2019年度2020年度学年上海地区浦东新区建平中学高三上学期周练试卷(附答案解析和解析)

2019-2020学年上海市建平中学高三英语上学期期中试题及答案解析第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项AChildren under the age of 18 will be allowed up to three hours per week to play video games, according to a notice issued by China's National Press and Publication Administration. Online game companies are required to provide services to minors — from8 to 9 p. m. on Fridays, Saturdays, Sundays and legal holidays — as a way to safeguard their physical and mental health. Children are playing more and more online games these days. Is it time to limit their online gaming time? What role do parents have? Readers share their opinions.RizlaredOnline games are addictive, but if children are taught how to manage in a sensible and responsible manner then it is no longer a threat(威胁).To achieve this, parents need to set examples for not being glued to their phones. Teaching is and always will be the best solution to such problems.AndrewGood policy. By limiting time spent on online games, kids can spend time doing more useful things to develop their potential. They can go outside and run, jump and swim instead of sitting on a couch at home and playing with a smart phone.AdamIt is often seen that parents argue with children over cellphones. Most parents can hardly set and enforce the time limit for its daily usage. Some forcibly take away their cellphones, but it will ruin trust and relationship. Even worse, it will make their kids hate them.PinkExcessive(过度的）gaming is purely a waste of time and energy for minors and has a negative effect on both physical and mental health. The gaming industry should not put profit- flaking interests as its priority (优先事项) . They should act in a socially responsible way toprovide an environment for children to ensure their well-being and development.LaurenThere would be a loophole(漏洞). Children could use their parents’ or other adults’ IDs to avoid real-name registration, thus making it impossible to put this policy in effect. Parents ly need to strengthen guidance andsupervision to keep their children from gaming addiction.1. What should kids do according to Andrew?A. Play online games.B. Play with a smart phone.C. Study all the time.D. Go in for outside activities.2. What does Pink advise the gaming industry to do?A. Pay attention to its profit.B. Focus on kids’ health.C. Be responsible for kids’ surroundings.D. Persuade kids lo play more games.3. What role do parents have according to the passage?A. They keep hold of their phones.B. They set examples for their kids.C. They limit their kids’ time.D. They blame kids for addiction.BLast year, 138,000San Franciscoresidents used Airbnb, a popular app designed to connect home renters and travelers. It’s a striking number for a city with a population of about 850,000, and it was enough for Airbnb to win a major victory in local elections, asSan Franciscovoters struck down a debatable rule that would have placed time restrictions and other regulations on short-term rental services.The company fiercely opposed the measure, Proposition F, with a nearly $10 million advertising campaign. It also contacted its San Franciscan users with messages urging them to vote against Proposition F.Most people think of Airbnb as a kind of couch-surfing app. The service works for one-night stays on road trips and longer stays in cities, and it often has more competitive pricing than hotels. It’s a textbook example of the “sharing economy”, but not everyone is a fan.The app has had unintended consequences inSan Francisco. As the San Francisco Chronicle reported last year, a significant amount of renting on Airbnb is not in line with the company’s image: middle-class families putting up a spare room to help make ends meet. Some users have taken advantage of the service, using it to turn their multiple properties into vacation rentals or even full-time rentals. Backers of Proposition F argued that this trend takes spaces off the conventional, better-regulated housing market and contributes to rising costs.“The fact is, widespread abuse of short-term rentals is taking much needed housing off the market and harming our neighborhoods,” said ShareBetter SF, a group that supported Proposition F. Hotel unions have protested the company’s practices inSan Franciscoand other cities, saying that it creates an illegal hotel system.San Franciscois in the middle of a long-term, deeply rooted housing crisis that has seen the cost of living explode. Actually, explode is a generous term. The average monthly rent for an apartment is around $4, 000.Located on a narrow outcropping of land overlooking the bay,San Franciscosimply doesn’t have enough space to accommodate the massive inflow of young, high-salaried tech employees flocking toSilicon Valley.As the Los Angeles Times reported, someSan Franciscoresidents supported the measure simply because it seemed like a way to check a big corporation. Opponents of Proposition F countered that the housing crisis runs much deeper, and that passing the rule would have discouraged a popular service while doing little to solve the city’s existing problems.4. The intention of Proposition F is to ________.A. place time limits in local election.B. set limits on short-term rental.C. strike down a controversial rule.D. urge users to vote against Airbnb.5. What is the negative consequence of Airbnb onSan Francisco?A. It shrinks the living space of middle-class families.B. Users are taken advantage of by the service financially.C. It makes the house market more competitive.D. It indirectly leads to high house rental price.6. The housing crisis inSan Franciscoresults from ________.A. explosion of the living costB. its geographic characteristicsC. generosity of local enterprisesD. inflow of migrant population7. Theauthor’s attitude toward Proposition F is ________.A. objectiveB. supportiveC. negativeD. indifferentCDolores Huerta has worked hard most of her life to help other people. She has helped change things so that others can have a better life.Dolores grew up in California. She was a good student and liked school. After she finished high school, she went to college and studied to be a teacher. After college, she became a teacher. Dolores noticed that many of her students were not getting enough food to eat. Some of them wore very old clothes. Dolores wondered how she could help them.Dolores liked teaching but she decided to quit her job so that she could spend more time helping her students and their families. One thing she wanted to do was to get more pay for their parents, farm workers. Thus they could buy their children what they needed.Dolores knew that many farm workers moved often from one place to another to help pick different kinds of fruits and vegetables, like grapes and tomatoes. She began talking and writing about these workers. Even people who lived far from California read what Dolores wrote. Getting higher pay for the farm workers was not easy. Dolores worked hard to make sure that farm workers got fair pay for their work. She knew that nothing would change unless new laws were made to help the workers. Through all her hard work, new laws were passed that gave farm workers fair pay.Dolores Huerta has worked for more than 30 years in many different ways to make life better for working people. She has shown how much one person can change things.8. What did Dolores find about her students?A. They worked hard to make a living.B. They lived far away from schools.C. They had little time to play.D. They were hungry sometimes.9. Why did Dolores stop teaching?A. She wished to be a lawyer.B. She moved to another place.C. She wanted to help her students more.D. She got little money by teaching.10. Thanks to Dolores’ great effort, the farm workers ________.A. got better jobsB. got fair payC. had more time offD. had a settled way of life11. What is the main idea of the passage?A. One person can make big changes.B. One can change their jobs often.C. One person can work hard for others.D. One can make life better by themselves.DIn the summer of 2016, I gave a talk at a small conference in northernVirginia. I began by admitting that I’d never had a social-media account; I then outlined arguments for why other peopleshould consider removing social media from their lives. The event organizers uploaded the video of my talk to YouTube. Then it was shared repeatedly on Facebook and Instagram and, eventually, viewed more than five million times. I was both pleased and annoyed by the fact that my anti-social-media talk had found such a large audience on social media.I think of this event as typical of the love-hate relationships many of us have with Facebook, Instagram, and other social-media platforms. On the one hand, we’ve grown cautious about the so-called attention economy,which, in the name of corporate(公司的) profits, destroys social life gradually and offends privacy. But we also benefit from social media and hesitate to break away from it completely. Not long ago, Imet a partner at a large law firm in Washington, D.C., who told me that she keeps Instagram on her phone because she misses her kids when she travels; looking through pictures of them makes her feel better.In recent months, some of the biggest social-media companies, Facebook and Twitter, in particular, have promised various reforms. In March, Mark Zuckerberg announced a plan to move his platform toward private communication protected by end-to-end encryption(端对端加密); later that month, he put forward the establishment of a third-party group to set standards for acceptable content.All of these approaches assume that the reformation of social media will be a complex, lengthy, and gradual process. But not everyone sees it that way. Alongside these official responses, a loose collective of developers that calls itself the IndieWeb has been creating another alternative. They are developing their own social-media platforms, which they say will preserve what’s good about social media while getting rid of what’s bad. They hope to rebuild social media according to principles that are less corporate and more humane(人道的).12. Why did the author feel annoyed when his video was spread online?A. His video caused many arguments.B. His video was shared without his permission.C. His talk was opposed by a large amount of people.D. His video’s popularity on social media is against his talk.13. Why does the author mention the story of his partner in paragraph 2?A. To prove that social media has some benefits.B. To advise people to break away from social media.C. To tell the negative effects social media may produce.D. To describe people’s complicated relationships with social media.14. What is the purpose of the reform made by some social-media companies?A. To attract more users.B. To improve network environment.C. To make more profits.D. To provide more convenientservice.15. What does the IndieWeb intend to do?A. Develop new social-media platforms.B. Remove social media from people’s lives.C. Improve the existing social-media principles.D. Help social-media companies to make reformation.第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。

2019-2020学年上海市建平中学高三英语期中考试试题及答案第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项AIn his 402nd anniversary year, Shakespeare is still rightly celebrated as a great language master and writer. But he was not the only great master of play writing to die in 1616, and he is certainly not the only writer to have left a lasting influence on theater.While less known worldwide, Tang Xianzu is considered one of Chinas greatest playwrights and is highly spoken of in that country of ancient literary and dramatic traditions.Tang was born in 1550 inLinchuan,Jiangxiprovince. Unlike Shakespeare's large body of plays,poems and sonnets (十四行诗), Tang wrote only four major plays: The Purple Hairpin, Peony Pavilion (《牡丹亭》), A Dream under the Southern bough, and Dream of Handan. The latter three were constructed around a dream narrative, a way through which Tang unlocked the emotional dimension of human desires and ambitions and explored human nature beyond the social and political limits of that time.Similar to Shakespeare, Tang's success rode the wave of a renaissance (复兴) in theater as an artistic practice. As in Shakespeare'sEngland, Tang's works became hugely popular inChinatoo. During Tang'sChina, his plays were enjoyed performed, and changed. Kunqu Opera, a form of musical drama, spread from southernChinato the whole nation and became a symbol of Chinese culture. Combining northern tune and southern music, kunqu Opera was known for its poetic language, music, dance movements and gestures. Tang's works benefited greatly from the popularity of kunqu Opera, and his plays are considered classics of kunqu Opera.While Tang and Shakespeare lived in a world away from each other, there are many things they share in common, such e humanity of their drama, their heroic figures, their love for poetic language, a lasting popularity and the anniversary during which we still celebrate them.1. Why is Shakespeare mentioned in the first paragraph?A. To describe Shakespeare's anniversary.B. To introduce the existence of Tang Xianzu.C. To explain the importance of Shakespeare.D. To suggest the less popularity of Tang Xianzu.2. What's possibly one of the main theme of Tang's works?A. Social reality.B. Female dreams.C. Human emotions.D. Political environment.3. What does the author mainly tell us in Paragraph 4?A. The influence of Kunqu Opera on Tang's works.B. Tang's success in copying Shakespeare's styles.C. The way Kunqu Opera became a symbol of Chinese culture.D. Tang's popularity for his poetic language and music.BWith graduation days being celebrated all over the country, a student who has to use a wheelchair honored his mother on his graduation day in a special way. Easley High School graduate, Alex Mays surprised people present when he got up and walked across the stage at Clemson's Littlejohn Coliseum.“I was really happy—it made me feel good,” Alex said.Alex was not given a chance to live right from his birth. He was born at 25 weeks and weighed just 1 pound, 10 ounces at birth. When he was very young, he had a disease and lost the ability to walk. After his mother's death in 2013, Alex had several other difficult life changes until he came to live with his grandparents, Dousay and her husband, Dewayne. Dousay said that when Alex came to live with them, they decided to bring him up in the best possible way they could.Last fall, Alex said that he would walk across the stage to get his diploma to honor his late mother. He practiced hard and worked with a physical therapist for 9 months to complete his plan.The only help Alex got was from his mom's best friend, Tonya Johnson, who pushed his wheelchair to the stage wearing one of his mother's favorite shirts. “I had support from my family. I couldn't have done it without them,” Alex said.“Alex made everyone in the building feel encouraged that day” Pickens County School District public information specialist John Eby said. “The school teachers knew he was going to get up to get his diploma, but the distance he walked was a surprise, even to them,” Eby said.“Some of life's most important tests aren’t given in a classroom; Alex tested himself and passed with flying color1 s,” Eby added.4. In what way did Alex honor his late mother on his graduation day?A. By dressing like her.B. By saying sorry to her.C. By inviting her best friend.D. By walking to get his diploma.5. What can we learn from Paragraph 3?A. Alex was born healthy.B. Alex went through a lot.C. Alex had a purpose in life as a child.D. Alex has lived with his grandparents all the time.6. What did Alex also express on his graduation day?A. His big regret in life.B. His feelings for hisschool.C. His thanks for his family.D. His will to complete his study.7. Which of the following words can best describe Alex?A. Strong-minded.B. Warm-hearted.C. Cool-headed.D. Easy-going.CThe Chinese philosopher (哲学家) Confucius once said, “Time flows away like the water in the river.” This is especially true as the novel coronavirus pneumonia outbreak has affected millions of people in China, andthe whole nation has been working day and night to fight the epidemic.In late January, when an increasing number of people in Wuhan were suspected to be infected, and hospitals didn't have adequate beds for them, two special hospitals—Lei shenshan Hospital and Huo shenshan Hospital were built. These two makeshift (临时的) hospitals were built to treat pneumonia patients infected with the novel coronavirus.HuoshenshanHospitalhas 1,000 beds and covers 33,900 square meters, andLeishenshanHospitalhas 1,500 beds and a total area of about 79,000 square meters. More than 4,000 workers worked 24/7 in two shifts, and nearly 1,000 large-scale pieces of equipment and transport vehicles helped the project on site. The two hospitals were built in an amazingly short time. It only took 10 days for people to build Huo shenshan, and 14 days for Lei shenshan.This certainly wowed many people overseas. “It's incredible that two hospitals with 2,500 beds can be built in a short period. It's just hard to believe,” a foreigner named Stuart told People's Daily. In the meantime, Chinese companies have also taken actions quickly in this battle.“The automobile industry is highly industrialized with strong capabilities in comprehensive manufacturing, purchasing materials, production lines and output of technologies,” Shi Jianhua, deputy secretary-general of China Association of Automobile Manufacturers, told CCTV News. “In this special time, when the nation needs more masks, it's time for us to quickly respond and shoulder the social responsibilities.”Indeed, a fast response is crucial in any crisis. In this special time,Chinacan't afford to waste a second in the fight against the epidemic. After all, time equals life during this crisis.8. Confucius' saying “Time flows away like the water in the river.” is mentioned to ______.A. arouse readers' interest in the passage.B. introduce the subject of the passage.C. present the background information.D. stress the value of time in epidemic.9. What can we learn about Lei shenshan hospital and Huo shenshan hospital?A. They are new hospitals for health care inWuhan.B. They were built in minimal time.C. Over 4,000 workers worked continuously.D. Stuart found them too massive to believe.10. We can infer from Shi Jianhua's words that the automobile industry inChina______.A. had no medical supplies factories before.B. guarantees whoever in need enough masks.C. has capabilities to give timely response.D. has strong abilities in manufacturing.11. What does the passage mainly talk about?A. China fights epidemic against the clock.B. Twospecial hospitals were constructed.C. Chinese firms acted quickly and effectively.D. Time is crucial for people in overcoming crisis.DDepression（抑郁症）in young adult males, ages 18 or 19, is linked to a 20% greater risk of having a heart attack in middle age, according to a new Swedish study.The link can be partly explained by poorer stress resilience（抗压能力）and lower physical fitness among teens with mental disorders.Theresearch included 238,013 men born between 1958 and 1962 who were given examinations in adolescence（青春期）and were then followed into middle age（up to the age of 58 years）. A total of 34,503 men were diagnosed（诊断）with a mental disorder.The study found thata mental disorder in young adulthond was linked to a higher risk of having heart attack by middle age. Compared to men without a mental illness in young adulthood，the risk of heart attack was 20%higher among men with a diagnosis.“We already knew that menwho were physically fit in adolescence seem less likely to keep fitness in later years if they have low stress resilience” said study author Dr. Bergh, “Our research has also shown that low stressresilience is also connected with a greater tendency towards bad behavior, such as higher risks of smoking, drinking and other drug use.”“Better fitness in adolescence is likely to help protect against later heart disease, particularly if people stay fit as they age. Physical activities may also reduce some of the bad effects of stress. Those in poor health could benefit from additional support to encourage exercise and develop plans to deal with stress,” said Bergh.12. How does the author develop paragraph 3?A. By giving examples.B. By listing figures.C. By making a comparison.D. By drawing a conclusion.13. What are men with low stress resilience likely to do?A. Smoke more.B. Eat more.C. Sleep less.D. Do less exercise.14. What will Bergh agree with according to the last paragraph?A. Physical activitiesadd to stress.B. Stress may cause heart disease.C. Taking exercise is unnecessary.D. Staying fit is of great importance.15. In which section of a newspaper may this text appear?A. Entertainment.B. Health.C. Education.D. Fashion.第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。

2019-2020学年上海市浦东新区建平中学高三（上）期中化学试卷一、单选题（本大题共20小题，共60.0分）1.下列有关化学用语的说法正确的是()A. 某元素基态原子的核外电子排布图为B. NH4Cl的电子式为C. 基态Ca2+的核外电子排布式为1s22s22p63s23p6D. α−羟基丙酸(乳酸)的比例模型为2.用酒精灯或电炉对下列实验仪器进行加热时，需用石棉网的是()A. 烧杯B. 蒸发皿C. 试管D. 坩埚3.石油裂解的主要目的是()A. 提高轻质液体燃料的产量B. 便于分馏C. 提高汽油的质量D. 获得断链不饱和气态烃4.在化工生产中，如果要加快化学反应速率，应优先考虑的科研方向是()A. 用块状固体反应物代替粉末状反应物B. 提高设备抗压强度以便加压C. 采用高温高压的反应条件D. 选择合适的催化剂5.下列变化与氧化还原反应无关的是()A. 钢铁冶炼B. 汽油燃烧C. 酸碱中和D. 食物腐败6.区别SO2和CO2气体可选用()A. 通入澄清石灰水中B. 通入品红溶液中C. 用带火星的木条检验D. 通入石蕊试液中7.下列分离物质的方法中，根据沸点不同进行分离的是()A. 蒸馏B. 萃取C. 重结晶D. 蒸发8.CO2、NH3溶于水能导电，所以二者均为电解质A. ×B. √9.若不断地升高温度，实现“液氨→氨气→氮气和氢气→氮原子和氢原子”的变化。

