+=故答案为.12014．若函数的极值点为，则__________．()e xf x x =0x x =()0f x =1e -1e--【分析】根据求导公式和运算法则可得，结合极值点的定义求出()e e x xf x x ='+，进而求出即可.01x =-(1)f -【详解】由题意得，，所以，()e x f x x =()e e x x f x x ='+因为是函数的极值点，0x x =()f x 所以，即，0000()e e 0x x f x x '=+=00e (1)0x x +=解得，易得－1是极小值点，所以.01x =-01()(1)e f x f =-=-故答案为.1e-15．电影院一排10个位置，甲、乙、丙三人去看电影，要求他们坐在同一排，且每人左右两边都有空位的坐法种数为____________．120【分析】根据题意，先排好7个空座位，由于空座位是相同的，形成6个空位是符合条件的，再将甲、乙、丙3人安排到这6个空位上即可.【详解】解：10个座位中，除了甲、乙、丙3人的座位，还有7个座位，形成6个空位，所以只需将甲、乙、丙3人安排到这6个空位上即可，故有（种）.36654120A =´´=所以每人左右两边都有空位的坐法种数为.120故120四、双空题16．己知函数，若，且，则实数k 的取值范231,1()1,1x x f x x x +≤⎧=⎨->⎩n m >()()f n f m k ==围为_______，设，则t 的取值范围为______________．t n m =- 04k <≤171,12⎤⎥⎦【分析】画出函数图象，由图象得出k 的取值范围，用表示出，结合二次函数的n m 性质求得的取值范围.t n m =-【详解】画出图象如下图所示，()fx 当时，，令，解得1x =(1)3114f =⨯+=()2140x x -=>x =因为，()()f n f m k ==由图象可知，；04k <≤由得，，且()(),n m f n f m >=2311m n+=-223n m -=1n <所以，(222121333n t n m n n n n -=-=-=-++<≤结合二次函数的性质可知，当时，取得最大值为131223n =-=⎛⎫⨯- ⎪⎝⎭t，当取得最小值为.2133217322312⎛⎫-⨯++= ⎪⎝⎭n =t212133-⨯+=所以的取值范围是.t 171,12⎤-⎥⎦故；.04k <≤171,12⎤⎥⎦五、解答题17．已知函数．2ln y x x =(1)求这个函数的图象在处的切线方程；1x =(2)若过点的直线l 与这个函数图象相切，求l 的方程．(0,0)(1)；1y x =-(2).1e y x=-【分析】(1)令，根据导数的几何意义求出，结合和直线的点斜()y f x =(1)f '(1)0f =式方程即可求出切线方程；(2)设切点为，根据导数的几何意义和两点坐标求直线斜率公式分别求出切2000(,ln )x x x 线的斜率，列出方程，解方程可得，进而求出斜率，利用直线的点斜式方程即10e -=x 可得出结果.【详解】(1)令，则，()y f x =2()ln f x x x =函数的定义域为，，()f x (0,)+∞()2ln f x x x x '=+所以，又，(1)2ln111f '=+=(1)0f =所以函数在处的切线方程为；1x =1y x =-(2)设切点为，2000(,ln )x x x 由(1)知，，0000()2ln f x x x x '=+又直线l 的斜率为，200000ln ln l x x k x x x ==有，解得，0002ln x x x +00ln x x =10e -=x 所以，100ln e l k x x -==-所以直线l 的方程为.1e y x=-18．(1)若，求正整数；33210n n A A =n (2)已知，求.56711710n n nC C C -=8n C (1)8(2)28【分析】（1）利用排列数公式可得，即求；()()()()221221012n n n n n n --=--（2）利用组合数公式可得，即求.223420n n -+=【详解】(1)由得，33210n n A A =，又，()()()()221221012n n n n n n --=--*3,N n n ≥∈∴，即，()()22152n n -=-8n =∴正整数为8.n (2)由得，56711710n n nC C C -=，()()()!5!!6!7!7!5!6!107!n n n n n n --⨯--=⨯∴即，()()6761660n n n ----=223420n n -+=解得或，又，2n =21n =05n ≤≤∴，2n =∴.88228n C C ==19．新冠疫情爆发后，某企业利用部分人工转产口罩.每生产万件(每件5个口罩)，x 需投入固定成本5万元，流动成本万元，当月产量小于7万件时，()C x (万元)；当月产量不小于7万件时，(万元).口()2123C x x x=+()36ln 17e C x x x x =++-罩销售价为6元/件，且生产的口罩能全部售出.（1）写出月利润(万元)关于月产量(万件)的函数解析式；(注：月利润月销售()p x x =收入固定成本流动成本)--（2）当月产量约为多少万件时，生产的口罩所获月利润最大？最大月利润是多少？（1）；（2）当月产量约为万件时，所获月利润最大，()23145,07312ln ,7x x x p x e x x x ⎧-+-<<⎪⎪=⎨⎪--≥⎪⎩3e 最大利润为8万元.（1）根据月利润等于销售额减去投入总成本减去固定成本，分时和两种07x <<7x ≥情况，得到关于的分段函数关系式；()p x x （2）当时，根据二次函数求最大值的方法求的最大值，当时，根07x <<()p x 7x ≥据函数的单调性求最大值，最后比较取最大的即可.【详解】（1）口罩销售价为6元/件，则万件口罩销售收入为万元.x 6x 依题意得，当时，，07x <<()22116254533p x x x x x x =---=-+-当时，，7x ≥()33661712l ln 5n x e e p x x x x x x ⎛⎫=-++--=--⎪⎝⎭∴，()23145,07312ln ,7x x x p x e x x x ⎧-+-<<⎪⎪=⎨⎪--≥⎪⎩（2）当时，，07x <<()()21673p x x =--+∴当时，的最大值为(万元)，6x =()p x ()67p =当时，，∴，7x ≥()3ln 12x e p x x =--()33221e e xp x x x x -'=-+=∴当时，单调递增，当，单调递减，37x e ≤<()p x 3x e ≥()p x ∴当时，取最大值(万元)，3x e =()p x ()3312ln 18p e e=--=∵，∴当时，取得最大值8万元，87>3x e =()p x 当月产量约为万件时，所获月利润最大，最大利润为8万元.3e 本题主要考查了根据实际问题选择合适的函数类型的能力，以及利用函数的单调性求最值的能力，属于中档题.20．设函数．