湖北省武汉市(第十五中学、十七中学、常青一中)2019-2020学年高二上学期期末数学试题

武汉市常青第一中学2019-2020学年度第二学期期中考试高二物理试卷考试时间：2020年4月23日10:30-12:00 试卷满分：100分一、单项选择题：（共10个小题，每小题3分，共30分，在每个小题给出的四个选项中，只有一个选项是符合题意的．）1．下列关于布朗运动的说法中正确的是A．布朗运动是指在显微镜下观察到的组成悬浮颗粒的固体分子的无规则运动；B．布朗运动是指在显微镜下直接观察到的液体分子的无规则运动；C．布朗运动是指液体分子的无规则运动；D．布朗运动是指在显微镜下观察到的悬浮固体颗粒的无规则运动。

2．下列现象中不能说明分子间存在分子力的是（）A．两铅块能被压合在一起B．钢绳不易被拉断C．空气容易被压缩D．水不容易被压缩3．如图所示，金属框上阴影部分表示肥皂膜．它被棉线分割成a、b两部分．若将肥皂膜的a部分用热针刺破，棉线的形状是选项图中的（）A．B．C．D．4．下列过程中可能发生的是( )A．将两瓶不同液体混合，然后它们又自发地各自分开B．利用其他手段，使低温物体温度更低，高温物体的温度更高C．打开一高压密闭容器，其内气体自发溢出后又自发溢进去，恢复原状D．某种物质从高温热源吸收20 kJ的热量，全部转化为机械能，而没有产生其他任何影响5．一瓶矿泉水喝完一半之后，把瓶盖拧紧，不久瓶内水的上方形成了水的饱和汽．当温度变化时，瓶内水的饱和汽压与温度变化关系的图像正确的是（）A． B．C．D．6．如图所示，某种自动洗衣机进水时，与洗衣缸相连的细管中会封闭一定质量的空气，通.设温度不变，洗衣缸内水位升高，则过压力传感器感知管中的空气压力，从而控制进水量细管中被封闭的空气A．体积不变，压强变大B．体积变小，压强变小C．体积不变，压强变小D．体积变小，压强变大7．图为某种椅子与其升降部分的结构示意图,M、N两筒间密闭了一定质量的气体，M可沿N的内壁上下滑动，设筒内气体不与外界发生热交换，当人从椅子上离开，M向上滑动的过程中A．外界对气体做功，气体内能增大B．外界对气体做功，气体内能减小C．气体对外界做功，气体内能增大D．气体对外界做功，气体内能减小8．一定质量的理想气体经历一系列状态变化，其p－1V图线如图所示，变化顺序由a→b→c→d→a，图中ab线段延长线过坐标原点，cd线段与p轴垂直，da线段与1V轴垂直．气体在此状态变化过程中()A．a→b，压强减小、温度不变、体积减小B．b→c，压强增大、温度升高、体积增大C．c→d，压强不变、温度升高、体积减小D．d→a，压强减小、温度升高、体积不变9．如图，玻璃管内封闭了一段气体，气柱长度为l，管内外水银面高度差为h，若温度保持不变，把玻璃管稍向上提起一段距离，则( )A．h变大l变小B．,h l均变小C．,h l均变大D．h变小l变大10．一根竖直的弹簧支持着一倒立汽缸的活塞，使汽缸悬空而静止．设活塞和缸壁间无摩擦且可以在缸内自由移动，缸壁导热性能良好，使缸内气体温度总能与外界大气的温度相同，则下列结论中正确的是A．若外界大气压强增大，则弹簧长度将不变，汽缸的上底面距地面的高度将减小B．若外界大气压强减小，则弹簧长度将不变，汽缸的上底面距地面的高度将减小C．若气温升高，则活塞向上移动，汽缸的上底面距地面的高度将增大D．若气温降低，则活塞不动，汽缸的上底面距地面的高度将不变二、多项选择题：（共4小题，每小题4分，共16分.在每小题给出的四个选项中，有多个选项是符合题意的．每小题全选对的得4分，有正确选项但不全的得2分，有错误选项或者不选的不得分．）11．2010年诺贝尔物理学奖授予安德烈·海姆和康斯坦丁·诺沃肖洛夫，以表彰他们在石墨烯材料方面的卓越研究．他们通过透明胶带对石墨进行反复的粘贴与撕开使得石墨片的厚度逐渐减小，最终寻找到了厚度只有0.34nm的石墨烯，是碳的二维结构．如图所示为石墨、石墨烯的微观结构，根据以上信息和已学知识判断，下列说法中正确的是( )A．石墨是晶体，石墨烯是非晶体B．石墨、石墨烯与金刚石都是晶体C．石墨是单晶体，石墨烯是多晶体D．他们是通过物理变化的方法获得石墨烯的12．氧气分子在0 ℃和100 ℃温度下单位速率间隔的分子数占总分子数的百分比随气体分子速率的变化分别如图中两条曲线所示．下列说法正确的是A．图中虚线对应于氧气分子平均动能较小的情形B．图中实线对应于氧气分子在0 ℃时的情形C．图中曲线给出了任意速率区间的氧气分子数目D．与0 ℃时相比，100 ℃时氧气分子速率出现在0～400 m/s区间内的分子数占总分子数的百分比较小13．如图所示，导热性能良好的气缸内用活塞封闭着一定质量、常温常压的气体，气缸固定不动．一条细线一端连结在活塞上，另一端跨过两个光滑的定滑轮后连结在一个小桶上，开始时活塞静止，现不断向小桶中添加细沙,使活塞缓慢向上移动（活塞始终未被拉出，气缸、周围环境温度不变）．则在活塞移动的过程中，下列说法正确的是A．气缸内气体的分子平均动能不变B．气缸内气体的内能变小C．气缸内气体的压强变小D．气缸内气体向外界放热14．如图甲、乙所示，容器A和容器B分别盛有氢气和氧气，用一段细玻璃管连通，管内有一段水银柱将两种气体隔开．当氢气的温度为0℃，氧气温度是20℃时，水银柱保持静止，下列情况中正确A．图甲中氢气升高10℃，氧气升高20℃，水银柱将向B侧移动B．图甲中两气体均升髙10℃，水银柱将向B侧移动C．图乙中两气体均降低10℃，水银柱将向B侧移动D．图乙中两气体均升高20℃，水银柱将向B侧移动三、填空题：（共2个小题,共14分）15．（6分）在发现查理定律时，尚未建立热力学温标，因此在查理定律的原始表述中采用的是摄氏温标。