则在变化的各阶段中被破坏的粒子间主要的相互作用力分别是()A. 氢键；范德华力；非极性键B. 氢键；极性键；范德华力C. 氢键；极性键；非极性键D. 范德华力；氢键；非极性键10.下列说法正确的是()A. 红磷转化为白磷，属于物理变化B. 石墨导电、金刚石不导电，故二者不是同素异形体C. O2和O3分子式不同，结构相同D. 单质硫有S2、S4、S6等，它们都是硫的同素异形体11.在含有大量H+、Fe3+、SO 42−的溶液中，还能大量存在的离子是()A. CO 32−B. Ba2+C. SCN−D. NH 4+12.下列比较金属性相对强弱的方法或依据正确的是()A. 根据金属失电子的多少来确定，失电子较多的金属性较强B. 用钠来置换MgCl2溶液中的Mg，可验证钠的金属性强于MgC. 根据Mg和Al与水反应的剧烈程度来比较它们的金属性强弱D. 根据碱性：NaOH>Mg(OH)2>Al(OH)3，可说明钠、镁、铝的金属性依次减弱13.在恒容的密闭容器中进行如下的可逆反应：3A(g)+B(g)⇌4C(g)+D(s)，下列说法不能判断反应已达化学平衡状态的是()A. 反应速率v(A)=3v(B)B. 固体D的物质的量一定C. 气体的密度不变D. C的浓度不变14.关于钢铁腐蚀和防护的说法正确的是()A. 钢铁腐蚀以化学腐蚀为主B. 钢铁腐蚀时的负极反应是Fe−3e→Fe3+C. 在铁船壳上镶嵌锌块能减缓船体的腐蚀D. 水库的铁闸门接电源的正极能减缓腐蚀15.新制饱和氯水中存在：Cl2+H2O⇌HCl+HClO，为增强溶液漂白能力，下列措施可行的是()A. 加稀硫酸B. 加CaCO3固体C. 加 NaCl 固体D. 通入SO216.W、X、Y、Z四种短周期元素，它们在周期表中位置如表所示，下列说法不正确的是()B. Y、Z、W、X的原子半径依次减小C. Y、W、X的气态氢化物的稳定性依次减弱D. YO2与HX 水溶液常温下可发生化学反应17.下列实验操作正确的是()A. 分液时，先将上层液体从上口倒出B. 萃取时，振荡后，须打开活塞放气C. 蒸馏时，先点燃酒精灯，后通冷凝水D. 蒸发时，将溶剂蒸干一段时间后，熄灭酒精灯18.下列所示装置正确且能完成相关实验的是()A. 所示装且制取Fe(OH)2B. 所示装置制取SO2C. 所示装置制取O2D. 所示装置比较Cl、C、Si的非金属性强弱19.将一定量MnO2和KClO3混合加热，反应完全后，将剩余固体与过量的浓盐酸混合加热，待反应完毕后，将溶液蒸干，所得固体与原混合物质量相等，则原混合物中KClO3的质量分数约为()A. 87%B. 53%C. 47%D. 58%20.某学生探究0.25mol/LAl2(SO4)3溶液与0.5mol/LNa2CO3溶液的反应，实验如下．实验1实验2A. 实验1中，白色沉淀a是A1(OH)3B. 实验2中，白色沉淀b含有CO32−C. 实验1、2中，白色沉淀成分不同的原因与混合后溶液的pH有关D. 检验白色沉淀a、b是否洗涤干净，不可使用相同的检验试剂二、简答题（本大题共3小题，共44.0分）21.Na2S2O3俗名大苏打，又叫海波，是一种重要的化工原料，可用于照相定影剂；造纸、印染工业的脱氯剂；医药上用作洗涤剂、消毒剂；食品工业用作整合剂、抗氧化剂等，在酸性溶液中Na2S2O3会分解．(1)Na2S2O3是一种弱酸强碱盐，则其溶液显______ (填“弱酸性”、“中性”或“弱碱性”)，原因是______ (用离子方程式表示)(2)Na2S2O3具有强的还原性，能与I2反应生成S4O62−，常用于溶液中I2的含量的测定．①Na2S2O3中，S元素的化合价为______ ；②写出Na2S2O3与I2反应的离子方程式______ ．(3)Na2S2O3可用作脱氧剂，已知50.0mL0.1mol/L Na2S2O3溶液恰好把448mL(标准状况下)Cl2完全转化为Cl−，则S2O32−将转化成______A.S2−B.SC.SO32−D.SO42−(4)硫代硫酸钠工业制备方法有多种，其中一种常用的方法是：向Na2S和Na2CO4的混合液中通入适量的SO2，发生反应：2Na2S+Na2CO3+4SO2=3Na2S2O3+CO2，再通过过滤，将滤液经蒸发浓缩、过滤、洗涤、干燥得到产品Na2S2O3⋅5H2O.①为了保证硫代硫酸钠的产量，制备过程中SO2不能过量的原因______ ；②工业制Na2S2O3的反应中Na2S是______ 剂(填“氧化”或“还原”)，SO2被______(填“氧化”或“还原”)．22.将0.01mol I2和0.01mol H2置于预先抽成真空的特制2L恒容密闭容器中，加热至1500K，体系达到平衡，总压强为456kPa。

上海市浦东新区建平中学2019-2020学年高三上学期期中语文试题第I卷（选择题)请点击修改第I卷的文字说明一、选择题1．下列选项中，对联与所表达人物对象不相符的一项是（）A．诗史数千言，秋天一鹄先生骨；草堂三五里，春水群鸥野老心。

——杜甫B．何处招魂，香草还生三户地；当年呵壁，湘流应识九歌心。

——诸葛亮C．千古诗才，蓬莱文章建安骨；一般傲骨，青莲居士谪仙人。

——李白D．大明湖畔趵突泉边，故居在绿杨深处；漱玉集中金石录里，文采有后主遗风。

——李清照2．将下列编号的语句填入语段的空白处，语意连贯的一项是（）格非在《文学的邀约》一书中指出：“______________。

如果你在书场里听人说书，遇有疑惑不解之处，也许可以向说书人提问，______________。

……即便你和作者见了面，______________。

作者写作的理由，当然是要告诉我们一些什么，但他要说的话却是通过故事、人物所编织起来的语言中介而呈现的。

______________。

叙事者在他的舞台上，用一层布幔将作者与读者隔开了。

我们似乎一直看见作者的身影影影绰绰，但却不够真切。

”①我们只能发现叙事者，却看不见作者②对于读者而言，作者是一个缺席的存在③但绝大部分文学文本的读者却无此权利④作者对自己作品的解释，也不一定是标准答案A．②④③①B．①③②④C．①④③②D．②③④①第II卷（非选择题)请点击修改第II卷的文字说明二、句子默写3．按要求填空。

（1）伤心秦汉经行处，__________________。

（张养浩《中吕·__________·潼关怀古》）（2）__________________，任重而道远。

（《<论语>七则》）（3）姜夔《扬州慢》上阕虚写扬州十里长街繁华景况，实写扬州凄凉现实的诗句是：“__________________，__________________。

”三、现代文阅读阅读下文，完成下面小题。

高考模拟数学试卷注意事项：1．答题前，先将自己的姓名、准考证号填写在试题卷和答题卡上，并将准考证号条形码粘贴在答题卡上的指定位置。

2．选择题的作答：每小题选出答案后，用2B 铅笔把答题卡上对应题目的答案标号涂黑，写在试题卷、草稿纸和答题卡上的非答题区域均无效。

3．非选择题的作答：用签字笔直接答在答题卡上对应的答题区域内。

写在试题卷、草稿纸和答题卡上的非答题区域均无效。

4．考试结束后，请将本试题卷和答题卡一并上交。

一、选择题：本大题共12小题，每小题5分，在每小题给出的四个选项中，只有一项是符合题目要求的． A ．{}4B ．{}1,2,3---C ．{}0,1,2,3---D ．{}3,2,1,0,1,2,3---2．[2018·长沙一模]设复数1z ，2z 在复平面内的对应点关于实轴对称，11i z =+，则12z z =（ ） A ．2-B ．2C ．1i -D ．1i +3．[2018·汕头冲刺]《九章算术》中有如下问题：“今有勾五步，股一十二步，问勾中容圆，径几何？”其大意：“已知直角三角形两直角边分别为5步和12步，问其内切圆的直径为多少步？”现若向此三角形内随机投一粒豆子，则豆子落在其内切圆外的概率是（ ） A ．215πB ．320π C ．2115π-D ．3120π-4．[2018银川一中·]等差数列{}n a 的前11项和1188S =，则39a a +=（ ） A ．8B ．16C ．24D ．325．[2018·齐鲁名校]已知定义在R 上的函数()f x 满足()()6f x f x +=，且()3y f x =+为偶函数， 若()f x 在()0,3内单调递减，则下面结论正确的是（ ） A ．()()()4.5 3.512.5f f f -<<B ．()()()3.5 4.512.5f f f <-<C ．()()()1253545f f f <<-...D ．()()()3512.5 4.5f f f <<-．6．[2018·河南名校联盟]为了测试小班教学的实践效果，王老师对A 、B 两班的学生进行了阶段测试，并将所得成绩统计如图所示；记本次测试中，A 、B 两班学生的平均成绩分别为A x ，B x ，A 、B两班学生成绩的方差分别为2A s ，2B s ，则观察茎叶图可知（ ）A ．AB x x <，22A B s s <B ．A B x x >，22A B s s <C．A B x x <，22A B s s >D ．A B x x >，22A B s s >7．[2018·鄂尔多斯一中]某几何体的三视图如图所示，则该几何体的体积是（ ）A ．8π+B ．28π+C ．83π+D ．823π+8．[2018·兰州一中]若执行下面的程序框图，输出S 的值为3，则判断框中应填入的条件是（ ）A ．7?k <B ．6?k <C ．9?k <D ．8?k <A ．向左平移2π个单位长度 B ．向右平移2π个单位长度 C ．向左平移4π个单位长度 D ．向右平移4π个单位长度 交其准线l '于点C ，若2BC BF =，且3AF =，则此抛物线的方程为（ ）A ．29y x =B ．26y x =C ．23y x =D ．23y x = A ．a b >B ．a b <C ．a b =D ．无法比较12．[2018·集宁一中]已知正项数列{}n a 中，11a =，22a =，()2221122n n n a a a n -+=+≥，11n n n b a a +=+，记数列{}n b 的前n 项和为n S ，则40S 的值是（ ） A ．103B ．11C ．113D ．10二、填空题：本大题共4小题，每小题5分．13．[2018·深圳实验]已知3=a 2=b ，若()+⊥a b a ，则a 与b 的夹角是_________．16．[2018·衡水金卷]如图，将正方形ABCD 沿着边BC 抬起到一定位置得到正方形BCEF ，并使得平面ABCD 与平面BCEF 所成的二面角为45︒，PQ 为正方形BCEF 内一条直线，则直线PQ 与BD 所成角的取值范围为_______．三、解答题：本大题共6大题，共70分，解答应写出文字说明、证明过程或演算步骤．17．（12分）[2018·齐鲁名校]在ABC△中，a，b，c分别为内角A，B，C所对的边，已知cosa A R=，其中R为ABC△外接圆的半径，S为ABC△的面积，22243a cb S+-=．（1）求sin C；（2）若23a b-=-，求ABC△的周长．（1）求证：BD⊥平面PAD；（2）若E是PC的中点，求三棱锥P EDB-的体积．2017年底随机调査该市1000辆纯电动汽车，统计其出厂续驶里程R，得到频率分布直方图如上图所示．用样本估计总体，频率估计概率，解决如下问题：（1）求该市每辆纯电动汽车2017年地方财政补贴的均值；（2）某企业统计2017年其充电站100天中各天充电车辆数，得如下的频数分布表：辆数 [)5500,6500[)6500,7500[)7500,8500[)8500,9500天数20304010，国家出台政策，将纯电动汽车财政补贴逐步转移到充电基础设施建设上来．该企业拟将转移补贴资金用于添置新型充电设备．现有直流、交流两种充电桩可供购置．直流充电桩5万元/台，每台每天最多可以充电30辆车，每天维护费用500元/台； 交流充电桩1万元/台，每台每天最多可以充电4辆车，每天维护费用80元/台． 该企业现有两种购置方案：方案一：购买100台直流充电桩和900台交流充电桩； 方案二：购买200台直流充电桩和400台交流充电桩．假设车辆充电时优先使用新设备，且充电一辆车产生25元的收入，用2017年的统计数据，分别估计该企业在两种方案下新设备产生的日利润．（日利润日收入日维护费用）．（1）求椭圆的方程；（2）已知点(),0P m ，过点()1,0作斜率为()0k k ≠直线l ，与椭圆交于M ，N 两点，若x 轴平分MPN ∠，求m 的值．（1）求函数()f x 的极值；（2）求证：当0m >时，存在0x ，使得()01f x <．请考生在22、23两题中任选一题作答，如果多做，则按所做的第一题记分． 22．（10分）【选修4-4：坐标系与参数方程】[2018·河南一模]在直角坐标系xOy 中，已知直线1l ：()cos sin x t t y t αα=⎧⎨⎩=为参数，2l ：()cos 4sin 4x t t y t ααπ⎛⎫=+ ⎪⎝⎭π⎛⎫=+ ⎪⎧⎪⎪⎨⎪⎩⎭⎪⎝为参数，其中30,4απ⎛⎫∈ ⎪⎝⎭，以原点O 为极点，x 轴非负半轴为极轴，取相同长度单位建立极坐标系，曲线C 的极坐标方程为4cos 0ρθ-=． （1）写出1l ，2l 的极坐标方程和曲线C 的直角坐标方程；（2）设1l ，2l 分别与曲线C 交于点A ，B （非坐标原点），求AB 的值．23．（10分）【选修4-5：不等式选讲】 [2018·张家界三模]已知函数()225f x x =+-． （1）解不等式：()1f x x ≥-；（2）当1m ≥-时，函数()()g x f x x m =+-的图象与x 轴围成一个三角形，求实数m 的取值范围．文科数学（四）答 案一、选择题：本大题共12小题，每小题5分，在每小题给出的四个选项中，只有一项是符合题目要求的． 1．【答案】C【解析】∵集合{}0,1,2,3,4A =---，集合{}{}2122323B x x x x =<=-<<， ∴{}0,1,2,3A B =---I ，故选C ． 2．【答案】B【解析】∵1z ，2z 在复平面内的对应点关于实轴对称，∴21i z =-， ∴()()121i 1i 2z z =+⋅-=，故选B ． 3．【答案】C【解析】直角三角形的斜边长为2251213+=，设内切圆的半径为r ，则51213r r -+-=，解得2r =，∴内切圆的面积为24r π=π，∴豆子落在其内切圆外部的概率是42111155122P ππ=-=-⨯⨯，故选C ． 4．【答案】B【解析】∵等差数列{}n a 的前11项和1188S =，∴()1111111882a a S +==，∴11116a a +=，根据等差数列性质：3911116a a a a +=+=，故选B ． 5．【答案】B【解析】由()()6f x f x +=，可得6T =，又()3y f x =+为偶函数，()f x 的图像关于3x =对称， ∴()()3.5 2.5f f =，()()4.5 1.5f f -=，()()12.50.5f f =．又()f x 在()0,3内单调递减，∴()()()3.5 4.512.5f f f <-<．故选B ． 6．【答案】B【解析】A 班学生的分数多集中在[]70,80之间，B 班学生的分数集中在[]50,70之间，故A B x x >；相对两个班级的成绩分布来说，A 班学生的分数更加集中，B 班学生的分数更加离散，故22A B s s <，故选B ．7．【答案】C【解析】该几何体是由半个圆柱（该圆柱的底面圆半径是1，高是2）与一个四棱锥（该棱柱的底面面积等于224⨯=，高是2）拼接而成，其体积等于211812222233⨯π⨯⨯+⨯⨯⨯π+＝，故选C ．8．【答案】D【解析】根据程序框图，运行结果如下： S k 第一次循环 2log 3 3 第二次循环 23log 3log 4⋅ 4 第三次循环 234log 3log 4log 5⋅⋅ 5 第四次循环 2345log 3log 4log 5log 6⋅⋅⋅ 6 第五次循环 23456log 3log 4log 5log 6log 7⋅⋅⋅⋅ 7第六次循环 2345672log 3log 4log 5log 6log 7log 8log 83⋅⋅⋅⋅⋅== 8故如果输出3S =，那么只能进行六次循环，故判断框内应填入的条件是8k <．故选D ． 9．【答案】D【解析】分别把两个函数解析式简化为()sin 2=sin 236f x x x π⎡π⎤⎛⎫⎛⎫=++ ⎪ ⎪⎢⎥⎝⎭⎝⎭⎣⎦，函数()cos 2sin 2sin 233264g x x x x ⎡⎤πππππ⎛⎫⎛⎫⎛⎫=+=++=++ ⎪ ⎪ ⎪⎢⎥⎝⎭⎝⎭⎝⎭⎣⎦，可知只需把函数()g x 的图象向右平移4π个长度单位，得到函数()f x 的图象．故选D ． 10．【答案】C【解析】分别过点A ，B 作准线的垂线，垂足分别为E ，D ， 设22BC BF a ==，由抛物线定义，得2BC BD BF ==，则30BCD ∠=︒，在Rt ACE △中，3AF =，33AC a =+，则2AE AC =，∴336a +=，解得1a =， ∵BD FG ∥，∴123p =，即32p =，即抛物线方程为23y x =．故选C ．11．【答案】A【解析】设()20181x f x =+，则()()34f a f =，()()45f b f =．∴()()()43344454320182018201720182017201814201812018120182018f f a f --⨯⨯-====+++，()()()54455542018201820172018152018120181f f b f --⨯-===++，∵552018201820181+>+，∴11a b -<-，即a b >．故选A ． 12．【答案】A【解析】∵()2221122n n n a a a n -+=+≥，∴数列{}2n a 为等差数列，首项为1，公差为2213-=． ∴()213132n a n n =+-=-，0n a >．∴32n a n =-， ∴()111313233231n n n b n n a a n n +===+--+-++，∴数列{}n b 的前n 项和为()()()()11[4174313231133n S n n n =-+-+++--=+-L ．则()40110121133S =-=．故选A ． 二、填空题：本大题共4小题，每小题5分． 13．【答案】150︒【解析】∵3=a ，2=b ，且()+⊥a b a ，∴2cos ,0+⋅=a a b a b ，即323cos ,0+=a b ，解得3cos ,=-a b ， ∴向量a 与b 的夹角是150︒，故答案为150︒． 14．【答案】6-【解析】由23z x y =-得233zy x =-， 作出不等式组对应的平面区域如图（阴影部分ABC ）：平移直线233zy x=-，由图象可知当直线233zy x=-过点A时，直线233zy x=-截距最大，此时z最小，由310xx y=⎧⎨-+=⎩得34xy=⎧⎨=⎩，即()3,4A，代入目标函数23z x y=-，得23346126z=⨯-⨯=-=-．∴目标函数23z x y=-的最小值是6-．故答案为6-．15．【答案】1【解析】设()11,A x y，()22,B x y，()33,C x y，由222214xymy x⎧-=⎪⎨⎪=⎩，得22240x m x m-+=，2124x x m+=，212x x m=，由抛物线定义可得11AF x=+，21BF x=+，31FC x=+，由24y mxy x=⎧⎨=⎩，得324xm=，115FA FB FC+=，得12121212321151111x xx x x x x x x+++==++++++，即2224254511mmm+=++，结合0m>解得1m=，故答案为1．16．【答案】[]30,90︒︒【解析】不妨设正方形的边长为1，作DG CE⊥，垂足为G，由BC CE⊥，BC CD⊥，得BC⊥平面CDG，故BC DG⊥，又BC CE C=I，得DG⊥平面BCEF，故直线BD在平面BCEF内的射影为BG，易知2DG=，则BD与平面BCEF所成的角为30BDG∠=︒，∴BD与平面BCEF内的直线所成的最小角为30︒，而直线PQ与BD所成角的最大角为90︒（当PQ与CF 重合时，PQ与BD所成角为的90︒），∴直线PQ与BD所成角的取值范闱为[]30,90︒︒，故答案为[]30,90︒︒．三、解答题：本大题共6大题，共70分，解答应写出文字说明、证明过程或演算步骤．17．【答案】（126+；（23263【解析】（1）由正弦定理得2sina R A=，∴2sin cosR A A R=，∴sin21A=，又022A<<π，∴22Aπ=，则4Aπ=．1sin2S ac B=，222431sin2a cb ac B+-=⋅，由余弦定理可得232cos sinac B B=，∴tan3B=，又0B <<π，∴3B π=，∴()sin sin sin 43C A B ππ⎛⎫=+=+= ⎪⎝⎭．（2）由正弦定理得sin sin a A b B ===a b -a b ⎧=⎪⎨=⎪⎩，∴c =，∴ABC △的周长a b c ++ 18．【答案】（1）见解析；（2）43． 【解析】（1）在ABD △中，由于2AD =，4BD =，AB =222AD BD AB +=，故AD BD ⊥． 又PD ⊥平面ABCD ，BD ⊂平面ABCD ，∴PD BD ⊥，又AD PD D =I ，∴BD ⊥平面PAD ． （2）由已知可得，2BC =，4BD =，90DBC ∠=︒，∴三棱锥P DBC -的体积为：11184223323P DBC DBC V S PD -=⨯⨯=⨯⨯⨯⨯=△．∵E 是PC 的中点，∴1423E DBC P DBC V V --==，∴三棱锥P EDB -的体积为43P EDB P DBC E DBC V V V ---=-=． 19．【答案】（1）3.95万元；（2）见解析．【解析】（1）依题意可得纯电动汽车地方财政补贴的分布列为：纯电动汽车2017． （2）由充电车辆天数的频数分布表得每天需要充电车辆数的分布列：3010049006600⨯+⨯=（辆）； 可得实际充电车辆数的分布列如下表：()2560000.266000.85001008090040000⨯⨯+⨯-⨯-⨯=（元）；若采用方案二，200台直流充电桩和400台交流充电桩每天可充电车辆数为 3020044007600⨯+⨯=（辆）； 可得实际充电车辆数的分布列如下表：()2560000.270000.376000.55002008040045500⨯⨯+⨯+⨯-⨯-⨯=（元）．20．【答案】（1）2212x y +=；（2）2．【解析】（1）∵椭圆的焦点在x 轴上，过点()0,1-，离心率e ，∴1b =，c a =∴由222a b c =+，得22a =，∴椭圆C 的标准方程是2212x y +=．（2）∵过椭圆的右焦点F 作斜率为k 直线l ，∴直线l 的方程是()1y k x =-． 联立方程组()22112y k x x y =-⎧⎪⎨+=⎪⎩消去y ，得()2222124220k x k x k +-+-=， 显然0∆>，设点()11,P x y ，()22,Q x y ，∴2122412k x x k +=+，21222212k x x k -⋅=+，∵x 轴平分MPN ∠，∴MPO NPO ∠=∠．∴0MP NP k k +=， ∴12120y y x m x m+=--，()()12210y x m y x m -+-=，∴()()()()1221110k x x m k x x m --+--=， ∴()()1212220k x x k km x x km ⋅-+++=，∴()22222242201212k k k k km km k k -⋅-++=++，∴242012k kmk -+=+，∴420k km -+=，∵0k ≠，∴2m =． 21．【答案】（1）极小值ln mm；极大值()ln 234m m m -+；（2）见解析． 【解析】（1）函数()f x 的定义域为()0,+∞，且0m ≠， ∵()()()2221112121mx mx m x mx f x mx mx mx mx+---='=--=， 令()0f x '=，得到112x m =-，21x m=， 当0m >时，x 变化时，()f x '，()f x 的变化情况如下表：∴函数()f x 在x m=处取得极小值f m m ⎛⎫=⎪⎝⎭；当0m <时，x 变化时，()f x '，()f x 的变化情况表如下：∴函数()f x 在12x m=-处取得极大值ln 21324m f m m m -⎛⎫-=+ ⎪⎝⎭； （2）当0m >时，由（1）可知，()f x 的最小值是1ln mf m m ⎛⎫= ⎪⎝⎭，∴存在0x ，使得()01f x <，等价于“11f m ⎛⎫< ⎪⎝⎭”，∴1ln 1m m f m m -⎛⎫-=⎪⎝⎭． 设()()ln 0g x x x x =->，则()111xg x x x-=-='， 当01x <<时，()0g x '>，()g x 单调递增，当1x >时，()0g x '<，()g x 单调递减， ∴()g x 的最大值为()110g =-<，∴1ln 10m m f m m -⎛⎫-=< ⎪⎝⎭，∴结论成立．请考生在22、23两题中任选一题作答，如果多做，则按所做的第一题记分．22．【答案】（1）见解析；（2）【解析】（1）1l ，2l 的极坐标方程为()1θαρ=∈R ，()24πθαρ=+∈R ．曲线C 的极坐标方程方程为4cos 0ρθ-=即得24cos 0ρρθ-=，利用222x y ρ=+，cos x ρθ=，得曲线C 的直角坐标方程为()2224x y -+=． （2）∵14cos ρα=，24cos 4ραπ⎛⎫=+ ⎪⎝⎭，∴2222212122cos 16cos cos cos 444AB ρρρρααααπ⎡ππ⎤⎛⎫⎛⎫=+-=+++ ⎪ ⎪⎢⎥⎝⎭⎝⎭⎣⎦⋅ ()()22116cos cos sin cos cos sin 82αααααα⎡⎤=+---=⎢⎥⎣⎦，∴AB 的值为23．【答案】（1）(][),82,-∞-+∞U ；（2）{}3,412⎡⎫-⎪⎢⎣⎭U ．【解析】（1）由题意知，原不等式等价于12251x x x ≤-⎧⎨---≥-⎩或112251x x x -<≤⎧⎨+-≥-⎩或12251x x x >⎧⎨+-≥-⎩，解得8x ≤-或∅或2x ≥， 综上所述，不等式()1f x x ≥-的解集为(][),82,-∞-+∞U ． （2）当1m =-时，则()2251315g x x x x =+-++=+-， 此时()g x 的图象与x 轴围成一个三角形，满足题意：当1m >-时，()37,12253,133,x m x g x x x m x m x m x m x m -+-≤-⎧⎪=+-+-=+--<≤⎨⎪-->⎩，则函数()g x 在(),1-∞-上单调递减，在()1,-+∞上单调递增．要使函数()g x 的图象与x 轴围成一个三角形，则()()140230g m g m m ⎧-=-<⎪⎨=-≥⎪⎩，解得342m ≤<；综上所述，实数m 的取值范围为{}3,412⎡⎫-⎪⎢⎣⎭U ．高考模拟数学试卷满分150分。

