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入舵市安恙阳光实验学校周考卷十一 Unit 1 ~ Unit 3(Book 6)本试卷满分120分；答题时间100分钟。
第一部分阅读理解（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的四个选项（A、B、C和D）中，选出最佳选项，并在答题卡上将该项涂黑。
AMoods, say the experts, are emotions that tend to become fixed, in influencing one’s outlook for hours, days or even weeks. That’s great if your mood is a pleasant one, but it will be a problem if you are sad, anxious, angry or simply lonely.Perhaps one of the best ways to deal with such moods is to talk them out: sometimes, though, there is no one to listen. Modern pharmacology (药理学) offers an abundance of antidepressants and anti-anxiety drugs. What many people don’t realize, however, is that scientists have discovered the effectiveness of several non-drug approaches to make you loose from an unwanted mood. These can be just as useful as drugs, and have the added benefit of being nonpoisonous. So next time you feel out of sorts, don’t head for the drug store-try the following approach. Of all the mood-altering self-help techniques, aerobic (有氧健身的) exercise seems to be the most efficient cure for a bad mood. “If you could keep the exercise, you’d be in high spirits,” says Kathryn Lance, author of Running for Health and Beauty. There is obviously a link between physical activity and mood changes.Researchers have explained biochemical and various other changes that make exercise compare favorable to drugs as a mood-raiser. Physical exertion (努力) such as housework, however, does little, probably because it is not intensive enough, and people usually do it unwillingly. The key is aerobic exercise-running, cycling, walk, swimming or other repetitive and sustained a session three to five times a week.1. he problem of talking bad moods out is that _____.A. it proves to be ineffectiveB. sometimes there is noaudienceC. it reveals people’s privacyD. it proves to be a badnonpoisonous2. The underlined word “ antidepressants” in Paragraph 2 Probably means____.A. a drug that relieves depressB. a drug that makespeople sadC. a drug that gives people better sleepD. a drug that isnonpoisonous3. What does the author prefer as a mood-raiser?A. Modern drugs.B. Talking them out.C. Aerobic exercise.D.housework..4. The minimum (最少) length of aerobic exercise a week is ______ according to the passage.A.15 minutesB. 60 minutesC. 100 minutesD. 160 minutes 1．B 细节理解题。
2022年高考复习文化常识周周练1．下列对相关文化常识的解说，不正确的一项是（）A．鳏寡孤独泛指没有劳动力而又没有亲属供养、无依无靠的人。
鳏:年老无妻或丧妻的男子。
寡:年老无夫或丧夫的女子。
孤:年幼丧父的孩子。
独:年老无子的老人。
B．古代对人的死有专用词：皇上死曰崩，王宫诸侯死曰薨，大夫死曰卒，士死曰不禄，平民死曰死。
C．“加”，可指在原有官职外加领官衔，以示尊崇。
加官为中国古代职官体系的常见现象,加官制度是我国古代官制体系中一个重要的内容。
D．男子20岁称弱冠。
这时行冠礼，即戴上表示已成人的帽子，以示成年，但体犹未壮，还比较年少，故称"弱"。
而女性成年礼为笄礼，即在女子16岁时改变幼年的发式，将头发绾成一个髻，随即以簪插定发髻。
1．D【女子15岁行笄礼。
】2．下列对相关文化常识的解说，不正确的一项是（）A．“车驾”本指马驾的车；后也指帝王所乘的车，常用为帝王的代称，颜师古曾注：“凡言车驾者，谓天子乘车而行。
”B．“考课”就是朝廷依照相关法令，在一定的年限内，对各级官吏进行考核，区别不同等级，予以升降赏罚。
C．“谥”，古代君主、大臣等具有一定地位的人死去之后，根据他们的生平与品德，而给予一个带有赞美性质的称号。
D．“服阕”的意思是守丧期满除服。
按照封建礼制，父母死后必须穿丧服守孝三年，三年后才能除去丧服。
2．C【“带有赞美性质的称号”不正确，也有带有批判性质的谥号。
】3．下列对相关文化常识的解说，不正确的一项是（）A．国子监，中国封建时代最高的教育管理机构，有的朝代兼为最高学府。
B．朔，农历每月月中。
古人用“晦”“朔”“望”“既望”等名称来标识日期。
C．衣冠，“衣”指衣服，“冠”指帽子。
“衣冠”指士大夫的穿戴，借指士大夫、官绅。
D．经传，原指经典和注释、阐述经义的著作，后来泛指比较重要的古书。
3．B【朔，农历每月初一。
】4．下列对相关文化常识的解说，不正确的一项是（）A．“御史大夫”在汉代是重要官职，与丞相、太尉合称“三公”，职掌监察百官。
星期一练习1、9+99+999+9999解：原式=10+100+1000+10000-1×4=11110-4=111062、999+999×999解：原式=999×（999+1）=999×1000=9990003、100+99-98-97+96+95-94-93+……+8+7-6-5+4+3-2-1解：原式=（100+99-98-97）+（96+95-94-93）+……+（8+7-6-5）+（4+3-2-1）=4×25=1004、200-198+196-194+……+8-6+4-2解：原式=（200-198）+（196-194）+……+（8-6）+（4-2）=2×50=1005、25×5×64×125解：原式=25×5×4×8×2×125=10×100×1000=1000000星期二练习1、56×165÷7÷11解：原式=56÷7×165÷11=8×15=1202、9999×2222+3333×3334解：原式=3333×3×2222+3333×3334=3333×6666+3333×3334=3333×（6666+3334）=3333×10000=333300003、99999×7+11111×37解：原式=11111×9×7+11111×37=11111×（63+37）=11111004、218×730+7820×73解：原式=2180×73+7820×73=73×（2180+7820）=73×10000=7300005、102×100+101×99-101×100-102×99解：原式=102×（100-99）-101×（100-99）=102-101=1星期三练习1、25×77+55×14+15×77解：原式=77×40+55×14=77×40+11×5×7×2=77×40+77×10=77×50=38502、3333×2222÷6666解：原式=3×1111×2×1111÷6666=11113、8÷7+9÷7+11÷7解：原式=（8+9+11）÷7=44、5÷（7÷11）÷（11÷16）÷（16÷35）解：原式=5÷7×11÷11×16÷16×35=5÷7×35=255、5445÷55解：原式=（5500-55）÷55=100-1=99星期四练习1、下面的算式中，不同汉字表示不同数字，相同的汉字表示相同的数字。
