吉林省长春外国语学校2012届高三数学上学期期中考试 文【会员独享】
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长春外国语学校2023—2024学年上学期高三年级第一次月考数学试卷本试卷分第Ⅰ卷和第Ⅱ卷两部分,共8页。
考试结束后,将答题卡交回。
注意事项:1.答题前,考生先将自己的姓名、准考证号填写清楚,将条形码准确粘贴在考生信息条形码粘贴区。
2.选择题必须使用2B铅笔填涂;非选择题必须使用0.5毫米黑色字迹的签字笔书写,字体工整、笔迹清楚。
3.请按照题号顺序在各题目的答题区域内作答,超出答题区域书写的答案无效;在草稿纸、试题卷上答题无效。
4.作图可先使用铅笔画出,确定后必须用黑色字迹的签字笔描黑。
5.保持卡面清洁,不要折叠,不要弄破、弄皱,不准使用涂改液、修正带、刮纸刀。
一、单项选择题(本题共8小题,每小题5分,共40分.在每小题给出的四个选项中,只有一项是符合题目要求的.)二、多项选择题(本题共4小题,每小题5分,共20分.在每小题给出的四个选项中,有多项符合题目要求.全部选对得5分,部分选对得2分,有选错的得0分.)12.函数()()1lnf x x x=-,x∈A.()0f x>三、填空题(本题共4小题,每小题5分,共20分).四、解答题(本题共6小题,满分70分,要求写出必要的解题过程).(1)求角A ;(2)若ABC 的面积为1,求a 的最小值.22.已知函数()e xf x a x a =--,其中0a >.(1)若1a =,证明:()0f x ≥;(2)设函数()()g x xf x =,若0x =为()g x 的极大值点,求a 的取值范围.长春外国语学校2023—2024学年上学期高三年级第一次月考数学答案一、选择题1.A2.B3.C4.A5.B6.B7.D8.A9.AD10.AC11.BCD12.ABD二、填空题13.m=-23-14.-7;715.-216.1三、解答题∴8=x21.(1)由已知()2cos cos 1cos 2a A B b A ⋅++=,22cos cos 2cos a A B b A ⋅+=,由正弦定理22sin cos cos 2sin cos A A B B A C ⋅+=,所以()2cos sin cos sin cos A A B B A C ⋅+=,即()2cos sin A A B C +=,又()0,C π∈,所以3cos 2A =,解得π6A =.(2)由题1sin 12bc A =,得4bc =,又222222cos 28a b c bc A b c bc =+-=+-≥-=-(b c =时取“=”)所以,a ≥=即a 的-2b c ==时取等号.。
A 单元 集合与常用逻辑用语目录A1 集合及其运算 ............................................................................................................................ 1 A2 命题及其关系、充分条件、必要条件 .................................................................................... 6 A3 基本逻辑联结词及量词 .......................................................................................................... 14 A4 单元综合 . (15)A1 集合及其运算【数学理卷·2015届辽宁省沈阳二中高三上学期期中考试(201411)】2. 已知集合,,则( )A .{|0<<} B.{|<<1} C.{|0<<1} D.{|1<<2}【知识点】集合及其运算A1【思路点拨】利用一元二次不等式的解法和指数函数的性质可化简集合M ,N .再利用交集的运算即可得出.【数学理卷·2015届湖南省岳阳一中高三上学期第三次月考(201411)】11. 已知集合{}{}()R |,|12,R A x x a B x x AB =<=<<=且ð,则实数a 的取值范围是 .【知识点】补集、并集的运算.A1【答案】【解析】2a ≥ 解析:{}R 12B x x =≤≥或ð,且()R R A B =ð,可得2a ≥,故答案为2a ≥。
【思路点拨】先根据已知条件求出B 的补集,再根据()R R A B =ð可求结果。
2010-2023历年吉林省长春外国语学校高二上学期期末考试化学试卷第1卷一.参考题库(共20题)1.下列说法中,正确的是A.ΔH>0 kJ/mol表示放热反应,ΔH<0 kJ/mol表示吸热反应B.1 mol H2SO4与1 mol Ba(OH)2反应时放出的热叫做中和热C.1 mol H2与0.5 mol O2反应放出的热就是H2的燃烧热D.热化学方程式中的化学计量数表示物质的量,所以可以是分数2.关于平衡常数的说法中,正确的是A.在平衡常数表达式中,反应物的浓度为初始浓度,生成物的浓度为平衡浓度B.在任何条件下,化学平衡常数都是一个恒定值C.平衡常数的大小只与浓度有关,与温度、压强、催化剂等无关D.从平衡常数的大小可以判断一个反应进行的程度3.有关如图所示装置的叙述不正确的是A.该装置内可发生原电池反应B.该装置中Pt为正极,电极反应为:O2+2H2O+4e-=4OH-C.溶液中会出现红褐色的沉淀D.该装置中Fe为阴极,电极反应为:Fe—2e-+2OH-=Fe(OH)24.用食用白醋(醋酸浓度约1mol/L)进行下列实验,能证明醋酸为弱电解质的是A.白醋中滴入石蕊试液呈红色B.实验测得该白醋的pH为2.3C.蛋壳浸泡在白醋中有气体放出D.白醋加入豆浆中有沉淀产生5.为除去MgCl2酸性溶液中的Fe3+,可在加热搅拌的条件下加入一种试剂,过滤后,再向滤液中加入适量的盐酸,这种试剂是A.NH3·H2OB.NaOHC.Na2CO3D.MgCO36.(16分)电解原理在化学工业中有广泛应用。
下图表示一个电解池,装有电解液a ;X、Y是两块电极板,通过导线与直流电源相连。
请回答以下问题:(1)若X、Y都是惰性电极,a是饱和NaCl溶液,实验开始时,同时在两边各滴入几滴酚酞溶液,则电解池中X极上的电极反应为_________________________,在X极附近观察到的现象是:________(2)用湿润的淀粉碘化钾试纸检验Y电极产生的气体,现象是,发生反应的离子方程式为(3)如果用电解方法精炼粗铜,电解液a选用CuSO4溶液,则X电极的材料是__ _______,电极反应式是__________________,Y电极的材料是_________,电极反应式是__________________7.已知H2(g) + Cl2(g) = 2HCl(g) △H= ―184.6kJ·mol-1,则反应HCl(g) =1/2H2(g) + 1/2Cl2(g)的△H为A.+184.6kJ·mol-1B.―92.3kJ·mol-1C.+92.3kJD.+92.3 kJ·mol-18.下列关于原电池和电解池的叙述正确的是A.原电池中失去电子的电极为阴极B.原电池的负极、电解池的阳极都发生氧化反应C.原电池的两极一定是由活动性不同的两种金属组成D.电解时电解池的阳极一定是阴离子放电9.已知某可逆反应mA(g)+ nB(g)pC(g),在密闭容器中进行,下图表示在不同反应时间t、温度T和压强P与反应物B在混合气体中的百分含量B%的关系曲线,由曲线分析,下列判断正确的是A.T1<T2、P1>P2、m+n>p,⊿H <0;B.T1>T2、P1<P2、m+n>p,⊿H >0;C.T1>T2、P1<P2、m+n0;D.T1<T2、P1>P2、m+n<0;10.一种一元强酸HA溶液中加入一种碱MOH后,溶液呈中性,下列判断正确的是A.加入的酸过量B.生成的盐不水解C.混合前酸与碱中溶质的物质的量相等D.反应后溶液中A-与M+物质的量浓度相等11.将Al片和Cu片用导线联接,一组插入浓硝酸中,一组插入稀氢氧化钠溶液中,分别形成的原电池,在这两个原电池中,负极分别为A.Al片、Al片B.Al片、Cu片C.Cu片、Al片D.Cu片、Cu片12.将足量BaCO3粉末分别加入下列溶液中,充分溶解至溶液饱和。
2022-2023学年第一学期期末考试高三年级语文试卷本试卷共5页。
考试结束后,将答题卡交回。
注意事项:1.答题前,考生先将自己的姓名、准考证号填写清楚,将条形码准确粘贴在考生信息条形码粘贴区。
2.选择题必须使用2B铅笔填涂;非选择题必须使用0.5毫米黑色字迹的签字笔书写,字体工整、笔迹清楚。
3.请按照题号顺序在各题目的答题区域内作答,超出答题区域书写的答案无效;在草稿纸、试题卷上答题无效。
4.作图可先使用铅笔画出,确定后必须用黑色字迹的签字笔描黑。
5.保持卡面清洁,不要折叠,不要弄破、弄皱,不准使用涂改液、修正带、刮纸刀。
一、现代文阅读(35分)(一)现代文阅读Ⅰ(本题共5小题,19分)阅读下面的文字,完成1~5题。
