VB书本实验5答案

第二部分综合练习理论练习一一单选1-5 CDCCB 640ABDCD 11-15 CCBBD 16-20 DBCBA二多选1 ABCE 2CE 3 BCE 4 ADE 5 ABCD6ABCDE 7ACD8ABCDE 9 ABC 10ABCDE三判断1-5 X V X V V6-10 V X V V V四填空1 x=int(Rnd*101)End If avg=s/82 i=l to 10Right(str(i),l)或Right(str(i mod 10))3 m*n/GCD(m,n)GCD(b, a mod b)4 Exit For i & “是素数”Next i五阅读程序1-4 DDCB六程序设计1Option Base 1Private Sub Form_click()Dim a( 10)Ciscreatedata a()sort a()Fori= ITo 10Print a(i);Next iEnd SubSub createdata(a())Fori = ITo 10a(i) = Int(Rnd * 101)Next iEnd SubSub sort(a())For i = 1 To 9Forj = 1 To 10-iIf a(j) > a(j + l)Thent = a(j): a(j) = a(j + 1): a(j + 1) = tEnd IfNext jNext iEnd Sub2Private Type ksno As String * 8Bscj As IntegerSjcj As IntegerEnd TypeDim student As ksPrivate Sub Form_Load()Open "c:\ksxx.dat" For Random As#l Len = Len(student)End SubPrivate Sub cmdadd_Click()student.no = Text 1.Textstudent.Bscj = Val(Text2.Text)student.Sjcj = Vai (Tex t3.Text)lastrecord = LOF( 1) / Len(student) + 1Put # 1, lastrecord, studentTextl.Text =Text2.Text = ””Text3.Text ="End SubPrivate Sub cmdquit_Click()Close #1EndEnd Sub1-5 CABCD理论练习二6-10 ABCCD 11-15 BBBAB1 CD2 AD3CE4BC6BCDE7CDE8ABCDE9 ABD三判断二多选1-5 X X X X V 6-10 V V V X X 16-20 DBAAC5 AD10ACDE1n-l 或者Sqr (n)02X y3 1 to 102*i-14Button=2start=True 五阅读程序1-5DBDAB六程序设计1Private Sub Form_click()四填空japan = 47528china = 22257n = 0 True — (x, y)Do While china <= japanchina = china * 1.098japan = japan * 1.028 n= n + 1LoopPrint n & ”年之后，中国GDP将超过日本”End Sub•VB6中的Split函数，其功能足将一字符巾用分界符分割为一字符串数组。

计算机VB实验内容实验二1. 《实践指导》P10，实验1，设计一个加法器程序（请参考本次实验中实例2）。

（程序实际运行效果可参考程序“Prg3.exe” ）保存要求：(1)在lab02文件夹中新建子文件夹“prg3”，用于保存本题的程序；(2)将本题的工程文件命名为“project3.vbp”，窗体文件命名为“form3.frm”。

注：该题的第5项要求中关于“同时第一个文本框获得焦点”部分不要求实现过程Private Sub Command1_Click()Dim a As Single, b As Single, c As Singlea = Val(Text1.Text)b = Val(Text2.Text)c = a + bLabel2 = cEnd SubPrivate Sub Command2_Click()Text1.Text = ""Text2.Text = ""Label2 = ""End Sub2. 编写一个标签变化程序（请参考本次实验中实例题1来完成，如下图1所示）（程序实际运行效果可参考程序“Prg4.exe” ）保存要求：(1)在lab02文件夹中新建子文件夹“prg4”，用于保存本题的程序；(2)将本题的工程文件命名为“project4.vbp”，窗体文件命名为“form4.frm”。

