studentH必修1综合质量评估
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高中英语学习材料***鼎尚图文理制作***单元质量评估(二)(时间:100分钟满分:120分)第一部分阅读理解(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)阅读下列短文,从每题所给的四个选项(A、B、C和D)中,选出最佳选项。
AGoing to the beach is many Americans' favourite activity.They went swimming in the ocean without giving a thought to what was underwater.But those days are long gone.In the summer of 1988,many of the beaches had to be closed because garbage(废料)from hospitals was found in the water.The garbage included glass bottles with samples of blood,and people were afraid they might get AIDS from the blood.At some beaches,sewage(污物)was found in the water.Americans were shocked by this state of affairs.People didn't think of the underwater garbage because it was out of sight.Some of the most polluted waters still look beautiful.San Francisco Bay is a good example of a beautiful bay that's full of chemicals.Scientists discovered pollution in some lakes and rivers when they found fish with rotting skin.People are told not to eat too much fish because of pollution.Most American cities put their garbage in the ground.But New York and a few other cities put their garbage in the ocean.Boston Harbour is so polluted thatscientists say it won't recover until the next century.The government has ordered the city to build a sewage treatment plant.Cleaning up oceans won't be easy,but people can no longer ignore this challenge.【语篇解读】美国海域受污染情况不容乐观。
阶段质量评估(一 ) Unit 1Friendship姓名: _____________班级:___________学号:____________得分:______________第Ⅰ卷第一部分:听力(共两节,满分30 分 )第一节 (共 5 小题;每题 1.5 分,满分7.5 分 )听下边 5 段对话。
每段对话后有一个小题,从题中所给的 A 、 B 、 C 3 个选项中选出最正确选项,并标在试卷的相应地点。
听完每段对话后,你都有10 秒钟的时间往返答相关小题和阅读下一小题。
每段对话仅读一遍。
1. When will the man leave for London?A. This Thursday. B . This Friday.C. This Saturday.答案:A2. What will the two speakers do first?B . Fix the shelf.A. Look for the new tie.C. Paint the shelf.答案:B3. Where is the Language Arts building?A. On the right of the bridge.B. At the end of Centre Walk.C. Opposite the Physical Education building.答案:C4. Which country are the two foreign girls from?A. China. B . Korea.C. Thailand.答案:A5. What does the man think the woman should have chosen?A . Biology.B . Medicine.C. History.答案:C第二节 (共 15 小题;每题 1.5 分,满分22.5 分 )听下边 5 段对话或独白。
高一第一次评估质量分析背景信息- 时间:XXXX年X月X日- 学校:XXXX中学- 年级:高一- 评估方式:笔试分析目的本文档旨在对高一第一次评估的质量进行分析,并提供有关成绩和学生表现的详细信息。
成绩分析根据我们的统计数据,高一第一次评估的平均分为X分(满分为100分)。
下面是一些具体的成绩数据:- 最高分:X分- 最低分:X分- 优秀学生人数(分数超过90分):X人- 及格人数(分数大于等于60分):X人- 不及格人数(分数小于60分):X人通过分析成绩数据,我们可以得出以下结论:1. 成绩总体分布较为均衡,没有出现明显的极高或极低的情况。
2. 大部分学生的成绩在及格及以上,这是一个积极的表现。
3. 优秀学生的数量较多,表明有一部分学生在这次评估中表现出色。
学生表现分析除了成绩数据,我们还对学生的表现进行了分析。
通过观察学生们在研究和课堂上的表现,我们得出以下结论:1. 多数学生在课堂上表现积极,积极参与讨论和提问。
2. 一些学生在课堂上存在分心和不专注的现象,需要进行进一步的关注和指导。
3. 学生们对学科内容的理解程度参差不齐,需要针对性地进行辅导和帮助。
建议根据以上分析,我们提出以下建议以提升高一学生的研究质量和表现:1. 针对不同层次的学生,采取不同的教学方法和辅导措施,确保每个学生都能得到适合的帮助和指导。
2. 继续鼓励学生积极参与课堂讨论,并提供更多机会让学生发表自己的观点和思考。
3. 针对注意力不集中的学生,提供适当的训练和方法,帮助他们养成良好的研究惯。
4. 加强与家长的沟通,及时了解学生在家庭环境中的情况,以便更好地提供帮助和支持。
结论通过对高一第一次评估的质量进行分析,我们对学生的整体表现和学习情况有了更深入的了解。
基于分析结果,我们提出了相应的建议,希望能够帮助学生们在未来的学习中取得更好的成绩和进步。
