2019~2020学年四川成都锦江区成都七中育才学校(水井

四川省成都市七中育才学校2019-2020学年九年级下学期3月月考英语试题学校:___________姓名：___________班级：___________考号：___________一、单项选择1．— Linda, who’s the performer on the show?— He’s my brother, ________ 11-year-old boy who loves dancing.A．a B．an C．the2．The teacher you saw in our classroom just now ________ be Mr. Wang. He has gone to Chongqing to attend a meeting.A．must B．might C．can’t3．By the end of last term, the school volleyball team ________ three prizes for our school. A．have won B．had won C．win4．In children’s mind, the father is the superhero ________ can always do everything to protect the family.A．who B．whom C．which5．Of the twin sisters, Laura is the ________ one and her face usually turns red when she talks to others.A．shyest B．shyer C．shy6．— Has Allen won a prize in the dancing competition?— Yes, ________ Allen ________ Jack has.A．both, and B．neither, nor C．not only, but also 7．You are not supposed to greet Japanese by kissing them. The greeting way in their country is different from ________.A．us B．ours C．our8．The mother ________ the radio a little, because her baby was sleeping.A．turned down B．left out C．kicked off9．The poet has drawn ________ from the nature, so he’s created many poems connected with countryside life.A．inspiration B．instructions C．courage 10．—Excuse me, I wonder ________ in the neighborhood.—Yes, there’s one McDonald’s in the shopping mall.A．where I can buy some foodB．how I can get to the restaurantC．if there’s a restaurant near here二、补全对话5选5A: How do you like the college, Allen?B: I think I like where it is and its size. It looks very small compared with our school.____11____A: Oh, the number of students in this college is only half of yours.B: ____12____A: That’s a difficult question to answer. There are all kinds. They’re difficult to describe. B: What do they do in their spare time?A: All kinds of interesting things. ____13____ Some students play sports on the playground. Some go to the library to study.B: ____14____A: Oh, yes. They play basketball, football and many more. ____15____B: Sounds great!A．Do you know what sports they play?B．There are teams for all kinds of sports.C．What kind of students can come here?D．You know, there are about 2,000 students in our school.E．There are different kinds of clubs to join, like the art club.三、完形填空After the Ministry of Education in late January announced that the 2020 spring term for schools was ____16____ nationwide due to the coronavirus (新冠病毒), many schools havestarted online courses for students to study at home. However, the online education turns out to be a ____17____ for both teachers and parents.Some teachers discover they leave the microphones off only ____18____ they finish the online course, and others are easy to be troubled by their own young children’s shouting and crying.As the schools stay ____19____, some parents complain that it’s hard for them to keep an eye on their kids especially when they are out for work. Chen Yan, a mom of a 10-year-old boy, said, “While working at the office, I often keep watching what my son’s doing at home through the camera. So far I’ve caught him doing everything ____20____ studying. He spends all the time playing video games, watching soap operas or chatting with friends.”16．A．put out B．put off C．put down 17．A．relief B．pleasure C．challenge 18．A．before B．after C．unless19．A．shut B．open C．alone 20．A．including B．besides C．exceptDo you know there is a special primary school in Yunnan province? It’s like an international school, but there are students from only one ____21____ country studying with the local students. Every morning, a number of students from Myanmar (缅甸) walk hand in hand across the border (边境) into China’s Y unnan province. They are ____22____ by policemen to Yinjing Frontier Primary School in Ruili. After school, they return to their homes in Myanmar.This is the first frontier primary school in China. The school has 36 Myanmar students and 99 Chinese students. The school began to ____23____ students from Myanmar in 1990.The students from Myanmar enjoy ____24____ in China, because they have many friendly classmates and caring teachers there. They have made many friends at school and the teachers do not ____25____ them differently because they come from a different country. The school has preschool classes and three grades (from grade one to three) and all classes are____26____ in Chinese and Burmese (缅甸语). More Myanmar parents want to send their children to the school because speaking Chinese well is ____27____ for them to work in China or do business with Chinese since China has been developing in such a rapid way.____28____, the school was not so good at first. To improve the education condition, thegovernment has spent 2.6 million yuan so far. With the help of the government, the school has also set up its own volunteer ____29____ which gets money given away by kind people from the two countries.Ruili, an important land port for southwestern China, is _____30_____ by a famous Chinese song: there is a beautiful place, which describes its natural beauty and colorful folklore. The government hopes through this way, people there and people around it can live a better life.21．A．European B．western C．foreign22．A．sold B．led C．understood 23．A．accept B．refuse C．send 24．A．ourselves B．yourselves C．themselves 25．A．divide B．treat C．tell26．A．written B．taught C．listened 27．A．important B．difficult C．interesting 28．A．Luckily B．Instead C．However 29．A．school B．company C．organization 30．A．forgotten B．described C．reminded四、阅读判断阅读下面短文，根据短文内容判断句子的正误。

2019-2020学年成都七中育才学校八年级（上）开学考数学试卷（考试时间：120分钟满分:150分）一、选择題（每小题3分，共30分） 1.下列计算正确的是（ ） A. （x+3） 2=X 2+9B. a 2∙ a 3=a 6C. 2X ^2=-⅛D. （a 2） 3=a 62X22. 人体中红细胞的述径约为0. 0000077米, 将0. 0000077用科学记数法表示为（）3.如图，AB 〃CD,若Z2=135Q ,则Zl 的度数是（） 4.以下列各组线段的长为边，能组成三角形的是（ ）5. 下列说法正确的是（） A. 抛掷一个正方体骰子，点数为奇数的概率是寺B. 买一张福利彩票一定中奖，是不可能事件C. 在地球上，上抛的篮球一定会下落，是必然事件D. 从一个装有5个黑球和1个红球的口袋中，摸出一个球是黑球是必然事件6. 若χ-3y=-5,则代数式5 - 2x+6y 的值是（） A. 0B. 5 7.下列说法正确的是（ ）A. 169的平方根是13B. -岛没有立方根1 Z ∙ D A. 7.7X10B. 7.7×10 5C. 0. 77X10D. 0. 77X10" C. 60° D. 75。

A. 2cm, 5cm> IOCnlB. 2cm, 3cm, 4cm C ・ 2cm, 3cm « 5cmD. 8cm, 4cm, 4cmC. 10D. 15 45C.正数的两个平方根互为相反数D. - （-13）没有平方根8.如图，在AABC中，ZB=90o , AC = 1O, ΛD为此三角形的一条角平分线，若BD=3,则三角形ADC的面Λ. 3 B. 10 C. 12 D. 159.两个三角形具备下列（）条件，则它们一定全等.A.两边和其中一边的对角对应相等B.两个角对应相等C.三条边对应相等D.两边及第三边上的高对应相等10.小亮从家出发步行到公交站台后，等公交车去学校，如图，折线表示这个过程中行程S （千米）与所花时间t （分）之间的关系.下列说法错误的是（）A.他家到公交车站台需行1千米B.他等公交车的时间为4分钟C.公交车的速度是500米/分D.他步行与乘公交车行驶的平均速度是300米/分二、填空题（每小题4分，共16分）11.计算（20 1 92 - 20 1 82）O= _ .12.如果x~+ （m^^l）x+l是完全平方式，则m的值为______ .13.已知，如图所示，AB=AC, AD丄BC于D,且ZkABC的周长为50cm, ∆ABD的周长为40cm,则AD= cm.C14・如图，一个长方体纸盒，它的长.宽、高分别为8cm, 4cm, 5cm,在盒顶点处A处有一只壁虎，它发现盒内其对顶角顶点B处有一只苍蝇，于是壁虎向点B爬行，则这只壁虎由A点爬行至点B的最短路径的平方为 __________ .三.解答題(共54分)15. (8分)计算：(1)-3 丄÷ ( -2)心-(n - 3・ 14) °(2) (x÷y) 2÷ (2x÷3y) (3x÷2y)416 ・(6 分)化简求值：[(x~+y~) -(x - y) '+2y (χ-y) ] ÷ (一2y),其中∣2χ-l∣ + (y+3) 2=017.(6 分)在Rt∆ΛBC 中，ZC=90o , ZΛ. ZB. ZC 的对边分别为a. b、c.若船c = 15: 17, b=24, 求a.18.（8分）如图，ΛB√CD,直线EF分别交AB、CD点E. F, EG平分ZAEF t（1）求证：AEGF是等腰三角形.（2）若Zl=40o,求Z2的度数・19.（8分）某初中对600名毕业生中考体育测试坐位体前屈成绩进行整理，绘制成如下不完整的统计图:根据统计图，下列问题.（1）请将条形统计图补充完整；（2）_____________________ 扇形统计图中，b= _______________________ ,得8分所对应扇形的圆心角度数为________________________（3）在本次调查的学生中，随机抽取1名男生，他的成绩不低于9分的概率为多少？20.（8分）一列快车从甲地驶往乙地，一列慢车从乙地驶往甲地，两车同时出发，到达目的地后停止，设慢车行驶时间为X小时，两车之间的距离为y千米，两者的关系如图所示：（1）____________ 两车出发小时后相遇；（2）求快车和慢车的速度；（3）求线段BC所表示的y与X的关系式，并求两车相距300千米时的时间.21.（10分）如图1,将两个完全相同的三角形纸片ABC和DEC重合放置，其中ZC = 90o, ZB=ZE = 30°・（1）操作发现：如图2,固定AABC,使ADEC绕点C旋转，当点D恰好落在AB边上时，填空：①线段DE与AC的位置关系是_____ ;②设ABDC的面积为0, ZXAEC的面积为S,则&与S?的数量关系是___________ •（2）猜想论证：当ADEC绕点C旋转到如图3所示的位置时，小明猜想（1）中Sl与0的数量关系仍然成立，并尝试分别作出了ABDC和AAEC中BC、CE边上的高，请你证明小明的猜想・（3）拓展探究已知ZABC = 60° ,点D是角平分线上一点，BD=CD=6, DE〃AB交BC于点E （如图4）,若在射线BA上存在点F,使S Z^F=SΛ≡,请求出相应的BF的长.'E 图2MND≡4参考答案与试題解析1.【解答】解：A、(x+3) 2=X2+6X+9,故本选项错误；B、/・a3=a2t3=a s,故本选项错误；C、2x 2=寻，故本选项错误；XD、(a2) 3=a2x3=a∖故本选项正确.故选:D.2.【解答】解：0.0000077 = 7.7X10".故选：A.3.【解答】解：VAB/7CD,若Z2=135o ,AZ2的同位角为135° .AZl = I80° - 135° =45° .故选:B.4.【解答】解：根据三角形的三边关系，得A、253<10,不能组成三角形；B、3+2>4,能够组成三角形；C、3+2=5,不能组成三角形；D、4+4=8,不能组成三角形.故选：B.5.【解答】解：A、抛掷一个正方体骰子，点数为奇数的概率是寺，故此选项错误，不合題意；B、买一张福利彩票一定中奖，是可能事件，故此选项错误，不合题意；C、在地球上，上抛的篮球一定会下落，是必然事件，正确，符合题意；D、从一个装有5个黑球和1个红球的口袋中，摸出一个球是黑球是随机事件，故此选项错误，不合题意; 故选：C.6.【解答】解：原式=5-2 (χ-3y) =5-2× ( -5) =15.故选：D.7.【解答】解：A、169的平方根是±13,故本选项错误；B、-PL有立方根，是-占，故本选项错误；125 5C、正数的两个平方根互为相反数，故本选项正确;D、- (-13) =13,有平方根，故本选项错误・故选：C.8.【解答】解：过D作DE丄AC于E.TAD 是ZBAC 的角平分线，ZB=90o (DB丄AB), DE丄AC,ABD=DE tVBD=3,∙∙∙DE=3,∙*∙SΔ.UJC=—-∙ .,∖C∙ DE=丄× 10×3=152 2故选：D.9.【解答】解：A、两边和其中一边的对角对应相等，不能判定两个三角形全等，故此选项错误；B、三个角对应相等，不能判定两个三角形全等，故此选项错误；C、三条边对应相等两个三角形全等，故此选项正确；D、两边及第三边上的高对应相等，这两边的夹角有可能一个是锐角一个是钝角，所以这两个三角形不一定全等，故此选项错误；故选：C.10.【解答】解：由函数图象可知他家到公交车站台需行1千米，他等公交车的时间= 14-10=4分钟，故A, B正确，与要求不符；公交车的速度=(5-1) ×1000÷ (22- 14) =4000÷8=500米/分，故C正确，与要求不符；他步行与乘公交车行驶的平均速度=5 X 1000 ÷ (22-4)=豎2米/分，故D错误，与要求相符.9故选:D.11.【解答】解：V20 1 92 - 20 1 82≠0,.∙. (20 1 92 - 20 1 82) °=1.故答案为：112.【解答】解：Tl+ (m-l) x+1是完全平方式，・•.(罟)2=1,即(In-I) 2=4,开方得：m- 1=2 或m-l = - 2,解得：m=3或m= 一1.故答案为：3或-1.13・【解答】解：V∆ABD的周长=ΛD÷AB÷BD=40cm,VAB=AC, AD丄BC 于D,ABD=CD,∖∙∆ΛBC 的周长=ΛC÷AB÷BD÷DC=2 (ΛB÷BD) =50cm,Λ2∆ΛBD 的周长=2 (ΛB÷BD÷AD) =80cm,Λ2AD=80 - 50=30cm,解得:∕∖D=15cm,故答案为：1514.【解答】解：如图(1)： AB2= (8+4) 2+52 = 169;(1)AB2=82+ (5÷4) 2=145;(3)如图(3)：AB2=42+ (5÷8) 2=185.V145<169<185,•••最短路径的平方为145 故答案为:145.15.【解答】解：(1) -3l→⅜-÷ ( -2) ! -( -3. 14)43+^-÷ ( -8) - 1 = 3- — - 132_,31—1—；32(2)(x+y) 2+ (2x÷3y) (3x÷2y) = x2÷2xy+y2÷6x2+13xy+6y2= 7x2÷15xy+7y2・16.【解答】解：原式=(x2+y2- x2+2Xy - y2+2xy - 2y2) ÷ ( -2y)=(4xy-2y2) ÷ ( -2y) =-2x+y,由于∣2x - 11+ (y+3) 2=0,17.【解答】解：设a=15x,则c=17x, 由勾股定理得，( 15x) 2+242= ( 17x) 2, 解得,X=3 9 则a = 15x = 45・18.【解答】（1）证明：VABZ/CD,AZl = ZAEG,TEG 平分ZAEF,∙∙∙ZΛEG=ZFEG,AZl = ZFEG,ΛFE=FG t即AEGF是等腰三角形；（2）解：VZl=40o, Z1 = ZΛEG=ZFEG,Λ ZAEF=40° +40° =80° ,ΛZ2=180o -80o =IOO O・19.【解答】解：（1）10 分的人数有600 - 20 - 10 - 40 - 20 - 80 - 70 - 180=180 （人）,补图如下:(2) 10分所占的百分比是：^.×100%=60%,600则b=60,4θθθQ=36° ;得8分所对应扇形的圆心角度数为360。

