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攀枝花学院课程考核命题暨试卷印刷审批表2、“院管课程”试卷印制须连同考试安排表一并上报。
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2008 ～2009 学年度第 二 学期《操作系统》试卷（B 卷）适用年级专业：2006级计算机科学与技术专业 考 试 形 式：（ ）开卷、（ √ ）闭卷二级学院： 行政班级： 学 号： 教 学 班： 任课教师： 姓 名： 注：学生在答题前，请将以上内容完整、准确填写，填写不清者，成绩不计。
共 五 大题 53 小题。
答案请直接写在试卷上！一、单项选择题（30 小题，每小题1分，共30分 请在备选答案中选出一个正确答案，并将其字母填入下表，填在其它地方不计分。
）1、下列四个操作系统中，是分时系统的为（ ）。
A 、CP ／MB 、MS －DOSC 、UNIXD 、WINDOWS NT2、操作系统内核与用户程序、应用程序之间的接口是（ ）。
A 、shell 命令B 、图形界面C 、系统调用D 、C 语言函数……………………………………………线………………………………………订………………………………………装…………………………………………………3、文件系统实现按名存取主要是通过（）来实现的。
A、查找位示图B、查找文件目录C、查找作业表D、内存地址转换4、下列叙述，正确的一条是（）A、在设备I/O中引入缓冲技术的目的是为了节省内存B、在请求页式管理中，FIFO置换算法的内存利用率是较高的C、处于阻塞状态的进程被唤醒后，可直接进入运行状态D、指令中的地址结构和外存容量是决定虚存作业地址空间的两个因素5、下述有关中断和陷入方式正确的叙述是。
（）A、处理机由用户态转到核心态，当中断陷入处理完后，再回到用户态执行用户程序.B、处理机由核心态转到用户态，当中断陷入处理完后，再回到核心态执行核心程序.C、处理机状态不变，当中断陷入处理完后，再回到核心态执行用户程序。
江苏省海安中学2025届高三年级学习测试数学试卷一､选择题：本题共8小题，每小题5分，共40分.在每小题给出的四个选项中，只有一个选项是正确的1.已知集合{}{}20,1,2,3,log 1A B xx ==≤∣，则A B ⋂=（ ）A.{}0,1,2B.{}1,2C.{}0,1D.{}12.命题“20,10x x x ∀>-+>”的否定为（ ）A.20,10x x x ∀>-+≤B.20,10x x x ∀≤-+≤C.20,10x x x ∃>-+≤D.20,10x x x ∃≤-+≤3.已知函数()21,0cos ,0x x f x x x ⎧+>=⎨≤⎩，则下列结论正确的是（ ）A.()f x 是偶函数B.()f x 是增函数C.()f x 是周期函数D.()f x 的值域为[)1,∞-+4.若a b >，则（ ）A.ln ln a b >B.0.30.3a b >C.330a b ->D.0a b ->5.已知函数()()1ln 1f x x x=+-，则()y f x =的图象大致是（ ）A. B.C. D.6.如图，矩形ABCD 的三个顶点A B C ､､分别在函数12,,xy y x y ===的图像上，且矩形的边分别平行于两坐标轴.若点A 的纵坐标为2，则点D 的坐标为（）A.11,24⎛⎫⎪⎝⎭ B.11,34⎛⎫ ⎪⎝⎭ C.11,23⎛⎫ ⎪⎝⎭ D.11,33⎛⎫ ⎪⎝⎭7.已知()912160,0,log log log a b a b a b >>==+，则ab=（ ）C.128.已知()()5,15ln4ln3,16ln5ln4a b c ==-=-，则（ ）A.a c b <<B.c b a <<C.b a c <<D.a b c<<二､多选题：本题共3小题，每小题6分，共18分.在每小题给出的选项中，有多项符合题目要求､全部选对得6分，部分选对的得部分分，选对但不全的得部分分，有选错的得0分9.下列函数中，在区间ππ,42⎛⎫⎪⎝⎭上单调递减的函数是（ ）A.πsin 4y x ⎛⎫=+ ⎪⎝⎭B.cos y x x=-C.sin2y x =D.πcos 3y x ⎛⎫=-⎪⎝⎭10.下面的结论中正确的是（ ）A.若22ac bc >，则a b >B.若0,0a b m >>>，则a m ab m b+>+C.若110,0,a b a b a b>>+=+，则2a b +≥D.若20a b >>，则()44322a b a b +≥-11.已知函数()cos sin2f x x x =，下列结论中正确的是（ ）A.()y f x =的图像关于()π,0中心对称B.()y f x =的图像关于π2x =对称C.()f xD.()f x 既是奇函数，又是周期函数三､填空题：本题共3小题，每小题5分，共15分.12.已知()(),f x g x 分别是定义在R 上的奇函数和偶函数，且()()321f x g x x x -=+-，则()()11f g +=__________.13.某市生产总值连续两年持续增加，第一年的增长率为p ，第二年的增长率为q ，则该市这两年生产总值的年平均增长率为__________.14.若存在实数t ，对任意的(]0,x s ∈，不等式()()ln 210x x t t x -+---≤成立，则整数s 的最大值为__________.（参考数据：ln3 1.099,ln4 1.386≈≈）四､解答题：本题共5小题，共77分.解答应写出文字说明､证明过程或演算步骤.15.（本题13分）如图1，在等腰直角三角形ABC 中，90,6,A BC D E ∠== ､分别是,AC AB 上的点，CD BE O ==为BC 的中点.将ADE 沿DE 折起，得到如图2所示的四棱锥A BCDE '-，其中AO =（1）求证：A O '⊥平面BCDE ；（2）求点B 到平面A CD '的距离.16.（本题15分）设数列{}n a 的各项均为正整数.（1）数列{}n a 满足1121212222n n n n a a a a n --++++= ，求数列{}n a 的通项公式；（2）若{}n a 是等比数列，且n a n ⎧⎫⎨⎬⎩⎭是递减数列，求公比q .17.（本题15分）已知函数()πsin (0)6f x x ωω⎛⎫=+> ⎪⎝⎭在2π0,3⎛⎤ ⎥⎝⎦上单调递增，在2π,π3⎛⎤ ⎥⎝⎦上单调递减，设()0,0x 为曲线()y f x =的对称中心.（1）求0x 的值；（2）记ABC 的角,,A B C 对应的边分别为,,a b c ，若0cos cos ,6A x b c =+=，求BC 边上的高AD 长的最大值.18.（本题17分）已知函数()()e ln xf x x m =-+.（1）当0m =时，求曲线()y f x =在点()()1,1f 处的切线方程；（2）当2m ≤时，求证()0f x >.19.