变位齿轮机构 (2)

机械原理课程设计设计题目变位齿轮机构1设计任务及要求 ........................................................................................................ 2 2数学模型 .................................................................................................................... 2 3 程序框图 ................................................................................................................... 6 4.程序清单与运行结果 ................................................................................................ 7 5程序清单 .................................................................................................................. 11 6设计总结 .................................................................................................................. 15 7参考文献 .................................................................................................................. 16 8机构运动简图 .......................................................................... 错误！未定义书签。

9中期检查报告 .......................................................................... 错误！未定义书签。

1设计任务及要求已知:齿轮z 1=19,z 2=52,m=10,分度圆压力角20=α,齿轮为正常齿制，工作情况为闭式传动，齿轮与曲柄共轴。

要求：1) 选择变位系数21x x 、。

2) 计算该对齿轮传动的各部分尺寸。

3) 以2号图纸绘制齿轮传动的啮合图。

(1) 选择变位系数21x x 、。

(2)计算该对齿轮传动的各部分尺寸。

(3)以2号图纸绘制齿轮传动的啮合图。

2数学模型(1) 齿轮基本参数： 注：下列尺寸单位为mm模数： m=10 压力角： 20=α 齿数： 1z =19 2z =52 齿顶高系数： 0.1=*a h 齿根高系数： 25.0=*c 传动比： 12/z z i =齿顶高变动系数：y x x -+=21σ分度圆直径； 11mz d = 22mz d = 基圆直径； αc o s 11mz d b = αc o s 22mz d b =齿顶高： )(11σ-+=*x h m h a a)(22σ-+=*x h m h a a齿根高： )(11x c h m h a f -+=*)(22x c h m h a f -+=**齿顶圆直径： 1112a a h d d +=2222a a h d d +=齿根圆直径； 1112f f h d d -= 2222f f h d d -=节圆直径： αα'='c o s c o s 11d d αα'='cos cos 22d d(2) 中心距a '： 2)(21z z m a +⨯= ； a '=（a/5+1）⨯5；(3) 啮合角α'： ；)cos(2)()cos(21ααα⨯'⨯+='z z m αααinv z z x x inv +++=')/()(tan 22121；(4) 分配变位系数21x x 、； 17sin 22min≈=*αah z min 1min min 1/)(z z z h x a -=*；min 2min min 2/)(z z z h x a -=*；；αααtan 2))((2121z z inv inv x x +-'=+(5) 重合度： )]tan (tan )tan (tan [212211ααααπε'-+'-=a a z z )/(cos 1111ab a d d -=α )/(c o s 2212a b a d d -=α一般情况应保证2.1≥ε(6) 齿距： m p π=(7) 节圆齿距： αα'='c o s c o sp p(8) 基圆齿距： απc o s m p b =(9) 齿顶圆齿厚： )(2111111ααi n v i n v r r r s s a a a a --= )(2222222ααinv inv r r r s s a a a a --=一般取25.0≥a s(10)基圆齿厚：)(tan arccos )s [tan(arcco 111111111αα----=a b a b b b b d dd d d d d s s )(tan arccos )s [tan(arcco 222222222αα----=a b a b b b b d dd d d d d s s (11)分度圆齿厚： απt a n22111m x m s += απtan 22122m x m s +=（12）滑动系数1u =(2tan a α'tan α-)(1z +2z )/(2z (11z +/2z )'tan α2tan a α-)2u =(1tan a α'tan α-)(1z +2z )/(1z (1+2z /1z )'tan α1tan a α-)适当调节1u 约等于2u（13）展角： '-'=11111a r c c o s )t a n (a r c c o s d dd d b b θ '-'=22222arccos )tan(arccos d dd d b b θ （14）不发生干涉：T>=ET 1)tan (tan /tan '212'ααα--=a z zT2)t a n (t a n /t a n '121'ααα--=a z zE 1)2s i n /()(4tan 11*ααz x h a --= E 2)2s i n /()(4tan 22*ααz x h a --=3 程序框图4.