综合质量评估(第一至第三章) (120分钟 150分)一、选择题(本大题共12小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的)1.(2015·大庆高一检测)设集合U={0,1,2,3,4,5},集合M={0,3,5},N={1,4,5},则M ∩(U ðN)等于 ( )A.{5}B.{0,3}C.{0,2,3,5}D.{0,1,3,4,5}【解析】选B.因为U ðN={0,2,3},M={0,3,5},所以M ∩(U ðN)={0,3}.【补偿训练】设全集U={x|x<6且x ∈N *},集合A={1,3},B={3,5},则U ð(A ∪B) = ( )A.{1,4}B.{1,5}C.{2,4}D.{2,5} 【解析】选C.由题意知U={1,2,3,4,5}, 又A ∪B={1,3,5},所以U ð(A ∪B)={2,4}. 2.(2015·淮南高一检测)函数y=1ln(x−1)的定义域为 ( )A.(1,+∞)B.[1,+∞)C.(1,2)∪(2,+∞)D.(1,2)∪[3,+∞) 【解析】选C.要使函数y=1ln(x−1)有意义,必须{ln(x −1)≠0,x −1>0,解得{x ≠2,x >1,,故函数的定义域为(1,2)∪(2,+∞). 【补偿训练】函数y=√x +1+12−x的定义域是 ( )A.[-1,2)B.[-1,2)∪(2,+∞)C.(2,+∞)D.[-1,+∞) 【解析】选B.要使函数y=√x +1+12−x有意义,必须{x +1≥0,2−x ≠0,,解得x ≥-1且x≠2,故函数的定义域为[-1,2)∪(2,+∞). 3.下列图形中,不是函数图象的是 ( )【解析】选B.由函数的定义可知:选项B 中存在给定某一实数,有两个值与之对应.【补偿训练】下列各组函数是同一函数的是 ( ) A.y=|x|x 与y=1B.y=|x-1|与y={x −1,x >1,1−x,x <1C.y=|x|+|x-1|与y=2x-1D.y=x 3+x x +1与y=x【解析】选D.A 定义域不同,故不是同一函数. B 定义域不同,故不是同一函数. C 对应法则不同,故不是同一函数.D 定义域与对应法则均相同,所以是同一函数.4.下列函数在其定义域内既是奇函数,又是增函数的是 ( ) A.y=√x B.y=3x C.y=lg|x| D.y=x 3【解析】选D.选项A 中函数的定义域为x ≥0,故不具备奇偶性;选项B 是增函数但不是奇函数;选项C 是偶函数;而选项D 在R 上是奇函数并且单调递增. 5.已知函数f(x)=1+x 21−x 2,则有 ( )A.f(x)是奇函数,且f (1x )=-f(x)B.f(x)是奇函数,且f (1x )=f(x)C.f(x)是偶函数,且f (1x )=-f(x)D.f(x)是偶函数,且f (1x)=f(x) 【解析】选C.因为f(x)=1+x 21−x 2,{x|x ≠±1},所以f (1x )=1+(1x )21−(1x )2=1+1x21−1x 2=x 2+1x 2−1=-x 2+11−x 2=-f(x),又因为f(-x)=1+(−x)21−(−x)2=1+x 21−x 2=f(x),所以f(x)为偶函数.【误区警示】解答本题在推导f (1x )与f(x)的关系时容易出现分式变形或符号变换错误.6.(2015·绍兴高一检测)函数f(x)={x +2,x ≤−1,x 2,−1<x <2,2x,x ≥2,若f(x)=2,则x 的值是( )A.√2B.±√2C.0或1D.√3【解析】选A.当x+2=2时,解得x=0,不满足x ≤-1;当x 2=2时,解得x=±√2,只有x=√2-1<x<2;当2x=2时,解得x=1,不符合x ≥2.故x=√27.已知a=log 20.3,b=20.3,c=0.30.2,则a,b,c 三者的大小关系是 ( ) A.b>c>a B.b>a>cC.a>b>cD.c>b>a【解析】选A.由于a=log20.3<log21=0,0<0.30.2<0.30=1,20.3>20=1,故log20.3<0.30.2<20.3,即a<c<b.【补偿训练】已知函数f(x)=lo g12|x+2|,若a=f(lo g123),b=f((13)0.3),c=f(ln3),则( )A.c<b<aB.b<c<aC.c<a<bD.a<b<c【解题指南】作出函数f(x)=lo g12|x+2|的图象判断此函数的单调性,利用中间量0,1比较lo g123,(13)0.3,ln3的大小,最后利用函数单调性比较a,b,c的大小.【解析】选A.函数y=lo g12|x|的图象如图(1),把y=lo g12|x|的图象向左平移2个单位得到y=lo g12|x+2|的图象如图(2),由图象可知函数y=lo g12|x+2|在(-2,+∞)上是减函数,因为lo g123=-log23<-log22=-1,0<(13)0.3<(13)=1,ln3>lne=1.所以-2<lo g123<(13)0.3<ln3,所以f(lo g123)>f((13)0.3)>f(ln3),即c<b<a.8.(2015·鹰潭高一检测)函数f(x)=2x-1+x-5的零点所在的区间为( )A.(0,1)B.(1,2)C.(2,3)D.(3,4)【解析】选C.利用根的存在性定理进行判断,由于f(2)=2+2-5=-1,f(3)=4+3-5=2,所以f(2)·f(3)<0,又f(x)为单调递增函数,所以函数f(x)=2x-1+x-5的零点所在的区间为(2,3).【补偿训练】函数f(x)=lnx+x3-9的零点所在的区间为( )A.(0,1)B.(1,2)C.(2,3)D.(3,4)【解析】选C.由题意知x>0,且f(x)在其定义域内为增函数,f(1)=ln1+13-9=-8<0,f(2)=ln2+23-9=ln2-1<0,f(3)=ln3+33-9=ln3+18>0,f(4)=ln4+43-9>0,所以f(2)f(3)<0,说明函数在区间(2,3)内有零点.9.某品牌电脑投放市场的第一个月销售100台,第二个月销售200台,第三个月销售400台,第四个月销售790台,则下列函数模型中能较好反映销售量y与投放市场月数x之间的关系的是( )A.y=100B.y=50x2-50x+100C.y=50×2xD.y=100log2x+100【解析】选C.对于A中的函数,当x=3或4时,误差较大.对于B中的函数,当x=4时误差也较大.对于C 中的函数,当x=1,2,3时,误差为0,x=4时,误差为10,误差很小.对于D 中的函数,当x=4时,据函数式得到的结果为300,与实际值790相差很远.综上,只有C 中的函数误差最小.10.(2015·临川高一检测)已知函数f(x)={a x ,x <0,(a −3)x +4a,x ≥0满足对任意x 1≠x 2,都有f(x 1)−f(x 2)x 1−x 2<0成立,则a 的范围是( )A.(0,14] B.(0,1) C.[14,1) D.(0,3)【解析】选A.由于x 1≠x 2,都有f(x 1)−f(x 2)x 1−x 2<0成立,即函数在定义域内任意两点的连线的斜率都小于零,故函数在定义域内为减函数,所以有{0<a <1,a −3<0,a 0≥(a −3)×0+4a,解得0<a ≤14.【补偿训练】若函数f(x)=log m (m-x)在区间[3,5]上的最大值比最小值大1,则实数m=( )A.3-√6B.3+√6C.2-√6D.2+√6【解析】选 B.由题意知m>5,所以f(x)=log m (m-x)在[3,5]上为减函数,所以log m (m-3)-log m (m-5)=1, log mm−3m−5=1,即m−3m−5=m,m 2-6m+3=0,解得m=3+√6或m=3-√6舍去). 所以m=3+√6.11.已知函数y=f(x)是定义在R 上的奇函数,当x ≥0时,f(x)=√x 3则当x<0时,f(x)的表达式是 ( )A.f(x)=√x 3(1-x)B.f(x)=-√x 3(1-x) C.f(x)=√x 3(1+x) D.f(x)=-√x 3(1+x)【解题指南】当x<0时,-x>0,由题意可知f(-x),再利用f(-x)=-f(x),可求f(x). 【解析】选A.设x<0,则-x>0, f(-x)=√−x 3(1-x)=-√x 3(1-x),又因为f(x)为奇函数,所以f(-x)=-f(x), 所以-f(x)=-√x 3(1-x),所以f(x)=√x 3(1-x).12.(2015·鄂州高一检测)若一系列函数的解析式相同,值域相同,但定义域不同,则称这些函数为“孪生函数”,那么解析式为y=2x 2-1,值域为{1,7}的所有“孪生函数”的个数等于 ( )A.6B.7C.8D.9【解析】选D.当y=2x 2-1=1时,解得x=±1,当y=2x 2-1=7时,解得x=±2,由题意可知是“孪生函数”的函数的定义域应为{−1,−2},{−1,2},{1,2},{1,−2},{−1,1,−2},{−1,1,2},{−1,−2,2},{1,−2,2},{−1,1,−2,2}共9个.二、填空题(本大题共4小题,每小题5分,共20分.请把正确答案填在题中横线上)13.(2015·温州高一检测)函数y=a x-1+1a>0,且a ≠1一定过定点 . 【解析】当x-1=0时,y=a x-1+1=a 0+1=2,由此解得x=1,即函数恒过定点(1,2). 答案:(1,2) 14.lg3+2lg2−1lg1.2= .【解析】lg3+2lg2−1lg1.2=lg(3×4)−1lg1.2=lg 1210lg1.2=1.答案:115.(2015·常德高一检测)如果函数f(x)=x2-ax+1仅有一个零点,则实数a的值是.