【物理】2017-2018学年七宝中学高二上

1.2 排列【基础梳理】【典型例题】题型一 排列数公式及运用【例1】（1）（2019·湖北省松滋市第一中学高二单元测试）,k N +∈且40,k ≤则(50)(51)(52)(79)k k k k ----L 用排列数符号表示为（ ）A ．5079k k A --B ．2979k A -C ．3079k A -D ．3050k A -（2）（2019·安徽六安一中高二月考（理））54886599A A A A +=-（ ） A ．527B ．2554C ．310D ．320（3）解不等式288A 6A x x -<；（4）解方程4321A 140A x x +=.【举一反三】1．（2019·青海高二月考（理））(3)(4)(9)(10)(,10)n n n n n n ----∈>N L 可表示为（ ）A ．93A n -B ．83A n -C ．73A n -D ．73C n - 2．（2019·广东高二期末）计算：812712A A =________. 3. 不等式A x 8<6A x －28的解集为( )A ．[2,8]B ．[2,6]C ．(7,12)D ．{8}4．解方程A 42x ＋1＝140A 3x .题型二 排列概念辨析【例2】（1）下列问题是排列问题的是( )A ．从10名同学中选取2名去参加知识竞赛，共有多少种不同的选取方法？B ．10个人互相通信一次，共写了多少封信？C ．平面上有5个点，任意三点不共线，这5个点最多可确定多少条直线？D ．从1,2,3,4四个数字中，任选两个相加，其结果共有多少种？（2）从3个不同的数字中取出2个：①相加；②相减；③相乘；④相除；⑤一个为被开方数，一个为根指数．则上述问题为排列问题的个数为( )A ．2B ．3C ．4D ．5【举一反三】1.判断下列问题是否为排列问题．(1)会场有50个座位，要求选出3个座位有多少种方法？若选出3个座位安排三位客人，又有多少种方法？ (2)从集合M ＝{1,2，…，9}中，任取两个元素作为a ，b ，可以得到多少个焦点在x 轴上的椭圆方程x 2a 2＋y 2b 2＝1？可以得到多少个焦点在x 轴上的双曲线方程x 2a 2－y 2b 2＝1? (3)从1,3,5,7,9中任取3个数字，有多少种方法？若这3个数字组成没有重复的三位数，又有多少种方法？2.下列问题是排列问题的是 ( )A ．从8名同学中选取2名去参加知识竞赛，共有多少种不同的选取方法？B ．10个人互相通信一次，共写了多少封信？C ．平面上有5个点，任意三点不共线，这5个点最多可确定多少条直线？D ．从1,2,3,4四个数字中，任选两个相乘，其结果共有多少种？题型三 排列的运用【例3-1】（2020·全国高三专题练习）有3名男生、4名女生，在下列不同条件下，求不同的排列方法总数.(1)选5人排成一排；(2)排成前后两排，前排3人，后排4人；(3)全体排成一排，女生必须站在一起；(4)全体排成一排，男生互不相邻；(5)全体排成一排，其中甲不站最左边，也不站最右边；(6)全体排成一排，其中甲不站最左边，乙不站最右边.【例3-2】例2 用0,1,2,3,4,5这六个数字可以组成多少个符合下列条件的无重复数字的数？(1)六位数且是奇数；(2)个位上的数字不是5的六位数；(3)不大于4310的四位数且是偶数．【举一反三】1．（2019·上海中学高二期末）老况、老王、老顾、小周、小郭和两位王女士共7人要排成一排拍散伙纪念照.（1）若两位王女士必须相邻，则共有多少种排队种数？（2）若老王与老况不能相邻，则共有多少种排队种数？（3）若两位王女士必须相邻，若老王与老况不能相邻，小郭与小周不能相邻，则共有多少种排队种数？2．（2019·平罗中学高二月考（理））现有5名男生和3名女生站成一排照相，（1）3名女生站在一起，有多少种不同的站法？（2）3名女生次序一定，但不一定相邻，有多少种不同的站法？（3）3名女生不站在排头和排尾，也互不相邻，有多少种不同的站法？（4）3名女生中，A，B要相邻，A，C不相邻，有多少种不同的站法？3.用数字0,1,2,3,4,5组成没有重复数字的四位数．(1)可组成多少个不同的四位数？(2）可组成多少个不同的四位偶数？(3)在所有的四位数中按从小到大的顺序排成一个数列，则第85个数为多少？4．用1,2,3,4,5,6,7排出无重复数字的七位数，按下述要求各有多少个？(1)偶数不相邻；(2)偶数一定在奇数位上；(3)1和2之间恰夹有一个奇数，没有偶数；(4)三个偶数从左到右按从小到大的顺序排列．【强化训练】1．（2020·全国高三专题练习）A，B，C，D，E，F六人围坐在一张圆桌周围开会，A是会议的中心发言人，必须坐最北面的椅子，B，C二人必须坐相邻的两把椅子，其余三人坐剩余的三把椅子，则不同的座次有（）A．60种B．48种C．30种D．24种2．（2020·浙江高三专题练习）已知5辆不同的白颜色和3辆不同的红颜色汽车停成一排，则白颜色汽车至少2辆停在一起且红颜色的汽车互不相邻的停放方法有（）A．1880 B．1440 C．720 D．2563．（2020·浙江高三专题练习）已知六人排成一排拍照，其中甲、乙、丙三人两两不相邻，甲、丁两人必须相邻，则满足要求的排队方法数为（）A．72B．96C．120D．2884．（2020·浙江高三专题练习）有5个空盒排成一排，要把红、黄两个球放入空盒中，要求一个空盒最多只能放入一个球，并且每个球左右均有空盒，则不同的放入种数为（）A．8 B．2 C．6 D．45．（2020·浙江高三专题练习）某次演出共有6位演员参加，规定甲只能排在第一个或最后一个出场，乙和丙必须排在相邻的顺序出场，请问不同的演出顺序共有（）A．24种B．144种C．48种D．96种6．（2020·黑龙江鹤岗一中高二期末（理））某班上午有五节课，分別安排语文，数学，英语，物理，化学各一节课.要求语文与化学相邻，数学与物理不相邻，则不同排课法的种数是（）A．24 B．16 C．8 D．127．（2019·陕西高三月考（理））将5个人从左至右排成一行，最左端只能排甲或乙，最右端不能排甲，则不同的排法共有( )A．36种B．42种C．48种D．60种8．（2018·平罗中学高二月考（理））《中国诗词大会》（第二季）亮点颇多，十场比赛每场都有一首特别设计的开场诗词在声光舞美的配合下，百人团齐声朗诵，别有韵味．若《将进酒》《山居秋暝》《望岳《送杜少府之任蜀州》和另确定的两首诗词排在后六场，且《将进酒》排在《望岳》的前面，《山居秋暝》与《送杜少府之任蜀州》不相邻且均不排在最后，则后六场的排法有（）A．288种B．144种C．720种D．360种9．（2020·四川高三期末（理））从0，1，3，5，7，9六个数中，任取两个做除法，可得到不同的商的个数是（）A．30 B．25 C．20 D．1910．（2019·河北高三月考（理））2019年7月1日迎来了我国建党98周年，6名老党员在这天相约来到革命圣地之一的西柏坡.6名老党员中有3名党员当年在同一个班，他们站成一排拍照留念时，要求同班的3名党员站在一起，且满足条件的每种排法都要拍一张照片，若将照片洗出来，每张照片0.5元（不含过塑费），且有一半的照片需要过塑，每张过塑费为0.75元.若将这些照片平均分给每名老党员（过塑的照片也要平均分），则每名老党员需要支付的照片费为（）A．20.5 B．21元C．21.5元D．22元11．（2019·海南枫叶国际学校高二期末）由0，1，2，3，4，5这六个数字可以组成没有重复数字且能被5整除的5位数的个数是（）A．144 B．192 C．216 D．24012．（2020·北京高三期末）2019年11月5日，第二届中国国际进口博览会在国家会展中心（上海）开幕，共有155个国家和地区，26个国际组织参加.现有甲、乙、丙、丁、戊、己六家企业参加某主题展览活动，每个企业一个展位.在排成一排的6个展位中，甲、乙、丙三个企业两两互不相邻的排法有________ 种. 13．（2019·上海高三月考）数字不重复，且个位数字与千位数字之差的绝对值等于2的四位数的个数为________.14．（2020·黑龙江哈尔滨三中高二期末（理））某单位安排5位员工在10月3日至7日值班，每天安排1人，每人值班1天．若5位员工中的甲、乙不排在相邻两天，则不同的安排方案共有___________种．（用数字作答）15．（2019·山东师范大学附中高二期中）已知75589n n nA A A -=，则n 的值为________． 16．（2018·海林市朝鲜族中学高二课时练习）设a ∈N *,a<28,则等式(28-a)(29-a)…(35-a)=35am A -中,m=____.17．（2011·江苏高二期中（理））已知1095m n A =⨯⨯⨯L ，则m n +为____________18（2017·上海市七宝中学高二期末）有8名学生排成一排，求分别满足下列条件的排法种数，要求列式并给出计算结果.（1）甲不在两端；（2）甲、乙相邻；（3）甲、乙、丙三人两两不得相邻；（4）甲不在排头，乙不在排尾。

