新题型组合训练4

2020河南中考新题型组合训练05一、完形填空I went to school in China for four years and for another six years in Canada. There are two teachers from these countries that really impressed me even though they are very 1 .When I 2 to Canada, I couldn't even order food on the flight. After two months on an ESL (English as a Second Language) course. I got my first 3 card. My mark in English was 65. I was very 4 . I couldn't 5 what would be said at the parent-teacher interview.“Hello!” Mrs. Franceschini welcomed my parents. “Richard just came to Canada a few months ago. I am amazed at how his English has 6 so fast.” she said. “On his first day, he was very shy and only use 7 words. Now he can answer and ask questions by using the whole sentences.”8 many other Chinese parents, my mom asked if she could give me extra homework. Don’t worry.Richard is already working very hard, “Mrs. Franceschini laughed. Then she shook my hand. “Richard, you did a good job. I am 9 of you!” she said.Back in Shanghai, my teacher Miss Li was very 10 . In a test, my average (平均分) was 97, the top of the class. I was proud to take my parents 11 the interview.Miss Li told my parents, Feng Yu is doing pretty well. But because of his 12 , he lost 3 points math. Otherwise he would be the top of the school I thought she was being 13 to me. But when I was about to leave, I realized Miss Li was very nice. She hosted a party for me and gave me a big card. Her phone number and e-mail address were on the card. “Feng Yu, you are my best student. I 14 you a successful life,” she wrote. If you want to talk or need any help, I am always here for you.”Miss Li and Mrs. Franceschini are both great teachers, just in different ways. One built up my learning abilities. 15 gave me tons of confidence and made learning enjoyable. I'm proud to have had them as my teachers.( ) 1. A. kind B. strict C. similar D. different( ) 2. A. moved B. arrive C. reached D. visited( ) 3. A. birthday B. green C. report D. ID( ) 4. A. satisfied B. upset C. serious D. careful( ) 5. A. imagine B. tell C. wonder D. doubt( ) 6. A. changed B. improved C. spoken D. increase( ) 7. A. long B. popular C. simple D. complete( ) 8. A. With B. Except C. Against D. Like( ) 9. A. proud B. certain C. afraid D. free( ) 10. A patient B. strict C. friendly D. hard-working( ) 11. A. in B. off C. to D. up( ) 12. A. method B. action C. habit D. carelessness( ) 13. A. unfair B. nice C. crazy D. polite( ) 14. A. hope B. prepare C. offer D. wish( ) 15. A. Other B. The other C. Another D. The others二、语篇填空第一节：阅读短文，从方框中选择适当的词并用其正确形式填空，使短文通顺、意思完整。

目录专题01 集合与常用逻辑用语（解析版）专题02 函数（1）（解析版）专题03 函数（2）（解析版）专题04 函数（3）（解析版）专题05 导数及其应用（解析版）专题06 不等式（解析版）专题07 数列（1）（解析版）专题08 数列（2）（解析版）专题09 平面向量（解析版）专题10 复数、推理与证明（解析版）专题11 排列组合和概率统计（解析版）专题12 三角函数（1）（解析版）专题13 三角函数（2）（解析版）专题14 三角函数（3）（解析版）专题15 平面解析几何（1）（解析版）专题16 平面解析几何（2）（解析版）专题17 平面解析几何（3）（解析版）专题18 立体几何（1）（解析版）专题19 立体几何（2）（解析版）专题20 立体几何（3）（解析版）专题01 集合与常用逻辑用语多项选择题1．（2019秋•启东市期末）已知全集U R =，集合A ，B 满足A B Ü，则下列选项正确的有()A ．AB B= B ．A B B= C ．()U A B =∅ ðD ．()U A B =∅ ð【分析】利用A B Ü的关系即可判断．【解答】解：A B Ü，A B A ∴= ，A B B = ，()U C A B =≠∅ ，()U A C B =∅ ， 故选：BD ．2．（2019秋•宿迁期末）已知集合[2A =，5)，(,)B a =+∞．若A B ⊆，则实数a 的值可能是( ) A ．3−B ．1C ．2D ．5【分析】利用A B ⊆，求出a 的范围，即可判断． 【解答】解：A B ⊆ ， 2a ∴<，故选：AB ．3．（2019秋•临高县校级期末）已知{A =第一象限角}，{B =锐角}，{C =小于90°的角}，那么A 、B 、C 关系是( )A ．B AC = B ．B C C = C ．B A B =D ．A B C ==【分析】可看出，“小于90°的角“和”第一象限的角“都包含”锐角“，从而可判断出选项B ，C 都正确；而小于90°的角里边有小于0°的角，而小于0°的角里边有第一象限角，从而可判断选项A 错误，而选项D 显然错误，从而可得出正确的选项．【解答】解： “小于90°的角”和“第一象限角”都包含“锐角”，B C ∴⊆，B A ⊆B C C ∴= ，B A B = ；“小于90°的角“里边有”第一象限角”，从而B A C ≠ ． 故选：BC ．4．（2019秋•聊城期末）若“2340x x +−<”是“22(23)30x k x k k −+++>”的充分不必要条件，则实数k 可以是( ) A ．8−B ．5−C ．1D ．4【分析】分别解出” 2340x x +−<”，“ 22(23)30x k x k k −+++>”，根据2340x x +−<”是“22(23)30x k x k k −+++>”的充分不必要条件，即可得出． 【解答】解：“2340x x +−<” 43x ⇔−<<． “22(23)30x k x k k −+++>” x k ⇔<，或3x k >+．“2340x x +−<”是“22(23)30x k x k k −+++>”的充分不必要条件，3k ∴…，或43k −+…，解得：3k …，或7k −…， 则实数k 可以是AD ． 故选：AD ．5．（2019秋•临沂期末）对于①sin 0θ>，②sin 0θ<，③cos 0θ>，④cos 0θ<，⑤tan 0θ>，⑥tan 0θ<，则θ为第二象限角的充要条件为( ) A ．①③B ．①④C ．④⑥D ．②⑤【分析】根据三角函数角的符号和象限之间的关系分别进行判断即可． 【解答】解：假设θ为象限角则①sin 0θ>，则θ为第一象限角或θ为第二象限角， ②sin 0θ<，则θ为第三象限角或θ为第四象限角 ③cos 0θ>，则θ为第一象限角或θ为第四象限角 ④cos 0θ<，则θ为第二象限角或θ为第三象限角 ⑤tan 0θ>，则θ为第一象限角或θ为第三象限角 ⑥tan 0θ<，则θ为第二象限角或θ为第四象限角， 若θ为第二象限角，则①④可以④⑥可以， 故选：BC ．6．（2019秋•泰安期末）下列选项中，p 是q 的必要不充分条件的是( )A ．:37p m <<；q ：方程22173x y m m +=−−的曲线是椭圆B ．:8p a …；q ：对[1x ∀∈，3]不等式20x a −…恒成立C ．设{}n a 是首项为正数的等比数列，p ：公比小于0；q ：对任意的正整数n ，2120n n a a −+<D ．已知空间向量(0a = ，1，1)−，(b x = ，0，1)−，:1p x =；q ：向量a与b 的夹角是3π【分析】A ，根据椭圆的方程以及充分条件和必要条件的定义进行判断即可；B ，求出，[1x ∀∈，3]不等式20x a −…恒成立等价于2a x …恒成立，即等价于9a …，即可判断；C ，根据等比数列的性质以及充分条件和必要条件的定义进行判断即可；D ，根据空间两向量的夹角大小求出x 的值，再根据充分必要条件的定义即可判断；【解答】解：A ，若方程22173x y m m +=−−的曲线是椭圆， 则703073m m m m −>−> −≠−，即37m <<且5m ≠， 即“37m <<”是“方程22173x y m m +=−−的曲线是椭圆”的必要不充分条件； B ，[1x ∀∈，3]不等式20x a −…恒成立等价于2a x …恒成立，等价于9a …； ∴ “8a …”是“对[1x ∀∈，3]不等式20x a −…恒成立”必要不充分条件； :{}n C a 是首项为正数的等比数列，公比为q ，∴当11a =，12q =−时，满足0q <，但此时12111022a a +=−=>，则2120n n a a −+<不成立，即充分性不成立，反之若2120n n a a −+<，则2221110n n a q a q −−+< 10a > ，22(1)0n q q −∴+<，即10q +<，则1q <−，即0q <成立，即必要性成立，则“0q <”是“对任意的正整数n ，2120n n a a −+<”的必要不充分条件．D ：空间向量(0a =，1，1)−，(b x = ，0，1)−，则001a b =++ ， cos a ∴<，1cos 32||||a bb a b π>===×，解得1x =±，故“1x =”是“向量a与b 的夹角是3π”的充分不必要条件．故选：ABC ．7．（2019秋•青岛期末）已知集合{(M x =，)|()}y y f x =，若对于1(x ∀，1)y M ∈，2(x ∃，2)y M ∈，使得12120x x y y +=成立，则称集合M 是“互垂点集”．