2016江西外语外贸职业学院数学单招测试题(附答案解析)
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单独招生统一考试英语试卷(满分120分,考试时间90分钟)一、选择题:(本题共20小题,每小题3分,共60分)1.This is the chance he needs to make a________start.A.curiousB.patientC.freshD.natural2.People in poor areas have improved their lives by selling goods________ online.A.aliveB.liveC.livingD.lively3.—Mr.Green,please feel________to let us know if you aren’t satisfied with our service.—OK,I will.It has been good so far.A.realB.readyC.freeD.fresh4.—I wish I could move away from the noisy city.—Really?But I think the life in the countryside may be. A.comfortableB.boringC.peacefulD.exciting5.David promised to help me with my physics last Sunday.But to my great disappointment,he never appeared that day.What does the word “disappointment”mean in the sentence?A.The feeling of being nervousB.The feeling of being lonelyC.The feeling of being unhappyD.The feeling of being worried6.Because of the war,love and happiness were totally________from little Tom’s childhood.A.separateB.absentC.extraD.blind7.—It is a________choice to decide whether take on a new challenge or remain the same.—Yeah,I just have difficulty making the decision.A.simpleB.straightC.doubleD.typical8.—Mary can get good marks in all her subjects,but she never shows off.—I agree.She is________.A.generousB.modestC.patientD.curious9.—It will be________.—That’s great!The whole world will be white.A.sunnyB.cloudyC.snowyD.foggy10.You’ve watched the boring soap opera thousands of times!Why don’t you go outside and find something________doing?A.usefulB.cheerfulC.enjoyableD.worth11.Hurry up,____you will miss the first train.A.andB.thenC.butD.or12.The shirt doesn't fit me.it's.small for me._____A.too muchB.much tooC.too manyD.many too13.The boss made them.___ten hours day.A.workedB.workingC.workD.to work14.Jenny nearly missed the flight_____doing too much shopping.A.as a result ofB.on top ofC.in front ofD.in need of15.What I need is_____book that contains_____ABC of oil painting.A.a;不填B.the;不填C.the;anD.a;the16.____did it take him to repair the computer?()A boutB.How oftenC.How longD.How far17.When he got to the station,the train___.()A.was leftB.had leftC.has leftD.would left18.in exams the___you are,the____mistakes you will make.()A.more carefully esB.more carefully fewerC.most carefully mostD.more carefully more19.i don't think he's ever been to the monkey island,___?()A.isn't heB.don't heC.is itD.has he20.1'd like to know____.()A.when will he give back the tapeB.whether has he received higher education.C.that he has been busyD.whether she will join in our English education二、短文改错:(共5小题,每小题3分,满分15分下面短文中划线部分是错误的,请改正,并将正确答案写在右边相应题号后的横线上。
考单招——上高职单招网【内容来自于相关网站和学校提供】(考试时间:90分钟满分:100分)选择题(每题4分,共100分):第1题:What should you write in the covering letter?A. You state the position you are applying for.B. You tell the recruiter where you gotthe job information.C. You demonstrate the reason why you think you are fit for the position.D. All the above.【正确答案】 D讲解:【解析】求职信的内容在第三段中很详细。
包含ABC三项,故选 D第2题:下列各句中,有语病的一项是()A.教育专家指出,父母一般不要让未成年的孩子过早地远离自己,否则,孩子的心理、性格可能会受到不良影响。
