《有机化学》(第四版)第三章-不饱和烃(习题答案)
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第三章 不饱和烃
思考题
习题3.1 写出含有六个碳原子的烯烃和炔烃的构造异构体的构造式。其中含有六个碳原子的烯烃,哪些有顺反异构?写出其顺反异构体的构型式(结构式)。(P69)
解:C6H12有13个构造异构体,其中4个有顺反异构体:
CH2=CHCH2CH2CH2CH3CH3CH=CHCH2CH2CH3CH3CH2CH=CHCH2CH3(Z,E)(Z,E) CH2=CCH2CH2CH3CH3CH2=CHCHCH2CH3CH3CH2=CHCH2CHCH3CH3
CH3C=CHCH2CH3CH3CH3CH=CCH2CH3CH3CH3CH=CH2CHCH3CH3(Z,E)(Z,E)
CH2=CHCCH3CH3CH3CH2=CCHCH3CH3CH3CH3C=CCH3CH3CH3CH2=CCH2CH3CH2CH3
C6H10有7个构造异构体:
CHCCH2CH2CH2CH3CH3CCCH2CH2CH3CH3CH2CCCH2CH3
CHCCHCH2CH3CH3CHCCH2CHCH3CH3CHCC(CH3)3CH3CCCHCH3CH3
习题3.2 用衍生物命名法或系统命名法命名下列各化合物:(P74)
(1) (CH3)2CHCH=CHCH(CH3)2 对称二异丙基乙烯 or 2,5-二甲基-3-己烯
(2) (CH3)2CHCH2CH=CHCHCH2CH3CH312345678 2,6-二甲基-4-辛烯
(3) CH3CH2CCCH2CH3123456 二乙基乙炔 or 3-己炔 (4) CH3CH2C(CH3)2CCH12345 3,3-二甲基-1-戊炔
(5) CH2=CHCH2CCH12345 1-戊烯-4-炔
(6) HCCC=CCH=CH2CH2CH2CH3CH2CH2CH3123456 3,4-二丙基-1,3-己二烯-5-炔
(7) CH3CH3
2,3-二甲基环己烯
(8) CH3CH3 5,6-二甲基-1,3-环己二烯
习题3.3 用Z,E-命名法命名下列各化合物:(P74)
(1) ↑C=CCH2CH3HClBr↑
(Z)-1-氯-1-溴-1-丁烯
(2) ↓C=CFCH3ClCH3CH2↑ (E)-2-氟-3-氯-2-戊烯
(3) ↑C=CCH2CH3CH2CH2CH3HCH3↓ (E)-3-乙基-2-己烯
(4) ↓C=CCH(CH3)2CH2CH2CH3CH3H↑ (E)-3-异丙基-2-己烯
习题3.4 完成下列反应式:(P83)
(1) C3H7CCC3H7lindlar催化剂C=CHC3H7HC3H7
(2) Li , 液NH3C3H7CCC3H7C=CHC3H7C3H7H (3) + Br2C=CHC2H5C2H5HBrHC2H5HBrC2H5
(4) CCHOOCCOOHC=CHOOCBrBrCOOH+ Br2
习题3.5 下列各组化合物分别与溴进行加成反应,指出每组中哪一个反应较快。为什么?(P84)
(1) CF3CH=CH2 和 CH3CH=CH2
(2) CH3CH=CH2 和
(CH3)3NCH=CH2
(3) CH2=CHCl 和 CH2=CH2 (4) CHCl=CHCl 和 CH2=CHCl
解:烯烃与溴的加成反应是由亲电试剂首先进攻;双键上电子云密度越大,越有利于亲电加成反应的进行。所以,各组中反应较快者如上所示。
习题3.6
分别为下列反应提出合理的反应机理:(P84)
(1) ClCl+ Cl2CHCl3- 80 Co
解:ClCl+ClCl -ClCl从背面进攻
(2) BrBrBrClBr2 , Cl -CCl4 , 0 Co+ 解:BrBr+Cl -从背面进攻BrBrBrClBrBr -从背面进攻
习题3.7
完成下列反应式:(P90)
(1) HICH3CH3I
(2) HBrC=CH3CCH3BrHCH3CH2CCH3BrBr
(3) HBrCH2=CHCH2CCHCHCH2CCHCH3Br
(4)
HBrCH3(CH2)3CCHCCH2BrCH3(CH2)3
(5) HBr过氧化物(CH3)2C=CHCH3CHCH3(CH3)2CHBr
(6) 2HBr过氧化物CH3CCHCH3CH2CHBr2
习题3.8 下列反应的产物是通过什么反应机理生成的?写出其反应机理。(P90)
CH2=CHCCH3CH3CH3CH3CHCCH3CH3CH3BrCH3CHCCH3BrCH3CH3HBrH++
解: H+CH2=CHCCH3CH3CH3CH3CHCCH3CH3CH3BrCH3CHCCH3BrCH3CH3CHCCH3CH3CH3CH3CH3CHCCH3CH3CH3Br -Br -甲基迁移(二级碳正离子)(三级碳正离子)
习题3.9 在酸催化下,下列化合物与溴化氢进行加成反应的主要产物是什么?如果反应在过氧化物作用下进行,其主要产物有何不同?为什么?(P90)
在酸催化下,烯烃与溴化氢的加成是亲电加成反应,加成取向决定于碳正离子的稳定性;