怎样进行发明创造如果没有设想，人类的一切创造都不可能进行。
即使是最简单的小发明、小创造，最初也必须先要有一个设想。
在军事上，一个好的设想可能替代众多的军士而打胜仗；在企业管理上，一个好的设想（通常又称点子）亦可产生极大的经济效益甚至能拯救濒临倒闭的工厂。
用设想赚钱，本篇给你提供按“四步”就班的方法：第一步，一日一想。
即每天提出一个创造性设想。
创造性思维的结果叫做创造性设想，简称设想（idea）。
它可以是一个新思想、新工艺和新技术，也可以是一个新事物、新发明。
不管想出来的是怪的、奇的，还是不存在的、不可能实现的。
只要是“新颖”的，就是一个好设想。
第二步，每周一创。
即每周完成一项创造。
从本周一日一想中提出的六个设想中，选出一个最佳设想，并对这个设想进行改正、完善，形成初步的创造结果。
第三步，每月一发明。
即每月完成一项发明。
从本月四周中经过改正、完善的四个设想创造中，选出一个最佳创造，对其进行可行性分析和物化的研究，使它成为一个能在实践中采用的创造发明。
这时，你也可尝试与一些企业、个人接触，把这个创造发明卖给他们，获得报酬。
第四步，每学期一专利。
即每个学期申报一项国家专利。
从本学期经可行性分析和实践检验的多个发明创造中，选出一个最佳创造发明，进行市场调查，了解其经济效益和市场前景；然后做好有关专利文件上报国家知识产权局，以取得该创造发明的专利权。
有了发明创造，拿到了国家专利，按学习篇中提到的去做，推广自己的发明创造成果，使它转化成你的财富。
大学生每月一发明大学生每月一发明大学生每月一发明大学生每月一发明大学生一学期创造发明登记表。
2019—2020学年第一学期八年级数学期末复习每日一练一一、选择题(每题3分，共24分)1. 下面图案中是轴对称图形的有()A 1个 B. 2个 C. 3个 D. 4个 2. 在ABC ∆中，70,55AB ∠=︒∠=︒，则ABC ∆是( )A.钝角三角形；B.等腰三角形；C.等边三角形；D.等腰直角三角形 3. 在ABC ∆和A B C '''∆中，,AB A B AC A C ''''==，高AD A D ''=，则C ∠和C '∠的关系是( )A.相等；B.互补；C.相等或互补；D.以上都不对4. 如图，在ABC ∆中，,AB AC D =是BC 中点，下列结论中不正确的是( ) A. B C ∠=∠； B. AD BC ⊥； C. AD 平分BAC ∠； D. 2AB BD =5. 由下列条件不能判定ABC ∆为直角三角形的是( )A. A B C ∠+∠=∠B. ::1:3:2A B C ∠∠∠=C. 2()()b c b c a +-= D. 111,,345a b c === 6. 在一个直角三角形中，若斜边的长是13，一条直角边的长为12，那么这个直角三角形 的面积是( )A .30 B. 40 C. 50 D. 60 7. 下列说法中正确的是( )A.两个直角三角形全等B.两个等腰三角形全等C.两个等边三角形全等D.两条直角边对应相等的直角三角形全等8. 已知正方形①、②在直线上，正方形③如图放置，若正方形①、②的面积分别为81 cm 2和144 cm 2，则正方形③的边长为( )A. 225 cm ；B. 63 cm ；C. 50 cm ；D. 15 cm二、填空题(每题3分，共30分)9. 如果等腰三角形的底角是50°，那么这个三角形的顶角的度数是 . 10. 直角三角形的两条直角边分别是9和12，则斜边是 .11. 如图，在Rt ABC ∆中，90,ACB D ∠=︒为斜边AB 的中点，AC =6 cm,BC =8 cm ，则CD 的长为 cm.线密班级 姓名 学号 试场号封12. 如图，在ABC ∆中，,AB AC D =为BC 中点，35BAD ∠=︒，则C ∠的度数 为 . 13. 已知等腰三角形的周长为15cm ，其中一边长为7 cm ，则底边长为 .14. 甲、乙两人同时从同一地点出发，甲往北偏东60°的方向走了12 km ，乙往南偏东30° 的向走了5 km ，这时甲、乙两人相距 km15. 20=︒，则C ∠16. 上 17. AD 折题18. 分2019—2020学年第一学期八年级数学期末复习每日一练二一、选择题(本大题共10小题，每小题3分，共30分)1. 下列四个数中，最大的一个数是（ ）A.2D. 2- 2. 下列图形中，是轴对称图形的是（ ）A.①②B.②③C.①④D.③④ 3. 下列说法正确的是（ ）A.81-的平方根是9±B. 7C.127的立方根是13± D. 21-（）的立方根是1-4. 一次函数32y x =-的图像与y 轴的交点坐标是（ ）A. 2(,0)3-B.2(,0)3C.(0,2)-D.(0,2)5. 若点(21,3)M m m -+在第二象限，则m 取值范围是（ ）A.12m >B.3m <-C.132m -<<D.12m <6. 一次函数y kx b =+的图象如图所示，则当0y ≥时，x 的取值范围是（ ） A.2x ≥- B.2x ≤- C.1x ≥- D.1x ≤-7. 如图，每个小正方形的边长为1，A 、B 、C 是小正方形的顶点，则ABC ∠的度数为（ ） A. 90︒ B. 60︒ C.45︒ D. 30︒ 8. 如图，已知AB AD =，那么添加下列一个条件后，仍无法判定．．．．．ABC ADC ≅V V 的是（ ）A.CB CD = ； B.BAC DAC ∠=∠；C.BAC DCA ∠=∠； D.90B D ∠=∠=︒9. 如图，在ABC V 中，90C ∠=︒，4AC =，3BC =，将ABC V 绕点A 逆时针旋转，使点C 落在线段AB 上的点E 处，点B 落在点D 处，则B 、D 两点间的距离为（ ）B.C.D.10. 如图，正方形ABCD 的边长为2cm ，动点P 从点A 出 发，在正方形的边上沿A B C →→的方向运动到点C 停止， 设点P 的运动路程为()x cm ， 在下列图象中，能表示ADP V的面积2()y cm 关于()x cm 的函数关系的图象是（ ）线密班级 姓名 学号 试场号封二、填空题(本大题共8小题，每小题3分，共24分，请将答案填在答题卡相应的位置上)11. = .12. 已知地球上海洋面积约为3610000002km ，则361000000用科学记数法可以表示为 .， cm .中，A B A C =，50A ∠=︒，CD AB ⊥于D ，则DCB ∠AOB ，15AOP ∠=︒，//PC OA ，4PC =，点D 是射线 .在平面直角坐标系中，已知直线334y x =-+与x 轴、y 轴分别交于A 、(0,)n 将ABC V 沿直线AC 折叠，使得点B 恰好落在轴x 上，标为).2019—2020学年第一学期八年级数学期末复习每日一练三一．选择题. （本大题共10小题，每小题3分，共30分）1. 下列图形中，轴对称图形的个数为A ．1个B ．2 个C ．3个D ．4个2.x 的取值范围是A ．4x >B ．4x ≠C ．4x ≤D ．4x ≥ 3.下列给出的三条线段的长，能组成直角三角形的是A ．1 、 2 、3B ．2 、 3、 4C ．5、 7 、 9D ．5、 12、 134.A B ．5C ．D 5.下列等式中正确的是A.3=- B. 22=- C.2=- D.3=-6. 如图，数轴上点A 对应的数是1，点B 对应的数是2，BC ⊥AB ，垂足为B ，且BC=1,以A 为圆心，AC 为半径画弧，交数轴于点D ，则点D 表示的数为A ．1.4BC 1+D ．2.47．如图，正五边形ABCDE 放入某平面直角坐标系后，若顶点A ，B ，C ，D 的坐标分别是（0，a ），（﹣3，2），（b ，m ），（c ，m ），则点E 的坐标是 A ．（2，﹣3） B ．（2，3）C ．（3，2）D ．（3，﹣2）8.如图，点E 、F 在AC 上，AD=BC ，AD//BC ，则添加下列哪一个条件后，仍无法判定△ADF ≌△CBE 的是A.DF=BEB.∠D=∠BC.AE=CFD.DF//BE9. 在同一直角坐标系内，一次函数y kx b =+与2y kx b =-的图象分别为直线为12,l l ，则下列图像中可能正确的是（ ）A B C D 10.已知点A (1,3)、B (3,1)-,点M 在x 轴上，当AM BM -最大时，点M 的坐标为 A ．(2,0) B ．(2.5,0) C ．(4,0) D ．(4.5,0)二．填空题. ( 本大题共8小题，每小题3分，共24分)11.圆周率 3.1415926π≈,用四舍五入法把π精确到千分位，得到的近似值是_______.12.已知点(,)P a b 在一次函数21y x =-的图像上，则21__________a b -+= 13.如图，已知△ABC ≌△DCB ，∠ABC=65°，∠ACB=30°，则∠ACD=______° 14.已知一个球体的体积为3288cm ，则该球体的半径为________cm.（注：球体体积公式V球体=343r π，r 为球体的半径.）A一、选择题（本大题共8小题，每小题3分，共30分．在每小题所给出的四个选项中，恰有一项是符合题目要求的，请将正确选项前的字母代号填涂在答题卡相应位置上）1．