盐城市2019届高三年级第一学期期中考试解析

盐城市2019届高三年级第一学期期中考试数学试题一、填空题（本大题共14小题，每小题5分，共70分，请将答案填写在答题卷相应的位置上．）1.若全集U＝{1，2，3}，A＝{1，2}，则∁U A＝_______．【答案】【解析】【分析】根据补集定义求解.【详解】因为U＝{1，2，3}，A＝{1，2}，所以∁U A＝.【点睛】本题考查集合的补集，考查基本求解能力.属基础题.2.函数的定义域为_______．【答案】【解析】【分析】根据偶次根式下被开方数非负列不等式，解得结果.【详解】由题意得，即定义域为.【点睛】本题考查函数定义域，考查基本求解能力.属基础题.3.若钝角的始边与x轴的非负半轴重合，终边与单位圆交于点P(m，)，则tan＝________．【答案】【解析】【分析】先根据点P在单位圆上以及钝角范围解得m,再根据三角函数定义求结果.【详解】因为点P在单位圆上，所以，因为钝角，所以，因此由三角函数定义得tan＝【点睛】本题考查三角函数定义，考查基本求解能力.属基础题.4.在△ABC中，角A，B，C的对边分别为a，b，c，若a＝3，b＝5，c＝7，则角C＝_______．【答案】【解析】【分析】根据余弦定理求cosC,再根据三角形内角范围得结果.【详解】根据余弦定理得：，因为，所以C＝.【点睛】本题考查余弦定理，考查基本求解能力.属基础题.5.已知向量，，，，其中，，若∥，则＝_______．【答案】【解析】【分析】根据向量平行坐标表示列方程，解得，再根据范围得结果.【详解】因为∥，所以,即，因为，，所以＝.【点睛】本题考查向量平行坐标表示，考查基本求解能力.属基础题.6.设等差数列的前n项和为，若，，则公差d＝_______．【答案】【解析】【分析】根据等差数列通项公式以及求和公式列关于首项与公差的方程组，解得结果.【详解】因为，，所以【点睛】本题考查等差数列基本量计算，考查基本求解能力.属基础题.7.在平面直角坐标系中，曲线在x＝0处的切线方程是_______．【答案】【解析】【分析】根据导数几何意义得切线斜率，再根据点斜式得结果.【详解】因为，所以，因此在x＝0处的切线斜率为，因为x＝0时，所以切线方程是【点睛】本题考查导数几何意义，考查基本求解能力.属基础题.8.设函数，则k＝﹣1是函数为奇函数的_______条件（选填“充分不必要、必要不充分、既不充分又不必要、充要”之一）【答案】充分不必要【解析】【分析】先根据为奇函数解得参数k取值范围，再根据取值范围包含关系确定充要关系.【详解】若为奇函数，则，，，所以，因此k＝﹣1是函数为奇函数的充分不必要条件.【点睛】本题考查奇函数性质应用，考查基本求解能力.属基础题.9.在△ABC中，AB＝2，AC＝1，A＝，点D为BC上一点，若，则AD＝_______．【答案】【解析】【分析】先根据条件得C为直角，再建立坐标系，利用数量积解得D点坐标，最后根据模的坐标表示得结果.【详解】因为AB＝2，AC＝1，A＝，所以,即,以 C为坐标原点，AC所在直线为x轴建立直角坐标系，则A(1,0),,设，因为，所以，因此【点睛】本题考查向量数量积坐标表示以及向量模的定义，考查基本求解能力.属中档题.10.若函数的所有正零点构成公差为d(d＞0)的等差数列，则d＝_______．【答案】【解析】【分析】设第一个正零点为，则第三个正零点为，再根据条件得第三个正零点与第一个正零点关系，解得公差.【详解】设第一个正零点为，则第三个正零点为，由题意得【点睛】本题考查正弦函数性质以及等差数列性质，考查基本求解能力.属中档题.11.如图，在四边形ABCD中，A＝，AB＝2，AD＝3，分别延长CB、CD至点E、F，使得，，其中＞0，若，则的值为_______．【答案】【解析】【分析】根据三角形相似得,再根据向量数量积得结果.【详解】因为，，所以,所以,因此.【点睛】本题考查向量数量积定义，考查基本求解能力.属中档题.12.已知函数在R上单调递增，则实数m的取值集合为_______．【答案】【解析】【分析】根据题意转化为导函数恒非负，再根据图象确定条件,解得结果.【详解】因为，所以恒成立，如图可得，即实数m的取值集合为.【点睛】本题考查利用导数研究函数单调性以及不等式恒成立问题，考查等价转化思想以及基本分析求解能力.属较难题.13.已知数列满足，其中，设，若为数列中唯一最小项，则实数的取值范围是_______．【答案】【解析】【分析】先求，再根据数列单调性求为数列中唯一最小项的条件，解得结果.【详解】因为，所以,,,所以,,因此要使为数列中唯一最小项，需【点睛】本题考查等差数列定义以及数列单调性，考查构造法以及基本分析求解能力.属较难题.14.在△ABC中，tanA＝﹣3，△ABC的面积S△ABC＝1，P0为线段BC上一定点，且满足CP0＝BC，若P为线段BC上任意一点，且恒有，则线段BC的长为_______．【答案】【解析】【分析】先根据恒成立确定位置，再根据面积公式以及两角和正切公式列方程组解得结果.【详解】取AC中点M，则,所以时，取最小值，因为恒有，所以，过A作于N.设则因为S△ABC＝1，所以；因为tanA＝﹣3，所以,因此，【点睛】本题考查向量数量积几何意义以及两角和正切公式，考查等价转化思想以及综合分析求解能力.属难题.二、解答题（本大题共6小题，共计90分，请在答题纸指定区域内作答，解答时应写出文字说明、证明过程或演算步骤．）15.若函数(a＞0，b＞0)的图象与x轴相切，且图象上相邻两个最高点之同的距离为π．（1）求a，b的值；（2）求在[0，]上的最大值和最小值．【答案】（1），（2）最大值；最小值【解析】【分析】（1）根据题意得周期，求得，根据图象确定b的值，（2）根据正弦函数性质求最值.【详解】解：（1）因为图像与轴相切，且，所以的最小值为，即，又由最高点间距离为，故，即（2）由（1）得，当时，有当时，即，有最大值；当时，即，有最小值.【点睛】函数的性质(1).(2)周期(3)由求对称轴，最大值对应自变量满足，最小值对应自变量满足，(4)由求增区间;由求减区间16.已知命题p：函数的图象与x轴至多有一个交点，命题q：．（1）若q为真命题，求实数m的取值范围；（2）若p q为假命题，求实数m的取值范围．【答案】（1）或. （2）或.【解析】【分析】（1）先解对数不等式得m的取值范围，再求补集得q为真命题时实数m的取值范围，（2）先求为真时实数m的取值范围，再求补集得命题是假命题时实数m的取值范围，最后求交集得结果.【详解】（1）解：由，得，所以，解得，又因为真命题，所以或.（2）由函数图像与轴至多一个交点，所以，解得，所以当是假命题时，或，由（1）为真命题，即是假命题，所以或，又为假命题，所以命题都是假命题，所以实数满足，解得或.【点睛】求为真时参数取值范围，往往先求p为真时参数取值范围，再求补集得结果.17.在△ABC中，角A，B，C所对的边分别为a，b，c，已知．（1）求A的大小；（2）若b＋c＝6，D为BC的中点，且AD＝，求△ABC的面积．【答案】（1）（2）【解析】【分析】(1)先根据正弦定理化边为角，再根据诱导公式以及两角和正弦公式化简得，即得结果，(2)根据，利用向量的模以及向量数量积、余弦定理化简求得，最后根据三角形面积公式得结果.【详解】解:（1）由正弦定理知，所以,即所以，化简得，因为中，，所以，即，又，所以（2）因为，所以，由，解得所以的面积【点睛】解三角形问题，多为边和角的求值问题，这就需要根据正、余弦定理以及三角形面积公式结合已知条件灵活转化边和角之间的关系，从而达到解决问题的目的.18.如图，PQ为某公园的一条道路，一半径为20米的圆形观赏鱼塘与PQ相切，记其圆心为O，切点为G．为参观方便，现新修建两条道路CA、CB，分别与圆O相切于D、E两点，同时与PQ分别交于A、B两点，其中C、O、G三点共线且满足CA＝CB，记道路CA、CB长之和为．（1）①设∠ACO＝，求出关于的函数关系式；②设AB＝2x米，求出关于x的函数关系式．（2）若新建道路每米造价一定，请选择（1）中的一个函数关系式，研究并确定如何设计使得新建道路造价最少．【答案】（1）①其中②其中（2）当时，取得最小值，新建道路何时造价也最少【解析】【分析】(1)①根据直角三角形得，即得，再根据直角三角形得，最后根据得结果.②根据三角形相似得，即得结果，(2) 选择（1），利用导数求最值，即得结果.【详解】解：（1）①在中，，所以，所以在中，所以，其中，②设，则在中，由与相似得，,即，即，即，即即，化简得，其中（2）选择（1）中的第一个函数关系式研究.令，得.令,当时，，所以递减；当时，，所以递增，所以当时，取得最小值，新建道路何时造价也最少【点睛】利用导数解答函数最值的一般步骤：第一步：利用或求单调区间；第二步：解得两个根；第三步：比较两根同区间端点的大小；第四步：求极值；第五步：比较极值同端点值的大小．19.已知正项数列的首项，前n项和满足．（1）求数列的通项公式；（2）若数列是公比为4的等比数列，且，，也是等比数列，若数列单调递增，求实数的取值范围；（3）若数列、都是等比数列，且满足，试证明: 数列中只存在三项．【答案】（1）（2）（3）见解析【解析】【分析】(1)先根据和项与通项关系得项之间递推关系，再根据等差数列定义以及通项公式得结果，(2)先根据条件解得，再根据数列单调性得恒成立，最后根据最值得结果，(3)先反设超过项，再通过方程组求解公比，通过矛盾否定假设，即得结果.【详解】解：（1），故当时，两式做差得，由为正项数列知，，即为等差数列，故（2）由题意，，化简得，所以，所以，由题意知恒成立，即恒成立，所以，解得（3）不妨设超过项，令，由题意，则有，即带入，可得（*），若则，即为常数数列，与条件矛盾;若，令得，令得，两式作商，可得，带入（*）得，即为常数数列，与条件矛盾，故这样的只有项.【点睛】解决数列的单调性问题可用以下三种方法①用作差比较法，根据的符号判断数列是递增数列、递减数列或是常数列.②用作商比较法，根据与1的大小关系及符号进行判断.③结合相应函数的图像直观判断，注意自变量取值为正整数这一特殊条件20.若函数在处取得极大值或极小值，则称为函数的极值点．设函数，，a，b，k R．（1）若为在x＝1处的切线．①当有两个极值点，，且满足·＝1时，求b的值及a的取值范围；②当函数与的图象只有一个交点，求a的值；（2）若对满足“函数与的图象总有三个交点P，Q，R”的任意突数k，都有PQ＝QR成立，求a，b，k 满足的条件．【答案】（1）①，或. ②. （2）与.【解析】【分析】(1)①根据极值点定义以及韦达定理求得，根据判别式大于零解得a的取值范围；②根据导数几何意义得，解方程或，再根据题意解得结果，(2)先化简方程有两个不等实根，，再根据题意得实数根满足，或，或，最后分类讨论，解得a，b，k满足的条件．【详解】解：（1）①由，因函数有两个极值点，所以两个不等的实数根，所以，即，又，所以，或.②因为函数在处的切线，所以，联立方程组，即，所以，整理得，解得或，因与只有一个交点，所以，解得.（2）联立方程组，由②得，即，方程有一根因与有三个交点，所以有两个不等实根，因与有三个交点且满足，所以实数根满足，或，或，因为满足与有三个交点的任意实数，令，则，解得，，当时，得，，此时，令，则，解得，，不满足与，不符题意；同理也不符题意；当时，由，得，此时总满足，为此只需有两个不等的实根即可，所以，化简得，综上所述，应满足条件与.【点睛】已知极值求参数,先将极值的关系准确转化为导函数方程根的关系，再结合方程根的分布转化为参数所满足的条件.。

