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Existence, uniqueness and multiplicity of rotating fluxon waves in annular Josephson juncti

Existence, uniqueness and multiplicity of rotating fluxon waves in annular Josephson juncti
Existence, uniqueness and multiplicity of rotating fluxon waves in annular Josephson juncti

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EXISTENCE,UNIQUENESS AND MULTIPLICITY OF ROTATING FLUXON W A VES IN ANNULAR JOSEPHSON JUNCTIONS GUY KATRIEL Abstract.We prove that the equation modelling an annular Joseph-son junction has a rotating ?uxon wave solution for all values of the parameters.We also obtain results on uniqueness of the rotating ?uxon wave in some parameter regimes,and on multiplicity of rotating ?uxon waves in other parameter regimes.1.Introduction The equation modelling a long Josephson junction is [7](1)φtt +αφt +sin(φ)=φxx +βφxxt +γ,where α>0,β>0,γ>0(α,βdescribe dissipative e?ects,while γdescribes the applied bias current).In the case of annular geometry the periodicity condition (2)φ(x +L,t )=φ(x,t )+2π,is imposed,where L is the circumference of the junction.De?nition 1.A rotating ?uxon wave is a solution of (1),(2)of the form (3)φ(x,t )=θ(kx +ωt ),where the function θ(z )satis?es (4)θ(z +2π)=θ(z )+2π?z ∈R .Clearly the assumption that (3)satis?es (2)implies that (5)k =2π

ω.

2GUY KATRIEL

Substituting(3)into(1)we obtain

(6)βωk2θ′′′(z)+(k2?ω2)θ′′(z)?αωθ′(z)?sin(θ(z))+γ=0,

so that rotating?uxon waves are given by solutions(ω,θ(z))of(6),withθ(z) satisfying(4).

Our aim in this paper is to study the questions of existence and unique-ness/multiplicity of rotating?uxon waves.We shall obtain existence of a ro-tating?uxon wave for all values of the parameters:

Theorem2.For any L>0,α>0,β>0,γ>0,(1),(2)has a rotating ?uxon wave solution(3),withω>0.

To prove Theorem2and our other results,we use methods of nonlinear functional analysis,reducing the problem to a?xed-point equation depending on a parameter(ω),to be solved by means of Leray-Schauder theory,coupled with an auxilliary scalar-valued equation,which we analyze.We have used a similar technique to prove existence of travelling waves of the discrete damped and dc-driven sine-Gordon equation[5].The details of the analysis di?er,and in the discrete sine-Gordon case we could not prove existence for all parameter values(which re?ects the phenomenon of‘pinning’in the discrete case)-while here we are able to do so.

Several researchers have studied long Josephson junctions,and annular ones in particular,experimentally,[2,8,9],numerically[1,6]and analytically [3,4,6,7].

Note that in the caseβ=0(known as the damped dc-driven sine-Gordon equation),(6)reduces to the damped dc-driven pendulum equation which is amenable to phase-plane analysis and is thus well understood,and the existence of rotating?uxon waves for allα>0,γ>0is known(see[10], Section2.2).The situation forβ>0is di?erent.Most existing analytical studies assume that eitherα,βandγare small,so that the equation is treated as a(singular)perturbation of the sine-Gordon equation(the case α=0,β=0,γ=0of(1)),or thatβis small so that the equation is a perturbation of the damped dc-driven sine-Gordon equation.An exception is [6],which studies travelling?uxon waves of kink type on an in?nite line,that is,solutions of(1)of the form(3)with(4)replaced byθ(+∞)?θ(?∞)=2π. Existence results for such waves are proved by a geometric analysis of the corresponding three-dimensional phase-space,and a very intricate structure of solutions is revealed.Here,as we noted,our approach is functional-analytic rather than geometric,leading to the general existence result of Theorem2.

Our method also allows us to derive some further information about the set of rotating?uxon waves.In the physical literature,a common and useful way to describe the behavior of a system is the‘I-V characteristic’-in this case theγ?ω(bias current-frequency)characteristic:

FLUXON WA VES IN ANNULAR JOSEPHSON JUNCTIONS3 De?nition3.The bias-frequency characterstic is the setχ?(0,∞)×(0,∞) of all pairs(ω,γ)for which(1),(2)has a rotating?uxon wave(3),with fre-quencyω.

The setχdepends,of course,on the parameters L,α,β.The following theorem shows that the setχis‘large’.