2019-2020学年四川省成都七中育才学校九年级（上）开学数学试卷一、选择题（本大题共10个小题，每小题3分，共30分，答案涂在答题卡上）1．（3分）育才校园文化博大精深，以下是“育”、“才”、“水”、“井”四字的甲骨文，其中是中心对称，但非轴对称图形的是（）A．B．C．D．2．（3分）下列各式由左边到右边的变形中，是因式分解的是（）A．a（x﹣y）＝ax﹣ay B．a2﹣b2＝（a+b）（a﹣b）C．x2﹣4x+3＝x（x﹣4）+3D．a2+1＝a（a+）3．（3分）如图，菱形ABCD的对角线AC、BD的长分别为8和6，则这个菱形的周长是（）A．20B．24C．40D．484．（3分）若分式的值为0，则x等于（）A．1B．1或﹣3C．﹣1或1D．﹣15．（3分）用配方法解方程x2+8x+9＝0，变形后的结果正确的是（）A．（x+4）2＝﹣9B．（x+4）2＝﹣7C．（x+4）2＝25D．（x+4）2＝7 6．（3分）将点（﹣3，2）先向右平移3个单位，再向下平移4个单位后与N点重合，则点N坐标为（）A．（﹣3，﹣2）B．（0，﹣2）C．（0，2）D．（﹣6，﹣2）7．（3分）如图，在Rt△ABC中，∠ACB＝90°，∠BAC＝33°，把△ABC绕点A按顺时针方向旋转∠BAC的大小，得到△AB′C′，延长BC交B′C′于点D，则∠BDC′等于（）A．147°B．143°C．157°D．153°8．（3分）如图，将两块完全相同的矩形纸片ABCD和矩形纸片AEFG按图示方式放置（点A、D、E在同一直线上），连接AC、AF、CF，已知AD＝3，DC＝4，则CF的长是（）A．5B．7C．5D．109．（3分）如图，已知AB∥CD∥EF，AD：AF＝3：5，BC＝6，CE的长为（）A．2B．4C．3D．510．（3分）如图，每个小正方形的边长均为1，则下列图形中的三角形（阴影部分）与△A1B1C1相似的是（）A．B．C．D．二、填空题（本大题共4小题，每小题4分，满分16分）11．（4分）已知多边形的内角和等于外角和的1.5倍，则这个多边形的边数为．12．（4分）已知x2﹣2xy＝6，2y2﹣xy＝5．则x2﹣4y2＝．13．（4分）已知等腰三角形的周长为29，一边长为7，则此等腰三角形的腰长为．14．（4分）如图，在Rt△ABC中，∠C＝90°，AC＝12，BC＝5，正方形CEDF按如图所示的方式放置，则该正方形的边长为．三、解答题（本大题共6小题，满分54分）15．（10分）（1）解方程：x（2x﹣3）+（3﹣2x）2＝0（2）解分式方程：16．（12分）（1）解不等式组，将解集在数轴是表示出来，并写出其最小整数集．（2）化简：（），并从2，3，4中取一个合适的数作为a的值代入求值．17．（6分）如图，在边长为1个单位长度的小正方形组成的网格中，△ABC的顶点均在格点上，点A的坐标为（2，3），点B的坐标为（3，0），点C的坐标为（0，2）．（1）以点C为旋转中心，将△ABC旋转180°后得到△A1B1C1，请画出△A1B1C1；（2）平移△ABC，使点A的对应点A2的坐标为（0，﹣1），请画出△A2B2C2．（3）若将△A1B1C1绕点P旋转可得到△A2B2C2，则点P的坐标为18．（8分）某商家预测“华为P30”手机能畅销，就用1600元购进一批该型号手机壳．面市后果然供不应求，又购进6000元的同种型号手机壳，第二批所购手机壳的数量是第一批的3倍，但进货单价比第一批贵了2元．（1）第一批手机壳的进货单价是多少元？（2）若两次购进手机壳按同一价格销售，全部售完后，为使得获利不少于2000元，那么销售单价至少为多少？19．（8分）如图，在Rt△ABC中，∠ACB＝90°，D、E分别是AB、AC的中点，延长BC 到F，使得CF＝BC，连接CD、EF．（1）求证：四边形CDEF为平行四边形；（2）若四边形CDEF的周长是32，AC＝16，求△ABC的面积；（3）在（2）的条件下，求点F到直线CD的距离．20．（10分）如图，△ABC是等腰直角三角形，∠ACB＝90°，D是射线CB上一点（点D 不与点B重合），以AD为斜边作等腰直角三角形ADE（点E和点C在AB的同侧），连接CE．（1）如图①，当点D与点C重合时，直接写出CE与AB的位置关系；（2）如图②，当点D与点C不重合时，（1）的结论是否仍然成立？若成立，请写出证明过程；若不成立，请说明理由；（3）当∠EAC＝15°时，请直接写出的值．一、填空题（每小题4分，共20分）21．（4分）若关于x的分式方程＝2a有增根，则a的值为．22．（4分）已知x2+y2＝3，xy＝，则（﹣）÷的值为．23．（4分）若直线l1：y1＝k1x+b1经过点（0，2），l2：y2＝k2x+b2经过点（3，1），且l1与l2关于x轴对称，则关于x的不等式k1x+b1＞k2x+b2的解集为．24．（4分）正方形A1B1C1A2，A2B2C2A3，A3B3C3A4，…，A n B n∁n A n+1，…按如图所示的方式放置，点A1，A2，A3，…，A n，…和点B1，B2，B3，…，B n，…分别在直线y＝kx+b（k ＞0）和x轴上．已知点A1（0，1），点B1（1，0），则C3的坐标是，∁n的坐标是．25．（4分）如图，AC，BD在AB的同侧，AC＝1，BD＝4，AB＝4，点M为AB的中点，若∠CMD＝120°，则CD的最大值是．二、解答题（共30分）26．（8分）“绿水青山就是金山银山”，为了保护环境和提高果树产量，某果农计划把68吨有机化肥运送到果园，为节省时间需要在一天之内运完．货运站有甲、乙两种货车，果农决定租用甲、乙两种货车共18辆，两种型号的货车的运输量和租金如下表（所租用货车都按一整天收费）：（1）求所付的货车租金总费用y（元）与租用甲型货车数量x（辆）的函数关系式；（2）请你帮该果农设计一种使租金总费用最少的方案，并求出所付的最少租金．27．（10分）在矩形ABCD中，AB＝6，AD＝8，E是边BC上一点，以点E为直角顶点，在AE的右侧作等腰直角△AEF．（1）如图1，当点F在CD边上时，求BE的长；（2）如图2，若EF⊥DF，求BE的长；（3）如图3，若动点E从点B出发，沿边BC向右运动，运动到点C停止，直接写出线段AF的中点Q的运动路径长．28．（12分）如图，已知长方形OABC的顶点O在坐标原点，A、C分别在x、y轴的正半轴上，顶点B（8，6），直线y＝﹣x+b经过点A交BC于D、交y轴于点M，点P是AD的中点，直线OP交AB于点E（1）求点D的坐标及直线OP的解析式；（2）求△ODP的面积，并在直线AD上找一点N，使△AEN的面积等于△ODP的面积，请求出点N的坐标（3）在x轴上有一点T（t，0）（5＜t＜8），过点T作x轴的垂线，分别交直线OE、AD 于点F、G，在线段AE上是否存在一点Q，使得△FGQ为等腰直角三角形，若存在，请求出点Q的坐标及相应的t的值；若不存在，请说明理由2019-2020学年四川省成都七中育才学校九年级（上）开学数学试卷参考答案与试题解析一、选择题（本大题共10个小题，每小题3分，共30分，答案涂在答题卡上）1．（3分）育才校园文化博大精深，以下是“育”、“才”、“水”、“井”四字的甲骨文，其中是中心对称，但非轴对称图形的是（）A．B．C．D．【分析】根据轴对称图形与中心对称图形的概念求解．【解答】解：A、不是轴对称图形，也不是中心对称图形，故此选项不合题意；B、是轴对称图形，不是中心对称图形，故此选项不合题意；C、不是轴对称图形，是中心对称图形，故此选项符合题意；D、是轴对称图形，也是中心对称图形，故此选项不合题意．故选：C．2．（3分）下列各式由左边到右边的变形中，是因式分解的是（）A．a（x﹣y）＝ax﹣ay B．a2﹣b2＝（a+b）（a﹣b）C．x2﹣4x+3＝x（x﹣4）+3D．a2+1＝a（a+）【分析】根据因式分解的定义逐个判断即可．【解答】解：A、不是因式分解，故本选项不符合题意；B、是因式分解，故本选项符合题意；C、不是因式分解，故本选项不符合题意；D、不是因式分解，故本选项不符合题意；故选：B．3．（3分）如图，菱形ABCD的对角线AC、BD的长分别为8和6，则这个菱形的周长是（）A．20B．24C．40D．48【分析】由菱形的性质可得AO＝CO＝4，BO＝DO＝3，AC⊥BD，由勾股定理可求AB ＝5，即可求菱形的周长．【解答】解：∵四边形ABCD是菱形∴AO＝CO＝4，BO＝DO＝3，AC⊥BD∴AB＝＝＝5∴这个菱形的周长＝4×5＝20故选：A．4．（3分）若分式的值为0，则x等于（）A．1B．1或﹣3C．﹣1或1D．﹣1【分析】直接利用分式的值为零则分子为零分母不等于零进而得出答案．【解答】解：若分式的值为0，则|x|﹣1＝0且（x+3）（x﹣1）≠0，解得：x＝﹣1．故选：D．5．（3分）用配方法解方程x2+8x+9＝0，变形后的结果正确的是（）A．（x+4）2＝﹣9B．（x+4）2＝﹣7C．（x+4）2＝25D．（x+4）2＝7【分析】方程移项后，利用完全平方公式配方即可得到结果．【解答】解：方程x2+8x+9＝0，整理得：x2+8x＝﹣9，配方得：x2+8x+16＝7，即（x+4）2＝7，故选：D．6．（3分）将点（﹣3，2）先向右平移3个单位，再向下平移4个单位后与N点重合，则点N坐标为（）A．（﹣3，﹣2）B．（0，﹣2）C．（0，2）D．（﹣6，﹣2）【分析】根据图形画出图形即可判断．【解答】解：如图，点A（﹣3，2）先向右平移3个单位得到B，再向下平移4个单位后与N点重合，观察图象可知N（0，﹣2），故选：B．7．（3分）如图，在Rt△ABC中，∠ACB＝90°，∠BAC＝33°，把△ABC绕点A按顺时针方向旋转∠BAC的大小，得到△AB′C′，延长BC交B′C′于点D，则∠BDC′等于（）A．147°B．143°C．157°D．153°【分析】由旋转的性质可得∠BAC＝∠CAC'＝33°，∠ACB＝∠AC'B'＝90°，由四边形内角和定理可求∠BDC′的度数．【解答】解：∵把△ABC绕点A按顺时针方向旋转∠BAC的大小，∴∠BAC＝∠CAC'＝33°，∠ACB＝∠AC'B'＝90°∵∠CAC'+∠ACD+∠BDC'+∠AC'B'＝360°∴∠BDC'＝360°﹣90°﹣90°﹣33°＝147°故选：A．8．（3分）如图，将两块完全相同的矩形纸片ABCD和矩形纸片AEFG按图示方式放置（点A、D、E在同一直线上），连接AC、AF、CF，已知AD＝3，DC＝4，则CF的长是（）A．5B．7C．5D．10【分析】由两块完全相同的矩形纸片ABCD和矩形纸片AEFG，得出AG＝AD＝BC＝3，FG＝AB＝CD＝4，∠FGA＝∠ABC＝90°，由勾股定理求出AC＝5，由SAS证得△FGA ≌△ABC，得出AF＝AC，∠GF A＝∠BAC，∠GAF＝∠BCA，由∠GF A+∠GAF＝90°，推出∠GAF+BAC＝90°，得出∠F AC＝90°，即△CAF是等腰直角三角形，即可得出结果．【解答】解：∵两块完全相同的矩形纸片ABCD和矩形纸片AEFG，∴AG＝AD＝BC＝3，FG＝AB＝CD＝4，∠FGA＝∠ABC＝90°，AC＝＝＝5，在△FGA和△ABC中，，∴△FGA≌△ABC（SAS），∴AF＝AC，∠GF A＝∠BAC，∠GAF＝∠BCA，∵∠GF A+∠GAF＝90°，∴∠GAF+BAC＝90°，∴∠F AC＝90°，∴△CAF是等腰直角三角形，∴CF＝AC＝5，故选：C．9．（3分）如图，已知AB∥CD∥EF，AD：AF＝3：5，BC＝6，CE的长为（）A．2B．4C．3D．5【分析】三条平行线截两条直线，所得的对应线段成比例．【解答】解：∵AB∥CD∥EF，∴，∴BE＝＝＝10，∴CE＝BE﹣BC＝10﹣6＝4，故选：B．10．（3分）如图，每个小正方形的边长均为1，则下列图形中的三角形（阴影部分）与△A1B1C1相似的是（）A．B．C．D．【分析】根据相似三角形的判定方法一一判断即可．【解答】解：因为△A1B1C1中有一个角是135°，选项中，有135°角的三角形只有B，且满足两边成比例夹角相等，故选：B．二、填空题（本大题共4小题，每小题4分，满分16分）11．（4分）已知多边形的内角和等于外角和的1.5倍，则这个多边形的边数为5．【分析】根据多边形的内角和定理与外角和公式列出方程，然后解方程即可．【解答】解：设多边形的边数是n，根据题意得（n﹣2）•180°＝1.5×360°，解得n＝5．故答案为：5．12．（4分）已知x2﹣2xy＝6，2y2﹣xy＝5．则x2﹣4y2＝﹣4．【分析】令x2﹣2xy＝6①，2y2﹣xy＝5②，①﹣②×2即可求解．【解答】解：x2﹣2xy＝6①，2y2﹣xy＝5②，②×2得：4y2﹣2xy＝10③，①﹣③得：（x2﹣2xy）﹣（4y2﹣2xy）＝﹣4，即x2﹣4y2＝﹣4，故答案为：﹣4．13．（4分）已知等腰三角形的周长为29，一边长为7，则此等腰三角形的腰长为11．【分析】分两种情况讨论，由等腰三角形的性质可求解．【解答】解：若腰长为7，则底边＝29﹣2×7＝15，∵7+7＜15∴不能组成三角形若底边为7，则腰长＝（29﹣7）÷2＝11故答案为1114．（4分）如图，在Rt△ABC中，∠C＝90°，AC＝12，BC＝5，正方形CEDF按如图所示的方式放置，则该正方形的边长为．【分析】先设正方形CEDF的边长为x，由CEDF为正方形得DE∥BC，从而得△ADE ∽△ABC，根据相似三角形的性质得比例式，解出x即可．【解答】解：设正方形CEDF的边长为x，则AE＝AC﹣EC＝12﹣x∵CEDF为正方形∴DE∥BC∴△ADE∽△ABC∴＝∴＝∴12x＝60﹣5x∴x＝故答案为：．三、解答题（本大题共6小题，满分54分）15．（10分）（1）解方程：x（2x﹣3）+（3﹣2x）2＝0（2）解分式方程：【分析】（1）根据因式分解法即可求出答案．（2）根据分式方程的解法即可求出答案．【解答】解：（1）∵x（2x﹣3）+（3﹣2x）2＝0，∴（2x﹣3）（x+2x﹣3）＝0，∴x＝或x＝1；（2）∵，∴4+x2﹣1＝（x﹣1）2，∴x2+3＝x2﹣2x+1，∴2x＝﹣2，∴x＝﹣1，经检验，x＝﹣1不是原方程的解．16．（12分）（1）解不等式组，将解集在数轴是表示出来，并写出其最小整数集．（2）化简：（），并从2，3，4中取一个合适的数作为a的值代入求值．【分析】（1）分别解不等式①和不等式②，根据不等式组解集的取法，得出其解集及最小整数解，再在数轴上表示出来即可．（2）先将所给的式子因式分解及按照分式乘除法的法则化简，再根据a应该取使得分式有意义的值，代入计算即可．【解答】解：（1）解不等式①得：x＞﹣4③解不等式②得：x≤2④∴不等式组的解集为：﹣4＜x≤2∴其最小整数解为：﹣3在数轴上表示如下：（2）（）＝[﹣]×＝×＝2+a当a＝4时，原式有意义，故取a＝4，代入得：原式＝2+4＝617．（6分）如图，在边长为1个单位长度的小正方形组成的网格中，△ABC的顶点均在格点上，点A的坐标为（2，3），点B的坐标为（3，0），点C的坐标为（0，2）．（1）以点C为旋转中心，将△ABC旋转180°后得到△A1B1C1，请画出△A1B1C1；（2）平移△ABC，使点A的对应点A2的坐标为（0，﹣1），请画出△A2B2C2．（3）若将△A1B1C1绕点P旋转可得到△A2B2C2，则点P的坐标为【分析】（1）利用网格特点和旋转的性质画出A、B、C的对应点A1、B1、C1即可；（2）根据点A和A2的坐标特征确定平移的方向和距离，利用次平移规律写出点B2、C2的坐标，然后描点即可；、（3）连接A1A2、C1C2、B1B2，它们都经过点（﹣1，0），从而得到旋转中心点P．【解答】解：（1）如图，△A1B1C1为所作；（2）如图，△A2B2C2为所作．（3）△A1B1C1绕点P旋转可得到△A2B2C2，则点P点坐标为（﹣1，0）．18．（8分）某商家预测“华为P30”手机能畅销，就用1600元购进一批该型号手机壳．面市后果然供不应求，又购进6000元的同种型号手机壳，第二批所购手机壳的数量是第一批的3倍，但进货单价比第一批贵了2元．（1）第一批手机壳的进货单价是多少元？（2）若两次购进手机壳按同一价格销售，全部售完后，为使得获利不少于2000元，那么销售单价至少为多少？【分析】（1）设第一批手机壳进货单价为x元，则第二批手机壳进货单价为（x+2）元，根据单价＝总价÷数量结合第二批手机壳的数量是第一批的3倍，即可得出关于x的分式方程，解之经检验后即可得出结论；（2）设销售单价为m元，根据获利不少于2000元，即可得出关于m的一元一次不等式，解之取其最小值即可得出结论．【解答】解：（1）设第一批手机壳进货单价为x元，根据题意得：3•＝，解得：x＝8，经检验，x＝8是分式方程的解．答：第一批手机壳的进货单价是8元．（2）设销售单价为m元，根据题意得：200（m﹣8）+600（m﹣10）≥2000，解得：m≥12．答：销售单价至少为12元．19．（8分）如图，在Rt△ABC中，∠ACB＝90°，D、E分别是AB、AC的中点，延长BC 到F，使得CF＝BC，连接CD、EF．（1）求证：四边形CDEF为平行四边形；（2）若四边形CDEF的周长是32，AC＝16，求△ABC的面积；（3）在（2）的条件下，求点F到直线CD的距离．【分析】（1）由三角形中位线定理推知ED∥FC，2DE＝BC，然后结合已知条件“CF＝BC”，利用一组对边平行且相等得到四边形DCFE为平行四边形；（2）根据在直角三角形中，斜边上的中线等于斜边的一半得到AB＝2DC，即可得出四边形DCFE的周长＝AB+BC，故BC＝32﹣AB，然后根据勾股定理即可求得；（3）过F作FH⊥DC于H，根据相似三角形的性质即可得到结论．【解答】解：（1）如图，∵D、E分别是AB、AC的中点，F是BC延长线上的一点，∴ED是Rt△ABC的中位线，∴ED∥FC．DE＝BC，∵CF＝BC，∴DE＝CF，∴四边形CDEF是平行四边形；（2）∵四边形CDEF为平行四边形，∴DC＝EF，∵DC是Rt△ABC斜边AB上的中线，∴AB＝2DC，∴四边形DCFE的周长＝AB+BC，∵四边形DCFE的周长为32，AC的长16，∴BC＝32﹣AB，∵在Rt△ABC中，∠ACB＝90°，∴AB2＝BC2+AC2，即AB2＝（32﹣AB）2+162，解得，AB＝20，∴BC＝12，∴△ABC的面积＝×12×16＝96；（3）过F作FH⊥DC于H，∴∠H＝∠ECF＝90°，∵∠EFC＝∠FCH，∴△ECF∽△FHC，∴＝，∴＝，∴FH＝，∴点F到直线CD的距离为．20．（10分）如图，△ABC是等腰直角三角形，∠ACB＝90°，D是射线CB上一点（点D 不与点B重合），以AD为斜边作等腰直角三角形ADE（点E和点C在AB的同侧），连接CE．（1）如图①，当点D与点C重合时，直接写出CE与AB的位置关系；（2）如图②，当点D与点C不重合时，（1）的结论是否仍然成立？若成立，请写出证明过程；若不成立，请说明理由；（3）当∠EAC＝15°时，请直接写出的值．【分析】（1）根据等腰直角三角形的性质、平行线的判定定理解答；（2）在AF上截取AF＝CD，连接EF，证明△EAF≌△EDC，根据全等三角形的性质得到EF＝EC，∠AEF＝∠DEC，根据平行线的判定定理证明；（3）分图②、图③两种情况，根据全等三角形的性质、等腰直角三角形的性质计算，得到答案．【解答】解：（1）当点D与点C重合时，CE∥AB，理由如下：∵△ABC是等腰直角三角形，∴∠CAB＝45°，∵△ADE是等腰直角三角形，∴∠ADE＝45°，∴∠CAB＝∠ADE，∴CE∥AB；（2）当点D与点C不重合时，（1）的结论仍然成立，理由如下：在AC上截取AF＝CD，连接EF，∵∠AED＝∠ACB＝90°，∴∠EAF＝∠EDC，在△EAF和△EDC中，，∴△EAF≌△EDC（SAS），∴EF＝EC，∠AEF＝∠DEC，∵∠AED＝90°，∴∠FEC＝90°，∴∠ECA＝45°，∴∠ECA＝∠CAB，∴CE∥AB；（3）如图②，∠EAC＝15°，∴∠CAD＝30°，∴AD＝2CD，AC＝CD，∴FC＝（﹣1）CD，∵△CEF为等腰直角三角形，∴EC＝FC＝CD，∵△ABC是等腰直角三角形，∴AB＝AC＝CD，∴＝＝，如图③，∠EAC＝15°，由（2）得，∠EDC＝∠EAC＝15°，∴∠ADC＝30°，∴CD＝AC，AB＝AC，延长AC至G，使AG＝CD，∴CG＝AG﹣AC＝DC﹣AC＝AC﹣AC，在△EAG和△EDC中，，∴△EAG≌△EDC（SAS），∴EG＝EC，∠AEG＝∠DEC，∴∠CEG＝90°，∴△CEG为等腰直角三角形，∴EC＝CG＝AC，∴＝，综上所述，当∠EAC＝15°时，的值为或．一、填空题（每小题4分，共20分）21．（4分）若关于x的分式方程＝2a有增根，则a的值为3．【分析】分式方程去分母转化为整式方程，由分式方程有增根求出a的值即可．【解答】解：＝2a，去分母得：﹣a+x＝2a（x﹣3），由分式方程有增根，得到x﹣3＝0，即x＝3，代入整式方程得：﹣a+3＝0，解得：a＝3．故答案为：3．22．（4分）已知x2+y2＝3，xy＝，则（﹣）÷的值为±．【分析】根据已知条件可以求得x+y＝±2，然后将其代入化简后的分式进行求值即可．【解答】解：∵x2+y2＝3，xy＝，∴（x+y）2＝x2+y2+2xy＝3+1＝4．∴x+y＝±2，∴（﹣）÷＝×＝﹣＝．故答案是：．23．（4分）若直线l1：y1＝k1x+b1经过点（0，2），l2：y2＝k2x+b2经过点（3，1），且l1与l2关于x轴对称，则关于x的不等式k1x+b1＞k2x+b2的解集为x＜6．【分析】根据对称的性质得出关于x轴对称的对称点的坐标，再根据待定系数法确定函数关系式y1＝k1x+b1，再根据对称的性质得到y2＝kx+b2，求出不等式的解集．【解答】解：依题意得：直线l1：y1＝k1x+b1经过点（0，2），（3，1），则．解得．故直线l1：y1＝﹣x+2．所以，直线l2：y2＝x﹣2．由k1x+b1＞k2x+b2的得到：﹣x+2＞x﹣2．解得x＜6．故答案是：x＜6．24．（4分）正方形A1B1C1A2，A2B2C2A3，A3B3C3A4，…，A n B n∁n A n+1，…按如图所示的方式放置，点A1，A2，A3，…，A n，…和点B1，B2，B3，…，B n，…分别在直线y＝kx+b（k ＞0）和x轴上．已知点A1（0，1），点B1（1，0），则C3的坐标是（11，4），∁n 的坐标是∁n（3×2n﹣1﹣1，2n﹣1）．【分析】由题意可知A1纵坐标为1，A2的纵坐标为2，A3的纵坐标为4，A4的纵坐标为8，…，即可得到C1，C2，C3，C4，C5的纵坐标，根据图象得出C1（2，1），C2（5，2），C3（11，4），即可得到C1，C2，C3，C4，C5…∁n在一条直线上，直线的解析式为y＝x+，把∁n的纵坐标代入即可求得横坐标．【解答】解：由题意可知A1纵坐标为1，A2的纵坐标为2，A3的纵坐标为4，A4的纵坐标为8，…，∵A1和C1，A2和C2，A3和C3，A4和C4的纵坐标相同，∴C1，C2，C3，C4，C5，…∁n的纵坐标分别为1，2，4，8，16，…2n﹣1，∴根据图象得出C1（2，1），C2（5，2），C3（11，4），∴直线C1C2的解析式为y＝x+，∵∁n的纵坐标为2n﹣1，把y＝2n﹣1代入y＝x+，解得x＝3×2n﹣1﹣1，∴∁n的坐标是（3×2n﹣1﹣1，2n﹣1）∴C3的坐标是（11，4），∁n（3×2n﹣1﹣1，2n﹣1），故答案为（11，4），（3×2n﹣1﹣1，2n﹣1）．25．（4分）如图，AC，BD在AB的同侧，AC＝1，BD＝4，AB＝4，点M为AB的中点，若∠CMD＝120°，则CD的最大值是7．【分析】如图，作点A关于CM的对称点A′，点B关于DM的对称点B′，证明△A′MB′为等边三角形，即可解决问题．【解答】解：如图，作点A关于CM的对称点A′，点B关于DM的对称点B′．∵∠CMD＝120°，∴∠AMC+∠DMB＝60°，∴∠CMA′+∠DMB′＝60°，∴∠A′MB′＝60°，∵MA′＝MB′，∴△A′MB′为等边三角形∵CD≤CA′+A′B′+B′D＝CA+AM+BD＝1+2+4＝7，∴CD的最大值为7，故答案为7．二、解答题（共30分）26．（8分）“绿水青山就是金山银山”，为了保护环境和提高果树产量，某果农计划把68吨有机化肥运送到果园，为节省时间需要在一天之内运完．货运站有甲、乙两种货车，果农决定租用甲、乙两种货车共18辆，两种型号的货车的运输量和租金如下表（所租用货车都按一整天收费）：（1）求所付的货车租金总费用y（元）与租用甲型货车数量x（辆）的函数关系式；（2）请你帮该果农设计一种使租金总费用最少的方案，并求出所付的最少租金．【分析】（1）租用甲型货车数量x（辆），则租用乙型货车数量（18﹣x）（辆），根据题意即可求出所付的货车租金总费用y（元）与租用甲型货车数量x（辆）的函数关系式；（2）根据题意可得不等式5x+3（18﹣x）≥68，解得x≥7，再根据一次函数的性质解答即可求解．【解答】解：（1）租用甲型货车数量x（辆），则租用乙型货车数量（18﹣x）（辆），根据题意得，y＝400x+300（18﹣x）＝100x+5400；（2）根据题意可得，5x+3（18﹣x）≥68，解得x≥7，∵k＝100＞0，∴y随x的增大而增大，∴当x＝7时，y最小＝100×7+5400＝6100，即租用7辆甲型货车，11辆乙型货车所付的租金最少，最少租金为6100元．27．（10分）在矩形ABCD中，AB＝6，AD＝8，E是边BC上一点，以点E为直角顶点，在AE的右侧作等腰直角△AEF．（1）如图1，当点F在CD边上时，求BE的长；（2）如图2，若EF⊥DF，求BE的长；（3）如图3，若动点E从点B出发，沿边BC向右运动，运动到点C停止，直接写出线段AF的中点Q的运动路径长．【分析】（1）如图1中，证明△ABE≌△ECF（AAS），即可解决问题．（2）如图2中，延长DF，BC交于点N，过点F作FM⊥BC于点M．证明△EFM≌△DNC（AAS），设NC＝FM＝x，利用勾股定理构建方程即可解决问题．（3）如图3中，在BC上截取BM＝BA，连接AM，MF，取AM的中点H，连接HQ．由△ABE∽△AMF，推出∠AMF＝∠ABE＝90°，由AQ＝FQ，AH＝MH，推出HQ＝FM，HQ∥FM，推出∠AHQ＝90°，推出点Q的运动轨迹是线段HQ，求出MF的长即可解决问题．【解答】解：（1）如图1中，∵四边形ABCD是矩形，∴∠B＝∠C＝90°，∵EF⊥AE，∠AEF＝90°，∴∠AEB＝∠EFC，∵EF＝AE，∴△ABE≌△ECF（AAS），∴CE＝AB＝6，∴BE＝BC﹣CE＝2．（2）如图2中，延长DF，BC交于点N，过点F作FM⊥BC于点M．同理可证△ABE≌△EMF，设BE＝x，则EM＝AB＝6，FM＝BE＝xEC＝8﹣x，∵EF⊥DF，∴∠DFE＝∠DCB＝90°，∴∠FEC＝∠CDF，CD＝AB＝EM∴△EFM≌△DNC（AAS），∴NC＝FM＝x，EN＝EC+NC＝8，NM＝EN﹣EM＝2，即在Rt△FMN中，FN2＝x2+22，在Rt△EFM中，EF2＝x2+62，在Rt△EFN中，FN2+EF2＝EN2，即x2+22+x2+62＝82，解得x＝2或﹣2（舍弃），即BE＝2，（3）如图3中，在BC上截取BM＝BA，连接AM，MF，取AM的中点H，连接HQ．∵∠BAM＝∠EAF＝45°，∴∠BAE＝∠MAF，∵＝＝，∴△ABE∽△AMF，∴∠AMF＝∠ABE＝90°，＝＝，∵AQ＝FQ，AH＝MH，∴HQ＝FM，HQ∥FM，∴∠AHQ＝90°，∴点Q的运动轨迹是线段HQ，当点E从点B运动到点C时，BE＝8，∴MF＝8，∴HQ＝MF＝4，∴线段AF的中点Q的运动路径长为4．28．（12分）如图，已知长方形OABC的顶点O在坐标原点，A、C分别在x、y轴的正半轴上，顶点B（8，6），直线y＝﹣x+b经过点A交BC于D、交y轴于点M，点P是AD的中点，直线OP交AB于点E（1）求点D的坐标及直线OP的解析式；（2）求△ODP的面积，并在直线AD上找一点N，使△AEN的面积等于△ODP的面积，请求出点N的坐标（3）在x轴上有一点T（t，0）（5＜t＜8），过点T作x轴的垂线，分别交直线OE、AD 于点F、G，在线段AE上是否存在一点Q，使得△FGQ为等腰直角三角形，若存在，请求出点Q的坐标及相应的t的值；若不存在，请说明理由【分析】（1）根据长方形的性质可得出点A的坐标，利用待定系数法可求出直线AD的解析式，利用一次函数图象上点的坐标特征可求出点D的坐标，再由点P是AD的中点可得出点P的坐标，进而可得出正比例函数OP的解析式；（2）利用三角形面积的公式可求出S△ODP的值，由直线OP的解析式，利用一次函数图象上点的坐标特征可得出点E的坐标，设点N的坐标为（m，﹣m+8），由△AEN的面积等于△ODP的面积，可得出关于m的含绝对值符号的一元一次方程，解之即可得出m 的值，再将其代入点N的坐标中即可得出结论；（3）由点T的坐标可得出点F，G的坐标，分∠FGQ＝90°、∠GFQ＝90°及∠FQG＝90°三种情况考虑：①当∠FGQ＝90°时，根据等腰直角三角形两直角边相等可得出关于t的一元一次方程，解之可得出t值，再利用等腰直角三角形的性质可得出点Q的坐标；②当∠GFQ＝90°时，根据等腰直角三角形两直角边相等可得出关于t的一元一次方程，解之可得出t值，再利用等腰直角三角形的性质可得出点Q的坐标；③当∠FQG ＝90°时，过点Q作QS⊥FG于点S，根据等腰直角三角形斜边等于斜边上高的二倍可得出关于t的一元一次方程，解之可得出t值，再利用等腰直角三角形的性质可得出点Q 的坐标．综上，此题得解．【解答】解：（1）∵四边形OABC为长方形，点B的坐标为（8，6），∴点A的坐标为（8，0），BC∥x轴．∵直线y＝﹣x+b经过点A，∴0＝﹣8+b，∴b＝8，∴直线AD的解析式为y＝﹣x+8．当y＝6时，有﹣x+8＝6，解得：x＝2，∴点D的坐标为（2，6）．∵点P是AD的中点，∴点P的坐标为（，），即（5，3），∴直线OP的解析式为y＝x．（2）S△ODP＝S△ODA﹣S△OP A，＝×8×6﹣×8×3，＝12．当x＝8时，y＝x＝，∴点E的坐标为（8，）．设点N的坐标为（m，﹣m+8）．∵S△AEN＝S△ODP，∴××|8﹣m|＝12，解得：m＝3或m＝13，∴点N的坐标为（3，5）或（13，﹣5）．（3）∵点T的坐标为（t，0）（5＜t＜8），∴点F的坐标为（t，t），点G的坐标为（t，﹣t+8）．分三种情况考虑：①当∠FGQ＝90°时，如图1所示．∵△FGQ为等腰直角三角形，∴FG＝GQ，即t﹣（﹣t+8）＝8﹣t，解得：t＝，此时点Q的坐标为（8，）；②当∠GFQ＝90°时，如图2所示．∵△FGQ为等腰直角三角形，∴FG＝FQ，即t﹣（﹣t+8）＝8﹣t，解得：t＝，此时点Q的坐标为（8，）；③当∠FQG＝90°时，过点Q作QS⊥FG于点S，如图3所示．∵△FGQ为等腰直角三角形，∴FG＝2QS，即t﹣（﹣t+8）＝2（8﹣t），解得：t＝，此时点F的坐标为（，4），点G的坐标为（，）此时点Q的坐标为（8，），即（8，）．综上所述：在线段AE上存在一点Q，使得△FGQ为等腰直角三角形，当t＝时点Q 的坐标为（8，）或（8，），当t＝时点Q的坐标为（8，）．。