2020年湖北省武汉市常青第一中学高二政治上学期期末试卷含解析一、选择题（共28小题，每小题2分，共56分。

在每小题的四个选项中，只有一项是最符合题目要求的）20.家庭居室装修成为新的经济增长点说明（）A.追求个性、追求享受成为消费的主流B.人们可以不断制造出新的消费热点C.劳务消费已经是居民最基本的消费D.家庭居室装修能够带动相关产业的发展参考答案：B2. 下列活动中属于实践基本形式的有①医生治病②法官办案③文艺演出④调节分配结构A．②③ B．②④ C．①④ D．③④参考答案：B3. 中国汽车产业通过原始创新、集成创新和引进消化吸收再创新，取得了一系列重大技术创新成果。

首届中国自主汽车技术与产品成果展成功举办引起世界关注。

中国汽车业的发展历程表明( )①创新就是对既往的否定和对现实的肯定②创新的过程必定是“扬弃”的过程③创新推动科技进步和社会生产力发展④创新推动生产关系和人类思维的变革A.①②B. ②③C.①④ D.③④参考答案：4. 恩格斯在马克思墓前的讲话中说，马克思发现了人类历史的发展规律，……人们首先必须吃、喝、住、穿，然后才能从事政治、科学、艺术、宗教等等。