B.同学们自发组织了志愿者团队去校外服务,几年中,他们共走访了二十多个社区、近四百户家庭和三千多公里路程。
C。
认识沙尘暴的特点,了解沙尘暴的成因,有助于更好地治理沙尘暴,减少沙尘暴造成的损失。
D.正是因为成千上万人的不断努力,整个社会才充满了活力与朝气,呈现出一派欣欣向荣的景象。
【正确答案】 C讲解: A项语意重复,“否则”与“过早地离开”保留其一。
B中走访后面不能加路程。
D中社会不能呈现欣欣向荣的景象。
第3题:A. try B. have C. think D. wait【正确答案】 A讲解:try to do sth 表示努力做某事,故选 A第4题:下列有关文学常识的表述,不正确的一组是()考单招——上高职单招网【内容来自于相关网站和学校提供】(考试时间:90分钟满分:100分)选择题(每题4分,共100分):第1题:What should you write in the covering letter?A. You state the position you are applying for.B. You tell the recruiter where you gotthe job information.C. You demonstrate the reason why you think you are fit for the position.D. All the above.【正确答案】 D讲解:【解析】求职信的内容在第三段中很详细。
考单招——上高职单招网【内容来自于相关网站和学校提供】(考试时间:90分钟满分:100分)选择题(每题4分,共100分):第1题:What should you write in the covering letter?A. You state the position you are applying for.B. You tell the recruiter where you got the job information.C. You demonstrate the reason why you think you are fit for the position.D. All the above.【正确答案】D讲解:【解析】求职信的内容在第三段中很详细。
包含ABC三项,故选D第2题:下列各句中,有语病的一项是()A.教育专家指出,父母一般不要让未成年的孩子过早地远离自己,否则,孩子的心理、性格可能会受到不良影响。
B.同学们自发组织了志愿者团队去校外服务,几年中,他们共走访了二十多个社区、近四百户家庭和三千多公里路程。
C。
认识沙尘暴的特点,了解沙尘暴的成因,有助于更好地治理沙尘暴,减少沙尘暴造成的损失。
D.正是因为成千上万人的不断努力,整个社会才充满了活力与朝气,呈现出一派欣欣向荣的景象。
【正确答案】C讲解: A项语意重复,“否则”与“过早地离开”保留其一。
B中走访后面不能加路程。
D中社会不能呈现欣欣向荣的景象。
第3题:A. try B. have C. think D. wait【正确答案】A讲解:try to do sth 表示努力做某事,故选A第4题:下列有关文学常识的表述,不正确的一组是()考单招——上高职单招网A.陶潜的《归园田居》、李白的《蜀道难》、杜甫的《兵车行》、李贺的《李凭箜篌引》都属于古体诗。
B.元代王实甫的《西厢记》、明代孔尚任的《桃花扇》、清代汤显祖的《牡丹亭》都是我国古代著名的戏曲作品。
2016年高职高考数学答案篇一:2016年高职数学模拟试卷高职高考班《数学》模拟试题班别学号姓名一、选择题:(本大题共15小题,每小题5分,共75分。
请把每题唯一的正确答案填入表格内)1、设集合M?{xx?1?1},集合N?{1,2,3,4},则集合M?N?()A. {1,2} B. {2,3} C. {3,4} D. {2,3,4}2、x?2是x?4的()A. 充分条件B. 必要非充分条件C. 充要条件D. 既非充分条件又非必要条件3、函数y?x?1在区间(?1,??)上是()A. 奇函数B. 偶函数C. 增函数D. 减函数4、不等式1?x0的解集为()1?xA. (??,?1)?[1,??)B. [?1,1]C. (??,?1]?[1,??)D. [?1,1) 5、已知tan?cos??0,且tan?sin??0,则角?是()A.第一象限角B. 第二象限角C. 第三象限角D. 第四象限角6、函数f(x)?2x?8?x?2x?152的定义域是()A. (?3,5)B. (??,?3)?(5,??)C. [?3,5]D. (?3,4)?(4,5)2x1,x17、设函数f(x)??2,则f[f(?3)]?()?x?2,x?1A. ?5 B. 15 C. ?11 D. 7 8、已知向量?(1,2)与向量?(4,y)垂直,则y?()A. ?8 B. 8C. 2 D. ?2 9、已知两条直线y?ax?2和y?(a?2)x?1互相垂直,则a?()A. 1 B.2 C. 0D. ?110、函数f(x)??x2?4x?7在区间[?3,4]上的最大值是()A. ?25B. 19C. 11D. 10111、等比数列{an}中,a1?,a4?3,则该数列的前5项之积为()9A. ?1B. 3C. 1D. ?312、已知数列{an}中,a1?3,an?an?1?3则a10?()A. 30B. 27C. 33D. 36x?13、函数f(x)?3sin(?)(x?R)的最小正周期是()46A. 2?B. 4?C. 8?D. ? 14、中心在原点,焦点在y轴上,离心率为,的椭圆标准方程为()2x2y2x2x2y2y222y1 C. ?1 ??1 B. ??1 D. x?A.44622615、在10件产品中有4件次品,现从中任取3件产品,至少有一件次品的概率是() A.2531 B.C.D.5656二、填空题:(每小题5分,共5×5=25分。
江西单独考试招生考试数学(满分120分,考试时间90分钟)一、选择题:(本题共10小题,每小题5分,共50分)1.已知命题:p “[]0,1,x x a e ∀∈≥”,命题:q “2,40x R x x a ∃∈-+=”,若命题,p q 均是真命题,则实数的取值范围是()A.[4,)+∞B.[1,4]C.[,4]e D.(,1]-∞2.已知πcos sin 6αα⎛⎫-+= ⎪⎝⎭7πsin 6α⎛⎫+ ⎪⎝⎭的值是()A.25-B.25C.5-D.53.在ABC ∆中,1AB =,2BC =,为AC 的中点,则()BE BA BC ∙-=()A.3B.32C.-3D.32-4.用一个平面去截正方体,所得的截面不可能是()(A)六边形(B)菱形(C)梯形(D)直角三角形5、化简3a a 的结果是()A.a B.12a C.41aD.83a 6.“032>x ”是“0<x ”成立的()A.充分不必要条件B.必要不充分条件C.充要条件D.既非充分也非必要条件7.下列不等式(组)解集为{}0x x <的是()A.2x -3<3x-3B.20231x x ⎧⎨⎩-<->C.2x -2x>0D.12x -<8.已知数列}{n a 的各项均为正数,其前项和为n S ,若}{log 2n a 是公差为-1的等差数列,且,836=S则1a 等于()A.214B.316C.218D.31129.