（本题17分）在平面内，若直线l 将多边形分为两部分，多边形在l 两侧的顶点到直线l 的距离之和相等，则称l 为多边形的一条“等线”，已知O 为坐标原点，双曲线()2222:10,0x y E a b a b-=>>的左､右焦点分别为12,,F F E 的离心率为2，点P 为E 右支上一动点，直线m 与曲线E 相切于点P ，且与E 的渐近线交于,A B 两点，当2PF x ⊥轴时，直线1y =为12PF F 的等线.（1）求E 的方程；（2）若y =是四边形12AF BF 的等线，求四边形12AF BF 的面积；（3）设13OG OP =，点G 的轨迹为曲线Γ，证明：Γ在点G 处的切线n 为12AF F 的等线江苏省海安中学2025届高三年级学习测试数学试卷答案解析人：福佑崇文阁一､单选题：本大题共8小题，每题5分，共40分在每小题提供的四个选项中，只有一项是符合题目要求的.12345678BCDCBADB二､多选题：本题共3小题，每小题6分，共18分.在每小题给出的选项中，有多项符合题目要求.全部选对的得6分，部分选对的得部分分，有选错的得0分.91011ACACDABD三､填空题：本题共3小题，每小题5分，共15分.12.11-14.2四､解答题：本题共5小题，共77分，解答应写出文字说明､证明过程或演算步骤.15.【详解】（1）解：（1）连接,,45,3OD OE B C CD BE CO BO ∠∠====== ，在COD 中，OD ==，同理得OE =，因为6BC =，所以AC AB ==所以AD A D A E AE ='==='因为AO =所以222222,A O OD A D A O OE A E '+=='+''所以,A O OD A O OE'⊥⊥'又因为0,OD OE OD ⋂=⊂平面,BCDE OE ⊂平面BCDE 所以A O '⊥平面BCDE ；（2）取DE 中点H ，则OH OB ⊥以O 为坐标原点，,,OH OB OA '所在直线分别为,,x y z 轴，建立空间直角坐标系则()(()()0,0,0,,0,3,0,1,2,0O A C D --'，设平面A CD '的一个法向量为(),,n x y z =，又((),1,1,0CA CD ==' ，所以300n CA y n CD x y ⎧⋅==⎪⎨⋅=+=⎪'⎩，令1x =，则1,y z =-=，则(1,n =-，又()()0,3,0,0,6,0B CB =，所以点B 到平面A CD '16.【详解】（1）因为1121212222n n n na a a a n --++++= ，①所以当2n ≥时，1121211222n n a a a n --+++=- ，②由①-②得，12nn a =，所以2nn a =，经检验，当1n =时，12a =，符合题意，所以2nn a =（2）由题设知0q >.若1q =，则1,n n a a a n n n ⎧⎫=⎨⎬⎩⎭是递减数列，符合题意.若1q <，则当1log q n a >时，11nn a a q =<，不为正整数，不合题意.若1q >，则()()1111n n n qn n a a a n n n n +⎡⎤-+⎣⎦-=++，当1qn n >+，即11n q >-时，11n n a a n n +>+，这与n a n ⎧⎫⎨⎬⎩⎭是递减数列相矛盾，不合题意.故公比1q =.17.【详解】（1）因为()πsin 6f x x ω⎛⎫=+⎪⎝⎭在2π(0,}3上单调递增，在2π,π3⎛⎤⎥⎝⎦上单调递减，所以2π13f ⎛⎫=⎪⎝⎭且4π3T ≥，所以2πππ2π,362k k ω⋅+=+∈Z ，可知13,2k k ω=+∈Z ，又由2π4π3ω≥，可知302ω<≤，所以12ω=，故()1πsin 26f x x ⎛⎫=+ ⎪⎝⎭，由1ππ,26x m m +=∈Z ，可得π2π3x m =-，即0π2π,3x m m =-∈Z .（2）22222201()2362cos cos 2222b c a b c bc a bc a A x bc bc bc+-+----=====，化简得2363a bc =-，因为11sin 22ABC S a AD bc A =⋅=，所以AD =，所以()22223()3()44363bc bc AD a bc ==-，又b c +≥，所以9bc ≤，当且仅当3b c ==时取等号，所以()22223()3327363436343634499()bc AD bc bc bc ==≤=-⎡⎤⎛⎫-- ⎪⎢⎥⎝⎭⎣⎦，所以AD ≤，故AD.18.【详解】（1）当()()10,e ln ,e xxm f x x f x x==--'=，所以()1e 1k f '==-，而()1e f =，切线方程为()()e e 11y x -=--，即所求切线方程为()e 110x y --+=；（2）()f x 得定义域为()()1,,e xm f x x m∞='-+-+，设()()1e xg x f x x m='=-+，则()21e 0()xg x x m '=+>+，故()f x '是增函数，当x m →-时，(),f x x ∞∞→-→+'时，()f x ∞'→+，所以存在()0,x m ∞∈-+，使得001e x x m=+①，且()0,x m x ∈-时，()()0,f x f x '<单调递减，()0,x x ∞∈+时，()()0,f x f x '>单调递增，故()()0min 00()e ln xf x f x x m ==-+②，由①式得()00ln x x m =-+③，将①③两式代入②式，结合2m ≤得：min 000011()20f x x x m m m m x m x m =+=++-≥-=-≥++，当且仅当01x m =-时取等号，结合（2）式可知，此时()00e 0x f x =>，故()0f x >恒成立.19.【详解】（1）由题意知()()212,,,0,,0b P c F c F c a ⎛⎫- ⎪⎝⎭，显然点P 在直线1y =的上方，因为直线1y =为12PF F 的等线，所以222212,2,b ce c a b a a -====+，解得1a b ==，E 的方程为2213y x -=（2）设()00,P x y ，切线()00:m y y k x x -=-，代入2213y x -=得：()()()2222200000032230k xk kx y x k x y kx y -+--+-+=，故()()()22222000000243230k kx y kkx y kx y ⎡⎤-+-+-+=⎣⎦，该式可以看作关于k 的一元二次方程()22200001230x k x y k y --++=，所以000002200031113x y x y x k x y y ===-⎛⎫+- ⎪⎝⎭，即m 方程为()001*3y y x x -=当m 的斜率不存在时，也成立渐近线方程为y =，不妨设A 在B 上方，联立得A B x x ==，故02A B x x x +==，所以P 是线段AB 的中点，因为12,F F 到过O 的直线距离相等，则过O 点的等线必定满足：,A B 到该等线距离相等，且分居两侧，所以该等线必过点P ，即OP的方程为y =，由2213y y x ⎧=⎪⎨-=⎪⎩，解得x y ⎧=⎪⎨=⎪⎩，故P .所以03A A y ====，所以03B B y ====-，所以6A B y y -=，所以1212122ABCD A B A B S F F y y y y =⋅-=-=（3）设(),G x y ，由13OG OP =，所以003,3x x y y ==，故曲线Γ的方程为()229310x y x -=>由（*）知切线为n ，也为0093133x y y x -=，即00133y y x x -=，即00310x x y y --=易知A 与2F 在n 的右侧，1F 在n 的左侧，分别记12,,F F A 到n 的距离为123,,d d d ，由（2）知000011A A x y y y x x ===--，所以3d 由01x ≥得12d d ==因为231d d d +==，所以直线n 为12AF F .等线.。
