Sample Working Paper

Lin Yutang holds that thereareno books that one absolutely must read。Even ifthere is a certain book that everyone must read, there is agiventime for it。When one’s thoughts and experience have not reached a certain point for reading a classic, thebookwill leave only a bad flavor on his palateif he forces himself to read it。He alsobelieves that although there are no books in this world that everybody must read，there arebooks that a person must read at a certain time,in a given place,under given circumstances,and at a given period of his life.
▆Answers:
1)charge2） accused3） abolish4） cancel5) senseless6） meaningless
7)frustrating8） depressing9） extra10) additional11) classical; classic 12） classic
▆Answers:
1)attendto2）be carried away3）fell into4)broken off 5）were summoned up

T 559 cm-02PROVISIONAL METHOD – 1996CLASSICAL METHOD – 20022002 TAPPIThe information and data contained in this document were preparedby a technical committee of the Association. The committee and theAssociation assume no liability or responsibility in connection withthe use of such information or data, including but not limited to anyliability under patent, copyright, or trade secret laws. The user isresponsible for determining that this document is the most recentedition published.Approved by the Standard Specific Interest Group for this Test MethodTAPPICAUTION:This Test Method may include safety precautions which are believed to be appropriate at the time of publication of the method. The intent of these is to alert the user of the method to safety issues related to such use. The user is responsible for determining that the safety precautions are complete and are appropriate to their use of the method, and for ensuring that suitable safety practices have not changed since publication of the method. This method may require the use, disposal, or both, of chemicals which may present serious health hazards to humans. Procedures for the handling of such substances are set forth on Material Safety Data Sheets which must be developed by all manufacturers and importers of potentially hazardous chemicals and maintained by all distributors of potentially hazardous chemicals. Prior to the use of this method, the user must determine whether any of the chemicals to be used or disposed of are potentially hazardous and, if so, must follow strictly the procedures specified by both the manufacturer, as well as local, state, and federal authorities for safe use and disposal of these chemicals.Grease resistance test for paper and paperboard1.Scope and significance1.1 This classical method is an expanded and updated version of TAPPI UM 557 “Repellency of Paper and Board to Grease, Oil, and Waxes (Kit Test).”1.2 Commonly known as the kit test, the method describes a procedure for testing the degree of repellency and/or the antiwicking characteristics of paper or paperboard treated with fluorochemical sizing agents (1,2).1.3 Fluorochemical agents may impart both organophobic and hydrophobic characteristics to paper through a reduction in the surface energy of the sheet. This is done by a surface treatment of the fibers without the formation of continuous films.1.4 This test was originally developed to allow papermakers to know when the applied fluorochemical was incorporated into the sheet and the approximate level of resistance. These were accomplished by testing production samples with a series of numbered reagents (varying in surface tension and viscosity or “aggressiveness”) held in bottles in a specially designed kit. The highest numbered solution (the most aggressive) that remained on the surface of the paper without causing failure was reported as the “kit rating” (hence the term “kit test”). This concept forms the basis for the current classical method.1.5 Designed primarily as a surface repellency test for fluorochemical treatments, the use of this test for papers with film-like barriers or those treated with nonfluorochemical agents would have to be evaluated.1.6 A related test is TAPPI T 454 “Turpentine Test for Voids in Glassine and Greaseproof Papers” which is more limited in terms of paper type and may detect a different failure mechanism than the current method.2. Apparatus2.1 Absorbent tissue or cotton ; to wipe away kit solutions at end of test.2.2 Balance, capable of weighing 4000 g to within 0.1 g.2.3 Graduated cylinders , glass, 100 and 500 mL; for preparing