【解析】由于函数f(x)=x2-ax+1仅有一个零点,即方程x2-ax+1=0仅有一个根,故Δ=a2-4=0,解得a=±2.答案:±2【延伸探究】若将函数改为f(x)=x2+ax-4在(0,1)内只有一个零点,则实数a的取值范围是.【解析】由于函数f(x)=x2+ax-4在(0,1)内只有一个零点,且f(0)=-4<0,函数f(x)的图象开口向上,则必有f(1)>0,即1+a-4>0,所以a>3.答案:a>316.对于定义在R上的函数f(x),有如下命题:①若f(0)=0,则函数f(x)是奇函数;②若f(-4)≠f(4),则函数f(x)不是偶函数;③若f(0)<f(4),则函数f(x)是R上的增函数;④若f(0)<f(4),则函数f(x)不是R上的减函数.其中正确的有(写出你认为正确的所有的序号).【解析】例如函数f(x)=x2,f(0)=0,但此函数不是奇函数,故①错误;若函数为偶函数,则在其定义域内的所有的x,都有f(-x)=f(x),若f(-4)≠f(4),则该函数一定不是偶函数,故②正确;对于函数f(x)=x2,f(0)<f(4),但该函数不是R上的增函数,故③错误;由于f(0)<f(4),则该函数一定不是减函数,故④正确.答案:②④三、解答题(本大题共6小题,共70分.解答时应写出必要的文字说明、证明过程或演算步骤)17.(10分)化简:a 43−8a 13b4b 23+2√ab 3+a 23÷(a−23−2√b 3a)×√a·√a 23√√a·√a35(式中字母都是正数).【解析】原式=a 13[(a 13)3−(2b 13)3](a 13)2+a 13·(2b 13)+(2b 13)2÷a 13−2b 13a×(a·a 23)12(a 12·a 13)15=a 13(a 13−2b 13)×a a 13−2b 13×a 56a 16=a13×a ×a23=a 2.18.(12分)(2015·郑州高一检测)已知集合A={x |2≤x <6},B={x |3<x <9}. (1)分别求R (A B)∩ð,(R B ð)∪A.(2)已知C={x |a <x <a +1},若C ⊆B,求实数a 的取值集合. 【解析】(1)因为A ∩B={x |3<x <6}, 所以R (A B)∩ð={x |x ≤3或x ≥6}, 因为R B ð={x|x ≤3或x ≥9}, 所以(R B ð)∪A={x|x<6或x ≥9}.(2)因为C ⊆B,所以{a ≥3,a +1≤9,解之得3≤a ≤8,所以a ∈[3,8].19.(12分)(2015·海口高一检测)已知函数f(x)=lg(1+x)-lg(1-x). (1)求定义域. (2)判断函数的奇偶性. 【解析】(1)由已知得{1+x >0,1−x >0,所以{x >−1,x <1,可得-1<x<1,故函数的定义域为{x |−1<x <1}.(2)f(-x)=lg(1-x)-lg(1+x)=-lg(1+x)+lg(1-x)=-[lg(1+x)−lg(1−x)]=-f(x).所以f(x)=lg(1+x)-lg(1-x)为奇函数.20.(12分)(2015·梅州高一检测)已知函数f(x)是定义在R 上的偶函数,且当x ≤0时f(x)=x 2+4x. (1)求函数f(x)的解析式.(2)画出函数的大致图象,并求出函数的值域.【解析】(1)当x>0时,-x<0,因为函数是偶函数,故f(-x)=f(x), 所以f(x)=f(-x)=(-x)2+4(-x)=x 2-4x,所以f(x)={x 2+4x,x ∈(−∞,0],x 2−4x,x ∈(0,+∞).(2)图象如图所示:函数的值域为[-4,+∞).【补偿训练】(2014·临沂高一检测)已知函数f(x)=log 3(ax+b)的图象经过点A(2,1),B(5,2).(1)求函数f(x)的解析式及定义域. (2)求f(14)÷f (√3+12)的值. 【解析】(1)因为函数f(x)=log 3(ax+b)的图象经过点A(2,1),B(5,2),所以{f(2)=1,f(5)=2,即{log 3(2a +b)=1,log 3(5a +b)=2,所以{2a +b =3,5a +b =9,解得{a =2,b =−1,所以f(x)=log 3(2x-1),定义域为(12,+∞).(2)f(14)÷f (√3+12)=log 327÷log 3√3=3÷12=6. 21.(12分)某公司要将一批不易存放的蔬菜从A 地运到B 地,有汽车、火车两种运输工具可供选择,两种运输工具的主要参考数据如下表:若这批蔬菜在运输过程(含装卸时间)中损耗为300元/h,设A,B 两地距离为xkm.(1)设采用汽车与火车运输的总费用分别为f(x)与g(x),求f(x)与g(x).(2)试根据A,B 两地距离大小比较采用哪种运输工具比较好(即运输总费用最小).(注:总费用=途中费用+装卸费用+损耗费用)【解析】(1)由题意可知,用汽车运输的总费用为:f(x)=8x+1000+(x50+2)·300=14x+1600(x>0),用火车运输的总费用为:g(x)=4x+2000+(x100+4)·300=7x+3200(x>0). (2)由f(x)<g(x)得x<1 6007. 由f(x)=g(x)得x=1 6007. 由f(x)>g(x)得x>1 6007.所以,当A,B 两地距离小于1 6007km 时,采用汽车运输好; 当A,B 两地距离等于1 6007km 时,采用汽车或火车都一样; 当A,B 两地距离大于1 6007km 时,采用火车运输好.【拓展延伸】选择数学模型分析解决实际问题(1)特点:信息由表格数据的形式给出,要求对数据进行合理的转化处理,建立数学模型,解答有关的实际问题.(2)三种常用方法:①直接法:若由题中条件能明显确定需要用的数学模型,或题中直接给出了需要用的数学模型,则可直接代入表中的数据,问题即可获解;②列式比较法:若题所涉及的是最优化方案问题,则可根据表格中的数据先列式,然后进行比较;③描点观察法:若根据题设条件不能直接确定需要用哪种数学模型,则可根据表中的数据在直角坐标系中进行描点,作出散点图,然后观察这些点的位置变化情况,确定所需要用的数学模型,问题即可顺利解决.22.(12分)(2015·成都高一检测)已知函数f(x)=a+b x (b>0,b ≠1)的图象过点(1,4)和点(2,16).(1)求f(x)的表达式.(2)解不等式f(x)>(12)3−x 2.(3)当x ∈(-3,4]时,求函数g(x)=log 2f(x)+x 2-6的值域.【解析】(1)由题知{4=a +b,16=a +b 2,所以{a =0,b =4或{a =7,b =−3(舍去), 所以f(x)=4x .(2)因为4x>(12)3−x2,所以22x>2x2−3,所以2x>x2-3,所以x2-2x-3<0,所以-1<x<3,所以不等式的解集为(-1,3).(3)g(x)=log24x+x2-6=log222x+x2-6=2x+x2-6=(x+1)2-7,因为-1∈(-3,4],所以g(x)min=-7,当x=4时,g(x)max=18,所以值域为[-7,18].关闭Word文档返回原板块。
综合素养评估卷时间:100分钟分数:120分第一部分阅读(共两节,满分50分)第一节(共15小题;每小题2.5分,满分37.5分)阅读下列短文,从每题所给的A、B、C、D四个选项中选出最佳选项。