2019届江苏省盐城市高三年级第一学期期中考试语 文注意事项：1．答题前，先将自己的姓名、准考证号填写在试题卷和答题卡上，并将准考证号条形码粘贴在答题卡上的指定位置。

2．选择题的作答：每小题选出答案后，用2B 铅笔把答题卡上对应题目的答案标号涂黑，写在试题卷、草稿纸和答题卡上的非答题区域均无效。

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写在试题卷、草稿纸和答题卡上的非答题区域均无效。

4．考试结束后，请将本试题卷和答题卡一并上交。

第I 卷（选择题）一、选择题1．在下面一段文字的横线处填入词语，最恰当的—项是（ ）文章的好坏与写作的快慢无关。

顷刻之间成数千言，未必____可诵，吟得一个字拈断数根须，亦未必________。

我们欣赏的是成品，不是过程。

袁虎倚马草露布，“手不辍笔，俄得七纸”，固然资为美谈，究非常人轨范。

________的人，也许是早有腹稿。

A ． 斐然 字字珠玑 文不加点B ． 斐然 字字千钧 一文不名C ． 蔚然 字字珠玑 一文不名D ． 蔚然 字字千钧 文不加点 2．在下面一段文字横线处填入语句，衔接最恰当的一项是（ ）________，________，________，________。

________，________。

生活充实，才会表白出、发抒出真实的深厚的情思来。

①它就是我们的充实的生活②有了源头才会不息地倾注出真实的水来 ③“要写出诚实的、自己的话” ④应该去寻到它的源头 ⑤空口念着是没用的 ⑥这源头很密迩、广大A ． ②⑥④①③⑤B ． ②⑥⑤③④①C ． ③⑤②⑥④①D ． ③⑤④②⑥① 3．下列诗句所描述的风俗，不属于古代年俗的—项是（ ） A ． —年滴尽莲花漏，碧井屠苏沈冻酒。

