陕西省西安市长安区2015-2016学年高一英语下学期期中试题

长安一中2020——2021学年第一学期高二年级期中考试 理科数学试卷一、选择题1. 若直线l 的方向向量为(1,0,2)a =，平面α的法向量为(2,0,4)n =--，则（ ） A. //l α B. l α⊥ C. l α⊂ D. l 与α斜交【答案】B 【解析】 【分析】由l 的方向向量(1,0,2)a = ，平面α的法向量(2,0,4)n =-- 可得2n a =-，从而得解. 【详解】∵(1,0,2)a = ，(2,0,4)n =--， ∴2n a =- ，即//n a .∴l α⊥. 故选：B【点睛】本题考查利用直线l 的方向向量与平面α的法向量关系判断线面位置关系.属于基础题.2. 已知命题:p x R ∀∈，2230x x -+>；命题q ：若22a b <，则a b <，下列命题为假命题的是（ ） A. p q ∨B. ()p q ∨⌝C. p q ⌝∨D.()p q ⌝∨⌝【答案】C 【解析】 【分析】解不等式可判断命题p 的真假，根据不等式性质可判断q 的真假，再由复合命题的性质判断命题真假．【详解】命题p ：x R ∀∈，2230x x -+>， 因为()2120x -+>，所以命题p 为真命题命题q ：若22a b <，则a b <，当1,4a b ==-时不等式不成立，所以命题q 为假命题 由复合命题真假判断可知A ：p q ∨为真命题；B ：()p q ∨⌝为真命题;C ：p q ⌝∨为假命题；D ：()p q ⌝∨⌝为真命题. 故选:C3. 已知抛物线22y x =的焦点与椭圆2212y x m +=的一个焦点重合，则m =（ ）A.74B.12764C.94D.12964【答案】A 【解析】 【分析】抛物线22y x =的焦点为1,02⎛⎫ ⎪⎝⎭，然后可算出答案.【详解】抛物线22y x =的焦点为1,02⎛⎫ ⎪⎝⎭，所以椭圆2212y x m +=的一个焦点为1,02⎛⎫ ⎪⎝⎭， 所以124m -=，即74m = 故选：A4. 已知正方体1111ABCD A B C D -，若112AB C B ⋅=-，则正方体的棱长等于（ ）A 2 B.C.D. 4【答案】C 【解析】 【分析】设正方体1111ABCD A B C D -的棱长为()0a a >，以点A 为坐标原点，AB 、AD 、1AA 所在直线分别为x 、y 、z 轴建立空间直角坐标系A xyz -，利用空间向量数量积的坐标运算以及等式112AB C B ⋅=-，可得出关于a 的等式，由此可得出该正方体的棱长.【详解】设正方体1111ABCD A B C D -的棱长为()0a a >，以点A 为坐标原点，AB 、AD 、1AA 所在直线分别为x 、y 、z 轴建立空间直角坐标系A xyz -，则()0,0,0A 、(),0,0B a 、()1,0,B a a 、()1,,C a a a ，()1,0,AB a a =，()10,,C B a a =--，则2112AB C B a ⋅=-=-，可得2a =因此，正方体1111ABCD A B C D -2. 故选：C.【点睛】本题考查利用空间向量数量积求解正方体的棱长，考查计算能力，属于基础题.5. 设1a ≥，则双曲线22214x y a a -=+离心率的取值范围为（ ）A. [)5,+∞B. [)6,+∞C. )5,⎡+∞⎣ D. )6,⎡+∞⎣【答案】C 【解析】 【分析】由双曲线方程可得2222441c a a e a a a a++===++，从而可得离心率的取值范围.【详解】由双曲线方程可得2222441c a a e a a a a++===++，又1a ≥44121415a a a a∴++≥⋅=+=，当且仅当4a a =，即2a =时取等号，所以双曲线的离心率的取值范围为)5,⎡+∞⎣. 故选：C.【点睛】本题考查双曲线的标准方程，以及双曲线的简单性质，不等式的性质的应用，属于基础题.6. 三棱锥A­BCD 中，AB ＝AC ＝AD ＝2，∠BAD＝90°，∠BAC＝60°，则AB CD ⋅等于( )A. －2B. 2C. 23-D. 23【答案】A 【解析】 试题分析：()····022cos602CD AD AC AB CD AB AD AC AB AD AB AC =-∴=-=-=-⨯⨯=-考点：平面向量数量积的运算7. 正方体1111ABCD A B C D -的棱长为1，O 是11A C 的中点，则O 到平面11ABC D 的距离为（ ） A.32B.24C.12D.33【答案】B 【解析】 【分析】O 是11A C 中点，1112OC AC =，因此O 到平面11ABC D 的距离等于1A 到平面11ABC D 距离的一半，求出1A 到平面11ABC D 距离即可．【详解】如图，连续1A D 与1AD 交于点M ，11ADD A 是正方形，则11A D AD ⊥，1111ABCD A B C D -是正方体，AB ⊥平面11ADD A ，而1A D ⊂平面11ADD A ，∴1AB A D ⊥，又1AD AB A ⋂=，∴1A D ⊥平面11ADD A ，又11122A M A D ==， ∴1A 到平面11ABC D 的距离为2， 又1112AC OC =，∴O 到平面11ABC D 的距离等于1A 到平面11ABC D 距离的一半即为24． 故选：B ．【点睛】方法点睛：本题考查求点到平面的距离，求P 到平面α的距离方法如下： （1）直接过P 作平面α的垂线，垂足为M ，求出PM 的长即可；（2）（转化法）若Q α∈，O 是直线PQ 上的点，且PQ OQ λ=，求出O 到平面α的距离d ，则P 到α距离为d λ．（3）体积法，利用三棱锥可以以任一面底面，换底后求出体积，则可求得点面距．（4）建立空间直角坐标系，若Q α∈，求出α的一个法向量，PQ 在n 方向上的投影的绝对值即为P 到平面α的距离．8. 已知点F 为椭圆()2221x y a a+>的一个焦点，过点F 作圆221x y +=的两条切线，若这两条切线互相垂直，则a =（ ） A. 2 23 D. 23【答案】C 【解析】 【分析】根据切线垂直，推导出F 点至坐标原点的距离，即可求得焦点坐标和a 【详解】由题可设(),0F c ，根据题意，作图如下：因为过F 点的两条切线垂直，故可得45OFH ∠=︒，则1OH HF ==， 故可得2OF =F 坐标为)2,0.则2,1c b ==，故2223a b c =+=，解得3a =故选:C.9. 下列命题中为真命题的是（ ） A. 命题“若2020x >，则0x >”的逆命题 B. 