给出下列四个集合：21{(,)|1}M x y y x ==+；{2(,)|M x y y ==；3{(,)|}x M x y y e =；4{(,)|sin 1}M x y y x ==+．其中是“互垂点集”集合的为( )A ．1MB ．2MC ．3MD ．4M【分析】根据题意即对于任意点1(P x ∀，1)y ，在M 中存在另一个点P ′，使得OP OP ⊥′．，结合函数图象进行判断．【解答】解：由题意，对于1(x ∀，1)y M ∈，2(x ∃，2)y M ∈，使得12120x x y y +=成立即对于任意点1(P x ∀，1)y ，在M 中存在另一个点P ′，使得OP OP ⊥′．21y x =+中，当P 点坐标为(0,1)时，不存在对应的点P ′．所以所以1M 不是“互垂点集”集合，y=所以在2M 中的任意点1(P x ∀，1)y ，在2M 中存在另一个点P ′，使得OP OP ⊥′ ． 所以2M 是“互垂点集”集合，x y e =中，当P 点坐标为(0,1)时，不存在对应的点P ′．所以3M 不是“互垂点集”集合，sin 1y x =+的图象中，将两坐标轴进行任意旋转，均与函数图象有交点， 所以所以4M 是“互垂点集”集合， 故选：BD ．8．（2019秋•淮安期末）已知函数2()43f x x x =−+，则()0f x …的充分不必要条件是( ) A ．[1，3]B ．{1，3}C ．(−∞，1][3 ，)+∞D ．(3,4)【分析】由()0f x …，得2430x x −+…，解得3x …或1x …．由此能求出()0f x …的充分不必要条件． 【解答】解：函数2()43f x x x =−+，由()0f x …，得2430x x −+…， 解得3x …或1x …．()0f x ∴…的充分不必要条件是{1，3}和(3,4)， 故选：BD ．9．（2019秋•镇江期末）使不等式110x+>成立的一个充分不必要条件是( ) A ．2x > B ．0x …C ．1x <−或1x >D ．10x −<<【分析】不等式110x+>，即10x x +>，(1)0x x +>，解得x 范围，即可判断出结论． 【解答】解：不等式110x +>，即10x x+>，(1)0x x ∴+>，解得0x >，或1x <−． 使不等式110x+>成立的一个充分不必要条件是：2x >．及1x <−，或1x >． 故选：AC ．10．（2019秋•连云港期末）已知p ，q 都是r 的充分条件，s 是r 的必要条件，q 是s 的必要条件，则( ) A ．p 是q 的既不充分也不必要条件 B ．p 是s 的充分条件 C ．r 是q 的必要不充分条件 D ．s 是q 的充要条件【分析】由已知可得p r s q ⇒⇒⇒；q r s ⇒⇒，然后逐一分析四个选项得答案． 【解答】解：由已知得：p r s q ⇒⇒⇒；q r s ⇒⇒．p ∴是q 的充分条件；p 是s 的充分条件；r 是q 的充要条件；s 是q 的充要条件．∴正确的是B 、D ．故选：BD ．11．（2019秋•苏州期末）已知集合{|2}A x ax =…，{2B =，若B A ⊆，则实数a 的值可能是( ) A ．1−B ．1C ．2−D ．2【分析】通过集合的包含关系，判断元素的关系，通过选项的代入判断是否成立．【解答】解：因为集合{|2}A x ax =…，{2B =，B A ⊆， 若1a =−，[2A −，)+∞，符合题意，A 对； 若1a =，(A −∞，2]，符合题意，B 对； 若2a =−，[1A −，)+∞，符合题意，C 对；若1a =，(A −∞，1]，不符合题意，D 错； 故选：ABC ．12．（2019秋•济宁期末）下列命题中的真命题是( ) A ．x R ∀∈，120x −> B ．*x N ∀∈，2(1)0x −> C ．x R ∃∈，1lgx <D ．x R ∃∈，tan 2x =【分析】根据指数函数的值域，得到A 项正确；根据一个自然数的平方大于或等于0，得到B 项不正确；根据对数的定义与运算，得到C 项正确；根据正弦函数tan y x =的值域，得D 项正确．由此可得本题的答案．【解答】解： 指数函数2t y =的值域为(0,)+∞∴任意x R ∈，均可得到120x −>成立，故A 项正确；当*x N ∈时，1x N −∈，可得2(1)0x −…，当且仅当1x =时等号 ∴存在*x N ∈，使2(1)0x −>不成立，故B 项不正确；当1x =时，01lgx =<∴存在x R ∈，使得1lgx <成立，故C 项正确；正切函数tan y x =的值域为R∴存在锐角x ，使得tan 2x =成立，故D 项正确 故选：ACD ．13．（2019秋•薛城区校级月考）已知集合{|1}A x ax ==，{0B =，1，2}，若A B ⊆，则实数a 可以为( ) A ．12B ．1C ．0D ．以上选项都不对【分析】由子集定义得A =∅或{1}A =或{2}A =，从而1a 不存在，11a=，12a =，由此能求出实数a ．【解答】解： 集合{|1}A x ax ==，{0B =，1，2}，A B ⊆， A ∴=∅或{1}A =或{2}A =，∴1a 不存在，11a=，12a =，解得1a =，或1a =，或12a =． 故选：ABC ．14．（2019秋•桥西区校级月考）设集合2{|0}A x x x =+=，则下列表述不正确的是( ) A ．{0}A ∈B ．1A ∉C ．{1}A −∈D ．0A ∈【分析】求出集合2{|0}{0A x x x =+==，1}−，利用元素与集合的关系能判断正确结果． 【解答】解：集合2{|0}{0A x x x =+==，1}−， 0A ∴∈，1A −∈，{0}A ⊂，{1}A −⊂，1A ∉． AC ∴选项均不正确，BD 选项正确．故选：AC ．15．（2019秋•葫芦岛月考）已知集合2{|20}Ax x x =−=，则有( ) A ．A ∅⊆B ．2A −∈C ．{0，2}A ⊆D ．{|3}A y y ⊆<【分析】可以求出集合A ，根据子集的定义及元素与集合的关系即可判断每个选项的正误． 【解答】解：{0A = ，2}，A ∴∅⊆，2A −∉，{0，2}A ⊆，{|3}A y y ⊆<．故选：ACD ．16．（2019秋•临淄区校级月考）设全集U ，则下面四个命题中是“A B ⊆”的充要条件的命题是( ) A ．A B A =B ．U UA B ⊇痧C ．U B A =∅ ðD ．U A B =∅ ð【分析】根据集合的补集，两个集合的交集、并集的定义，再由充要条件的定义判断哪些选项符合条件． 【解答】解：对于选项A ，由A B A = ，可得A B ⊆．由A B ⊆ 可得A B A = ，故选项A ，A B A = 是命题A B ⊆的充要条件，故A 满足条件． 对于选项B ，由S SA B ⊇痧 可得A B ⊆，由A B ⊆ 可得S SA B ⊇痧，故S SA B ⊇痧 是命题A B ⊆的充要条件，故B 满足条件．对于选项C ，由S B A φ= ð，可得A B ⊆，由A B ⊆ 可得S B A φ= ð，故S B A φ= ð 是命题A B ⊆的充要条件，故C 满足条件．对于选项D ，由S A B φ= ð，可得B A ⊆，不能退出A B ⊆，故选项D ，S A B φ= ð不是命题A B ⊆的充要条件，故D 不满足条件． 故选：ABC ．17．（2019秋•葫芦岛月考）已知集合{||4}A x Z x =∈<，B N ⊆，则( )A ．集合B N N =B ．集合A B 可能是{1，2，3}C ．集合A B 可能是{1−，1}D ．0可能属于B【分析】根据Z ，N 的定义，及集合元素的特点进行逐一判断即可． 【解答】解：因为B N ⊆，所以B N N = ，故A 正确．集合A 中一定包含元素1，2，3，集合B N ⊆，1，2，3都属于集合N ，所以集合A B 可能是{1，2，3}正确．1−不是自然数，故C 错误．0是最小的自然数，故D 正确． 故选：ABD ．18．（2019秋•市中区校级月考）给出下列关系，其中正确的选项是( ) A ．{{}}∅∈∅B ．{{}}∅∉∅C ．{}∅∈∅D ．{}∅⊆∅【分析】根据元素与集合的关系，集合并集的运算，空集是任何集合的子集即可判断每个选项的正误． 【解答】解：显然∅不是集合{{}}∅的元素，A ∴错误；∅不是集合{{}}∅的元素，∅是{}∅的元素，∅是任何集合的子集，从而得出选项B ，C ，D 都正确．故选：BCD ．19．（2019秋•罗庄区期中）给出下列四个条件：①22xt yt >；②xt yt >；③22x y >；④110x y<<．其中能成为x y >的充分条件的是( ) A ．①B ．②C ．③D ．④【分析】首先分清条件与结论，条件是所选答案，结论是x y >，充分性即为所选答案推出x y >． 【解答】解：①．由22xt yt >可知，20t >，故x y >．故①是．②．由xt yt >可知，0t ≠，当0t <时，有x y <；当0t >时，有x y >．故②不是． ③由22x y >，则||||x y >，推不出x y >，故③不是； ④．由110x y <<．由函数1y x=在区间(0,)+∞上单调递减，可得0x y >>，故④是． 故选：AD ．20．（2019秋•宁阳县校级期中）若220x x −−<是2x a −<<的充分不必要条件，则实数a 的值可以是( ) A ．1B ．2C ．3D ．4【分析】求解一元二次不等式，把若220x x −−<是2x a −<<的充分不必要条件转化为(1−，2)(2−Ü，)a ，由此得到a 的范围，则答案可求．【解答】解：由220x x −−<，解得12x −<<． 又220x x −−<是2x a −<<的充分不必要条件，(1∴−，2)(2−Ü，)a ，则2a …． ∴实数a 的值可以是2，3，4． 故选：BCD ．21．（2019秋•薛城区校级期中）若集合M N ⊆，则下列结论正确的是( ) A ．M N M =B ．M N N =C ．M M N ⊆D ．M N N ⊆【分析】利用子集、并集、交集的定义直接求解． 【解答】解： 集合M N ⊆， ∴在A 中，M N M = ，故A 正确；在B 中，M N N = ，故B 正确； 在C 中，M M N ⊆ ，故C 正确； 在D 中，M N N ⊆ ，故D 正确． 故选：ABCD ．22．（2019秋•凤城市校级月考）下列命题正确的有( ) A ．A ∅=∅ B ．()U UU A B A B = 痧?C ．A B B A =D ．()U U A A =痧【分析】利用集合的交、并、补运算法则直接求解． 【解答】解：在A 中，A A ∅= ，故A 错误； 在B 中，()()()U U U A B A B = 痧?，故B 错误； 在C 中，A B B A = 同，故C 正确； 在D 中，()U U A A =痧，故D 正确． 故选：CD ．23．（2019秋•北镇市校级月考）已知集合{2M −，2334x x +−，24}x x +−，若2M ∈，则满足条件的实数x 可能为( ) A ．2B ．2−C ．3−D ．1【分析】根据集合元素的互异性2M ∈必有22334x x =+−或224x x =+−，解出后根据元素的互异性进行验证即可．【解答】解：由题意得，22334x x =+−或224x x =+−， 若22334x x =+−，即220x x +−=， 2x ∴=−或1x =，检验：当2x =−时，242x x +−=−，与元素互异性矛盾，舍去； 当1x =时，242x x +−=−，与元素互异性矛盾，舍去． 若224x x =+−，即260x x +−=， 2x ∴=或3x =−， 经验证2x =或3x =−为满足条件的实数x ． 故选：AC ．24．已知集合{|32A x x a b ==+，a ，}b Z ∈，{|23B x x a b ==−，a ，}b Z ∈，则( ) A ．A B ⊆B ．B A ⊆C ．A B =D ．A B =∅【分析】利用集合的基本关系可判断集合的关系．【解答】解：已知集合{|32A x x a b ==+，a ，}b Z ∈，{|23B x x a b ==−，a ，}b Z ∈， 若x 属于B ，则：233*(2)2*(2)x a b a b a =−=−+−； 2a b −、2a −均为整数，x 也属于A ，所以B 是A 的子集；若x 属于A ，则：322*(3)3*x a b a b =+=+−（a ）； 3a b +、a 均为整数，x 也属于B ，所以A 是B 的子集；所以：A B =， 故选：ABC ．25．已知集合2{|10}A x x =−=，则下列式子表示正确的有( ) A ．