B ． 桑柘影斜春社散，家家扶得醉人归。

C ． 当年恶梦惊唐王，秦琼敬德守门旁。

D ． 男儿酌献女儿避，酹酒烧钱灶君喜。

4．下列教室励志标语中，最贴切的一组是（ ）A ． 唯有埋头，方能昂首非学无以广才，非志无以成学 B ． 鹰击天风壮，鹏飞海浪春 今天辛苦一阵子，明天幸福一辈子 C ． 今日不努力，明天去搬砖 笑看人生峰高处，唯有磨难多正果D ． 修身，治国，平天下 天王盖地虎，全上985；宝塔镇河妖，至少211 5．下列选项中，对下图漫画寓意的理解最贴切的一项是（ ）A ． 无论闲乘电梯还是勇攀悬崖，都呈现了精彩的人生。

江苏省盐城市2019-2020学年高三上学期期中物理试卷一、单选题（本大题共5小题，共15.0分）1.如图所示，汽车以恒定的速率运动，分别通过凸形桥面的最高点a、水平桥b及凹形桥面最低点c，桥面粗糙情况是相同的，关于汽车发动机功率大小的下述说法中正确的是()A. 汽车通过a点时功率最大，通过c点时最小B. 汽车通过b点时功率最大C. 汽车通过a点时功率最小，通过c点时功率最大D. 汽车功率不变2.如图所示，B为竖直圆轨道的左端点，它和圆心O的连线与竖直方向的夹角为α。

一小球在圆轨道左侧的A点以速度v0平抛，恰好沿B点的切线方向进入圆轨道。

已知重力加速度为g，则AB之间的水平距离为()A. v02tanαg B. 2v02tanαgC. v02gtanαD. 2v02gtanα3.对于做匀速圆周运动的质点，下列说法正确的是()A. 根据公式a=v2r，可知其向心加速度a与半径r成反比B. 根据公式a=ω2r，可知其向心加速度a与半径r成正比C. 根据公式ω=2πn，可知其角速度ω与转数n成正比D. 根据公式ω=vr，可知其角速度ω与半径r成反比4.如图所示，PQ为某电场中的一条电场线，下列说法正确的是()A. 该电场一定是匀强电场B. 该电场一定是点电荷产生的电场C. P点的电场强度一定比Q点的大D. 正电荷在P点受到的电场力方向沿着电场线方向5.质量为1kg的物体在水平粗糙的地面上受到一水平外力F作用运动，如图甲所示，外力F做功和物体克服摩擦力做功与物体位移的关系如图乙所示，重力加速度g为10m/s2.下列分析错误的是()A. s=9m时，物体速度为3m/sB. 物体运动位移为13.5mC. 前3m运动过程中物体的加速度为3m/s2D. 物体与地面之间的动摩擦因数为0.2二、多选题（本大题共5小题，共20.0分）6.如图所示，蹦床运动员从最高点由静止下落，到接触床面，直至下降到最低点的过程中，不计空气阻力，则()A. 从最高点到接触床面前，运动员做自由落体运动B. 从最高点到接触床面前，运动员处于完全失重状态C. 当刚接触蹦床时，运动员的速度最大D. 从接触床面到下降到最低点的过程中，运动员一直处于超重状态7.根据开普勒关于行星运动的规律和圆周运动知识知：太阳对行星的引力F∝mr2，行星对太阳的引力F′∝Mr2，其中M、m分别为太阳和行星的质量，r为太阳与行星间的距离。

