初中分式及分式方程100道计算题
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. 分式及分式方程计算题练习
1.分式计算:
(1))2(216322baabcab2 (2)9323496222aababaa
(3) 2322233()()91xxxxx (4)22266(3)443xxxxxxx
(5) (6) 1596234122yyyyyyyy
(7) yxxyxyxx2121
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. (8) 22229631yxyxyxyxyx
(9) 221(2).1aaaa (10) 4222xxxxxx
(11) 2()xyxyxxy (12) (x+y)•
(13) (14)
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. (15)
(16)
(17)
(18)
(19) (20)
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(21) (22)
(23) )2(216322baabcab (24) 9323496222aababaa
(25) 23xx·22694xxx (26) 4232yzxxzyxyx
(27) 21xx-x-1 (28) 1111322aaaa
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(29) babba22 (30) 29631aa
(31) 1311112xxxx)( (32) 4)223(2xxxxxx
(33) 11)11(2xxxx (34) (1+1x1)÷1xx2
(35) 23.25223xxxx (36) (11xyxy)÷22xyxy
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(37) xxxxxxx112122 (37) 22233)()()3(xyxyyxyxa
(39) ).2(121yxxyxyxx (40) 2224421142xxxxxxx
2.解方程
⑴ xx523 ⑵
625xxxx
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⑶ 2-x-313-xx-2 ⑷ 1132422xx
(5)11117162xxxx (6)65879854xxxxxxxx
(7)21321xxx (8) 32421132xxxx
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(9) 233xx (10) +=﹣1
(11) xxx23123 (12) 1x–2 = 2x
(13) xx132 (14) 2311xx
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. (15)
(16)
(17) =0 (18)
(19)
(20) ﹣=1
(21) 114112xxx (22) 0(,0)1mnmnmnxx
(23) 4x42x3 (24) 1-xx-2 =12-x -3 .
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(25) 112342xxxx (26) 2454262xxxx
(27) 32x-2 +11-x =3 (28)
(29) 2911213133131xxxxx (30) .21xx-211x=0
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(31)
(32) 41312111xxxx
(33) 3513xx (34) 255522xxx=1
(35) 2124111xxx (36) 2227461xxxxx
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(37) 11322xxx (38) 512552xxx
(39) 113112xxx (40) 22416222xxxxx
3.已知12,4xyyx,求1111yxxy的值。
4.求)1999)(1998(1.....)3)(2(1)2)(1(1)1(1xxxxxxxx的值,并求当x=1时,该代数式的值。