()()1ln 0f x ax x a x=+>（1）当时，求的极值；1a =()f x（2）如果≥在上恒成立，求实数的取值范围．()f x ax ()0,∞+a （1）有极小值，没有极大值；（2）．()11f =20,e ⎛⎤ ⎥⎝⎦【详解】试题分析：（1）当时，求导令导函数等于零，列表，通过表格找到函数1a =极值即可；（2）求恒成立问题一般要分离参数，构造函数求其最小值，只需最小值大于零即可求出取值范围.a 试题解析：（1）由已知，当时，，∴，1a =()1ln f x x x x =+()21ln 1f x x x +-'=()312f x x x +'=>'∴在上单调递增，且，()f x '()0,+∞()10f '=，随变化如下表：()f x '()f x x x()0,11()1,+∞()f x '-+()f x ↘极小值↗∴有极小值，没有极大值． ()f x ()11f =（2）（方法一）由题可得恒成立，()211ln a x x -≤当时，上式恒成立；x e ≥当时，，又，故0x e <<()211ln a x x ≤-0a >()211ln x x a≥-令，则， 令，()()21ln h x x x =-()()12ln h x x x =-'()0h x '=x =∴当 时， ，0x <<()0h x '>x e <<()0h x '<∴，()(max 12eh x he ==-=∴，解得：，∴的取值范围是． 12ea ≥20a e <≤a 20,e ⎛⎤ ⎥⎝⎦（方法二）由题可得， 设，则，()()1ln ,0g x ax x ax x x =+->()21ln g x a x x ='-∵，∴在上单调递增，，，0a >()g x '()0,+∞()110g '=-<12110a ag e e ⎛⎫=-> ⎪'⎝⎭∴使得，则， 101,a x e ⎛⎫∃∈ ⎪⎝⎭()00g x '=2001ln a x x =由知，且时， ，时， ，0a >01x >00x x <<()0g x '<0x x >()0g x '>∴，∴，∴∴，()()00min 002ln 10ln x g x g x x x -==≥01ln 2x ≥0x ≥2a e ≤∴的取值范围是．a 20,e ⎛⎤ ⎥⎝⎦（方法三）由题可得恒成立，()21ln 0f x a ax a xx -=+-≥令，则， ()21ln h x a x a x =+-()h x'=∴时， ，0x<<()0h x '<x >，∴，()0h x '>()min 20h x a a ==≥∴，解得：，∴的取值范围是． 2ln 1a ≥2a e ≤a 20,e ⎛⎤ ⎥⎝⎦21．如图，从左到右共有5个空格.（1）向5个空格中放入0，1，2，3，4这5个数，一共可组成多少个不同的5位奇数；（2）用红，黄，蓝三种颜色给5个空格上色，要求相邻空格不同色，问一共有多少种涂色方案；（3）向这5个空格中放入7个不同的小球，要求每个空格都有球，则有多少种不同的方法？（1）36个；（2）48种；（3）16800种.【分析】（1）先排个位，再排首位，最后排其他位置，并用分步计数原理求解即可；（2）按要求分析每个格子的颜色数量，顺序填涂，用分步计数原理求解即可；（3）由题意可先分成5堆，在把分好的5堆排到5个位置即可求解【详解】（1）个位有放法，首位有放法，其余三位任意放，12C 13C 共有个五位奇数.11323336C C A =（2）第⼀个格⼦有3种涂色方案，剩下每个格⼦均有2种涂色方案，共有种涂色方案.43248⨯=（3）7个不同的球可分为1，1，1，1，3这样的5堆，有种分发，37C 在5个位置全排列有种方法；35754200C A =7个不同的球可分为1，1，1，2，2这样的5堆，有种分发，227522C C A 在5个位置全排列有种方法；2257552212600C C A A =所以共有种方法.42001260016800+=22．已知函数．323()22f x x ax b=-+(1)讨论的单调性；()f x (2)是否存在，使得在区间的最小值为且最大值为？若存在，求出,a b ()f x [0,1]1-1a ，b 的所有值；若不存在，说明理由．(1)当时，)在上单调递增，在上单调递减；0a >()f x (),0,,2a ⎛⎫-∞+∞⎪⎝⎭0,2a ⎛⎫ ⎪⎝⎭当时，在单调递增.0a =()f x (),-∞+∞当时，)在上单调递增，在上单调递减.0a <()f x (),,0,2a ⎛⎫-∞+∞ ⎪⎝⎭,02a ⎛⎫ ⎪⎝⎭(2)或0,1a b ==-8,13a b ==【分析】（1）由，得出，求出的两根，比较根的大小并分类讨论，()f x ()'f x ()0f x '=进而求出函数的单调性；()f x （2）利用（1）中的单调区间讨论在上的最值，最终确定参数的值.()f x ()f x []0,1,a b 【详解】(1)由，得.323()22f x x ax b =-+()2()6332f x x ax x x a '=-=-令，即，解得或.()0f x '=()320x x a -=0x =2a x =若，则当时，；0a >(),0,2a x ⎛⎫∈-∞+∞ ⎪⎝⎭ ()0f x '>当时，.0,2a x ⎛⎫∈ ⎪⎝⎭()0f x '<所以)在上单调递增，在上单调递减.()f x (),0,,2a ⎛⎫-∞+∞⎪⎝⎭0,2a ⎛⎫ ⎪⎝⎭若，则在上恒成立，0a =2()60f x x '=≥R 所以在单调递增.()f x (),-∞+∞若，则当时，；0a <(),0,2a x ⎛⎫∈-∞+∞ ⎪⎝⎭ ()0f x '>当时，.,02a x ⎛⎫∈ ⎪⎝⎭()0f x '<所以)在上单调递增，在上单调递减.()f x (),,0,2a ⎛⎫-∞+∞ ⎪⎝⎭,02a ⎛⎫ ⎪⎝⎭(2)满足题设条件的存在.,a b 当时，由（1）知，在单调递增，0a ≤()f x []0,1所以在区间的最小值为，最大值为.()f x []0,1()0f b =()3122f a b =-+此时满足题设条件当且仅当，，即.,a b 1b =-3212a b -+=0,1a b ==-当即时，由（1）知，在单调递减，12a≥2a ≥()f x []0,1所以在区间的最大值为，最小值为.()f x []0,1()0f b =()3122f a b =-+此时满足题设条件当且仅当，，即.,a b 3212a b -+=-1b =8,13a b ==(ii)当即时，由（1）知，012a<<02a <<)在上单调递减，在上单调递增.()f x 0,2a ⎡⎫⎪⎢⎣⎭,12a ⎛⎤ ⎥⎝⎦当时，取得极小值即为的最小值，2ax =()f x ()f x 3233()222228a a a a f a b b ⎛⎫⎛⎫=⨯-⨯⨯+=-+ ⎪ ⎪⎝⎭⎝⎭的最大值为或.()f x ()0f b =()3122f a b =-+若，，则矛盾.318a b -+=-1b =a =02a <<若，则或，与矛盾318a b -+=-3212a b -+=a =a =-0a =02a <<综上，当或时，在区间的最小值为且最大值为.0,1a b ==-8,13a b ==()f x [0,1]1-1。

