2024年中考第一次模拟考试（深圳卷）英语（考试时间：70分钟试卷满分：75分）一、完形填空（共10小题，每小题1分，满分10分）阅读下面短文，从短文后所给的A、B、C、D 四个选项中选出能填入相应空白处的最佳选项，并在答题卡上将相应的字母编号涂黑。
There was a lonely kitten in a small village. She had no families or friends, so she spent her days lying around. She wanted to make friends with others, but everyone was too busy to 1 her.One day, the kitten saw a group of children playing in the 2 . She walked to them quietly, hoping to make some friends. But as soon as she got close, they started 3 her. They said she was too small and too dirty to play with them.The kitten was heartbroken. She 4 the park, crying. She didn’t understand why nobody wanted to be her friend. She felt so lonely and 5However, she met an old cat who was sitting by a tree. The old cat asked her what was wrong, and the kitten told her everything. The old cat listened 6 and then said, “Don’t worry, little one. I will be your 7 . And I will teach you how to be strong and brave.”The kitten was surprised and thankful. She spent the rest of the day with the old cat, learning how to 8 trees. She also learned how to be confident.From that day on, the kitten was never 9 again. She had a friend who loved her and taught her everything. Whenever she saw the children in the park, she would walk by them 10 because she knew that she didn’t need their approval(认可) to be happy.1．A．save B．notice C．punish D．miss2．A．river B．forest C．park D．street3．A．playing with B．laughing at C．shaking hands with D．taking photos of 4．A．ran away from B．arrived at C．drew a picture of D．heard of 5．A．excited B．satisfied C．nervous D．unloved6．A．impolitely B．angrily C．carelessly D．patiently7．A．friend B．follower C．interviewer D．protector8．A．plant B．climb C．burn D．protect9．A．embarrassed B．tired C．lonely D．bored10．A．quietly B．shamefully C．proudly D．slowly二、阅读理解（共15小题，每小题2分，满分30分）阅读下面短文，掌握大意，然后从11～25各题所给的A、B、C、D项中，选出最佳选项，并在答题卡上将该项涂黑。
2024年中考最后一卷（深圳卷）英语本试卷共75分，考试时间70分钟。
注意事项：1. 答卷前，考生务必在答题卡上用黑色字迹的钢笔或签字笔填写自己的考生号、姓名、试室号、座位号，再用2B铅笔把对应这两个号码的标号涂黑。
2. 选择题每小题选出答案后，用2B铅笔把答题卡上对应题目的答案标号涂黑。
如需要改动，用橡皮擦干净后，再选涂其他答案。
不能答在试卷上。
3. 非选择题必须用黑色字迹的钢笔或签字笔作答，答案必须写在答题卡各题目指定区域的相应位置上；如需要改动，先划掉原来的答案，然后再写上新的答案，改动的答案也不能超出指定的区域；不准使用铅笔、圆珠笔和涂改液。
不按以上要求作答的答案无效。
4. 考生必须保持答题卡的整洁，考试结束，将本试卷和答题卡一并交回。
第一部分选择题（50分）一、完型填空（10分）阅读下面短文,从短文后所给的A、B、C、D四个选项中选出能填入相应空白处的最佳选项,并在答题卡上将相应字母编号涂黑。