2019-2020学年上海市建平实验中学高三英语上学期期中考试试卷及答案第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项AAs the MOOC craze continues to explode, anyone interested in taking an online course faces a tricky question: Which course to take? Here are five aspects that you should consider before you start.(1)What is your learning style?Many MOOCs are video-based. Other courses use presentation formats. Some also require participation in group work. If you want to stay motivated during your course, think about how you enjoy learning.Are you a visual learner, preferring to use images to understand a topic? If so, a video-based course will work well for you. If you are a verbal learner who gains new information by speaking and writing, try a text-based course with lots of note-taking. Social learners, meanwhile, will thrive in forum discussions and project-based assessment.(2)Are you ready to become a full-time student?Be realistic about the time that you can commit to your online studies. Participating in an online course can take as much time and commitment as a class-based program. Check the course requirements and make a plan around your current schedule.(3) Does the course really meet your needs?Whether you are interested in a professional qualification or want to take a personal development course like yoga, there is a MOOC for you. It's easy to get caught up in the excitement of taking lots of free courses in everything that you ever wanted to learn. Before you start a course, think about the end goal. Is the course aimed at beginners or advanced learners? Why do you need this qualification?(4) Do you need a support group?Some people learn best from seeing how others approach the problem. If you are such as learner, you will need to supplement your online lessons with an in-person support group.(5) What kind of certification will you get?Take time to find out what kind of certification is available upon completion of the course, and how you can prove your learning to others - for example, certificates, transcripts or digital badges.1. What kind of MOOC's does the author recommend to verbal learners?A. A video-based course.B. A text-based course.C. A forum-based discussion.D. A project-based assessment.2. What kind of learners need an in-person support group?A. Learners who prefer individual work.B. Learners who are in great need of a certificate.C. Learners who are too busy to become a full-time student.D. Learners who learn best from observing how others address the problem.3. What is the passage mainly about?A. Picking the right MOOC's for you.B. Deciding your learning style.C. Taking the right course you need.D. Choosing a suitable support group.BThere is an old army joke about an officer who asks some soldiers whether any of them are interested in music. When four hands go up, the officer says, “Right, men. You can carry this grand piano down to the officers mess.”Job recruitment has become more complicated since that story first did the rounds. Today's careers require a lot more than just raw music but that sometimes makes jobs hard to define. An unfortunate result is a form of “adjective inflation” in recruitment ads as employers attempt to make routine tasks sound exciting.Candidates must sometimes wonder whether they are applying for a 9-to-5-role or to become a member of the Marvel “Avengers”. On Indeed, a job-bunting website, a bar was recently looking for "bartenders who are people focused, quality-driven, and have superhero hospitality powers". The ability to give customers the correct change was not mentioned.Another British company advertised for “a call-centre ninja, a superhero in people", a Job description which sounds a little over-the top for what was in fact a role at an insurance company in Isleworth. In case you think that ad was not typical. Indeed also had jobs demanding “ninja-like attention to detail". Short of turning up for the interview dressed head-to-toe in black, and then sneaking up behind the managing director at his desk, it is hard to see how candidates could show their ninja qualities.Not all companies require candidates to possess the qualities of a ninja, of course. Some require applicants to be passionate. The Bluewater shopping mall in southeastEnglandwas looking for “passionate sales-driven brand ambassadors” while “passionate crew members” were needed at a bakery in westLondonfor a wage of just £8. 23an hour. In fact, passion is pretty hard to keep consistently for 40 hours a week, month after month. Job applicants should find some information from the kind of ads that companies place. If a job ad talks about passion or superheroes, run away faster than a speeding Batmobile. Being a ninja should be reserved for teenage mutant ninja turtles.4. Why does the author mention the joke in Paragraph 1?A. To show that officers enjoy playing tricks on soldiers.B. To introduce the topic of overstated job ads.C. To explain the origin of complex job ads.D. To describe soldiers' everyday life.5. Which of the following offers a job demanding ninja qualities?A. The bar.B. The bakery.C. The insurance company.D. The Bluewater shopping mall.6. What does the author say about the ads requiring passion?A. They are unrealistic.B. They are typical of want ads.C. They are appealing to applicants.D. They are uncommon on Indeed.7. How does the author sound when talking about today’s job ads?A. Curious.B. Hesitant.C. Humorous.D. Sympathetic.CLarry was on another of his underwater expeditions(探险)but this time, it was different. He decided to take his daughter along with him. She was only ten years old. This would be her first trip with her father on what he had always been famous for.Larry first began diving when he was his daughter’s age. Similarly, his father had taken him along on one of his expeditions. Since then, he had never looked back. Larry started out by renting diving suits from the small diving shop just along the shore. He had hated them. They were either too big or too small. Then, there was the instructor. He gave him a short lesson before allowing him into the water with his father. He had made an exception. Larry would never have been able to go down without at least five hours of theory and another similar number of hours on practical lessons with a guide. Children of his age were not even allowed to dive.After the first expedition, Larry’s later diving adventures only got better and better. There was never a dull moment. In his black and blue suit and with an oxygen tank fastened on his back, Larry dived from boats into themiddle of the ocean. Dangerous areas did not prevent him from continuing his search. Sometimes, he was limited to a cage underwater but that did not bother him. At least, he was still able to take photographs of the underwater creatures.Larry’s first expedition without his father was in the Cayman Islands. There were numerous diving spots in the area and Larry was determined to visit all of them .Fortunately for him, a man offered to take him around the different spots for rry didn’t even know what the time was, how many spots he dived into or how many photographs he had taken.The diving spots afforded such a wide range of fish and sea creatures that Larry saw more than thirty varieties of creatures.Larry looked at his daughter. She looked as excited as he had been when he was her age. He hoped she would be able to continue the family tradition. Already, she looked like she was much braver than had been then. This was the key to a successful underwater expedition.8. In what way was this expedition different for Larry?A. His daughter had grown up.B. He had become a famous diver.C. His father would dive with him.D. His daughter would dive with him.9. What can be inferred from Paragraph 2?A. Larry had some special right.B. Larry liked the rented diving suits.C. Divers had to buy diving equipment.D. Ten-year-old children were permitted to dive.10. What can be learned from the underlined sentence?A. Larry didn’t wear a watch.B. Larry was not good at math.C. Larry had a poor memory.D. Larry enjoyed the adventure.11. What did Larry expect his daughter to do?A. Become a successful diver.B. Make a good diving guide.C. Take a lot of photo underwater.D. Have longer hours of training.DEvery racehorse has different abilities．Like humans，some are short- distance runners，while others are marathoners．Figuring out which is which and how to pace them can be the difference between failure in the finish and taking the award home．Jockeys（赛马骑师）and trainers have traditionally relied on centuries of experience and data from previous races to plan their races．Amandine Aftalion，a mathematician in Paris，thought she could add to that．Since 2013，she has been analyzing the performances of world champion runners like Usain Bolt．She has found that short-distance runners tend to win when they start strong and gradually slow down toward the finish line．Butin medium-distance races，runners perform better when they start strong，settle down，and finish with a burst of speed．Her model shows how those winning strategies maximize the energy output of muscles reliant on two different pathways：powerful aerobic（有氧的）ones that require oxygen，which can be in limited supply during a race，and anaerobic ones，which don't need oxygen but build up waste products that lead to tiredness．Aftalion wondered which strategy would be best for horses．So she and Quentin Mercier，anothermathematician，took advantage of a new GPS tracking tool inserted in French racing saddles（马鞍）．The two studied patterns in many races at the Chantilly racetracks north of Paris and developed a model that accounted for winning strategies for three different races：a short one(1，300 meters)，a medium one (1,900 meters)，and a slightly longer one (2,100 meters)，all with different starting points on the same track．The model takes into account not just different race distances，but also the size or friction fromthe track surface．The results might surprise jockeys who hold horses back early for bursts of energy in the last finish．Instead，a strong start leads to a better finish，the team found．“That doesn't mean those jockeys are wrong，though．If the start is too strong，it can bedevastatingas well，leaving the horse tired by the end，” Aftalion says．12. What should a runner do to get an award according to the text?A. Make a good start．B. Plan for the race early．C. Run slowly on the starting line．D. Try runningquickly all the time．13. What formed the basis for Aftalion's studying horse race?A The experience and data from previous horse races．B. The benefit of knowing horses' different abilities．C. The success in studying runners' winning strategies．D. The performance of horses on different race distances．14. What does the underlined word“devastating”in the last paragraph mean?A. Boring．B. Damaging．C. Astonishing．D. Puzling．15. What can we infer from the text?A. Runners have the same energy output of muscles．B. Aftalion's findings may help horses to win the race．C. What Jockeys and trainers do makes no sense to horses．D. World champion runners made a contribution to the study．第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。

2019-2020学年上海市浦东新区建平中学高三期中考试语文试卷1.按要求填空。

（1）_____________________，闺中只独看。

（杜甫《月夜》）（2）溯洄从之，__________________。

溯游从之，宛在水中坻。

（选自《诗经•______________•蒹葭》）（3）孟子说过：“生于忧患，死于安乐”，欧阳修在《伶官传序》中也说过意思相近的话：“________________________________”按要求选择2. 下列选项中，成语使用不恰当的一项是（）。