2019-2020学年四川省成都七中育才学校九年级（上）开学数学试卷一、选择题（本大题共10个小题，每小题3分，共30分，答案涂在答题卡上）1．（3分）育才校园文化博大精深，以下是“育”、“才”、“水”、“井”四字的甲骨文，其中是中心对称，但非轴对称图形的是（）A．B．C．D．2．（3分）下列各式由左边到右边的变形中，是因式分解的是（）A．a（x﹣y）＝ax﹣ay B．a2﹣b2＝（a+b）（a﹣b）C．x2﹣4x+3＝x（x﹣4）+3D．a2+1＝a（a+）3．（3分）如图，菱形ABCD的对角线AC、BD的长分别为8和6，则这个菱形的周长是（）A．20B．24C．40D．484．（3分）若分式的值为0，则x等于（）A．1B．1或﹣3C．﹣1或1D．﹣15．（3分）用配方法解方程x2+8x+9＝0，变形后的结果正确的是（）A．（x+4）2＝﹣9B．（x+4）2＝﹣7C．（x+4）2＝25D．（x+4）2＝76．（3分）将点（﹣3，2）先向右平移3个单位，再向下平移4个单位后与N点重合，则点N坐标为（）A．（﹣3，﹣2）B．（0，﹣2）C．（0，2）D．（﹣6，﹣2）7．（3分）如图，在Rt△ABC中，∠ACB＝90°，∠BAC＝33°，把△ABC绕点A按顺时针方向旋转∠BAC 的大小，得到△AB′C′，延长BC交B′C′于点D，则∠BDC′等于（）A．147°B．143°C．157°D．153°8．（3分）如图，将两块完全相同的矩形纸片ABCD和矩形纸片AEFG按图示方式放置（点A、D、E在同一直线上），连接AC、AF、CF，已知AD＝3，DC＝4，则CF的长是（）A．5B．7C．5D．109．（3分）如图，已知AB∥CD∥EF，AD：AF＝3：5，BC＝6，CE的长为（）A．2B．4C．3D．510．（3分）如图，每个小正方形的边长均为1，则下列图形中的三角形（阴影部分）与△A1B1C1相似的是（）A．B．C．D．二、填空题（本大题共4小题，每小题4分，满分16分）11．（4分）已知多边形的内角和等于外角和的1.5倍，则这个多边形的边数为．12．（4分）已知x2﹣2xy＝6，2y2﹣xy＝5．则x2﹣4y2＝．13．（4分）已知等腰三角形的周长为29，一边长为7，则此等腰三角形的腰长为．14．（4分）如图，在Rt△ABC中，∠C＝90°，AC＝12，BC＝5，正方形CEDF按如图所示的方式放置，则该正方形的边长为．三、解答题（本大题共6小题，满分54分）15．（10分）（1）解方程：x（2x﹣3）+（3﹣2x）2＝0（2）解分式方程：16．（12分）（1）解不等式组，将解集在数轴是表示出来，并写出其最小整数集．（2）化简：（），并从2，3，4中取一个合适的数作为a的值代入求值．17．（6分）如图，在边长为1个单位长度的小正方形组成的网格中，△ABC的顶点均在格点上，点A的坐标为（2，3），点B的坐标为（3，0），点C的坐标为（0，2）．（1）以点C为旋转中心，将△ABC旋转180°后得到△A1B1C1，请画出△A1B1C1；（2）平移△ABC，使点A的对应点A2的坐标为（0，﹣1），请画出△A2B2C2．（3）若将△A1B1C1绕点P旋转可得到△A2B2C2，则点P的坐标为．18．（8分）某商家预测“华为P30”手机能畅销，就用1600元购进一批该型号手机壳．面市后果然供不应求，又购进6000元的同种型号手机壳，第二批所购手机壳的数量是第一批的3倍，但进货单价比第一批贵了2元．（1）第一批手机壳的进货单价是多少元？（2）若两次购进手机壳按同一价格销售，全部售完后，为使得获利不少于2000元，那么销售单价至少为多少？19．（8分）如图，在Rt△ABC中，∠ACB＝90°，D、E分别是AB、AC的中点，延长BC到F，使得CF ＝BC，连接CD、EF．（1）求证：四边形CDEF为平行四边形；（2）若四边形CDEF的周长是32，AC＝16，求△ABC的面积；（3）在（2）的条件下，求点F到直线CD的距离．20．（10分）如图，△ABC是等腰直角三角形，∠ACB＝90°，D是射线CB上一点（点D不与点B重合），以AD为斜边作等腰直角三角形ADE（点E和点C在AB的同侧），连接CE．（1）如图①，当点D与点C重合时，直接写出CE与AB的位置关系；（2）如图②，当点D与点C不重合时，（1）的结论是否仍然成立？若成立，请写出证明过程；若不成立，请说明理由；（3）当∠EAC＝15°时，请直接写出的值．一、填空题（每小题4分，共20分）21．（4分）若关于x的分式方程＝2a有增根，则a的值为．22．（4分）已知x2+y2＝3，xy＝，则（﹣）÷的值为．23．（4分）若直线l1：y1＝k1x+b1经过点（0，2），l2：y2＝k2x+b2经过点（3，1），且l1与l2关于x轴对称，则关于x的不等式k1x+b1＞k2x+b2的解集为．24．（4分）正方形A1B1C1A2，A2B2C2A3，A3B3C3A4，…，A n B n∁n A n+1，…按如图所示的方式放置，点A1，A2，A3，…，A n，…和点B1，B2，B3，…，B n，…分别在直线y＝kx+b（k＞0）和x轴上．已知点A1（0，1），点B1（1，0），则C3的坐标是，∁n的坐标是．25．（4分）如图，AC，BD在AB的同侧，AC＝1，BD＝4，AB＝4，点M为AB的中点，若∠CMD＝120°，则CD的最大值是．二、解答题（共30分）26．（8分）“绿水青山就是金山银山”，为了保护环境和提高果树产量，某果农计划把68吨有机化肥运送到果园，为节省时间需要在一天之内运完．货运站有甲、乙两种货车，果农决定租用甲、乙两种货车共18辆，两种型号的货车的运输量和租金如下表（所租用货车都按一整天收费）：型号甲乙每辆每天运输量（吨）53每辆每天租金（元）400300（1）求所付的货车租金总费用y（元）与租用甲型货车数量x（辆）的函数关系式；（2）请你帮该果农设计一种使租金总费用最少的方案，并求出所付的最少租金．27．（10分）在矩形ABCD中，AB＝6，AD＝8，E是边BC上一点，以点E为直角顶点，在AE的右侧作等腰直角△AEF．（1）如图1，当点F在CD边上时，求BE的长；（2）如图2，若EF⊥DF，求BE的长；（3）如图3，若动点E从点B出发，沿边BC向右运动，运动到点C停止，直接写出线段AF的中点Q 的运动路径长．28．（12分）如图，已知长方形OABC的顶点O在坐标原点，A、C分别在x、y轴的正半轴上，顶点B（8，6），直线y＝﹣x+b经过点A交BC于D、交y轴于点M，点P是AD的中点，直线OP交AB于点E （1）求点D的坐标及直线OP的解析式；（2）求△ODP的面积，并在直线AD上找一点N，使△AEN的面积等于△ODP的面积，请求出点N的坐标（3）在x轴上有一点T（t，0）（5＜t＜8），过点T作x轴的垂线，分别交直线OE、AD于点F、G，在线段AE上是否存在一点Q，使得△FGQ为等腰直角三角形，若存在，请求出点Q的坐标及相应的t的值；若不存在，请说明理由。

