吉林省延边二中2010~2011学年度高三数学第二次阶段性测试【会员独享】
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延边二中2016——2017学年度第二学期第二次阶段检测高二年级数学(文科)试卷一、选择题(唯一选择,共12小题,每题4分,共48分)1.集合{}{}2|0,|55x A x x x B x =+≥=≥,则A B ⋂=A .{}}01x x x ≥≤-或 B.{}}1x x ≥- C.{}}1x x ≥ D.{}}0x x ≥2.设()()12i i a ++的实部与虚部相等,其中a 为实数,则a=A .-3B .-2C . 2D .33.已知a R ∈,则“2a >”是“22a a >”的( )A .充分不必要条件B .必要不充分条件C .充要条件D .既非充分也非必要条件4.已知函数f(x)=⎩⎪⎨⎪⎧ 2x +1,x <1,x 2+ax ,x≥1,若f(f(0))=4a ,则实数a 等于A. 2 B .45 C .12D .9 5.下列函数中,既是偶函数又在(),0-∞上单调递增的函数是A.2y x =B.2x y = C .21log y x = D .sin y x = 6.关于直线m l ,及平面βα,下列说法中正确的是A .若l ∥α,l m 则,=βα ∥m B .若l ∥α, m ∥α ,则l ∥m C .若l l ,α⊥∥β,则βα⊥ D .若l ∥α,l ∥m ,则α⊥m7. 若函数21()2x x f x a+=-是奇函数,则使3f x >()成立的x 的取值范围为 A .( ) B.() C .0,1() D .1,+∞()8.椭圆C 的中心在原点,焦点在x 轴上,离心率等于12,且它的一个顶点恰好是抛物线283x =的焦点,则椭圆C 的标准方程为 A.22142x y += B.22143x y += C.221129x y += D.2211612x y +=9.已知函数()f x是定义在R内的奇函数,且满足()()4f x f x+=,当()0,2x∈时,()22f x x=,则()2015f=A.-2 B.2 C.-98 D.9810.下列图象中,有一个是函数3221()(1)1(,0)3f x x ax a x a R a=++-+∈≠的导函数()f x'的图象,则(1)f-=A.31B.31-C.37D.31-或3511.函数()y f x=在[]0,2上单调递增,且函数()2f x+是偶函数,则下列结论成立的是A.()57122f f f⎛⎫⎛⎫<<⎪ ⎪⎝⎭⎝⎭B.()75122f f f⎛⎫⎛⎫<<⎪ ⎪⎝⎭⎝⎭C.()75122f f f⎛⎫⎛⎫<<⎪ ⎪⎝⎭⎝⎭D.()57122f f f⎛⎫⎛⎫<<⎪ ⎪⎝⎭⎝⎭12.已知12,F F分别为双曲线)0,0(12222>>=-babyax的左、右焦点,P为双曲线右支上的任意一点,若212PFPF的最小值为8a,则双曲线的离心率e的取值范围是A.(]1,3B. (3C.3,3⎤⎦D.[)3,+∞二.填空题(共4小题,每题4分,共16分)13.函数)2(log221xxy-=的单调递减区间是 .14.函数f(x)=log a(6-ax)在上为减函数,则a的取值范围是________.15.已知定义在R上的偶函数()f x在[0,)+∞单调递增,且(1)0f=,则不等式(2)0f x-≥的解集是.16.已知命题p:关于x的不等式a x>1(a>0,a≠1)的解集是{x|x<0},命题q:函数y=lg(ax2-x+a)的定义域为R,如果p∨q为真命题,p∧q为假命题,则实数a的取值范围.三.简答题(本答题共5个小题, 17、18题各10分,19、20、21题各12分)17.为考查某种疫苗预防疾病的效果,进行动物实验,得到统计数据如下:现从所有试验动物中任取一只,取到“注射疫苗”(Ⅰ)求22⨯列联表中的数据x ,y,A ,B 的值;(Ⅱ)能够有多大把握认为疫苗有效?18.已知曲线C 的极坐标方程是ρ=2cosθ,以极点为平面直角坐标系的原点,极轴为x 轴的正半轴,建立平面直角坐标系,直线L 的参数方程是12x m y t ⎧=+⎪⎪⎨⎪=⎪⎩(t 为参数).(1)求曲线C 的直角坐标方程和直线L 的普通方程;(2)设点P (m ,0),若直线L 与曲线C 交于A ,B 两点,且|PA|•|PB|=1,求实数m 的值.19.如图,矩形ABCD 中,对角线BD AC 、的交点为AD G ,⊥平面,ABEF BC EB AE EB AE ,,2===⊥为CE 上的点,且CE BF ⊥.(I ) 求证:AE ⊥平面BCE ;(II )求三棱锥GBF C -的体积.ACDE GB F20.已知椭圆22221x y a b+=(a >b >0)的左、右焦点为F 1、F 2,点A 在椭圆上,且2AF 与x 轴垂直.(1)求椭圆的方程;(2)过A 作直线与椭圆交于另外一点B ,求△AOB 面积的最大值.21.已知函数ln 1()x x f x e+=(e 是自然对数的底数),()1ln h x x x x =--. (Ⅰ)求曲线()y f x =在点(1,(1))f 处的切线方程;(Ⅱ)求()h x 的最大值.。
延边二中2008~2009学年度高三第二次阶段性测试数 学 试 卷(理科)第I 卷(选择题共60分)一、选择题:本大题共12小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的.1.若全集R U =,集合},02|{},01|{2≤-=<-=x x x B x x A 则A ∩B =( ) A .{}21|<<x x B .{}21|≤<x x C .{}21|≥<x x x 或D .{}21|>≤x x x 或2.设等比数列{}n a 中,前n 项和为n S ,已知38S =,67S =,则789a a a ++=( ) A18 B 18- C 578 D 5583.设函数()()()()2 01 153 1x x f x a x x x ⎧⎪⎪⎨⎪⎪⎩≤<==->在区间[)+∞,0上连续,则实数a 的值为 ( ) A .2 B .1 C .0 D .3 4.用数学归纳法证明“nn n n n 212111211214131211+++++=--++-+-”时,由k n =的假设证明1+=k n 时,如果从等式左边证明右边,则必须证得右边为( )A .1212111+++++k k kB .2211212111+++++++k k k kC .1212121+++++k k kD .22112121++++++k k k 5.设S n 是等差数列{}n a 的前n 项和,若==5935,95S Sa a 则 ( )A .1B .-1C .2D .216.若指数函数)10()(≠>=a a a x f x且则不等式0|)(|1<-x f 的解集为( )A .}11|{<<-x xB .}11|{>-<x x x 或C .}10|{<<x xD .{|1001}x x x -<<<<或7.若c b a 、、是常数,则“0402<->c a b a 且”是“对任意R ∈x ,有02>++c x b x a ”的 ( )A .充分不必要条件B .必要不充分条件C .充要条件D .既不充分也不必要条件8.已知命题P :任意2,10x R x x ∈++>,则 ( )A. p ⌝:存在2000,10x R x x ∈++<B. p ⌝:存在2000,10x R x x ∈++≤C. p ⌝:任意2000,10x R x x ∈++<D. p ⌝:任意2000,10x R x x ∈++≤ 9.()f x '是()f x 的导函数,()f x '的图象如图所示, 则()f x 的图象只可能是( )10.已知函数12||4)(-+=x x f 的定义域是[]b a ,(,)a b ∈Z ,值域是[]1,0,那么满足条件的整数数对),(b a 共有( )A.2个B.3个C. 5个D.无数个11.数列}{n a 的前n 项的和),1,0(2R n n p qn pn S n ∈>≠+=,则当0<p 时,下列不等式中成立的是 ( )A.n n na S na <<1B. 1na S na n n <<C. n n na na S <<1D. n n S na na <<112、已知函数⎪⎩⎪⎨⎧>+-≤-=0,0,1)21()(2x x x x x f x则函数)(log )(x f x g a =(其中0<a<1)的单调递减区间是A 、 1(0,]2 B 、1[,)2+∞ C 、 D 、 B .C .D .A .第Ⅱ卷(非选择题 共90分)考生注意事项: 请用0.5毫米黑色墨水签字笔在答题卡上书写作答,在试题卷上书写作答无效....................... 二、填空题:本大题共4小题,每小题5分,共20分.把答案填在答题卡的相应位置. 13.已知对任意的)()()(,,b f a f b a f R b a ⋅=+∈都成立,且1)1(=f ,则=+++)2003()2004()2()3()1()2(f f f f f f 14.已知0lim→x x x sin =1,则2lim π→x x x2cos -π=____________.15.若函数52(2)(|1|≤≤-=-x x f x ),则)(x f 的值域为 . 16.对于定义在R 上的函数)(x f ,有下述四个命题:①若)(x f 是奇函数,则)1(-x f 的图象关于点A (1,0)对称;②若对于任意)1()1(,-=+∈x f x f R x 有,则函数)(x f 的图象关于直线1=x 对称;③若函数)1(-x f 的图象关于直线1=x 对称,则)(x f 为偶函数;④函数)1(x f y +=与函数)1(x f y -=的图象关于直线1=x 对称. 其中正确命序号为 .(把你认为正确命题的序号都填上) 三、解答题:本大题共6小题,共70分.17题10分,其余12分.17.函数32()332f x x ax bx =+++在2x =处取得极值,其图象在1x =的切线与直线350x y -+=垂直。