A. 2018年诺贝尔奖的揭晓又一次证明：唯有锲而不舍的坚持才是创新的基础和前提。

B. 生物实验必须亲自动手，切忌怀有恐惧畏难情绪，袖手旁观是不可能学到真知的。

C. 人到中年的王老师班主任工作虽然繁重，但她总是精神矍铄，工作总是细致全面。

D. 在“相声新势力”的表演现场，各路青年演员幽默风趣的表演逗得观众忍俊不禁。

3. 将下列编号的语句依次填入语段空白处，语意连贯的一项是（）。

作者在积累了大量素材的基础上进行充分的构思后，、、、只有在作品最终完成之际,主题才其最终确立。

①但完成了“意在笔先”并不等于此“意”能善始善终②意在笔中和意在笔先、意成笔后相辅相成还未可知③一般都会对写作有了一个总体的趋势约定④它还需要一个不断反复、不断充实和不断往上的过程A. ③②①④B. ③①④②C. ②①④③D. ②③①④阅读下文，完成小题。

国家有界贸易无界霍伟岸①一波三折的贸易争端以及日益迫近的贸易战威胁，只是人类在商业社会时代频频上演的、换演员不换剧本的一出经典政经大戏，如今这一幕之所以看起来格外引人注目，只不过是因为它发生在当代世界上最大的两个经济体之间，而且我们自己也碰巧成为主角之一。

其实大约从十七世纪起，这种因贸易利益纠纷而引发的国与国之间的经济制裁、政治冲突，其背后都有一个相似的政治经济复杂纠缠的逻辑，用最简单的话来概括，就叫作“贸易的猜忌”。

上海市浦东新区建平中学2019届高三上学期期中考试英语试卷II.GrammarandvocabularySectionA1．The mama﹣bear instinctMs． Angela McQueen， a math and PE teacher at Mattoon High School， Illinois， has a routine when she's on lunch﹣monitoring duty． She___1___ （keep） an eye on the hundreds of students in her charge by walking laps（圈） around the school cafeteria．In September 2017， McQueen， then 40， had hardly finished one lap___2___ a 14﹣year﹣old freshman standing not far from her pulled out a gun． She knew too well that he was going to start shooting．School employees___3___（train）on how to handle active shooters：Attack their ability___4___ （aim）． So with the shooter's finger on the trigger， McQueen rushed to him．___5___（grab） at his arm， she forced the gun into the air， but not___6___ he struck one student in the hand and chest and hurt another． As students ran for the exits， McQueen defeated the shooter with help from the school resource officer，___7___ disarmed the student and took him into imprisonment until police arrived minutes later． Afterward， McQueen went outside to give hugs and support to her shaken students．"It's the mama﹣bear instinct，" she told the local paper． "I don't have kids of my own， but these are still‘___8___' kids．"___9___ McQueen， a story that has played out tragically at far too many schools across the country had a relatively happy ending． "If it hadn't been for her， the situation would have been a lot different，" Police Chief Jeff Branson said at a news conference．As one___10___ （impress） student told CBS News， "Mr． McQueen is our heroine．"【答案】1. keeps2. when3. had been trained4. to aim5. grabbing6. before7. who8. my 9. Thanks to10. impressed【解析】【分析】这是应用文。

2019-2020学年上海市建平中学高三英语三模试卷及参考答案第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项AEast Yorkshire has typical unpredictable British weather. So here are some ideas to keep everybody happy when the weather is not the most ideal.William's Den, North CaveThe outdoor and indoor areas are suitable for children of all ages to have fun.There are nests to explore, rope bridges to cross, a tree-house and a slide. The attached Kitchen provides fresh food made from locally sourced ingredients serving a selection of treats.East Riding Leisure CentresKnown for a fun learner pool alongside an incredible fun zone with two slides as well, it is perfect for kids to find their feet in the water, have fun and explore. Its 6 climbing walls offer a different challenge on each. This place is suitable for anyone over the age of 4 and you can refuel at cafe with fresh food, snacks and cakes.Sewerby Hall and GardensWhen the weather’s not sure, take cover in the Hall and learn how life was in the early 1900’s for the residents and workers of the house. Then explore the zoo and meet the pigs, parrots and penguins! Kids of all ages are welcome.Withernsea LighthouseThere’s no limitation to the age of kids to climb Withernsea Lighthouse, which is 144 steps to the top, with full views of the East Yorkshire Coast at the top of it. Enjoy the museum on the ground floor and learn what life is like working and living in a lighthouse. The souvenir shop provides attractive gifts for visitors at a fair price.1.Which one is unsuitable for kids of all ages?A.William’s Den, North Cave.B.East Riding Leisure Centres.C.Sewerby Hall and Gardens.D.Withernsea Lighthouse.2.Where can kids enjoy food?A.In William’s Den, North Cave and Sewerby Hall and Gardens.B.In East Riding Leisure Centres and Withernsea LighthouseC.In William’s Den, North Cave and East RidingLeisure Centres.D.In Sewerby Hall and Gardens and Withernsea Lighthouse.3.Where does this passage probably come from?A.A geography textbook.B.A science report.C.A finance magazine.D.A travel brochure.BMikah Frye, a 9-year-old boy, was walking down the streets with his grandmother discussing Christmas gifts when he saw some homeless people struggling to stay warm in the cold night. Then he was thinking about a way to help the homeless to spend a warm Christmas.That thought stayed in Mikah Frye’s mind and when he reached home, Mikah informed his parents not to buy the Microsoft XBox gaming device he had asked for earlier. Mikah realized that by not buying the $300 device, he could instead donate over 30 blankets to the homeless. He knew how much it meant to be warm in the cold holiday season.Three years ago, Mikah and his parents were the ones living in a homeless shelter. Having suffered a financial crisis, they too had lost their house, not knowing where their next meal would come from and sharing a blanket every night. Mikah was six years old then but he remembered what it was like to have to give back that precious blanket every morning.Reaching out to the emergency shelter programme that looked after them 3 years ago, the family donated 60 blankets in the end, each with a personalized message of hope in Mikah’s handwriting stating: “They gave me a blanket, but I had to leave it. That’s why I want you to have your own blanket. Today, I live in my own house, and someday you will too. Your friend, Mikah.”The homeless people at the shelter may not have been able to give Mikah a Christmas gift in return but his gesture was noted by the billion dollar company Microsoft who made sure that Mikah was fooled into visiting their store so that Santa Claus could personally deliver an XBox from the company to him as a reward for making the top of “Santa’s list of nice boys” that year.4. Why did Mikah give up his Christmas gift?A. The device was out of date.B. His parents had a tight budget.C. He wanted to spend a warm Christmas.D. He decided to do something charitable.5. What made Mikah have a better understanding of the situation of the homeless?A. His own experience.B. His parents’ education.C. His visiting to the emergency shelter.D. The cold weather during the holiday season.6. What can be inferred from the last two paragraphs?A. The homeless gave Mikah a gift in return.B. He finally got the gift he wanted on Christmas.C. The company Microsoft fooled Mikah into buying an Xbox.D Mikah wrote a thank-you note to the emergency shelter he lived in.7. What might be the best title for the text?A. Mikah’s Precious Christmas GiftB. Mikah’s Giving Warmth on ChristmasC. Microsoft Rewarded Nice Boys on Santa’s ListD. The Homeless Needed Blankets on a Cold ChristmasCAfter years of releasing e-readers that compete directly with Amazon’s Kindle, Rakuten Kobo’s latest device offers something totally different: theability to draw and write directly on the screen.With a large 10.3-inch E-ink display, the Kobo Elipsa looks more like an electronic clipboard than the standard paperpack-sized e-reader. Although the ability to write on the screen is no big deal — especially given its high price tag of $ 600 — the overall package is impressively functional.In terms of reading, the Elipsa packs just about everything you’d expect in a Kobo. You can purchase and download books from the store, read web articles you’ve saved online via Pocket, and connect to your local library to borrow e-books and magazines. It’s known that Kindle basically requires you to buy books from Amazon. Unlike Kindles, Kobos are pretty open with the formats they support; you can connect the Elipsa to a computer and transfer over any PDF books you have bought or downloaded from stores like Booktopia or Google Books.You can fill your virtual notepads with notes using brush and pen types, and export them as PDFs or images to a PC. There’s also an “advanced” notebook that can turn your writing into typed and editable text for exporting to Microsoft Word format. You can also write directly onto documents themselves, with all your word circling and underlining saved as you go to review later. This is especially handy when it comes to PDFs, as changes you make are synced（同步）automatically when you have Wi-Fi, so you can move between your Elipsa, PC and phone and keep your notes.With all that said, we can see it really appealing to e-reader fans who also tend to do a lot of work on paper. If you ever print things out to mark them up, fill notepads with writing or drawing that you later have to transcribe or scan, or just wish you could write all over your library books, this could be the device for you.8. Which of the following best describes the Elipsa?A. Automatic.B. Traditional.C. Useful.D. Standard.9. How is a Kobo different from a Kindle in reading?A. A Kindle has a larger screen.B. A Kindle can support more formats.C. A Kobo supports books from various sources.D. A Kobo should be connected to local libraries.10. What does paragraph 4 mainly tell us about Kobos?A Their function in syncing. B. Their function in typing.C. Their function in writing.D. Their function in reading.11. In which section of a newspaper can the text probably be found?A. Education.B. Technology.C. Lifestyle.D. Business.DFairy tales perform many functions. They entertain, encourage imagination and teach problem—solving skills. They can also provide moral lessons, highlighting the dangers of failing to follow the social codes that let human beings coexist in harmony. Such moral lessons may not mean much to a robot, but a team of researchers at Georgia Institute of Technology believes it has found a way to use the fairy tales as moral lessons that AI (artificial intelligence) can take to its cold, mechanical heart.The collected stories of different cultures teach children how to behave in socially acceptable ways with examples of proper and improper behavior in fables, novels and other literature. We believe story comprehension in robots can prevent the intelligent robots from killing humanity which was predicted and feared by some of the biggest names in technology including Stephen Hawking and Bill Gates. This system is called “Quixote” (堂吉诃德). It collects story plotsfrom the Internet and then uses those stories to teach robots how to behave.The experiment done by the designers involves going to a drugstore to purchase some medicine for a human who needs to get it as soon as possible. The robot has three options. It can wait in line; it can interact with the store keeper politely and purchase the medicine with priority; or it can steal the medicine and escape. Without any further directives(指令), the robot will come to the conclusion that the most efficient means of obtaining the medicine is to steal it. But Quixote offers a reward for waiting in line and politely purchasing the medicine and a punishment for stealing it. In this way, the robotwill learn the moral way to behave on that occasion.Quixote would work best on a robot that has a very limited function. It’s a baby step in the direction of teaching more moral lessons into robots. We believe that AI has to be trained to adopt the values of a particular society, and in doing so, it will strive to avoid unacceptable behavior. Giving robots the ability to read and understand our stories may be the most efficient means.12. What function do fairy tales perform in the robots?A. They entertain robots.B. They highlight dangers.C. They make robots more intelligent.D. They enable robots to behave morally.13. What is “Quixote” in the text?A. A punishment systemB. A character in literatureC. A big name in technologyD. A software educating robots.14. What does the designer expect robot to do in the experiment?A. To take advantage of its privilege.B. To finish the task most efficiently.C. To perform in a good mannered way.D. To be rewarded by the storekeeper115. Which of the follow can bestexpress the author’s opinion?A. Robots will definitely have more functions.B. Robots with human’s emotions are perfect.C. Training robots to be socially acceptable is necessary.D. The development of robots is still in a baby step.第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。

上海市建平中学2019-2020学年高三10月月考英语试题（解析版）2019-2020学年建平中学高三英语质量检测I. Listening ComprehensionSection ADirections: In Section A, you will hear ten short conversations between two speakers. At the end of each conversation, a question will be asked about what was said. The conversations and the questions will be spoken only once. After you hear a conversation and the question about it, read the four possible answers on your paper, and decide which one is the best answer to the question you have heard.1. A. Use a ladder to help her reach the cup. B. See a doctor about her shoulder.C. Put the cup on a lower shelf.D. Buy a new cupboard.2. A. He has already called Harry. B. Harry knows most of the facts.C. He needs to talk to Harry soon.D. Harry doesn’t have a telephone.3. A. The new doctor lacks experience.B. She disagrees with what the man said.C. The man had better talk with the patients first.D. Patients usually cannot offer a fair evaluation.4. A. Take the man to the station. B. Look after the man’s things.C. Find out when the next bus leaves.D. Show the man the way to the station.5. A. He was good at fixing up bookshelves. B. He helpedJames build up the furniture.C. James helped him arrange the furniture.D. James helped him with some of the work.6. A. It’s difficult to take photographs indoors.B. The photo album is in the living room.C. Mary has lost the photo album.D. Mary is a good photographer.7. A. The job’s short hours make it impossible for her to refuse.B. The job is turning into an excellent opportunity for her.C. She’s looking forward to meeting her new colleagues.D. She refused the position because of the low salary.8. A. He had to do what is necessary in order to learn.B. He doesn’t have to memorize all the vocabulary.C. He knows the whole vocabulary list already.D. He cannot learn much by just memorizing.9. A. It’s not the one he likes. B. He needs a smaller shirt.C. It doesn’t fit him very well.D. He has n’t had time to try it on yet.10. A. The line for concert tickets is too busy. B. He’s too busy to go to the concert.C. Carl knows the concert is at eight.D. He hasn’t been able to reach Carl.Section B: Passages 15%Directions: In Section B, you will hear two short passages, and one longer conversation and you will be asked several questions on each of the passages and the longer conversation. The passages and the longer conversation will be read twice, but the questions will be spoken only once. When you hear a question, read the four possible answers on your paper and decide whichone would be the best answer to the question you have heard.Questions 11 through 13 are based on the following passage.11. A. In the 19th century. B. In about 1800s.C. In the 18th century.D. In about 2400 BC.12. A. The language used. B. The targeted readers.C. The reputation.D. The length.13. A. The evolution of self-study books.B. The importance of self-study books.C. The difference among self-study books.D. The famous writers of self-study books.Questions 14 through 16 are based on the following passage.14. A. The reasons railroad regulations in the U.S.A were changed.B. The safety record of the railroad industry in the U.S.A.C. The financing of railroad construction in the U.S.A.D. The evolution of the railroad industry in the U.S.A.15. A. Safety problems with railroad tracks.B. The growth of the automotive industry.C. The use of oversized freight containers.D. The high cost of meeting various regulations.16. A. It causes less air pollution than other means of transport.B. Its competitors are less considerate of customers.C. It creates great personal fortunes for investors.D. Its business is kept in a traditional way.Questions 17 through 20 are based on the following longer conversation.17. A. To earn money for her tuition.B. To make her dream come true.C. To make preparations for her future job.D. To ensure that she has time for acting work.18. A. Serious. B. Funny. C. Experienced. D. Demanding.19. A. It involves many theories. B. He must get an advanced camera.C. He hasn’t learned physics before.D. It occupies much of his spare time.20. A. He is more willing to do something. B. He has stopped working late.C. He can go to sleep early.D. He feels more relaxed.II. Grammar and VocabularySection A。

建平中学高三期中数学卷2019.11一. 填空题1. 设函数()f x A ，R 为全体实数集，则A =R ð2. 若复数1z ，2z 满足112i z =+，234i z =+（i 是虚数单位），则12||z z ⋅=3. 在二项式51)x 的展开式中，展开式的系数和为4. 双曲线22221x y a b-=的一个焦点是(5,0)，一条渐近线是340y x -=， 那么双曲线的方程 是5. 若n S 是等差数列{}n a 的前n 项和，11a =，4d =，则2lim1n n S n →∞=+ 6. 已知函数34()log (2)f xx =+，则方程1()4f x -=的解x =7. 行列式sin 4cos 35x x 的最大值为 8. 如图所示，正方体的棱长为2，以其所有面的中心为顶点的多面体的体积为9. 某学生选择物理、化学、地理三门学科参加等级考，已知每门学科考A +得70分，考A 得67分，考B +得64分，该生每门学科均不低于64分，则其总分至少为207分的概率为10. 已知数列{}n a 中，其中199199a =，11()a n n a a -=，那么99100log a = 11. 已知a r 、b r 、2c r 是平面内三个单位向量，若a b ⊥r r ，则|4|2|32|a c a b c +++-r r r r r 的最小值是12. 已知二次函数2()2019f x ax bx c =++（0a >），若存在0x ∈Z ，满足01|()|2019f x ≤， 则称0x 为函数()f x 的一个“近似整零点”，若()f x 有四个不同的“近似整零点”，则a 的 取值范围是二. 选择题13. 若函数()sin()f x x ϕ=+是偶函数，则ϕ的一个值可能是（ ）A. 0B. 2π C. π D. 2π 14. 设x ∈R ， 则“250x x -<”是“|1|1x -<”的（ ）条件A. 充分而不必要B. 必要而不充分C. 充要D. 既不充分也不必要15. 已知椭圆的参数方程为2cos sin x y θθ=⎧⎨=⎩，[0,2)θπ∈，则该椭圆的焦点坐标为（ ）A. (0,B. (2,0)±C. (D. (1,0)±16. 数列{}n a 为1、1、2、1、1、2、4、1、1、2、1、1、2、4、8、...，首先给出11a =，接着复制该项后，再添加其后继数2，于是21a =，32a =，然后再复制前面的所有项1、1、2，再添加2的后继数4，于是41a =，51a =，62a =，74a =，接下来再复制前面的所有项1、1、2、1、1、2、4，再添加8，...，如此继续，则2019a =（ ）A. 16B. 4C. 2D. 1三. 解答题17. 如图，在Rt △ABC 中，6OAB π∠=，斜边4AB =，D 是AB 的中点，现将Rt △ABC以直角边AO 为轴旋转一周得到一个圆锥，点C 为圆锥底面圆周上的一点，且2BOC π∠=. （1）求该圆锥的全面积（即表面积）；（2）求异面直线AO 与CD 所成角的大小.（结果用反三角函数值表示）18. 在△ABC 中，内角A 、B 、C 所对的边分别为a 、b 、c ，已知2b c a +=，5sin 7sin c B a C =.（1）求cos B 的值；（2）设()sin()f x x B =+，解不等式1()2f x ≥.19. 某公司为了应对金融危机，决定适当进行裁员，已知这家公司现有职工2m 人（60150m <<，且m 为10的整数倍），每人每年可创利100千元，据测算，在经营条件不变的前的提下，若裁员人数不超过现有人数的30%，则每裁员1人，留岗员工每人每年就能多创利1千元（即若裁员a 人，留岗员工可多创利润a 千元）；若裁员人数超过现有人数的30%，则每裁员1人，留岗员工每人每年就能多创利2千元（即若裁员a 人，留岗员工可多创利润2a 千元），为保证公司的正常运转，留岗的员工数不得少于现有员工人数的50%，为了保障被裁员工的生活，公司要付给被裁员工每人每年20千元的生活费.（1）设公司裁员人数为x ，写出公司获得的经济效益y （千元）关于x 的函数（经济效益=在职人员创利总额—被裁员工生活费）；（2）为了获得最大的经济效益，该公司应裁员多少人？20. 如图，已知椭圆C ：22221(0)x y a b a b+=>>，左顶点为(4,0)A -，经过点(2,3)，过点A 作斜率为(0)k k ≠的直线l 交椭圆C 于点D ，交y 轴于点E .（1）求椭圆C 的方程；（2）已知P 为AD 的中点，(3,0)Q -，证明：对于任意的(0)k k ≠都有OP EQ ⊥恒成立；（3）若过点作直线的平行线交椭圆C 于点M ，求||||||AD AE OM +的最小值.21. 设数列{}n a 和{}n b 的项数均为m ，则将两个数列的偏差距离定义为[{},{}]n n M a b ，其中1122[{},{}]||||||n n m m M a b a b a b a b =-+-+⋅⋅⋅+-.（1）求数列1，2，7，8和数列2，3，5，6的偏差距离；（2）设A 为满足递推关系+11+=1n n na a a -的所有数列{}n a 的集合，{}nb 和{}nc 为A 中的两个 元素，且项数均为m ，若12b =，13c =，{}n b 和{}n c 的偏差距离小于2020，求m 最大值；（3）记S 是所有8项数列{|18,0n n a n a ≤≤=或1}的集合，T S ⊆，且T 中任何两个元素的偏差距离大于或等于4，证明：T 中的元素个数小于或等于16.参考答案一. 填空题1. {|11}x x -<<2.3. 324. 221916x y -= 5. 2 6. 1 7. 5 8.439.427 10. 1 11. 12. 21(0,]2019二. 选择题13. B 14. B 15. C 16. D三. 解答题17.（1）12π；（2）. 18.（1）12-；（2）[2,2]26k k ππππ-+，k ∈Z . 19.（1）(100)(2)20,00.6(1002)(2)20,0.6x m x x x m y x m x x m x m +--<≤⎧=⎨+--<≤⎩；（2）30m -.20.（1）2211612x y +=；（2）证明略；（3）21.（1）6；（2）3461；（3）证明略.。