七中育才学校2019-2020学年度(上) 期末检测七年级数学试题A 卷一、 选择题(每小题3分，共30分)1． 32-的倒数是（ ） A ．23- B ．23 C ．32 D ．32- 2．12月24日，第八次中日韩领导人会议在四川成都举行．数据表明2018年三国间贸易总额超过7200亿美元，请将数据7200亿用科学记数法表示为（ ）A ．107.210⨯B ．87210⨯C ．97210⨯D ．117.210⨯3．下列各式中，是同类项的是（ ）A ． 22a b 与23b a -B ． 2x π与212xC ． 2212m n -与225tm n D ． 6xy -与6yz - 4．下列表述正确的是（ ）A ．由31a -=，得31a =-B ．由||||x y =，得x y =C ．由24x =，得24x = D ．由a b =，得22a b = 5．从五边形的一个顶点出发可以连接的对角线条数为（ ）A ．1B ．2C ．3D ．46．2019年是大家公认的5G 商用元年．移动通讯行业人员想了解5G 手机的使用情况，在某高校随机对500位大学生进行了问卷调查．下列说法正确的是（ ）A ．该调查方式是普查B ．该调查中的个体是每一位大学生C ．该调查中的样本是被随机调查的500位大学生5G 手机的使用情况D ．该调査中的样本容量是500位大学生7．用一个平面去截正方体，则截面形状不可能是（ ）A ．四边形B ．五边形C ．六边形D ．七边形8．如图， 点O 在直线AB 上，OD 是AOC ∠的角平分线，42COB ∠=︒．则DOC ∠的度数是( )A ．59°B ．60°C ．69°D ．70°9．若a ,b 互为相反数，则下列等式不一定成立的是（ ）A ．1a b=- B ．a b =- C ．b a =- D ．0a b += 10．成都市某电影院共有4个大厅和5个小厅．其中1个大厅、2个小厅，可同时容纳1680人观影；2个大厅、1个小厅，可同时容纳2280人观影．设1个小厅可同时容纳x 人观影，由题意得下列方程正确是（ ）A ．2(1680)2280x x +-=B ．2(16802)2280x x +-=C ．2(2280)1680x x +-=D ．1(2280)16802x x +-= 二．填空题(每小题4分：共16分)11． 35-的绝对值是 ．12．若3x =是方程82ax x -=-的解，则a = ． 13．单项式23a b -的系数为 , 次数为 ． 14．将一个高为8，底面半径为3的实心圆柱体铸铁零件改造成一个实心正方体零件(改造过程中的损耗忽略不计)，则改造后的正方体的棱长为 ．(π取3)三、解答题(共54分)15、 (1)计算：215(3)|51|2⎛⎫-÷-+-⨯-- ⎪⎝⎭(2)计算：2020216(12)(1)34⎛⎫-+-⨯--- ⎪⎝⎭ (3)解方程：61143x x --=- 16．先化简,再求值: ()()22223531m n mn m n n m ⎡⎤++--⎣⎦,其中2,3m n =-=． 17．一个几何体是由大小相同的棱长为1的小立方体搭建而成,从上面看到的几何体的形状如图所示,其中小正方形中的数字表示在该位置的小立方体的个数．（1）画出该几何体的主视图和左视图；（2）求该几何体的体积和表面积．18．列方程解应用题：2019年12月16日，成贵高铁正式开通客运业务．据悉，试运行期间高铁运行的速度为250/km h ，若将速度提升到300/km h ，则运行时间将缩短25分钟，请计算成贵高铁全线的距离大约是多少千米?19．近年，《中国诗词大会》、《朗读者》、《经典咏流传》、《国家宝藏》等文化类节目相继走红，被人们称为“清流综艺”．七中育才某兴趣小组想了解全校学生对这四个节目的喜爱情况，随机抽取了部分学生进行调查统计，要求每名学生选出一个自己最喜爱的节目，并将调查结果绘制成如下统计图(其中《中国诗词大会》，《朗读者》，《经典咏流传》，《国家宝藏》分别用A ，B ，C ，D 表示)．请你结合图中信息解答下列问题：(1)本次调查的学生人数是 人；(2)请把条形统计图补充完整；(3)在扇形统计图中，B 对应的圆心角的度数是 °；(4)已知七中育才学校共有4800名学生，请根据样本估计全校最喜爱《朗读者》的人数是多少?20．如图,点A 和点B 在数轴上对应的数分别为a 和b ,且2(2)|8|0a b ++-=．(1)线段AB 的长为 ； (2)点C 在数轴上所对应的数为x ,且x 是方程6117x x -=+的解,在线段AB 上是否存在点D 使得56AD BD CD +=?若存在,请求出点D 在数轴上所对应的数,若不存在,请说明理由；(3)在(2)的条件下,线段AD 和BC 分别以6个单位长度/秒和5个单位长度/秒的速度同时向右运动,运动时间为t 秒,点M 为线段AD 的中点,点N 为线段BC 的中点,若5MN =,求t 的值．B 卷一、填空题(每小题4分，共20分)21． 21x y -=，则()()2221x x x y +-+-= ．22．若201912020x =，则|||1||2||3|x x x x +-+-+-= ． 23．已知整式32(1)7(3)2m n x x m x ---++-是关于x 的二次二项式，则关于y 的方程(33)5n m y my -=--的解为 ．24一列数按某规律排列如下：11，12，21，13，22，31，14，23，32，41，⋯，若第n 个数为56，则n = ．25．如图，等边三角形ABC 的周长为30cm ，P ,Q 两点分别从B ,C 两点同时出发，点P 以6cm /s 的速度按顺时针方向在三角形的边上运动，点Q 以14cm /s 的速度按逆时针方向在三角形的边上运动．设P ,Q 两点第一次在三角形ABC 的顶点处相遇的时间为1t ，第二次在三角形ABC 顶点处相遇的时间为2t ，则2t = ．二．解答题(本大题共3小题，共30分)26． 从锦江区社保局获悉，我区范围内已经实现了全员城乡居民新型社会合作医疗保险制度．享受医保的城乡居民可在规定的医院就医并按规定标准报销部分医疗费用．下表是住院费用报销的标准： 住院费用x(元) 0<x<50005000<x≤20000 x>20000 每年报销比例40% 50% 60%(说明：住院费用的报销采取分段计算方式，如：某人一年住院费用共30000元，则5000元按40%报销，15000元按50%报销，余下的10000元按60%报销；实际支付的住院费=住院费用-按标准报销的金额．)(1)若我区居民张大哥一年住院费用为20000元，则按标准报销的金额为 元，张大哥实际支付了 元的住院费；(2)若我区居民王大爷一年内本人实际支付的住院费用为21000元，则王大爷当年的住院费用为多少元?27． 如图1，在表盘上12：00时，时针、分针都指向数字12，我们将这一位置称为“标准位置”(图中OA )．小文同学为研究12点t 分(060t <<)时，时针与分针的指针位置，将时针记为OB ，分针记为OC ．如：12：30时，时针、分针的位置如图2所示，试解决下列问题：(1)分针OC 每分钟转动 °；时针OB 每分钟转动 °；(2)当OC 与OB 在同一直线上时，求t 的值；(3)当OA 、OB 、OC 两两所夹的三个角AOC ∠、AOB ∠、BOC ∠中有两个角相等时，试求出所有符合条件的t 的值．(本小题中所有角的度数均不超过180°)28． 幻方的历史很悠久，传说中最早出现在夏禹时代的“洛书”，用今天的数学符号翻译出来，就是一个三阶幻方，即将若干个数组成一个正方形数阵，任意一行、一列及对角线上的数字之和都相等．观察下图：(1)若图1为“和m 幻方”，则a = ，b = ，c = ．(2) 若图2为“和m幻方”，请通过观察上图的三个幻方，试着用含p、q的代数式表示r，并说明理由．(3)若图3为“和m幻方”，且x为整数，试求出所有满足条件的整数n的值．参考答案A 卷一、选择题1．A 2．D 3．B 4．D 5．B 6．C 7．D 8．C 9．A 10．B二、填空题11．35 12．73 13．13- 14．6 三、解答题15．（1）原式=5(2)96-⨯-+⨯=10+54=64；（2）原式= (7283)1-+-=671-=66；（3）3(6)124(1)x x -=--3181244x x -=-+3412418x x +=++734x =347x =． 16．化简，求值．原式=222233533m n mn m n mn ++-+=283m n +；当2m =-，3n =时，原式=28(2)3+3⨯-⨯=843+3⨯⨯=99．17． （1）如图所示：（2）体积：3(2321)18V =+++⨯=表面积：2=2(6+5+4)130S ⨯⨯=答：该几何体的体积为8，表面积为30．18．解：设成贵高铁全线距离大约是x 千米，则2525030060x x -= 解得：625x =答：成贵高铁全线距离大约是625千米．19．（1）100；（2）如图：（3）72；（4）204800=960100⨯（人） 答：全校最喜欢《朗读者》的人数是960人．20．（1）10；（2）∵6117x x -=+ 解得，14x =即点C 在数轴上对应的数为14．∵点D 在线段AB 上．∴10AD BD AB +==∵56AD BD CD +=∴5106CD = 解得：12CD =∴14-12=2即点D 对应的数为2；（3）由题意知，M Q 、N 分别为AD 、BC 的中点，∴M 、N 初始位置对应数为0，11．M 对应的数是2+2=02- N 对应的数是 8+14=112又∵M 在AD 上， N 在BC 上，∴可知M 的速度在O 处向右，速度为6个单位/秒， N 的速度在11处向右速度为5个单位/秒， 运动t 秒后，M 对应的数为：6t ， N 对应的数为：11+5t ，∵5MN =∴|(115)6|5t t +-=解得，6t =或16，t ∴的值为6s 或16sB 卷一、填空题21．222、423、56y =24、5025、25二、解答题．26．（1）9500 （2）10500（2）解：设王大爷当年的住院费为x 元，则500040%+1500050%+60%20000)21000x x ⨯⨯-=-（ 解得：46250x =答：王大爷当年的住院费为46250元．27．（1）6，0．5（2）当OC 与OB 在同一直线上时，时针OB 转了0.5t 度，即0.5AOB t ∠=︒分针OC 转了6t 度，即6AOC t ∠=︒∴60.5180t t ︒-︒=︒ 解得，36011t =∴t 的值为36011． （3）①当AOC BOC ∠=∠时，∵3606AOC t ∠=︒-︒60.5=5.5BOC t t t ∠=︒-︒︒∴3606=5.5t t -︒︒ ∴72023t =； ②当AOB AOC ∠=∠时∵3606AOC t ∠=︒-︒0.5BOC t ∠=︒∴3606=0.5t t -︒︒ ∴72013t =； ∴综上所述，符合条件的t 的值为72023或72013 28．（1）-5，9，3（2）2p q r =+（3）-3，-2，0，1．。

