全国II高考真题十分钟练2015

2015年普通高等学校招生全国统一考试(新课标II)英语本试卷分第Ⅰ卷（选择题）和第Ⅱ卷（非选择题）两部分。

考试结束后，将本试卷和答题卡一并交回。

第Ⅰ卷注意事项：1. 答第Ⅰ卷前，考生务必将自己的姓名、准考证号填写在答题卡上。

2. 选出每小题答案后，用铅笔把答题卡上对应题目的答案标号涂黑。

如需改动，用橡皮擦干净后，再选涂其他答案标号。

不能答在本试卷上，否则无效。

第一部分听力（共两节，满分30分）做题时，现将答案标在试卷上，录音内容结束后，你将有两分钟的时间将试卷上的答案转涂到答题卡上。

第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话，每段对话后有一个小题。

从题中所给的A,B,C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

例：How much is the shirt?A. £ 19.15B. £ 9.18C. £ 9.15答案是C。

1. 1. What time is it now?A. 9:10B. 9:50C. 10:002. What does the woman think of the weather?It’s nice. It’s warm It’s cold.3. What will the man do?A. Attend a meeting.B. Give a lectureC. Leave his office.4. What is the woman’s opinion about the course?A. Too hardB. Worth taking.C. Very easy.5. What does the woman want the man to do?A. Speak louderB. Apologize to her.C. Turn off the radio.第二节（共15小题；每小题1.5分，满分22.5分）听下面5短话或独白，没段话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

2015年高考真题全国新课标卷II文综地理部分及详细答案解析（高清2015普通高等学校招生全国统一考试注意事项： 1.本试卷分第Ⅰ卷和第Ⅱ卷两部分。

答题前，考生务必在将自己的姓名、考生号填写在答题卡上。

2. 回答第Ⅰ卷时，选出每小题选出答案后，用铅笔把答题卡上对应题目的答案标号涂黑，如需改动，用橡皮擦干净后，再选涂其他答案标号。

写在试卷上无效。

3. 回答第Ⅱ卷时，将答案卸载答题卡上，写在试卷上无效。

4. 考试结束，将本试卷和答题卡一并交回。

第Ⅰ卷本卷共35小题。

每小题4分，共140分。

在每个小题给出的四个选项中，只有一项是符合题目要求的。

桑基、蔗基、菜基鱼塘是珠江三角洲地区传统的农业景观和被联全国推介的典型生态循环农业模式。

改革开放以来，随着工业化和城镇化的快速发展，传统的基墉农业用地大部分变为建设用地。

保留下来的基塘也变以花卉、菜基为主。

据此完成1－3题1、该地基塘转就以为建设用地对局地气候的影响是A、大气湿度增高B、大气降水增多C、近地面风速增大D、气温变率增大2、农民用花基、菜基鱼塘取代桑基、蔗基的直接目的是A、提高土壤质量B、节省劳动力C、促进生态循环D、提高经济收入3、桑基、蔗基鱼塘被保留的很少，反映了该生态循环农业模式A、与当地产业发展方向不一致B、不具有在其他地区推广的价值C、与现代农业发展要求不相符D、不适应当地水热条件的变化2013且7月30日，我国西北某地出出沙尘暴，图Ⅰ示意该地当日14时－24时气温、气压随时间的变化。

据此完成4－5题。

4、强沙尘暴经过该地时间段是A．16时－17时 B .17时－18时C．18时－19时 D. 19时－20时5、与正常情况相比，强沙尘暴经过时，该地A．气温水平差异减小B 水平气压梯度增大C．地面吸收太阳辐射增多 D 大气逆辐射减弱1996年我国与M国签订海洋渔业发展合作规划，至2010年我国有20多家沿海渔业企业在M国从事渔业捕捞和渔业产品加工工，产品除满足M国需求外，还远销其他国家，图2示意M国的位置，据此完成6－8题6、中资企业在M国从事渔业捕捞和渔业产品加工的主要目的是A、满足我国需求B、拓展国际市场C、提高技术水平D、增加当地就业7、如考虑运输成本，在下列国家中，M国中资企业的产品首先应销往： A. 美国B.日本C.澳大利亚D.法国8、如果都以当地时间8：00-12：00和14：00-18：00作为工作时间，在M国的中资企业若在双方工作时间内向其总部汇报业务，应选在当时时间的A、8：00—9：00 B 、11：00—12：00 C 、14：00—15：00 D、17：00—18：00 圣劳伦斯河是一条著名的“冰冻之河”。