已知函数,log 31()(2xx x f -=实数c b a ,,满足),,,0(0)()()(c b a c f b f a f <<⋅⋅若实数0x 为方程0)(=x f 的一个解,那么下列不等式中,不可能成立的是()A.0x <B.0x >bC.0x <D.0x >10.已知向量(2,1)=-a ,(0,3)=b ,则2-=a b ()A.(2,7)- C.7二、填空题:(共20分.)1.不等式06||2<--x x (R x ∈)的解集是___________________;2.已知⎩⎨⎧<-≥=0,10,1)(x x x f ,则不等式2)(≤+x x xf 的解集是_________________;3.若不等式2229x x a x x +≤≤+在]2,0(∈x 上恒成立,则a 的取值范围是___________;4、计算:a·a²=_____.三、解答题:(共3小题,共50分.解答应写出文字说明、证明过程或演算步骤.)1.如图1,矩形ABCD 中,AB=12,AD=6,E、F 分别为CD、AB 边上的点,且DE=3,BF=4,将△BCE 沿BE 折起至△PBE 位置(如图2所示),连结AP、PF,其中PF=2.(1)求证:PF⊥平面ABED;(2)求点A 到平面PBE 的距离. 2.已知椭圆C:的离心率为,且过点A(2,1).(Ⅰ)求椭圆C 的方程;(Ⅱ)若P,Q 是椭圆C 上的两个动点,且使∠PAQ 的角平分线总垂直于x 轴,试判断直线PQ 的斜率是否为定值?若是,求出该值;若不是,说明理由.3.已知函数f(x)=x 2﹣(a﹣2)x﹣alnx(a∈R).(Ⅰ)求函数y=f(x)的单调区间;(Ⅱ)当a=1时,证明:对任意的x>0,f(x)+e x>x 2+x+2.参考答案:一、选择题1-5题答案:ADBDB 6-10题答案:AADCB 二、填空题1.)3,3(-;2.]1,(-∞;3.⎥⎦⎤⎢⎣⎡1,132;4、【答案】【解析】解:根据同底数幂的乘法法则,同底数幂相乘,底数不变,指数相加,即计算即可.本题主要考查同底数幂的乘法的性质,熟练掌握性质是解题的关键,三、解答题1.如图1,矩形ABCD 中,AB=12,AD=6,E、F 分别为CD、AB 边上的点,且DE=3,BF=4,将△BCE 沿BE 折起至△PBE 位置(如图2所示),连结AP、PF,其中PF=2.(1)求证:PF⊥平面ABED;(2)求点A到平面PBE的距离.【解答】解:(1)连结EF,由翻折不变性可知,PB=BC=6,PE=CE=9,在△PBF中,PF2+BF2=20+16=36=PB2,所以PF⊥BF…(2分)在图1中,利用勾股定理,得EF==,在△PEF中,EF2+PF2=61+20=81=PE2,∴PF⊥EF…(4分)又∵BF∩EF=F,BF⊂平面ABED,EF⊂平面ABED,∴PF⊥平面ABED.…(6分)(2)解:由(1)知PF⊥平面ABED,∴PF为三棱锥P﹣ABE的高.…(8分)设点A到平面PBE的距离为h,由等体积法得VA﹣PBE =VP﹣ABE,…(10分)即∴h=,即点A到平面PBE的距离为.…(14分)2.已知椭圆C:的离心率为,且过点A(2,1).(Ⅰ)求椭圆C的方程;(Ⅱ)若P,Q是椭圆C上的两个动点,且使∠PAQ的角平分线总垂直于x轴,试判断直线PQ 的斜率是否为定值?若是,求出该值;若不是,说明理由.【解答】解:(Ⅰ)因为椭圆C的离心率为,且过点A(2,1),所以,.…因为a2=b2+c2,解得a2=8,b2=2,…(3分)所以椭圆C的方程为.…(Ⅱ)解法一:因为∠PAQ的角平分线总垂直于x轴,所以PA与AQ所在直线关于直线x=2对称.设直线PA的斜率为k,则直线AQ的斜率为﹣k.…(5分)所以直线PA的方程为y﹣1=k(x﹣2),直线AQ的方程为y﹣1=﹣k(x﹣2).设点P(xP ,yP),Q(xQ,yQ),由,消去y,得(1+4k2)x2﹣(16k2﹣8k)x+16k2﹣16k﹣4=0.①因为点A(2,1)在椭圆C上,所以x=2是方程①的一个根,则,…所以.…同理.…所以.…又.…所以直线PQ的斜率为.…所以直线PQ的斜率为定值,该值为.…解法二:设点P(x1,y1),Q(x2,y2),则直线PA的斜率,直线QA的斜率.因为∠PAQ的角平分线总垂直于x轴,所以PA与AQ所在直线关于直线x=2对称.所以kPA =﹣kQA,即,①…因为点P(x1,y1),Q(x2,y2)在椭圆C上,所以,②.③由②得,得,④…同理由③得,⑤…(由①④⑤得,化简得x1y2+x2y1+(x1+x2)+2(y1+y2)+4=0,⑥…由①得x1y2+x2y1﹣(x1+x2)﹣2(y1+y2)+4=0,⑦…⑥﹣⑦得x1+x2=﹣2(y1+y2).…(10分)②﹣③得,得.…所以直线PQ的斜率为为定值.…解法三:设直线PQ的方程为y=kx+b,点P(x1,y1),Q(x2,y2),则y1=kx1+b,y2=kx2+b,直线PA的斜率,直线QA的斜率.…因为∠PAQ的角平分线总垂直于x轴,所以PA与AQ所在直线关于直线x=2对称.所以kPA =﹣kQA,即=,…(6分)化简得x1y2+x2y1﹣(x1+x2)﹣2(y1+y2)+4=0.把y1=kx1+b,y2=kx2+b代入上式,并化简得2kx1x2+(b﹣1﹣2k)(x1+x2)﹣4b+4=0.(*)…(7分)由,消去y得(4k2+1)x2+8kbx+4b2﹣8=0,(**)则,…(8分)代入(*)得,整理得(2k﹣1)(b+2k﹣1)=0,所以或b=1﹣2k.…(10分)若b=1﹣2k,可得方程(**)的一个根为2,不合题意若时,合题意.所以直线PQ的斜率为定值,该值为3.已知函数f(x)=x2﹣(a﹣2)x﹣alnx(a∈R).(Ⅰ)求函数y=f(x)的单调区间;(Ⅱ)当a=1时,证明:对任意的x>0,f(x)+e x>x2+x+2.【解答】解:(Ⅰ)函数f(x)的定义域是(0,+∞),f′(x)=2x﹣(a﹣2)﹣=…(2分)当a≤0时,f′(x)>0对任意x∈(0,+∞)恒成立,所以,函数f(x)在区间(0,+∞)单调递增;…(4分)当a>0时,由f′(x)>0得x>,由f′(x)<0,得0<x<,所以,函数在区间(,+∞)上单调递增,在区间(0,)上单调递减;(Ⅱ)当a=1时,f(x)=x2+x﹣lnx,要证明f(x)+e x>x2+x+2,只需证明e x﹣lnx﹣2>0,设g(x)=e x﹣lnx﹣2,则问题转化为证明对任意的x>0,g(x)>0,令g′(x)=e x﹣=0,得e x=,容易知道该方程有唯一解,不妨设为x0,则x满足e x0=,当x变化时,g′(x)和g(x)变化情况如下表x(0,x0)x(x,∞)g′(x)﹣0+g(x)递减递增g(x)min =g(x)=e x0﹣lnx﹣2=+x﹣2,因为x0>0,且x≠1,所以g(x)min>2﹣2=0,因此不等式得证.。