2023—2024学年度第一学期期中考试高一英语试卷第Ⅰ卷（选择题95分）第一部分听力（共两节，满分30分）第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. What is the weather like today?A. Hot.B. Cold.C. Windy.2. What does the man think of his new job?A. Boring.B. Satisfying.C. Poorly-paid.3. What are the speakers mainly talking about?A. A menu.B. A restaurant.C. A bill.4. What time did Suzy leave home?A. 4:30.B. 5:00.C. 5:15.5. What is the man’s suggestion?A. Going to the concert.B. Just walking around.C. Going to see a show.第二节（共15小题，每小题15分，满分22.5分）听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项。

听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间，每段对话或独白读两遍。

听第6段长对话，回答第6、7题。

6. What is the most challenging thing for the man?A. Eating the local food.B. Adjusting to the local climate.C. Recovering from the time difference.7. How long will the man probably stay in Singapore?A. Just for the weekend.B. A bit less than 12 days.C. About 15 days.听第7段长对话，回答第8至9题。

江苏省太湖高级中学201—2019学年度第二学期期中考试试卷高 一 数 学2019．4一、选择题（本大题共12小题，每小题5分，共60分．在每小题所给出的四个选项中，只有一项是正确的，请把正确选项前的字母代号填涂在答题卡相应位置．．．．．．．上） 1．在△ABC 中，若a 2＝b 2＋c 2＋bc ，则角A 为A ．30°B ．45°C ．120°D ．150°2．已知点A(1，B(﹣1，，则直线AB 的倾斜角是A ．60°B ．30°C ．120°D ．150°3．在△ABC 中，a ＝2，b ＝B ＝6π，则角A 为A ．4πB ．3πC ．34πD ．4π或34π 4．在长方体ABCD —A 1B 1C 1D 1中，AB ＝BC ＝2，AC 1与平面BB 1C 1C 所成的角为30°，则该长方体的体积为A ．8B ．C ．D ．5．在△ABC 中，A ：B ：C ＝1：1：4，则a ：b ：c 等于A ．1：1B ．2：2C ．1：1：2D ．1：1：46．已知一圆锥的侧面展开图是一个中心角为直角的扇形，若该圆锥的侧面积为4π，则该圆锥的体积为A B ．43π C ．3π D7．在△ABC 中，若cosC ＝，b cosA ＋a cosB ＝3，则△ABC 外接圆的半径为A ．B ．C ．4D ．68．如图，在正四棱柱ABCD —A 1B 1C 1D 1中，AA 1＝2AB ，则异面直线A 1B 与AD 1所成角的余弦值为A ．15 B ．25 C ．35 D ．459．已知M(1，2)，N(4，3)，直线l 过点P(2，﹣1)且与线段MN 相交，那么直线l 的斜率k的取值范围是A．[﹣3，2] B．(-∞，﹣3][2，+∞)C．[13-，12] D．(-∞，13-][12，+∞)10．已知两条直线m、n与两个平面α、β，有下列四个命题：①若m∥n，n∥α，则m ∥α；②若α∥β，m∥n，且m⊥α，则n⊥β；③若m⊥n，m⊥α，则n∥α或n⊂α；④若α⊥β，m∥α，则m⊥β．其中，正确命题的个数是A．1 B．2 C．3 D．411．在△ABC中，若(a﹣b)(sinA＋sinB)＝(c﹣b)sinC，a b2＋c2的取值范围是A．(3，6) B．(3，5) C．(5，6] D．[5，6]12．在△ABC中，若cos2C2＝54a cosA﹣14c cosB＋12，且b＝2，则边a的最小值为A．5B．5C．9625D．11225二、填空题（本大题共4小题，每小题5分，共计20分．不需要写出解答过程，请将答案填写在答题卡相应的位置上．．．．．．．．．．）13．若直线l1：ax＋(1﹣a)y＝3与l2：(a﹣1)x＋(2a＋3)y＝2互相垂直，则实数a的值为．14．在正四棱柱ABCD—A1B1C1D1中，AA1＝2AB，E为AA1中点，则异面直线BE与CD1所成角的余弦值为．15．如图，PA⊥平面ABC，AC⊥BC，PA＝4，AC BC＝1，E、F分别为AB、PC 的中点，则三棱锥B—EFC的体积为．16．在△ABC中，若b＝6，ac cosB＝a2﹣b2，O为△ABC内一点，且满足OA+ OB OC0+=，∠BAO＝30°，则OA＝．第8题第15题三、解答题（本大题共6小题，共计70分．请在答题纸指定区域．．．．．．．内作答，解答应写出文字说明，证明过程或演算步骤．）17．（本题满分10分）已知在平面直角坐标xOy 中，A(8，﹣6)，B(2，2)．（1）求线段AB 的中垂线方程；（2）求过点P(﹣2，1)且与直线AB 平行的直线l 的方程．18．（本题满分10分）如图，在四棱锥V —ABCD 中，底面四边形ABCD 是矩形，VD ⊥平面ABCD ，过AD 的平面分别与VB ，VC 交于点M ，N ．（1）求证：BC ⊥平面VCD ；（2）求证：AD ∥MN ．19．（本题满分12分）在△ABC 中，若A ＝4，a 2﹣c 2＝12b 2． （1）求sinC 的值；（2）若△ABC 的面积为3，求边长a ．20．（本题满分12分）如图，在四棱锥P —ABCD 中，底面四边形ABCD 是矩形，平面PAD ⊥平面ABCD ，PA ⊥PD ，PA ＝PD ，E ，F 分别为AD ，PB 的中点．（1）求证：PE ⊥BC ；（2）求证：平面PAB ⊥平面PCD ；（3）求证：EF ∥平面PCD ．21．（本题满分12分）某学校的平面示意图为如下五边形区域ABCDE，其中三角形区域ABE为生活区，四边形区域BCDE为教学区，AB，BC，CD，DE，EA，BE为学校的主要道路（不考虑宽度）．∠BCD＝∠CDE＝23π，∠BAE＝3π，DE＝3BC＝3CD＝3 km．（1）求道路BE的长度；（2）求生活区△ABE面积的最大值．22．（本题满分14分）如图，在长方形ABCD中，AB＝2，BC＝1，E为CD的中点，F为AE的中点，现在沿AE将△ADE向上折起，在折起的图形中解答下列问题：（1）在线段AB上是否存在一点K，使得BC∥平面DFK？若存在，请证明你的结论；若不存在，请说明理由；（2）若平面ADE⊥平面ABCE，求证：平面BDE⊥平面ADE．。