2015年高考全国新课标卷Ⅱ理科数学真题一、选择题1、已知集合A={–2,–1,0,1,2}，B={x|(x –1)(x+2)<0}，则A∩B=() A ．{–1,0} B ．{0,1} C ．{–1,0,1} D ．{0,1,2}2、若a 为实数，且(2+ai)(a –2i)=–4i ，则a=() A ．–1 B ．0 C ．1 D ．23、根据下面给出的2004年至2013年我国二氧化硫排放量(单位：万吨)柱形图，以下结论中不正确的是()A ．逐年比较，2008年减少二氧化硫排放量的效果最显着B ．2007年我国治理二氧化硫排放显现成效C ．2006年以来我国二氧化硫排放量呈减少趋势D ．20064、已知等比数列{a n }满足a 1=3，a 1+a 3+a 5=21，则A ．21 B ．42 C ．63 D ．84 5、设函数f(x)=，则f(–2)+f(log 212)=() A ．3 B ．6 C ．9 D ．12 6.一个正方体被一个平面截去一部分后，分体积的比值为()A ．B ．C ．D ．7、过三点A ．2 8、如上左2a=() A ．0 9、已知A ，C 为该球上的动点，若三棱锥O –ABC 的体积最大值为36A ．36π．256π10、如上左O 是AB 的中点，点P 沿着边BC ，CD 与DA 运动，记∠BOP=x x 的函数，则y=f(x)的图像大致为()A ．B ．C ．D ． 11、已知A ，B 为双曲线E 的左，右顶点，点M 在E 上，△ABM 为等腰三角形，且顶角为120°，则E 的离心率为()A ．B ．2C ．D ．12、设函数f’(x)是奇函数f(x)(x R)的导函数，f(–1)=0，当x>0时，xf’(x)–f(x)<0,则使得f(x)>0成立的x 的取值范围是() A ．(–∞,–1)∪(0,1) B ．(,0)∪(1,+∞)C ．(–∞,–1)∪(–1,0) D ．(,1)∪(1,+∞) 二、填空题13、设向量a,b 不平行，向量λa+b 与a+2b 平行，则实数λ=． 14、若x ，y 满足约束条件，则z=x+y 的最大值为．15、(a+x)(1+x)4的展开式中x 的奇数次幂项的系数之和为32，则a=．16、设S n 是数列{a n }的前n 项和，且a 1=–1，a n+1=S n S n+1，则S n =________________． 三、解答题17、△ABC 中，D 是BC 上的点，AD 平分∠BAC，△ABD 面积是△ADC 面积的2倍． (1)求．(2)若AD=1，DC=，求BD 和AC 的长．18.某公司为了了解用户对其产品的满意度，从A ，B 两地区分别随机抽查了20个用户，得到用户对产品的满意度评分如下： A 地区：62738192958574645376 78869566977888827689B 地区：73836251914653736482 93486581745654766579(1)均值及分散程度(记事件C ：“A 地区用户的满意等级高于B 19、如图，长方形ABCD –A 1B 1C 1D 1中，AB=16，BC=101F=4．过点E ，F 的平面α(1)在途中画出这个正方形(不必说明画法和理由(2)求直线AF 与α平面所成角的正弦值．20、已知椭圆C ：9x 2+y 2=M 2(m>0)．直线l A ，B ，线段AB 的中点为M ．(1)(2)若l l 的21、设函数(1)证明：(2)2)|≤e –1，求m 的取值范围．22、[选修4ABC 内一点，⊙O 与△ABC 的底边BC 交于M ，N E ，F 两点． (1)(2)若AG EBCF 的面积． 23、[选修4xOy 中，曲线C 1：(t 为参数，t≠0)，其中0≤α<π． 在以O C 2：ρ=2sinθ，C 3：ρ=2cosθ． (1)求C 2与C (2)若C 1与C 2相交于点A ，C 1与C 3相交于点B ，求|AB|的最大值24、[选修4–5：不等式选讲]设a ，b ，c ，d 均为正数，且a+b=c+d ，证明： (1)若ab>cd ，则+>+；(2)+>+是|a –b|<|c –d|的充要条件． 2015年高考全国新课标卷Ⅱ理科数学真题 一、选择题1、答案：A ．∵(x–1)(x+2)<0，解得–2<x<1，∴B={x|–2<x<1}，∴A∩B={–1,0}．2、答案：B ．∵(2+ai)(a–2i)=(2a+2a)+(a 2–4)i=–4i ，∴a 2–4=–4，解得a=0．3、答案：D ．由柱形图得，从2006年以来，我国二氧化硫排放量呈下降趋势，故年排放量与年份负相关．4、答案：B ．∵a 1+a 3+a 5=a 1+a 1q 2+a1q 4=3(1+q 2+q 4)=21，∴1+q 2+q 4=7，整理得(q 2+3)(q 2–2)=0．