江西单独考试招生考试数学(满分120分,考试时间90分钟)一、选择题:(本题共10小题,每小题5分,共50分)1.函数sin 2y x =的图象向左平移4π个单位再向上平移1个单位,所得图象的函数解析式是()A.cos 2y x =B.22cos y x=C.)42sin(1π++=x y D.22sin y x=2.已知*112,1,()2nn n a a a n N a +==∈+,则n a 的通项为()A.321n a n =+B.21n a n =+C.11n a n =+D.221n a n =+3.两非零向量a 和b ,若a b a b ==-,则a 与a b + 的夹角为()A.30︒B.45︒C.60︒D.90︒4.等差数列{}n a 的前项和为n S ,当1a ,d 变化时,若2811a a a ++是一个定值,那么下列各数中也为定值的是()A.13S B.15S C.20S D.8S 5、方程43)22(log =x 的解为()A .4=x B .2=x C .2=x D .21=x 6.在ABC ∆中,为BC 中点,,,a b c 成等差数列且38,cos ,5a c B a c +==>,则AD BC ⋅ 等于()A.252B.252-C.72D.72-7.抛掷一枚骰子,落地后面朝上的点数为偶数的概率等于()A.0.5B.0.6C.0.7D.0.88.已知函数,1)1ln()(-+-=x x x f 则()A.没有零点B.有唯一零点C.有两个零点,,21x x 并且21,0121<<<<-x x D.有两个零点,,21x x 并且3121<+<x x 9.定义在R 上的函数)(x f 满足),(21)5(,1)1()(,0)0(x f x f x f x f f ==-+=且当1021≤<≤x x 时,)()(21x f x f ≤,则=)20081(f ()A.21B.161C.321D.64110.函数2sin cos 2y x x =+的最小值和最小正周期分别为()A.1和2πB.0和2πC.1和πD.0和π二、填空题:(共20分)1.函数()()0010cos 520sin 3-++=x x y 的最大值是____________;2.若224sin 2cos -=⎪⎭⎫ ⎝⎛-παα,则ααsin cos +的值为___________;3.若()51cos =+βα,()53cos =-βα,则=⋅βαtan tan ___________;三、解答题:(本题共3小题,共50分.解答应写出文字说明、证明过程或演算步骤.)1.在如图所示的圆台中,AB,CD 分别是下底面圆O,上底面圆O′的直径,满足AB⊥CD,又DE 为圆台的一条母线,且与底面ABE 成角.(Ⅰ)若面BCD 与面ABE 的交线为l,证明:l∥面CDE;(Ⅱ)若AB=2CD,求平面BCD 的与平面ABE所成锐二面角的余弦值.2.如图为2017届淮北师范大学数学与应用数学专业N 名毕业生的综合测评成绩(百分制)分布直方图,已知80~90分数段的学员数为21人.(Ⅰ)求该专业毕业总人数N 和90~95分数段内的人数n;(Ⅱ)现欲将90~95分数段内的n 名毕业生随机的分配往A、B、C 三所学校,若每所学校至少分配两名毕业生,且甲乙两人必须进同一所学校,共有多少种不同的分配方法?(Ⅲ)若90~95分数段内的这n 名毕业生中恰有两女生,设随机变量ξ表示n 名毕业生中分配往乙学校的两名学生中女生的人数,求ξ的分布列和数学期望.3.已知椭圆C:+=1(a>b>0),其左右焦点为F1,F 2,过F 1直线l:x+my+=0与椭圆C交于A,B 两点,且椭圆离心率e=;(Ⅰ)求椭圆C 的方程;(Ⅱ)若椭圆存在点M,使得2=+,求直线l 的方程.参考答案:一、选择题1-5题答案:BAACA 6-10题答案:CACAD 二、填空题1.7;1;2.21;3.2三、解答题1.在如图所示的圆台中,AB,CD分别是下底面圆O,上底面圆O′的直径,满足AB⊥CD,又DE为圆台的一条母线,且与底面ABE成角.(Ⅰ)若面BCD与面ABE的交线为l,证明:l∥面CDE;(Ⅱ)若AB=2CD,求平面BCD的与平面ABE所成锐二面角的余弦值.【解答】(Ⅰ)证明:如图,在圆台OO′中,∵CD⊂圆O′,∴CD∥平面ABE,∵面BCD∩面ABE=l,∴l∥CD,∵CD⊂平面CDE,l⊄平面CDE,∴l∥面CDE;(Ⅱ)解:连接OO′、BO′、OE,则CD∥OE,由AB⊥CD,得AB⊥OE,又O′B在底面的射影为OB,由三垂线定理知:O′B⊥OE,∴O′B⊥CD,∴∠O′BO就是求面BCD与底面ABE所成二面角的平面角.设AB=4,由母线与底面成角,可得OE=2O′D=2,DE=2,OB=2,OO′=,∴cos∠O′BO=.2.如图为2017届淮北师范大学数学与应用数学专业N名毕业生的综合测评成绩(百分制)分布直方图,已知80~90分数段的学员数为21人.(Ⅰ)求该专业毕业总人数N和90~95分数段内的人数n;(Ⅱ)现欲将90~95分数段内的n名毕业生随机的分配往A、B、C三所学校,若每所学校至少分配两名毕业生,且甲乙两人必须进同一所学校,共有多少种不同的分配方法?(Ⅲ)若90~95分数段内的这n名毕业生中恰有两女生,设随机变量ξ表示n名毕业生中分配往乙学校的两名学生中女生的人数,求ξ的分布列和数学期望.【解答】解:(Ⅰ)80~90分数段的毕业生的频率为:=(0.04+0.03)×5=0.35,p1此分数段的学员总数为21人,∴毕业生的总人数N为N==60,90~95分数段内的人数频率为:=1﹣(0.01+0.04+0.05+0.04+0.03+0.01)×5=0.1,p2∴90~95分数段内的人数n=60×0.1=6.(Ⅱ)将90~95分数段内的6名毕业生随机的分配往A、B、C三所学校,每所学校至少分配两名毕业生,且甲乙两人必须进同一所学校,共有:=18不同的分配方法.(Ⅲ)ξ所有可能取值为0,1,2,P(ξ=0)==,P(ξ=1)==,P(ξ=2)==,所以ξ的分布列为:ξ012P所以随机变量ξ数学期望为E(ξ)==.3.已知椭圆C:+=1(a>b>0),其左右焦点为F1,F 2,过F 1直线l:x+my+=0与椭圆C交于A,B 两点,且椭圆离心率e=;(Ⅰ)求椭圆C 的方程;(Ⅱ)若椭圆存在点M,使得2=+,求直线l 的方程.【解答】解:(Ⅰ)过F 1直线l:x+my+=0,令y=0,解得x=﹣,∴c=,∵e==,∴a=2,∴b 2=a 2﹣c 2=4﹣3=1,∴椭圆C 的方程为+y 2=1;(Ⅱ)设A(x 1,y 1),B(x 2,y 2),M(x 3,y 3),由2=+,得:x3=x 1+x 2,y 3=y 1+y 2代入椭圆方程可得:(x 1+x 2)2+(y 1+y 2)2﹣1=0,∴(x 12+y 12)+(x 22+y 22)+(x 1x 2+4y 1y 2)=1,∴x 1x 2+4y 1y 2=0联立方程消x 可得(m 2+4)y 2+2my﹣1=0,∴y 1+y 2=,y 1y 2=,∴x 1x 2+4y 1y 2=(my 1+)(my 2+)+4y 1y 2=(m 2+4)4y 1y 2+m(y 1+y 2)+3=0,即m 2=2,解得m=±所求直线l 的方程:x±y+=0.。
2016江西外语外贸职业学院单招测试题(含答案解析)考单招——上高职单招网(考试时间:90分钟满分:100分)选择题(每题4分,共100分):第1题:下列加下划线字的读音正确的一项是()A.胡髭(zī)媲美(bì)名讳(huì)清荇(xìng)B.炽热(chì)怵目(chù)装殓(liǎn)袅娜(nuó)C.果蠃(luǒ)滟滪(yù)啁啾(jiū)戕害(qiāng)D.漫溯(shuò)嘉猷(yóu)寥阔(liáo)眩惑(xuàn)【正确答案】C讲解:本题考查字音,偏重易错字词的读音。