（3分）下列表情中，是轴对称图形的是（ ） A ． B ． C ． D ． 2．（3分）的算术平方根是（ ） A ．2 B ．±2 C ． D ．±3．（3分）在实数﹣、、、中，无理数的个数是（ ）A ．1B ．2C ．3D ．4 4．（3分）如图，AB 、CD 相交于点E ．若△AEC ≌△BED ，则下列结论中不正确的是（ ） A ．AC=BD B ．AC ∥BD C ．E 为CD 中点 D ．∠A=∠D线试场5．（3分）下列各组数是勾股数的是（）A．3，4，5 B．1.5，2，2.5 C．32，42，52D．，，（第5题）（第6题）（第10题）6．（3分）若正比例函数y=kx的图象如图所示，则一次函数y=kx+k的图象大致是（）A．B．C．D．7．（3分）下列各点中，位于第四象限的点是（）A．（4，5）B．（﹣4，5）C．（4，﹣5）D．（﹣4，﹣5）8．（3分）已知一次函数y=kx+b的图象经过第一、二、三象限，则b的值可以是（）A．﹣2 B．﹣1 C．0 D．29．（3分）将一次函数图象y=2x向右平移1个单位，所得图象对应的函数关系式为（）A．y=2x﹣2 B．y=2x﹣1 C．y=2x+1 D．y=2x+210．（3分）张师傅驾车从甲地到乙地，两地相距500千米，汽车出发前油箱有油25升，途中加油若干升，加油前、后汽车都以100千米/小时的速度匀速行驶，已知油箱中剩余油量y（升）与行驶时间t（小时）之间的关系如图所示．以下说法错误的是（）A．加油前油箱中剩余油量y（升）与行驶时间t（小时）的函数关系是y=﹣8t+25B．途中加油21升；C．汽车加油后还可行驶4小时；D．汽车到达乙地时油箱中还余油6升二、填空题（本大题共8小题，每小题3分，共24分．不需写出解答过程，请把答案直接填写在答题卡相应位置上）11．（3分）在平面直角坐标系中，若点P坐标为（4，3），则它位于第象限．12．（3分）如图，AB∥CD，BF=DE，要得到△ABF≌△CDE，需要添加的一个条件是．13．（3分）太仓是一座沿江临沪的新兴港口城市，一座宜居宜业的现代田园城市，综合实力一直处于全国百强县(市)前十位。
一、选择题Ⅰ(每小题2分，共20分)1．殷周时代可能已经有“中国”意识，但只有到秦汉建立统一帝国……一个初步统一的“中国”才真正形成。
以下属于其形成原因的有()①民心所向，人民渴望统一②经济发展要求打破割据③采取正确的方针，远攻近交④历代秦王的雄才大略A．①②③B．①③④C．①②③④D．①②④2．(2023·温州模拟)钱穆先生说：“秦代之中央政府，较之西周武王、成王时，其统一性，已远为进步。
”其“进步”主要表现在()A．实行郡国并行制B．实行郡县制C．创立皇帝制度D．设立中朝3．(2022·浙江德清县高三模拟)根据考古发现《睡虎地秦墓竹简行书》记载，“行命书及书署急者，辄(立即)行之；不急者，日蹙(毕)，勿敢留。
留者以律论之”。
这反映出秦朝() A．皇权的至高无上B．行政管理的严格高效C．文官政治的确立D．严刑酷法的治国理念4．史载：“秦兼天下，建皇帝之号，立百官之职。
汉因循而不革，明简易，随时宜也。
其后颇有所改。
”其中“颇有所改”的是()A．设丞相B．设内朝C．设御史大夫D．设三公九卿5. 感叹“大道”既隐，有学者把先秦到秦汉的历史列为“方国—王国—帝国”(“方国”就是活动在一定区域，以血缘为纽带的部落集团)。
试想，这一变化反映的主要问题是() A．最高统治者开始建立皇帝制B．周边王朝完全臣服于秦汉王朝C．统一的多民族中央集权国家逐渐形成D．中央王朝统治范围极大扩张6．(2023·杭州模拟)钱穆先生在评论汉代的士人政府时认为，汉政府自武帝后，渐渐从宗室、军人、商人之组合，转变为士人参政的新局面。
该局面()A．彻底结束了贵族政治B．实现了社会公平公正C．促进了儒学地位的提高D．开启官僚政治体制先河7．《文献通考》记载：“延康(东汉献帝)元年，尚书陈群以为天朝选用，不尽人才，乃立九品官人之法。
州郡县俱置大小中正，各取本处人，在诸府公卿及台省郎吏，有德充才盛者为之。
”下列关于“九品官人法”的解读，正确的是()A．由“中正官”根据出身门楣评定人物的才能B．是各个州郡县选拔各自地方官员的选官制度C．考选方式封闭，造成世家大族对官场的垄断D．为知识分子提供了参政机会，打破门第界限8．《汉书》中关于汉代“博士”记载：“博士‘(董)仲舒通五经，能持论，善属文’”“博士‘明于古今，温故知新，通达国体’”。
第一章小结与复习一、选择题1．在﹣，0，，﹣1这四个数中，最小的数是（）A．﹣ B．0 C． D．﹣12．-2的相反数是（）A．2 B．-2 C．12D．123．（4分）2015的相反数是（）A．12015B．12015- C．2015 D．﹣20154．（3分）12-的相反数是（）A．2 B．﹣2 C．12D．12-5．（3分）6的绝对值是（）A．6 B．﹣6 C．16D．16-6．下列说法正确的是（）A．一个数的绝对值一定比0大B．一个数的相反数一定比它本身小C．绝对值等于它本身的数一定是正数D．最小的正整数是17．某地一天的最高气温是12℃，最低气温是2℃，则该地这天的温差是（）A．﹣10℃ B．10℃ C．14℃ D．﹣14℃8．（4分）下列说法错误的是（）A．﹣2的相反数是2B．3的倒数是1 3C ．（﹣3）﹣（﹣5）=2D ．﹣11，0，4这三个数中最小的数是09．（3分）如图，数轴上的A 、B 、C 、D 四点中，与数3-表示的点最接近的是（ ）A ．点AB ．点BC ．点CD ．点D 10．（3分）（2015•娄底）若|a ﹣1|=a ﹣1，则a 的取值范围是（ ）．A ．a ≥1B ．a ≤1C ．a ＜1D ．a ＞1二、填空题11．有一种原子的直径约为0.00000053米，用科学记数法表示为 ．12．一组按规律排列的数：2，0，4，0，6，0，…，其中第7个数是 ，第n 个数是 （n 为正整数）．13．-3的倒数是 ，-3的绝对值是 ． 14．数轴上到原点的距离等于4的数是 ．15．|a|=4，b 2=4，且|a+b|=a+b ， 那么a-b 的值是 ．16．在数轴上点P 到原点的距离为5，点P 表示的数 ．17．绝对值不大于2的所有的整数是 ．18．．把下列各数分别填在相应的集合内（本小题每空2分，满分6分） －11、 5%、 －2．3、61 、3.1415926、0、 34-、 39 、2014、－9 分数集： 。
手惰市安逸阳光实验学校高考英语一轮复习系列训练（M2）星期一（U1-M2）第一节单项填空1. Carol said the work would be done by October, ______personally I doubt very much.A. itB. thatC. whenD. which2. ______ is mentioned above, the number of the students in senior schools is increasing.A. WhichB. AsC. ThatD. It3. This is the factory _______we visited last year.A. whereB. whichC. the oneD. at which4. There was ________ time __________ I hated to go to school.A. a; thatB. a; whenC. the; thatD. the; when5. September 18,1913 is the day ______we’ll never forget.A. thatB. whenC. on whichD. on that6. The hard-working farmers and their happy life_____ we saw in the countryside made a wonderful impression on us.A. whomB. whoC. whichD. that7. Have you found the woman ______purse was lost?A. herB. of whichC. thatD. whose8. The comrade _______is speaking at the meeting is an advanced worker.A. whomB. whichC. whoD. whose9. That is one of those books that _____ worth reading.A. isB. haveC. hasD. are10. That was the reason______ Mac gave me the other day.A. whyB. for thatC. whichD. for which11. ---I’m afraid Mr. Wood can’t see you until 4o’clock.