2023年四川省攀枝花市成考专升本高等数学二自考真题(含答案)学校:________ 班级:________ 姓名:________ 考号:________一、单选题(30题)1.A.A.在(-∞，-1)内，f(x)是单调增加的B.在(-∞，0)内，f(x)是单调增加的C.f(-1)为极大值D.f(-1)为极小值2.A.A.B.C.D.3.4.袋中有5个乒乓球，其中4个白球，1个红球，从中任取2个球的不可能事件是A.A.{2个球都是白球}B.{2个球都是红球}C.{2个球中至少有1个白球)D.{2个球中至少有1个红球)5.A.A.F(x)B.-F(x)C.0D.2F(x)6.7.A.A.1.2B.1C.0.8D.0.7 8.9.10.11.A.A.1/26B.1/5C.1/2D.112.A.A.0B.1C.2D.313.若事件A与B为互斥事件，且P(A)=0．3，P(A+B)=0．8，则P(B)等于（）．A.A.0．3B.0．4C.0．5D.0．614.A.-1B.-1/2C.0D.115.A.A.-1B.-2C.1D.216.17.18.A.A.B.C.D.19.（）。
A.B.－1C.2D.－420.A.0B.C.D.21.设z=x3e y2，则dz等于【】A.6x2ye y2dxdyB.x2e y2(3dx+2xydy)C.3x2e y2dxD.x3e y2dy22.23.A.A.B.C.D.24.25.函数y=xe x单调减少区间是A.A.(-∞，0)B.(0，1)C.(1，e)D.(e，+∞)26.A.A.(-∞，0)B.(-∞，1)C.(0，+∞)D.(1，+∞)28.29.30.二、填空题(30题)31.32.33.34.35.36. 已知函数y的n-2阶导数y n-2=x2cosx，则y(n)=_________。
37.38. 函数f(x)=x/lnx的驻点x=_________。
攀枝花学院学生创新实验项目结题报告书项目名称：偏钛酸直接包膜生产钛白新工艺研究承接单位：攀枝花学院材料工程学院负责人：任杰小组成员：林睿何洋李思艾指导教师：邹建新完成时间：2012年10月28日教务处制二〇一年月一、课题名称：偏钛酸直接包膜生产钛白新工艺研究结题报告二、课题提出的背景：作为第三大无机化学品的二氧化钛，近几年全球需求持续保持高速增长，随着全球二氧化钛市场不断细分，大量新产品的出现使需求增幅更大。
未来几年全球二氧化钛需求年增速保持在2%～3%，但随着二氧化钛应用领域向功能材料的延伸，全球二氧化钛市场供应仍将进一步趋紧。
目前钛白生产方法主要有硫酸法和氯化法，而盐酸法在国外目前还处于产业化研究阶段。
从国外来看，氯化法约站60%，硫酸法约占40%。
在国内钛白生产还是主要以硫酸法为主，2009年占国内产能的99%，产出钛白约150万吨理论与实践意义。
攀枝花地区富含丰富的钛资源，已建成的钛白粉产能为25.5万吨/a，全部采用硫酸法生产。
国内除锦州钛白粉厂外，全部采用硫酸法进行生产，目前国内硫酸法钛白产能约150万吨，占总钛白产能的99%。
目前国内外硫酸法钛白的生产工艺是采用钛矿（钛渣）酸解后获得钛液（硫酸氧钛），经水解后得到偏钛酸，再通过高温煅烧获得TiO2粉末，如果是生产锐钛型钛白产品，则对该TiO2粉末可直接进行干磨即得到商品钛白，如果是生产金红石型钛白产品，则需对该TiO2粉末进行后处理（包膜）才能得到商品钛白。
在金红石钛白后处理过程中，需要对干粉状的钛白粗品加水使之变成液态状的浆料，经过砂磨机湿磨后包膜处理，再次干燥脱水并气流粉碎使之成为干粉状的钛白成品。
在此干燥过程中消耗了大量的热并带来设备投资（如喷雾干燥器等），同时，在此砂磨过程中也会消耗大量的电并带来设备投资（如耐驰卧式砂磨机等），由此引发环境污染等一系列问题。
若将包膜工序放在偏钛酸水洗及漂白工序后，直接对纯净的偏钛酸进行包膜处理，再经煅烧并气流粉碎后即可得商品钛白，该方法取消了干磨工序、打浆工序、干燥脱水工序和湿磨工序等四道工序，必将带来能耗和成本的大大降低，具有直接的巨大经济效益，也将为硫酸法钛白行业的发展带来新的机遇和动力，突破传统的生产工艺流程，对建立节能、环保、增效、短流程的硫酸法钛白工艺具有重要的理论和实际意义，同时也将为地方经济发展作出显著贡献。
2022年攀枝花攀西职业学院公共课《C语言》科目期末试卷B(有答案）一、填空题1、在C语言源程序中，一个变量代表【】。
2、执行下面程序段后，k的值是_______。
k=1；n=263；do{k*=n%10；n/=10；} while（n）；3、鸡兔共有30只，脚共有90只，下面程序段是计算鸡兔各有多少只。
请填空。
for（x=0；x<=30；x++）{y=30一x；if（_______）printf（"%d，%d\n"，x，y）；}4、设x的二进制数是11001101，若想通过x&y运算使x中的低4位不变，高4位清零，则y的二进制数是_______。
5、把int类型变量low中的低字节及变量high中的高字节放入变量s中的表达式是_______。
6、C语言所提供的基本数据类型包括：单精度型、双精度型、_______、_______和_______。
7、设有一输入函数scanf（"%d”，k）；它不能使float类型变量k得到正确数值的原因是_______未指明变量k的地址和_______格式控制符与变量类型不匹配。
8、下面程序段的运行结果是_______。
char ch[]="600"；int a，s=0；for（a=0；ch[a]>= '0'&&ch[a]<='9'；a++）s=10*s+ch[a]-'o'；printf（"%d"，s）；9、若有定义：doublex[3][5]；，则x数组中行下标的下限为_______，列下标的上限为_______。
10、下面程序可求出图中方括号内的元素之积，请填空。