市2019届高三年级第一学期期中考试英语试题(Word版)第一部分听力(共两节,满分20分)做题时, 先将答案标在试卷上. 录音容结束后, 你将有两分钟的时间将试卷上的答案转涂到答题卡上.第一节(共5小题:每小题1分,满分5分)听下面5段对话.每段对话后有一个小题,从题中所给的所给的A、B、C、D四个选项中,选出最佳选项,并标在试卷的相应位置.听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题.每段对话仅读一遍.1. What will the speakers do over the weekend?A. Go camping.B. Stay at home.C. Climb the mountains.2. What does the table probably feel like?A. Smooth.B. Rough.C. Cool.3. Why does the man want to go to the playground?A. He misses playing like a child.B. He wants to work out.C. He needs to rest.4. What will happen to the appointment?A. It will be cancelled.dB. It will be postponedC. It will be on time.5. Where are the speakers?A. At home.B. In a hospital.C. In a school.第二节(共15小题; 每小题1分,满分15分)听下面5段对话或独白.每段对话或独白后有几个小题, 从题中所给的所给的A、B、C、D四个选项中,选出最佳选项,并标在试卷的相应位置.听每段对话或独白前,你将有时间阅读各个小题,每小题5秒;听完后,各小题将给出5秒钟的作答时间.每段对话或独白读两遍. 听第6段材料,回答第6、7题.1.How are the reviews for the Greek restaurant?A. Mostly positive.B. Mostly negative.C. Vague.7. Which restaurant will the speakers probably go to?A. Italian.B. Greek.C. Japanese.听第7段材料,回答第8、9题.8. What is the probable relationship between the speakers?A. Mother and son.B. Coach and athlete.C. Teacher and student.9. What was the score after half-time?A. It was tied.B. The boy’s team was down by ten points.C. The oby’s team wa sup by two points.听第8段材料,回答第10至12题.10. Where does Lina study?A. In France.B. In Germany.C. In England.11. How many languages can Lina speak?A. TwoB. Three.C. Four.12. What does the woman suggest the man do?A. Take over the family farm.B. Be honest with his parents.C. Go back to school.听第9段材料,回答第13至16题.13. How did the boy feel about his book report when he finished it?A. Proud.B. Disappointed.C. Worried.14. Which section of the report was the worst?A. The main paragraphs.B. The introduction.C. The conclusion.15. What does the boy need to improve on most?A. His writng style.B. His listening.C. His comprehension.16. What does the woman suggest the boy do?A. Give up.B. Keep on doing.C. Speak to the teacher.听第10段材料,回答第17至20题.17. When is Cannes Film Festival held every year?A. In May.B. In June.C. In October.18. Which walk goes along the coast?A. Central Avenue.B. Fish Street. V. Main Street.19. How can life in Cannes be described?A. Boring.B. Exciting.C. Relaxing.20. What does the speaker suggest people do in Cannes?A. Enjoy the city on foot.B. Buy some postcards as gifts.C. Visit Cannes in May.第二部分英语知识运用(共两节,满分35分)第一节单项填空(共15小题; 每小题1分,满分35分)请认真阅读下面各题,从题中所给的A、B、C、D四个选项中,选出最佳选项,并在答题卡上将该项涂黑.21. It took over a decade for the economist’s far-sighted views to gain _______, but they have widespread support now.A. currencyB. certificateC. sympathyD. scholarship22.The details of costs and prices are ______, as no one knows exactly what is included and what is not.A. arbitraryB. authenticC. ambiguousD. artificial23. ---I’d been standing there for several minutes before he _____ my presence.---He must have been absorbed in his reading.A. neglectedB. maintainedC. registeredD. revealed24. I had ______ wanted to rush outside and leave all the frustrating things behind but something told me I had to stay and face the music.A. gracefullyB. reluctantlyC. essentiallyD. desperately25. The expression add oil has enjoyed so much popularity in the past years, ______ was collected into the OED last month.A. thatB. whichC. asD. when26. According to Baidu, the high-quality content of Cloud Music will reach massive users _______ Baidu’s app and video platform.A. in honor ofB. in view ofC. by virtue ofD. by way of27. The two men were ________ the heavey trunk for nearly ten minutes, trying to get it up the stairs.A. toying withB. interfering withC. wrestling withD. conflicting with28. Our tutor would listen to us reading our essays aloud, but rarely, ____, commented on them.A. if everB. if anyC. if possibleD. if anything29. ---Do you know Melinda was dismissed for her casual attitude towards job?---No doubt I tried to be pleasant to her but she _______.A. gave me the cold shoulderB. made my dayC. cost me the earthD. pulled my leg30. The Greens’ travel to India _____ enjoyable but Mrs Green was too particular about the accommodation.A. could beB. should beC. must have beenD. could have been31. No man understands a deep book ______ he has seen and lived at least part of its contents.A. untilB. ifC. thoughD. once32. While police suspected ______ he had some connection with the robbery, they couldn’t find solid evidence.A. whetherB. thatC. whatD. how33. The smartphone _____ to be the best ever, users all over the world claim they love it.A. is judgedB. judgedC. having judgedD. to be judged34. When the famous pianist turns thirty, he ______ the piano for more than twenty years.A. playsB. will playC. has been playingD. will have been playing35. ---Why don’t you share the bill and go Dutch?---I couldn’t possibly allow it. _______.A. You asked for itB. It’s on meC. You name itD. It’s a deal第二节完形填空(共20小题;每小题1分,满分20分)请认真阅读下面短文,从短文后各题所给的A、B、C、D四个选项中,选出最佳选项,并在答题卡上将该项涂黑.My parents are from South Africa, and I’m a vegetarian, which no one in my small hometown in Washington understood. I always felt 36 from everybody else at school. As hard as I tried to keep myself 37 , I started getting bullied(霸凌). I 38 who I was, wore really plain clothes, and tied up my bright red hair and 39 I wouldn’t attract as much attention. Eventually, I 40 to an arts high school, which was much more 41 . There, I felt brave enough to show off the unique sides of my 42 and made friends who loved me for who I was.More recently, I’ve 43 with confidence in my skin. When I moved to L. A., I started getting bad cystic acne(痤疮). I didn’t want to go outside, and if I had to, I would 44 makeup. I’ve learned that you can’t 45 control your skin, but you can control how you treat yourself. When I tell myself I’m beautiful, or take a(n) 46 few minutes for skin care, I wake up the next morning feeling 47 .A lot of Riverdale fans made the 48 that I was as mean as Cheryl when the show was first 49 , so I started a YouTube channel for them to get to know my true 50 . And so many of them ask for advice about how to 51 bullying. Playing a 52 girl has helped me see the reasons I was bullied. I tell them, whoever is treating you that way is 53 something, and it has nothing to do with you. Like for Cheryl, every time her 54 erupts, it has to d o with how she’s feeling about herself rather than the other characters. Cheryl behaves in a way that 55 her wealth and upbringing, a privileged daughter of a businessman.My motto: If you take care of yourself, you’ll always feel confident and happy.36. A. absent B. free C. distinct D. immune37. A. active B. unique C. unnoticed D. ambitious38. A. hid B. displayed C. remembered D. forgot39. A. yet B. thus C. moreover D. meanwhile40. A. submitted B. transported C. slipped D. transferred41. A. persuasive B. inclusive C. expensive D. negative42. A. hair B. origin C. personality D. identity43. A. gone B. met C. started D. struggled44. A. abuse B. absorb C. attach D. apply45. A. constantly B. strictly C. hardly D. loosely46. A. spare B. extra C. precious D.unhappy47. A. nervous B. depressed C. content D. ridiculous48. A. assumption B. explanation C. definition D. presentation49. A. aired B. scheduled C. designed D. adapted50. A. strengths B. charms C. values D. characters51. A. handle B. relieve C. clarify D. monitor52. A. popular B. mean C. foreign D. sensitive53. A. seeing throughB. falling through C. putting through D. going through54. A. violence B. excitement C. curiosity D. anxiety55. A. multiplies B. shares C. reflects D. decreases第三部分阅读理解(共15小题;每小题2分,满分30分)请认真阅读下列短文,从短文后各题所给的A、B、C、D四个选项中,选出最佳选项,并在答题卡上将该项涂黑.Over the years, the term Wall Street has come to represent the world of high finance, but it’s also just a street! And before that, it was actually a wall----hence the name.The wall used to protect New Yorkers from attacks by Native American Indians. But eventually, the English knocked the wall down. There are a number of important landmarks on Wall Street. Here are a few of them.TRINITY CHURCHTrinity Church is located at the intersection of WallStreet and Broadway. The original church was destroyed inthe Great New York CITY FIRE OF 1776. The currentchurch was built in 1846. These days, Trinity Church hasseveral choirs, and offers free classical and contemporarymusic concerts.FEDERAL HALL NATIONALMEMORIALFederal Hall was built in 1700 as New York’s City Hall.Later, it became the first capitol building of the United Statesof America. It was the place where George Washington wasinaugurated as the first president of the United States in1789, and it is also where the United States Bill of Rightswas drafted. These days, the building is run by the NationalPark Service as a museum commemorating the historicevents.THE NEW YORK STOCK EXCHANGEThe New York Stock Exchange (NYSE) is aneo-classical building located at 11 Wall Street,. It is theworld’s largest stock exchange by market capitalization ofits listed companies (at US $12.25 trillion as of May 2010).You can visit the building and watch from the third floor astraders buy and sell shares from companies around theworld.BANKERS STRUST COMPANY BUILDINGAt 14 Wall Street you can find the Bankers TrustCompany Building. It’s a 227-metre skyscraper thatoccupies an entire block. The building was originally theheadquarters of Bankers Trust. These days, it serves as theAmerican headquarters of Deutsche Bank.56. How did Wall Street Wall acquire its name?A. Local New Yorkers named it after a certain man.B. Some Native American Indians gave it the name.C. The street got its name due to the original architecture there.D. The English adopted the name in memory of the original wall.57. Among the important landmarks, which used to stage certain political events?A. Trinity Church.B. Federal Hall National Memorial.C. The New York Stock Exchange.D. Bankers Trust Company Building.BDo you like cholocate? It’s popular all over the world, but why? Scientists have been trying to discover its secrets.The main thing is that chocolate makes us happy. This may have something to do with the 380 known chemicals found in it. The problem is that many of these chemicals appear in other types of food too. So, it’s difficult to know why the ones i n chocolate make us feel good. But we aren’t all lost. Adam Drewnowski at the University of Michigan found that chocolate makes the human brain produce natural opiates, called opioids(鸦片). These can stop pain and make us feel good.Others think that we feel good after eating chocolate because of a chemical called anandamide. This occurs naturally in the brain and seems to give us a feeling of happiness. Normally, our levels of anandamide are very low and our body uses it quickly. But two scientists, Emmanuelle di Tomaso of Harvard University and Daniele Piomelli of the