模拟试卷1A
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金融硕士MF金融学综合(资本结构与公司价值)模拟试卷1(题后含答案及解析)题型有:1. 单项选择题 4. 简答题单项选择题1.最佳资本结构是指( )。
A.每股利润最大时的资本结构B.企业风险最小时的资本结构C.企业目标资本结构D.综合资金成本最低,企业价值最大时的资本结构正确答案:D解析:最佳资本结构的定义即综合资金成本最低,企业价值最大的资本结构。
知识模块:资本结构与公司价值2.调整企业资金结构并不能( )。
A.降低财务风险B.降低经营风险C.降低资金成本D.增强融资弹性正确答案:B解析:经营风险与资金结构无关,资金结构与财务风险相关。
知识模块:资本结构与公司价值3.要使资本结构达到最佳,应使( )达到最低A.边际资本成本B.债务资本成本C.个别资本成本D.综合资本成本正确答案:D解析:这是最佳资本结构的定义。
知识模块:资本结构与公司价值4.通过企业资本结构的调整,可以( )。
A.提高经营风险B.降低经营风险C.影响财务风险D.不影响财务风险正确答案:C解析:资本结构影响财务风险。
知识模块:资本结构与公司价值5.某企业的借入资本和权益资本的比例为1:3,则该企业( )。
A.只有经营风险B.只有财务风险C.没有风险D.既有经营风险又有财务风险正确答案:D解析:经营风险存在于任何企业,而财务风险只存在于有负债的企业中,所以,存在借入资本时,就会具有财务风险,同时也有经营风险。
知识模块:资本结构与公司价值6.(上海财大2012)企业资本总市值与企业占用的投入总资本之差即( )。
A.市场增加值B.经济增加值C.资本增加值D.经济利润正确答案:A解析:经济增加值:税后收益一投入资本。
市场增加值=总市值一投入资本知识模块:资本结构与公司价值7.(上海财大2013)甲乙丙三人讨论债务结构,其中甲认为:(1)一个公司资本结构和财务杠杆没有太大关系,财务杠杆不改变公司向股东分配的权益。
(2)完美市场假设是资本结构不影响公司价值的必要条件之一。
考研数学一(线性代数)模拟试卷1(题后含答案及解析)题型有:1. 选择题 2. 填空题 3. 解答题选择题下列每题给出的四个选项中,只有一个选项符合题目要求。
1.设A是三阶矩阵,B是四阶矩阵,且|A|=2,|B|=6,则为( ).A.24B.一24C.48D.一48正确答案:D解析:知识模块:线性代数部分2.设A为二阶矩阵,且A的每行元素之和为4,且|E+A|=0,则|2E+A2|为( ).A.0B.54C.-2D.-24正确答案:B解析:因为A的每行元素之和为4,所以A有特征值4,又|E+A|=0,所以A有特征值一1,于是2E+A2的特征值为18,3,于是|2E+A2|=54,选(B).知识模块:线性代数部分3.设n维行向量,A=E—αTα,B=E+2αTα,则AB为( ).A.0B.一EC.ED.E+αTα正确答案:C解析:知识模块:线性代数部分4.设A,B为n阶矩阵,则下列结论正确的是( ).A.若A,B可逆,则A+B可逆B.若A,B可逆,则AB可逆C.若A+B可逆,则A—B可逆D.若A+B可逆,则A,B都可逆正确答案:B解析:若A,B可逆,则|A|≠0,|B|≠0,又|AB|=|A||B|,所以|AB|≠0,于是AB可逆,选(B).知识模块:线性代数部分5.设A,B为n阶对称矩阵,下列结论不正确的是( ).A.AB为对称矩阵B.设A,B可逆,则A-1+B-1为对称矩阵C.A+B为对称矩阵D.kA为对称矩阵正确答案:A解析:由(A+B)T=AT+BT=A+B,得A+B为对称矩阵;由(A-1+B-1)T=(A-1)T+(B-1)T=A-1+B-1,得A-1+B-1为对称矩阵;由(ka)T=kAT=kA,得kA为对称矩阵,选(A).知识模块:线性代数部分6.设A,B皆为n阶矩阵,则下列结论正确的是( ).A.AB=0的充分必要条件是A=0或B=0B.AB≠0的充分必要条件是A≠0且B≠0C.AB=0且r(A)=n,则B=0D.若AB≠0,则|A|≠0或|B|≠0正确答案:C解析:知识模块:线性代数部分7.n阶矩阵A经过若干次初等变换化为矩阵B,则( ).A.|A|=|B|B.|A|≠|B|C.若|A|=0则|B|=0D.若|A|>0则|B|>0正确答案:C解析:因为A经过若干次初等变换化为B,所以存在初等矩阵P1,Ps,Q1,…,Qt,使得B=Ps…P1AQ1…Qt,而P1,…,Ps,Q1,…,Q都是可逆矩阵,所以r(A)=r(B),若|A|=0,即r(A)<n,则r(B)<n,即|B|=0,选(C).知识模块:线性代数部分8.设A为m×n阶矩阵,C为n阶矩阵,B=AC,且r(A)=r,r(B)=r1,则( ).A.r>r1B.r<r1C.r≥r1D.r与r1的关系依矩阵C的情况而定正确答案:C解析:因为r1=r(B)=r(AC)≤r(A)=r,所以选(C).知识模块:线性代数部分9.设A为m×n阶矩阵,B为n×m阶矩阵,且m>n,令r(AB)=r,则( ).A.r>mB.r=mC.r<mD.r≥m正确答案:C解析:显然AB为m阶矩阵,r(A)≤n,r(B)≤n,而r(AB)≤min{r(A),r(B))≤n<m,所以选(C).知识模块:线性代数部分10.设A为四阶非零矩阵,且r(A*)=1,则( ).A.r(A)=1B.r(A)=2C.r(A)=3D.r(A)=4正确答案:C解析:因为r(A*)=1,所以r(A)=4—1=3,选(C).知识模块:线性代数部分11.设A,B都是n阶矩阵,其中B是非零矩阵,且AB=0,则( ).A.r(B)=nB.r(B)<nC.A2一B2=(A+B)(A—B)D.|A|=0正确答案:C解析:因为AB=0,所以r(A)+r(B)≤n,又因为B是非零矩阵,所以r(B)≥1,从而r(A)<n,于是|A|=0,选(D).知识模块:线性代数部分12.设A,B分别为m阶和n阶可逆矩阵,则的逆矩阵为( ).A.B.C.D.正确答案:D解析:知识模块:线性代数部分13.A.B=P1P2AB.B=P2P1AC.B=P2AP1D.B=AP2P1正确答案:D解析:P1=E12,P2=E23(2),显然A首先将第2列的两倍加到第3列,再将第1及第2列对调,所以B=AE23(2)E12=AP2P1,选(D).知识模块:线性代数部分14.A.B=P1AP2B.B=P2AP1C.B=P2-1AP1D.B=P1-1AP2-1正确答案:D解析:知识模块:线性代数部分填空题15.正确答案:23解析:按行列式的定义,f(x)的3次项和2次项都产生于(x+2)(2x+3)(3x+1),且该项带正号,所以x2项的系数为23.知识模块:线性代数部分16.设A为三阶矩阵,A的第一行元素为1,2,3,|A|的第二行元素的代数余子式分别为a+1,a一2,a一1,则a=_________.正确答案:1解析:由(a+1)+2(a一2)+3(a一1)=0得a=1.知识模块:线性代数部分17.设A是m阶矩阵,B是n阶矩阵,且=_________.正确答案:(-1)mnab解析:将B的第一行元素分别与A的行对调m次,然后将B的第二行分别与A的行对调m次,如此下去直到B的最后一行与A的行对调m次,则知识模块:线性代数部分18.设A=(α1,α2,α3)为三阶矩阵,且|A|=3,则|α1+2α2,α2—3α3,α3+2α1|=________.正确答案:-33解析:|α1+2α2,α2—3α3,α3+2α1|=|α1,α2—3α3,α3+2α1|+|2α2,α2—3α3,α3+2α1|=|α1,α2-3α3,α3|+2|α2,-3α3,α3+2α1|=|α1,α2,α3|一6|α2,α3,α3+2α1|=|α1,α2,α3|一6|α2,α3,2α1|=|α1,α2,α3|一12|α2,α3,α1|=|α1,α2,α3|一12|α1,α2,α3|=一33 知识模块:线性代数部分19.设三阶矩阵A=(α,γ1,γ2),B=(β,γ1,γ2),其中α,β,γ1,γ2是三维列向量,且|A|=3,|B|=4,则|5A一2B|=________.正确答案:63解析:由5A一2B=(5α,5γ1,5γ2)一(2β,2γ1,2γ2)=(5α一2β,3γ1,3γ2),得|5A一2B|=|5α一2β,3γ1,3γ2|=9|5α一2β,γ1,γ2|=9(5|α,γ1,γ2|一2|β,γ1,γ2|)=63 知识模块:线性代数部分20.设α=(1,一1,2)T,β=(2,1,1)T,A=αβT,则An=_________.正确答案:解析:知识模块:线性代数部分21.正确答案:0解析:由A2=2A得An=2n-1A,An-1=2n-2A,所以An一2An-1=0.知识模块:线性代数部分22.正确答案:解析:知识模块:线性代数部分23.A2一B2=(A+B)(A—B)的充分必要条件是_________.正确答案:AB=BA解析:A2一B2=(A+B)(A一B)=A2+BA—AB一B2的充分必要条件是AB=BA.知识模块:线性代数部分24.设A是三阶矩阵,且|A|=4,则=__________正确答案:2解析:知识模块:线性代数部分25.正确答案:解析:知识模块:线性代数部分26.正确答案:8解析:因为A为四阶矩阵,且|A*|=8,所以|A*|=|A|3=8,于是|A|=2.又AA*=|A|E=2E,所以A*=2A-1,故知识模块:线性代数部分27.设A为三阶矩阵,且|A|=3,则|(一2A)*|=_________.正确答案:576解析:因为(一2A)*=(一2)2A*=4A*,所以|(一2A)*|=|4A*|=43|A|2=64×9=576.知识模块:线性代数部分28.正确答案:解析:知识模块:线性代数部分29.正确答案:解析:知识模块:线性代数部分30.正确答案:解析:知识模块:线性代数部分31.正确答案:解析:知识模块:线性代数部分32.设A为n阶可逆矩阵(n≥2),则[(A*)*]-1=_________(用A*表示).正确答案:解析:知识模块:线性代数部分33.正确答案:解析:知识模块:线性代数部分34.设n维列向量α=(a,0,…,0,a)T,其中a<0,又A=E-ααT,,且B为A的逆矩阵,则a=________.正确答案:-1解析:知识模块:线性代数部分35.设三阶矩阵A,B满足关系A-1BA=6A+BA,且,则B=__________.正确答案:解析:由A-1BA=6A+BA,得A-1B=6E+B,于是(A-1-E)B=6E,知识模块:线性代数部分36.设A是4×3阶矩阵且r(A)=2,B=,则r(AB)=__________.正确答案:2解析:因为|B|=10≠0,所以r(AB)=r(A)=2.知识模块:线性代数部分37.正确答案:2解析:因为AB=0,所以r(A)+r(B)≤3,又因为B≠0,所以r(B)≥1,从而有r(A)≤2,显然A有两行不成比例,故r(A)≥2,于是r(A)=2.知识模块:线性代数部分38.正确答案:解析:知识模块:线性代数部分解答题解答应写出文字说明、证明过程或演算步骤。
翠竹外国语实验学校一年级(上)英语模拟测试卷Listening :I.听录音圈出你所听到的内容。
(10%)1. Aa2. Uu3. Nn4. Bb5. 26. 77. This is my mother.8. It’s a shirt.9. It’s a big hand. 10. She’s a girl.II. 听录音,写出字母的大写和小写。
10%Dd, Qq, Ff, Ss, Hh, Kk, Ll, Rr, Ww, JjIII . 听录音,用序号1,2,3,… 给图片排序。
18%1.This is my mother.2.It’s a book bag.3.Good morning.4.It’s a mouth.5.This is my brother.6.These are shoes.7.She’s a girl.8.This is my baby brother.9.Seven oranges.IV.(听录音,把小朋友们穿的衣服给他们连起来)10%1.What’s Anne wearing?She’s wearing a dress.2.What’s John wearing?He’s wearing a shirt.3.What’s Betty wearing?She’s wearing a sweater.4.What’s Peter wearing?He’s wearing a hat.5.What’s Pat wearing?She’s wearing pants.V. 圈出你所听到的内容5%1. ( I ) am John.2. I have (six ) markers.3. (They ) are six books.4. This is my (baby sister).5. His hair is (short).6. Are these blue (pants)?VI. 听录音,将两边的问句和答句用线连接起来。
教师资格证《信息技术学科知识与教学能力(高级中学)》(题库)模拟试卷一[单选题]1.下列说法正确(江南博哥)的是()A.编制并传播计算机病毒是一种犯罪行为B.在虚拟社区发表文章是没有任何限制的C.在自编的商业软件中加入防盗版病毒是国家允许的D.利用黑客软件对民间网站进行攻击是不犯法的[单选题]2.通过网上查找高考成绩,实际上是检索存储高考成绩的()A.数据库文件B.Word文档文件C.文本文件D.电子表格文件[单选题]3.以下行为不构成计算机犯罪的是()A.破解他人计算机密码,破坏其数据B.通过网络向他人计算机散布计算机病毒C.利用互联网对他人进行诽谤、谩骂D.发送广告电子邮件[单选题]4.在求解某数学题时,即使该题无解,也需答出结果是“无解”,此规定体现了算法特征的()A.可行性B.有穷性C.1个或多个输出D.确定性[单选题]5.()是考试发展的趋势,体现出信息技术带给教育评价的优越性。
A.纸笔测试B.计算机支持的考试C.电子学档评价D.上机操作[单选题]6.已知ƒ(1)=1,ƒ(2)=2,当n≥3时,ƒ(n)=ƒ(n-1)+ƒ(n-2),编程求ƒ(100)的值,应选择的算法为()A.解析法B.穷举法C.递归法D.冒泡排序法[单选题]7.在关系模型中,关于主键,说法正确的是()A.只能由一个属性构成B.每个数值不允许有NULL值C.仅能由一个字段组成D.不能与其他表中的外键建立关系[单选题]8.和传统教学模式相比,多媒体辅助教学有着明显的优点,下列不属于多媒体教学优点的是()A.能弥补视角和空间的局限性B.有利于激发学生的学习积极性C.能创设生动形象的教学环境D.有利于完成情感教学目标[单选题]9.通过上网缴纳水电费、煤气费等属于()A.电子商务B.现金买卖C.储蓄业务D.通存通兑[单选题]10.若在网上下载一幅动画图片,在下载时保存的对话框中看到的是“11.htm”,则下载下来的将是( )A.网页文件B.位图图像C.会动的图片D.以上都不对[单选题]11.用“画图”程序在填充某图形的颜色时,发生溢出现象,这是因为()A.该图形没有完全封闭B.没有选中对象C.没有选中颜色D.没有选中正确的填充工具[单选题]12.下列关于键和主键的描述,错误的是()A.能唯一标识表中每一条记录的字段或字段组合称为关键字或键B.只有一个键可作为表的主键,即主关键字C.主键的意义是此字段的数据在表中不可重复D.主键只能是一个字段[单选题]13.在日常生活中,我们常常会碰到许多需要解决的问题,以下描述中最适合用计算机编程来处理的是()A.确定放学回家的路线B.计算某个同学期中考试各科成绩的总分C.计算1000以内的奇数的平方和D.在因特网上查找自己喜欢的歌曲[单选题]14.下列关于网络的说法,错误的是( )A.将两台计算机用网线连接在一起就是一个网络B.网络按覆盖范围可以分为LAN、MAN和WANC.计算机网络有数据通信、资源共享和分布处理等功能D.上网时我们享受的服务不只是眼前的计算机提供的[单选题]15.如图所示,PhotoShop中,在使用自由变换(Ctrl+T)命令时,如果要使图像有透视效果(见下图),下列说法正确的是( )A.按住Shift键B.按住Ctrl键C.按住Ctrl+Shift键D.按住Ctrl+Shift+Alt键[问答题]1.李老师家的计算机操作系统从WindowsXP升级到了Windows7,可是计算机上的“猫”(Modem)因为没有合适的驱动程序而“罢工”,请你帮帮李老师。
中科院心理咨询基础知识培训模拟试卷1(含答案)答题时间150分钟一、单选题共200题,每题0.3分,共60分1.16PF的条目数共有(C)条。
A.16B.90C.187D.4992 .调节内脏系统活动的皮层下中枢位于(A)A.下丘脑B.脑干C.上丘脑D.小脑3 .社会行为公式B=f(P,E)中,E的含义是(D)A彳亍为B.函数关系C.个体D.个体所处的情境4 .社会给予青年暂缓履行成人的责任和义务机会如大学学习期间,这个时期称为(D)A.同一性确立期B.心理代偿期C.危机处理期D.延缓偿付期5 .根据统计学标准,心理异常是:(八)A.由个体行为偏离平均值的程度决定的B.事件不确定性的函数C.由个体主观上的不适体验程度决定的D.心理不稳定性的函数6 .弗洛伊德学说在咨询心理学历史上属于(C)。
A彳亍为学派B.认知学派C.动力学派D.人本主义学派7 .以下不属于专业伦理所包含的要素是(C)。
A.心理专业人员的人生观、价值系统B.专业伦理守则C.心理专业人员的技术和方法D.法律、法规及政策和制度8 .20世纪20年代,临床心理学家将会谈法定义为(八)。
A.有目的的交谈B.有结构的交谈C.有理论的交谈D.有价值的交谈9 .心理咨询师的共情是指体验求助者的内心要(八)A.如同体验自己B.就是体验自己C.以自己为参照D.以社会为参照10 .〃不固定角色〃是一种坦诚交流技术,它属于(D)A彳亍为治疗B.认知行为疗法C.完形治疗D.人本主义疗法11 .某受测者EPQ的得分为P=55分,E=42分,N=61,则气质类型属于(C)oA.胆汁质B.多血质C.黏液质D.抑郁质12 .躯体感觉中枢位于大脑皮层的(D)A.额叶B.颗叶C.枕叶D.顶叶13麦孤独WWcDougaII用(D)来解释人类的社会行为。
A.认知过程B.学习C.社会影响D.本能14 .艾里克森认为幼儿期良好的人格特征是(C)A.希望品质B.意志品质C.目标品质D.能力品质15 .区分IL'理正常的心理学原则中,人格相对稳定性原则认为:(A)A.无明显原因的人格改变提示异常B.心理过程通过人格表现出来C.人格在各种条件下都应是稳定的D.人格是各种心理过程的总和16 .斯金纳的条件反射是(八)。
试卷类型:A2025年普通高等学校招生全国统一考试模拟演练一数学用2B 铅笔将试卷类型(A)填涂在答题卡相应位置上。
将条形码横贴在答题卡右上角“条形码粘贴处”本试卷共19小题,满分150分。
考试用时120分钟。
注意事项: 1.答卷前,考生务必将自己的姓名、考生号、考场号和座位号填写在答题卡上。
2.作答选择题时,选出每小题答案后,用2B 铅笔在答题卡上对应题目选项的答案信息点涂黑;如需改动,用橡皮擦干净后,再选涂其他答案。
答案不能答在试卷上。
3.非选择题必须用黑色字迹的钢笔或签字笔作答,答案必须写在答题卡各题目指定区域内相应位置上;如需改动,先划掉原来的答案,然后再写上新的答案,不准使用铅笔和涂改液。
不按以上要求作答无效。
4.考生必须保持答题卡的整洁。
考试结束后,将试卷和答题卡一并交回。
一、选择题:本题共8小题,每小题5分,共40分。
在每小题给出的四个选项中,只有一项是符合题目要求的。