这说明A. 生产力决定生产关系B. 生产活动是人类社会存在和发展的基础C. 人民群众是历史的创造者D. 社会存在决定社会意识参考答案：B5. 经济学中著名的“丰收悖论”是这样表述的：（在完全竞争的市场上）如果某一农场主获得丰收，他的农场收入会增加；如果所有农场主的收成都破丰收记录的话，则他们的农场收入都会下降。

“丰收悖论”反映了A．总收入和总产量成正相关关系B．价格变动对生产有逆向的凋节作用C．在完全竞争的市场下，劳动效率与劳动收益成反比D．需求弹性小的农产品供过于求，会形成买方市场参考答案：D6. 十一届全国人大二次会议听取《政府工作报告》《最高人民法院工作报告》《最高人民检察院工作报告》等。

全国人大代表本着高度负责的态度，以饱满的政治热情，分组审议报告，这些报告最后在全体会议上通过。

2020-2021学年度第二学期武汉市部分重点中学期中考试
高二数学试卷
考试时间：2021年4月26日14：00-16:00 试卷满分：150分
一、单选题（在每小题给出的四个选项中，只有一项是符合题目要求的.本题共8小题，每小题5分，共40分）
1．某校高二（1）班甲、乙两同学进行投篮比赛，他们进球的概率分别是34和45，现甲、乙各投篮一次，恰有一人进球的概率是（ ）.
A ．120
B ．320
C ．720
D ．15
2. 维生素C 又叫抗坏血酸,是一种水溶性维生素,是高等灵长类动物与其他少数生物的必需营养素.现从猕猴桃、柚子两种食物中测得每100克维生素C 的含量(单位:mg),得到茎叶图如图所示,则下列说法中不正确的是( ).
A. 每100克柚子维生素C 含量的众数为121.
B.每100克猕猴桃维生素C 含量的中位数为113.
C.每100克猕猴桃维生素C 含量的极差为32.
D.每100克猕猴桃维生素C 含量的平均数小于每100克柚子维生素C 含量的平均数.
3. 在63()x x
的展开式中，常数项为（ ）. A ．145 B ．105 C ．30 D ．135
4．有8件产品，其中4件是次品，从中有放回地取3次（每次1件），若X 表示取得次品的次数，则(2)P X ≤=（ ）.
A ．38
B ．1314
C ．45
D ．78
5．将序号分别为1，2，3，4，5的5张参观券全部分给4人，每人至少1张，如果分给同一人的2张参观券连号，那么不同的分法种数是（ ）.
A ．96
B ．120
C ．240
D ．24
6．目前，国内很多评价机构经过反复调研论证，研制出“增值评价”方式．下面是某市对。

2019-2020学年湖北省武汉市常青第一中学高二数学理上学期期末试题含解析一、选择题：本大题共10小题，每小题5分，共50分。

在每小题给出的四个选项中，只有是一个符合题目要求的1. 动点P到点M（1，0）与点N（3，0）的距离之差为2，则点P的轨迹是（）A．双曲线B．双曲线的一支C．两条射线D．一条射线参考答案：D【考点】轨迹方程．【分析】根据双曲线的定义：动点到两定点的距离的差的绝对值为小于两定点距离的常数时为双曲线；距离当等于两定点距离时为两条射线；距离当大于两定点的距离时无轨迹．【解答】解：|PM|﹣|PN|=2=|MN|，点P的轨迹为一条射线故选D．2. 已知、均为单位向量，它们的夹角为60°，那么｜＋3|=()学科A．B C．D．4参考答案：C略3. 已知双曲线E的中心为原点，P（3，0）是E的焦点，过P的直线l与E相交于A，B 两点，且AB的中点为N（﹣12，﹣15），则E的方程式为（）A．B．C．D．参考答案：B【考点】双曲线的标准方程；直线与圆锥曲线的综合问题．【分析】已知条件易得直线l的斜率为1，设双曲线方程，及A，B点坐标代入方程联立相减得x1+x2=﹣24，根据=，可求得a和b的关系，再根据c=3，求得a和b，进而可得答案．【解答】解：由已知条件易得直线l的斜率为k=k PN=1，设双曲线方程为，A（x1，y1），B（x2，y2），则有，两式相减并结合x1+x2=﹣24，y1+y2=﹣30得=，从而==1即4b2=5a2，又a2+b2=9，解得a2=4，b2=5，故选B．4. 下列命题中真命题的是（）A．在同一平面内，动点到两定点的距离之差（大于两定点间的距离）为常数的点的轨迹是双曲线；B．在平面内，F1，F2是定点,|F1F2|=6，动点M满足|MF1|+|MF2|=6，则点M的轨迹是椭圆；C．“若-3<m<5则方程是椭圆” ；D．存在一个函数，它既是奇函数，又是偶函数。