AIn the coming months, we are bringing together artists from all over the globe, to enjoy speaking Shakespeare’s plays in their own language, in our Globe, within the architecture Shakespeare wrote for. Please come and join us.National Theatre of China Beijing|ChineseThis great occasion(盛会) will be the National Theatre of China’s first visit to the UK. The compa ny’s productions show the new face of 21st century Chinese theatre. This production of Shakespeare’s RichardⅢwill be directed by the National’s Associate Director, Wang Xiaoying.Date & Time: Saturday 28 April, 2:30 p.m. & Sunday 29 April, 1:30 p.m. & 6:30 p.m. Marjanishvili Theatre Tbilisi|GeorgianOne of the most famous theatres in Georgia, the Marjanishvili, founded in 1928, appears regularly at theatre festivals all over the world. This new production of As You Like It is helmed(指导) by the company’s artistic director Levan Tsuladze. Date & Time: Friday 18 May, 2:30 p.m. & Saturday 19 May, 7:30 p.m.Deafinitely Theatre London|British Sign Language (BSL)By translating the rich and humourous text of Love’s Labour’s Lost into the physical language of BSL, Deafinitely Theatre creates a new interpretation of Shakespeare’s comedy and aims to build a bridge between deaf and hearing worlds by performing to both groups as one audience.Date & Time: Tuesday 22 May, 2:30 p.m. & Wednesday 23 May, 7:30 p.m.Habima National Theatre Tel Aviv|HebrewThe Habima is the centre of Hebrew-language theatre worldwide. Founded in Moscow after the 1905 revolution, the company eventually settled in Tel Aviv in the late1920s. Since 1958, they have been recognised as the national theatre of Israel. This production of Shakespeare’s The Merchant of Venice marks their first visit to the UK.Date & Time: Monday 28 May, 7:30 p.m. & Tuesday 29 May, 7:30 p.m.1. Which play will be performed by the National Theatre of China?A. RichardⅢ.B. Love’s Labour’s Lost.C. As You Like It.D. The Merchant of Venice.解析:细微环节理解题。
综合质量评估本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分。
满分150分。
考试用时120分钟。
第Ⅰ卷第一部分:听力(共两节,满分30分)第一节(共5小题;每小题1.5分,满分7.5分)听下面5段对话。
每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。
听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1.How long is the bank open every day?A.Five hours B.Eight hours.C.Nine hours.2.What does the man mean?A.Nobody can help her with her reading.B.The new librarian can help to find a good dictionary.C.The librarian may be of some help to the woman.3.What’s the weather like now?A.It’s cloudy.B.It’s raining.C.It’s snowing.4.What do you think about the man’s English?A.Better and better.B.Worse and worse.C.Faster and faster.5.What did the man like?A.Oranges.B.Apples.C.Pears.第二节(共15小题;每小题1.5分,满分22.5分)听下面5段对话或独白。
每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。
听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,各小题给出5秒钟的作答时间。
每段对话或独白读两遍。
听第6段材料,回答第6至7题。
全方位评估高一学生的综合素质英文版Comprehensive Assessment of High School Freshmen's Overall QualityIn order to evaluate the overall quality of high school freshmen, it is essential to consider a wide range of factors. The assessment should encompass not only academic performance but also personal characteristics, social skills, and extracurricular activities.Academic performance is a key component of the assessment. This includes grades in core subjects such as math, science, language arts, and social studies. In addition, standardized test scores and participation in advanced placement or honors classes should be taken into account.Personal characteristics play a significant role in determining a student's overall quality. These include traits such as responsibility, resilience, creativity, and leadership potential. Observing how students interact with their peers and teachers can provide valuable insights into their character.Social skills are another important aspect of the assessment. The ability to communicate effectively, work collaboratively, and resolve conflicts peacefully are all indicators of a student's social competence. Participation in group projects, clubs, and community service activities can demonstrate these