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2012北京东城二模化学(WORD)有答案

2012北京东城二模化学(WORD)有答案
2012北京东城二模化学(WORD)有答案

北京市东城区2011—2012学年第二学期高三综合练习(二)

理科综合(化学部分)

可能用到的相对原子质量:H 1 C 12 O 16 Mg 24 Al 27

第一部分(选择题)

6.下列说法正确的是

A. 碘、铁都是人体必需的微量元素

B. 淀粉和纤维素互为同分异构体,均可水解得到葡萄糖

C. 碳酸钡、碳酸氢钠、氢氧化镁等均可作为抗酸药物使用

D. 聚氯乙烯塑料制品可用于食品包装

7.下列说法不正确

...的是

A.46 g C2H6O中共用电子对数为8×6.02×1023

B. 20 g重水(D2O)中含有的电子数为10×6.02×1023

C. 100 mL 2.0 mol·L-1 NH4HCO3溶液中NH4+ 数为0.2×6.02×1023

D. 标准状况下,22.4 L NO与CO的混合气体中含有的原子数为2×6.02×1023

8.下列事实可以用同一原理解释的是

A. 漂白粉和明矾都常用于自来水的处理

B. 乙烯可使溴水或酸性高锰酸钾溶液褪色

C. 铁片和铝片置于冷的浓硫酸中均无明显现象

D. 苯酚和氢氧化钠溶液在空气中久置均会变质

9. 模拟铁的电化学防护的实验装置如右图所示,下列说法不正

..确.的是

A. 若X为碳棒,开关K置于A处可减缓铁的腐蚀

B. 若X为锌棒,开关K置于A或B处均可减缓铁的腐蚀

C. 若X为锌棒,开关K置于B处时,铁电极上发生的反应为

2H++2e—=H2↑

D. 若X为碳棒,开关K置于A处时,铁电极上发生的反应为2H++2e—=H2↑K

A

B

食盐水

X Fe

10. 氢化热是指一定条件下,1 mol 不饱和化合物加氢时放出的热量。表中是环己烯

下列说法正确的是

A. 环己二烯与H 2的反应最剧烈

B. 环己烯、环己二烯和苯有相同的官能团

C. 三种化合物中环己二烯的稳定性最强

D. 上述条件下,1 mol

转变为

时放热113 kJ

11. T ℃时,将6 mol CO 2和8 mol H 2充入2 L 密闭容器中,发生反应CO 2(g)+3H 2(g)

CH 3OH(g)+H 2O(g),容器中H 2的物质的量随时间变化如图中实线所示。图中虚线表示仅改变某一反应条件时,H 2的物质的量随时间的变化。下列说法正确的是

A. 反应开始至a 点时v (H 2)=1 mol·L -1·min -1

B. 若曲线Ⅰ对应的条件改变是升温,则该反应?H >0

C. 曲线Ⅱ对应的条件改变是降低压强

D. T ℃时,该反应的化学平衡常数为0.125 12.根据表中信息判断,下列选项不正确...

的是

A .第①组反应的其余产物为H 2O 和 O 2

B .第②组反应中Cl 2 与 FeBr 2的物质的量之比为1︰2 C. 第③组反应中生成1mol Cl 2,转移电子2mol

D .氧化性由强到弱顺序为MnO 4- > Cl 2 > Fe 3+ > Br 2

n (H 2)/mol t /min

(8,2) (11,2)

(1,6)

a

b

c 2 4 6 8 10

2

4 6 8

第二部分(非选择题)

25.(14分)以苯为原料合成有机物H (结构简式:)的路线如下(A~H 各表

示一种有机物):

已知:RX +

Mg

R —MgX

(R 表示烃基;X 表示卤素原子)