上海市七宝中学2017学年高二第二学期4月月考试卷II. Grammar and VocabularySection ADirections:After reading the passages below, fill in the blanks to make the passages coherent and grammatically correct. For the blanks with a given word, fill in each blank with the proper form of the given word; for the other blanks, use one word that best fits each blank.(A)The Bennets had made plans to dine with the Lucases. And during the main part of the day Miss Lucas was kind enough to spend a lot of time listening sympathetically to Mr. Collins. Elizabeth made sure to thank her, but Charlotte assured her friend that she was happy to be useful, and (1)________ this was worth the little sacrifice of her time.This was very kind, but Charlotte’s kindness went further than Elizabeth (2)________ imagine. Charlotte’s purpose was nothing less than to prevent Mr C ollins from proposing marriage again to Elizabeth, by encouraging him to proposing marriage to (3)________. Miss Lucas would have felt almost certain of her plan’s success if Mr Collins did not plan to leave so very soon.But here she underestimated him, because the very next morning he rushed to Lucas Lodge to swear his love to her. In as short (4)________ time as Mr. Collins long speeches would allow, Miss Lucas accepted his proposal of marriage, and everything was settled down between them.Charlotte did not think highly of men, but marriage (5)________(always be) her only goal. It might not always bring happiness, but it was the only way (6)________ ________ a well-educated young woman who was not rich could live a secure and prosperous life.What she liked the least about the arrangement was the surprise (7)________ would give to Elizabeth Bennet, (8)________ friendship she valued beyond that of any other person.In a private meeting with Elizabeth, she told her of the news.Elizabeth was so astonished that she could not help but (9)________(cry) out: “Engaged to Mr. Collins! My dear Charlotte-that’s impossible!” “Why should you be so surprised, my dear Eliza? Do you think it is unbelievable that any woman could be attracted by Mr. Collins, (10)________ he was not lucky enough to succeed with you?”【答案】1. that 2. could 3. herself 4. a 5. had always been 6. in which 7. that 8. whose 9. cry 10. though【分析】1.考察宾语从句关联词，第二句宾语从句中不缺乏句子成分及句意，填写连词that；注第二句宾语从句连词that不可省。