材料一:敬仰中华优秀传统文化,要结合新的时代条件传承和弘扬,更好构筑中国精神、中国价值、中国力量,为实现中华民族伟大复兴提供不竭动力。
中华优秀传统文化蕴含着丰富的哲学思想、人文精神、价值理念、道德规范,积淀着中华民族最深沉的精神追求,承载着中华民族的精神基因,代表着中华民族独特的精神标识,是中华民族的根和魂。
当前,百年变局和世纪疫情相互交织,世界之变、时代之变、历史之变正以前所未有的方式展开,世界进入新的动荡变革期。
越是在这个时候,越是要有强大的战略定力,越是要有坚定的文化自信。
习近平总书记强调:“在中外文化沟通交流中,我们要保持对自身文化的自信、耐力、定力。
”发展中国特色社会主义文化,就要以马克思主义为指导,坚持中华文化立场,立足当代中国现实,结合当今时代条件,发展面向现代化、面向世界、面向未来的,民族的科学的大众的社会主义文化,推动社会主义精神文明和物质文明协调发展。
在延续民族文化血脉中开拓前进,在不忘本来的基础上吸收外来、面向未来,我们才能在世界文化漱荡中始终站稳脚跟。
(摘编自2022年7月7《人民日报》,蔡文成《敬仰中华优秀传统文化》)材料二:自诞生之日起,中国动画就深受中国传统美学的影响,追求“以形写神、形神兼备”,成功塑造了诸多影响至今的典型形象。
吉林省长春外国语学校2012届高三上学期期中考试英语试题第I卷(选择题共95分)第一部分:英语知识运用(共四节,满分55分)第一节语音知识(共5小题;每小题1分,满分5分)从每小题的A、B、C、D四个选项中,找出其划线部分与所给单词的划线部分读音相同的选项,并在答题卡上将该选项涂黑。
1.Tuesday A. excuse B. difficult C. adjust D. square2. Chinese A. begin B. appreciate C. basement D. enemy3. houses A. nurses B. horses C. pulses D. causes4. school A. wood B. stood C. food D. blood5. official A. concert B. musician C. success D. physical第二节情景对话(共5小题;每小题1分,满分5分)根据对话情景和内容,从对话后所给的选项中选出能填入每一空白处的最佳选项,并在答题卡上将该选项涂黑。
选项中有两个为多余选项。
After school, Linda and James are talking on their way home.Linda: I feel a bit tired after a whole day’s work.James: So do I. 6Linda: I enjoy chatting online with my friends, going to the movies and doing many other things. James: 7Linda: I collect stamps. I try my best to get stamps from other countries. What about you? James: 8 It is a fun way to exercise, though cycling is a bit dangerous. I like playing tennis, too.Linda: No wonder you are always so energetic.James: Yes. If we do exercise every day, we can keep our heart and lungs in good shape.Linda: 9 Can you give me some tips on how to keep fit?James: The best way to keep fit is to do some sports. I’m going cycling now.10Linda: Sounds wonderful! Let’s go t o the countryside together.A. What’s your favorite sport?B. Now I’m putting on weight.C. I enjoy riding my bike and looking at the scenery along the road.D. What do you do to relax yourself?E. Do you want to go with me?F. What’s your favorite hobby?G. You really should do some sports to lose weight.第三节语法和词汇知识(共15小题;每小题1分,满分15分)从每小题的A、B、C、D四个选项中,选出可以填入空白处的最佳选项,并在答题卡上将该选项涂黑。
长春外国语学校2011—2012学年第一学期期末考试高一年级政治科试卷出题人:白雪梅一、选择题(只有一个最符合题意的选项,每小题2分,共30分)1、用“拉面”技术学日语,用Photoshop技能交换学拉小提琴,用杨氏太极招式交换摄影技术……这是厦门理工学院校园里出现的五花八门的“技能交换”现象。
如果从市场角度看“技能交换”现象,下列理解正确的是()A. “技能交换”属于商品流通B. “技能交换”属于商品交换C. “技能交换”属于物物交换D. 技能的本质是一般等价物2、随着信息技术的发展,许多人购物和旅行时经常使用信用卡。
信用卡作为电子货币的一种,在使用过程中执行的货币职能有()①一般等价物②流通手段③贮藏手段④支付手段A. ①②B. ①③C. ②④D. ③④3、假定某国待售商品量2 000 亿件,平均每件商品价格为10元,货币每年平均流通4次,当年该国流通中需要货币量是________亿元。
当年该国政府实际发行了10 000亿元纸币,这时的1元相当________元,就会________。
()A. 5 0000.25使纸币购买力下降B. 5 0000.5引发通货膨胀C. 5 0000.5使纸币购买力提高D. 20 0002使纸币升值4、2011年10月份,100日元兑人民币为8.2778元,而2010年5月初时,100日元兑人民币仅为7.2元,日元兑人民币进入“8时代”。
此次汇率变动是有人欢喜有人愁,下列认识符合这次汇率变动的影响的是()①旅行社:赴日本旅游线路团费报价上涨②对外劳务输出公司:对去日本务工的人来说,就等于涨工资了③留学生:赴日留学成本将减少④海关:日本对我国出口将增加A.①② B.②④ C.③④ D.②③5北京—福州动车组(新型快速列车)仅运行了两个多月之后,因为上座率低而停①价格是影响消费的重要因素②人们生活水平不断提高③消费者总是选择物美价廉的商品④新型快速列车的发展不适合市场需求A. ①②B. ①③C. ①④D. ②④6、某行业去年的劳动生产率是每小时生产2件商品,每件商品价值用货币表示为260元。
吉林省长春市朝阳区长春外国语学校2023-2024学年高三上学期11月期中英语试题学校:___________姓名:___________班级:___________考号:___________一、阅读理解With the cost of living in the United States soaring, more and more people are setting their sights on an international destination.EcuadorFor real bargain hunters, Ecuador is cheap and safe with a very comfortable year-round climate. The cost of living for one person in the country is $750. Ecuador is geographically diverse with miles of endless beaches, hills and rainforests. Housing is economical with the average rent for one person costing around $307 per month.Costa RicaCosta Rica is the perfect place to live abroad without depleting(耗尽)your savings. The cost of living is around $893 and rent for one person runs approximately $406 per month. The tropical destination has cost-effective healthcare. The weather is gorgeous, the water is warm and the housing is highly affordable.UruguayThe