2019-2020学年武汉市第十七中学高三英语上学期期末试卷及参考答案第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项ANational Disability Insurance Scheme (方案)The National Disability Insurance Scheme (NDIS) will transform the way Queenslanders with disability are supported and change the way disability services are funded and delivered.Under the scheme, Queenslanders with disability will have choice and control over how they access support and who delivers them. They will also have certainty that they will be supported throughout their lifetime to achieve their personal goals.The NDIS will have an effect on the following programs.School Transport Assistance Program for Students with DisabilityThe NDIS will not disrupt existing services for qualified students. The Queensland Government will also continue to provide school transport assistance for students with disability who are not qualified to receive funding via the NDIS.For more information about the School Transport Assistance Program, and to check your qualification, visit the Education and Training website.Taxi Subsidy (补助金) SchemeThe Queensland Governmenthas lengthened the Taxi Subsidy Scheme (TSS) membership for NDIS qualified members to 31 October, 2022. This will allow more time to solve transport support arrangements under the Commonwealth’s NDIS.You can find more information about the TSS and your qualification on the TransLink website.Disability Parking Permit SchemeNo changes will be made to the Disability parking permit scheme when the NDIS is introduced inQueensland. Current arrangements for this scheme will be maintained.You can find more information on this scheme, and check your qualification, on the Queensland Government website.Public Transport Concessions for People with DisabilityThere will be no change to concessions on public transport for people with disability when the NDIS is introduced inQueensland. TransLink will continue to ensure concessions are provided for disabled persons travelling on public transport inQueenslandwhen the NDIS is introduced.You can find more information about public transport discounts for people with disability, and check your qualification, on the TransLink website,1.Which program helps drive the disabled to and from school?A.Taxi Subsidy Scheme.B.Disability Parking Permit Scheme.C.Public Transport Concessions for People with Disability.D.School Transport Assistance Program for Students with Disability.2.What can we learn about Taxi Subsidy Scheme?A.The scheme is for parking permit.B.The existing membership can be effective for longer time.C.There is no change to current arrangements for the scheme.D.The NDIS will not break off existing services for qualified students.3.What do the four programs have in common?A.They are all related to transport.B.They are all largely affected by NDIS.C.They all can be checked on the same website.D.They all provide discounts for disabled persons.BThe first patient who died on my watch was an older man with a faulty heart. We tried to slow it down with treatment, but it suddenly stopped beating completely. Later, whenever I would have a case like that one, I found myself second-guessing my clinical management. However, it turns out that thinking twice may actually cause more harm than good.In a working paper, Emory University researchers found that when doctors delivering a baby have a bad result, they are more likely to switch to a different delivery method with the next patient, often unnecessarily and sometimes with worse results.Because doctors make so many decisions that have serious consequences, thefalloutfrom second-guessing appears especially large for us. A 2006 study found that if a patient had a bleed after being prescribed (开药)warfarin, the physician was about 20% less likely to prescribe later patients the blood thinner that prevents strokes (中风). However, if a patient was not on warfarin and had a stroke physicians were still no more likely to prescribe warfarin to their other patients.These findings highlight interesting behavioral patterns in doctors. In the blood-thinner study, doctors were more affected by the act of doing harm (prescribing a blood thinner that ended up hurting doctors were more affected by the act of doing harm(prescribing a blood thinner that ended up hurting a patient) and less affected by letting harm happen (not prescribing a blood thinner and the patient having a stroke). Yet a stroke is often more permanent and damaging than a bleed.But this phenomenon is not unique to medicine. ''Overreaction to Fearsome Risks'' holds true for broader society.For instance, sensational headlines about shark attacks on humans in Florida in 2001 caused a panic and led the state to prohibit shark-feeding expeditions. Yet shark attacks had actually fallen that year and, according to the study, such a change was probably unnecessary given the extremely small risk of such an attack happening.Humans are likely to be influenced by emotional and often irrational (不理性的) thinking when processing information, bad events and mistakes. As much as we don't want to cause an unfortunate event to happen again, we need to be aware that a worst situation that can be imagined doesn't necessarily mean we did anything wrong. When we overthink, we fail to rely on thinking based on what we know or have experienced. Instead, we may involuntarily overanalyze and come to the wrong conclusion.I have treated dozens of patients who presented with the same illnesses as my first patient, who died more than a year ago. Instead of second-guessing myself, I trusted my clinical instinct (本能) and stayed the course. Every one of those