解得q 2=2，∴a 3+a 5+a 7=a 1q 2+a 1q 4+a 1q 6=a 1q 2(1+q 2+q 4)=3×2×7=42． 5、答案：C ．∵f(–2)=1+log 2(2+2)=3，()222log 121log 3log 412log 1222f -+-==222log 3log 2log 6226+===，∴f(–2)+f(log 212)=9．6、答案：D ．如图所示截面为ABC ，设边长为a ，则截取部分体积为S △ADC ·|DB|=a 3， 所以截去部分体积与剩余部分体积的比值为=．7、答案：C ．由题可得，解得，所以圆方程为x 2+y 2–2x+4y –20=0，令x=0，解得y=–2±2， 所以|MN|=|–2+2–(–2–2)|=4． 8、答案：B ．输入a=14，b=18．第一步a≠b 成立，执行a>b ，不成立执行b=b –a=18–14=4； 第二步a≠b第三步a≠b 第四步a≠b 第四步a≠b 第五步a≠b 9、答案：C 点C 到平面10、答案：当点P 在CD 当x=时，从点P B ． 11、答案：过点M 作， 12、答案：因为当x>0 又因为函数且g(–， 二、填空题131415、答案：所以Ca+Ca+C+C+C=32，解得a=3．16、答案：–．∵a n+1=S n+1–S n =S n S n+1，∴–=1．即–=–1，∴{}是等差数列， ∴=–(n –1)=–1–n+1=–n ，即S n =–． 三、解答题17、答案：(1)；(2)|BD|=，|AC|=1．(1)如图，由题意可得S △ABD =|AB||AD|sin ∠BAD，S △ADC =|AC||AD|sin ∠CAD， ∵S △ABD =2S △ADC ，∠BAD=∠DAC，∴|AB |=2|AC|，∴==． (2)设BC 边上的高为h ，则S △ABD =|BD|·h=2S △ADC =2××h ，解得|BD|=，设|AC|=x ，|AB|=2x ，则cos ∠BAD=，cos ∠DAC=．∵cos∠DAC=cos ∠BAD ，∴=，解得x=1或x=–1(舍去)．∴|AC|=1． 18、(1)如图所示．通过茎叶图可知A 地区的平均值比B 地区的高，A地区的分散程度大于B地区．(2)记事件不满意为事件A1，B1，满意为事件A2，B2，非常满意为事件A3，B3．则由题意可得P(A1)=，P(A2)=，P(A3)=，P(B1)=，P(B2)=，P(B3)=，则P(C)=P(A2)P(B1)+P(A3)(P(B1)+P(B2))=×+×(+)=．19、(1)如图所示(2)建立空间直角坐标系．由题意和(1)可得A(10,0,0)，F(0,4,8)，E(10,4,8)，G(10,10,0)，则向量AF=(–10,4,8)，EF=(–10,0,0)，EG=(0,6,–8)．设平面EFHG的一个法向量为n=(x,y,z)，则，即，解得x=0，令y=4，z=3，则n=(0,4,3)．所以直线AF与α平面所成角的正弦值为sinθ=|cos<AF,n>|===．20、(1)设直线l的方程为y=kx+b(k≠0)，点A(x1,y1)，B(x2,y2)，则M(,)，联立方程，消去y整理得(9+k2)x2+2kbx+b2–m2=0(*)，∴x1+x2=–，y1+y2=k(–)+2b=，∴kOM ·kAB=·k=·(–)·k=–9．k=4±，有21∴∴，所以此时当令e–m–2m 在而．当当22则∵．在在Rt△AEO中，sin∠OAE===．∴∠OAE=60°，∵∠OAE=∠OAF=∠EAF，AE=AF，∴∠EAF=2∠OAE=60°，∴△AEF、△ABC是等边三角形．连接OM，∴OM=2．∵OD⊥MN，∴MD=ND=MN=．在Rt△ODM中，OD===1，∴AD=OA+AD=4+1=5．在Rt△ADB中，AB===．∴四边形EBCF的面积为S△ABC –S△AEF=×()2–×(2)2=．23、(1)将曲线C2，C3化为直角坐标系方程C2：x2+y2–2y=0，C3：x2+y2–2x=0．联立，解得或．所以交点坐标为(0,0)，(,)．(2)曲线C1的极坐标方程为θ=α(ρ∈R，ρ≠0)，其中0≤α<π．∵A的极坐标为(2sinα,α)，B的极坐标为(2cosα,α)．∴|AB|=|2sinα–2 cosα|=4|sin(α–)|．当α=时，|AB|取得最大值，最大值为4．24、(1)由题意可得(+)2=a+b+2，(+)2=c+d+2，∵ab>cd，∴>，而a+b=c+d，∴(+)2>(+)2，即+>+．(2)+>+，即a+b+2>c+d+2，∴>，∴ab>cd，∴–4ab<–4cd，∴(a+b)2–4ab<(c+d)2–4cd，∴(a–b)2<(c–d)2，∴|a–b|<|c–d|．。

