全国计算机等级考试二级教程--C语言程序设计课后习题答案

《全国计算机等级考试二级教程——C语言程序设计》习题分析与详细解答第一章程序设计基本概念习题分析与解答1．1 【参考答案】EXE1．2 【参考答案】［1］.C ［2］.OBJ ［3］.EXE1．3 【参考答案】［1］顺序结构［2］选择结构［3］循环结构第二章C程序设计的初步知识习题分析与解答一、选择题2．1 【参考答案】B)2．2 【参考答案】D)2．3 【参考答案】B)2．4 【参考答案】A)2．5 【参考答案】C)2．6 【参考答案】A)2．7 【参考答案】B)2．8 【参考答案】B)2．9 【参考答案】D)2．10 【参考答案】C)2．11 【参考答案】B)2．12 【参考答案】B)2．13 【参考答案】A)二、填空题2．14 【参考答案】［1］11 ［2］122．15 【参考答案】［1］4.2 ［2］4.22．16 【参考答案】［1］{ ［2］} ［3］定义［4］执行2．17 【参考答案】［1］关键字［2］用户标识符2．18 【参考答案】［1］int ［2］float ［3］double2．19 【参考答案】float a1=1.0, a2=1.0；或float a1=1, a2=1;(系统将自动把1转换为1.0)2．20 【参考答案】存储单元2．21 【参考答案】 3.52．22 【参考答案】［1］a*b/c ［2］a/c*b ［3］b/c*a2．23 【参考答案】把10赋给变量s2．24 【参考答案】［1］位［2］1位二进制数据(0或1)2．25 【参考答案】［1］8 ［2］127 ［3］01111111 ［4］-128 [ 5 ] 10000000 2．26 【参考答案】［1］32767 ［2］-32768 ［3］100002．27 【参考答案】［1］十［2］八［3］十六三、上机改错题2．28 【分析与解答】第1行的错误：(1) include是一个程序行，因此在此行的最后不应当有分号(;)。

《全国计算机等级考试二级教程--C语言程序设计》课后习题答案第一章1.1 EXE1.2 C OBJ EXE1.3 顺序选择循环第二章一. 选择题2.1 B 2.2 D 2.3 B 2.4 A 2.5 C 2.6 A 2.7 B2.8 B 2.9 D 2.10 C 2.11 B 2.12 B 2.13 A二. 填空题2.14 11 122.15 4.2 4.22.16 { } 定义执行语句2.17 关键字用户标识符2.18 int float double2.19 float a1=1; float a2=1;2.20 存储单元2.213.52.22 (a*b)/c a*b/c a/c*b2.23 把常量10赋给变量s2.24 位1或02.25 8 127 0111111 -128 100000002.26 32767 -32768 10000000000000002.27 10 8 16三. 上机改错题2.28#include "stdio.h"; 删除行尾的";"main(); / * main function * / 删除")"后的";",注释中的*要紧靠“/”,即应为“/*”和“*/”函数开始处遗失了一个“{”float r,s ; /*/*r is radius*/,/* s is area of circuilar*/*/ 注释符号不可嵌套使用r = 5.0 ;s = 3.14159 * r * r ;printf("%f\n",s) 行尾遗失了“;”函数结束处遗失了一个“}”2.29#include "stdio.h"main /* main function */ main后遗失了“()”{float a,b,c,v; /*a,b,c are sides, v is volume of cube */a=2.0; b=3.0; c=4.0 行尾遗失了“;”v=a*b*c;printf("%f\n", v) 行尾遗失了“;”}第三章一. 选择题3.1 C 3.2 C 3.3 D 3.4 C 3.5 D 3.6 B 3.7 C 3.8 D 3.9 A 3.10 B3.11 C 3.12 D 3.13 D 3.14 A 3.15 C 3.16 C 3.17 C 3.18 无答案3.19 C 3.20 B二. 填空题3.21 (1)-2002500(2)i=-200,j=2500(3)i=-200j=25003.22 12 0 03.23 一条语句;3.24 ;3.25 100,25.81,1.89234 100 25.81 1.89234 100 25.81 1.89234 3.26 x=127,x= 127,x= 177,x= 7f,x= 1273.27 x=127,x=127 ,x=$127 ,x=$000127,x=%06d3.28 a=513.789215,a= 513.79,a= 513.78921500,a= 513.78921500三. 编程题和改错题3.29 修改后的程序如下：main(){double a,b,c,s,v;printf("input a,b,c:");scanf("%lf%lf%lf",&a,&b,&c);s =a*b;v=a*b*c;printf("a=%f,b=%f,c=%f\n", a,b,c);printf("s=%f,v=%f\n",s,v);}3.30#includemain(){int a=560,b=60;printf("560 minute is %d hour and %d minute.\n",a/b,a%b); }3.31#includemain(){int a,b;a=1500;b=350;printf("a div b is : %d\n",a/b);printf("a mod b is : %d\n",a%b);}3.32#includemain(){double a,b,c,ave;printf ("input 3 double number : \n");scanf ("%lf%lf%lf",&a,&b,&c);printf ("%.1f\n",(a+b+c)/3);}3.33#includevoid main()int a,b,c,t;printf("请依次输入整数a,b,c:");scanf("%d%d%d",&a,&b,&c);printf("\n你输入的值是: a=%d,b=%d,c=%d\n",a,b,c);t=b;b=a;a=c;c=t;printf("交换之后的值是:a=%d,b=%d,c=%d\n",a,b,c);}第四章一. 选择题4.1 A 4.2 A 4.3 A 4.4 D 4.5 C 4.6 A 4.7 B 4.8 C 4.9 D 4.10 C二. 