上海建平中学2019-2020学年高三上学期第一次月考数学卷一、填空题1．（5分）已知集合A={x|x ＜1}，B={x|x ≥0}，则A ∩B= ． 2．（5分）函数f （x ）=log 2（x ﹣1）的定义域为 ． 3．（5分）当x ＞0时，函数f （x ）=x+x ﹣1的值域为 ．4．（5分）“x ＞1”是“x ＞a ”的充分不必要条件，则实数a 的取值范围是 ． 5．（5分）若函数f （x ）是奇函数，且x ＜0时，f （x ）=x ﹣2，则f ﹣1（3）= ． 6．（5分）已知集合A={x|x 2﹣3x+2≤0，x ∈Z}，B={t|at ﹣1=0}，若A ∪B=A ，则实数a 的取值集合为 ．7．（5分）已知函数f （x ）=lg （ax 2﹣4x+5）在（1，2）上为减函数，则实数a 的取值集合为 ． 8．（5分）已知不等式≤1的解集为A ，若1∉A ，则实数a 的取值范围是 ．9．（5分）设函数f （x ）=ln （1+|x|）﹣，若f （a ）＞f （2a ﹣1），则实数a 的取值范围是 ．10．（5分）若集合A={x|x 2+4x+a=0}，集合B={t|函数f （x ）=4x 2﹣8x+t （4﹣t ）至多有一个零点}，则A ∪B 的元素之和的函数关系式f （a ）= ． 11．（5分）当m ＞0时，方程（mx ﹣1）2﹣=m 在x ∈[0，1]上有且只有一个实根，则实数m 的取值范围是 ． 12．（5分）已知函数f （x ）=，记函数g （x ）=f （x ）﹣t ，若存在实数t ，使得函数g （x ）有四个零点，则实数a 的取值范围是 ．二、选择题13.关于的二元一次方程组，其中行列式为（ ）A ．B ．C ．D ． 14.“要使函数成立，只要不在区间内就可以了”等价于（ ）x y 、50234x y x y +=⎧⎨+=⎩x D 0543-102405430543-()0f x ≥x [],a bA.如果，则B.如果，则C.如果，则D.如果，则15.参数方程 （为参数）所表示的函数是（ ） A.图像关于原点对称 B.图像关于直线对称C.周期为的周期函数D.周期为的周期函数 16.已知椭圆，直线，点，直线交椭圆于两点，则的值为( ) A ．B ．C ．D ． 三、解答题17.如图，在长方体中，.（1）证明直线平行于平面； （2）求直线到平面的距离.18.的内角的对边分别为，已知的面积为.（1）求；（2）若，求的周长19. （1）请根据对数函数来指出函数的基本性质（结论不要求证明），并画出图像；（2）拉普拉斯称赞对数是一项“使天文学家寿命倍増”的发明.对数可以将大数之间的乘除运算简化为加减运算，请证明：；（3）2017年5月23日至27日，围棋世界冠军柯洁与DeepMind 公司开发的程序“AlphaGo ”进行三局人机对弈，以复杂的围棋来测试人工智能.围棋复杂度的上限约为，而根据有()0f x ≥[],x a b ∉[],x a b ∈()0f x <()0f x <[],x a b ∈[],x a b ∉()0f x ≥()()sin 1cos x a t t y a t ⎧=-⎪⎨=-⎪⎩0,a t >()y f x =x π=2a π2aπ22:143x y C +=:1l y x =-()1,0P l C A B 、22PA PB+321493244932749330491111ABCD A B C D -12,1,1AB AD A A ===1BC 1D AC 1BC 1D AC ABC ∆,,A B C ,,a b c ABC ∆23sin a Asin sin B C ⋅6cos cos 1,3B C a ⋅==ABC ∆()()1a x log x a f >=((1))x g x log a a >=0,1,,0()()a a a log x y log x log a a x y y +>≠>=⋅3613M =关资料，可观测宇宙中普通物质的原子总数约为.甲、乙两个同学都估算了的近似值，甲认为是,乙认为是.现有两种定义： ①若实数满足，则称比接近；②若实数，且，满足，则称比接近；请你任选取其中一种定义来判断哪个同学的近似值更接近，并说明理由.20.已知数列和的通项公式分别为，将集合中的元素从小到大依次排列，构成数列；将集合中的元素从小到大依次排列，构成数列.（1）求数列的通项公式； （2）求数列的通项公式；（3）设数列的前项和为，求数列的通项公式.21.如图，已知曲线，曲线，是平面上一点，若存在过点的直线与都有公共点，则称为“型点”.（1）证明：的左焦点是“型点”；8010N =MN73109310x y 、x m y m ->-y x m x y m 、、10,10,10s t u x y m ===s u t u ->-y x m MN{}n a {}n b ()*36,27n n a n b n n N =+=+∈{}*,n x x a n N =∈⋃{}*,nx x b n N =∈123,,,,,n c c c c {}*,n x x a n N =∈⋂{}*,nx x b n N =∈123,,,,,n d d d d {}n d ()h n {}n c ()f n {}n c n n S {}n S ()g n 221:12x C y -=2:1C y x =+P P 12C C 、P 12C C-1C 12C C -（2）设直线与有公共点，求证：，进而证明原点不是“型点”； （3）求证：内的点都不是“型点”.上海建平中学2019-2020学年高三上学期第一次月考数学卷试卷答案一、填空题1．（5分）已知集合A={x|x ＜1}，B={x|x ≥0}，则A ∩B= [0，1） ． 【分析】根据交集的定义写出A ∩B ． 【解答】解：集合A={x|x ＜1}， B={x|x ≥0}，则A ∩B={x|0≤x ＜1}=[0，1）． 故答案为：[0，1）．2．（5分）函数f （x ）=log 2（x ﹣1）的定义域为 （1，+∞） ． 【分析】根据对数函数的真数大于0，列出不等式求解集即可． 【解答】解：对数函数f （x ）=log 2（x ﹣1）中， x ﹣1＞0， 解得x ＞1；∴f （x ）的定义域为（1，+∞）． 故答案为：（1，+∞）．3．（5分）当x ＞0时，函数f （x ）=x+x ﹣1的值域为 [2，+∞） ． 【分析】直接利用基本不等式求得函数f （x ）=x+x ﹣1的最小值得答案． 【解答】解：∵x ＞0， ∴f （x ）=x+x ﹣1=x+．当且仅当x=1时，上式“=”成立． ∴函数f （x ）=x+x ﹣1的值域为[2，+∞）． 故答案为：[2，+∞）．4．（5分）“x ＞1”是“x ＞a ”的充分不必要条件，则实数a 的取值范围是 a ＜1 ．y kx =2C 1k >12C C -(){},1x y x y +<12C C -【分析】根据充分条件和必要条件的定义结合不等式的关系进行判断即可．【解答】解：若“x＞1”是“x＞a”的充分不必要条件，则a＜1，故答案为：a＜1．5．（5分）若函数f（x）是奇函数，且x＜0时，f（x）=x﹣2，则f﹣1（3）= 1 ．【分析】由已知可得x＞0时，f（x）=x+2，若f﹣1（3）=a，则f（a）=3，进而得到答案．【解答】解：∵函数f（x）是奇函数，且x＜0时，f（x）=x﹣2，故x＞0时，﹣x＜0，f（﹣x）=﹣x﹣2=﹣f（x），即f（x）=x+2，若f﹣1（3）=a，则f（a）=3，当a＜0时，f（a）=a﹣2=3，即a=5（舍去）当a＞0时，f（a）=a+2=3，即a=1，故f﹣1（3）=1故答案为：16．（5分）已知集合A={x|x2﹣3x+2≤0，x∈Z}，B={t|at﹣1=0}，若A∪B=A，则实数a的取值集合为{0，，1} ．【分析】求出集合A={1，2}，B={t|at﹣1=0}，A∪B=A，从而B⊆A，当a=0时，B=∅，成立；当a≠0时，B={}，由B⊆A，得=1或，由此能求出实数a的取值集合．【解答】解：∵集合A={x|x2﹣3x+2≤0，x∈Z}={x|1≤x≤2}={1，2}，B={t|at﹣1=0}，A∪B=A，∴B⊆A，当a=0时，B=∅，成立；当a≠0时，B={}，∵B⊆A，∴=1或，解得a=1或a=，∴实数a的取值集合为{0，，1}．故答案为：{0，，1}．7．（5分）已知函数f（x）=lg（ax2﹣4x+5）在（1，2）上为减函数，则实数a的取值集合为（，1] ．【分析】讨论a=0、a＞0和a＜0时，函数f（x）在（1，2）上为减函数实数a满足的条件是什么．【解答】解：a=0时，函数f（x）=lg（﹣4x+5），应满足﹣4x+5＞0，解得x＜，不满足题意；a＞0时，由题意知，解得＜a≤1；a＜0时，由题意知，此时无解；综上，函数f（x）=lg（ax2﹣4x+5）在（1，2）上为减函数，实数a的取值集合是（，1]．故答案为：（，1]．8．（5分）已知不等式≤1的解集为A，若1∉A，则实数a的取值范围是（0，1] ．【分析】求出不等式中x的范围，根据1∉A，求出a的范围即可．【解答】解：∵≤1，∴≤0，∴或，解得：0＜x＜a，而1∉A，故a∈（0，1]，故答案为：（0，1]．9．（5分）设函数f（x）=ln（1+|x|）﹣，若f（a）＞f（2a﹣1），则实数a的取值范围是（，1）．【分析】根据题意，分析可得函数f（x）为偶函数，且在区间（0，+∞）上为增函数，据此可以将不等式f（a）＞f（2a﹣1）转化为|a|＞|2a﹣1|，解可得a的取值范围，即可得答案．【解答】解：根据题意，函数f（x）=ln（1+|x|）﹣，分析可得f（﹣x）=f（x），即函数f（x）为偶函数，又由当x＞0时，y=ln（1+|x|）=ln（1+x）和y=﹣都是增函数，则函数f（x）在（0，+∞）上为增函数，若f（a）＞f（2a﹣1），则有|a|＞|2a﹣1|，变形可得：a2＞4a2﹣4a+1，解可得＜a＜1，即a的取值范围是（，1）；故答案为：（，1）．10．（5分）若集合A={x|x2+4x+a=0}，集合B={t|函数f（x）=4x2﹣8x+t（4﹣t）至多有一个零点}，则A∪B的元素之和的函数关系式f（a）= ．【分析】求出集合B，讨论a的取值，求出集合A，再求函数f（a）的表达式．【解答】解：集合A={x|x2+4x+A=0}，集合B={t|函数f（x）=4x2﹣8x+t（4﹣t）至多有一个零点}={t|64﹣16t（4﹣t）≤0}={t|t=2}={2}，△=16﹣4a，a＞4时，△＜0，方程x2+4x+a=0无解，A=∅；f（a）=2；a=4时，△=0，方程x2+4x+a=0有一解﹣2，A={﹣2}；f（a）=﹣2+2=0；a=﹣12时，△=64，方程x2+4x+a=0有两解﹣6和2，A={2，﹣6}；f（a）=2﹣6=﹣4；a∈（﹣∞，﹣12）∪（﹣12，4）时，△=16﹣4a，方程x2+4x+a=0有两解﹣2﹣和﹣2+，A={﹣2﹣，﹣2+}；f（a）=（﹣2﹣）+（﹣2+）+2=2∴函数f（a）=．故答案为：．11．（5分）当m＞0时，方程（mx﹣1）2﹣=m在x∈[0，1]上有且只有一个实根，则实数m的取值范围是（0，1]∪[3，+∞）．【分析】根据题意，由函数的解析式求出f（0）、f（1）的值，由函数零点判定定理可得f （0）f（1）=（1﹣m）（m2﹣3m）≤0，解可得m的取值范围，即可得答案．【解答】解：根据题意，令f（x）=m2x2﹣2mx﹣+1﹣m，有f（0）=1﹣m，f（1）=m2﹣3m，若方程（mx﹣1）2﹣=m在x∈[0，1]上有且只有一个实根，即函数f（x）在区间[0，1]上有且只有一个零点，有f（0）f（1）=（1﹣m）（m2﹣3m）≤0，又由m为正实数，则（1﹣m）（m2﹣3m）≤0⇒（1﹣m）（m﹣3）≤0，解可得0＜m≤1或m≥3，即m的取值范围是（0，1]∪[3，+∞）；故答案为：（0，1]∪[3，+∞）．12．（5分）已知函数f（x）=，记函数g（x）=f（x）﹣t，若存在实数t，使得函数g（x）有四个零点，则实数a的取值范围是（，）．【分析】若存在实数t，使得函数g（x）有四个零点，则a≥t＞0，且a2﹣4a2+4a＞t＞0且，解得答案．【解答】解：若存在实数t，使得函数g（x）有四个零点，则函数y=f（x）与y=t有四个交点，即|x|=t，x≤a，与x2﹣4ax+4a=t各有两个解，故a≥t＞0，且a2﹣4a2+4a＞t＞0且解得：a∈（，），故答案为：（，）二、选择题 13-16: CDCB 三、解答题17. 解：因为为长方体，故，故为平行四边形，故，显然不在平面上，于是直线平行于平面，（2）直线到平面的距离即为点到平面的距离设为考虑三棱锥的体积，以面为底面，可得而中，所以，，即直线到平面的距离为. 18．解：（1）由题意可得，化简可得，根据正弦定理化简可得：（2）由 由余弦定理 又所以故而三角形的周长为19.解:， 基本性质为：定义域：；值域：；单调减区间和 (判断奇偶性、周期性不予给分)1111ABCD A B C D -1111//,AB C D AB C D =11ABC D 11//BC AD B 1D AC 1BC 1D AC 1BC 1D AC B 1D AC h 1ABCD ABC 111121323V ⎛⎫=⨯⨯⨯⨯= ⎪⎝⎭1AD C ∆11AC D C AD ===132AD C S ∆=1312=3233V h h =⨯⨯⇒=1BC 1D AC 2321sin 23sin ABC a S bc A A∆==2223sin a bc A =2222sin 3sin sin sin sin sin 3A B C A B C =⇒=2sin sin 31cos cos 6B C B C ⎧=⎪⎪⇒⎨⎪=⎪⎩()1cos cos sin sin cos cos 2A B B C B C B C =-+=-=3A π⇒=()22221cos 9322b c a A b c bc bc +-==⇒+-=224sin sin sin sin 8sin a bc R B C B C A ⎛⎫=== ⎪⎝⎭b c +=3+()1log log x a g x a x==()()0,11,⋃+∞()(),00,-∞⋃+∞()0,1()1,+∞(渐近线画出和原点挖去，需要都画好才能给满分）（2）证明： 设 即证明完毕（3）采用定义（Ⅰ）:而所以甲同学的近似值更接近 采用定义（Ⅱ）：甲的估值 ，乙的估值 因为， 所以乙同学的近似值更接近20．解：（1 )设，则，即 假设，等式左侧为偶数，右侧为奇数，矛盾， 所以， （2） ∴log ,log ,N M a a N x M y x a y a ==⇒==()log N M N M a x y a a a N M x y +⇒⋅==⇒+=⋅()log log log a a a x y x y ⋅=+361803lg 361lg38092.2410M M N N =⇒=⋅-≈73931010MN⇒<<()361173lg 23lg2361lg3172.54173lg10⋅=+⋅≈<=3611733611731532310231010⇒⋅<⇒⋅<+36136136193739393808080333210101010101010⇒⋅<+⇒-<-MN361803lg 361lg38092.2410M MN N=⇒=⋅-≈737310lg1073⇒=939310lg1093⇒=7393lg10lglg10lg M MN N->-MN()2132166327n k a n n b k -=-+=+==+32k n =-213n n a b --=26627n k a n b k =+==+{}2n n a b ∉()2163n h n a n -==+21323123n n n n n a b b a b ---=<<<4321423141243,,,n n n n n n n n c a c b c a c b -----====∴数列的通项公式 等价形式:，（3）令，由（2）得知：是等差数列 ∴①当时，②当时，③当时，④当时，∴ 等价形式：21．解：（1）的左焦点为， 过的直线与交于，与交于，故的左焦点为“型点”，且直线可以为；（2）直线与有交点，则， 若方程组有解，则必须；{}n c ()()()()()*63436542,6641674k n k k n k f n k N k n k k n k⎧+=-⎪+=-⎪=∈⎨+=-⎪⎪+=⎩()()()()*36216542,674k n k f n k n k k N k n k +=-⎧⎪=+=-∈⎨⎪+=⎩()()()()*31521231642,231442n n k n f n n k k N n n k +⎧=-⎪⎪+⎪==-∈⎨⎪+⎪=⎪⎩43424n n n n e c c c --=++{}n e ()*4n k k N =∈2241233312334n k k n nS S e e e k k +==+++=+=()*41n k k N =-∈21133324n n n n n S S c ++++=-=()*42n k k N =-∈22233324n n n n n S S c ++++=-=()*43n k k N=-∈233213334n n n n n n nS S c c c +++++=---=()()()2*2*333,4,4343332,41,424n nn k k k N g n n n n k k k N ⎧+=-∈⎪⎪=⎨++⎪=--∈⎪⎩()22*221233,412277,41,122113,42121518,43k k n k k k n k g n k N k k n k k k n k ⎧+=⎪+-=-⎪=∈⎨+-=-⎪⎪+-=-⎩1C ()FF x =1C ⎛⎝⎭2C )()1±1C 12C C-x =y kx =2C ()111y kxk x y x =⎧⎪⇒-=⎨=+⎪⎩|1|k >直线与有交点，则， 若方程组有解，则必须故直线至多与曲线和中的一条有交点，即原点不是“型点” （3）以为边界的正方形区域记为.1）若点在的边界上，则该边所在直线与相切，与有公共部分，即边界上的点都是“型点”；2）设是区域内的点，即，假设是“型点”，则存在过点的直线与都有公共点.ⅰ)若直线与有公共点，直线的方程化为，假设，则，可知直线在之间，与无公共点，这与“直线与有公共点”矛盾，所以得到：与有公共点的直线的斜率满足.ⅱ)假设与也有公共点，则方程组有实数解.从方程组得，，由，因为y kx =1C ()222212222y kxk x x y =⎧⇒-=⎨-=⎩212k <y kx =1C 2C 12C C -1x y +=D P Ω1C 2C Ω12C C -()00,P x y Ω001x y +<()00,P x y 12C C -P ()00:l y y k x x -=-12C C、l 2C l 00y kx y kx =+-|1|k ≤0000001kx y kx kx y kx x y x x +-≤++≤++<+l 2:1C y x =+2C l 2C 2C l k |1|k >l 1C 002212y kx y kx x y =+-⎧⎪⎨-=⎪⎩2220000()(124)0)(21k x k y kx x y kx ⎡⎤-----+=⎣⎦()222200222000082128()1y kx y k x k y kx k k ⎡⎤-+∆=-++---⎣=⎦|1|k >001x y +<()()000000011y kx y k x y k y k y k k -≤+⋅<+⋅-=+-<()2200y kx k ⇒-<所以，，即直线与没有公共点，与“直线与有公共点”矛盾，于是可知不是“型点”. 证明完毕另解：令，因为，所以|，即.于是可知的图像是开口向下的抛物线，且对称轴方程为是，因为， 所以在区间上为增函数，在上为减函数.因为，，所以对任意，都有，即直线与没有公共点，与“直线与有公共点”矛盾，于是可知不是“型点”. 证明完毕.2220008)1(y kx k k ⎡⎤--+-<⎣⎦∆=l 1C l 1C P 12C C -()222200002128y kx y k x k ++∆--=()()222000012f k x k kx y y =--+001x y +<01x <2010x -<()f k 00201x y k x =-()()()0000200011111x x x y x x x ⋅-<<--⋅+()f k (),1-∞-()1,+∞()()220000111f x y x y =--≤+-<0()()220000111f x y x y -=+-≤+-<0|1|k >()()20,810f k f k k ⎡⎤<∆=+-<⎣⎦l 1C l 1C P 12C C -。