吉林省延边二中2010-2011学年高二第二次月考(数学(理))试)考试说明:本试卷分第Ⅰ卷(选择题60分)和第Ⅱ卷(非选择题60分)两部分,试卷共4页,共三大题,20小题。
第Ⅰ卷注意事项:1、 答第Ⅰ卷前,考生务必将自己的班级、姓名、考号、考试科目涂写在答题卡上。
2、 每小题选出答案后,用2B 铅笔把答题卡上对应题目的答案标号涂黑。
如需改动,用橡皮擦干净后,再选涂其他答案标号。
不涂到答题卡上不得分。
一.单项选择题(在每题给出的四个选项中,只有一项是最符合题目要求的。
每小题 5 分,共12题,60分)1.抛物线)0(2<=a ax y 的焦点坐标是 ( )A .)4,0(aB .)41,0(a -C .)41,0(a D .)0,41(a2.动点P 到直线05=+x 的距离减去它到M (2,0)的距离的差等于3,则点P 的轨迹是( )A .直线B .椭圆C .双曲线D .抛物线3.设椭圆22221(00)x y m n m n +=>>,的右焦点与抛物线28y x =的焦点相同,离心率为12,则此椭圆的方程为( )A .2211216x y += B .2211612x y += C .2214864x y += D .2216448x y += 4.已知双曲线的离心率为2,焦点是(4,0)-,(4,0),则双曲线方程为( )A .221412x y -= B .221124x y -= C .221106x y -= D .221610x y -= 5. 已知抛物线()022>=p px y 的准线与圆07622=--+x y x 相切,则p 的值为()A.12B.1C.2D.4 6. 过椭圆22221x y a b+=(0a b >>)的左焦点1F 作x 轴的垂线交椭圆于点P ,2F 为右焦点,若1260F PF ∠=,则椭圆的离心率为( )A .2 B .3 C .12 D .137.已知a =(2,-1,3),b =(-1,4,-2),c =(7,5,λ),若a 、b 、c 三向量共面,则实数λ等于 ( )A .627B .637C .647D .6578.已知a +b +c =0,|a |=2,|b |=3,|c |=19,则向量a 与b 之间的夹角><b a ,为A .30°B .45°C .60°D .以上都不对9.在下列命题中:①若a 、b 共线,则a 、b 所在的直线平行;②若a 、b 所在的直线是异面直线,则a 、b 一定不共面;③若a 、b 、c 三向量两两共面,则a 、b 、c 三向量一定也共面;④已知三向量a 、b 、c ,则空间任意一个向量p 总可以唯一表示为p =x a +y b +z c .其中正确命题的个数为( )A . 0B .1C . 2D .3 10.已知点A (4,1,3),B (2,-5,1),C 为线段AB 上一点,且3||||AC AB =,则点的坐标是 ( )A .715(,,)222-B . 3(,3,2)8-C . 107(,1,)33-D .573(,,)222-11.设A 、B 、C 、D 是空间不共面的四点,且满足0,0,0=⋅=⋅=⋅,则△BCD 是 ( )A .钝角三角形B .直角三角形C .锐角三角形D .不确定12. 已知二面角l αβ--的大小为060,,m n 为异面直线,且,m n αβ⊥⊥,则,m n 所成的角为( )A.030B.060C.090D.0120第Ⅱ卷注意事项:1、 用蓝色或黑色钢笔或圆珠笔将答案写在答题纸上,直接答在试卷上不得分..........。
延边二中2010~2011学年度高三第二次阶段性测试政治试卷本试卷分第I卷(选择题)和第II卷(非选择题)两部分。
共100分,考试时间90分钟。
第I卷(共48分)一、选择题(本题包括24小题,每小题2分,共48分,请将正确答案涂在答题卡上)1.读下图:当价格运行到a点时,可能出现的经济现象是A.企业扩大规模增加投资B.商品供过于求C.市场秩序极度混乱 D.商品处于卖方市场2②城乡居民家庭食品支出额整体上呈现下降趋势③我国城乡居民的消费心理不断发生变化④农村居民消费水平远远低于城市居民消费水平A.①② B.②③ C.①④ D.②④3.漫画《正式工与聘用工》反映的问题是①我国需要建立和谐的劳动关系,维护劳动者平等就业的权利②公有制经济和非公有制经济要互相促进、共同发展③我国需要完善分配制度,注重体现公平④要正确处理效率与公平的关系A.①② B.③④C.①③ D.②④2009年2月20日,盐城市城西、越河水厂受到挥发酚类化合物污染,市区发生大范围断水,给人民生活带来极大不便。
据此回答4--5题。
4.经调查,盐城水被污染是由于取水口的上游地区近几年盲目引进了上百家化工企业,本次污染事故系某化工企业偷排污水所致。
该化工厂唯利是图的做法体现了市场调节的:A.盲目性B.自发性C.滞后性D.违法性5.针对上述情况,两市政府决定:对饮用水源地保护区范围内的所有化工生产企业实施搬迁,对于违法违规生产的则坚决拆除。
确保居民饮用水不被污染。
两市政府的决定属于宏观调控的:A.经济手段B.法律手段C.行政手段D.市场手段6.为有效控制高耗能高污染行业过快增长,落实节能减排目标,国家实行差别电价政策,提高高耗能产品差别电价标准。
这表明A.国家限制电力工业发展,贯彻和落实科学发展观B.国家运用行政手段,促进经济又好又快发展C.国家自觉运用市场机制调节经济发展D.国家发挥宏观调控在资源配置中的基础性作用7.2009年由中国移动、中国电信和中国联通三大运营商投资的大规模的网络建设将产生巨大的“乘数效应”,形成一条包括3G网络建设、终端设备制造、运营服务、信息服务在内的庞大产业链,将拉动近2万亿元的社会投资。
吉林省延边二中2009~2010学年度第一学期期中考试试卷高二数学考试说明:本试卷分第Ⅰ卷(选择题60分)和第Ⅱ卷(非选择题60分)两部分,共三大题,21小题。
第Ⅰ卷注意事项:1、 答第Ⅰ卷前,考生务必将自己的班级、姓名、考号、考试科目涂写在答题卡上。
2、 每小题选出答案后,用2B 铅笔把答题卡上对应题目的答案标号涂黑。
如需改动,用橡皮擦干净后,再选涂其他答案标号。
不涂到答题卡上不得分。
一、单项选择题(在每题给出的四个选项中,只有一项是最符合题目要求的。
每小题5 分,共12题,60分)1.某数列既成等差数列也成等比数列,那么该数列一定是 ( )A .公差为0的等差数列B .公比为1的等比数列C .常数数列1,1,1,…D .以上都不对2. 在△ABC 中,已知a=5 2 , c=10, A=30°, 则∠B= ( )A . 105°B . 60°C . 15°D . 105°或15°3.下列各式中最小值是2的是 ( ) A .y x +x y B .4522++x x C .tan x +x tan 1 D . x x -+22 4.下列各点中,位于不等式(x+2y+1)(x -y+4)<0表示的平面区域内的是 ( )A .(0,0)B .(-2,0)C .(-1,0)D .(2,3)5. “2b ac =”是“a 、b 、c 成等比数列”的( )条件A .充分不必要B .必要不充分C . 充要D . 既不充分也不必要6.命题“若△ABC 不是等腰三角形,则它的任何两个内角不相等.”的逆否命题 是 ( ) A .“若△ABC 是等腰三角形,则它的任何两个内角相等.”B .“若△ABC 任何两个内角不相等,则它不是等腰三角形.”C .“若△ABC 有两个内角相等,则它是等腰三角形.”D .“若△ABC 任何两个角相等,则它是等腰三角形.”7.若c C b B a A cos cos cos ==则△ABC 为 ( )A .等边三角形B .等腰三角形C .直角三角形D .钝角三角形 8.已知数列2()256n n a n N n =∈+,则数列{}n a 的最大项是 ( ) A .第14项 B .第15项 C .第16项 D .第17项9. 在等比数列中,301013S S =,1030140S S +=,则20S = ( )A .90B .70C .40D .3010.设4)1(2,2)1(1,)(2≤≤≤-≤+=f f bx ax x f 且,则)2(-f 的取值范围为( )A .[]6,9 B.[]5,10 C.[]3,12 D .[]4,1111.若不等式213log (1)tan ()4x παπα->-<<-恒成立,则实数x 的取值范围为( ) A .()1,0- B.()0,1 C.()1,2 D .()1,+∞12. 数列1,2,2,3,3,3,4,4,4,4,5,5,5,5,5,6,…的第1000项的值是 ( )A . 42B .45C . 48D .51第Ⅱ卷注意事项:1、 用蓝色或黑色钢笔或圆珠笔将答案写在答题纸上,直接答在试卷上不得分..........。