2017学年七宝中学高二年级月考试卷2017.10一、填空题1.已知，则__________.()()2014,2017,2015,2016OA OB ==AB = 2.等差数列的前项和为，则__________.{}n a n n S ()12lim32nn n nS n S →∞+=+3.已知正的面积是，则__________.ABC ∆AB BC ⋅=4.已知，若，则正数__________.()()()1,,2,20a k b k ==->()()a b a b +⊥- k =5.已知的内角所对的边分别是,若依次成等差数列，且,且Rt ABC ∆,,A B C ,,a b c ,,A B C A B C <<__________.::a b c =6.设等比数列的公比，前项和为，则__________.{}n a 2q =n n S 44S a =7.若三点，若存在实数，使得，则实数__________.()()()2,2,,0,0,4A B a C λAB BC λ=a =8.已知，则__________.()8,1821,92n n nn a n N n *-⎧≤≤⎪⎪=∈⎨⎛⎫⎪≥ ⎪⎪⎝⎭⎩()12lim n n a a a →∞+++= 9.已知等差数列的公差不为零，且，则的最大值是__________.{}n a 11920m n a a a a -+=+mn 10.设两向量，满足，它们的夹角为，若向量与向量夹角为钝角，12,e e 122,1e e == 3π1227te e + 12e te + 则实数的取值范围__________.t 11.设都是非零向量，其中任意两个都不平行，已知，则关于的方程,,a b c ()(),a b c a b c ++x 的解__________.()a c xb +=x =12.给定平面上四点满足，,则面积的最大值为,,,O A B C 4,3,2OA OB OC ===3OB OC ⋅=ABC ∆__________.二、选择题13.已知依次成等比数列，则实数的值为（ ）1,,,,9a x b --x或不确定.A 3.B 3-.C 33-.D 14.下列等式中不恒成立的是（ ）.A a b b a ⋅=⋅ .B ()a b a b λλ⋅=⋅ w o r d 版添加公众号：上海辅导圈.C ()222a ba b ⋅=⋅ .D ()()22a b a b a b -=+⋅- 15.在数列中每相邻两项间插入3个数，使它们与原数列构成一个新数列，则新数列的第41项（ {}n a ）不是原数列的项 是原数列的第10项 .A .B 是原数列的第11项是原数列的第12项.C .D 16.已知数列满足，则下列命题中的真命题是（ ）{}n a ()1120,n n a pa p a R +=+≠∈，则数列一定是等比数列 .A 2p =-{}2n a +，数列不存在极限.B 10,0p a >≠{}n a ，数列一定是等比数列.C 1p ≠21n a p ⎧⎫+⎨⎬-⎩⎭ ，则数列的极限为.D 01p <<{}n a 21p-三、解答题17.已知向量和的夹角为，且.a b 60︒3,4a b ==（1）求向量在方向上的投影；ba（2）若，求实数的取值范围.ka b -≥k 18.已知，且向量不平行，.其中是正实数.2,1a b == ,a b ()()3,5c a t b d ka t b =+-=++,k t （1）若，且，求向量的夹角；2e =0a b e ++= ,a b （2）若，试求的最小值.c d2k t +w o r d 版添加公众号：上海辅导圈19.我们要计算由抛物线轴以及直线所围成的区域的面积,可用轴上的分点2,y x x =1x =S x 反区间分成个小区间，在每个小区间上做一个小矩形，使矩形的左端点在抛物1210,,,,,1n n n n- []0,1n 线上，这些矩形的高分别为，矩形的底边长都是，设所有这些矩形面2y x =2221210,,,,n n n n -⎛⎫⎛⎫⎛⎫⎪⎪ ⎪⎝⎭⎝⎭⎝⎭1n 积的总和为，为求，只须令分割的份数无限增大，就无限趋近于，即.n S S n n S S lim n n S S →∞=（1）求数列的通项公式，并求出；n S S （2）利用同样的思想方法，探求由函数的图像，轴以及直线和所围成的区()212y x x =≤≤x 1x =2x =域的面积.T 20.设数列的前项和为，对一切，点都在的图像上.{}n a n n S n N *∈,nSn n ⎛⎫⎪⎝⎭()2n a f x x x =+（1）证明：当，时，；2n ≥n N *∈()1221n na a n -+=-（2）求数列的通项公式；{}n a （3）设为数列前项积，若不等式对一切恒成立，求实数n T 1n n a a ⎧⎫-⎨⎬⎩⎭n ()32n n a T f a a +<-n N *∈的取值范围.a 21.定义向量的“相伴函数”为函数，的“相伴(),OM ab =()sin cos f x a x b x =+()sin cos f x a x b x =+向量”为，（其中为坐标原点），记平面内所有向量的“相伴函数”构成的集合为.(),OM a b =O S （1）设，求证：；()3sin 4sin 2g x x x π⎛⎫=++ ⎪⎝⎭()g x S ∈（2）已知且，求其“相伴向量”的模；()()cos 2cos h x x x α=++()h x S ∈（3）已知为圆上一点，向量的“相伴函数”在处取得()(),0M a b b ≠()22:21C x y -+=OM()f x 0x x =最大值，当点在圆上运动，求的取值范围.M C 0tan 2x w or d 版添加公众号：上海辅导圈参考答案一、填空题1. 2. 3.4. 5. 6.7. 8. 9. 28-215841936110. 且11.12. 172t -<<-t ≠1+二、选择题13. 14. 15. 16. B C C D三、解答题17. （1）；（2）2[)1,1,3k ⎛⎤∈-∞+∞ ⎥⎝⎦ 18. （1）（2）1arccos 4⎛⎫- ⎪⎝⎭1519. （1）；（2）()()31216n n n n S n --=13S =7320. （1）略（2）（3）2n a n =)0⎛⎫+∞ ⎪ ⎪⎝⎭21. （1）略（2（3）)(0⎡⎣ w o r d 版添加公众号：上海辅导圈。