Theorem4.For any L>0,α>0,β>0,the bias-frequency characteristic χhas a subsetχ0?χwhich has the following properties:

(i)χ0is connected.

(ii)For anyω>0there existsγ>0with(ω,γ)∈χ0.

(iii)For anyγ>0there existsω>0with(ω,γ)∈χ0.

(iv)(0,0)∈

α≤ω≤γ

L

>1

and

(9)α+βk2≥√

γ(ω))|ω>0}

4GUY KATRIEL

where

γ(0)=0,

(12)lim

ω→+∞

γ(ω)=γ.

Let us note that in the caseβ=0,part of the above theorem is not true:whileχis connected and can be parameterized as in(10)(for any k>0,α>0;see[10],sec.2.2),the function

2.

Then there exists a valueγ0>0such that given any0

FLUXON WA VES IN ANNULAR JOSEPHSON JUNCTIONS 5

An important issue which we do not address here is the question of stability.For example:is it true that for any value of α>0

,β>0,γ>0there exists at least one rotating ?uxon wave of (1)which is at least locally asymptotically stable?

2.Existence of rotating fluxon waves

In this section we prove Theorem 4,which in particular implies Theorem

2.To do so we ?rst recast our problem into a functional-analytic form,so that we can apply Leray-Schauder theory.

Multiplying both sides of (6)by θ′(z )and integrating over [0,2π],taking

(4)into account,we obtain

ω βk 2 2π0(θ′′(z ))2dz +α

2π0

(θ′(z ))2dz =2πγ.By our assumption that α>0,β>0,γ>0this implies that ω>0,as stated in Proposition 5,and thus we may set

(15)λ=1

λ

u ′′(z )?αu ′(z )?λsin(z +u (z ))+λγ?α=0.

Rotating ?uxon solutions of (1),(2)thus correspond to pairs (λ,u (z ))with λ>0and u (z )satisfying (17),(18).

By integrating (18)over [0,2π],taking (17)into account,we obtain

(19)1

λ,so that we can rewrite (18)as

βk 2u ′′′(z )+ λk 2?

12π 2π0

sin(s +u (s ))ds =0.

(20)We note that if (λ,u (z ))is a solution to our problem then so is (λ,u (z +c )+c )for any constant c (this of course corresponds to the time-invariance of (1)),

6GUY KATRIEL

hence by adjusting c we may assume that

(21) 2π0u(s)ds=0.

We thus seek pairs(λ,u(z)),satisfying(17),(19),(20)and(21).

Multiplying(20)by1+u′(z)and integrating over[0,2π]we obtain Lemma9.Any solution(λ,u)of(17),(20)and(21)satis?es (22)λ 2π0sin(s+u(s))ds=βk2 2π0(u′′(s))2ds+α 2π0(u′(s))2ds.

In particular,together with(19),(22)implies that

λγ≥α,

which gives the upper bound of(7).Also,noting that the value of the integral on the left-hand side of(19)is at most1,we have

(23)γ?1≤

α

2π 2π0(u′′′(s))2ds 1

2π 2π0(u′(s))2ds 1

2π 2π0(u(s))2ds

1

FLUXON WA VES IN ANNULAR JOSEPHSON JUNCTIONS7 We de?ne a family of linear mappings Lλ:X→Z(λ=0)by (25)Lλ(u)=βk2u′′′(z)+ λk2?1

2π 2π0sin(s+u(s))ds.

Solving(17),(20),(21)is equivalent to solving

(27)Lλ(u)=λN(u),u∈X,

so that our problem reduces to:?nd(λ,u)∈(0,∞)×X such that(27)and (19)hold(we note that,by a simple bootstrap argument,any solution u∈X of(27)is in fact C∞).In other words,de?ning the nonlinear functionalΦ: (0,∞)×Z→R by

(28)Φ(λ,u)=α

2π 2π0sin(s+u(s))ds,

we need to solve the pair of equations(27)and

(29)Φ(λ,u)=γ,

for the unknowns(λ,u)∈(0,∞)×X.

We derive some estimates on Lλwhich will be useful.Let u∈X and write u as a Fourier series

u(z)= l=0a l e ilz.

Noting that

Lλ(e ilz)=? (lα+βk2l3)i+l2(λk2?λ?1) e ilz,

so that

L?1

λ

(e ilz)=? (lα+βk2l3)i+l2(λk2?λ?1) ?1e ilz,

8GUY KATRIEL

we obtain

L?1λ(u) Y= l=0a l (lα+βk2l3)i+l2(λk2?λ?1) ?1e ilz Y

= l=0l2|a l|2 (lα+βk2l3)2+l4(λk2?λ?1)2 ?1 1

2

≤ (α+βk2)2+(λk2?λ?1)2 ?12

= (α+βk2)2+(λk2?λ?1)2 ?1

2

.