设计要求：(1)单击窗体（Form1），则窗体打印输出文字“你点击了窗体”（如下图2所示）(2)单击按钮Command1，则在Label1中显示“你点击了按钮Command1，请进入”，字体大小15磅，字体为宋体（如下图3所示）(3)单击按钮Command2，Label1显示“你点击了按钮Command2，请离开”，字体大小25磅，字体为黑体（如下图4所示）（图1）（图2）（图3）（图4）过程Private Sub Command1_Click()Label1.FontSize = 15Label1.FontName = "宋体"Label1 = "你点击了按钮Command1，请进入"End SubPrivate Sub Command2_Click()Label1.FontSize = 25Label1.FontName = "黑体"Label1 = "你点击了按钮Command2，请离开"End SubPrivate Sub Form_Click()Form1.Print "你点击了窗体"End Sub实验三二、设计题1．《实践指导》P20，实验3。

实验报告参考答案（本部）实验一VB集成开发环境实验内容（3）：四、设计流程①界面设计：在窗体上画一个标签。

②属性设置：标签的width设为2000，height设为300。

有边框是BordStyle设为1，背景透明是BackStyle设为0。

显示“等级考试”是将caption设为“等级考试”，居中是将Alignment设为2。

③代码设计：无五、关键代码（注意：解题方法有多种，其它方法只要能完成实验任务也是正确的）无六、调试和测试结果至少要写测试结果正确，如果写了调试中出现的典型问题及解决方法，分数给高些实验二简单的VB程序设计实验内容（3）：四、设计流程①界面设计：在窗体上画一个标签、一个命令按钮。

②属性设置：固定边框是BordStyle设为1，背景透明是BackStyle设为0。

③代码设计：分别在3个事件过程form_load()，form_click(),Cmd1_click()中编程。

其中图片从网上下载，与工程文件、窗体文件保存在同一目录，代码中使用相对路径app.path。

五、关键代码（注意：解题方法有多种，其它方法只要能完成实验任务也是正确的）Private Sub Form_Load()Form1.Picture = LoadPicture(App.Path + "\tu.jpg")Form1.Caption = "我的变化"End SubPrivate Sub Form_Click()LBL1.Top = 0LBL1.Left = 0End SubPrivate Sub Cmd1_Click()Cmd1.Height = 1500Cmd1.Width = 2000End Sub六、调试和测试结果至少要写测试结果正确，如果写了调试中出现的典型问题及解决方法，分数给高些实验三数据类型及其运算四、设计流程①界面设计：在窗体上画1个文本框、1个标签、6个命令按钮。

<大学程序设计基础-Visual Basic>教材课后习题答案第1章一、选择题1 2 3 4 5 6 7B D BC B B D第2章一、选择题1 2 3 4 5 6 7 8 9 10B C B C B C A A A A11 12 13 14A B A A二、填空题1.rem或’ _ ：2.“” # #3.5x2-3x-2sinA/34.3214565.300三、操作题1、程序段：Private Sub Command1_Click()Dim x As Integer, y As IntegerDim s As Long, c As Longx = Text1.Texty = Text2.Texts = x * yc = (x + y) * 2Label3.Caption = "长方形的面积为" + Str(s)Label4.Caption = "长方形的周长为" + Str(c)End Sub3、程序段：Private Sub Command1_Click()Text1.Text = "第一"End SubPrivate Sub Command2_Click()Text1.Text = "第二"End Sub4、程序代码：Private Sub Text1_Change()Text1.MaxLength = 10End Sub5、程序代码：Private Sub Text1_Click()Text1.SelStart = 0Text1.SelLength = Len(Text1.Text)End Sub第3章一、选择题1 2 3 4 5 6 7D A D B A D B二、填空题1. False2.B^2-4*a*c else三、操作题1．从键盘输入三个值，判断它们能否构成三角形的三个边。

如果能构成一个三角形，则计算三角形的面积。

沈阳师范大学面向对象程序设计实验报告实验题目实验五数组和自定义类型学号姓名刘丽年级10级指导教师王飞提交时间10.24一、实验目的（1）掌握数组的声明、数组元素的引用。