江苏省重点高中最新排名1.南京外国语学校2.南师附中3.江苏省苏州中学4.江苏省扬州中学5.南京金陵中学6.无锡市第一中学7.江苏省天一中学8.江苏省泰兴中学9.徐州市第一中学10.江苏省苏州实验中学11.江苏省南通中学12.南京市第一中学13.无锡市辅仁高级中学14.江苏省常州高级中学17.江苏省启东中学18.南通第一中学19.江苏省锡山高级中学20.盐城中学21.江苏省梅村高级中学22.江苏省梁丰高级中学23.江苏省南菁高级中学24.常州市第一中学25.江苏省溧水高级中学26.江苏省如东高级中学27.苏州市第一中学28.苏州市第十中学29.江苏省江阴高级中学30.南京市第十三中学32.徐州市第三中学33.江苏省前黄高级中学34.苏州中学园区35.苏州新区第一中学36.江苏教育学院附属中学37.江苏省淮阴中学38.南京市第九中学39.江苏省常熟中学40.江苏省姜堰中学41.江苏省海安高级中学42.江苏省木渎中学43.江苏省通州高级中学45.江苏省昆山中学46.江苏省如皋中学48.江苏省镇江中学49.江苏省怀仁高级中学50.江苏省黄桥中学51.南通市第三中学52.南京市江宁高级中学53.江苏省泰州中学54.姜堰市第二中学55.江苏省滨海中学56.江苏省华罗庚中学57.苏州市第六中学58.江苏省清江中学59.江苏省郑集高级中学60.江苏省丹阳高级中学61.江苏省邗江中学63.江苏省南通市如东栟茶中学64.盐城第一中学65.江苏省扬中高级中学66.江苏省太湖高级中学67.江苏省建湖高级中学68.江阴市长泾中学69.江苏省侯集中学70.张家港高级中学71.江苏省奔牛高级中学72.南师附属扬子中学73.江苏省羊尖高级中学74.包场中学75.江阴市第一中学76.丰县中学78.苏州第三中学79.东山高级中学80.苏大附中81.南京市第五中学82.江苏省东台中学83.苏州新区二中84.江苏省沙溪高级中学85.江阴市青阳中学86.通州市西亭中学87.江苏省沭阳高级中学88.江苏省高淳高级中学89.江苏省金坛中学90.震泽中学91.江苏省淮安中学92.宜兴官林中学93.江阴市华士高级中学94.江苏省响水中学95.江苏省白蒲高级中学96.涟水县中学97.徐州高级中学98.江苏省泗阳中学99.江苏省溧阳高级中学100.连云港板浦高级中学。

【小问2详解】
，其中 ，由题意得： ，解得： ，故 ，故 的值域为 ，令 ，解得： ，所以 的单调递增区间为：
【小问3详解】
因为 ，所以 ，则 ，令 ，则 ，所以方程 在 上有根等价于 在 上有根，因为 ，所以 ，解得： ，故 的取值范围是 .
12、
【解析】
M﹣ABC四个面都为直角三角形，MA⊥平面ABC，MA=AB=BC=2，
A.
B
C.
D.
5．已知函数 ，则 在 上的最大值与最小值之和为（）
A. B.
C. D.
6．使得 成立的一个充分不必要条件是（）
A. B.
C. D.
7．曲线 与直线 在 轴右侧的交点按横坐标从小到大依次记为 , , , , ,…,则 等于
A. B.2
C.3 D.
8．满足不等式 成立的 的取值集合为（）
17、（1）
（2）
【解析】（1）根据题意选取点代入函数解析式，取出参数 即可.
（2）先求出2021年全球产生的数据量，然后结合条件可得答案.
【小问1详解】
由题意点 在函数模型 的图像上
则 ，解得
所以
【小问2详解】
2021年时，间隔年份为13，则2021年全球产生的数据量是
2021年全球产生的数据量是2011年的倍数为：
【思路点睛】本题主要考查三角函数的图象以及简单的三角方程，属于中档题.解答本题的关键是将曲线 与直线 在 轴右侧的交点按横坐标转化为 根，可得 或 ，令 取特殊值即可求得 ，从而可得 .
8、A
【解析】先求出一个周期内不等式的解集，再结合余弦函数的周期性即可求解.
【详解】解：由 得：
当 时，
因为 的周期为
14．若函数 满足：对任意实数 ，有 且 ，当 [0,1]时， ,则 [2017,2018]时, ______________________________

