Acm试题及答案
- 格式:docx
- 大小:20.77 KB
- 文档页数:18
Acm试题及答案
Acm试题及答案
1001 Sum Problem (2)
1089 A+B for Input-Output Practice (I) (3)
1090 A+B for Input-Output Practice (II) (4)
1091A+B for Input-Output Practice (III) (6)
1092A+B for Input-Output Practice (IV) (7)
1093 A+B for Input-Output Practice (V) (9)
1094 A+B for Input-Output Practice (VI) (11)
1095A+B for Input-Output Practice (VII) (12)
1096 A+B for Input-Output Practice (VIII) (14)
2000 ASCII码排序 (15)
2001计算两点间的距离 (16)
2002计算球体积 (17)
2003求绝对值 (18)
2004成绩转换 (19)
2005第几天? (20)
2006求奇数的乘积 (22)
2007平方和与立方和 (23)
2008数值统计 (24)
2009求数列的和 (25)
2010水仙花数 (27)
2011多项式求和 (28)
2012素数判定 (29)
2014青年歌手大奖赛_评委会打分 (31)
2015偶数求和 (32)
2016数据的交换输出 (34)
2017字符串统计 (35)
2019数列有序! (37) 2020绝对值排序 (38)
2021发工资咯:) (40)
2033人见人爱A+B (41)
2039三角形 (43)
2040亲和数 (44)
1001 Sum Problem
Problem Description
Hey, welcome to HDOJ(Hangzhou Dianzi University Online
Judge).
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3
+ ... + n.
Input
The input will consist of a series of integers n, one integer
per line.
Output
For each case, output SUM(n) in one line, followed by a blank
line. You may assume the result will be in the range of 32-bit
signed integer.
Sample Input
1
100
Sample Output
1
5050
Author
DOOM III
解答:
#include
main()
{ int n,i,sum;
sum=0;
while((scanf("%d",&n)!=-1))
{
sum=0;
for(i=0;i<=n;i++)
sum+=i;
printf("%d\n\n",sum);
}
}
1089 A+B for Input-Output Practice
(I)
Problem Description
Your task is to Calculate a + b.
Too easy?! Of course! I specially designed the problem for
acm beginners.
You must have found that some problems have the same
titles with this one, yes, all these problems were designed for the
same aim.
Input
The input will consist of a series of pairs of integers a and b,
separated by a space, one pair of integers per line.
Output
For each pair of input integers a and b you should output the
sum of a and b in one line, and with one line of output for each
line in input.
Sample Input
1 5
10 20
Sample Output 6
30
Author
lcy
Recommend
JGShining
解答:
#include
main()
{
int a,b;
while(scanf("%d%d",&a,&b)!=EOF)
printf("%d\n",a+b);
}
1090 A+B for Input-Output Practice
(II)
Problem Description
Your task is to Calculate a + b.
Input
Input contains an integer N in the first line, and then N lines
follow. Each line consists of a pair of integers a and b, separated
by a space, one pair of integers per line.
Output
For each pair of input integers a and b you should output the
sum of a and b in one line, and with one line of output for each
line in input.
Sample Input
2
1 5
10 20 Sample Output
6
30
Author
lcy
Recommend
JGShining
解答:
#include
#define M 1000
void main()
{
int a ,b,n,j[M],i;
//printf("please input n:\n");
scanf("%d",&n);
for(i=0;i
{
scanf("%d%d",&a,&b);
//printf("%d %d",a,b);
j[i]=a+b;
}
i=0;
while(i
{
printf("%d",j[i]); i++;
printf("\n");
}
}
1091A+B for Input-Output Practice (III)
Problem Description Your task is to Calculate a + b.
Input
Input contains multiple test cases. Each test case contains a
pair of integers a and b, one pair of integers per line. A test case
containing 0 0 terminates the input and this test case is not to be
processed.
Output
For each pair of input integers a and b you should output the
sum of a and b in one line, and with one line of output for each
line in input.
Sample Input
1 5
10 20
0 0
Sample Output
6
30
Author
lcy
Recommend
JGShining
解答:
#include
main()
{
int a,b;
scanf("%d %d",&a,&b);
while(!(a==0&&b==0))
{
printf("%d\n",a+b); scanf("%d %d",&a,&b);
}
}
1092A+B for Input-Output Practice (IV)
Problem Description
Your task is to Calculate the sum of some integers.
Input
Input contains multiple test cases. Each test case contains a
integer N, and then N integers follow
in the same line. A test case starting with 0 terminates the
input and this test case is not to be processed.
Output
For each group of input integers you should output their sum
in one line, and with one line of output for each line in input.
Sample Input
4 1 2 3 4
5 1 2 3 4 5
Sample Output
10
15
Author
lcy
Recommend
JGShining
解答:
#include
int main()
{
int n,sum,i,t;
while(scanf("%d",&n)!=EOF&&n!=0)