（共10小题,每小题1分）The grandfather had become very old. His legs would not carry him, his eyes could not see, his ears could not hear, and he was 1 . When he ate, bits of food sometimes dropped out of his mouth. His son and his son’s wife no longer 2 him to eat with them 3 the table. He had to eat his meals in the corner near the stove.One day they gave him his food in a bowl. He tried to move the bowl 4 , but it fell to the floor and broke. His daughter-in-law scolded him. She told him that he spoiled 5 in the house and broke their dishes, and she said that from now on he would get his food in a wooden dish. The old man sighed and said nothing.A few days later, the old man’s son and his wife were sitting in their hut, resting and 6 their little boy playing on the floor. They saw him 7 something out of small pieces of wood. His father asked him, “What are you making, Misha?” The little grandson said, “I’m making a wooden bucket. When you and Mamma get 8 , I’ll feed you out of this wooden dish.”The young peasant and his wife looked at each other and tears 9 their eyes. They were ashamed 10 they bad treated the old grandfather so meanly, and from that day they again let the old man eat with them at thetable and took better care of him.1．A．boneless B．toothless C．careless D．breathless2．A．allowed B．asked C．accepted D．advised3．A．on B．in C．at D．off4．A．farthest B．closest C．farther D．closer5．A．nothing B．everything C．anything D．something6．A．noticing B．looking C．seeing D．watching7．A．putting up B．putting together C．putting out D．putting in8．A．old B．weak C．disabled D．useless9．A．formed B．froze C．fixed D．filled10．A．though B．if C．because D．so二、阅读理解（40分）第一节阅读下列短文,从每小题所给的A、B、C、D四个选项中选山最佳选项,并在答题卡上将相应字母编号涂黑。
新题型2021年中考英语模拟冲刺试题三（深圳专用）第一卷选择题50分Ⅰ 完形填空（本大题共10小题，每小题1分，共10分）通读下面短文，掌握其大意，然后在各小题所给的A、B、C、D四个选项中，选出一个最佳答案，并将答题卡上对应题目所选的选项涂黑。
One afternoon last year, I walked with one of my friends along the road in my hometown. He was not a clever student but worked harder than any other student when we studied at school. And now, he is an 1 worker in his company. I wanted to ask him for help because I had some 2 with my work.When we came to a wide bridge, we met a blind man who went to the 3 direction as ours. He walked very 4 , finding the way with the stick in his hand.I chatted with my 5 as we were walking. I 6 my five job-hopping (跳槽) experiences within two years and complained the trouble I was still