2024届江苏省太湖高级中学英语高三第一学期期末学业水平测试模拟试题注意事项：1．答卷前，考生务必将自己的姓名、准考证号、考场号和座位号填写在试题卷和答题卡上。

用2B铅笔将试卷类型（B）填涂在答题卡相应位置上。

将条形码粘贴在答题卡右上角"条形码粘贴处"。

2．作答选择题时，选出每小题答案后，用2B铅笔把答题卡上对应题目选项的答案信息点涂黑；如需改动，用橡皮擦干净后，再选涂其他答案。

答案不能答在试题卷上。

3．非选择题必须用黑色字迹的钢笔或签字笔作答，答案必须写在答题卡各题目指定区域内相应位置上；如需改动，先划掉原来的答案，然后再写上新答案；不准使用铅笔和涂改液。

不按以上要求作答无效。

4．考生必须保证答题卡的整洁。

考试结束后，请将本试卷和答题卡一并交回。

第一部分（共20小题，每小题1.5分，满分30分）1．Due to the reform and opening-up, our living conditions, undoubtedly, have improved ________ over the past decades.A．considerately B．approximately C．appropriately D．considerably2．—Do you know Linda was fired for her casual attitude towards the job?—No wonder she _________ when I tried to amuse her this morning.A．was tickled pink B．pulled my legC．gave me the cold shoulder D．saw the handwriting on the wall3．While his approach was a complete ________ from established practices, the result was satisfactory.A．separation B．prohibition C．departure D．judgment4．________ some leaders and scientists have praised China’s achievement in space technology, ot hers regard China’s progress as a threat.A．Unless B．OnceC．Even though D．Now that5．His suggestion_______to see the film Avatar interested every one of us.A．that we go B．which we should go C．that we would go D．we should go 6．Different tastes among tourists from outside the mainland ________ the list of the country's attractions．A．top B．shape C．lead D．show7．The accident which left 15 people on board dead ________ if both the angry female passenger and the bus driver had kept calm.A．should have avoided B．should be avoidedC．could have avoided D．could have been avoided8．Children who are not active or_____ diet is high in fat will gain weight quickly.A．what B．whoseC．which D．that9．In terms of Mrs. Meng’s being arrested without solid evidence, the western media has _____ public attention away from where it should be, that is, the rule of law. A．transformed B．shiftedC．attracted D．changed10．I ____ about what you’ve said and I’ve decided to take your advice．A．thought B．have been thinkingC．was thinking D．was thinking11．—How did you like John’s exhibition of paintings last weekend?—To tell you the truth, his paintings didn’t ________ me much.A. refer to B．appeal to C．belong to D．occur to12．No student ________ go out of school to have lunch without permission of the headteacher.A．might B．mustC．shall D．could13．Youth is a period of our life we see no limit to our hopes and wishes. A．where B．thatC．what D．when14．The bus dropped me off and pulled away _____I realized I had left my bag on it. A．while B．beforeC．after D．since15．Jane can’t attend the meeting at 3 o’clock this afternoon because she ______ a class at that time.A．will teach B．would teachC．has taught D．will be teaching16．______ property, we’re amon g the richest people in this city．A．In search of B．In spite of C．In place of D．In terms of17．—Flight MU257 _______________ . I must be off now.—Have a nice trip.A．is being announced B．has announcedC．was announcing D．had been announced18．— Excuse me, do you mind if I open the window?— Well, if you __________. I can put on more clothes.A．can B．mayC．must D．shall19．During the economic crisis, we should help those for ______life is far from easy．A．whom B．whose C．who D．whoever20．Advertising often functions as an indicator for ______ society considers to be socially acceptable and desirable at the time.A．what B．whetherC．how D．which第二部分阅读理解（满分40分）阅读下列短文，从每题所给的A、B、C、D四个选项中，选出最佳选项。