skills.Extracurricular activities offer students the opportunity to showcase their talents and interests outside of the classroom. Participation in sports, music, art, or other hobbies can reveal a student's passion and dedication. These activities also help develop important life skills such as time management and teamwork.Overall, a comprehensive assessment of high school freshmen's overall quality should consider academic performance, personal characteristics, social skills, and extracurricular activities. By taking a holistic approach to evaluation, schools can gain a more complete understanding of their students and better support their growth and development.。
综合评估检测(一)必修1~3(120分钟 135分)Ⅰ. 语言知识及应用(共两节,满分45分)第一节完形填空(共15小题;每小题2分,满分30分)阅读下面短文,掌握其大意.然后从1~15各题所给的A、B、C和D项中,选出最佳选项。
What is Math Anxiety?Math anxiety or fear of math is actually quite common. Math anxiety is quite 1 to stage-fright. Why does someone suffer stage-fright? Fear of something going wrong in front of a crowd? Fear of 2 the lines? Fear of being judged 3 ? Fear of going completely blank? Math anxiety shows fear of some type. The fear that one won’t be able to do the math or the fear that it’s too hard or the fear of failure which often results from having a lack of 4 . For the most part, math anxiety is the 5 about doing the math right, our minds draw a 6 and we think we’ll fail and of course the more frustrated and anxious our minds become, the 7 the chance for drawing blanks.Where Does Math Anxiety Come From?Usually math anxiety results from 8 experiences in mathematics. Math anxiety is often due to poor teaching and poor experiences in math which typically leads to math 9 . When one tries to memorize procedures, rules and routines without much 10 , the math is quickly forgotten and 11 soon sets in. Think about your experiences with one concept—the division of fractions(分数). You probably learned about reciprocals(倒数) and inverses(倒转). Well, you memorized the rule and it 12 . Why does it work? Think of math as memorizing all the procedures—what if you forget a few? Therefore, with this type of strategy, a good 13 will help, but, what if you don’t have a good memory? Understanding the math is critical. Once students 14 they can do the math, the whole notion of math anxiety can be overcome. Teachers and parents play an important 15 in ensuring students understand the mathbeing presented to them.1. A. different B. similar C. far D. familiar2. A. understanding B. memorizing C. forgetting D. reading3. A. poorly B. crazily C. highly D. publicly .4. A. wish B. conscience C. determination D. confidence5. A. fear B. joy C. pleasure D. interest6. A. conclusion B. line C. blank D. comparison7. A. further B. greater C. less D. smaller8. A. unpleasant B. unfair C. unimportant D. unfortunate9. A. anger B. anxiety C. failure D. misunderstanding10. A. forgetting B. using C. understanding D. knowing11. A. panic B. excitement C. agreement D. encouragement12. A. opens B. works C. starts D. runs13. A. memory B. method C. brain D. body14. A. fill B. realize C. confirm D. recognize15. A. task B. aim C. appointment D. role第二节语法填空(共10小题;每小题1. 5分,满分15分)阅读下面短文,按照句子结构的语法性和上下文连贯的要求,在空格处填入一个适当的词或使用括号中词语的正确形式填空。
综合评估检测(一)必修1~3120分钟 150分第一部分听力(共两节,满分30分)第一节(共5小题;每小题1 5分,满分7 5分)听下面5段对话。
每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。
听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