（2）掌握固定长度数组和动态数组的使用差别。

（3）掌握数组常用的操作和常用算法。

（4）掌握列表框和组合框的使用。

（5）掌握自定义类型及数组的使用。

二、实验内容及要求（1）完成课堂讲授的两个示例例5.1和例5.4。

（2）完成实验E第1实验内容（教材p272）。

（3）完成课堂讲授的实例5.10和5.13（教材p113和教材p118）。

（4）完成实验E第7实验内容（教材p273）。

三、实验分析与设计例5.1 计算一个班100个学生的平均成绩，然后统计高于平均分的人数。

步骤1 启动VisualBasic6.0，创建一个“标准EXE”类型的应用程序，步骤2 设计界面：不需添加控件如图所示：步骤3 设置控件属性。

步骤4 事件及编程，如下所示：窗体事件Private Sub Form_Click()Dim mark(1 To 100) As IntegerDim aver!, n%, i%aver = 0For i = 1 To 100mark(i) = InputBox("输入第" & i & "位学生的成绩")aver = aver + mark(i)Next iaver = aver / 100n = 0For i = 1 To 100If mark(i) > aver Then n = n + 1Next iPrint "平均分：", aver, "高于平均分的人数：", nEnd Sub步骤5 单击“运行”按钮运行程序，若程序运行有错，则进入代码窗口中调试。