2020年江苏省太湖高级中学高三英语月考试卷及答案第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项AIt was a weeknight and one of my twin daughters marched into the room, waving a book she'd finished. “Dad, why are books with science in them always about boys?” she asked.I told her that simply wasn't true; there were loads of great science fictions with girls in them. She agreed, but argued that in those stories it was the boys who were doing science, and the girls were justalong for the ride. My other daughter took her sister's side and challenged me to give an example.This left me in a difficult position. I could either go through our library to point out some wonderful examples of female-led science fictions, or just admit they were right and remain in my comfortable chair.I've been asked several times how I came up with the idea forA Problematic Paradoxand my answer is always the same: it came to me in a moment of inspiration. I like that answer because it's simple and makes me seem very creative. The fact that this explanation is not true bothers me from time to time. Here's the truth: the story wasn't my idea. It was my daughters who suggested I write something for them that had a girl doing science.My daughters were at an age when many young women turn away from STEM (science, technology, engineering, and math), believing those areas of study unfriendly or out-of-the-norm for girls. I also read about how important role models can be to young people. It's one thing to tell a person they can do something, but seeing someone like them doing that thing can be more powerful.So, I kept two guidelines for the book in mind: First, the story had to be fun for anyone, because it's as important for boys to understand that science is for everyone. Second, I wanted the main character, Nikola, to be imperfect. She should be someone with shortcomings as we all have. I think this not only makes a story more interesting to read, but also helps make it clear that the most extraordinary things can be done by ordinary people.1. What does the underlined phrase “along for the ride” in paragraph 2 probably mean?A. Entering a bike race.B. Offering vital help.C. Doing unimportant things.D. Playing the leading role.2. What do we know about the bookA Problematic Paradox1?A. Its main character is perfect.B. It is a female-led science fiction.C. It is intended to appeal to girls only.D. Its idea comes from the author's inspiration.3. Which of the following best describes the author's book?A. Serious and abstract.B. Simple and practical.C. Creative and well-organized.D. Inspiring and interesting.BPaper is an important part of modern life. People use it in school, at work, to make artwork and books, to wrap presents and much more. Trees are the most common material for paper these days.So how do people make paper out of trees today? People first cut trees, load them onto trucks and bring them to a factory. Machines cut open the outer coverings of the trees, and cut the trees into pieces. Those pieces are boiled into a soup. After that, it is hit flat, dried and cut up into sheets of paper.The entire process, from planting a small tree to buying your school notebook, takes a very long time. Just growing the trees takes 10 to 20 years.Making tons of paper from trees can harm the planet. Humans cut down 80, 000 to 160,000 trees around the world every day, and use many of them to make paper. Some of those trees come from tree farms. But people also cut down forests for paper, which means that animals and birds lose their homes.Cutting forests down also contributes to climate change, and paper factories pollute the air. After you throw paper, it often takes the paper six to nine years to break down. That's why recycling is important. It saves a lot of trees, slows climate change and helps protect endangered animals, birds and all creatures that rely on forests for their homes and food.So if paper isn't good for the environment, why don't people write on something else?The answer: They do. With computers, tablets and cellphones, people use much less paper than in the past. Maybe a day will come when we won't use paper at all — or will save it for very special books and artworks.4. What can we know about making paper out of trees?A. It costs much money.B. It takes a lot of time.C. It is very easy and fast.D. It is dangerous and difficult.5. What is the impact of paper production?A. It promotes the recycling.B. It does harm to the environment.C. It slows down the climate change.D. It protects the animals from losing homes.6. How will we use paper someday in the future according to the text?A. Use it for books only.B. Use the recycled paper.C. Treasure it occasionally.D. Use it for artworks.7. What idea does the author want to express from the text?A. The influence of making paper on environment.B. The wonderful experience of making paper.C. The necessary process of making paper.D. The good reasons for making paper.CAt the World Economic Forum last month, President Trump drew claps when he announced the United States would respond to the forum's proposal to plant one trillion(万亿) trees to fight climate change. The trillion-tree idea won wide attention last summer after a study published in the journal Science concluded thatplanting so many trees was “the most effective climate change solution to date”.If only it were true. But it isn't. Planting trees would slow down the planet's warming, but the only thing that will save us and future generations from paying a huge price in dollars, lives and damage to nature is rapid and considerable reductions in carbon release from fossil fuels, to net zero by 2050.Focusing on trees as the big solution to climate change is a dangerous diversion(偏离). Worse still, it takes attention away from those responsible for the carbon release that are pushing us toward disaster. For example, in the Netherlands, you can pay Shell an additional 1 euro cent for each liter of regular gasoline you put in your tank, to plant trees to balance the carbon release from your driving. That's clearly no more than disaster slightly delayed. The only way to stop this planet from overheating is through political, economic, technological and social solutions that end the use of fossil fuels.There is no way that planting trees, even across a global area the size of theUnited States, can absorb the huge amounts of fossil carbon released from industrial societies. Trees do take up carbon from the atmosphere as they grow. But this uptake merely replaces carbon lost when forests were cleared in the first place, usually long ago. Regrowing forests where they once grew can undo some damage done in the past, but even a trillion trees can't store enough carbon to head off dramatic climate changes this century.In a sharp counter argument to last summer's Paper in Science, Justin Gillis wrote in the same journal in October that the study's findings were inconsistent with the dynamics of the global carbon cycle. He warned that “the claimthat global tree restoration(复原) is our most effective climate solution is simply scientifically incorrect and dangerously misleading”.8. What do we know about the trillion-tree idea?A. It was published in a journal.B. It was proposed last summer.C. It was put forward by Trump.D. It drew lots of public attention.9. What is paragraph 3 mainly about?A. A drawback of the tree planting strategy.B. An example of balancing carbon release.C. An anecdote of making a purchase at Shell.D. A responsibility for politicians and economists.10. What was Justin Gillis's attitude towards global tree restoration?A. Indifferent.B. Opposed.C. Hesitant.D. Supportive.11. What is the best title for the text?A. Contradictory Ideas on Tree Planting.B. A Trillion Trees Come to the Rescue.C. Planting Trees Won't Save the World.D. The Best Solution to Climate Change.DThere is an old Chinese proverb that states “One generation plants the trees; another gets the shade,” and this is how it should be with mothers and daughters. The relationship between a mother and a daughter is sometimes confusing. The relationship can be similar to friendship. However, the mother and daughter relationship has unique characteristics that distinguish it from a friendship. These characteristics include responsibilities and unconditional love, whichprecludemothers and daughters from being best friends.Marina, 27 years old, said, “I love spending time with my mom, but I wouldn’t consider her my best friend. Best friends don’t pay for your wedding. Best friends don’t remind you how they carried you in their body and gave you life! Best friends don’t tell you how wise they are because they have been alive at least 20 years longer than you.” This doesn’t mean that the mother and daughter relationship can’t be very close and satisfying. This generation of mothers and adult daughters has a lot in common, which increases the likelihood of shared companionship. Mothers and daughters have always shared the common experience of being homemakers,responsible for maintaining(保持) and passing on family values and traditions. Today contemporary mothers and daughters also share the experience of work and technology, which may bring them even closer together.Best friends may ormay not continue to be best friends, but for better or worse; the mother and daughter relationship is permanent, even if for some unfortunate reason they aren’t speaking. Sometimes this is not an equal relationship. Daughters don’t always feel responsible for their mother’s emotional well-being. But mothers never stop being mothers, which includes frequently wanting to protect their daughters and often feeling responsible for their happiness. The mother and daughter relationship is a relationship that is not replaceable by any other. Mothers always “trump(胜过)” friends.12. What does the underlined word “preclude” in paragraph 1 probably mean?A. differ.B. benefit.C. prevent.D. change.13. What can we learn from what Marina said?A. Best friends will not spend money on her wedding.B. Best friends will not remind her of important issues in life.C. Her mother is wiser on account of her age.D. Her mother is definitely not her best friend.14. Why can a mother and a daughter build a even closer relationship today?A. Because they share advanced technology with each other.B. Because they work together to support the whole family.C. Because they experience the same values and traditions.D. Because they have common experience in life and work.15. What is the text mainly about?A. How to build a good mother and daughter relationship.B. A mother-daughter relationship is irreplaceable.C. Mothers want to be daughters’ friends.D. A daughter is a mother’s best friend.第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。