1.已知复数z 满足()i z i 3+1=4+3,则=z A.25 B.52 C.425 D.2542.若抛物线2=ax y ()0>a 的焦点到准线的距离为a 2,则=a A.2B.21 C.4 D.413.若函数()x f y 2=log 的定义域和值域均为R ,则()x f 的表达式可以为A.xB.()21+x C.1+2xe x D.()xe x1+24.若nb a x x ⎪⎭⎫ ⎝⎛1+),,(*∈N n b a 的展开式中存在常数项,则n 的最小值为A.4B.3C.2D.15.已知事件B A ,相互独立,且()()B A P AB P ⋂=,则()AB P 的最大值为A.21B.41 C.81 D.16.从棱长为2的正方体的六个面的中心中任取三点,记其构成的三角形面积为随机变量X ,则()=X E A.53+3 B.104+33 C.56+32 D.54+337.已知数列{}n a 满足()21+2-=n n a a ,Z a ∈1,若0>∃M ,使得*N n ∈∀,M a n ≤恒成立,则1a 的所有可能值之和为A.8B.9C.10D.118.已知点()01,A ,()42,Q ,⊙P 与直线4=x 相切于点B ,过点A 且垂直于AP 的直线与⊙P 交于D C ,两点,且23=∠CBD sin .则P A PQ -的最小值为A.5 B.3 C.2 D.1二、选择题:本题共3小题,每小题6分,共18分。
模拟试卷(1)I . Each of the statements below is followed by four choices. Please choosethe one that best completes each statement.(10 %)1. In the word internationalists, nation is ________.A. rootB. stemC. baseD. root, stem, base2. ________is the most important of all characteristics of the basic word stock.A. ProductivityB. StabilityC. CollocabilityD. All national character3. Nonbasic vocabulary includes all of the following except________.A. slangB. Anglo-Saxon wordsC. argotsD. neologisms4. It is assumed that the world has 3 000 languages, which can be grouped intoroughly _ language families on the basis of similarities in their basic word stock and grammar.A. 200B. 300C. 400D. 5005. The following languages all belong to the Eastern set except________.A. Balto-SlavicB. Indo-IranianC. ArmenianD. Italic6. In the Eastern set, Armenian and________are the sole modern languages inthe two respective families.A. AlbanianB. RussianC. SlovenianD. Lithuanian7.The minimal meaningful units in a language are known as __________ .A. wordsB. allomorphsC. morphemesD. morphs8. The ________ are "actual spoken, minimal carriers of meaning".A. morphsB. allomorphsC. morphemesD. allophones9. Morphemes are _____ units, which are realized in speech by discrete units known as ________ .A. concrete; allomorphsB. abstract; morphsC. abstract; lexemesD. concrete; morphs10. 30% to 40% of the total number of new words in English are produced through _________ .A. compoundingB. affixationC. conversionD. shortening11. The prefixes mal- in maltreat, mis- in misleading and pseudo- inpseudo-scientific are ________ prefixes.A. negativeB. reversativeC. pejorativeD. locative12. A word is the combination of ________ and ________.A. spelling, soundB. form, meaningC. spelling, meaningD. sound, meaning13. By form we refer to________.A. its symbolsB. its spellingC. its pronunciationD. both its pronunciation and spelling14. Reference is the relationship between language and________.A. the worldB. the conceptC. the senseD. the motivation15. All of the following are sense relations except________.A. polysemyB. ameliorationC. homonymyD. antonymy16. ________ is a common feature peculiar to all natural languages becausethe majority of words have more than one meaning.A. HyponymyB. SynonymyC. PolysemyD. Homonymy17. Which of the following words does not undergo the process of narrowing of meaning?A. Meat.B. Liquor.C. Disease.D. Journal.18. ________factor is the one that often contributes to the associatedtransfer of meaning and euphemistic use of words, etc.A. ScientificB. PsychologicalC. HistoricalD. Internal19. The change of word meaning is achieved by modes of____A. degradation and elevationB. transference and euphemismC. extension and narrowingD. all the above20. A word has meaning only when a connection has been established between thelinguistic sign and a________.A. referenceB. referentC. conceptD. senseII. Complete the following statements with proper words or expressions according to the course book. (10 %)21. Lexicology is a branch of linguistics, studying the origins and ________ of words.22. A word is a minimal free form of a language that has a given sound, meaning and ________function.23. Modern English expands its vocabulary chiefly through________.24. The three main means of creating new words in modern English are ________,compounding and conversion.25. The overwhelming majority of blends are________.26. Words imitating natural sounds are________words.27. Every word that has meaning has sense but not every word has_______ .28. The relationship between the word form and meaning is conventionaland arbitrary, and most words can be said to be _______.29. Componential analysis, according to Leech, is the process of breaking down the sense of a word into its ________ components.30. At the time when the words were created, it was endowed with only onemeaning. The first meaning is the ________ meaning and the latter meanings are ________meaning.31. ________is a semantic process in which the primary meaning stands atthe center and the secondary meanings proceed out of it in every direction like rays.32. Extension and______are the most common modes of word meaning changes.33. Narrowing of meaning is also known as______, which is the opposite of______.34. The extra-linguistic context refers to the________situation, which may extend to embrace the entire________.35. Linguistic context can be subdivided into_______ context and_____ context.36. Context can be divided into ____and _____ context.37. Regarded as a derivational process without the addition of an affix, conversion can be called as _______.38. ________are the most complete description of words available to us.They are large in scope and size, containing at least 200 000 headwords.39. ________ are medium-sized ones containing words ranging from 50 000to 150 000. And they are most used on desk.40. Based on the degree of similarity, homonyms fall into three types: ________, homographs and________.III. Please decide whether the following statements are true or false. (10%)( ) 41. A word can be defined in different ways from different points of view.( ) 42. Under no circumstances can sound and meaning be intrinsically related.( ) 43. The introduction of printing press resulted in a lot more differences between sound and form.( ) 44. In early Middle English period, English, Latin, and Celtic existed side by side.( ) 45. The introduction of printing into England marked the beginning of Modern English period.( ) 46. Modern English is considered to be an analytic language.( ) 47. Conversion not only changes the grammatical function of items involved but their original meaning.( ) 48. Stylistically, back-formed words are largely informal and some of them have not gained acceptance.( ) 49. Backformation is considered to be the opposite process of affixation. ( ) 50. Complementaries can be used in comparative degrees.( ) 51. In a language, there are more synonyms than antonyms.( ) 52. Antonyms differ in semantic inclusion.( ) 53. The meaning of paper in "a white paper" is determined by grammatical context.( ) 54. The ambiguity in "They saw her duck" is due to polysemy.( ) 55. The clue for the meaning of jetty in "The harbour is protected bya jetty — a wall built out into the water" is definition.( ) 56. Idioms are generally felt to be informal; therefore they are usually inappropriate for formal settings.( ) 57. The stylistic features of idioms are fixed and unchangeable.( ) 58. Idioms are peculiar to native culture and language.( ) 59. Dictionary is closely related to lexicology because they both deal with the form, meaning, usage and origins of vocabulary units.( ) 60. In the Anglo-Saxon period, difficult Latin words and definitions were often collected into lists called glossaries for the sake of research.IV. Please give the meaning of the following prefixes (the italicized part of the word).You are to write your answer in English on the answer sheet. (10%)61. a political 62. dis obey 63. il literate 64.de centralize65. un bug 66. mal treat 67. mis interpret 68. pseudo-scientific69. arch bishop 70. co direct 71. extra-large 72. hyper active73. macro economics 74. micro computer 75. mini-bus 76.over-anxious77. out swim 78. sub-system 79. sub normal 80.super sophisticatedV. Please give the direct expressions of the following euphemisms. (10%) 81. pass away 82. social disease83. custodian 84. extermination engineer 85. meet engineer 86. sanitation engineer87. mortician 88. hairdresser89. Gee 90. Gosh almightyVI. Please translate the following idioms into Chinese.(20%)91. in a brown study92. lip service93. bury the hatchet94. tit for tat95. the lion's share96. diamond cut diamond97. like cures like98. a fish out of water99. the salt of the earth100. see eye to eye with101. as green as grass102. once in a blue moon103. ride the high horse104. a bed of roses105. make bricks without straw106. an apple of discord107. Jack of all trades108. a fly in the ointment109. cut and dried110. wide of the markVII. Answer the following questions. (30%)111. In what way are words related to vocabulary?112. What is the fundamental difference between content and functional words?113. What is the difference between grammatical and lexical morphemes, and inflectional and derivational morphemes? Give examples toillustrate their relationships.114. What are the merits and demerits of componential analysis?115. What is hyponymy?模拟试卷(1)答案及评分标准I. Please choose the one that best completes each statement. (10%)1-5 D D B B D6-10 A C A B B11-15 C B D A B16-20 C D B D B评分标准:本题共20道题,共10分;每题0.5分。