2015年普通高等学校招生全国统一考试(课标全国卷Ⅱ)一、选择题1.A 因为B={x|(x-1)(x+2)<0}={x|-2<x<1},A={-2,-1,0,1,2},故A∩B={-1,0}.选A.2.B ∵(2+ai)(a -2i)=-4i ⇒4a+(a 2-4)i=-4i, ∴{4a =0,a 2-4=-4,解得a=0. 3.D 由柱形图可知:A 、B 、C 均正确,2006年以来我国二氧化硫年排放量在逐渐减少,所以排放量与年份负相关,∴D 不正确.4.B 设{a n }的公比为q,由a 1=3,a 1+a 3+a 5=21得1+q 2+q 4=7,解得q 2=2(负值舍去).∴a 3+a 5+a 7=a 1q 2+a 3q 2+a 5q 2=(a 1+a 3+a 5)q 2=21×2=42. 5.C ∵-2<1,∴f(-2)=1+log 2[2-(-2)]=3;∵log 212>1, ∴f(log 212)=2log 212-1=2log 26=6.∴f(-2)+f(log 212)=9.6.D 如图,由已知条件可知,截去部分是以△ABC 为底面且三条侧棱两两垂直的正三棱锥D-ABC.设正方体的棱长为a,则截去部分的体积为16a 3,剩余部分的体积为a 3-16a 3=56a 3.它们的体积之比为15.故选D.评析 本题主要考查几何体的三视图和体积的计算,考查空间想象能力. 7.C 设圆心为P(a,b),由点A(1,3),C(1,-7)在圆上,知b=3-72=-2.再由|PA|=|PB|,得a=1.则P(1,-2),|PA|=√(1-1)2+(3+2)2=5,于是圆P 的方程为(x-1)2+(y+2)2=25.令x=0,得y=-2±2√6,则|MN|=|(-2+2√6)-(-2-2√6)|=4√6. 8.B 开始:a=14,b=18, 第一次循环:a=14,b=4; 第二次循环:a=10,b=4; 第三次循环:a=6,b=4; 第四次循环:a=2,b=4;第五次循环:a=2,b=2. 此时,a=b,退出循环,输出a=2.评析 熟悉“更相减损术”对理解框图所确定的算法有帮助. 9.C ∵S △OAB 是定值,且V O-ABC =V C-OAB ,∴当OC⊥平面OAB 时,V C-OAB 最大,即V O-ABC 最大.设球O 的半径为R,则(V O-ABC )max =13×12R 2×R=16R 3=36,∴R=6,∴球O 的表面积S=4πR 2=4π×62=144π.评析 点C 是动点,如果以△ABC 为底面,则底面面积与高都是变量,因此转化成以△OAB 为底面(S △OAB 为定值),这样高越大,体积越大.10.B 当点P 与C 、D 重合时,易求得PA+PB=1+√5;当点P 为DC 的中点时,有OP⊥AB,则x=π2,易求得PA+PB=2PA=2√2.显然1+√5>2√2,故当x=π2时, f(x)没有取到最大值,则C 、D 选项错误.当x∈[0,π4)时, f(x)=tan x+√4+tan 2x ,不是一次函数,排除A,故选B.11.D 设双曲线E 的标准方程为x 2a2-y 2b 2=1(a>0,b>0),则A(-a,0),B(a,0),不妨设点M 在第一象限内,则易得M(2a,√3a),又M 点在双曲线E 上,于是(2a )2a 2-(√3a )2b 2=1,解得b 2=a 2,∴e=√1+b 2a 2=√2. 12.A 令g(x)=f (x )x,则g'(x)=xf '(x )-f (x )x 2,由题意知,当x>0时,g'(x)<0,∴g(x)在(0,+∞)上是减函数.∵f(x)是奇函数, f(-1)=0,∴f(1)=-f(-1)=0, ∴g(1)=f (1)1=0,∴当x∈(0,1)时,g(x)>0,从而f(x)>0; 当x∈(1,+∞)时,g(x)<0,从而f(x)<0. 又∵g(-x)=f (-x )-x=-f (x )-x=f (x )x=g(x),∴g(x)是偶函数,∴当x∈(-∞,-1)时,g(x)<0,从而f(x)>0; 当x∈(-1,0)时,g(x)>0,从而f(x)<0. 综上,所求x 的取值范围是(-∞,-1)∪(0,1).评析 出现xf '(x)+f(x)>0(<0)时,考虑构造函数F(x)=xf(x),出现xf '(x)-f(x)>0(<0)时,考虑构造函数g(x)=f (x )x.二、填空题 13.答案 12解析 由于a,b 不平行,所以可以以a,b 作为一组基底,于是λa+b 与a+2b 平行等价于λ1=12,即λ=12. 14.答案 32解析 作出可行域,如图:由z=x+y 得y=-x+z,当直线y=-x+z 过点A (1,12)时,z 取得最大值,z max =1+12=32. 15.答案 3解析 设f(x)=(a+x)(1+x)4,则其所有项的系数和为f(1)=(a+1)·(1+1)4=(a+1)×16,又奇数次幂项的系数和为12[f(1)-f(-1)],∴12×(a+1)×16=32,∴a=3. 评析 二项展开式问题中,涉及系数和的问题,通常采用赋值法. 16.答案 -1n解析 ∵a n+1=S n+1-S n ,∴S n+1-S n =S n+1S n ,又由a 1=-1,知S n ≠0,∴1S n-1Sn+1=1,∴{1S n}是等差数列,且公差为-1,而1S 1=1a 1=-1,∴1S n=-1+(n-1)×(-1)=-n,∴S n =-1n .三、解答题17.解析 (Ⅰ)S △ABD =12AB·ADsin∠BAD, S △ADC =12AC·ADsin∠CAD.因为S △ABD =2S △ADC ,∠BAD=∠CAD,所以AB=2AC. 由正弦定理可得sin∠B sin∠C =AC AB =12.(Ⅱ)因为S △ABD ∶S △ADC =BD∶DC,所以BD=√2. 在△ABD 和△ADC 中,由余弦定理知AB 2=AD 2+BD 2-2AD·BDcos∠ADB, AC 2=AD 2+DC 2-2AD·DCcos∠ADC. 故AB 2+2AC 2=3AD 2+BD 2+2DC 2=6. 由(Ⅰ)知AB=2AC,所以AC=1.评析 本题考查正弦定理,余弦定理的应用,以及三角形的面积公式.属常规题,中等偏易. 18.解析 (Ⅰ)两地区用户满意度评分的茎叶图如下:A 地区B 地区4 6 8 35 1 36 4 6 4 2 6 2 4 5 5 6 8 8 6 437 3 3 4 6 9 9 2 8 6 518 3 2 1 7 5 5 2 9 1 3通过茎叶图可以看出,A 地区用户满意度评分的平均值高于B 地区用户满意度评分的平均值;A 地区用户满意度评分比较集中,B 地区用户满意度评分比较分散. (Ⅱ)记C A1表示事件:“A 地区用户的满意度等级为满意或非常满意”; C A2表示事件:“A 地区用户的满意度等级为非常满意”; C B1表示事件:“B 地区用户的满意度等级为不满意”; C B2表示事件:“B 地区用户的满意度等级为满意”,则C A1与C B1独立,C A2与C B2独立,C B1与C B2互斥,C=C B1C A1∪C B2C A2. P(C)=P(C B1C A1∪C B2C A2) =P(C B1C A1)+P(C B2C A2) =P(C B1)P(C A1)+P(C B2)P(C A2).