country is exquisite(精美的), offering nearly 400 miles of coast, rolling mountains and four distinct seasons. The cost of living is nearly half of what it is in the states at $1,090 and you can find a nice apartment at the reasonable price of $500 per month.PanamaPanama could be a good option for anyone to live cheaply. The cost of living is under half of what it would cost in the U.S. at $1,040 for one person. Rent runs approximately $530 per month and food takes up another $353, but outside of that costs are minimal. The country has a mild climate and offers world-class beaches.1.Which country has economical healthcare?A.Ecuador.B.Costa Rica.C.Uruguay.D.Panama. 2.What makes Uruguay special?A.Its reasonable rent.B.Its good bargains.C.Its diverse climates.D.Its cheap apartments.3.How much is the cost of living in the United States?A.Close to $1,090.B.Around $750.C.Under $893.D.Above $2,080.At St. Francis High School in La Canada, Calif, there’s something to be said about math teacher Jim Connor.Truth is, Connor can be a bit of a drudge. But the 70-year-old Vietnam vet says he’s not here to entertain his students. “It drives me crazy when people say school should be fun,” he says. “I mean, it’s nice if it could be, but you can’t make school fun.”And for years, the kids thought that’s all there was to him — until last November, when senior Pat McGoldrick learned they didn’t know the half of him.Pat was in charge of a student blood drive and had just come to Children’s Hospital Los Angeles for a meeting. And he says it was weird: whenever he told someone he went to St. Francis High School, they all said, “Oh, you must know Jim Connor. Isn’t he wonderful? ”“It was disbelief, really,” Pat says. “It was almost kind of finding this alter ego (另一面) that he has.” Inside the blood donor center, Pat found a plaque listing all the top blood donors at the hospital, including the record holder, Jim Connor. Then he learned something even more unbelievable: that whenever Connor isn’t torturing kids with calculus (微积分), he’s on a whole other tangent-cuddling sick babies. Three days a week for the past 20 years, Jim has volunteered at the hospital, stepping in become involved in an activity when parents can’t, to hold, feed and comfort their children.“They tend to calm for him,” Nurse Erin says. “They tend to relax with him. They fall asleep with him.”“I just like them and relate to them somehow,” Connor says.Connor has never been married; he has no kids of his own. But he has fallen hard for these babies.“I’ve always respected him, but now it’s to an even different degree — really to the point where I try to emulate him,” Pat says. “He’s the epitome of a man of service.”4.What do we learn from paragraph 2?A.School can never be fun.B.Connor is highly demanding.C.Connor’s students drive him crazy.D.Connor thinks education is for all.5.What did Pat find out about Mr Connor?A.Mr Connor donated blood as well as his time.B.Mr Connor was awarded for his love toward babies.C.Mr Connor used to be a very strict teacher.D.Mr Connor had a unique teaching philosophy.6.Which of the following is true about Mr. Connor?A.He works two shifts every day for a living.B.He has his alter ego in the eyes of his students all the time.C.He has the ability to connect with those kids he holds.D.He falls hard for those sick kids so he decided not to have his own.7.Which expression can best replace the underlined word “epitome”?A.the best example B.the simplest oneC.the better man D.another candidateA new study found people growing up in rural areas have better navigation (导航) skills than those raised in cities and that people whose home cities have grid layouts (网格布局) are slightly better at navigating similarly organised streets, despite having poorer performance overall.The study involved nearly 4,000,000 participants from 38 countries who played Sea Hero Quest (SHQ), a game requiring them to navigate a boat in a virtual environment to find the places marked on a map. The researchers found that where people grew up influenced their performance in the game, while their present living place did not affect their scores.The researchers compared the home cities of the participants by analysing the “lack-of-order” state of the street networks, to measure the complexity of the layouts. People whose hometown’s street layouts were more ordered like New York were worse at playing SHQ. Those from cities with less ordered street layouts like Prague performed only slightly worse than those from rural areas. To test if people from cities could more effectively find the right direction in environments similar to where they grew up, the researchers developed a city-themed version of SHQ, called CHQ, requiring participants to drive down the streets in a virtual environment from simple grids to more winding street layouts. People growing up in cities with grid layouts were slightly better at navigating in similar environments, although the difference was not as significant as their performance in SHQ.The SHQ project was designed to aid Alzheimer’s research. Professor MichaelHornberger said, “Lack of spatial (空间的) navigation is a key Alzheimer’s symptom in the early stages of the disease. We are seeking to use the knowledge learned from SHQ to develop better disease monitoring tools.” Dr Susan Kohlhaas also said, “Thanks to the amazing response, we have been able to collect data from over four million players. If we’re to understand Alzheimer’s, it’s vital that we have participation from as many people as possible with diverse backgrounds and experiences.”8.What is the finding of the study?A.Street patterns in games are vital to one’s performance.B.People raised in cities have a good sense of direction.C.Growing up in rural areas improves navigation skills.D.One’s present living place affects their navigation skills.9.What did the participants do in the game?A.They drew their own maps of places in a virtual environment.B.They carried out a task of finding the marked place.C.They marked some places on a map to navigate a boat.D.They played games against each other to mark the map.10.What can be inferred about SHQ from Paragraph 3?A.It’s harder than CHQ for those from cities.B.Researchers developed it based on CHQ.C.It evaluates navigation skills better than CHQ.D.Players from New York did better than those from Prague.11.Why does Dr Susan Kohlhaas acknowledge the project?A.It helps Alzheimer’s patients play SHQ.B.It helps people gain navigation skills.C.It helps get a better knowledge of Alzheimer’s.D.It helps spot Alzheimer’s at an early stage.On Feb. 23, an environmental advocacy group “Grassroots” led by students hosted its monthly clothing exchange. The clothing exchange is a free activity on campus where students can donate clothes in exchange for new ones.“One of the key things about sustainability (可持续性) is to reuse,” Crystal Tynon, Co-president and Clothing Exchange Chair, said. “Instead of throwing away old clothes andbuying new clothes, you can donate them and give them a new purpose. You might be done with those clothing items, but someone else might not be.”According to Tynon, “Grassroots” is hoping to expand the activities to other schools. In order to do so, the team is brainstorming new ways to get the word out about donations, hours and events. Now, the clothing exchange is one of the club’s most well-known activities. “Throughout the semester when people realize we have these exchanges, they genuinely bring clothes and participate a lot more. So it does make a difference to clothing sustainability and it does create a community where everyone can share their clothes,” she added.As “Grassroots” is an initiative dedicated to sustainability, paper advertisement is not an option. Instead, the