步骤6 保存文件，生成可执行文件。

例5.4 求一维数组中各元素之和、最小数组元素，并将最小数组元素与数组中第一个元素交换。

第一章VB开发环境与VB概述习题答案习题一、选择题第二章常用控件与界面设计习题答案习题一、选择题第三章实验与习题实验实验3_1…算术运算Private Sub Command1_Click()Const a As Single = 3, b As Single = 2, c As Single = -1, d As Single = 6Dim x As Single, y As Single, z As Single, m As Singlex = 2: y = 1: z = 1: m = 1List1.ClearList1.AddItem a / (b + c / b)List1.AddItem (x + Sqr(x ^ 2 + 1)) ^ (1 / 3)List1.AddItem ((2 * y) / (a * x + b * y) * (a * x - b * y))List1.AddItem 1 + 1 / (1 + 1 / m)List1.AddItem 1 / 2 * (d / 3) ^ (2 * x)List1.AddItem Log(y + Cos(x) ^ 2)List1.AddItem Abs((Exp(x) + Sin(x) ^ 3) / (x + y))List1.AddItem Log((Exp(x * y) + Abs(1 / Tan(z) + Cos(x) ^ 3)) / (x + y - z))List1.AddItem Sin(45 * 3.1415 / 180) + (Exp(10) + Log(10)) / Sqr(x + y + 1) List1.AddItem Log(a) / Log(b)End Sub…关系运算Private Sub Command2_Click()List1.ClearList1.AddItem Mid("Visual Basic", 1, 12) = Right("Language Visual Basic", 12) List1.AddItem "ABCRG" >= "abcde"List1.AddItem Int(134.69) >= CInt(134.9)List1.AddItem 78.9 / 32.77 <= 97.5 / 43.87 And -45.4 > -4.98List1.AddItem Str(32.345) = CStr(32.345)End Sub…逻辑运算Private Sub Command3_Click()Dim x As Integer, y As IntegerDim C1 As Integer, C2 As Integer, C3 As IntegerC1 = 70: C2 = 80: C3 = 90x = 9: y = -2List1.ClearList1.AddItem x + y < 10 And x - y > 0List1.AddItem (x% >= 0 And y% >= 0) Or (x% < 0 And y% < 0)List1.AddItem x = 0 Xor y = 0List1.AddItem C1 + C2 + C3 >= 255 Or C1 > 90 And C2 > 90 And C3 > 80End Sub实验3_2略实验3_3略实验3_4…零售结算Private Sub Command1_Click()Dim dj As Single, sl As Single, je As Single, n As IntegerLabel1.Caption = "金额："dj = InputBox("请输入商品的单价：", "单价框")sl = InputBox("请输入商品的数量：", "数量框", 1)je = dj * sln = MsgBox("共计金额=" & je, vbOKCancel + vbInformation, "结果") If n = vbOK Then Label1.Caption = "金额：" & Str(je) & "元"End Sub…产生随机数Private Sub Command2_Click()Dim m As Integer, n As IntegerDim x1 As Integer, x2 As Integer, x3 As Integerm = V al(Text1.Text): n = Text2.TextRandomizex1 = Int(Rnd * (n - m + 1) + m)x2 = Int(Rnd * (n - m + 1) + m)x3 = Int(Rnd * (n - m + 1) + m)Label4.Caption = "结果为：" & Str(x1) & Str(x2) & Str(x3)End Sub…求逆序数Private Sub Command3_Click()Dim a As Integer, h As Integer, t As Integer, n As IntegerRandomizea = Int(Rnd * (999 - 100 + 1) + 100)h = Mid(CStr(a), 1, 1)t = Mid(CStr(a), 2, 1)n = Right(CStr(a), 1)Label5.Caption = a & "-->" & Format(n * 100 + t * 10 + h, "000")End Sub实验3_5略习题选择题填空题1、2 -32768~327672、整型长整型单精度双精度3、0 False “”4、Chr(Int(Rnd*(Asc(“L”)-Asc(“C”))+Asc(“C”)))x>0 And y>0 Or x<0 And y<0c>=”a” And c<=”z” Or c>=”A” And c<=”Z”x>=10 And x<20x<z Xor y<z5、False2TrueFalseTrueTrueTrueTrue6、18820010068.568765547、a=1 b=1a=2 b=1a=3 b=1a=4 b=18、Y Mod 4=0 And Y Mod 100<>0 Or Y Mod 400 =09、He Said, “Good morning”.10、EDEF11、(A>0 And A<>Int(A)) And (B<0 And B<>Int(B))12、a+b+c+d(a+b+c+d)/4sumaver13、(f-2*h)/2(4*h-f)/2简答题1、略2、Private Sub Form_Click()Const g = 9.8Dim V0 