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单元质量评估(二)Unit 2(120 minutes150 marks)PartⅠListening Comprehension(30 marks)Section A(22. 5 marks)Directions: In this section, you will hear six conversations between two speakers. For each conversation, there are several questions and each question is followed by three choices marked A, B and C. Listen carefully and then choose the best answer for each question.You will hear each conversation TWICE.1. When does the conversation take place?A. In the morning.B. At noon.C. In the afternoon.2. Where does the woman work?A. The marketing department.B. The personnel department.C. The accounting department.3. What is the number of the room the man will live in?A. Room 543.B. Room 523.C. Room 513.4. How will the man pay for the fare?A. By credit card.B. By cash.C. By check.5. Where did the accident happen?A. On a highway.B. On a freeway.C. On a road.6. What was strange about the accident?A. Two people got hurt.B. The truck turned over.C. No one was killed.7. What do we know about the conversation?A. It takes place at a restaurant.B. It takes place at the woman’s home.C. It is a telephone conversation.8. How many pizzas does the man order?A. One.B. Two.C. Three.9. What drink is ordered?A. Pineapple juice.B. Tomato juice.C. Orange juice.10. What can we know from the conversation?A. Miles Everson arranged the meeting with the man.B. The man met Miles Everson at a school party.C. The man and Miles Everson met by chance.11. What does Miles Everson do?A. He fixes computers.B. He teaches computer.C. He runs a company.12. How does the woman feel about the news about Everson?A. Excited.B. Surprised.C. Shocked.13. Why are they going to have an interview?A. To find someone to look after their kids.B. To find someone to clean the house.C. To find someone to teach their kids.14. What quality is the least important for them?A. Honest.B. Hardworking.C. Friendly.15. What don’t they like about the last girl they have?A. She did not work hard.B. She was not punctual.C. She always told lies.【听力材料】Conversation 1M: Good morning. My name’s James Goodman.W: Ah, good morning, Mr. Goodman. Nice to meet you. I’m Lucy White from Personnel. Sit down, please.M: Thank you very much.W: Now, have you brought your curriculum vitae with you?M: Oh, my CV. Yes, here it is. There are three copies.W: Have you brought your certificates as well?M: No, I haven’t. I’m awfully sorry. Can I send them to you by mail?W: Yes, that’ll be all right. Now, let’s talk about the post.Conversation 2W: Welcome to our hotel, sir.M: Thank you. My best friend helped me book the hotel and he thinks highly of your hotel.W: Thanks a lot. Please give me your name card, OK?M: Here you are.W: Mr. Lee from Beijing, right. Your room was booked last week.M: Right, which room should I stay?W: OK, sir. Your room is 523, and how long will you stay?M: Four days. I’ll be checking out on Saturday.W: And how will you pay?M: By credit card. Would you like to show me the way?W: Yes, please, and here is your key, sir.Conversation 3W: Was there an accident on the freeway today?M: You haven’t heard about it?W: No, do you know what happened?M: A car knocked into a truck on the 210, but strangely enough the truck turned over.W: Are you serious?M: I’m telling you the truth.W: Did anyone get hurt?M: Two people were injured.W: Well, it’s unbelievable that no one was killed.M: Yes, they were lucky.Conversation 4W: Let me just read that back to you.M: OK.W: Um, one ham and pineapple pizza—large. And one medium tomato with extra cheese. And two orange juices.M: Right. Oh, and better add in some garlic bread.W: Garlic bread. OK. Delivery will be in about fifteen minutes.Conversation 5M: I came across one of our old school friends the other day.W: Oh, yeah? Who was that?M: Miles Everson.W: The computer boy?M: Yeah, you remember. He was always really quiet, just spent his time with his computers. Well, It turns out he now owns his own computer company. It’s been a real success and he’s now a millionaire.W: Miles Everson a millionaire? Who would have believed it!Conversation 6M: So, what sort of person are we looking for?W: Oh, well, they’d have to be reliable, of course. I don’t want to find that we are about to go out and they haven’t shown up, or they are running late or something. M: Oh, yeah, of course. That last kid—what was her name? She. . .W: Oh, please, she was always late, but you have to admit she was a hard worker—always cleaned the house while we were out.M: Well, that’s not so important as far as I’m concerned. I mean they are being paid to look after the kids. If they clean the place up it’s a bonus, but. . .W: But, no. . . we need to be able to trust them, of course—I mean, leaving them here in the house with the kids, you know. . .M: Oh, yeah. Honesty is definitely important.W: Oh, but also they have to be friendly. It’s no good if the kids don’t like them.M: True. So, who should we interview, then?答案:1~5. ABBAB 6~10. BCBCC 11~15. CBABBSection B(7. 5 marks)Directions: In this section, you will hear a short passage. Listen carefully and then fill in the numbered blanks with the information you have heard. Fill in each blank with NO MORE THAN THREE WORDS.You will hear the short passage TWICE.The Swimming Competition Time October the 10th, next Saturday.Place The City Swimming pool.Where to meet At16.When to leave At 8: 00 a. m.How to go there 17.18 Sports uniform and sports shoes. What to bring The student card, some19.What to remember Not to20.Tell the teacher if you don’t feel well and don’t swim if you’re sick.【听力材料】Morning, boys and girls. I’m going to tell you the arrangements for this year’s Swimming Competition. So listen carefully.As you know, the Swimming Competition will be held on October the 10th, next Saturday. We’ll meet here at the school hall first before going to the City Swimming pool. A coach will come and pick us up at eight o’clock sharp. So make sure you come on time. If you get here later than eight o’clock, you will need to stay in the school library. You can read in the library until 5: 00 p. m. .You should bring your student card with you. And you should wear your sports uniform and sports shoes that day. Don’t co me in your casual clothes. Lunch time is from 1: 00 p. m. to 2: 00 p. m. . You should bring some food and drinks with you.There is a small shop next to the pool where you can buy your own food and drinks.When you get to the pool, please remember not to run around. The ground is usually slippery and it’s easy to slip and fall. Last year, one of our students hurt his arm because he chased his classmate. So everyone should be careful this time.One last thing. If you’re swimming that day but don’t fe el well, please tell me or the other teachers. When you’re sick, you should not swim. Safety is very important.OK, that’s all. I hope we’ll enjoy the next Saturday.答案: 16. the school hall17. By coach18. What to wear19. food and drinks20. run aroundPartⅡLanguage Knowledge(45 marks)Section A(15 marks)Directions: For each of the following unfinished sentences there are four choices marked A, B, C and D. Choose the one that best completes the sentence.21. (2014·株洲高一检测)Zhuzhou is a beautiful city there are many famous industries in China and even in the world.A. whereB. whichC. thatD. when【解析】选A。
必修一综合质量评估
Student
本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分,共150分,考试时间120分钟.