2019~2020学年四川成都锦江区 成都七中育才学校水井坊校区初二上学期期中数学试卷(详解)一、选择题（本大题共10小题，每小题3分，共30分。

）1.A.B.C.D.【答案】【解析】实数的平方根是（ ）．B的平方根是．故选．2.A.B.C.D.【答案】A 选项：B 选项：C 选项：D 选项：【解析】下列二元一次方程的一组解的是（ ）．C当，代入，得，故错误；当，代入，得，故错误；当，代入，得，故正确；当，代入，得，故错误．故选 C .3.A.，，(为正整数） B.，，C.，，D.，，【答案】A 选项：B 选项：【解析】以下四组数中不是勾股数的是（ ）．D ，故，，（为正整数）是勾股数．，故，，是勾股数．C 选项：D 选项：，故，，是勾股数．，故，，不是勾股数．故选 D .4.A.B.C.D.【答案】A 选项：B 选项：C 选项：D 选项：【解析】下列根式中属于最简二次根式的是（ ）．C ，故不是最简二次根式，故错误；，故不是最简二次根式，故错误；是最简二次根式，故正确；，故不是最简二次根式，故错误；故选 C .5.A.B.C.D.【答案】【解析】若点在第二象限，则的值可以是（ ）．D 点在第二象限，∴．观察可知，只有选项中的符合要求．故选．6.A. B.C.D.【答案】【解析】函数中，自变量的取值范围在数轴上表示正确的是（ ）．C ∵，∴，即，故选．7.A.B.C.D.【答案】【解析】如果有意义，那么的取值范围是（ ）．D由二次根式有意义的条件可知，，，解得．故选．8.A.B.C.D.【答案】【解析】已知点和点是坐标平面内两点，且它们关于轴对称，则点的坐标为（ ）．C关于轴对称的两点，横坐标相等，纵坐标互为相反数，故点的坐标为．故选．9.A.B.C.D.【答案】【解析】已知，且，是两个连续的整数，则等于（ ）．B ∵，∴，∵，、是连续整数，∴，，∴．故选．10.A.B. C. D.【答案】【解析】一个长方形抽屉长，宽，贴抽屉底面放一根木棍，那么这根木棍最长（不计木棍粗细）可以是（ ）．A根据题意得：木棍最长．故答案为：．故选．二、填空题（本大题共4小题，每小题3分，共12分。

2019-2020学年四川省成都七中育才学校水井坊校区八年级（下）期中数学试卷一、选择题（共10小题，每小题3分，满分30分）1．（3分）下列各式：，，，x+y，，其中分式有（）A．1个B．2个C．3个D．4个2．（3分）下列从左到右的变形是因式分解的是（）A．x2+1＝x（x+）B．a3﹣a＝a（a+1）（a﹣1）C．a2﹣3a﹣4＝（a+4）（a﹣1）D．ax﹣ay+1＝a（x﹣y）+13．（3分）如果x＞y，则下列式子错误的是（）A．＞B．﹣3x＜﹣3y C．x﹣2＜y﹣2D．1﹣x＜1﹣y4．（3分）如果把分式中的x，y都扩大4倍，那么分式的值（）A．不变B．扩大2倍C．扩大3倍D．扩大4倍5．（3分）已知分式的值为0，那么x的值是（）A．﹣1B．3C．1D．3或﹣16．（3分）下列命题错误的是（）A．对角线互相平分的四边形是平行四边形B．对角线互相垂直且平分的四边形是菱形C．矩形的对角线相等且互相平分D．对角线相等的四边形是矩形7．（3分）如果2a﹣3是多项式4a2+ma﹣9的一个因式，则m的值是（）A．0B．6C．12D．﹣128．（3分）矩形具有而菱形不一定具有的性质是（）A．对角线互相平分B．邻角互补C．对角相等D．对角线相等9．（3分）若不等式x≤m的解都是不等式x≤2的解，则m的取值范围是（）A．m≤2B．m≥2C．m＜2D．m＞210．（3分）如图，在Rt△ABC中，∠BAC＝90°，D为BC的中点，DE⊥AB，且AC＝6cm，AB＝8cm，则△ADE的周长为（）A．8cm B．10cm C．12cm D．14cm二、填空题（本大题共4小题，每小题4分，共16分）11．（4分）函数y＝+中，自变量x的取值范围是．12．（4分）计算：＝．13．（4分）菱形的面积是24，一条对角线长是6，则菱形的边长是．14．（4分）如图所示，将矩形ABCD沿对角线BD折叠，使点C落在C'处，BC'交AD于点E，AD＝8，AB ＝4，那么△BDE的面积＝．三、解答题（共6小题，满分0分）15．计算题（1）分解因式：2x2y﹣8xy+8y（2）解方程：＝+116．化简：（1）÷（2）（x﹣1﹣）÷17．先化简，再求值：（﹣）÷，其中a是方程x2﹣2x﹣2＝0的解．18．已知a、b、c是△ABC的三边的长，且满足a2+2b2+c2﹣2b（a+c）＝0，试判断此三角形的形状．19．威丽商场销售A，B两种商品，售出1件A种商品和4件B种商品所得利润为600元；售出3件A种商品和5件B种商品所得利润为1100元．（1）求每件A种商品和每件B种商品售出后所得利润分别为多少元；（2）由于需求量大，A、B两种商品很快售完，威丽商场决定再一次购进A、B两种商品共34件．如果将这34件商品全部售完后所得利润不低于4000元，那么威丽商场至少需购进多少件A种商品？20．如图，在△ABC中，∠ACB＝90°，AC＝BC，D为BC边的中点，过点B作BF⊥AB交AD的延长线于点F，CE平分∠ACB交AD于点E．（1）求证：判断四边形CEBF的形状，并证明；（2）若AD＝，求BF及四边形CEBF的面积．四、填空题（本大题共5小题，每小题0分，共20分）21．如果a+4＝b，那么8b﹣b2+a2＝．22．若关于x的方程＝﹣1的解为正数，则m的取值范围是．23．如图，函数y＝3x和y＝ax+4的图象相交于点A（m，3），则不等式0≤3x＜ax+4的解集是．24．对于两个不相等的实数a、b，我们规定符号M ax{a，b}表示a、b中的较大值，例如：M ax{2，4}＝4，按照这个规定，求方程M ax{x，﹣x}＝的解．25．在Rt△ABC中，BC＝12，AB＝26，点D为斜边AB的中点，P为AC边一动点，△BDP沿着PD所在的直线对折得到△EDP．若△EDP与△ADP重合部分的面积为△EDP的面积一半，此时CP＝．五、解答题（本大题共3小题，共30分）26．平价大药房准备购进KN95、一次性医用两种口罩．两种口罩的进价和售价如表．已知：用1800元购进一次性医用口罩的数量是用2000元购进KN95口罩的数量的5倍．KN95口罩一次性医用口罩进价（元/个）m+10.2m售价（元/个）15 2.5（1）求m的值；（2）要使购进的KN95、一次性医用两种口罩共1000个的总利润不少于1560元，且不超过1603元，问该药店共有多少种进货方案？27．如图1，在边长为6的菱形ABCD中，AC＝BC，点M、N分别是边BC、边CD上的动点，且MB＝NC．连接AM、AN、MN，若MN交AC于点P．（1）△AMN是什么特殊的三角形？说明理由；（2）如图1，当BM＝CM时，求MN的长；（3）如图2，在（2）的条件下，点E、F分别是边AM、边AN上的动点，连接EF、PF，EF+PF是否存在最小值？若存在，求出最小值及此时AF的长；若不存在，请说明理由．28．如图，点O为平面直角坐标系的原点，在矩形OABC中，两边OC、OA分别在x轴和y轴上，且点B （a，b）满足：+（b+4）2＝0．（1）求点B的坐标（，）；（2）若过点B的直线BP与矩形OABC的OC边交于点P，且将矩形OABC的面积分为1：3两部分，①求直线BP的解析式；②在直线BP确定一点Q，使得△ACQ的面积等于矩形OABC的面积，求点Q的坐标；（3）D在线段AB上，AD＝AB，M在坐标轴上，N为（2）中直线BP上一动点，若四点O、D、M、N构成平行四边形，直接写出M的坐标．。

2019-2020学年成都市七中育才学校高三英语下学期期中考试试卷及答案第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项AThank you. It’s my great honor to be given this award.You cannot imagine that I have always been a late starter. Years ago, when I was 16, I took an important exam — GCE(General Certificate of Education), which turned out to be a failure. My dad was reading my report card and saw that my position in class was 29th, but the number in class was 29. It meant that I had achieved the distinction of being bottom of my class.I wasn’t lazy, and I was really trying. You can picture how I felt. Dad put his hand on my shoulder and said, “You can only do the best you can, but whatever you decide to do, make sure you love it.” He was a really sweet guy and a great man. I knew his attempt to hide his disappointment with some of his encouraging words. I was depressed for a week, but his advice was a wake-up call.Fortunately I love working with my hands, and I was good at two things: woodwork and art, and I really loved to draw and paint. I was quite talented. Dad strongly encouraged me to go to art school, which in those days wasn’t the obvious place that a father would suggest.So I got into Hartlepool College of Art. The college was a revelation (出乎意料), the passionate teachers there, who were extremely interested in the students, not just tolerating them but actually engaging with them. It was a world apart from my schooling until then. It’s extraordinary what an enthusiastic teacher can do, drawing the student out, lighting independence, and encouraging a design of your own future, rather than waiting for something to happen. I’m honored to have become one of these passionate teachers years later.My teachers inspired me, and thanks to my dad, here I am tonight. I think I should mention all the talents I have worked with over time, and to my kids and my wife Giannina, thank you.Thank you for this great award. I shall find a very special place for it.1. How did the author feel after taking GCE?A. Happy.B. Upset.C. Tired.D. Relieved.2. What didHartlepoolCollege of Art impress the author most?A. The teachers were strict with students.B. The students set good examples for each other.C. The teachers inspired students’ passion for learning.D. The students got prepared for their lessons independently.3. The author gave this speech to ________.A. share his career choiceB. explain his teaching methodsC. describe his life experienceD. show his appreciationBIt's a popular belief that a fish's memory lasts for only seven seconds. It may seem sad to think that they don't remember what they've eaten or where they’ve been, and they don't identify you or any of their friends--every moment intheir life would be like seeing the world for the first time.But don't be so quick to feel sorry for them. A new study has found that fish have a much better memory than we used to think. In fact, certain species of fish can even remember events from as long as 12 days ago. In the study, researchers from Mac Ewan University in Canada trained a kind of fish called African cichlids to go to a certain area of their tank to get food.They then waited for 12 days before putting them back in the tank again. Researchers used computer software to monitor the fish’s movements.They found that after such a long break the fish still went to the same place where they first got food. This suggested that they could remember their past experiences.In fact. scientists had been thinking for a long time that African cichlids might have a good memory. An earlier study showed that they behaved aggressively(挑衅地) in front of certain fish, perhaps because they remembered their past "fights".But until the latest findings, there was no clear evidence.Just as a good memory can make our lives easier, it also plays an important part when a fish is trying to survivein the wild. "If fish are able to remember that a certain area contains safe food, they will be able to go back to that area without putting their lives at risk,"lead researcher Trevor Hamilton told Live Science.For a long time, fish were placed far below chimpanzees, dolphins and mice on the list of smart animals.But this study has given scientists a new understanding of their intelligence.4. According to the text, people commonly believe that ______.A. fish don't recognize any of their friendsB. a fish's memory lasts for only seven minutesC. fish can only remember part of their past experiencesD. fish can remember things that happened long ago5. How can fish benefit most from a good memory?A. They can remember their enemies and fight.B. They can remember where to get food and survive.C. They can remember their friends and help each other.D. They can remember where to go when in danger.6. What can we learn from the text?A. Only African cichlids have a good memory.B. African cichlids can remember things for 12 days.C. African cichlids always treat other fish aggressively.D. African cichlids don't belong to the list of smart animals.7. What is the text mainly about?A. What we can learn from fish.B. Fish having a very bad memory.C. How fish improve their memory.D. Fish being smarter than we thought.CTeens who have good, supportive relationships with their teachers enjoy better healthas adults, according to research published by an American research center.“This research suggests that improving students' relationships with teachers could have positive and long-lasting effects beyond just academic success," said Jinho Kim, a professor atKoreaUniversityand author of the study."Itcould also bring about healthimplicationsin the long run.”Previous research has suggested that teens' social relationships might be linked to health outcomes in adulthood. However, it is not clear whether the link between teen relationships and lifetime health is causal（因果的）-it could be that other factors, such as different family backgrounds, might contribute to both relationship problems in adolescence and to poor health in adulthood. Also, most research has focused on teens' relationships with their peers（同龄人）, rather than on their relationships with teachers.To explore those questions further, Kim analyzed data on nearly 20,000 participants from the Add Health study, a national study in theU.S.that followed participants from seventh grade into early adulthood. Theparticipant pool included more than 3,400 pairs of siblings（兄弟姐妹）. As teens, participants answered questions, like “How often have you had trouble getting along with other students and your teachers?" As adults, participants were asked about their physical and mental health.Kim found that participants who had reported better relationships with both their peers and teachers in middle and high school also reported better physical and mental health in their mid-20s. However, when he controlled for family background by looking at pairs of siblings together, only the link between good teacher relationships and adult health remained significant.The results suggest teacher relationships are more important than previously realized and that schools should invest in training teachers on how to build warm and supportive relationships with their students. "This is not something that most teachers receive much training in," Kim said, “but it should be.”8. What does the underlined word “implications" in Paragraph 2 refer to?A. Recipes.B. Habits.C. Benefits.D. Risks.9. What is Paragraph 3 mainly about?A. Poor health in adolescence.B. Limitations of the previous research.C. Teens' relationships with their peers.D. Factors affecting health in adulthood.10. What does Kim's research show?A. Good adult health depends on teens' good teachers.B. Good family background promises long-term adult health.C. Healthy peer relationships leads to students' academic success.D. Positive student-teacher relationship helps students' adult health.11. Where does this text probably come from?A. A health magazine.B. A medical report.C. A term paper.D. A family survey.DGetting rid of dirt, in the opinion of most people, is a good thing However, there is nothing fixed about attitudes to dirt.In the early 16th century, people thought that dirt on the skin was a means to block outdisease, as medical opinion had it that washing off dirt with hot water could open up the skin and let ills in. A particular danger wasthought to lie in public baths. By 1538, the French king had closed the bath houses in his kingdom. So did the king ofEnglandin 1546. Thus began a long time when the rich and the poor inEuropelived with dirt in a friendly way. Henry IV, king ofFrance, was famously dirty. Upon learning that a nobleman had taken a bath, the king ordered that, to avoid the attack of disease, the nobleman should not go out.Though the belief in the merit(优点) of dirt was long-lived, dirt has no longer been regarded as a nice neighbor ever since the 18th century. Scientifically speaking, cleaning away dirt is good to health. Clean water supply and hand washing are practical means of preventing disease. Yet, it seems that standards of cleanliness have moved beyond science since World War II. Advertisements repeatedly sell the idea: clothes need to be whiter than white, cloths ever softer, surfaces to shine. Has the hate for dirt, however, gone too far?Attitudes to dirt still differ hugely nowadays. Many first-time parents nervously try to warn their children off touching dirt, which might be responsible for the spread of disease. On the contrary, Mary Ruebush, an American immunologist(免疫学家), encourages children to play in the dirt to build up a strong immune system. And the latter position is gaining some ground.12. The kings ofFranceandEnglandin the 16th century closed bath houses because .A. they lived healthily in a dirty environmentB. they thought bath houses were too dirty to stay inC. they considered bathing as cause of skin diseaseD. They believed disease could be spread in public baths13. Which of the following best describes Henry IV’s attitude to bathing?A. CuriousB. AfraidC. ApprovingD. Uninterested14. How does the passage mainly develop?A. By following the order of time.B. By making comparison.C. By providing examplesD. By following the order of importance.115. What is the author’s purpose in writing the passages?A. To call attention to the danger of dirt.B. To introduce the history of dirt.C. To present the change of views on dirt.D. To stress the role of dirt.第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。