由所给数据得C A1,C A2,C B1,C B2发生的频率分别为1620,420,1020,820,故P(C A1)=1620,P(C A2)=420,P(C B1)=1020,P(C B2)=820, P(C)=1020×1620+820×420=0.48.19.解析 (Ⅰ)交线围成的正方形EHGF 如图:(Ⅱ)作EM⊥AB,垂足为M,则AM=A 1E=4,EM=AA 1=8. 因为EHGF 为正方形,所以EH=EF=BC=10. 于是MH=√EH 2-EM 2=6,所以AH=10.以D 为坐标原点,DA ⃗⃗⃗⃗⃗ 的方向为x 轴正方向,建立如图所示的空间直角坐标系D-xyz,则A(10,0,0),H(10,10,0),E(10,4,8),F(0,4,8),FE ⃗⃗⃗⃗⃗ =(10,0,0),HE ⃗⃗⃗⃗⃗⃗ =(0,-6,8). 设n=(x,y,z)是平面EHGF 的法向量, 则{n ·FE ⃗⃗⃗⃗ =0,n ·HE ⃗⃗⃗⃗⃗ =0,即{10x =0,-6y +8z =0,所以可取n=(0,4,3).又AF ⃗⃗⃗⃗⃗ =(-10,4,8),故|cos<n,AF ⃗⃗⃗⃗⃗ >|=|n ·AF ⃗⃗⃗⃗⃗||n ||AF ⃗⃗⃗⃗⃗ |=4√515. 所以AF 与平面EHGF 所成角的正弦值为4√515. 评析 本题背景常规,设问新颖,鼓励动手试验、创新尝试、独立思考.对空间想象力有较高要求.20.解析 (Ⅰ)设直线l:y=kx+b(k≠0,b≠0),A(x 1,y 1),B(x 2,y 2),M(x M ,y M ). 将y=kx+b 代入9x 2+y 2=m 2得(k 2+9)x 2+2kbx+b 2-m 2=0,故 x M =x 1+x 22=-kb k 2+9,y M =kx M +b=9bk 2+9.于是直线OM 的斜率k OM =yM x M=-9k ,即k OM ·k=-9. 所以直线OM 的斜率与l 的斜率的乘积为定值. (Ⅱ)四边形OAPB 能为平行四边形.因为直线l 过点(m3,m),所以l 不过原点且与C 有两个交点的充要条件是k>0,k≠3. 由(Ⅰ)得OM 的方程为y=-9k x. 设点P 的横坐标为x P .由{y =-9k x ,9x 2+y 2=m 2得x P 2=k 2m29k 2+81,即x P =3√k 2+9.将点(m 3,m)的坐标代入l 的方程得b=m (3-k )3,因此x M =k (k -3)m3(k 2+9).四边形OAPB 为平行四边形当且仅当线段AB 与线段OP 互相平分,即x P =2x M . 于是3√k 2+9=2×k (k -3)m 3(k 2+9),解得k 1=4-√7,k 2=4+√7.因为k i >0,k i ≠3,i=1,2,所以当l 的斜率为4-√7或4+√7时,四边形OAPB 为平行四边形. 评析 本题考查直线与圆锥曲线的位置关系,设问常规,但对运算能力要求较高,考查学生的思维能力.21.解析 (Ⅰ)f '(x)=m(e mx-1)+2x.若m≥0,则当x∈(-∞,0)时,e mx -1≤0, f '(x)<0; 当x∈(0,+∞)时,e mx-1≥0, f '(x)>0. 若m<0,则当x∈(-∞,0)时,e mx-1>0, f '(x)<0; 当x∈(0,+∞)时,e mx-1<0, f '(x)>0.所以, f(x)在(-∞,0)单调递减,在(0,+∞)单调递增.(Ⅱ)由(Ⅰ)知,对任意的m, f(x)在[-1,0]单调递减,在[0,1]单调递增,故f(x)在x=0处取得最小值.所以对于任意x 1,x 2∈[-1,1],|f(x 1)-f(x 2)|≤e -1的充要条件是{f (1)-f (0)≤e -1,f (-1)-f (0)≤e -1, 即{e m -m ≤e -1,e -m +m ≤e -1.① 设函数g(t)=e t-t-e+1,则g'(t)=e t-1.当t<0时,g'(t)<0;当t>0时,g'(t)>0.故g(t)在(-∞,0)单调递减,在(0,+∞)单调递增. 又g(1)=0,g(-1)=e -1+2-e<0,故当t∈[-1,1]时,g(t)≤0. 当m∈[-1,1]时,g(m)≤0,g(-m)≤0,即①式成立; 当m>1时,由g(t)的单调性,g(m)>0,即e m-m>e-1; 当m<-1时,g(-m)>0,即e -m+m>e-1. 综上,m 的取值范围是[-1,1].22.解析 (Ⅰ)由于△ABC 是等腰三角形,AD⊥BC,所以AD 是∠CAB 的平分线. 又因为☉O 分别与AB,AC 相切于点E,F,所以AE=AF, 故AD⊥EF. 从而EF∥BC.(Ⅱ)由(Ⅰ)知,AE=AF,AD⊥EF,故AD 是EF 的垂直平分线.又EF 为☉O 的弦,所以O 在AD 上.连结OE,OM,则OE⊥AE.由AG 等于☉O 的半径得AO=2OE,所以∠OAE=30°. 因此△ABC 和△AEF 都是等边三角形. 因为AE=2√3,所以AO=4,OE=2. 因为OM=OE=2,DM=12MN=√3,所以OD=1. 于是AD=5,AB=10√33. 所以四边形EBCF的面积为12×(10√33)2×√32-12×(2√3)2×√32=16√33. 23.解析 (Ⅰ)曲线C 2的直角坐标方程为x 2+y 2-2y=0,曲线C 3的直角坐标方程为x 2+y 2-2√3x=0.联立{x 2+y 2-2y =0,x 2+y 2-2√3x =0,解得{x =0,y =0,或{x =√32,y =32.所以C 2与C 3交点的直角坐标为(0,0)和(√32,32).(Ⅱ)曲线C 1的极坐标方程为θ=α(ρ∈R,ρ≠0),其中0≤α<π. 因此A 的极坐标为(2sin α,α),B 的极坐标为(2√3cos α,α). 所以|AB|=|2sin α-2√3cos α|=4|sin (α-π3)|.当α=5π6时,|AB|取得最大值,最大值为4.24.解析 (Ⅰ)因为(√a +√b )2=a+b+2√ab ,(√c +√d )2=c+d+2√cd , 由题设a+b=c+d,ab>cd 得(√a +√b )2>(√c +√d )2. 因此√a +√b >√c +√d .(Ⅱ)(i)若|a-b|<|c-d|,则(a-b)2<(c-d)2, 即(a+b)2-4ab<(c+d)2-4cd. 因为a+b=c+d,所以ab>cd. 由(Ⅰ)得√a +√b >√c +√d .(ii)若√a +√b >√c +√d ,则(√a +√b )2>(√c +√d )2,即a+b+2√ab>c+d+2√cd.因为a+b=c+d,所以ab>cd.于是(a-b)2=(a+b)2-4ab<(c+d)2-4cd=(c-d)2.因此|a-b|<|c-d|.综上,√a+√b>√c+√d是|a-b|<|c-d|的充要条件.。