going through. My friend 7 nodded and smiled, but he kept silent all along.After a while, I looked forward and found that the blind man walked farther than we did. I couldn't 8 it. I asked, “How did the blind man walk 9 than we did?” My friend said, “Because he put his whole 10 into walking. He was trying his best to walk while we were walking.”That was for sure. He was just absorbed (专注的) in walking, but I was always talking and complaining while walking. When we do something, we must do it with all our heart.( ) 1. A. excellent B. awful C. shy D. clever( ) 2. A. information B. trouble C. advice D. money( ) 3. A. wrong B. right C. same D. different ( ) 4. A. quickly B. slowly C. quietly D. patiently ( ) 5. A. father B. stranger C. teacher D. friend( ) 6. A. worried about B. talked about C. turned out D. cheeked out ( ) 7. A. just B. very C. still D. even( ) 8. A. achieve B. guess C. mention D. believe( ) 9. A. better B. faster C. worse D. earlier( ) 10. A. body B. energy C. heart D. spaceII．阅读理解。
2024年深圳中考数学全真模拟卷（四）（时间：90分钟满分：100分）第一部分选择题一,选择题（本大题共10小题,每小题3分,共30分）1. 下列各数中,为无理数的是（）A. πB. 22C. 0D. −202472. 下列图形中既是轴对称图形又是中心对称图形的是（）A. B. C. D.3. 下列运算正确的是（）A. a2⋅a3=a5B. (a2)3=a5C. a6÷a2=a3D. 3a2−2a=a24. 不等式3(1−x)>2−4x的解在数轴上表示正确的是（）A. B.C. D.5. 某初三学生6次立定跳远的成绩（单位：cm）如下：180,190,195,175,180,200,则这组数据的中位数是（）A. 175B. 180C. 185D. 1956. 如图是A,B,C三岛的平面图,C岛在A岛的北偏东35∘方向,B岛在A岛的北偏东80∘方向,C岛在B岛的北偏西55∘方向,则A,B,C三岛组成一个（）第6题图A. 等腰直角三角形B. 等腰三角形C. 直角三角形D. 等边三角形7. 如图,已知矩形OABC 与矩形ODEF 是位似图形,P 是位似中心,若点B 的坐标为(2,4),点E 的坐标为(−1,2),则点P 的坐标为（ ）第7题图A. (−4,0)B. (−3,0)C. (−2,0)D. (−1.5,0)8. 下列说法正确的是（ ）A. 将油滴入水中,油会浮在水面上是不可能事件B. 抛出的篮球会下落是随机事件C. 了解一批圆珠笔芯的使用寿命,采用普查的方式D. 若甲,乙两组数据的平均数相同,s 甲2=2,s 乙2=2.5,则甲组数据较稳定9. 如图,四边形ABCD 内接于⊙O ,连接OA ,OC ,若∠AOC:∠ADC =2:3,则∠ABC 的度数为（ ）第9题图A. 30∘B. 40∘C. 45∘D. 50∘10. 如图1,Rt △ABC 的边BC 与长方形DEFG 的边DE 都在直线l 上,且点C 与点D 重合,AB =DG ,将△ABC 沿着射线DE 方向移动至点B 与点E 重合时停止,设△ABC 与长方形DEFG 重叠部分的面积是y ,CD 的长度为x ,y 与x 之间的关系图象如图2所示,则长方形DEFG 的面积为（ ）A. 8B. 10C. 6D. 15第二部分非选择题二,填空题（本大题共5小题,每小题3分,共15分）11. 计算(√7+1)(√7−1)的结果等于.12. 一个不透明的箱子中有5个红球和若干个黄球,除颜色外无其他差别.若任意摸出一个球,摸出红球的概率为1,则这个箱子中黄球的个数为个.4BC的长为半径作13. 如图,在△ABC中,AB=AC,分别以点B和点C为圆心,大于12弧,两弧交于点D,作直线AD交BC于点E.若∠BAC=110∘ ,则∠BAE的大小为度.第13题图14. 如图,已知在平面直角坐标系中,点A在x轴负半轴上,点B在第二象限内,反比例的图象经过△OAB的顶点B和边AB的中点C,如果△OAB的面积为6,那函数y=kx么k的值是.第14题图15. 如图,在Rt △ABC 中,∠ABC =90∘ ,AB =BC ,点D 为BC 上一点,点E 为AD 上一点,∠BED =∠CED =45∘ ,若BD =3,则CE 的长为 .