{1}A ∈B ．1A −⊆C ．A ∅⊆D ．{1，1}A −⊆【分析】利用集合与集合基本运算求出A 集合，再由集合与集合的关系，元素与集合的关系判断可得答案， 【解答】解：已知集合2{|10}{1A x x =−==−，1}，由集合与集合的关系，元素与集合的关系判断可得：以上式子表示正确的有：A ∅⊆，{1，1}A −⊆． 故选：CD ．26．已知集合{|13}A x x =−<…，集合{|||2}B x x =…，则下列关系式正确的是( ) A ．A B =∅B ．{|23}A B x x =− 剟C ．{|1R A B x x =− …ð或2}x >D ．{|23}R A B x x =< …ð【分析】求解绝对值不等式化简集合B ，再利用交、并、补集的运算性质逐一分析四个选项得答案． 【解答】解：{|13}A x x =−< …，{|||2}{|22}B x x x x ==−剟?， {|13}{|22}{|12}A B x x x x x x ∴=−<−=−< 剟剟，故A 不正确； {|13}{|22}{|23}A B x x x x x x =−<−=− 剟剟?，故B 正确； {|2R Bx x =<− ð或2}x >， {|13}{|2R A B x x x x ∴=−<<− …ð或2}{|2x x x >=<−或1}x >−，故C 不正确； {|13}{|2R A B x x x x =−<<− …ð或2}{|23}x x x >=<…，故D 正确．∴正确的是B ，D ．故选：BD ．27．下列命题正确的是( )A ．“26x <<”是“24120x x −−<”的必要不充分条件B ．函数()tan 2f x x =的对称中心是(2k π，0)()k Z ∈ C ．“x R ∀∈，3210x x −+…”的否定是“x R ∃∈，3210x x −+>”D ．设常数a 使方程sin x x a +=在闭区间[0，2]π上恰有三个解1x ，2x ，3x 则12373x x x π++=【分析】A 由24120x x −−<，解得26x −<<，可得“26x <<”是“24120x x −−<”的充分不必要条件； B 由tan 20x =，解得2x k π=，即2k x π=，()k Z ∈，即可得出函数()tan 2f x x =的对称中心； C 取1x =−，则32110x x −+=−<，即可判断出；:sin D x x a +=化为sin()32ax π+=，由于常数a 使方程sin x x a +=在闭区间[0，2]π上恰有三个解1x ，2x ，3x ，则2a =，解得即可． 【解答】解：由24120x x −−<，解得26x −<<，因此“26x <<”是“24120x x −−<”的充分不必要条件，A不正确；由tan 20x =，解得2x k π=，即2k x π=，()k Z ∈因此函数()tan 2f x x =的对称中心是(2k π，0)()k Z ∈，B 正确；取1x =−，则32110x x −+=−<，因此“x R ∀∈，3210x x −+>” C 不正确；sin x x a =化为sin()32ax π+=，由于常数a 使方程sin x x a +=在闭区间[0，2]π上恰有三个解1x ，2x ，3x ，则2a=，解得33x ππ+=，3ππ−，23ππ+，12373x x x π∴++=，D 正确． 故选：BD ．28．有限集合S 中元素的个数记做()card S ，设A ，B 都为有限集合，下列命题中真命题是( ) A ．A B =∅ 的充要条件是()card A B card = （A ）card +（B ）B ．A B ⊆的必要条件是card （A ）card …（B ）C ．A B à的充要条件是card （A ）card …（B ）D ．A B =的充要条件是card （A ）card =（B ）【分析】分清集合之间的关系与各集合元素个数之间的关系，注意本题对充要条件的考查．集合的元素个数，体现两个集合的关系，但仅凭借元素个数不能判断集合间的关系，比如第四个句子元素个数相等，元素不一定相同．【解答】解：?A B =∅ 集合A 与集合B 没有公共元素，A 正确A B ⊆集合A 中的元素都是集合B 中的元素，B 正确A B à集合A 中至少有一个元素不是集合B 中的元素，因此A 中元素的个数有可能多于B 中元素的个数，C错误A B =集合A 中的元素与集合B 中的元素完全相同，两个集合的元素个数相同，并不意味着它们的元素相同，D 错误故选：AB ．29．使“a b <”成立的必要不充分条件是“( )”A ．0x ∀>，a b x +…B ．0x ∃…，a x b +<C ．0x ∀…，a b x <+D ．0x ∃>，a x b +… 【分析】根据不等式的关系结合必要不充分条件分别进行判断即可．【解答】解：若a b <，0x ∀>，则a x b x +<+，a a x <+ ，a a xb x ∴<+<+，即a b x <+，则a b x +…不一定成立；故A 错误，若a b <，当2a =，4b =，10x ∃=…，有a x b +<成立，反之不一定成立；故B 满足条件．0x ∀…，由a b <得a x b x +<+， 0x …，a x a ∴+…，即a a x b x +<+…则a b x <+成立，故C 满足条件，若a b <，当2a =，3b =，10x ∃=>，有a x b +…成立，反之不一定成立；故D 满足条件． 故选：BCD ．30．在下列结论中正确的是( )A ．“p q ∧”为真是“p q ∨”为真的充分不必要条件B ．“p q ∧”为假是“p q ∨”为真的充分不必要条件C ．“p q ∧”为真是“p ¬”为假的充分不必要条件D ．“p ¬”为真是“p q ∧”为假的充分不必要条件 【分析】利用复合命题真假的判定方法即可判断出结论．【解答】解：“p q ∧”为真是“p q ∨”为真的充分不必要条件，A 正确； “p q ∧”为假是“p q ∨”为真的充分不必要条件，B 不正确； “p q ∧”为真是“p ¬”为假的充分不必要条件，C 正确；“p ¬”为真，p 为假⇒ “p q ∧”为假，反之不成立，可能q 为假，p 为真，因此“p ¬”为真是“p q ∧”为假的充分不必要条件，D 正确． 故选：ACD ．专题02 函数（1）多项选择题1．（2019秋•清江浦区校级期末）已知函数()f x 是偶函数，且(5)(5)f x f x −=+，若()()sin g x f x x π=，()()cos h x f x x π=，则下列说法正确的是( ) A ．函数()y g x =是偶函数 B ．10是函数()f x 的一个周期C ．对任意的x R ∈，都有(5)(5)g x g x +=−D ．函数()y h x =的图象关于直线5x =对称【分析】根据题意，依次分析选项，综合即可得答案． 【解答】解：根据题意，依次分析选项：对于A ，()()sin g x f x x π=，()()sin ()()sin g x f x x f x x ππ−=−−=−−，又由函数()f x 是偶函数，则()()sin g x f x x π−=−， 即函数()g x 为奇函数，A 错误对于B ，由于()f x 是偶函数，且(5)(5)f x f x −=+，得(5)(5)(5)f x f x f x −=+=−，即(10)()f x f x +=， 则()f x 是周期为10的周期函数，所以(10)(10)cos(10)()cos ()h x f x x f x x h x πππ+=++==， 则()y h x =是的最小正周期为10，故B 正确；对于C ，(5)(5)sin((5))(5)sin(5)(5)(sin )(5)(sin )(5)sin (5)g x f x x f x x f x x f x x f x x g x ππππππ+=++=−+=−−=−−−=−=−，故C 正确；对于D ，(5)(5)cos(55)(5)cos(55)(5)cos(5510)(5)cos(55)(5)h x f x x f x x f x x f x x h x πππππ−=−−=+−=+−+=++=+， 所以函数()y h x =的图象关于直线5x =对称，D 正确； 故选：BCD ．2．（2019秋•胶州市期末）下列函数是偶函数的是( ) A ．()tan f x x =B ．()sin f x x =C ．()cos f x x =D ．()||f x lg x =【分析】根据题意，依次分析选项中函数的奇偶性，综合即可得答案． 【解答】解：根据题意，依次分析选项：对于A ，()tan f x x =，是正切函数，是奇函数，不符合题意； 对于B ，()sin f x x =，是正弦函数，是奇函数，不符合题意； 对于C ，()cos f x x =，是余弦函数，是偶函数，符合题意；对于D ，()||f x lg x =，其定义域为{|0}x x ≠有()||||()f x lg x lg x f x −=−==，是偶函数，符合题意； 故选：CD ．3．（2019秋•菏泽期末）对数函数log (0a y x a >且1)a ≠与二次函数2(1)y a x x =−−在同一坐标系内的图象不可能是( )A ．B ．C ．D ．【分析】对a 分类讨论，利用对数函数的单调性、二次函数的性质即可判断出结论．【解答】解：若1a >，则对数函数log a y x =在(0,)+∞上单调递增，二次函数2(1)y a x x =−−开口向上，对称轴102(1)xa >−，经过原点，可能为A ，不可能为B ．若01a <<，则对数函数log a y x =在(0,)+∞上单调递减，二次函数2(1)y a x x =−−开口向下，对称轴102(1)xa <−，经过原点，可能为C ，不可能为D ．故选：BD ．4．（2019秋•龙岩期末）函数()f x 的定义域为R ，且(1)f x −与(2)f x −都为偶函数，则( ) A ．()f x 为偶函数 B ．(1)f x +为偶函数C ．(2)f x +为奇函数D ．()f x 为同期函数【分析】根据题意，由(1)f x −为偶函数，可得函数()f x 的图象关于直线1x =−对称，则有()(2)f x f x −−，由(2)f x −都为偶函数，可得函数()f x 的图象关于直线2x =−对称，则有()(4)f x f x −−，联立分析可得(2)()f x f x +=，即函数()f x 是周期为2的周期函数，据此分析可得()f x 和(1)f x +为偶函数，综合即可得答案．【解答】解：根据题意，若(1)f x −为偶函数，即函数()f x 的图象关于直线1x =−对称，则有()(2)f x f x −−， 若(2)f x −都为偶函数，即函数()f x 的图象关于直线2x =−对称，则有()(4)f x f x −−，则有(2)(4)f x f x −−−−，变形可得(2)()f x f x +=，即函数()f x 是周期为2的周期函数，则D 正确； 又由函数()f x 的图象关于直线2x =−对称且()f x 的周期为2，则()f x 的图象也关于y 轴对称，即()f x 为偶函数，A 正确；又由函数()f x 的图象关于直线1x =−对称且()f x 的周期为2，则()f x 的图象也关于直线1x =对称，即(1)f x +为偶函数，B 正确； 同理：(2)f x +为偶函数，C 错误； 故选：ABD ．5．（2019秋•启东市期末）下列函数中，既是偶函数，又在区间(,0)−∞上单调递减的函数是( ) A．y =B ．||1()2x y =C ．121log ||y x = D ．sin y x =【分析】结合奇偶性及单调性的定义，再结合指数与对数函数，幂函数及余弦函数的性质即可判断．【解答】解；结合幂函数的性质可知y =(,0)−∞上单调递减，符合题意； 结合指数函数的性质可知，||1()2x y =在(,0)−∞上单调递增，不符合题意；结合对数函数的性质可知，121log (,0)||y x −∞上单调递减且为偶函数，符合题意；结合正弦函数的性质可知sin y x =为奇函数，不符合题意． 故选：AC ．6．（2019秋•淮安期末）下列函数中定义域是R 的有( ) A ．2x y =B ．y lgx =C ．3y x =D ．tan y x =【分析】根据常见的基本初等函数的定义域，判断是否满足题意即可． 【解答】解：对于A ，函数2x y =，定义域为R ，满足题意； 对于B ，函数y lgx =，定义域为(0,)+∞，不满足题意； 对于C ，函数3y x =，定义域为R ，满足题意； 对于D ，函数tan y x =，定义域为(2k ππ−+，)2k ππ+，k Z ∈，不满足题意．