考研数学一(选择题)高频考点模拟试卷1(题后含答案及解析) 题型有:1.1.无界的一个区间是( )A.(-∞,-1)B.(-1,0)C.(0,1)D.(1,+∞)正确答案:C解析:因此f(x)在区间(0,1)内无界.其他三个区间内f(x)都是有界的.知识模块:函数、极限、连续2.若f(x)在开区间(a,b)内可导,且x1,x2是(a,b)内任意两点,则至少存在一点ξ,使下列诸式中成立的是( )A.f(x2)-f(x1)=(x1-x2)f’(ξ),ξ∈(a,b)B.f(x1)-f(x2)=(x1-x2)f’(ξ),ξ在x1,x2之间C.f(x1)-f(x2)=(x2-x1)f’(ξ),x1<ξ<x2D.f(x2)-f(x1)=(x2-x1)f’(ξ),x1<ξ<x2正确答案:B解析:由拉格朗日中值定理易知(A),(C)错,(B)正确,又因未知x1与x2的大小关系,知(D)不正确.知识模块:一元函数微分学3.设X1和X2是任意两个相互独立的连续型随机变量,它们的概率密度分别为f1(x)和f2(x),分布函数分别为F1(x)和F2(x),则A.f1(x)+f2(x)必为某一随机变赶的概率密度.B.f1(x)f2(x)必为某一随机变量的概率密度.C.F1(x)+F2(x)必为某~随机变量的分布函数.D.F1(x)F2(x)必为某一随机变量的分布函数.正确答案:D 涉及知识点:综合4.设f(x)=,其中g(x)为有界函数,则f(x)在x=0处( ).A.极限不存在B.极限存在,但不连续C.连续,但不可导D.可导正确答案:D解析:因为f(0+0)=,所以f(x)在x=0处连续;=0,即f+’(0)=0,=0,即f-’=0,因为f+’=f-’=0,所以f(x)在x=0处可导,应选(D).知识模块:高等数学5.设f(x)在x=0的邻域内有定义,f(0)=1,且=0,则f(x)在x=0处( ).A.可导,且f’(0)=0B.可导,且f’(0)=一1C.可导,且f’(0)=2D.不可导正确答案:B解析:知识模块:高等数学6.设f(x)二阶连续可导,且,则( )A.x=0为f(x)的极大点B.x=0为f(x)的极小点C.(0,f(0))为y=f(x)的拐点D.x=0不是f(x)的极值点,(0,f(0))也不是y=f(x)的拐点正确答案:C解析:知识模块:高等数学部分7.设n阶矩阵A的伴随矩阵A*≠0,若ξ1,ξ2,ξ3,ξ4是非齐次线性方程组Ax=b的互不相等的解,则对应的齐次线性方程组Ax=0的基础解系( )A.不存在.B.仅含一个非零解向量.C.含有两个线性无关的解向量.D.含有3个线性无关的解向量.正确答案:B解析:由A*≠O知A*至少有一个元素Aij=(一1)i+jMij≠0,故A的余子式Mij≠0,而Mij为A的n一1阶子式,故r(A)≥n一1,又由Ax=b有解且不唯一知r(A)<n,故r(A)=n一1.因此Ax=0的基础解系所含向量个数为n一r(A)=n 一(n一1)=1,只有(B)正确.知识模块:线性代数8.设A、B为n阶矩阵,且A与B相似,E为n阶单位矩阵,则A.AE-A=λE-B.B.A与B有相同的特征值和特征向量.C.A与B都相似于一个对角矩阵.D.对任意常数t,tE-A与tE-B相似.正确答案:D 涉及知识点:综合9.A.f(x)是增函数,g(x)是减函数B.f(x)是减函数,g(x)是增函数C.f(x)与g(x)都是增函数D.f(x)与g(x)都是减函数正确答案:D 涉及知识点:综合10.如果级数收敛,则级数( )A.都收敛B.都发散C.敛散性不同D.同时收敛或同时发散正确答案:D解析:由于an=(an+bn)—bn,且必发散,故选D。
2021年桂林市初中学业水平考试试卷英语模拟试卷(一)二、单项选择(每小题1分,共10分)从各题的A、B、C三个选项中,选出最佳选项。
31.—(2020·白银)Don't keep the lights on when they're not in use!—B.A.Not at all B.Sorry,I won'tC.No,thanks32.—(2020·自贡)Look,who's C woman in red?—She's my new English teacher with ______eightyearold daughter.A.the;a B.a;an C.the;an33.(2020·恩施州)I hear that it often A in Sichuan and there are usually floods,especially in summer.A.rains B.rained C.raining34.(2020·沈阳)You should walk __B__in snowy weather so that you will not fall over.A.happily B.slowly C.sadly35.— (2019·温州)Sir,did you enjoy your stay in our __A__?—Yes,I slept well and I like the breakfast.A.hotel B.school C.factory36.(2019·沈阳)Last week,some students __C__an English play at Rosie Bridge School.A.put out B.put away C.put on37.(2019·昆明)Tom cannot run as__A__as his friends,so he practises running very hard.A.fast B.faster C.slow38.—(2020·攀枝花)China is going to use AI to protect the Great Wall.—Great! AI is so helpful that people B use it in their daily life now.A.must B.can C.shall39.Don't worry.We are old enough to look after __A__.A.ourselves B.myself C.herself40.—(2020·温州)How often do you go to the cinema?—C.I only watch movies at home.A.Always ually C.Never三、(2019·百色改编)补全对话(每小题 1分,共5分)根据对话内容,从方框中选出最佳选项补全对话。
参考答案2023年普通高等学校招生全国统一考试考前模拟试卷数学(一)1.D 【解析】B ={x |x 2=4}={-2,2},由题可知,UA )∩B ={2}.故选D.2.C 【解析】∵z =(4-i )(2i-1)=8i -4+i +2=-2+9i ,故z =-2-9i ,∴z 的共轭复数在复平面内对应的点为(-2,-9),位于第三象限.故选C .3.B 【解析】|a +b |=a 2+b 2+2a·b 姨=|a |2+|b |2+2a ·b 姨=10姨,|b |=12+12姨=2姨,∴a ·b =2,∴a 在b 上的投影向量为a·b |b |·b |b |=b =(1,1),故选B .4.D 【解析】由题意可知,该事件的概率为12·C 22C 28+12·C 22C 23=12×128+12×13=31168,故选D.5.B 【解析】由题意可知,结果只需精确到0.001即可,令x=0.5,取前6项可得,e 姨=+∞n=0移0.5nn !≈5n=0移0.5nn !=0.500!+0.511!+0.522!+0.533!+0.544!+0.555!=1+0.5+0.252+0.1256+0.062524+0.03125120≈1.649,∴e 姨的近似值为1.649,故选B.6.A 【解析】设f (x )=sin x-x ,x ∈0,仔22',则f ′(x )=cos x -1<0,∴f (x )在0,仔222上单调递减,∴f (x )<f (0)=0,∴当x ∈0,仔222时,sin x-x <0,即sin x<x .a =sin 20°=sin 仔9<仔9=b ,c=12ln e 姨=14<仔9=b ,c =12ln e 姨=14<6姨-2姨4=sin 15°<sin 20°=a ,∴c<a<b ,故选A .7.B 【解析】由题意可知,设底面圆的半径为R ,则S=仔R 2=16仔,解得R =4.∵由直三棱柱的定义可知,要使能截得直三棱柱体积最大,只需要圆的内接三角形面积最大即可,S =12ab sin C =12·2R sin A ·2R sin B ·sin C=2R 2sin A ·sin B ·sin C ≤2R 2sin A+sin B+sin C 3223≤2R 2·sin A+B+C 3223=2R 2·sin 仔3223=33姨4R 2.当且仅当sin A=sin B=sin C ,即A=B=C =仔3时,等号成立,∴三角形是正三角形时,圆的内接三角形面积最大,V=Sh =33姨4×42×6=723姨.∴能截得直三棱柱体积最大为723姨.故选B .8.D 【解析】g (x +1)为偶函数,则g (x )关于x =1对称,即g (x )=g (2-x ),即(x-1)f (x )=(1-x )f (2-x ),即f (x )+f (2-x )=0,∴f (x )关于(1,0)对称,又f (x )是定义域为R 的偶函数,∴f (x )=-f (2-x )=-f (x -2),∴f (x -4)=f [(x -2)-2]=-f (x -2)=-[-f (x )]=f (x ),即f (x -4)=f (x ),∴f (x )周期为4,∴f (5.5)=f (1.5)=f (-2.5)=f (2.5)=2,∴g (-0.5)=g (2.5)=1.5f (2.5)=3.故选D.9.ABD 【解析】∵sin 兹+cos 兹=15①,∴(sin 兹+cos 兹)2=sin 2兹+2sin 兹cos 兹+cos 2兹=125,∴2sin 兹cos 兹=-2425.又兹∈(0,仔),∴sin 兹>0,∴cos 兹<0,即兹∈仔2,22仔,故A 正确;(sin 兹-cos 兹)2=1-2sin 兹cos 兹=4925,∴sin 兹-cos 兹=75②,故D 正确;由①②,得sin 兹=45,cos 兹=-35,故B 正确;tan 兹=sin 兹cos 兹=-43,故C 错误.故选ABD .10.BCD 【解析】如图1,当P 为BC 1的中点时,OP ∥DC 1∥AB 1,故A 不正确;∵如图2,A 1C 奂平面AA 1C 1C ,O ∈平面AA 1C 1C ,O 埸A 1C ,P 埸平面AA 1C 1C ,∴直线A 1C 与直线OP 一定是异面直线,故B 正确;∵如图2,A 1A 奂平面AA 1C 1C ,O ∈平面AA 1C 1C ,O 埸A 1A ,P 埸平面AA 1C 1C ,∴直线A 1A 与直线OP 一定是异面直线,故C 正确;∵如图3,AD 1奂平面AD 1C ,O ∈平面AD 1C ,O 埸AD 1,P 埸平面AD 1C ,∴直线AD 1与直线OP 一定是异面直线,故D 正确.故选BCD.11.BD 【解析】如图所示,当直线l 的倾斜角越小时,△PQA 1的周长越大,故A 不正确;△PF 1Q 的周长为|PF 1|+|QF 1|+|PQ |=4a +|PF 2|+|QF 2|+|PQ |=4a +2|PQ |,∴△PF 1Q 的周长与2|P P /Q |之差为4a ,故B 正确;设P (x ,y ),则tan 琢=|y |a+x,tan 琢=-|y |x-a,由tan 琢tan 茁=a-x a+x不是常量,故C 不正确;由tan 琢·tan 茁=|y |a+x ·|y |a-x =y 2a 2-x 2=x 2a 2-221b 2a 2-x 2=-b 2a 2为常量,故D 正确.故选BD .12.AD 【解析】令x 1=x 2=1得,f (1)=f (1)+f (1),f (1)=0,故A 正确;再令x 1=x 2=-1得,f (1)=f (-1)+f (-1)=0,f (-1)=0,故B 错;令x 1=-1,x 2=x ,则f (-x )=x 2f (-1)+f (x )=f (x ),f (x )是偶函数,故C 错;令x 1=x ,x 2=1x,则f (1)=1x2f (x )+x 2f 1x 22,∴f (x )=-x 4f 1x 22,当0<x <1时,1x>1,f 1x 22>0,∴f (x )<0,故D 正确.故选AD .13.0.3【解析】由P (X ≥90)=0.5知,滋=90,∵P (X ≤70)=P (X ≥110)=0.2,∴P (70≤X ≤90)=1-2×0.22=0.3.故答案为0.3.14.45姨5≤r ≤13姨【解析】当A ,B 两点都在圆内时,则4+9<r 2,4+1<r 22,解得r >13姨,直线AB 的方程为y -3x +2=1-32+2,即x +2y -4=0,原点到直线AB 的距离为|-4|1+4姨=45姨5,又k OA =-32,k OB =12,k AB =-12,参考答案第1页共28页参考答案第2页共28页A 1B 1C 1D 1OPDABC A 1B 1C 1D 1OPDABC A 1B 1C 1D 1OPDABC 图1图2图3第10题答图xy OAB 第14题答图xy OF 1F 2P 2Q 2QPA 1A 2第11题答图37∴原点与线段AB 上的点所在直线的斜率的范围为-32,12!",∵圆C :x 2+y 2=r 2(r >0)与线段AB (包含端点)有公共点,∴45姨5≤r ≤13姨.故答案为45姨5≤r ≤13姨.15.4【解析】由题意得,ab (a +3b )=3a+b ,∴a +3b =3a+b ab =3b +1a ,∴(a +3b )2=3b +1a a &(a +3b )=10+3a b +3b a ≥10+23a b ·3b a姨=16(当且仅当a=b=1时取等号).∵a +3b ≥4,∴a +3b 的最小值为4.答案为4.16.6e e 2-1,+a &∞【解析】∵f (x 0)+3e x<0,即3ln x 0-kx 0+k x 0+3e x 0<0.当x 0=1时,3e <0显然不成立,即在x 0=1时不满足原式;当x 0∈(1,e ]时,整理得x 0ln x 0+e x 02-1<k 3.令g (x )=x ln x +e x 2-1,x ∈(1,e ],则g ′(x )=(x 2-2e x -1)-(x 2+1)ln x (x 2-1)2,∵当x ∈(1,e ]时,(x 2+1)ln x >0,x 2-2e x -1=(x -e )2-e 2-1<0,则g ′(x )<0,当x ∈(1,e ]时恒成立,∴g (x )在(1,e ]上单调递减,则g (x )≥g (e )=2e e 2-1,则2e e 2-1<k 3,即k >6e e 2-1.综上所述,数k 的取值范围为6e e 2-1,+a &∞.故答案为6ee 2-1,+a &∞.17.【解析】(1)∵a 1+2a 2+…+na n =2n ,∴当n ≥2时,a 1+2a 2+…+(n -1)a n -1=2(n -1),两式相减得na n =2,a n =2n ,又n =1时,a 1=2,也符合.∴a n =2n.(2)由(1)知,1a n =n 2,∵对任意的正整数m ≥2,均有b m -1+b m +b m +1=1a m =m 2,故数列{b n }的前99项和b 1+b 2+b 3+b 4+b 5+b 6+…+b 97+b 98+b 99=(b 1+b 2+b 3)+(b 4+b 5+b 6)+…+(b 97+b 98+b 99)=1a 2+1a 5+…+1a 98=3322+982a &2=825.18.【解析】(1)由题得a-b=a sin A-c sin C sin B ,∴a-b=a 2b -c 2b,∴ab-b 2=a 2-c 2,∴ab=a 2+b 2-c 2,∴ab =2ab cos C ,∴cos C=12.∵0<C <仔,∴C =仔3.(2)由正弦定理得c sin C =2R =4,则c =4sin C=4sin 仔3=23姨,由余弦定理得c 2=12=a 2+b 2-2ab cos C ≥2ab-ab=ab ,即ab ≤12(当且仅当a=b 时取等号),故S =12ab sin C ≤12×12×3姨2=33姨(当且仅当a=b 时取等号).即△ABC 面积S 的最大值为33姨.19.【解析】(1)由题意得,(0.002+0.006+0.008+a+b+0.008+0.002+0.002)×20=1,110+0.5-(0.002+0.006+0.008)×2020a×20=1255,,,+,,,-,解得a =0.012,b =0.010,∴滋=(60×0.002+80×0.006+100×0.008+120×0.012+140×0.01+160×0.008+180×0.002+200×0.002)×20=125.6.(2)某职工日行步数w =157(百步),着=157-125.6125.6×100=25,∴职工获得三次抽奖机会,设职工中奖次数为X ,在方案甲下X~B 3,13a &,E (X)=1.在方案乙下E (X )=1.8,∴更喜欢方案乙.20.【解析】(1)在直三棱柱ABC 鄄A 1B 1C 1中,A 1A ⊥平面ABC ,AB 奂平面ABC ,∴A 1A ⊥AB ,又AB ⊥AC ,A 1A ∩AC=A ,A 1A ,AC 奂平面ACC 1A 1,∴AB ⊥平面ACC 1A 1,又A 1M 奂平面ACC 1A 1,∴A 1M ⊥AB ,又在矩形ACC 1A 1中,AA 1=4,A 1M=AM =22姨,即A 1M 2+AM 2=A 1A 2,∴A 1M ⊥AM ,∵AB ∩AM=A ,AB ,AM 奂平面ABM ,∴A 1M ⊥平面ABM.