填空题4.11 非0 04.12 < > >= <=同级== ！=同级4.13 ! && ||4.15 !4.16 a == b || a < c x > 4 || x < -44.17 14.18 x <= 0 1 > 04.19 3 2 24.20 *#三. 编程题4.21 略#include/* 检查日期的合法性*/int checkdate(int year, int month, int day) {if(year < 1900 || year > 2005){printf("输入的年份无效!\n");return 0;}else if(month < 0 && month > 12){printf("输入的月份无效!\n");return 0;}else if(day <= 0 && day > 31){printf("输入的日期无效!\n");return 0;}else{switch(month){case 4:case 9:case 11:if(day > 30){printf("输入的日期无效!\n");return 0;}break;case 2:if((year%4 == 0 && year%100 != 0) || year%400 == 0) {if(day > 29){printf("输入的日期无效!\n");return 0;}}else{if(day > 28){printf("输入的出生日期无效!\n");return 0;}}}/* end of switch(m0)*/}return 1;}void main(){int y0, m0, d0; /* 生日*/int y1, m1, d1; /* 当前日期*/int years, months, days; /* 实足年龄*/printf("请输入学生的生日:");scanf("%d%d%d", &y0,&m0,&d0);if(checkdate(y0, m0, d0)){printf("请输入当前日期:");scanf("%d%d%d", &y1,&m1,&d1);/*当前日期合法性检查*/if(!checkdate(y1, m1, d1)){return;}else if(y0 > y1){printf("出生年份比当前年份晚!\n"); return;}else if(y0 == y1){if(m0 > m1){printf("出生年月比当前年月晚!\n"); return;}else if(m0 == m1){if(d0 > d1){printf("出生年月日比当前年月日晚!\n"); return;}}}}/* 计算实足年龄*/years = y1 - y0;months = m1 - m0;days = d1 - d0;/* 修正实足年龄天数*/if(days < 0){months--;switch(m1){case 1:case 5:case 7:case 10:case 12:days += 30;break;case 2:case 4:case 6:case 8:case 9:case 11:days += 31;break;case 3:if((y1%4 == 0 && y1%100 != 0) || y1%400 == 0) {days += 29;}else{days += 28;}break;}/* end of switch(m1) */}/* end of if(days < 0) *//* 修正实足年龄月数*/if(months < 0){months += 12;years--;}/* end of if(months < 0) */printf("出生日期: %d年%d月%d日\n", y0, m0, d0);printf("当前日期: %d年%d月%d日\n", y1, m1, d1);printf("实足年龄: %d年%d月%d日\n", years, months, days);return;}4.23#includevoid main(){int a;printf ("请输入一个整数:"); scanf ("%d",&a);if (a%2==0){printf ("%d 是偶数\n", a);}else{printf ("%d 是奇数\n", a);}}4.24#includevoid main(){int a,b,c,temp,max;printf ("请输入三个整数:"); scanf ("%d %d %d",&a,&b,&c); temp=(a>b)? a:b;max=(temp>c)? temp:c;printf ("\n");printf ("你输入的数中最大的是%d.\n",max); }4.25(1)不嵌套的if语句#includevoid main(){int x,y;printf("input x :");scanf("%d",&x);if ( x>-5 && x<0 ){printf("y is %d\n",y=x);}if ( x==0 ){printf("y is %d\n",y=x-1);}if ( x>0 && x<10 ){printf("y is %d\n",y=x+1);}if ( x>=10 || x<=-5){printf("error\n");}}(2)嵌套的if语句#includevoid main(){int x,y;printf("input x :");scanf("%d",&x);printf("\n");if(x < 0){if(x > -5){printf("y is %d.\n",y=x); }else{printf("error!\n");}}if(0 == x){printf("y is %d.\n",y=x-1);if(x > 0){if(x < 10){printf("y is %d.\n",y=x+1); }else{printf("error!\n");}}}(3)if_else语句#includevoid main(){int x,y;printf("input x :");scanf("%d",&x);if( x>-5 && x<0 ){printf("y is %d.\n",y=x); }else if( x==0 )printf("y is %d.\n",y=x-1); }else if( x>0 && x<10 ) {printf("y is %d.\n",y=x+1); }else{printf("error!\n");}}(4)switch语句#includevoid main(){int x,y;printf("input x : ");scanf("%d",&x);switch (x){case -4:case -3:case -2:case -1:printf("y is %d.