2019-2020学年成都市七中育才学校高三语文下学期期末考试试题及答案一、现代文阅读（36分）(一)现代文阅读I(9分)阅读下面的文字，完成下面小题。

游移的容器朱以撒我一直认为一个人多搬几次家也有好处，它和新鲜的周边环境、人事关联，会生出许多新的念头。

每一个陌生的环境都是很有探索意义的，包括新空间的各种结构，和自己以前的感觉肯定有差别。

我搬到闽江边正是莺声已老的时节，江面上总是在清晨浮动着一层薄薄的水汽，很氤氲的情调。

我不善水，却对水有着欣赏的兴致。

每日在水边行走，看白鹭一步一啄的闲适，觉得一个人的心境若真如此，就是一只轻松的白鹭了。

闽江水在流经我住的这一段似乎特别徐缓，使人不复有孔夫子的逝水之叹。

一些人春冬无辍，背着浮桶下水，向江心游去，让自己的体温融在寒冷的水温里。

由于水缓也就不容易获得什么戏剧性——日子平平常常就好了，戏剧性是给外人看的，就像一个演员在台上风情万种地演，眉眼都是波澜，待她坐在后台喘气歇息，觉得这下才是真实的。

把楼盘建在江边肯定是开发商蓄谋已久的，而于入住者言，长久地拥有了一条江也是一种快慰。

譬如它的滋润，离江河很远的人是觉察不到的，滋润融在江边的空气里，无声地进入皮肤、器具。

滋润永远看不到，是感觉出来的，或者在抚摸时，指掌间触碰到了。

我往往会把一些宣纸钉在墙上退退火气，要写的时候取下来，抖一抖，它们柔软无骨，声响变得温和柔顺，不像先前哗啦哗啦地急切。

我说，我听到滋润潜入一张纸的每一条纤维里了。

几年后，我又搬了一次家。

那是在夕阳斜晖里，我看到了满山的芦苇闪动着银子般的光泽，素心同调，彼此俯仰。

很快地，暮色下来，四处静谧，后来就看到头顶密集的星辰，心中便有一丝暗喜。

在没有月亮的夜晚，一座山更显示出它的厚重和威严，尤其是草木朦胧其上，星点秋萤之火掠过，更是疑幻兼有。

山水如此地不同，水以长流为法，山以不动为宗，它们相同的地方只有一点，都是天生天养、自然而然的天物，动者自动，静者自静，于人来说，都可深于托寄情思。

成都七中育才学校 2020 届九年级（上）入学测试题数 学满分 150 分 时间 120 分钟A 卷（共 100 分）出题人：黄心雨审题人：罗丹梅、何瑜一、选择题（本大题共 10 个小题，每小题 3 分，共 30 分，答案涂在答题卡上）1．育才校园文化博大精深，以下是“育”、“才”、“水”、“井”四字的甲骨文，其中是中心对 称，但非轴对称图形的是（）A． B． C． D．2．下列各式由左边到右边的变形中，是因式分解的是（ ）A ． a ( x - y )＝ax ﹣ayB ．a 2+1＝a （a + 1）aC ．x 2﹣4x +3＝x （x ﹣4）+3D ． a 2 - b 2 = (a + b ) (a - b )3. 菱形 ABCD 的对角线 AC 、BD 的长分别为 8 和 6，则这个菱形的周长是（ ）A ．20B ．24C ．40D ．484. 若分式 (x + 3)(x -1)的值为 0，则 x 等于（） A ．1B ．1 或﹣3C ．﹣1 或 1D ．﹣15. 用配方法解方程 x 2+8x +9＝0，变形后的结果正确的是（ ）A ．（x +4）2＝﹣9B ．（x +4）2＝﹣7C ．（x +4）2＝25D ．（x +4）2＝76. 将点（﹣3，2）先向右平移 3 个单位，再向下平移 4 个单位后与 N 点重合，则点 N 坐标为（ ）A ．(-3,-2)B ．(0,-2)C ．(0,2)D ．(-6,-2)7. 如图，在 Rt △ABC 中，∠ACB ＝90°，∠BAC ＝33°，把△ABC 绕点 A 按顺时针方向旋转∠BAC 的大小，得到△AB ′C ′，延长 BC 交 B ′C ′于点 D ，则∠BDC ′等于（ ）A ．147°B ．143°C ．157°D ．153°8.如图，将两块完全相同的矩形纸片 ABCD 和矩形纸片 AEFG 按图示方式放置（点 A 、D 、E 在同一直线上），连接 AC 、AF 、CF ，已知 AD ＝3，DC ＝4，则 CF 的长是（ ）A ．5B ．7C ． 5D ．10 9.如图，已知 AB ∥CD ∥EF ，AD ：AF ＝3：5，BC ＝6，CE 的长为（ ） A ．2B ．4C ．3D ．510.如图，每个小正方形的边长均为 1，则下列图形中的三角形（阴影部分）与△A 1B 1C 1 相似的是（）A ．B ．C ．第 10 题图x -12D ．⎝ ⎭第 7 题图第 8 题图第 9 题图二、填空题（本大题共 4 小题，每小题 4 分，满分 16 分）11．已知某多边形的内角和等于外角和的 1.5 倍，则这个多边形的边数为 ．12．已知 x 2﹣2xy ＝6，2y 2﹣xy ＝5．则 x 2﹣4y 2＝．13．已知等腰三角形的周长为 29，一边长为 7，则此等腰三角形的腰长为． 14．如右图，在 Rt △ABC 中，∠C=90°，AC =12，BC=5，正方形 CEDF 按如图所示的方式放置，则该正方形的边长为．三、解答题（本大题共 6 小题，满分 54 分） 15.（每小题 5 分）（1）解方程： x (2x - 3) + (3 - 2x ) 2= 0 16.（每小题 6 分）（2）解分式方程：4 x 2 -1 +1 = x -1x +1⎛ a 2 - 2a 3 ⎫ 3 - a（2）化简： a 2 - 4a + 4 - a - 2 ÷ 4 - a 2 ，并从 2，3，4 中取一个合适的数作为 a 的值代入求值．17.（6 分）如图，在边长为 1 个单位长度的小正方形组成的网格中，△ABC 的顶点均在格点上，点 A 的坐标为（2，3），点 B 的坐标为（3，0），点 C 的坐标为（0，2）．（1）以点 C 为旋转中心，将△ABC 旋转 180°后得到△A 1B 1C 1，请画出△ A 1B 1C 1；（2）平移△ABC ，使点 A 的对应点 A 2 的坐标为（0，﹣1），请画出△A 2B 2C 2． （3）若将△A 1B 1C 1 绕点 P 旋转可得到△A 2B 2C 2，则点 P 的坐标为.18.（8 分）某商家预测“华为 P 30”手机能畅销，就用 1600 元购进一批该型号手机壳．面市后果然供不应求，又购进 6000 元的同种型号手机壳，第二批所购手机壳的数量是第一批的 3 倍，但进货单价比第一批贵了 2 元．（1）第一批手机壳的进货单价是多少元？（2）若两次购进手机壳按同一价格销售，全部售完后，为使得获利不少于 2000 元，那么销售单价至少为多少？19.（8 分）如图，在 Rt △ABC 中，∠ACB ＝90°，D 、E 分别是 AB 、AC 的中点，延长 BC 到 F ，使 1得 CF ＝ 2BC ，连接 CD 、EF ．（1）求证：四边形 CDEF 为平行四边形；（2）若四边形 CDEF 的周长是 32，AC ＝16，求△ABC 的面积；第 19 题图20.（10 分）如图，△ABC 是等腰直角三角形，∠ACB ＝90°，D 是射线 CB 上一点（点 D 不与点 B 重合），以 AD 为斜边作等腰直角三角形 ADE （点 E 和点 C 在 AB 的同侧），连接 CE ． （1）如图①，当点 D 与点 C 重合时，直接写出 CE 与 AB 的位置关系；（2）如图②，当点 D 与点 C 不重合时，（1）的结论是否仍然成立？若成立，请写出证明过程；若不成立，请说明理由；．B 卷（满分 50 分）一、填空题（每小题 4 分，共 20 分）ax21．若关于 x 的分式方程+= 2a 有增根，则 a 的值为 ．3 - x x - 323．若直线 l 1：y 1＝k 1x +b 1 经过点（0，2），l 2：y 2＝k 2x +b 2 经过点（3，1），且 l 1 与 l 2 关于 x 轴对称，则关于 x 的不等式 k 1x +b 1＞k 2x +b 2 的解集为 ． 24．正方形 A 1B 1C 1A 2，A 2B 2C 2A 3，A 3B 3C 3A 4，…，A n B n C n A n+1，…按如图所示的方式放置，点 A 1， A 2，A 3，…，A n ，…和点 B 1，B 2，B 3，…，B n ，…分别在直线 y ＝kx +b （k ＞0）和 x 轴上．已知点 A 1（0，1），点 B 1（1，0），则 C 3 的坐标是 ，C n 的坐标是 ． 25. 如图，AC ，BD 在 AB 的同侧，AC ＝1，BD ＝4，AB ＝4，点 M 为 AB 的中点，若∠CMD ＝120°， 则 CD 的最大值是 ．第 24 题图（左）第 25 题图（右）二、解答题（共30 分）26.（8 分）“绿水青山就是金山银山”，为了保护环境和提高果树产量，某果农计划把68 吨有机化肥运送到果园，为节省时间需要在一天之内运完．货运站有甲、乙两种货车，果农决定租用甲、乙两种货车共18 辆，两种型号的货车的运输量和租金如下表（所租用货车都按一整天收费）：（1）求所付的货车租金总费用y（元）与租用甲型货车数量x（辆）的函数关系式；（2）请你帮该果农设计一种使租金总费用最少的方案，并求出所付的最少租金．27.（10 分）在矩形ABCD 中，AB＝6，AD＝8，E 是边BC 上一点，以点E 为直角顶点，在AE 的右侧作等腰直角△AEF．（1）如图1，当点F 在CD 边上时，求BE 的长；（2）如图2，若EF⊥DF，求BE 的长；（3）如图3，若动点E 从点B 出发，沿边BC 向右运动，运动到点C 停止，直接写出线段AF 的中点Q 的运动路径长．28.（12 分）如图，已知长方形OABC 的顶点O 在坐标原点，A、C 分别在x、y 轴的正半轴上，顶点B（8，6），直线y＝﹣x+b 经过点A 交BC 于D、交y 轴于点M，点P 是AD 的中点，直线OP 交AB 于点E。

2019-2020学年成都市七中育才学校新校区高三语文期末考试试卷及参考答案一、现代文阅读（36分）(一)现代文阅读I(9分)阅读下面的文字，完成下面小题。

“天下”是中国传统文化对世界秩序的一种原初想象，“天下主义”是以“天下”理念为核心，由具有普遍性和开放性的世界秩序、价值规范与理想人格构成的思想体系。

在当今全球化语境之下，中国文化理念和文化战略的自觉自信体现的正是“天下主义”的精神内核。

文化自信首先是一种“以天下观天下”的世界观的自信。

《道德经》有云：“修之于天下，其德乃普。

故以身观身，以家观家，以乡观乡，以国观国，以天下观天下。

”“天下”是中国文化特有的思维尺度，是一个最宏大、最完备的分析单位，具有最广阔的容纳力。

面对差异性的多元文化格局，西方文化多以民族国家为基本单位，文化视域限于国家、民族内部，虽然也有关于世界的思考，比如斯多葛学派的“世界主义”等，但其思考方式是“以国家观世界”，与中国文化的立足点和尺度不同。

中国文化的“天下”蕴含了“天下无外”的理想，各个民族的历史文化在世界内部是平等共存的；中国文化依循“修身、齐家、治国、平天下”的进路，从“身-家-国”逻辑同构的角度，最终达到“天下大同”的境界。

与西方文化相较，“天下”的世界观更具有开放性和包容性。

文化自信的核心是“以天下为一家”的价值观的自信。

中国文化是以儒家文化为代表的伦理型文化，梁漱溟认为“中国伦理始于家庭而不止于家庭”，中国文化重视家庭生活，整个社会关系是依照家庭关系推广发挥的。

“以天下为一家”的价值观实质上是一种关系性伦理，把“自我”和“他者”看成一体共生的关系。

“天下”是一个最大的家，家庭利益的最大化就是个体利益的最大化，共同体的善与个体的善是统一的。

文化自信最终体现为一种人格自信。

无论是“以天下观天下”的世界观，还是“以天下为一家”的价值观，最终都沉淀为个体的精神品格。

中国文化倡导和推崇的理想人格是“君子”，这是由中国人独特的精神气质所决定的。

成都市七中育才学校2019~2020 学年度（下）6 月阶段性监测2022 届语文试题卷A 卷（100 分）第Ⅰ卷（选择题共 24 分）一、基础知识（每小题 3 分，共 12 分）1.下面加点字注音无误的一项是（）A 选聘．（pìn）迭．起 (dié) 步骤．（zòu）气冲斗．牛 (dǒu)B 呜咽．(yè)憎．恶（zēng）震悚．（sǒng）诲．人不倦 (huì)C 告罄．(qìng) 亘．古（gèng）诘．问（jié）白雪皑皑．(ái)D 侮．辱（wǔ）粗拙．（zhuō）慎．重（shèn）潜．心贯注(qiǎn)2.下列语句中书写完全正确的一项是（）A （长妈妈）喜欢切切察察，时常向人们低声叙说些什么事。

B无论什么情况下他都同样认真，不做到完全妥贴决不放松。

C 闻先生总是头发零乱，他是无暇及此。

D 刺骨的寒冷吞噬着他们已经疲惫不堪的躯体。

3.下列语句中加点的成语使用正确的一项是（）A 为了筹建助残爱心基金会，他呕．心．沥．血．，四处奔波。

B 晚年的他穷困潦倒、衣食无着，落得个马．革．裹．尸．的结局。

C 吴同学在年级歌咏比赛时迟到了，同学们从此对他深．恶．痛．绝．。

D 一心想要逃脱法律制裁的他在法庭上慷．慨．淋．漓．地为自己狡辩。

4.下列语句中没有语病的一项是（）A 市交管局发言人表示：成都地铁的修建，其目的是为了解决城市交通拥堵的难题。

B 记得我刚认识他的时候，还只是一个七八岁的孩子，天真烂漫、无拘无束。

C 纪录片《厉害了，我的国》展示了我国在各个领域所取得的举世瞩目的成就。

D对于“创建全国文明城市”这项工作，我们不仅要落实到位，也要宣传到位。

二、文言文阅读（每小题3 分，共12 分）阅读下面的文言文，完成5-8 题。

河中石兽纪昀沧州南一寺临河干，山门圮于河，二石兽并沉焉。

阅十余岁，僧募金重修，求二石兽于水中，竟不可得。

成都七中育才学校 2019-2020 学年度上期期中测试八年级语文试卷温馨提示：亲爱的同学们，进入八年级的你们，相信已褪去了青涩与懵懂，更多一份成熟与踏实。

希望你们细心、用心地完成试题，考出自己满意的成绩！试卷说明：全卷分 A 卷和B 卷，A 卷满分 100 分，B 卷满分 50 分；完成时间 120 分钟。

A 卷分第 I 卷和第 II 卷，第 I 卷为选择题，第 II 卷为其他类型的题。

请将答案写在答题卷上。

A 卷（100 分）第Ⅰ卷（选择题共 24 分）一、基础积累与运用（共 12 分，每小题 3 分）1.下面词语中加点字的读音完全正确的一项是（）A.要塞．（sài）教诲．（huǐ）不辍．（chuò）粗糙．（cāo）B.颁．发（bān）悄．然（qiǎo）炽．热（zhì）侏儒．（rú）C.夺魁．（kuí）咆哮．（xiào）骤．雨（zhòu）瞥．见（piē）D.歼．灭（qiān）渗．透（shèn）凛．冽（lǐn）周济．（jì）2.下列句子中没有错别字的一项是（）A.今年诺贝尔奖的获得者有：经济学家帕西，他建立了促进国际仲栽的各国议会联盟。