University of California believe that the anandamide in chcocolate raises levels of the chemical in our brain. And other substances in chocolate slow down the speed at which we use it. So, chocolate helps us feel happier for longer! Great!But which chocolate is the best? Well, for a start, there’s more anandamide in dark chocolate than milk chocolate. So, you need to buy some dark chocolate. Then, you should follow these five tips from connoisseur chocolate makers Ghirardelli. They say that when choosing chocolate, you need to use all five senses:1.Sight: good chocolate has a shine to it.2.Smell: rub the chocolate with your finger to release the aroma. It should have a deepchocolate smell.3.Sound: when you break a piece of chocolate it should snap crisply, creating a soundsimilar to that of a thin piece of wood being broken.4.Touch: the chocolate should melt easily in your mouth becoming a thick liquid.5.Taste: good chocolate should not taste too sweet or too bitter.58. Why does the author mention opioids in Paragraph 2?A. To prove chocolate contains the same chemicals as opioids.B. To show the sharp contrast between chocolate and opioids.C. To suggest that chocolate is as highly addictive as opioids.D. To help explain the reason why chocolate brings pleasure.59. The underlined word “it” in Paragraph 3 refers to _______.A. anandamideB. chocolateC. opiateD. Brain60. Which of the following best suits “perfect chocolate” according to chocolate makers?A. Milk chocolate that produces a dull sound when broken.B. Milk chocolate that has shiny appearance and bitter taste.C. Dark chocolate that is easy to melt and of moderate taste.D. Dark chocolate that gives off a sweet and deep fragrance.CLandscapes are not only the setting for history; they are also a major ssource of our sense of history and identity. Read them right, and historical landscapes can be more informative than any other kind of source. This is even more the case with sacred landscapes, which were reflection of our ancestors’ beliefs about their relation to the cosmos and can still today seem to hold a spiritual influence.Over the years, I’ve had the good fortune to have spent time in many historical landscapes, hoping to picture something of the spirits of the people who shaped them over the centuries. I still remember years ago walking along the Inca sacred lines around Cuso, Peru. In this ancient landscape, old sites that once belonged to Incan royals had become torn Spanish mansions. Or many years ago, before the Gulf Wars, I took a journey through south Iraq, the heart land of civilization, where the desert is still crossed by dried-up riverbeds of the Euphrates and canals that once sustained the world’s first cities.Britain also has its own magical ancient landscapes. From the Mesolithic to the Bronze andIron Ages, rich layers of the past are still present in the landscape surrounding Stonehenge, even as traffic rushes down the A303. It is the A303 that is the problem. As the main road to the south west from the home counties, the road runs right past Stonehenge. One of humanity’s most famous monuments, Stonehenge is an archaeological landscape without parallel in Europe, and perhaps the world. The first circle at Stonehenge was made 5,000 years ago, and the great stone circle itself in a round 2,500 BC ----the age of the pyramids! And the mysteries of this amazing monument and the complex prehistoric societies that produced it are by no means exhausted, as new discoveries continue to show.All the more worrying to me then, this unique landscape is currently at the centre of a projected plan by Highways England, which aims to relieve congestion on the A303 by creating a four-lane road with a 1.8-mile tunnel, and an expressway interchange 1.5 miles to the west. While the National Trust and English Heritage have offered qualified support for the plan, UNESCO has expressed its opposition. Meanwhile, the Stonehenge Alliance, a group of archaeologists and environmental campaigners, says the plan is based on inadequate and obsolete information. In the end, the argument is about the totality of an ancient landscape, and that includes the ancient astronomical alignment that was purposefully chosen by our ancestors, and that will, in my view, be werecked by the xpressway interchange. Time perhaps for a rethink in the name of future generations?61. What can historical landscapes offer us?A. Details of ancient lifestyle.B. Sacred writingsC. Rich historical informationD. Breathtaking sights.62. What did the author want to explore when touring historical landscapes?A. Different archcitecture.B. His sense of belonging.C. The rise of ancient citiesD. The spirits of ancestors.63. Which of the following is True about Stonehenge?A. The first stone circle has a longer history than the pyramids.B. New discoveries have solved the mysteries of the monument.C. The ancient monument must have been the heart land of civilizaiton.D. The landscape surrounding Stonehenge has rich layers of the present.64. What is the author’s attitude towards the projected plan by Highways England?A. He is for it because it will benefit the future generations.B. He keeps cool but believes a better solution could be adopted.C. It should be stopped because it will destroy the totality of the monument.D. It is rather practical especially with qualified support from the government.D.The news one day reached Gabriel that Bathsheba had left the neighborhood. Her abrupt departure is more emphatic than her verbal refusal of his offer. It may have been observed that there is no regular path for getting out of love as there is for getting in. All that Gabriel learnt of Bathsheba’s movements was done indirectly. It appeared that she had gone to a place called Weatherbury, which, whether as a visitor or permanently, he could not discover.Gabriel had two dogs. George, the elder, had originally belonged to a shepherd (牧羊人) of inferior morals and dreadful temper. Long experience had so precisely taught the animal the difference between different orders. Though old, he was clever and trustworthy still. The youngdog, Ge orge’s son, might possibly have been the image of his mother, for there was not much resemblance between him and George. He was learning the sheep-keeping business. So earnest and yet so wrongheaded was this young dog that if sent behind he did it so thoroughly that he would have chased them across the whole country with the greatest pleasure if not called off.One night, when Gabriel had returned to his house, he called as usual to the dogs, previously shutting them up in the outhouse till next morning. Only one responded----old George; the other could not be found. ①Gabriel then concluded that the young one had not finished his meal, and he went indoors to the luxxury of a bed.It was a still and wet night. Just before dawn he was woken by the abnormal reverberation of familiar music. To the shepherd, the note of the sheep-bell is beating with unusual violence and rapidity. The experienced ear of Gabriel knew the sound was caused by the running of the flock with great speed. ②He jumped out of bed and ascended the hill. These two hundred ewes( female sheep) seemed to have absolutely vanished from the hill. Gabriel called at the top of his voice:‘Ovey, ovey, ovey!’He called again: the valleys and furthest hills resounded but no sheep. He passed through the trees and along the ridge of the hill. ③He advanced: at one point the rails were broken through, and there he saw the footprints of his ewes. The dog came up, licked his hand, and made signs implying that he expected some great reward. Gabriel looked over the side of the mountain. The ewes lay dead----a pile of two hundred dead bodies.As far as could be learnt, it appeared that the poor young dog, still under the impression that since he was kept for funning after sheep, the more he ran after them the better, had at the end of his meal off the dead lamb, which may have given him additional energy and spirits, collected all the ewes into a corner and driven the timid creatures through the hedge, breaking down a portion of the rotten railing. ④Gabriel was an intensely humane man; his first feeling now was one of pity for the untimely fate of these gentle ewes and their unborn lambs. It was a sxecond to remember another stage of the matter. All the savings had been gone at a blow; his hopes of being an independent farmer were laid low. Gabriel’s energies, patience, and industry had been so severely taxed during the years of his life, to reach his present stage of progress, that no more seemed to be left in him. He leant down upon a rail, covered his face with his hands and uttered in thankfulness: “Thank God I am not married: what would she have done in the poverty now coming upon me!”Gabriel found that the value of remaining lambs, plant, and implements which were really his own would be about sufficient to pay his debts, leaving himself a free man with the clothes he stood up in, and nothing more. Two months later, Gabriel was discovered at the hiring fair in Casterbridge. Though he was not hired, he earned a few pennies at the hiring fair and learned that another fair would be held at Shottsford, 10 miles beyong Weatherbury.65. How did Gabriel feel after Bathsheba’s departure?A. He was consumed with anger.B. He quickly adapted and moved on .C. He decided to stick to his first love.D. He was at a loss to grasp the reasons.66. What can we learn about the young dog?A. He was more than capable of doing a shepherd dog’s duty.B. He was slow in responding to Gabriel’s different orders.C. He bore a striking resemblance to the old dog George.D. He belonged to those of terrible temper and behavior.67. Where should the sentence “ On the extreme summit, he saw the younger dog standing against the sky----dark and motionless.” Be put in the passage?A.①B. ②C. ③D. ④68. Two hundred ewes died mainly due to ______.A. Gabriel’s carelessness.B. the absence of old GeorgeC. the young dog’s wrong impressionD. the unpleasant weather conditions69. Why did Gabriel utter such words in thankfulness after such a blow to him?A. He eas greatly relieved to know that no villager got hurt in the disaster.B. He felt lucky that he oculd pay off his debts with the remaining things on the farm.C. He was convinced that with patience and industry such a situation would improve.D. He had such a considerate and sympathetic nature that he didn’t want ot bother others.70. What might happen in the following paragraphs?A. Gabriel decided to see Bathsheba on his way to Shottsford.B. Gabriel found a good job in Casterbridge and succeeded again.C. The young dog was abandoned for his failure ot perform his duty.D. Good neighbors gave Gabriel a hand and restored the rotten railing.第四部分任务型阅读(共10小题;每小题1分,满分10分)请认真阅读下列短文,并根据所读容在文章后表格中的空格里填入一个最恰当的单词。