命题“若0xy =，则0x =或0y =”的否命题 C. 命题“若220x x +-=，则1x =” D. 命题“若21x ≥，则1≥x ”的逆否命题 【答案】B 【解析】 【分析】依次判断每个命题的真假即可.【详解】A 项，命题“若2020x >，则0x >”的逆命题为“若0x >，则2020x >”，显然命题为假；B 项，命题“若0xy =，则0x =或0y =”的逆命题为“若0x =或0y =，则0xy =”，显然命题为真，则原命题的否命题也为真；C 项，解220x x +-=，得1x =或2x =-，所以命题“若220x x +-=，则1x =”为假；D 项，211x x ≥⇒≤-或1≥x ，所以命题“若21x ≥，则1≥x ”是假命题，则其逆否命题也为假命题. 故选：B.10. 设有下列四个命题：1p ：两两相交且不过同一点的三条直线必在同一平面内． 2p ：过空间中任意三点有且仅有一个平面．3p ：若空间两条直线不相交，则这两条直线平行． 4p ：若直线l ⊂平面α，直线m ⊥平面α，则m l ⊥．则上述命题中所有真命题的个数是（ ）． A. 1 B. 2C. 3D. 4【答案】B 【解析】 【分析】利用两交线直线确定一个平面可判断命题1p 的真假；利用三点共线可判断命题2p 的真假；利用异面直线可判断命题3p 的真假，利用线面垂直的定义可判断命题4p 的真假. 【详解】对于命题1p ，可设1l 与2l 相交，这两条直线确定的平面为α； 若3l 与1l 相交，则交点B平面α内， 同理，3l 与2l 的交点A 也在平面α内，所以，AB α⊂，即3l α⊂，命题1p 为真命题；对于命题2p ，若三点共线，则过这三个点的平面有无数个， 命题2p 为假命题；对于命题3p ，空间中两条直线不相交，可能平行可能异面，命题3p 为假命题； 对于命题4p ，若直线m ⊥平面α，则m 垂直于平面α内所有直线， 直线l ⊂平面α，∴直线m ⊥直线l ，命题4p 为真命题. 故选:B11. 已知直线l 过抛物线C 的焦点，且与C 的对称轴垂直，l 与C 交于,A B 两点，12,AB P =为C 的准线上一点，则ABP ∆的面积为（ ） A. 18 B. 24C. 36D. 48【答案】C 【解析】解：设抛物线的解析式为y2=2px （p ＞0）， 则焦点为F （2p ，0），对称轴为x 轴，准线为x=-2p∵直线l 经过抛物线的焦点，A 、B 是l 与C 的交点， 又∵AB ⊥x 轴 ∴|AB|=2p=12 ∴p=6又∵点P 在准线上 ∴DP=（2p +|-2p|）=p=6 ∴S △ABP=12（DP•AB ）=12×6×12=36 故选C ．12. 在ABC 中，“sin cos B C <”是“ABC 为钝角三角形”的（ ） A. 必要不充分条件 B. 充分不必要条件 C. 充分必要条件 D. 既不充分也不必要条件【答案】B 【解析】 【分析】利用充分条件、必要条件的定义，结合特殊值法、正弦函数的单调性以及诱导公式判断可得出结论.【详解】充分性：在ABC 中，若sin cos B C <，则cos 0C >，可知C 为锐角，且cos sin 2C C π⎛⎫=- ⎪⎝⎭.若角B 为直角，则sin 1B =，则cos 1C >不成立，故角B 不可能为直角； 若角B 为锐角，则sin cos sin 2B C C π⎛⎫<=-⎪⎝⎭，02C π<<，则022C ππ<-<，由于正弦函数sin y x =在0,2π⎛⎫⎪⎝⎭上为增函数，可得2B C π<-，即2B C π+<，即2A ππ-<，2A π∴>，此时，ABC 为钝角三角形；若角B 为钝角，即2B ππ<<，可得02B ππ<-<，02C π<<，则022C ππ<-<，由sin cos B C <可得()sin sin 2B C ππ⎛⎫-<-⎪⎝⎭， 由于正弦函数sin y x =在0,2π⎛⎫⎪⎝⎭上为增函数，可得2B C ππ-<-，可得2B C π->，22B C ππ∴>+>，此时，ABC 为钝角三角形；所以，充分性成立；必要性：若ABC 为钝角三角形，且角C 为钝角，则角B 为锐角，那么sin 0cos B C >>， 必要性不成立.综上所述，在ABC 中，“sin cos B C <”是“ABC 为钝角三角形”的充分不必要条件. 故选：B.【点睛】方法点睛：判断充分条件和必要条件，一般有以下几种方法： （1）定义法； （2）集合法； （3）转化法.13. 如图，过抛物线22(0)y px p =>的焦点F 的直线交抛物线于点A ，B ，交其准线l 于点C ，若F 是AC 的中点，且4AF =，则线段AB 的长为（ ）A. 5B. 6C.163D.203【答案】C 【解析】 【分析】设,A B 在准线上的射影分别为,M N ，根据点F 是AC 的中点， 2AM HF =，取得2p =， 设BF BN m ==，根据相似求得43BF =，再结合焦点弦的性质，即可求解. 【详解】设,A B 在准线上的射影分别为,M N ，准线与x 轴交于H ，则HF p =， 由于点F 是AC 的中点，且4AF =，根据抛物线的定义，可得224AM HF p ===，所以2p =，设BF BN m ==，则BN BC FH CF =，即424m m -=，解得43m =，所以416433AB AF BF =+=+=， 即AB 的长为163. 故选：C.【点睛】本题主要考查了抛物线的定义及其应用，其中解答中熟记抛物线上的点到焦点的距离等于到准线的距离是解答的关键，着重考查转化思想，以及推理与运算能力.14. 已知1F ，2F 是椭圆的两个焦点，满足120MF MF ⋅=的点M 总在椭圆内部，则离心率的取值范围是（ ） A. ()0,1 B. 10,2⎛⎫⎪⎝⎭C. 20,⎛⎫ ⎪ ⎪⎝⎭D. 2,1⎛⎫⎪ ⎪⎝⎭【答案】C【解析】 【分析】由120MF MF ⋅=可知，M 在以原点为圆心，c 为半径的圆上，所以圆在椭圆内部，可得c b <. 【详解】因数120MF MF ⋅=所以M 在以原点为圆心，c 为半径的圆上 所以圆在椭圆内部， 所以c b <所以2222<=-c b a c2212<c a 202e <<故选：C.【点睛】本题主要考查了点与椭圆的位置关系，还考查转化化归的能力，属于中档题.二、填空题15. 设双曲线22221(0,0)x y a b a b-=>>C 的渐近线方程为___________.【答案】y = 【解析】 【分析】根据离心率公式得到ba=，再计算渐近线得到答案. 【详解】由双曲线的方程可得渐近线的方程为：by x a=±，由题意离心率c e a ===b a =y =，故答案为：y =.