2015年高考全国卷2英语试题第Ⅰ卷第一部分听力（共两节，满分30分）略第二部分阅读理解（共两节，满分40分）AMy color television has given me nothing but a headache. I was able to buy it a little over a year ago because I had my relatives give me money for my birthday instead of clothes that wouldn’t fit. I let a salesclerk fool me into buying a discontinued model. I realized this a day later, when I saw newspaper advertisements for the set at seventy-five dollars less than I had paid. The set worked so beautiful when I first got it home that I would keep it on until stations signed off for the night. Fortunately, I didn’t get any channels showing all-night movies or I would never have gotten to bed.Then I started developing a problem with the set that involved static(静电) noise. For some reason, when certain shows switched into a commercial, a loud noise would sound for a few seconds. Gradually, this noise began to appear during a show, and to get rid of it, I had to change to another channel and then change it back. Sometimes this technique would not work, and I had to pick up the set and shake it to remove the sound. I actually began to build up my arm muscles(肌肉) shaking my set.When neither of these methods removed the static noise, I would sit helplessly and wait for the noise to go away. At last I ended up hitting the set with my first, and it stopped working altogether. My trip to the repair shop cost me $62, and the sit is working well now, but I keep expecting more trouble.21. Why did the author say he was fooled into buying the TV set?A.He got an older model than he had expected.B.He couldn’t return it when it was broken.C.He could have bought it at a lower price.D.He failed to find any movie shows on it.【参考答案】C【考查内容】细节理解题【解析思路】根据第一段第四行“when I saw newspaper advertisements for the set at seventy-five dollars less than I had paid.”当我看到报纸上75美元比我买的价格低的时候，我感觉我上当了。