程序清单与运行结果运行清单：#include"math.h"#include"stdio.h"#define z1 19#define z2 52#define t 20*3.14/180 /*yalijiao,unit:rad*/#define m 10/*moshu*/#define hax 1.0#define cx 0.25#define Zmin 17.0#define pi 3.14main(){ int a,ai; double ti; /*niehejiao*/double x1,x2,xh;double db1,db2; /*jiyuanzhijing*/double d1,d2; /*fenduyuanzhijing*/double ha1,ha2; /*chidinggao*/double hf1,hf2; /*chigengao*/double df1,df2; /*chigenyuanzhijing*/double di1,di2; /*jieyuanzhijing*/double da1,da2; /*chidingyuanzhijing*/double p; /*chiju*/double p1; /*jieyuanchiju*/double pb; /*jiyuanchiju*/double S1,S2; /*chihou*/double Sb1,Sb2; /*jiyuanchihou*/double Sa1,Sa2; /*chidinghou*/double o1,o2; /*jieyuanzhanjiao*/double e; /*chonghedu*/double y,Xmin1,Xmin2; /*y shifenlixishu*/ double cdb; /*chuandongbi*/double cgm; /*chidingaobiandongxishu*/ double u1,u2;double T1,T2,E1,E2;int j,i;a=m*(z1+z2)/2;printf("a=%d \n",a);i=a/5;ai=(i+1)*5;printf("ai=%d (mm)\n",ai);ti=acos(a*cos(t)/ai);printf("ti=%4.3f (rad)\n",ti);cdb=z2/z1;printf("\n cdb=%5.3f \n",cdb);y=0.5*(z1+z2)*(cos(t)/cos(ti)-1);printf("y=%5.3f \n",y);d1=m*z1;d2=m*z2;printf("d1=%5.3f,d2=%5.3f (mm)\n",d1,d2);db1=m*z1*cos(t);db2=m*z2*cos(t);di1=d1*cos(t)/cos(ti);di2=d2*cos(t)/cos(ti);printf("di1=%5.3f,di2=%5.3f (mm)\n",di1,di2);p=m*pi;p1=p*cos(t)/cos(ti);pb=pi*m*cos(t);printf("p=%5.3f,p1=%5.3f,pb=%5.3f \n",p,p1,pb);Xmin1=hax*(Zmin-z1)/Zmin; printf("Xmin1=%3.4f (mm)\n\n",Xmin1); Xmin2=hax*(Zmin-z2)/Zmin; printf("Xmin2=%3.4f (mm)\n\n",Xmin2); xh=0.5*(tan(ti)-ti-(tan(t)-t))*(z1+z2)/tan(t);printf("xh=x1+x2=%5.3f \n",xh);for(j=0;j<10;j++){ x1=Xmin1+0.04*j;x2=xh-x1;if(x2<Xmin2)break;cgm=xh-y;ha1=m*(hax+x1-cgm);ha2=m*(hax+x2-cgm);hf1=(hax+cx-x1)*m;hf2=(hax+cx-x2)*m;da1=d1+2*ha1;da2=d2+2*ha2;df1=d1-2*hf1;df2=d2-2*hf2;S1=0.5*pi*m+2*x1*m*tan(t);S2=0.5*pi*m+2*x2*m*tan(t);Sb1=S1*db1/d1-db1*(tan(acos(db1/db1))-acos(db1/db1)-(tan(t)-t));Sb2=S2*db2/d2-db2*(tan(acos(db2/db2))-acos(db2/db2)-(tan(t)-t));Sa1=S1*da1/d1-da1*(tan(acos(db1/da1))-acos(db1/da1)-(tan(t)-t));Sa2=S2*db2/d2-da2*(tan(acos(db2/da2))-acos(db2/da2)-(tan(t)-t));o1=tan(acos(db1/di1))-acos(db1/di1);o2=tan(acos(db2/di2))-acos(db2/di2);e=(z1*(tan(acos(db1/da1))-tan(ti))+z2*(tan(acos(db2/da2))-tan(ti)))/(2*pi);u1=((tan(acos(db2/da2))-tan(ti))*((z1+z2)/z2))/(((1+z1/z2)*tan(ti))-tan(acos(db2/da2)));u2=((tan(acos(db1/da1))-tan(