第15题图三,解答题（本大题共7小题,共55分）16. （5分）计算：(−12)−2+(π−3.14)0+4cos45∘−|1−√2|.17. （7分）先化简,再求值：x+3x 2−4÷(2−x+1x+2),其中x =5.18. （8分）某校开设拓展课程.为让学生可以根据自己的兴趣爱好选择最喜欢的课程,进行问卷调查,问卷设置以下四种选项：A（综合模型）,B（摄影艺术）,C （音乐鉴赏）,D（劳动实践）,随机抽取了部分学生进行调查,每名学生必须且只能选择其中最喜欢的一种课程,并将调查结果整理绘制成如下不完整的统计图. 根据以上信息,解答下列问题：（1）此次被调查的学生人数为名.（2）直接在答题卡中补全条形统计图.（3）求拓展课程D（劳动实践）所对应的扇形的圆心角的度数.（4）根据抽样调查结果,请你估计该校800名学生中,有多少名学生最喜欢C （音乐鉴赏）拓展课程.19. （8分）小美打算买一束百合和康乃馨组合的鲜花,在“母亲节”祝福妈妈.已知买2支百合和1支康乃馨共需花费14元,3支康乃馨的价格比2支百合的价格多2元.（1）求买一支康乃馨和一支百合各需多少元？（2）小美准备买康乃馨和百合共11支,且百合不少于2支.设买这束鲜花所需费用为w元,康乃馨有x支,求w与x之间的函数关系式,并设计一种使费用最少的买花方案,写出最少费用.20. （8分）设a,b是任意两个实数,用max{a,b}表示a,b两数中较大者,例如：max{−1,−1}=−1,max{1,2}=2,max{4,3}=4,参照上面的材料,解答下列问题：（1）max{5,2}=,max{0,3}= .（2）若max{3x+1,−x+1}=−x+1,求x的取值范围.（3）求函数y=x2−2x−4与y=−x+2的图象的交点坐标,函数y=x2−2x−4的图象如图所示,请你在图中作出函数y=−x+2的图象,并根据图象直接写出max{−x+2,x2−2x−4}的最小值.21. （9分）根据以下素材,探索完成任务.探究遮阳伞下的影子长度素材1图1是某款自动旋转遮阳伞,伞面完全张开时张角呈180∘ ,图2是其侧面示意图.已知支架AB长为2.5米,且垂直于地面BC,悬托架AE=DE=0.5米,点E固定在伞面上,且伞面直径DF是DE的4倍.当伞面完全张开时,点D,E,F始终共线.为实现遮阳效果最佳,伞面装有接收器可以根据太阳光线的角度变化,自动调整手柄D沿着AB移动,以保证太阳光线与DF始终垂直.素材2某地区某天下午不同时间的太阳高度角α（太阳光线与地面的夹角）参照表：参考数据：√3≈1.7,√2≈1.4.素材3小明坐在露营椅上的高度（头顶到地面的距离）约为1米,如图2,小明坐的位置记为点Q.问题解决任务1 确定影子长度.某一时刻测得BD=1.7米,请求出此时影子GH的长度.任务2 判断是否照射到.这天14点,小明坐在离支架3米处的Q点,请判断此时小明是否会被太阳光照射到？任务3 探究合理范围.小明打算在这天14：00—15：00露营休息,为保证小明全程不被太阳光照射到,请计算BQ的取值范围.22. （10分）【阅读资料】如图1,在平面直角坐标系xOy中,A,B两点的坐标分别为A(x1,y1),B(x2,y2),由勾股定理得AB2=|x2−x1|2+|y2−y1|2,所以A,B两点间的距离为AB=√(x2−x1)2+(y2−y1)2.我们知道,圆可以看成到圆心距离等于半径的点的集合,如图2,在平面直角坐标系xOy中,A(x,y)为圆上任意一点,则A到原点的距离的平方为OA2=|x−0|2+|y−0|2,当⊙O的半径为r时,⊙O的方程可写为x2+y2=r2.【问题拓展】如果圆心坐标为P(a,b),半径为r,那么⊙P的方程可以写为. 【综合应用】如图3,⊙P与x轴相切于原点O,P点坐标为(0,6),A是⊙P上一点,连,作PD⊥OA,垂足为D,延长PD交x轴于点B,连接AB.接OA,使tan∠POA=34①证明：AB是⊙P的切线.②是否存在到四点O,P,A,B距离都相等的点Q？若存在,求Q点坐标,并写出以Q为圆心,以OQ为半径的⊙Q的方程,若不存在,说明理由.2024年深圳中考数学全真模拟卷（四）第一部分 选择题一,选择题（本大题共10小题,每小题3分,共30分）1．A 2．A 3．A 4．A 5．C 6．A 7．C 8．D 9．C【解析】设∠AOC =2x ∘ ,∠ADC =3x ∘ ,∵ 圆心角∠AOC 和圆周角∠ABC 都对着ADC ,∴∠ABC =12∠AOC =x ∘ .∵ 四边形ABCD 是⊙O 的内接四边形,∴∠ADC +∠ABC =180∘ ,∴3x +x =180,解得x =45,即∠ABC =45∘ .故选C. 10．B【解析】从题图2可知,△ABC 向右平移2个单位时,点B,D 重合,故BC =2,此时S =12CD ⋅AB =12×2×AB =2,所以AB =DG =2,当△ABC 再向右平移3个单位时,点E ,C 重合,故DE =5,所以长方形DEFG 的面积为2×5=10.故选B.第二部分 非选择题二,填空题（本大题共5小题,每小题3分,共15分）11．6 12．15 13．55 14．−4【解析】如图,过点B 作BD ⊥OA 于点D .∵ 点B 在反比例函数y =kx 的图象上.∴ 设B (−m,n ),点B 在第二象限内.∵△OAB 的面积为6,∴OA =12n,∴A(−12n ,0). ∵ 点C 是AB 的中点,∴C(−mn+122n,n 2).∵ 点C 在反比例函数y =kx 的图象上.