(2)取AC 的中点为N ,连接BN ,∴BN ⊥AC ,又平面ABC ⊥平面ACC 1A 1,平面ABC ∩平面ACC 1A 1=AC ,BN 奂平面ABC ,∴BN ⊥平面ACC 1A 1,取A 1C 1的中点N 1,连接NN 1,同理可得NN 1⊥平面ABC ,如图建立空间直角坐标系,则B (3姨,0,0),C (0,1,0),A 1(0,-1,4),M (0,1,2),设P (0,t ,3-t ),t ∈[-1,1],则B B 2P =(-3姨,t ,3-t ),易知平面ABC 的法向量为n =(0,0,1),设BP 与平面ABC 所成角为兹,设t-1=姿∈[-2,0],∴sin 兹=3-t 3+t 2+(3-t )2姨=(3-t )22t 2-6t +12姨=2姨2·1-3(t-1)t 2-3t +6姨=2姨2·1-3姿姿2-姿+4姨.当姿=0时,sin 兹=2姨2,当姿∈[-2,0)时,sin 兹=2姨2·1-3姿-1+4姿姨,∵y=x +4x 在[-2,0)上单调递减,∴sin 兹关于姿单调递减,故sin 兹∈2姨2,25姨5"a .综上可得sin 兹∈2姨2,25姨5!".21.【解析】(1)由题意知,|22姨-x |=2姨·(x -2姨)2+y 2姨,两边平方,整理即得x 2+2y 2=4,∴曲线C 的方程为x 24+y 22=1.(2)设M (x 0,y 0),A (x 1,y 1),B (x 2,y 2),当x 20=43时,y 20=43,则不妨设点M 23姨3,23姨3a &,则点A 23姨3,-23姨3a &或A -23姨3,23姨3a &,此时O B 2M ·O B 2A =0,则OM ⊥OA ;当x 20≠43时,设直线MA :y=kx+m ,MA 1B 1C 1PAB C xyz NN 1第20题答图参考答案第3页共28页参考答案第4页共28页38由直线MA 与圆O :x 2+y 2=43相切,可得|m |1+k 2姨=23姨,即3m 2=4(1+k 2),联立y=kx+m ,x 2+2y 2=44,可得(2k 2+1)x 2+4kmx +2m 2-4=0,Δ=16k 2m 2-4(2k 2+1)(2m 2-4)=8(4k 2+2-m 2)=163(4k 2+1)>0,由韦达定理可得x 0+x 1=-4km 2k 2+1,x 1x 2=2m 2-42k 2+1,则O O $M ·O O $A =x 0x 1+y 0y 1=x 0x 0+(kx 0+m )(kx 1+m )=(1+k 2)x 0x 1+km (x 0+x 1)+m 2=(1+k 2)(2m 2-4)-4k 2m 2+m 2(1+2k 2)1+2k 2=3m 2-4(1+k 2)1+2k 2=0,∴OM ⊥OA ,同理可得OM ⊥OB.选①,由OM ⊥OA 及OP ⊥AM 可得Rt △MOP ∽Rt △AOP ,则|PM ||OP |=|OP ||PA |,∴|PM |·|PA |=|OP |2=43.选②,由OM ⊥OA 及OM ⊥OB 可得,A ,O ,B 三点共线,则|OA |=|OB |,又|MA |2=|OA |2+|OM |2=|OB |2+|OM |2=|MB |2,因此,|MA |=|MB |.22.【解析】(1)根据题意得,f (x )的定义域为(0,+∞),∴f ′(x )=e x -1-1x -e +12,又f ″(x )=e x -1+1x2>0,∴f ′(x )在(0,+∞)上单调递增,易知f ′(2)=e -12-e +12=0,∴当0<x <2时,f ′(x )<0,当x >2时,f ′(x )>0,∴函数f (x )在(0,2)单调递减,在(2,+∞)单调递增.(2)∵a >0,f (x )的定义域为(0,+∞),∴f ′(x )=e x -1-1x-a ,∴f ″(x )=e x -1+1x2>0,∴f ′(x )在(0,+∞)上单调递增,设h (x )=e x-x -1,则h ′(x )=e x -1,当x >0时,h ′(x )>0,∴h (x )单调递增,当x <0时,h ′(x )<0,∴h (x )单调递减,∴h (x )≥h (0)=0,∴e x -x-1≥0,即e x ≥x+1,∴f ′(1+a )=e a -11+a -a >a +1-11+a -a =1-11+a>0,又f ′(1)=-a <0,∴存在唯一的t 0∈(1,1+a ),使得f ′(t 0)=0,即e t 0-1 -1t 0-a =0,当x ∈(0,t 0)时,f ′(t 0)<0,f (x )单调递减,当x ∈(t 0,+∞)时,f ′(t 0)>0,f (x )单调递增,∴f (x )min =f (t 0),又e x ≥x +1,∴x ≥ln (x +1),∴x -1≥ln x ,当x =1时,等号成立,则x >ln x ,∴f (x )=e x -1-ln x -ax >e x -1-x-ax =e x -1-(a +1)x ,即f (x )>e x -1-(a +1)x ,又e x≥x +1,∴e x -1≥x ,∴ex 2-1≥x 2,∴e x -2≥x 24,又e x -1>e x -2,∴e x -1>x 24,∴f (x )>e x -1-(a+1)x >x 24-(a +1)x ,即f (x )>x 24-(a +1)x ,∴f [4(a+1)]>16(a +1)24-(a +1)×4(a +1)=0,当x $0时,f (x )>0,若函数f (x )有唯一零点x 0,则f (t 0)=0,∴x 0=t 0,即e x 0-1 =1x 0+a ,∴f (x 0)=1x 0+a -ln x 0-ax 0=0,设u (x 0)=1x 0+a -ln x 0-ax 0,∴u ′(x 0)=-1x 20-1x 0-a <0,∴u (x 0)在(1,+∞)单调递减,∴u (1)=1>0,u (2)=12-ln 2-a <0,∴1<x 0<2.2023年普通高等学校招生全国统一考试考前模拟试卷数学(二)1.C 【解析】由题意可得,z=4+3i i =(4+3i )i i 2=4i -3-1=3-4i.故选C.2.C 【解析】解不等式x 2-x -6≤0得,-2≤x ≤3,即A ={x |-2≤x ≤3},解不等式x -1<0得x <1,则B ={x |x <1},UB )={x |x ≥-2}.故选C .3.A 【解析】∵O ,A ,B 三点共线,则O O $A ∥O O $B ,∴埚姿∈R ,O O $B =姿O O $A ,即x m +n =姿(5m -3n ).整理得,(5姿-x )m =(3姿+1)n.又∵向量m ,n 不共线,则5姿-x =3姿+1=0,则x =-53.故选A .4.B 【解析】log 9a 1+log 9a 2+…+log 9a 10=log 9[(a 1a 10)·(a 2a 9)·(a 3a 8)·(a 4a 7)·(a 5a 6)]=log 995=5,故选B .5.A 【解析】sin 2琢+仔660=sin 2琢+仔363-仔223=-cos 2琢+仔333=2sin 2琢+仔363-1=2×89-1=79.故选A .6.C 【解析】小明从中随机夹了3个饺子共有C 310=10×9×83×2×1=120种;如果是1个麸子、1个钱币饺子、1个糖饺子,共有5×3×2=30种;如果是1个麸子、2个钱币饺子,共有C 15C 23=15种;如果是2个麸子、1个钱币饺子,共有C 25C 13=30种.由古典概型的概率公式得,小明夹到的饺子中,既有麸子饺子又有钱币饺子的概率是P =30+15+30120=58.故选C .7.D 【解析】由题可得AB =8,∵AP=BP ,∴S △ABP =12×8×4=16,∵PC ⊥平面ABP ,且PC =4,∴V C 鄄ABP =13×16×4=643,∵AP=BP =42姨,∴AC=BC =43姨,∴S △ABC =12×8×48-16姨=162姨,设点P 到平面ABC 的距离为d ,则V P 鄄ABC =13×162姨d =643,解得d =22姨.故选D.8.C 【解析】a 1a =b 1b 两边同取自然对数得ln a a =ln b b,设f (x )=ln x x,由f ′(x )=1-ln x x2,令f ′(x )>0,解得0<x <e ,令f ′(x )<0,解得e <x ,∴f (x )在区间(0,e )上单调递增,在区间(e ,+∞)上单调递减,∴f (x )在x =e 处取得最大值f (e )=1e,在区间(0,e )上函数f (x )有唯一的零点x =1,在区间(e ,+∞)上函数f (x )>0,又∵a>b >0且f (a )=f (b )>0,∴1<b<e ,a >e.故选C.9.ABD 【解析】如图,∵正四棱柱ABCD 鄄A 1B 1C 1D 1的底面边长为2,∴B 1D 1=22姨,又侧棱AA 1=1,∴DB 1=(22姨)2+12姨=3,则P 与B 1重合时PD =3,此时P 点唯一,故A 正确;∵PD =3姨∈(1,3),DD 1=1,则PD 1=2姨,即点P 的轨迹是一段圆弧,故B 正确;连接DA 1,DC 1,可得平面A 1DC 1∥平面ACB 1,则当P 为A 1C 1中点时,DP 有最小值为(2姨)2+12姨=3姨,故C 错误;平面BDP 即为平面BDD 1B 1,平面BDP 截正四棱柱ABCD 鄄A 1B 1C 1D 1的外接球所得平面图形为外接球的大圆,其半径为1222+22+12姨=32,面积为9仔4,故D 正确.故选ABD .10.BD 【解析】∵f (x )=tan x-cos x ,∴f (0)=-1,f (仔)=1,f (0)≠f (仔),故A 错误;参考答案第5页共28页参考答案第6页共28页PABC第7题答图DABCA 1B 1C 1D 1P122第9题答图39。
考研数学一(矩阵及其运算)模拟试卷1(题后含答案及解析) 题型有:1. 选择题 2. 填空题 3. 解答题选择题下列每题给出的四个选项中,只有一个选项符合题目要求。
1.下列命题中不正确的是A.如A是n阶矩阵,则(A—E)(A+E)=(A+E)(A—E).B.如A,B均是n×1矩阵,则ATB=BTA.C.如A,B均是n阶矩阵,且AB=0,则(A+B)2=A2+B2.D.如A是n阶矩阵,则AmAk=AkAm.正确答案:C解析:(A)中,由乘法有分配律,两个乘积均是A2一E,而(D)是因乘法有结合律,两乘积都是Am+k,故(A),(D)都正确.关于(B),由于ATB,BTA都是1×1矩阵,而1阶矩阵的转置仍是其自身,故ATB=(ATB)T=BTA亦正确.唯(C)中,从AB=0还不能保证必有BA=0,例如A=,则AB=,因此,(C)不正确.选(C).知识模块:矩阵及其运算2.已知3阶矩阵A可逆,将A的第2列与第3列交换得B,再把B的第1列的一2倍加至第3列得C,则满足PA-1=C-1的矩阵P为A.B.C.D.正确答案:B解析:对矩阵A作一次初等列变换相当于用同类的初等矩阵右乘A,故应选(B).知识模块:矩阵及其运算3.设A,P均为3阶矩阵,PT为P的转置矩阵,且PTAP=.若P=(α1,α2,α3),Q=(α1+α2,α2,α3),则QTAQ=A.B.C.D.正确答案:A解析:对矩阵P作一次初等列变换:把第2列加至第1列,便可得到矩阵Q.若记E12(1)=,则Q=PE12(1).那么QTAQ=[PE12(1)]TA[PE12(1)]=(1)(PTAP)E12(1)所以应选(A).知识模块:矩阵及其运算4.设A是任一n(n≥3)阶方阵,A*是其伴随矩阵,又k为常数,且k≠0,±1,则必有(kA)*=A.kA*.B.kn-1A*.C.knA*.D.k-1A*.正确答案:B解析:由于kA=(kaij),故行列式|kA|的代数余子式按定义为再根据伴随矩阵的定义知应选(B).知识模块:矩阵及其运算5.设A,B是n阶矩阵,则C=的伴随矩阵是A.B.C.D.正确答案:D解析:由于CC*=|C|E=|A||B|E,因此应选(D).另外,作为选择题不妨附加条件A,b可逆,那么知识模块:矩阵及其运算6.设A,B,C是n阶矩阵,且ABC=E,则必有A.CBA=E.B.BCA=E.C.BAC=E.D.ACB=E.正确答案:B解析:由ABC=E知A(BC)=(BC)A=E,或(AB)C=C(AB)=E,可见(B)正确.由于乘法不一定能交换,故其余不恒成立.知识模块:矩阵及其运算7.设A,B,C均为n阶矩阵,E为n阶单位矩阵,若B=E+AB,C=A+CA,则B—C=A.E.B.一E.C.A.正确答案:A解析:由B=E+AB(E一A)B=EB=(E—A)-1;C=A+CAC(E—A)=AC=A(E—A)-1(或C=AB).那么B—C=(E一A)-1-A(E—A)-1=(E—A)(E 一A)-1=E(或B—C=B—AB=E).故选(A).知识模块:矩阵及其运算填空题8.设A,B均是n阶对称矩阵,则AB是对称矩阵的充要条件是__________.正确答案:AB=BA解析:两个对称矩阵的乘积不一定是对称矩阵.例如而AB对称AB=BTAT=BA.所以应填:AB=BA.知识模块:矩阵及其运算9.设α,β均为3维列向量,βT是β的转置矩阵,如果则αTβ=___________.正确答案:5解析:设α=(a1,a2,a3)T,β=(b1,b2,b3)T,则而αTβ=(a1,a2,a3)=a1b1+a2b2+a3b3,注意到αTβ正是矩阵αβT的主对角线元素之和,所以αTβ=1+6+(-2)=5.知识模块:矩阵及其运算10.设α=(1,2,3)T,β=(1,,0)T,A=αβT,则A3=_________.正确答案:解析:由于A=αβT==2.所以A3=(αβT)(αβT)(αβT)=α(βTα)(βT α)βT=4αβT=4A= 知识模块:矩阵及其运算11.已知A=,则An=___________.正确答案:解析:由于A=λE+J,其中J=,而进而知J4=J5=…=0.于是知识模块:矩阵及其运算12.已知A=,则An=__________.正确答案:解析:对A分块为则B=3E+J,由于J3=J4=…=0,于是Bn=(3E+J)n=3nE+3n -2J2.而C=(3,-1),C2=6C,…,Cn=6n-1C,所以知识模块:矩阵及其运算13.设A=,则A2013一2A2012=___________.解析:由于A2013一2A2012=(A一2E)A2012,而A一2E=试乘易见(A 一2E)A=0,从而A2013一2A2012=0.知识模块:矩阵及其运算14.已知PA=BP,其中P=,则A2012=__________.正确答案:E解析:因为矩阵P可逆,由PA=BP得A=P-1BP.那么A2=(P-1BP)(P-1BP)=P-1B(PP-1)BP=P-1B2P.归纳地A2012=P-1B2012P.因为,易见B2012=E.所以A2012=P-1EP=E.知识模块:矩阵及其运算15.已知2CA一2AB=C—B,其中A=,则C3=____________.正确答案:解析:由2CA一2AB=C-B得2CA一C=2AB—B.故有C(2A—E)=(2A—E)B.因为2A—E=可逆,所以C=(2A—E)B(2A—E)-1.那么C3=(2A—E)B3(2A—E)-1 知识模块:矩阵及其运算16.已知A=,则An=___________.正确答案:解析:先求A的特征值与特征向量.由对λ=0,由(0E—A)x=0,解出α1=;对λ=6,由(6E—A)x=0,解出α2=令P=.而A=PAP-1,于是知识模块:矩阵及其运算17.=___________.正确答案:解析:E12=是初等矩阵,左乘A=所得E12A是A作初等行变换(1,2两行对换),而E122011A表示A作了奇数次的1,2两行对换,相当于矩阵A作了一次1,2两行对换,故而右乘E13是作1,3两列对换,由于是偶数次对换,因而结果不变,即为所求.知识模块:矩阵及其运算18.设A=,(A-1)*是A-1的伴随矩阵,则(A-1)*=__________.正确答案:解析:因为A-1.(A-1)*=|A-1|E,有(A-1)*=|A-1|A=A.本题|A|=6,所以(A-1)*= 知识模块:矩阵及其运算19.已知n阶行列式|A|=,则|A|的第k行代数余子式的和Ak1+Ak2+…+Akn=___________.正确答案:解析:若依次求每个代数余子式再求和,这很麻烦.我们知道,代数余子式与伴随矩阵A*有密切的联系,而A*与A-1又密不可分.对于A用分块技巧,很容易求出A-1.由于又因A*=|A|A-1,那么可见Ak1+Ak2+…+Akn= 知识模块:矩阵及其运算20.(Ⅰ)已知A=,则(A*)-1=____________.(Ⅱ)已知A=,则A-1=____________.(Ⅲ)设A,B均为三阶矩阵,E是三阶单位矩阵,已知AB=A 一2B,B=,则(A+2E)-1=____________.(Ⅳ)设A=,B=(E+A)-1(E—A),则(E+B)-1=____________.(Ⅴ)如A3=0,则(E+A+A2)-1=____________.正确答案:解析:(Ⅰ)由AA*=|A|E,有(Ⅱ)A=(Ⅲ)由AB=A一2B有AB+2B=A+2E 一2E,得知(A+2E)(E-B)=2E,即(A+2E)(E一B).(Ⅳ)由于B+E=(E+A)-1(E 一A)+E=(E+A)-1(E—A)+(E+A)-1(E+A) =(E+A)-1[(E—A)+(E+A)]=2(E+A)-1,故(B+E)-1=(E+A).(Ⅴ)注意(E—A)(E+A+A2)=E—A3=E.知识模块:矩阵及其运算解答题解答应写出文字说明、证明过程或演算步骤。
考研数学三(行列式和矩阵)模拟试卷1(题后含答案及解析)题型有:1. 选择题 2. 填空题 3. 解答题选择题下列每题给出的四个选项中,只有一个选项符合题目要求。