ti))*((z1+z2)/z1))/(((1+z1/z2)*tan(ti))-tan(acos(db1/da1)));T1=tan(ti)-(z2/z1)*(tan(acos(db2/da2))-tan(ti));T2=tan(ti)-(z1/z2)*(tan(acos(db1/da1))-tan(ti));E1=tan(t)-(4*(hax-x1))/(z1*sin(2*t));E2=tan(t)-(4*(hax-x2))/(z2*sin(2*t));if(e>=1.2)printf("重合度满足要求\n");elseprintf("重合度不满足要求\n");if((Sa1>=0.25*m)&&(Sa2>=0.25*m))printf("齿顶厚满足要求\n");elseprintf("齿顶厚不满足要求\n");if((T1>=E1)&&(T2>=E2))printf("不发生干涉\n");elseprintf("发生干涉\n");if((Sa1>=0.25*m)&&(Sa2>=0.25*m)&&(e>1.2)&&(T1>=E1)&&(T2>=E2)){ printf("d1=%5.3f,d2=%5.3f (mm)\n",d1,d2);printf("x1=%5.3f,x2=%5.3f (mm)\n",x1,x2);printf("cgm=%5.3f \n",cgm);printf("ha1=%5.3f,ha2=%5.3f (mm)\n",ha1,ha2);printf("hf1=%5.3f,hf2=%5.3f (mm)\n",hf1,hf2);printf("da1=%5.3f,da2=%5.3f (mm)\n",da1,da2);printf("df1=%5.3f,df2=%5.3f (mm)\n",df1,df2);printf("S1=%5.3f,S2=%5.3f (mm)\n",S1,S2);printf("Sb1=%5.3f,Sb2=%5.3f (mm)\n",Sb1,Sb2);printf("Sa1=%5.3f,Sa2=%5.3f (mm)\n",Sa1,Sa2);printf("o1=%6.5f,o2=%6.5f (rad)\n",o1,o2);printf("e=%5.3f \n",e);printf("db1=%5.3f,db2=%5.3f (mm)\n",db1,db2);printf("u1=%5.3f,u2=%5.3f \n",u1,u2);printf("T1=%5.3f,T2=%5.3f (mm)\n",T1,T2);printf("E1=%5.3f,E2=%5.3f (mm)\n",E1,E2);}}}5程序清单a=355ai=360 (mm)ti=0.385 (rad)cdb=2.737y=0.500d1=190.000,d2=520.000 (mm)di1=192.676,di2=527.324 (mm)p=31.400,p1=31.842,pb=29.508Xmin1=-0.1176 (mm)Xmin2=-2.0588 (mm)xh=x1+x2=0.525重合度满足要求齿顶厚满足要求不发生干涉d1=190.000,d2=520.000 (mm)x1=-0.118,x2=0.643 (mm)cgm=0.025ha1=8.570,ha2=16.176 (mm)hf1=13.676,hf2=6.070 (mm)da1=207.139,da2=552.353 (mm)df1=162.647,df2=507.861 (mm)S1=14.844,S2=20.378 (mm)Sb1=16.607,Sb2=26.423 (mm)Sa1=7.568,Sa2=4.192 (mm)o1=0.02026,o2=0.02026 (rad)e=1.557db1=178.553,db2=488.672 (mm)u1=6.182,u2=-19.844T1=0.073,T2=0.339 (mm)E1=-0.002,E2=0.321 (mm)重合度满足要求齿顶厚满足要求不发生干涉d1=190.000,d2=520.000 (mm)x1=-0.078,x2=0.603 (mm)cgm=0.025hf1=13.276,hf2=6.470 (mm)da1=207.939,da2=551.553 (mm) df1=163.447,df2=507.061 (mm) S1=15.135,S2=20.087 (mm) Sb1=16.880,Sb2=26.149 (mm) Sa1=7.441,Sa2=4.360 (mm)o1=0.02026,o2=0.02026 (rad) e=1.555db1=178.553,db2=488.672 (mm) u1=5.305,u2=-16.564T1=0.083,T2=0.336 (mm)E1=0.011,E2=0.316 (mm)重合度满足要求齿顶厚满足要求不发生干涉d1=190.000,d2=520.000 (mm) x1=-0.038,x2=0.563 (mm)cgm=0.025ha1=9.370,ha2=15.376 (mm)hf1=12.876,hf2=6.870 (mm)da1=208.739,da2=550.753 (mm) df1=164.247,df2=506.261 (mm) S1=15.426,S2=19.796 (mm) Sb1=17.154,Sb2=25.876 (mm) Sa1=7.308,Sa2=4.525 (mm)o1=0.02026,o2=0.02026 (rad) e=1.552db1=178.553,db2=488.672 (mm) u1=4.608,u2=-14.413T1=0.093,T2=0.332 (mm)E1=0.024,E2=0.311 (mm)重合度满足要求齿顶厚满足要求不发生干涉d1=190.000,d2=520.000 (mm) x1=0.002,x2=0.523 (mm)cgm=0.025ha1=9.770,ha2=14.976 (mm)hf1=12.476,hf2=7.270 (mm)da1=209.539,da2=549.953 (mm) df1=165.047,df2=505.461 (mm) S1=15.717,S2=19.505 (mm) Sb1=17.427,Sb2=25.602 (mm)o1=0.02026,o2=0.02026 (rad) e=1.548db1=178.553,db2=488.672 (mm) u1=4.040,u2=-12.894T1=0.102,T2=0.329 (mm)E1=0.037,E2=0.307 (mm)重合度满足要求齿顶厚满足要求不发生干涉d1=190.000,d2=520.000 (mm) x1=0.042,x2=0.483 (mm)cgm=0.025ha1=10.170,ha2=14.576 (mm) hf1=12.076,hf2=7.670 (mm)da1=210.339,da2=549.153 (mm) df1=165.847,df2=504.661 (mm) S1=16.008,S2=19.214 (mm) Sb1=17.701,Sb2=25.329 (mm) Sa1=7.022,Sa2=4.843 (mm)o1=0.02026,o2=0.02026 (rad) e=1.544db1=178.553,db2=488.672 (mm) u1=3.568,u2=-11.763T1=0.112,T2=0.326 (mm)E1=0.050,E2=0.302 (mm)重合度满足要求齿顶厚满足要求不发生干涉d1=190.000,d2=520.000 (mm) x1=0.082,x2=0.443 (mm)cgm=0.025ha1=10.570,ha2=14.176 (mm) hf1=11.676,hf2=8.070 (mm)da1=211.139,da2=548.353 (mm) df1=166.647,df2=503.861 (mm) S1=16.299,S2=18.923 (mm) Sb1=17.974,Sb2=25.055 (mm) Sa1=6.869,Sa2=4.998 (mm)o1=0.02026,o2=0.02026 (rad) e=1.540db1=178.553,db2=488.672 (mm) u1=3.170,u2=-10.889T1=0.122,T2=0.323 (mm)重合度满足要求齿顶厚满足要求不发生干涉d1=190.000,d2=520.000 (mm) x1=0.122,x2=0.403 (mm)cgm=0.025ha1=10.970,ha2=13.776 (mm) hf1=11.276,hf2=8.470 (mm)da1=211.939,da2=547.553 (mm) df1=167.447,df2=503.061 (mm) S1=16.590,S2=18.632 (mm) Sb1=18.248,Sb2=24.782 (mm) Sa1=6.711,Sa2=5.148 (mm)o1=0.02026,o2=0.02026 (rad) e=1.535db1=178.553,db2=488.672 (mm) u1=2.830,u2=-10.192T1=0.132,T2=0.320 (mm)E1=0.076,E2=0.292 (mm)重合度满足要求齿顶厚满足要求不发生干涉d1=190.000,d2=520.000 (mm) x1=0.162,x2=0.363 (mm)cgm=0.025ha1=11.370,ha2=13.376 (mm)hf1=10.876,hf2=8.870 (mm)da1=212.739,da2=546.753 (mm) df1=168.247,df2=502.261 (mm) S1=16.881,S2=18.341 (mm) Sb1=18.521,Sb2=24.508 (mm) Sa1=6.546,Sa2=5.295 (mm)o1=0.02026,o2=0.02026 (rad) e=1.530db1=178.553,db2=488.672 (mm) u1=2.536,u2=-9.624T1=0.142,T2=0.317 (mm)E1=0.089,E2=0.288 (mm)重合度满足要求齿顶厚满足要求不发生干涉d1=190.000,d2=520.000 (mm) x1=0.202,x2=0.323 (mm)cgm=0.025ha1=11.770,ha2=12.976 (mm)hf1=10.476,hf2=9.270 (mm)da1=213.539,da2=545.953 (mm)df1=169.047,df2=501.461 (mm)S1=17.172,S2=18.050 (mm)Sb1=18.795,Sb2=24.235 (mm)Sa1=6.375,Sa2=5.439 (mm)o1=0.02026,o2=0.02026 (rad)e=1.525db1=178.553,db2=488.672 (mm)u1=2.278,u2=-9.151T1=0.152,T2=0.314 (mm)E1=0.102,E2=0.283 (mm)重合度满足要求齿顶厚满足要求不发生干涉d1=190.000,d2=520.000 (mm)x1=0.242,x2=0.283 (mm)cgm=0.025ha1=12.170,ha2=12.576 (mm)hf1=10.076,hf2=9.670 (mm)da1=214.339,da2=545.153 (mm)df1=169.847,df2=500.661 (mm)S1=17.463,S2=17.759 (mm)Sb1=19.068,Sb2=23.961 (mm)Sa1=6.199,Sa2=5.579 (mm)o1=0.02026,o2=0.02026 (rad)e=1.519db1=178.553,db2=488.672 (mm)u1=2.052,u2=-8.752T1=0.162,T2=0.311 (mm)E1=0.116,E2=0.278 (mm)Press any key to continue6设计总结、通过此次课程设计，我对机械设计和制造有了深入的了解，对本专业的有了更深入的了解。