2015年普通高等学校招生全国统一考试英语（课标卷II）第Ⅰ卷第一部分阅读理解（共两节，满分40分）第一节（共15小题：每小题2分，满分30分）阅读下列短文，从每题所给的四个选项（A、B、C和D）中，选出最佳选项。

AMy color television has given me nothing but a headache. I was able to buy it a little over a year ago because I had my relatives give me money for my birthday instead of a lot of clothes that wouldn’t fit. I let a salesclerk fool me into buying a discontinued model. I realized this a day later, when I saw newspaper advertisements for the set at seven-five dollars less than I had paid. The set worked so beautifully when I first got it home that I would keep it on until stations signed off for the night.Fortunately, I didn’t get any channels showing all-night movies or I would never have gotten to bed.Then I started developing a problem with the set that involved static(静电) noise. For some reason, when certain shows switched into a commercial, a loud noise would sound for a few seconds. Gradully, this noise began to appear during a show, and to get rid of it, I had to change to another channel and then change it back. Sometimes this technique would not work, and I had to pick up the set and shake it to remove the sound. I actually began to build up my arm muscles(肌肉) shaking my set.When neither of these methods removed the static noise ,I would sit helplessly and wait for the noise to go away.At last I ended up hitting the set with my fist,and it stopped working altogether.My trip to the repair shop cost me $62, and the set is working well now,but I keep expecting more trouble.1. Why did the author say he was fooled into buying the TV set?A.He got an older model than he had expected.B.He couldn’t return it when it was broken.C.He could have bought it at a lower price.D.He failed to find any movie shows on it.2. Which of the followi ng can best replace the phrase”signed off”in Paragraph 1?A.ended all their programsB.provided fewer channelsC.changed to commercialsD.showed all-night movies3. How did the author finally get his TV set working again?A. By shaking and hitting it.B. By turning it on and off.C. By switching channels.D. By having it repaired.4. How does the anthor sound when telling the story?A. CuriousB. AnxiousC. CautiousD. HumorousBYour house may have an effect on your figure. Experts say the way you designyour home could play a role in whether you pack on the pounds or keep them off. You can make your environment work for you instead of against you. Here are some ways to turn your home into part of diet plan.Open the curtains and turn up the lights. Dark environments are more likely to encourage overeating , for people are often less self-conscious（难为情）when they’re in poorly lit places-and so more likely to eat lots of food . If your home d oesn’t have enough window light, get more lamps and flood the place with brightness.Mind the colors. Research suggests warm colors fuel our appetites. In one study , people who ate meals in a blue room consumed 33 percent less than those in a yellow or red room . Warm colors like yellow make food appear more appetizing , while cold colors make us feel less hungry . So when it’s time to repaint, go blue.Don’t forget the clock-or the radio. People who eat slowly tend to consume about 70 fewer calories（卡路里）per meal than those who rush through their meals. Begin keeping track of the time, and try to make dinner last at least 30 minutes. And while you’re at it, actually sit down to eat. If you need some help slowing down, turn on relaxing music. It makes you less likely to rush through a meal.Downsize the dishs. Big serving bowls and plates can easily make us fat. We eat about 22 percent more when using a 12-inch plate instead of a 10-inch plate. When we choose a large spoon over a smaller one ,total intake（摄入）jumps by 14 percent. And we’ll pour about 30 percent more liquid into a short, wide glass than a tall, skinny glass.5. The text is especially helpful for those who care about_______.A. their home comfortsB. their body shapeC. house buyingD. healthy diets6. A home environment in blue can help people_________.A.digest food betterB.reduce food intakeC.burn more caloriesD.regain their appetites7. What are people advised to do at mealtimes?A. Eat quickly.B. Play fast music.C. Use smaller spoons.D. Turn down the lights.8. What can be a suitable title for the test?A.Is Your Hourse Making You Fat?B.Ways of Serving DinnerC.Effects of Self-ConsciousnessD. Is Your Home Environment Relaxing?CMore student than ever cefore are taking a gap-year (间隔年)before going to university.It used to be called the “year off”between school and university.The gap-year phenomenon originated(起源) with the months left over to Oxbridge applicants between entrance exams in November and the start of the next academic year.This year, 25,310 students who have accepted places in higher education institutions have put off their entry until next year, according to statistics on university entrance provided by the University and College Admissions Service(UCAS).That is a record 14.7% increase in the number of students taking a gap year. Tony Higgins from UCAS said that the statistics are good news for everyone in higher education. “Students who take a well-planned year out are more likely to be satisfied with, and complete, their chosen course. Students who take a gap year are often more mature and responsible,” he said.But not everyone is happy. Owain James, the president of the National Union of Students (NUS), argued that the increase is evidence of student hadship –young people are being forced into earning money before finishing their education.“New students are now aware that they are likely to leave university up to ￡15,000 in debt. It is not surprising that more and more students are taking a gap year to earn money to support their study for the degree.NUS statistics show that over 40% of students are forced to work during term time and the figure increases to 90% during vacation periods,”he said.9. What do we learn about the gap year from the text?A. It is flexible in length.B. It is a time for relaxation.C. It is increasingly popular.D. It is required by universities.10. According to Tony Higgins, students taking a gap year______.A.are better prepared for college studiesB.know a lot more about their future jobsC.are more likely to leave university in debtD.have a better chance to enter top universities11. How does Owain James feel about the gap-year phenomenon?A. He's puzzled.B. He's worried.C. He's surprised.D. He's annoyed.12. What would most students do on their vacation according to NUS statistics?A. Attend additional courses.B. Make plans for the new term.C. Earn money for their education.D.Prepare for their graduate studies.DChoose Your One-Day Tours!Tour A-Bath & Stonchenge including entrance fees to the ancient Roman bathrooms and Stonehenge-￡37until 26 March and ￡39 thereafter.Visit the city with over 2,000 years of history and Bath Abbey,the Royal Crescent and the Costume Museum.Stonehenge is one of the world’s most famous prehistoric monuments dating back over 5,000 years.Tour B-Oxford & Stratford including entrance fees to the University St Mary’s Church Tower and Anne Hathaway's house-￡32until 12 March and -￡36 thereafter.Oxford:Includes a guided of England’s oldest university city and colleges. Look over the “city of dreaming spires(尖顶)”form St Mary’s Church Tower.Stratford:Includes a guided tour exploring much of the Shakespeare wonder. Tour C—Windsor Castle & Hampton Court including entrance fees to Hampton Court Palace-£34 until 11 March and -£37 thereafter.Includes a guided tour of Windsor and Hampton Court, Henry Vill’s favourite palace. Free time to visit Windsor Castle（entrace fees not included）. With 500 years of history, Hampton Court was once the home of four Kings and one Queen. Now this former royal palace is open to the public as a major tourist attraction. Visit the palace and its various historic gardens, which include the famous maze(迷宫)where it is easy to get lost!Tour D-Cambridge including entrance fees to the Tower of Saint Mary the Great-£33 until 18 March and £37 thereafter.Includes a guided tour of Cambridge, the famous university town, and the gardens of the 18th century.13. Which tour will you choose if you want to see England’s oldest university city?A.Tour AB.Tour BC.Tour CD.Tour D14. Which of the following tours charges the lowest fee on 17 March?A. Windsor Castle & Hampton Court.B.Oxford & StratfordC. Bath &Stonehenge.D. Cambridge.15. Why is Hampton Court a major tourist attraction?A.It used to be the home of royal families.B.It used to be a well-known mazeC.It is the oldest palace in BritainD.It is a world-famous castle.第二节（共5小题：每小题2分，满分10分）根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。