延边二中2010~2011学年度第一学期高三第二次阶段性测试物理试卷考试说明:本试卷分第I 卷(选择题)和第Ⅱ卷(非选择题)两部分,满分110分,考试时间为90分钟。
其中第Ⅱ卷第18~19题为选考题,其它为必考题。
将选择题答案涂在答题卡上,其它试题答案答在答题纸上,在本试卷上答题无效。
第I 卷(选择题共48分)一、选择题:(本题共12小题,每小题给出的四个选项中,至少有一个选项是正确的,全部选对的得4分。
选对但不全的得2分,有选错或不答的得0分)1.如图是某质点运动的速度图像,由图像得到的正确结果是:A .0~1 s 内的平均速度是2m/sB .0~1s 内的位移大小是3 mC .0~1s 内的加速度大于2~4s 内的加速度D .0~1s 内的运动方向与2~4s 内的运动方向相反2.汽车拉着拖车在平直的公路上运动,下面的说法正确的是:A .汽车能拉着拖车向前运动是因为汽车对拖车的拉力大于拖车拉汽车的力B .汽车先对拖车施加拉力,然后才产生拖车对汽车的拉力C .匀速前进时,汽车对拖车的拉力等于拖车向后拉汽车的力;加速前进时,汽车向前拉拖车的力大于拖车向后拉汽车的力D .加速前进时,是因为汽车对拖车的拉力大于拖车受到的阻力,且汽车向前的牵引力一定大于拖车对它的拉力3.一水平抛出的小球落到一倾角为θ的斜面上时,其速度方向与斜面垂直,运动轨迹如右图中虚线所示。
小球在竖直方向下落的距离与在水平方向通过的距离之比为:A .1tan θB .12tan θC .tan θD .2tan θ 4.一汽车在路面情况相同的公路上直线行驶,下面关于车速、惯性、质量和滑行路程的讨论,正确的是:A .车速越小,它的惯性越小B .车速越大,刹车后滑行的路程越长C .质量越大,它的惯性越大D .车速越大,刹车后滑行的路程越长,所以惯性越大5.如图所示,质量分别为m 1和m 2两个物体通过轻弹簧连接,在力F 的作用下一起沿水平方向做匀速直线运动(m 1在地面,m 2在空中),力F 与水平方向成θ角。
延边二中2010-2011学年度第二学期六月份月考高一英语(100分) 2011年6月I、单项选择(每题1分,共20分)1. He argued _______ smoking, and insisted that it was ________ argument that smoking was harmful to health.A. for; beyondB. against; overC. for; overD. against; beyond2. It was ________ the trouble to explain a job fully to new employees.A. worth to takeB. worthwhile takingC. worthy of takingD. worthy to take3. The headmaster wants to have the opening speech ________ by our math teacher next month.A. deliverB. to deliverC. deliveredD. delivering4. -Do you mind _____alone at home?-No, but I want a good book_______.A. leaving; to readB. to be left; readingC .to leave; reading D. being left; to read5. Some of you may have finished unit one. _____ , you can go on to unit two.A. If you mayB. If you doC. If notD. If so6. During his five-day state visit to Japan, Hu Jintao delivered such an ________ speech that all the people present were ________.A. inspiring; excitingB. inspiring; excitedC. inspired; excitingD. inspired; excited7. They argued ________each other _________ where to spend the golden week.A. at; overB. with; aboutC. about; atD. over; on8. The teacher, with 6 girls and 8 boys of her class, ________ visiting a museum when the earthquake struck.A. wasB. wereC. had beenD. would be9. He is determined to become a specialist ________ computer when he grows up.A. forB. inC. onD. about10. The best means to go there _________walking.A. isB. areC. to beD. be11. I still remember to the Famen Temple and what I saw there.A. to takeB. to be takenC. takingD. being taken12. At times the balance in nature is ______,resulting in a number of possibly unforeseen effects.A.troubled B.confused C.disturbed D.puzzled13. The government tried it’s best to ______ the people’s needs, but the people were still not _____.In fact, what the government did was not ________.A. satisfy; satisfied; satisfyingB. satisfy; satisfying; satisfiedC satisfied; satisfied; satisfying D. satisfying; satisfied; satisfied14. To the surprise of many people, in ten years the city's population _______ by 12%.A. gainedB. expandedC. developedD. spread15. Only after I read the text over again _____ its main idea.A. that I knewB. did I knowC. I could knowD. I did know16. The UN is trying to ______ the world ________ hunger.A. get rid of; byB. rid; ofC. be rid of ;byD. get rid; ofAfter that we often read, played and talked together. My friends are always 38 to help me. It made me 39 I am handicapped(残疾的).Once they asked me, "What is the most beautiful thing in our school ?" Without hesitation I said, "It is the 40 . "21. A. with B. without C. under D. on22. A. walk B. run C. sit D. stand23. A. school B. wheelchair C. home D. hospital24. A. he B. she C. everyone D. nobody25. A. thought B. interest C. anger D. surprise26. A. red B. brown C. white D. black27. A. entering B. hiding C. coming D. turning28 A. feeling B. kindness C. sorrow D. pain29. A. made B. prevented C. kept D. let30. A. walk B. study C. practice D. speak31. A. laughed B. smiled C. stared D. looked32. A. quickly B. slowly C. happily D. shyly33. A. brave B. sad C. hurt D. excited34. A. honest B. friendly C. luckily D. handsome35. A. pushed B. placed C. drew D. pulled36 A. satisfied B. sorry C. loyal D. grateful37 A. signs B. sights C. buildings D. students38. A. ready B. smart C. wise D. unwilling39. A. forget B. remember C. imagine D. think40. A. teachers B. schoolyard C. classmates D. friendship III. 