\n",y=x);break;case 0:printf("y is %d.\n",y=x-1);break;case 1:case 2:case 3:case 4:case 5:case 6:case 7:case 8:case 9:printf("y is %d.\n",y=x+1);break;default:printf("error!\n");}}第五章一. 选择题5.1 D 5.2 C 5.3 B 5.4 C 5.5 C 5.6 B 5.7 D 5.8 A 5.9 D 5.10 D二. 填空题5.11 5 4 65.12 死循环5.13 -15.14 115.15 d=1.0 k++ k<=n5.16 x>=0 x三. 编程题5.17#includevoid main(){int i;int sig = 1;int sum = 0;for(i=1; i<=101; i++,i++) {sum += sig*i;sig *= -1;}printf("sum=%d\n", sum); }5.18(1)#includevoid main(){int i;double m=1.0; double e = 1.0;for(i=1; i<50; i++) {m *= i;e += 1/m;}printf("e=%f\n",e); }(2)#includevoid main(){int i=1;double m=1.0; double e = 1.0; while(1/m >= 0.0004) {m *= i;e += 1/m;i++;}printf("e=%f\n",e);}5.19#includevoid main(){int year;int col = 0;for(year=1600; year<=2000; year++){if((year%4 == 0 && year%100 != 0) || year%400 == 0) {printf("%d\t", year);col++;if(col%5 == 0){printf("\n");}}}printf("\n");}5.20#include#define N 7void main(){int i;int j;int m;int k = N/2;for(i=0; i {m = i-k;if(m < 0){m *= -1;}for(j=0; j {printf(" ");}for(j=0; j<2*(k-m)+1; j++) {printf("*");}printf("\n");}第六章一. 选择题6.1 B 6.2 D 6.3 A 6.4 A 6.5 B 6.6 D 6.7 D 6.8 B 6.9 A 6.10 A 6.11 C二. 填空题6.12 -16.13 16.14 ctype.h6.15 16.16 10A 20B 30C 40D6.177.29 101.298AB6.18 A7.29B101.2986.19 A B C (每个字符后有三个空格)三. 编程题6.20#include#define N 80void main(){char str[N];int iLoop = 0;gets(str);while(str[iLoop]){printf("%c-%d\t", str[iLoop],str[iLoop]); iLoop++;if(iLoop%3 == 0){printf("\n");}}printf("\n");}6.21#include#define N 80void main(){char str[N];int num = 0;int iLoop = 0;gets(str);while(str[iLoop]){if(str[iLoop] >= '0' && str[iLoop] <= '9') {num = 10*num + (str[iLoop] - '0');}iLoop++;}printf("%d\n",num);}6.22#include#include#define N 80void main(){char str[N];int num = -1;do{gets(str);num++;}while(strcmp(str, "EOF"));printf("您输入了%d行字符！\n",num); }#include#define N 80void main(){char str[N];int iLoop = 0;int num = 0;gets(str);while(str[iLoop] && iLoop < N){if(str[iLoop] >= 'a' && str[iLoop] <= 'z'){num++;}iLoop++;}printf("您输入了字符中有%d个小写字母！\n",num); }6.24#includevoid main(){int iLoop1;int iLoop2;printf("请输入图案的行数(不大于26):");scanf("%d", &line);for(iLoop1 = 0; iLoop1 < line; iLoop1++){for(iLoop2 = 0; iLoop2 < line - iLoop1; iLoop2++) {printf(" ");}for(iLoop2 = 0; iLoop2 < 2*iLoop1+1; iLoop2++) {printf("%c",iLoop1 + 'A');}printf("\n");}}第七章一. 选择题7.1 C 7.2 C 7.3 B 7.4 C 7.5 A 7.6 D 7.7 A二. 填空题7.8 127.9 9.0000007.10 47.11 n=1 s7.12 <=y z*x7.13 1 s*i 0 f(k)三. 程序调试和编程题7.14fun(int n){ int k,yes;for(k=2; k<=n/2; k++){if(n%k == 0) { yes = 0; break;} else yes = 1;}return yes;}7.15int mymod(int a, int b){return a%b;}7.16double fun(int n){double sum = 0;int iLoop;int sig = -1;for(iLoop=1; iLoop<=n; iLoop++) {sig *= -1;sum += sig*1.0/iLoop;}return sum;}7.17double fun(int n){double t = 1.0;int iLoop;long tmp;for(iLoop=2; iLoop<=n; iLoop++) {tmp = iLoop*iLoop;t -= 1.0/tmp;}return t;}7.18#includedouble fun(double x){return x*x + 5*x + 4;}void main(){int x = 2;printf("y1=%f\n", fun(x));printf("y2=%f\n", fun(x+15));printf("y3=%f\n", fun(sin(x)));}第八章一. 