patients survived. You should trust your instinct in your life, too.4. The first two paragraphs suggest that________.A. bad medical outcomes affect doctorsB delivering babies can be difficult workC. some doctors are not very experiencedD. doctors sometimes make silly mistakes5. In the blood-thinner study, doctors________.A. tend to prescribe less effective medicineB. are more concerned about the patients' safetyC. become less confident in writing a prescriptionD. believe a stroke is more treatable than a bleeding6. What does the underlined word ''fallout'' in Paragraph 3 probably mean?A. ResultB. BenefitC. DifferenceD. Absence7. The author will probably agree that________.A. we should not doubt our own decisionsB. our experience will pave way for our futureC. humans are emotional and irrational on the wholeD. instincts don't necessarily lead to wrong directionsCMy first week working in a restaurant, one of the servers said something that stuck with me: Everyone should work in a restaurant for at least a year. At the time, I didn't get it, but I took the advice to heart and worked in restaurants on and off for the next eight years. Before realizing it, I mastered many important skills, one of which is communication skill.When I was little, I was so shy that I used to hide behind my mom whenever someone spoke to me. And when I first started in restaurants, I had two personalities: Restaurant Lizzy and Home Lizzy. It was easier to pretend to be a different person while at work, since it was so different from who I actually was. But gradually, the skills I learned working in restaurants helped Home Lizzy come out of her shell in the real world.When you work in a restaurant, you don't have the luxury of hiding behind your parents to avoid talking to people. I'm still 110% an introvert, but restaurant work helped me communicate. Working in a restaurant not only helped me speak clearly, deliberately and directly but also taught me how to talk about almost everything. Some guests don't want their servers to interact too much with them, and that's fine. But some sit at the bar simply to chat with you. You learn how to judge your guests' level of interest in communicating with you, and how to exit a conversation at the appropriate time.My restaurant work is something that I'm most proud of and I know I wouldn't be the person I am today without those eight years of experience. If you're still on the fence about working in a restaurant for that long, start with one year. I doubt that you'll look back.8. What did the writer think of the server's words?A. Impressive.B. Ridiculous.C. Amusing.D. Logical.9. What do we infer from Paragraph 2?A. The writer tried different jobs.B. The writer became more sociable.C. The writer used an invented name.D. The writer had a hard time at work.10. Which of the following best describes the writer's restaurant work?A. Boring.B. Relaxing.C. Worthwhile.D. Unchallenging.11. What message does the writer try to convey in this passage?A. A strong-willed soul can reach his goal.B. Things are difficult before they are easy.C. Communication skills advance your career.D. Restaurantwork helps to achieve a better self.DSurfing the Internet for fun will make you a better employee, according to an Australian study.The University of Melbourne study shows that people who use the Internet for their own reasons at work are about 9 percent more productive than those who do not. Study author Brent Coker said, “Surfing the Internet at times helps increase an employee's attention.”“People need to relax for a bit to get back their attention,” Coker said on the university's website. “Having a short break, such as a quick surfing of the Internet, helps the mind to rest itself, leading to a higher total Internet attention for a day's work, and as a result, increases productivity (生产效率),” he said.According to the study of 300 workers, 70 percent of people who use the Internet at work surf the Internet for their own reasons during office hours. Among the most popular surfing activities are searching for information about products, reading online news, playing online games and watching videos. “Firms spend a lot of money on software toblocktheir employees from watching videos, using social networking sites or shopping online,” said Coker. “That's not always a good idea.”However, Coker said the study looked at people who surfed the Internet in moderation (适度), or were on the Internet for less than 20 percent of their total time in the office. “Those who spend too much time surfing the Internet will have a lower productivity than those without.” he said.12. What does the University of Melbourne study mainlyshow?A. People who surf the Internet are good employees.B. Not everyone surfs the Internet for fun during office hours.C. The Internet is becoming more and more important in people's life.D. Surfing the Internet for fun at times during office hours increases productivity.13. Which of the following is NOT mentioned in the passage as one of the most popular surfing activities?A. Watching videos.B. Reading online news.C. Reading online novels.D. Playing online games.14. The underlined word “block” in Paragraph 4 means “________”.A. stopB. organizeC. protectD. separate15. What can we infer from the last paragraph?A. Those who never surf the Internet have the lowest productivity.B. Spending too much time surfing the Internet reduces productivity.C. Most people don't surf the Internet in moderation during office hours.D. People should spend as little time as possible surfing the Internet.第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。