江苏省无锡市太湖高级中学 2022-2023 学年高一下学期第
二次学情调研数学试题
学校:___________姓名：___________班级：___________考号：___________
一、单选题 1．已知 (1 + i) z = i （i 是虚数单位），则| z |=
A．
1 2
B． 2 2
F
，设
uuur r AB=a
，
uuur AD
=
r b
.
(1)若
uuur EF
=
r xa
+
r yb
，求
x
，
y
的值；
(2)若
uuur AB
= 1 ， ÐBAD
=
60° ，求 cos ÐAFB .
19．在四棱锥 E - ABCD 中，底面 ABCD 是正方形， AC 与 BD 交于点 O ， EC ^ 底面
1．B
参考答案：
【分析】利用复数除法运算求得 z ，再求 z .
【详解】依题意
z
=
i 1+ i
=
i (1- i) (1+ i)(1- i)
=
1 2
+
1 2
i
，所以
z
=
æ 1 ö2 çè 2 ÷ø
+
æ çè
1 2
ö2 ÷ø
=
2. 2
故选：B.
【点睛】本小题主要考查复数除法运算，考查复数的模的运算，属于基础题.
（）
A．若 m // n ， n / /a ，则 m / /a
B．若 m ^ a ， n ^ b ，a ^ b ，则 m ^ n

2023-2024学年江苏省无锡市太湖高级中学高二（上）期中数学试卷一、单选题（共8小题，每小题5分，共40分.在每小题列出的四个选项中，选出符合题目要求的一项.） 1．直线（a +1）x +3y +3＝0与直线x +（a ﹣1）y +1＝0平行，则实数a 的值为（ ） A ．﹣2B ．12C ．2D ．2或﹣22．已知点A ，B ，C 不共线，对空间任意一点O ，若OP →=34OA →+18OB →+18OC →，则P ，A ，B ，C 四点（ ） A ．不共面 B ．共面C ．不一定共面D ．无法判断3．已知向量a →=(2√3，0，2)，向量b →=(1，0，√3)，则向量a →在向量b →上的投影向量为（ ） A ．(12，0，√32)B ．(2√3，0，2)C ．(1，0，√3)D ．(√3，0，3)4．若圆x 2+y 2+2x ﹣4y +1＝0被直线2ax ﹣by +2＝0（a ＞0，b ＞0）平分，则1a+1b的最小值为（ ） A ．14B ．9C ．4D ．195．已知平行六面体ABCD ﹣A 1B 1C 1D 1的所有棱长均为2，∠BAD ＝∠BAA 1＝∠DAA 1＝60°，M 为C 1D 1的中点，则向量AM →的模长为（ ） A ．√15B ．4C ．√17D ．√196．已知A 、B 为椭圆x 24+y 23=1上两点，O 为坐标原点，M （异于点O ）为弦AB 中点，若AB 两点连线斜率为12，则OM 两点连线斜率为（ ） A ．−23B ．−32C ．−34D ．−437．已知点P 是圆M ：（x ﹣2）2+（y ﹣2）2＝2上的动点，线段AB 是圆C ：（x +1）2+（y +1）2＝4的一条动弦，且|AB|=2√3，则|PA →+PB →|的最大值是（ ） A ．3√2B ．8√2C ．5√2D ．8√2+28．《九章算术》中，将四个面都为直角三角形的四面体称为鳖臑，在如图所示的鳖臑A ﹣BCD 中，AB ⊥平面BCD ．∠BDC ＝90°，BD ＝2AB ＝2CD ＝2，E 是BC 的中点，H 是△ABD 内的动点（含边界），且EH ∥平面ACD ，则CA →⋅EH →的取值范围是（ ）A ．[0，3]B ．[12，3]C ．[12，112]D ．[3，112]二、多选题（本题共4小题，每小题5分，共20分。

江苏省太湖高级中学2023年化学高二上期末联考试题注意事项：1．答卷前，考生务必将自己的姓名、准考证号填写在答题卡上。

2．回答选择题时，选出每小题答案后，用铅笔把答题卡上对应题目的答案标号涂黑，如需改动，用橡皮擦干净后，再选涂其它答案标号。

回答非选择题时，将答案写在答题卡上，写在本试卷上无效。

3．考试结束后，将本试卷和答题卡一并交回。

一、选择题（每题只有一个选项符合题意）1、若要检验酒精中是否含有少量水，可选用的试剂是（）A．生石灰B．金属钠C．浓硫酸D．无水硫酸铜2、某化学科研小组研究在其他条件不变时，改变某一条件对化学平衡的影响，得到如下变化规律(图中p表示压强，T 表示温度，n表示物质的量)：根据以上规律判断，下列结论正确的是()A．反应Ⅰ：ΔH>0，p2>p1B．反应Ⅱ：ΔH<0， T2>T1C．反应Ⅲ：ΔH>0，T2>T1或ΔH<0，T2<T1D．反应Ⅳ：ΔH<0，T2>T13、将纯锌片和纯铜片按图示方式插入同浓度的稀硫酸中一段时间，以下叙述正确的是（）A．两烧杯中铜片表面均无气泡产生B．甲中铜片是正极，乙中铜片是负极C．两烧杯中溶液的pH均增大D．产生气泡的速度甲比乙慢4、下列实验操作中，不用于物质分离的是A．B．C．D．5、下列物质中属于酸性氧化物的是A．CO B．SiO2C．Fe2O3D．(CH3CO)2O6、下列有机物的命名正确的是( )A．2—乙基丁烷B．2,2—二甲基丁烷C．3-甲基-2-丁烯 D．2-甲基-3-丁烯7、可逆反应A(s)＋B(g)2C(g) ΔH<0，在密闭容器中达到平衡后，改变条件，能使B的转化率提高的是A．保持温度不变，增大容器体积使压强减小B．保持恒温恒容，充入氦气C．其他条件不变时，升高温度D．保持恒温恒容，加入一定量A物质8、下图是电解饱和NaCl 溶液的实验装置，x、y 都是惰性电极，a 是饱和NaCl 溶液，同时在两边各滴入几滴酚酞试液，下列有关该实验正确的说法是A．x 电极为阳极，y 电极为阴极B．x 电极附近溶液变红色，且有刺激性气味气体产生C．若将两电极产生的气体收集起来，X电极得到的气体与Y电极得到的气体之比之比略大于1：1D．电解后，将溶液混匀，电解前后溶液的pH 未发生变化9、某物质的结构为，关于该物质的说法正确的是（）A．是苯的同系物B．1mol该物质最多可以和6mol氢气发生加成反应C．能发生加聚反应D．分子中的所有原子无法处于同一平面10、常温下，用0.1000 mol·L－1NaOH溶液滴定20.00mL0.1000 mol·L－1CH3COOH溶液。