B.她那修长美妙的身体犹如被空气托住了，衬着蓝天白云，酷似敦煌壁画中凌空翔舞的“飞天”。

C.母亲是个好劳动。

她这样地整日劳禄着，我到四五岁时就很自然地在旁边帮她的忙了。

D.无疑，这张脸平淡无奇，嶂碍重重，没法弥补，不是传播智慧的殿堂，而是禁锢思想的囚牢。

3.下列句子中加点成语使用错误的一项是（）A.王老师一贯和．颜．悦．色．，我们遇到什么问题都愿意向她请教。

B.在公安机关的严厉打击下，锐．不．可．当．的恶势力团伙被彻底粉碎。

C.新中国刚成立之时，中国人民白．手．起．家．，创造着自己新的伟大的社会主义事业。

D.今天他正．襟．危．坐．，和平日嬉皮笑脸的样子判若两人。

4.下列语句没有语病的一项是（）A.体育蕴含着独特的魅力，它既能铸造健美的体魄，而且能展示奋力拼搏的精神。

2019~2020学年四川成都锦江区七中育才学校初二下学期期末英语试卷A卷听力略一、单项选择（共10小题，每小题1分，共10分）1.Xiao Zhan is talented actor. He is very popular these days.A.aB. anC. \2.—I'm busy, but Eliza wants me to hang out with her. What should I do?—I think you should learn to her invitation.A.turn downB. cut downC. fall down3.On November 11th, many people spent money buying useless things. I think they should choose thingsnext year.A.earlyB. seriouslyC. cheaply4.—Jack, can you buy some salt for me in the supermarket. It's not enough for the soup.—Mom, . But can I finish my homework first?A.I'd love toB. Sorry, I can'tC. I'm afraid not5.—yogurt do we need when we make a banana milk shake?—I think one cup is enough.A.How aboutB. How manyC. How much6.There is to discuss, so they will end the meeting very soon.A.something importantB. nothing importantC. anything important7.The teacher always says, "You can't get better grades you put your heart into it."A.as long asB. ifC. unless8.Tom sang of all in the singing competition. So he won the first prize.A.wellB. betterC. best9.—I wonder .—I think you can study computer science really hard.A.how I am going to become a computer programmerB.why you want to be a computer programmerC.where I can be a computer programmer10.All the students promised not to tell Ms． Brown anything about the party. They want to give her abig .A.concertB. surpriseC. invitation二、补全对话（共5小题，每小题2分，共10分）A: Mary, the winter vacation is coming soon.___1___B: I'm going to travel to Sanya with my friends. How about you?A: 2 We all like standing at the top of the mountains.B: It's great. 3A: Yes. We often do it when we have time.B: It's good exercise. 4A: Would you like to go there with us?B: ___5__My parents will go out. I have to look after my sister.A: What a good girl!三、完形填空（共15小题，共20分）AMore and more middle school students these days feel tired and angry. They even have no interest in their __1__ . Some of them stop studying and want to leave school.Some doctors and experts think many students have a lot of problems not only with their bodies but also with their minds. Many students start to 2 their homework or exams. Because they have too much pressure（压力）and can't have a good sleep. It is not good for their health and studies. What should they do with the problems?There are many ways to 3 them. First, some students spend too much time on study. They should find time to relax. Second, they should have enough time to sleep because it canhelp them make 4 mistakes. And a good sleep can make them understand teachers better. Finally, they should have exercise every day because it can help them relax. All students should know that doing exercise is 5 . As a saying goes "All work and no play makes Jack a dull（迟钝的） boy."1. A. exercise B. housework C. schoolwork2. A. hear about B. worry about C. think about3. A. solve B. keep C. follow4. A. less B. fewer C. more5. A. interesting B. difficult C. necessaryBOur parents and teachers always tell us to be honest （诚实的） and civilized （有教养的）, but many of us forget this as we _1 _ . That's not true for Yang Yang, a 14-year-old teenager from Changsha, a Hunan province. She moved many people by being honest in __2__ this year.On a cold and snowing morning, when Yang Yang getting __3_ to eat in a restaurant, she dropped （掉落） a full __4__ of food. She stood sadly and didn't know what to do. The restaurant waiter was so ___5__that he said to Yang. "Don't worry. We can give you_ 6__ meal for free."Everyone thought that this story would end like this. But when Yang left after eating, the waiter found 75 yuan and a piece of paper on the table. It said, "I'm sorry that the money might not be enough for my 7 , but that's all I have. Thank you for your help." The waiter was deeply touched after reading the words. He thought that the money was 8 a week's pocket money （零花钱） for the girl. He tried to 9 the honest girl on the internet. Finally, the waiter found the girl after her teacher heard about the story.However, Yang thought it was not a big thing. "I got other people's help and should 10 for their help, " she said. The reporter from People's Daily said, "This honest girl warm people's hearts by her words and action on such a cold winter day."1. A. grow up B. take up C. make up2. A. September B. April C December3. A. organized B. ready C. closed4. A. plate B. menu C. spoon5. A. angry B. understanding C. upset6. A. other B. others C. another7. A. experience B. mistake C. activity8. A. mainly B. hardly C. probably9. A. look for B. look after C. look at10. A. thank B. work C. prepare四、判断型阅读 (共5小题，每小题2分，共10分）1.The water can't stand the food in the UK after having three days of hamburgers, sandwiches and potatoes.2.To welcome the new students, the school prepared hotpot.3.Although hot pot and hotpot are different in writing they are the same food.4.The writer could have mutton, onion and tomatoes in the dining hall according to the article.5.Hot pot is cheap and easy to prepare, so we often see it at parties in the UK.五、阅读理解（共10小题，每小题2分，共20分）APeople in Beijing can't cat on the subway from May 2019. Are these subway rules good or bad? Different people have different ideas.1. Does Zhao Xin like the rules?A.Yes, he does.B. No, he doesn't.C. I don't know.2. Why doesn't Sun Run like the people eating on the subway?A. Because she is tired and hungry.B. Because she doesn't like the smell and it's difficult to keep the subway clean.C. Because she thinks the smell is bad and the subway is not a good place for eating.3. How many students disagree to eat on the subway?A. One.B. Two.C. Three4. Which of the following is right?A.Xing Yuxi doesn't think people can eat their food on the subway.B.Zhang Jiahao thinks the rules are good for keeping the subway clean.C.Sun Run thinks people should at least be able to drink water on the subway.5. The article mainly talks about .A. different ideas of eating on the subwayB. different rules on the subway.C. different people on the subwayBVincent Caspar is from Africa. He moved to America in the early 1980s. When he first arrived, he stayed at a hotel. He found out every morning the hotel workers par a new soap in his room. In fact, he could still use the old one. The next day, though he refused, the hotel worker gave him another new one. Vincent was surprised that many other hotels did the same thing in America.He thought it would be better to bring the old soap together and give it to pool people in Africa. Each year, many children in Africa die from illnesses（疾病）because of bacteria. People can easily stop such illnesses by washing hands with soaps.in 2001, Vincent set up an organization called the Global Soap Project （工程） . Many hotels join it. They send the used soap to the organization. Workers carefully put the soaps with the same color and smell together. They heat（加热）the soaps and make them into new ones. Finally, the organization takes the new soap to Africa and other poor countries and gives it to poor people. It is truly helpful to stop illnesses.1.When Vincent Caspar first arrived in America, he found .A.workers usually took soaps home from hotelsB. hotels threw away（扔掉） a lot of used soapsC. he should buy soaps in the hotel himself2. The underlined word "bacteria" means"______" in Chinese.A. 细菌B. 食品C. 矿物质3. Vincent Caspar brought the soaps together to .A. make moneyB. help poor peopleC. be famous4. Workers before they make new soaps.A. put the soaps into hot water and heat themB. cut the soaps into small piecesC. bring the soaps together and heat them5. What is the best title?A. Vincent—a helpful and warm-hearted man.B. Soaps—helpful to stop illness.C. A helpful organization—Global Soap Project.B卷六、首字母填空（共5小题，每小题1分，共5分）1. Everyone is surprised that so many buildings and f appear in town in such a short time. Lots of workers go there to look for jobs.2. C ___ the Spring Festival is one of Chinese people's favorite traditions. They always have a big meal with their family.3. Too many kids have the flu in hospital these days. There are no a beds there.4. Mr. Li found someone breaking into a car. He called the police. The police c__ the mansuccessfully with the help of Mr. Li.5. Greg hung out with his friends very late yesterday without telling his parents. So his father shouted at hima .七、补全对话（共10小题，每小题1分，共10分）A: What are you reading, Jill?B: I'm reading a book about parents and kids. It's interesting. Do you know "strawberry kids" ?A: No. I have never heard of it.B: The strawberry looks nice, but only a little pressure（压力） can make it out of 1__. Manystudents are like strawberries. They 2__break down when they face difficulties. They don't know what to do.A: I met such a student in the primary school. He was an excellent monitor（班长） in my class. One day, the teacher criticized（批评） him because he didn't organize the class meeting well, He felt so sad thathe even 3 this ability. He thought he was not good enough for the work as the monitor. Why are they so easy to break down?B: The book says parents are one of the 4 reasons. Most of these kids have helicopter parents. A: What does it 5 ?B: Helicopter parents take away all the difficulties and make almost 6 good for their kids. They try to do all they can for their kids in their daily life. So watching kids tail（失败） without helping them is the __7__thing helicopter parents can do in the world. Your monitor was such a strawberry kid. Maybe he had helicopter parents.A: I think so. His parents 8 criticized him. He was the best one in their eyes.B: But it's important for parents to let their kids grow up by failing and keeping on trying.A: I quite agree. I think helicopter parents have to know and 9 the idea of letting kids fail as part, of their growing life. They should give kids the time to be kids, grow up and experience life _10__ . As an expert said, "When you have problems, don't ask others for help too quickly."B: Yes. Problems and worries are normal in life. Everyone must face them and work them out.八、选词填空（共10小题，每小题1分，共10分）Do you hear of 5G? It can give you a faster online experience. You can download（下载） a moviein seconds _1__ 5G. In fact, 5G can do a lot more than this. Here are some of them.Education: Do you have online classes at home? With 5G, you can have classes outside your home. The classes can go smoothly（流畅地） as the__ 2___ , you have at home.Self-driving car: With the help of 5G. Self-driving cars can drive 3 than real drivers. These cars can send information to each other. They can also "talk" to traffic lights and road sensors （传感器）. 5G will make cars have faster response than 4 . It usually takes drivers longer to have responses.5 care: Xiao Ming is at school.6 he feels uncomfortable and falls down. An ambulance （救护车） comes. Doctors send Xiao Ming's information to the hospital by using 5G. Doctors at the hospital get the information. They have a video call 7 sure the illness. With 5G, people see doctors like this.Virtual reality（VR）虚拟现实 : You put on a headphones at home. Now you feel like you are at azoo. You hear the sound of the tigers. You can touch a fish. It makes you feel like you are really in a __8___ place.Smart home: 5G makes the Internet of Things 9 . The Internet of Things is a large network that join everything together. Smart homes are part of it.All in all, 5G will make our mobile Internet faster. It 10 in changing the traditional ways of living and working, too.九、七选五（共5小题，每小题1分，共5分）Li Ziqi, an online video maker, is famous and popular with many people now.Li's life looks like one out of a fairy tale（童话）. Her fans call her" the goddess（女神）of nature". 1 The most wonderful thing about her is that she does the things in a traditional Chinese way. Millions of people love her videos. These videos bring the inner（内心的） peace to the people. She has some 50 million fans in China and another 8 million outside China. However, they still know little about her. In her videos, she doesn't speak or have interviews. 2To find Li, we have to travel to a village in Sichuan in southwest of China. Li said she grew up with her grandparents there. She came to live with them because her step mother（继母） didn't like her. But her grandparents were poor. 3 In 2012, she decided to return to the countryside to look after her grandmother. Four years later, she started making online videos about her life there."When I worked in the city, it was about survival （生存） . Now when I worked inthe countryside, I feel like I'm truly living, " Li said, "What I want to bring to people is not complicated（复杂）. 4 A teacher friend once told me about some students who thought rice grew from trees. So I want kids in the city to know the truth."A few days ago, she got a prize from the Communist Youth League of China（中国共青团）. Some people say Li is one of China's most successful online video makers. __5__She is just filming her life or filming the life that she wants. "This is important to me. I have to work harder and do more things that are meaningful." says Li.十、任务型阅读（共5小题，每小题1分，共5分）Everyone needs friends. Friends are important in your life. They can make your life interesting. They can reach for your hand and touch your heart in difficult times. Life would be hard and boring without any friends.Friends are people you know well. Some of them may be outgoing. Some may be quiet. But they are all people you like to spend time with. When you are bored, you may have a friend who often plays with you. When you feel sad, you may have a friend who is always there to listen. While some people may have problems making friends, the following can help you.Tell the truth.A good friendship starts with telling the truth. Friends must believe in each other. Goodfriends always believe in one another and do things honestly（诚实地）. Tell the truth and do things honestly, your friend will be closer to you. Or they may leave you one day.Be ready to share.Sharing with your friends makes you happier. You don't have to give your money or your clothes to friends. You should talk about your ideas and feelings. In this way, your friends can know more about you.Understand each other.Understanding is important for everyone. Talking about the problem can make it easier to solve. You must try to put yourself in your friend's place, so you can understand the problem and your friend better.In fact, good friendship does not easily last. Each of you should do something to keep it. You must give as much as you take. If you don't, friendship will die away.十一、书面表达（共1小题，共15分）下面是一份有关学生习惯的问卷调查（questionnaire）。