# include<stdio.h>int main(){ int x[3][3]={7,2,1,3,4,8,9,2,6};int s,*p;p=_______;s=*p*_______;printf("product=%d",s);return(0);}二、选择题11、以下表达式值为3的是（ )A.16-13%10B.2+3/2C.14/3-2D.（2+6)/（12-9)12、设有说明语句：char w；intx；float y；double z；则表达式w*x+z-y值的数据类型为（）。
目录一、引言 (2)二、调查方案设计 (2)（一）问题研究方法 (2)（二）调查方针 (2)（三）问卷设计 (2)（四）调查对象 (2)（五）抽样方案 (3)三、调查实施 (3)四、调查分析设计 (4)（一）客户满意度指标体系设计 (4)（二）钱包份额分析方案 (5)五、调查结果 (5)（一）客户满意度调查结果 (5)（二）钱包份额调查结果 (8)六、局限性及必要说明 (11)（一）局限性 (11)（二）必要说明 (11)七、结论和建议 (12)（一）结论 (12)（二）建议 (12)八、附件 (13)附件一：调查问卷 (13)图一 (5)图二 (6)图三 (7)图四 (7)图五 (8)图六 (9)图七 (9)图八 (10)一、引言进入攀枝花学院已经整整三年，我们每天都过着四点一线的生活（教室——寝室——图书馆——食堂），食堂这个我们朝夕相处的地方，爱过，恨过，质疑过，也斗争过，对其的怨气已经积压了整整三个年头，对其的兴趣估计攀枝花学院的广大同学都是浓厚的。
当学习了《客户关系管理》课程中客户满意度指标体系以及客户终生价值分析后，再次激起了我对食堂的兴趣，此次我能用专业的工具分析、研究，不仅满足了自身的兴趣，也让我在实践中检验了书本理论知识，真正做到了学以致用。
二、调查方案设计（一）问题研究方法本次调查我们将采用实地问卷调查法，是直接从学生身上获得一手数据，通过这种方法，和定性研究我们希望能够描述攀枝花学院一食堂客户满意度，并进一步探究这种结果背后的的深层次原因。
（二）调查方针本次调查我们是本着自愿、公开、严密、谨慎的原则，对数据地进行的收集，本着科学、负责的原则，对数据进行专业的分析。
（三）问卷设计作为消费者我们所关心的话题无非是关于饭菜供应情况、环境、服务情况等，所以针对这个研究课题，我们从食物、环境、服务人员、创新、钱包份额五个维度设计问卷，其中食物方面有8个问题，环境方面有4个问题，服务人员方面有3个问题，创新方面有3个问题，钱包份额方面有4个问题。
2023年第六届华教杯全国大学生数学竞赛初赛真题（非数学类专业组）一、选择题（10题、3分/题）1．已知xxx +-=11)(α，333)(x x -=β，则当1→x 时（）．A ．)(x α是关于)(x β的2阶无穷小B ．)(x α与)(x β是高阶无穷小C ．)(x β与)(x α是等价无穷小D ．)(x α与)(x β是同阶无穷小，但不是等价无穷小2．=+-⎰dx xx e x2211(（）．A ．Cx e x++1B ．C x e x++21C ．C x e x++212D ．C xe x++2213．=++-⎰dx n x x n x x e x]2sin )sin (cos 2cos)cos [sin ππ（）．A ．C n x e x ++)2cos(πB ．Cn x e x++-)2cos(πC ．Cn x e x ++-)2tan(πD ．C n x e x++-)tan(π4．=++∑∑==∞→n i n j n j i ji n 11221lim （）．A ．2ln 2+πB ．2ln 2+πC ．3ln 2+πD ．3ln 2+π5．=+⎰πn dx x 0)2sin(1（）．A ．nB ．n2C ．n 3D ．n226．=++∞→nn n n 12)1(lim （）．A ．0B ．1C ．2D ．37．=+⎰-xdx x x 22322cos )sin (ππ（）．A ．2πB ．4πC ．6πD ．8π8．∑∞==≤≤-=022,,cos n na x nx ax ππ（）．A ．0B ．1C ．2D ．39．=++++++∞→（nn n n nn n n 1221212lim n 21（）．A ．ln2B ．ln3C ．2ln 1D ．3ln 110．设0022>->=b ac a R D ，，，=>+++=⎰⎰)0)2(222p cy bxy ax p dxdyI D （）．A ．2b ac p -πB ．bac p -πC ．bac p -2πD ．bac p -2π二、填空题（7题、4分/题）1．=--→1cos )sec(sin )sec(tan lim20x x x x ．2．=-+⎰dx xe x e x x 2)1()1(．3．点)2,2,2(0M 关于直线32431:-=+=-z y x L 的对称点1M 的坐标为．4．()()()⎰⎰=---Ddxdy xy x y y x 4122．其中y x x y D ==;:及)21,0(,.4122∈=--+y x y x y x 所围成的区域．5．正方形的边长L 以2m/s 的速度增大，当L=4m 时，其内接圆的面积的变化速率为．6．=⎪⎭⎫ ⎝⎛6sin)2023(π．7．设1321242n n x n-=⋅⋅⋅⋅，则=∞→n xn e lim ．三、解答题（3题、14分/题）1．设函数)(x f 在][b a ，上具有连续导数，若μλ，为实数且)()(21)(22a b a b dx x f ba-+-=⎰μλ，)(21)(31)(2233a b a b dx x xf ba-+-=⎰μλ，证明：存在)(b a ，∈ξ，使得λξ=)('f ．2．若!!21)(2n x x x x f nn ++++= ，其中n 为自然数，求方程0)()(1=+x f x f n n 在)(∞+-∞，内实根的个数．3．曲线],2[,sin ππ∈=x x y 绕y 轴旋转一周，求所得几何体的体积．2023年第六届华教杯全国大学生数学竞赛初赛真题（非数学类专业组）参考答案一、选择题1、D 2、B 3、B 4、B 5、D 6、B 7、D8、B9、C10、A二、填空题1、1-2、C xex+-113、)6,6,6(-4、614415、π46、23-7、1三、解答题1、【参考解析】考虑积分dx x f x b a x ba⎰---))()()(('λ，利用分布积分及)()(21)(22a b a b dx x f ba-+-=⎰μλ，)(21)(31)(2233a b a b dx x xf b a -+-=⎰μλ，有⎰⎰-++-----+b ab a badxx f x a b x f x b a x dx x ab ax bx )()2()())(()(2λ⎰⎰-++-=b a b a dxx xf dx x f b a a b )(2)()()(63λ))(21)(31(2))()(21)(()(62233223a b a b a b a b b a a b -+---+-++-=μλμλλ0=由积分中值定理知，存在)(b a ，∈ξ，使得λξ=)('f ．