《高级语言程序设计》课程设计说明书设计题目：编写万年历系统目录第1章需求分析 (2)第2章概要设计 (2)第3章详细设计 (5)第4章运行结果及分析 (12)第5章课程设计心得 (17)参考文献 (17)1第1章需求分析（1）程序运行时，首先给出六个菜单选项和输入提示：图1（2）用户可以通过主菜单选择不同选项。
输入1，通过输入具体日期可显示该日的星期；输入2，通过输入年份可判断是否是闰年；若输入3，打印某年的年历；输入4，打印某年某月的日历；输入5，查询某月的最大天数；输入6，退出。
第2章概要设计1．闰年的判断：计算所输入的年份是否可被4整除，若不能被整除，为平年。
若可被4整除，计算此年份能否被100整除，不能被100整除则为闰年。
既能被4整除，也能被100整除的年份，若也能被400整除，则为闰年，否则为平年。
闰年366天，平年365天3图2代码：int runnian(int year){if(year%4==0&&year%100!=0||year%400==0) return 1;elsereturn 0;}2．判断某月的天数；通过函数：int day1(int year,int month){int a[12]={31,28,31,30,31,30,31,31,30,31,30,31}; 若为闰，则二月为29天。
图2-1代码：if(runnian(year))a[1]=29;3.打印年历第3章详细设计#include <stdio.h>#include <stdlib.h>bool isLeapyear( int nowYear );int calcuWeek( int totalDays );int calcuDays( int nowYear,int nowMonth,int nowDay );bool checkValid( int nowYear,int nowMonth,int nowDay ); void nowMonthprint( int nowYear,int nowMonth,int nowDay );5void weekDayPrint( int nowYear,int nowMonth,int nowDay );void nowYearprint( int nowYear );void menuPrint();const int leapDay[12]={31,29,31,30,31,30,31,31,30,31,30,31};//存储闰年每月天数const int noleapDay[12]={31,28,31,30,31,30,31,31,30,31,30,31};//存储非闰年每月天数int main(){int year,month,day;while( true ){menuPrint();int op;scanf("%d",&op);switch( op ){case 1:{printf("请输入年月日（格式为YYYY-MM-DD）：");scanf("%d-%d-%d",&year,&month,&day);if ( checkValid(year,month,day) )weekDayPrint(year,month,day);else{printf("输入错误!!!退出操作\n");break;}break;}case 2:{printf("请输入需要查询的年份：");scanf("%d",&year);if( year > 9999 || year < 0 ){printf("年份输入错误!!!退出操作\n\n");}if ( isLeapyear( year ) )printf("%-4d年是闰年！！！\n\n",year);elseprintf("%-4d年是平年！！！\n\n",year);break;}case 3:printf("请输入需要查询的年份：");scanf("%d",&year);if( year > 9999 || year < 0 ){printf("年份输入错误!!!退出操作\n\n");break;}nowYearprint(year);break;case 4:printf("请输入年月日（格式为YYYY-MM-DD）：");scanf("%d-%d-%d",&year,&month,&day);if ( checkValid(year,month,day) )nowMonthprint(year,month,day);else{printf("输入错误!!!退出操作\n");break;}break;case 5:int maxdays;printf("请输入需要查询的年份及月份（格式YYYY-MM）："); scanf("%d-%d",&year,&month);if( year > 9999 || year < 0 || month > 12 || month < 0 ){printf("年份及月份输入错误!!!退出操作\n\n");7}if ( isLeapyear(year))maxdays = leapDay[month-1];elsemaxdays = noleapDay[month-1];printf("%d年%d月最大天数为%d\n\n",year,month,maxdays);break;case 6:printf("退出系统，谢谢使用\n\n");return 0;break;}}return 0;}bool isLeapyear( int nowYear ) // 判断是否闰年{if( nowYear%4 == 0 && nowYear%100 != 0 || nowYear%400 == 0) return true;elsereturn false;}bool checkValid( int nowYear,int nowMonth,int nowDay )// 输入合法性检查{if ( nowYear <= 0 ){printf( "输入年份不合法！！！");return false;}if ( nowMonth < 0 && nowMonth > 12 ){printf("输入月份不合法！！！");return false;}if ( nowDay < 0 && nowDay > 31 && isLeapyear(nowYear) ){printf("输入号数不合法！！！");return false;}if ( nowDay < 0 && nowDay > 30 && !isLeapyear(nowYear) ) {printf("输入号数不合法！！！");return false;}return true;}int calcuDays( int nowYear,int nowMonth,int nowDay )// 计算总天数{int days = 0;int mon = 0;for ( int i = 1;i < nowYear;i++ ){if( isLeapyear( i ) )days += 366;elsedays += 365;}for ( int j = 1;j < nowMonth;j++ ){if ( isLeapyear(nowYear) )mon = mon + leapDay[j-1];elsemon = mon + noleapDay[j-1];}days = days + mon + nowDay;return days;}int calcuWeek( int totalDays ) // 计算星期几{int weekNo = totalDays%7;9return weekNo;}void weekDayPrint( int nowYear,int nowMonth,int nowDay ) //打印某年某日星期几{int days = calcuDays(nowYear,nowMonth,nowDay);int weekNo = calcuWeek( days );switch ( weekNo ){case 0:printf( "%-4d年%-2d月%-2d日是星期天！！！",nowYear,nowMonth,nowDay); break;case 1:printf( "%-4d年%-2d月%-2d日是星期一！！！",nowYear,nowMonth,nowDay); break;case 2:printf( "%-4d年%-2d月%-2d日是星期二！！！",nowYear,nowMonth,nowDay); break;case 3:printf( "%-4d年%-2d月%-2d日是星期三！！！",nowYear,nowMonth,nowDay); break;case 4:printf( "%-4d年%-2d月%-2d日是星期四！！！",nowYear,nowMonth,nowDay); break;case 5:printf( "%-4d年%-2d月%-2d日是星期五！！！",nowYear,nowMonth,nowDay); break;case 6:printf( "%-4d年%-2d月%-2d日是星期六！！！",nowYear,nowMonth,nowDay); break;}printf("\n\n");}void nowMonthprint( int nowYear,int nowMonth,int nowDay ) // 打印月历{int monthDay;int days = calcuDays(nowYear,nowMonth,1);int weekNo = calcuWeek(days);if ( isLeapyear(nowYear) )monthDay = leapDay[nowMonth-1];elsemonthDay = noleapDay[nowMonth-1];printf( "-----------------%4d年%02d月---------------\n",nowYear,nowMonth );printf( "%-5s%-5s%-5s%-5s%-5s%-5s%-5s\n","天","一","二","三","四","五","六" );for ( int j = 1; j <= monthDay; j++ ){if ( j == 1){for ( int k = 0;k < weekNo;k++ )printf("%-5s"," ");}if ( nowDay == j )printf("*%-4d",j );elseprintf( "%-5d",j);if ( weekNo%7 == 6 )printf("\n");weekNo = calcuWeek(days+j) ;}printf("\n");}void nowYearprint( int nowYear ) // 打印年历{int monthDay;for ( int i = 0; i < 12; i++ ){int days = calcuDays(nowYear,i+1,1);int weekNo = calcuWeek(days);if ( isLeapyear(nowYear) )monthDay = leapDay[i];elsemonthDay = noleapDay[i];printf( "-----------%4d年%02d月-----------\n",nowYear,i+1 );11printf( "%-5s%-5s%-5s%-5s%-5s%-5s%-5s\n","天","一","二","三","四","五","六" ); for ( int j = 1; j <= monthDay; j++ ){if ( j == 1){for ( int k = 0;k < weekNo;k++ )printf("%-5s"," ");}printf( "%-5d",j);if ( weekNo%7 == 6 )printf("\n");weekNo = calcuWeek(days+j) ;}printf("\n");}}void menuPrint() // 打印系统菜单{printf("\t万年历查询系统\n");printf("\n******************************");printf("\n1.查询某年某月某日是星期几");printf("\n2.查询某年是否是闰年");printf("\n3.打印某年的年历");printf("\n4.打印某年某月的月历");printf("\n5.查询某月的最大天数");printf("\n6.退出");printf("\n*****************************\n");printf("\n请选择：");}第四章运行结果及分析1.登陆界面13图3登陆界面提供了六个选项进行选择，并提示输入后的操作方法；2.查询具体日期图4输入指令后，可查询某天是星期几；3.判断闰年图5 4.显示全年日历图615图7图84查询某月最大天数图10第5章课程设计心得通过本次课程设计我第一次通过自己的实践对书本上的知识进行了与生活相关的运用。