故选：AC ．7．（2019秋•泰州期末）德国数学家狄里克雷(Dirichlet ，PeterGustavLejeune ，1805~1859)在1837年时提出：“如果对于x 的每一个值，y 总有一个完全确定的值与之对应，那么y 是x 的函数．”这个定义较清楚地说明了函数的内涵．只要有一个法则，使得取值范围中的每一个x ，有一个确定的y 和它对应就行了，不管这个法则是用公式还是用图象、表格等形式表示，例如狄里克雷函数()D x ，即：当自变量取有理数时，函数值为1；当自变量取无理数时，函数值为0．下列关于狄里克雷函数()D x 的性质表述正确的是( )A ．()0D π=B ．()D x 的值域为{0，1}C ．()D x 的图象关于直线1x =对称D ．()D x 的图象关于直线2x =对称【分析】结合已知定义可写出函数解析式，然后结合函数的性质即可判断． 【解答】解：由题意可得()0,1,x D x x Q =∈为无理数， 由于π为无理数，则()0D π=，故A 正确；结合函数的定义及分段函数的性质可知，函数的值域{0，1}，故B 正确；结合函数可知，当x Q ∈时，()1D x =关于1x =，2x =都对称，当x 为无理数时，()0D x =关于1x =，2x =都对称． 故选：ABCD ．8．（2019秋•连云港期末）下列函数中，既是奇函数，又在区间[1−，1]上单调递增的是( ) A ．()2f x x =B ．()2x f x =C ．()tan f x x =D ．()cos f x x =【分析】结合基本初等函数的奇偶性及单调性的定义及性质对各选项进行判断． 【解答】解：结合指数函数的性质可知，2x y =为非奇非偶函数，A 不符合题意； cos y x =为偶函数，不符合题；2y x =为奇函数且在[1−，1]上单调递增，符合题意；结合正切函数的性质可知，tan y x =为奇函数且在[1−，1]上单调递增． 故选：AC ．9．（2019秋•三明期末）下列各选项给出的两个函数中，表示相同函数的有( )A ．()f x x =与()g x =B ．()|1|f t t =−与()|1|g x x =−C ．()f x x =与2()log 2xg x =D ．21()1x f x x −=+与()1g x x =−【分析】根据两个函数的定义域相同，对应关系也相同，即可判断是相同函数．【解答】解：对于A ，函数()f x x =与()||g x x =的解析式不同，表示相同函数；对于B ，函数()|1|f t t =−的定义域为R ，()|1|g x x =−的定义域为R ，定义域相同，对应关系也相同，是相同函数；对于C ，函数()f x x =的定义域为R ，2()log 2g x =x x =的定义域为R ，定义域相同，对应关系也相同，是相同函数；对于D ，函数21()11x f x x x −==−+的定义域为(−∞，1)(1−−∪，)+∞，()1g x x =−的定义域为R ，定义域不同，不是相同函数． 故选：BC ．10．（2019秋•宿迁期末）已知2(21)4f x x −=，则下列结论正确的是( ) A ．f （3）9=B ．(3)4f −=C ．2()f x x =D ．2()(1)f x x =+【分析】利用配凑法求出函数解析式，进而得解．【解答】解：2(21)(21)2(21)1f x x x −=−+−+，故2()21f x x x =++，故选项C 错误，选项D 正确；f （3）16=，(3)4f −=，故选项A 错误，选项B 正确． 故选：BD ．11．（2019秋•泉州期末）已知1(A x ，)m 和2(B x ，)m 为函数()2sin3xf x =的图象上两点，若21||x x k π−=，{1k ∈，2，3，4，5}，则m 的值可能为( )A ．0B ．1CD 【分析】由已知可得()f x 的周期为6π，再分k 的不同取值即可求出结论． 【解答】解：由已知可得()f x 的周期为6π， 当3k =时，如下图所示，此时0m =当2k =或4k =时，如下图所示，结合对称性，此时1m =±当1k =或5k =时，如下图所示，结合对称性，此时m =综上，本题答案为ABD 故选：ABD ．12．（2019秋•清远期末）已知定义在R 上的函数()f x 满足：()()0f x f x +−=，且当0x …时，()1x f x e x =+−．若(sin )((2sin ))f x f k x +…在x R ∈上恒成立，则k 的可能取值为( )A ．1B ．0C ．1−D ．2−【分析】先判断函数的奇偶性和单调性，得到sin (2sin )x k x +…，再根据题意，利用检验法判断即可． 【解答】解：定义在R 上的函数()f x 满足：()()0f x f x +−=，()f x 为奇函数， 当0x …时，()1x f x e x =+−，显然()f x 在(0,)+∞递增，所以()f x 在R 上递增，(sin )((2sin ))f x f k x +…在x R ∈上恒成立， 可得sin (2sin )x k x +…，(1)sin 2k x k −…，当1k =时，02…，不成立，故A 错误；当0k =时，sin 0x …成立，不恒成立，故B 错误；当1k =−时，2sin 2x −…，即sin 1x −…，恒成立，故C 正确； 当2k =−时，3sin 4x −…，即4sin 3x −…恒成立，故D 正确； 故选：CD ．13．（2019秋•海南期末）已知函数2()361f x x x =−−，则( ) A ．函数()f x 有两个不同的零点 B ．函数()f x 在(1,)−+∞上单调递增C ．当1a >时，若()x f a 在[1x ∈−，1]上的最大值为8，则3a =D ．当01a <<时，若()x f a 在[1x ∈−，1]上的最大值为8，则13a =【分析】结合二次函数的零点及单调性及复合函数的单调性与最值的关系分别检验各选项即可判断． 【解答】解：因为二次函数对应的一元二次方程的判别式△2(6)43(1)480=−−××−=>， 所以函数()f x 有两个不同的零点，A 正确；因为二次函数()f x 图象的对称轴为1x =，且图象开口向上， 所以()f x 在(1,)+∞上单调递增，B 不正确； 令x t a =，则22()()3613(1)4x f a g t t t t ==−−=−−． 当1a >时，1t a a 剟，故()g t 在1[,]a a 上先减后增，又112a a +>，故最大值为g （a ）23618a a =−−=，解得3a =（负值舍去）． 同理当01a <<时，1a t a 剟，()g t 在1[,]a a 上的最大值为2136()18g a a a=−−=， 解得13a =（负值舍去）．故选：ACD ．14．（2019秋•滨州期末）已知函数2()23f x x x =−−，则下列结论正确的是( ) A ．函数()f x 的最小值为4− B ．函数()f x 在(0,)+∞上单调递增C ．函数(||)f x 为偶函数D ．若方程(|1|)f x a −=在R 上有4个不等实根1x ，2x ，3x ，4x ，则12344x x x x +++=【分析】由二次函数的性质，可判断选项A ，B 真假，根据奇偶性定义，可判断选项C 真假，作出()y h x =的图象，结合对称性，可判断选项D 真假．【解答】解：二次函数()f x 在对称轴1x =处取得最小值，且最小值f （1）4=−，故选项A 正确；二次函数()f x 的对称轴为1x =，其在(0,)+∞上有增有减，故选项B 错误；由()f x 得，2(||)||2||3f x x x =−−，显然(||)f x 为偶函数，故选项C 正确； 令2()(|1|)|1|2|1|3h x f x x x =−=−−−−，方程(|1|)f x a −=的零点转化为()y h x =与y a = 的交点， 作出()h x 图象如右图所示：图象关于1x = 对称，当()y h x = 与y a = 有四个交点时， 两两分别关于1x =对称，所以12344x x x x +++=， 故选项D 正确． 故选：ACD ．15．（2019秋•费县期末）已知函数()x x f x e e −=−，()x x g x e e −=+，则以下结论错误的是( ) A ．任意的1x ，2x R ∈且12x x ≠，都有1212()()0f x f x x x −<−B ．任意的1x ，2x R ∈且12x x ≠，都有1212()()0g x g x x x −<−C ．()f x 有最小值，无最大值D ．()g x 有最小值，无最大值【分析】由函数()f x 及函数()g x 的性质直接判断即可． 【解答】解：1()x xf x e e =−在R 上单调递增，无最值，故选项AC 错误； 1()x xg x e e =+为偶函数，易知其在(,0)−∞为减函数，在(0,)+∞为增函数，且在1x =处取得最小值，无最大值，故选项B 错误； 故选：ABC ．16．（2019秋•枣庄期末）具有性质：1()()f f x x=−的函数，我们称为满足“倒负”变换的T函数．下列函数中T 函数有( )A ．1y x x=−B ．1y x x=+C ．,010,11,1x x y x x x<<== −> D ．1(0)1xy lnx x−≠+ 【分析】根据题意，逐项判断即可．【解答】解：由1()()f f x x=−可知，若函数()f x 在1x =处有意义，则f （1）0=，故排除B ；对于A ，11()()f x f x x x=−=−，符合题意，故A 正确；对于C ，当01x <<时，11x>，则1()()f x f x x =−=−，符合题意； 当1x >时，101x <<，则11()()f f x x x==−，符合题意； 当1x =时，f （1）0=符合题意，故C 正确；对于D ，函数的定义域为(1−，0)(0∪，1)，1111()()111x x f ln ln f x x x x −−==≠−++，故D 错误． 故选：AC ．17．（2019秋•泰安期末）已知集合{(M x =，)|()}y y f x =，若对于任意实数对1(x ，1)y M ∈，存在2(x ，2)y M ∈，使12120x x y y +=成立，则称集合M 是“垂直对点集”；下列四个集合中，是“垂直对点集”的是( ) A ．21(,)|M x y y x==B ．{(,)|sin 1}M x y y x ==+C ．{(,)|22}x M x y y ==− D ．2{(,)|log }M x y y x ==【分析】由题意可得：集合M 是“垂直对点集”，即满足：曲线()y f x =上过任意一点1(A x ，1)y 与原点的直线，曲线()y f x =上都存在过点2(B x ，2)y 与原点的直线与之垂直，根据题意，对四个选项逐一分析即可得到答案．【解答】解：由题意可得：集合M 是“垂直对点集”，即满足：曲线()y f x =上过任意一点与原点的直线，都存在过另一点与原点的直线与之垂直． 对于A ，21{(,)|}M x y yx ==，其图象向左向右和x 轴无限接近，向上和y 轴无限接近，如图，在图象上任取一点1(A x ，1)y ，连OA ，过原点作OA 的垂线OB 必与21y x =的图象相交， 即一定存在点2(B x ，2)y ，使得OB OA ⊥成立， 故21{(,)|}M x y yx ==是“垂直对点集”，故A 正确． 对于B ，{(,)|sin 1}M x y y x ==+，在图象上任取一点A ，连OA ，过原点作直线OA 的垂线OB ，因为sin 1y x =+的图象沿x 轴向左向右无限延展，且与x 轴相切， 因此直线OB 总会与sin 1y x =+的图象相交．所以{(,)|sin 1}M x y y x ==+是“垂直对点集”，故B 正确； 对于C ，{(,)|22}x Mx y y ==−，其图象过点(0,1)−，且向右向上无限延展，向左向下无限延展， 据指数函数的图象和性质可知，在图象上任取一点A ，连OA ，过原点作OA 的垂线OB 必与22x y =−的图象相交， 即一定存在点B ，使得OB OA ⊥成立，故{(,)|22}x M x y y ==−是“垂直对点集”，故C 正确． 对于D ，2{(,)|log }M x y y x ==，(0)x >，取(1,0)，则不存在点2(x ，222log )(0)x x >，满足2100x ×+=， 因此集合M 不是“垂直对点集”，故D 不正确； 故选：ABC ．18．（2019秋•菏泽期末）下列函数中是偶函数，且在(0,)+∞上为增函数的有( ) A ．cos y x =B ．2y x =C ．3y x =D ．2log ||y x =【分析】根据函数的图象和性质判断即可．【解答】解：其中A ，B ，D 函数是偶函数，排除C ，B ，D 且在(0,)+∞上为增函数，对于D 根据翻折变换图象如下：故选：BD ．19．（2019秋•葫芦岛期末）已知函数3()2bx f x ax +=+在区间(2,)−∞上单调递增，则a ，b 的取值可以是（ ） A ．1a =，32b >B ．01a <…，2b =C ．1a =−，2b =D ．12a =，1b = 【分析】根据题意，将函数的解析式变形可得23()2bb a f x ax a−=++，结合反比例函数的性质以及函数图象平移的规律可得22a −− (230)a−<，分析可得a 、b 的关系，据此分析选项可得答案．【解答】解：根据题意，函数22(2)333()222b b bax bx b a a a f x ax ax ax a ++−−+===++++，其定义域为2{|}x x a≠−， 若函数3()2bx f x ax +=+在区间(2,)−∞上单调递增， 必有22a −−…且230b a−<，即01a <…且23ba<， 据此分析选项：A 、B 、D 符合； 故选：ABD ．。