In particular(dropping the?rst term on the right-hand side of(30))

(31) L?1

λ Z,Y≤

λ

2

≤λ2=λ

|λ2k2?1|.

De?ning F:(0,∞)×Z→Z by

(33)F(λ,u)=λL?1

λ?N(u),

we may rewrite(27)as

(34)u=F(λ,u),u∈Z.

We note that since L?1

λmaps Z onto X,any solution u∈Z of(34)is in fact

in X.

Since sin(z+u(z)) L2≤1and N(u)is the orthogonal projection of sin(z+u(z))∈L2[0,2π]into Z,we have

(35) N(u) Z≤1?u∈Z.

FLUXON WA VES IN ANNULAR JOSEPHSON JUNCTIONS9 Using(35)and(30),we have the bound:

(36)

F(λ,u) Z≤ F(λ,u) Y≤λ (α+βk2)2+(λk2?λ?1)2 ?1

Σ0.

Since the mapping F that we have de?ned satis?es the hypotheses of Theorem10,we have a setΣ0as in the Theorem.

We de?neχ0?χby

(39)χ0={(ω,Φ(ω?1,u))|ω>0,(ω?1,u)∈Σ0},

and we will show thatχ0has all the properties claimed in Theorem4.

SinceΦis continuous andΣ0is connected,χ0is connected,so we have (i)of Theorem4.

Part(ii)of Theorem4follows from the following

Lemma11.LetΣ0be as in Theorem10.For anyλ>0there exists u∈Z such that(λ,u)∈Σ0.

10GUY KATRIEL

proof:Since from(34)and(36)we have

(40)(λ,u)∈Σ? u Z≤λ1

Σ0,Λalso contains arbitrary small positive values.SinceΣ0,henceΛ,is connected,we conclude thatΛ=(0,∞).

To prove thatχ0satis?es property(iii)of Theorem4(and hence also Theorem2),we need to show that

(41)(0,∞)?Φ(Σ0).

SinceΣ0is connected andΦis continuous,Φ(Σ0)is also connected,so that to prove(41)it su?ces to show thatΦtakes arbitrarily large and arbitrarily small positive values onΣ0.Since the integral in the de?nition(28)ofΦis bounded by1,it is immediate that

(42)lim

λ→0+,(λ,u)∈Σ

Φ(λ,u)=+∞,

so thatΦtakes arbitrarily large values onΣ0.We shall prove

Lemma12.

(43)lim

λ→+∞,(λ,u)∈Σ

Φ(λ,u)=0.

This implies thatΦtakes arbitrarily small positive values onΣ0,com-pleting the proof of(41),and thus of part(iii)of Theorem4holds.

proof of Lemma12:Applying Wirtinger’s inequality(24)with v=u′, Lemma9implies

(44)

(λ,u)∈Σ?λ1

2π 2π0(u′(s))2ds.

From(34)and(31)we obtain

(45)(λ,u)∈Σ? u Y≤λ2

2π 2π0sin(s+u(s))ds

≤(βk2+α)λ3

FLUXON WA VES IN ANNULAR JOSEPHSON JUNCTIONS11 which implies that

(46)lim

λ→+∞,(λ,u)∈Σ

1

n (n≥1),and note that by

part(ii)of the Theorem,there exists,for each n,γn>0such that(ωn,γn)∈χ0.By the de?nition ofχ0there exists u n∈Σ0such thatγn=Φ(ω?1n,u n). But by Lemma12we haveγn→0as n→∞.Hence we have(ωn,γn)→(0,0), so we have(0,0)∈

2

<1

then F(λ,.):Z→Y(hence also F(λ,.):Z→Z)is a contraction.

proof:Computing the Frech′e t derivative of N:Z→Z we have

N′(u)(v)=cos(z+u(z))v(z)?

1

2

?u∈Z, which,by(47),completes the proof.

Lemma14.Fixingα≥0,β>0,there existsλ0>0such that for any λ∈[0,λ0)the equation(34)has a unique solution,which we denote by uλ. The mappingλ→uλfrom[0,λ0)into Z is continuous and is real-analytic forλ∈(0,λ0).

proof:It is easy to see that we can?ndλ0>0such that(47)holds for λ∈[0,λ0),and thus by Lemma13,for anyλ∈[0,λ0)the mapping F(λ,.): Z→Z is a contraction,so that,by Banach’s?xed-point Theorem,equation (34)has a unique solution,which we denote by uλ.Real-analyticity of the mappingλ→uλfollows from the real-analytic implicit function Theorem.