2019届江苏省盐城市高三年级第一学期期中模拟考试数学试题★祝你考试顺利★注意事项：1、考试范围：高考考查范围。

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7、本科目考试结束后，请将答题卡依序排列上交。

8、本科目考试结束后，请将试卷自行保管，以供教师讲评分析试卷使用。

一、填空题：本大题共14小题，每小题5分，共计70分. 请把答案填写在答题卡相应位置上.1.已知集合，，则=_________.【答案】【解析】【分析】由交集的定义可得出结论【详解】，，则=【点睛】本题主要考察集合的交集运算，即取两个集合中的公共元素2.已知函数的最小正周期为4，则=________.【答案】【解析】【分析】的周期计算公式可得答案【详解】由周期计算公式可得，解得=【点睛】或的最小正周期计算公式均为3.函数的定义域是．【答案】【解析】试题分析：根据题意，由于则可知,解不等式组可知x的范围是，故答案为。

考点：函数定义域点评：主要是考查了对数函数的定义域的运用，属于基础题。

盐城市2019届高三年级第一学期期中考试语文试题(含答案)盐城市2019届高三年级第一学期期中考试语文试题一、语言文字运用（15分）1.在下面一段文字的横线处填入词语，最恰当的一项是（3分）文章的好坏与写作的快慢无关，顷刻间成数千言，未必▲可诵，吟得一字拈断数茎须，亦未必▲，我们欣赏的是成品，不是过程。

“手不辍笔，俄得七纸”，固然资为美谈，终究不是常人轨范。

▲的人，也许是早有腹稿。

A.斐然字字珠玑文不加点B.斐然字字千钧一文不名C.蔚然字字珠玑一文不名D.蔚然字字千钧文不加点2．在下面一段文字横线处填入语句，衔接最恰当的一项是（3分），，，。

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生活充实，才会表白出、发抒出真实的深厚的情思来。

①它就是我们的充实的生活②有了源头才会不息地倾注出真实的水来③“要写出诚实的、自己的话”④应该去寻到它的源头⑤空口念着是没用的⑥这源头很密迩、广大A.②⑥④①③⑤B.②⑥⑤③④①C.③⑤②⑥④①D.③⑤④②⑥①3.下列诗句所描述的风俗，不属于．．．古代年俗的一项是（3分）A.一年滴尽莲花漏，碧井屠苏沈冻酒。

B.桑柘影斜春社散，家家扶得醉人归。

C.当年恶梦惊唐王，秦琼敬德守门旁。

D.男儿酌献女儿避，酹酒烧钱灶君喜。

4.下列教室励志标语中，最贴切的一组是（3分）A.唯有埋头，方能昂首非学无以广才，非志无以成学B.鹰击天风壮，鹏飞海浪春今天辛苦一阵子，明天幸福一辈子C.今日不努力，明天去搬砖笑看人生峰高处，唯有磨难多正果D.修身，治国，平天下天王盖地虎，全上985；宝塔镇河妖，至少2115.下列选项中，对右图漫画寓意的理解最贴切的一项是（3分）A.无论闲乘电梯还是勇攀悬崖，都呈现了精彩的人生。