2019-2020学年成都七中育才学校八年级（上）开学考数学试卷（考试时间：120分钟满分：150分）一、选择题（每小题3分，共30分）1．下列计算正确的是（）A．（x+3）2＝x2+9 B．a2•a3＝a6C．2x﹣2＝D．（a2）3＝a62．人体中红细胞的直径约为0.0000077米，将0.0000077用科学记数法表示为（）A．7.7×10﹣6B．7.7×10﹣5C．0.77×10﹣6D．0.77×10﹣53．如图，AB∥CD，若∠2＝135°，则∠1的度数是（）A．30°B．45°C．60°D．75°4．以下列各组线段的长为边，能组成三角形的是（）A．2cm，5cm，10cm B．2cm，3cm，4cmC．2cm，3cm，5cm D．8cm，4cm，4cm5．下列说法正确的是（）A．抛掷一个正方体骰子，点数为奇数的概率是B．买一张福利彩票一定中奖，是不可能事件C．在地球上，上抛的篮球一定会下落，是必然事件D．从一个装有5个黑球和1个红球的口袋中，摸出一个球是黑球是必然事件6．若x﹣3y＝﹣5，则代数式5﹣2x+6y的值是（）A．0 B．5 C．10 D．157．下列说法正确的是（）A．169的平方根是13B．﹣没有立方根C．正数的两个平方根互为相反数D．﹣（﹣13）没有平方根8．如图，在△ABC中，∠B＝90°，AC＝10，AD为此三角形的一条角平分线，若BD＝3，则三角形ADC的面积为（）A．3 B．10 C．12 D．159．两个三角形具备下列（）条件，则它们一定全等．A．两边和其中一边的对角对应相等B．两个角对应相等C．三条边对应相等D．两边及第三边上的高对应相等10．小亮从家出发步行到公交站台后，等公交车去学校，如图，折线表示这个过程中行程s（千米）与所花时间t（分）之间的关系．下列说法错误的是（）A．他家到公交车站台需行1千米B．他等公交车的时间为4分钟C．公交车的速度是500米/分D．他步行与乘公交车行驶的平均速度是300米/分二、填空题（每小题4分，共16分）11．计算（20192﹣20182）0＝．12．如果x2+（m﹣1）x+1是完全平方式，则m的值为．13．已知，如图所示，AB＝AC，AD⊥BC于D，且△ABC的周长为50cm，△ABD的周长为40cm，则AD＝cm．14．如图，一个长方体纸盒，它的长、宽、高分别为8cm，4cm，5cm，在盒顶点处A处有一只壁虎，它发现盒内其对顶角顶点B处有一只苍蝇，于是壁虎向点B爬行，则这只壁虎由A点爬行至点B的最短路径的平方为．三、解答题（共54分）15．（8分）计算：（1）|﹣3|+÷（﹣2）﹣3﹣（π﹣3.14）0 （2）（x+y）2+（2x+3y）（3x+2y）16．（6分）化简求值：[（x2+y2）﹣（x﹣y）2+2y（x﹣y）]÷（﹣2y），其中|2x﹣1|+（y+3）2＝017．（6分）在Rt△ABC中，∠C＝90°，∠A、∠B、∠C的对边分别为a、b、c．若a：c＝15：17，b＝24，求a．18．（8分）如图，AB∥CD，直线EF分别交AB、CD点E、F，EG平分∠AEF，（1）求证：△EGF是等腰三角形．（2）若∠1＝40°，求∠2的度数．19．（8分）某初中对600名毕业生中考体育测试坐位体前屈成绩进行整理，绘制成如下不完整的统计图：根据统计图，下列问题．（1）请将条形统计图补充完整；（2）扇形统计图中，b＝，得8分所对应扇形的圆心角度数为；（3）在本次调查的学生中，随机抽取1名男生，他的成绩不低于9分的概率为多少？20．（8分）一列快车从甲地驶往乙地，一列慢车从乙地驶往甲地，两车同时出发，到达目的地后停止，设慢车行驶时间为x小时，两车之间的距离为y千米，两者的关系如图所示：（1）两车出发小时后相遇；（2）求快车和慢车的速度；（3）求线段BC所表示的y与x的关系式，并求两车相距300千米时的时间．21．（10分）如图1，将两个完全相同的三角形纸片ABC和DEC重合放置，其中∠C＝90°，∠B＝∠E＝30°．（1）操作发现：如图2，固定△ABC，使△DEC绕点C旋转，当点D恰好落在AB边上时，填空：①线段DE与AC的位置关系是；②设△BDC的面积为S1，△AEC的面积为S2，则S1与S2的数量关系是．（2）猜想论证：当△DEC绕点C旋转到如图3所示的位置时，小明猜想（1）中S1与S2的数量关系仍然成立，并尝试分别作出了△BDC和△AEC中BC、CE边上的高，请你证明小明的猜想．（3）拓展探究已知∠ABC＝60°，点D是角平分线上一点，BD＝CD＝6，DE∥AB交BC于点E（如图4），若在射线BA上存在点F，使S△DCF＝S△BDE，请求出相应的BF的长．参考答案与试题解析1．【解答】解：A、（x+3）2＝x2+6x+9，故本选项错误；B、a2•a3＝a2+3＝a5，故本选项错误；C、2x﹣2＝，故本选项错误；D、（a2）3＝a2×3＝a6，故本选项正确．故选：D．2．【解答】解：0.0000077＝7.7×10﹣6．故选：A．3．【解答】解：∵AB∥CD，若∠2＝135°，∴∠2的同位角为135°．∴∠1＝180°﹣135°＝45°．故选：B．4．【解答】解：根据三角形的三边关系，得A、253＜10，不能组成三角形；B、3+2＞4，能够组成三角形；C、3+2＝5，不能组成三角形；D、4+4＝8，不能组成三角形．故选：B．5．【解答】解：A、抛掷一个正方体骰子，点数为奇数的概率是，故此选项错误，不合题意；B、买一张福利彩票一定中奖，是可能事件，故此选项错误，不合题意；C、在地球上，上抛的篮球一定会下落，是必然事件，正确，符合题意；D、从一个装有5个黑球和1个红球的口袋中，摸出一个球是黑球是随机事件，故此选项错误，不合题意；故选：C．6．【解答】解：原式＝5﹣2（x﹣3y）＝5﹣2×（﹣5）＝15．故选：D．7．【解答】解：A、169的平方根是±13，故本选项错误；B、﹣有立方根，是﹣，故本选项错误；C、正数的两个平方根互为相反数，故本选项正确；D、﹣（﹣13）＝13，有平方根，故本选项错误．故选：C．8．【解答】解：过D作DE⊥AC于E．∵AD是∠BAC的角平分线，∠B＝90°（DB⊥AB），DE⊥AC，∴BD＝DE，∵BD＝3，∴DE＝3，∴S△ADC＝•AC•DE＝×10×3＝15故选：D．9．【解答】解：A、两边和其中一边的对角对应相等，不能判定两个三角形全等，故此选项错误；B、三个角对应相等，不能判定两个三角形全等，故此选项错误；C、三条边对应相等两个三角形全等，故此选项正确；D、两边及第三边上的高对应相等，这两边的夹角有可能一个是锐角一个是钝角，所以这两个三角形不一定全等，故此选项错误；故选：C．10．【解答】解：由函数图象可知他家到公交车站台需行1千米，他等公交车的时间＝14﹣10＝4分钟，故A、B正确，与要求不符；公交车的速度＝（5﹣1）×1000÷（22﹣14）＝4000÷8＝500米/分，故C正确，与要求不符；他步行与乘公交车行驶的平均速度＝5×1000÷（22﹣4）＝米/分，故D错误，与要求相符．故选：D．11．【解答】解：∵20192﹣20182≠0，∴（20192﹣20182）0＝1．故答案为：112．【解答】解：∵x2+（m﹣1）x+1是完全平方式，∴（）2＝1，即（m﹣1）2＝4，开方得：m﹣1＝2或m﹣1＝﹣2，解得：m＝3或m＝﹣1．故答案为：3或﹣1．13．【解答】解：∵△ABD的周长＝AD+AB+BD＝40cm，∵AB＝AC，AD⊥BC于D，∴BD＝CD，∵△ABC的周长＝AC+AB+BD+DC＝2（AB+BD）＝50cm，∴2△ABD的周长＝2（AB+BD+AD）＝80cm，∴2AD＝80﹣50＝30cm，解得：AD＝15cm，故答案为：1514．【解答】解：如图（1）：AB2＝（8+4）2+52＝169；如图（2）：AB2＝82+（5+4）2＝145；（3）如图（3）：AB2＝42+（5+8）2＝185．∵145＜169＜185，∴最短路径的平方为145故答案为：145．15．【解答】解：（1）|﹣3|+÷（﹣2）﹣3﹣（π﹣3.14）0＝3+÷（﹣8）﹣1＝3﹣﹣1＝1；（2）（x+y）2+（2x+3y）（3x+2y）＝x2+2xy+y2+6x2+13xy+6y2＝7x2+15xy+7y2．16．【解答】解：原式＝（x2+y2﹣x2+2xy﹣y2+2xy﹣2y2）÷（﹣2y）＝（4xy﹣2y2）÷（﹣2y）＝﹣2x+y，由于|2x﹣1|+（y+3）2＝0，∴x＝，y＝﹣3，∴原式＝﹣1+（﹣3）＝﹣4．17．【解答】解：设a＝15x，则c＝17x，由勾股定理得，（15x）2+242＝（17x）2，解得，x＝3，则a＝15x＝45．18．【解答】（1）证明：∵AB∥CD，∴∠1＝∠AEG，∵EG平分∠AEF，∴∠AEG＝∠FEG，∴∠1＝∠FEG，∴FE＝FG，即△EGF是等腰三角形；（2）解：∵∠1＝40°，∠1＝∠AEG＝∠FEG，∴∠AEF＝40°+40°＝80°，∴∠2＝180°﹣80°＝100°．19．【解答】解：（1）10分的人数有600﹣20﹣10﹣40﹣20﹣80﹣70﹣180＝180（人），补图如下：（2）10分所占的百分比是：×100%＝60%，则b＝60，得8分所对应扇形的圆心角度数为360°×＝36°；故答案为：60，36°；（3）根据题意得：＝，答：他的成绩不低于9分的概率为．20．【解答】解：（1）由图知：两车出发4.8小时相遇；故答案为：4.8（2）快车8小时到达，慢车12小时到达，故：快车速度为1200÷8＝150（千米/时），慢车速度为1200÷12＝100（千米/时）；（3）由题可得，点C是快车刚到达乙地，∵点C的横坐标是8，∴纵坐标是：100×8＝800，即点C的坐标为（8，800）．设线段BC对应的函数解析式为y＝kx+b，∵点B（4.8，0），点C（8，800），∴，解得，∴线段BC所表示的y与x的函数关系式是y＝250x﹣1200（4.8≤x≤8）．当y＝300时，300＝250x﹣1200，解得x＝6．（1200﹣300）÷（150+100）＝3.6（小时）．即两车相距300千米时的时间为6或3.6时．21．【解答】解：（1）①如图1中，由旋转可知：CA＝CD，∵∠ACB＝90°，∠B＝30°，∴∠CAD＝60°，∴△ADC是等边三角形，∵∠ECD＝90°，∠DEC＝30°，∴∠CDE＝60°，∴∠EDC＝∠DCA，∴DE∥AC，②∵AB＝2AC，AD＝AC，∴AD＝BD，∴S△BDC＝S△ADC，∵DE∥AC，∴S△ADC＝S△ACE，∴S1＝S2．故答案为：DE∥AC，S1＝S2．（2）如图3中，∵△DEC是由△ABC绕点C旋转得到，∴BC＝CE，AC＝CD，∵∠ACN+∠BCN＝90°，∠DCM+∠BCN＝180°﹣90°＝90°，∴∠ACN＝∠DCM，在△ACN和△DCM中，，∴△ACN≌△DCM（AAS），∴AN＝DM，（3）如图4中，作DF∥BC交AB于F．延长CD交AB于H．∵DF∥BE，DE∥BF，∴四边形DEBF是平行四边形，∴S△BDF＝S△BDE，S△BDF＝S△DFC，∴S△DFC＝S△BDE，∵∠ABC＝60°，BD平分∠ABC，∴∠ABD＝∠DBE＝30°，∵DF∥BE，∴∠FDB＝30°，∴∠FBD＝∠FDB＝30°，∴FB＝FD，∴四边形DEBF是菱形，∵BD＝CD＝6，∴∠DBC＝∠DCB＝30°，∵∠DEC＝∠ABC＝60°，∴∠CDE＝90°，∴DE＝CD•tan30°＝6×＝2，∴BF＝DE＝2，∵DE∥AB，∴∠BHC＝∠EDC＝90°，∴CH⊥AB，作点F关于CH的对称点F′，连接DF′，易知S△DFC＝S△DF′C，在Rt△DFH中，FH＝HF′＝DF•sin30°＝，∴BF′＝4，综上所述，满足条件的BF的值为2或4。

2019-2020学年成都市七中育才学校新校区高三英语期末试卷及答案第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项AFilms to watch in MarchGretaA lonely young waitress finds a handbag on aNew Yorksubway train. Luckily, the address is inside, so she returns it to the piano teacher who left it there. She then discovers that the piano teacher makes a habit of dropping bags around the city on purpose to make new friends. Directed by Neil Jordan, the actors are attractive. Grace Moretz is the waitress and Isabelle Huppert is the one who admires her. Thanks to them, Greta winds up being far more enjoyable than it has any right to be.The AftermathThe Aftermath is one of the few World WarⅡ-related films. Based on Rhidian Brook’s novel,this touching romantic movie is starred by Keira Knightley, who is the wife of a British officer. She hates the Germans because her son was killed in an air raid. But is there a chance that a tall, dark andhandsome man might persuade her to overcome her hate?Captain MarvelIt took Marvel Studios a decade to finally make a female superhero. It’s also the first Marvel film to be directed by a woman, who has directed Half Nelson and Missisippi Grind. Captain Marvel is set in the 1990s. The Oscar-winning Brie Larson stars as Carol Danvers, a US Air Force fighter pilot, while Samuel L Jackson, as usual, plays Nick Fury.DumboDumbo is a classic Disney cartoon, who has big ears and there have been plenty of those kind of movies in recent years.Burtonalways has inspirations to direct such kind of movies from Edward Scissorhands to Miss Peregrine’s Home for Peculiar Children. Magical figures have always been his favorite characters.1. What makes Captain Marvel special?A. Winning Oscar.B. Its female director.C. Time setting.D. A woman pilot.2. Which film is better for a 7-year-old kid to watch?A. The AftermathB. Captain MarvelC. GreteD. Dumbo3. Where can you most probably read the text?A. Reader’s DigestB. NatureC. Scientific AmericanD. National GeographicBIt all happened one afternoon in Carl's backyard a few years ago. We had just finished playing stickball, and I was about to go home.“Wait a minute,” Carl yelled. He ran into his house and cameback with a book for me to take home and read. All he said was, “See if you like it.”I said ly nothing. I kept the book for a couple of weeks and then returned it unread. Carl never asked me if I liked it or not. During the following two years Carl lent me three more books. Each time I returned them unread.A few days after graduating from high school, Carl asked, “Benny, which college are you going to?”“I'm not going to college.” I said.“Why not?” he asked.“Because my father can't afford the tuition (学费).” I answered.“Is that it?” Carl asked. “Yes,” I said.I lied. I had no intention of going back to school now that I was out. The following day, Carl knocked on my door and handed me a check for seventy-five dollars from his father along with the bookMartin Eden.“I think that should do it.” he said.Once again I was in shock. I was working full-time in my brother's bakery. I attended two classes atWayneUniversitypart-time at night. Halfway through the semester, after receiving failing grades on exams and essays, I decided there was no way I would ever become a good student and get satisfactory grades. I dropped out of college.One day, curious, I picked up the book, thinking Carl was trying to tell me something. Despite difficulty, I pressed on. By the time I finished the book, I understood why: the main character, Martin Eden, had my own poor educational background, but managed to educate himself and become a published author.4. What do we know about the author?A. He often told lies.B. He quit school unwillingly.C. He had thought little of education before.D. He became a published author.5. What kind of person is Carl?A. Caring.B. Emotional.C. Stubborn.D. Cautious.6. What message does Carl want to convey?A. Reading makes a rich man.B. Reading is the journey of the soul.C. Reading makes a person better known.D.Readingopens up new opportunities.7. What is the best title for the text?A. A strong desire for collegeB. A wish for better educationC. A wise friendD. A wise bookCNowadays organic food hasbecome a fashion. Organic food sales reached a record of $ 45.2 billion in 2017, making it one of the fastest-growing parts of American agriculture. Some people may buy organic food for these reasons like resource cycling and biodiversity, but most people may choose organic food because they think it's healthier. While a small number of studies have shown relationships between eating organic food and reducing risks of being ill, no studies, up to now, have answered the question whether eating organic food can improve health.According to the United States Department of Agriculture(USDA), organic food does not suggest anything about health. In 20155 Miles McEvoy, then chief of the National Organic Program for the USDA, refused to admit any health benefits of organic food, saying the question has nothing to do with the National Organic Program. Instead, the USDA thinks that organic refers to a production method that increases cycling of resources keeps ecological balance, and protects biodiversity.I'm an environmental health scientist who has spent over 20 years studying pesticides that do harm to human beings. Several years ago, I was part of the study on whether an organic diet can reduce pesticide exposure. This study focused on a group of pesticides which have always been harmful to children's brain development. We found that children who ate traditional diets had nine times higher exposure to these pesticides than children who ate organic diets.Last month, I published a small study that suggested a path forward to answering the question whethereating organic food actually improves health. My study got a lot of attention. While the results were novel, they didn't answer the big question. As I toldThe New York Timesin 2003, “What does this really mean for the safety of my kids? But we don't know. Nobody does. It was true then, and it's still true now.”8. Why do most people prefer to buy organic food?A. For its health benefits.B. For biodiversity.C. For its delicious taste.D. For resource cycling.9. What does the USDA suggest about organic food?A. It can improve people's health.B. It is produced in an environment-friendly way.C. It can reduce risks of being ill.D. It has nothing to do with the National Organic Program.10. What can be concluded from the author's study?A. Pesticides don't harm children's brain.B. Traditional diets benefit people's health.C. Organic diets can reduce pesticide exposure.D. The results are meaningful to children's safety.11. What is the best title for the text?A.What Is Organic Food?B. Is Organic Food Healthier?C. How Should We Avoid Pesticides?D. What Are the Benefits of Organic Food?DTo hear people talk about Internet friendships, you would think it was one giant web of cat-fishing and e-crime. While we all undoubtedly have to take measures to remain safe online, assuming every friendship or connection made on Instagram, Twitter or Facebook is cheating or insincere would be a mistake.As a woman who works in the creative industry, I have found real joy in seeking out a community I couldn’t find elsewhere, and making some great friends along the way. My first online friendship was on Twitter with my(now) best friend, during the university exam period. We exchanged study notes in dozens of direct messages, set a study date, and haven’t looked back since.Drawn to each other by similar circumstances, friendships online are similar to offline in that they tend to begin because of shared interest or common ground-maybe they’ve read the post on Instagram. Maybe they have the same taste in food or politics. Or maybe they just love memes too. If online friendships start similar to friendships offline, they grow in the same way, too. Often through mutual support: apart from calling a friend to congratulate him on that new job, you also re-tweet his jokes and praise his Instagram story.Despite my positive experiences when I tell people, most are still suspicious. Eyebrows are raised higher when I explain not only have I found a community online but have made friendships with people I meetface-to-face too. Actually, these are just as valid as other friendships, according to behavioural psychologist Jo Hemmings, who says online friendships can be real.So how do you know if people are there for the real you or just because you’re popular on Instagram? Hemmings has simple rules. She tells me “You have to equally feel comfortable that you’re getting something of each other instead of being used to enable something that isn’t friendship.”Therefore, if all a “friend” online is asking you to do is to promote their work or personal brand and rarely takes an interest in you, then there may be room to question the basis of the friendship. On that note it is worth remembering that just because someone has a lot of followers, it doesn’t necessarily mean they have lots of friends.12. What is most people’s attitude towards online friendship?A. Negative.B. Positive.C. Objective.D. Neutral.13. Why does the writer share her own experience in paragraph 2?A. To introduce the background information of the text.B. To convey the writer’s attitude and give the related example.C. To prove the likely risk for people to develop friendship online.D. To remind people of the various benefits of making friends online.14. How can online and offline friendships be deepened?A. They should be based on shared interest.B. They need to have common ground.C. They require support from each other.D. They can’t live without social media.15. According to the author, what’s the golden rule to make friends online?A. A friend to all is a friend to none.B. Without confidence there is no friendship.C. A friend without faults will never be found.D. Friendship cannot stand always on one side.第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。