七宝中学2020―2020学年度第一学期高二物理期末考试卷一、单项选择题(每小题2分，共16分。

每小题只有一个正确选项，将答案写到答题纸上)1．首先发现电流磁效应的物理学家是（）DA．法拉第 B．特斯拉 C．安培 D．奥斯特2．下述说法正确的是( )BA．由E=F/q可知，电场中某点的场强与电场力成正比B．由E=k2rQ可知，点电荷电场中某点的场强与该点电荷的电荷量成正比C．根据场强叠加原理可知，合电场的场强一定大于分电场的场强D．电场线就是点电荷在电场中的运动轨迹3．下图中，表示磁场B的方向、通电直导线中电流I的方向以及通电直导线所受磁场力F的方向，其中正确的是（）C4．如图所示，通有恒定电流的直导线左边有一个矩形线框，线框平面与直导线共面，使线框向右平移并紧贴直导线越过，则线框中的磁通量变化情况为（）AA．先增大后减小，再增大再减小B．先增大到最大，再减小C．先减小后增大，再减小D．不能确定水流方向B5．小船横渡一条河，船头开行方向始终与河岸垂直。

若小船相对水的速度大小不变时，小船的一段运动轨迹如图所示，则河水的流速( )BA．由A到B水速一直增大B．由A到B水速一直减小C．由A到B水速先增大后减小D．由A到B水速先减小后增大6．如右图所示为用“与”门构成的简易报警器的示意电路。