B.人一旦实现了目标，就会失去奋斗动力，无所事事。

C.经历艰难攀登的人，比走捷径者更懂得成功的快乐。

D.不同的人机遇不同，但是奋斗可以弥补机遇的不足。

二、文言文阅读（18分）阅读下面的文言文，完成6～9题。

故龙图阁学士滕公墓志铭苏轼神宗初临海内，厉精为治，旁求天下，以出异人，得英伟大度之士。

3.2函数f(x)=sin x 的最小正周期为 A4. 若哥函数f(x) =乂3a WQ)的图象过点(2,5. 若等比数列{a n }满足a 2= 3 , a 4=9 ,则a 6 =A6. 若a ,b 均为单位向量，且 a I (a -2b ),则a ,b 的夹角大小为 ▲7. 若函数f(x)= nx 12 m x2 -1是奇函数，则m=A8. 31已知点P 是函数f (x) =cosx(0 <x <-)图象上一点，则曲线 y = f (x)在点P 处的切线斜率的9.在等差数列｛a n ｝中，S n是其前n 项和，若S 7=S 5+4,则S 9-S 3=A 10. 在 MBC 中，a,b,c 分别为角A,B,C 的对边，若a = 4,b=3, A=2B,则 sinB=▲11. 如图，在等月MBC 中，AB=AC , M 为BC 中点，点D 、1 一 一 一 q在边 AB 、AC 上，且 A D= — D B, AE=3EC ,若2E 分别高考数学精品复习资料2019.5盐城市20xx 届高三年级第一学期期中考试数学试题(总分160分，考试时间120分钟)、填空题：本大题共14小题，每小题5分，计70分.不需写出解答过程，请把答案写在答题纸的指 定位置上.若集合 A ={0,1},集合 B={0,—1},则 AUB= —A a b命题“若a Ab ,则2 >2 ”的否命题为▲1. 2.= 90, 贝U cos A=12.若函数f(x) = x2+ax-2在(0,十口)上单调递增，则实数a的取值范围是▲.13.设函数y =x2—3M2nJL x + 2M4n」(n w N*)的图象在x轴上截得的线段长为d n,记数列的2前n项和为S n,若存在正整数n,使得log2(S n+1 ) 至18成立，则实数m的最小值为▲. 3 3 _ 23 --|x3-2x2 +x| (x<1)……”14.已知函数f(x)=J 1 1 ' '若命题"二t w R ,且t #0 ,使得f(t)之kt ”是ln x (x 之1)假命题，则实数k的取值范围是▲.二、解答题：本大题共6小题，计90分.解答应写出必要的文字说明，证明过程或演算步骤，请把答案写在答题纸的指定区域内.15.(本小题满分14分)已知函数f (x) =sin缶x+acos^x满足f(0) = J3,且f (x)图象的相邻两条对称轴间的距离为二.(1)求a与切的值；.二二. 5 二(2)若f (叼=1 , a w (--,-),求cos(a --)的值.16」本小题湖分14分卜坦虎诚y= 1电(一£ +心—3)的定义域为上，函数y =，一.工w 10g的值域为5.x十1 1(1)当制=2时，求月；•(2)若'&巨是“艾wE”的总岐不充分祭件，求实数用的取画范圉」17.(本小题满分14分) 」)设^ ABC的面积为S,且2S+43AB AC =0.(1 )求角・。