12GUY KATRIEL

Returning to the proof of part(v)of Theorem4,we note that since, by Lemma11,for eachλthere exists u such that(λ,u)∈Σ0,and since the uniqueness in Lemma14implies that whenλ<λ0such a u is unique inΣ, we must have

(50)0<λ<λ0,(λ,u)∈Σ?(λ,u)∈Σ0.

Thus if we setω0=1

2π 2π0sin(s+u(s))ds>0.

The strictness in the above inequality follows from the fact that,by (22),if we had equality this would imply u=0,but it is easy to check that (λ,0)∈Σforλ>0.

3.More on the bias-frequency characteristic

In this section we prove Theorem6,which shows that for a certain open subset of the space of parameters L,α,β,the bias-frequency characteristicχis a connected,real analytic curve,and can be represented as the graph of a function:γ=

FLUXON WA VES IN ANNULAR JOSEPHSON JUNCTIONS13 The condition k>1ensures that the quadratic function p(μ)has a minimum, and we have p(0)=1>0.Moreover the condition(9)ensures that p′(0)≥0, which implies p is increasing on[0,∞),so that(54)holds.We thus obtain a unique solution uλto(34).The fact that it is real-analytic inλ∈(0,∞) follows from the analytic implicit function Theorem and the fact that the

functionλ→L?1

λfrom(0,∞)to the space B(Z)of bounded linear operators

from Z to itself is real-analytic.

Let us note here that it is precisely the last statement in the above proof

-the fact thatλ→L?1

λis real-analytic,that breaks down whenβ=0,and

is responsible for the fact that in that case(i.e.the case of the damped,dc-forced sine-Gordon equation)the curveχis not smooth(see[10],?g.2).The

reason that,whenβ=0,λ→L?1

λis not real-analytic can be gleaned by

recalling the de?nition(25):ifβ=0then atλ=1γ(ω)=Ψ(ω?1)we have(10).The fact that

14GUY KATRIEL

To prove claim(57)we note that,

since

Ψ(λ)=α

2π 2π0sin(s+uλ(s))ds,

we have

Ψ′(λ)=?α

2π 2π0cos(s+uλ(s))Dλuλ(s)ds,

and using Cauchy’s inequality (58)Ψ′(λ)≤?

α

λ2)asλ→0+.In fact

we shall prove a much stronger statement:

Lemma17.We have

(59) Dλuλ Z=O(λ)asλ→0+.

proof:We di?erentiate the identity

Lλ(uλ)=λN(uλ)

with respect toλ,obtaining

(60)(DλLλ)(uλ)+Lλ(Dλuλ)=N(uλ)+λN′(uλ)(Dλuλ).

We note that,because we assumeλ∈(0,λ0),whereλ0is de?ned as in

Lemma14,λL?1

λN′(uλ)is a contraction from Z to itself so the inverse of

I?λL?1

λN′(uλ)is well de?ned as a mapping from Z to itself.Moreover we

have,using(49),

(61)

[I?λL?1λN′(uλ)]?1 Z,Z≤1

2π 2π0cos2(s+uλ(s))(1+u′λ(s))2ds 1

2π 2π0(1+u′λ(s))2ds

12≤ 1+ λ22,

FLUXON WA VES IN ANNULAR JOSEPHSON JUNCTIONS15

so that

(63) N(uλ) Y=O(1)asλ→0+.

From(32)and(63)we have

(64)

L?1λN(uλ) Z≤ L?1λN(uλ) X≤ L?1λ Y,X N(uλ) Y=O(λ)asλ→0+.

From the de?nition(25)of Lλwe have,for all u∈X

(DλLλ)(u)= k2+1

λ2 u X?u∈X.

From(64)we have

(66) uλ X=λ L?1λN(uλ) X=O(λ2)asλ→0+,

so using(65),(66)

(67) (DλLλ)(uλ) Y=O(1)asλ→0+,

and together with(32)

(DλLλ)(uλ) Z≤ L?1λ(DλLλ)(uλ) X=O(λ)asλ→0+.

(68) L?1

λ

Using(61),(62),(64)and(68)we obtain(59).