当报警器发出警报声时，电键S1、S2处于的状态为（）CA．S1、S2都断开 B．S1、S2都闭合C．S1闭合，S2断开 D．S1断开，S2闭合7．如右图，M、N和P是以MN为直径的半圈弧上的三点，O点为半圆弧的圆心，∠MOP=60°．电荷量相等、符号相反的两个点电荷分别置于M、N两点，这时O点的场强大小为E1；若将N处的点电荷移至P点，则O点的场强大小变为E2，E1与E2之比为（）BA．1∶2 B．2∶1 C．2∶3D．4∶3【解析】（2020海南卷）依题意，每个点电荷在O点产生的场强为12E，则当N点处的点电荷移至P点时，O点场强如图所示，合场强大小为122EE=，则1221EE=，B正确。

2017-2018学年上海市闵行区七宝中学高一下学期3月周测物理试卷2一、单选题1. 如图所示，S1和S2是两个相干波源，由它们发生的波相互叠加，实线表示波峰，虚线表示波谷，对于a、b、c三点的振动情况，下列判断中正确的是（）A. a点始终是波峰与波峰相遇B. 再过0.25周期，a点为振动减弱的点C. b、c处的振动始终是减弱的D. a、b二点均为振动加强点【答案】D【分析】A.a处是振动加强点，该点位移也是呈周期性变化，不会总是波峰和波峰相遇，故A错误；B.a处是波峰与波峰相遇，振动加强点，振动永远加强，不会成为振动减弱的点。

故B错误；C.b处是波谷与波谷相遇，振动加强点，故C错误；D.结合以上的分析可知，a、b二点均为振动加强点，故D正确；2. 如图所示表示两列同频率相干水波在t=0时刻的叠加情况，图中实线表示波峰，虚线表示波谷，已知两列波的振幅均为2cm，波速为2m/s，波长为0.4m，E点是BD连线和AC连线的交点，下列说法正确的是（）A. A.E.C三点均是振动减弱点B. D.E.B三点均是振动加强点C. B.D两点在该时刻的竖直高度差为4cmD. t=0.05s，E点离开平衡位置2cm【答案】B【分析】A.点A和点C均为波峰与波谷叠加，为振动减弱点.B点是波峰与波峰，D点是波谷与波谷叠加点，即为振动加强点，则E点在振动加强点连线上，也是振动加强点，故A错误，B正确；C.D点在该时刻波峰与波峰叠加，振动加强，偏离平衡位置的位移为4cm，B点在该时刻波谷与波谷叠加，振动加强，偏离平衡位置的位移为−4cm，则D.B两点在该时刻的竖直高度差为8cm；故C错误。