As Single, t As SingleDim S As SingleV0 = InputBox("请输入V0的值：")t = InputBox("请输入时间t的值：")S = (1 / 2) * g * t ^ 2 + V0 * tMsgBox ("位移量为：" & S)End Sub3、Private Sub Command1_Click()Dim l As Single, w As Single, h As SingleDim s As Singlel = Text1.Textw = Text2.Texth = Text3.Texts = (l * w + l * h + w * h) * 2Label1.Caption = sEnd Sub第四章选择分支与循环实验答案实验4-1方法一：x<=5 ; y方法二：Is<=2 ;Case Else实验4-2Shape1.BackColor=vbRed;Inter=15;Inter=Inter-1;Inter;实验4-3b<cb=aa=k实验4-4方法二：s*n ; t/s<10^-5实验4-5方法一:m>=10^-4 ; (-1)^(n+1)*m实验4-6x2=x3 ; <10^-6实验4-7实验4-8i+2*j+5*k=10 ; n实验4-9题目一：a) 5b)i=16 p=12 n=5c)i=9 p=8 n=1题目二：120 10实验4-10N=1 ；S=N& "*3 " & "+1 "实验4-11Len(st); Ch=Lcase(ch) ; Case Else ; Mid(Char,I,1)&St实验4-12i\100 ; (i Mod 100)\10习题一、选择题二、填空题1．Is=0 ; 1 To 10 ; Is >102. 93. 3 ; 4 154. this is a book ;This Is A Book5. 3 ; 3 ; 3 56. 32 07. 48. 15 19. 1 ; 401 ;10410. 1 2 3 ;1 3; 111. (3)12. 2 0 2413. 10 1414. BAABC CBAABC15. X Mod P=0 ; X=X+1 ;Find=False16. abs(t)<10^(-7) ; s+t17. Mid(n,1,1)=Mid(n,2,1) And Mid(n,3,1)=Mid(n,4,1)S=S+118. Mid(n,i,1)>Mid(n,i+1,1)19. "输入n";N/I=0 ;Print I第五章数组实验5_1Int(90 * Rnd) + 10a(i) = a(21 - i)a(21 - i) = t5_2k = x Mod 10i = i + 15_3s5_4max < a(i, j)row = Icol = j5_51ReDim Preserve prime(m)prime(j)5_6d Mod 25_7Exit Fora(j + 1) = a(j)5_8N – IA(j) = A(j + 1)5_9A(i, 1)JMin = MaxNot Flag5_10ch >= "0" And ch <= "9"P = P & chReDim Preserve C(k)5_11Private Sub Form_Click()Dim x As Integer, i As Integer, k As Integer, j As Integer Dim a() As Integerx = InputBox("输入正整数x=")i = 2Print x; "的质因子为:";Do While x >= iIf x Mod i = 0 Thenk = k + 1ReDim Preserve a(k)a(k) = ix = x \ iElsei = i + 1End IfLoopFor j = 1 To UBound(a)Print a(j);Next jEnd Sub习题一选择题二填空题1.V ariant2.ReDim A(N)A(1)If M < A(I) Then M = A(I)3.Int(26 * Rnd) + 65Chr(t)i + 1 To 10A(i) > A(j)4.InStr(s, ",")Right(s, Len(s) - n)s5. 4 5 66 5 43 2 16.T – 1I + 17.k = 6 - i – jmax = m8.j = aj = j - 39.i + 1i = i + 110. 237三编程题1．Option ExplicitOption Base 1Private Sub Command1_Click()Dim a(10) As IntegerDim i As Integer, max As IntegerFor i = 1 To 10a(i) = Int(90 * Rnd) + 10Print a(i);Next iPrinti = 1max = 0Do While i <= 10If a(i) Mod 3 = 0 ThenIf a(i) > max Thenmax = a(i)End IfEnd Ifi = i + 1LoopIf max = 0 ThenPrint "无要找的数"ElsePrint max & "是最大的能被3整除的数"End IfEnd Sub2．Option ExplicitOption Base 1Private Sub Command1_Click()Dim A() As IntegerDim I As Integer, m As IntegerDim K As IntegerReDim A(10)For I = 1 To 10A(I) = IPrint A(I);Next IPrintm = InputBox("ÊäÈëm")K = 9 + mReDim Preserve A(K)For I = 11 To KA(I) = A(I - 10)Next IFor I = 1 To 10A(I) = A(I + m - 1)Next IFor I = 1 To 10Print A(I);Next IPrintEnd Sub3．Option ExplicitPrivate Sub Command1_Click()Dim I As Integer, J As Integer, K As IntegerDim a() As Integer, n As Integer, p As IntegerDim s As String, Flag As Booleanp = 1For K = 10 To 100I = 1Do While I <= 10 And Not FlagJ = 1Do While J <= 10 And Not Flagn = I ^ 2 + J ^ 2If n = K ThenFlag = TrueReDim Preserve a(p)a(p) = Kp = p + 1s = I & Str(J) & Str(K)List1.AddItem sEnd IfJ = J + 1LoopI = I + 1LoopFlag = FalseNext KEnd Sub4．