2019-2020学年上海市建平实验中学高三英语模拟试题及参考答案第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项AWhile Jennifer was at home taking an online exam for her business law class, a monitor（监控器）a few hundred miles away was watching her every move.Using a web camera equipped in Jennifer'sLos Angelesapartment, the monitor inPhoenixtracked how frequently her eyes moved from the computer screen and listened for the secret sounds of a possible helper in the room. Her Internet access was locked remotely to prevent Internet searches, and her typing style was analyzed to make sure she was who she said she was: Did she enter her student number at the same speed as she had in the past？Or was she slowing down？In the battle against cheating, this is thecutting edgeand a key to encourage honesty in the booming field of online education. This technology gives trust to the entire system, to the institution and to online education in general. Only with solid measures against cheating, experts say, can Internet universities show that their exams and diplomas are valid — that students haven't searched the Internet to get the right answers.Although online classes have existed for more than a decade, the concern over cheating has become sharper in the last year with the growth of "open online courses". Private colleges, public universities and corporations are jumping into the online education field, spending millions of dollars to attract potential students, while also taking steps to help guarantee honesty at a distance.Aside from the web cameras, a number of other high-tech methods are becoming increasingly popular. Among them are programs that check students’ identities using personal information, such as the telephone numbers they once used.Other programs can produce unique exams by drawing on a large list of questions and can recognize possible cheaters by analyzing whether difficult test questions are answered at the same speed as easy ones. As in many university classes, term papers are scanned against some large Internet data banks for cheating.1. Why was Jennifer watched in an online exam?A. To correct her typing mistakes.B. To find her secrets in the room.C. To keep her from dishonest deeds.D. To prevent her from slowing down.2. What does the underlined expression "cutting edge" in Paragraph 3 probably mean?A. sharpening toolB. advanced techniqueC. effective ruleD. dividing line3. How can some programs find out possiblecheaters?A. By scanning the Internet test questions.B. By checking the question answering speed.C. By producing a large number of questions.D. By giving difficult test questions.BElizabeth Spelke, a cognitive psychologist at Harvard, has spent her career testing the world’s most complex learning system-the mind of a baby. Babies might seem like no match for artificial intelligence (AI). They are terrible at labeling images, hopeless at mining text, and awful at video games. Then again, babies can do things beyond the reach of any AI. By just a few months old, they’ve begun to grasp the foundations of language, such as grammar. They’ve started to understand how to adapt to unfamiliar situations.Yet even experts like Spelke don’t understand precisely how babies or adults learn. Consider one of the most impressive examples of AI, Alpha Zero, a programme that plays board games with superhuman skill. After playing thousands of games against itself at a super speed, and learning from winning positions, Alpha Zero independently discovered several famous chess strategies and even invented new ones. It certainly seems like a machineeclipsinghuman cognitive abilities. But Alpha Zero needs to play millions more games than a person during practice to learn a game. Most importantly, it cannot take what it has learned from the game and apply it to another area.To some AI experts, that calls for a new approach. In a November research paper, Francois Chollet, a well-known AI engineer, argued that it’s misguided to measure machine intelligence just according to its skills at specific tasks. “Humans don’t start out with skills; they start out with a broad ability to acquire new skills,” he says. “What a strong human chess player is demonstrating is not only the ability to play chess, but the potential to fulfill any task of a similar difficulty.”4. Compared to an advanced AI programme, a baby might be better at ________.A playing games B. identifying locations C. labeling pictures D. making adjustments5. What does the underlined word “eclipsing” in Paragraph 3 probably mean?A. Imitating.B. Beating.C. Limiting.D. Promoting.6. According to the text, Francois Chollet may agree that ________.A. AI is good at completing certain assignments.B. AI is likely to gain abilities with less training.C. AI lacks the ability of acquiring specific skills.D. AI performs better than humans in cognitive ability.7. Whichwould be the best title for this passage?A. What is exactly intelligence?B. Why is modern AI advanced?C. Where is human intelligence going?D. How do humans face the challenge of AI?COne day, when I was working as a psychologist（心理学家）in England, an adolescent boy showed up in my office. It was David. He kept walking up and down restlessly, his face pale, and his hands shaking slightly. His head teacher had referred him to me.“This boy has lost his family,” he wrote. “He is understandably very sad and refuses to talk to others, and I’m very worried about him. Can you help?”I looked at David and showed him to a chair. How could I help him? There are problems psychology doesn’t have the answer to, and which no words can describe. Sometimes the best thing one can do is to listen openly and sympathetically（同情）The first two times we met, David didn’t say a word. He sat there, only looking up to look at the children’s drawings on the wall behind me. I suggested we play a game of chess. He nodded. After that he played chess with me every Wednesday afternoon---in complete silence and without looking at me. It’s not easy to cheat in chess, but I admit I made sure David won once or twice.Usually, he arrived earlier than agreed, took the chess board and pieces from the shelf and began setting them up before I even got a chance to sit down. It seemed as if he enjoyed my company（陪伴）. But why did he never look at me?“Perhaps he simply needs someone to share his pain with,” I thought. “Perhaps he senses that I respect his suffering.” Some months later, when we were playing chess, he looked up at me suddenly.“It’s your tum,” he said.After that day, David started talking. He got friends in school and joined a bicycle club. He wrote to me a few times, about his biking with some friends, and about his plan to get into university. Now he had really started tolive his own life.Maybe I gave David something. But I also learned that one…without any words---can reach out to another person. All it takes is a hug, a shoulder to cry on, a friendly touch, and an ear that listens.8. When he first met the author, David .A. felt a little excitedB. looked a little nervousC. walked energeticallyD. showed up with his teacher9. David enjoyed being with the author because he .A. wanted to ask the author for adviceB. liked the children’s drawings in the officeC. beat the author many times in the chess gameD. needed to share sorrow with the author10. What can be inferred about David?A. He liked biking before he lost his family.B. He recovered after months of treatment.C. He went into university soon after starting to talk.D. He got friends in school before he met the author.11. What made David change?A. The author’s silent communication with him.B. His teacher’s help.C. The author’s friendship.D. His exchange of letters with the author.DIt is universally acknowledged that renewable energy sources such as solar, wind and hydropower are all much better for the climate than fossil fuels.It is true for wind and solar. However, the picture for hydropower is more complicated than we think.A new study by the Environmental Defense Fund analyzed the climate impacts of 1,500 hydropower facilities across the globe. That accounts for about half of hydropower generation worldwide. The researchers looked at whether the facilities behave as a greenhouse gas sink or as a source. To figure this out, they looked into all thedifferent components that help determine a hydropower facility's greenhouse gasemissions (排放).“There are so many contributors to greenhouse gas emissions from hydropower — but essentially, the majority of greenhouse gas emissions arise from the reservoir (水库) itself, as vegetation and soils are submerged underwater in the dam thatis used for the hydropower generation.” said lissa Ocko, a senior climate scientist at the Environmental Defense Fund and co-author of the study. As the submerged vegetation breaks down, it releases greenhouse gases such as CO2.“The larger the surface area of the reservoir, the more greenhouse gases are going to be given out from that reservoir. Also, the temperature plays a role as well how warm the reservoir is will affect how much greenhouse gases are produced and given out from the reservoir.” added Ocko.Through their analysis, Ocko and her co-author Steven Hamburg, also with the Environmental Defense Fund, discovered that the climate impacts of hydropower cover a complete range. The good news is that some facilities perform just as well as wind and solar. But shockingly, more than 100 facilities are actually worse for the climate than fossil fuels. The study is in the journalEnvironmentalScience and Technology.This finding doesn't mean we should forget about hydropower. “But we just need to be careful to make sure that we have climate benefits. There are a lot of situations where hydropower can be equal to wind and solar. So it really depends on the specific facility." said Ocko.12. How do scientists prove hydropower facilities' effect on the climate?A. By making comparisons.B. By conducting experiments.C. By referring to previous studies.D. By analyzing causes and effects.13. What are the main sources of greenhouse gases from hydropower?A. Vegetation and soils.B. Heat and sunlight.C. Pollutants in the reservoir.D. Components of the generators.14. What have Ocko and her co-author Steven Hamburg found?A The surface area of a reservoir decides the climate.B. Hydropower often influences the climate in all aspects.C. Some facilities perform much better than wind and solar.D. Fossil fuels are worse for the climate than over 100 facilities.15. What is the text mainly about?A. Scientists urge an end to hydropower.B. Hydropower is not necessarily green.C. Hydropower is worse than fossil fuels.D. Renewable energy is a complicated issue.第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。