2020河南中考新题型组合训练一、完形填空Body image-the way people feel about their looks--is a big problem for many young people today. According to a 1 , more than half the teenage girls in the USA think 2 should be on a diet (节食) and almost one in five teenage boys are 3 about their bodies and their weight.But what's the cause? In the study, many blame (责备) the media (媒体). Turn on the TV and you'll 4 see beautiful models, handsome actors and fit sports stars.5 a magazine or a newspaper, look through the internet, and it's usually6 .Many young people feel pressure to 7 these "perfect" people. But for most, this is just not possible. In the USA, the average (平均的) woman is 163 cm tall and weighs 64 kilos, 8 the average model is 180cm tall and weighs 53 kilos.When people don't look the way many 9 people look, they may become less confident. Some stop eating 10 in order to lose weight. Students can lose so much confidence that they start to 11 taking part in classroom activities at school.Body image problems don’t 12 as we get older, either. In the UK, for example women over 50 spend more money on cosmetics (化妆品) than any other 13 group. Older men spend a lot of money trying to 14 hair loss.Is there a solution to the problem? A 2016 study in the UK suggested that body image should be provided in 15 . Others believe it's a problem that all of society needs to deal with. As Meaghan Ramsey says, “We need to judge (评判) people by what they do, not what they look like.”( ) 1. A. newspaper B. magazine C. study D. book( ) 2. A. we B. they C. you D. she( ) 3. A. excited B. sure C. worried D. happy( ) 4. A. probably B. hardly C. never D. finally( ) 5. A. Get B. Open C. Take D. Find( ) 6. A. the same B. different C. special D. interesting ( ) 7. A. look after B. look for C. look at D. look like( ) 8. A. because B. although C. but D. or( ) 9. A. kind B. strong C. young D. famous( ) 10. A. early B. proper C. slowly D. carefully( ) 11. A. enjoy B. stop C. finish D. forget( ) 12. A. come B. continue C. disappear D. happen( ) 13. A. age B. job C. hobby D. man( ) 14. A. make B. avoid C. refuse D. protect( ) 15. A. supermarkets B. streetsC. parksD. schools二、语篇填空第一节：阅读短文，从方框中选择适当的词并用其正确形式填空，使短文通顺、意思完整。

2020广东中考高分突破英语课件考前抢分特训参考答案Part1新题型特训新题型特训一——语法选择一、1~5BCBAA6~10CDCBD二、1~5DBABC6~10BDBAD三、1~5BCABA6~10BDCAA四、1~5BACBB6~10ACCCC新题型特训二——语法选择一、1~5CBCBA6~10ACDDC二、1~5DBCBA6~10BCDDA三、1~5CDCAB6~10DACAD四、1~5ABABA6~10DABDC新题型特训三——语法选择一、1~5BCDAD6~10BBCBD二、1~5BCCBD6~10DAABB三、1~5CADCA6~10BBABC四、1~5DCADA6~10BBCDB新题型特训四——回答问题一、1.The average people sit down to have breakfast at weekends at 8:28 a.m.2.The most popular place for people to have breakfast is at the table at home.3.More than 13% of people never have breakfast.4.The purpose of putting cereal into water is to make it soft.5.The world’s largest breakfast on record took place in Germany.二、1.They are short video apps.2.It had more than 300 million users in China in June.3.She was very excited.4.Three/3 social media’s features are mentioned.5.They don't have to know about their real names.三、1.It is on the 15th day of the seventh month in the Chinese lunar calendar.2.They may think it seems strange and even a bit scary.3.They celebrate it by lighting pumpkin lanterns and dressing up in costumes.4.It takes place in Mexico.5.They encourage us to live our best lives.四、1.It has become the world’s busiest museum.2.It has been open to the public for 95 years.3.It is 599 years old.4.The products with cute and humorous pictures of emperors are very popular.5.Because she has watched several popular TV shows about the museum.新题型特训五——回答问题一、1.It means people took under 100 steps a day.2.Twenty-one/21 million people took a hundred steps a day.3.Various apps and online services, such as food delivery platforms and shopping websites.4.They like watching others playing digital games on screens.5.They think it’s a burden for them.二、1.People communicated by letters in ancient times.2.It was invented in the 19th century.3.John Coker invented the electromagnetic telegraph.4.WeChat has become the most popular in China.5.Four/4 methods are mentioned.三、1.Because you can learn new things./Because it can make you feel good.(回答任意一条均可)2.It is September 5.3.There are 3/three ways.4.Volunteering is to give time to help others without pay.5.It is fundraising.