【点睛】本题考查了双曲线渐近线方程，属于简单题.16. 一个椭圆中心在原点，焦点12F F ，在x轴上，(P 是椭圆上一点，且|PF 1|，|F 1F 2|，|PF 2|成等差数列，则椭圆方程为____． 【答案】22186x y +【解析】 【分析】设椭圆方程为2222x y a b+=1，（a ＞b ＞0），由已知结合椭圆性质及等差数列性质列出方程求出a ，b ，由此能求出椭圆方程．【详解】∵个椭圆中心在原点，焦点F 1，F 2在x 轴上，∴设椭圆方程为2222x y a b+=1，（a ＞b ＞0），∵P （2|PF 1|，|F 1F 2|，|PF 2|成等差数列，∴2243124a b a c⎧+=⎪⎨⎪=⎩，且a 2=b 2+c 2， 解得，，∴椭圆方程为22186x y +=．故答案为22186x y +=．【点睛】本题考是椭圆方程的求法，是基础题，解题时要认真审题，注意椭圆性质的合理运用．17. 已知正方体1111ABCD A B C D -的棱长为a ，则点1A 与面对角线1BC 所在直线间的距离是______． 【答案】6a 【解析】 【分析】连接11,BC B C 交于点O ，连接1A O ，根据正方体的性质，易得1BC ⊥平面11A B O ，进而得到1BC ⊥1A O ，则1A O 的长度即为所求.【详解】如图所示：连接11,BC B C 交于点O ，连接1A O ， 因为111111111,,BC B C BC A B B C A B B ⊥⊥⋂=， 所以1BC ⊥平面11A B O ， 所以1BC ⊥1A O ， 所以1A O 的长度即为所求.因为1112,A B a B O a ==， 所以2211116AO A B B O a =+= 故答案为：6a 18. 已知抛物线()220y px p =>在第一象限内的部分上一点()3,A b 到抛物线焦点F 的距离为4，若P 为抛物线准线上任意一点，则PAF △的周长最小值为______． 【答案】434+ 【解析】 【分析】利用抛物线的定义由342p+=求得抛物线方程24y x =，进而得到准线方程1x =-，焦点坐标()1,0F ，()3,23A ，然后作出点A 关于准线的对称点()5,23A '-求解. 【详解】因为抛物线()220y px p =>上的点()3,A b 到抛物线焦点F 的距离为4，由抛物线的定义得；342p+=，解得2p =， 所以抛物线方程为24y x =，准线方程为1x =-，焦点坐标为()1,0F ，()3,23A ，如图所示：点A 关于准线的对称点(5,23A '-，则AP +PF 的最小值为()()22512343A F '=--+=所以PAF △的周长最小值为4故答案为：4三、解答题19. 已知m ∈R ，命题p ：对任意[]0,1x ∈，不等式2223x m m -≥-恒成立；命题q ：存在[]1,1x ∈-，使得m ax ≤成立．（1）若p 为真命题，求m 的取值范围；（2）当1a =时，p 且q 为假命题，p 或q 为真命题，求m 的取值范围． 【答案】（1）[]1,2；（2）()(],11,2-∞.【解析】 【分析】（1）考查不等式恒成立，构造函数()[]()220,1f x x x =-∈，求其最小值()2min 3f x m m≥-即可；（2）p 且q 为假命题，p 或q 为真命题，则p ，q 中一个是真命题，一个是假命题，分p 真q 假、p 假q 真两类讨论即可.【详解】（1）对任意[]0,1x ∈，不等式2223x m m -≥-恒成立，令()[]()220,1f x x x =-∈，则()2min 3f x m m ≥-，当[]0,1x ∈时，()()min 02f x f ==-，即232m m -≤-，解得12m ≤≤． 因此，当p 为真命题时，m 的取值范围是[]1,2．（2）当1a =时，若q 为真命题，则存在[]1,1x ∈-，使得m x ≤成立，所以1m ． 因此，当命题q 为真时，1m ．因为p 且q 为假命题，p 或q 为真命题， 所以p ，q 中一个是真命题，一个是假命题． 当p 真q 假时，由121m m ≤≤⎧⎨>⎩得12m <≤；当p 假q 真时，由121m m m ⎧⎨≤⎩或得1m <．综上所述，m 的取值范围为()(],11,2-∞．【点睛】本题借助命题的“外衣”，考查了不等式恒成立问题，和存在性问题，是一道很典型的题目.20. 如图，在长方体1111ABCD A B C D -中，1224AB BC AA ===，E 为11A D 的中点，M 为线段11C D 上一点，且满足11114MC D C =，F 为MC 的中点．（1）求证：//EF 平面1A DC ；（2）求直线1A D 与直线CF 所成角的余弦值． 【答案】（1）证明见解析；（210【解析】 【分析】（1）以D 为原点建立空间直角坐标系，求出EF 和平面1A DC 的一个法向量为n ，满足0EF n ⋅=即可；（2）利用111cos ,DA CF DA CF DA CF⋅=⋅可求出.【详解】（1）证明：在长方体1111ABCD A B C D -中，建立如图所示空间直角坐标系，由1224AB BC AA ===，E 为11A D 的中点，M 为线段11C D 上一点，且满足11114MC D C =， 得()0,0,0D ，()1,0,2E ，70,,12F ⎛⎫ ⎪⎝⎭，()12,0,2A ，()0,4,0C ，∴()12,0,2DA =，()0,4,0DC =，71,,12EF ⎛⎫=-- ⎪⎝⎭．设平面1A DC 的一个法向量为(),,n x y z =．由122040n DA x z n DC y ⎧⋅=+=⎨⋅==⎩，取1z =-，得()1,0,1n =-，∵0EF n ⋅=，且EF ⊄平面1A DC ，∴//EF 平面1A DC ．（2）解：由（1）知，()12,0,2DA =，又10,,12CF ⎛⎫=- ⎪⎝⎭， ∴11110cos ,55222DA CF DA CF DA CF⋅===⋅⨯．∴直线1A D 与直线CF 10． 【点睛】本题考查线面平行证明和异面直线所成角的求解，建立空间直角坐标系，利用向量的方法求解是解决本题的有效办法.21. 已知椭圆()222210y x a b a b +=>>的离心率22e =，且过点(0,2．（1）求椭圆方程；（2）已知1F 、2F 为椭圆的上、下两个焦点，AB 是过焦点1F 的一条动弦，求2ABF 面积的最大值．【答案】（1）2212y x +=；（2. 