阅读理解(每题2分共15题,满分30分)AThere is a wonderful story about a young girl who had no family and no one to love her.One day, feeling very sad and lonely, she was walking through a grassland when she noticed a small butterfly caught in a thorn (荆棘) bush. The young girl carefully released the Butterfly. Instead of flying away, the little butterfly changed into a beautiful fairy. The young girl rubbed her eyes in disbelief.“For your wonderful kindness,” the good fairy said to the girl, “I will give you any wish you would like.” The little girl thought for a moment and then replied, “I want to be happy.”The fairy leaned toward her and whispered in her ear. Then the fairy disappeared. As the little girl grew up, there was no one in the land as happy as she. Everyone asked her secret of happiness .She would only smile and answer, “The secret of my happiness is that I listened to a good fairy when I was a little girl.”When she was very old and on her deathbed, the neighbors all gathered around her, that her unbelievable secret of happiness would die with her. “Tell us, please,”they begged, “Tell us what the good fairy said.”The lovely old woman simply smiled and said, “She told me that everyone, no matter how secure they seemed, no matter how old or young, how rich or poor, had need of me.”41. ______ the girl felt sad and lonely.A. There were many friends butB. There was nobody to love her soC. There was nothing to doD. Seeing the butterfly was caught42. Noticing the butterfly was caught by the thorn, the orphan girl ______.A. helped the butterfly escaped from the thornB. felt sorrow, but she didn’t go up to help itC. fell down on it tooD. failed to help it release from the thorn43. The butterfly ______ after was saved by the little girl.A. flied awayB. still diedC. changed into a fairyD. was more beautiful than before44. The only thing that the little girl wanted was________.A. to be richB. to have her own parentsC. to have a lot of friendsD. happiness45. The neighbors all gathered around the old happy woman when she was dying, because ______.A. they loved this woman deeply and they didn‘t wanted her to dieB. the woman had lots of money to be shared as soon as she diedC. they wanted to know the secret of her lifetime happinessD. they wanted to pray for her after her deathBSweetest Day is celebrated on the third Saturday in October as a day to make someone happy. It is an occasion which offers all of us an opportunity to remember not only the sick, the aged, and children who have lost their parents, but also friends, workmates, relatives and neighbors whose helpfulness and kindness we have enjoyed.Over 60 years ago, when a Cleveland man noticed that some people, such as children who lost their parents and patients who lay in bed, too often felt forgotten and neglected, he developed in his mind the idea of showing them that they were remembered. He did this by giving them small gifts. With the help of his friends and neighbors, he gave those people small gifts on a Saturday in October. During the years that followed, other Clevelanders began to take part in the celebration, which came to be called “Sweetest Day”. Over time, the Sweetest Day idea of spreading cheer to the poor, the sick and children who had lost their parents was broadened to include everyone, and became an occasion for remembering others with a kind act or a small gift. Soon the idea spread to other cities all over the USA.Sweetest Day is not based on any single group’s religious beliefs or on a family relationship. It is a reminder that a thoughtful word or deed enriches life and gives it meaning.Because for many