2、【参考解析】由题设知)(x f n 在)(∞+-∞，内连续，当n 为偶数时，,)(lim ,)(lim -∞=+∞=-∞→+∞→x f x f n n n n 故)(x f n 存在极小点0x ，则由()(),!!0000n x n x x f x f nn n n =+'=又(),10=n f 从而(),0>x f n 即()x f n 在()∞+∞-，内无实根．当n 为奇数时，()()，，-∞=+∞=-∞→+∞→x f x f n n n n lim lim 知()x f n 在区间()∞+∞-，内有实根．由()(),1x f x f n n -='而1-n 为偶数，则()0>'x f ，知()x f n 在区间()∞+∞-，严格单增，故其有唯一实根．从而()x f n ()x f n 1+无论n 为奇数还是偶数，它在()∞+∞-，内有唯一实根．3、【参考解析】曲线],2[,sin ππ∈=x x y 的反函数为]1,0[,arcsin ∈-=y y x π，所以所得几何体的体积为：⎰-=12)arcsin (dy y V ππ，设则即,sin ,arcsin u y u y ==⎰⎰-=-=202102cos )()arcsin (πππππudu u dy y V =)88(42-π+ππ．。
攀枝花学院2022～2023学年春季学期 2022级汉语言文学/中文专业《大学英语(2)》随堂测试本科试题卷考试时间： 45分钟(闭卷)院(系)：专业（专业方向）：班级：姓名：学号：Part I. Reading Comprehension (3%*10=30%)There are 2 passages in this part. Each passage is followed by some questions or unfinished statements. For each of them there are four choices marked A, B, C and D. You should decide on the best choice.Passage 1Have you ever wondered why birds sing? Maybe you thought that they were just happy. After all, you probably sing when you are happy.Some scientists believe that birds do sing some of the time just because they are happy. However, they sing most of the time for a very different reason. Their singing is actually a warning to other birds to stay out of their territory.Do you know what a “territory” is? A territory is an area that an animal, usually the male, claims (声称) as its own. Only he and his family are welcome there. No other families of the same species are welcome. Your house is your territory where only your family and friends are welcome. If a stranger should enter your territory and threaten you, you might shout. Probably this would be enough to frighten him away.If so, you have actually frightened the stranger away without having to fight him. A bird does the same thing. But he expects an outsider almost any time, especially at nesting (筑巢) season. So he is screaming all the time, whether he can see an outsider or not. This screaming is what we call a bird’s song, and it is usually enough to keep an outsider away.1. Some scientists believe that most of the time bird’s singing is actually ________.A. an expression of happinessB. a way of warningC. an expression of angerD. a way of greeting2. What is a bird’s “territory”?A. A place where families of other species are not accepted.B. A place where a bird may shout at the top of its voice.C. An area for which birds fight against each other.D. An area which a bird considers to be its own.3. Why do birds keep on singing at nesting season?A. Because they want to invite more friends.B. Because their singing helps frighten outsiders away.C. Because they want to find outsiders around.D. Because their singing helps get rid of their fears.4. How does the writer explain b irds’ singing?A. By comparing birds with human beings.B. By reporting experiment results.C. By describing birds’ daily life.D. By telling a bird’s story.5. What does the underline word “screaming” in paragraph 4 mean?A. 哭喊声B. 令人惊愕的C. 尖叫声D. 尖叫的Passage 2A letter written by Charles Darwin in 1875 has been returned to the Smithsonian Institution Archives (档案馆) by the FBI after being stolen twice.