----Oh, ____ I won’t wait.A. no doubtB. after allC. in that caseD. in this way12. Marry has been fortunate to find a job she loves and, ___, she gets well paid for it.A. sooner or laterB. besidesC. as a resultD. more or less13. He hasn’t slept at all for three days. ____he is tired out.A. There is no wonderB. There is no needC. It is no wonderD. It is no way14. She wanted to use the ____money to buy her husband a present for the coming Christmas.A. remainedB. remainingC. leavingD. left15. ____the watch ___and see if something is wrong with it.A. Take; apartB. Take; outC. Put; apartD.Put ;out16. What do you advice for____ the dirty mark from my bag?A. removingB. movingC. gettingD. bringing17. The farm which ___in the earthquake last year____.A. destroyed; was belonged to my uncle.B. destroyed; belonged to my uncleC. was destroyed; belonged to my uncleD. was destroyed; was belonged to my uncle.18. ____, tears came down.A. Hearing the bad newsB. Heard the bad newsC. When to hear the bad news.D. When she heard the bad news19. If you give me your photo, I’ll give you mine_____.A. on turnB. by returnC. in returnD. by turns20. At that time, China was _____ Japan, so going abroad was extremely difficult.A. at the war withB. at the war againstC. at war withD. during the war with21. There is no doubt _____ America is a developed country.A. whetherB. ifC. thatD. which 22. The reference book, mainly ______ use in colleges, is a bestseller this year.A. designed forB. designed toC. designing ofD. designing for23. He _____ the bag, but saw nothing in it.A. looked throughB. looked intoC. looked out ofD. looked up24. _____ his immediate help with my sick daughter, I treated him in an expensive restaurant.A. In return forB. Because ofC. Thanks toD. In case of25. I would walk to school every day _____ ride a bicycle.A. rather thanB. more thanC. other thanD. less than第二节完形填空"Everything happens for the best, "my mother said whenever I faced26. A. put B. take C. move D. carry27. A. devoted B. designed C. found D. enjoyed28. A. invited B. promised C. refused D. accepted29. A. large B. all C. no D. small30. A. experience B. examination C. agreement D. college31. A. played B. joined C. taken D. fought32. A. possible B. successful C. right D. important33. A. shown B. disappeared C. resulted D. turned 34. A. woke B. advised C. demanded D. reminded35. A. While B. After C. Before D. So36. A. What B. How C. Whenever D. Wherever37. A. calling B. answering C. broadcasting D. announcing38. A. make B. act C. broadcast D. play39. A. moved B. sorry C. thankful D. satisfied40. A. future B. coming C. last D. later第三节语法填空Frederick William I, the king of Prussia, would never have imagined that his greatest gift 41_________ the Russian people would have such an 42(amaze)_____________ history. This gift was the Amber Room,43____________ was given this name 44_______________ several tons of amber were used to make 45_____________.The amber which 46(select)______________ had a beautifulyellow-brown colour 47___________ honey. The design of the48________________ was in the fancy style popular in those days. It was also a treasure 49(decorate)________________ with gold and jewels, which took the country’s best artists about ten years 50(make)_______________.41______________42_____________43_____________44_____________45_____ _________46______________47_____________48_____________49_____________50______________第四节阅读理解AThe London Summer School in Classics 2008 will be held at King’s College London. It will run from 8th July until 17th July. Applications close on 2nd June, 2008. For an application form, please download either the 2-page PDF or the word format document from the foot of the page. If you have any problems downloading the application form or any questions, please contact: London Summer School in Classics, King’s College London.Tel: 020 7848 2299Fax: 020 7848 2545OrganizationThe school is organized by the colleges of the University of London. The summer school offers eight days of intensive teaching in Greek and Latin. There are four language classes each day as well as lectures and a debate, between 10:30 am and 4:30 pm. The course is not residential (提供住宿的), and there is no teaching during the weekend of 12th to 13th July.The fee is £85.00. Travel grants (旅行补助金) are available as a contribution to your travel costs, but may not cover all your expenses. The travel grants are arranged during the summer school.Teaching is generally in groups of 12-15 people and it, as far as possible, comprises (包含) of students of roughly the same level of experience. The style of teaching is friendly, but demanding: a lot of work is expected from students during the school, but they usually find the whole experience both stimulating and valuable. Some classes concentrate chiefly on reading, while others offer a mixture of grammar and translation practice. Our tutors include some of the most experienced and talented teachers of Classics in the London area and beyond.The Summer School in Classics caters for a wide range of interests and for both school & university students as well as those who wish to learn Greek or Latin, or to revive their knowledge of the languages. Our principal concern is to provide a thorough program of language learning in a lively university environment.51. To join in the school, you have to apply before ________.A. 8th July, 2008B. 17th July, 2008C. 13th July, 2008D. 2nd June, 200852. Which of the following is true?A. learn the grammar of Greek and Latin onlyB. do a lot of reading in Greek and LatinC. do some translation work onlyD. speak Greek and Latin with experienced teachers53. What does the London Summer School in Classics do?A. Providing a stimulating experience for students.B. Teaching students languages in a lively environment.C. Promoting students to develop a wide range of interests.D. Improving students’ level of debating in the argument.54. Which is one of the teaching ways of the school?A. Student groups consist of the same level students strictly.B. Studen ts needn’t do any work in the class.C. Students are generally divided into groups of 12-15.D. Students learn Greek and Latin by listening to teachers all day.55. What can we know from the passage?A. The fee is £85, including the travel costs.B. Students needn’t go to class on 12th and 13th July.C. People should fill in two application forms.D. People can contact the school by phone or email.BIt was a winter morning, just a couple of weeks before Christmas 2005. While most people were warming up their cars, Trev or, my husband, had to get up early to ride his bike four kilometers away from home to work. On arrival, he parked his bike outside the back door as he usually does. After putting in 10 hours of labor, he returned to find his bike gone.The bike, a black Kona 18 speed, was our only transport. Trevor used it to get to work, putting in 60-hour weeks to support his young family. And the bike was also used to get groceries(食品杂货)，saving us from having to walk long distances from where we live.I was so sad that someone would steal our bike that I wrote to the newspaper and told them our story. Shortly after that, several people in our area offered to help. One wonderful stranger even bought a bike, then called my husband to pick it up. Once again my husband had a way to get to and from his job. It really is an honor that a complete stranger would go out of their way for someone they have never met before. People say that a smile can be passed from one person to another, but acts of kindness from strangers are even more so. This experience has had a spreading effect in our lives because it strengthened our faith in humanity(人性) as a whole. And it has influenced us to be more mindful of ways we, too, can share with others. No matter how big or how small, an act of kindness shows that someone cares. And the results can be everlasting.56. How did people get to know the couple’s problem?A. From radio broadcasts.B. From TV newsC. From a newspaper.D. From a stranger.57.Which of the following is TRUE?A. The author used to get to work by bike.B. The author’s husband often parked the bike beside the back door.C. Several strangers offered bikes to them, but they only accepted oneof them.D. Somebody had stolen their bike before, but soon returned it to the