1.设A是三阶矩阵,B是四阶矩阵,且|A|=2,|B|=6,则为( ).A.24B.-24C.48D.-48正确答案:D解析:选D.知识模块:行列式2.设A为二阶矩阵,且A的每行元素之和为4,|E+A|=0,则|2E+A2|为( ).A.0B.54C.-2D.-24正确答案:B解析:因为A的每行元素之和为4,所以A有特征值4,又|E+A|=0,所以A有特征值-1,于是2E+A2的特征值为18,3,于是|2E+A2|=54,选B.知识模块:行列式填空题3.设f(x)=,则x2项的系数为_______.正确答案:23解析:按行列式的定义,f(x)的3次项和2次项都产生于(x+2)(2x+3)(3x+1),且该项带正号,所以x2项的系数为23.知识模块:行列式4.设A为三阶矩阵,A的第一行元素为1,2,3,|A|的第二行元素的代数余子式分别为a+1,a-2,a-1,则a=_______.正确答案:1解析:由(a+1)+2(a-2)+3(a-1)=0得a=1.知识模块:行列式5.设A是m阶矩阵,B是n阶矩阵,且|A|=a,|B|=b,则=_______.正确答案:(-1)mnab解析:将B的第一行元素分别与A的行对调m次,然后将B的第二行分别与A的行对调m次,如此下去直到B的最后一行与A的行对调m次,则=(-1)mnab.知识模块:行列式6.设三阶方阵A=[A1,A2,A3],其中Ai(i=1,2,3)为三维列向量,且A 的行列式|A|=-2,则行列式|-A1-2A2,2A2+3A3,-3A3+2A1|=_______.正确答案:12解析:由(-A1-2A2,2A2+3A3,-3A3+2A1)=(A1,A2,A3)得|-A1-2A2,2A2+3A3,-3A3+2A1|=|A1,A2,A3|.=12.知识模块:行列式7.设三阶矩阵A=(α,γ1,γ2),B=(β,γ1,γ2),其中α,β,γ1,γ2是三维列向量,且|A|=3,|B|=4,则|5A-2B|=_______.正确答案:63解析:由5A-2B=(5α,5γ1,5γ2)-(2β,2γ1,2γ2)=(5α-2β,3γ1,3γ2),得|5A-2B|=|5α-2β,3γ1,3γ2|=9|5α-2β,γ1,γ2|=9(5|α,γ1,γ2|-2|β,γ1,γ2|)=63.知识模块:行列式8.设A为n阶可逆矩阵(n≥2),则[(A*)*]-1=______(用A*表示).正确答案:解析:由A*=|A|A-1得(A*)*=|A*|.(A*)-1=|A|n-1.(|A|A-1)-1=|A|n-2A,故[(A*)*]-1= 知识模块:矩阵9.设α=(1,-1,2)T,β=(2,1,1)T,A=αβT,则An=______.正确答案:解析:βTα=3,A2=αβT.αβT=3αβT=3A,则An=3n-1A=3n-1 知识模块:矩阵10.A=,且n≥2,则An-2An-1=______.正确答案:O解析:由A2=2A得An=2n-1A,An-1=2n-2A,所以An-2An-1=O.知识模块:矩阵11.设A=,则(A+3E)-1(A2-9E)=______.正确答案:解析:(A+3E)-1(A2-9E)=(A+3E)-1(A+3E)(A-3E)=A-3E= 知识模块:矩阵12.A2-B2=(A+B)(A-B)的充分必要条件是______.正确答案:AB=BA解析:A2-B2=(A+B)(A-B)=A2+BA-AB-B2的充分必要条件是AB=BA.知识模块:矩阵13.设A是三阶矩阵,且|A|=4,则=______.正确答案:2解析:=|2A-1|=23|A-1|=2.知识模块:矩阵14.设A为三阶矩阵,且|A|=4,则=______.正确答案:解析:由A*=|A|A-1=4A-1得=|(2A-1)|-1= 知识模块:矩阵15.设A为四阶矩阵,|A*|=8,则=______.正确答案:8解析:因为A为四阶矩阵,且|A*|=8,所以|A*|=|A|3=8,于是|A|=2.又AA*=|A|E=2E,所以A*=2A-1,故|(A) -1=|4A-1-6A-1|=|(-2)A-1|=(-2)4|A-1|=16×=8.知识模块:矩阵16.若矩阵A=,B是三阶非零矩阵,满足AB=O,则t=______.正确答案:1解析:由AB=O得r(A)+r(B)≤3,因为r(B)≥1,所以r(A)≤2,又因为矩阵A有两行不成比例,所以r(A)≥2,于是r(A)=2.由得t=1.知识模块:矩阵17.设A=,则A-1=______.正确答案:解析:则A-1= 知识模块:矩阵18.设A=,则A-1=______.正确答案:解析:设A1=,A2=,于是A-1=而A-1=,A-1=,故A-1= 知识模块:矩阵19.设A=,则(A*)-1=________.正确答案:解析:|A|=10,因为A*=|A|A-1,所以A*=10A-1,故(A*)-1= 知识模块:矩阵20.设A=,则(A-2E)-1=________.正确答案:解析:则(A-2E)-1= 知识模块:矩阵21.设n阶矩阵A满足A2+A=3E,则(A-3E)-1=________.正确答案:(A+4E)解析:由A2+A=3E,得A2+A-3E=O,(A-3E)(A+4E)=-9E,(A-3E)[ (A+4E)]=E,则(A-3E)-1=(A+4E).知识模块:矩阵22.设A==________.正确答案:解析:令A=(α1,α2,α3),因为|A|=2,所以A*A=|A|E=2E,而A*A=(A*α1,A*α2,A*α3),所以A*α1=,A*α2=,A*α3=于是知识模块:矩阵23.设n维列向量α=(a,0,…,0,a)T,其中a<0,又A=E-ααT,B=E+αα2,且B为A的逆矩阵,则a=________.正确答案:-1解析:由AB=(E-ααT)(E+-ααT)=E+ααT-ααT-2aααT=E且ααT≠O,得-1-2a=0,解得a=-1.知识模块:矩阵24.设三阶矩阵A,B满足关系A-1BA=6A+BA,且A=,则B=________.正确答案:解析:由A-1BA=6A+BA,得A-1B=6E+B,于是(A-1-E)B=6E,B=6(A-1-E)-1= 知识模块:矩阵25.设A是4×3阶矩阵且r(A)=2,B=,则r(AB)=________.正确答案:2解析:因为|B|=10≠0,所以r(AB)=r(A)=2.知识模块:矩阵解答题解答应写出文字说明、证明过程或演算步骤。
2022年河南省实验中学中考物理模拟试卷(一)一、单选题(本大题共6小题,共18分)1.在0℃的房间里,静止在地面上的铅球()A. 具有机械能B. 具有内能C. .没有内能D. 无法判断2.日常生活中,下列估测不符合事实的是()A. 一只“220V60W”的白炽灯工作10ℎ消耗电能约0.6kW⋅ℎB. 手机待机的电流为0.15AC. 家用电饭煲的电功率约为900WD. 照明电路的电压是220V3.粗细相同的两根镍铬合金线A和B,A的长度大于B的长度,将它们串联后接入电路,则通过它们的电流和两端电压的关系是()A. I A>I B,U A=U BB. I A<I B,U A=U BC. I A=I B,U A>U BD. I A=I B,U A<U B4.取一个橙子,把铜片、铁片插入其中,就制成了一个水果电池。
用电压表测量电压如图所示,下列说法正确的是()A. 铁片是水果电池的正极B. 两个相同水果电池串联后可提供更高电压C. 该水果电池的电压是3VD. 水果电池将内能转化为电能5.法拉第发现电磁感应现象,标志着人类从蒸汽机时代步入了电气化时代.下列设备利用电磁感应原理的是()A. 空调B. 电扇C. 发电机D. 电熨斗6.如图所示是小明家的部分电路,他将开关S闭合后,发现L不发光,检测后发现是e点左侧零线断路的缘故。
则S闭合后,用测电笔分别测试图中的a、b、c、d、e五点时,氖管发光的点有()A. 2个B. 3个C. 4个D. 5个二、多选题(本大题共2小题,共6分)7.如图所示,电源电压保持不变,关于电路的工作情况,下列说法中正确的是()A. 同时闭合两个开关,通过两只灯泡的电流一定相同B. 若电压表和电流表的位置对调,闭合S1、S2后,则两表都被烧坏C. 若先闭合S1,再闭合S2,电压表示数不变,电流表的示数变大D. 若灯L1被短路,闭合S1、S2后,灯L1,L2均不亮,电流表损坏8.如图所示,变阻器R2上标有“20Ω1A”的字样。
2021届全国普通高等学校招生统一考试上海英语模拟试卷1学校_________ 班级__________ 姓名__________ 学号__________一、用单词的适当形式完成短文1. Directions: After reading the passage below, fill in the blanks to make the passage coherent and grammatically correct. For the blanks with a given word, fill in each blank with the proper form of the given word; for the other blanks, use one word that best fits each blank.Exploring BeyondFollowing the call of our restless genes has not ended well forall explorers. The British explorer Captain James Cook died in afight with Hawaiians ten years after he received the precious mapfrom Tupaia. His death, some say, brought to a close 【小题1】Western historians call the Age of Exploration. Yet it hardly【小题2】(end)our exploring. We have remained enthusiastic about fillingin the Earth's maps; reaching its farthest poles, highest peaks, and deepest trenches(海豹); sailing to its every corner and then flying off the planet entirely. With the NASA Rover Curiosity now【小题3】(stir)us all as it explores Mars, some countries and private companies are preparing to send humans to the red planet as well. Some visionaries even talk of having a spacecraft【小题4】(send)to the nearest star.NASA's Michael Barratt—a doctor, diver, and jet pilot; a sailor for 40 years; an astronaut for 12—is among those【小题5】ache to go to Mars. Barratt consciously sees himself as an explorer Cook and Tupaia. "We're doing what 【小题6】did," he says. "It works this way at every point in human history. A society develops an enabling technology, 【小题7】it's the ability to preserve and carry food or build a ship or launch a rocket."Not all of us【小题8】ride a rocket or sail the infinite sea. Yet, 【小题9】a species, we're curious enough and interested enough bythe prospect to help pay for the trip and cheer at the voyagers return. Yes, we hope to find a better place to live or acquire alarger territory or make a fortune. But we also explore simply【小题10】(discover)what's there.二、选用适当的单词或短语补全短文2. Directions: Complete the following passage by using the words in the box. Each word can only be used once. Note that there is one wordUndercover WingsThe nocturnal(夜间活动)dot-underwing moth(蛾)may use shape -shifting patterns on its wings as a way to attract mates in the dark. In a study published last September in Current Biology, scientists report the【小题1】on males' forewings of three patches(色斑)that change darkness and size when viewed from particular angles. In females, the entire forewing darkens.Although butterfly and moth species that are active during the day are known to employ visual effects to communicate, researchers had thought their nocturnal cousins relied almost【小题2】on chemical signals because of the lack of light. But these【小题3】wing patterns, now found for the first time in a nocturnal moth, suggest the insects may also use visual signals. Because only the males have this pattern, researchers say it is likely a(n)【小题4】selected mechanism.Jennifer Kelley, an ecologist based at the University of Western Australia, and her colleagues first noticed the visual phenomenon while looking at museum moth specimens(标本)for another project. "As soon as we figured the effect was angle-【小题5】, we knew that to understand how it works, we had to understand the【小题6】physics," Kelley says. The group contacted Gerd Schröder-Turk and Bodo Wilts, who are physicists at Murdoch University in Perth and the Adolphe Merkle Institute in Switzerland respectively.Together the researchers found that when the wings are viewed from above, they【小题7】available light directly, like a dull mirror. When viewed from an angle, however, they let some of thelight through to reveal a deeper layer of darkness, which【小题8】as patches on the male's wings. If the insects were to beat their wings 【小题9】—a common behavior among males approaching potential mates—the patches would flash on and off, creating a striking signal even in very【小题10】light.三、完形填空3. When you are stuck on a problem, sometimes it is best to stop thinking about it—consciously, anyway. Research has shown that taking a break or a nap can help the brain create_________to a solution. Now a new study_________on the effect of this so-called incubation(潜伏期)by using sound cues to focus the sleeping mind on a targeted problem.When humans sleep, parts of the brain replay certain memories, strengthening and transforming them. About a decade ago researchers developed a technique, called targeted memory reactivation(TMR), aimed at further enhancing_________memories: when a sound becomes associated with a memory and is later played during sleep, that memory gets_________. In a study published last November in Psychological Science, scientists tested whether_________the memory of a puzzle during sleep might also improve problem-solving.About 60 participants visited the laboratory before and after a night of_________. First, they_________spatial, verbal and conceptual puzzles, with a distinct music clip repeating in the background for each, until they had worked on six puzzles they could not solve. Overnight they wore electrodes(电极)to detect slow-wave sleep, which may be important for memory enhancement—and a device played the sounds _________to three of the six unsolved puzzles. The next day, back at the lab, the participants attempted the six puzzles again.