2020年湖北省武汉市第十七中学高二物理上学期期末试卷含解析一、选择题：本题共5小题，每小题3分，共计15分．每小题只有一个选项符合题意1. 右图为某电场的部分电场线。

由图可知A、B两点的场强大小EA EB（选填“>”、“<”或“＝”）。

参考答案：>2. 关于天然放射现象，下列叙述正确的是（）A、若使放射性物质的温度升高，其半衰期将缩短B、β衰变所释放的电子是原子核内的中子转变为质子时产生的C、β衰变所释放的电子是原子核外的电子电离形成的D、α、β、γ三种射线中，γ射线的穿透力最强，电离本领最强参考答案：B3. 关于力，下列说法中错误的是A．力是物体对物体的作用B．力是矢量，它既有大小又有方向C．力可以只有施力物体而没有受力物体D．力是改变物体运动状态的原因参考答案：4. 如图2所示，在条形磁铁从图示位置绕轴转动90°的过程中，放在导轨右端附近的金属棒将( )A．向左运动B．向右运动C．静止不动D．无法判断参考答案：B5. 下列物理量属于矢量的是（）A．速率 B．牛顿 C．质量 D．位移参考答案：D二、填空题：本题共8小题，每小题2分，共计16分6. 质子（）和粒子（）从静止开始经相同的电势差加速后垂直进入同一匀强磁场做圆周运动，则这两粒子的动能之比E k1:E k2= ，轨道半径之比r 1:r 2=，周期之比T1:T2= 。