people remembering takes the form of gift giving, Sweetest Day offers us the opportunity to show others that we care, in a positive way.46.What is Cleveland?A. An island.B. A country.C. A city in America.D. A village in England.47.What do most people usually do to show their care to others according to the passage?A. They give gifts.B. They give money.C. They send regards.D. They offer help.48.What can we learn from the first paragraph?A. Sweetest Day is celebrated on the third Sunday in October.B. Sweetest Day is just an occasion to care about disabled people.C. Sweetest Day is an occasion for lovers to express love.D. Sweetest Day is a day to make others happy.49.The underlined word “neglected” in the second paragraph means “______”.A. rememberedB. hatedC. disappointedD. paid little or no attention to50.Which of the following has little relationship to Sweetest Day?A. Visiting sick people of the hospital.B. Visiting children who have lost their parents.C. Giving flowers to sweethearts.D. Giving friends small gifts.CEurope is now the biggest market for organic food in the world, having grown by 25 percent a year over the past 10 years. De nmark’s agriculture minister is herself an organic farmer. The UK market for organic food grew by 55 percent in 2000, while the food market as a whole grew by only one percent. Yet only seven percent of British shoppers account for nearly 60 percent of organic sales. However popular the idea of organic farming may be, it is still an interest for only a few people.So what makes the idea of organic farming popular? Organic farming means farming with natural materials, rather than with man-made fertilizers or pesticides. Organic farmers rely on many methods — such as crop rotation (农作物的轮作) and the use of resistant(有抵抗力的) varieties, because they are necessary for organic farmers to compensate for the shortage of man-made chemicals.Organic farming is often supposed to be safer than traditional farming for the environment. Yet after a long research on organic farming worldwide for a number of years, science continues to be against this opinion. The House of Commons committee on agriculture publicized that, even with complete research work, it would fail to find any scientific evidence to prove “that any of claims (宣称) made for organic farming is always true”.However, the talk about the benefits of organic farming is going on. This is partly because many people depend on their individual farm, the soil, the weather, and so on.51. The first paragraph mainly tells us _____.A. organic farming has been performed only in Europe over the past 10 yearsB. governments of European countries have cared less about organic farmingC. organic farming is far from being as popular as expectedD. European countries need organic food more than the other countries in the world52. The underlined words “compensate for” in the second paragraph probably mean “________”.A. argue forB. care forC. struggle forD. pay for53. What can we know about organic farming?A. It refers to farming with natural materials, instead of chemical fertilizers.B. It refers to farming with chemical fertilizers rather than natural fertilizers.C. It refers to farming with soil rather than any other thing.D. It refers to growing crops with man-made fertilizers and pesticides.54. According to the third paragraph, _____.A. organic farming is safer than traditional farming for the environmentB. the idea that organic farming is safer has not been proven by scienceC. organic farming is accepted by the UK’s House of Commons committeeD. organic farming is preferred to traditional farming55. Which of the following is TRUE, according to the passage?A. The UK’s agriculture minister is an organic farmer.B. Organic farming is popular with young people.C. Farmers make use of many different kinds of methods to improve the organic sales system.D. Ninety-three percent of British shoppe rs don’t buy organic products.When I was in high school, most of my friend had bicycles. I hoped I could also have it. One day I saw a second-hand bicycle, that was only one hundred yuan. I asked my father the money. But he said he could only give me half of the money. He should find the other half myself. So I went to sell newspapers after the school. My father was pleased if I showed him the money a month after. He gives me the other fifty.You can imagine how much happy I was when I rode to school on my own bicycle.