第Ⅰ卷(选择题)
一、选择题(本大题共12小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的)
1.已知全集U ={1,2,3,4,5,6,7,8,9},M ={1,3,5,6},N ={1,2,4,7,9},则M ∪(∁U N )等于( )
A .{3,5,8}
B .{1,3,5,6,8}
C .{1,3,5,8}
D .{1,5,6,8}
2.如图,I 是全集,A ,B ,C 是它的子集,则阴影部分所表示的集合是( )
A .(∁I A ∩
B )∩
C B .(∁I B ∪A )∩C
C .(A ∩B )∩∁I C
D .(A ∩∁I B )∩C
3.已知函数f (x )=7+a x -1的图象恒过点P ,则P 点的坐标是( )
A .(1,8)
B .(1,7)
C .(0,8)
D .(8,0)
4.下列各组函数中,表示同一函数的是( )
A .y =x 2和y =(x )2
B .y =lg(x 2-1)和y =lg(x +1)+lg(x -1)
C .y =log a x 2和y =2log a x
D .y =x 和y =log a a x
5.若x =1是函数f (x )=a x +b (a ≠0)的一个零点,则函数h (x )=ax 2+bx 的零点是( )
A .0或-1
B .0或-2
C .0或1
D .0或2
6.若lg x -lg y =a ,则lg ⎝⎛⎭⎫x 23-lg ⎝⎛⎭⎫y 23=( )
A .3a
B .32a
C .a
D .a 2
7.设a =22.5,b =log 12
2.5,c =⎝⎛⎭⎫12 2.5,则a ,b ,c 之间的大小关系是( )
A .c >b >a
B .c >a >b
C .a >c >b
D .b >a >c
8.函数f (x )=3x 2
1-x
+lg(3x +1)的定义域是( ) A.⎝⎛⎭
⎫-13,+∞ B .⎝⎛⎭⎫-13,1 C.⎝⎛⎭⎫-13,13 D .⎝
⎛⎭⎫-∞,-13 9.若实数x ,y 满足|x |-ln 1y
=0,则y 关于x 的函数的图象形状大致是( )
10.设函数
若f (x 0)>1,则x 0的取值范围是( )
A .(-1,1)
B .(-1,+∞)
C .(-∞,-2)∪(0,+∞)
D .(-∞,-1)∪(1,+∞) 11.已知f (x )为奇函数,且当x <0时,f (x )=x 2+3x +2.则当x ∈[1,3]时,f (x )的最小值是( )
A .2
B .14
C .-2
D .-14
12.对于定义域为R 的函数f (x ),若存在非零实数x 0,使函数f (x )在(-∞,x 0)和(x 0,+∞)上与x 轴均有交点,则称x 0为函数f (x )的一个“界点”.则下列四个函数中,不存在“界点”的是( )
A .f (x )=x 2+bx -1(b ∈R )
B .f (x )=|x 2-1|
C .f (x )=2-|x -1|
D .f (x )=x 3+2x
第Ⅱ卷(非选择题)
二、填空题(本大题共4小题,每小题4分,共16分.把答案填在题中横线上)
13.已知集合M ={(x ,y )|y =-x +1},N ={(x ,y )|y =x -1},那么M ∩N 为______.
14.已知函数f (x )=⎩⎪⎨⎪⎧
1,x ∈Q 0,x ∈∁R Q ,则f (f (2π))=____________. 15.对于函数f (x )=ln x 的定义域中任意的x 1,x 2(x 1≠x 2),有如下结论:
①f (x 1+x 2)=f (x 1)·f (x 2);
②f (x 1·x 2)=f (x 1)+f (x 2);
③f (x 1)-f (x 2)x 1-x 2
>0. 上述结论中正确结论的序号是______.
16.已知直线y =mx 与函数f (x )=⎩⎨⎧ 2-⎝⎛⎭⎫13x ,x ≤012x 2+1,x >0的图象恰好有3个不同的公共点,则实数
m 的取值范围是______.
三、解答题(本大题共6小题,共74分.解答应写出文字说明、证明过程或演算步骤)
17.(本小题满分12分)已知全集U =R ,A ={x |2x -4>0},B ={x |2≤2x <16},C ={0,1,2}.
(1)求∁U (A ∩B );
(2)如果集合M =(A ∪B )∩C ,写出M 的所有真子集.
18.(本小题满分12分)已知f (x )=log 2x +1x -1
; (1)求f (x )的定义域和值域;
(2)判断f (x )的奇偶性并证明.
19.(本小题满分12分)已知函数f(x)是定义在R上的奇函数,当x>0时,f(x)=log2x.
(1)求f(x)的解析式;
(2)解关于x的不等式f(x)≤1 2.
20.(本小题满分12分)某服装厂生产一种服装,每件服装的成本为40元,出厂单价定为60元.该厂为鼓励销售商订购,决定当一次订购量超过100件时,每多订购1件,订购的全部服装的出场单价就降低0.02元,根据市场调查,销售商一次订购量不会超过600件.
(1)设销售商一次订购x件,服装的实际出厂单价为p元,写出函数p=f(x)的表达式;
(2)当销售商一次订购多少件服装时,该厂获得的利润最大?最大利润是多少?
21.(本小题满分12分)定义在[-1,1]上的偶函数f (x ),已知当x ∈[0,1]时的解析式为f (x )=-22x +a 2x (a ∈R ).
(1)求f (x )在[-1,0]上的解析式.
(2)求f (x )在[0,1]上的最大值h (a ).
22.(本小题满分14分)已知函数
f (x )=⎩⎨⎧ 2-⎝⎛⎭⎫13x ,x ≤0,12x 2-x +1,x >0.
(1)写出该函数的单调区间;
(2)若函数g (x )=f (x )-m 恰有3个不同零点,求实数m 的取值范围;
(3)若f (x )≤n 2-2bn +1对所有x ∈[-1,1],b ∈[-1,1]恒成立,求实数n 的取值范围.。