选择题8.1 A 8.2 B 8.3 B 8.4 C 8.5 B 8.6 B 8.7 C 8.8 D 8.9 B 8.10 C 8.11 C 8.12 C二. 填空题8.13 1108.14 7 18.15 (1)char *p=&ch; (2) p=&ch; (3)scanf("%c",p); (4)*p='A'; (5)printf("%c",*p);8.16 (1)s=p+3; (2)s=s-2 (3)50 (4)*(s+1) (5)2 (6)10 20 30 40 50三. 编程题8.17void fun(double x, double y, double *sum, double *div){*sum = x + y;*div = x - y;return;}8.18void fun(double x, double y, double z, double *max, double *min){*max = x;*min = x;if(*max < y){*max = y;}if(*max < z){}if(*min > y){*min = y;}if(*min > z){*min = z;}return;}第九章一. 选择题9.1 D 9.2 A 9.3 A 9.4 C 9.5 C 9.6 A 9.7 B 9.8 D 9.9 C 9.10 C 9.11 C 9.12 D 9.13 D 9.14 A 9.15 A 9.16 A 9.17 C 9.18 C二. 填空题9.19 9 09.20 69.21 129.22 39.23 27219.24 -850,2,09.25 k=p k9.26 (c=getchar()) c-'A'三. 编程题9.27#include#define N 81int main(){int counter[10] = {0};int iLoop = 0;char str[N];gets(str);while(str[iLoop]){if(str[iLoop] >= '0' && str[iLoop] <= '9'){counter[str[iLoop] - '0']++;}iLoop++;}for(iLoop=0; iLoop < 10; iLoop++){printf("%d - %d\n", iLoop, counter[iLoop]); }return 0;}9.28void fun(int array[], int arraysize, int start) {int iLoop;if(start < arraysize-1){if(start <=0){start = 1;}for(iLoop = start; iLoop < arraysize; iLoop++) {array[iLoop-1] = array[iLoop];}}for(iLoop = 0; iLoop < arraysize; iLoop++) {printf("No.%d = %d\n", iLoop, array[iLoop]); }}9.29int fun(int arry1[], int arry2[], int arrysize) {int iLoop;int counter = 0;for(iLoop = 0; iLoop < arrysize; iLoop++) {if(arry1[iLoop] % 2){arry2[counter++] = arry1[iLoop];}}return counter;}9.30void fun(char array[], int arraysize){int iLoop1;int iLoop2;char temp;/* 冒泡排序*/for(iLoop1 = 0; iLoop1 < arraysize - 1; iLoop1++){for(iLoop2 = 0; iLoop2 < arraysize - 1 - iLoop1; iLoop2++) {if(array[iLoop2] < array[iLoop2 + 1]){temp = array[iLoop2];array[iLoop2] = array[iLoop2 + 1];array[iLoop2 + 1] = temp;}}}}9.31#includevoid fun(int array[], int arraysize, int inertNumber){int iLoop;int iLoop2;if(array[0] < array[arraysize-1]){for(iLoop = 0; iLoop< arraysize; iLoop++){if(array[iLoop] > inertNumber){for(iLoop2 = arraysize - 1; iLoop2 >= iLoop; iLoop2--) {array[iLoop2 + 1] = array[iLoop2];}array[iLoop] = inertNumber;break;}}if(iLoop >= arraysize){array[arraysize] = inertNumber;}}else{for(iLoop = 0; iLoop< arraysize; iLoop++){if(array[iLoop] < inertNumber){for(iLoop2 = arraysize - 1; iLoop2 >= iLoop; iLoop2--) {array[iLoop2 + 1] = array[iLoop2];}array[iLoop] = inertNumber;break;}}if(iLoop >= arraysize){array[arraysize] = inertNumber;}}}int main(){int iLoop;int a[20] = {7,6,5,3,2,1};for(iLoop = 0; iLoop < 6; iLoop++){printf("%d ", a[iLoop]);}printf("\n");fun(a, 6, 0);for(iLoop = 0; iLoop < 7; iLoop++){printf("%d ", a[iLoop]);}printf("\n");fun(a, 7, 4);for(iLoop = 0; iLoop < 8; iLoop++){printf("%d ", a[iLoop]);}printf("\n");fun(a, 8, 8);for(iLoop = 0; iLoop < 9; iLoop++){printf("%d ", a[iLoop]);}printf("\n");return 0;}9.32int fun(int number, int array[]){int iLoop = 0;int iLoop2;int binLen;int midNumber;int div;int remain;midNumber = number;do{div = midNumber/2;remain = midNumber%2;midNumber = div;array[iLoop++] = remain;}while(midNumber);binLen = iLoop;for(iLoop2 = 0, iLoop = binLen - 1; iLoop2 < iLoop; iLoop2++, iLoop--) {midNumber = array[iLoop2];array[iLoop2] = array[iLoop];array[iLoop] = midNumber;}return binLen;}9.33#include#include#define N 15void fun(int array[], int arraysize){int x;int iLoop2;for(iLoop = 0; iLoop < arraysize; iLoop++){iLoop2 = 0;x = rand()%20;do{if(x == array[iLoop2] && iLoop > 0){x = rand()%20;iLoop2 = 0;}iLoop2++;}while(iLoop2 < iLoop);array[iLoop] = x;}}int main(){int a[N];int iLoop;fun(a, N);for(iLoop = 0; iLoop < N; iLoop++){printf("%d\n", a[iLoop]);}return 0;}第十章一. 选择题10.1 C 10.2 B 10.3 C 10.4 B 10.5 C 10.6 A 10.7 C 10.8 A 10.9 C 10.10 C二. 填空题10.11 GFEDCB10.12 XYZ10.13 SO10.14 1010.16 strlen(str)-1 j--10.17 310.18 goodgood！三. 编程题10.19char* mygets(char *str){int iLoop = 0;char ch;while((ch=getchar()) != '\n'){str[iLoop++] = ch;}str[iLoop] = '\0';return str;}char * myputs(char *str){int iLoop = 0;while(str[iLoop]){putchar(str[iLoop++]);}putchar('\n');return str;}10.20#include#includeint fun(char *str){int len;int iLoop1;int iLoop2;int result = 1;len = strlen(str);for(iLoop1 = 0, iLoop2 = len - 1; iLoop1 < iLoop2; iLoop1++, iLoop2--) {if(str[iLoop1] != str[iLoop2]){break;}}return result;}int main(){char a[20] = "ABCDCBA";char b[20] = "ABCDEBA";printf("%d\n", fun(a));printf("%d\n", fun(b));return 0;}10.21char fun(char *str, int pos){int len;int iLoop;char ch;len = strlen(str);if(pos > len){return NULL;}ch = str[pos];for(iLoop = pos; iLoop < len - 1; iLoop++) {str[iLoop] = str[iLoop + 1];}str[len-1] = '\0';return ch;}第十一章一. 选择题11.1 D 11.2 B 11.3 A 11.4 C二. 填空题11.5 IJKLEFGHABCD11.6 711.7 811.8 *(s+j) i+1 i11.9 1711.10 (*fun)() (*fun)(a+i*h)/h mypoly三. 编程题11.11#include#include#define N 81int main(int argc, char **argv){char sig;int dig;int pos;char str[N] = {'\0'};char outStr[N] = {'\0'};if(argc < 2){sig = '-';dig = 10;}else{sig = argv[1][0];dig = argv[1][1] - '0';}printf("请输入一个字符串：");gets(str);if(sig == '-'){pos = strlen(str) - dig;if(pos <= 0){pos = 0;}strcpy(outStr, str + pos);}else if(sig == '+'){strcpy(outStr, str);pos = strlen(outStr);if(pos > dig){pos = dig;}outStr[pos] = '\0';}printf("处理后的字串为：");printf("%s\n", outStr);return 0;}11.12#include#includevoid movebin(char *bin){int len;int iLoop;len = strlen(bin);for(iLoop = len; iLoop > 0; iLoop--) {bin[iLoop] = bin[iLoop - 1];}return;}void fun(int n, char *bin){int pos;pos = strlen(bin);if(n == 0){return;}if(n == 1){movebin(bin);bin[0] = '1';return;}movebin(bin);bin[0] = (n%2) + '0';n /= 2;fun(n, bin);return;}int main(){int a = 4;char bin[50] = {""};fun(a, bin);printf("%s\n", bin);return 0;}11.13#includelong fun(int n){if(n == 1){return n;}else{return fun(n-1) + n;}}int main(){int num;int sum;printf("请输入一个自然数："); scanf("%d", &num);sum = fun(num);printf("结果是：%d\n", sum); return 0;}11.14#includeint fun(int n){if(n == 0 || n == 1){return 1;}else{return fun(n-1) + fun(n-2);}}int main(){int num;int result;printf("请输入一个自然数：");scanf("%d", &num);result = fun(num);printf("斐波拉契级数为：%d\n", result);return 0;}第十二章一. 选择题12.1 B 12.2 B 12.3 A 12.4 C 12.5 D 12.6 B 12.7 A 12.8 A二. 填空题12.9 2,5,1,2,3,-212.10 2468第十三章一. 选择题13.1 A 13.2 C 13.3 B 13.4 C 13.5 D 13.6 D 13.7 D二. 填空题13.8 ar=9 ar=9 ar=1113.9 int* s *b三. 编程题13.10#define MYALPHA(C) ((C>='A' && C<='Z') || (C>='a' && C<='z')) ? 1 : 0 13.11#define SWAP(t,x,y) {t tmp; tmp=x; x=y; y=tmp;}13.12#include#includeint main(){int *p;int tmp;int iLoop;int iLoop2;p = (int *)malloc(sizeof(int)*3);scanf("%d%d%d", p,p+1,p+2);for(iLoop = 0; iLoop < 2; iLoop++){for(iLoop2 = 0; iLoop2 < 2 - iLoop; iLoop2++){if(*(p + iLoop2) > *(p + iLoop2 + 1)){tmp = *(p + iLoop2);*(p + iLoop2) = *(p + iLoop2 + 1);*(p + iLoop2 + 1) = tmp;}}}printf("%d %d %d\n", *p, *(p+1), *(p+2));free(p);p = NULL;return 0;}第十四章一. 选择题14.1 D 14.2 D 14.3 D 14.4 A 14.5 C 14.6 C 14.7 C 14.8 B14.9 struct link *next14.10 p->next m>p->data14.11 (struct list*) struct list struct list* struct list return h三. 编程题14.12#include#define N 3struct stud{char num[5], name[10];int s[4];double ave;};void readrec(struct stud array[], int size){int iLoop;for(iLoop=0; iLoop {scanf("%s%s%d%d%d%d", array[iLoop].num, array[iLoop].name, &array[iLoop].s[0], &array[iLoop].s[1],&array[iLoop].s[2], &array[iLoop].s[3]);array[iLoop].ave = (array[iLoop].s[0] + array[iLoop].s[1] +array[iLoop].s[2] + array[iLoop].s[3])/4.0;}return;}void writerec(struct stud array[], int size){int iLoop;for(iLoop=0; iLoop{printf("%s\t%s\t%d\t%d\t%d\t%d\t%f\n",array[iLoop].num,array[iLoop].name,array[iLoop].s[0],array[iLoop].s[1],array[iLoop].s[2],array[iLoop].s[3],array[iLoop].ave);}return;}{struct stud stu[N];readrec(stu, N);writerec(stu, N);return 0;}14.13#include#include#define N 100struct node{int data;struct node* next;};int seekMaxValue(struct node *pNode){int max;struct node* pMove;pMove = pNode;max = pMove->data;pMove = pMove->next;while(pMove){if(max < pMove->data){max = pMove->data;}pMove = pMove->next;}return max;}struct node* seekMaxValueAddress(struct node *pNode) {int max;struct node* maxAddress;struct node* pMove;pMove = pNode;max = pMove->data;maxAddress = pMove;pMove = pMove->next;while(pMove){if(max < pMove->data){max = pMove->data;maxAddress = pMove;}pMove = pMove->next;}return maxAddress;}int main(){struct node* head;struct node* pNode;int iLoop;head = (struct node*)malloc(sizeof(struct node)); pNode = head;pNode->next = NULL;for(iLoop=0; iLoop {pNode->next = (struct node*)malloc(sizeof(struct node)); pNode = pNode->next;pNode->next = NULL;pNode->data = iLoop;}printf("%d\n", seekMaxValue(head->next));printf("%d\n", seekMaxValueAddress(head->next));return 0;}第十五章一. 