D.波传播的周期T=λv=0.42s=0.2s，再经过t=0.05s时，即为14个周期，E点是波峰与波峰相遇，所以离开平衡位置的位移大小为4cm.故D错误。

3. 如图所示，S1、S2为水波槽中的两个波源，它们分别激起两列水波，图中实线表示波峰、虚线表示波谷。

2017学年第一学期上海七宝中学高二年级10月月考考卷及答案（考试时间120分钟，分值150分）I. Listening comprehension （30）Section ADirections: In Section A, you will hear ten short conversations between two speakers. At the end of each conversation, a question will be asked about what was said. The conversations and the questions will be spoken only once. After you hear a conversation and the question about it, read the four possible answers on your paper, and decide which one is the best answer to the question you have heard.1. A. The way ahead is blocked. B. Their car’s gone wrong.C. They’ve had a car accident.D. Their car is in the way.2. A. In a grocery. B. At a café. C. On an airliner. D.At a restaurant.3. A. $2.75. B. $22.00. C. $11.00. D. $5.50.4. A. Employer and employee. B. Nurse and patient.C. Examiner and examinee.D. Teacher and student.5. A. She used to learn to play the violin. B. She’s just bought a new violin.C. She doesn’t play the violin well.D. She promises to be a violinist.6. A. He is taking a driving test. B. He is learning to change lanes.C. He is looking for a car park.D. He is trying to park his car.7. A. They are having a lesson. B. They are attending a concert.C. They are watching a ball game.D. They are seeing a movie.8. A. He has had no letter from Philip Ross.B. He doesn’t do business with Philip Ross.C. He doesn’t know Philip Ross.D. He doesn’t care about Philip Ross’s business.9. A. Find out what’s happening. B. Get out of the area right away.C. Go and help clear the road.D. Take a short cut down the road.10. A. She’s going to vote against either of the two candidates.B. She wants to know more about the two candidates.C. She is uncertain about her choice of the two candidates.D. She’s decided on the candidate she’s going to vote for.Section BDirections:In section B, you will hear two short passages, and you will be asked three questions on each of the passages. The passages will be read twice, but the questions will be spoken only once. When you hear a question, read the four possible answers on your paper and decide which one would be the best answer to the question you have heard.Questions 11 through 13 are based on the following passage.11. A. Staying on gum trees all day long. B. Having a daily diet of gum leaves.C. Looking for food in a limited area.D. Storing its leafy diet in a large tube.12. A. It lives only in wet land. B. Its body gets slightly wet.C. It takes its mother’s milk.D. It rarely drinks water.13. A. It leaves its mother a year and a half after it is born.B. It’s been carried on its mother’s back since its birth.C. It is tended in its mother’s pouch and then on her back.D. It leaves its mother after birth and grows on gum trees.Questions 14 through 16 are based on the following passage.14. A. Amy Chua’s change one year after the release of her book.B. Amy Chua’s reflection on American education.C. Amy Chua’s prediction of future teenage education.D. Amy Chua’s defense of her idea of parenting.15. A. She received no response from the TV audience.B. She got more invitations to make public speeches.C. She had more followers than she had expected.D. She invited more criticism among the critics.16. A. Super-strict parenting is meant for pre-school children.B. Tiger parenting is appropriate for a certain range of age.C. Parents should stop employing super-strict parenting.D. Less strict parenting is ideal for children of all ages.Section CDirections: In section C, you will hear two longer conversations. The conversations will be read twice. After you hear each conversation, you are required to fill in the numbered blanks with the information you hear. Write your answers on the answer sheet.Blanks 17 through 20 are based on the following conversationBlanks 21 through 24 are based on the following conversationComplete the form. Write NO MORE THAN THREE WORDS for each answer.II. Grammar and VocabularySection A: （16）Read the following two passages. Fill in each blank with one proper word or the proper form of the given word to make the passage coherent. Make sure that your answers are grammatically correct.(A)Parents feel that it is difficult to live with teenagers. Then again, teenagers have similar feelings about their parents, __25_____( say) that it is not easy living withthem. According to a recent research, the most common argument between parents and teenagers is that regarding untidiness and daily routine tasks. On the one hand, parents go mad about messy rooms, clothes thrown on the floor and their children's refusal to help with the housework. On the other hand, teenagers lose their patience continually when parents blame them ____26____ dropping the towel in the bathroom, not ___27___( clean) up their room or refusing to do the shopping at the supermarket.The research , conducted by St. George University, ___28____(show) that different parents have different approaches to these problems. However, some approaches are more popular than others. For example, those parents who yell at their children for their untidiness, but __29___( late ) clean the room for them, have fewer chances of changing their children's behavior. On the contrary, those who let teenagers experience the consequences of their actions can do better. For example, when teenagers who don't help their parents with the shopping don't find their favorite drink in the refrigerator, they ____30___ (force) to reconsider their action.Psychologists say that communication is the most important thing in parent-child relationships. Parents should talk to their children but at the same time they should lend an ear to what they have to say. Parents __31__scold their children when they are untidy but they should also understand that their room is their own private space. Communication is a two-way process. It is only by listening to and understanding each other ___32__problems between parents and children can be settled.(B)Side-effects of drugs are usually provided when patients are advised by doctors to take them whether they are over-the-counter medicine or health nutritional supplements. 33 (convince) that the pills will work wonders inside their bodies, patients usually buy them and take them blindly.In order for a chemical to be considered a safe drug, it must 34 (prove) safe and its benefits outweigh the risks through experiments. However, no substance that has the power to do this is completely safe. Drugs are approved only after tests have demonstrated that they are relatively safe when 35 (use) as directed. Thus some very dangerous drugs are approved because they are necessary to treat serious illnesses. Many people suffer ill effects from drugs called side effects, even though they take the drug exactly as directed. The human population contains a great variety of genetic variation, but drugs 36 (test) on just a few thousand people. When a particular drug is taken by millions, some people 37 not respond in a predictable way, 38 _the drug has been tested. A patient may also acquire a tolerance for a certain drug, 39 means the patient has to take ever larger doses to produce the desired effect. Tolerance may lead to addiction,40 the person becomes sodependent on the drug that he or she will have severe psychological and physical disturbances when the drug is taken away.Section B （38）Directions: Complete the following passage by using the words in the box. Each word can only be used once. Note that there is one word more than you need.Evaluating one's education at the close of each business day, most trained teachers, administrators, politicians, and statesmen made ___41___ analyses of all that has transpired (泄露产生）。