参考答案：1:2 1:；1:27. （4分）质量为m的汽车，驶过一半径为R的拱桥，到达桥顶时汽车的速度为v，则此时汽车对桥的压力为______________。

参考答案：mg-mv2/R8. 电磁波谱有无线电波、、可见光、紫外线、X射线、γ射线。

参考答案：9. 长为L的导体棒原来不带电，现将一带电量为 +q的点电荷放在距棒左端R处，如图所示。

当棒达到静电平衡后，求棒上感应电荷在棒内中点产生的场强大小、方向。

参考答案：10. （1）完成核反应方程：；（2）已知的半衰期约为 3.8 天，则约经过天，16 g 的衰变后还剩 1 g 。

2019-2020学年湖北省武汉市第十五中学高二数学理测试题含解析一、选择题：本大题共10小题，每小题5分，共50分。

在每小题给出的四个选项中，只有是一个符合题目要求的1. 若复数z满足(i是虚数单位),则z的共轭复数是（）A. B. C. D.参考答案：A因为，所以，因此的共轭复数是，选A.2. P是椭圆上任意一点，F1、F2是焦点，那么∠F1PF2的最大值是（）A．600 B．300 C．1200D．900参考答案：A3. 如角满足，则（）A．B． C. D．参考答案：D由题意可得，选D.4. 过点P(2,2)的直线与圆相切，且与直线垂直，则a=（）A. －1B. 1C. －2D.参考答案：D5. 设函数在区间上单调递减，则实数a的取值范围是（）A. (－∞,2)B. (1,2]C.(0,3]D. (4,+∞)参考答案：B【分析】函数的定义域为，由导函数的解析式可知函数的单调递减区间为，单调递增区间为，据此得到关于a的不等式组，求解不等式组可得实数a的取值范围.【详解】函数的定义域为，由函数的解析式可得：，据此可得函数的单调递减区间为，单调递增区间为，结合题意有：，解得：，即实数a的取值范围是(1，2].本题选择B选项.【点睛】本题主要考查导函数研究函数的单调性，属于中等题.6. 如图所示，在正方体ABCD-A1B1C1D1中，四面体A-B1CD1在面AA1D1D上的正投影图形为参考答案：A7. 若直线与圆相离，则点与圆的位置关系是（）在圆上在圆外在圆内以上都有可能参考答案：C略8. 下列推理是归纳推理的是（）A．由a1=1，a n=3n﹣1，求出s1，s2，s3，猜出数列{a n}的前n项和的表达式B．由于f（x）=xsinx满足f（﹣x）=﹣f（x）对?x∈R都成立，推断f（x）=xsinx为偶函数C．由圆x2+y2=1的面积S=πr2，推断：椭圆+=1的面积S=πabD．由平面三角形的性质推测空间四面体的性质参考答案：A【考点】归纳推理．【分析】直接利用归纳推理的定义，判断选项的正误即可．【解答】解：对于A，设数列﹛a n﹜的前n项和为s n，由a1=1，a n=3n﹣1，求出s1，s2，s3，猜出数列{a n}的前n项和的表达式，满足归纳推理的形式与步骤，所以A正确．对于B，由f（x）=xsinx，满足f（﹣x）=﹣f（x）对?x∈R都成立，推断f（x）=xsinx 为奇函数，是函数的奇偶性的定义的应用，是演绎推理，所以B不正确；对于C，由圆x2+y2=r2的面积s=πr2推断：椭圆+=1（a＞b＞0）的面积S=πab，是类比推理，所以C不正确；对于D，由平面三角形的性质推测空间三棱锥的性质是类比推理，所以D不正确．故选：A．9. 下列说法中正确的是()A．若ac＞bc，则a＞b B．若a2＞b2，则a＞bC．若＞，则a＜b D．若＜，则a＜b 参考答案：D10. 如图，正方体ABCD－A1B1C1D1的棱长为1，线段B1D1上有两个动点E、F，且EF＝，则下列结论中错误的是 ( )A．AC⊥BEB．EF∥平面ABCDC．三棱锥A－BEF的体积为定值D．△AEF的面积与△BEF的面积相等参考答案：D略二、填空题:本大题共7小题,每小题4分,共28分11. 已知三角形两边长分别为2和2，第三边上的中线长为2，则三角形的外接圆半径为．参考答案：2【考点】余弦定理；正弦定理．【分析】设AB=2，AC=2，AD=2，D为BC边的中点，BC=2x，则BD=DC=x，由，且cos∠ADB=﹣cos∠ADC，代入可求BC，则可得A=90°，外接圆的直径2R=BC，从而可求【解答】解：设AB=2，AC=2，AD=2，D为BC边的中点，BC=2x，则BD=DC=x△ABD中，由余弦定理可得，△ADC中，由余弦定理可得，∴∴x=2∴BC=4∴AB2+AC2=BC2即A=90°∴外接圆的直径2R=BC=4，从而可得R=2故答案为：212. 若，，与的夹角为60°，则________________.参考答案：13. 若数列{}的通项公式是则数列{}中最大项；参考答案：14. 在等差数列{a n}中，若a10=0，则有等式a1+a2+…+a n=a1+a2+…+a19-n（n<19，n∈N*）成立，类比上述性质，相应地：在等比数列{b n}中，若b11=1，则有等式 _ 成立.参考答案：15. 设直线过点其斜率为1，且与圆相切，则的值为▲参考答案：16. 采用系统抽样从含有8000个个体的总体（编号为0000，0001，…，，7999）中抽取一个容量为50的样本，已知最后一个入样编号是7900，则最前面2个入样编号是参考答案：0060，022017. 已知，则中共有项．A. B. C.D.参考答案：D略三、解答题：本大题共5小题，共72分。