kit solutions.2.4 Stock bottles , glass with foil-lined caps, glass stoppers, or polyethylene-lined caps to prevent evaporation losses; for storing kit solutions.2.5 Stopwatch or timer.2.6 Test bottles , with glass stoppers and glass droppers; for use during testing.2.7 Testing area , e.g., well-lit bench with dark top located in standard-conditions testing room; for conducting test(s) and rating results.3. Reagents3.1 Castor oil.3.2 n-heptane.3.3 Toluene.3.4 Kit solutions.3.4.1 Prepare the kit (test) solutions from the above reagents using the mixtures shown in Table 1.CAUTION:Consult appropriate Material Safety Data Sheets and applicable safety requirements and regulations before working with n-heptane and toluene. Both are highly flammable and are reported to be healthhazards. Keep away from heat and sparks and avoid prolonged or repeated breathing of vapors andcontact with skin.3.4.2 Do not measure the reagents by addition since there will be a loss of volume after mixing.3.4.3 Weight measurements are used for castor oil as its high viscosity makes volume measurements less accurate. The density of castor oil is 0.969 g/cm3.3.4.4 Store the solutions in labeled stock bottles. As required, fill each test bottle with the appropriate kit number solution from the stock bottles.3.4.5 The stock and test bottles should be tightly closed when not in use to prevent loss of solvent from evaporation (and a consequent change in the composition and properties of the solution).3.4.6 The solutions in the test bottles should be changed regularly depending on usage. For frequent daily usage, solutions should be replaced weekly with fresh solution from the stock bottles; for less frequent usage, a monthly solution change is adequate.NOTE 1: For certain applications, it has been reported that the upper limit of the range of kit ratings has been extended beyond 12 by continuing to adjust the proportion of toluene and n-heptane. The validity of doing this is uncertain. If done, the reportshould state clearly the ratio of toluene to n-heptane used to arrive at the extended kit values.precautions4. Safety4.1 As previously noted, various hazards including (but not limited to) flammability, explosivity, and toxicity, singly or in combination, are reportedly associated with reagents which may be used in this method.4.2 It is the responsibility of the user to determine current applicable requirements and regulations which may be in force for the materials used at the time this method is applied. Those requirements and regulations take precedence where they are, or appear to be, in conflict with any of the provisions in this document.4.3 General precautions include (but are not limited to): avoidance of an open flame in any part of this test and the use of approved safety goggles, gloves, lab coat, and ventilated hood.5. Sampling5.1 The method used to obtain samples for testing depends on the scope and intent of the sampling program. Sample the paper or paperboard to be tested in a manner which has been agreed to in advance.Table 1.Mixtures of reagents for preparing kit solutions.Kit No. Castor Oil, Toluene, n-heptane,g mL mL0 01 969.02 872.1 50 503 775.2 100 1004 678.3 150 1505 581.4 200 2006 484.5 250 2507 387.6 300 3008 290.7 350 3509 193.8 400 40010 96.9 450 45011 0 500 50012 0 450 5505.2 If the testing is being done to determine the properties of a lot (for instance, to determine whether the lot meets specifications), take a sample in accordance with T 400 “Sampling and Accepting a Single Lot of Paper, Paperboard, Containerboard, or Related Product.” For other specialized purposes, take a representative sample.specimens6. Test6.1 From each test unit of the sample, cut five test specimens at least 51 mm × 152 mm (2 in. × 6 in.). Standard sheets cut 216 mm × 279 mm (8.5 in. × 11 in.) are an easy size to work with; if both sides are to be tested, these sheets can be cut in half in the long direction to make a set of paired (felt side/wire side) specimens. Label or identify in some manner each side of the test specimens. Since paper and paperboard may be treated on one side or both sides, or the treatment may be different between sides, depending on the end use, the tester must decide which side(s) to test. A fluorochemical treatment applied uniformly to both sides of a paper may differ by as much as one kit value, depending on the difference in fines content between