Option ExplicitPrivate Sub Command1_Click()Dim A(10) As IntegerDim B(10) As Integer, S As StringDim I As Integer, J As Integer, X As IntegerA(1) = Int(90 * Rnd) + 10S = A(1)For I = 2 To 10DoX = Int(90 * Rnd) + 10For J = 1 To I - 1If X = A(J) Then Exit ForNext JIf J = I ThenA(I) = XS = S & " " & A(I)Exit DoEnd IfLoopNext IText1.Text = SB(1) = Int(90 * Rnd) + 10S = B(1)For I = 2 To 10DoX = Int(90 * Rnd) + 10For J = 1 To I - 1If X = B(J) Then Exit ForNext JIf J = I ThenB(I) = XS = S & " " & B(I)Exit DoEnd IfLoopNext IText2.Text = SS = ""For I = 1 To 10For J = 1 To 10If A(I) = B(J) ThenS = S & " " & A(I)End IfNext JNext IText3.Text = SEnd SubPrivate Sub Command2_Click()Text1.Text = ""Text2.Text = ""Text3.Text = ""Text1.SetFocusEnd Sub5．Option ExplicitPrivate Sub Command1_Click()Dim I As Integer, J As IntegerDim a() As Integer, K As Integer, Sum As Integer K = V al(Text1.Text)I = 1DoJ = K Mod 10ReDim Preserve a(I)a(I) = JSum = Sum + JK = K \ 10I = I + 1Loop Until K = 0Text2.Text = SumEnd Sub6．Option ExplicitPrivate Sub Command1_Click()Dim a(100, 2) As Integer, K As IntegerDim I As Integer, J As IntegerDim M As Integer, N As IntegerK = 1For I = 1 To 99For J = 1 To 99If I > J ThenM = I - JN = I + JIf Sqr(M) = Int(Sqr(M)) And Sqr(N) = Int(Sqr(N)) ThenList1.AddItem I & " " & Ja(K, 1) = Ia(K, 2) = JK = K + 1End IfEnd IfNext JNext IEnd Sub第六章参考答案实验实验6-11、Exit Do2、Y(X)3、X >= -1实验6-2【题目二】42 、26、8实验6-31、s1, key2、s As String3、ch >= "a" And ch <= "z"4、Mid(s, i, 1) = Chr(Asc(ch) + k - 26)思考：解密函数Private Sub dec(s As String, k As Integer) '解密过程Dim i As Integer, ch As String * 1For i = 1 To Len(s)ch = Mid(s, i, 1)If "A" <= ch And ch <= "Z" ThenIf Asc(ch) - k < Asc("A") ThenMid(s, i, 1) = Chr(Asc(ch) - k + 26) '小于A的ASCII值则加上26 ElseMid(s, i, 1) = Chr(Asc(ch) - k)End IfElseIf ch >= "a" And ch <= "z" Then '多分支格式，ch介于小写a与z之间If Asc(ch) - k < Asc("a") ThenMid(s, i, 1) = Chr(Asc(ch) - k + 26) '小于a的ASCII值则加上26ElseMid(s, i, 1) = Chr(Asc(ch) - k)End IfEnd IfNext iEnd Sub实验6-41、b() As Integer, st As String2、L <= R3、ReDim Preserve b(R)4、L = L + 1辗转相除法求最大公约数函数Private Function Gcd(ByV al p As Integer, ByV al q As Integer) As IntegerDim r As Integerr = p Mod qDo While r <> 0p = qq = rr = p Mod qLoopGcd = qEnd Function实验6-5【题目一】age = age(n - 1) - 3【题目二】1、(Left + Right) / 22、Left = Mid + 1实验6-61、3 -12、7 43、3 -14、7 0实验6-7【题目一】1、Sqr(2 + t)2、Abs(a - 1) < eps【题目二】1、Dim X As Integer2、"S(" & I & ")=" & S(I)3、(j * i + 1)习题参考答案一选择题二、填空1（1）形式、（2）实在2（1）按地址传递、（2）ByV al3（1）窗体模块、（2）标准模块、（3）类模块4（1） 65（1）4 20 1016（1） 6 26 、（2）-2 987（1）10 6 、（2） 5 -58（1） 6 5 、（2）8 79（1）11 、（2）710（1）Fun(i) 、（2）Fun=p11（1） 4 、（2）20.712（1）29 、（2）28.713（1）k = j 、（2）b() As Integer14（1）gec 、（2）ge 、（3） 315（1）p1 = True And p2 = True 或p1 