(1)C 的名称是 。

(2) H 在一定条件可制得一种高分子材料,该反应的化学方程式是 。 (3)反应①~⑤中,属于加成反应的有 。

(4的说法正确的是 (填序号)。

a. 与G 互为同系物

b. 能与氢溴酸发生取代反应

c. 能被酸性K 2Cr 2O 7溶液氧化

d. 与氯气光照时发生取代反应可得5种一氯代物 (5)反应⑤的化学方程式是 。

(6)I 是E 的同分异构体,符合下列条件的I 有 种结构,写出其中任意一种的结构

简式: 。

a. 分子中除苯环外不含其他环状结构;苯环侧链中不含“”结构

b. 核磁共振氢谱表明分子中有5种不同化学环境的氢。

—C =C —OH CH —CH 3

OH —— O

+ R —MgX

H +

/H 2O

—C — OMgX R

—C — OH R

乙醚

3OH C CH 2

26.(15分)四种短周期元素W 、X 、Y 、Z ,原子序数依次增大,请结合表中信息回答下列问题。

(1)Z 在元素周期表中位于 族。

(2)上述元素的最高价氧化物对应的水化物中,有一种物质在一定条件下均能与其它三种

物质发生化学反应,该元素是 (填元素符号)。

(3)①下列可作为比较X 和Y 金属性强弱的依据是 (填序号)。

a.自然界中的含量

b.相应氯化物水溶液的pH

c.单质与水反应的难易程度

d.单质与酸反应时失去的电子数 ②从原子结构的角度解释X

的金属性强于Y 的原因: ,原子半径X>Y ,所以原子核对最外层电子的吸引力XY 。

(4)W 的一种氢化物HW 3可用于有机合成,其酸性与醋酸相似。体积和浓度均相等的

HW 3与X 的最高价氧化物对应的水化物混合,反应的化学方程式是 ,混合后溶液中离子浓度由大到小的顺序是 。

(5)Y 单质和Mg 组成的混合物是一种焰火原料,某兴趣小组设计如下所示的实验方案,

测定混合物中Y 的质量分数。

a. m 、n

b. m 、y

c. n 、y

27.(14分)某课外活动小组设计下列实验装置,验证“二氧化碳与水接触时才能和过氧化钠反应”。

(1)过氧化钠与二氧化碳反应的化学方程式是,该反应中,反应物的总能量(填“大于”或“小于” )生成物的总能量。

(2)装置Ⅰ中的试剂是(填序号) 。

a. 稀盐酸

b.稀硫酸

c.小苏打

d.石灰石

(3)实验时,应先打开弹簧夹(填K1 或K2),观察到预期现象后,关闭它,再打开另一个弹簧夹。

(4)实验过程中将带火星的木条置于a口,观察到带火星的木条始终不复燃。

①为观察到最终木条复燃,甲建议在Ⅲ后安装一个盛有碱石灰的干燥管,目的

是;

②乙认为即使采纳甲的建议且最终观察到木条复燃,也不能证明CO2参与了反应,原

因是。

(5)为进一步达到实验目的,应补充的实验是:取最终反应后Ⅲ中所得固体,。

28. (15分)SO 2随意排放会造成严重的大气污染。下列是某小组同学设计处理烟气(主要含SO 2、N 2、O 2、粉尘)中SO 2的方法。

(1)方法一:利用氯碱工业产品处理含SO 2的烟气,流程如下:

①“吸收装置”中发生反应的离子方程式是 ;

②合成塔中每合成1 mol 气体放出热量92.3 kJ (25 ℃、101 kPa ),反应的热化学方程式是 ;

③上述流程中循环利用的物质是 。

(2)方法二:利用FeCl 3溶液的氧化性吸收烟气中的SO 2。

① 该反应的离子方程式是 (反应a )。为验证该反应,同学们将SO 2通入

0.05 mol·L -1

FeCl 3溶液中,溶液很快由黄色变为红褐色;将溶液长时间放置后,最终变为浅绿色。

关于红褐色液体,以下是同学们的分析推测与实验。

② 利用胶体的 (填性质)可以检验步骤ⅰ中是否得到了Fe(OH)3胶体; ③ 根据反应b ,说明步骤ⅱ中液体颜色变化的原因是 (用离子方程式及必要

的文字说明);

④ 经讨论后得出结论:FeCl 3溶液和SO 2反应过程中,反应a 、b 在体系中共存。请从化学反应速率和反应限度的角度分析,SO 2通入FeCl 3溶液中产生上述现象的原因是 。

烟气

参考答案及评分标准

第一部分共20小题,每题6分

6.A

7.C

8.C

9.C 10.D 11.A 12.D 第二部分共11小题,共180分。 25.(共14分) (1)乙醛 (2)

(3)②④ (4)b c (5)

(6)3

、或 中的任意一种

26.(共15分)

(1)ⅣA (2)Na

(3)① b c ②电子层数相同,质子数Y > X

(4)HN 3+NaOH =NaN 3+H 2O c (Na +)>c (N 3-)>c (OH -)>c (H +) (5)a b c 27.(共14分)

(1)2Na 2O 2 +2 CO 2 =2Na 2CO 3 + O 2 大于 (2)b c (3)K 2

(4)①除去未充分反应的CO 2 ②水与Na 2O 2反应生成氧气

(5)加入稀盐酸,将产生的气体通入澄清石灰水(合理答案均给分) 28.(共15分)

(1)① SO 2+OH -=HSO 3-

O —CH =CH 2

CH =CH 2

HO

CH 2

CHO

C 2

浓H 2SO 4

C CH 3

OH +

H 2

O

C 2

n

一定条件

CH 2

n

②H2(g)+Cl2(g)=2HCl(g) H=-184.6 kJ·mol-1

③NaCl溶液

(2)①2Fe3++SO2+2H2O=2Fe2++SO42-+4H+

②丁达尔效应

③加入铁粉时发生反应2Fe3++Fe=3Fe2+,c(Fe3+)减小,使反应b逆向移动

④由于化学反应速率:b>a,化学反应限度:a>b,所以产生上述现象

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