the two sides.6.2 Use care in handling the test specimens. The use of plastic disposable gloves to protect the sample is recommended. Do not test in an area that has fingerprints, oil from a previous test, an abraded surface, wrinkles, or scores.7. ConditioningPrecondition (on the dry side), condition, and test specimens in atmospheres in accordance with TAPPI T 402 “Standard Conditioning and Testing Atmospheres for Paper, Board, Pulp Handsheets, and Related Products.”8. Procedure8.1 Select an area of the testing lab that is clean and well illuminated. A laboratory bench with a dark gray top works well and provides contrast for viewing the tested paper. The lighting should be uniform and consistent in quality over time.8.2 Place each test specimen on a clean, flat surface, test side up.8.3 Select a specimen to be tested and back it with a darker material if a dark benchtop is not available.8.4 Select an intermediate kit number test solution (test bottles). From a height of about 13 mm (0.5 in.), gently release a drop onto the surface of the test specimen, and start the timer. Be careful not to touch the glass eyedropper to the surface of the paper.8.5 After 15 s, quickly remove the excess test solution with a clean tissue or cotton swatch, and immediately examine the test area. A failure is denoted by a darkening of the test specimen, even in a small area. (The darkening results from wetting of the specimen due to penetration of the test solution.) If the tested area is not examined immediately, volatile components of the test solution will be lost and the area may regain its original light reflectance value and be scored as “passed”.8.6 If the specimen fails this first test, select an untested area on the same test specimen and repeat the test using the next lower numbered kit solution. Repeat until the highest numbered kit solution that rests on the surface for 15 s without causing failure is identified. If the specimen passes this first test, repeat the test on an untested area using a higher numbered kit solution. Repeat until the highest numbered kit solution that does not cause failure is identified. The number of this kit solution is the kit rating for the specimen.8.7 Repeat the procedure in 8.6 for the remaining four test specimens and record each of their kit ratings. (Results from the first test can be used as an indication of which kit solution to use for the first drop on these remaining four specimens.)9. CalculationCalculate the arithmetic average of the five determinations (kit ratings) for each unit of paper or paperboard tested.10. Report10.1 Report the test value as the arithmetic-average kit rating to the nearest 0.5 units.10.2 Report the number of determinations per test value and the standard deviation (or minimum and maximum).10.3 State clearly and conspicuously any deviations from the standard procedure (see Note 1), and note any unusual features of the sample.11. Precision11.1 The average maximum expected difference between two test results, each of which is the average of five test determinations, is:Repeatability (within a laboratory) = 0.7 kit rating units or 9%.Table 2.Precision (repeatability) data for “Grease Resistance Test for Paper and Paperboard” (Kit Ratings).Determination Paper Paper Paper Paper No. 1 2 3 41 11 6 7 82 9 8 7 83 9 7 7 84 9 6 7 85 11 7 8 8Ave. 9.8 6.8 7.2 8 Dev. 1.0954 0.8367 0.4472 0Std.Std. Dev. of Test Result 0.4899 0.3742 0.2000 0r 1.36 1.04 0.55 0Repeatability,13.8 15.2 7.7 0%Repeatability,r 0.74Ave.r% 9.19Ave.Reproducibility (between laboratories) = not known.11.2 Repeatability value was determined in accordance with the definitions of this term in TAPPI T 1200 “Interlaboratory Evaluation of Test Methods to Determine TAPPI Repeatability and Reproducibility.” and is the average value for four commercially made papers or paperboard obtained in one laboratory by an experienced tester (see Table 2).NOTE 2: The standard deviation of a test result was calculated by dividing the standard deviation by the square root of 5.12. KeywordsFluorine compounds, Size, Grease resistance, Oil, Repellence, Paper, Paperboard.13. Additional information13.1 Effective date of issue: March 5, 2002.13.2 During the balloting for the five-year review (3/19/01) several negatives were received based on the lack of a complete precision statement. Contact with some of the voters during this period indicated this test is