center relies mostly on word-of-mouth and e-mail announcements. It is bringing speakers to campus to talk about sustainability and environmental advocacy. It also has partnerships with local organizations such as “the Sunrise Rochester”, working together to have volunteers become more involved in local sustainability.Chloe Mendoza has been a volunteer since her freshman year. Not only does Mendoza appreciate the intended mission of promoting sustainability, but she also thinks the center has transformed into a safe and accepting community space for all students. Those who have come in looking for something practical often end up leaving with an armful of clothing and a heart full of warmth.“My favorite part about working there is that we get to help people find things that they need for free. Just providing a place for students to go where there isn’t pressure to spend money is really important. A lot of students love saving, so it’s something that students can relate and engage with easily, so I think it’s a really easy way to get students more involved in sustainability,” says Mendoza.12.Which of the following best describes Tynon’s feelings about their clothing exchange?A.Impressive.B.Innovative.C.Demanding.D.Rewarding.13.What can we learn about “Grassroots”?A.It relies heavily on paper advertisements.B.It cooperates with local institutions.C.It invites speakers to be volunteers.D.It earns instant fame in the community.14.What does Mendoza think is an additional benefit of the clothing exchange?A.It brings spiritual comfort.B.It widens the circle of friends.C.It reduces academic pressure.D.It gives a sense of achievement. 15.Which of the following could be the best title for the text?A.Saving Up Through Clothing ExchangeB.Engaging Students in “Grassroots” EventsC.Clothing Exchange Is the Only Way for SustainabilityD.Environmental Advocacy — “Grassroots” Catches On二、七选五your social circle and gain life-enriching benefits by becoming friends with someone younger or older than you. Having friends of different ages can greatly improve the quality of your life.Having older friends can change your attitude towards life because they have already gone through the challenges you are facing. They have been young parents, have survived a job loss, and can help you get through these changes in your own life. 17 Then you’ll feel more ready for what’s coming in future stages.When older people make friends with younger people, they get to share their experiences which can be very rewarding. 18 Giving your wisdom and attention makes you feel better. It gives you meaning and is good for your mental health. Having younger friends can also make you feel younger by including new ideas and energy in your life.19 While making new friends may seem frightening, it’s actually easier than you think. You can first think about your acquaintances or coworkers and see if any of them share your values and interests and would make a good friend. Then see if you can make a coffee date. Besides, you can consider joining in a class that your coworker or acquaintance participates in that you think you will enjoy. 20All in all making friends with people not your age can open your eyes to new ideas and new experiences that can be life-changing.A.For human beings, giving is good.B.Where to find friends sharing a common interest?C.Then how can you make intergenerational friends?D.Having friends at your own age is natural, of course.E.What’s more, younger friends can give you some fresh ideas.F.It’s believed that joining in activities like volunteering is also an effective way.G.An older friend also helps you “try on” certain life experiences before you get there.