【解析】 【分析】（1）根据离心率的值，可列出a c ，的关系式，再根据经过()0,-2点，可得出a 的值和c 的值，最后再结合222a b c =+，可算出b 的值，直接写出椭圆方程即可.（2）根据题意设出直线的方程和椭圆方程联立方程组，由根和系数的关系，再结合三角形面积公式，可把三角形面积表示成含有参数的关系式，最后根据不等式，可求得面积的最大值. 【详解】（1）由题意，a =2c e a ==得1c =，所以1b =，所以椭圆方程是2212y x +=．（2）由于直线AB 经过上焦点()0,1，设直线AB 方程为1y kx =+，联立方程组22112y kx y x =+⎧⎪⎨+=⎪⎩将1y kx =+代入椭圆方程2212y x +=，得()222210k x kx ++-=，则222A B k x x k +=-+，212A B x x k ⋅=-+， ∴A Bx x -==21212ABF A B S F F x x =⋅-△，可知122F F=则2211122ABF S k ===≤+△．=，即0k =时，2ABF S．【点睛】椭圆与直线相交时，三角形面积问题的关键点为：设直线方程、联立方程组、韦达定理、列出三角形面积的关系式，最后根据函数或不等式，可求出三角形面积的范围. 22. 如图，在四棱柱1111ABCD A B C D -中，底面ABCD 是等腰梯形，AB CD ∥，4AB =，2BC CD ==，顶点1D 在底面ABCD 内的射影恰为点C.（1）求证：BC ⊥平面ACD 1；（2）若直线DD 1与底面ABCD 所成的角为4π，求平面11ABC D 与平面ABCD 所成锐二面角的余弦值.【答案】（1）证明见解析（221 【解析】 【分析】（1）连接1D C ，则1 D C ⊥平面ABCD ，推导出1BC D C ⊥，连接AC ，过点C 作CG ⊥AB 于点G ，推导出BC ⊥AC ，由此能证明BC ⊥平面ACD 1;（2）以C 为坐标原点，分别以CA ，CB ，CD 1，所在直线为x 轴，y 轴，z 轴，建立空间直角坐标系，利用向量法能求出平面11ABC D 与平面ABCD 所成锐二面角的余弦值． 【详解】解：（1）证明：如图，连接1D C ，则1 D C ⊥平面ABCD ，BC ABCD ⊂平面，1BC D C ∴⊥在等腰梯形ABCD 中，连接AC ，过点C 作CG AB ⊥于点G ，4,2,AB BC CD AB CD ===∥，则223,1,213AG BG CG ===-=22223(3)23AC AG CG ∴=+=+=因此满足22216,AC BC AB BC AC +==∴⊥ 又1D C ，AC ⊂面1AD C ，1D CAC C =BC ∴⊥平面1AD C（2）由（1）知1,,AC BC D C 两两垂直，1D C ⊥平面11,,24ABCD D DC D C CD π∴∠=∴==以C 为坐标原点，分别以1,,CA CB CD 所在直线为x 轴，y 轴，z 轴， 建立如图所示的空间直角坐标系，则(0,0,0)C ，(23,0,0)A ，(0,2,0)B ，1(0,0,2)D ，(23,2,0)AB ∴=-，1(23,0,2)AD =-设平面11ABC D 的法向量(,,)n x y z =，由100AB n AD n ⎧⋅=⎪⎨⋅=⎪⎩，得23202320x y x z ⎧-+=⎪⎨-+=⎪⎩， 可得平面11ABC D 的一个法向量(1,3,3)n =， 又1(0,0,2)CD =为平面ABCD 的一个法向量， 设平面11ABC D 与平面ABCD 所成锐二面角为θ， 则112321cos 727CD n CD nθ⋅===，因此平面11ABC D 与平面ABCD 所成锐二面角的余弦值为217．【点睛】本题考查线面垂直的证明，考查二面角的余弦值的求法，考查空间中线线、线面、面面间的位置关系等基础知识，考查运算求解能力，是中档题．23. 已知抛物线C ：22y x =的焦点为F ，平行于x 轴的两条直线12,l l 分别交C 于A B ，两点，交C 的准线于P Q ，两点．（Ⅰ）若F 在线段AB 上，R 是PQ 的中点，证明//AR FQ ；（Ⅱ）若PQF ∆的面积是ABF ∆的面积的两倍，求AB 中点的轨迹方程.【答案】（Ⅰ）见解析；（Ⅱ）21y x =-．【解析】【分析】 设22111,0,,,,,,,,222222a b a b A B b P a Q b R ⎛⎫⎛⎫+⎛⎫⎛⎫⎛⎫--- ⎪ ⎪ ⎪ ⎪ ⎪⎝⎭⎝⎭⎝⎭⎝⎭⎝⎭⇒l 的方程为2(x a -+ )0b y ab +=．（Ⅰ）由F 在线段AB 上⇒10ab +=，又122211a b a b ab k b k a a ab a a---=====-=+-⇒//AR FQ ；（Ⅱ）设l 与x 轴的交点为()1,0D x ⇒1111,2222ABF PQF a b S b a FD b a x S ∆∆-=-=--=⇒111222a b b a x ---=⇒10x =（舍去），11x =．设满足条件的AB 的中点为(),E x y ．当AB 与x 轴不垂直时⇒()211y x a b x =≠+-⇒2a b y +=⇒()211y x x =-≠．当AB 与x 轴垂直时⇒E 与D 重合⇒所求轨迹方程为21y x =-． 【详解】由题设1,02F ⎛⎫ ⎪⎝⎭，设12:,:l y a l y b ==，则0ab ≠，且 22111,0,,,,,,,,222222a b a b A B b P a Q b R ⎛⎫⎛⎫+⎛⎫⎛⎫⎛⎫--- ⎪ ⎪ ⎪ ⎪ ⎪⎝⎭⎝⎭⎝⎭⎝⎭⎝⎭． 记过,A B 两点的直线为l ，则l 的方程为()20x a b y ab -++=（Ⅰ）由于F 线段AB 上，故10ab +=，记AR 的斜率为1,k FQ 的斜率为2k ，则122211a b a b ab k b k a a ab a a ---=====-=+-， 所以//AR FQ（Ⅱ）设l 与x 轴的交点为()1,0D x ， 则1111,2222ABF PQF a b S b a FD b a x S ∆∆-=-=--=，由题设可得111222a b b a x ---=，所以10x =（舍去），11x =． 设满足条件的AB 的中点为(),E x y ．当AB 与x 轴不垂直时，由AB DE k k =可得()211y x a b x =≠+-． 而2a b y +=，所以()211y x x =-≠． 当AB 与x 轴垂直时，E 与D 重合，所以，所求轨迹方程为21y x =-【点睛】本题考查了1.抛物线定义与几何性质；2.直线与抛物线位置关系；3.轨迹求法．。