“We realized in the mid-1970s that it was missing,” says Effie Kapsalis, hea d of the Smithsonian Institution Archives. “It was noted as missing and likely taken by an intern (实习生), from what the FBI is telling us. Word got out that it was missing when someone asked to see the letter for research purposes,” and the intern put the letter back. “The intern likely took the letter again once nobody was watching it.”Decades passed. Finally, the FBI received a tip that the stolen document was located very close to Washington, D.C. Their art crime team recovered the letter but were unable to press charges because the time of limitations had ended. The FBI worked closely with the Archives to determine that the letter was both authentic and definitely Smithsonian’s property.The letter was written by Darwin to thank an American geologist, Dr. Ferdinand Vandeveer Hayden, for sending him copies of his research into the geology of the region that would become Yellowstone National Park.The letter is in fairly good condition, in spite of being out of the care of trained museum staff for so long. “It was luckily in good shape,” says Kapsalis, “and we just have to do some minor things in order to be able to unfold it. It has some glue on it that has colored it slightly, but nothing that will prevent us from using it. After it is repaired, we will take digital photos of it and that will be available online. One of our goals is to get items of high research value or interest to the public online.”It would now be difficult for an intern, visitor or a thief to steal a document like this. “Archiving prac tices have changed greatly since the 1970s,” says Kapsalis, “and we keep our high value documents in a safe that I don’t even have access to.”6. What happened to Darwin’s letter in the 1970s?A. It was recovered by the FBI.B. It was stolen more than once.C. It was put in the archives for research purposes.D. It was purchased by the Smithsonian Archives.7. What did the FBI do after the recovery of the letter?A. They proved its authenticity.B. They kept it in a special safe.C. They arrested the suspect immediately.D. They pressed criminal charges in vain.8. What is Darwin’s letter about?A. The evolution of Yellowstone National Park.B. His cooperation with an American geologist.C. Some geological evidence supporting his theory.D. His acknowledgement of help from a professional.9. What will the Smithsonian Institution Archives do with the letter according to Kapsalis?A. Reserve it for research purposes only.B. Turn it into an object of high interest.C. Keep it a permanent secret.D. Make it available online.10. What has the past half century witnessed according to Kapsalis?A. Growing interest in rare art objects.B. Radical changes in archiving practices.C. Recovery of various missing documents.D. Increases in the value of museum exhibits.Part II. Words in Use (2%*10=20%)There are 10 incomplete sentences in this part. For each sentence