在过氧化物存在下,烯烃与溴化氢的加成是自由基加成反应,加成取向决定于自由基的稳定性;
(1) 2-甲基-1-丁烯
解:CH2=CCH2CH3CH3HBrCH3CCH2CH3CH3Br
稳定性:>CH2CHCH3CH2CH3CH3CCH3CH2CH3
HBr过氧化物CH2=CCH2CH3CH3BrCH2CHCH2CH3CH3
稳定性:>CH2CCH3CH2CH3BrCH2CCH3CH2CH3Br
(2) 2,4-二甲基-2-戊烯
解:CH3C=CHCHCH3CH3CH3HBr(CH3)2CCH2CHCH3CH3Br
稳定性:>(CH3)2CCH2CHCH3CH3(CH3)2CHCHCHCH3CH3 HBr过氧化物CH3C=CHCHCH3CH3CH3(CH3)2CHCHCHCH3CH3Br
稳定性:>(CH3)2CCHCHCH3BrCH3(CH3)2CCHCHCH3CH3Br
(3) 2-丁烯
解:HBrCH3CH=CHCH3CH3CH2CHCH3Br
稳定性:CH3CH2CHCH3CH3CHCH2CH3
CH3CH=CHCH3HBr过氧化物CH3CH2CHCH3Br
稳定性:CHCH3BrCH3CHCHCH3CH3CHBr
习题3.10 烯烃加H2SO4的反应机理,与烯烃加HX的机理相似。试写出丙烯与硫酸加成的反应机理。(P94)
解:CH3CH=CH2CH3CHCH3CH3CHCH3OSO2OHH+-OSO2OH
习题3.11 完成下列反应式:(P94)
(1) (CH3)2C=CH2Br2 , H2OCH3CCH2OHCH3BrCH3CCH2BrCH3OH+多少
解释: (CH3)2CCH2BrH2O(1)(2)方式(1)空间障碍更小! (2) (CH3)2C=CH2H2OH+CH3CCH3CH3OH
(3) Cl2 , H2OClOH
(4) CCHOH+ H2OHgSO4H2SO4COHCH3O
(5) (1) H2SO4(2) H2OOH
(6) +CH280% H2SO4 -H2OOHCH3OH+主要产物
习题3.12 完成下列反应式:(P97)
(1) (CH3)3CCH=CH2(2) H2O2 , OH-, H2O(1) BH3THF(CH3)3CCH2CH2OH
(2) C2H5C=CH2CH3(2) H2O2 , OH-, H2O(1) 1/2(BH3)2C2H5CHCH2OHCH3
(3) CH3(CH2)2CCC2H5(2) CH3CO2H , 0 Co(1) 1/2(BH3)2CH3(CH2)2C=CCH2CH3HH
(4) C4H9CCH(2) H2O2 , OH-, H2O(1) BH3THFC4H9CH2CHOC4H9CH=CHOH 习题3.13 写出乙炔与亲核试剂(CN-、HCN)加成的反应机理。(P99)
解:CHCH + CN -CH=CHCNHCNCH2=CHCN
习题3.14 在C2H5O-的催化下,CH3C≡CH与C2H5OH反应,产物是CH2=C(CH3)OC2H5而不是CH3CH=CHOC2H5,为什么?(P99)
解:该反应是亲核加成反应:
CH3C=CH-OC2H5CH3C=CH2OC2H5CCHCH3+ C2H5O-C2H5OHNuclear reagent
习题3.15 完成下列反应式:(P99)
(1) CH3CH3OCCH3OCH3COOHH+
解释:H+CH3COO-CH3CH3OCCH3OCH3
(2) OOHH2SO4
解释:OHOH+- H+OHOHCH3
习题3.16 完成下列反应式:(P101)
(1) CH3(CH2)9CH=CH2CH3CO3HCH3(CH2)9CHCH2O (2) (CH3)2C=CCH2CH=CH2CH31mol m-ClC6H4CO3HCHCl3 , 25 Co(CH3)2CCCH2CH=CH2CH3O
氧化反应总是发生在电子云密度较大的双键上。
习题3.17 完成下列反应式:(P103)
(1) CH3CHCH=CH2CH3KMnO4 , OH-H2O , 0 CoCH3CHCHCH3CH2OHOH
(2) KMnO4 , OH-H2O , 0 CoCH3CH=CHC3H7CH3CHCHC3H7OHOH
(3) KMnO4 , H2OpH=7CH3CH2CCCH3CH3CH2CCCH3OO
(4) KMnO4 , H2OpH=12HCCCH3CO2 + H2O +CH3COO-
习题3.18 写出下列反应物的构造式:(P103)
(1) C8H16(A)(1) KMnO4 , H2O , OH-, (2) H+(CH3)2CHCH2CO2H + CH3CH2CO2H
CH3CHCH2CH=CHCH2CH3CH3(A)的构造式为:
(2) CH3CH2C=O + CO2 + H2OCH3C5H10(B)(1) KMnO4 , H2O , OH-,
(2) H+
(B)的构造式为:CH3CH2C=CH2CH3
(3) (1) KMnO4 , H2O , OH-(2) H+C7H12(C)CH3CHCO2H + CH3CH2CO2HCH3
(C)的构造式为:CH3CHCCH3CCH2CH3