author.58.What do we learn from the couple’s experience?A. Strangers are usually of little help.B. One should take care of their bike.C. News reports make people famous.D. An act of kindness can mean a lot.59. Why was the bike so important to the couple?A. They used it for work and daily life.B. It was their only possession.C. It was a nice Kona 18 speed.D. The man’s job was bike racing.60. We can conclude that _______A. the couple worked 60 hours a week.B. people were busy before ChristmasC. the stranger brought over the bikeD. life was hard for the young family.CThe literal meaning of philosophy is “love of wisdom”. But this meaning does not tell us very much. Unlike the other disciplines, philosophy cannot be defined by what you study, because it is actually unlimited. Anything can be the subject matter of philosophy: are, history, law, language, literature, mathematics, and in fact, the other academic disciplines are directly related to philosophy. For this reason you get a Doctorate（博士学位）of Philosophy (Ph. D. ) in biochemistry, or computer science, or psychologyTwo broad sub-fields of philosophy are logic and the history of philosophy. Logic is the science of argument and critical thinking. It provides sound methods for distinguishing good from bad reasoning. The history of philosophy involves the study of major philosophers and periods in the development of philosophy.Of what use is philosophy? First it is useful in educational advancement. It is necessary for understanding other disciplines. Only philosophy questions the nature of the concepts used in a discipline, and its relation to other disciplines. And through the study of philosophy, one develops sound methods of research and analysis that can be applied to any field.There are a number of general uses of philosophy. It strengthens one’s ability to solve problems, to communicate, to organize ideas and issues, to persuade, and to take what is the most important from a large quantity of data. These general uses are of great benefit in the career field, not necessarily for obtaining one’s first job after graduation, but for preparing for positions of responsibility, management andleadership later on. It is very short-sighted after all, to take a course of studies only for the purpose of getting one’s first job. The useful skills developed through the study of philosophy have significant long-term benefits in career advancement. No other discipline systematically follows the ideals of wisdom, leadership, and capacity to resolve human conflict61. What’s the meaning of philosophy according to the passage？A. social sciencesB. both social and natural sciencesC. natural sciencesD. the subject matter of politics62. What does “discipline” mean in the first paragraph?A. literatureB. scienceC. subjectD. occupation63. With the study of philosophy, you can .A. make progress in your career developmentB. succeed in everythingC. find a good job soon after graduationD. become a great leader64. According to the passage, which of the following statements is TRUE?A. Philosophy is an independent discipline.B. The study of philosophy brings you immediate benefits.C. Logic helps you to become a better thinker.D. The meaning of philosophy is too limited to define.65. From the passage, we can conclude .A. not all the subjects have to do with philosophyB. philosophy can be helpful for the study of any other subjectsC. a person will get a Ph.D. if he/she studies philosophyD. philosophy is the only solution to all the problems in the worldDWugging, or web use giving, describes the act of giving to charity at no cost to the user. By using , which is being added to a number of university computers across the UK, students can raise money every time they search, but it won’t cost t hem a penny.Research shows that students are extremely passionate about supporting charity — 88% of full time students have used the Internet to give to charity. This age group is often the least likely to have their own income. 