2019-2020学年江苏省盐城市高三（上）期中数学试卷一、填空题（本大题共14小题，共70.0分）1. 已知集合A ={y|y =x 2−1,x ∈R}，B ={y|y =x 2+1,x ∈R}，则A ∩B =______．2. 角θ的始边与x 轴正半轴重合，终边上一点坐标为(−1,2)，则tanθ=______．3. “x <5”是“x <1”的__________________________条件4. 设向量a ⃗ =(1,2),b ⃗ =(2,3)，若向量λa ⃗ +b ⃗ 与向量c ⃗ =(−3,−3)共线，则λ=______．5. 函数y =lg(1−1x )+√2x −3的定义域是______ ．6. 若f(x)为奇函数，当x <0时，f(x)=log 2(2−x)，则f(2)= ______ ．7. 已知等差数列{a n }的前n 项和为S n ，且a 1=−20，若S n 的最小值仅为S 6，则公差d 的取值范围是______．8. 若sin(π2+α)=35，则cos2α= ___________． 9. 已知f (x )=sin (x +7π4)+cos (x −3π4)(x ∈R)，则f(x)的最小值为________．10. 已知函数f(x)={x 2−2x ⋯x <0−x 2−2x ⋯x ≥0，若f(3−a 2)<f(2a)，则实数a 的取值范围是________． 11. 在等比数列{a n }中，若a 2=9，a 5=243，则数列{a n }的前4项和为________． 12. 已知△ABC 是等腰直角三角形，AC =BC =2，则AB ⃗⃗⃗⃗⃗ ⋅BC ⃗⃗⃗⃗⃗ = ______ ． 13. 在△ABC 中，已知AB =2，，若BC =3，AC 的长为________；若点D 为AC 中点，且BD =√172，sin A 的值为________．14. 已知函数f(x)=sinx −2x −a ，若f(x)在[0,π]上的最大值为−1，则实数a 的值是______． 二、解答题（本大题共6小题，共90.0分）15. 已知函数f(x)=sin(ωx +π4)(ω>0)的图象的相邻两条对称轴之间的距离等于π3．(1)求函数f(x)的解析式；(2)求最小正实数m ，使得f(x)图象向左平移m 个单位后所对应的函数是偶函数．16. 已知命题p:∀x ∈[−12,1]，不等式m −x 2>0恒成立；q ：方程x 2m 2+y 24=1表示焦点在x 轴上的椭圆．(1)若¬p为假命题，求实数m的取值范围；(2)若p∨q为真命题，p∧q为假命题，求实数m的取值范围．17.如图，某自来水公司要在公路两侧铺设水管，公路为东西方向，在路北侧沿直线铺设线路l1，在路南侧沿直线铺设线路l2，现要在矩形区域ABCD内沿直线将l1与l2接通．已知AB=60m，BC=80m.公路两侧铺设水管的给用为每米1万元，穿过公路的EF部分铺设水管的费用为每米−α，矩形区域内铺设水管的总费用为2万元，设∠EFB=π2W．(1)求W关于α的函数关系式；(2)求W的最小值及相应的角α．18.已知向量m→=(sinA,sinB)，n→=(cosB,cosA)，m→.n→=sin2C，其中A、B、C为ΔABC的内角，所对的边分别是a，b，c．(1)求角C的大小；(2)若2c=a+b，且CA→.(AB→−AC→)=18，求AB的长．)2．19.各项均为正数的数列{a n}中，前n项和S n=(a n+12(1)求数列{a n}的通项公式；(2)是否存在正整数m，k，使得a m，a m+5，a k成等比数列？若存在，求出m和k的值，若不存在，请说明理由．−1在点(2,f(2))处的切线方程．20.求函数f(x)=lnx+x+2x-------- 答案与解析 --------1.答案：{y|y≥1}解析：【分析】本题考查交集的求法，是基础题，解题时要认真审题，注意交集定义的合理运用．【解答】解：∵集合A={y|y=x2−1,x∈R}={y|y≥−1}，B={y|y=x2+1,x∈R}={y|y≥1}，∴A∩B={y|y≥1}．故答案为{y|y≥1}．2.答案：−2解析：解：∵角θ的始边与x轴正半轴重合，终边上一点坐标为(−1,2)，=−2，∴x=−1，y=2，则tanθ=yx故答案为：−2．由题意利用任意角的三角函数的定义，求得tanθ的值．本题主要考查任意角的三角函数的定义，的应用，属于基础题．3.答案：必要不充分解析：【分析】本题考查必要条件，充分条件，充要条件的判断，由x<1可得x<5，反之不成立，即可判断出．【解答】解：由x<1可得x<5，反之不成立，∴x<5是x<1的必要不充分条件．故答案为必要不充分．4.答案：−1解析：【分析】本题考查向量共线的坐标形式的充要条件，属基础题．a ⃗ //b ⃗ ⇔x 1y 2−x 2y 1=0，先求出向量λa ⃗ +b ⃗ 的坐标，然后根据向量共线的坐标形式的充要条件：a ⃗ //b ⃗ ⇔x 1y 2−x 2y 1=0建立等式，解之即可． 【解答】解：λa ⃗ +b ⃗ =(2+λ,3+2λ)c ⃗ =(−3,−3) ∵若向量λa ⃗ +b⃗ 与向量c ⃗ =(−3,−3)共线， ∴−3×(2+λ)−3×(3+2λ)=0解得：λ=−1 故答案为−1．5.答案：[log 23,+∞)解析：解：要使函数有意义，则{1−1x >02x −3≥0，即{x <0或x >1x ≥log 23， ∴x ≥log 23，即函数的定义域为[log 23,+∞)， 故答案为：[log 23,+∞)根据函数成立的条件，即可求出函数的定义域．本题主要考查函数定义域的求法，要求熟练掌握常见函数成立的条件，比较基础．6.答案：−2解析：解：f(x)为奇函数，则f(−x)=−f(x)， 当x <0时，f(x)=log 2(2−x)， 则f(−2)=log 2(2+2)=2， 则f(2)=−f(−2)=−2． 故答案为：−2．f(x)为奇函数，则f(−x)=−f(x)，由已知得到f(−2)，再由f(2)=−f(−2)，即可得到结论． 本题考查函数的奇偶性的运用：求函数值，注意运用定义和已知的解析式，考查运算能力，属于基础题．7.答案：(103,4)解析：解：S n=−20n+n(n−1)2d=d2n2−(20+d2)n，∵S n的最小值仅为S6，则d2>0，5.5<20+d2d<6.5，解得：103<d<4．∴公差d的取值范围是(103,4)．故答案为：(103,4)．利用等差数列的求和公式、二次函数的单调性即可得出．本题考查了等差数列的求和公式、二次函数的单调性，考查了推理能力与计算能力，属于中档题．8.答案：−725解析：【分析】本题考查了三角函数的诱导公式以及余弦二倍角公式应用，属于基础题．根据诱导公式求cosα，再由二倍角公式即可求解．【解答】解：由，得cos2α=2cos2α−1=1825−1=−725．故答案为−725．9.答案：−2解析：【分析】本题考查两角和与差的三角函数公式的应用以及正弦函数的图象和性质，利用两角和与差的三角函数公式化简函数式得到f(x)=√2sinx，再根据正弦函数的性质即可求出答案，属于基础题．【解答】解：f(x)=sinxcos7π4+cosxsin7π4+cosxcos3π4+sinxsin3π4=√22sinx−√22cosx−√22cosx+√22sinx，当时，f(x)取最小值−2．故答案为−2．10.答案：(−3,1)解析： 【分析】本题主要考查分段函数的单调性、二次函数的单调性、一元二次不等式的解法．判断函数的单调性，再解不等式． 【解答】解：当x ≥0时，f (x )=−x 2−2x 是减函数，最小值为0， 当x <0时，f (x )=x 2−2x 是减函数，且f (x )>0， 所以f (x )在R 上是减函数，所以f(3−a 2)<f(2a)等价于3−a 2>2a ， 解得−3<a <1，所以不等式的解集是(−3,1)． 故答案为(−3,1)．11.答案：120解析： 【分析】本题主要考查了等比数列的通项公式和求和公式．属于基础题． 直接应用等比数列的通项公式和求和公式不难求解． 【解答】解：设等比数列{a n }的公比为q ，前n 项和为S n ,则q 3=a5a 2=27，∴q =3，∴a 1=a 2q=3，∴S 4=a 1(1−q 4)1−q=3×(1−34)1−3=120，故答案为120．12.答案：−4解析：【解答】解：∵△ABC 是等腰直角三角形，AC =BC =2，∴AB =2√2，<AB ⃗⃗⃗⃗⃗ ⋅BC ⃗⃗⃗⃗⃗ >=135∘，AB ⃗⃗⃗⃗⃗ ⋅BC ⃗⃗⃗⃗⃗ =|AB ⃗⃗⃗⃗⃗ |×|BC ⃗⃗⃗⃗⃗ |cos135°=2√2×2×(−√22)=−4 故答案为：−4 【分析】由已知得AB =2√2，<AB ⃗⃗⃗⃗⃗ ⋅BC ⃗⃗⃗⃗⃗ >=135∘，AB ⃗⃗⃗⃗⃗ ⋅BC ⃗⃗⃗⃗⃗ =|AB ⃗⃗⃗⃗⃗ |×|BC ⃗⃗⃗⃗⃗ |cos135°，代入计算即可得到所求值．本题考查了向量的数量积运算，属于基础题。

盐城市2019届高三年级第一学期期中考试数学试题（总分160分，考试时间120分钟）一、填空题（本大题共14小题，每小题5分，共70分，请将答案填写在答题卷相应的位置上．） 1．若全集U ＝{1，2，3}，A ＝{1，2}，则∁U A ＝ ． 考点：集合的运算。

答案：{}3解析：∁U A 就是在全集U 中找出集合A 没有的元素，所以，∁U A ＝{}3 2．函数ln y x =的定义域为 ． 考点：二次根式的定义，对数函数的性质。

答案：[)1,+∞解析：由二次根式的定义，得：ln x ≥0，所以，x ≥1，定义域为[)1,+∞3．若钝角α的始边与x 轴的非负半轴重合，终边与单位圆交于点P(m ，32)，则tan α＝ ．考点：三角函数的概念。

答案：3-解析：点P 在单位圆上，所以，223()12m +=，因为α是钝角，所以，m ＝－12，tan yxα=＝3- 4．在△ABC 中，角A ，B ，C 的对边分别为a ，b ，c ，若a ＝3，b ＝5，c ＝7，则角C ＝ ． 考点：余弦定理。

答案：23π 解析：由余弦定理，得：cosC ＝2222a b c ab+-＝9254912352+-=-⨯⨯，所以，C ＝23π5．已知向量(1m =，1)-，(cos n α=，sin )α，其中[0α∈，]π，若m ∥n ，则α＝ ． 考点：平面数量的数量积，平行（共线）向量的性质。

答案：34π解析：因为m ∥n ，所以，sin α＝－cos α即tan α＝－1，故α＝34π 6．设等差数列{}n a 的前n 项和为n S ，若36a =，749S =，则公差d ＝ ． 考点：等差数列的通项公式、前n 项和公式，等差数列的性质。

答案：1 解析：17747()7492a a S a +===，所以，4a ＝7， 公差d ＝7-6＝1 7．在平面直角坐标系中，曲线21x y e x =++在x ＝0处的切线方程是 ． 考点：导数及其应用，直线方程。