2015-2016学年度上学期（期末）考试高一英语试题【新课标】试卷说明：1、本试卷满分150分，答题时间120分钟。

2、请将答案直接填涂在答题卡上，考试结束只交答题卡。

第一部分：选择题（共四节, 满分90分）第一节：单项填空（共20小题，每小题1分，满分20分）从A、B、C、D四个选项中，选出可以填入空白处的最佳选项。

1. ________it is to throw snowballs at each other on the playground after snow!A. How funB. What funC. What a funD. How funny2.We find ______ easy to get along with our new teachers here.A. thatB. itC. thisD. 不填3.--Tom is _____ to computer games.--No wonder he is not doing well in school recently.A. interestedB. curiousC. crazyD. addicted4.The computer system _______suddenly while he was searching for information on the Internet.A. broke downB. broke outC. broke upD. broke in5.Her singing career _______ after an appearance in the Spring Festival TV Show ten years ago.A. got offB. put offC. set offD. took off6. Is this the first time that Jack ______ this kind of food?A. enjoysB. has enjoyedC. enjoyedD. had enjoyed7. He is a man with rich experience, _________ much can be learned.A. whoB. from whoC. from whomD. what8. _______ is known to us all, America is a developed country _________ theFirst World.A. As; belongs toB. As; belonging toC. What; belonging toD. It; belongs to9. —I won the first prize in the English speech contest held in our school last month!—_______!A. Thank youB. Enjoy yourselfC. CongratulationsD. Good Luck10. Reading is ____ good habit. Stick to it, and you’ll make _______ progress.A. a, /B. a, aC. /, aD. the, a11. Prices of daily goods _______through a computer can be lower than store prices.A. are boughtB. boughtC. been boughtD. buying12. Frank put the medicine in the top drawer to make sure it would not be _____ to the kids.A. relativeB. accessibleC. acceptableD. changeable13. _____ the difficult maths problem, I have consulted(咨询) Professor Russell several times.A. Working outB. Worked outC. To work outD. Work out14. Tsinghua University, _____ in 1911, is home to a great number of outstanding figures.A. foundB. foundingC. foundedD. to be founded15. Do you get up every morning _____ energetic and ready to start a new day?A. feelB. feelingC. to feelD. felt16. Swimming is my favorite sport. There is _____ like swimming as a means of keeping fit.A. somethingB. anythingC. nothingD. everything17. To my great surprise, he wasn’t _____ when he heard the _____ news.A. surprising; surprisingB. surprised; surprisingC. surprised; surprised C. surprising; surprised18. We really appreciate _____ to your party on Saturday.A. invitingB. to inviteC. being invitedD. to be invited19. When I was young, I _____ in a faraway village for several years, which is unforgettable.A. livedB. have livedC. was livedD. had lived20. The roads are crowded _____ walking is quicker than driving.A. in order thatB. so thatC. so as toD. in order to第二节：阅读理解。

长安一中2022-2023学年度第一学期高一年级期中考试英语试题时间：120分钟，满分：150分注意事项：1.答卷前，考生务必将自己的姓名、准考证号填写在答题卡上，并将条形码粘贴在规定位置。

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第一部分听力（共两节，满分30分）第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标到试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1．What is the man probably doing?A．Writing a report. B．Reading a newspaper. C．Looking for a newspaper. 2．How does the man usually go to work?A．By bus. B．By car. C．On foot.3．Why does the man take an umbrella?A．Because it’s raining now.B．Because it will rain soon.C．Because his wife dislikes walking in the sun.4．How much is the cheaper book?A．5 dollars. B．15 dollars. C．20 dollars.5．What do we know about the man?A．He likes his new job very much.B．He makes very little money now.C．He is busy with his job now.第二节（共15小题；每小题1.5分，共22.5分）听下面5 段对话或独白。