5.multiplicity of rotating fluxon waves

In this section we prove Theorem8,which shows that for some values of the parameters L,β,ifα>0is su?ciently small then there exists an interval ofγ’s for which there exist at least three rotating?uxon waves.

Lemma18.Assume thatβ>0and(8),(14)hold.Then for anyα≥0,λ≥0,the equation(34)has a unique solution,which we denote by uα,λ. The mapping(α,λ)→uα,λfrom[0,∞)×[0,∞)into Z is continuous.

As in the proof of Lemma16,this follows from the Banach?xed point Theorem applied to(34).Note that(14)implies that(9)holds for allα≥0.

Since in the following argument the dependence onαis important,we display it in the notation(of course uα,λalso depends on the parameters k and β,but since we shall regard these as?xed we can suppress this dependence). proof of Theorem8:Under the conditions of Lemma18we can de?ne Ψα(λ)as in(55),now de?ned for allλ∈[0,∞),so that rotating?uxon waves correspond to solutions of

(69)Ψα(λ)=γ,λ>0.

16GUY KATRIEL

We write Ψα(λ)in the form (see (28))(70)Ψα(

λ)

=α2

π 2π

sin(s +u α,λ(s ))ds.We note some properties of the function Υα(λ)(valid for any α≥0).Since u α,0=0we have

(71)

Υα(0)=0.From (46)we obtain:

(72)

lim λ→+∞Υα(λ)=0.Lemma 15implies

(73)Υα(λ)>0?λ>0.

(71),(72),(73),imply that Υα(λ)attains a positive global maximum at some λ>0.In particular this is true for α=0,and we denote the global maximum of Υ0(λ)by γ0,and assume that it is attained at λ0>0:

(74)Υ0(λ0)=γ0=max λ>0

Υ0(λ).We now ?x an arbitrary 0

14,Υ0(λ2)

2

?α∈[0,α0],λ∈[0,λ2].From (74),(75)and (76)we obtain,for all α∈[0,α0],

(77)Υα(λ0)>γ0?

?4?,Υα(λ2)<

3

λ1<

?2?α∈[0,α0],λ≥λ1.

FLUXON WA VES IN ANNULAR JOSEPHSON JUNCTIONS17

Together with(77),(78)this gives,for all0<α<α0,

(80)Ψα(λ0)>γ0??,

(81)Ψα(λ1)

(82)Ψα(λ2)

and by(70)we also have

(83)lim

Ψα(λ)=+∞.

λ→0+

Thus by continuity ofΨαon(0,∞),if we takeγ∈(?,γ0??)then by(83)and (81)the equation(69)has a solutionλ∈(0,λ1),by(81)and(80)the equation (69)has a solutionλ∈(λ1,λ0),and by(80)and(82)the equation(69)has a solutionλ∈(λ1,λ2).We have thus found,under the stated assumptions,three solutions of(69),corresponding to three rotating?uxon waves with di?erent frequencies.

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Einstein Institute of Mathematics,The Hebrew University of Jerusalem, Jerusalem,91904,Israel

E-mail address:haggaik@https://www.doczj.com/doc/7912662230.html,

共同保密协议中英文对照版

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逻辑错误一览-全了!----这个必看啊---

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外阴白色病变的检查诊断方法是什么 外阴奇痒是外阴白色病变的主要症状,搔痒时间从发病到治疗有2~3月之内,也有达20年之久,搔痒剧烈程度不分季节与昼夜。专家提示,一旦发现自己有类似于外阴白色病变的这种,应立即到医院进行确诊。早期的诊断及治疗对我们早日恢复健康并且尤为重要。 外阴白色病变的检查: 多点活检送病理检查,确定病变性质,排除早期癌变,活检应在有皲裂,溃疡,隆起,硬结或粗糙处进行,为做到取材适当,可先用1%甲苯胺蓝(toluidine blue)涂病变区,待白干后,再用1%醋酸液擦洗脱色,凡不脱色区表示该处有裸核存在,提示在该处活检,发现非典型增生或甚至癌变的可能性较大,如局部破损区太广,应先治疗数日,待皮损大部愈合后,再选择活检部位以提高诊断准确率。 外阴白色病变的诊断: 1、症状判断:外阴白斑一般根据症状就可以判断,比如,外阴局部粘 膜发白,瘙痒、粗糙、脱屑等现象的出现,都会诊断为外阴白斑,当然,外阴白斑有很多的类型,如果外阴白斑属于增生型,也就是说局部的皮肤粘膜增厚了,弹性变差了,而且也出现了相应的溃疡等不适症状。这是主要的外阴白斑的诊断方法。 2、细胞活检:有时外阴白斑的诊断需要进一步的做细胞活检,观察有 没有癌细胞,以便于确诊。活检病理检查确定病变性质,排除早期癌变。活检应在有皲裂溃疡、隆起、硬结或粗糙处进行为做到取材适当,外阴白斑的诊断方法可先用1%甲苯胺蓝涂病变区,待白干后再用1%醋酸液擦洗脱色。凡不脱色区表示该处有裸核存在,提示在该处活检发现非典型增生或甚至癌变的可能性较大。如局部破损区太广,应先治疗数日待皮损大部愈合后,再选择活检部位以提高诊断准确率。 3、病理诊断依据:除了解疾病的主要临床症状外,还应对疾病的发病 机理有一定的认识,因为导致外阴白斑皮肤瘙痒及色素的减退或脱色的疾病有很多种,不只是外阴白斑一种,它们的表现虽有些不同,但用肉眼不易区别开来,所以当遇到外阴有病损不典型或慢性皲裂、局限性增厚、溃破等症状的患者时,必须依靠活组织病理检查确诊。