上海市七宝中学2017-2018学年高二上学期期末考试数学试卷一、填空题1.将参数方程122x ty t=+⎧⎨=-⎩,(t R ∈,t 为参数)化为普通方程______________．【答案】250x y +-= 【解析】 【分析】可将2y t =-左右同乘2，再消参即可求解普通方程【详解】2242y t y t =-⇒=-，结合12x t =+可得250x y +-= 故答案为：250x y +-=【点睛】本题考查参数方程转化成普通方程，属于基础题2.已知椭圆22194x y +=，直线2180x y ++=，则椭圆上点到这条直线的最短距离是______________．【答案】5【解析】 【分析】可将椭圆的标准式转化为参数方程，再由点到直线距离公式求解即可【详解】由22194x y +=⇒对应参数方程为：3cos 2sin x y =⎧⎨=⎩θθ，由点到直线距离公式得d ==()sin 1+=-θϕ时，mind ==故答案为：5【点睛】本题考查椭圆参数方程的应用，点到直线的距离公式，属于中档题 3.123101011111111111392733C C C C -+-+--+除以5的余数是【答案】3【解析】试题分析：123101011111111111392733C C C C -+-+--+1111(13)2204820453=-+===+，它除以5余数为3．考点：二项式定理，整除的知识．4.如图为某几何体的三视图，则其侧面积为_______2cm【答案】4π 【解析】 【分析】根据三视图可知几何体为圆锥，利用底面半径和高可求得母线长；根据圆锥侧面积公式可直接求得结果.【详解】由三视图可知，几何体为底面半径为1∴4= ∴圆锥的侧面积：144S ππ=⨯⨯=本题正确结果：4π【点睛】本题考查圆锥侧面积的求解问题，关键是能够根据三视图准确还原几何体，考查学生对于圆锥侧面积公式的掌握情况.5.甲、乙、丙、丁4名同学被随机地分到 、、A B C 三个社区参加社会实践，要求每个社区至少有一名同学，则甲、乙两人被分在同一个社区的概率是______________． 【答案】16【解析】 【分析】可把甲乙看成一个整体，再分到三个社区，算出对应的方法种数，再由题意算出所有的分配种数，结合古典概型公式求解即可【详解】把甲乙看作一个整体，再与其他两人分到、、A B C 三个社区共有33A 种方法，而所有的分配方法有2343C A种，则甲、乙两人被分在同一个社区的概率是33234316A P C A == 故答案为：16【点睛】本题考查排列组合公式的应用，古典概型的求法，属于基础题6.在侧棱长为S ABC -中，40ASB BSC CSA ∠=∠=∠=︒，过A 作截面AEF ，交SB 于E ，交SC 于F ，则截面AEF 周长的最小值为__________．【答案】6 【解析】将棱锥的侧面沿侧棱SA 展开，如图，'AA 的长就是截面AEF 周长的最小值，由题意'120ASA ∠=︒，由等腰三角形的性质得'2cos3026AA SA =︒=⨯=.【点睛】立体几何中的最短距离问题，主要是空间几何体表面上的距离问题，解决此问题的方法是把几何体的表面（或侧面）展开，化空间问题为平面问题，利用平面上两点间线段最短的性质求解．这部分我们要着重掌握直棱柱、正棱锥、正棱台、圆柱、圆锥、圆台的侧面展开图的性质以及展开的方法． 7.长方体1111ABCD A B C D -内接于球O ，且AB BC 2==，1AA =A 、B 两点之间的球面距离为______． 【答案】2π3【解析】 【分析】利用长方体外接球直径为其体对角线长求得外接球半径，及AB 所对球心角，利用弧长公式求出答案．【详解】由2AB BC ==，1AA =得114AC BD ===，∴长方体1111ABCD A B C D -外接球的半径1122BO AO AC AB ==== ABO ∴为正三角形，∴3AOB π∠=，,A B ∴两点间的球面距离为π2π233⨯=， 故答案为：2π3． 【点睛】本题考查了长方体外接球问题，以及求两点球面距离，属于简单题．8.从装有1n +个球（其中n 个白球，1个黑球）的口袋中取出m 个球()0,,m n m n N <≤∈，共有1mn C +种取法．在这1mn C +种取法中，可以分成两类：一类是取出的m 个球全部为白球，一类是取出的m 个球中白球1m -个，则共有01111m m n n C C C C -⋅+⋅种取法，即有等式：011111m m mn n n C C C C C -+⋅+⋅=．试根据上述思想化简下列式子：1122m m m k m kn k n k n k n C C C C C C C ---+⋅+⋅++⋅= ．(1,,,)k m n k m n N ≤<≤∈．【答案】mn k C +【解析】解：在01122m m m k m kk n k n k n k n C C C C C C C C ---+⋅+⋅++⋅=中，从第一项到最后一项分别表示：从装有n 个白球，k 个黑球的袋子里， 取出m 个球的所有情况取法总数的和，故答案应为：从从装有n+k 球中取出m 个球的不同取法数mn k C +故答案为：mn k C +9.在平行六面体ABCD A B C D '-''' 中，4AB = ，3AD = ，5A A '= ，90BAD ∠=︒ ，60A AB A AD ''∠=∠=︒ ，则AC '= __________．【解析】连接AC ，因为04,3,90AB AD BAD ==∠=，所以5AC =, 根据cos cos cos A AB A AC CAB ∠=∠⋅∠''，即1cos 2A AC '=∠045A AC ∠='，则0135C CA ∠=', 而5,5AC AA '==,根据余弦定理得AC '=.点睛：本题考查了几何体的对角线长的求解，以及余弦定理的应用，同时考查了空间象限能力，计算推理的能力，属于中档试题，立体几何是高中数学中的重要内容，也是高考重点考查的考点与热点，此类问题的设置一般有线面位置关系的证明与角度距离的计算等两类问题．10.的线段，在该几何体的侧视图与俯视图中，这条棱的投影分别是长为a 和b 的线段，则+a b 的最大值为 ． 【答案】4 【解析】构造如图所示长方体，长方体的长、宽、高分别为，则，，，，所以。