there are four choices marked A.B. C. and D. Choose the ONE answer that best completes the sentence.11. “We are sorry for the delay, but it’s not _________,” the waitress apologized to the travelers.A. intentionalB. ambitiousC. awkwardD. magnificent12. A library’s properties are not allowed ____________ outside except after a permission from librarystaff.A. takingB. being takingC. to takeD. to be taken13. Excited at the news, she jumped up and _________ her head against the bed.A. leanedB. ventC. terrifiedD. bumped14. My teacher pointed out several _________ that might have led to the failure of my essay.A. laundryB. shellC. massD. flaws15. My noisy, _______________ roommate constantly woke me up around three in the morning.A. unacceptableB. inconsiderateC. illiterateD. irregular16. Don’t let the fear of boredom prevent you from ________ these benefits out of your adventure alone.A. hauntingB. reapingC. blurtingD. sowing17. _________ he hesitated, embarrassed and seemingly at a loss for words. Then he answered thequestion in a low voice.A. Once in a whileB. For a moment or twoC. At a timeD. For some time18. For some people, it’s difficult to _________ a conversation with a complete stranger, but for some it’seasy to shoot the breeze with a stranger.A. do justiceB. work outC. strike upD. lose sight of19. Kevin Ross made national headlines when he completed four years of college and was found to be_________, unable to read or spell.A. inevitableB. illiterateC. illegalD. immature20. Change can cause harm, particularly if we are not prepared to _________ it.A. adjust toB. account forC. contribute toD. look upPart III. Cloze (2%*10=20%)Directions：Decide which of the following words given below would best complete the passage if inserted in the corresponding blanks.Everyone wants to win a first-place blue ribbon, to be the best in something. Even kids in Kindergarten want that blue ribbon. In sports, I was never a blue-ribbon person. In a race, I was always 21 . In baseball I was likely to be hit on the head or drop the ball. During the spring of my kindergarten year, our class had a field trip to a park in a town about twenty miles away. Making that drive now is no big 22 but when you’re six and you’ve lived in a town of 300 people all your life, going to a big town of a couple of thousand people is really something.I don’t remember too much about it. But there was one that I will never forget — the three-legged race. The parents tied our feet together. One little boy got me for a 23 . He was the second most 24 boy in our class so he usually won at everything and I knew that with me tied to him he didn’t have a chance. And I’m sure he knew he was in trouble. The gun sounded and we were off. Some couples were falling and stumbling all around us, 25 we stayed on our feet and made it to the other side.26 , when we turned around and headed back for home, we were in the lead! Only one couple had a chance to win, and they were a good several yards behind us.A few feet