A选项媲美pì,B装殓liàn,D漫溯sù是经常考查的词语,注意积累。
第2题:A.but B.so C.or D.while【正确答案】B讲解:任何汤都需要盐和胡椒,听了这话,孩子们就回去拿了。
前后有因果关系。
第3题:下列不符合文意的一项是()A.位置可能决定个别恐鳄基本以海龟为食的习惯。
B.大型鳄鱼更容易灭绝的罪魁祸首是空间的限制。
C.原产北美的恐鳄说明大型鳄鱼出现在不同地方和时期。
D.出现大型鳄龟生存的合适条件通常不会持续太久。
【正确答案】D讲解:A项对应文字在原文第九段,与题干要求符合。
B项对应文字在原文第十一段,与题干要求符合。
C项对应文字在原文第十段,与题干要求符合。
D项对应文字在原文第十一段,忽略了关键词“似乎偶尔”,犯有混淆或然与必然的错误,不符合原意。
第4题:—What would you like to do?—I want to ____________(申请)the position of sales manager.A.search forB.apply forC.require forD.look for考单招——上高职单招网【正确答案】B讲解:A.search for寻找B.apply for 申请C.require for需求D.look for寻找第5题:Smoking is _______ the school rules.A. inB. toC. againstD. with【正确答案】C讲解:解析:be against 违抗,反对。
单独招生统一考试英语试卷(满分120分,考试时间90分钟)一、选择题:(本题共20小题,每小题3分,共60分)1.If there were no subjunctive mood,English___much easier.A.will beB.would have beenC.could have beenD.would be2.The guard at the gate insisted that everybody____the rules.A.obeysB.obeyC.will obeyD.would obey3.If she had worked harder,she____.A.would succeedB.had succeededC.should succeedD.would have succeeded4.If we had followed his plan,we could have done the work better with ____money and____people.A.little;fewerB.fewer;lessC.less;fewerD.less;few5.The rice____if you had been more careful.A.would not be burningB.would not burnC.would not have been burnD.would not burn6.I insist that a doctor____immediately.A.has been sent forB.sends forC.will be sent forD.be sent for7.I wish I____you yesterday.A.seenB.did seeC.had seenD.were to see8.If my lawyer____here last Saturday,he____me from going.A.had been;would have preventedB.had been;would preventC.were;would preventD.were;would have prevented9.Without electricity human life____quite different today.A.isB.will beC.wouldn’t beD.won’t be10.-----We could have walked to the station;it was so near-----Yes.A taxi_____at all necessary.A.wasn’tB.hadn’t beenC.wouldn’t beD.won’t be11.-Excuse me,I am looking for a copy machine.()Go upstairs and it's in the room______your left.A、at isB、fromC、in andD、on12.I told Mary that you'd be late_____she wouldn't start worrying.()A、so thatB、becauseC、even ifD、unless13.We thought there must be something_________because we hadn't heard from you for quite a long time.()A、rightB、wrongC、good isD、bad14.She'd lived in London and Manchester,but she liked______and moved to Cambridge.A.bothB.neitherC.noneD.either15.Grandma pointed to the hospital and said,"That's______I was born."A.whenB.howC.whyD.where16.Would you please tell me the price of___handbag you are carrying?If it’s reasonable,I plan to buy______,too.()A、/,itB、the,oneC、a,itD、/,one17.---1am going to take you to Shanghai Disneyland this summer holiday, Bob.()---Is it a____?Don’t disappoint me,I hope.A、requestB、solutionC、replyD、Promise18.___.the course she preferred a bit hard for her,she decided to move to()a lower level.A、FindingB、FoundC、To findD、Find is19.Before you select a book,you'd better the first few pages to() know whether it is it too easy or too difficult for you.A、look outB、look upC、look forD、look through20、______makes Mr.Mark ley anxious is.fewer and fewer customers stepinto his store.And shopping online is getting increasingly popular in recent years.