陕西省西安市长安区第一中学2022-2023学年高一上学期期末考试英语试题学校:___________姓名：___________班级：___________考号：___________一、阅读理解We are currently looking for responsible teenagers and young adults to assist with Summer Camp.Youth Teaching Assistants(YTA)are aged15and older and offer support to the instructors.YTA options will be available from June22to August21on a weekly basis. Summer Camp meets for a five-day week,Monday through Friday.Summer Camp is held on the National Mall in the S.Dillon Ripley Center,unless otherwise stated.Serving as a YTA provides an outstanding way for teens to be involved with a national organization,the Smithsonian Institution.Assisting a professional Instructor,YTAs are introduced to the world of teaching.The wide range of programs offers YTAs the opportunity to experience and learn about subjects such as art,science,or theater.YTAs earn community service credits and also have an interesting experience to add to an application for college or a future job.Some of YTA responsibilities are as follows:You will be given a monitor packet for your class.This packet contains a list of participant names and other important information.It must be given to the YTA supervisor(管理者)at the end of the day and should not be taken home.Arrive at8:15a.m.on Mondays and8:30a.m.the rest of the week.During this time, you will help the instructor prepare for class.Wear your name tag(标签)at all times.You need it to assure access to the Ripley Center every morning.Make sure you have a name tag for each camper as well.Hand out and collect student evaluations at the end of class on the last day.Don’t forget to give the instructors their evaluations to fill out.Mobile phone use must be limited to break times or emergencies.Please do not use it during the times when you are attending to campers,especially drop-off and pick-up times. 1．What can we learn about Summer Camp?A．It will last for more than two months.B．It is targeted at teenagers aged15and above.C．It offers campers a two-day break every week.D．Its teachers are from the S.Dillon Ripley Center.2．What’s Paragraph2mainly about?A．The benefits of being a YTA．B．The responsibilities of being a YTA．C．The subjects that Summer Camp covers.D．The introduction to the Smithsonian Institution.3．As YTAS,teenagers__________.A．can’t go home at night.B．can’t use mobile phones.C．should prepare for the next day’s classes.D．should arrive15minutes earlier on Mondays.4．What type of writing is this text?A．A daily schedule.B．An advertisement.C．An announcement.D．A plan for a camp.Beijing issued on Thursday China’s first autonomous(自动的)driving permits to two robotaxi operators-Baidu Inc and Pony.ai,which for the first time allows the removal of a safety operator from the driver’s seat on public roads in the capital.Industry experts said the move marks a significant milestone for the autonomousride-hailing(打车服务)industry in China,indicating an openness to taking a further step toward a fully driverless vehicle.Since Thursday,users can hail a driverless robotaxi using the Apollo Go mobile app from10am to4pm for free,according to Baidu Inc.The driverless robotaxi is expected to hit the road around the clock within six months,said Wei Dong,vice-president of Baidu Intelligent Driving Business Group.The company is concentrating on expanding its commercial robotaxi pilot services in more cities at an early stage.The robotaxi service provided by Pony.ai,which obtained a taxi license in Guangzhou on April24,covers hundreds of locations,including subway stations,parks,stadiums, commercial buildings and residential areas.“The approval to operate driverless robotaxis in Beijing is a critical milestone in the change from testing driverless autonomous vehicles to offering driverless robotaxi rides to public passengers,”said Peng Jun,co-founder and CEOof Pony.ai.Beijing is taking the lead in promoting the development of commercialized autonomous driving in China,said Zhang Xiang,a researcher at the Automobile Industry Innovation Research Center,adding that other first-tier cities,such as Shanghai and Shenzhen,might follow Beijing and allow autonomous vehicles to carry passengers in the near future.The move will help autonomous driving companies get more testing experience of the driverless pattern,said Lyu Jinghong,an intelligent mobility analyst,adding that more tests are required to realize the goal of fully autonomous driving.5．What’s the significance of China’s issuing autonomous driving permits?A．It is an important advance in robotaxi industry.B．It proves the security of autonomous vehicles.C．The self-driving technology has been used widely.D．Fully driverless vehicles can be reached by the public.6．What can we know about the robotaxi service offered by Pony.ai at present? A．People can hail the driverless robotaxi free of charge.B．The autonomous vehicle is in service around the nation.C．The robotaxi service can cover a wide range of locations.D．It is provided for the citizens in Guangzhou at any time.7．What remains to be done to achieve fully autonomous driving?A．Expanding the robotaxi services to more cities.B．Carrying out more tests on the autonomous vehicles.C．Developing the self-driving technology to a large extent.D．Calling for the companies to improve self-driving services.A tiny Alaska village has experienced a boom in tourism in recent years as polar bears spend more time on land than on Arctic sea ice.More than2,000people visited the northern Alaska village of Kaktovik in2018to see polar bears in the wild.The far north community lies in an area where increasingly higher temperature has sped up the movement of sea ice,the primary habitat(栖息地)of polar bears. As ice has gradually moved to deep water beyond the continental shelf,more bears are remaining on land to look for food.Polar bears have always been a common sight on sea ice near Kaktovik,but villagersstarted noticing a change in the mid-1990s.More bears seemed to stay on land,and researchers began taking note of more female bears making homes in the snow on land instead of on the ice to raise their babies.U.S.Fish and Wildlife Service biologists began hearing reports of the increasing number of polar bears in the area in the early2000s.As more attention was given to the plight(困境)of polar bears about a decade ago,more tourists started heading to Kaktovik.The village had fewer than50visitors annually before2011,said Jennifer Reed,of the Arctic National Wildlife Refuge.“Today we’re talking about hundreds and hundreds of visitors,many from around the world each year,”Reed said.Most tourists visit in the fall, when bears are forced toward land because sea ice is farthest away from the shore.Bruce Inglangasak,a local hunter who sometimes offers wildlife-viewing tours,said he's been offering polar bear tours since2004.Most of his clients(客户)are from China and Europe,as well as from the lower48U.S.states.Many tourists stay several days in the village,which has two small hotels.The villagers have benefited a lot from that.In turn,they provide more effective protection for polar bears with financial support from tourism development. 8．What causes more polar bears to stay on land in Kaktovik?A．Food shortage.B．Climate change.C．Habitats’movement to shore.D．Their preference for land.9．How did common people feel about more sight of bears on land?A．Excited.B．Puzzled.C．Concerned.D．Shocked. 10．What can be inferred from the last paragraph?A．Hotels in Kaktovik are in demand in autumn.B．Kaktovik has about50visitors annually. C．Inglangasak makes a living as a tour guide.D．Tourism affects the balance of nature. 11．Which saying can describe the text?A．The fittest can survive.B．After a storm comes a calm. C．One man’s fault is another man’s lesson.D．Every coin has two sides.Do you know how it is when you see someone yawn and you start yawning too?Or how hard it is to be among people laughing and not laugh yourself?Well,apparently it’s because we have mirror neurons(神经元)in our brains.Put simply,the existence of mirror neurons suggests that every time we see someone else do something,our brains imitate it,whether or not we actually perform the same action.ThisD．determine our knowledge and language abilities.三、完形填空I’ve been farming sheep on a hillside for54years.I use a small tractor to get about.My34．A．ability B．dream C．idea D．luck 35．A．lesson B．meal C．job D．test四、用单词的适当形式完成短文五、告知信/通知46．新年即将来临，学生会将于星期五晚上8：00—10：00在学校五楼报告厅举办一场英语晚会，现请你以学生会的名义发一份英语书面通知，欢迎全校师生参加，通知包含以下要点：1.晚会主题：“迎新春，享受英语”；2.节目内容；3.参会要求。