四、1.It raised$25 billion.2.He was born in Hangzhou, Zhejiang.3.He wanted to learn English.4.It was founded in 1999.5.He set up a website called China Pages.Part2难题组合训练难题组合训练一一、1~5BCADD6~10BACBC二、1~5BDABC6~10ABDCD三、1~5ACCCD四、1.a 2.make/earn/get 3.However 4.honest 5.returning6.brushes7.look8.that9.with10.his难题组合训练二一、1~5BCBBB6~10CADBA二、1~5CADAB6~10BCBCC三、1~5ACDCA四、1.without 2.bikes/bicycles 3.on 4.mountains 5.easy6.Though/ Although7.how8.sent9.looked10.only难题组合训练三一、1~5BAADB6~10ADCBC二、1~5ABCDB6~10CADCD三、1~5CDDCD四、1.ran 2.then 3.a 4.allowed 5.When 6.hands7.saved8.like9.terrible/dangerous/bad10.you难题组合训练四一、1~5BADAC6~10BADBA二、1~5BCCDA6~10CBADD三、1~5CBCDA四、1.them 2.because/since/as 3.love 4.an 5.old6.make7.successfully8.also9.how10.in难题组合训练五一、1~5BACBA6~10CDDBB二、1~5BBADC6~10ABCAD三、1~5BDACC四、1.played 2.Instead 3.job 4.a 5.by 6.his7.was8.chance/right9.unlucky10.regrettedPart3科普文专题特训1~5ACCCD6~10CCBBC11~15DACCB16~20BDACC21~25DDADC26~30ADBDCPart4传统文化专题特训一、1~5BABAC6~10DCBAC二、1~5DBCAA6~10CADCC11~15CCADB16~20FDAGC三、(A)1.most 2.invited/asked 3.arrive 4.of 5.interested6.that7.according8.also9.hours10.example(B)d/called 2.lonely 3.herself 4.real 5.a6.At7.mend8.legs9.stopped10.happily四、(一)A.回答问题1.Chen Xiaoqing is the director of Season 1 of Flavorful Origins.2.There are 20/twenty episodes.3.Colorful flower crabs.4.Teochew Orange Cakes is the author’s favourite episode.5.Its English translation makes some people not so much satisfied with the show.B.书面表达Food has a way of bringing us back home.This article reminds me of an interesting experience about cooking.One day I offered to help Mum cook some fish.Everything went smoothly until I put some sugar into the pan.I mistook it for salt! To make matters worse, the fish got stuck to the bottom of the pan and were burnt.That day I realized cooking is never an easy job.It needs skills and patience.In my opinion, it is necessary for young people to learn cooking as it is an important life skill everyone should master.What’s more, it may help us learn a lesson about love and care for others.Each homemade meal is filled with love of the one who cooks it.(二)A.回答问题1.It’s on April 23.2.There were four/4 teams.3.Students should recite and understand the meaning in the very beginning of learning.4.It is Chinese Poetry Conference.5.The common theme of the competition and the program is Chinese poetry.B.书面表达Recently, more and more activities and programs about Chinese traditional literature have attracted people’s attention.As for me, I’m really interested in Chinese traditional literature.It describes ancient people’s lives to us, and it’s also a symbol of our traditional culture.If you want to learn more about Chinese traditional literature, here is some useful advice for you.Firstly, turn to the Internet for help when you face problems.Secondly, you are supposed to keep on reading andlearning.Finally, you can watch some programs about Chinese traditional literature.You are sure to make progress!。

2020英语中考新题型组合训练共20套（含答案）2020中考新题型组合训练：Day 01⼀、完形填空The secret SoldierA young soldier, Robert Shurtliff, lay dying in a hospital bed. He was too 1 to speak or move. Two men stood over him.“I think this young man has 2 ,” one man said.“I'll take his jacket and boots,” said the other.Robert gathered all of his strength to 3 , “I...I'm alive.”The doctor came running over as Robert fell into a coma(昏迷). “We can 4 him,” he said as he examined the young soldier,“Oh, my! He’s a 5 !”It was true. The young soldier, Robert Shurtliff, was really Deborah Sampson. 6 who was she?Deborah Sampson had grown up in Massachusetts, living as a servant. She 7 of having great adventures (冒险). 8 the Revolutionary War broke out in 1775, women were not allowed to serve in the army. But Deborah 9 herself as a man and became a soldier. She called herself Robert Shurtliff.One day, during an attack, Deborah was shot in the neck and 10 . Another soldier lifted Deborah into his horse and rode her to the 11 . A doctor treated the wound on her neck and asked if 12 had any other injuries. Deborah lied and said no. She was afraid that if the doctor examined her leg, he would discover her 13 . Using a pocket knife, Deborah got the bullet(⼦弹) out of her own leg. She 14 to fight as a soldier.After the war ended, Deborah got married and had children. But she still longed for 15 . So she put on her soldier's uniform and travelled around the country telling of her life as young, brave soldier, Robert Shurtliff.( ) 1. A. busy B. weak C. surprise D. strong( ) 2. A. got up B. lost heart C. passed away D. got lost( ) 3. A. whisper B. cry C. shout D. laugh( ) 4. A. accept B. kill C. support D. save( ) 5. A. soldier B. mother C. woman D. father( ) 6. A. Though B. But C. Or D. However( ) 7. A. died B. talked C. heard D. dreamed( ) 8. A. When B. While C. Until D. Since( ) 9. A. worked B. pressed C. acted D. lived( ) 10. A. arm B. hand C. leg D. stomach( ) 11. A. hospital B. library C. classroom D. bedroom( ) 12. A. she B. he C. it D. they( ) 13. A. appearance B. ability C. beauty D. secret( ) 14. A. failed B. continued C. agreed D. planned( ) 15. A. home B. fashion C. peace D. adventure⼆、语篇填空第⼀节：阅读短⽂，从⽅框中选择适当的词并⽤其正确形式填空，使短⽂通顺、意思完整。