()A、What,whyB、What,thatC、That,thatD、It,what二、填空题:(共30分)There was once a lonely girl who wanted love very much.One day__1____she was walking in the forests,she found two__2____birds.She took them ___3___and put them in a small cage.She was___4___to have two friends. She looked after them with love and the birds grew___5____.One day the girl___6__to leave the door of the cage open.The larger and stronger of the__7___flew out of the cage.The girl was___8___that it would fly away.She__9___it quickly.She felt glad that she caught the bird before it could__10___away.Suddenly she couldn’t hear a__11____ from the bird When she opened her hand,the bird was___12____dear Her love killed the bird!Then she noticed the other bird jumping up and down __13____the cage.She could feel its great need for___14_____.It wanted to fly into the clear,blue sky.So she lifted it from the cage and let it fly away____15____.The bird circled once,twice and three times.The girl___16__as the bird flew.She didn’t care about___17___the bird any more.She wanted it to be happy.Suddenly the bird flew___18____andlanded softly on her shoulder.It sang the sweetest song she had ever ___19___.The fastest way to lose love is to hold on it too hard and the best way to keep love is to give it___20____.()1.A、while B、during C、before D、after()2.A、dead B、dying C、living D、alive()3.A、on B、out C、up D、home()4.A、worried B、quick C、happy D、sad()5.A、heavier B、strong C、bigger D、weak()6.A、happened B、started C、stopped D、wanted()7.A、two B、three C、four D、five()8.A、surprised B、shocked C、afraid D、wondering ()9.A、held B、caught C、put D、killed()10.A、walk B、jump C、run D、fly()11.A、sound B、voice C、word D、cry()12.A、still B、already C、yet D、just ()13.A、outside B、inside C、against D、across ()14.A、freedom B、water C、food D、air()15.A、sad B、happy C、sadly D、happily ()16.A、cried B、watched C、ran D、walked ()17.A、losing B、catching C、keeping D、feeding ()18.A、farther B、closer C、slower D、quicker()19.A、sung B、written C、heard D、learned ()20.A、care B、cage C、wings D、help三、阅读理解:(共20分)Joe and Helen Mills had two small children.One was six and the other four. They always resisted going to bed,and Helen was always complaining(抱怨)about this and asking Joe for help.But as he did not come home until after they had gone,to bed during the week,he was unable to help except at weekends.Joe considered himself a good singer,but really his voice was not at all musical.However,he decided that,if he sang to the children when they went to bed,it would help them to relax,and they would soon go to sleep.He did this every Saturday and Sunday night until he heard his small son whispered to his younger sister,“If you pretend that you’re asleep, he stops.”1.The children always resisted going to bed,which.A.made Helen suffer a lotB.satisfied their motherC.Helen was not satisfied withD.gave Helen much trouble2.The husband couldn’t help the wife to look after the children.A.because he returned from work too lateB.since his voice sounded like a singer’sC.except on Saturday and SundayD.for he did not come home until after the