六月月考答案单选 1-5 DBCDD 6-10 BBABA 11-15 DCABB 16-20 BBADD完型 BAACD ADBBA ACDBA DBAAD阅读 BACDC CADDC CDABD单词56.crowded 57. audience 58. observed 59.nutrition 60 . hits 61. organization62. argument 63. considerate 64. referring 65. occupation改错When I was in high school, most of my friend had bicycles. I hoped I could also have it. Onefriends oneday I saw a second-hand bicycle, that was only one hundred yuan. I asked my father /\ the money.which forBut he said he could only give me half of the money. He should find the other half myself. So I wentIto sell newspapers after the school. My father was pleased if I showed him the money a month laterWhen after.He gives me the other fifty. You can imagine how much happy I was when I rode to school ongavemy own bicycle.解析。
吉林省延边第二中学2023-2024学年高二上学期第二次阶段检测数学试卷一、单选题1.设X 是一个离散型随机变量,其分布列为则q 等于( )A .1B .1C .12D .12.设()10,0.8X B ~,则()21D X +等于 A .1.6B .3.2C .6.4D .12.83.已知椭圆()()22:1,0,4,0,43620y x C A B +=-,过A 作直线PQ 与C 交于,P Q 两点,则BPQ V 的周长为( ) A .24B .20C .16D .124.设a ,b 为正数,若直线10ax by -+=被圆224210x y x y ++-+=截得弦长为4,则2a b ab+的最小值为( ) A .6B .7C .8D .95.2022年10月31日15:37分,我国将“梦天实验舱”成功送上太空,成功将中国空间站建设完毕,中国空间站将于2023年正式进入运营阶段.现空间站要安排甲、乙等6名航天员到3个不同的实验舱开展实验,3舱中每个舱至少一人至多三人,则不同的安排方案共有( ) A .450种B .720种C .90种D .360种6.为了响应国家发展足球的战略,某校在秋季运动会中,安排了足球射门比赛.现有10名同学参加足球射门比赛,已知每名同学踢进的概率均为0.6,每名同学有2次射门机会,且各同学射门之间没有影响.现规定:踢进两个得10分,踢进一个得5分,一个未进得0分,记X 为10个同学的得分总和,则X 的数学期望为( ) A .30B .40C .60D .807.袋子中装有大小、形状完全相同的2个白球和2个红球.现从中不放回地摸取2个球,已知第二次摸到的是红球,则第一次摸到红球的概率为( ) A .12B .13C .23D .348.已知点1F ,2F 是双曲线22:13y C x -=的左、右焦点,点P 是双曲线C 右支上一点,过点2F 向12F PF ∠的角平分线作垂线,垂足为点Q ,则点(A 和点Q 距离的最大值为( )A .2BC .3D .4二、多选题9.下列等式正确的有( )A .11m m mn n n A mA A -++=B .11m m n n nC mC --=C .3333201834520212022C C C C C ++++=L D .0242020201920202020202020202C C C C ++++=L 10.一个质地均匀的正四面体表面上分别标有数字1,2,3,4,抛掷该正四面体两次,记事件A 为“第一次向下的数字为偶数”,事件B 为“两次向下的数字之和为奇数”,则下列说法正确的是( )A .()13P A =B .事件A 和事件B 互为对立事件C .()12P B A =D .事件A 和事件B 相互独立11.如图,在某城市中,M ,N 两地之间有整齐的方格形道路网,其中1A 、2A 、3A 、4A 、5A 是道路网中位于一条对角线上的5个交汇处,现在甲需要从道路网M 出发,随机选择一条沿街的最短路径走到N 处为止,下列说法正确的是( )A .如果甲需要经过5A ,那么从M 到N 的线路有4条;B .如果甲需要经过2A ,那么从M 到N 的线路有16条;C .如果甲需要经过3A ,那么从M 到N 的线路有36条;D .甲从M 到N 的线路一共有70条;12.已知抛物线C :()220y px p =>的焦点为F ,直线l 与C 交于()11,A x y ,()22,B x y 两点,其中点A 在第一象限,点M 是AB 的中点,作MN 垂直于准线,垂足为N ,则下列结论正确的是( )A .若以AB 为直径作圆M ,则圆M 与准线相切B .若直线l 经过焦点F ,且12OA OB ⋅=-u u u r u u u r,则4p =C .若3AF FB =u u u r u u u r ,则直线l 的倾斜角为π3D .若以AB 为直径的圆M 经过焦点F ,则AB MN三、填空题13.已知2n的展开式中二项式系数和是64,则展开式中x 的系数为.14.若随机变量X 的概率分布列为()6kP X k ==,k =1,2,3,则()2P X ≤=. 15.阿基米德是古希腊著名的数学家、物理学家,他利用“逼近法”得到椭圆的面积除以圆周率π等于椭圆的长半轴长与短半轴长的乘积. 已知椭圆22221x ya b+=(a >b >0)的右焦点为(3,0)F ,过F 作直线l 交椭圆于A 、B 两点,若弦AB 中点坐标为(2,1)-,则该椭圆的面积为.16.某人从甲地到乙地,乘火车、轮船、飞机的概率分别为0.2,0.4,0.4,乘火车迟到的概率为0.4,乘轮船迟到的概率为0.3,乘飞机迟到的概率为0.5,则这个人迟到的概率是;如果这个人迟到了,他乘船迟到的概率是.四、解答题17.已知22)nx 的展开式中,只有第六项的二项式系数最大 (1)求该展开式中常数项;(2)求展开式中系数最大的项为第几项?18.已知双曲线22221(00)y x a b a b -=>>,与双曲线22142x y -=有相同的渐近线,且经过点M, (1)求双曲线C 的标准方程(2)已知直线0x y m -+=与曲线C 交于不同的两点A ,B ,且线段AB 的中点在圆2220x y +=上,求实数m 的值.19.某学校组织开展了“学习强国答题挑战赛暨主题党日活动”.规则如下:每班派两名选手参赛,每位选手回答三个题,满分为60分,每题答对得10分,答错不得分.某班派了甲、乙两名同学参赛,且甲同学三题能回答正确的概率均为23,乙同学三题能回答正确的概率依次为23、12、14,两人的累计得分为班级总得分,总得分不少于50分班级将获得参加决赛的资格.(1)三题答完结束后,记X 为乙同学的累计得分,求X 的分布列和期望; (2)求班级获得决赛资格的概率.20.甲、乙去某公司应聘面试.该公司的面试方案为:应聘者从7道备选题中一次性随机抽取3道题,按照答对题目的个数为标准进行筛选.已知7道备选题中应聘者甲有4道题能正确完成,3道题不能完成;应聘者乙每题正确完成的概率都是47,且每题正确完成与否互不影响.(1)分别求甲、乙两人正确完成面试题数的分布列;(2)请从均值和方差的角度分析比较甲、乙两人谁的面试通过的可能性较大?21.已知椭圆()2222:10x y E a b a b +=>>的离心率e =)1-.(1)求椭圆E的方程;=+与椭圆E交于A,B两点,且椭圆E上存在点M,使得四边形OAMB为(2)设直线:l y kx m平行四边形.试探究:四边形OAMB的面积是否为定值?若是定值,求出四边形OAMB的面积;若不是定值,请说明理由.22.自“新型冠状肺炎”疫情爆发以来,科研团队一直在积极地研发“新冠疫苗”.在不懈努力下,我国公民率先在2020年年末开始使用安全的新冠疫苗,使我国的“防疫”工作获得更大的主动权.研发疫苗之初,为了测试疫苗的效果,科研人员以白兔为对象,进行了一些实验:(1)实验一:选取10只健康白兔,编号1至10号,注射一次新冠疫苗后,再让它们暴露在含有新冠病毒的环境中,实验结果发现:除2、3、7、10号四只白兔仍然感染了新冠病毒,其他白兔未被感染.现从这10只白兔中随机抽取3只进行研究,将仍被感染的白兔只数记作X,求X的分布列和数学期望.(2)实验二:疫苗可以再次注射第二针加强针,科研人员对白兔多次注射疫苗后,每次注射的疫苗对白兔是否有效互相不影响.试问:若将实验一中未被感染新冠病毒的白兔的频率当做疫苗的有效率,那么一只白兔注射两次疫苗后的有效率能否保证达到96%?如若可以,请说明理由;若不可以,请问每支疫苗的有效率至少要达到多少才能满足以上要求?。