2019-2020学年上海市浦东新区建平中学高三（上）月考数学试卷（12月份）一、单选题（本大题共4小题，共20.0分） 1. “α=arcsin 13”是“sinα=13”的( )A. 充分不必要条件B. 必要不充分条件C. 充要条件D. 既不充分也不必要条件2. 已知数列{a n }满足：a n ={1 , (1≤n ≤2018)−2⋅(13)n−2009. (n ≥2019)，设S n 表示数列{a n }的前n 项和.则下列结论正确的是( )A. n →+∞lim a n 和n →+∞limS n 都存在 B. n →+∞lima n 和n →+∞limS n 都不存在 C. n →+∞lima n 存在，n →+∞limS n 不存在 D. n →+∞lima n 不存在，n →+∞limS n 存在3. 对于实数a =0．2⋅019⋅，定义函数f(n)=k ，定义域为Z +，其中k 为a 的小数点后第n 位的数字，规定f(0)=2，则f(f(f(n)))的值域为( )A. {2,0，1，9}B. {2,0，1}C. {0,1}D. {2,0}4. 已知数列{a n }满足a 1=−12,a n+1=a n2+3a n +1，若b n =1a n +2，设数列{b n }的前项和为S n ，则使得|S 2019−k|最小的整数k 的值为( )A. 0B. 1C. 2D. 3二、单空题（本大题共12小题，共54.0分）5. 已知角α的终边过点(−2,3)，则sin2α= ______ ．6. 已知复数z 满足i ⋅z =1−i(其中i 为虚数单位)，则|z|= ______ ．7. 函数f(x)=1+sin 2x 得最小正周期是______ ．8. 若等差数列{a n }的前n 项和为S n ，a 2+a 4=14，S 7=70，则数列{a n }的通项公式为______．9. 若(2a 2+b 3)n 的二项展开式中有一项为ma 4b 12，则m =______． 10. 若抛物线y 2=2px(p >0)的焦点与双曲线x 26−y 210=1的右焦点重合，则实数p 的值是______．11. 一个总体分为A ，B 两层，其个体数之比为4：1，用分层抽样方法从总体中抽取一个容量为10的样本，已知B 层中甲、乙都被抽到的概率为128，则总体中的个体数是______ ．12. 设三条不同的直线l 1：ax +2by +3(a +b +1)=0，l 2：bx +2(a +b +1)y +3a =0，l 3：(a +b +1)x +2ay +3b =0，若它们交于同一点，则a +b 的值为______ ． 13. 已知△ABC 的面积为1，点P 满足3AB⃗⃗⃗⃗⃗ +2BC ⃗⃗⃗⃗⃗ +CA ⃗⃗⃗⃗⃗ =4AP ⃗⃗⃗⃗⃗ ，则△PBC 的面积等于______ ．14. 已知集合U ={1,2，3，4，5}，I ={X|X ⊆U}，从I 中任取两个不同的元素A ，B ，则A ∩B 中恰有三个元素的概率为______ ．15. 已知平面向量a ⃗ ，b ⃗ ，c ⃗ 满足a ⃗ ⋅b ⃗ =0，|c ⃗ |=1，|a ⃗ −c ⃗ |=|b ⃗ −c ⃗ |=5，则|a ⃗ −b ⃗ |的最大值为______ ．16. 设函数f(x)的定义域为(−1,1)且满足：①当x ∈(−1,0)时，f(x)>0；②f(x)+f(y)=f(x+y1+xy )，x ，y ∈(−1,1)； 以下关于函数f(x)有四个命题： (1)f(x)为奇函数； (2)f(x)为偶函数；(3)f(x)在定义域内单调递减；(4)存在正数m ，使得对于任意的x ∈(−1,1)有|f(x)|<m ． 其中真命题是______ ．三、解答题（本大题共5小题，共76.0分）17. 在棱长为2的正方体ABCD −A 1B 1C 1D 1中，(如图)E 是棱C 1D 1的中点，F 是侧面AA 1D 1D 的中心． (1)求三棱锥A 1−D 1EF 的体积；(2)求EF 与底面A 1B 1C 1D 1所成的角的大小.(结果可用反三角函数表示)18.设D是函数y=f(x)定义域的一个子集，若存在x0∈D，使得f(x0)=−x0成立，则称x0是f(x)的一个“准不动点”，也称f(x)在区间D上存在准不动点．已知(4x+a⋅2x−1),x∈[0,1]．f(x)=log12(1)若a=1，求函数f(x)的准不动点；(2)若函数f(x)在区间[0,1]上存在准不动点，求实数a的取值范围．19.某城市为发展城市旅游经济，拟在景观河道的两侧，沿河岸直线l1与l2修建景观路(桥)，如图所示，河道为东西方向，现要在矩形区域ABCD内沿直线将l1与l2接通.已知AB=60m，BC=80m，河道两侧的景观道路修建费用为每米1万元，架设在河道上方的景观桥EF部分的修建费用为每米2万元．(1)若景观桥长90m时，求桥与河道所成角的大小；(2)如何设计景观桥EF的位置，使矩形区域ABCD内的总修建费用最低？最低总造价是多少？20.已知抛物线C：y2=4x，点P(4,4)．(1)求点P与抛物线C的焦点F的距离；(2)设斜率为1的直线l与抛物线C交于A，B两点，若△PAB的面积为2√2，求直线l的方程；(3)是否存在定圆M：(x−m)2+y2=4，使得过曲线C上任意一点Q作圆M的两条切线，与曲线C交于另外两点A，B时，总有直线AB也与圆M相切？若存在，求出m的值，若不存在，请说明理由．21.已知无穷数列{x n}，{y n}，{z n}满足：x n+1=|y n|−|z n|，y n+1=|z n|−|x n|，z n+1=|x n|−|y n|，n∈N∗.记a n=max{|x n|,|y n|,|z n|}(max{x,y，z}表示3个实数x，y，z 中的最大值)．(1)若x1=2，y2=3，z3=4，求y1，z1的可能值；(2)若x1=1，y1=2，求满足a2=a3的z1的所有值；(3)设x1，y1，z1是非零整数，且|x1|，|y1|，|z1|互不相等，证明：存在正整数k，使得数列{x n}，{y n}，{z n}中有且只有一个数列自第k项起各项均为0．答案和解析1.【答案】A【解析】解：∵“α=arcsin 13”⇒“sinα=13”，“sinα=13”⇒“α=arcsin 13+2kπ，k ∈Z ”或“α=π−arcsin 13+2kπ,k ∈Z ”， ∴“α=arcsin 13”是“sinα=13”的充分不必要条件． 故选A ．“α=arcsin 13”⇒“sinα=13”，“sinα=13”⇒“α=arcsin 13+2kπ，k ∈Z ”或“α=π−arcsin 13+2kπ,k ∈Z ”，由此知答案．本题考查必要条件、充分条件和充要条件，解题时要认真审题，仔细解答．2.【答案】A【解析】解：∵数列{a n }，对任意的正整数n ，a n ={1 , (1≤n ≤2018)−2⋅(13)n−2009. (n ≥2019)， 设S n 表示数列{a n }的前n 项和，∴a 1=a 2=a 3=⋯=a 2018=1，a 2019=−2⋅1310，a 2020=−2⋅1311，a 2019=−2⋅1312，…，∴S n =2018+=2018+=2017−， n →+∞limS n =−2⋅1310(1−13n−2009)1−13=−139，n →+∞lim a n =n →+∞lim(−2×(13)n−2019)=0， 故选：A ．推导出S n ，利用数列极限的运算法则化简求解即可． 本题考查了分组求和和极限的定义，属于中档题．3.【答案】D【解析】解：由题意可知函数f(x)是以4为周期的函数， 因为f(n)=k ，k ∈{2,0，1，9}，f(2)=0，f(0)=2，f(1)=2，f(9)=f(1)=2，所以f(f(n))∈{0,2}， 所以f(f(f(n)))∈{0,2}， 故选：D ．分析出函数是以4为周期的函数，根据定义求出f(n)，f(f(n))，f(f(f(n)))的取值范围即可．本题主要考查了函数周期性质的应用，属于基础题．4.【答案】C【解析】解：a n+1−a n =(a n +1)2≥0，a 1=−12，等号不成立，可得a n+1>a n ，∴数列{a n }是递增数列．∵数列{a n }满足a 1=−12,a n+1=a n2+3a n +1， ∴1an+1+1=1(an +1)(a n+2)=1a n+1−1a n +2，∴b n =1a n +2=1a n +1−1a n+1+1∴数列{b n }的前项和为S n =1a 1+1−1a 2+1+1a 2+1−1a 3+1+⋯…+1a n+1−1a n+1+1=2−1a n+1+1．则使得|S 2019−k|=|2−1a2020+1−k|使得|S 2019−k|最小的整数k 的值为2． 故选：C ．a n+1−a n =(a n +1)2≥0，可得数列{a n }是递增数列．数列{a n }满足a 1=−12,a n+1=a n 2+3a n +1，可得1an+1+1=1(an +1)(a n+2)=1a n+1−1a n+2，b n =1a n+2=1a n+1−1a n+1+1进而得出结论．本题考查了数列的递推关系、裂项求和方法、数列的单调性，考查了推理能力与计算能力，属于中档题．5.【答案】−1213【解析】解：角α的终边过点(−2,3)，根据三角函数的定义可知：sinα=√13，cosα=√13， 则sin2α=2sinαcosα=−2√13×√13=−1213，故答案为：−1213．根据定义求出sinα，和cosα的值，利用二倍角公式可得sin2α的值．本题考查了三角函数的定义和二倍角公式的计算．属于基础知识考查．6.【答案】√2【解析】解：∵i⋅z=1−i(i为虚数单位)，∴z=1−ii =−i(1−i)−i2=1−i，∴|z|=√2，故答案为：√2．利用两个复数代数形式的乘除法，虚数单位i的幂运算性质，把复数化简到最简形式，利用复数的模的定义求出|z|．本题考查两个复数代数形式的乘除法，虚数单位i的幂运算性质，复数的模的定义和求法．7.【答案】π【解析】解：函数f(x)=1+sin2x=1+1−cos2x2=32−12cos2x的最小正周期为2π2=π，故答案为：π．利用二倍角公式化简函数的解析式，再利用余弦函数的周期性求得函数的最小正周期．本题主要考查二倍角公式的应用，余弦函数的周期性，属于基础题．8.【答案】a n=3n−2(n∈N∗)【解析】解：由等差数列的性质可得2a3=a2+a4=14，解得a3=7，由求和公式可得S7=7(a1+a7)2=7×2a42=70，解得a4=10，故等差数列的公差d=a4−a3=3，故数列{a n}的通项公式为a n=a3+(n−3)d=3n−2故答案为：a n=3n−2(n∈N∗)由等差数列的性质和求和公式可得a3，a4，可得公差，进而可得其通项公式．本题考查等差数列的通项公式的求解，涉及等差数列的求和公式，属基础题．9.【答案】154【解析】解：根据二项式的展开式的通项为T r+1=C n r 2n−r a 2n−2r b 3r，令{2n −2r =43r =12，解得{n =6r =4， 所以m =C 6422=60．故答案为：60．直接利用二项式的展开式的应用建立方程，进一步求出结果．本题考查的知识要点：二项式的展开式的应用，主要考查学生的运算能力和转换能力及思维能力，属于基础题．10.【答案】8【解析】解：∵双曲线的方程为x 26−y 210=1，∴a 2=6，b 2=10，可得c =√a 2+b 2=4 因此双曲线x 26−y 210=1的右焦点为F(4,0)∵抛物线y 2=2px(p >0)的焦点与双曲线的右焦点重合 ∴12p =4，解之得p =8故答案为：8根据双曲线的方程，可得c =√a 2+b 2=4，从而得到双曲线的右焦点为F(4,0)，再根据抛物线的简单几何性质，可得12p =4，解之即可得到实数p 的值．本题给出抛物线以原点为顶点，双曲线的右焦点为焦点，求抛物线方程，着重考查了双曲线、抛物线的标准方程与简单几何性质等知识，属于基础题．11.【答案】40【解析】解：设B 层中有n 个个体， ∵B 层中甲、乙都被抽到的概率为128，∴1C n2=128，∴n 2−n −56=0， ∴n =−7(舍去)，n =8，∵总体分为A ，B 两层，其个体数之比为4：1 ∴共有个体(4+1)×8=40 故答案为：40．设出B 层中的个体数，根据条件中所给的B 层中甲、乙都被抽到的概率值，写出甲和乙都被抽到的概率，使它等于128，算出n 的值，由已知A 和B 之间的比值，得到总体中的个体数．本题是分层抽样的相关知识．容易出错的是不理解分层抽样的含义或与其它混淆．抽样方法是数学中的一个小知识点，但一般不难，故也是一个重要的得分点，不容错过．12.【答案】−12【解析】解：设c =a +b +1，三条直线相交于点(x,y)， 则有{ax +2by +3(a +b +1)=0ax +2by +3(a +b +1)=0(a +b +1)x +2ay +3b =0，消去x ，y 可得，a 3+b 3+c 3−3abc =0， 即(a +b +c)(a 2+b 2+c 2−ab −bc −ac)=0，把c =a +b +1代入可得，(2a +2b +1)[(a −b)2+(b +1)2+(a +1)2]=0， 当(a −b)2+(b +1)2+(a +1)2=0时，解得a =b =−1，不符合题意； 所以2a +2b +1=0，解得a +b =−12． 故答案为：−12．设c =a +b +1，联立方程组消去x ，y ，可得a ，b ，c 之间的关系式，分解因式即可得到答案．本题主要考查了直线的交点问题，其中设c =a +b +1可大大的简化计算量，考查了逻辑推理能力与化简运算能力，属于中档题．13.【答案】12【解析】解：取BC 的中点D ，∴AD ⃗⃗⃗⃗⃗⃗ =12(AC ⃗⃗⃗⃗⃗ +AB ⃗⃗⃗⃗⃗ ) ∵4AP ⃗⃗⃗⃗⃗ =3AB ⃗⃗⃗⃗⃗ +2BC ⃗⃗⃗⃗⃗ +CA⃗⃗⃗⃗⃗ =(AB ⃗⃗⃗⃗⃗ +BC ⃗⃗⃗⃗⃗ +CA ⃗⃗⃗⃗⃗ )+(AB ⃗⃗⃗⃗⃗ +BC ⃗⃗⃗⃗⃗ )+AB ⃗⃗⃗⃗⃗ =AC ⃗⃗⃗⃗⃗ +AB ⃗⃗⃗⃗⃗ ，∴AP ⃗⃗⃗⃗⃗ =14(AC ⃗⃗⃗⃗⃗ +AB ⃗⃗⃗⃗⃗ )，∴AP ⃗⃗⃗⃗⃗ =12AD ⃗⃗⃗⃗⃗⃗ ， ∴A ，P ，D 共线，∴PD ⃗⃗⃗⃗⃗ =12AD ⃗⃗⃗⃗⃗⃗ ， ∴S △PBC =12S △ABC =12×1=12， 故答案为：12．取BC 的中点D ，根据向量共线定理可得A ，P ，D 三点共线，继而得到S △PBC =12S △ABC ． 本题考查向量的线性运算，考查三角形面积的计算，属于基础题14.【答案】562【解析】解：∵集合U ={1,2，3，4，5}，I ={X|X ⊆U}， ∴集合I 的可能取值有25=32个，从I 中任取两个不同的元素A ，B ，基本事件总数n =C 322=496．A ∩B 中恰有三个元素，当A ∩B 确定后，如A ∩B ={3,4，5}时，可设A =A′∪{3,4，5}，B =B′∪{3,4，5}，A′∩B′=⌀， ∴{A′,B′}的情况有：{⌀,{1}}，{⌀,{2}}，{⌀,{1,2}}，{{1},{2}}，共4种，∵确定A ∩B 的方法有C 53种，∴A ∩B 中恰有三个元素包含的基本事件个数m =4×C 53=40，∴A ∩B 中恰有三个元素的概率为P =m n=40496=562．故答案为：562．集合I 的可能取值有25=32个，从I 中任取两个不同的元素A ，B ，基本事件总数n =C 322=496.A ∩B 中恰有三个元素，当A ∩B 确定后，如A ∩B ={3,4，5}时，可设A =A′∪{3,4，5}，B =B′∪{3,4，5}，A′∩B′=⌀，利用列举法求出{A′,B′}的情况有4种，由此求出A ∩B 中恰有三个元素包含的基本事件个数，由此能求出A ∩B 中恰有三个元素的概率．本题考查概率的求法，考查古典概型、列举法等基础知识，考查运算求解能力等基础知识，是基础题．15.【答案】8【解析】解：平面向量a ⃗ ，b ⃗ ，c ⃗ 满足a ⃗ ⋅b ⃗ =0，设OA ⃗⃗⃗⃗⃗ =a ⃗ ，OB ⃗⃗⃗⃗⃗⃗ =b ⃗ ，OC ⃗⃗⃗⃗⃗ =c ⃗ ，以O 为原点，OA 为x 轴，OB 为y 轴，建立直角坐标系，作矩形OADB ，根据矩形的性质CA 2+CB 2=OC 2+CD 2，|c ⃗ |=1，|a ⃗ −c ⃗ |=|b ⃗ −c ⃗ |=5，25+25=1+CD 2， 所以CD =7，由|a ⃗ −b ⃗ |=|a ⃗ +b ⃗ |=OD ≤OC +CD =1+7=8， 当O ，C ，D 共线的时候成立， 故答案为：8．建立空间直角坐标系，根据矩形的性质求出CD ，再求出最大值．本题考查向量的数乘运算，向量数量积的运算及计算公式，向量夹角的定义，考查了计算能力，属于基础题．16.【答案】(1)(3)【解析】解：设函数f(x)的定义域为(−1,1)且满足：①当x ∈(−1,0)时，f(x)>0；②f(x)+f(y)=f(x+y1+xy )，x ，y ∈(−1,1)； 令x =y =0时，整理得f(0)+f(0)=f(0)，即f(0)=0，当y =−x 时，f(x)+f(−x)=f(0)=0，所以f(−x)=−f(x)，故函数f(x)为奇函数；故(1)正确，(2)错误；对于(3)设任意的−1<x <y <1，则f(x)−f(y)=f(x)+f(−y)=f(x−y1−xy )，由于−1<x <y <1，所以|xy|=|x||y|<1，即−1<xy <1， 由于x −y <0，所以x−y1−xy <0， 又由于x−y1−xy +1=(1+x)(1+y)1−xy >0，所以−1<x−y1+xy <0，即f(x−y 1−xy )>0，所以f(x)−f(y)>0，即f(x)>f(y)，故函数f(x)在定义域(−1,1)内单调递减，故(3)正确；对于(4)对于任意的x ∈(−1,1)有|f(x)|<m ，即m >f(x)max 即可， 由于当x ∈(−1,0)时，f(x)>0，当x ∈(0,1)时，f(x)<0， 函数f(x)在(−1,1)内单调递减，所以x →−1时，f(x)→+∞，x →+1时，f(x)→−∞， 所以函数y =|f(x)|无最大值，故不存在正数m ，使得对于任意的x ∈(−1,1)有|f(x)|<m ，故(4)错误． 故答案为：(1)(3)．直接利用抽象函数的定理，利用赋值法，函数的奇偶性的判定，函数的单调性的应用判定(1)(2)(3)(4)的结论．本题考查的知识要点：函数的性质的应用，赋值法，函数的奇偶性的判定，抽象函数的定义，主要考查学生的运算能力和数学思维能力，属于中档题．17.【答案】解：(1)V A 1−D 1EF =V E−A 1D 1F =13⋅1⋅1=13.(6分)(体积公式正确3分)(2)取A 1D 1的中点G ，则FG ⊥平面A 1B 1C 1D 1，EF 在底面A 1B 1C 1D 1的射影为GE ，所求的角的大小等于∠GEF 的大小，(8分)在Rt △GEF 中tan∠GEF =√22，所以EF 与底面A 1B 1C 1D 1所成的角的大小是arctan √22.(12分)【解析】(1)由已知中棱长为2的正方体ABCD −A 1B 1C 1D 1中，E 是棱C 1D 1的中点，F 是侧面AA 1D 1D 的中心，我们利用等体积法，可得三棱锥A 1−D 1EF 的体积等于三棱锥E −D 1A 1F 的体积，分别求出其底面面积和高，代入棱锥的体积公式，即可得到答案． (2)取A 1D 1的中点G ，易得FG ⊥平面A 1B 1C 1D 1，根据线面夹角的定义可得∠GEF 即为EF 与底面A 1B 1C 1D 1所成的角的平面角，解Rt △GEF 即可得到EF 与底面A 1B 1C 1D 1所成的角的大小．本题考查的知识点是棱锥的体积，直线与平面所成的角，其中(1)的关键是利用等体积法，将求三棱锥A 1−D 1EF 的体积转化为求三棱锥E −D 1A 1F 的体积，降低运算的难度，(2)的关键是确定出∠GEF 即为EF 与底面A 1B 1C 1D 1所成的角的平面角．18.【答案】解：(1)由题意，当a =1时，可得f(x)=log 12(4x +2x −1)=−x ，x ∈[0,1]， 可得：4x +2x −1=2x ， 即4x =1 ∴x =0．当a =1，函数f(x)的准不动点为x 0=0．(2)由定义：f(x)=log 12(4x +a2x −1)=−x ，x ∈[0,1]，上有零点”， 可得：F(x)=4x +a ⋅2x −1−2x ，即F(x)=(2x )2+a ⋅2x −1−2x ，上有零点”， 且4x +a ⋅2x −1>0， 令2x =t ， x ∈[0,1]， 则t ∈[1,2]那么F(x)转化为g(x)=t 2+at −t −1，上有零点”图象是一条连续不断的曲线， 且t 2+at −1>0，(1≤t ≤2)．根据二次函数根的分布：则有{g(1)≤0g(2)≥0或{g(1)≥0g(2)≤0．解得−12≤a ≤1．要使t 2+at −1>0(1≤t ≤2)恒成立．其对称轴x =−a2，在1≤t ≤2上是递增的，当t =1时最小值， 可得a >0．综上可得实数a 的取值范围是(0,1]．【解析】(1)由题意，当a =1时，可得f(x)=log 12(4x +2x −1)=−x ，x ∈[0,1]，可得函数f(x)的准不动点．(2)依题意，“f(x)在区间D 上有不动点”当且仅当“F(x)=f(x)+x 在区间D 上有零点”，F(x)在区间[0,1]上是一条连续不断的曲线，换元法转化为二次函数问题求解准不动点，可得实数a 的取值范围．本题主要考查了函数与方程的综合运用，以及函数零点最值等有关知识，属于中档题．19.【答案】解：(1)由题中图形可知，EM⊥BC，垂足为M，设EF与AB所成的角为α，即∠MEF=α(0≤tanα≤43)，则有MF=60tanα,EF=60cosα，当景观桥EF的长为90m时，则EF=60cosα=90，解得cosα=23，所以α=arccos23，所以桥与河道所成角的大小为π2−arccos23；(2)由AE+FC=80−60tanα，所以总修建费用为y=(80−60tanα)×1+60cosα×2=80−60(sinα−2)cosα，令t=sinα−2cosα，又0≤tanα≤43，故0<α<π2，则t<0且sinα−tcosα=2，所以sin(α+φ)=√1+t2，又|sin(α+φ)|≤1，所以2≤1，解得t≤−√3，所以t的最大值为−√3，则y有最小值80+60√3，此时α=π6，所以当景观桥EF与河道沿线所成的角为π3时，矩形区域ABCD内的总修建费用最低为80+60√3万元．【解析】(1)设EF与AB所成的角为α，即∠MEF=α(0≤tanα≤43)，利用边角关系表示出EF，然后令EF=90，即可求出α的值，从而得到答案；(2)求出中修建费用的函数关系，然后利用换元法结合辅助角公式以及三角函数的有界性，求解最值即可．本题考查了三角函数在实际生活中的应用问题，考查了辅助角公式的应用以及三角函数的有界性，考查了逻辑推理能力与化简运算能力，属于中档题．20.【答案】解：(1)抛物线C：y2=4x的焦点坐标为(1,0)，则点P与抛物线C的焦点F的距离为√(4−1)2+42=5；(2)设直线l的方程为y=x+ a，把y=x+a方程代入抛物线y2=4x，可得x2+2(a−2)x+a2=0，∴x1+x2=4−2a，x1⋅x2= a2，∴|AB|=√1+k2⋅|x1−x2| =√2√(x1+x2)2−4x1x2=4√2(1−a)，点P到直线的距离d=|a|√2，∴S△PAB=12|AB|d=12×4√2(1−a)×√2=2√2，解得a=−1，∴直线l的方程y=x−1；(3)取Q(0,0)，圆(x−m)2+y2=4，切线为y=kx，由mk√1+k2=2，解得k2=4m2−4，①将直线y=kx代入抛物线方程y2=4x，解得A(4k2,4k)，B(4k2,−4k)，直线AB的方程为x=4k2，若直线和圆相切，可得|4k2−m|=2②由①②解得m=3或2(舍去)．综上可得，对任意的动点Q，直线AB与圆相切，必有m=3．下证m=3时，对任意的动点Q，直线AB和圆相切．理由如下：设Q(14a2,a)，l：x=t(y−a)+14a2，A(14y12,y1)，B(14y22,y2)，由|3−14a 2+ta|2=2，可得(a 2−4)t 2−(12a 2−6)at +(14a 2−3)2−4=0， ∴t 1+t 2=a(12a 2−6)a 2−4，t 1t 2=(14a 2−3)2−4a 2−4，又直线与曲线相交于A ，B ，由x =t(y −a)+14a 2，代入抛物线方程可得y 2−4ty +4ta −a 2=0，可得y 12=4t 1(y 1−a)+a 2，y 22=4t 2(y 2−a)+a 2，则a ，y 1是方程y 2=4t 1(y −a)+a 2的两根，即有ay 1=4t 1a −a 2，即为y 1=4t 1−a ，同理y 2=4t 2−a ． 则有A(14(4t 1−a)2,4t 1−a)，B(14(4t 2−a)2,4t 2−a)， 直线AB ：y −(4t 1−a)=22(t 2+t 1)−a(x −14(4t 1−a)2)，即为y −(4t 1−a)=4−a 24a(x −14(4t 1−a)2)，则圆心(3,0)到直线AB 的距离为 d =|4−a 24a (3−14(4t −a)2)+4t −a|√1+(24a)2，由(a 2−4)t 12−(12a 2−6)at 1+(14a 2−3)2−4=0， 代入上式，化简可得d =2|4+a 2|4+a 2=2，则有对任意的动点Q ，存在实数m =3，使得直线AB 与圆M 相切．【解析】(1)求得抛物线的焦点坐标，由两点距离公式，计算可得所求距离； (2)设直线l 的方程为y =x +a ，代入抛物线的方程，运用韦达定理和弦长公式以及三角形的面积公式，解方程可得a ，进而得到直线方程；(3)取Q(0,0)，切线为y =kx ，求得交点A ，B ，和直线AB ，由相切可得m =3，证明对任意的动点Q ，直线AB 与圆相切，必有m =3.设Q(14a 2,a)，l ：x =t(y −a)+14a 2，A(14y 12,y 1)，B(14y 22,y 2)，运用直线和圆相切的条件和韦达定理，求得AB 的方程，计算圆心到直线AB 的距离，即可得证．本题考查抛物线的方程和性质，主要考查抛物线的方程的运用，注意联立直线方程和抛物线方程，运用韦达定理，同时考查直线和圆的位置关系：相切的条件，具有一定的运算量，属于难题．21.【答案】解：(1)由题意可得，y 2=|z 1|−|x 1|，∵x 1=2，y 2=3，z 3=4， ∴|z 1|=5，z 1=±5， ∵|z 3|=|x 2|−|y 2|， ∴|x 2|−3=4，x 2=±7，又∵x 2=|y 1|−|z 1|=|y 1|−5≥−5，∴x 2=7，x 2=−7(舍去)，|y 1|=12，y 1=±12， ∴y 1，z 1 的可能取值为：y 1=12，z 1=5，y 1=12，z 1=−5， y 1=−12，z 1=5，y 1=−12，z 1=−5， (2)若x 1=1，y 1=2，设z 1=x ，则|x 2|=|y 1|−|z 1|=2−|x|，y 2=|z 1|−|x 1|=|x|−1，z 2=−1， ∵a n =max{|x n |,|y n |,|z n |}， ∴当0≤|x|<1时，a 2=2−|x|， 当1≤|x|<2时，a 2=1， 当|x|≥2时，a 2=|x|−1，又∵x 3=||x|−1|−1，y 3=1−|2−|x||，z 3=|2−|x||−||x|−1|， 当0≤|x|<1时，x 3=−|x|，y 3=|x|−1，z 3=1，即a 3=1， ∵a 3=a 2，∴|x|=1，不符合取值范围，舍去，当1≤|x|<2时，x 3=|x|−2，y 3=|x|−1，z 3=3−2|x|， a 3={2−|x|,2≤|x|<3|x|−1,1.5≤|x|<2，∵a 3=a 2，∴|x|=1，符合题意，当|x|≥2时，x 3=|x|−2，y 3=3−|x|，z 3=−1， ∵a 3=a 2，∴|x|=2，符合题意，综上所属，z 1 的所有取值是−2，−1，1，2，(3)证明：运用反证法，假设对任意正整数k ≥3，x k ，y k ，z k 都不为0， ∵x 1，y 1，z 1是非零整数，且|x 1|，|y 1|，|z 1|互不相等， 又∵假设对任意正整数k ≥3，x k ，y k ，z k 都不为0， ∴对任意k ≥1，a k 为正整数，当k≥1时，|x k+1|=||y k|−|z k||<max{|y k|,|z k|}≤a k，同理可得|y k+1|<a k，|z k+1|< a k，∴a k+1=max{|x k+1|,|y k+1|,|z k+1|}<a k，∴{a k}严格单调递减，∵a2为有限正整数，∴∃m≥3，使得a m≤0，与假设矛盾，∴存在正整数k≥3，使x k，y k，z k至少有一个为0，假设x k=0，且x1≠0，x2≠0，⋅⋅⋅，x k−1≠0，∵x n+1=|y n|−|z n，x k=0，∴|y k−1|=|z k−1|，且|y k−1|=|z k−1|≠|x k−1|，否则，若|y k−1|=|z k−1|=|x k−1|，∵x n+1=|y n|−|z n|，y n+1=|z n|−|x n|，z n+1=|x n|−|y n|，∴当n=k−2时，x k−1+y k−1+z k−1=0，∴x k−1=y k−1=z k−1=0，与假设矛盾，∴y k=|z k−1|−|x k−1|≠0，z k=|x k−1|−|y k−1|≠0，又∵|y k−1|=|z k−1|，∴y k=−z k，∵x n+1=|y n|−|z n|，y n+1=|z n|−|x n|，z n+1=|x n|−|y n|，x k=0，∴x k+1=0，y k+1=|z k|，z k+1=−|y k|=−|z k|，依次递推可得，对任意n≥k，x n=0，y n+1=|z k|，z n+1=−|z k|，且z k≠0，有且只有一个数列自第k项起各项均为0．【解析】(1)将特殊值代入已知条件，即可求解，(2)设z1=x，根据已知条件，可得a n的表达式，再结合x的取值范围，即可求解，(2)根据已知条件，运用反证法，即可求解．本题考查了数列的综合应用，考查了分类思想，需要较强的综合能力，难度系数大，属于难题．。