陕西省西安市长安区第一中学2024-2025学年高一上学期第一次教学质量检测数学试题一、单选题1．下列四组对象，能构成集合的是（ ） A ．长安一中所有高个子的学生 B ．倒数等于它自身的实数 C ．一切较大的数D ．中国著名的艺术家2．已知命题:R,11p x x ∀∈-<，命题2:R,10q x x x ∃∈-+<，则（ ） A ．命题p 和命题q 都是真命题 B ．命题p 的否定和命题q 都是真命题 C ．命题q 的否定和命题p 都是真命题 D ．命题p 的否定和命题q 的否定都是真命题3．已知二次函数()2321y k x x =-++有两个零点，则k 的取值范围是（ ）A ．4k <B ．4k ≤C ．4k <且3k ≠D ．4k ≤且3k ≠4．已知实数x ，y 满足41x y -≤-≤-，145x y -≤-≤，则3x y +的最大值为（ ） A ．15B ．16C ．18D ．195．已知全集{|9}U x N x +=∈<，{}()1,6U C A B ⋂=，{}()2,3U A C B ⋂=，{}()5,7,8U C A B ⋃=，则B = A ．{}2,3,4B ．{}1,4,6C ．{}4,5,7,8D ．{}1,2,3,66．设a ，b 为实数，甲：2ab b >，乙：0a b <<，则甲是乙的（ ） A ．充分不必要条件 B ．必要不充分条件 C ．充要条件D ．既不充分也不必要条件7．已知a ，b 为不相等的正实数，满足11a b a b+=+．则下列不等式中不正确的为（ ）A ．2a b +>B ．212a b a b+++>C ．118a b a b ++≥+D ．222841a b a +≥+8．设函数()21f x mx mx =--，命题“存在13x ≤≤，()2f x m ≤-+”是假命题，则实数m 的取值范围为（ ） A ．3{|}7m m <B ．{|3}m m ≤C ．3{|}7m m >D ．{|}3m m >二、多选题9．已知全集{}1,2,3,4,5,6,7,8U =，{}260A x x x m =-+=∣，A U ⊆且U A ð中有6个元素，则实数m 的值可以是（ ） A ．5B ．6C ．7D ．810．已知关于x 的不等式2(23)(3)10a m x b m x +--->（0a >，0b >）的解集为1(,1),2∞∞⎛⎫--⋃+ ⎪⎝⎭，则下列结论正确的是（ ）A ．21a b +=B ．ab 的最大值为18C ．12a b+的最小值为4D ．11a b+的最小值为3+11．对于正整数集合{}()*12,,,N ,3n A a a a n n =∈≥L ，如果去掉其中任意一个元素()1,2,,i a i n =L 之后，剩余的所有元素组成的集合都能分为两个交集为空集的集合，且这两个集合的所有元素之和相等，就称集合A 为“可分集”，则下列说法正确的是（ ）A ．{}1,3,5,7,9不是“可分集”B ．集合A 中元素个数最少为7个C ．若集合A 是“可分集”，则集合A 中元素全为奇数D ．若集合A 是“可分集”，则集合A 中元素个数为奇数三、填空题12．已知集合{}4,2A m =--，{}24,B m =-，且A B =，则m 的值为．13．如图所示，将一矩形花坛ABCD 扩建为一个更大的矩形花坛AMPN ，要求点B 在AM 上，点D 在AN 上，且对角线MN 过点C ，已知4AB =，3AD =，当AM =时，矩形花坛AMPN 的面积最小．14．已知集合{}*123,,n A a a a a =⊆N L ，其中n ∈N 且3n ≥，123n a a a a <<<<L ，若对任意的(),x y A x y ∈≠，都有xy x y k-≥，则称集合A 具有性质()*k M k ∈N ． （1）集合{}1,2,A a =具有性质3M ，则a 的最小值；（2）已知集合A 具有性质14M ，则集合A 中元素个数的最大值为．四、解答题15．已知全集U =R ，集合2{430},{24}A xx x B x x =-+≤=<<∣∣，{}22C x a x a =≤≤+∣且C 为非空集合.(1)分别求(),U A B A B ⋂⋃ð；(2)若x C ∈是x B ∈的充分不必要条件，求a 的取值范围.16．已知集合{}2560A x x x =+-=，{}22(21)30B x x m x m =-++-=.（1）当1m =-时，集合C 满足{}1C ⊆ ()A B ⋃，这样的集合C 有几个？ （2）若A B B =I ，求实数m 的取值范围.17．某厂家拟定在2023年举行促销活动，经调查测算，该产品的年销量（即该厂的年产量）x 万件与年促销费用()0m m ≥万元满足32kx m =-+（k 为常数）．如果不举行促销活动，该产品的年销量只能是1万件．已知2023年生产该产品的固定投入将为10万元，每生产1万件，该产品需要再投入16万元（再投入费用不包含促销费用），厂家将每件产品的销售价格定为“平均每件产品的固定投入与再投入”的32倍．(1)求k 的值；(2)将2023年该产品的利润y （万元）表示为年促销费用m （万元）的函数； (3)该厂家2023年约投入多少万元促销费用时，获得的利润最大，最大利润是多少？1.414，结果保留1位小数）．18．已知函数2y ax bx c =++．(1)关于x 的不等式20ax bx c ++<的解集为{}13x x -<<，求关于x 的不等式()22230bx a c x a ---≥的解集；(2)已知0a >，0b >，当2x =时，2y ab c =+，①求2+a b 的最小值；②求()()221412a b +--的最小值．19．已知集合{}()122k A a a a k =≥L L ,,，其中()Z 1,2,i a i k ∈=L L ，由A 中元素可构成两个点集P 和Q ：(){},,,P x y x A y A x y A =∈∈+∈，(){},,,Q x y x A y A x y A =∈∈-∈，其中P 中有m 个元素，Q 中有n 个元素.新定义1个性质G ：若对任意的x A ∈，必有x A -∉，则称集合A 具有性质G(1)已知集合{}0,1,2,3J =}与集合{}1,2,3K =-和集合{}222L y y x x ==-+，判断它们是否具有性质G ，若有，则直接写出其对应的集合P ，Q ；若无，请说明理由; (2)集合A 具有性质G ，若2024k =，求：集合Q 最多有几个元素？ (3)试判断：集合A 具有性质G 是m n =的什么条件并证明.。

陕西省西安市长安区第一中学2014届高三上学期第一次模拟考试英语试题I卷（选择题共95分）第一部分：英语知识运用（共四节，满分55分）第一节语音知识（共5小题；每小题1分，满分5分）从每小题的A、B、C、D四个选项中，找出其划线部分与所给单词的划线部分读音相同的选项，并在答题卡上将该选项涂黑。

1. tomato A. women B. observe C. modern D. wonder2. realize A. really B. weather C. reasonable D. breath3. advise A. island B. decision C. present D. increase4. sugar A. underline B. circulate C. success D. pull5. theory A. months B. worthy C. smooth D. mouths第二节情景对话（共5小题；每小题1分，满分5分）根据对话情景和内容，从对话后所给的选项中选出能填入每一空白处的最佳选项，并在答题卡上将该选项涂黑。

选项中有两个为多余选项。

Dorothy: Debbie！I can‟t believe it！I haven‟t seen you for ages.Debbie: Dorothy！It‟s really a nice surprise！ 6Dorothy: Pretty good.Debbie: 7Dorothy: I w ish I could. But I‟m on my way out. I have to be in the city in an hour.Debbie 8Dorothy There‟s a lot of traffic and I really have to get going. You know where I live, so why don‟t you drop in one evening?Debbie: I‟ll do that.9 . Let‟s keep in touch.Dorothy: I‟d really like to. I‟ll talk to you soon, Debbie. I‟m glad I ran into you.Debbie: 10A. It‟s been a whole year since we saw each other last time.B. Where have you been?C. How are you?D. Can you join me?E. And you should feel free to call or visit me.F. Come on. Just for a minute.G. Me too. Take care.第三节语法和词汇知识（共15小题；每小题1分，满分15分）从每小题的A、B、C、D四个选项中，选出可以填入空白处的最佳选项，并在答题卡上将该选项涂黑。

长安一中 2017—2018 学年度第一学期期中考试高二级英语试卷(重点、平行)时间：120分钟总分:150 命题人：张晓利审题人:唐晓娟注意:请将36—40题答案涂在答题卡71-75 位置第I卷第一部分听力（共两节，满分30 分）第一节听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置.听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题.每段对话仅读一遍.1。