(Each repeated the experiment with a different set of puzzles the following night.) All told, the subjects solved 32 percent of the sound-stimulated puzzles compared with 21 percent of the_________puzzles.The researchers "very bravely went for quite complex tasks that involved a lot of complex processing, and remarkably they found these really strong effects in all of their __________." says Penny Lewis,a psychologist at Cardiff University, who was not involved in the research. "These are supercool results. Now we need to go out and try to understand them by firstly replicating(复制)them and secondly trying to __________the component processes that are actually being influenced."Beyond providing new evidence that humans restructure memories while sleeping, the research may have __________implications. "In a futuristic world, maybe TMR could help us use sleep to work on our problems," says lead author Kristin Sanders, who was a graduate student at Northwestern University during the study. Sleep-monitoring technology is increasingly accessible—and even without devices, prospective solvers can focus on important problems before __________.Still, sleep is not __________; people need to do their homework and load their heads with the puzzle pieces involved. "I'm not goingto solve cancer with this technique," Sanders says, "because I am totally __________cancer research."【小题1】A.applications B.commitment C.attention D.pathways【小题2】A.counts B.expands C.insists D.passes【小题3】A.treasured B.selected C.devoted D.shortened 【小题4】A.dimmed B.stored C.reactivated D.researched 【小题5】A.neglecting B.examining C.erasing D.revisiting 【小题6】A.sleep B.experiment C.training D.relaxation 【小题7】A.created B.solved C.attempted D.classified 【小题8】A.assigned B.transformed C.explained D.introduced 【小题9】A.unsettled B.untargeted C.unstated D.untested【小题10】A.puzzles B.brains C.processes D.tasks【小题11】A.work out B.turn to C.take on D.bring about 【小题12】A.individual B.conceptual C.practical D.collective 【小题13】A.dinner B.dawn C.bed D.schooling 【小题14】A.significant B.magic C.fixed D.possible【小题15】A.dependentonB.curiousaboutC.interestedinD.ignorant of四、阅读选择4. I confess I hesitated when the editor in chief of The New York Times Magazine told me in late 2014 that I would be editing a new front-of-book column called Letter of Recommendation, about stuff people really like. The column was the brainchild of our staff writer, Sam Anderson, he explained. Sam figured that there was no shortage of places to find out what writers hate but few spaces for writers to talk about what they love. We would push against this trend, 900 words a week, 40-something times per year.The reason for my hesitation was a simple, unfortunate fact about writing. Writing about things you hate is easy: not just fun, but generative. The criticism tends to entertain, even if you disagree, but the ode doesn't. The writerly tone is well-suited to our age, but it's hard not to see it as a collective defense mechanism—as if revealing your true feelings exposes your unmentionable secrets to the public. Obsessions(喜欢), meanwhile, are inseparable from our peculiarities as people—we come to love things for often weird reasons. When the column really works, it's as revealing about the author as it is its subject. One writer, a man in his late 30s, for example, recommended Pedialyte, which he drinks to balance theeffects of both drinking and exercise, and to cheat his way back to youth.I probably see somewhere between three and five Letter of Recommendation pitches a day. It's a great spot for trying out new writers in the magazine, so I try my best to keep up with all the email, but I often fail.(I feel genuinely terrible about this every day of my life.) Determining which to assign involves seeing how it meets the various criteria we've settled on over the years. We don't like the column to be timely—everything else in the world is timely. But on the other hand, we need to put a headline on the thing that people might reasonably recognize, stop and read about. There should be a personal angle to the recommendation, but also some universally recommendable aspect. But then again, it shouldn't be too recommendable; this isn't a column for lifehacks. The recommendation itself should be attractively unexpected—"sideways," as editors are perhaps too fond of saying—but really, it's just an excuse to cut brilliant writers loose to amuse or inspire us.【小题1】Sam Anderson proposed a column called Letter of Recommendation because he found ________.A.the fashion trend was not easy to push againstB.there was a shortage of good quality columnsC.writers could hardly find a place to share their likesD.his brainchild could sometimes increase readership【小题2】The word "ode"(in paragraph 2)is closest in meaning to________.A.praise B.blame C.hesitation D.determination 【小题3】Why is the writer in his late 30s mentioned in paragraph 2? A.To give an example of the writerly tone.B.To highlight the way that the column selects writers.C.To show how a collective defense mechanism works.D.To illustrate how writers reveal themselves in the column.【小题4】The writer hopes that in the column, ________.A.the recommended items are quite familiar to readersB.the recommended items should follow the latest trendC.readers can learn about life skills from the recommendations D.readers will find the recommendations beyond their expectation5. LilyStudying abroad is an area that is becoming increasingly interesting for researchers, as more students are choosing to do a semester, a year or even a degree in another country. In my research, I set out to establish whether young people attending a course abroad acquire more global awareness than students enrolled on similar courses in their home country, Using a comparative study of 50 Canadian undergraduates, half of whom studied abroad for varying lengths of time, there were shown to be considering gains in global awareness and these were not only noted by the students themselves but also their tutors.ThomasMy research project asked ten students starting a year of study abroad to keep a daily record of their experiences. Having begun the diary a month before leaving home they continued it for a month after they returned. The primary reason for studying abroad in all cases was to polish their language skill. The students were allowed towrite as freely as they wished by were asked to include comments on their language learning experience as well as on the strategies they used to cope with living in a new culture. Analysing the diaries, we found remarkably similar patterns. All the participants demonstrate a gradual recognition and acceptance of difference in other cultures and a new objectivity about their own culture as a result of their experience.JasmineThis paper reports on some research carried out last year into why students choose a period of study abroad, their reasons for selecting a specific destination, their behaviour when abroad and the extent to which the experience matches their expectations. Having administered a questionnaire to 1,000 international students studying at a number of universities in Australia, we got 696 responses. An initial analysis of the responses has revealed some interesting data suggesting that the key factor affecting all the areas we were investigating was the individual's personality and study interests. Country of origin and 'gender proved less significant than expected.JimmyThis research looked at the career paths of 35 young business people who had spent part of their university course at a foreign educational institution in order to ascertain whether those people had acquired greater cross-cultural perspectives through their experience of study abroad. Concerned about the lack of cultural awareness of their staff, a group of US business corporations proposed the research. The results are less conclusive than expected, but they do suggest that a period of study in a foreign country may help students to develop the cross-cultural awareness that US employers currently seek.