19% of 22 to 24 year olds have short-term debts of more than £5,000. With rising personal debt levels in this age group, due to university tuition fees or personal loans and a lack of long-term savings, traditional methods of donating to charity are often not appealing (有感染力的) or possible.Beth Truman, a 21 year old recent university graduate, has used to donate to her chosen charity, the RSPCA, for two years and has seen the “wugging” movement grow in popularity with students. “When you’re at university you become more socially aware, but it’s sometimes hard to give to others when you have little money yourself,”says Beth. “Wugging is great for people in this age group as it allows them to use the technology on a daily basis to give to charity, without costing them a single penny.”Wugging is perfect for people who want to be more socially aware and supportive but don’t feel they have the means to do so. Students using the web can raise money for causes they care about without costing them anything in terms of time or money, and charities get a valuable source of funding. works like any other search engine, allowing users to search for information, news and images but users can decide which of the UK’s 170,000 charities they would like to support throug h their clicks. then makes monthly payments to every registered charity. Launched in June 2005, is now the eighth largest search engine and one of the busiest charity websites in the UK.66. What does “wugging”show According to the passage?A. a websiteB. a school organizationC. a student movementD.a charity-related action67. In the case of charity, ______.A. receives much money from studentsB. offers valuable information to studentsC. frees students of the financial worriesD. praises students for their money-raising 68. What does we think of the “wugging” movement?A. It makes popular in the UK.B. It becomes easy to do charity because of it.C. It results in students’ more social awareness.D. It helps students to save money.69. From the passage, we can inferred that ______.A. “wugging” is a win-win idea for both students and charitiesB. most full time students do charity on the Internet every dayC. helps students pay for the college educationD. is the most successful search engine in the UK70. What’s the general idea of this passage?A. “Wugging”, a new popular term on the Internet.B. More Britain charities benefit from the Internet.C. Students raise money for charity by “wugging”.D. British people show strong interest in charity.星期一（U1-M2）第一节单项填空1—5 DBBBA 6-10 DDCDC 11-15 CBCBA 16-20 ACDCC 21-25 CABAA第二节完形填空26-30 DBCAA 31-35 ACADB 36-40 BACDB第三节语法填空41. to 42. amazing 43. which 44. because 45. it 46. was selected47. like 48. room 49. decorated 50. to make第四节阅读理解51-55 DBBCB 56-60 CBDAD 61-65 BCACB 66-70 DCBAC。
教科版九年级物理上册第一章分子动理论与内能复习题一、单项选择题（共20小题；共40分）1. 下列属于热量单位的是A. 牛顿（）B. 帕斯卡（）C. 瓦特（）D. 焦耳（）2. 关于温度、热量、比热容和内能，下列说法正确的是A. 的冰块，内能可能为零B. 物体内能增大一定是吸了热C. 一碗水倒掉一半后，内能减小D. 物体的温度越高，所含热量越多3. 在试管中装适量的水，试管口用塞子塞住，用酒精灯对试管加热，如图所示。
加热一段时间后，塞子冲出去了，则A. 加热过程中，酒精的化学能全部转化为水的内能B. 塞子冲出前，试管内气体内能是通过做功的方式增大的C. 塞子冲出时，试管内气体温度不变D. 塞子冲出时，塞子增加的机械能是由试管内气体内能转化的4. 图中的示意图形象反映物质气、液、固三态分子排列的特点，正确的说法是A. 甲是气态B. 乙是气态C. 丙是气态D. 甲是固态5. 水的比热容比煤油的大。
如图用规格相同的两试管分别装上质量相同的煤油和水，隔着石棉网同时对两试管加热。
下列各图中的哪一图线能反映该实验情况A. B.C. D.6. 关于温度、热量、内能，以下说法正确的是A. 温度高的物体内能一定大B. 物体的温度越高，所含的热量越多C. 物体的内能与温度有关，只要温度不变，物体的内能就一定不变D. 内能少的物体也可能将能量传给内能多的物体7. 生活中小明发现同样的一杯热水，冬天室温低时冷却得快，夏天室温高时冷却得慢。
好动脑筋的小明同学针对这一现象，提出以下几个问题。
其中属于可探究的科学问题是A. 为什么热水在室温低时比室温高时冷却得快?B. 热水冷却的快慢与质量有关吗?C. 热水冷却的快慢与环境的温差有关吗?D. 热水冷却的快慢与它的质量、温度有关吗?8. 下列有关分子动理论的说法，错误的是A. 客厅里摆上鲜百合花，花香弥漫客厅，说明分子在永不停息地运动B. 在冷、热两杯水中各滴入一滴墨水，墨水在热水中扩散得快C. 一根铁棒不容易被拉长，是因为其分子之间存在相互作用的引力D. 水、酒精等液体都能流动，说明液体分子之间不存在相互作用的引力9. 下列实例中，改变物体内能的方式与其它三个不同的是A. 用力搓手，手会发热B. 用炉灶烧水，水温升高C. 气缸内气体被压缩，温度升高D. 用锯条锯木头，锯条温度升高10. 如图所示，两个相同规格的电加热器加热装在相同烧杯中的质量、初温都相同的不同液体，并使液体升高的温度相同。