延边二中2009-2010学年第一学期高二年级第二次月考数学试卷(满分120分,时间90分钟) 2009-12-7一、选择题(每小题5分,共60分)1、一个命题与他们的逆命题、否命题、逆否命题这4个命题中 ( )A 、 真命题与假命题的个数相同B 、真命题的个数一定是奇数C 、真命题的个数一定是偶数D 、真命题的个数一定是可能是奇数,也可能是偶数2、双曲线2214y x -=的渐近线方程为 ( ) A.12y x =± B.2y x =± C.14y x =± D.4y x =±3、与椭圆221916x y +=有相同焦点的双曲线方程是 ( ) A.22134x y -= B.221916x y -= C.221169y x -= D.22143y x -= 4、“a ≠1或b ≠2”是“a +b ≠3”的 ( )A 、充分不必要条件B 、必要不充分条件C 、充要条件D 、既不充分也不必要5、已知抛物线的焦点在直线y x 2--4=0上,则此抛物线的标准方程是 ( )A.x y 162=B.y x 82-=C. x y 162=或y x 82-=D. x y 162=或y x 82=6、命题p :存在实数m ,使方程x 2+mx +1=0有实数根,则“非p ”形式的命题是( )A 、 存在实数m ,使得方程x 2+mx +1=0无实根B 、 不存在实数m ,使得方程x 2+mx +1=0有实根C 、 对任意的实数m ,使得方程x 2+mx +1=0有实根D 、 至多有一个实数m ,使得方程x 2+mx +1=0有实根 7、已知直线1y kx =+与椭圆2215x y m+=恒有公共点,则实数m 的取值范围为 ( ) A .1m ≥ B .1,01m m ≥<<或 C .05,1m m <<≠且 D . 1,5m m ≥≠且8、过点(0,2)与抛物线28y x =只有一个公共点的直线有 ( )A.1条B.2条C.3条D.无数条9、双曲线虚轴上的一个端点为M,两个焦点为F 1、F 2,︒=∠12021MF F ,则双曲线的离心率为 ( ) A.3 B.26 C.36 D.3310、已知点P 在椭圆1204022=+y x 上, 21,F F 是椭圆的两个焦点,21PF F ∆是直角三角形,则这样的点P 有 ( )A.2个B.4个C. 6个D.8个11、已知抛物线23y x =-+上存在关于直线0x y +=对称的相异两点A 、B ,则AB 等于 ( )A . 3B . 4C .D . 12、双曲线22221(0,0)x y a b a b-=>>的焦点为12,,F F 弦AB 过1F 且在双曲线的同一支上,若222AF BF AB +=,则2ABF ∆的周长为 ( )A. 4aB. 8aC. 12aD.不确定二.填空题(每小题5分,共20分)13、 抛物线2y ax =的准线方程为1y =,则a =________。
2010年吉林省延边州某校高考数学模拟训练试卷1(文科)一、选择题(共12小题,每小题5分,满分60分)1. 已知集合A ={1, 2, 3, 4},B ={3, 4, 5, 6},C ={1, 3, 4, 6},则下列关系正确的是( )A A ⊆(B ∪C) B B ⊆(A ∪C)C A ∩B =B ∩CD C ⊇(A ∩B)2. 已知复数z =1+2ii 5,则它的共轭复数z ¯等于( ) A 2−i B 2+i C −2+i D −2−i3. 在△ABC 中,D 是BC 边的中点,E 是AD 的中点,若BE →=mAB →+nAC →,则m +n 的值是( )A 1B −1C 12D −124. 在等比数列{a n }中,若a 2+a 3=2,a 12+a 13=3,则a 22+a 23的值是( )A 94B 49C 92D 29 5. 命题“∀x ∈R ,x 2−2x +2≤0”的否定为( )A ∃x ∈R ,x 2−2x +2>0B ∃x ∈R ,x 2−2x +2≥0C ∃x ∈R ,x 2−2x +2≤0D ∃x ∈R ,x 2−2x +2≥06. 甲、乙两个小组各5名同学在某次英语口语测试中的成绩统计如下面的茎叶图所示,若x ¯甲、x ¯乙分别表示甲、乙两个小组5名同学的平均成绩,则下列结论正确的是( )A x ¯甲>x ¯乙,且甲组比乙组成绩整齐B x ¯甲>x ¯乙,且乙组比甲组成绩整齐C x ¯甲<x ¯乙,且甲组比乙组成绩整齐 D x ¯甲<x ¯乙,且乙组比甲组成绩整齐7. 若△ABC 的内角A 满足sin2A =34,则sinA +cosA 的值是( ) A √72 B −√72 C 74 D −748. 已知△ABC 的三边长分别为AC =3,BC =4,AB =5,在AB 边上任选一点P ,则∠APC <90∘的概率是( )A 916B 925C 1625D 349. 上海浦东新区2008年的生产总值约为3151亿元人民币,如果从此浦东新区生产总值的年增长率为10.5%,求浦东新区最早哪一年的生产总值超过8000亿元人民币?某同学为解答这个问题设计了一个程序框图,但不慎将此框图的一个处理框中的内容污染而看不到了,则此框图中因被污染而看不到的内容应是( )A a =a +bB a =a ×bC a =(a +b)nD a =a ×b n10. 对于直线m ,n 和平面α,β,α⊥β的一个充分条件是( )A m ⊥n ,m // α,n // βB m ⊥n ,α∩β=m ,n ⊂αC m // n ,n ⊥β,m ⊂αD m // n ,m ⊥α,n ⊥β11. 已知椭圆C:x 2a 2+y 2b 2=1(a >b >0)的两个焦点分别为F 1、F 2,点M 在椭圆C 上,若存在F 1M →⋅F 2M →=0,则椭圆C 的离心率的取值范围是( )A (12,1)B [12,1)C (√22,1)D [√22,1)12. 函数f(x)=e −x −x 的零点所在的区间是( )A (−1, −12)B (−12, 0)C (0, 12)D (12, 1)二、填空题(共4小题,每小题5分,满分20分)13. 若关于x 的方程(32)x =3−2a 有负数根,则函数y =log a (2x +3)在区间[1, 4]上的最大值是________.14. 商场在一周内共卖出某种品牌的皮鞋300双,商场经理为考察其中各种尺码皮鞋的销售情况,以这周内某天售出的40双皮鞋的尺码为一个样本,分为5组,已知第三组的频率为0.25,第1,2,4组的频数分别为6,7,9,若第5组表示的是尺码为40∼42的皮鞋,则售出的这300双皮鞋中含尺码为40∼42的皮鞋约为________双.15. 一个几何体的三视图如右图所示,(尺寸的长度单位为cm ).则该几何体的表面积为________cm 2.16. 已知函数y =Asin(ωx +φ)(A >0, ω>0, 0<φ<π2)的图象经过点(0, 1),且一个最高点的坐标为(1, 2),则ω的最小值是________.2010年吉林省延边州某校高考数学模拟训练试卷1(文科)答案1. D2. B3. D4. C5. A6. B7. A8. C9. B10. C11. D12. D13. log a1114. 6015. 18+2√316. π3。