【小题1】The passage is mainly about four researchers' findings on________.A.the reasons for young students to study abroadB.the impact and effects of studying in another countryC.the trend of more students furthering their study abroadD.the interest of students who once studied in another country【小题2】________used the subjects' personal account as the research material.A.Lily B.Thomas C.Jasmine D.Jimmy【小题3】According to the passage, which of the following statements is true?A.Most of the researchers found the students global awareness increased.B.All of the researchers took a reserved attitude towards studying abroad.C.None of the researchers thought gender played a role in students' choice.D.Only one of the researchers did research on the subjects' career development.6. When antibiotics(抗生素)first became available,farmers used them freely. Now scientists know that the overuse of antibiotics can cultivate drug-resistant bacteria that are dangerousto human health. Among debates over what kinds of restrictions should be put in place, figuring out how antibiotic-resistant bacteriaevolve and make their way to humans remains an area of intense interest.Jo Handelsman is tracing one such pathway that, as she puts it, travels from "farm to table."Handelsman, a microbiologist who is now associate director for science at the White House Office of Science and Technology Policy, looked into dairy cows, which are oftentreated with antibiotics and produce manure(排泄物)that farmers use on their crops. In addition to nutrients, that fertilizer may harbor antibiotic-resistant bacteria—a problem because the bacteria can come into contact with plants that are finally shipped to supermarkets and sometimes eaten raw.To find out how those antibiotic-resistant bacteria come to exist, Handelsman and her colleagues at Yale University added manure from a nearby Connecticut farm to raised beds of soil in 2013. In this case, the manure specifically came from cows that were not treated with antibiotics. The researchers unexpectedly found that there were more soil bacteria carrying antibiotic-resistant genes when they were grown with the manure than when they were grown with syntheticnitrogen-based fertilizer—even though the cows were drug-free.Previous research has found that manure from pigs treated with antibiotics contains resistant bacteria, but the cow-pie results suggest there are more factors promoting resistance besidesantibiotic use. Something about manure itself may encourage naturally resistant bacteria to increase.The findings should not, however, give the impression that resistance is everywhere, notes Lance Price, a microbiologist at George Washington University(who was not involved in the study). "We can control this. There's very clear evidence that when we turnoff the antibiotic tap, we bring down drug-resistant bacteria," says Lance.Next on the farm-to-table schedule, Handelsman will test whether radishes grown in soil treated with cow manure are capable of taking up resistant genes from bacteria through their vascular system(循环系统). "They have veins(血管)just like us," she says. "We don'thave any evidence yet that they're taking up the bacteria, but it's a really interesting possibility."【小题1】What does Jo Handelsman's research focus on?A.How antibiotics makes its way onto our table.B.What restrictions should be put to antibiotics use.C.How antibiotics-resistant bacteria reach human beings.D.What damage the overuse of antibiotics does to humans.【小题2】What did Jo's research find?A.Drug-free cows produced manure with antibiotic-resistant bacteria. B.Synthetic nitrogen-based fertilizer did more good to the environment.C.Soil bacteria carrying antibiotic-resistant genes were increasing with time.D.Manure from pigs treated with antibiotics contained fewerresistant bacteria.【小题3】Lance Price is quoted in the passage in order to ________. A.provide more evidence that drug-resistance bacteria are dangerous B.suggest another possible explanation to the antibiotics problems C.emphasize the importance of feeding cows with no antibiotics D.show that the research findings may not be that worrisome【小题4】Which of the following statements is Jo most likely to agree with?A.It is very likely that widespread resistance to antibiotics is not inevitable.B.Plants grown in soil fertilized with cow manure may contain drug-resistant genes.C.There is possibility that radishes take up resistant genes wherever they are planted.D.The vascular system plays a key role in guarding radishes against bacteria.五、六选四7. Washing the dishes can help you live longer in later yearsEven a small increase in light activity, such as washing dishesor a little gentle gardening, might help lower the risk of an early death among older adults, researchers say.“It is important for elderly people, who might not be able to do much moderate intensity activity, that just moving around and doinglight intensity activity will have strong effects and is beneficial,” said Ulf Ekelund, a professor and first author of the study at the Norwegian School of Sport Sciences. However, the study finds that there is more “bang for your buck” if you engage in intense activity compared with light activity. 【小题1】Published in the BMJ, the latest research involved a review of eight studies encompassing a total of more than 36,000 people with an average age of almost 63 years. Participants were followed for five to six years; 2,149 deaths were recorded. Crucially, all of the studies involved monitoring the physical activity of individuals who had activity trackers. 【小题2】For each study participants were split into four equal-sized groups, based on the total amount of time spent active, and the risk of death assessed, taking into account factors such as age, gender, body mass index, and socioeconomic status. This was then repeated for an amount of activity at different levels of intensity. The results were analysed together to give an overview. 【小题3】The resultsheld for different intensities of activity. The team said the study supported the message “sit less and move more and more often.”【小题4】It only looked at the situation for middle age and older adults, most of whom lived in the US or Europe, and some of theeffect could be due to those people with a higher risk of death being less likely to engage in physical activity. Physical activity levels also were only measured over one period of time.A.It is said that higher levels of any physical activity help keep off an early grave.B.The studies did not rely on self-reporting, which, the experts noted, could be unreliable.C.The latest study backs up previous research suggesting reducing time spent sitting still is beneficial.D.However, the study had limitations.E.A short period of intense activity is viewed as beneficial as much longer periods of lesser activity.F.The team found a greater volume of activity overall was linked to a lower risk of death.六、概要写作8. Directions: Read the following passage. Summarize in no more than 60 words the main idea of the passage and how it is illustrated. Use your own words as far as possible.The Useful BeanDo you know what the common factor in bee food, vinyl plastic, and tofu is? It is the soybean. Some part of the soybean is used in these products as well as many other edible(可以食用的)and nonedible products.The soybean is also considered to be one of the multipurpose and hardy plants. It can grow in low-quality soil. Throughout the life of the plant, a release of nutrients throughout plant roots makes soil more fertile. Soybeans are also very high in protein. With its hardiness, soil benefits, high-protein content, and various uses, some people believe the soybean will become the greatest weapon against world hunger.There are three standard procedures taken from the soybean plant—oil, protein, and whole soybeans. Oil is used for edible purposes such as cooking oil and salad dressing. Industries make nonedible use of soybean oil by adding to antistatic sprays, printer ink, and shampoo. One significant nonedible use of soybean oil is the making of vinyl plastics. Vinyl is used to make everything fromcredit cards and garden hoses to computer parts.Protein from the soybean is also used in edible and nonedible products. Edible uses for the protein include baby foods and hypoallergenic milk. Even animals benefit: bee food and fish food contain protein from the soybean. Some industries use the protein for nonedible purposes such as cosmetics, adhesives, yarn, and water-based paints.Items made using whole soybeans are the most commonly recognized product of the soybean plant. Whole soybeans are used to make foodfor people and animals. Grocery stores carry a variety of foods made with whole soybeans. Some of these items are pancake flour, coffee, soymilk, soy sauce and tofu.As the versatility(多用途)and hardiness of this bean gains popularity, more uses of soybean products will certainly be discovered._____________________________________________________________________ _____________________________________________________________________ _____________________________________________________________________ _____________________________________________________________________ _____________________________________________________________________ _____________________________________________________________________ _____________________________________________________________________ ______________________七、汉译英(整句)9. 在他看来,值得投资的是体验,而不是物品。