江苏中学排名 Revised as of 23 November 2020江苏省中学排名,江苏省重点中学排名1.南京外国语学校2.南师附中3.江苏省苏州中学4.江苏省扬州中学5.南京金陵中学6.无锡市第一中学7.江苏省天一中学8.江苏省泰兴中学9.徐州市第一中学10.江苏省苏州实验中学11.江苏省南通中学12.南京市第一中学13.无锡市辅仁高级中学14.江苏省常州高级中学15.南京市中华中学16.江苏省启东中学90分以上十六所，为江苏顶级学校。

18.南通第一中学19.江苏省锡山高级中学20.盐城中学21.江苏省梅村高级中学22.江苏省梁丰高级中学23.江苏省南菁高级中学24.常州市第一中学25.江苏省溧水高级中学26.江苏省如东高级中学27.苏州市第一中学28.苏州市第十中学29.江苏省江阴高级中学30.南京市第十三中学31.镇江市第一中学32.徐州市第三中学33.江苏省前黄高级中学34.苏州中学园区35.苏州新区第一中学36.江苏教育学院附属中学37.江苏省淮阴中学38.南京市第九中学39.江苏省常熟中学40.江苏省姜堰中学41.江苏省海安高级中学42.江苏省木渎中学43.江苏省通州高级中学45.江苏省昆山中学46.江苏省如皋中学47.江苏省宜兴高级中学48.江苏省镇江中学49.江苏省怀仁高级中学50.江苏省黄桥中学51.南通市第三中学52.南京市江宁高级中学53.江苏省泰州中学80分以上53所。

54.姜堰市第二中学55.江苏省滨海中学56.江苏省华罗庚中学57.苏州市第六中学58.江苏省清江中学59.江苏省郑集高级中学60.江苏省丹阳高级中学61.江苏省邗江中学62.江苏省武进高级中学63.江苏省南通市如东栟茶中学64.盐城第一中学65.江苏省扬中高级中学66.江苏省太湖高级中学67.江苏省建湖高级中学68.江阴市长泾中学69.江苏省侯集中学70.张家港高级中学71.江苏省奔牛高级中学72.南京航空航天大学附属中学70分以上72所学校73.江苏省羊尖高级中学74.包场中学75.江阴市第一中学76.丰县中学77.江苏省太仓高级中学78.苏州第三中学79.东山高级中学80.苏大附中81.南京市第五中学82.江苏省东台中学83.苏州新区二中84.太仓市沙溪高级中学85.江阴市青阳中学86.通州市西亭中学 87.江苏省沭阳高级中学60分以上级别87所，属于优秀级学校88.江苏省高淳高级中学89.江苏省金坛中学90.震泽中学91.江苏省淮安中学92.宜兴官林中学93.江阴市华士高级中学94.江苏省响水中学95.江苏省白蒲高级中学96.涟水县中学97.徐州高级中学98.江苏省泗阳中学99.江苏省溧阳高级中学100.连云港板浦高级中学。

率先在全省实行全面小班化教育，已成为满足学生个性发展、特长发展、
多元发展的优质特色高中。尤其是艺术教育，一直是学校自身发展的亮 点和特色，在无锡市艺术教育领域中起着引领作用，在江苏省基础教育 领域中也彰显出特有的发展优势。
4
（一）学校基本情况
（二）师资情况
我校现专设艺教处，下
辖美术、音乐两个教研组，
业生金湉是无锡籍旅法女高音歌唱家。周文君、郑晨、须雨婷、童行等多位 同学先后在中国美院、四川美院专业考试中荣获第一名。董达元、管宇峥、 顾意顺、郑晨、莫蕾分别是03、04、05、07年江苏省美术统考省、市状元； 04年陆聚佳考取上海音乐学院，09年金湉以中国地区唯一全免学费的成绩
考取法国图卢兹音乐学院。
的河流、蓊郁的树木、玲珑的假山、翼然的红亭、苍翠的松柏、碧绿的草
坪、宁静的小径。校园的每一角每一处无不融入艺术的氛围，成为学生获 取审美意念的最直接的观照。
9
三、艺术教育课程开发
（一）教育理念
（二）艺术课程
（三）艺普互通
（四）校本开发
学校围绕“以美启智、以美启真、以美储德、以美怡情”的艺术教育理 念，培养学生感悟美、欣赏美、创造美的意识，促进广大学生树立正确的审 美观念，健康的审美情趣，提高创造美的能力。学校创新艺术教育，以艺术 班美育教学为主体，带动全校美育教学。教学是科学也是艺术，如何把两者
年级
高一 高二上
周课时
6课时 6课时
上课周数
38周 19周 19周 20周
课时总和
228课时 114课时
备注 乐 理 、视 唱 练耳 、 主修 专业、舞蹈、声乐选修
乐 理 、视 唱 练耳 、 主修 专业、舞蹈、声乐选修
高二下 12课时 高三上 24课时