周滚动练习（一）周滚动练习(一)[测试范围：18.1 时间：40分钟 分值：100分]一、选择题(每题4分，共32分)1．如图1－G －1，假定平行四边形ABCD 的周长是28 cm ，△ABC 的周长是22 cm ，那么AC 的长为( )图1－G －1A ．6 cmB ．12 cmC ．4 cmD ．8 cm2．以下不能判定一个四边形是平行四边形的是( )A ．两组对边区分平行的四边形是平行四边形B ．两组对边区分相等的四边形是平行四边形C ．一组对边平行，另一组对边相等的四边形是平行四边形D ．对角线相互平分的四边形是平行四边形3．如图1－G －2，▱ABCD ，依据图中尺规作图的痕迹，判别以下结论中不一定成立的是( )A ．∠DAE ＝∠BAEB ．∠DEA ＝12∠DAB C ．DE ＝BE D ．BC ＝DE图1－G －2 图1－G －34．小敏不慎将一块平行四边形玻璃打碎成如图1－G －3所示的四块，为了能在商店配到一块与原来相反的平行四边形玻璃，他带了两块碎玻璃，其编号应该是( )A ．①②B ．①④C ．③④D ．②③5．如图1－G －4是屋架设计图的一局部，D 是斜梁AB 的中点，立柱BC ，DE 垂直于横梁AC ，AB ＝4 m ，∠A ＝30°，那么DE 的长为( )A ．1 mB ．2 mC ．3 mD ．4 m图1－G －4 图1－G －56．如图1－G －5，在四边形ABCD 中，E 是BC 边的中点，衔接DE 并延伸，交AB 的延伸线于点F ，AB ＝BF .添加一个条件，使四边形ABCD 是平行四边形，你以为以下四个条件可选择的是( )A ．AD ＝BCB ．CD ＝BFC ．∠A ＝∠CD ．∠F ＝∠CDF7．如图1－G－6，在▱ABCD中，BF平分∠ABC，交AD于点F，CE平分∠BCD，交AD于点E，假定AB＝6，EF＝2，那么BC的长为()A．8 B．10C．12 D．14图1－G－6图1－G－7.如图1－G－7，四边形ABCD中，R，P区分是BC，CD上的点，E，F区分是AP，RP 的中点，当点P在CD上从点C向点D移动而点R不动时，以下结论成立的是() A．线段EF的长逐渐增大B．线段EF的长逐渐减小C．线段EF的长不变D．线段EF的长与点P的位置有关二、填空题(每题4分，共24分)9．如图1－G－8所示，在▱ABCD中，BD是对角线，E，F是BD上的点，且BE＝DF，请写出图中的一对全等三角形：__________________．图1－G－8图1－G－910．如图1－G－9，在▱ABCD中，BE⊥AB交对角线AC于点E，假定∠1＝20°，那么∠2的度数为________．11．如图1－G－10，在▱ABCD中，两条对角线AC，BD相交于点O，假定△ABO的面积是3，那么▱ABCD的面积为________．图1－G－10图1－G－1112．如图1－G－11，在▱ABCD中，∠A＝70°，DC＝DB，那么∠CDB＝________°.13．如图1－G－12，CD是△ABC的中线，E，F区分是AC，DC的中点，EF＝1，那么BD＝________．图1－G－12图1－G－1314．如图1－G－13，在▱ABCD中，E为边CD上一点，将△ADE沿AE折叠至△AD′E 处，AD′与CE交于点F.假定∠B＝52°，∠DAE＝20°，那么∠FED′的度数为________．三、解答题(共44分)15．(10分)如图1－G －14，请在以下四个结论中选出两个作为条件，推出四边形ABCD 是平行四边形，并予以证明(写出一种即可)．①AD ∥BC ；②AB ＝CD ；③∠A ＝∠C ；④∠B ＋∠C ＝180°.：在四边形ABCD 中，________．求证：四边形ABCD 是平行四边形．图1－G －1416．(10分)如图1－G －15，点A ，C 在EF 上，AD ∥BC ，DE ∥BF ，AE ＝CF .(1)求证：四边形ABCD 是平行四边形；(2)直接写出图中一切相等的线段(AE ＝CF 除外)．图1－G －1517．(12分)如图1－G －16，在平行四边形ABCD 中，将△BCD 沿BD 翻折，使点C 落在点E 处，BE 和AD 相交于点O .求证：OA ＝OE .图1－G －1618．(12分)：如图1－G －17，在△ABC 中，DE ，DF 是△ABC 的中位线，衔接EF ，AD ，其交点为O .求证：(1)△CDE ≌△DBF ；(2)OA ＝OD .图1－G －17教员详解详析1．D [解析] 依据平行四边形的对边相等可得AB ＋BC ＝12×28＝14(cm)，又△ABC 的周长是22 cm ，所以AC ＝22－14＝8(cm)．2．C3．C [解析] A ．由作法可知AE 平分∠DAB ，所以∠DAE ＝∠BAE ，故本选项不契合题意；B ．∵CD ∥AB ，∴∠DEA ＝∠BAE ＝12∠DAB ，故本选项不契合题意； C ．无法证明DE ＝BE ，故本选项契合题意；D ．∵∠DAE ＝∠DEA ，∴AD ＝DE .又∵AD ＝BC ，∴BC ＝DE ，故本选项不契合题意．4．D [解析] ∵只要②③两块角的两边相互平行，且中间局部相连，角的两边的延伸线的交点就是平行四边形的顶点，∴带②③两块碎玻璃，就可以确定平行四边形的大小．5．A [解析] ∵D 是斜梁AB 的中点，立柱BC ，DE 垂直于横梁AC ，∴E 是AC 的中点，∴DE 是直角三角形ABC 的中位线．依据三角形的中位线定理得DE ＝12BC . 又∵在Rt △ABC 中，AB ＝4 m ，∠A ＝30°，∴BC ＝12AB ＝2 m ， ∴DE ＝12BC ＝1 m.6．D [解析] 题干中有AB ＝BF ，因此证AB ∥CD ，AB ＝CD 即可，而要证这两个条件应证△BEF ≌△CED .结合题干中条件：E 为BC 的中点，又有对顶角，因此添加∠F ＝∠CDF 可证△BEF ≌△CED ，可得AB ∥CD ，AB ＝CD .7．B [解析] ∵四边形ABCD 是平行四边形，∴AD ∥BC ，DC ＝AB ＝6，AD ＝BC ，∴∠AFB ＝∠FBC .∵BF 平分∠ABC ，∴∠ABF ＝∠FBC ，那么∠ABF ＝∠AFB ，∴AF ＝AB ＝6.同理可得：DE ＝DC ＝6.∵EF ＝AF ＋DE －AD ＝2，即6＋6－AD ＝2，解得AD ＝10.故BC ＝10.应选B.8．C [解析] 衔接AR ，那么EF 是△APR 的中位线，EF ＝12AR .由于在点P 的移动进程中，点A 和点R 的位置不变，所以AR 的长度不变．因此，线段EF 的长也不变．9．△AFD ≌△CEB ，△BAF ≌△DCE ，△ABD ≌△CDB (答案不独一，选其中一对即可)[解析] 此题为开放性标题，契合条件的结果不独一．[点评] 此题是对平行四边形基础知识的考察，注重知识的灵敏运用．10．110° [解析] ∵四边形ABCD 是平行四边形，∴AB ∥CD ，∴∠BAE ＝∠1＝20°.∵BE ⊥AB ，∴∠ABE ＝90°，∴∠2＝∠BAE ＋∠ABE ＝110°.11．12 [解析] ∵OA ＝OC ，∴△ABO 的面积＝△CBO 的面积＝3，∴S ▱ABCD ＝2S △ABC ＝4S △ABO ＝12.12．4013．214．36° [解析] ∵四边形ABCD 是平行四边形，∴∠D ＝∠B ＝52°.由折叠的性质得：∠D ′＝∠D ＝52°，∠EAD ′＝∠DAE ＝20°，∴∠AEF ＝∠D ＋∠DAE ＝52°＋20°＝72°，∠AED ′＝180°－∠EAD ′－∠D ′＝108°，∴∠FED ′＝108°－72°＝36.15．解：答案不独一，选以下解法中的一个即可．解法一：：在四边形ABCD 中，①AD ∥BC ，③∠A ＝∠C .求证：四边形ABCD 是平行四边形．证明：∵AD ∥BC ，∴∠A ＋∠B ＝180°，∠C ＋∠D ＝180°.∵∠A ＝∠C ，∴∠B ＝∠D .∴四边形ABCD 是平行四边形．解法二：：在四边形ABCD 中，①AD ∥BC ，④∠B ＋∠C ＝180°.求证：四边形ABCD 是平行四边形．证明：∵∠B ＋∠C ＝180°，∴AB ∥CD .又∵AD ∥BC ，∴四边形ABCD 是平行四边形．解法三：：在四边形ABCD 中，②AB ＝CD ，④∠B ＋∠C ＝180°.求证：四边形ABCD 是平行四边形．证明：∵∠B ＋∠C ＝180°，∴AB ∥CD .又∵AB ＝CD ，∴四边形ABCD 是平行四边形．解法四：：在四边形ABCD 中，③∠A ＝∠C ，④∠B ＋∠C ＝180°.求证：四边形ABCD 是平行四边形．证明：∵∠B ＋∠C ＝180°，∴AB ∥CD ，∴∠A ＋∠D ＝180°.∵∠A ＝∠C ，∴∠B ＝∠D ， ∴四边形ABCD 是平行四边形．16．解：(1)证明：∵AD ∥BC ，DE ∥BF ，∴∠E ＝∠F ，∠DAC ＝∠BCA ，∴∠DAE ＝∠BCF .在△ADE 和△CBF 中，⎩⎨⎧∠E ＝∠F ，AE ＝CF ，∠DAE ＝∠BCF ，∴△ADE ≌△CBF (ASA)，∴AD ＝BC .又AD ∥BC ，∴四边形ABCD 是平行四边形．(2)AD ＝BC ，EC ＝AF ，ED ＝BF ，AB ＝DC .理由如下：∵△ADE ≌△CBF ，∴AD ＝BC ，ED ＝BF .∵AE ＝CF ，∴EC ＝AF .∵四边形ABCD 是平行四边形，∴AB ＝DC .17．证明：∵四边形ABCD 为平行四边形，∴AD ∥BC ，AD ＝BC ，∴∠ADB ＝∠CBD .由折叠可知∠EBD ＝∠CBD ，BE ＝BC ，∴AD ＝BE ，∠EBD ＝∠ADB ，∴BO ＝DO ，∴AD －DO ＝BE －BO ，即OA ＝OE .18．证明：(1)∵DE ，DF 是△ABC 的中位线，∴DF ＝CE ，DF ∥CE ，BD ＝DC ，∴∠C ＝∠BDF .在△CDE 和△DBF 中，⎩⎨⎧DC ＝BD ，∠C ＝∠BDF ，CE ＝DF ，∴△CDE ≌△DBF (SAS)．(2)∵DE ，DF 是△ABC 的中位线，∴DF ＝AE ，DF ∥AE ，∴四边形DEAF是平行四边形．又∵EF与AD交于点O，∴OA＝OD.。