一、完形填空I saw at my seat waiting for the school paper to be passed around.I waited 1 , knowing that once I received it, I would know how good a writer I really was.2 the paper arrived at my classroom, I nearly knocked down five of my classmates to get the first paper.With a school paper in my hands, I returned to my seat.About a month earlier, I had handed in one of what I3 to be my best stories.I named it. The symbol of Success.The head of the EnglishDepartment at my school, Professor Cullen, had said that she would include some reviews of students’stories in the latest school paper.Professor Cullen was4 for sharp criticism(严厉的批判). Impressing (打动) her was very5 , but I want to be the first to do so.I sat at the edge of my seat as I read through the other story reviews. There wasn’t one story that got more than three stars. I became calm and wasn't anxious to know my review. It was long after that when I heard 6 shout out "Five stars? Seriously?" behind me. I turned around and saw the shocked expression 7 Gene’s face, "Peter, your story gets five stars!”I couldn’t believe what I was hearing. I turned my 8 back to my story and saw the five stars at the end of the reviewthat I had not read yet. I 9 the view written by Professor Cullen. She wrote I had a 10 for story writing.I was proud that I achieved what I thought was 11 , for so long I believed that I wasn’t so good as I thought I was and that my talent was not enough to cover up my lack (缺乏) of writing skills.But this review proved that I was 12 a good writer.I also thought there was a great future of me in the 13 of fiction writing.The review and the five stars 14 the world to me.Those five stars became the 15 of my success. ( ) 1. A. patiently B. anxiously C. freely D. calmly( ) 2.A. While B. As long as C. When D. Until( ) 3. A. imagined B. guessed C. believed D. agree ( ) 4. A. used B. known C. provide D. named( ) 5. A. easy B. necessary C. hard D. important( ) 6. A. someone B. anyone C. everyone D. no one ( ) 7.A. above B. on C. in D. of( ) 8.A. book B. feelings C. eyes D. ability( ) 9. A. look up B. look for C. look around D. look through ( ) 10. A. talent B. chance C. sense D. confidence ( ) 11. A. possible B. impossible C. simple D. valuable ( ) 12. A. truly B. probablyC. likely D. mostly( ) 13. A. background B. place C. area D. field( ) 14. A. meant B. controlled C supported D. won ( ) 15. A. object B. symbolC. method D. pride二、语篇填空第一节：阅读短文，从方框中选择适当的词并用其正确形式填空，使短文通顺、意思完整。

2020河南中考新题型组合训练一、完形填空At the age of 16, Einstein failed in several exams because he often played with some bad kids. One weekend morning, Einstein carried a fishing net and prepared to go fishing with those 1 . His father stopped him and said to him calmly. Einstein, you were spending too much time 2 , so you failed in the exams. I'm 3 about your future with your mother.“What are you worrying about? Jack and Robert also 4 in the exams, but they went fishing as usual.”“My boy, you cant think so.” Looking at Einstein, his father said lovingly, “There is a 5 in our hometown. I hope you can listen to it carefully.”“There were two cats playing on the roof. 6 , they fell into the chimney (烟囱). When they climbed out of the chimney, one cat's face was dirty 7 the other's was clean. Seeing the dirty-faced cat, the clean faced one thought its own face was also dirty, so it quickly ran to the riverside and washed its: 8 . The dirty aced cat saw the clean-faced one, thinking its own face was clean as well, so it still walked happily in the street.”“Einstein, 9 can be your mirror. Only you are your own mirror. Some of the kids are not strict with themselves. If you take them to be your mirror, even a 10 person may become stupid.” Hearing this Einsteins face turned red. He put down his fishing net and returned to his small room.After that, Einstein often took himself as a mirror to be 11 with himself, and kept telling himself, “I am special, so I needn’t be as common as others.” This was why Einstein 12 in his career.1, 000 people have 1, 000 kinds of wishes in life. Different wishes will produce different 13 about life. You can learn from other people, but you can 14 follow others completely.You must see yourself clearly, and know what you want to get. Your future doesn’t 15 how others act but on how you are going to act.( ) 1. A. adults B. kids C. teachers D. artists( ) 2. A. playing B. working C. reading D. studying ( ) 3. A. excited B. curious C. worried D. crazy( ) 4. A. checked B. passed C. dreamed D. Failed ( ) 5. A. song B. story C. speech D. saying ( ) 6. A. Luckily B. Hopefully C. Suddenly D. Naturally ( ) 7. A. while B. or C. so D. for( ) 8. A. mouth B. tail C. nose D. face( ) 9. A. somebody B. nobody C. anybody D. everybody ( ) 10. A. poor B. rich C. lazy D. clever ( ) 11. A. tired B. angry C. strict D. satisfied ( ) 12. A. regretted B. graduated C. succeeded D. made( ) 13. A. ideas B. reasons C. mistakes D. secrets ( ) 14. A. sometimes B. often C. always D. never( ) 15. A. try on B. depend on C. live on D. go on二、语篇填空第一节：阅读短文，从方框中选择适当的词并用其正确形式填空，使短文通顺、意思完整。

2020河南中考新题型组合训练03一、完形填空A video showing a 12-year-old boy from Moche, Peru, doing his homework on the sidewalk, under a streetlight, has been watched several million times on Facebook after being 1 by local police.Staff at the Moche police station first 2 Victor Martin late last month, while checking security cameras (监控摄像). They found a young boy sitting on the sidewalk by 3 at night. At first, they thought he was doing something bad, but later they realized he was 4 writing something in his notebook, taking advantage of the streetlight overhead. Moved by the boy's 5 , the police shared the video on Facebook.At the time of this writing, victor's heartwarming and 6 heartbreaking story has spread all around the world. Local TV station 7 to find the boy and sat down with his mother to learn why he was doing his homework on the street instead of at home.It turns out that the 12-year-old's family is so 8 that they couldn’t pay for electricity, so they just depended on a 9 during the night. Unluckily, Victor Martin could 10 finish his homework before the sun went down, and recently he couldn't 11 the weak candlelight any more.