雅礼中学 2024届模拟试卷( 一 )物理参考答案一 、单选题(本题共 6 小题 , 每小题 4 分 , 共 24 分 , 在每小题给出的四个选项中 , 只有 一 项是符合题目 要求的)题号2 3 4 5答案CD B D CC1 . C 【解析】A. 核反应前后核子数量不变 , 但是核反应前后总质量要变化 , 出现质量亏损 , 故 A 错误;B. 衰变放出的 o e 是原子核中的 一 个中子转化为 一 个质子时放出的 一 个电子 , 故 B 错误 ;C. 由于放射性物质的放射性是原子核本身的性质 , 不会受环境影响 , 则通过高温烹煮后不能消除放射性 , 故 C 正确 ;D. 半衰期由原子核内部因素决定 , 与原子核所处的物理环境和化学状态无关 , 故 D 错误 。
故选C 。
2 . D 【解析】由图得速度和位移成正比 , 物体不是做匀 变速直线运动 。
AB. 随着位移增大 , 物体速度均 匀增大 , 所以相同 时间 内物体位移越来越大 , 速度变化量越来越大 , AB 错误 ; CD. 相同位移速度变化量相同 , 对同 一 物体 , 动量变化量相同 , 但动能变化量不 同 , 所以所受外力的冲量相同 , 做功不同 , C 错误 , D 正确 ;故选 D 。
3 . B 【解析】ABC. 由题可知 , 振幅 A = 20 cm , 频率 f= 0 . 5 Hz , 由图可知波的波长为 入 8 m , 波向右传播 , 该时刻 P 点的振动方向沿 y 轴负 方向 , Q 点的振动方向沿 y 轴正方向 , 故从该时刻开始计时 P 点的振动方程为20sin( rt+t ) cm故 t = 0 时 P 点的位移为 y = 1o,/2 cm 当 ti=0. 25 S 时 P 点的位移为 y ' = 0P 点到达平衡位置 , AC 错误 , B 正确 ;D. 从该时刻开始计时 , 质点 Q 从平衡位置向上振动 , 故质点 Q 的振动方程为 y = 20sin(xt) cm D 错误 。
考研教育学专业基础综合(辨析题)模拟试卷1(题后含答案及解析) 题型有:1.1.教育就是智育。
正确答案:错误。
教育是培养人的社会活动,是承传社会文化,传递生产验和社会生活经验的基本途径,广义的教育泛指一切能够增进人们的知识和技能,影响人们的思想观念的活动。
智育是对智力因素,包括个人的思维品质、元认知和创造力等的培养和开发。
智育只是教育的一个组成部分。
教育还要包括人在德、体、美、劳等方面的发展。
把教育等同于智育,就会造成只重视学生的学业成绩,忽视德育等其他几个方面,这不符合人的全面发展的要求,也不会培养出社会需要的合格的人才。
涉及知识点:教育与人的发展2.教学有法,但无定法。
正确答案:正确。
教学是一种创造性活动,选择与运用教学方法和手段要根据各方面的实际情况统一考虑。
万能的方法是没有的,只依赖于一两种方法进行教学无疑是有缺陷的。
每个教师都应当恰当地选择和创造性地运用教学方法,表现自己的教学艺术和形成自己的教学风格。
涉及知识点:教育学原理3.教学方法就是教师的教法。
正确答案:这种说法是不全面的。
教学方法不仅包括教师的教法,而且还要包括学生的学习力法,是教授法和学习法的统一。
教师在教学过程中处于主导地位,但不可忽视了学生的学习法,否则会因缺乏针对性和可行性而不能有效地达到教学目的。
因此在教学过程中,教师不仅要灵活地采用不同的教学方法,而且还要考虑学生的学习方法,这样才能充分发挥学生的主动参与性,形成良好的师生互动、生动活泼的教学气氛。
涉及知识点:教育学原理4.只要教育得法,人人都可以成为歌唱家、科学家、诗人。
正确答案:(1)这种说法是错误的。
(2)学校教育是一种特殊环境,特别是对年青一代的发展起着主导作用。
①学校教育能排除和控制一些不良因素的影响,给人以更多的正面教育,使人按照一定的思想政治方向发展,使年青一代健康成长。
②学校教育给人的影响比较全面、系统和深刻。
③学校有专门负责教育工作的教师。
他们有明确的教育目的,熟悉教育内容,懂得教育的规律和方法,能自觉地促进学生的思想、学业、身心按照一定的方向发展。
《马克思主义政治经济学原理》期末考试题一、单选题:(每小题1分,共20分)1、在生产关系体系中,决定生产关系性质的是()①人们在直接生产过程中的相互关系②产品分配关系③生产资料所有制形式④人们在交换和消费过程中的关系2、经济规律的客观性意味着()①人们在经济规律面前是无能为力的②它作用的后果是永远不可改变的③它的存在和发生作用是不以人的主观意志为转移的④它的存在和作用是不受时间、地点和条件限制的3、政治经济学研究生产关系要联系()①生产力和上层建筑②某个社会特有的经济规律③生产力和生产方式④某个社会的基本经济规律4、简单商品经济的基本矛盾是()①使用价值和价值的矛盾②具体劳动和抽象劳动的矛盾③个别价值和社会价值的矛盾④私人劳动和社会劳动的矛盾5、与赊购商品有关的货币职能是()①价值尺度②流通手段③支付手段④贮藏手段6、具体劳动和抽象劳动是()①不同商品生产中的两种不同性质的劳动②同一商品生产中分别进行的两个劳动过程③商品生产中同一劳动的两重属性④劳动过程中两种不同职能的分工7、在商品价值中()①C+V+M都是在这次生产过程中新创造的价值②C+V是由旧价值转移来的,M是新创造的价值③C是由旧价值转移来的,V+M是新创造的价值④C是不变资本价值转移来的,V是可变资本价值转移来的,M是新创造的价值8、资本主义生产过程是()①价值形成过程和价值增殖过程的统一②劳动过程和价值增殖过程的统一③劳动过程和价值形成过程的统一④生产使用价值的过程和价值形成过程的统一9、马克思区分不变资本和可变资本的依据是资本的不同部分()①价值周转方式不同②在价值形成中的作用不同③在价值增殖中的作用不同④价值转移的方式不同10、资本有机构成提高意味着()①可变资本在全部资本中的比重下降②流动资本在全部资本中的比重下降③不变资本在全部资本中的比重下降④固定资本在全部资本中的比重下降11、资本积聚是()①剩余价值的资本化②小资本联合成大资本③个别资本通过资本积累增大资本总额④工人的剩余劳动创造的12、无产阶级相对贫困化是指()①无产阶级的收入在社会国民收入中的比重上升②无产阶级的收入在社会国民收入中的比重下降③无产阶级的收入绝对量的下降④无产阶级的物质生活状况绝对恶化13、产业资本循环要顺利进行的必要条件是()①实行边生产、边销售、边采购②投入的资本能不断增殖③使资本在空间上按比例并存,在时间上继起④流通过程和生产过程顺利的通过14、资本的周转速度()①与周转时间成正比,与周转次数成反比②与周转时间成正比,与周转次数成正比③与周转时间成反比,与周转次数成正比④与周转时间成反比,与周转次数成反比15、社会总资本再生产问题的核心是()①恢复原有规模的再生产②扩大原有规律的再生产③社会总产品的实现④生产资料生产的优先增长16、固定资本更新是()①资本主义经济危机周期性爆发的原因②资本主义经济危机周期性爆发的基础③资本主义经济危机周期性爆发的因素④资本主义经济危机周期性爆发的条件17、资本主义级差地租产生的原因是()①土地肥沃的差别②土地位置的差别③土地的资本主义经营垄断④土地私有权的存在18、平均利润率形成后,价值规律发生作用的形式是市场价格围绕着()①价值上下波动②生产价格上下波动③垄断价格上下波动④成本价格上下波动19、国家垄断资本主义是()①私人垄断资本的一种表现形式②国内垄断和国际垄断相结合的垄断资本主义③工业垄断与银行垄断相结合的垄断资本主义④垄断资本与国家政权相结合的垄断资本主义20、金融寡头在经济上的统治是通过()①股份公司实现的②参与制实现的③控制国家政权实现的④竞争实现的二、多选题:(每小题2分,共10分)1、货币是()①人们协商的产物②处于相对价值形式的商品③经常固定充当一般等价物的商品④商品交换发展的结果⑤商品内在矛盾的必然结果2、劳动不是商品,因为()①劳动发生在购买之后,而不是发生在购买之前②承认劳动是商品,无异于否定资本主义剥削③它本身没有价值④如果劳动是商品它的价值就是无法确定⑤它不能拿到市场上去交换3、属于固定资本无形磨损的是()①生产原设备的劳动生产率提高、价值下降②木质建筑结构磨损③钢铁设备锈蚀④刀具使用磨损⑤新机器取代旧机器,原机器设备贬值4、借贷资本的利息()①是剩余价值的特殊转化形式②是平均利润的一部分③是企业全部利润④是职能资本家为取得货币资本使用权而支付的一部分m⑤体现着借贷资本家和其他资本家集团共同剥削工人的关系5、第二次世界大战后,资本输出的特点表现为()①资本输出的规模有了巨大增长②发展中国家与发达资本主义国家之间资本渗透大大加强③资本输出的流向侧重于制造业和第三产业④发达资本主义国家之间的资本渗透大大加强⑤私人对外直接投资比重迅速增大三、计算题:(10分)某资本主义企业投入固定资产150万元,其中厂房120万元,使用期限30年。
2024年辽宁省中考物理模拟练习试卷(一)一、选择题(本题共9小题,共18分。
1~6题为单选题,每题2分;7~9题为多选题,每题2分,漏选得1分,错选得0分1.如图展示的是智能机器人和主持人的互动情况。
下列说法正确的是()A.机器人声音可以在真空中传播·B.机器人构造特殊,它是用超声波与人进行面对面沟通C.能区分机器人和主持人声音主要是根据他们的音色不同D.机器人的声音在空气中的传播速度是3×108m/s2.下列有关物态变化的说法,正确的是()A.冬天,司机往水箱里加点防冻液,是因为防冻液的凝固点比水高B.夏天,从冰箱里取出的易拉罐外壁会出现小水滴,这是水蒸气凝华形成的C.在皮肤上涂一些酒精会感到凉爽,是酒精蒸发放热造成的D.冻豆腐里面有很多小孔,是由于豆腐里的水先凝固后熔化形成的3.下列有关现象与光学知识对应错误的是()A.能从不同方向看见不发光的物体——漫反射B.黑板反光看不清字——镜面反射C.影子的形成——光的反射形成的D.平静的水面出现岸边景物的倒影——平面镜成像4.我国自行研制的第三艘航空母舰——福建舰,采用了最先进的电磁弹射器。
电磁弹射器的弹射车处于强磁场中,当弹射车内的导体有强电流通过时,弹射车就给舰载机提供强大的推力,使舰载机快速起飞。
下列各图能正确反映电磁弹射器工作原理的是()A.B.C.D.5.如图的小实验,将书和直尺叠放在水平桌面上,一只手用力压住课本,另一只手抽出直尺。
下列说法正确的是()A.当手压课本的力增大时,抽出直尺的力大小不变B.手对书的压力和书对手的支持力是一对相互作用力C.书受到的重力和直尺对书的支持力是一对平衡力D.当直尺水平向左抽出时,书受到直尺对它的摩擦力水平向右6.如图是小虎家中电路的一部分,下列说法中正确的是()A.可以用漏电保护器代替保险丝B.电冰箱接入三孔插座后,其外壳与大地相连C.正确使用试电笔接触A点,氢管会发光D.为了用电安全,应在乙处安装开关,甲处安装电灯7.我国刑法规定驾驶员醉酒后驾车要负刑事责任。
模拟试卷(一)一、单项选择题(请选择一个正确答案,将相应字母填入括号内。
每题1分,共20分)1.注塑模设计时,主流道衬套通常是根据( D )的尺寸来选取。
A、定模座板B、定位圈C、定模板D、喷嘴2.( B )脱模剂,用于聚酰胺塑料件的脱模,效果较好。
A、硬脂酸锌B、液体石蜡C、硅油D、石墨3.有的制品要求不同颜色或透明度,在成型前应先在原料中加入所需的( D )。
A、增塑剂B、润滑剂C、稳定剂D、着色剂4.通常注射机的实际注射量最好在注射机的最大注射量的( C )以内。
A、60%B、70%C、80%D、90%5.社会主义职业道德的核心是( D )。
A、集体主义B、共产主义C、全心全意依靠工人阶级D、全心全意为人民服务6.形成人们道德品质内因的是( B )。
A、职业道德教育B、职业道德修养C、职业道德意志D、职业道德行为7.文明礼貌的具体要求不包括( D )。
A、仪表端庄B、语言规范C、举止得体D、待人傲慢8.一个完整的计算机系统包括( D )。
A、主机、键盘、显示器B、计算机及其外部设备C、系统软件与应用软件D、计算机的硬件系统和软件系统9.下列材料中硬度最高的是:( D )A、碳素工具钢B、合金工具钢C、高速钢D、硬质合金10.下列材料淬火后硬度最高的是:( A )A、Tl2B、l6MnC、40CrD、2011.轴类零件定位用的顶尖孔是属于:( C ) 。
A、精基准B、粗基准C、辅助基准D、自为基准12.注射模标准模架选用时.通常考虑几个模板的厚度,下列( C )不是可供选择的。
A、动模板B、定模板C、支撑板D、垫块13.定模板厚度通常与( B )尺寸有关。
A、型芯B、型腔C、侧型芯D、镶块14.斜导柱分型与抽芯机构的结构形式按斜导柱与滑块位置的设置不同有四种形式,其中( B )的特点是没有推出机构。
A、斜导柱在定模.滑块在动模的结构B、斜导柱在动模,滑块在定模的结构C、斜导柱与滑块同在动模的结构D、斜导柱与滑块同在定模的结构15.绘制模具总装图时,下列( D )选项是不需要的。
A、技术要求B、BOM表C、外形尺寸D、零件尺寸16.在绘制零件工程图时,若需表达零件外形某个细微特征,最好选择( A )视图。
A、局部放大B、局部剖C、全剖D、半剖17.注塑CAE软件功能齐全,但不能进行( D )。
A、流动分析B、保压分析C、翘曲分析D、回弹分析18.下列关于注塑模装配时的修配原则,( A )选项是正确的。
A、型腔应保证大端尺寸在制品尺寸公差范围内B、型芯应保证大端尺寸在制品尺寸公差范围内C、拐角处圆角半径型腔应偏小D、拐角处圆角半径型芯应偏大19.推出机构装配时,通常需要根据图纸要求进行导柱孔的加工,下列( D )操作是不需要的。
A、配铰B、划线C、配钻D、配铣20.职业道德是一种( B )的约束机制。
A、强制性B、非强制性C、随意性D、自发性二、多项选择题(请选择一个以上正确答案,将相应字母填入括号内。
每题全部选择正确得分;错选或多选、少选均不得分,也不倒扣分。
每题2分,共30分)1.推杆常用材料是( AC )。
A、T8AB、20CrC、65MnD、40CrE、45钢2.根据塑料的特性和使用要求,塑料制品的后处理可进行( BD )。
A、电镀B、退火处理C、回火处理D、调湿处理E、热喷涂3.以下说法正确的是(ABCDE )。
A、普通车床的主轴转速和进给量的调整范围大,能加工工件的内外表、端面和内外螺纹B、车床是主要用车刀对旋转的工件进行车削加工的机床C、在车床上可用钻头,扩孔钻、铰刀、丝锥、板牙和滚花工具等进行相应的加工D、车床主要用于加工轴、盘、套和其他具有回转表面的工件E、车床是机械制造和修配工厂中使用最广的一类机床4.职业道德的主要特征是( ABC )。
A、职业道德与人们的职业活动相联系B、职业道德的连续性C、公约、守则使职业道德具体化D、职业道德的规范化E、职业道德的人性化5.热塑性塑料的工艺性能主要包括(ABCDE )。
A、收缩性B、流动性C、相容性D、吸湿性E、热敏性。
6.安排箱体零件的机械加工工艺过程时,一般应遵循下列原则(AD )。
A、先粗后精B、先孔后面 C、先小后大D、先面后孔E、先外后内7.全面质量管理的基础工作有(ABCDE )。
A、标准化工作B、计量工作C、质量信息工作D、质量责任制E、质量教育工作8.用人单位有(ABCDE )行为的,劳动保障行政部门或者人事行政部门应当责令用人单位支付劳动报酬或者经济补偿金。
A、未按照劳动人事合同约定支付劳动报酬B、克扣或者无故拖欠职工工资的C、拒不支付职工延长工作时间工资报酬的D、解除劳动人事合同后,未依法给予职工经济补偿的E、未按照劳动人事合同约定提供劳动条件的9.常见的型腔结构形式有( ABCD )。
A、整体式B、嵌入式C、镶拼式D、瓣合式E、修配式10.常用的注塑CAE分折软件有( AD )。
A、Moldflow B.Autoform C.Dynaform D.C-mold E.Ansys11.在导柱、导套装配时,当将长导柱压入固定板时,需要导套进行定位.其目的主要是为了保证( AC )的精度要求。
A、垂直度 B平面度 C、同心度 D、平行度 E、对称度12.常见的塑料模装配中的修配原则有( ADE )。
A、型腔应保证大端尺寸在制品尺寸公差范围内B、热处理后,凡经磨削加工的零件,可不需要退磁C、拐角处圆角半径型腔应偏小D、拐角处圆角半径型芯应偏小E、热处理后,凡经磨削加工的零件,均应充分退磁13.注塑模具验收时.常从下列( ABDE )等因素进行检验。
A、模具结构B、塑件几何形状C、注塑参数D、模具材料E、塑件表面质量14. ISO9000系列质量标准包括( ABC)等标准。
A、1SO9001质量体系B、ISO9002质量体系C、ISO9003质量体系D、 ISO9004质量体系E、ISO90O5质量体系15.模具管理包括下列( ABCDE )等内容。
A、模具档案管理B、模具台帐管理C、模具生产现场管理D、模具库房管理E、模具价格管理三、简答题(每题5分,共20分。
)1.注射模浇口的常见结构形式有哪些?①直接浇口;适合各种塑料成型,尤其加工热敏性及高粘度材料成型高质量的大型或深腔壳、箱形塑件。
②侧浇口;广泛应用于多型腔模中;断面尺寸较小的塑件。
③点浇口;适用于多型腔中心进料模具,且要求浇口痕迹小可自动去除的塑件。
④中心浇口;适用于筒形、环形或中心带孔的塑件成型。
⑤潜伏式浇口;适用于塑件外观要求较高的塑件。
⑥扇形浇口;适用于进料边宽度较大的薄片状塑件。
⑦护耳式浇口;适用于薄板状且质量要求高的塑件。
2.斜导柱分型与抽芯机构的原理及特点是什么,主要应用于哪些场合?①开模时,开模力通过斜导柱作用于滑块上,迫使滑块在动模板的导滑槽内向左滑动,直至斜导柱脱离滑块,即完成抽芯动作。
(2分)②弹簧、钢珠等为滑块定位装置,保证滑块抽芯后的最终位置。
(1分)③合模时,斜导柱进入滑块的斜导柱孔内使滑块向右移动,完成复位动作。
(1分)④楔紧块保证滑块在复位后即成型时的准确位置。
(2分)3.成型零件的一般工作条件是什么?常用材料有哪些?成型零件与熔料直接接触,用于成型塑件的内外表面,主要承受高温、高压、腐蚀、摩擦等工作条件,因此常用的材料有渗碳钢20Cr、调质钢45、40 Cr、高碳工具钢T10、T12、耐蚀钢4Cr13、预硬钢P20、时效硬化钢NAK80等材料。
4.金属材料的工艺性能有哪几个方面?答:1)铸造性(可铸性):指金属材料能用铸造的方法获得合格铸件的性能。
2)可锻性:指金属材料在压力加工时,能改变形状而不产生裂纹的性能。
3)切削加工性(可切削性,机械加工性):指金属材料被刀具切削加工后而成为合格工件的难易程度。
4)焊接性(可焊性):指金属材料对焊接加工的适应性能。
5)热处理性能四、计算、论述题(每题15分,共30分。
)1.(Ⅰ)(Ⅱ)2.先复位机构的应用场合是什么?常见先复位机构的工作原理及特点是什么?答:先复位机构的应用场合主要有:1)推出机构没有先复位则无法安放嵌件的场合;2)在侧抽芯机构中,推出机构没有先复位,合模时会出现侧抽型芯与推杆出现干涉的场合。
常见的先复位机构有:1)弹簧先复位机构:利用固定在复位杆或导向杆或顶杆上的弹簧,通过弹簧力推动推杆固定板,实现先复位。
该复位机构结构简单,但推出力受弹簧所决定,一旦弹簧失效,必须马上更换。
2)楔形滑块先复位机构:工作原理:合模时复位杆作用在楔形滑块上,楔形滑块另一侧压在支承板上,一方面沿着推杆固定板上的滑槽做横向移动,另一方面推动推杆固定板实现复位。
该机构结构较复杂,复位可靠,但由于受楔形滑块尺寸的影响,行程有限,相对行程较短。
3)摆杆先复位机构:利用复位杆带动制定固定在支撑板上的摆杆,摆杆发生转动,从而压迫推杆固定板向下运动,从而实现复位。
特点是摆杆前端带有滚轮可减小摩擦,但结构较复杂,占用一定的空间。
4)杠杆先复位机构:工作原理类似摆杆先复位机构,杠杆固定在推杆固定板上,合模时复位杆带动杠杆机构发生转动,转动时杠杆机构一端顶住支承板,从而迫使推杆固定板复位。