2015年普通高等学校招生全国统一考试(课标全国卷Ⅱ)第Ⅰ卷第一部分阅读理解第一节A[语篇解读]本文作者以幽默的口吻介绍了自己购买彩电后遇到的种种麻烦。

1.C推理判断题。

根据第一段中“I realized this a day later...at seventy-five dollars less than I had paid.”可知,作者之所以认为被愚弄买了电视机,是因为一天后他在看报纸的广告时得知自己多花了75美元。

故选C。

2.A词义猜测题。

根据第一段最后一句“Fortunately,I didn’t get any channels showing all-night movies or I would never have gotten to bed.”可知,画线短语的意思为“结束所有的电视节目”。

故选A。

3.D细节理解题。

根据文章最后一句话可知,最后作者不得不到维修店去修理电视机,让其重新工作。

故选D。

[评析]本题虽然属于细节理解题,但如果考生不注意审题,未抓住“finally”和“get his TV set working again”这两处关键内容,则容易误选A。

4.D推理判断题。

根据文章中多处细节及最后一句中“but I keep expecting more trouble”可判断作者以幽默的口吻叙述了自己购买彩电后遇到的种种麻烦。

故选D。

B[语篇解读]本文主要介绍了几种通过改变屋内环境进行饮食调节的方法。

5.B细节理解题。

根据文章第一句和第二句可知,本文的阅读对象主要是那些关心自己体形的人。

故选B项。

6.B细节理解题。

根据文章第三段第三句话可知,研究发现人在蓝色房间里比在黄色或红色房间里吃饭时少摄入33%的食物。

故选B。

7.C细节理解题。

根据文章最后一段第四句话可知,我们使用大的汤匙时摄入食物的总量比使用小的汤匙时摄入食物的总量多14%。

故选C。

8.A主旨大意题。

整篇文章主要介绍了几种通过改变屋内环境与设施进行饮食调节的方法。

2015·全国卷Ⅱ(英语)本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分。

第Ⅰ卷第一部分听力(共两节，满分30分)第一节(共5小题：每小题1.5分，满分7.5分)听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

例：How much is the shirt?A．￡19.15. B．￡9.18.C．￡9.15.答案是C。

1．[2015·全国卷Ⅱ] What time is it now?A．9：10. B．9：50.C．10：00.2．[2015·全国卷Ⅱ] What does the woman think of the weather?A．It's nice. B．It's warm.C．It's cold.3．[2015·全国卷Ⅱ] What will the man do?A．Attend a meeting. B．Give a lecture.C．Leave his office.4．[2015·全国卷Ⅱ] What is the woman's opinion about the course?A．Too hard. B．Worth taking.C．Very easy.5．[2015·全国卷Ⅱ] What does the woman want the man to do?A．Speak louder. B．Apologize to her.C．Turn off the radio.第二节(共15小题：每小题1.5分，满分22.5分)听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

2015年高考新课标全国卷II语文试题(一)文言文阅读(19分)阅读下面的文言文，完成4-7题。

来护儿，字崇善，未识而孤，养于世母关氏。

吴氏提携鞠养，甚有慈训。

幼儿卓荦，初读《诗》日，舍书叹曰："大丈夫在世，或为国灭贼以取功名!”群辈惊其言而壮其志。

及长，雄略秀出，志气英远。

会周师定淮南所住白土村地居疆埸数见军旅护兒常慨然有立功名之志及开皇初宇文忻等镇广陵平陈之役护兒有功焉进位上开府,赏物一千段。

仁寿初,迁瀛州刺史,以善政闻,频见劳勉。

炀帝嗣位,被追入朝,百姓攀恋,累日不能出境,诣阙上书致请者,前后数百人。

帝谓曰:“昔国步未康,卿为名将,今天下无事,又为良二千石,可谓兼美矣。

”大业六年,车驾幸江都,谓护兒曰:“衣锦昼游,古人所重,卿今是也。

”乃赐物二千段,并牛酒,令谒先人墓,宴乡里父老。

仍令三品已上并集其宅,酣饮尽日,朝野荣之。

十二年,驾幸江都,护兒谏曰:“陛下兴军旅,百姓易咨怨,车驾游幸,深恐非宜。

伏愿驻驾洛阳,与时休息。

陛下今幸江都,是臣衣锦之地,臣荷恩深重,不敢专为身谋。

”帝闻之,厉色而起,数日不得见。

后怒解,方被引入,谓曰:“公意乃尔,朕复何望!”护兒因不敢言。

及宇文化及构逆,深忌之。

是日旦将朝,见执。

护兒曰:“陛下今何在?”左右曰:“今被执矣。

”护兒叹曰:“吾备位大臣,荷国重任,不能肃清凶逆,遂令王室至此,抱恨泉壤,知复何言!”乃遇害。

护儿重然诺，敦交契，廉于财利，不事产业。

至于行军用兵，特多谋算，每览兵法，曰："此亦岂异人意也! ”善抚士卒，部分严明，故咸得其死力。

(节选自《北史·来护儿传》)4.下列对文中画波浪线部分的断句,正确的一项是(3分)A.会周师定淮南所/住白土村/地居疆埸/数见军旅护儿/常慨然有立功名之志/ 及开皇初/宇文忻等镇广陵/平陈之役/护儿有功焉/B. 会周师定淮南所/住白土村/地居疆埸/数见军旅/护儿常慨然有立功名之志/ 及开皇初/宇文忻等镇广陵/平陈之役护儿有功焉/C. 会周师定淮南/所住白土村/地居疆埸/数见军旅护儿/常慨然有立功名之志/及开皇初/宇文忻等镇广陵/平陈之役/护儿有功焉/D.会周师定淮南/所住白土村/地居疆埸/数见军旅/护儿常慨然有立功名之志及开皇初/宇文忻等镇广陵/平陈之役/护儿有功焉/【答案】D【解析】此题考查文言断句能力。

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2015年普通高等学校招生全国统一考试•全国卷Ⅱ英语(时间:120分钟分值:150分)第Ⅰ卷第一部分听力(共两节, 满分30分)第一节(共5小题; 每小题1. 5分, 满分7. 5分)听下面5段对话。

每段对话后有一个小题, 从题中所给的A、B、C三个选项中选出最佳选项, 并标在试卷的相应位置。

听完每段对话后, 你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. What time is it now?A. 9:10.B. 9:50.C. 10:00.2. What does the woman think of the weather?A. It’s nice.B. It’s warm.C. It’s cold.3. What will the man do?A. Attend a meeting.B. Give a lecture.C. Leave his office.4. What is the woman’s opinion about the course?A. Too hard.B. Worth taking.C. Very easy.5. What does the woman want the man to do?A. Speak louder.B. Apologize to her.C. Turn off the radio.第二节(共15小题; 每小题1. 5分, 满分22. 5分)听下面5段对话或独白。

每段对话或独白后有几个小题, 从题中所给的A、B、C三个选项中选出最佳选项, 并标在试卷的相应位置。

听每段对话或独白前, 你将有时间阅读各个小题, 每小题5秒钟; 听完后, 各小题给出5秒钟的作答时间。

每段对话或独白读两遍。

听第6段材料, 回答第6、7题。