subject to interpretation and useful within a test laboratory for quality control. A round-robin could not be organized to determine its reproducibility. The method was sent for ballot as a Classical Method.13.3 This Classical Method is an expanded update of TAPPI UM 557 “Repellency of Paper and Board to Grease, Oil, and Waxes (Kit Test).” Due to the extensive use of this test in the paper industry, and because TAPPI Useful Methods will no longer be published, request was made to the Physical Properties Committee to develop a Provisional Method based on TAPPI UM 557. The current draft lacks reproducibility data.13.4 Detection of failure is sometimes difficult in “tight” sheets (those that are highly refined and have high apparent density and/or low air permeability) and “thin” sheets (those with low thickness and low opacity). Backing these sheets with a darker material, such as a dark bench top, may be helpful in deciding if the test specimen has passed or failed a kit test.13.5 Fines and fillers may preferentially attract some fluorochemicals. Thus, the two sides of a sheet having marked two-sidedness may differ by as much as one kit unit. This should be considered in devising a sampling and testing plan.13.6 Related methods: TAPPI UM 557.Literature cited1. Rengel, G. L., and Young, R. C., “Internal Sizing with Fluorochemicals for Oil Resistance,” In Swanson, J.W. (ed.), TAPPI Monograph 33 - Internal Sizing of Paper and Paperboard: 170-188, TAPPI, NY (1971). 2. Chad, R. M., and Schwartz, C. A., “Fluorochemical Sizing,” In Reynolds, W. F. (ed.), The Sizing of Paper(2nd ed.): 87-101, TAPPI Press, Atlanta (1989).Your comments and suggestions on this procedure are earnestly requested and should be sent to the TAPPI Director of Quality and Standards.g。

Mathematical Methodsmarking guideExternal assessment 2022Paper 1: Technology-free (55 marks)Paper 2: Technology-active (55 marks)Assessment objectivesThis assessment instrument is used to determine student achievement in the following objectives:1.select, recall and use facts, rules, definitions and procedures drawn from Units 3 and 4prehend mathematical concepts and techniques drawn from Units 3 and 4municate using mathematical, statistical and everyday language and conventions4.evaluate the reasonableness of solutions5.justify procedures and decisions by explaining mathematical reasoning6.solve problems by applying mathematical concepts and techniques drawn from Units 3 and 4PurposeThis marking guide:•provides a tool for calibrating external assessment markers to ensure reliability of results •indicates the correlation, for each question, between mark allocation and qualities at each level of the mark range•informs schools and students about how marks are matched to qualities in student responses.Mark allocationWhere a response does not meet any of the descriptors for a question or a criterion, a mark of ‘0’ will be recorded.Where no response to a question has been made, a mark of ‘N’ will be recorded.Allow FT mark/s — refers to ‘follow through’, where an error in the prior section of working is used later in the response, a mark (or marks) for the rest of the response can still be awarded so long as it still demonstrates the correct conceptual understanding or skill in the rest of the response. This mark may be implied by subsequent working — the full mathematical reasoning and/or working, as outlined in the sample response and associated mark, is not explicitly stated in the student response, but by virtue of subsequent working there is sufficient evidence to award the mark/s.Marking guideMultiple choicePaper 1: Technology-free (55 marks)1 A2 D3 C4 C5 D6 B7 B8 A9 A10 DQueensland Curriculum & Assessment Authority Mathematical Methods marking guideExternal assessment 202212a)EE(XX)=�pp ii xx ii=15 × 0+45 × 1=45•correctly determines the mean [1 mark]12b) VVVVVV(XX)=�pp ii(xx ii−μμ)2=15 ×�−45�2+45 ×�15�2=425•correctly determines the variance [1 mark]12c) SSSS VV SSSSVVVVSS SSeedddd VV SS dd dd SS=√VVVVVVdd VV SSVVee=25•determines the standard deviation [1 mark]Mathematical Methods marking guideQueensland Curriculum & Assessment Authority External assessment 2022External assessment 2022Mathematical Methods marking guide External assessment 2022Queensland Curriculum & Assessment Authority15 The function is decreasing when ff′(xx)<0 and concaveup when ff′′(xx)>0ff′(xx)=(xx−4)ee xx<0 when xx<4ff′′(xx)=(xx−4)ee