精神分裂症的病因是什么

精神分裂症的病因是什么 精神分裂症是一种精神方面的疾病,青壮年发生的概率高,一般 在16~40岁间,没有正常器官的疾病出现,为一种功能性精神病。 精神分裂症大部分的患者是由于在日常的生活和工作当中受到的压力 过大,而患者没有一个良好的疏导的方式所导致。患者在出现该情况 不仅影响本人的正常社会生活,且对家庭和社会也造成很严重的影响。 精神分裂症常见的致病因素: 1、环境因素:工作环境比如经济水平低低收入人群、无职业的人群中,精神分裂症的患病率明显高于经济水平高的职业人群的患病率。还有实际的生活环境生活中的不如意不开心也会诱发该病。 2、心理因素:生活工作中的不开心不满意,导致情绪上的失控,心里长期受到压抑没有办法和没有正确的途径去发泄,如恋爱失败, 婚姻破裂,学习、工作中不愉快都会成为本病的原因。 3、遗传因素:家族中长辈或者亲属中曾经有过这样的病人,后代会出现精神分裂症的机会比正常人要高。 4、精神影响:人的心里与社会要各个方面都有着不可缺少的联系,对社会环境不适应,自己无法融入到社会中去,自己与社会环境不相

适应,精神和心情就会受到一定的影响,大脑控制着人的精神世界, 有可能促发精神分裂症。 5、身体方面:细菌感染、出现中毒情况、大脑外伤、肿瘤、身体的代谢及营养不良等均可能导致使精神分裂症,身体受到外界环境的 影响受到一定程度的伤害,心里受到打击,无法承受伤害造成的痛苦,可能会出现精神的问题。 对于精神分裂症一定要配合治疗,接受全面正确的治疗,最好的 疗法就是中医疗法加心理疗法。早发现并及时治疗并且科学合理的治疗,不要相信迷信,要去正规的医院接受合理的治疗,接受正确的治 疗按照医生的要求对症下药,配合医生和家人,给病人创造一个良好 的治疗环境,对于该病的康复和痊愈会起到意想不到的效果。

纳什均衡哈佛第六讲

Lecture VI:Existence of Nash equilibrium Markus M.M¨o bius February26,2008 ?Osborne,chapter4 ?Gibbons,sections1.3.B 1Nash’s Existence Theorem When we introduced the notion of Nash equilibrium the idea was to come up with a solution concept which is stronger than IDSDS.Today we show that NE is not too strong in the sense that it guarantees the existence of at least one mixed Nash equilibrium in most games(for sure in all?nite games). This is reassuring because it tells that there is at least one way to play most games.1 Let’s start by stating the main theorem we will prove: Theorem1(Nash Existence)Every?nite strategic-form game has a mixed-strategy Nash equilibrium. Many game theorists therefore regard the set of NE for this reason as the lower bound for the set of reasonably solution concept.A lot of research has gone into re?ning the notion of NE in order to retain the existence result but get more precise predictions in games with multiple equilibria(such as coordination games). However,we have already discussed games which are solvable by IDSDS and hence have a unique Nash equilibrium as well(for example,the two thirds of the average game),but subjects in an experiment will not follow those equilibrium prescription.Therefore,if we want to describe and predict 1Note,that a pure Nash equilibrium is a(degenerate)mixed equilibrium,too. 1

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