children had gone to bed weekends3.Joe worked.A.all the week including Saturday and SundayB.during the week including the weekendsC.every day but Saturday and SundayD.every week except on Sunday4.Which of the following conclusions can we draw from the above story?A.Joe’s song did help the children to relax.B.With Joe’s help,the children went to sleep.C.The wife must be thankful to her husband for the great help.D.The children were so tired of their father’s voice that they pretended to be asleep.5.This joke tells about.A.Joe and HelenB.Helen’s troubleC.Joe’s fooleryD.the bright idea of the two small children四、书面表达:(满分10分)请以"绝不放弃"为话题,写一篇不少于50词的文章,立意自定,文体自选,标题自拟,所写内容必须在话题范围之内.要求选好角度,确定立意,明确文体,自拟标题;不要套作,不得抄袭.参考答案:一、选择题:1-5:BDBCC6-10:DCADA11-15:DABBD16-20:BDADB二、填空题:1.A2.B3.D4.C5.B6.A7.A8.C9.B10. D11.A12.B13.B14.A15.D16.B17.A18.B19. C20.A三、阅读理解:1C2C3C4D5C江西单独考试招生文化考试语文试题卷(满分150分,考试时间120分钟)一、选择题:(本题共20小题,每小题3分,共60分)1、下列词语中加点的字的读音完全相同的一项是A、儒.腐嗫嚅.濡.染蠕.动妇孺.B、婵.娟禅.让蝉.联惮.烦禅.杖C、绯.红斐.然扉.页菲.薄翡.翠D、噪.音燥.热腥臊.躁.动害臊.2、下列词语中字形完全正确的一项是A、废驰博闻强识狙击珠联璧合B、翔实貌合神离宣泄轻歌慢舞C、攀援张皇失措撕杀见贤思齐D、端详猝不及防泄露饱经沧桑3、依次填入下列各句横线处的词语,恰当的一项是(1)契诃夫这篇小说所表现的思想是相当复杂的:既嘲笑了当时的所谓“上流社会”,也了一些虚无思想。
考单招——上高职单招网 一、选择题:本大题共10小题,每小题5分,共50分。
在每小题给出的四个选项中,只有一个是符合题目要求的。
(1)已知全集{}11,7,5,3,2=I ,{}7,5,2-=a A ,{}11,5=A C I ,则a 的值为( )A .2B .8C .2或8D .2-或8(2)设)(x f =⎪⎩⎪⎨⎧〈+≥--11112|2|2x x x x 则=)]21([f f ( )A .21 B .134 C .59- D .4125(3)下列各组函数中,表示同一函数的是( )A .55x y =与2x y =B .x y =与 33x y =C .1)3)(1(-+-=x x x y 与3+=x y D .1=y 与0x y =(4) 若x x f 2)(=的反函数为)(1x f -,且4)()(11=+--b fa f,则ba 11+的最小值是( ).A .1B .21 C .31 D .41 (5)为确保信息安全,信息需加密传输,发送方由明文→密文(加密),接收方由密文→明文(解密),已知加密规则为:明文a,b,c,d 对应密文a+2b,2b+c,2c+3d,4d,例如,明文1,2,3,4对应密文5,7,18,16.当接收方收到密文14,9,23,28时,则解密得到的明文为 ( )A.4,6,1,7B.7,6,1,4C.6,4,1,7D.1,6,4,7 (6)已知)(x f 的定义域是]1,1[-,则)(log 21x f 的定义域是( )考单招——上高职单招网 A .]2,21[B .]2,0(C .),2[+∞D .)21,0( (7)若函数)(x f 是定义在R 上的偶函数,在]0,(-∞上是减函数,且0)2(=f ,则使得0)(<x f 的x 的取值范围是 ( )A .)2,(-∞B .),2(+∞C .(-2,2)D .),2()2,(+∞--∞(8)当10<<a 时,在同一坐标系中,函数x y a y a x log ==-与的图象是( )A B C D(9)已知函数))((R x x f y ∈=满足)1()1(-=+x f x f ,且]1,1[-∈x 时,2)(x x f =,则函数)(x f y =与x y 5log =的图象的交点个数为 ( ) A .0个 B .2个 C .3个 D .4个(10)实系数方程220x ax b ++=的两根为1x 、2x ,且12012x x <<<<则 21b a -- 的取值范围是 ( )A.1(,1)4B.1(,1)2C.11(,)24- D.11(,)22-第二部分 非选择题(共100分)二、填空题:本大题共4小题,每小题5分,共20分。
xy1 1oxy o 1 1oy x 11 oy x1 1考单招——上高职单招网 (11)设f (x )是R 上的函数,且f (-x )=-f (x ),当x ∈[0,+∞)时,f (x )=x (1+),那么当x ∈(-∞,0)时,f (x )=_____ ___;(12)函数21432-+--=x x x y 的定义域是(13)函数x x y 21-+=的值域是(14)若函数213ln()1xy x x+=+-的最大值与最小值分别为M,m ,则M+m =三、解答题:本大题共6小题,共80分,解答应写出文字说明、演算步骤或推证过程。
(15)(本题满分12分)已知函数)0(22)(2≠++-=a b ax ax x f ,在区间[]3,2上有最大值5,最小值2。
(1)求a ,b 的值。
(2)若[]42,)2()()(,1在x x f x g b m ⋅-=<上单调,求m 的取值范围。
(16) (本题满分12分) 函数6)1(3)1()(22+-+-=x a x a x f , (1)若)(x f 的定义域为R ,求实数a 的取值范围. (2)若)(x f 的定义域为[-2,1],求实数a 的值. (17)(本题满分14分)某饮料公司经市场调研,发现该饮料的日销售额(y 万元)与天气气温(x ℃)之间有密切联系。
现知,当气温分别为25℃、27℃、29℃时,日销售额分别为1万元、1.1万元、1.3万元。
为了调节生产,需估测气温升高后对日销售额的影响,以这三个气温考单招——上高职单招网 下的日销售额为依据,用一个函数模拟日销售额(y 万元)与天气气温(x ℃)关系。
模拟函数考虑选用二次函数c x b x a y +-+-=)25()25(2或函数cb a yx +⋅=-25(其中c b a ,,为常数)。
现已知气温为33℃时,该饮料的日销售额为2.2万元, 请问用以上哪个函数作为模拟函数较好,并说明理由。