选择题15.1 D 15.2 A 15.3 B 15.4 A二. 填空题15.5 1111000015.6 a^a15.7 a|0xffff15.8 x|0xff0015.9 a=(012500>>2)15.10 ch|0x20第十六章一. 选择题16.1 B 16.2 C二. 填空题16.3 3 !feof(f1) f2 fclose(f1) fclose(f2) 16.4 fopen(fname,"w") ch16.5 "r" !feof(fp) fgetc(fp)16.6 CCCCBBBBAAAA三. 编程题16.7#include#define N 10#define LEN 81int main(){char *str[N] = {"AAAAAAAAA", "BBBBBBBBB", "CCCCCCCCC", "DDDDDDDDD", "EEEEEEEEE", "FFFFFFFFF", "GGGGGGGGG", "HHHHHHHHH","IIIIIIIII","JJJJJJJJJ"};char str2[N][LEN];FILE *fp;int iLoop;fp = fopen("str.txt", "w");if(fp == NULL){printf("创建文件失败！\n");return 1;}else{for(iLoop = 0; iLoop < N; iLoop++) {fputs(str[iLoop], fp);fputs("\n",fp);}}fclose(fp);fp = fopen("str.txt", "r");if(fp == NULL){printf("打开文件失败！\n"); return 1;}else{for(iLoop = 0; iLoop < N; iLoop++) {fgets(str2[iLoop], LEN - 1, fp);}}fclose(fp);for(iLoop = 0; iLoop < N; iLoop++) {printf("%s", str2[iLoop]);}return 0;}16.8#include#define N 10int main(){float num;int iLoop;FILE *fp;fp = fopen("num.bin", "wb+");if(fp == NULL){printf("创建文件失败！\n");return 1;}/* 从键盘读入10个数并写文件*/ printf("请输入%d个数：", N);for(iLoop = 0; iLoop < N; iLoop++) {scanf("%f", &num);fwrite(&num, sizeof(num), 1, fp);}/* 文件指针回到开始处*/rewind(fp);/* 从文件读出10个数并显示*/for(iLoop = 0; iLoop < N; iLoop++) {fread(&num, sizeof(num), 1, fp); printf("%f\n", num);}/* 移文件指针到第四个数开始处*/ fseek(fp, 3L*sizeof(num), SEEK_SET); /* 读入一个新数据*/printf("请输入一个新数据：");scanf("%f", &num);fwrite(&num, sizeof(num), 1, fp);/* 文件指针回到开始处*/rewind(fp);/* 从文件读出10个数并显示*/for(iLoop = 0; iLoop < N; iLoop++) {fread(&num, sizeof(num), 1, fp); printf("%f\n", num);}/* 关闭文件*/fclose(fp);return 0;}她含着笑，切着冰屑悉索的萝卜，她含着笑，用手掏着猪吃的麦糟，她含着笑，扇着炖肉的炉子的火，她含着笑，背了团箕到广场上去晒好那些大豆和小麦，大堰河，为了生活，在她流尽了她的乳液之后，她就用抱过我的两臂，劳动了。

《全国计算机等级考试二级教程——C语言程序设计》习题分析与解答第一章程序设计基本概念习题分析与解答1．1 【参考答案】.EXE1．2 【参考答案】［1］.C ［2］.OBJ ［3］.EXE1．3 【参考答案】［1］顺序结构［2］选择结构［3］循环结构第二章C程序设计的初步知识习题分析与解答一、选择题2．1 【参考答案】B)2．2 【参考答案】D)2．3 【参考答案】B)2．4 【参考答案】A)2．5 【参考答案】C)2．6 【参考答案】A)2．7 【参考答案】B)2．8 【参考答案】B)2．9 【参考答案】D)2．10 【参考答案】C)2．11 【参考答案】B)2．12 【参考答案】B)2．13 【参考答案】A)二、填空题2．14 【参考答案】［1］11 ［2］122．15 【参考答案】［1］4.2 ［2］4.22．16 【参考答案】［1］{ ［2］} ［3］定义［4］执行2．17 【参考答案】［1］关键字［2］用户标识符2．18 【参考答案】［1］int ［2］float ［3］double2．19 【参考答案】float a1=1.0, a2=1.0；或float a1=1, a2=1;(系统将自动把1转换为1.0)2．20 【参考答案】存储单元2．21 【参考答案】 3.52．22 【参考答案】［1］a*b/c ［2］a/c*b ［3］b/c*a2．23 【参考答案】把10赋给变量s2．24 【参考答案】［1］位［2］1位二进制数据(0或1)2．25 【参考答案】［1］8 ［2］127 ［3］01111111 ［4］-128 [ 5 ] 10000000 2．26 【参考答案】［1］32767 ［2］-32768 ［3］100002．27 【参考答案】［1］十［2］八［3］十六三、上机改错题2．28 【分析与解答】第1行的错误：(1) include是一个程序行，因此在此行的最后不应当有分号(;)。