三、完形填空Every year I’d read over 2,000 college applications from students all over the world.It isrecommendations, one23 is always irresistible in a candidate:kindness.The most surprising 24 of kindness I’ve ever 25 came from a student who had excellent scores and a supportive recommendation from his college counselor(顾问).Even with these qualifications,he might not have 26 .But one letter of recommendation caught my eye.It was from a school security 27 .Letters of recommendation are typically written by people like former presidents,celebrities,and Olympic athletes.The security guard wrote that he supported this student’s admission because of his 28 . This young man was the only person in the school who knew the names of every member of the guard staff. He turned off lights in empty rooms,consistently 29 the hallway monitor each morning and tidied up the classroom after his peers left school 30 nobody was watching. This student, the security guard wrote, had a(n) 31 respect for every person at the school, regardless of position, popularity or power.It gave us a 32 onto a student’s life in the moments when nothing“counted”. That student was admitted by unanimous(一致的)vote of the admissions committee.Next year there might be a flood of security guard recommendations 33 this essay.But if it means students will start paying as much 34 to the people who clean their classrooms as they do to their principals and teachers,I’m happy to help start that 35 .21.A.decent B.difficult C.delicate D.desperate 22.A.However B.Otherwise C.Besides D.Therefore 23.A.ability B.quality C.limitation D.assumption 24.A.signal B.image C.appearance D.indication25.A.come out B.pick up C.come across D.bring up 26.A.stood up B.stood out C.given up D.given out 27.A.guard B.teacher C.principal D.counselor 28.A.wisdom B.bravery C.encouragement D.consideration 29.A.bothered B.answered C.visited D.thanked 30.A.as if B.now that C.even if D.in order that 31.A.demanding B.amusing C.refreshing D.puzzling 32.A.passion B.trouble C.method D.window 33.A.due to B.in need of C.except for D.along with 34.A.money B.notice C.attention D.curiosity 35.A.policy B.trend C.arrangement D.career四、用单词的适当形式完成短文阅读下面短文,在空白处填入1个适当的单词或括号内单词的正确形式。
吉林长春外国语学校2012—2013学年度上学期期中考试高二语文试题第I卷阅读题甲必考题一、现代文阅读(9分,每小题3分)阅读下面的文字,完成1-3题。
骨钙素可能有助糖尿病治疗长期以来,人们一直认为人的骨骼是赋予身体形状与稳定的支架。
但现在研究人员发现,骨头看来会分泌一种帮助控制糖和脂肪的激素——这可能对预防和治疗Ⅱ型糖尿病具有重要意义。
哥伦比亚大学的研究人员发现,某些骨细胞会产生一种叫骨钙素的激素,通过以前不为人知的机制控制血糖和脂肪的代谢。
哥伦比亚大学医学院主管遗传学的杰勒德•卡尔桑蒂今天说:“这是一个令人兴奋的概念,因为这是一个器官的新功能。
从医学角度看也十分令人兴奋,因为它有可能成为治疗Ⅱ型糖尿病的方法。
对老鼠进行的实验表明,成骨细胞会释放骨钙素,这既能促进胰岛素的分泌又能增加胰岛素的敏感性。
它还可以在增加胰岛素的细胞的数量,同时减少脂肪储量。
卡尔桑蒂说,总之,这意味着组成人体骨骼的各种骨头并不只是各种组织的一个框架,而是一种帮助控制能量代谢的内分泌器官。
他说:“这些结果揭开了内分泌学一个一直不为人知的重要方面。
”卡尔桑蒂和同事的研究报告刊登在明天出版的《细胞》月刊上。
他们对基因被改变从而体内不产生骨钙素的实验鼠进行了研究。
他说:“我们发现,由于缺少骨钙素,尽管饮食正常,这些老鼠还是得了Ⅱ型糖尿病,且体重超重,这是很不寻常的。
”糖尿病的大多数疗法是通过增加胰岛素来控制血糖,但问题在于这样做也降低了胰岛素的敏感性。
卡尔桑蒂说,骨钙素在增加胰岛素分泌的同时,也能提高胰岛素的敏感性,这使其有可能成为理想的治疗方法。
目前,他的研究小组正对不同物种注射这种激素,看能不能预防或消除Ⅱ型糖尿病。
“如果获得成功,下一个物种将是人类。
”1.从原文看,下列对“骨钙素”的说明,不正确的一项是()A.骨钙素是由骨头分泌出来的一种激素,它能够通过一种以前不为人所知的机制控制血糖和脂肪的代谢。
B.由成骨细胞释放出来的骨钙素既能促进胰岛素的分泌,又能增加胰岛素的敏感性,还能增加胰岛素细胞的数量和减少脂肪储量。
2018-2019学年吉林省长春外国语学校高一下学期期中考试数学试题一、单选题1.设集合,,则()A.B.C.D.【答案】D【解析】先化简集合,再和集合求交集,即可得出结果.【详解】因为,又,所以.故选D【点睛】本题主要考查集合的交集,熟记概念即可,属于基础题型.2.=()A.B.C.D.【答案】D【解析】根据诱导公式,以及特殊角所对应的三角函数值,即可求出结果.【详解】因为.故选D【点睛】本题主要考查三角函数的值,熟记诱导公式即可,属于基础题型.3.等差数列中,,则()A.B.C.D.【答案】A【解析】由等差数列的前项和公式,结合等差数列的性质,即可求出结果.【详解】因为等差数列中,,所以,即,因此.故选A 【点睛】本题主要考查等差数列的性质,熟记等差数列的性质以及前项和公式,即可求解,属于基础题型. 4.有4个式子:①;②;③;④;其中正确的个数为( ) A . B .C .D .【答案】C【解析】根据向量的数乘运算,可判断①②;根据相反向量可判断③;由向量的数量积可判断④. 【详解】由向量乘以实数仍然为向量,所以,故①正确,②错误; 由,所以,即③正确;由,得不一定成立,故④错误.故选C 【点睛】本题主要考查平面向量的数乘、相反向量以及向量的数量积,熟记概念即可,属于常考题型.5.在ABC ∆中,已知40,20,60b c C ==∠= ,则此三角形的解的情况是( ) A .有一解 B .有两解C .无解D .有解但解的情况不确定 【答案】C【解析】分析:利用正弦定理列出关系式,将,,sin b c C 的值代入求出sin B 的值,即可做出判断. 详解:在ABC ∆中,40,20,60b c C ===,∴由正弦定理sin sin b cB C=,得40sin 2sin 120b CB c===>,则此时三角形无解,故选C.点睛:本题主要考查正弦定理在解三角形中的应用,属于中档题.正弦定理是解三角形的有力工具,其常见用法有以下三种:(1)知道两边和一边的对角,求另一边的对角(一定要注意讨论钝角与锐角);(2)知道两角与一个角的对边,求另一个角的对边;(3)证明化简过程中边角互化;(4)求三角形外接圆半径.6.在中,若,则()A.B.C.D.【答案】D【解析】根据余弦定理,即可求出结果.【详解】因为,所以,由余弦定理可得,因此.