And p2 、（2）p1 = p2 – 2 、（3）Isp = True 、（4）m Mod i = 016（1）Convert(st) 、（2）Len(s) 、（3）"A" To "F" 、（4）k = k + p * h17（1）isualVi 、（2）sualV isu18（1）s + a 、（2）n + 1 、（3）x As Single, n As Integer 、（4）p * (x + i) / ((2 * i - 1) * i * x) 三、改错题1、Option Base 1Private Sub Command1_Click()Dim A() As Integer, I As Integer, J As Integer, Logic As BooleanDim K As IntegerReDim A(1)A(1) = 50————————'K=1For I = 51 To 149K = 1 '位置错Logic = FalseCall Sub1(A, I, Logic)If Logic ThenK = K + 1ReDim A(K) 'ReDim Preserve A(K)A(K) = IEnd IfNext IFor I = 1 To UBound(A)Text1 = Text1 & Str$(A(I))If I Mod 5 = 0 Then Text1 = Text1 & vbCrLfNext IEnd SubPrivate Sub Sub1(A() As Integer, N As Integer, F As Boolean)Dim I As Integer, J As Integer, Ub As IntegerUb = UBound(A)For I = 1 To UbFor J = 2 To A(I)If A(I) Mod J = 0 And N Mod J = 0 ThenExit For 'Exit SubEnd IfNext JF = TrueNext IEnd Sub2、Option ExplicitOption Base 1Private Sub Command1_Click()Dim I As Integer, Flg As Boolean, S1 As Integer, S2 As IntegerDim J As Integer, K As Integer, P() As IntegerReDim P(1)P(1) = 2For I = 3 To 150 Step 2For J = 2 To Sqr(I)If I Mod J = 0 Then Exit ForNext JIf J > Sqr(I) ThenReDim Preserve P(UBound(P) + 1)P(UBound(P) + 1) = I 'P(UBound(P)) = IEnd IfNext IFor I = 80 To 125If fun(I, P, S1, S2) Then 'If fun(I, P, S1, S2)Text1 = Text1 & Str$(I) & "=" & Str(S1) & "*" & Str$(S2) & vbCrLf End IfNext IEnd SubPrivate Function fun(N As Integer, P() As Integer, S1 As Integer, S2 As Integer) As Boolean Dim I As Integer, J As IntegerFor I = 1 To UBound(P)For J = 1 To UBound(P) - 1If N = P(I) * P(J) ThenS1 = P(I)S2 = P(J)'fun = TrueExit Functionfun = True '位置错End IfNext JNext IEnd Function3、Option ExplicitPrivate Sub Get_Chess(Chess() As Integer, idx As Integer, Over As Integer) 'ByV al idx As IntegerDim Ub As Integer, Counter As Integer, K As IntegerUb = UBound(Chess)Chess(idx) = 0Counter = 1K = 0 '位置错Do Until Counter = Ub - 1Do Until K = 2idx = idx + 1If idx > Ub Then idx = 1K = K + Chess(idx)LoopChess(idx) = 0Counter = Counter + 1LoopFor Over = 1 To UbIf Chess(Over) <> 0 Then Exit ForNext OverEnd SubPrivate Sub Command1_Click()Dim Chess(32) As Integer, I As Integer, J As IntegerDim K As Integer, idx As IntegerFor I = 1 To 32For J = 1 To 32Chess(J) = 1Next JCall Get_Chess(Chess, I, K)If K = 23 ThenText1 = "从第" & Str$(I) & "号棋子开始取"Exit ForEnd IfNext IEnd Sub5、Option ExplicitPrivate Sub Form_Click()Dim S As String, Flg As BooleanDoS = InputBox("输入一个自然数")If S = "" Or Not IsNumeric(S) ThenMsgBox "请重新输入", 48 + vbOKOnlyElseExit DoEnd IfLoopjudge(S, Flg) ' Call judge(S, Flg) 或judge S, Flg If Flg ThenPrint S; "是回文数"ElsePrint S; "不是回文数"End IfEnd SubPrivate Sub judge(Ch As String, F As Boolean)Dim L As Integer, I As IntegerL = Len(Ch)F = True ' F = FalseFor I = 1 To LIf Mid$(Ch, I, 1) <> Mid$(Ch, L + 1 - I, 1) Then Exit Sub Next IF = False ' F = TrueEnd Sub四、编程题1、编程验证任一大于2的偶数可以表示成两个素数之和。