2019-2020学年武汉市常青第一中学高三语文第三次联考试卷及答案解析一、现代文阅读（36分）(一)现代文阅读I(9分)阅读下面的文字，完成下面小题。

月亮已经升上高空，满天的星星亮晶晶的。

夜很静，刮着小风，不时传来秋虫在草丛中唧唧啾啾的叫声。

老武①看了一阵，觉得浑身更加困乏，便又钻进小窑洞里，躺在草上，脑子里胡乱想着，就睡着了。

老武在小窑洞里不知过了多久，朦朦胧胧听见窑洞门开了。

顺草缝一看，只见门外进来三条黑影。

有个人低声喊：“武同志，武同志！”老武听清是张忠老汉的声音，赶快钻出来一看，原来另两个人影是雷石柱和孟二楞。

老武忙问村里的情形，张忠老汉便把伪军在村里清查的情形仔细说了一遍。

雷石柱接着说：“狗日的没有查出什么来，很生气，临走给维持会②下令，限三天，叫把护村自卫团闹好，赶快放哨，每天黑夜，还要向维持会作口头报告。

”孟二楞也插进来说“他要叫我放哨，我就不放，狗日的！”老武听着没说话；掏出烟袋连着抽了两袋，才说：“既是按年龄强迫编制，恐怕是谁也躲不下。

不过……”停了一刻，继续说：“不过咱们不能让自卫团成了敌人的，一定要想办法，叫自卫团不起作用，同时还要瞅机会搞敌人，把人都拉过来，变成我们的自卫团。

”十月初的一天，正遇上孟二楞被维持会强迫放哨时，村外进来一个人。

那人整整齐齐，穿一身黑衣裳，背个小包被，一副商人打扮，大摇大摆地进来。

孟二楞一见，立时心上一阵火起：“哈！这还不是汉家山常见的那个大汉奸吗！”便上去挡住，大叫一声：“哪里来的？”那人吃一惊，站住脚把孟二楞斜瞟一眼，爱理不理地又要往前走。

孟二楞心上一气，火早已冒起来，跑上去没客气，举手就是一拳打去，那人踉跄倒退几步，脸色一变，也张牙舞爪地要打孟二楞。

刚举起手，叫孟二楞上前一把抓住，用力向后一扭，那人就地转了个圈，胳膊便朝了后。

孟二楞另一只手起来，把那人的脖子一卡，用力往地下一按，那人便“通”一声狗吃屎趴在地上。

孟二楞提起蒜钵似的拳头，照头照背，就是一顿饱打。