故选D【点睛】本题主要考查解三角形,熟记余弦定理即可,属于基础题型.7.要得到函数的图象,只要将函数的图象()A.向左平移个单位B.向右平移个单位C.向左平移个单位D.向右平移个单位【答案】D【解析】由函数图像的平移变换规律:左加右减即可得答案.【详解】,故要得到的图象,只需将函数的图象向右平移个单位,故选:D.【点睛】本题考查三角函数图象的平移变换,该类题目要注意平移方向及平移对象. 8.在中,,则的值为( ) A .B .C .D .±【答案】B 【解析】先由判断的正负,再求出的值,即可得出结果. 【详解】 因为在中,,所以,因此,又,所以.故选B 【点睛】本题主要考查三角恒等变换,熟记二倍角公式、同角三角函数基本关系即可,属于基础题型.9.已知()162a b a b a ==-=,,,则向量a 与向量b 的夹角是( )A .6πB .4πC .3πD .2π【答案】C【解析】试题分析:由条件得22a b a ⋅-=,所以223cos 16cos a b a a b αα⋅=+==⋅=⨯⨯,所以1cos 2α=,即3πα=. 【考点】向量的数量积运算. 10.在中,,则这个三角形一定是( )A .等腰三角形B .直角三角形C .等腰直角三角形D .等腰或直角三角形【答案】A【解析】在△ABC 中,,由正弦定理可得:,即.又. 所以,即.有.所以△ABC为等腰三角形.故选A.11.在数列中,(),则该数列的前10项和为()A.B.C.D.【答案】B【解析】先由题意得到数列为等差数列,根据等差数列前项和,即可得出结果. 【详解】因为在数列中,(),所以数列是以2为公差的等差数列,又,所以,故,因此,该数列的前10项和为.故选B【点睛】本题主要考查等差数列的基本运算,熟记等差数列的通项公式以及前项和公式即可,属于常考题型.12.函数在一个周期内的图象如图,此函数的解析式为A.B.C.D.【答案】A【解析】由函数的图象可得函数的最大值为2,最小值为–2,故有A=2.再由函数的周期性可得,解得ω=2,∴y=2sin(2x+φ).把点(–,2)代入函数的解析式可得2sin[2×(–)+φ]=2,∴2×(–)+φ=2kπ+,k∈Z,解得φ=2kπ+,k∈Z.故函数的解析式为y=2sin(2x+2kπ+),k∈Z,考查四个选项,只有A符合题意.故选A.二、填空题13.在等差数列中,,则________.【答案】2【解析】由,结合题中条件,即可得出结果.【详解】因为在等差数列中,,所以,即.故答案为2【点睛】本题主要考查等差中项的问题,熟记概念即可,属于基础题型.14.在中,已知,是方程的两个实根,则___________.【答案】-7【解析】试题分析:,,.【考点】三角恒等变换.15.已知,,则_______.【答案】【解析】先由题意求出,再由两角差的正弦公式即可得出结果.【详解】因为,,所以,因此.故答案为【点睛】本题主要考查三角恒等变换,给值求值问题,熟记两角差的正弦公式即可,属于基础题型.16.一个扇形的面积为1,周长为4,则这个扇形的圆心角为__________.【解析】解:设这个扇形的圆心角为,则利用已知条件可知,4=r+2r,1=1/2r 2联立方程组可知=2三、解答题 17.已知,求 (1)的值; (2)的值.【答案】【解析】试题分析:由的值求得的值,(1)中利用两角和的正切公式展开,代入即可求值;(2)中将分式的分子分母同除以,将其转化为用表达的式子,代入求值试题解析:(1)∵tan ="2," ∴;所以=;(2)由(1),tanα=-, 所以==.【考点】二倍角公式及同角间的三角函数关系式18.已知平面向量,.(1)若⊥ ,求x 的值; (2)若∥ ,求|-|. 【答案】(1)或(2)|-|=||=||【解析】(1)由⊥,•0,构造一个关于x 的方程,解方程即可求出满足条件的x 的值.(2)若∥,根据两个向量平行,构造一个关于x 的方程,解方程求出x 的值后,分类讨论后,即可得到||.(1)∵⊥,∴•(1,x)•(2x+3,﹣x)=2x+3﹣x2=0整理得:x2﹣2x﹣3=0解得:x=﹣1,或x=3(2)∵∥∴1×(﹣x)﹣x(2x+3)=0即x(2x+4)=0解得x=﹣2,或x=0当x=﹣2时,(1,﹣2),(﹣1,2)(2,﹣4)∴||=2当x=0时,(1,0),(3,0)(﹣2,0)∴||=2故||的值为2或2.【点睛】本题考查了判断两个平面向量的垂直关系的转化,向量的模,平行向量与共线向量的概念及公式,考查了向量的坐标运算,属于基础题.19.已知、、为的三内角,且其对边分别为、、,若.(1)求角的大小;(2)若,求的面积.【答案】(1);(2).【解析】(1)已知等式左边利用两角差的余弦函数公式化简,求出的值,确定出的度数,即可求出的度数;(2)利用余弦定理列出关系式,再利用完全平方公式变形,将与的值代入求出的值,再由的值,利用三角形面积公式即可求出三角形的面积.【详解】(1)∵cos B cos C-sin B sin C=,∴cos(B+C)=.∵A+B+C=π,∴cos(π-A)=.∴cos A=-.又∵0<A<π,∴A=.(2)由余弦定理,得a2=b2+c2-2bc·cos A.则(2)2=(b+c)2-2bc-2bc·cos.∴12=16-2bc-2bc·(-).∴bc=4.∴S△ABC=bc·sin A=×4×=.【点睛】本题主要考查余弦定理、特殊角的三角函数以及三角形面积公式的应用,属于中档题.对余弦定理一定要熟记两种形式:(1);(2),同时还要熟练掌握运用两种形式的条件.另外,在解与三角形、三角函数有关的问题时,还需要记住等特殊角的三角函数值,以便在解题中直接应用.20.记为等差数列的前项和,已知.(1)求的通项公式(2)求,并求的最小值【答案】(1) ;(2) ,最小值.【解析】(1)设等差数列的公差为,根据题意求出,进而可得出通项公式;(2)根据等差数列的前项和公式先求出,再由得到范围,进而可得出结果.【详解】(1)因为数列为等差数列,设公差为,由可得,即,所以;(2)因为为等差数列的前项和,所以,由得,所以当时,取最小值,且最小值为.【点睛】本题主要考查等差数列,熟记通项公式以及前项和公式即可,属于常考题型.21.已知函数(1)求函数的最小正周期及单调递增区间;(2)求在区间的最大值和最小值.【答案】(1)最小正周期为;单调增区间;(2) 最大值2最小值-1 【解析】(1)先化简整理,结合正弦函数的周期性以及单调性,即可求出结果;(2)先由,得到,由正弦函数的性质得到,进而可得出结果.【详解】(1)因为,所以最小正周期为;由得,即单调递增区间为;(2)因为,所以,所以,故,即函数在区间的最大值为2,最小值为-1.【点睛】本题主要考查正弦型三角函数的性质,熟记正弦函数的性质即可,属于常考题型. 22.在中,角所对的边分别是,且(1)求证: 为直角三角形;(2),求的取值范围.【答案】(1)见详解;(2).【解析】(1)根据正弦定理,将化简整理,即可得出结果;(2)先由二倍角公式,将化为二次函数的形式,用换元法令,得到关于的二次函数,根据角的范围,求出的范围,再结合二次函数的单调性,即可得出结果.【详解】(1)因为,所以,即,因为角为三角形内角,所以角,故,即角,为直角,所以为直角三角形;(2)因为,所以,令,由(1)可知,所以,所以,因此在上单调递减;在上单调递增;故,,又,所以.故的取值范围.【点睛】本题主要考查三角形形状的判定以及函数的值域,熟记正弦定理、以及三角函数与二次函数的性质即可,属于常考题型.。
长 春 外 国 语 学 校2011—2012学年第一学期期中考试高三数学
试卷(文科)
考试时间120分钟,满分150分
第Ⅰ卷(选择题 共60分)
一、选择题:本大题共12小题,每小题5分,共60分。
在每小题给出的四个选项中,只有
一项是符合题目要求的,请将正确答案填在答题卡的指定位置.
1.已知集合}3,2,1{=M ,}4,3,2{=N ,则( )
A. N M ⊆
B. M N ⊆
C. },3,2{=N M
D. }4,1{=N M 2.“4
π
α=
”是“12sin =α”的( )
A.充分不必要条件
B.必要不充分条件
C,充要条件 D.既不充分又不必要条件
3.设函数⎪⎩⎪⎨⎧≤->-+=)
1(1)
1(2)(2
2x x x x x x f ,则])2(1[f f 的值为( ) A.
1615 B. 1627- C. .
98
D. 18 4.已知函数)(x f 是定义在R 上的奇函数,且)()2(x f x f -=+,若1)1(=f ,则
=-)4()3(f f ( )
A. -1
B. 1
C. -2
D. 2
5.设9
.04
=a ,48
.08
=b ,5
.1)
2
1(-=c ,则( ) A. b a c >> B.c a b >> C. c b a >> D. b c a >>
6.若02log 2log <<b a ,则下列结论正确的是( )
A. 10<<<b a
B. 10<<<a b
C. 1>>b a
D. 1>>a b 7.已知5
3)(-=x
x f ,则)(x f 是( )
A.奇函数且在),0(+∞上单调递增
B.奇函数且在),0(+∞上单调递减
C.