from the finish line, disaster struck: I tripped and fell. We were 27 enough that my partner could have easily dragged me across the finish line and won. But he didn’t. Instead he stopped, 28 down and helped me up — just at the other couple crossed the finish line. As a result,we received a small red ribbon for coming in second.I still remember that moment when the young boy decided that helping a friend get on her feet was more important than winning a blue ribbon. And 13 years later, I still have that little ribbon because it’s a 29 that a friend like this boy is one who really 30 .21. A. last B. first C. quick D. successful22. A. question B. event C. one D. deal23. A. partner B. helper C. supporter D. competitor24. A. tallest B. youngest C. athletic D. handsome25. A. but B. therefore C. however D. and26. A. Silently B. Unbelievably C. Secretly D. Undoubtedly27. A. strong B. brave C. clever D. close28. A. lay B. slowed C. moved D. reached29. A. warning B. reminder C. gift D. notice30. A. depends B. counts C. supports D. worthyPart IV. Expressions in Use. (3%*10=30%)Fill in the blanks with the expressions given below. Change the form where necessary. Each31. Freshmen at most universities lean on heavily peer groups because they are completely new to thecollege environment.32. It’s OK to take good memories from high school with you to college, but make sure not to get caughtup in them.33. Both teachers and students have powerful reasons to hold fast to their traditional positions.34. They decided to write the book because many people seemed to have lost sight of what it means totake a trip.35. To get myself ready to climb the world’s major mountains, I started to work out in a gym and climbthe local mountains.36. Do you want to eat at the school canteen or order in a pizza?37. I don’t know how I’d have done on this adventure without her, but surely she has made the journeymore rewarding, to say the least.38. This is the only picture I have that does justice to the beauty of the valley.39. She just now bumped into one of her high school classmates on campus.40. My mom used to wash clothes for me, but now I have to learn to do (my) laundry by myself.。
2014～2015学年度第二学期《C++程序设计》试卷（A 卷）一、判断题（每小题1分，共5分）1、抽象类可以实例化对象。
（）2、友元函数可以访问该类的私有数据成员。
（）3、C++语言支持封装性和继承性，不支持多态性。
（）4、纯虚函数是在抽象类中说明的虚函数，它在该抽象类中没有定义具体的操作内容。
（）5、析构函数和构造函数都能被继承。
（）二、选择题（每小题2分，共50分）1、在C++中，源程序变为可执行程序的正确顺序应该是（）。
A.编辑、链接、编译、执行B.编辑、编译、链接、执行C.编译、编辑、链接、执行D.编译、链接、编辑、执行2、下列关于C++与C 语言的关系描述中,错误的是（）。
A.C 语言是C++语言的一个子集 B.C++与C 语言是兼容的C.C++对C 语言进行了一些改进 D.C++和C 语言都是面向对象的3、cout 是I0流库预定义的（）。
A.类 B.对象 C.包含文件 D.常量4、任意一个类，析构函数的个数最多是（）。
A.不限个数 B.1 C.2 D.35、在函数定义前加上关键字“inline ”表示该函数被定义为（）。
A.重载函数 B.内联函数 C.成员函数 D.普通函数6、下面有关重载函数的说法中正确的是（）。
A.重载函数必须具有不同的返回值类型B.重载函数形参个数必须不同C.重载函数必须有不同的形参列表D.重载函数名可以不同7、编译时的多态性可以通过使用（）获得。
A.虚函数和指针 B.重载函数和析构函数C.虚函数和对象 D.虚函数和引用8、分析以下程序：#include <iostream>using namespace std;void fun(int num)得分阅卷人得分阅卷人{cout<<num<<endl;}void fun(char ch){cout<<(ch+1)<<endl;}int main(){fun('A');return0;}以上程序的输出结果是（）。