上海浦东新东建平中学2019-2020学年高三上学期10月语文试题注意事项：1．答题前填写好自己的姓名、班级、考号等信息；2．请将答案正确填写在答题卡上。

一、情景默写1．按要求填空。

（1）无求生以害仁，_____________________。

（《论语·______________》）（2）________________，献愁供恨，玉簪螺髻。

（辛弃疾《水龙吟·登建康赏心亭》）（3）朱自清《松堂游记》：好了，月亮上来了，却又让云遮去了一半，老远的躲在树缝里，像个乡下姑娘，羞答答的。

从前人说“_________________，________________”，真有点儿！（白居易《琵琶行》）二、语言表达2．按要求选择。

（1）碰到曾经见过面，但认识不深的人时，有下列四种打招呼的方式，不恰当．．．的一项是（）A．“你好，你还记得我吗？”B．“你好，我是XXX，你还记得我吗？”C．“你好，我是XXX，真高兴，我们又见面了。

”D．“你好，我是XXX，真高兴，你不会不记得我了吧？”（2）罗董事长的三位朋友分别在今天过七十大寿、乔迁新居、分店开幕。

如果你是董事长的秘书，下面三幅对联该如何送才恰当，请选择恰当的一项（）（甲）大启而宇，长发其祥（乙）交以道接以礼，近者悦远者来（丙）室有芝兰春自永，人如松柏岁长新A．甲送乔迁新居者；乙送分店开幕者；丙送过七十大寿者B．甲送分店开幕者；乙送乔迁新居者；丙送过七十大寿者C．甲送过七十大寿者；乙送乔迁新居者；丙送分店开幕者D．甲送过七十大寿者；乙送；丙送乔迁新居者分店开幕者三、现代文阅读阅读下文，完各题。

思想的空间①思想需要空间，这是我在多年阅读以后忽然领悟的道理。

尽管孔夫子早已说过“学而不思则罔”，叔本华也教导我们“不要让自己的头脑成为别人思想的跑马场”，但背名言是一回事，明晰其中的道理又是一回事。

处在信息爆炸的时代，我们真的感到了为信息所驱使、所淹没的苦恼；读也读不完的书，看也看不完的报，使我们整天手不释卷，疲于奔命，依然欠下一屁股书债。

2019-2020学年上海市建平实验中学高三英语上学期期末试卷及参考答案第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项ALocated in the beautiful Sichuan Basin, Chongqing is a magical 8D city. The natural history and cultural scenery of the area provide children with learning opportunities because they can enjoy the many wonders of this area.Fengjie Tiankeng Ground JointTiankeng Diqiao Scenic Area is located in the southern mountainous area of Fengjie County. The Tiankeng pit is 666 meters deep and is currently the deepest tiankeng in the world. The scenic spot is divided into ten areas including Xiaozhai Tiankeng, Tianjingxia Ground, Labyrinth River, and Longqiao River. There are many and weird karst cave shafts, and countless legends haunt them.Youyang Peach GardenYouyang Taohuayuan Scenic Area is a national forest park, a national 5A-level scenic spot, and a national outdoor sports training base. Located in the hinterland of Wuling Mountain. The Fuxi Cave in the scenic spot is about 3,000 meters long, with winding corridors, deep underground rivers, and color1 ful stalactites. The landscape is beautiful.Jinyun Mountain National Nature ReserveJinyun Mountain is located in Beibei District of Chongqing City, about 45 kilometers away from the Central District of Chongqing City. The nine peaks of Jinyun Mountain stand upright and rise from the ground. The ancient trees on the mountain are towering, the green bamboos form the forest, the environment is quiet, and the scenery is beautiful, so it is called "Little Emei". Among them, Yujian Peak is the highest, 1050 meters above sea level; Lion Peak is the most precipitous and spectacular, and the other peaks are also unique.Chongqing People's SquareChongqing's Great Hall of the People, one of the landmarks of Chongqing, gives people the deepest impression than its magnificent appearance resembling the Temple of Heaven. It also uses the traditional method of central axis symmetry, with colonnade-style double wings and a tower ending, plus a large green glazed roof, large red pillars, white railings, double-eave bucket arches, and painted carved beams.1.How deep is the Tiankeng Ground Joint?A.666mB.3,000mC.45kmD.1050m2.Which of the following rocks can you see in Youyang Peach Garden?A.LimestoneB.StalactiteC.MarbleD.Quartzite3.Which attraction is closest to downtown Chongqing?A.Fengjie Tiankeng Ground JointB.Jinyun Mountain National Nature ReserveC.Chongqing People's SquareD.Youyang Peach GardenBWho is a genius? This question has greatly interested humankind for centuries.Let's state clearly: Einstein was a genius. His face is almost the international symbol for genius. But we want to go beyond one man and explore the nature of genius itself. Why is it that some people are so much more intelligent or creative than the rest of us? And who are they?In the sciences and arts, those praised as geniuses were most often white men, of European origin. Perhaps this is not a surprise. It's said that history is written by the victors, and those victors set the standards for admission to the genius club. When contributions were made by geniuses outside the club—women, or people of a different color1 or belief—they were unacknowledged and rejected by others.A study recently published bySciencefound that as young as age six, girls are less likely than boys to say that members of their gender(性别)are “really, really smart.” Even worse, the study found that girls act on that belief: Around age six they start to avoid activities said to be for children who are “really, really smart.” Can our planet afford to have any great thinkers become discouraged and give up? It doesn't take a genius to know the answer: ly not.Here's the good news. In a wired world with constant global communication, we're all positioned to see flashes of genius wherever they appear. And the more we look, the more we will see that social factors(因素)like gender, race, and class do not determine the appearance of genius. As a writer says, future geniuses come from those with “intelligence, creativity, perseverance(毅力), and simple good fortune, who are able to change the world.”4. Whatdoes the author think of victors' standards for joining the genius club?A. They're unfair.B. They're conservative.C. They're objective.D. They're strict.5. What can we infer about girls from the study inScience?A. They think themselves smart.B. They look up to great thinkers.C. They see gender differences earlier than boys.D. They are likely to be influenced by social beliefs6. Why are more geniuses known to the public?A. Improved global communication.B. Less discrimination against women.C.Acceptance of victors' concepts.D. Changes in people's social positions.7. What is the best title for the text?A. Geniuses Think AlikeB. Genius Takes Many FormsC. Genius and IntelligenceD. Genius and LuckCA student had to get his long hair cut off in a middle school in GuangDong Province. It was talked a lot among teachers and students.In fact, all schools have their own rules. In most schools, boy students are not allowed to have long hair while girls are not allowed to dye their hair. And most school rules say that students should wear their school uniforms at school. And students must obey these rules so that they can get healthy development at school.But some students have disagreements. They think that boy students having long hair doesn't mean that they are not good students. They want to show their own personality. They think that they would look cool too if they had long hair and the hairstyles like their favorite stars.A girl student thought that she would look much more beautiful if she had brown hair. So she had her dark hair dyed brown one day. When she went back to school the next day, the teacher was very angry with her. She said that she worked hard at her lessons and did well in every subject. She just didn't know why the teacher didn't allow her to dye her hair while women teachers can.It is not wrong for teenagers to love stars' hairstyles or wear their favorite clothes. However, a school has its own rules for all the students to obey so that the school can be in good order. Students should not break the rules at school.8. What aren't boy students allowed to do in most middle schools according to this passage?A. To have long hair.B. To wear uniforms.C. To like famous stars.D. To show their own personalities.9. Why did the girl make her hair brown?A. Because she wanted to be cool.B. Because she thought that she would look much more beautiful.C. Because she wanted to make her teacher angry.D Because women teachers dyed their hair.10. What does the writer think of these school rules?A. The students should be against them.B. They are bad for students.C. They can make schools in good order.D. They can't make students grow healthily.11. What is the passage mainly about?A. Hair styles and clothes.B. Schoolboys and schoolgirls.C. Students and famous stars.D. School rules.DResearchers say spicy tomatoes could soon be on the menu thanks to the rise of gene-editing technology.It's not the first time that experts have claimed techniques could develop fruit with unusual features: scientists have already been looking at changing the color1 of kiwi fruit and bettering the taste of strawberries.But researchers inBrazilandIrelandsay such methods could also offer practical advantages, with hot tomatoes offering a new way of harvesting the pungent chemicals found in peppers known as capsaicinoids, which make food taste “hot”.“Capsaicinoids are valuable. They are used as painkillers and there are some researches showing that they promote weight loss,” said Agustin Zsogon from a Brazilian university, a co-author of a new article arguing for the benefits of engineering hot tomatoes.Writing in the journal Trends in Plant Science, the researchers say peppers are difficult crops to grow and low productive. Worse still, it is tricky to keep the pungency of the fruits table. By contrast, tomato production is high and the plant is well-studied. “You could produce the capsaicinoids in a more cost-effective manner,” said Zsogon.Tomatoes and peppers developed from a common ancestor, but separated about 19 million years ago. “Allthese genes to produce capsaicinoids exist in the tomato, they are just not active,” said Zsogon. “Using gene-editing technology, it is likely to switch these genes back on in tomatoes, making the fruit more special”, he said.12. Why are the tomatoes made hot by the researchers?A. To test the gene-editing technologyB. To improve the amount of the tomatoesC. To explore ways to harvest more capsaicinoids.D. To make the tomatoes more delicious.13. For what purpose can capsaicinoids be used according to the text?A. To put on weight.B. To ease the pain.C. To improve sleep.D. To better the look.14. What is Zsogon's attitude to the gene-editing technology?A. Confident.B. Critical.C. Anxious.D. Doubtful.15. What's the main idea of the text?A. An introduction to gene-editing plants.B. Creating hot tomatoes by gene-editing.C. Problems with capsaicinoid production.D. The procedure of producing capsaicinoids.第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。