偶函数且在),0(+∞上单调递增 D.偶函数且在),0(+∞上单调递减
8.若函数1)1()1()(2
2+-+-=x m x m x f 是偶函数,则)(x f 在区间]0,(-∞上是( )
A.增函数
B.减函数
C. 常数
D.以上答案都不对 9.函数x
x x f 9
lg )(-
=的零点所在的大致区间是( ) A. (0,1) B. (5,6) C. (9,10) D. (10,11)
高三文科数学试卷 第1页(共4页)
10.曲线1323+-=x x y 在点(1,-1)处的切线方程是( )
A. 43-=x y
B. 23+-=x y
C. 34+-=x y
D. 54-=x y
11.已知函数⎩⎨⎧≥+-<=)
0(4)3()
0()(x a x a x a x f x 满足对任意的实数21x x ≠都有
0)
()(2
121<--x x x f x f 成立,则实数a 的取值范围是( )
A. ),3(+∞
B. (0,1)
C. ]4
1,0( D. (1,3)
12.已知直线⎪⎪⎩
⎪⎪⎨
⎧=+-=t
y t x 21231(t 为参数)与曲线)4sin(22πθρ-=相交于B A , 两点,则线段AB 的长为( )
A. 2
B. 3
C. 2
D. 5
第Ⅱ卷(非选择题 共90分)
二、填空题:本大题共4小题,每小题5分,共20分.请将正确答案填在答题卡的指定位置.
13.函数1||21
)(2-+-=
x x x f 的定义域为______________________.
14.函数5
42)
2
1()(++-=x x x f 的单调递增区间为______________________. 15.已知函数2
2
3
3)(m nx mx x x f +++=在1-=x 时有极值0,则=+n m
_______________.
16.关于函数)0(|
|1
lg )(2≠+=x x x x f ,有下列命题:
(1)其图像关于y 轴对称;(2))(x f 的最小值是2lg
(3)当0>x 时,)(x f 是增函数;当0<x 时,)(x f 是减函数。
(4))(x f 在区间(-1,0),(2,+∞)上是增函数。
(5))(x f 无最大值,也无最小值。
其中所有正确结论的序号是_________________________.
高三文科数学试卷 第2页(共4页)
三、解答题:本大题共6个小题,共70分,解答应写出文字说明,证明过程或演算步骤.
17.(本小题满分10分)
记关于x 的不等式
01
>+-x a
x 的解集为P ,不等式1|1|≤-x 的解集为Q , (1)若3=a ,求Q P .(2)若P Q ⊆,求实数a 的取值范围. 18.(本小题满分12分) 已知函数),10(11
)(R m a a a
m x f x
∈≠>+-=且是奇函数。
(1)求m 的值。
(2)当2=a 时,解不等式6
1)2(02
<
--<x x f 19.(本小题满分12分)
已知函数)(log )(22
1m mx x x f --=
(1)若1=m ,求函数)(x f 的定义域。
(2)若函数)(x f 的值域为R ,求实数m 的取值范围。
(3)若函数)(x f 在区间)31,(--∞上是增函数,求实数m 的取值范围。
20.(本小题满分12分)
已知函数)(x f y =的定义域为R ,对任意的y x ,R ∈,都有
)()()(y f x f y x f +=+,对任意的0>x ,都有0)(<x f ,且3)3(-=f
(1)证明函数)(x f y =在R 上是减函数。
(2)证明函数)(x f y =是奇函数。
(3)试求)(x f y =在区间)0,](,[<∈mn Z n m n m 且上的值域。
21.(本小题满分12分)
若函数1)1()(2
+++=x m x x f 在区间[0,2]上有零点,求实数m 的 取值范围
22.(本小题满分12分)
已知函数)0(2
)1ln()(2
≥+
-+=k x k x x x f . (1)当2=k 时,求曲线)(x f y =在点))1(,1(f 处的切线方程。
(2)求)(x f y =的单调区间。
高三文科数学试卷 第3页(共4页)
高三年级期中文科数学试卷答题卡
一、选择题:本大题共12小题,每小题5分,共60分。
在每小题给出的四个选项中,只有
二、填空题:本大题共4小题,每小题5分,共20分.请将正确答案填在答题卡的指定位置.
13.__________________________. 14.________________________. 15.___________________________. 16._________________________.
三、解答题:本大题共6个小题,共70分,解答应写出文字说明,证明过程或演算步骤.
17.(本小题满分10分) 【解】
高三文科数学试卷 第4页(共4页)
姓名_________________ 学号_________ 班级___________ 考号______________
18.(本小题满分12分)
【解】
19.(本小题满分12分)
【解】
20.(本小题满分12分)
【解】
高三文科数学试卷答题卡第2页(共4页)
21.(本小题满分12分)
【解】
【解】高三文科数学试卷答题卡第3页(共4页)
高三年级期中文科数学试卷答案
一、选择题:本大题共12小题,每小题5分,共60分。
在每小题给出的四个选项中,只有
一项是符合题目要求的,请将正确答案填在答题卡的指定位置.
13.),2()2,1[]1,2()2,(+∞----∞ 14. ),2[+∞ 15. 11 16. (1)(2)(4) 三、解答题:本大题共6个小题,共70分,解答应写出文字说明,证明过程或演算步骤.
17.(本小题满分10分)
(1)),3(]2,0[)1,(+∞--∞ (2))0,(-∞ 18.(本小题满分12分) (1)21=
m (2))2
13
1,2()1,2131(
+-- 19.(本小题满分12分) (1)),2
5
1()251,
(+∞+--∞ (2)),0[]4,(+∞--∞ _____ 班级___________ 考号______________
(3)]2,322[- 20.(本小题满分12分)
(1)(2)证明略 (2)],[m n -- 21.(本小题满分12分) ]3,(--∞
22.(本小题满分12分) (1)032ln 223=-+-y x
(2)0=k 时,增区间为)0,1(-,减区间为),0(+∞ 10<<k 时,增区间为)0,1(-,),1(+∞-k k ;减区间)1,0(k
k
- 1=k 时,增区间为(-1,+∞) 1>k 时,增区间为)1,1(k k --,),0(+∞;减区间)0,1(k
k -。