∴−mn+122n ⋅n 2=−mn . ∴−mn =−4,∴k =−4.故答案为−4.15．18√55【解析】∵∠ABC =90∘ ,AB =BC .∴∠BAC =∠ACB =45∘ ,AC =√2BA .∵∠BED =∠CED =45∘ ,∴△ABE ∼△CAE .∴CE AE =AE BE =AC BA =√2,∴CE =√2AE ,AE =√2BE .∴CE =2BE ,∴BC =√5BE .如图,过点D 作DF//BE ,交CE 于点F .则∠EDF =∠BED =∠CED ,∴DF =EF .∴BD CD =EF CF =DF CF =BE CE =12,∴CD =2BD =6.∴BC =9,∴√5BE =9,∴BE =9√55,∴CE =18√55. 三,解答题（本大题共7小题,共55分）16．解：原式=4+1+4×√22−(√2−1)=4+1+2√2−√2+1 =6+√2.17．解：原式=x+3(x−2)(x+2)÷x+3x+2=x+3(x−2)(x+2)⋅x+2x+3=1x−2.当x =5时,原式=15−2=13.18．（1） 120解：此次被调查的学生人数为12÷10%=120（名）,故答案为120.（2） 选择B 的学生有120−12−48−24=36（名）.补全条形统计图如图所示.（3）360∘×24120=72∘ ,即拓展课程D（劳动实践）所对应的扇形的圆心角的度数是72∘ .（4）800×48120=320（名）.答：估计该校800名学生中,有320名学生最喜欢C（音乐鉴赏）拓展课程. 19．（1）解：设买一支康乃馨需x元,买一支百合需y元.根据题意,得{x+2y=14,3x−2y=2,解得{x=4,y=5.答：买一支康乃馨需4元,买一支百合需5元.（2）根据题意,得w=4x+5(11−x)=−x+55.∵百合不少于2支,∴11−x≥2,解得x≤9.∵−1<0,∴w随x的增大而减小.∴当x=9时,w最小,即买9支康乃馨,买11−9=2（支）百合费用最少.w min=−9+55=46（元）.∴w与x之间的函数关系式为w=−x+55,买9支康乃馨和2支百合费用最少,最少费用为46元.20．（1） 5, 3解：max{5,2}=5,max{0,3}=3.故答案为5,3.（2）∵max{3x+1,−x+1}=−x+1.∴3x+1≤−x+1,解得x≤0.（3）联立两函数表达式成方程组{y=x2−2x−4, y=−x+2,解得{x1=−2,y1=4,{x2=3,y2=−1,∴两函数图象的交点坐标为(−2,4)和(3,−1).画出直线y=−x+2,如图所示.观察函数图象可知,当x=3时,max{−x+2,x2−2x−4}取最小值−1.21．任务1 解：如图,过点E作EI⊥AB于点I,过点G作GJ⊥FH于点J.∵BD=1.7米,AB=2.5米,∴AD=0.8米.∵AE=DE=0.5米,∴DI=12AD=0.4米.∴IE=0.3米,∴sin∠IDE=35.∵∠FDG=∠DGJ=90∘ ,∴sin∠α=sin∠IDE,四边形DGJF为矩形,∴GJ=DF=2米.在Rt△GJH中,GH=GJsinα=2×53=103（米）.任务2 （方法1）如图,过点Q作PQ⊥BC交HF于点P. 由（1）知,∠IDE=∠α=∠DGB.∵∠α=60∘ ,∴在Rt△IDE中,DI=12DE=14米.AD=12米,∴BD=2米.在Rt△DBG中,BG=√3=√3米.在Rt△GHJ中,GH=√3=√3米.在Rt△PQH中,当PQ=1时,QH=√3=√3米.∴小明刚好被照射到时离B点的距离为√3+√3−√3=√3<3.∴小明会被照射到. （方法2）如图,过点Q 作PQ ⊥BC 交FH 于点P .与方法1同理,得BG =√3米,GH =√3米.∴QH =BH −BQ =(√3−3)米. 在Rt △PQH 中,PQ =√3QH =6−3√3<1.∴ 小明会被照射到.任务3 当tanα=45∘ 时,BQ min =5−√22. 当tanα=60∘ 时,BQ max =√3=5√33. ∴5−√22<BQ <5√33.22．【问题拓展】 解：设A (x,y )为⊙P 上任意一点.∵P (a,b ),半径为r ,∴AP 2=(x −a )2+(y −b )2=r 2.故答案为(x −a )2+(y −b )2=r 2.【综合应用】 ① ∵PO =PA ,PD ⊥OA ,∴∠OPD =∠APD .在△POB 和△PAB 中.{PO =PA,∠OPB =∠APB,PB =PB,∴△POB ≌△PAB ,∴∠POB =∠PAB . ∵⊙P 与x 轴相切于原点O ,∴∠POB =90∘ .∴∠PAB =90∘ ,∴AB 是⊙P 的切线.② 存在到四点O ,P ,A ,B 距离都相等的点Q .当点Q 在线段BP 中点时,∵∠POB =∠PAB =90∘ .∴QO =QP =BQ =AQ .此时点Q 到四点O ,P ,A ,B 距离都相等.∵∠POB =90∘ ,OA ⊥PB .∴∠OBP =90∘−∠DOB =∠POA .∴tan∠OBP=OPOB =tan∠POA=34.∵P点坐标为(0,6),∴OP=6,OB=43OP=8.过点Q作QH⊥OB于点H,如图,则有∠QHB=∠POB=90∘ ,∴QH//PO,∴△BHQ∼△BOP.∴QHOP =BHOB=BQBP=12,∴QH=12OP=3,BH=12OB=4,∴OH=8−4=4.∴点Q的坐标为(4,3),∴OQ=√OH2+QH2=5.∴以Q为圆心,以OQ为半径的⊙Q的方程为(x−4)2+(y−3)2=25.。