上海市七宝中学2017学年高二第二学期5月月考试卷II. Grammar and VocabularySection ADirections:After reading the passages below, fill in the blanks to make the passages coherent and grammatically correct. For the blanks with a given word, fill in each blank with the proper form of the given word; for the other blanks, use one word that best fits each blank.(A)Does City Living Hurt Mental Health?People often move to cities (1)________ better jobs and more cultural activities. But are they putting (2)________ at risk? Maybe.Experts at the American Psychiatry Association say that “natural environments or green spaces” do much for good our mental health and (3)________(experience) nature helps people recover from the mental tiredness that comes from day-to-day work.On the other hand, (4)________ they cannot say exactly why, mental health experts say some research suggests that city living might hurt our mental health.Andrea Mechelli is a doctor with the Institute of Psychiatry at Kings College, London. "There have been studies (5)________ people were taken out of an urban environment into a rural environment, and their symptoms would improve. And we also see that the greater the city the greater the risk."Kings College researchers, along with city planners and land and building designers hoped (6)________(learn) more about city living and mental illness. So, they created a smartphone app called Urban Mind. They say they wanted to understand (7)________ different parts of the urban environment affect mental wellbeing.The Urban Mind app (8)________(measure) your experience of city living in the moment. Researchers collected real time information from 108 people, who answered just over 3,000 questions during a one-week period.The researchers found that being outdoors, seeing trees, hearing birdsong, seeing the sky, and feeling in contact with nature (9)________(associate) with higher levels of mental well-being. They also found that these seeming effects of nature were especially strong in those individuals at greater risk of mental health problems.The Urban Mind Project team says it hopes "the results will inform future urban planning and social policy (10)________(intend) to improve design and health."【答案】1.for 2.themselves 3.experiencing 4.although/though 5.where 6.to learn 7.how 8.measures 9.were associated 10.intended【分析】1.考介词。

2017-2018学年上海市闵行区七宝中学高二年级上学期期末考试数学试卷一、填空题（1-6题每题4分，7-12题每题5分，共54分）1.已知复数z =（i 为虚数单位），则z z g =________【答案】13【解析】复数131311313393z z z z ===∴=∴=•==g故答案为132. 若抛物线22y px =的焦点与椭圆2215x y +=的右焦点重合，则_________p =【答案】4p =【解析】椭圆的右焦点（2，0），抛物线的焦点与椭圆的右焦点重合，可得：22p=，解得4p =3. 如果复数z 满足-2z i z i ++=（i 是虚数单位），则z 的最大值为________【答案】1【解析】跟据复数满足的条件，可知复数z 的几何意义是到虚轴上的点到（0，1），（0，-1）的距离之和，z 的最大值为：1。

4. 二元一次方程组232x y a x y b -=⎧⎨+=⎩的增广矩阵通过矩阵变换可得103011⎛⎫ ⎪-⎝⎭，则代数式_____________的值为b a + 【答案】9【解析】跟据已知条件可得3,1x y ==-{32=a912b +-=∴，解得5,4,a b ==549a b ∴+=+=。

5. 直线210ax y +-=与120a x y -++=（）平行，则______________a = 【答案】2【解析】第一个直线与第二个直线的斜率分别为,(1)2aa --，因为两直线平行所以斜率相等所以2a =6. 已知12,x x 是方程230()x mx m R ++=∈的两虚根，则12________x x +=【答案】【解析】12x x Q 与是两虚跟，2121212121,33,3,x x x x x x x x x ∴==∴=∴==g g1212x x x x ∴==∴+=7. 已知集合{}558,A z z z z C =+--=∈与{}4,B z z z C ==∈，则集合A B ⋂中元素个数为_____________【答案】2【解析】集合A 表示双曲线221169x y -=，集合B 表示2216x y += 的圆，双曲线和圆的交点有两个。