vb实验5~6及答案考试用5-1 随机产生30～100（包括30、100）的10个正整数，存放于数组中，显示该数组的值，并求出最大值、最小值和平均值，如图5-1所示。

要求：窗体显示字体默认、大小为小三，通过单击窗体触发程序运行。

图5-1Private Sub Form_Click()Dim a(9) As Integer, max%, min%, ave!Randomizemax = 30: min = 100: ave = 0For i = 0 To 9a(i) = Int(Rnd * 71 + 30)Print a(i);ave = ave + a(i)If a(i) > max Then max = a(i)If a(i) < min Then min = a(i)Next iave = ave / 10PrintPrint "Max="; max, "Min="; min, "Ave="; Format(ave, "0.0")End Sub5-2 已知6个学生的成绩，通过Array函数对数组赋初值，利用String函数，以每5分用一个“◆”符号显示，随后显示学生的成绩。

要求：窗体中所有控件字体默认、大小为小四，计算结果在程序启动时立即在窗体中显示。

效果如图5-2所示。

图5-2Private Sub Form_Load()Dim Mark As Variant, i%Form1.ShowMark = Array(56, 78, 98, 88, 76, 78)For i = LBound(Mark) To UBound(Mark)Print String(Mark(i) \ 5, "◆"); Mark(i)PrintNext iEnd Sub5-3 随机产生20个学生的成绩（整数），统计各分数段人数。

学院专业(班级)姓名学号任课教师目录实验一 Visual Basic编程环境和控件 (1)实验二窗体及基本控件使用 (7)实验三顺序结构程序设计 (14)实验四选择结构程序设计 (20)实验五选择结构程序设计（续） (25)实验六循环结构程序设计 (33)实验七循环结构程序设计（续） (38)实验八常用控件 (42)实验九常用控件（续） (51)实验十数组 (56)实验十一数组（续） (65)实验十二顺序文件 (70)实验十三过程 (77)实验十四过程（续） (84)实验十五菜单及通用对话框 (90)实验十六随机文件（选作） (94)附录:VB统考编程题（精选） (98)期末自测题（A卷） (108)期末自测题（B卷） (113)实验报告的整理与编写上机实验结束后，编写实验报告是软件工程的要求，也是培养科学作风的重要途径，实验报告的主要内容包括：（1）实验目的实验作为教学的一个重要环节，其目的在于更深入地理解和掌握课程教学中的有关基本概念，应用基本技术解决实际问题，从而进一步提高分析问题和解决问题的能力。

因此，当我们着手做一个实验的时候，必须明确实验的目的，以保证达到课程所指定的基本要求。

在写实验报告时，要进一步确认是否达到了预期的目的。

（2）实验内容实验的目的是要通过解决一些具体问题来达到的。

在书中，每一部分都安排了多个实验题目，根据教学安排、进度、实验条件、可提供的机时、学生的基础等因素，可以选择其中的几个或全部。

因此，在实验报告中，实验内容是指本次实验中实际完成的内容。

在每一个实验题目中，一般都提出一些具体要求，其中有些具体要求是为了达到实验目的而提出的，不仅有具体的实验题目，还应包括具体要求。

（3）程序设计说明包括算法设计思路，必要的流程图，界面设计说明、使用模块及变量的说明等。

（4）源程序代码Visual Basic的源程序包括界面设计和代码。

程序设计的产品是程序，它应与算法或流程图相一致，要与用户界面设计一致。