“One day, my son said ‘12 I continue with the candle, I will be crazy! I’d better go outside to finish my homework,’” Rosa Angulo Cordoba told Panamericana TV. She 13 that Victor's neck would often become hard to move because of tilting (倾斜) his head to let the candlelight through.Victor's mother said that although he 14 housework and takes care of the family sheep every day, the sixth grader takes 15 very seriously and gets good grades.( ) 1. A. share B. taken C. discussed D. praise ( ) 2. A. met B. interviewed C. noticed D. caught ( ) 3. A. itself B. yourself C. myself D. himself ( ) 4. A. shyly B. actually C. carelessly D. certainly( ) 5. A. wish B. plan C. spirit D. hobby ( ) 6. A. by the way B. at least C. at the same time D. in the end ( ) 7. A. managed B. stopped C. promised D. refused ( ) 8. A. traditional B. popular C. special D. poor( ) 9. A. flash B. candle C. camera D. fire( ) 10. A. seldom B. even C. only D. still( ) 11. A. change B. stand C. enjoy D. protect( ) 12. A. Although B. Because C. If D. Until( ) 13. A. added B. warned C. hoped D. lied( ) 14. A. puts off B. worries about C. gives up D. helps with ( ) 15. A. health B. school C. friendship D. safety二、语篇填空第一节：阅读短文，从方框中选择适当的词并用其正确形式填空，使短文通顺、意思完整。

2020英语中考新题型组合训练：Day 1一、完形填空Mr. Hawkins, the headmaster, stopped Anna one day at the school gate.“Now,” he said, “I want you to tell me the 1 , my dear.” Feeling something terrible had happened. Anna said slowly " 2 .”I have had a most 3 accusation (投诉) made against you by Mrs. Bond.“Mrs. Bond?” said Anna, not understanding. Janet Bond was a quiet little 4 of a child. As far as Anna could remember, she had never had 5 to speak an angry word to the girl“Mrs. Bond,” went on Mr. Hawkins, “told me that you scolded (责备) her daughter yesterday afternoon.”“Scolded?” cried Anna. “I certainly didn’t do that. 6 not in school." she added honestly.Mrs. Bond’s7 is that Janet was a little late back to school in the afternoon. She said she set out from home a little late.“Just a minute," said Anna, beginning to8 . “She did come late, very late. I had marked her 9 , of course. Then she 10 slowly in, when we'd started our paper-cutting, and I believe I said she was a nuisance(讨厌的人). She didn't appear to hear and was certainly quite 11 .”“A nuisance!" Mr. Hawkins couldn’t12 it and asked, "You're sure you only said a nuisance.”I may not even have said that, "Anna replied, I was not angry at all at that moment-13 certainly didn’t scold her.”Mrs. Bond said that you called her child a blasted (该死的) nuisance, is that true?“Indeed it isn’t,” said Anna. The child or the mother had14 it up! After Anna's explanation, Mr. Hawkins felt 15 . "Just as I thought, my dear, but of course I had to make sure.”( ) 1. A. rest B. truth C news D. secret( ) 2. A. Naturally B. No way C. Exactly D. Certainly not( ) 3. A. mistaken B. correct C. serious D. careless( ) 4. A. mouse B. pig C. rabbit D. bird( ) 5. A. courage B. chance C. time D. cause( ) 6. A. At first B. At least C. In fact D. After all( ) 7. A. explanation B. excuse C. story D. question( ) 8. A. think B. imagine C. complain D. understand( ) 9. A. absent B. present C. sick D. early( ) 10. A. rushed B. jumped C. walked D pushed( ) 11. A. sad B. tired C. cheerful D. proud( ) 12. A. guess B. repeat C. follow D. believe( ) 13. A. as B. and C. but D. or( ) 14. A put B. picked C. looked D. made( ) 15. A. interested B. satisfied C. disappointed D. surprised二、语篇填空第一节：阅读短文，从方框中选择适当的词并用其正确形式填空，使短文通顺、意思完整。

原创精品资源学科网独家享有版权，侵权必究！1 组合训练04 I.七选五根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。

选项中有两项为多余选项。

It is important to introduce yourself in a creative, memorable way to distinguish yourself from the crowd. 1 Since being witty(言辞诙谐的)doesn’t always come easily, try one of these creative introductions and separate yourself from the rest.Write your first or last name on a piece of paper. 2 So if your name is Tom, you might say you are tireless, optimistic and mild.3 Then say that you will do so in the words of your "best and worst critic" — your mother. By breaking the ice in this way, you can go on in either a humorous or serious fashion.Introduce yourself silently, by drawing a picture of yourself on a large sheet of paper. 4 In fact, in some groups, it may be b etter if you don’t. Put a title at the top of your drawing, if you like, such as, "Hello! This is me."Turn the traditional introduction upside down by describing yourself in exactly opposite terms of who you are. Have fun with this "back door approach", and keep people guessing just how much you are exaggerating (夸张). 5 Don’t bother calling me tomorrow, because I will be hiding in a closet. Send text messages to my girlfriend while I drink a Bud Light on the job.A. This introduction requires you to be gifted in art.B. Freely admit that you don’t like talking about yourself.C. It makes no difference whether you possess artistic abilities.D. For example: I am probably the laziest person you will ever meet.E. Use each letter as the first letter in an adjective that describes you.F. Bring in the surprise factor — sometimes known as the shock factor.G . After all, anybody can stand up and announce their name, business title and job responsibilities.【文章大意】本文是一篇说明文，介绍了几种比较有创意的自我介绍的方式。