延边二中2010-2011学年度高三第二次阶段性测试数 学 试 卷一、选择题(本大题共12小题,,每小题5分,共60分.在每小题给出的四个选项中,选出一个符合题目要求的选项)1.设全集{|0},{|1},U U x x A x x A =>=>集合则C 等于 ( ) A .{|01}x x << B .{|1}x x <C .{|1}x x ≤D .{|01}x x <≤2.函数y =( )A .[1,2]B .[1,2)C .1(,1]2D .1[,1]23.若函数()(0,1)x f x a a a -=>≠是定义域为R 的增函数,则函数()log (1)a f x x =+的图像大致是( )4.下列命题中的假命题是( )A .21,10>+≠>∀xx x x 都有且B .)0,1(,恒过定点直线a y ax R a =+∈∀C .),0(,)1()(,342+∞⋅-=∈∃+-且在是幂函数使m m x m x f R m 上单调递减 D .)2sin(,ϕϕ+=∈∀x y R 函数都不是偶函数5.若函数2()22f x x x cx c x 3=-++=在处有极值,则函数()1f x x =的图象处的切线的斜率为( )( )A .1B .—3C .—5D .—126.已知a 、b 是不共线的向量,AB λ=+a b ,(,)AC μλμ=+∈a b R,则A 、B 、C 三点共线的充要条件是( )(A )1λμ+= (B )1λμ-= (C )1λμ=- (D )1λμ= 7.对任意非零实数a 、b ,规定a b ⊗的运算原理如图所示,则130.511()log 2716-⊗=( )(A )12 (B )53(C )1 (D )1-8.要得到函数2cos()sin()163y x x ππ=+--的图象,只需将函数cos(2)6y x π=-的图象 ( )A .向左平移8π个单位 B .向右平移2π个单位 C .向右平移3π个单位 D .向左平移4π个单位9.函数1()()sin 2xf x x π=-在区间[0,2]上的零点个数为 ( )A .1个B .2个C .3个D .4个10.已知一个几何体是由上下两部分构成的组合体,其三视图如下,若图中圆的半径为1,等( )A .43πB .2πC .83π D .103π11.已知点(,)x y 满足约束条件203202x y x y x +-≥⎧⎪--≥⎨⎪≤⎩,若函数2()log (1)a f x x =+(0a >且1a ≠)图象通过的定点是(,)m n ,则y nx m--的最大值为( ) A .1B .32C .2D .412.已知)(x f 、)(x g 都是定义在R 上的函数,()0g x ≠,()()()()f x g x f x g x ''<, )()(x g a x f x =(a>0且a ≠1),25)1()1()1()1(=--+g f g f ,在有穷数列()()f n g n ⎧⎫⎨⎬⎩⎭( n =1,2,…,10)中,任意取前k 项相加,则前k 项和大于6463的概率是 ( )A .51 B .52 C .53 D .54 二、填空题(本大题共4小题,每小题5分,共20分) 13.已知2)6tan(=-πα,52)6tan(=+βπ,则=+)tan(βα 。
14.(理科)已知△ABC 的内角A ,B ,C 的对边分别为a ,b ,c ,且2,32cos -=⋅=CB AC C 且则,26=+b a c 等于 。
(文科)设1232,2,()((2))log (1),2,x e x f x f f x x -⎧<⎪=⎨-≥⎪⎩则的值为 。
15.已知函数()sin (),()2xf x x f x f x ''=-的导数为且的最大值为b ,若2()2l n2[1,)g x x b x k x =--+∞在上单调递减,则实数k 的取值范围是 。
16.关于函数||12)(x xx f +=)(R x ∈的如下结论:①)(x f 是偶函数;②函数)(x f 的值域为)2,2(-;③若1x ≠2x ,则一定有)(1x f ≠)(2x f ④函数|)1(|+x f 的图象关于直线1=x 对称;其中正确结论的序号有_________。
(请将你认为正确的结论的序号都填上)邪恶动态图/xieedontaitu/ 奀莒哃三、解答题(本大题共6小题,共70分,解答应写出文字说明、证明过程或演算步骤) 17.(本小题满分10分)已知函数21()2cos sin cos (0)().42f x a x b x x f f π=+-==且 (1)求()f x 的最小正周期; (2)求()f x 的单调递增区间。
18.(本小题满分12分)如图,在三棱锥P ABC -中,PA AC ⊥,PA AB ⊥,PA AB =,3ABC π∠=,2BCA π∠=,点D ,E 分别在棱,PB PC 上,且//DE BC ,(Ⅰ)求证:BC ⊥平面PAC(Ⅱ)当D 为PB 的中点时,求AD 与平面PAC 所成的角的正弦值; (Ⅲ)是否存在点E 使得二面角A DE P --为直二面角?并说明理由.19.(本题满分12分)等差数列{}n a 的各项均为正数,13a =,前n 项和为n S ,{}n b 为等比数列, 12b =,且2232,b S = 33120b S =. (1)求n a 与n b ;(2)求数列{}n n a b 的前n 项和n T 。
20.(本小题满分12分)已知函数32()(,0)f x x ax bx c =-+++-∞在上是减函数,在(0,1)上是增函数,函数()f x 在R 上有三个零点,且1是其中一个零点。
(1)求b 的值;(2)求(2)f 的取值范围。
21.(本小题满分12分)设函数()(01)xxf x ka a a a -=->≠且是定义域为R 上的奇函数。
(1)若2(1)0,(2)(4)0f f x x f x >++->试求不等式的解集; (2)若223(1),()2()[1,)2x x f g x a a mf x -==+-+∞且在上的最小值为—2,求m 的值。
22.(本题满分12分)已知椭圆2222:1(0)x y C a b a b +=>>的离心率为3,右焦点F 也是抛物线24y x=的焦点。
(1)求椭圆方程;(2)若直线l 过点F 且与C 相交于A 、B 两点。
①若2AF FB =,求直线l 的方程;②若动点P 满足OP OA OB =+,问动点P 的轨迹能否与椭圆C 存在公共点?若存在,求出点P 的坐标;若不存在,说明理由。
第二次阶段性测试参考答案一、选择题:本大题共12个小题,每小题5分,共60分. 1—6DCDDCD 7—12CDBACB二、填空题:本大题共4个小题,每小题5分,共20分. 13.12 14.(理科)4;(文科)2 15.K ≥0; 16.②③ 三、解答题: 17.解:(1)由, ………………3分21()sin cos 2sin 2222f x x x x x x ∴=+-=+ sin(2).3x π=+………………6分故最小正周期.T π= ………………7分 (2)由222(),232k x k k πππππ-≤+≤+∈Z得5().1212k x k k ππππ-≤≤+∈Z ………………9分 故()f x 的单调递增区间为5[,]().1212k k k ππππ-+∈Z ………………10分 18.解:(法1)(Ⅰ)∵PA AC ⊥,PA AB ⊥,AC AB A = ,∴PA ⊥底面ABC ,∴PA ⊥BC.又90BCA ︒∠=,∴AC ⊥BC.∴BC ⊥平面PAC.(4分) (Ⅱ)∵D 为PB 的中点,DE//BC ,∴12DE BC =, 又由(Ⅰ)知,BC ⊥平面PAC ,∴DE ⊥平面PAC ,垂足为点E. ∴∠DAE 是AD 与平面PAC 所成的角,∵PA ⊥底面ABC , ∴PA ⊥AB ,又PA=AB ,∴△ABP 为等腰直角三角形, ∴AD AB =,∴在Rt △ABC 中,60ABC ︒∠=,∴12BC AB =.∴在Rt △ADE 中,sin 24DE BC DAE AD AD ∠===,∴AD 与平面PAC 所成的角的大小arcsin4.(8分) (Ⅲ)∵AE//BC ,又由(Ⅰ)知,BC ⊥平面PAC ,∴DE ⊥平面PAC ,又∵AE ⊂平面PAC ,PE ⊂平面PAC ,∴DE ⊥AE ,DE ⊥PE , ∴∠AEP 为二面角A DE P --的平面角,∵PA ⊥底面ABC ,∴PA ⊥AC ,∴90PAC ︒∠=.∴在棱PC 上存在一点E ,使得AE ⊥PC , 这时90AEP ︒∠=,故存在点E 使得二面角A DE P --是直二面角.(12分)(法2)如图,以A 为原煤点建立空间直角坐标系A xyz -,设PA a =,由已知可得(0,0,)P a ,(0,0,0)A,1(,0)2B a -,,0)C . (Ⅰ)∵(0,0,)AP a =,1(,0,0)2BC a = ,∴0AP BC ∙= ,∴BC ⊥AP .又∵90BCA ︒∠=,∴BC ⊥AC ,∴BC ⊥平面PAC.(4分) (Ⅱ)∵D 为PB 的中点,DE//BC ,∴E 为PC 的中点,∴11(,,)442D a a a -,1(0,,)42E a a ,∴又由(Ⅰ)知,BC ⊥平面PAC , ∴DE ⊥平面PAC ,垂足为点E.∴∠DAE 是AD 与平面PAC 所成的角,∵111,,,422AD a a AE a ⎛⎫⎛⎫=-= ⎪ ⎪ ⎪ ⎪⎝⎭⎝⎭ ,∴cos AD AE DAE AD AE⋅∠==⋅ , ∴AD 与平面PAC所成的角的大小arccos4。
(8分) (Ⅲ)∵AE//BC ,又由(Ⅰ)知,BC ⊥平面PAC ,∴DE ⊥平面PAC ,又∵AE ⊂平面PAC ,PE ⊂平面PAC ,∴DE ⊥AE ,DE ⊥PE , ∴∠AEP 为二面角A DE P --的平面角,∵PA ⊥底面ABC ,∴PA ⊥AC ,∴90PAC ︒∠=.∴在棱PC 上存在一点E , 使得AE ⊥PC ,这时90AEP ︒∠=,故存在点E 使得二面角A DE P --是直二面角.(12分)19.【解析】(1)设{}n a 的公差为d ,{}n b 的公比为q ,则d 为正整数,3(1)n a n d =+-,12n n b q -=依题意有23322(93)2120(6)232S b d q S b d q ⎧=+=⎨=+=⎩,即2(93)60(6)16d q d q ⎧+=⎨+=⎩,(3分)解得2,8d q =⎧⎨=⎩或者65103d q ⎧=-⎪⎪⎨⎪=⎪⎩(舍去),故32(1)21,2n n n a n n b =+-=+=。