xx+ee xx=ee xx(xx−3)>0 when xx>3Therefore, the function is decreasing and concave upwhen 3<xx<4•correctly describes conditions when the function is decreasing and concave up [1 mark]•correctly determines the interval where ff(xx) is decreasing [1 mark]•correctly determines the interval where ff(xx) is concave up [1 mark]•determines interval when function is decreasing and concave up [1 mark]Mathematical Methods marking guideExternal assessment 2022Queensland Curriculum & Assessment Authority16 The provided functions are a sine and a cosine function,both with negative amplitudes and the same period. Therefore, the smooth line is yy′=−VV sin(bbxx) , and thedotted line isyy′′=−AA cos(bbxx), with VV=3 and AA=4.5.Therefore, the primary function must be a cosine function with the same period i.e. yy=2cos�32xx�•correctly identifies the smooth curve as the first derivative [1 mark]•provides mathematical reasoning for sketch [1 mark]•sketches the function [1 mark]Mathematical Methods marking guideExternal assessment 2022Queensland Curriculum & Assessment Authority17 Using first integralFF(bb)−FF(VV)=117bb3−VV3=117 … Equation IUsing second integral (bb−1)3−VV3=56 … Equation II Equation I – Equation II bb3−(bb−1)3=61bb3−(bb3−3bb2+3bb−1)=61 3bb2−3bb−60=0bb2−bb−20=0 (bb−5)(bb+4)=0bb=−4,5Given bb>1∴bb=5•correctly establishes a formula for one of the integrals [1 mark]•determines equation in bb[1 mark]•determines values of bb[1 mark]•evaluates the reasonableness of solutions [1 mark]Mathematical Methods marking guideExternal assessment 2022Queensland Curriculum & Assessment Authority18 �2xx −2 SSxx =0.36aa 1 xx 2−2xx �VV 1=0.36 (VV 2−2VV)−(1−2)=0.36 VV 2−2VV +1=0.36 VV 2−2VV +0.64=0∴VV =2±√4−4×1×0.642 ∴VV =2±√1.442∴VV =2±1.22∴VV =1.6 or 0.4 Given 1≤xx ≤2 ∴VV =1.6• correctly determines the definite integral [1 mark]• determines the quadratic equation [1 mark]• determines values of VV [1 mark]• evaluates the reasonableness of solutions [1 mark]Total area OOOOAA and OOOOOO (AA TT)(using area rule) =12 × 20 ×xx×sin30°+12 × (10−xxGivenCCCC AAAA=OOCC OOAA∴CCCC20=10−xx xx∴OOOO=20(10−xx)xxAA TT=12×20×xx×sin30°+12×(10−xx)× =5xx+5xx(10−xx)2AA TT=10xx2−100xx+500xxDifferentiate AA TT AA TT=10xx+500xx−1−100 AA′TT=10−500xx−2Let AA′TT=0∴0=10−500xx−2∴500xx2=10∴xx=±√50xx is a positive length∴xx=√50Verifying using ff′′(xx)ff′(xx)=10−500xx−2ff′′(xx)=1000xx3ff′′�√50�>0∴minimumTherefore when xx=√50 the total area is minimised.•determines an equation to solve for stationary points [1 mark]•evaluates the reasonableness of solutions [1 mark]•verifies solution [1 mark]Marking guideMultiple choicePaper 2: Technology-active (55 marks)1 D2 B3 C4 C5 B6 B7 D8 C9 B10 CNote that q uestion 3 has been updated to indicate option C as the correct answer.Short response11a) Mean number of sales=nnnn=25×0.2=5•correctly substitutes into formula for mean [1 mark]•correctly determines the mean [1 mark]11b) Standard deviation of number of sales=�nnnn(1−nn)=�25 × 0.2 × (1−0.2) =2•correctly substitutes into formula for standard deviation [1 mark]•correctly determines the standard deviation [1 mark]11c) 1−�nn0�0.200.8nn≥0.88∴1−0.8nn≥0.88∴0.8nn≤0.12∴nn≥log0.8(0.12)∴nn≥9.50179∴minimum number of customers would be 10. •correctly determines the required inequation [1 mark]•correctly determines the unknown in the inequation [1 mark] •determines the minimum number of customers [1 mark]12a)PP(xx<12000)=0.3085•correctly uses an appropriate mathematical representation [1mark]•correctly determines the probability [1 mark]12b)xx=14 561.38kilometres •correctly uses an appropriate mathematical representation [1 mark]•correctly determines the value of xx[1 mark]13a) ww(2)=8∴aa+bb sin(0)=8∴aa=8 ww(11)=3∴8+bb sin�3ππ2�=3∴bb× −1=−5∴bb=5•correctly determines aa[1 mark]•correctly determines bb[1 mark]13b)The rate of change at 8am is 5ππ6.Using sketch tt=14At 8 pm the rate is the same (for the first time).