《全国计算机等级考试二级教程——C语言程序设计》习题分析与详细解答第一章程序设计基本概念习题分析与解答1．1 【参考答案】 EXE1．2 【参考答案】［1］ .C ［2］ .OBJ ［3］ .EXE1．3 【参考答案】［1］顺序结构［2］选择结构［3］循环结构第二章 C程序设计的初步知识习题分析与解答一、选择题2．1 【参考答案】 B)2．2 【参考答案】 D)2．3 【参考答案】 B)2．4 【参考答案】 A)2．5 【参考答案】 C)2．6 【参考答案】 A)2．7 【参考答案】 B)2．8 【参考答案】 B)2．9 【参考答案】 D)2．10 【参考答案】 C)2．11 【参考答案】 B)2．12 【参考答案】 B)2．13 【参考答案】 A)二、填空题2．14 【参考答案】［1］ 11 ［2］ 122．15 【参考答案】［1］ 4.2 ［2］ 4.22．16 【参考答案】［1］ { ［2］ } ［3］定义［4］执行2．17 【参考答案】［1］关键字［2］用户标识符2．18 【参考答案】［1］ int ［2］ float ［3］ double2．19 【参考答案】 float a1=1.0, a2=1.0；或float a1=1, a2=1;(系统将自动把1转换为1.0)2．20 【参考答案】存储单元2．21 【参考答案】 3.52．22 【参考答案】［1］ a*b/c ［2］ a/c*b ［3］ b/c*a2．23 【参考答案】把10赋给变量s2．24 【参考答案】［1］位［2］ 1位二进制数据(0或1)2．25 【参考答案】［1］ 8 ［2］127 ［3］01111111 ［4］-128 [ 5 ] 10000000 2．26 【参考答案】［1］ 32767 ［2］ -32768 ［3］ 10000000000000002．27 【参考答案】［1］十［2］八［3］十六三、上机改错题2．28 【分析与解答】第1行的错误：(1) include是一个程序行，因此在此行的最后不应当有分号(;)。

全国计算机等级考试二级教程——《C语言程序设计》课后题及参考答案第三章、顺序结构一、选择题3.1 若a、b、c、d都是int类型变量且初值为0，以下选项中不正确的赋值语句是A) a=b=c=100; B) d++; C) c+b; D) d=(c=22)-(b++);答案：C3.2 以下选项中不是C语句的是A) {int i; i++; printf("%d\n", i); } B) ; C) a=5,c=10 D) { ; } 答案：C3.3 以下合法的C语言赋值语句是A) A=B=58 B) k=int(a+b); C) a=58,b=58 D) --i; 答案：D3.4 以下程序的输出结果是A) 0 B) 1 C) 3 D)不确定的值main() { int x=10,y=3; printf("%d\n", y=x/y); } 答案：C3.5 若变量已正确说明为int类型，要给a、b、c输入数据，以下不正确的输入语句是A) read(a,b,c); B) scanf("%d%d%d",a,b,c); C) scanf("%D%D%D",&a,&b,&c); D) scanf("%d%d%d",&a,&b,&c);答案：D3.6 若变量已正确说明为float类型，要通过以下赋值语句给a赋予10、b赋予22、c赋予33，以下不正确的输入形式是A) 10<CR> 22<CR> 33<CR> B) 10.0,22.0,33.0 C) 10.0<CR> 22.0 33.0 D) 10 22<CR>33 scanf("%f %f %f", &a, &b, &c);答案：B3.7 若变量以正确定义，要将a和b中的数进行交换，下面不正确的语句组是A) a=a+b,b=a-b,a=a-b; B) t=a,a=b,b=t; C) a=t; t=b; b=a; D) t=b; b=a; a=t;答案：C3.8 若变量已正确定义，以下程序段的输出结果是A) 输出格式说明与输出项不匹配，输出无定值B) 5.17000 C) 5.168000 D) 5.169000x=5.16894; printf("%f\n",(int)(x*1000+0.5)/(float)1000);答案：D3.9 若有以下程序段，c3中的值是A) 0 B) 1/2 C) 0.5 D) 1int c1=1,c2=2,c3; c3=c1/c2;答案：A3.10 若有以下程序段，其输出结果是A) 0,0,-10 B) 0,0,5 C) -10,3,-10 D) 3,3,-10int a=0,b=0,c=0; c=(a-=a-5),(a=b,b+3); printf("%d,%d,%d\n",a,b,c);答案：B3.11 当运行以下程序时，在键盘上从第一列开始输入9876543210<CR>（此处<CR>代表Enter），则程序的输出结果是A) a=98,b=765,c=4321B) a=10,b=432,c=8765C) a=98,b=765.000000,c=4321.000000D) a=98,b=765,c=4321.0main() { int a; float b,c; scanf("-?O",&a,&b,&c); printf("\na=%d,b=%f,c=%f\n",a,b,c); }答案：C3.12 以下程序的输出结果是A) a=%2,b=%5B) a=2,b=5C) a=%%d,b=%%dD) a=%d,b=%dmain() { int a=2,b=5; printf("a=%%d,b=%%d\n",a,b); }答案：D3.13 若int类型占两个字节，则以下程序段的输出是A) -1,-1 B) -1,32767 C) -1,32768 D) -1,65535int a=-1; printf("%d,%u\n",a,a);答案：D3.14 以下程序段的输出是A) *496 * B) * 496* C) *000496* D)输出格式符不合法int x=496; printf("*%-06d*\n",x);答案：A3.15 以下程序段的输出是A) |3.1415| B) | 3.0| C) | 3| D) | 3.|float a=3.1415; printf("|%6.0f|\n",a);答案：C3.16 以下程序段的输出是A) |2345.67800| B) |12345.6780| C) |12345.67800| D) |12345.678| printf("| .5f|\n",12345.678);答案：C3.17 以下程序段的输出是A) *0000057.66* B) * 57.66* C) *0000057.67* D) * 57.67* float a=57.666; printf("* 0.2f*\n",a);答案：C3.18 若从终端输入以下数据，要给变量C赋以283.19，则正确的输入语句是A) scanf("%f",c);B) scanf("%8.4f",&c); C) scanf("%6.2f",&c); D) scanf("%8",&c); 283.1900<CR> <CR>表示Enter键答案：由于印刷错误，本题没有正确答案。