(18)(本题满分14分)设()f x 是定义在(0,)+∞上的增函数,对任意,(0,)x y ∈+∞,满足()()()f xy f x f y =+。
(1)求证:①当(1,)()0()()()xx f x f f x f y y∈+∞>=-时,② (2)若(5)1f =,解不等式(1)(2) 2.f x f x +->(19)(本题满分14分) 已知函数xxx f -+=11lg)( (Ⅰ)求证:对于)(x f 的定义域内的任意两个实数b a ,,都有)1()()(abba fb f a f ++=+;(Ⅱ)判断)(x f 的奇偶性,并予以证明.(20). (本题满分14分) 对于定义域为[]0,1的函数()f x ,如果同时满足以下三条:①对任意的[]0,1x ∈,总有()0f x ≥;②(1)1f =;③若12120,0,1x x x x ≥≥+≤,都有1212()()()f x x f x f x +≥+成立,则称函数()f x 为理想函数.(1) 若函数()f x 为理想函数,求(0)f 的值;考单招——上高职单招网 (2)判断函数()21x g x =-])1,0[(∈x 是否为理想函数,并予以证明; (3) 若函数()f x 为理想函数,假定∃[]00,1x ∈,使得[]0()0,1f x ∈,且00(())f f x x =,求证00()f x x =.参考答案一、选择题(每小题5分,共50分)11.)1(3x x - 12.),4[]1,3()3,(+∞⋃--⋃--∞13.]1,(-∞ 14.6 三、解答题:(本大题共6小题,共80分)15.。
(12分)解析:(1)a b x a x f -++-=2)1()(2 --------------------1分①当0>a 时,[]3,2)(在x f 上为增函数故⎩⎨⎧==⇒⎩⎨⎧=++-=++-⇒⎩⎨⎧==01224452695)2(2)3(b a b a a b a a f f ----------------4分②当[]3,2)(0在时,x f a <上为减函数故⎩⎨⎧=-=⇒⎩⎨⎧=++-=++-⇒⎩⎨⎧==31524422692)2(2)3(b a b a a b a a f f --------------7分(2)011==∴<b a b即22)(2+-=x x x f --------------------8分考单招——上高职单招网 2)22()2(22)(22++-=-+-=x x xx x x g mm ------------9分分)(或分)(分)(或分)(1 62 1 221 4222 1 2222≥≤∴≥+≤+m m m m -------------11分即62log 1≥≤m m 或 ------------ 12分16.(12分)解:(1)①若1,012±==-a a 即,1)当a =1时,6)(=x f ,定义域为R ,适合;2)当a =-1时,66)(+=x x f ,定义域不为R ,不合;②若6)1(3)1()(,01222+-+-=≠-x a x a x g a 为二次函数,)(x f 定义域为R ,R x x g ∈≥∴对0)(恒成立,11150)511)(1(110)1(24)1(901222<≤-⇒⎩⎨⎧≤+-<<-⇒⎪⎩⎪⎨⎧≤---=∆>-∴a a a a a a a ; 综合①、②得a 的取值范围]1,115[-------------6分 (2)命题等价于不等式06)1(3)1(22≥+-+-x a x a 的解集为[-2,1], 显然012≠-a20112-=<-∴x a 且、12=x 是方程06)1(3)1(22=+-+-x a x a 的两根,考单招——上高职单招网 ⎪⎩⎪⎨⎧==+->-<⇒⎪⎪⎪⎩⎪⎪⎪⎨⎧-=-=⋅-=--=+>-<∴4023*******)1(31122221221a a a a a a x x a a x x a a 或或,解得a 的值为a =2. ------12分17(14分)、模拟函数为1)25(401)25(8012+-+-=x x y 和9.021.025+⋅=-x y 当x=33时,y 1=2, y 2=2.5与日销售额2.2相比,显然二次函数模拟更好一点 ---14分18(14分)、(1) ①()()()()11110f f f f =+∴= 又()f x 在(0 ,+∞)上是增函数,所以()f x >0②由 ()()x x f f y f y f x y y ⎛⎫⎛⎫+==⎪ ⎪⎝⎭⎝⎭ 得()()x f f x f y y ⎛⎫=- ⎪⎝⎭-----7分 (2) ∵ ()()()2115525f f f =+=+=()()()()125250f x f f x f x ∴+>+= 且()f x 在(0 ,+∞)上是增函数1020150x x x x+>⎧⎪∴>⎨⎪+>⎩解得 1049x << -------------14分19.(14分函数定义域为{}11<<-x x )1,1(-= …………………………………2分(Ⅰ)证明:=+-∈∀)()(),1,1(,b f a f b a b b a a -++-+11lg 11lg)1)(1()1)(1(lg b a b a --++=,…4分考单招——上高职单招网 b a ab b a ab abb a ab ba ab b a f --++++=++-+++=⎪⎭⎫ ⎝⎛++11lg 1111lg1)1)(1()1)(1(lg b a b a --++=, 所以=+)()(b f a f ⎪⎭⎫⎝⎛++ab b a f 1.……………………………………7分(Ⅱ)=+--∈∀)()(),1,1(x f x f x 0lg11111lg 11lg 11lg ==⎪⎭⎫⎝⎛-+⎪⎭⎫ ⎝⎛+-=-+++-x x x x x x x x 即)()(x f x f -=-,所以()f x ……………………………14分20(14分)解:(1)取021==x x 可得0)0()0()0()0(≤⇒+≥f f f f .---------------1分又由条件①0)0(≥f ,故0)0(=f .---------------3分(2)显然12)(-=x x g 在[0,1]满足条件①0)(≥x g ;---------------4分也满足条件②1)1(=g .---------5分 若01≥x ,02≥x ,121≤+x x ,则)]12()12[(12)]()([)(21212121-+---=+-++x x x x x g x g x x g0)12)(12(1222122121≥--=+--=+x x x x x x ,即满足条件③,---------------8分故)(x g 理想函数. ---------------9分(3)由条件③知,任给m 、∈n [0,1],当n m <时,由n m <知∈-m n [0,1],)()()()()(m f m f m n f m m n f n f ≥+-≥+-=∴. --------------11分若)(00x f x <,则000)]([)(x x f f x f =≤,前后矛盾.考单招——上高职单招网 若)(00x f x >,则000)]([)(x x f f x f =≥,前后矛盾.--------------14分。