What will Dorothy do on the weekend?A. Go out with her friend.B。

Work on her paper.C。

Make some plans。

2。

What was the normal price of the T-shirt?A。

＄15. B. ＄30。

C。

＄50。

3。

What has the woman decided to do on Sunday afternoon?A. To attend a wedding。

B. To visit an exhibition。

C。

To meet a friend.4. When does the bank close on Saturday？A。

At l:00 p。

m。

B。

At 3:00 p.m。

C。

At 4:00 p.m。

5. Where are the speakers？A。

In a store.B。

In a classroom。

C. At a hotel。

第二节听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后,各个小题将给出5秒钟的作答时间.每段对话或独白读两遍。

听第6段材料，回答第6、7题。

6。

What do we know about Nora?A. She prefers a room of her own。

2015-2016学年高二英语下学期暑假作业试题（18）一、阅读理解(本大题共5小题，共38.0分)AArriving in Sydney on his own from India, my husband, Rashi d, stayed in a hotel for a short time while looking for a house f or me and our children.During the first week of his stay, he went out one day to do so me shopping. He came back in the late afternoon to discover t hat his suitcase was gone. He was extremely worried as the s uitcase had all his important papers, including his passport （护照）.He reported the case to the police and then sat there, lo st and lonely in strange city, thinking of the terrible troubles of getting all the paperwork organized again from a distant count ry while trying to settle down in a new one.Late in the evening, the phone rang. It was a stranger. He was trying to pronounce my husband’s name and was aski ng him a lot of questions. Then he said they had found a pile of papers in their trash can（垃圾桶）that had been left out on the footpath.My husband rushed to their home to find a kind family h olding all his papers and documents. Their young daughter ha d gone to the trash can and found a pile of unfamiliar papers. Her parents had carefully sorted them out, although they had f ound mainly foreign addresses on most of the documents. At l ast they had seen a half-written letter in the pile in which my husband had given his ne w telephone number to a friend.That family not only restored the important documents t o us that day but also restored our faith and trust in people. W e still remember their kindness and often send a warm wish to their way.What did Rashid plan to do after his arrival in Sydney?A. Go shoppingB. Find a houseC. Join his familyD. Take his familyThe girl’s parents got Rashid’s phone number from_______. A. a friend of his family B. a Sydney policemanC. a letter in his papersD. a stranger in Sydney3. What does the underlined word “restored” in the last paragr aph mean?A. showedB. deliveredC. sent outD. gave back4. Which of the following can be the best title for the text?A. From India to Australia.B. Turning Trash to Treasure.C. Living in a New Country.D. In Search of New Friends.BEnglish is the most widely used language in the history of o ur planet. One in every seven human beings can speak it. Mo re than half of the world's books and three quarters of internat ional mails are in English. Of all languages, English has the la rgest vocabulary - perhaps as many as two million words.However, let's face it: English is a crazy language. There is no egg in an eggplant, neither pine nor apple in a pineapple a nd no ham in a hamburger. Sweet-meats are candy, while sweetbreads, which aren't sweet, are meat.We take English for granted. But when we explore its parad oxes (矛盾) , we find that quicksand can work slowly, boxing rings are square, public bathrooms have no baths in them. And why is i t that a writer writes, but fingers don't fing, grocers don't groce , and hammers don't ham? If the plural (复数形式) of tooth is teeth, shouldn't the plural of booth be beeth? One goose, two geese - so one moose, two meese? How can a slim chance and a fat chance be the same, while a wise man and a wise guy are opposites? How can overlook and overse e be opposites, while quite a lot and quite a few are alike? Ho w can the weather be hot as hell one day and cold as hell the next?English was invented by people, not computers, and it reflects the creativity of human beings. That's why, when stars are ou t, they are visible; but when the lights are out, they are invisibl e. And why, when I wind up my watch, I start it; but when I wind up this essay, I end it.5. According to the passage________.A. there should be eggs in an eggplantB. sweet-meats and sweetbreads are differentC. pineapples are the apples on the pine treeD. boxing rin gs should be round6. What does the author use most to prove his idea?A. Plurals.B. Paradoxes.C. Comparisons.（比较） D. Synonyms.（同义词）7. The underlined words "a wise guy" in paragraph 3 probably mean "______ ".A. somebody wiseB. a valuable chanceC. an opposite word D. a stupid person8. The last paragraph is written to show .A. English is importantB. a word may have s everal definitionsC. human beings are creativeD. why people inven ted English第二节(共5小题;每小题3分, 满分15分)根据短文内容，从短文后的选项中选出能填入空白处的最佳选项，并在答题卡上将该项涂黑。

2015—2016学年度第二学期高一英语05月份联考试卷第Ⅰ卷第一部分听力（共两节，每小题1.5分，满分30分。

）做题时，先将答案标在试卷上，录音内容结束后，你将有两分钟的时间将试卷上的答案转涂到答题卡上。

第一节听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1.What is the woman going to do tomorrow?A. Go fishingB. Go swimmingC. Go to the hospital2.How does the man find his job?A. It is interesting and fun.B. Its pay is good.C. It is always tiring.3.What are the speakers talking about?A.A story.B. A book.C.A movie.4.Where does the conversation probably take place?A. At the railway station.B. At the bus stop.C. At the airport.5.Where is the man going ?A. The classroom.B. The cinema.C. The library.第二节听下面5段对话或独白。

选出最佳选项。

请听第6段材料. 回答第6至7题。

6.Why is the man going to the United States?A. To travel.B. To visit his friends.C. To attend a conference.7.When will the man probably leave for the United States?A. In mid-February.B. In mid-January.C. In early January请听第7段材料，回答第8至9题。

2015-2016学年度第二学期高一年级英语学科期末试卷命题人：夏婷婷审题人：张晖注意：本卷共 10 页，满分110分时间：100分钟第Ⅰ卷第一部分听力（共两节，共20小题，共20分）第一节听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

（）1.How long does the woman want to stay？A. About seven days.B. About five days.C. About twelve days.（）2. How many people could go for a drive in the man's opinion？A. Only one of them.B. The two of them.C. Their whole family.（）3．Which of the following can tell the movie scared the girls？A. They couldn't stop talking about it.B. They screamed.C. They were talking loudly.（）4. What is the man doing？A. Making a request.B. Offering a suggestion.C. Asking for permission.（）5. How much is the man's telephone bill?A.＄50.B.＄24.C.＄30.第二节听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B, C三个选项中选出最佳选项，并标在试卷的相应位置。

听每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的作答时间。