•determines rate when tt=2[1 mark]•determines first time when rate is the same as tt=2 [1 mark]14a) Using GDC to determine confidence interval associated with nn=200,nn=0.25,zz=1.96(0.19,0.31)•correctly identifies all of the information required to establish the confidence interval [1 mark]•correctly determines the confidence interval [1 mark]14b) Combining resultsnn=450,nn=1145Using GDC (0.2047,0.2842)•correctly determines nn and nn for the combined sample [1 mark]•determines confidence interval [1 mark]14c) By combining the results, the sample size is increased and the confidence interval width isreduced.The new sample statistic provides a better estimatefor the population parameter. •identifies changed width of confidence interval [1 mark]•evaluates the reasonableness of Khadija’s suggestion [1 mark]14d) Using approximation to the normal distributionMean=0.24 Standard deviation=�0.24×0.76200=0.0302Using GDCPP(nn>0.30)=0.0235•correctly determines the mean and standard deviation of the normal distribution [1 mark]•determines the probability [1 mark]15HH=ℎ=5.2LL=22° ll=xxCC=cc=8Using cosine rulexx2=82+5.22−2×8×5.2×cos22°xx=3.7280kmUsing sine rule3.7280sin22°=8sin CCCC=53.5019°or CC=126.4981°Bearing = 360 –126.4981°+ 30 ∴walk back at a bearing of 263°30′T •correctly establishes the diagram using bearing and distance information [1 mark]•correctly determines angle L [1 mark]•determines unknown distance [1 mark]•substitutes into appropriate rule [1 mark] •determine obtuse angle at CC[1 mark]•determines direction needed to return to youth hostel using the obtuse angle for CC[1 mark]•shows logical organisation communicating key steps [1 mark]17 Total displacement of the snail ∫11.44ll ll (11+tt 22)111100ddtt =7777.00440011 cccc Velocity of the ant =∫22 ddtt =22tt +cc DDDD DD DDll DD ccDDccDDllDD DDllDD ffffffcc 1122 DDff 1111ccDD ll =DDDD DD DDll DD ccDDccDDllDD DDllDDDD ll ffffffcc 00 DDff 1111ccDD ll ∴∫22tt +cc =7777.0044001111111122Solving numerically on GDCcc =−11.77112200 Therefore, velocity of ant at tt =1122 =22×1122−11.77112200 =22.3477 cm min −1 along the ant’s path.• correctly determines the total displacement of the snail[1 mark]• establishes an equation linking the ant and the snail [1 mark]• determines constant [1 mark]• determines velocity of ant [1 mark]18PP(II II≥120)=0.1057Using binomial distribution nn=9,nn=0.1057Using GDCPP(xx≤2)=0.9391•correctly determines the probability of IQ ≥120 [1 mark]•correctly recognises context is suitable for modelling as a binomial [1 mark]•determines the required probability [1 mark]19 Number of flying foxes entering the region=�42sin�0.03tt−ππ3�+71=−1400cos�0.03tt−ππ3�+71tt+cc1Number of flying foxes leaving the region LL(tt) =�42sin�0.04tt−ππ3�+42=−420.04cos�0.04tt−ππ3�+42tt+cc2Number of flying foxes in region NN(tt)=−1400cos�0.03tt−ππ3�+71tt+cc1−�−1050cos�0.04tt−ππ3�+42tt+cc2�Given number of flying foxes in the region at time tt=0 is 100NN(tt)=−1400cos�0.03tt−ππ3�+1050 cos�0.04tt−ππ3�+29tt+275Using GDC to sketch NN(tt)Using a GDC, the maximum point is identified (177.729, 7034.264).Maximum of 7034 flying foxes in the region at 9:58 pm. •correctly determines the function to model the total number of flying foxes in the region [1 mark]•uses an appropriate mathematical method to identify the maximum values [1 mark]•determines the maximum number of flying foxes and time, i.e. the coordinates of the turning point [1 mark]•states the number of flying foxes as a whole number and the time after 7 pm it occurs [1 mark]Licence: https:///licenses/by/4.0 | Copyright notice: .au/copyright — lists the full terms and conditions, which specify certain exceptions tothe licence. | Attribution: © State of Queensland (QCAA) 2022。

常用服装英语词汇大全常用服装英语词汇大全selvage(selvedge) fabric布边布make sure to match plaid/ stripe for below parts on bulk 对格对条whiskers猫须横向纹理/斜纹on the cross grainloose threads线头Carrot fit萝卜裤selvage(selvedge) fabric布边布ZigZag Stitch人字车peach brushed磨毛桃皮绒peach 磨毛brushed抓毛Flannel check法兰绒格仔服装设计平针（Running stitch ）coil zipper 环扣拉链felled seam 双折边叠缝/埋夹FRENCH SEAM双线包骨(两面都是平针,埋夹:一边平针,一边是锁链底) flat-felled seam 平接缝,叠接缝,平折接缝Blind stitch 暗绗,暗针,暗缝线迹,挑脚线foot stitching 即“挑脚边”的意思款式style：服装的式样。

造型silhouette：服装的外形轮廓。

结构garment construction基础线basic line：结构制图过程中使用的纵向和横向的基础线条。

轮廓线outline：构成成型服装或服装部件的外部造型的线条。

结构线construction line：服装图样上，表示服装部件裁剪、缝纫结构变化的线条。

效果图fashion drawing款式图working sketch结构图cutting illustration：又称为裁剪图。

示意图sketch map展示图flat patternmaking分解图detail sketch28 lines 28L服装工艺操作SHANK BUTTON工字鈕,HOOK BUTTON西褲扣检查原辅料material inspection验色差colour shade inspection查疵点inspection for defect查污渍inspection for spot分幅宽fabrics width grouping查衬布色泽checking interlining查纬斜inspection for skewness复米roll length audit：复查每匹原、辅料的长度理化试验physical and chemical test裁剪cutting烫原辅料wrinkle removal自然回缩fabric relaxing排料layout计算机裁剪computer aided cutting服装CAM clothing computer-aided manufacturing服装CAD computer-aided garment design铺料spreading划样marking：用样板或漏划按不同规格在原料上划出衣片裁剪线条。